#include <bits/stdc++.h>
using namespace std;
int main() {
  double y;
  int x = 0, n, m, n1, j = 1;
  scanf("%d", &n);
  for (int i = 0; i < n; i++) {
    scanf("%d", &m);
    if (j == 1 && m < 0) {
      n1 = m;
      j = 0;
    }
    if (n1 <= m && m < 0) {
      n1 = m;
    } else {
      y = (int)sqrt((m));
      if (y * y != m) {
        if (x < m) {
          x = m;
        }
      }
    }
  }
  if (x != 0)
    printf("%d\n", x);
  else
    printf("%d\n", n1);
  return 0;
}

### Prompt

Please formulate a CPP solution to the following problem:

Given an array a1, a2, ..., an of n integers, find the largest number in the array that is not a perfect square.

A number x is said to be a perfect square if there exists an integer y such that x = y2.

Input

The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of elements in the array.

The second line contains n integers a1, a2, ..., an ( - 106 ≤ ai ≤ 106) — the elements of the array.

It is guaranteed that at least one element of the array is not a perfect square.

Output

Print the largest number in the array which is not a perfect square. It is guaranteed that an answer always exists.

Examples

Input

2
4 2


Output

2


Input

8
1 2 4 8 16 32 64 576


Output

32

Note

In the first sample case, 4 is a perfect square, so the largest number in the array that is not a perfect square is 2.

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  double y;
  int x = 0, n, m, n1, j = 1;
  scanf("%d", &n);
  for (int i = 0; i < n; i++) {
    scanf("%d", &m);
    if (j == 1 && m < 0) {
      n1 = m;
      j = 0;
    }
    if (n1 <= m && m < 0) {
      n1 = m;
    } else {
      y = (int)sqrt((m));
      if (y * y != m) {
        if (x < m) {
          x = m;
        }
      }
    }
  }
  if (x != 0)
    printf("%d\n", x);
  else
    printf("%d\n", n1);
  return 0;
}

```