#include <bits/stdc++.h>
#define rep(i,n) for (int i = 0; i < (n); ++i)
using namespace std;
typedef long long ll;

const int M=1e6;
int a[M];

int main(){
       
    int n;
    string s;
    cin >> n >> s;
    
    s = s+s;
    
    for(int i1=0; i1<2; i1++){
        for(int i2=0; i2<2; i2++){
            a[0] = i1;
            a[1] = i2;
            for(int i=2; i<=n+1; i++){
                if(s[i-1]=='o' && a[i-1]==0) a[i] = 1-a[i-2];
                if(s[i-1]=='o' && a[i-1]==1) a[i] = a[i-2];
                if(s[i-1]=='x' && a[i-1]==0) a[i] = a[i-2];
                if(s[i-1]=='x' && a[i-1]==1) a[i] = 1-a[i-2];
            }
            if(a[n]==a[0] && a[n+1]==a[1]){
                for(int i=0; i<n; i++)
                    cout << (a[i]?"S":"W");
                return 0;
            }
        }
    }
    cout << -1;
    return 0;
}

### Prompt

Create a solution in CPP for the following problem:

Snuke, who loves animals, built a zoo.

There are N animals in this zoo. They are conveniently numbered 1 through N, and arranged in a circle. The animal numbered i (2≤i≤N-1) is adjacent to the animals numbered i-1 and i+1. Also, the animal numbered 1 is adjacent to the animals numbered 2 and N, and the animal numbered N is adjacent to the animals numbered N-1 and 1.

There are two kinds of animals in this zoo: honest sheep that only speak the truth, and lying wolves that only tell lies.

Snuke cannot tell the difference between these two species, and asked each animal the following question: "Are your neighbors of the same species?" The animal numbered i answered s_i. Here, if s_i is `o`, the animal said that the two neighboring animals are of the same species, and if s_i is `x`, the animal said that the two neighboring animals are of different species.

More formally, a sheep answered `o` if the two neighboring animals are both sheep or both wolves, and answered `x` otherwise. Similarly, a wolf answered `x` if the two neighboring animals are both sheep or both wolves, and answered `o` otherwise.

Snuke is wondering whether there is a valid assignment of species to the animals that is consistent with these responses. If there is such an assignment, show one such assignment. Otherwise, print `-1`.

Constraints

* 3 ≤ N ≤ 10^{5}
* s is a string of length N consisting of `o` and `x`.

Input

The input is given from Standard Input in the following format:


N
s


Output

If there does not exist an valid assignment that is consistent with s, print `-1`. Otherwise, print an string t in the following format. The output is considered correct if the assignment described by t is consistent with s.

* t is a string of length N consisting of `S` and `W`.
* If t_i is `S`, it indicates that the animal numbered i is a sheep. If t_i is `W`, it indicates that the animal numbered i is a wolf.

Examples

Input

6
ooxoox


Output

SSSWWS


Input

3
oox


Output

-1


Input

10
oxooxoxoox


Output

SSWWSSSWWS

### Response

```cpp
#include <bits/stdc++.h>
#define rep(i,n) for (int i = 0; i < (n); ++i)
using namespace std;
typedef long long ll;

const int M=1e6;
int a[M];

int main(){
       
    int n;
    string s;
    cin >> n >> s;
    
    s = s+s;
    
    for(int i1=0; i1<2; i1++){
        for(int i2=0; i2<2; i2++){
            a[0] = i1;
            a[1] = i2;
            for(int i=2; i<=n+1; i++){
                if(s[i-1]=='o' && a[i-1]==0) a[i] = 1-a[i-2];
                if(s[i-1]=='o' && a[i-1]==1) a[i] = a[i-2];
                if(s[i-1]=='x' && a[i-1]==0) a[i] = a[i-2];
                if(s[i-1]=='x' && a[i-1]==1) a[i] = 1-a[i-2];
            }
            if(a[n]==a[0] && a[n+1]==a[1]){
                for(int i=0; i<n; i++)
                    cout << (a[i]?"S":"W");
                return 0;
            }
        }
    }
    cout << -1;
    return 0;
}

```