#include <bits/stdc++.h>
int main() {
  int count;
  std::string input;
  bool yep;
  std::cin >> count;
  std::string answer[count];
  for (int i = 0; i < count; i++) {
    yep = false;
    std::cin >> input;
    if (input.length() % 2 != 0)
      yep = false;
    else {
      for (int j = 0; j < input.length() / 2; j++) {
        if (input[j] == input[j + (input.length() / 2)])
          yep = true;
        else {
          yep = false;
          break;
        }
      }
    }
    if (yep == true) {
      answer[i] = "YES";
    } else
      answer[i] = "NO";
  }
  for (int i = 0; i < count; i++) {
    std::cout << answer[i] << std::endl;
  }
}

### Prompt

Please provide a cpp coded solution to the problem described below:

A string is called square if it is some string written twice in a row. For example, the strings "aa", "abcabc", "abab" and "baabaa" are square. But the strings "aaa", "abaaab" and "abcdabc" are not square.

For a given string s determine if it is square.

Input

The first line of input data contains an integer t (1 ≤ t ≤ 100) —the number of test cases.

This is followed by t lines, each containing a description of one test case. The given strings consist only of lowercase Latin letters and have lengths between 1 and 100 inclusive.

Output

For each test case, output on a separate line:

  * YES if the string in the corresponding test case is square, 
  * NO otherwise. 



You can output YES and NO in any case (for example, strings yEs, yes, Yes and YES will be recognized as a positive response).

Example

Input


10
a
aa
aaa
aaaa
abab
abcabc
abacaba
xxyy
xyyx
xyxy


Output


NO
YES
NO
YES
YES
YES
NO
NO
NO
YES

### Response

```cpp
#include <bits/stdc++.h>
int main() {
  int count;
  std::string input;
  bool yep;
  std::cin >> count;
  std::string answer[count];
  for (int i = 0; i < count; i++) {
    yep = false;
    std::cin >> input;
    if (input.length() % 2 != 0)
      yep = false;
    else {
      for (int j = 0; j < input.length() / 2; j++) {
        if (input[j] == input[j + (input.length() / 2)])
          yep = true;
        else {
          yep = false;
          break;
        }
      }
    }
    if (yep == true) {
      answer[i] = "YES";
    } else
      answer[i] = "NO";
  }
  for (int i = 0; i < count; i++) {
    std::cout << answer[i] << std::endl;
  }
}

```