Abaixo está uma instrução que descreve uma tarefa de geração de SQL, combinada com uma entrada que fornece mais contexto sobre os esquemas de tabela disponíveis. Escreva o código SQL que responda adequadamente à solicitação
 ###Instrução: Quantas vezes o terceiro lugar foi conquistado por drnovice?
 ###Tabelas: CREATE TABLE passages (passages_id AUTO_INCREMENT PRIMARY KEY, Incumbent VARCHAR, Reason for Vacancy VARCHAR, Appointed Successor VARCHAR, Date of Appointment VARCHAR, Elected Successor VARCHAR, Date of Election VARCHAR) CREATE TABLE house_of_schleswig-holstein-sonderburg-glücksburg (house_of_schleswig-holstein-sonderburg-glücksburg_id AUTO_INCREMENT PRIMARY KEY, Name VARCHAR, Birth VARCHAR, Marriage VARCHAR, Became Consort VARCHAR, Ceased to be Consort VARCHAR, Spouse VARCHAR) CREATE TABLE role_in_disease (role_in_disease_id AUTO_INCREMENT PRIMARY KEY, Condition VARCHAR, Prothrombin time VARCHAR, Partial thromboplastin time VARCHAR, Bleeding time VARCHAR, Platelet count VARCHAR) CREATE TABLE year_by_year (year_by_year_id AUTO_INCREMENT PRIMARY KEY, Season VARCHAR, Champions VARCHAR, Runner-up VARCHAR, Third Place VARCHAR, Top Goalscorer VARCHAR, Club VARCHAR) CREATE TABLE members_of_the_georgia_state_house_of_representatives_2007-2008 (members_of_the_georgia_state_house_of_representatives_2007-2008_id AUTO_INCREMENT PRIMARY KEY, District INT, Representative VARCHAR, Party VARCHAR, First elected INT, Residence VARCHAR)  
SELECT COUNT Club FROM year_by_year WHERE Third Place = Drnovice