At least randomly, such a \(z\)  can be easily found. In [1]},
alternatively to satisfying enum:deranditemi it was shown
that by choosing \(z^{\prime } \in {\pm 1}^n\)  by majority vote, i.e.
\(z^{\prime }_i = \operatornamewithlimits{\arg \!\max }_{b \in {\pm 1}} \operatornamewithlimits{\mathbb {P}}[\mathbf {Z}_i = b]\) 
