#include <cstdio>
const int N=1000000;
int p[N],pN[N];
int main(){p[0]=0;p[1]=0;int i,k,n,c;
for(i=2;i<N;i++)p[i]=1;for(i=2;i*i<N;){for(k=2;i*k<N;k++)p[i*k]=0;do{i++;}while(!p[i]);}for(i=0,c=0;i<N;i++){p[i]&&c++;pN[i]=c;}for(;scanf("%d",&n)+1;printf("%d\n",pN[n]));}
### Prompt

Generate a cpp solution to the following problem:

Write a program which reads an integer n and prints the number of prime numbers which are less than or equal to n. A prime number is a natural number which has exactly two distinct natural number divisors: 1 and itself. For example, the first four prime numbers are: 2, 3, 5 and 7.



Input

Input consists of several datasets. Each dataset has an integer n (1 ≤ n ≤ 999,999) in a line.

The number of datasets is less than or equal to 30.

Output

For each dataset, prints the number of prime numbers.

Example

Input

10
3
11


Output

4
2
5

### Response

```cpp
#include <cstdio>
const int N=1000000;
int p[N],pN[N];
int main(){p[0]=0;p[1]=0;int i,k,n,c;
for(i=2;i<N;i++)p[i]=1;for(i=2;i*i<N;){for(k=2;i*k<N;k++)p[i*k]=0;do{i++;}while(!p[i]);}for(i=0,c=0;i<N;i++){p[i]&&c++;pN[i]=c;}for(;scanf("%d",&n)+1;printf("%d\n",pN[n]));}
```