#include <bits/stdc++.h>
using namespace std;
void solution() {
  long long int n, m, a, b, c, d, p, q, cnt = 0, ct = 0, sum = 0, ans = 0;
  string st;
  cin >> st;
  long long int sz = st.size();
  if (sz % 2 == 1)
    cout << "NO" << endl;
  else {
    string s1, s2;
    for (long long int i = 0; i < sz / 2; i++) s1 += st[i];
    for (long long int i = sz / 2; i < sz; i++) s2 += st[i];
    if (s1 == s2)
      cout << "YES" << endl;
    else
      cout << "NO" << endl;
  }
}
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  cout.tie(NULL);
  int t;
  cin >> t;
  while (t--) solution();
  return 0;
}

### Prompt

Please formulate a CPP solution to the following problem:

A string is called square if it is some string written twice in a row. For example, the strings "aa", "abcabc", "abab" and "baabaa" are square. But the strings "aaa", "abaaab" and "abcdabc" are not square.

For a given string s determine if it is square.

Input

The first line of input data contains an integer t (1 ≤ t ≤ 100) —the number of test cases.

This is followed by t lines, each containing a description of one test case. The given strings consist only of lowercase Latin letters and have lengths between 1 and 100 inclusive.

Output

For each test case, output on a separate line:

  * YES if the string in the corresponding test case is square, 
  * NO otherwise. 



You can output YES and NO in any case (for example, strings yEs, yes, Yes and YES will be recognized as a positive response).

Example

Input


10
a
aa
aaa
aaaa
abab
abcabc
abacaba
xxyy
xyyx
xyxy


Output


NO
YES
NO
YES
YES
YES
NO
NO
NO
YES

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
void solution() {
  long long int n, m, a, b, c, d, p, q, cnt = 0, ct = 0, sum = 0, ans = 0;
  string st;
  cin >> st;
  long long int sz = st.size();
  if (sz % 2 == 1)
    cout << "NO" << endl;
  else {
    string s1, s2;
    for (long long int i = 0; i < sz / 2; i++) s1 += st[i];
    for (long long int i = sz / 2; i < sz; i++) s2 += st[i];
    if (s1 == s2)
      cout << "YES" << endl;
    else
      cout << "NO" << endl;
  }
}
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  cout.tie(NULL);
  int t;
  cin >> t;
  while (t--) solution();
  return 0;
}

```