#include <bits/stdc++.h>
using namespace std;
int main(void) {
  string s;
  cin >> s;
  int k;
  cin >> k;
  if (s.length() % k) {
    cout << "NO" << endl;
    exit(0);
  }
  int n = s.length() / k;
  bool palin = true;
  for (int i = 0; i < k; i++) {
    int l = i * n;
    int r = l + (n - 1);
    while (l <= r) {
      if (s[l] != s[r]) palin = false;
      l++, r--;
    }
    if (!palin) {
      cout << "NO" << endl;
      exit(0);
    }
  }
  cout << "YES" << endl;
  return 0;
}

### Prompt

Please formulate a Cpp solution to the following problem:

While Mike was walking in the subway, all the stuff in his back-bag dropped on the ground. There were several fax messages among them. He concatenated these strings in some order and now he has string s.

<image>

He is not sure if this is his own back-bag or someone else's. He remembered that there were exactly k messages in his own bag, each was a palindrome string and all those strings had the same length.

He asked you to help him and tell him if he has worn his own back-bag. Check if the given string s is a concatenation of k palindromes of the same length.

Input

The first line of input contains string s containing lowercase English letters (1 ≤ |s| ≤ 1000).

The second line contains integer k (1 ≤ k ≤ 1000).

Output

Print "YES"(without quotes) if he has worn his own back-bag or "NO"(without quotes) otherwise.

Examples

Input

saba
2


Output

NO


Input

saddastavvat
2


Output

YES

Note

Palindrome is a string reading the same forward and backward.

In the second sample, the faxes in his back-bag can be "saddas" and "tavvat".

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main(void) {
  string s;
  cin >> s;
  int k;
  cin >> k;
  if (s.length() % k) {
    cout << "NO" << endl;
    exit(0);
  }
  int n = s.length() / k;
  bool palin = true;
  for (int i = 0; i < k; i++) {
    int l = i * n;
    int r = l + (n - 1);
    while (l <= r) {
      if (s[l] != s[r]) palin = false;
      l++, r--;
    }
    if (!palin) {
      cout << "NO" << endl;
      exit(0);
    }
  }
  cout << "YES" << endl;
  return 0;
}

```