#include<stdio.h>
int n,k,i;
int cade[100001];
int main(void){
	while(1){
		scanf("%d %d",&n,&k);
		if(n==0 && k==0){
			break;
		}
		for(i=0;i<100001;i++){
			cade[i]=0;
		}
		int a,flg=0;
		for(i=0;i<k;i++){
			scanf("%d",&a);
			if(a==0){
				flg=1;
			}
			else {
				cade[a]=1;
			}
		}
		for(i=n;i>=1;i--){
			if(cade[i]>=1 && cade[i-1]>=1 && i-1!=0){
				cade[i-1]=cade[i]+1;
			}
		}
		for(i=1;i<n;i++){
			if(cade[i]>0 && cade[i+1]!=0){
				cade[i+1]=cade[i];
			}
		}
		int max=0;
		for(i=1;i<=n;i++){
			if(max<cade[i]){
				max=cade[i];
			}
		}
		if(flg==1){
			for(i=1;i<n;i++){
				if(cade[i]==0 && cade[i+1]>0){
					if(max<cade[i-1]+cade[i+1]){
						max=cade[i-1]+cade[i+1]+1;
					}
				}
			}
		}
		printf("%d\n",max);
	}	
	return 0;
}
### Prompt

Generate a Cpp solution to the following problem:

problem

There are n cards with one integer from 1 to n and one blank card. Of these n + 1 cards, k cards are given, but 1 ≤ k ≤ n. You can write one integer from 1 to n on a blank card. I want to make a continuous sequence of integers as long as possible with just a given card.

Write a program that outputs the maximum length of a contiguous sequence of integers that can be made from a given card when the given card is entered.



input

The input consists of multiple datasets. Each dataset is given in the following format. The input ends on a line containing two zeros.

On the first line, two integers n (1 ≤ n ≤ 100000) and k (1 ≤ k ≤ n) are written in this order, separated by one blank. The following k line contains one integer. Written one by one, representing the integers written on the given k cards. Blank cards are represented by 0.

Of the scoring data, 40% of the points are 1 ≤ n ≤ 1000, 1 ≤ k ≤ 500, 20% of the points are 1 ≤ n ≤ 60000, 1 ≤ k ≤ 50000. Satisfy 1 ≤ n ≤ 100000, 1 ≤ k ≤ 100000.

The number of datasets does not exceed 5.

output

Outputs an integer on one line for each dataset.

Examples

Input

7 5
6
2
4
7
1
7 5
6
2
0
4
7
0 0


Output

2
4


Input

None


Output

None

### Response

```cpp
#include<stdio.h>
int n,k,i;
int cade[100001];
int main(void){
	while(1){
		scanf("%d %d",&n,&k);
		if(n==0 && k==0){
			break;
		}
		for(i=0;i<100001;i++){
			cade[i]=0;
		}
		int a,flg=0;
		for(i=0;i<k;i++){
			scanf("%d",&a);
			if(a==0){
				flg=1;
			}
			else {
				cade[a]=1;
			}
		}
		for(i=n;i>=1;i--){
			if(cade[i]>=1 && cade[i-1]>=1 && i-1!=0){
				cade[i-1]=cade[i]+1;
			}
		}
		for(i=1;i<n;i++){
			if(cade[i]>0 && cade[i+1]!=0){
				cade[i+1]=cade[i];
			}
		}
		int max=0;
		for(i=1;i<=n;i++){
			if(max<cade[i]){
				max=cade[i];
			}
		}
		if(flg==1){
			for(i=1;i<n;i++){
				if(cade[i]==0 && cade[i+1]>0){
					if(max<cade[i-1]+cade[i+1]){
						max=cade[i-1]+cade[i+1]+1;
					}
				}
			}
		}
		printf("%d\n",max);
	}	
	return 0;
}
```