#include <iostream>
#include <vector>
#include <cmath>

using namespace std;

int main() {
	int n, k;
	while(cin >> n >> k) {
		if (n == 0 && k == 0) {
			break;
		}
		vector<int> data(n+1, 0);
		int a;
		for (int i = 0; i < k; i++) {
			cin >> a;
			data[a] = 1;
		}
		int MAX = data[n];
		for (int i = n-1; i > 0; i--) {
			if (data[i] == 0 || data[i+1] == 0) {
			} else {
				data[i] += data[i+1];
			}
			MAX = max(MAX, data[i]);
		}
		if (data[0] == 1) {
			for (int i = 1; i <= n; i++) {
				if (data[i] > 0) {
					if (i+data[i] < n) {
						MAX = max(MAX, data[i]+1);
						if (i+data[i]+1 < n) {
							MAX = max(MAX, data[i]+data[i+data[i]+1]+1);
						}
					}
				} else {
					MAX = max(MAX, 1);
					if (i+1 < n) {
						MAX = max(MAX, data[i+1]+1);
					}
				}
			}
		}
		cout << MAX << endl;
	}
	return 0;
}
### Prompt

Please create a solution in Cpp to the following problem:

problem

There are n cards with one integer from 1 to n and one blank card. Of these n + 1 cards, k cards are given, but 1 ≤ k ≤ n. You can write one integer from 1 to n on a blank card. I want to make a continuous sequence of integers as long as possible with just a given card.

Write a program that outputs the maximum length of a contiguous sequence of integers that can be made from a given card when the given card is entered.



input

The input consists of multiple datasets. Each dataset is given in the following format. The input ends on a line containing two zeros.

On the first line, two integers n (1 ≤ n ≤ 100000) and k (1 ≤ k ≤ n) are written in this order, separated by one blank. The following k line contains one integer. Written one by one, representing the integers written on the given k cards. Blank cards are represented by 0.

Of the scoring data, 40% of the points are 1 ≤ n ≤ 1000, 1 ≤ k ≤ 500, 20% of the points are 1 ≤ n ≤ 60000, 1 ≤ k ≤ 50000. Satisfy 1 ≤ n ≤ 100000, 1 ≤ k ≤ 100000.

The number of datasets does not exceed 5.

output

Outputs an integer on one line for each dataset.

Examples

Input

7 5
6
2
4
7
1
7 5
6
2
0
4
7
0 0


Output

2
4


Input

None


Output

None

### Response

```cpp
#include <iostream>
#include <vector>
#include <cmath>

using namespace std;

int main() {
	int n, k;
	while(cin >> n >> k) {
		if (n == 0 && k == 0) {
			break;
		}
		vector<int> data(n+1, 0);
		int a;
		for (int i = 0; i < k; i++) {
			cin >> a;
			data[a] = 1;
		}
		int MAX = data[n];
		for (int i = n-1; i > 0; i--) {
			if (data[i] == 0 || data[i+1] == 0) {
			} else {
				data[i] += data[i+1];
			}
			MAX = max(MAX, data[i]);
		}
		if (data[0] == 1) {
			for (int i = 1; i <= n; i++) {
				if (data[i] > 0) {
					if (i+data[i] < n) {
						MAX = max(MAX, data[i]+1);
						if (i+data[i]+1 < n) {
							MAX = max(MAX, data[i]+data[i+data[i]+1]+1);
						}
					}
				} else {
					MAX = max(MAX, 1);
					if (i+1 < n) {
						MAX = max(MAX, data[i+1]+1);
					}
				}
			}
		}
		cout << MAX << endl;
	}
	return 0;
}
```