Abaixo está uma instrução que descreve uma tarefa de geração de SQL, combinada com uma entrada que fornece mais contexto sobre os esquemas de tabela disponíveis. Escreva o código SQL que responda adequadamente à solicitação
 ###Instrução: Qual são todos os u16 2º viii com u15 3º iv sendo bbc
 ###Tabelas: CREATE TABLE 2013-2014_teams (2013-2014_teams_id AUTO_INCREMENT PRIMARY KEY, School VARCHAR, Location VARCHAR, Founded INT, Affiliation VARCHAR, Nickname VARCHAR) CREATE TABLE aerial_victories (aerial_victories_id AUTO_INCREMENT PRIMARY KEY, Date VARCHAR, Unit INT, Aircraft VARCHAR, Opponent VARCHAR, Location VARCHAR) CREATE TABLE club_statistics (club_statistics_id AUTO_INCREMENT PRIMARY KEY, Name VARCHAR, Season VARCHAR, Games VARCHAR, Goals VARCHAR, Assists VARCHAR, Points VARCHAR) CREATE TABLE winning_head_of_the_river_championship_events (winning_head_of_the_river_championship_events_id AUTO_INCREMENT PRIMARY KEY, Crew INT, Open 1st VIII VARCHAR, Open 2nd VIII VARCHAR, Open 3rd VIII VARCHAR, U16 1st VIII VARCHAR, U16 2nd VIII VARCHAR, U16 3rd VIII VARCHAR, U15 1st IV VARCHAR, U15 2nd IV VARCHAR, U15 3rd IV VARCHAR, U15 4th IV VARCHAR, U15 5th IV VARCHAR, U15 6th IV VARCHAR) CREATE TABLE vocabulary_comparison (vocabulary_comparison_id AUTO_INCREMENT PRIMARY KEY, English VARCHAR, Scots VARCHAR, West Frisian VARCHAR, Afrikaans VARCHAR, Dutch VARCHAR, Dutch ( Limburgish ) VARCHAR, Low German VARCHAR, Low German ( Groningen ) VARCHAR, Middle German ( Luxemburgish ) VARCHAR, German VARCHAR, Yiddish VARCHAR, Gothic VARCHAR)  
SELECT U16 2nd VIII FROM winning_head_of_the_river_championship_events WHERE U15 3rd IV = BBC