Q:

Is the use of % in printf operator overloading? If not, what is it?

Please explain what happening here:
class Test{
public static void main(String[] args){
    int a = 43%2;
    System.out.printf("The test remainder is %d %s",a,"hello");
 }
}

In the above code i want to know is it operator overloading of the % operator?

A:

Nope. Java currently has very limited support for operator overloading, and this is not one of those cases.
The % in the string literal is handled by the implementation of java.util.Formatter. String#format and PrintWriter#printf delegate the formatting work to Formatter, which manually parses the string.
The only reason % has value there is due to how Formatter handles the string.
If you view the code, you'll find:
if (conversion == '%' || conversion == 'n')

followed by a switch statement which handles the different types.

