Q:

Dealing with Android's texture size limit

I have a requirement to display somewhat big images on an Android app.
Right now I'm using an ImageView with a source Bitmap.
I understand openGL has a certain device-independent limitation as to
how big the image dimensions can be in order for it to process it.
Is there ANY way to display these images (with fixed width, without cropping) regardless of this limit,
other than splitting the image into multiple ImageView elements?
Thank you.
UPDATE 01 Apr 2013
Still no luck so far all suggestions were to reduce image quality. One suggested it might be possible to bypass this limitation by using the CPU to do the processing instead of using the GPU (though might take more time to process).
I don't understand, is there really no way to display long images with a fixed width without reducing image quality? I bet there is, I'd love it if anyone would at least point me to the right direction.
Thanks everyone.

A:

You can use BitmapRegionDecoder to break apart larger bitmaps (requires API level 10). I've wrote a method that will utilize this class and return a single Drawable that can be placed inside an ImageView:
private static final int MAX_SIZE = 1024;

private Drawable createLargeDrawable(int resId) throws IOException {

    InputStream is = getResources().openRawResource(resId);
    BitmapRegionDecoder brd = BitmapRegionDecoder.newInstance(is, true);

    try {
        if (brd.getWidth() <= MAX_SIZE && brd.getHeight() <= MAX_SIZE) {
            return new BitmapDrawable(getResources(), is);
        }

        int rowCount = (int) Math.ceil((float) brd.getHeight() / (float) MAX_SIZE);
        int colCount = (int) Math.ceil((float) brd.getWidth() / (float) MAX_SIZE);

        BitmapDrawable[] drawables = new BitmapDrawable[rowCount * colCount];

        for (int i = 0; i < rowCount; i++) {

            int top = MAX_SIZE * i;
            int bottom = i == rowCount - 1 ? brd.getHeight() : top + MAX_SIZE;

            for (int j = 0; j < colCount; j++) {

                int left = MAX_SIZE * j;
                int right = j == colCount - 1 ? brd.getWidth() : left + MAX_SIZE;

                Bitmap b = brd.decodeRegion(new Rect(left, top, right, bottom), null);
                BitmapDrawable bd = new BitmapDrawable(getResources(), b);
                bd.setGravity(Gravity.TOP | Gravity.LEFT);
                drawables[i * colCount + j] = bd;
            }
        }

        LayerDrawable ld = new LayerDrawable(drawables);
        for (int i = 0; i < rowCount; i++) {
            for (int j = 0; j < colCount; j++) {
                ld.setLayerInset(i * colCount + j, MAX_SIZE * j, MAX_SIZE * i, 0, 0);
            }
        }

        return ld;
    }
    finally {
        brd.recycle();
    }
}

The method will check to see if the drawable resource is smaller than MAX_SIZE (1024) in both axes. If it is, it just returns the drawable. If it's not, it will break the image apart and decode chunks of the image and place them in a LayerDrawable.
I chose 1024 because I believe most available phones will support images at least that large. If you want to find the actual texture size limit for a phone, you have to do some funky stuff through OpenGL, and it's not something I wanted to dive into.
I wasn't sure how you were accessing your images, so I assumed they were in your drawable folder. If that's not the case, it should be fairly easy to refactor the method to take in whatever parameter you need.

A:

You can use BitmapFactoryOptions to reduce size of picture.You can use somthing like that :
BitmapFactory.Options options = new BitmapFactory.Options();
options.inSampleSize = 3; //reduce size 3 times

