#include <iostream>
int main(){
	int n,c=0;
	scanf("%d",&n);
	c+=(n>=105);
	c+=(n>=135);
	c+=(n>=165);
	c+=(n>=189);
	c+=(n>=195);
	printf("%d",c);
    return 0;
}

### Prompt

Please create a solution in Cpp to the following problem:

The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0

### Response

```cpp
#include <iostream>
int main(){
	int n,c=0;
	scanf("%d",&n);
	c+=(n>=105);
	c+=(n>=135);
	c+=(n>=165);
	c+=(n>=189);
	c+=(n>=195);
	printf("%d",c);
    return 0;
}

```