see e.g. [1]}, chapters 1,2; we conclude following that for all the sufficiently greatest positive values of
the constant \( \ K > 0 \ \)
\(\int _X N[T](|f(x)|/K) \ \mu (dx) \le \int _0^{\infty } N[T](t/K) |dT(t)| =\) 
\(\int _0^{\infty } \frac{|dT(t)|}{T(t/K)} < \infty , \hspace{8.53581pt} K > k;\) 
