#include<iostream>
using namespace std;
int c,n;
int main(){
	cin>>n;
	for(;n;n--)
	{
		if(n%2<1)continue;
		int m=0;
		for(int j=1;j<=n;j++)m+=n%j<1;
		if(m==8)c++;
	}
	cout<<c<<endl;
}

### Prompt

In Cpp, your task is to solve the following problem:

The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0

### Response

```cpp
#include<iostream>
using namespace std;
int c,n;
int main(){
	cin>>n;
	for(;n;n--)
	{
		if(n%2<1)continue;
		int m=0;
		for(int j=1;j<=n;j++)m+=n%j<1;
		if(m==8)c++;
	}
	cout<<c<<endl;
}

```