#include<iostream>
using namespace std;
int main()
{
	int i,n,a=0,s=0;
	cin>>n;
	for(i=1;i<=n;i++)
	{
		for(int j=1;j<=i;j++)
		{
			if(i%j==0&&i&1) a++;
		}
		if(a==8) s++;
		a=0;
	}
	cout<<s<<endl;
	return 0;
}

### Prompt

Your challenge is to write a Cpp solution to the following problem:

The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0

### Response

```cpp
#include<iostream>
using namespace std;
int main()
{
	int i,n,a=0,s=0;
	cin>>n;
	for(i=1;i<=n;i++)
	{
		for(int j=1;j<=i;j++)
		{
			if(i%j==0&&i&1) a++;
		}
		if(a==8) s++;
		a=0;
	}
	cout<<s<<endl;
	return 0;
}

```