#include <bits/stdc++.h>
using namespace std;
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  int t;
  cin >> t;
  while (t--) {
    char a[101], b[51], c[51];
    cin >> a;
    int n = strlen(a);
    if (n % 2 != 0)
      cout << "NO\n";
    else {
      int k = 0, i;
      for (i = 0; i < (n / 2); i++) b[i] = a[i];
      b[i] = '\0';
      for (i = (n / 2); i < n; i++) c[k++] = a[i];
      c[k] = '\0';
      if (!(strcmp(b, c)))
        cout << "YES\n";
      else
        cout << "NO\n";
    }
  }
  return 0;
}

### Prompt

Your challenge is to write a CPP solution to the following problem:

A string is called square if it is some string written twice in a row. For example, the strings "aa", "abcabc", "abab" and "baabaa" are square. But the strings "aaa", "abaaab" and "abcdabc" are not square.

For a given string s determine if it is square.

Input

The first line of input data contains an integer t (1 ≤ t ≤ 100) —the number of test cases.

This is followed by t lines, each containing a description of one test case. The given strings consist only of lowercase Latin letters and have lengths between 1 and 100 inclusive.

Output

For each test case, output on a separate line:

  * YES if the string in the corresponding test case is square, 
  * NO otherwise. 



You can output YES and NO in any case (for example, strings yEs, yes, Yes and YES will be recognized as a positive response).

Example

Input


10
a
aa
aaa
aaaa
abab
abcabc
abacaba
xxyy
xyyx
xyxy


Output


NO
YES
NO
YES
YES
YES
NO
NO
NO
YES

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  int t;
  cin >> t;
  while (t--) {
    char a[101], b[51], c[51];
    cin >> a;
    int n = strlen(a);
    if (n % 2 != 0)
      cout << "NO\n";
    else {
      int k = 0, i;
      for (i = 0; i < (n / 2); i++) b[i] = a[i];
      b[i] = '\0';
      for (i = (n / 2); i < n; i++) c[k++] = a[i];
      c[k] = '\0';
      if (!(strcmp(b, c)))
        cout << "YES\n";
      else
        cout << "NO\n";
    }
  }
  return 0;
}

```