Abaixo está uma instrução que descreve uma tarefa de geração de SQL, combinada com uma entrada que fornece mais contexto sobre os esquemas de tabela disponíveis. Escreva o código SQL que responda adequadamente à solicitação
 ###Instrução: Tentativas contra corretas a partir de 2007-10-15 têm quantas tentativas para?
 ###Tabelas: CREATE TABLE average_polling (average_polling_id AUTO_INCREMENT PRIMARY KEY, Party VARCHAR, Result, Parliam. election 2005 VARCHAR, Result, County elections 2007 VARCHAR, Aug 2008 VARCHAR, Sep 2008 VARCHAR, Oct 2008 VARCHAR, Nov 2008 VARCHAR, Dec 2008 VARCHAR, Jan 2009 VARCHAR, Feb 2009 VARCHAR, Mar 2009 VARCHAR, Apr 2009 VARCHAR, May 2009 VARCHAR, Jun 2009 VARCHAR, Jul 2009 VARCHAR, Aug 2009 VARCHAR) CREATE TABLE 2007_2008_table (2007_2008_table_id AUTO_INCREMENT PRIMARY KEY, Club VARCHAR, Played VARCHAR, Drawn VARCHAR, Lost VARCHAR, Points for VARCHAR, Points against VARCHAR, Tries for VARCHAR, Tries against VARCHAR, Try bonus VARCHAR) CREATE TABLE summary_of_election_results_1973_-_2003 (summary_of_election_results_1973_-_2003_id AUTO_INCREMENT PRIMARY KEY, Election INT, Labour INT, Conservative INT, Liberal INT, Social Democratic Party INT, Social and Liberal Democrats/ Liberal Democrats INT, Independent INT, Green INT, Other VARCHAR, Control VARCHAR) CREATE TABLE newly_named_dinosaurs (newly_named_dinosaurs_id AUTO_INCREMENT PRIMARY KEY, Name VARCHAR, Novelty VARCHAR, Status VARCHAR, Authors VARCHAR, Location VARCHAR) CREATE TABLE race_4_-_5.01.2010 (race_4_-_5.01.2010_id AUTO_INCREMENT PRIMARY KEY, Position INT, Pilot VARCHAR, Glider VARCHAR, Speed VARCHAR, Distance VARCHAR)  
SELECT Tries for FROM 2007_2008_table WHERE Tries against = correct as of 2007-10-15