#include <iostream>
#include <memory.h>
using namespace std;
int main()
{
	bool prime[1000010];
	memset(prime,1,1000010);
	prime[0]=prime[1]=0;
	int i,j,n,sum;
	for (i=2;i<1000000;i++)
	{
		if (prime[i])
		{
			for (j=2;i*j<1000000;j++)
			{
				prime[i*j]=false;
			}
		}
	}
	while(cin>>n)
	{
		sum=0;
		for(i=2;i<=n;i++)
		{
			sum+=prime[i];
		}
		cout<<sum<<endl;

	}	
	return 0;
}
### Prompt

In cpp, your task is to solve the following problem:

Write a program which reads an integer n and prints the number of prime numbers which are less than or equal to n. A prime number is a natural number which has exactly two distinct natural number divisors: 1 and itself. For example, the first four prime numbers are: 2, 3, 5 and 7.



Input

Input consists of several datasets. Each dataset has an integer n (1 ≤ n ≤ 999,999) in a line.

The number of datasets is less than or equal to 30.

Output

For each dataset, prints the number of prime numbers.

Example

Input

10
3
11


Output

4
2
5

### Response

```cpp
#include <iostream>
#include <memory.h>
using namespace std;
int main()
{
	bool prime[1000010];
	memset(prime,1,1000010);
	prime[0]=prime[1]=0;
	int i,j,n,sum;
	for (i=2;i<1000000;i++)
	{
		if (prime[i])
		{
			for (j=2;i*j<1000000;j++)
			{
				prime[i*j]=false;
			}
		}
	}
	while(cin>>n)
	{
		sum=0;
		for(i=2;i<=n;i++)
		{
			sum+=prime[i];
		}
		cout<<sum<<endl;

	}	
	return 0;
}
```