#include<cstdio>
#include<algorithm>
using namespace std;
int n,k;
int dat[100002];
int main(void){
  scanf("%d%d",&n,&k);
  int i,j;
  int no=0,ls=0,ans=0;
  bool lf=false,cf=false;
  while(n!=0){
    for(i=0;i<k;i++)scanf("%d",&(dat[i]));
    sort(dat,dat+k);
    dat[k]=100005;
    i=0;
    if(dat[i]==0){
      cf=true;
      i++;
      if(dat[i]!=1)lf=true;
    }
    while(i<k){
      j=i;
      while(j<k && dat[j+1]==dat[j]+1)j++;
      ls=no;no=j-i+1;i=j;
      if(cf&&lf){
    ans=ans<no+ls+1?no+ls+1:ans;
      }
      else{
    ans=ans<no?no:ans;
      }
      if(dat[j+1]==dat[j]+2)lf=true;
      i++;
    }
    printf("%d\n",ans);
    scanf("%d%d",&n,&k);
  }
  return 0;
}
### Prompt

Generate a cpp solution to the following problem:

problem

There are n cards with one integer from 1 to n and one blank card. Of these n + 1 cards, k cards are given, but 1 ≤ k ≤ n. You can write one integer from 1 to n on a blank card. I want to make a continuous sequence of integers as long as possible with just a given card.

Write a program that outputs the maximum length of a contiguous sequence of integers that can be made from a given card when the given card is entered.



input

The input consists of multiple datasets. Each dataset is given in the following format. The input ends on a line containing two zeros.

On the first line, two integers n (1 ≤ n ≤ 100000) and k (1 ≤ k ≤ n) are written in this order, separated by one blank. The following k line contains one integer. Written one by one, representing the integers written on the given k cards. Blank cards are represented by 0.

Of the scoring data, 40% of the points are 1 ≤ n ≤ 1000, 1 ≤ k ≤ 500, 20% of the points are 1 ≤ n ≤ 60000, 1 ≤ k ≤ 50000. Satisfy 1 ≤ n ≤ 100000, 1 ≤ k ≤ 100000.

The number of datasets does not exceed 5.

output

Outputs an integer on one line for each dataset.

Examples

Input

7 5
6
2
4
7
1
7 5
6
2
0
4
7
0 0


Output

2
4


Input

None


Output

None

### Response

```cpp
#include<cstdio>
#include<algorithm>
using namespace std;
int n,k;
int dat[100002];
int main(void){
  scanf("%d%d",&n,&k);
  int i,j;
  int no=0,ls=0,ans=0;
  bool lf=false,cf=false;
  while(n!=0){
    for(i=0;i<k;i++)scanf("%d",&(dat[i]));
    sort(dat,dat+k);
    dat[k]=100005;
    i=0;
    if(dat[i]==0){
      cf=true;
      i++;
      if(dat[i]!=1)lf=true;
    }
    while(i<k){
      j=i;
      while(j<k && dat[j+1]==dat[j]+1)j++;
      ls=no;no=j-i+1;i=j;
      if(cf&&lf){
    ans=ans<no+ls+1?no+ls+1:ans;
      }
      else{
    ans=ans<no?no:ans;
      }
      if(dat[j+1]==dat[j]+2)lf=true;
      i++;
    }
    printf("%d\n",ans);
    scanf("%d%d",&n,&k);
  }
  return 0;
}
```