For the Von Neumman measurement [1]}, we keep the initial state of spin 1, expressed as \((a_1|0\rangle ^1 + b_1|1\rangle ^1)\psi ^1(x_1)\)  in the old theory and \(\lbrace a_1\psi _0^1(x), b_1\psi _1^1(x)\rbrace \)  in the new, but set the initial state of spin 2 to the `ready' state \(|0\rangle ^2\psi ^2(x_2)\) , meaning the we have only one spatial wavefunction \(\psi _0^2(x)\)  for spin 2 in this basis (\(a_2 =1\) , \(b_2 =0\) ).
