#include<cstdio>
#include<cstring>
#include<algorithm>
#include<cmath>
#include<map>
#include<vector>
#include<set>
#define SF scanf
#define PF printf
#define MAXN 3010
#define MOD 1000000007
using namespace std;
typedef long long ll;
ll dp[MAXN][MAXN];
int n,m;
char s[MAXN];
int endx[MAXN],pre[MAXN];
int main(){
	SF("%d%d",&n,&m);
	SF("%s",s+1);
	for(int i=1;i<=n+1;i++)
		pre[i]=pre[i-1]+(s[i]=='1');
	int las=1;
	int u,v;
	for(int i=1;i<=n+1;i++)
		endx[i]=max(endx[i],i);
	for(int i=1;i<=m;i++){
		SF("%d%d",&u,&v);	
		endx[u]=max(endx[u],v);
	}
	for(int i=1;i<=n+1;i++)
		endx[i]=max(endx[i],endx[i-1]);
	dp[1][pre[endx[1]]]=1;
	for(int i=1;i<=n;i++)
		for(int j=0;j<=n;j++)
			if(dp[i][j]){
				int l=endx[i];
				int r=endx[i+1];
				int one=j;
				int zero=endx[i]-i+1-j;
				if(zero)
					(dp[i+1][j+pre[r]-pre[l]]+=dp[i][j])%=MOD;
				if(one)
					(dp[i+1][j-1+pre[r]-pre[l]]+=dp[i][j])%=MOD;
			}
	PF("%lld",dp[n+1][0]);
}
### Prompt

Please formulate a CPP solution to the following problem:

There is a string S of length N consisting of characters `0` and `1`. You will perform the following operation for each i = 1, 2, ..., m:

* Arbitrarily permute the characters within the substring of S starting at the l_i-th character from the left and extending through the r_i-th character.



Here, the sequence l_i is non-decreasing.

How many values are possible for S after the M operations, modulo 1000000007(= 10^9+7)?

Constraints

* 2≦N≦3000
* 1≦M≦3000
* S consists of characters `0` and `1`.
* The length of S equals N.
* 1≦l_i < r_i≦N
* l_i ≦ l_{i+1}

Input

The input is given from Standard Input in the following format:


N M
S
l_1 r_1
:
l_M r_M


Output

Print the number of the possible values for S after the M operations, modulo 1000000007.

Examples

Input

5 2
01001
2 4
3 5


Output

6


Input

9 3
110111110
1 4
4 6
6 9


Output

26


Input

11 6
00101000110
2 4
2 3
4 7
5 6
6 10
10 11


Output

143

### Response

```cpp
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<cmath>
#include<map>
#include<vector>
#include<set>
#define SF scanf
#define PF printf
#define MAXN 3010
#define MOD 1000000007
using namespace std;
typedef long long ll;
ll dp[MAXN][MAXN];
int n,m;
char s[MAXN];
int endx[MAXN],pre[MAXN];
int main(){
	SF("%d%d",&n,&m);
	SF("%s",s+1);
	for(int i=1;i<=n+1;i++)
		pre[i]=pre[i-1]+(s[i]=='1');
	int las=1;
	int u,v;
	for(int i=1;i<=n+1;i++)
		endx[i]=max(endx[i],i);
	for(int i=1;i<=m;i++){
		SF("%d%d",&u,&v);	
		endx[u]=max(endx[u],v);
	}
	for(int i=1;i<=n+1;i++)
		endx[i]=max(endx[i],endx[i-1]);
	dp[1][pre[endx[1]]]=1;
	for(int i=1;i<=n;i++)
		for(int j=0;j<=n;j++)
			if(dp[i][j]){
				int l=endx[i];
				int r=endx[i+1];
				int one=j;
				int zero=endx[i]-i+1-j;
				if(zero)
					(dp[i+1][j+pre[r]-pre[l]]+=dp[i][j])%=MOD;
				if(one)
					(dp[i+1][j-1+pre[r]-pre[l]]+=dp[i][j])%=MOD;
			}
	PF("%lld",dp[n+1][0]);
}
```