Abaixo está uma instrução que descreve uma tarefa de geração de SQL, combinada com uma entrada que fornece mais contexto sobre os esquemas de tabela disponíveis. Escreva o código SQL que responda adequadamente à solicitação
 ###Instrução: Nomeie o nome para 14.5 2013 rev
 ###Tabelas: CREATE TABLE fire_station_locations_and_apparatus (fire_station_locations_and_apparatus_id AUTO_INCREMENT PRIMARY KEY, Station VARCHAR, Engine Company VARCHAR, Ambulance VARCHAR, Address VARCHAR, Phone VARCHAR) CREATE TABLE supplemental_first_round_selections (supplemental_first_round_selections_id AUTO_INCREMENT PRIMARY KEY, Pick INT, Player VARCHAR, Team VARCHAR, Position VARCHAR, Hometown/School VARCHAR) CREATE TABLE singles:_6_2_titles_4_runner-ups (singles:_6_2_titles_4_runner-ups_id AUTO_INCREMENT PRIMARY KEY, Outcome VARCHAR, Year INT, Championship VARCHAR, Surface VARCHAR, Opponent in the final VARCHAR, Score in the final VARCHAR) CREATE TABLE forbes_global_2000 (forbes_global_2000_id AUTO_INCREMENT PRIMARY KEY, April 2013 Cum. Rank INT, Name VARCHAR, Rank 2012 INT, Rank 2013 INT, Base VARCHAR, 2013 rev (bil. USD ) VARCHAR, 2013 Profit (mil. USD ) VARCHAR, Assets 2013 (bil.$) VARCHAR, Market cap March 15 (mil.$) INT) CREATE TABLE values (values_id AUTO_INCREMENT PRIMARY KEY, Constellation VARCHAR, Largest component, fractional share INT, Other components, fractional shares VARCHAR, N, Laakso-Taagepera INT, N, Golosov INT)  
SELECT Name FROM forbes_global_2000 WHERE 2013 rev (bil. USD ) = 14.5