#include <bits/stdc++.h>
using namespace std;
int main() {
  int t;
  cin >> t;
  string str;
  while (t--) {
    cin >> str;
    if (str.length() < 2 || str.length() % 2 != 0) {
      cout << "NO" << endl;
      continue;
    }
    int left = 0;
    int right = str.length() / 2;
    bool flag = true;
    while (right < str.length()) {
      if (str[left++] != str[right++]) {
        cout << "NO" << endl;
        flag = false;
        break;
      }
    }
    if (right >= str.length() && flag) {
      cout << "YES" << endl;
    }
  }
  return 0;
}

### Prompt

Create a solution in cpp for the following problem:

A string is called square if it is some string written twice in a row. For example, the strings "aa", "abcabc", "abab" and "baabaa" are square. But the strings "aaa", "abaaab" and "abcdabc" are not square.

For a given string s determine if it is square.

Input

The first line of input data contains an integer t (1 ≤ t ≤ 100) —the number of test cases.

This is followed by t lines, each containing a description of one test case. The given strings consist only of lowercase Latin letters and have lengths between 1 and 100 inclusive.

Output

For each test case, output on a separate line:

  * YES if the string in the corresponding test case is square, 
  * NO otherwise. 



You can output YES and NO in any case (for example, strings yEs, yes, Yes and YES will be recognized as a positive response).

Example

Input


10
a
aa
aaa
aaaa
abab
abcabc
abacaba
xxyy
xyyx
xyxy


Output


NO
YES
NO
YES
YES
YES
NO
NO
NO
YES

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  int t;
  cin >> t;
  string str;
  while (t--) {
    cin >> str;
    if (str.length() < 2 || str.length() % 2 != 0) {
      cout << "NO" << endl;
      continue;
    }
    int left = 0;
    int right = str.length() / 2;
    bool flag = true;
    while (right < str.length()) {
      if (str[left++] != str[right++]) {
        cout << "NO" << endl;
        flag = false;
        break;
      }
    }
    if (right >= str.length() && flag) {
      cout << "YES" << endl;
    }
  }
  return 0;
}

```