#include <iostream>
using namespace std;
string s;
int len, last[26], a[26], ans;
int main()
{
    cin >> s;
    len = ans = s.length();
    for (int i = 0; i < len; ++i) {
        a[s[i] - 'a'] = max(a[s[i] - 'a'], i - last[s[i] - 'a']);
        last[s[i] - 'a'] = i + 1;
    }
    for (int i = 0; i < 26; ++i) {
        ans = min(ans, max(a[i], len - last[i]));
    }
    cout << ans << endl;
    return 0;
}
### Prompt

Please formulate a cpp solution to the following problem:

Snuke can change a string t of length N into a string t' of length N - 1 under the following rule:

* For each i (1 ≤ i ≤ N - 1), the i-th character of t' must be either the i-th or (i + 1)-th character of t.



There is a string s consisting of lowercase English letters. Snuke's objective is to apply the above operation to s repeatedly so that all the characters in s are the same. Find the minimum necessary number of operations.

Constraints

* 1 ≤ |s| ≤ 100
* s consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:


s


Output

Print the minimum necessary number of operations to achieve the objective.

Examples

Input

serval


Output

3


Input

jackal


Output

2


Input

zzz


Output

0


Input

whbrjpjyhsrywlqjxdbrbaomnw


Output

8

### Response

```cpp
#include <iostream>
using namespace std;
string s;
int len, last[26], a[26], ans;
int main()
{
    cin >> s;
    len = ans = s.length();
    for (int i = 0; i < len; ++i) {
        a[s[i] - 'a'] = max(a[s[i] - 'a'], i - last[s[i] - 'a']);
        last[s[i] - 'a'] = i + 1;
    }
    for (int i = 0; i < 26; ++i) {
        ans = min(ans, max(a[i], len - last[i]));
    }
    cout << ans << endl;
    return 0;
}
```