#include<bits/stdc++.h>
#define ll long long
#define re register
#define cs const

using std::cerr;
using std::cout;

cs int N=1e6+7;

int n,c1;
int ans;
char s[N];

void Main(){
	scanf("%d%s",&n,s+1);
	for(int re i=1;i<=n;++i)s[i]-=49;
	for(int re i=1;i<=n;++i)
		if(s[i]==1){
			c1=true;
			ans^=((n-1)^(i-1)^(n-i))==0;
		}
	if(ans)cout<<1<<"\n";
	else if(c1)cout<<0<<"\n";
	else {
		ans=0;
		for(int re i=1;i<=n;++i)
			if(s[i]==2)ans^=((n-1)^(i-1)^(n-i))==0;
		cout<<(ans*2)<<"\n";
	}
}

inline void file(){
#ifdef zxyoi
	freopen("B.in","r",stdin);
#endif
}signed main(){file();Main();return 0;}
### Prompt

Generate a cpp solution to the following problem:

Given is a sequence of N digits a_1a_2\ldots a_N, where each element is 1, 2, or 3. Let x_{i,j} defined as follows:

* x_{1,j} := a_j \quad (1 \leq j \leq N)
* x_{i,j} := | x_{i-1,j} - x_{i-1,j+1} | \quad (2 \leq i \leq N and 1 \leq j \leq N+1-i)



Find x_{N,1}.

Constraints

* 2 \leq N \leq 10^6
* a_i = 1,2,3 (1 \leq i \leq N)

Input

Input is given from Standard Input in the following format:


N
a_1a_2\ldotsa_N


Output

Print x_{N,1}.

Examples

Input

4
1231


Output

1


Input

10
2311312312


Output

0

### Response

```cpp
#include<bits/stdc++.h>
#define ll long long
#define re register
#define cs const

using std::cerr;
using std::cout;

cs int N=1e6+7;

int n,c1;
int ans;
char s[N];

void Main(){
	scanf("%d%s",&n,s+1);
	for(int re i=1;i<=n;++i)s[i]-=49;
	for(int re i=1;i<=n;++i)
		if(s[i]==1){
			c1=true;
			ans^=((n-1)^(i-1)^(n-i))==0;
		}
	if(ans)cout<<1<<"\n";
	else if(c1)cout<<0<<"\n";
	else {
		ans=0;
		for(int re i=1;i<=n;++i)
			if(s[i]==2)ans^=((n-1)^(i-1)^(n-i))==0;
		cout<<(ans*2)<<"\n";
	}
}

inline void file(){
#ifdef zxyoi
	freopen("B.in","r",stdin);
#endif
}signed main(){file();Main();return 0;}
```