#include <bits/stdc++.h>
using namespace std;

int main() {

    int N,W;
    cin >> N >> W;
    vector<int> dp(W+1,0);
    
    for(int i=0; i<N; i++) {
	int v,w,m;
	cin >> v >> w >> m;

	for(int k=0; m>0; k++) {
	    int num = min(m, (1<<k));
	    m -= num;
	    for(int j=W; j >= num*w; j--) 
		dp[j] = max(dp[j], dp[j-num*w] + num*v);
	}
    }

    int ans = 0;
    for(int x : dp) ans = max(ans,x);
    cout << ans << endl;
    return 0;
}
### Prompt

Your task is to create a CPP solution to the following problem:

You have N items that you want to put them into a knapsack. Item i has value vi, weight wi and limitation mi.

You want to find a subset of items to put such that:

* The total value of the items is as large as possible.
* The items have combined weight at most W, that is capacity of the knapsack.
* You can select at most mi items for ith item.



Find the maximum total value of items in the knapsack.

Constraints

* 1 ≤ N ≤ 100
* 1 ≤ vi ≤ 1,000
* 1 ≤ wi ≤ 1,000
* 1 ≤ mi ≤ 10,000
* 1 ≤ W ≤ 10,000

Input


N W
v1 w1 m1
v2 w2 m2
:
vN wN mN


The first line consists of the integers N and W. In the following N lines, the value, weight and limitation of the i-th item are given.

Output

Print the maximum total values of the items in a line.

Examples

Input

4 8
4 3 2
2 1 1
1 2 4
3 2 2


Output

12


Input

2 100
1 1 100
2 1 50


Output

150

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;

int main() {

    int N,W;
    cin >> N >> W;
    vector<int> dp(W+1,0);
    
    for(int i=0; i<N; i++) {
	int v,w,m;
	cin >> v >> w >> m;

	for(int k=0; m>0; k++) {
	    int num = min(m, (1<<k));
	    m -= num;
	    for(int j=W; j >= num*w; j--) 
		dp[j] = max(dp[j], dp[j-num*w] + num*v);
	}
    }

    int ans = 0;
    for(int x : dp) ans = max(ans,x);
    cout << ans << endl;
    return 0;
}
```