#include <bits/stdc++.h>
#define PB push_back
#define MP make_pair
#define REP(i,n) for (int i=0;i<(n);i++)
#define FOR(i,a,b) for(int i=(a);i<(b);i++)
#define ALL(a) (a).begin(),(a).end()
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<int,int> P;
const int INF=1e9;
const int MOD=100000;
int main(){
	int d,n;
	cin>>d;
	REP(times,d){
		cin>>n;
		char fld[n][n],a,b;
		REP(i,(n+1)/2){
			if(i%2==0){a='#';b=' ';}
			else{a=' ';b='#';}
			REP(j,(n-i*2)){
				fld[i+j][i]=a;
				fld[i][i+j]=a;
				fld[n-1-i][i+j]=a;
				fld[i+j][n-1-i]=a;
			}
			fld[i+1][n-1-i]=b;
		}
		if(n%4==0)fld[n/2][n/2]=' ';
		REP(i,n){
			REP(j,n)cout<<fld[j][i];
			cout<<endl;
		}
		if(times!=d-1)cout<<endl;
	}
}
### Prompt

Please formulate a CPP solution to the following problem:

I decided to create a program that displays a "round and round pattern". The "round and round pattern" is as follows.

* If the length of one side is n, it is displayed as a character string with n rows and n columns.
* A spiral pattern that rotates clockwise with the lower left corner as the base point.
* The part with a line is represented by # (half-width sharp), and the blank part is represented by "" (half-width blank).
* Leave a space between the lines.



Create a program that takes an integer n as an input and outputs a "round and round pattern" with a side length of n.



Input

The input is given in the following format:


d
n1
n2
::
nd


The number of datasets d (d ≤ 20) is given to the first line, and the side length ni (1 ≤ ni ≤ 100) of the i-th round pattern is given to each of the following d lines.

Output

Please output a round and round pattern for each data set. Insert a blank line between the datasets.

Example

Input

2
5
6


Output

#####
#   #
# # #
# # #
# ###

######
#    #
# ## #
# #  #
# #  #
# ####

### Response

```cpp
#include <bits/stdc++.h>
#define PB push_back
#define MP make_pair
#define REP(i,n) for (int i=0;i<(n);i++)
#define FOR(i,a,b) for(int i=(a);i<(b);i++)
#define ALL(a) (a).begin(),(a).end()
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<int,int> P;
const int INF=1e9;
const int MOD=100000;
int main(){
	int d,n;
	cin>>d;
	REP(times,d){
		cin>>n;
		char fld[n][n],a,b;
		REP(i,(n+1)/2){
			if(i%2==0){a='#';b=' ';}
			else{a=' ';b='#';}
			REP(j,(n-i*2)){
				fld[i+j][i]=a;
				fld[i][i+j]=a;
				fld[n-1-i][i+j]=a;
				fld[i+j][n-1-i]=a;
			}
			fld[i+1][n-1-i]=b;
		}
		if(n%4==0)fld[n/2][n/2]=' ';
		REP(i,n){
			REP(j,n)cout<<fld[j][i];
			cout<<endl;
		}
		if(times!=d-1)cout<<endl;
	}
}
```