The \(1/N_c\)  expansion of the operator that yields the baryon magnetic moment operator, in consequence, becomes [1]}
\(M^{kc} = m_1 G^{kc} + \frac{1}{N_c} m_2 \mathcal {D}_2^{kc} + \frac{1}{N_c^2} m_3 \mathcal {D}_3^{kc} + \frac{1}{N_c^2} m_4 \mathcal {O}_3^{kc}, \) 
