#include <bits/stdc++.h>
using namespace std;

int main() {
  int n;
  cin>>n;
  int s=0;
  for(int x=1; x<=n; x+=2){
    int k=0;
    for(int i=1; i<=n; i++){
      if (x%i==0) k+=1;
    }
    if (k==8) s+= 1;
  }
  cout << s;
}
### Prompt

In cpp, your task is to solve the following problem:

The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;

int main() {
  int n;
  cin>>n;
  int s=0;
  for(int x=1; x<=n; x+=2){
    int k=0;
    for(int i=1; i<=n; i++){
      if (x%i==0) k+=1;
    }
    if (k==8) s+= 1;
  }
  cout << s;
}
```