#include <iostream>
using namespace std;

int main() {
	int n,k,m;
	bool nu[100001]={};
	while(1){
		cin >> n >> k;
		if(n==0){return 0;}
		for(int i=0;i<=n;i++){
			nu[i]=false;
		}
		for(int i=0;i<k;i++){
			cin >> m;
			nu[m]=true;
		}
		int s=0,ws=0,ms=0,mws=0;
		for(int i=1;i<=n;i++){
			if(nu[i]){
				s++;
				ws++;
			}else{
				if(s>ms){ms=s;}
				if(ws>mws){mws=ws;}
				ws=s+1;
				s=0;
			}
		}
		if(s>ms){ms=s;}
		if(ws>mws){mws=ws;}
		if(nu[0]){
			cout << mws << endl;
		}else{
			cout << ms << endl;
		}
	}
}
### Prompt

Your challenge is to write a CPP solution to the following problem:

problem

There are n cards with one integer from 1 to n and one blank card. Of these n + 1 cards, k cards are given, but 1 ≤ k ≤ n. You can write one integer from 1 to n on a blank card. I want to make a continuous sequence of integers as long as possible with just a given card.

Write a program that outputs the maximum length of a contiguous sequence of integers that can be made from a given card when the given card is entered.



input

The input consists of multiple datasets. Each dataset is given in the following format. The input ends on a line containing two zeros.

On the first line, two integers n (1 ≤ n ≤ 100000) and k (1 ≤ k ≤ n) are written in this order, separated by one blank. The following k line contains one integer. Written one by one, representing the integers written on the given k cards. Blank cards are represented by 0.

Of the scoring data, 40% of the points are 1 ≤ n ≤ 1000, 1 ≤ k ≤ 500, 20% of the points are 1 ≤ n ≤ 60000, 1 ≤ k ≤ 50000. Satisfy 1 ≤ n ≤ 100000, 1 ≤ k ≤ 100000.

The number of datasets does not exceed 5.

output

Outputs an integer on one line for each dataset.

Examples

Input

7 5
6
2
4
7
1
7 5
6
2
0
4
7
0 0


Output

2
4


Input

None


Output

None

### Response

```cpp
#include <iostream>
using namespace std;

int main() {
	int n,k,m;
	bool nu[100001]={};
	while(1){
		cin >> n >> k;
		if(n==0){return 0;}
		for(int i=0;i<=n;i++){
			nu[i]=false;
		}
		for(int i=0;i<k;i++){
			cin >> m;
			nu[m]=true;
		}
		int s=0,ws=0,ms=0,mws=0;
		for(int i=1;i<=n;i++){
			if(nu[i]){
				s++;
				ws++;
			}else{
				if(s>ms){ms=s;}
				if(ws>mws){mws=ws;}
				ws=s+1;
				s=0;
			}
		}
		if(s>ms){ms=s;}
		if(ws>mws){mws=ws;}
		if(nu[0]){
			cout << mws << endl;
		}else{
			cout << ms << endl;
		}
	}
}
```