where the Hadamard product [1]} is denoted by \(\circ \)  and the vector \(v=(A\circ W)u\) . The
corresponding solution of (REF ) is [2]}
\(x(t^{\ast })=e^{(A\circ W-\text{diag}((A\circ W)u))t^{\ast }}x(0)\) 
