#include<stdio.h>
#define LL long long
LL GCD(LL a,LL b)
{
    return b==0?a:GCD(b,a%b);
}
int main()
{
    LL a,b;
    while(scanf("%lld%lld",&a,&b)!=EOF)
    {
        LL c=GCD(a,b);
        printf("%lld %lld\n",c,a/c*b);
    }
    return 0;
}
### Prompt

Your challenge is to write a Cpp solution to the following problem:

Write a program which computes the greatest common divisor (GCD) and the least common multiple (LCM) of given a and b.

Constraints

* 0 < a, b ≤ 2,000,000,000
* LCM(a, b) ≤ 2,000,000,000
* The number of data sets ≤ 50

Input

Input consists of several data sets. Each data set contains a and b separated by a single space in a line. The input terminates with EOF.

Output

For each data set, print GCD and LCM separated by a single space in a line.

Example

Input

8 6
50000000 30000000


Output

2 24
10000000 150000000

### Response

```cpp
#include<stdio.h>
#define LL long long
LL GCD(LL a,LL b)
{
    return b==0?a:GCD(b,a%b);
}
int main()
{
    LL a,b;
    while(scanf("%lld%lld",&a,&b)!=EOF)
    {
        LL c=GCD(a,b);
        printf("%lld %lld\n",c,a/c*b);
    }
    return 0;
}
```