Abaixo está uma instrução que descreve uma tarefa de geração de SQL, combinada com uma entrada que fornece mais contexto sobre os esquemas de tabela disponíveis. Escreva o código SQL que responda adequadamente à solicitação
 ###Instrução: Qual 2003 tem um 2012 de 1–4?
 ###Tabelas: CREATE TABLE college_career (college_career_id AUTO_INCREMENT PRIMARY KEY, Rank INT, Name VARCHAR, Attempts INT, Net Yds INT, Yds/Att INT, Year INT) CREATE TABLE league_table (league_table_id AUTO_INCREMENT PRIMARY KEY, Club VARCHAR, Played VARCHAR, Drawn VARCHAR, Lost VARCHAR, Points for VARCHAR, Points against VARCHAR, Tries for VARCHAR, Tries against VARCHAR, Try bonus VARCHAR, Losing bonus VARCHAR, Points VARCHAR) CREATE TABLE grand_slam_men's_doubles_performance_timeline (grand_slam_men's_doubles_performance_timeline_id AUTO_INCREMENT PRIMARY KEY, Tournament VARCHAR, 1998 VARCHAR, 1999 VARCHAR, 2001 VARCHAR, 2002 VARCHAR, 2003 VARCHAR, 2004 VARCHAR, 2005 VARCHAR, 2006 VARCHAR, 2007 VARCHAR, 2008 VARCHAR, 2009 VARCHAR, 2010 VARCHAR, 2011 VARCHAR, 2012 VARCHAR, Career SR VARCHAR, Career Win-Loss VARCHAR) CREATE TABLE ___group (___group_id AUTO_INCREMENT PRIMARY KEY, Species VARCHAR, Strain VARCHAR, Type VARCHAR, Base Pairs INT, Genes INT) CREATE TABLE buildings_above_140m (buildings_above_140m_id AUTO_INCREMENT PRIMARY KEY, Rank VARCHAR, Name VARCHAR, City VARCHAR, Height in m (ft) VARCHAR, Floors INT, Year built INT)  
SELECT 2003 FROM grand_slam_men's_doubles_performance_timeline WHERE 2012 = 1–4