#include <bits/stdc++.h>
using namespace std;
int main() {
  string s, x, y;
  long long i, l, k, c, flag;
  cin >> s;
  cin >> k;
  l = s.length();
  c = 0;
  flag = 0;
  if (l % k == 0) {
    for (i = 0; i < l; i++) {
      c++;
      x += s[i];
      y = s[i] + y;
      if (c == l / k) {
        if (x.compare(y) != 0) {
          flag = 1;
          break;
        } else {
          x = "";
          y = "";
          c = 0;
        }
      }
    }
  } else
    flag = 1;
  if (flag)
    cout << "NO" << endl;
  else
    cout << "YES" << endl;
  return 0;
}

### Prompt

Please formulate a cpp solution to the following problem:

While Mike was walking in the subway, all the stuff in his back-bag dropped on the ground. There were several fax messages among them. He concatenated these strings in some order and now he has string s.

<image>

He is not sure if this is his own back-bag or someone else's. He remembered that there were exactly k messages in his own bag, each was a palindrome string and all those strings had the same length.

He asked you to help him and tell him if he has worn his own back-bag. Check if the given string s is a concatenation of k palindromes of the same length.

Input

The first line of input contains string s containing lowercase English letters (1 ≤ |s| ≤ 1000).

The second line contains integer k (1 ≤ k ≤ 1000).

Output

Print "YES"(without quotes) if he has worn his own back-bag or "NO"(without quotes) otherwise.

Examples

Input

saba
2


Output

NO


Input

saddastavvat
2


Output

YES

Note

Palindrome is a string reading the same forward and backward.

In the second sample, the faxes in his back-bag can be "saddas" and "tavvat".

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  string s, x, y;
  long long i, l, k, c, flag;
  cin >> s;
  cin >> k;
  l = s.length();
  c = 0;
  flag = 0;
  if (l % k == 0) {
    for (i = 0; i < l; i++) {
      c++;
      x += s[i];
      y = s[i] + y;
      if (c == l / k) {
        if (x.compare(y) != 0) {
          flag = 1;
          break;
        } else {
          x = "";
          y = "";
          c = 0;
        }
      }
    }
  } else
    flag = 1;
  if (flag)
    cout << "NO" << endl;
  else
    cout << "YES" << endl;
  return 0;
}

```