#include <bits/stdc++.h>
using namespace std;
const double pi = acos(0.0) * 2.0;
const double eps = 1e-12;
const int step[8][2] = {{1, 0}, {-1, 0}, {0, 1},  {0, -1},
                        {1, 1}, {1, -1}, {-1, 1}, {-1, -1}};
template <class T>
inline T abs1(T a) {
  return a < 0 ? -a : a;
}
template <class T>
inline T max1(T a, T b, T c = -1234567, T d = -1234567) {
  T ans = a > b ? a : b;
  if (c != -1234567) ans = max1(ans, c);
  if (d != -1234567) ans = max1(ans, d);
  return ans;
}
template <class T>
inline T min1(T a, T b, T c = -1234567, T d = -1234567) {
  T ans = a < b ? a : b;
  if (c != -1234567) ans = min(ans, c);
  if (d != -1234567) ans = min(ans, d);
  return ans;
}
template <class T>
inline T gcd1(T a, T b) {
  if (a < b) swap(a, b);
  if (a % b == 0) return b;
  return gcd1(b, a % b);
}
template <class T>
inline T lb(T num) {
  return num & (-num);
}
inline int jud(double a, double b) {
  if (abs1(a - b) < eps) return 0;
  if (a < b) return -1;
  return 1;
}
template <typename it, typename t1>
inline int find(t1 val, it a, int na, bool f_small = 1, bool f_lb = 1) {
  if (na == 1) return 0;
  int be = 0, en = na - 1;
  if (*a <= *(a + na - 1)) {
    if (f_lb == 0)
      while (be < en) {
        int mid = (be + en + 1) / 2;
        if (jud(*(a + mid), val) != 1)
          be = mid;
        else
          en = mid - 1;
      }
    else
      while (be < en) {
        int mid = (be + en) / 2;
        if (jud(*(a + mid), val) != -1)
          en = mid;
        else
          be = mid + 1;
      }
    if (f_small && jud(*(a + be), val) == 1 && be != 0) be--;
    if (!f_small && jud(*(a + be), val) == -1 && be != na - 1) be++;
  } else {
    if (f_lb)
      while (be < en) {
        int mid = (be + en + 1) / 2;
        if (jud(*(a + mid), val) != -1)
          be = mid;
        else
          en = mid - 1;
      }
    else
      while (be < en) {
        int mid = (be + en) / 2;
        if (jud(*(a + mid), val) != 1)
          en = mid;
        else
          be = mid + 1;
      }
    if (!f_small && jud(*(a + be), val) == -1 && be != 0) be--;
    if (f_small && jud(*(a + be), val) == 1 && be != na - 1) be++;
  }
  return be;
}
inline int bitnum(unsigned long long nValue) {
  nValue = ((0xaaaaaaaaaaaaaaaaull & nValue) >> 1) +
           (0x5555555555555555ull & nValue);
  nValue = ((0xccccccccccccccccull & nValue) >> 2) +
           (0x3333333333333333ull & nValue);
  nValue = ((0xf0f0f0f0f0f0f0f0ull & nValue) >> 4) +
           (0x0f0f0f0f0f0f0f0full & nValue);
  nValue = ((0xff00ff00ff00ff00ull & nValue) >> 8) +
           (0x00ff00ff00ff00ffull & nValue);
  nValue = ((0xffff0000ffff0000ull & nValue) >> 16) +
           (0x0000ffff0000ffffull & nValue);
  nValue = ((0xffffffff00000000ull & nValue) >> 32) +
           (0x00000000ffffffffull & nValue);
  return nValue;
}
long long pow(long long n, long long m, long long mod = 0) {
  long long ans = 1;
  long long k = n;
  while (m) {
    if (m & 1) {
      ans *= k;
      if (mod) ans %= mod;
    }
    k *= k;
    if (mod) k %= mod;
    m >>= 1;
  }
  return ans;
}
const int maxn = 11110;
pair<int, int> co[maxn];
int can(int a, int b) {
  if (b == 0) {
    if (a == 0)
      return -1;
    else
      return 0;
  } else {
    if (a / b >= 0 && a % b == 0)
      return a / b;
    else
      return 0;
  }
}
int main() {
  pair<int, int> final, ans;
  scanf("%d%d", &ans.first, &ans.second);
  char str[maxn];
  scanf("%s", str);
  int l = strlen(str);
  for (int i = 0; i < l; i++) {
    pair<int, int> dir;
    if (str[i] == 'R')
      dir.first = 1, dir.second = 0;
    else if (str[i] == 'U')
      dir.first = 0, dir.second = 1;
    else if (str[i] == 'L')
      dir.first = -1, dir.second = 0;
    else
      dir.first = 0, dir.second = -1;
    co[i + 1].first = co[i].first + dir.first;
    co[i + 1].second = co[i].second + dir.second;
  }
  bool f = 0;
  for (int i = 0; i < l; i++) {
    pair<int, int> k;
    k.first = ans.first - co[i].first;
    k.second = ans.second - co[i].second;
    int a, b;
    if (k.first == 0 && k.second == 0)
      f = 1;
    else if ((a = can(k.first, co[l].first)) &&
             (b = can(k.second, co[l].second))) {
      if (a == -1 || b == -1) f = 1;
      if (a == b) f = 1;
    }
  }
  if (f)
    cout << "Yes" << endl;
  else
    cout << "No" << endl;
  return 0;
}

