#include<bits/stdc++.h>
using namespace std;
int main()
{
	int i,j,n,x,s=0;
	scanf("%d",&n);
	for(i=1; i<=n; i++)
	{
		if(i%2==0) continue;
		x=0;
		for(j=1; j<=n; j++)
			if(i%j==0) x++;
		if(x==8) s++;
	}
	printf("%d",s);


	return 0;
}
### Prompt

Create a solution in cpp for the following problem:

The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;
int main()
{
	int i,j,n,x,s=0;
	scanf("%d",&n);
	for(i=1; i<=n; i++)
	{
		if(i%2==0) continue;
		x=0;
		for(j=1; j<=n; j++)
			if(i%j==0) x++;
		if(x==8) s++;
	}
	printf("%d",s);


	return 0;
}
```