The digamma functions appearing in the expressions are easily calculated using the formulas [1]}:
\(\psi \Big (\frac{1}{2}-n\Big )=\sum _{k=1}^n\frac{2}{2k-1}-\ln 4-\gamma ,\qquad \psi (1+n)=\sum _{k=1}^n\frac{1}{k}-\gamma .\) 
