#include <bits/stdc++.h>
using namespace std;
int main() {
  int a, b, c;
  cin >> a >> b >> c;
  int c0, c1, c2;
  int max;
  c0 = a / 3 + b / 3 + c / 3;
  c1 = (a - 1) / 3 + (b - 1) / 3 + (c - 1) / 3 + 1;
  if (a < 1 || b < 1 || c < 1) c1 -= 1;
  c2 = (a - 2) / 3 + (b - 2) / 3 + (c - 2) / 3 + 2;
  if (a < 2 || b < 2 || c < 2) c2 -= 2;
  max = c0;
  if (c1 > c0) max = c1;
  if (c2 > c0) max = c2;
  cout << max << endl;
  return 0;
}

### Prompt

Your task is to create a Cpp solution to the following problem:

Fox Ciel has some flowers: r red flowers, g green flowers and b blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:

  * To make a "red bouquet", it needs 3 red flowers. 
  * To make a "green bouquet", it needs 3 green flowers. 
  * To make a "blue bouquet", it needs 3 blue flowers. 
  * To make a "mixing bouquet", it needs 1 red, 1 green and 1 blue flower. 



Help Fox Ciel to find the maximal number of bouquets she can make.

Input

The first line contains three integers r, g and b (0 ≤ r, g, b ≤ 109) — the number of red, green and blue flowers.

Output

Print the maximal number of bouquets Fox Ciel can make.

Examples

Input

3 6 9


Output

6


Input

4 4 4


Output

4


Input

0 0 0


Output

0

Note

In test case 1, we can make 1 red bouquet, 2 green bouquets and 3 blue bouquets.

In test case 2, we can make 1 red, 1 green, 1 blue and 1 mixing bouquet.

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  int a, b, c;
  cin >> a >> b >> c;
  int c0, c1, c2;
  int max;
  c0 = a / 3 + b / 3 + c / 3;
  c1 = (a - 1) / 3 + (b - 1) / 3 + (c - 1) / 3 + 1;
  if (a < 1 || b < 1 || c < 1) c1 -= 1;
  c2 = (a - 2) / 3 + (b - 2) / 3 + (c - 2) / 3 + 2;
  if (a < 2 || b < 2 || c < 2) c2 -= 2;
  max = c0;
  if (c1 > c0) max = c1;
  if (c2 > c0) max = c2;
  cout << max << endl;
  return 0;
}

```