where \(r_0\)  is an infrared scale. To perform the Fourier transforms we used Eq.(REF ) and the following formulas, that can be found in [1]}, [2]}:
\(\int \frac{d^3\mathbf {q}}{(2\pi )^3}e^{i\mathbf {q}\cdot \mathbf {r}}\log (\mathbf {q}^2)=-\frac{1}{2\pi r^3}\ , \qquad \int \frac{d^3\mathbf {q}}{(2\pi )^3}e^{i\mathbf {q}\cdot \mathbf {r}}\log ^2 \biggl (\frac{\mathbf {q}^2}{\mu ^2}\biggr )=\frac{2}{\pi r^3}\log \biggl (\frac{r}{r_0}\biggr ) \ .\) 