### Prompt

Construct a Cpp code solution to the problem outlined:

Fox Ciel has a robot on a 2D plane. Initially it is located in (0, 0). Fox Ciel code a command to it. The command was represented by string s. Each character of s is one move operation. There are four move operations at all:

  * 'U': go up, (x, y)  →  (x, y+1); 
  * 'D': go down, (x, y)  →  (x, y-1); 
  * 'L': go left, (x, y)  →  (x-1, y); 
  * 'R': go right, (x, y)  →  (x+1, y). 



The robot will do the operations in s from left to right, and repeat it infinite times. Help Fox Ciel to determine if after some steps the robot will located in (a, b).

Input

The first line contains two integers a and b, ( - 109 ≤ a, b ≤ 109). The second line contains a string s (1 ≤ |s| ≤ 100, s only contains characters 'U', 'D', 'L', 'R') — the command.

Output

Print "Yes" if the robot will be located at (a, b), and "No" otherwise.

Examples

Input

2 2
RU


Output

Yes


Input

1 2
RU


Output

No


Input

-1 1000000000
LRRLU


Output

Yes


Input

0 0
D


Output

Yes

Note

In the first and second test case, command string is "RU", so the robot will go right, then go up, then right, and then up and so on.

The locations of its moves are (0, 0)  →  (1, 0)  →  (1, 1)  →  (2, 1)  →  (2, 2)  →  ...

So it can reach (2, 2) but not (1, 2).

