Abaixo está uma instrução que descreve uma tarefa de geração de SQL, combinada com uma entrada que fornece mais contexto sobre os esquemas de tabela disponíveis. Escreva o código SQL que responda adequadamente à solicitação
 ###Instrução: Quem foi o vencedor da corrida XII Spring Trophy com a BRM como construtor?
 ###Tabelas: CREATE TABLE repechage (repechage_id AUTO_INCREMENT PRIMARY KEY, Rank INT, Rowers VARCHAR, Country VARCHAR, Time VARCHAR, Notes VARCHAR) CREATE TABLE grand_slam_men's_doubles_finals:_20_16–4 (grand_slam_men's_doubles_finals:_20_16–4_id AUTO_INCREMENT PRIMARY KEY, Outcome VARCHAR, Year INT, Championship VARCHAR, Surface VARCHAR, Partner VARCHAR, Opponents VARCHAR, Score VARCHAR) CREATE TABLE non-championship_race_results (non-championship_race_results_id AUTO_INCREMENT PRIMARY KEY, Race Name VARCHAR, Circuit VARCHAR, Date VARCHAR, Winning driver VARCHAR, Constructor VARCHAR, Report VARCHAR) CREATE TABLE -_106_seats (-_106_seats_id AUTO_INCREMENT PRIMARY KEY, Riding VARCHAR, Candidate's Name VARCHAR, Gender VARCHAR, Residence VARCHAR, Occupation VARCHAR, Votes INT, Rank VARCHAR) CREATE TABLE ladies_european_tour_career_summary (ladies_european_tour_career_summary_id AUTO_INCREMENT PRIMARY KEY, Year INT, Tournaments played INT, Cuts made INT, Wins INT, 2nd INT, 3rd INT, Top 10s INT, Best finish VARCHAR, Earnings ( € ) VARCHAR, Money list rank VARCHAR, Scoring average VARCHAR, Scoring rank VARCHAR, Rolex ranking INT)  
SELECT Winning driver FROM non-championship_race_results WHERE Constructor = brm AND Race Name = xii spring trophy