#include<cstdio>
#include<algorithm>

using namespace std;

int a[100000];

int main()
{
	for(int n,k;scanf("%d%d",&n,&k),n;){
		for(int i=0;i<k;i++)	scanf("%d",a+i);

		sort(a,a+k);
		int white=(a[0]?0:1);

		int maxlen=0;
		int len[2]={},bf[2]={-100,-100};
		for(int i=1,j=white;i<=n&&j<k;i++){
			if(a[j]==i){
				for(int m=0;m<=white;m++){
					if(a[j]==bf[m]+1)	len[m]++;
					else	len[m]=1;
					bf[m]=a[j];
				}
				j++;
			}
			else{
				if(white){
					len[1]=len[0]+1;
					bf[1]=i;
				}
				len[0]=0;
			}
			maxlen=max(maxlen,max(len[0],len[1]));
		}

		printf("%d\n",maxlen);
	}

	return 0;
}
### Prompt

Please formulate a cpp solution to the following problem:

problem

There are n cards with one integer from 1 to n and one blank card. Of these n + 1 cards, k cards are given, but 1 ≤ k ≤ n. You can write one integer from 1 to n on a blank card. I want to make a continuous sequence of integers as long as possible with just a given card.

Write a program that outputs the maximum length of a contiguous sequence of integers that can be made from a given card when the given card is entered.



input

The input consists of multiple datasets. Each dataset is given in the following format. The input ends on a line containing two zeros.

On the first line, two integers n (1 ≤ n ≤ 100000) and k (1 ≤ k ≤ n) are written in this order, separated by one blank. The following k line contains one integer. Written one by one, representing the integers written on the given k cards. Blank cards are represented by 0.

Of the scoring data, 40% of the points are 1 ≤ n ≤ 1000, 1 ≤ k ≤ 500, 20% of the points are 1 ≤ n ≤ 60000, 1 ≤ k ≤ 50000. Satisfy 1 ≤ n ≤ 100000, 1 ≤ k ≤ 100000.

The number of datasets does not exceed 5.

output

Outputs an integer on one line for each dataset.

Examples

Input

7 5
6
2
4
7
1
7 5
6
2
0
4
7
0 0


Output

2
4


Input

None


Output

None

### Response

```cpp
#include<cstdio>
#include<algorithm>

using namespace std;

int a[100000];

int main()
{
	for(int n,k;scanf("%d%d",&n,&k),n;){
		for(int i=0;i<k;i++)	scanf("%d",a+i);

		sort(a,a+k);
		int white=(a[0]?0:1);

		int maxlen=0;
		int len[2]={},bf[2]={-100,-100};
		for(int i=1,j=white;i<=n&&j<k;i++){
			if(a[j]==i){
				for(int m=0;m<=white;m++){
					if(a[j]==bf[m]+1)	len[m]++;
					else	len[m]=1;
					bf[m]=a[j];
				}
				j++;
			}
			else{
				if(white){
					len[1]=len[0]+1;
					bf[1]=i;
				}
				len[0]=0;
			}
			maxlen=max(maxlen,max(len[0],len[1]));
		}

		printf("%d\n",maxlen);
	}

	return 0;
}
```