Abaixo está uma instrução que descreve uma tarefa de geração de SQL, combinada com uma entrada que fornece mais contexto sobre os esquemas de tabela disponíveis. Escreva o código SQL que responda adequadamente à solicitação
 ###Instrução: Exibir os nomes e total de horas de trabalho para os trabalhadores que trabalharam em projetos sustentáveis, ordenados alfabeticamente pelo nome do trabalhador.
 ###Tabelas: 
CREATE TABLE construction_workers (worker_id INT, name TEXT); CREATE TABLE project_types (project_id INT, project_type TEXT); CREATE TABLE worker_projects (worker_id INT, project_id INT, total_labor_hours INT); INSERT INTO construction_workers (worker_id, name) VALUES (1, 'John Doe'), (2, 'Jane Smith'), (3, 'Maria Garcia'), (4, 'Ahmed Patel'), (5, 'Fatima Khan'), (6, 'Raj Patel'), (7, 'Karen Jackson'); INSERT INTO project_types (project_id, project_type) VALUES (1, 'Residential'), (2, 'Commercial'), (3, 'Sustainable'), (4, 'Historical Restoration'), (5, 'Sustainable'), (6, 'Sustainable'), (7, 'Residential'); INSERT INTO worker_projects (worker_id, project_id, total_labor_hours) VALUES (1, 1, 500), (1, 2, 300), (2, 2, 600), (2, 3, 400), (3, 1, 700), (3, 3, 500), (4, 4, 800), (4, 5, 900), (5, 6, 1000), (6, 7, 1100), (7, 3, 1200), (7, 5, 1300);
SELECT construction_workers.name, SUM(worker_projects.total_labor_hours) FROM construction_workers INNER JOIN worker_projects ON construction_workers.worker_id = worker_projects.worker_id INNER JOIN project_types ON worker_projects.project_id = project_types.project_id WHERE project_types.project_type = 'Sustainable' GROUP BY construction_workers.name ORDER BY construction_workers.name ASC;