The relation between \(V_0(r)\)  and \(V_1(r)\)  and the potentials appearing in Eqs. (REF ) and (REF ) was derived in Ref. [1]} and is given by
\(\hspace{-19.91684pt} & & V_{\bar{Q}Q}(r) =\cos ^2(\theta (r))V_0(r) +\sin ^2(\theta (r))V_1(r) \\\hspace{-19.91684pt} & & V_{\bar{M}M, \parallel }(r) =\sin ^2(\theta (r))V_0(r) +\cos ^2(\theta (r))V_1(r) \\\hspace{-19.91684pt} & & V_{\text{mix}}(r) =\cos (\theta (r))\sin (\theta (r))\Big (V_0(r) +V_1(r)\Big ) \\\hspace{-19.91684pt} & & V_{\bar{M}M, \perp }(r) = 0.\) 
