#include <bits/stdc++.h>
int main() {
  long a, b, c, sobo;
  scanf("%ld", &a);
  scanf("%ld", &b);
  scanf("%ld", &c);
  sobo = a / 3 + b / 3 + c / 3;
  if ((a == 0) || (b == 0) || (c == 0))
    sobo = sobo;
  else {
    {
      if ((a % 3 > 0) && (b % 3 > 0) && (c % 3 > 0))
        sobo = sobo + (a % 3 + b % 3 + c % 3) / 3;
      else {
        if (((a % 3 == 2) && (b % 3 == 2)) || ((b % 3 == 2) && (c % 3 == 2)) ||
            ((a % 3 == 2) && (c % 3 == 2)))
          sobo = sobo + 1;
      }
    }
  }
  printf("%ld", sobo);
  return 0;
}

### Prompt

Your task is to create a Cpp solution to the following problem:

Fox Ciel has some flowers: r red flowers, g green flowers and b blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:

  * To make a "red bouquet", it needs 3 red flowers. 
  * To make a "green bouquet", it needs 3 green flowers. 
  * To make a "blue bouquet", it needs 3 blue flowers. 
  * To make a "mixing bouquet", it needs 1 red, 1 green and 1 blue flower. 



Help Fox Ciel to find the maximal number of bouquets she can make.

Input

The first line contains three integers r, g and b (0 ≤ r, g, b ≤ 109) — the number of red, green and blue flowers.

Output

Print the maximal number of bouquets Fox Ciel can make.

Examples

Input

3 6 9


Output

6


Input

4 4 4


Output

4


Input

0 0 0


Output

0

Note

In test case 1, we can make 1 red bouquet, 2 green bouquets and 3 blue bouquets.

In test case 2, we can make 1 red, 1 green, 1 blue and 1 mixing bouquet.

### Response

```cpp
#include <bits/stdc++.h>
int main() {
  long a, b, c, sobo;
  scanf("%ld", &a);
  scanf("%ld", &b);
  scanf("%ld", &c);
  sobo = a / 3 + b / 3 + c / 3;
  if ((a == 0) || (b == 0) || (c == 0))
    sobo = sobo;
  else {
    {
      if ((a % 3 > 0) && (b % 3 > 0) && (c % 3 > 0))
        sobo = sobo + (a % 3 + b % 3 + c % 3) / 3;
      else {
        if (((a % 3 == 2) && (b % 3 == 2)) || ((b % 3 == 2) && (c % 3 == 2)) ||
            ((a % 3 == 2) && (c % 3 == 2)))
          sobo = sobo + 1;
      }
    }
  }
  printf("%ld", sobo);
  return 0;
}

```