#include <bits/stdc++.h>
using namespace std;
int main() {
  std::ios_base::sync_with_stdio(0);
  cin.tie(NULL);
  cout.tie(NULL);
  int t;
  cin >> t;
  while (t--) {
    string s;
    int cnt = 0;
    cin >> s;
    for (int i = 0, j = s.size() / 2; i < s.size() / 2 && j < s.size();
         i++, j++) {
      if (s[i] == s[j]) {
        cnt++;
      }
    }
    if (cnt * 2 == s.size()) {
      cout << "yes\n";
    } else {
      cout << "no\n";
    }
  }
}

### Prompt

In CPP, your task is to solve the following problem:

A string is called square if it is some string written twice in a row. For example, the strings "aa", "abcabc", "abab" and "baabaa" are square. But the strings "aaa", "abaaab" and "abcdabc" are not square.

For a given string s determine if it is square.

Input

The first line of input data contains an integer t (1 ≤ t ≤ 100) —the number of test cases.

This is followed by t lines, each containing a description of one test case. The given strings consist only of lowercase Latin letters and have lengths between 1 and 100 inclusive.

Output

For each test case, output on a separate line:

  * YES if the string in the corresponding test case is square, 
  * NO otherwise. 



You can output YES and NO in any case (for example, strings yEs, yes, Yes and YES will be recognized as a positive response).

Example

Input


10
a
aa
aaa
aaaa
abab
abcabc
abacaba
xxyy
xyyx
xyxy


Output


NO
YES
NO
YES
YES
YES
NO
NO
NO
YES

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  std::ios_base::sync_with_stdio(0);
  cin.tie(NULL);
  cout.tie(NULL);
  int t;
  cin >> t;
  while (t--) {
    string s;
    int cnt = 0;
    cin >> s;
    for (int i = 0, j = s.size() / 2; i < s.size() / 2 && j < s.size();
         i++, j++) {
      if (s[i] == s[j]) {
        cnt++;
      }
    }
    if (cnt * 2 == s.size()) {
      cout << "yes\n";
    } else {
      cout << "no\n";
    }
  }
}

```