Abaixo está uma instrução que descreve uma tarefa de geração de SQL, combinada com uma entrada que fornece mais contexto sobre os esquemas de tabela disponíveis. Escreva o código SQL que responda adequadamente à solicitação
 ###Instrução: Qual AVE-No tem um Nome de livigno alps?
 ###Tabelas: CREATE TABLE title_holders_from_2000_until_2010 (title_holders_from_2000_until_2010_id AUTO_INCREMENT PRIMARY KEY, Year INT, Miss Universe Philippines VARCHAR, Binibining Pilipinas-World VARCHAR, Binibining Pilipinas-International VARCHAR, Binibining Pilipinas-Tourism VARCHAR, First runner-up VARCHAR, Second runner-up VARCHAR) CREATE TABLE populations (populations_id AUTO_INCREMENT PRIMARY KEY, Country VARCHAR, Orphans as % of all Children INT, AIDS Orphans as % of Orphans INT, Total Orphans (Total) INT, Total Orphans (AIDS Related) VARCHAR, Maternal (Total) INT, Maternal (AIDS Related) VARCHAR, Paternal (Total) INT, Paternal (AIDS Related) VARCHAR, Double (Total) INT, Double (AIDS Related) VARCHAR) CREATE TABLE pre-season_organization (pre-season_organization_id AUTO_INCREMENT PRIMARY KEY, Team VARCHAR, Location VARCHAR, Venue VARCHAR, League and position in 1991 VARCHAR, Coach VARCHAR) CREATE TABLE 2006_regular_season_football_standings (2006_regular_season_football_standings_id AUTO_INCREMENT PRIMARY KEY, School VARCHAR, Team VARCHAR, Division Record VARCHAR, Overall Record VARCHAR, Season Outcome VARCHAR) CREATE TABLE alpine_club_classification (alpine_club_classification_id AUTO_INCREMENT PRIMARY KEY, AVE- No. INT, Name VARCHAR, Country VARCHAR, Highest mountain VARCHAR, Height (m) INT)  
SELECT MIN AVE- No. FROM alpine_club_classification WHERE Name = livigno alps