In the two lower parts of fig. 2 the resulting two-boson density and the
boson-exchange potential (REF ) are shown in
r- and Q-spaceIn Q-space multiplied by \(Q^2\) . for solution 4
in the tables, both in very good agreement.
In the Fourier transformation to Q-space the process
\(gg\rightarrow q\bar{q}\)  is elastic and consequently the
created \(q\bar{q}\) -pair has no mass. However, if we take a finite mass
of the created fermions of 1.4 GeV (such a mass has been assumed for a
comparable system in potential models [1]}), a boson-exchange
potential is obtained (given by the dashed line in the lower part of
fig. 2), which cannot be consistent with the density \(\rho (r)\) .
Thus, our solutions require massless fermions. This allows to
relate the generated system to the absolute vacuum of fluctuating
boson fields with energy \(E_{vac}=0\) .
