When \(\xi \)  has finite variance, [1]} (see in particular the second paragraph after its statement) gives (REF ) with \(\sqrt{\mathrm {Var}(\xi ^{(b_{n})})}\)  instead of \(v_{n}\) , and the estimate (REF ) yields \(v_{n} \sim \sqrt{n \mathrm {Var}(\xi ^{(b_{n})})}\) .
