#include<cstdio>
int sosu[1000000]={};
bool f[1000000]={false};
int main(){
  sosu[2] = 1;
  for(int i=3;i<=999999;i+=2){
    if(!f[i]){
      sosu[i] = 1;
      if(i < 1000){
	for(int j=i*i;j<=999999;j+=i) f[j] = true;
      }
    }
    sosu[i] += sosu[i-1];
    sosu[i+1] += sosu[i];
  }
  int n;
  while(scanf("%d",&n)!=EOF) printf("%d\n",sosu[n]);
  return(0);
}


### Prompt

Please provide a cpp coded solution to the problem described below:

Write a program which reads an integer n and prints the number of prime numbers which are less than or equal to n. A prime number is a natural number which has exactly two distinct natural number divisors: 1 and itself. For example, the first four prime numbers are: 2, 3, 5 and 7.



Input

Input consists of several datasets. Each dataset has an integer n (1 ≤ n ≤ 999,999) in a line.

The number of datasets is less than or equal to 30.

Output

For each dataset, prints the number of prime numbers.

Example

Input

10
3
11


Output

4
2
5

### Response

```cpp
#include<cstdio>
int sosu[1000000]={};
bool f[1000000]={false};
int main(){
  sosu[2] = 1;
  for(int i=3;i<=999999;i+=2){
    if(!f[i]){
      sosu[i] = 1;
      if(i < 1000){
	for(int j=i*i;j<=999999;j+=i) f[j] = true;
      }
    }
    sosu[i] += sosu[i-1];
    sosu[i+1] += sosu[i];
  }
  int n;
  while(scanf("%d",&n)!=EOF) printf("%d\n",sosu[n]);
  return(0);
}


```