For instance, in [1]} the following parameters are given for the full decoding at the hardest rate \(\frac{k}{n} = 0.46\) :

\(& & \frac{\ell _1}{n} & = 0.0366 & \frac{\ell _2}{n} & = 0.0547 & \frac{\ell _3}{n} &= 0.0911 & \frac{\ell _4}{n} &= 0.3576 \\\frac{p_1}{n} &= 0.00559 & \frac{w_1^{(1)}}{n} &= 0.011515 & & & & & & \\\frac{p_2}{n} &= 0.01073 & \frac{w_1^{(2)}}{n} &=0.023029 & \frac{w_2^{(2)}}{n} &= 0.016676 & & & & \\\frac{p_3}{n} &= 0.02029 & \frac{w_1^{(3)}}{n} &= 0.0232 & \frac{w_2^{(3)}}{n} &=0.033351 & \frac{w_3^{(3)}}{n} &= 0.009993 & & \\\frac{p_4}{n} &= 0.03460& \frac{w_1^{(4)}}{n} &= 0.0066 & \frac{w_2^{(4)}}{n} &= 0.0099 & \frac{w_3^{(4)}}{n} &= 0.0114 & w_4^{(4)}&=0.0612\) 
