#include <bits/stdc++.h>
using namespace std;
const int64_t mod = 1e9 + 7, INF = 1e18L + 5, N = 2e5 + 5;
const string yes = "YES", no = "NO";
void pavvo() {
  string s;
  cin >> s;
  int64_t n = s.size();
  string t = s.substr(0, n / 2);
  string p = s.substr(n / 2, n);
  ;
  cout << ((t == p) ? yes : no) << '\n';
}
signed main() {
  ios_base::sync_with_stdio(false);
  cin.tie(nullptr);
  int64_t T = 1;
  cin >> T;
  for (int64_t test = 1; test <= T; ++test) {
    pavvo();
  }
  cerr << "Time : " << 1000 * ((double)clock()) / (double)CLOCKS_PER_SEC
       << "ms\n";
  return 0;
}

### Prompt

Please create a solution in Cpp to the following problem:

A string is called square if it is some string written twice in a row. For example, the strings "aa", "abcabc", "abab" and "baabaa" are square. But the strings "aaa", "abaaab" and "abcdabc" are not square.

For a given string s determine if it is square.

Input

The first line of input data contains an integer t (1 ≤ t ≤ 100) —the number of test cases.

This is followed by t lines, each containing a description of one test case. The given strings consist only of lowercase Latin letters and have lengths between 1 and 100 inclusive.

Output

For each test case, output on a separate line:

  * YES if the string in the corresponding test case is square, 
  * NO otherwise. 



You can output YES and NO in any case (for example, strings yEs, yes, Yes and YES will be recognized as a positive response).

Example

Input


10
a
aa
aaa
aaaa
abab
abcabc
abacaba
xxyy
xyyx
xyxy


Output


NO
YES
NO
YES
YES
YES
NO
NO
NO
YES

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
const int64_t mod = 1e9 + 7, INF = 1e18L + 5, N = 2e5 + 5;
const string yes = "YES", no = "NO";
void pavvo() {
  string s;
  cin >> s;
  int64_t n = s.size();
  string t = s.substr(0, n / 2);
  string p = s.substr(n / 2, n);
  ;
  cout << ((t == p) ? yes : no) << '\n';
}
signed main() {
  ios_base::sync_with_stdio(false);
  cin.tie(nullptr);
  int64_t T = 1;
  cin >> T;
  for (int64_t test = 1; test <= T; ++test) {
    pavvo();
  }
  cerr << "Time : " << 1000 * ((double)clock()) / (double)CLOCKS_PER_SEC
       << "ms\n";
  return 0;
}

```