#include <stdio.h>

int main(){
	int n;
	while(scanf("%d", &n) != EOF){
		int *arr = new int[n + 1];
		
		for(int i = 2; i <= n; i++){
			if(arr[i] == 0){
				for(int j = 2*i; j <= n; j += i){
					arr[j] = 1;
				}
			}
		}
		
		int cnt = 0;
		for(int i = 2; i <= n; i++){
			if(arr[i] == 0){
				cnt++;
			}
		}
		delete [] arr;
		
		printf("%d\n", cnt);
	}
	return 0;
}
### Prompt

Create a solution in CPP for the following problem:

Write a program which reads an integer n and prints the number of prime numbers which are less than or equal to n. A prime number is a natural number which has exactly two distinct natural number divisors: 1 and itself. For example, the first four prime numbers are: 2, 3, 5 and 7.



Input

Input consists of several datasets. Each dataset has an integer n (1 ≤ n ≤ 999,999) in a line.

The number of datasets is less than or equal to 30.

Output

For each dataset, prints the number of prime numbers.

Example

Input

10
3
11


Output

4
2
5

### Response

```cpp
#include <stdio.h>

int main(){
	int n;
	while(scanf("%d", &n) != EOF){
		int *arr = new int[n + 1];
		
		for(int i = 2; i <= n; i++){
			if(arr[i] == 0){
				for(int j = 2*i; j <= n; j += i){
					arr[j] = 1;
				}
			}
		}
		
		int cnt = 0;
		for(int i = 2; i <= n; i++){
			if(arr[i] == 0){
				cnt++;
			}
		}
		delete [] arr;
		
		printf("%d\n", cnt);
	}
	return 0;
}
```