Abaixo está uma instrução que descreve uma tarefa de geração de SQL, combinada com uma entrada que fornece mais contexto sobre os esquemas de tabela disponíveis. Escreva o código SQL que responda adequadamente à solicitação
 ###Instrução: Risca RFC tem 54 tentativas a favor e quantos empates?
 ###Tabelas: CREATE TABLE 2006_2007_table (2006_2007_table_id AUTO_INCREMENT PRIMARY KEY, Club VARCHAR, Played VARCHAR, Won VARCHAR, Drawn VARCHAR, Lost VARCHAR, Points for VARCHAR, Points against VARCHAR, Tries for VARCHAR, Points VARCHAR) CREATE TABLE top_markets_2000–2011 (top_markets_2000–2011_id AUTO_INCREMENT PRIMARY KEY, Country or territory VARCHAR, 2000 INT, 2001 INT, 2002 INT, 2003 INT, 2004 INT, 2005 INT, 2006 INT, 2007 INT, 2008 INT, 2009 INT, 2010 INT, 2011 INT) CREATE TABLE 2010_senior_manx_grand_prix_practice_times__&__leaderboard (2010_senior_manx_grand_prix_practice_times__&__leaderboard_id AUTO_INCREMENT PRIMARY KEY, Rank INT, Rider VARCHAR, Sat 21 Aug VARCHAR, Mon 23 Aug VARCHAR, Tues 24 Aug VARCHAR, Wed 25 Aug VARCHAR, Thurs 26 Aug VARCHAR, Fri 27 Aug VARCHAR, Sat 28 Aug VARCHAR) CREATE TABLE development_of_population (development_of_population_id AUTO_INCREMENT PRIMARY KEY, year INT, total INT, German VARCHAR, Romanian VARCHAR, Hungarian VARCHAR, other VARCHAR, of which Romanies (Gypsies) VARCHAR) CREATE TABLE eighthfinals (eighthfinals_id AUTO_INCREMENT PRIMARY KEY, Team #1 VARCHAR, Agg. VARCHAR, Team #2 VARCHAR, 1st leg VARCHAR, 2nd leg VARCHAR)  
SELECT Drawn FROM 2006_2007_table WHERE Tries for = 54