Abaixo está uma instrução que descreve uma tarefa de geração de SQL, combinada com uma entrada que fornece mais contexto sobre os esquemas de tabela disponíveis. Escreva o código SQL que responda adequadamente à solicitação
 ###Instrução: Quantas vezes o prêmio inte awards foi concedido?
 ###Tabelas: CREATE TABLE setting_the_nba_finals'_3pt_record (setting_the_nba_finals'_3pt_record_id AUTO_INCREMENT PRIMARY KEY, Game INT, 3PM-A VARCHAR, Percent Made INT, Total Made INT, Total Attempted INT, Series Percent INT) CREATE TABLE north_dakota_counties_by_per_capita_income (north_dakota_counties_by_per_capita_income_id AUTO_INCREMENT PRIMARY KEY, County VARCHAR, Per capita income VARCHAR, Median household income VARCHAR, Median family income VARCHAR, Population INT, Number of households INT) CREATE TABLE awards_and_nominations (awards_and_nominations_id AUTO_INCREMENT PRIMARY KEY, Award VARCHAR, Year INT, Category VARCHAR, Work VARCHAR, Result VARCHAR) CREATE TABLE "sandy_bridge_dual-core"_32_nm ("sandy_bridge_dual-core"_32_nm_id AUTO_INCREMENT PRIMARY KEY, Model number VARCHAR, sSpec number VARCHAR, Cores VARCHAR, Frequency VARCHAR, Turbo VARCHAR, L2 cache VARCHAR, L3 cache VARCHAR, GPU model VARCHAR, GPU frequency VARCHAR, Socket VARCHAR, I/O bus VARCHAR, Release date VARCHAR, Part number(s) VARCHAR, Release price ( USD ) VARCHAR) CREATE TABLE operating_performance (operating_performance_id AUTO_INCREMENT PRIMARY KEY, Year ended VARCHAR, Passengers (thousand) INT, RPK (million) INT, ASK (million) INT, Load factor (%) INT, Yield (S¢/km) INT)  
SELECT COUNT Year FROM awards_and_nominations WHERE Award = inte awards