Abaixo está uma instrução que descreve uma tarefa de geração de SQL, combinada com uma entrada que fornece mais contexto sobre os esquemas de tabela disponíveis. Escreva o código SQL que responda adequadamente à solicitação
 ###Instrução: 6ª carreira/salário de consultor de design ($500.000-grau) envolve qual 3ª carreira/salário?
 ###Tabelas: CREATE TABLE careers (careers_id AUTO_INCREMENT PRIMARY KEY, Career Card VARCHAR, Starting career/salary VARCHAR, 2nd career/salary VARCHAR, 3rd career/salary VARCHAR, 4th career/salary VARCHAR, 5th career/salary VARCHAR, 6th career/salary VARCHAR) CREATE TABLE punjab (punjab_id AUTO_INCREMENT PRIMARY KEY, Serial No. INT, District VARCHAR, Headquartered City VARCHAR, City Population (2009) INT, City Area(km 2 ) INT) CREATE TABLE investment_and_financing (investment_and_financing_id AUTO_INCREMENT PRIMARY KEY, Department VARCHAR, Projects INT, Municipalities INT, Farmers INT, Irrigated Ha INT, BID/PRONAR Investment (US$) VARCHAR, Local Investment (US$) VARCHAR, Total VARCHAR) CREATE TABLE all-time_goalscorers (all-time_goalscorers_id AUTO_INCREMENT PRIMARY KEY, Name VARCHAR, Career VARCHAR, Apps INT, Goals INT, Average INT) CREATE TABLE existing_stadiums (existing_stadiums_id AUTO_INCREMENT PRIMARY KEY, Stadium VARCHAR, Capacity VARCHAR, Club VARCHAR, Division VARCHAR, Rank in Respective Divisions VARCHAR)  
SELECT 3rd career/salary FROM careers WHERE 6th career/salary = design consultant ($500,000-degree)