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
const double pi = acos(0.0) * 2.0;
const double eps = 1e-12;
const int step[8][2] = {{1, 0}, {-1, 0}, {0, 1},  {0, -1},
                        {1, 1}, {1, -1}, {-1, 1}, {-1, -1}};
template <class T>
inline T abs1(T a) {
  return a < 0 ? -a : a;
}
template <class T>
inline T max1(T a, T b, T c = -1234567, T d = -1234567) {
  T ans = a > b ? a : b;
  if (c != -1234567) ans = max1(ans, c);
  if (d != -1234567) ans = max1(ans, d);
  return ans;
}
template <class T>
inline T min1(T a, T b, T c = -1234567, T d = -1234567) {
  T ans = a < b ? a : b;
  if (c != -1234567) ans = min(ans, c);
  if (d != -1234567) ans = min(ans, d);
  return ans;
}
template <class T>
inline T gcd1(T a, T b) {
  if (a < b) swap(a, b);
  if (a % b == 0) return b;
  return gcd1(b, a % b);
}
template <class T>
inline T lb(T num) {
  return num & (-num);
}
inline int jud(double a, double b) {
  if (abs1(a - b) < eps) return 0;
  if (a < b) return -1;
  return 1;
}
template <typename it, typename t1>
inline int find(t1 val, it a, int na, bool f_small = 1, bool f_lb = 1) {
  if (na == 1) return 0;
  int be = 0, en = na - 1;
  if (*a <= *(a + na - 1)) {
    if (f_lb == 0)
      while (be < en) {
        int mid = (be + en + 1) / 2;
        if (jud(*(a + mid), val) != 1)
          be = mid;
        else
          en = mid - 1;
      }
    else
      while (be < en) {
        int mid = (be + en) / 2;
        if (jud(*(a + mid), val) != -1)
          en = mid;
        else
          be = mid + 1;
      }
    if (f_small && jud(*(a + be), val) == 1 && be != 0) be--;
    if (!f_small && jud(*(a + be), val) == -1 && be != na - 1) be++;
  } else {
    if (f_lb)
      while (be < en) {
        int mid = (be + en + 1) / 2;
        if (jud(*(a + mid), val) != -1)
          be = mid;
        else
          en = mid - 1;
      }
    else
      while (be < en) {
        int mid = (be + en) / 2;
        if (jud(*(a + mid), val) != 1)
          en = mid;
        else
          be = mid + 1;
      }
    if (!f_small && jud(*(a + be), val) == -1 && be != 0) be--;
    if (f_small && jud(*(a + be), val) == 1 && be != na - 1) be++;
  }
  return be;
}
inline int bitnum(unsigned long long nValue) {
  nValue = ((0xaaaaaaaaaaaaaaaaull & nValue) >> 1) +
           (0x5555555555555555ull & nValue);
  nValue = ((0xccccccccccccccccull & nValue) >> 2) +
           (0x3333333333333333ull & nValue);
  nValue = ((0xf0f0f0f0f0f0f0f0ull & nValue) >> 4) +
           (0x0f0f0f0f0f0f0f0full & nValue);
  nValue = ((0xff00ff00ff00ff00ull & nValue) >> 8) +
           (0x00ff00ff00ff00ffull & nValue);
  nValue = ((0xffff0000ffff0000ull & nValue) >> 16) +
           (0x0000ffff0000ffffull & nValue);
  nValue = ((0xffffffff00000000ull & nValue) >> 32) +
           (0x00000000ffffffffull & nValue);
  return nValue;
}
long long pow(long long n, long long m, long long mod = 0) {
  long long ans = 1;
  long long k = n;
  while (m) {
    if (m & 1) {
      ans *= k;
      if (mod) ans %= mod;
    }
    k *= k;
    if (mod) k %= mod;
    m >>= 1;
  }
  return ans;
}
const int maxn = 11110;
pair<int, int> co[maxn];
int can(int a, int b) {
  if (b == 0) {
    if (a == 0)
      return -1;
    else
      return 0;
  } else {
    if (a / b >= 0 && a % b == 0)
      return a / b;
    else
      return 0;
  }
}
int main() {
  pair<int, int> final, ans;
  scanf("%d%d", &ans.first, &ans.second);
  char str[maxn];
  scanf("%s", str);
  int l = strlen(str);
  for (int i = 0; i < l; i++) {
    pair<int, int> dir;
    if (str[i] == 'R')
      dir.first = 1, dir.second = 0;
    else if (str[i] == 'U')
      dir.first = 0, dir.second = 1;
    else if (str[i] == 'L')
      dir.first = -1, dir.second = 0;
    else
      dir.first = 0, dir.second = -1;
    co[i + 1].first = co[i].first + dir.first;
    co[i + 1].second = co[i].second + dir.second;
  }
  bool f = 0;
  for (int i = 0; i < l; i++) {
    pair<int, int> k;
    k.first = ans.first - co[i].first;
    k.second = ans.second - co[i].second;
    int a, b;
    if (k.first == 0 && k.second == 0)
      f = 1;
    else if ((a = can(k.first, co[l].first)) &&
             (b = can(k.second, co[l].second))) {
      if (a == -1 || b == -1) f = 1;
      if (a == b) f = 1;
    }
  }
  if (f)
    cout << "Yes" << endl;
  else
    cout << "No" << endl;
  return 0;
}

```