Would appreciate detailed advice. Its my first time using SPSS or any statistics software. I'm using SPSS v13 for this study. It's important! I've never used SPSS before but there's only a One way ANOVA option in the menu, and I only have this software. If I still cant use Two-way Anova, is independent T-test able to subtitute my work for acquiring the estimated mean and p-values of four variables (TC/LDL/HDL/Tri) with their four classes (Male:19-23;24-29|Female:19-23;24-29)?
SPSS\nWith your data entered, go to ANALYZE > GENERAL LINEAR MODEL > UNIVARIATE \nEnter dependent variable in Dependent List \nEnter independent variables in Factor \nContinue – OK \nOutput:\n(A) Descriptives (N, Mean, Std. Dev., etc) \nThis will give you a table. On the right hand side, the significances will be listed, along with the F values. On the far left side, under the column “source,” your variables will be listed. The corresponding F values and significances are for main effects and interaction effects. If the significance reading is less than .05, you are able to reject the null hypothesis.
z = (8.6 - 9.3) / [2.3/sqrt(50)] = -0.7/.325 = -2.15\n\nUsing Excel, the cumulative normal distribution greather than this z score is 98.4%.  If you don't have Excel available,  you can always look up -2.15 in a Z score table.  Remember the value it gives you is below the Z score.  You want the part greater than the Z score, so you have to use one minus the look up value.