#include<iostream>
#include<string.h>
int main(){int m=1,n=999999,o,c=n/2+1,d;bool*v=new bool[c];for(memset(v,1,c);m<499;m++)for(o=m*2+1,d=o*3;v[m]&&d<n+1;d+=o*2)v[d/2]=0;for(;!(std::cin>>n).eof();printf("%d\n",c))for(c=n-->1,m=1;m<n/2+1;)c+=v[m++];delete[]v;}
### Prompt

Please create a solution in cpp to the following problem:

Write a program which reads an integer n and prints the number of prime numbers which are less than or equal to n. A prime number is a natural number which has exactly two distinct natural number divisors: 1 and itself. For example, the first four prime numbers are: 2, 3, 5 and 7.



Input

Input consists of several datasets. Each dataset has an integer n (1 ≤ n ≤ 999,999) in a line.

The number of datasets is less than or equal to 30.

Output

For each dataset, prints the number of prime numbers.

Example

Input

10
3
11


Output

4
2
5

### Response

```cpp
#include<iostream>
#include<string.h>
int main(){int m=1,n=999999,o,c=n/2+1,d;bool*v=new bool[c];for(memset(v,1,c);m<499;m++)for(o=m*2+1,d=o*3;v[m]&&d<n+1;d+=o*2)v[d/2]=0;for(;!(std::cin>>n).eof();printf("%d\n",c))for(c=n-->1,m=1;m<n/2+1;)c+=v[m++];delete[]v;}
```