#include <bits/stdc++.h>
using namespace std;
typedef long long ll;

int main() {
  int N;
  cin >> N;
  string S;
  cin >> S;
  char c[2] = {'S', 'W'};
  for (int i = 0; i < 2; i++) {
    for (int j = 0; j < 2; j++) {
      vector<int> T;
      T.push_back(i);
      T.push_back(j);
      for (int k = 0; k < N; k++) {
        if (S[k] == 'o') {
          if (T[k + 1] == 0)
            T.push_back(T[k]);
          else
            T.push_back(1 - T[k]);
        } else {
          if (T[k + 1] == 0) {
            T.push_back(1 - T[k]);
          } else {
            T.push_back(T[k]);
          }
        }
      }
      if (T[0] == T[N] && T[1] == T[N + 1]) {
        for (int i = 1; i < N + 1; i++) {
          cout << "SW"[T[i]];
        }
        cout << endl;
        return 0;
      }
    }
  }
  cout << -1 << endl;
}
### Prompt

Please create a solution in cpp to the following problem:

Snuke, who loves animals, built a zoo.

There are N animals in this zoo. They are conveniently numbered 1 through N, and arranged in a circle. The animal numbered i (2≤i≤N-1) is adjacent to the animals numbered i-1 and i+1. Also, the animal numbered 1 is adjacent to the animals numbered 2 and N, and the animal numbered N is adjacent to the animals numbered N-1 and 1.

There are two kinds of animals in this zoo: honest sheep that only speak the truth, and lying wolves that only tell lies.

Snuke cannot tell the difference between these two species, and asked each animal the following question: "Are your neighbors of the same species?" The animal numbered i answered s_i. Here, if s_i is `o`, the animal said that the two neighboring animals are of the same species, and if s_i is `x`, the animal said that the two neighboring animals are of different species.

More formally, a sheep answered `o` if the two neighboring animals are both sheep or both wolves, and answered `x` otherwise. Similarly, a wolf answered `x` if the two neighboring animals are both sheep or both wolves, and answered `o` otherwise.

Snuke is wondering whether there is a valid assignment of species to the animals that is consistent with these responses. If there is such an assignment, show one such assignment. Otherwise, print `-1`.

Constraints

* 3 ≤ N ≤ 10^{5}
* s is a string of length N consisting of `o` and `x`.

Input

The input is given from Standard Input in the following format:


N
s


Output

If there does not exist an valid assignment that is consistent with s, print `-1`. Otherwise, print an string t in the following format. The output is considered correct if the assignment described by t is consistent with s.

* t is a string of length N consisting of `S` and `W`.
* If t_i is `S`, it indicates that the animal numbered i is a sheep. If t_i is `W`, it indicates that the animal numbered i is a wolf.

Examples

Input

6
ooxoox


Output

SSSWWS


Input

3
oox


Output

-1


Input

10
oxooxoxoox


Output

SSWWSSSWWS

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;

int main() {
  int N;
  cin >> N;
  string S;
  cin >> S;
  char c[2] = {'S', 'W'};
  for (int i = 0; i < 2; i++) {
    for (int j = 0; j < 2; j++) {
      vector<int> T;
      T.push_back(i);
      T.push_back(j);
      for (int k = 0; k < N; k++) {
        if (S[k] == 'o') {
          if (T[k + 1] == 0)
            T.push_back(T[k]);
          else
            T.push_back(1 - T[k]);
        } else {
          if (T[k + 1] == 0) {
            T.push_back(1 - T[k]);
          } else {
            T.push_back(T[k]);
          }
        }
      }
      if (T[0] == T[N] && T[1] == T[N + 1]) {
        for (int i = 1; i < N + 1; i++) {
          cout << "SW"[T[i]];
        }
        cout << endl;
        return 0;
      }
    }
  }
  cout << -1 << endl;
}
```