#include <bits/stdc++.h>
using namespace std;
int main(){
    long N;
    cin>>N;
    cout<<(N>104)+(N>134)+(N>164)+(N>188)+(N>194)<<endl;
}
### Prompt

Please create a solution in Cpp to the following problem:

The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main(){
    long N;
    cin>>N;
    cout<<(N>104)+(N>134)+(N>164)+(N>188)+(N>194)<<endl;
}
```