#include <algorithm>
#include<stdio.h>
#include <cstdio>
#include <iostream>
#include <iomanip>
#include <string>
#include <algorithm>
#include <vector>
#include <math.h>
#include<stack>
#include <queue>
#include<map>
#include <set>
#include<math.h>
using namespace std;
#define int long long
#define ll long long
#define rep(i,n) for(ll i=0;i<n;++i)
#define Rep(i,n) for(ll i=1;i<=n;++i)
#define loop(i,m,n) for(ll i=m;i<n;++i)
#define ggr getchar(); getchar();return 0;
#define pie 3.141592653589793238462643383279
#define elif else if
#define P pair<ll,ll>
#define prique priority_queue<ll>
const int mod = 1000000007;
const int mod2 = 998244353;
int bin(int bina) {
	int ans = 0;
	for (int i = 0; bina > 0; i++)
	{
		ans = ans + (bina % 2) * pow(10, i);
		bina = bina / 2;
	}
	return ans;
}
bool prime(int n) {
	for (ll i = 2; i <= sqrt(n); i++) {
		if (n % i == 0)return false;
	}
	return n != 1;
}
int gcd(int x, int y) {
	if (y == 0)return x;
	return gcd(y, x % y);
}
int lcm(int x, int y) {
	return x * y / gcd(x, y);
}
int kai(int x) {
	if (x == 0)return 1;
	return kai(x - 1) * x % mod;
}
int mod_pow(int x, int y, int mod) {
	int res = 1;
	while (y > 0) {
		if (y & 1) {
			res = res * x % mod;
		}
		x = x * x % mod;
		y >>= 1;
	}
	return res;
}
long nCr(int n, int r) {
	int ans = 1;
	for (ll i = n; i > n - r; --i) {
		ans = ans * i;
	}
	for (ll i = 1; i < r + 1; ++i) {
		ans = ans / i;
	}
	return ans;
}
struct union_find {
	int par[200010], size_[200010];
	void init(int x) {
		rep(i, x) { par[i] = i; size_[i] = 1; }
	}
	int find(int x) {
		if (par[x] == x)return x;
		return par[x] = find(par[x]);
	}
	void unite(int x, int y) {
		x = find(x); y = find(y);
		if (x == y)return;
		if (size_[x] < size_[y]) {
			par[x] = y;
			size_[y] += size_[x];
		}
		else {
			par[y] = x;
			size_[x] += size_[y];
		}
	}
};

signed main() {
	int n, a, b;
	cin >> n >> a >> b;
	if (n % 12 == 0)cout << a << ' ' << b << endl;
	elif(n % 12 == 1)cout << a - b << ' ' << b << endl;
	elif(n % 12 == 2)cout << a - b << ' '<<a << endl;
	elif(n % 12 == 3)cout << 0-b << ' ' << a << endl;
	elif(n % 12 == 4)cout << 0-b << ' '<<a - b << endl;
	elif(n % 12 == 5)cout << 0-a << ' '<<a - b << endl;
	elif(n % 12 == 6)cout << 0-a << ' ' << 0- b << endl;
	elif(n % 12 == 7)cout << 0-a+b << ' ' << 0- b << endl;
	elif(n % 12 == 8)cout << 0-a+b << ' ' <<0-a<< endl;
	elif(n % 12 == 9)cout << b << ' ' << 0-a << endl;
	elif(n % 12 == 10)cout << b << ' ' << 0-a+b << endl;
	elif(n % 12 ==11)cout << a << ' ' << 0-a+b << endl;
}

### Prompt

Please create a solution in Cpp to the following problem:

Tashizan Hikizan (Calculation Training)

square1001 You gave E869120 two numbers, $ A $ and $ B $, as birthday presents.

E869120 You decided to use these two numbers for calculation training.

Specifically, E869120 does the following for these numbers exactly $ N $ times:

* Replace $ A $ with $ A-B $ on odd-numbered operations
* Replace $ B $ with $ A + B $ on even-numbered operations




E869120 Find out what the values ​​of $ A $ and $ B $ are after you have operated $ N $ times.

input

Input is given from standard input in the following format.


$ N $
$ A $ $ B $


output

E869120 Please output the values ​​of $ A $ and $ B $ after you have operated $ N $ times in this order, separated by blanks.

