In order to exemplify the comparison with [1]}, we consider the north pole contribution of \(_{\mathrm {eq},H}(E^\bullet _1,\eth _1)\) . The corresponding contribution in [1]} is given by:
\(\left[\frac{1}{1-t_1t_2^{-1}}\right]^+\left[\frac{1}{1-t_1^{-1}t_2^{-1}}\right]^+ +\left[\frac{1}{1-t_1^{-1}t_2}\right]^-\left[\frac{1}{1-t_1 t_2}\right]^-.\) 
