Abaixo está uma instrução que descreve uma tarefa de geração de SQL, combinada com uma entrada que fornece mais contexto sobre os esquemas de tabela disponíveis. Escreva o código SQL que responda adequadamente à solicitação
 ###Instrução: Qual é o valor máximo de 2010 para um valor de intervalo de 1980 de 2.43?
 ###Tabelas: CREATE TABLE per_capita_gdp (per_capita_gdp_id AUTO_INCREMENT PRIMARY KEY, Economy VARCHAR, 1980 INT, Gap from Thailand as of 1980 (times) VARCHAR, 1985 INT, 1990 INT, 1995 INT, 2000 INT, 2005 INT, 2010 INT, 2012 INT, Gap from Thailand as of 2012 (times) VARCHAR, GDP as of 2012 after purchasing power parity (PPP) calculations (USD billions) VARCHAR, GDP per capita as of 2012 (PPP) INT) CREATE TABLE members_of_parliament (members_of_parliament_id AUTO_INCREMENT PRIMARY KEY, Election VARCHAR, 1st Member VARCHAR, 1st Party VARCHAR, 2nd Member VARCHAR, 2nd Party VARCHAR) CREATE TABLE doubles_9_5–4 (doubles_9_5–4_id AUTO_INCREMENT PRIMARY KEY, Outcome VARCHAR, Date VARCHAR, Tournament VARCHAR, Surface VARCHAR, Partner VARCHAR, Opponents VARCHAR, Score VARCHAR) CREATE TABLE table_of_standard_amino_acid_abbreviations_and_properties (table_of_standard_amino_acid_abbreviations_and_properties_id AUTO_INCREMENT PRIMARY KEY, Amino Acid VARCHAR, 3-Letter VARCHAR, 1-Letter VARCHAR, Side-chain polarity VARCHAR, Side-chain charge (pH 7.4) VARCHAR, Hydropathy index VARCHAR) CREATE TABLE 2007_boys'_team (2007_boys'_team_id AUTO_INCREMENT PRIMARY KEY, Player VARCHAR, Height VARCHAR, School VARCHAR, Hometown VARCHAR, College VARCHAR)  
SELECT MAX 2010 FROM per_capita_gdp WHERE Gap from Thailand as of 1980 (times) = 2.43