Abaixo está uma instrução que descreve uma tarefa de geração de SQL, combinada com uma entrada que fornece mais contexto sobre os esquemas de tabela disponíveis. Escreva o código SQL que responda adequadamente à solicitação
 ###Instrução: Nomeie os pontos contra para o cwmllynfell rfc
 ###Tabelas: CREATE TABLE all-time_top_scorers (all-time_top_scorers_id AUTO_INCREMENT PRIMARY KEY, Rank INT, Player VARCHAR, Goals INT, Apps INT, Rate INT) CREATE TABLE 2010_2011_table (2010_2011_table_id AUTO_INCREMENT PRIMARY KEY, Club VARCHAR, Played VARCHAR, Drawn VARCHAR, Lost VARCHAR, Points for VARCHAR, Points against VARCHAR, Tries for VARCHAR, Tries against VARCHAR, Try bonus VARCHAR, Losing bonus VARCHAR, Points VARCHAR) CREATE TABLE singles_wins_5 (singles_wins_5_id AUTO_INCREMENT PRIMARY KEY, Date VARCHAR, Tournament VARCHAR, Surface VARCHAR, Opponent in the final VARCHAR, Score VARCHAR) CREATE TABLE appliances (appliances_id AUTO_INCREMENT PRIMARY KEY, Name VARCHAR, Processor VARCHAR, Hard Drive VARCHAR, Ethernet Ports VARCHAR, Dimensions VARCHAR) CREATE TABLE comparison_of_toy_group_breeds_of_major_kennel_clubs (comparison_of_toy_group_breeds_of_major_kennel_clubs_id AUTO_INCREMENT PRIMARY KEY, The Kennel Club (UK) Toy Group VARCHAR, Canadian Kennel Club Toy Dogs Group VARCHAR, American Kennel Club Toy Group VARCHAR, Australian National Kennel Council Toy Dogs Group VARCHAR, New Zealand Kennel Club Toy Group VARCHAR)  
SELECT Points against FROM 2010_2011_table WHERE Club = cwmllynfell rfc