#include <bits/stdc++.h>
using namespace std;

int main() {
  int N;
  cin >> N;
  vector<bool> s(N);
  char ch;
  for (int i = 0; i < N; ++i) {
    cin >> ch;
    s[i] = (ch == 'o');
  }
  vector<bool> r(N);
  bool find(false);
  for (int i = 0; i < 4; ++i) {
    r[0] = (i / 2 == 0);
    r[1] = (i % 2 == 0);
    for (int j = 2; j < N; ++j) {
      r[j] = (r[j-1] ^ s[j-1]) ? !r[j-2] : r[j-2];
    }
    if ((((r[N-1] ^ s[N-1]) ? !r[N-2] : r[N-2]) == r[0]) && ((r[0] ^ s[0]) ? !r[N-1] : r[N-1]) == r[1]) {
      find = true;
      break;
    }
  }
  if (find) {
    for (int i = 0; i < N; ++i) {
      cout << (r[i] ? 'S' : 'W');
    }
  } else {
    cout << -1;
  }
  cout << endl;
}

### Prompt

Please create a solution in Cpp to the following problem:

Snuke, who loves animals, built a zoo.

There are N animals in this zoo. They are conveniently numbered 1 through N, and arranged in a circle. The animal numbered i (2≤i≤N-1) is adjacent to the animals numbered i-1 and i+1. Also, the animal numbered 1 is adjacent to the animals numbered 2 and N, and the animal numbered N is adjacent to the animals numbered N-1 and 1.

There are two kinds of animals in this zoo: honest sheep that only speak the truth, and lying wolves that only tell lies.

Snuke cannot tell the difference between these two species, and asked each animal the following question: "Are your neighbors of the same species?" The animal numbered i answered s_i. Here, if s_i is `o`, the animal said that the two neighboring animals are of the same species, and if s_i is `x`, the animal said that the two neighboring animals are of different species.

More formally, a sheep answered `o` if the two neighboring animals are both sheep or both wolves, and answered `x` otherwise. Similarly, a wolf answered `x` if the two neighboring animals are both sheep or both wolves, and answered `o` otherwise.

Snuke is wondering whether there is a valid assignment of species to the animals that is consistent with these responses. If there is such an assignment, show one such assignment. Otherwise, print `-1`.

Constraints

* 3 ≤ N ≤ 10^{5}
* s is a string of length N consisting of `o` and `x`.

Input

The input is given from Standard Input in the following format:


N
s


Output

If there does not exist an valid assignment that is consistent with s, print `-1`. Otherwise, print an string t in the following format. The output is considered correct if the assignment described by t is consistent with s.

* t is a string of length N consisting of `S` and `W`.
* If t_i is `S`, it indicates that the animal numbered i is a sheep. If t_i is `W`, it indicates that the animal numbered i is a wolf.

Examples

Input

6
ooxoox


Output

SSSWWS


Input

3
oox


Output

-1


Input

10
oxooxoxoox


Output

SSWWSSSWWS

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;

int main() {
  int N;
  cin >> N;
  vector<bool> s(N);
  char ch;
  for (int i = 0; i < N; ++i) {
    cin >> ch;
    s[i] = (ch == 'o');
  }
  vector<bool> r(N);
  bool find(false);
  for (int i = 0; i < 4; ++i) {
    r[0] = (i / 2 == 0);
    r[1] = (i % 2 == 0);
    for (int j = 2; j < N; ++j) {
      r[j] = (r[j-1] ^ s[j-1]) ? !r[j-2] : r[j-2];
    }
    if ((((r[N-1] ^ s[N-1]) ? !r[N-2] : r[N-2]) == r[0]) && ((r[0] ^ s[0]) ? !r[N-1] : r[N-1]) == r[1]) {
      find = true;
      break;
    }
  }
  if (find) {
    for (int i = 0; i < N; ++i) {
      cout << (r[i] ? 'S' : 'W');
    }
  } else {
    cout << -1;
  }
  cout << endl;
}

```