because Ross doesn't have one
because Ross do have one
conj n:prop mod v pro:indef
because ross doesn't have one .
b ɪ k ʌ z WORD_BOUNDARY ɹ ɔ s WORD_BOUNDARY d ʌ z ə n t WORD_BOUNDARY h æ v WORD_BOUNDARY w ʌ n WORD_BOUNDARY
b e c a u s e WORD_BOUNDARY r o s s WORD_BOUNDARY d o e s n ' t WORD_BOUNDARY h a v e WORD_BOUNDARY o n e WORD_BOUNDARY