On the other hand, the \(B^0 \rightarrow K^0 X(3872)\)  decay can also proceed via the following processes: in the first step the anti-bottom quark in the \(B^0\)  meson turns into an anti-charm quark and a \(\bar{s} c\)  pair via the \(W\) -external emission diagram, which is, in general, the dominant term of the weak decays [1]}. The next step consists in introducing a pair of sea quarks \(d\bar{d}\)  with the quantum numbers of the vacuum, to form a \(K^0\)  and a \(D^+\)  (or \(D^{*+}\) ) with the \(\bar{s}c\)  pair. While the \(\bar{c}\)  and \(d\)  quark from the \(B^0\)  meson will be hadronized into a \(D^{*-}\)  (or \(D^-\) ) meson. These above processes are shown in Fig. REF  (a). Finally, the final-state interactions of the \(D^+ D^{*-}\)  and \(D^{*+}D^-\)  will lead to the production of the \(X(3872)\)  resonance, as shown in Fig. REF  (b).
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