Abaixo está uma instrução que descreve uma tarefa de geração de SQL, combinada com uma entrada que fornece mais contexto sobre os esquemas de tabela disponíveis. Escreva o código SQL que responda adequadamente à solicitação
 ###Instrução: question: Nomeie as tentativas com tentativas contra de 38
 ###Tabelas: CREATE TABLE other_incidents (other_incidents_id AUTO_INCREMENT PRIMARY KEY, Name VARCHAR, Date VARCHAR, Year INT, Location VARCHAR, Killed VARCHAR, Injured VARCHAR) CREATE TABLE goalkeeping_leaders (goalkeeping_leaders_id AUTO_INCREMENT PRIMARY KEY, Player VARCHAR, Club VARCHAR, Games Played INT, Minutes INT, Goals Against INT, GA Average INT, Wins INT, Loses INT) CREATE TABLE 2010_2011_table (2010_2011_table_id AUTO_INCREMENT PRIMARY KEY, Club VARCHAR, Played VARCHAR, Drawn VARCHAR, Lost VARCHAR, Points for VARCHAR, Points against VARCHAR, Tries for VARCHAR, Tries against VARCHAR, Try bonus VARCHAR, Losing bonus VARCHAR, Points VARCHAR) CREATE TABLE year_by_year_performance (year_by_year_performance_id AUTO_INCREMENT PRIMARY KEY, Coach VARCHAR, Season VARCHAR, Record VARCHAR, Home VARCHAR, Away VARCHAR, Win % INT, Average (Total) Home Attendance VARCHAR) CREATE TABLE men's_doubles:_8_5_titles_3_runner-ups (men's_doubles:_8_5_titles_3_runner-ups_id AUTO_INCREMENT PRIMARY KEY, Outcome VARCHAR, Year INT, Championship VARCHAR, Surface VARCHAR, Partner VARCHAR, Opponents in the final VARCHAR, Score VARCHAR)  
SELECT Tries for FROM 2010_2011_table WHERE Tries against = 38