Abaixo está uma instrução que descreve uma tarefa de geração de SQL, combinada com uma entrada que fornece mais contexto sobre os esquemas de tabela disponíveis. Escreva o código SQL que responda adequadamente à solicitação
 ###Instrução: Quando as tentativas contra são 90, quantos pontos existem?
 ###Tabelas: CREATE TABLE races_and_results (races_and_results_id AUTO_INCREMENT PRIMARY KEY, District VARCHAR, Incumbent VARCHAR, Party VARCHAR, Elected INT, Status VARCHAR, 2008 Candidates VARCHAR, Results VARCHAR) CREATE TABLE list_of_songs_released_in_2008 (list_of_songs_released_in_2008_id AUTO_INCREMENT PRIMARY KEY, Song title VARCHAR, Artist VARCHAR, Year VARCHAR, Genre VARCHAR, Single / Pack name VARCHAR, Release date VARCHAR, Family Friendly VARCHAR, Additional Rock Band 3 Features VARCHAR) CREATE TABLE 2009_2010_table (2009_2010_table_id AUTO_INCREMENT PRIMARY KEY, Club VARCHAR, Played VARCHAR, Drawn VARCHAR, Lost VARCHAR, Points for VARCHAR, Points against VARCHAR, Tries for VARCHAR, Tries against VARCHAR, Try bonus VARCHAR, Losing bonus VARCHAR, Points VARCHAR) CREATE TABLE 20th_century (20th_century_id AUTO_INCREMENT PRIMARY KEY, Date VARCHAR, Epicenter VARCHAR, Magnitude INT, Fatalities VARCHAR, Name VARCHAR) CREATE TABLE 1910s (1910s_id AUTO_INCREMENT PRIMARY KEY, meas. num INT, passed VARCHAR, YES votes INT, NO votes INT, % YES VARCHAR, Const. Amd.? VARCHAR, type VARCHAR, description VARCHAR)  
SELECT Points FROM 2009_2010_table WHERE Tries against = 90