#include "bits/stdc++.h"

using namespace std;

int main (){
	int n;
	cin >> n;
	int a[45];
	a[0] = 1;
	a[1] = 1;
	for (int i = 2;i<=n;i++){
		a[i] = a[i - 1] + a[i - 2];
	}
	cout << a[n]<<endl;

	return 0;
}
### Prompt

In Cpp, your task is to solve the following problem:

Write a program which prints $n$-th fibonacci number for a given integer $n$. The $n$-th fibonacci number is defined by the following recursive formula:

\begin{equation*} fib(n)= \left \\{ \begin{array}{ll} 1 & (n = 0) \\\ 1 & (n = 1) \\\ fib(n - 1) + fib(n - 2) & \\\ \end{array} \right. \end{equation*}

Constraints

* $0 \leq n \leq 44$

Input

An integer $n$ is given.

Example

Input

3


Output

3

### Response

```cpp
#include "bits/stdc++.h"

using namespace std;

int main (){
	int n;
	cin >> n;
	int a[45];
	a[0] = 1;
	a[1] = 1;
	for (int i = 2;i<=n;i++){
		a[i] = a[i - 1] + a[i - 2];
	}
	cout << a[n]<<endl;

	return 0;
}
```