#include <bits/stdc++.h>
using namespace std;
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  int test;
  cin >> test;
  while (test--) {
    string s;
    cin >> s;
    if (s.length() % 2 == 0) {
      bool check = true;
      int i = 0;
      int j = s.length() / 2;
      int n = s.length() / 2;
      while (n) {
        if (s[i] != s[j]) {
          check = false;
        }
        i++;
        j++;
        n--;
      }
      if (check) {
        cout << "YES" << endl;
      } else {
        cout << "NO" << endl;
      }
    } else {
      cout << "NO" << endl;
    }
  }
  return 0;
}

### Prompt

Construct a Cpp code solution to the problem outlined:

A string is called square if it is some string written twice in a row. For example, the strings "aa", "abcabc", "abab" and "baabaa" are square. But the strings "aaa", "abaaab" and "abcdabc" are not square.

For a given string s determine if it is square.

Input

The first line of input data contains an integer t (1 ≤ t ≤ 100) —the number of test cases.

This is followed by t lines, each containing a description of one test case. The given strings consist only of lowercase Latin letters and have lengths between 1 and 100 inclusive.

Output

For each test case, output on a separate line:

  * YES if the string in the corresponding test case is square, 
  * NO otherwise. 



You can output YES and NO in any case (for example, strings yEs, yes, Yes and YES will be recognized as a positive response).

Example

Input


10
a
aa
aaa
aaaa
abab
abcabc
abacaba
xxyy
xyyx
xyxy


Output


NO
YES
NO
YES
YES
YES
NO
NO
NO
YES

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  int test;
  cin >> test;
  while (test--) {
    string s;
    cin >> s;
    if (s.length() % 2 == 0) {
      bool check = true;
      int i = 0;
      int j = s.length() / 2;
      int n = s.length() / 2;
      while (n) {
        if (s[i] != s[j]) {
          check = false;
        }
        i++;
        j++;
        n--;
      }
      if (check) {
        cout << "YES" << endl;
      } else {
        cout << "NO" << endl;
      }
    } else {
      cout << "NO" << endl;
    }
  }
  return 0;
}

```