Abaixo está uma instrução que descreve uma tarefa de geração de SQL, combinada com uma entrada que fornece mais contexto sobre os esquemas de tabela disponíveis. Escreva o código SQL que responda adequadamente à solicitação
 ###Instrução: 4ª carreira/salário do navegador ($90.000-grau) envolve qual 3ª carreira/salário?
 ###Tabelas: CREATE TABLE fa_premier_league (fa_premier_league_id AUTO_INCREMENT PRIMARY KEY, Date VARCHAR, Opponents VARCHAR, H / A VARCHAR, Result F – A VARCHAR, Attendance INT, League position VARCHAR) CREATE TABLE careers (careers_id AUTO_INCREMENT PRIMARY KEY, Career Card VARCHAR, Starting career/salary VARCHAR, 2nd career/salary VARCHAR, 3rd career/salary VARCHAR, 4th career/salary VARCHAR, 5th career/salary VARCHAR, 6th career/salary VARCHAR) CREATE TABLE passengers (passengers_id AUTO_INCREMENT PRIMARY KEY, Year INT, Domestic passengers INT, International passengers INT, Total passengers INT, Change VARCHAR) CREATE TABLE notable_villains (notable_villains_id AUTO_INCREMENT PRIMARY KEY, Character VARCHAR, Portrayed by VARCHAR, Crime VARCHAR, First appearance VARCHAR, Last appearance VARCHAR) CREATE TABLE asian_champions_league_appearances (asian_champions_league_appearances_id AUTO_INCREMENT PRIMARY KEY, Date VARCHAR, Venue VARCHAR, Opponent VARCHAR, Score VARCHAR, Result VARCHAR)  
SELECT 3rd career/salary FROM careers WHERE 4th career/salary = navigator ($90,000-degree)