#include <iostream> 

using namespace std;
int main()
{
	int f[100];
	int n;
	cin >> n;
	f[0] = 1;
	f[1] = 1;
	for(int i = 0; i < n; i++)
	{
		f[i+2] = f[i+1] + f[i];
	}
	cout << f[n] << endl;
    return 0;
}

### Prompt

Please formulate a cpp solution to the following problem:

Write a program which prints $n$-th fibonacci number for a given integer $n$. The $n$-th fibonacci number is defined by the following recursive formula:

\begin{equation*} fib(n)= \left \\{ \begin{array}{ll} 1 & (n = 0) \\\ 1 & (n = 1) \\\ fib(n - 1) + fib(n - 2) & \\\ \end{array} \right. \end{equation*}

Constraints

* $0 \leq n \leq 44$

Input

An integer $n$ is given.

Example

Input

3


Output

3

### Response

```cpp
#include <iostream> 

using namespace std;
int main()
{
	int f[100];
	int n;
	cin >> n;
	f[0] = 1;
	f[1] = 1;
	for(int i = 0; i < n; i++)
	{
		f[i+2] = f[i+1] + f[i];
	}
	cout << f[n] << endl;
    return 0;
}

```