However, insert a line break at the end.

Constraint

* $ 1 \ leq N \ leq 1000000000000000000 \ (= 10 ^ {18}) $
* $ 1 \ leq A \ leq 1000000000 \ (= 10 ^ 9) $
* $ 1 \ leq B \ leq 1000000000 \ (= 10 ^ 9) $
* All inputs are integers.



Input example 1


3
3 4


Output example 1


-4 3


The value of $ (A, B) $ changes as $ (3,4) → (-1,4) → (-1,3) → (-4,3) $.

Input example 2


8
6 9


Output example 2


3 -6






Example

Input

3
3 4


Output

-4 3

### Response

```cpp
#include <algorithm>
#include<stdio.h>
#include <cstdio>
#include <iostream>
#include <iomanip>
#include <string>
#include <algorithm>
#include <vector>
#include <math.h>
#include<stack>
#include <queue>
#include<map>
#include <set>
#include<math.h>
using namespace std;
#define int long long
#define ll long long
#define rep(i,n) for(ll i=0;i<n;++i)
#define Rep(i,n) for(ll i=1;i<=n;++i)
#define loop(i,m,n) for(ll i=m;i<n;++i)
#define ggr getchar(); getchar();return 0;
#define pie 3.141592653589793238462643383279
#define elif else if
#define P pair<ll,ll>
#define prique priority_queue<ll>
const int mod = 1000000007;
const int mod2 = 998244353;
int bin(int bina) {
	int ans = 0;
	for (int i = 0; bina > 0; i++)
	{
		ans = ans + (bina % 2) * pow(10, i);
		bina = bina / 2;
	}
	return ans;
}
bool prime(int n) {
	for (ll i = 2; i <= sqrt(n); i++) {
		if (n % i == 0)return false;
	}
	return n != 1;
}
int gcd(int x, int y) {
	if (y == 0)return x;
	return gcd(y, x % y);
}
int lcm(int x, int y) {
	return x * y / gcd(x, y);
}
int kai(int x) {
	if (x == 0)return 1;
	return kai(x - 1) * x % mod;
}
int mod_pow(int x, int y, int mod) {
	int res = 1;
	while (y > 0) {
		if (y & 1) {
			res = res * x % mod;
		}
		x = x * x % mod;
		y >>= 1;
	}
	return res;
}
long nCr(int n, int r) {
	int ans = 1;
	for (ll i = n; i > n - r; --i) {
		ans = ans * i;
	}
	for (ll i = 1; i < r + 1; ++i) {
		ans = ans / i;
	}
	return ans;
}
struct union_find {
	int par[200010], size_[200010];
	void init(int x) {
		rep(i, x) { par[i] = i; size_[i] = 1; }
	}
	int find(int x) {
		if (par[x] == x)return x;
		return par[x] = find(par[x]);
	}
	void unite(int x, int y) {
		x = find(x); y = find(y);
		if (x == y)return;
		if (size_[x] < size_[y]) {
			par[x] = y;
			size_[y] += size_[x];
		}
		else {
			par[y] = x;
			size_[x] += size_[y];
		}
	}
};

signed main() {
	int n, a, b;
	cin >> n >> a >> b;
	if (n % 12 == 0)cout << a << ' ' << b << endl;
	elif(n % 12 == 1)cout << a - b << ' ' << b << endl;
	elif(n % 12 == 2)cout << a - b << ' '<<a << endl;
	elif(n % 12 == 3)cout << 0-b << ' ' << a << endl;
	elif(n % 12 == 4)cout << 0-b << ' '<<a - b << endl;
	elif(n % 12 == 5)cout << 0-a << ' '<<a - b << endl;
	elif(n % 12 == 6)cout << 0-a << ' ' << 0- b << endl;
	elif(n % 12 == 7)cout << 0-a+b << ' ' << 0- b << endl;
	elif(n % 12 == 8)cout << 0-a+b << ' ' <<0-a<< endl;
	elif(n % 12 == 9)cout << b << ' ' << 0-a << endl;
	elif(n % 12 == 10)cout << b << ' ' << 0-a+b << endl;
	elif(n % 12 ==11)cout << a << ' ' << 0-a+b << endl;
}

```