We prove now that the cohomology class of \(\bar{R}_{2k}\)  is the same for different \(E\) -linear connections on \(A\) . In order to prove this, we consider the skew algebroid product \(\tilde{E}=E\times T{\mathbb {R}}\) , as in the classical way for Lie algebroids [1]} and for differentiable manifolds in [2]} and the induced vector bundle \(\tilde{A}\)  over \(M\times {\mathbb {R}}\) . Every two \(E\) -linear connections \(\nabla ^{(1)}\)  and \(\nabla ^{(2)}\)  on \(A\)  gives rise to a \(\tilde{E}\) -linear connection \(\tilde{\nabla }\)  on \(\tilde{A}\) , by \(\tilde{\nabla }_{X}s=(1-t) \nabla _{X}^{(1)}s+t\nabla _{X}^{(2)}s\)  and \(\tilde{\nabla }_{\frac{\partial }{\partial t}}s=0\) , \(\forall \, X\in \Gamma (E)\)  and \(s\in \Gamma (A) \) . Considering the morphisms of almost Lie algebroids \(\tilde{I}_{u}=(i_{u},I_{u})\) , where \(i_{u}\colon M\rightarrow M\times {\mathbb {R}}\)  and \(I_{u}\colon E\rightarrow \tilde{E}\) , \(u=0,1\) , \(i_{u} ( x ) =(x,u)\) , \(I_{u}(e)=(e,u)\) . The vector bundles \(i_{u}^{\ast }E\)  are canonically isomorphic with \(E\)  and the restrictions of \(\tilde{\nabla }\)  to \(i_{u}^{\ast }E\)  coincides with \(\nabla \) . More, concerning the curvatures \(R^{(u)}\)  of the two linear \(E\) -connections and the curvature \(\tilde{R}\) , the restrictions \(\tilde{I}_{u}^{\ast }\)  of the curvature tensors are \(\tilde{I}_{u}^{\ast }\tilde{R}=R^{(u)}\) , \(u=0,1\) . Thus \(\tilde{I}_{u}^{\ast }\tilde{R}^{k}=\big ( R^{(u)}\big ) ^{k}\) .
