#include <bits/stdc++.h>
#pragma GCC optimize("Ofast")
#pragma GCC optimize("unroll-loops")
#pragma GCC optimize("inline")
using namespace std;
inline int my_getchar() {
  static char buf[1048576];
  static int s = 1048576;
  static int e = 1048576;
  if (s == e && e == 1048576) {
    e = fread(buf, 1, 1048576, stdin);
    s = 0;
  }
  if (s == e) {
    return EOF;
  }
  return buf[s++];
}
inline void rd(int &x) {
  int k;
  int m = 0;
  x = 0;
  for (;;) {
    k = my_getchar();
    if (k == '-') {
      m = 1;
      break;
    }
    if ('0' <= k && k <= '9') {
      x = k - '0';
      break;
    }
  }
  for (;;) {
    k = my_getchar();
    if (k < '0' || k > '9') {
      break;
    }
    x = x * 10 + k - '0';
  }
  if (m) {
    x = -x;
  }
}
inline int rd_int(void) {
  int x;
  rd(x);
  return x;
}
struct MY_WRITER {
  char buf[1048576];
  int s;
  int e;
  MY_WRITER() {
    s = 0;
    e = 1048576;
  }
  ~MY_WRITER() {
    if (s) {
      fwrite(buf, 1, s, stdout);
    }
  }
};
MY_WRITER MY_WRITER_VAR;
void my_putchar(int a) {
  if (MY_WRITER_VAR.s == MY_WRITER_VAR.e) {
    fwrite(MY_WRITER_VAR.buf, 1, MY_WRITER_VAR.s, stdout);
    MY_WRITER_VAR.s = 0;
  }
  MY_WRITER_VAR.buf[MY_WRITER_VAR.s++] = a;
}
inline void wt_L(char a) { my_putchar(a); }
inline void wt_L(int x) {
  int s = 0;
  int m = 0;
  char f[10];
  if (x < 0) {
    m = 1;
    x = -x;
  }
  while (x) {
    f[s++] = x % 10;
    x /= 10;
  }
  if (!s) {
    f[s++] = 0;
  }
  if (m) {
    my_putchar('-');
  }
  while (s--) {
    my_putchar(f[s] + '0');
  }
}
int main() {
  int Lj4PdHRW;
  int KL2GvlyY = rd_int();
  for (Lj4PdHRW = (0); Lj4PdHRW < (KL2GvlyY); Lj4PdHRW++) {
    int i;
    int N;
    rd(N);
    int res[N];
    for (i = (0); i < (N); i++) {
      res[i] = i + 2;
    }
    {
      int FmcKpFmN;
      if (N == 0) {
        wt_L('\n');
      } else {
        for (FmcKpFmN = (0); FmcKpFmN < (N - 1); FmcKpFmN++) {
          wt_L(res[FmcKpFmN]);
          wt_L(' ');
        }
        wt_L(res[FmcKpFmN]);
        wt_L('\n');
      }
    }
  }
  return 0;
}

### Prompt

Please create a solution in cpp to the following problem:

Given n, find any array a_1, a_2, …, a_n of integers such that all of the following conditions hold: 

  * 1 ≤ a_i ≤ 10^9 for every i from 1 to n.

  * a_1 < a_2 < … <a_n

  * For every i from 2 to n, a_i isn't divisible by a_{i-1}




It can be shown that such an array always exists under the constraints of the problem.

Input

The first line contains the number of test cases t (1 ≤ t ≤ 100). Description of the test cases follows.

The only line of each test case contains a single integer n (1 ≤ n ≤ 1000).

It is guaranteed that the sum of n over all test cases does not exceed 10^4.

Output

For each test case print n integers a_1, a_2, …, a_n — the array you found. If there are multiple arrays satisfying all the conditions, print any of them.

Example

Input


3
1
2
7


Output


1
2 3
111 1111 11111 111111 1111111 11111111 111111111

Note

In the first test case, array [1] satisfies all the conditions.

In the second test case, array [2, 3] satisfies all the conditions, as 2<3 and 3 is not divisible by 2.

In the third test case, array [111, 1111, 11111, 111111, 1111111, 11111111, 111111111] satisfies all the conditions, as it's increasing and a_i isn't divisible by a_{i-1} for any i from 2 to 7.

### Response

```cpp
#include <bits/stdc++.h>
#pragma GCC optimize("Ofast")
#pragma GCC optimize("unroll-loops")
#pragma GCC optimize("inline")
using namespace std;
inline int my_getchar() {
  static char buf[1048576];
  static int s = 1048576;
  static int e = 1048576;
  if (s == e && e == 1048576) {
    e = fread(buf, 1, 1048576, stdin);
    s = 0;
  }
  if (s == e) {
    return EOF;
  }
  return buf[s++];
}
inline void rd(int &x) {
  int k;
  int m = 0;
  x = 0;
  for (;;) {
    k = my_getchar();
    if (k == '-') {
      m = 1;
      break;
    }
    if ('0' <= k && k <= '9') {
      x = k - '0';
      break;
    }
  }
  for (;;) {
    k = my_getchar();
    if (k < '0' || k > '9') {
      break;
    }
    x = x * 10 + k - '0';
  }
  if (m) {
    x = -x;
  }
}
inline int rd_int(void) {
  int x;
  rd(x);
  return x;
}
struct MY_WRITER {
  char buf[1048576];
  int s;
  int e;
  MY_WRITER() {
    s = 0;
    e = 1048576;
  }
  ~MY_WRITER() {
    if (s) {
      fwrite(buf, 1, s, stdout);
    }
  }
};
MY_WRITER MY_WRITER_VAR;
void my_putchar(int a) {
  if (MY_WRITER_VAR.s == MY_WRITER_VAR.e) {
    fwrite(MY_WRITER_VAR.buf, 1, MY_WRITER_VAR.s, stdout);
    MY_WRITER_VAR.s = 0;
  }
  MY_WRITER_VAR.buf[MY_WRITER_VAR.s++] = a;
}
inline void wt_L(char a) { my_putchar(a); }
inline void wt_L(int x) {
  int s = 0;
  int m = 0;
  char f[10];
  if (x < 0) {
    m = 1;
    x = -x;
  }
  while (x) {
    f[s++] = x % 10;
    x /= 10;
  }
  if (!s) {
    f[s++] = 0;
  }
  if (m) {
    my_putchar('-');
  }
  while (s--) {
    my_putchar(f[s] + '0');
  }
}
int main() {
  int Lj4PdHRW;
  int KL2GvlyY = rd_int();
  for (Lj4PdHRW = (0); Lj4PdHRW < (KL2GvlyY); Lj4PdHRW++) {
    int i;
    int N;
    rd(N);
    int res[N];
    for (i = (0); i < (N); i++) {
      res[i] = i + 2;
    }
    {
      int FmcKpFmN;
      if (N == 0) {
        wt_L('\n');
      } else {
        for (FmcKpFmN = (0); FmcKpFmN < (N - 1); FmcKpFmN++) {
          wt_L(res[FmcKpFmN]);
          wt_L(' ');
        }
        wt_L(res[FmcKpFmN]);
        wt_L('\n');
      }
    }
  }
  return 0;
}

```