Abaixo está uma instrução que descreve uma tarefa de geração de SQL, combinada com uma entrada que fornece mais contexto sobre os esquemas de tabela disponíveis. Escreva o código SQL que responda adequadamente à solicitação
 ###Instrução: E se o clube tivesse 431 pontos contra eles?
 ###Tabelas: CREATE TABLE 2008_2009_table (2008_2009_table_id AUTO_INCREMENT PRIMARY KEY, Club VARCHAR, Played VARCHAR, Drawn VARCHAR, Lost VARCHAR, Points for VARCHAR, Points against VARCHAR, Tries for VARCHAR, Tries against VARCHAR, Try bonus VARCHAR, Losing bonus VARCHAR, Points VARCHAR) CREATE TABLE head_quarters_and_support_regiments (head_quarters_and_support_regiments_id AUTO_INCREMENT PRIMARY KEY, Unit VARCHAR, Complement VARCHAR, Killed VARCHAR, Wounded VARCHAR, Missing VARCHAR) CREATE TABLE 3601–3700 (3601–3700_id AUTO_INCREMENT PRIMARY KEY, NGC number INT, Object type VARCHAR, Constellation VARCHAR, Right ascension ( J2000 ) VARCHAR, Declination ( J2000 ) VARCHAR, Apparent magnitude INT) CREATE TABLE league_table (league_table_id AUTO_INCREMENT PRIMARY KEY, Club VARCHAR, Played VARCHAR, Drawn VARCHAR, Lost VARCHAR, Points for VARCHAR, Points against VARCHAR, Points difference VARCHAR, Bonus Points VARCHAR, Points VARCHAR) CREATE TABLE season_4:_1995-1996 (season_4:_1995-1996_id AUTO_INCREMENT PRIMARY KEY, No. in series INT, No. in season INT, Title VARCHAR, Director VARCHAR, Writer(s) VARCHAR, Original air date VARCHAR, Production code VARCHAR)  
SELECT Club FROM league_table WHERE Points against = 431