#include <bits/stdc++.h>
using namespace std;
int main() {
  string s;
  cin >> s;
  long int l, n, i, k, m;
  cin >> n;
  l = s.length();
  k = l / n;
  int f = 1;
  if (l % n != 0) {
    f = 0;
  } else {
    for (int j = 0; j < n; j++) {
      for (i = j * k, m = (j + 1) * k; i < (j + 1) * k; i++, m--) {
        if (s[i] != s[m - 1]) {
          f = 0;
          break;
        }
      }
    }
  }
  if (f == 0)
    cout << "NO";
  else
    cout << "YES";
}

### Prompt

Develop a solution in cpp to the problem described below:

While Mike was walking in the subway, all the stuff in his back-bag dropped on the ground. There were several fax messages among them. He concatenated these strings in some order and now he has string s.

<image>

He is not sure if this is his own back-bag or someone else's. He remembered that there were exactly k messages in his own bag, each was a palindrome string and all those strings had the same length.

He asked you to help him and tell him if he has worn his own back-bag. Check if the given string s is a concatenation of k palindromes of the same length.

Input

The first line of input contains string s containing lowercase English letters (1 ≤ |s| ≤ 1000).

The second line contains integer k (1 ≤ k ≤ 1000).

Output

Print "YES"(without quotes) if he has worn his own back-bag or "NO"(without quotes) otherwise.

Examples

Input

saba
2


Output

NO


Input

saddastavvat
2


Output

YES

Note

Palindrome is a string reading the same forward and backward.

In the second sample, the faxes in his back-bag can be "saddas" and "tavvat".

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  string s;
  cin >> s;
  long int l, n, i, k, m;
  cin >> n;
  l = s.length();
  k = l / n;
  int f = 1;
  if (l % n != 0) {
    f = 0;
  } else {
    for (int j = 0; j < n; j++) {
      for (i = j * k, m = (j + 1) * k; i < (j + 1) * k; i++, m--) {
        if (s[i] != s[m - 1]) {
          f = 0;
          break;
        }
      }
    }
  }
  if (f == 0)
    cout << "NO";
  else
    cout << "YES";
}

```