#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <iostream>
#include <algorithm>
#include <stack>
#include <queue>
#include <math.h>
#include <set>
#include <map>
#include <string>
#include <list>
#include <string.h>
#include <functional>
//#include <Windows.h>
//#include "Library.h"
//#include "Math.h"
using namespace std;
typedef long long int ll; typedef pair <int, int> P; typedef vector <int> vecint;
//const int INF = 2000000000;
const double EPS = 10e-9;
const int mvm = 1000001;
int v[100], w[100], m[100];
int dp[10001];
int main()
{
	int n, W; cin >> n >> W;
	memset(dp, 0, sizeof(dp));
	for (int i = 0; i < n; i++)
		cin >> v[i] >> w[i] >> m[i];
	for (int i = 0; i < n; i++)
	{
		for (int a = 0; a < w[i]; a++)
		{
			deque <int> deq, deqi;
			{
				for (int j = 0; j * w[i] + a <= W; j++)
				{
					int val = dp[a + j * w[i]] - j * v[i];
					while (!deq.empty() && val >= deq.back()) { deq.pop_back(); deqi.pop_back(); }
					deq.push_back(val);
					deqi.push_back(j);
					dp[a + j * w[i]] = deq.front() + j * v[i];
					if (j - deqi.front() == m[i]) { deqi.pop_front(); deq.pop_front(); }
				}
			}
		}
	}
	cout << dp[W] << endl;
	return 0;
}
### Prompt

Please create a solution in cpp to the following problem:

You have N items that you want to put them into a knapsack. Item i has value vi, weight wi and limitation mi.

You want to find a subset of items to put such that:

* The total value of the items is as large as possible.
* The items have combined weight at most W, that is capacity of the knapsack.
* You can select at most mi items for ith item.



Find the maximum total value of items in the knapsack.

Constraints

* 1 ≤ N ≤ 100
* 1 ≤ vi ≤ 1,000
* 1 ≤ wi ≤ 1,000
* 1 ≤ mi ≤ 10,000
* 1 ≤ W ≤ 10,000

Input


N W
v1 w1 m1
v2 w2 m2
:
vN wN mN


The first line consists of the integers N and W. In the following N lines, the value, weight and limitation of the i-th item are given.

Output

Print the maximum total values of the items in a line.

Examples

Input

4 8
4 3 2
2 1 1
1 2 4
3 2 2


Output

12


Input

2 100
1 1 100
2 1 50


Output

150

### Response

```cpp
#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <iostream>
#include <algorithm>
#include <stack>
#include <queue>
#include <math.h>
#include <set>
#include <map>
#include <string>
#include <list>
#include <string.h>
#include <functional>
//#include <Windows.h>
//#include "Library.h"
//#include "Math.h"
using namespace std;
typedef long long int ll; typedef pair <int, int> P; typedef vector <int> vecint;
//const int INF = 2000000000;
const double EPS = 10e-9;
const int mvm = 1000001;
int v[100], w[100], m[100];
int dp[10001];
int main()
{
	int n, W; cin >> n >> W;
	memset(dp, 0, sizeof(dp));
	for (int i = 0; i < n; i++)
		cin >> v[i] >> w[i] >> m[i];
	for (int i = 0; i < n; i++)
	{
		for (int a = 0; a < w[i]; a++)
		{
			deque <int> deq, deqi;
			{
				for (int j = 0; j * w[i] + a <= W; j++)
				{
					int val = dp[a + j * w[i]] - j * v[i];
					while (!deq.empty() && val >= deq.back()) { deq.pop_back(); deqi.pop_back(); }
					deq.push_back(val);
					deqi.push_back(j);
					dp[a + j * w[i]] = deq.front() + j * v[i];
					if (j - deqi.front() == m[i]) { deqi.pop_front(); deq.pop_front(); }
				}
			}
		}
	}
	cout << dp[W] << endl;
	return 0;
}
```