#include <iostream>
using namespace std;

int main() {
	ios::sync_with_stdio(false);
	int N;
	cin >> N;
	string s, t;
	cin>>s;
	s+=s[0];
	for (int a=0; a<4; a++){
		if (a==0) t="SS";
		else if (a==1) t="SW";
		else if (a==2) t="WS";
		else t="WW";
		for (int i=2; i<=N+1; i++){
			if (t[i-1]=='S'){
				if (s[i-1]=='o'){
					if (t[i-2]=='S') t+='S';
					else t+='W';
				}
				else{
					if(t[i-2]=='S') t+='W';
					else t+='S';
				}
			}
			else{
				if (s[i-1]=='o'){
					if (t[i-2]=='S') t+='W';
					else t+='S';
				}
				else{
					if(t[i-2]=='S') t+='S';
					else t+='W';
				}				
			}

		}
	    if (t[0] == t[N]&& t[1] == t[N + 1]) {
	            cout << t.substr(0, N);
	            return 0;
	     }
	}
	cout << -1 << endl;
}
	

### Prompt

Construct a Cpp code solution to the problem outlined:

Snuke, who loves animals, built a zoo.

There are N animals in this zoo. They are conveniently numbered 1 through N, and arranged in a circle. The animal numbered i (2≤i≤N-1) is adjacent to the animals numbered i-1 and i+1. Also, the animal numbered 1 is adjacent to the animals numbered 2 and N, and the animal numbered N is adjacent to the animals numbered N-1 and 1.

There are two kinds of animals in this zoo: honest sheep that only speak the truth, and lying wolves that only tell lies.

Snuke cannot tell the difference between these two species, and asked each animal the following question: "Are your neighbors of the same species?" The animal numbered i answered s_i. Here, if s_i is `o`, the animal said that the two neighboring animals are of the same species, and if s_i is `x`, the animal said that the two neighboring animals are of different species.

More formally, a sheep answered `o` if the two neighboring animals are both sheep or both wolves, and answered `x` otherwise. Similarly, a wolf answered `x` if the two neighboring animals are both sheep or both wolves, and answered `o` otherwise.

Snuke is wondering whether there is a valid assignment of species to the animals that is consistent with these responses. If there is such an assignment, show one such assignment. Otherwise, print `-1`.

Constraints

* 3 ≤ N ≤ 10^{5}
* s is a string of length N consisting of `o` and `x`.

Input

The input is given from Standard Input in the following format:


N
s


Output

If there does not exist an valid assignment that is consistent with s, print `-1`. Otherwise, print an string t in the following format. The output is considered correct if the assignment described by t is consistent with s.

* t is a string of length N consisting of `S` and `W`.
* If t_i is `S`, it indicates that the animal numbered i is a sheep. If t_i is `W`, it indicates that the animal numbered i is a wolf.

Examples

Input

6
ooxoox


Output

SSSWWS


Input

3
oox


Output

-1


Input

10
oxooxoxoox


Output

SSWWSSSWWS

### Response

```cpp
#include <iostream>
using namespace std;

int main() {
	ios::sync_with_stdio(false);
	int N;
	cin >> N;
	string s, t;
	cin>>s;
	s+=s[0];
	for (int a=0; a<4; a++){
		if (a==0) t="SS";
		else if (a==1) t="SW";
		else if (a==2) t="WS";
		else t="WW";
		for (int i=2; i<=N+1; i++){
			if (t[i-1]=='S'){
				if (s[i-1]=='o'){
					if (t[i-2]=='S') t+='S';
					else t+='W';
				}
				else{
					if(t[i-2]=='S') t+='W';
					else t+='S';
				}
			}
			else{
				if (s[i-1]=='o'){
					if (t[i-2]=='S') t+='W';
					else t+='S';
				}
				else{
					if(t[i-2]=='S') t+='S';
					else t+='W';
				}				
			}

		}
	    if (t[0] == t[N]&& t[1] == t[N + 1]) {
	            cout << t.substr(0, N);
	            return 0;
	     }
	}
	cout << -1 << endl;
}
	

```