Now, it is assumed that those conditional probabilities follow the Gaussian process \(\mathcal {N}(\mu _{0,1}, \mathbf {\sigma ^{2}})\)  with the same variance \(\sigma \)  [1]} and means \(\mu _{1}\)  and \(\mu _{0}\) , respectively for the two abnormal and intact cases, we have:
\(\begin{split}P(x_{ij}|EV_{0,1}) = \frac{1}{\mathbf {\sigma }\sqrt{2\pi }} \exp \left[-\frac{(x_{ij}-\mu _{0,1})^{2}}{2\mathbf {\sigma }^{2}}\right],\end{split}\) 
