#include<cstdio>
#define LL long long
LL gcd(LL a,LL b)
{
	if(!b) return a;
	return gcd(b,a%b);
}
int main()
{
	LL a,b,g;
	while(~scanf("%lld%lld",&a,&b))
	{
		g=gcd(a,b);
		a*=b;
		printf("%lld %lld\n",g,a/g);
	}
}
### Prompt

Generate a CPP solution to the following problem:

Write a program which computes the greatest common divisor (GCD) and the least common multiple (LCM) of given a and b.

Constraints

* 0 < a, b ≤ 2,000,000,000
* LCM(a, b) ≤ 2,000,000,000
* The number of data sets ≤ 50

Input

Input consists of several data sets. Each data set contains a and b separated by a single space in a line. The input terminates with EOF.

Output

For each data set, print GCD and LCM separated by a single space in a line.

Example

Input

8 6
50000000 30000000


Output

2 24
10000000 150000000

### Response

```cpp
#include<cstdio>
#define LL long long
LL gcd(LL a,LL b)
{
	if(!b) return a;
	return gcd(b,a%b);
}
int main()
{
	LL a,b,g;
	while(~scanf("%lld%lld",&a,&b))
	{
		g=gcd(a,b);
		a*=b;
		printf("%lld %lld\n",g,a/g);
	}
}
```