#include <iostream>
#include <string>
using namespace std;

int main(){
int n;
int b;
int c;
int d;
while(cin >> n){
int a[n+1];
b=1;
while(b<n+1){
a[b]=0;
b=b+1;}
a[1]=1;
d=0;
b=2;
while(b<n+1){
if(a[b]==0){d=d+1; c=2; while(1){if(c*b>n){break;} a[c*b]=1; c=c+1;}}
b=b+1;}
cout << d <<endl;}


}
### Prompt

Generate a CPP solution to the following problem:

Write a program which reads an integer n and prints the number of prime numbers which are less than or equal to n. A prime number is a natural number which has exactly two distinct natural number divisors: 1 and itself. For example, the first four prime numbers are: 2, 3, 5 and 7.



Input

Input consists of several datasets. Each dataset has an integer n (1 ≤ n ≤ 999,999) in a line.

The number of datasets is less than or equal to 30.

Output

For each dataset, prints the number of prime numbers.

Example

Input

10
3
11


Output

4
2
5

### Response

```cpp
#include <iostream>
#include <string>
using namespace std;

int main(){
int n;
int b;
int c;
int d;
while(cin >> n){
int a[n+1];
b=1;
while(b<n+1){
a[b]=0;
b=b+1;}
a[1]=1;
d=0;
b=2;
while(b<n+1){
if(a[b]==0){d=d+1; c=2; while(1){if(c*b>n){break;} a[c*b]=1; c=c+1;}}
b=b+1;}
cout << d <<endl;}


}
```