Now we use the formula in Section 5 of [1]} to pin down the number of strings in \(\widehat{E_{7(-5)}}^d\) .
We compute that
\(&N([0,1,2,4,5,6])=1, \quad N([0,1,2,3,5,6])=8, \quad N([0,1,3,4,5,6])=11, \\&N([0,1,2,3,4,6])=15, \quad N([0,2,3,4,5,6])=54, \quad N([1,2,3,4,5,6])=83,\\&N([0,1,2,3,4,5])=97.\) 
