Abaixo está uma instrução que descreve uma tarefa de geração de SQL, combinada com uma entrada que fornece mais contexto sobre os esquemas de tabela disponíveis. Escreva o código SQL que responda adequadamente à solicitação
 ###Instrução: Quantas temporadas na divisão principal para a equipe que terminou em 5º lugar em 2012-2013.
 ###Tabelas: CREATE TABLE islands_under___square_miles__ km_ (islands_under___square_miles__ km__id AUTO_INCREMENT PRIMARY KEY, Island's Name VARCHAR, Area (sq mi) INT, Area (km 2 ) INT, Location VARCHAR, Population (2000) VARCHAR) CREATE TABLE winners_of_the_yugoslavian_motorcycle_grand_prix (winners_of_the_yugoslavian_motorcycle_grand_prix_id AUTO_INCREMENT PRIMARY KEY, Year INT, Track VARCHAR, 250 cc VARCHAR, 500 cc VARCHAR, Report VARCHAR) CREATE TABLE members_for_2013–14 (members_for_2013–14_id AUTO_INCREMENT PRIMARY KEY, Club VARCHAR, Position in 2012–13 VARCHAR, First season in top division VARCHAR, Number of seasons in top division INT, Number of seasons in Prva HNL INT, First season of current spell in top division VARCHAR, Top division titles VARCHAR, Last top division title VARCHAR) CREATE TABLE officially_assigned_code_elements (officially_assigned_code_elements_id AUTO_INCREMENT PRIMARY KEY, English short name (upper/lower case) VARCHAR, Alpha-2 code VARCHAR, Alpha-3 code VARCHAR, Numeric code INT, ISO 3166-2 codes VARCHAR) CREATE TABLE men's (men's_id AUTO_INCREMENT PRIMARY KEY, Skip VARCHAR, Third/Vice skip VARCHAR, Second VARCHAR, Lead VARCHAR, City VARCHAR)  
SELECT COUNT Number of seasons in top division FROM members_for_2013–14 WHERE Position in 2012–13 = 005 5th