#include<bits/stdc++.h>
using namespace std;
int main()
{
int a[100000];
int n;
string s;
cin>>n>>s;
s=s+s;
for(int i=0;i<2;i++)
  for(int j=0;j<2;j++)
  {
  	a[0]=i;
  	a[1]=j;
  	for(int i=2;i<=n+1;i++)
  	{
  		if(a[i-1]&&s[i-1]=='o')a[i]=a[i-2];
  		if(!a[i-1]&&s[i-1]=='o')a[i]=1-a[i-2];
  		if(a[i-1]&&s[i-1]=='x')a[i]=1-a[i-2];
  		if(!a[i-1]&&s[i-1]=='x')a[i]=a[i-2];
	}
	if(a[0]==a[n]&&a[1]==a[n+1])
	{
		for(int i=0;i<n;i++)cout<<(a[i]?"S":"W");
		return 0;
	}
  }
  cout<<-1;
return 0;
}
### Prompt

Please create a solution in Cpp to the following problem:

Snuke, who loves animals, built a zoo.

There are N animals in this zoo. They are conveniently numbered 1 through N, and arranged in a circle. The animal numbered i (2≤i≤N-1) is adjacent to the animals numbered i-1 and i+1. Also, the animal numbered 1 is adjacent to the animals numbered 2 and N, and the animal numbered N is adjacent to the animals numbered N-1 and 1.

There are two kinds of animals in this zoo: honest sheep that only speak the truth, and lying wolves that only tell lies.

Snuke cannot tell the difference between these two species, and asked each animal the following question: "Are your neighbors of the same species?" The animal numbered i answered s_i. Here, if s_i is `o`, the animal said that the two neighboring animals are of the same species, and if s_i is `x`, the animal said that the two neighboring animals are of different species.

More formally, a sheep answered `o` if the two neighboring animals are both sheep or both wolves, and answered `x` otherwise. Similarly, a wolf answered `x` if the two neighboring animals are both sheep or both wolves, and answered `o` otherwise.

Snuke is wondering whether there is a valid assignment of species to the animals that is consistent with these responses. If there is such an assignment, show one such assignment. Otherwise, print `-1`.

Constraints

* 3 ≤ N ≤ 10^{5}
* s is a string of length N consisting of `o` and `x`.

Input

The input is given from Standard Input in the following format:


N
s


Output

If there does not exist an valid assignment that is consistent with s, print `-1`. Otherwise, print an string t in the following format. The output is considered correct if the assignment described by t is consistent with s.

* t is a string of length N consisting of `S` and `W`.
* If t_i is `S`, it indicates that the animal numbered i is a sheep. If t_i is `W`, it indicates that the animal numbered i is a wolf.

Examples

Input

6
ooxoox


Output

SSSWWS


Input

3
oox


Output

-1


Input

10
oxooxoxoox


Output

SSWWSSSWWS

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;
int main()
{
int a[100000];
int n;
string s;
cin>>n>>s;
s=s+s;
for(int i=0;i<2;i++)
  for(int j=0;j<2;j++)
  {
  	a[0]=i;
  	a[1]=j;
  	for(int i=2;i<=n+1;i++)
  	{
  		if(a[i-1]&&s[i-1]=='o')a[i]=a[i-2];
  		if(!a[i-1]&&s[i-1]=='o')a[i]=1-a[i-2];
  		if(a[i-1]&&s[i-1]=='x')a[i]=1-a[i-2];
  		if(!a[i-1]&&s[i-1]=='x')a[i]=a[i-2];
	}
	if(a[0]==a[n]&&a[1]==a[n+1])
	{
		for(int i=0;i<n;i++)cout<<(a[i]?"S":"W");
		return 0;
	}
  }
  cout<<-1;
return 0;
}
```