#include<stdio.h>
int main(){
	int S,h,m,s;
	scanf("%d", &S);
	h = S /3600;
	m = S % 3600  / 60;
	s = S % 60;
	printf("%d:%d:%d\n", h,m,s);
}

### Prompt

Construct a cpp code solution to the problem outlined:

Write a program which reads an integer $S$ [second] and converts it to $h:m:s$ where $h$, $m$, $s$ denote hours, minutes (less than 60) and seconds (less than 60) respectively.

Constraints

* $0 \leq S \leq 86400$

Input

An integer $S$ is given in a line.

Output

Print $h$, $m$ and $s$ separated by ':'. You do not need to put '0' for a value, which consists of a digit.

Example

Input

46979


Output

13:2:59

### Response

```cpp
#include<stdio.h>
int main(){
	int S,h,m,s;
	scanf("%d", &S);
	h = S /3600;
	m = S % 3600  / 60;
	s = S % 60;
	printf("%d:%d:%d\n", h,m,s);
}

```