where \(\zeta _0\)  is determined from the energy conservation equation.
Using \(\zeta _0 = 1.17\)  for ideal gas (\(\gamma = 5/3\) )
[1]},
\(R_s\) , the temperature \(T\) , and the shock velocity \(v_s\)  are written as
\(R_s &=& 5.0{\left(\frac{E_{51}}{n_0} \right)}^{1/5}t_3{}^{2/5}\ \ {\rm (pc)}\ \ ,\\T_s &=& 1.5\times 10^{10}\left(\frac{E_{51}}{n_0}\right)R_s^{-3}\ \ {\rm (K)}\\&=& 1.2\times 10^8 \times {\left(\frac{E_{51}}{n_0}\right)}^{2/5}t_3{}^{-6/5}\ \ {\rm (K)}\ \ ,\\v_s &=& \frac{dR_s}{dt} = 2.1\times 10^8 \times {\left(\frac{E_{51}}{n_0}\right)}^{1/5}t_3{}^{-3/5}\ \ {\rm (cm\ s^{-1})}\ \ ,\) 
