The "photoelectrons" emitted as a result of the photoelectric effect have a certain kinetic energy, which can be measured. This kinetic energy (for each photoelectron) is independent of the intensity of the light, but depends linearly on the frequency; and if the frequency is too low (corresponding to a photon energy that is less than the work function of the material), no photoelectrons are emitted at all, unless a plurality of photons, whose energetic sum is greater than the energy of the photoelectrons, acts virtually simultaneously (multiphoton effect)  Assuming the frequency is high enough to cause the photoelectric effect, a rise in intensity of the light source causes more photoelectrons to be emitted with the same kinetic energy, rather than the same number of photoelectrons to be emitted with higher kinetic energy. COUNT 8
QSN1 What is emitted as a result of the photoelectric effect? ANS1 photoelectrons QSN2 What does the kinetic energy of a photoelectron depend on? ANS2 the frequency QSN3 What happens if the photoelectron's frequency is too low? ANS3 no photoelectrons are emitted at all QSN4 What is the term used when photoelectrons act virtually at the same time? ANS4 multiphoton effect QSN5 What type of energy due photoelectrons emitted due to the photoelectric effect have? ANS5 kinetic QSN6 What factor of the initial light source does the energy of the photoelectrons depend on? ANS6 frequency QSN7 When the photon energy is less than the work function of the material the light is shone upon, how many photoelectrons are emitted? ANS7 no photoelectrons are emitted at all QSN8 If the photoelectric effect is occuring, increasing the intensity of the light source causes what? ANS8 more photoelectrons to be emitted with the same kinetic energy