#include <bits/stdc++.h>
using namespace std;
int main() {
    int n,m;
    while(cin>>n>>m,n,m){
    	bool num[100000]={};
    	int co=0;
    	for(int i=0,x;i<m;i++){
    		cin>>x;
    		if(x==0)co++;
    		else num[x]=1;
    	}
    	int ans=0;
    	for(int i=1;i<=n-ans;i++){
    		if(num[i]){
    			for(int j=i+1,now=1,fin=co;;j++,now++){
    				if(!num[j]&&fin>0)fin--;
    				else if(!num[j]){
    					ans=max(ans,now);
    					break;
    				}
    			}
    		}
    	}
    	cout<<ans<<endl;
    }
}
### Prompt

Generate a Cpp solution to the following problem:

problem

There are n cards with one integer from 1 to n and one blank card. Of these n + 1 cards, k cards are given, but 1 ≤ k ≤ n. You can write one integer from 1 to n on a blank card. I want to make a continuous sequence of integers as long as possible with just a given card.

Write a program that outputs the maximum length of a contiguous sequence of integers that can be made from a given card when the given card is entered.



input

The input consists of multiple datasets. Each dataset is given in the following format. The input ends on a line containing two zeros.

On the first line, two integers n (1 ≤ n ≤ 100000) and k (1 ≤ k ≤ n) are written in this order, separated by one blank. The following k line contains one integer. Written one by one, representing the integers written on the given k cards. Blank cards are represented by 0.

Of the scoring data, 40% of the points are 1 ≤ n ≤ 1000, 1 ≤ k ≤ 500, 20% of the points are 1 ≤ n ≤ 60000, 1 ≤ k ≤ 50000. Satisfy 1 ≤ n ≤ 100000, 1 ≤ k ≤ 100000.

The number of datasets does not exceed 5.

output

Outputs an integer on one line for each dataset.

Examples

Input

7 5
6
2
4
7
1
7 5
6
2
0
4
7
0 0


Output

2
4


Input

None


Output

None

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
    int n,m;
    while(cin>>n>>m,n,m){
    	bool num[100000]={};
    	int co=0;
    	for(int i=0,x;i<m;i++){
    		cin>>x;
    		if(x==0)co++;
    		else num[x]=1;
    	}
    	int ans=0;
    	for(int i=1;i<=n-ans;i++){
    		if(num[i]){
    			for(int j=i+1,now=1,fin=co;;j++,now++){
    				if(!num[j]&&fin>0)fin--;
    				else if(!num[j]){
    					ans=max(ans,now);
    					break;
    				}
    			}
    		}
    	}
    	cout<<ans<<endl;
    }
}
```