#include <stdio.h>

int main(void) {

	int s;

	scanf("%d", &s);

	printf("%d:%d:%d\n", (s / 3600) % 60, (s / 60) % 60, s % 60);

	return 0;
}

### Prompt

Develop a solution in cpp to the problem described below:

Write a program which reads an integer $S$ [second] and converts it to $h:m:s$ where $h$, $m$, $s$ denote hours, minutes (less than 60) and seconds (less than 60) respectively.

Constraints

* $0 \leq S \leq 86400$

Input

An integer $S$ is given in a line.

Output

Print $h$, $m$ and $s$ separated by ':'. You do not need to put '0' for a value, which consists of a digit.

Example

Input

46979


Output

13:2:59

### Response

```cpp
#include <stdio.h>

int main(void) {

	int s;

	scanf("%d", &s);

	printf("%d:%d:%d\n", (s / 3600) % 60, (s / 60) % 60, s % 60);

	return 0;
}

```