and \(\bar{X}^{(n)}=\lbrace \bar{X}^{(n)}(t):t \ge 0\rbrace \) , where \(\bar{X}^{(n)}(t)=x(X^{(n)}(t))\)  \((t \ge 0)\) . Thus \(\bar{X}^{(n)}\)  corresponds to the process with the same notation in Theorem REF . (To ease notation we have not indexed \(x\)  by \(n\) . To aid connection with [1]}, the 4-dimensional vector \(\bar{X}^{(n)}(t)\)  is rendered in bold and the infinite-dimensional vector \(X^{(n)}(t)\)  is not.)
