On using this \(\tilde{\phi }_{con,A,B}(x)\)  in Eq. (REF ), we get the well
known trigonometric Scarf potential [1]}
\(\tilde{V}^{(1)}(x)\longrightarrow \tilde{V}^{(1)}_{con}(x,A,B) = [(A-1)A+B^{2}]\sec ^{2}{x}-B(2A-1)\sec {x}\tan {x}-A^{2}.\) 
