Abaixo está uma instrução que descreve uma tarefa de geração de SQL, combinada com uma entrada que fornece mais contexto sobre os esquemas de tabela disponíveis. Escreva o código SQL que responda adequadamente à solicitação
 ###Instrução: Qual é a resposta de 1989-90 quando o 2004-05 mostra grp?
 ###Tabelas: CREATE TABLE competition_timeline (competition_timeline_id AUTO_INCREMENT PRIMARY KEY, Competition VARCHAR, 1970–71 VARCHAR, 1971–72 VARCHAR, 1972–73 VARCHAR, 1973–74 VARCHAR, 1974–75 VARCHAR, 1975–76 VARCHAR, 1976–77 VARCHAR, 1977–78 VARCHAR, 1978–79 VARCHAR, 1979–80 VARCHAR, 1980–81 VARCHAR, 1981–82 VARCHAR, 1982–83 VARCHAR, 1983–84 VARCHAR, 1984–85 VARCHAR, 1985–86 VARCHAR, 1986–87 VARCHAR, 1987–88 VARCHAR, 1988–89 VARCHAR, 1989–90 VARCHAR, 1990–91 VARCHAR, 1991–92 VARCHAR, 1992–93 VARCHAR, 1993–94 VARCHAR, 1994–95 VARCHAR, 1995–96 VARCHAR, 1996–97 VARCHAR, 1997–98 VARCHAR, 1998–99 VARCHAR, 1999–00 VARCHAR, 2000–01 VARCHAR, 2001–02 VARCHAR, 2002–03 VARCHAR, 2003–04 VARCHAR, 2004–05 VARCHAR, 2005–06 VARCHAR, 2006–07 VARCHAR, 2007–08 VARCHAR, 2008–09 VARCHAR, 2009–10 VARCHAR, 2010–11 VARCHAR, 2011–12 VARCHAR) CREATE TABLE heat_2 (heat_2_id AUTO_INCREMENT PRIMARY KEY, Rank INT, Athletes VARCHAR, Country VARCHAR, Time VARCHAR, Notes VARCHAR) CREATE TABLE by_access_to_electricity (by_access_to_electricity_id AUTO_INCREMENT PRIMARY KEY, Region VARCHAR, Public network VARCHAR, Own/community generator VARCHAR, Solar panel VARCHAR, Other source VARCHAR, None VARCHAR) CREATE TABLE other_appearances_in_tour_de_france (other_appearances_in_tour_de_france_id AUTO_INCREMENT PRIMARY KEY, Year INT, Stage INT, Category VARCHAR, Start VARCHAR, Finish VARCHAR, Leader at the summit VARCHAR) CREATE TABLE results_pool_a (results_pool_a_id AUTO_INCREMENT PRIMARY KEY, Date VARCHAR, Score VARCHAR, Set 1 VARCHAR, Set 2 VARCHAR, Set 3 VARCHAR, Set 4 VARCHAR, Set 5 VARCHAR, Total VARCHAR)  
SELECT 1989–90 FROM competition_timeline WHERE 2004–05 = grp