#include <stdio.h>

int main(void)
{
	int n;
	
	while(scanf("%d", &n) != EOF){
	
	bool *d = new bool [n+1];
	int count = 0;

	for(int i = 0; i <= n; i++)
		d[i] = true;

	for(int i = 2; i <= n; i++){
		if(d[i]){
			count++;
			for(int j = i*2; j <= n; j+=i)
				d[j] = false;
		}
	}
	printf("%d\n", count);
	}


	return 0;
}
### Prompt

Develop a solution in cpp to the problem described below:

Write a program which reads an integer n and prints the number of prime numbers which are less than or equal to n. A prime number is a natural number which has exactly two distinct natural number divisors: 1 and itself. For example, the first four prime numbers are: 2, 3, 5 and 7.



Input

Input consists of several datasets. Each dataset has an integer n (1 ≤ n ≤ 999,999) in a line.

The number of datasets is less than or equal to 30.

Output

For each dataset, prints the number of prime numbers.

Example

Input

10
3
11


Output

4
2
5

### Response

```cpp
#include <stdio.h>

int main(void)
{
	int n;
	
	while(scanf("%d", &n) != EOF){
	
	bool *d = new bool [n+1];
	int count = 0;

	for(int i = 0; i <= n; i++)
		d[i] = true;

	for(int i = 2; i <= n; i++){
		if(d[i]){
			count++;
			for(int j = i*2; j <= n; j+=i)
				d[j] = false;
		}
	}
	printf("%d\n", count);
	}


	return 0;
}
```