#include<iostream>
using namespace std;
int main()
{
long n,i,j,*nn;
for(;;){
cin>>n;
if(cin.eof())break;
nn=new long [n+1];
nn[1]=0;nn[2]=1;
for(i=3;i<=n;i+=2)nn[i]=1;
for(i=4;i<=n;i+=2)nn[i]=0;
for(i=3;i*i<=n;){
for(j=i;i*j<=n;j+=2)nn[i*j]=0;
i++;while(nn[i]==0)i++;
}
for(i=2,j=0;i<=n;i++)if(nn[i]==1)j++;
cout<<j<<endl;
delete [] nn;
}
return 0;
}
### Prompt

Please provide a Cpp coded solution to the problem described below:

Write a program which reads an integer n and prints the number of prime numbers which are less than or equal to n. A prime number is a natural number which has exactly two distinct natural number divisors: 1 and itself. For example, the first four prime numbers are: 2, 3, 5 and 7.



Input

Input consists of several datasets. Each dataset has an integer n (1 ≤ n ≤ 999,999) in a line.

The number of datasets is less than or equal to 30.

Output

For each dataset, prints the number of prime numbers.

Example

Input

10
3
11


Output

4
2
5

### Response

```cpp
#include<iostream>
using namespace std;
int main()
{
long n,i,j,*nn;
for(;;){
cin>>n;
if(cin.eof())break;
nn=new long [n+1];
nn[1]=0;nn[2]=1;
for(i=3;i<=n;i+=2)nn[i]=1;
for(i=4;i<=n;i+=2)nn[i]=0;
for(i=3;i*i<=n;){
for(j=i;i*j<=n;j+=2)nn[i*j]=0;
i++;while(nn[i]==0)i++;
}
for(i=2,j=0;i<=n;i++)if(nn[i]==1)j++;
cout<<j<<endl;
delete [] nn;
}
return 0;
}
```