
which is parallel to Eq.(27) in [1]} with a major difference that here, the anisotropic factor is dependent also on the curvature emendations appearing due to alteration in the action integral.
From above equation, it is worth-noticing that mainly three factors are responsible for compelling the system to withdraw isotropic pressure condition. The first one being the effect of Weyl tensor, second being the shear force of the fluid flow and last term being the dissipative factor keeping in mind the consequences of Palatini \(f(R)\)  gravity denoted by \(\vartheta _1\) . We express the Weyl tensor in the above-mentioned equation in terms of fluid variables using Eq. (REF ) and reattain Eq. (REF ) as
\(\nonumber \Pi \dot{\hat{R}}&=\frac{f_R}{2\hat{R}^2}\frac{\partial }{\partial t}\int _0^{\hat{R}}\left(\frac{\mu }{f_R}\right)^{\prime }\hat{R}^3d\hat{R}-\frac{3f_R}{2\hat{R}^2}\int _0^{\hat{R}}\left(\frac{qUB\hat{R}^2}{f_R}+\frac{\zeta _1\hat{R}^{\prime }}{4\pi f_R}\right)d\hat{R}\\ &-\frac{\hat{R}f_R}{8\pi }\frac{\partial }{\partial t}(\zeta _2-\zeta _3)+\frac{(\mu +P_r)A\sigma \hat{R}}{2}-\frac{\hat{R}f_R\Psi _{diss}}{8\pi }-\frac{\vartheta _1\hat{R}f_R}{8\pi }.\) 
