Abaixo está uma instrução que descreve uma tarefa de geração de SQL, combinada com uma entrada que fornece mais contexto sobre os esquemas de tabela disponíveis. Escreva o código SQL que responda adequadamente à solicitação
 ###Instrução: Quantas médias estão associadas a um valor de 62/38 de 2003-2004?
 ###Tabelas: CREATE TABLE 2003 (2003_id AUTO_INCREMENT PRIMARY KEY, Week 1 VARCHAR, Week 2 VARCHAR, Week 3 VARCHAR, Week 4 VARCHAR, Week 5 VARCHAR) CREATE TABLE siena_college_research_institute_survey (siena_college_research_institute_survey_id AUTO_INCREMENT PRIMARY KEY, Seq. VARCHAR, Name VARCHAR, Background INT, Party Leadership INT, Communication Ability INT, Relations with Congress INT, Court Appointments INT, Handling of Economy INT, Luck INT, Ability to Compromise INT, Willing to take Risks INT, Executive Appointments INT, Overall Ability INT, Imagination INT, Domestic Accomplishments INT, Integrity INT, Executive Ability INT, Foreign Policy Accomplishments INT, Leadership Ability INT, Intelligence INT, Avoid Crucial Mistakes INT, Expert's View INT, Overall INT) CREATE TABLE 0_–_728_throw_3_times (0_–_728_throw_3_times_id AUTO_INCREMENT PRIMARY KEY, 1st throw INT, 2nd throw INT, 3rd throw INT, Equation VARCHAR, Result INT) CREATE TABLE relegation (relegation_id AUTO_INCREMENT PRIMARY KEY, Team VARCHAR, Average VARCHAR, Points INT, Played INT, 2003-04 VARCHAR, 2004-05 VARCHAR, 2005-06 VARCHAR) CREATE TABLE season_three_2011 (season_three_2011_id AUTO_INCREMENT PRIMARY KEY, Series # INT, Episode # INT, Title VARCHAR, Written by VARCHAR, Directed by VARCHAR, Viewers INT, Original airdate VARCHAR)  
SELECT COUNT Average FROM relegation WHERE 2003-04 = 62/38