#include <bits/stdc++.h>
using namespace std;
int main() {
  int T;
  cin >> T;
  while (T--) {
    string s;
    cin >> s;
    int n = s.size();
    string a, b;
    for (int i = 0; i < n; ++i) {
      if (i < (n / 2))
        a += s[i];
      else
        b += s[i];
    }
    if (a == b)
      cout << "YES\n";
    else
      cout << "NO\n";
  }
}

### Prompt

Generate a CPP solution to the following problem:

A string is called square if it is some string written twice in a row. For example, the strings "aa", "abcabc", "abab" and "baabaa" are square. But the strings "aaa", "abaaab" and "abcdabc" are not square.

For a given string s determine if it is square.

Input

The first line of input data contains an integer t (1 ≤ t ≤ 100) —the number of test cases.

This is followed by t lines, each containing a description of one test case. The given strings consist only of lowercase Latin letters and have lengths between 1 and 100 inclusive.

Output

For each test case, output on a separate line:

  * YES if the string in the corresponding test case is square, 
  * NO otherwise. 



You can output YES and NO in any case (for example, strings yEs, yes, Yes and YES will be recognized as a positive response).

Example

Input


10
a
aa
aaa
aaaa
abab
abcabc
abacaba
xxyy
xyyx
xyxy


Output


NO
YES
NO
YES
YES
YES
NO
NO
NO
YES

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  int T;
  cin >> T;
  while (T--) {
    string s;
    cin >> s;
    int n = s.size();
    string a, b;
    for (int i = 0; i < n; ++i) {
      if (i < (n / 2))
        a += s[i];
      else
        b += s[i];
    }
    if (a == b)
      cout << "YES\n";
    else
      cout << "NO\n";
  }
}

```