#include <bits/stdc++.h>
using namespace std;
int main() {
  int a, b, l, f, i, j = 0;
  string s, c, d, g, h;
  cin >> s >> a;
  l = s.size();
  b = l / a;
  if (a > l) {
    cout << "NO";
  } else if (l % a != 0) {
    cout << "NO";
  } else {
    for (i = 0; i < s.size(); i = i + b) {
      g = s.substr(i, b);
      h = g;
      reverse(g.begin(), g.end());
      if (g.compare(h) == 0) {
        j++;
      } else {
        cout << "NO";
        return 0;
      }
    }
    cout << "YES";
  }
}

### Prompt

Your challenge is to write a CPP solution to the following problem:

While Mike was walking in the subway, all the stuff in his back-bag dropped on the ground. There were several fax messages among them. He concatenated these strings in some order and now he has string s.

<image>

He is not sure if this is his own back-bag or someone else's. He remembered that there were exactly k messages in his own bag, each was a palindrome string and all those strings had the same length.

He asked you to help him and tell him if he has worn his own back-bag. Check if the given string s is a concatenation of k palindromes of the same length.

Input

The first line of input contains string s containing lowercase English letters (1 ≤ |s| ≤ 1000).

The second line contains integer k (1 ≤ k ≤ 1000).

Output

Print "YES"(without quotes) if he has worn his own back-bag or "NO"(without quotes) otherwise.

Examples

Input

saba
2


Output

NO


Input

saddastavvat
2


Output

YES

Note

Palindrome is a string reading the same forward and backward.

In the second sample, the faxes in his back-bag can be "saddas" and "tavvat".

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  int a, b, l, f, i, j = 0;
  string s, c, d, g, h;
  cin >> s >> a;
  l = s.size();
  b = l / a;
  if (a > l) {
    cout << "NO";
  } else if (l % a != 0) {
    cout << "NO";
  } else {
    for (i = 0; i < s.size(); i = i + b) {
      g = s.substr(i, b);
      h = g;
      reverse(g.begin(), g.end());
      if (g.compare(h) == 0) {
        j++;
      } else {
        cout << "NO";
        return 0;
      }
    }
    cout << "YES";
  }
}

```