
In Ref. [1]} we have calculated the \(\pi ^2\)  contributions to \(\bar{d}_5^{\nu ^2}\)  and
\(a_6^{\nu ^2}\)  which read
\(\bar{d}_5^{\pi ^2 \nu ^2} &=&\frac{306545}{512} \pi ^2 \nu ^2,\\a_6^{\pi ^2 \nu ^2} &=& \frac{25911}{256} \pi ^2 \nu ^2.\) 
