The \(M_s\)  = 0.32 \(\mu _B\) /f.u., obtained from the extrapolation of a linear fit of the high \(H\)  data (\(>\)  80 kOe), as well as the \(M\)  = 0.56 \(\mu _B\) /f.u. at \(H\)  = 90 kOe (see Table REF ), are far below the value expected for a simple linear AFM coupling between two FM sublattices in Ir and Co/Fe sites, even considering the \(\sim \) 10% of ASD. As aforementioned, NPD studies of La\(_{2-x}\) Sr\(_x\) CoIrO\(_6\)  indicated that Co and Ir form two AFM sublattices [1]}, [2]}. Assuming a similar scenario here, i.e. an AFM sublattice for Ir and another for Fe/Co, the Ir\(^{4+}\)  magnetic moments (here considered simply as \(J\)  = 1/2) would cancel. However, the AFM coupling between Fe\(^{3+}\)  (S = 5/2) and Co\(^{2+}\)  (S = 3/2) would not compensate, resulting in FIM behavior. Taking into account that we have 0.5 of Fe\(^{3+}\)  and 0.5 of Co\(^{2+}\)  per formula unit, the difference between the moments yields \(M\)  = 1.0 \(\mu _B\) /f.u., somewhat larger than \(M_s\)  and \(M(90 kOe)\) . Applying the usual formula to compute the decrease in \(M\)  due to the ASD [3]}, [4]}
\(M = M_{exp}\times (1-2ASD), \) 
