#include <bits/stdc++.h>
using namespace std;
int main(){int n,a=0,j,i,r;cin>>n;for(i=1;i<=n;i+=2){r=2;for(j=2;j<=i/2;++j)if(i%j==0)++r;a+=r==8;}cout<<a<<'\n';}
### Prompt

Create a solution in cpp for the following problem:

The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main(){int n,a=0,j,i,r;cin>>n;for(i=1;i<=n;i+=2){r=2;for(j=2;j<=i/2;++j)if(i%j==0)++r;a+=r==8;}cout<<a<<'\n';}
```