#include <bits/stdc++.h>
using namespace std;
int main() {
  int t, x, i, j, k, p, s, f;
  string st;
  cin >> t;
  while (t--) {
    cin >> st;
    x = st.size();
    if (x % 2 == 1)
      cout << "NO\n";
    else {
      p = x / 2;
      f = 0;
      for (i = 0; i < p; i++) {
        for (j = 0; j <= i; j++) {
          if (st[j] != st[p + j]) {
            f = 1;
            break;
          }
        }
        if (f == 1) break;
      }
      if (f == 0)
        cout << "YES\n";
      else
        cout << "NO\n";
    }
  }
}

### Prompt

Construct a CPP code solution to the problem outlined:

A string is called square if it is some string written twice in a row. For example, the strings "aa", "abcabc", "abab" and "baabaa" are square. But the strings "aaa", "abaaab" and "abcdabc" are not square.

For a given string s determine if it is square.

Input

The first line of input data contains an integer t (1 ≤ t ≤ 100) —the number of test cases.

This is followed by t lines, each containing a description of one test case. The given strings consist only of lowercase Latin letters and have lengths between 1 and 100 inclusive.

Output

For each test case, output on a separate line:

  * YES if the string in the corresponding test case is square, 
  * NO otherwise. 



You can output YES and NO in any case (for example, strings yEs, yes, Yes and YES will be recognized as a positive response).

Example

Input


10
a
aa
aaa
aaaa
abab
abcabc
abacaba
xxyy
xyyx
xyxy


Output


NO
YES
NO
YES
YES
YES
NO
NO
NO
YES

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  int t, x, i, j, k, p, s, f;
  string st;
  cin >> t;
  while (t--) {
    cin >> st;
    x = st.size();
    if (x % 2 == 1)
      cout << "NO\n";
    else {
      p = x / 2;
      f = 0;
      for (i = 0; i < p; i++) {
        for (j = 0; j <= i; j++) {
          if (st[j] != st[p + j]) {
            f = 1;
            break;
          }
        }
        if (f == 1) break;
      }
      if (f == 0)
        cout << "YES\n";
      else
        cout << "NO\n";
    }
  }
}

```