Abaixo está uma instrução que descreve uma tarefa de geração de SQL, combinada com uma entrada que fornece mais contexto sobre os esquemas de tabela disponíveis. Escreva o código SQL que responda adequadamente à solicitação
 ###Instrução: Qual é o Pontos Contra, quando a Diferença de Tentativas é +22?
 ###Tabelas: CREATE TABLE season_7:_1998-1999 (season_7:_1998-1999_id AUTO_INCREMENT PRIMARY KEY, No. in series INT, No. in season INT, Title VARCHAR, Director VARCHAR, Writer(s) VARCHAR, Original air date VARCHAR, Production code VARCHAR) CREATE TABLE monthly_mobile_subscriber_additions (monthly_mobile_subscriber_additions_id AUTO_INCREMENT PRIMARY KEY, Year INT, January INT, February INT, March INT, April INT, June INT, July INT, August INT, September INT, October INT, November INT, December INT, Annual Additions(in millions) INT, Average Monthly Additions(in millions) INT) CREATE TABLE list_of_housing_and_construction_ministers (list_of_housing_and_construction_ministers_id AUTO_INCREMENT PRIMARY KEY, Minister VARCHAR, Party VARCHAR, Governments VARCHAR, Term start VARCHAR, Term end VARCHAR) CREATE TABLE fed_cup_doubles_performances_0–5 (fed_cup_doubles_performances_0–5_id AUTO_INCREMENT PRIMARY KEY, Edition VARCHAR, Round VARCHAR, Date VARCHAR, Partnering VARCHAR, Against VARCHAR, Surface VARCHAR, Opponents VARCHAR, Result VARCHAR) CREATE TABLE pool_1 (pool_1_id AUTO_INCREMENT PRIMARY KEY, Team VARCHAR, Tries for VARCHAR, Tries against VARCHAR, Try diff VARCHAR, Points for VARCHAR, Points against VARCHAR, Points diff VARCHAR)  
SELECT Points against FROM pool_1 WHERE Try diff = +22