#include <bits/stdc++.h>
using namespace std;
long long gcd(long long a, long long b) { return !b ? a : gcd(b, a % b); }
const int LM = 1e3 + 5;
class problem {
 public:
  void init() {
    ios::sync_with_stdio(false);
    long long R, G, B;
    cin >> R >> G >> B;
    long long ans = R / 3 + G / 3 + B / 3;
    for (int i = 0; i < min(3LL, min(R, min(G, B))); i += 1)
      ans = max(ans, i + (R - i) / 3 + (G - i) / 3 + (B - i) / 3);
    cout << ans << endl;
  }
};
int main() {
  problem obj;
  obj.init();
  return 0;
}

### Prompt

Construct a CPP code solution to the problem outlined:

Fox Ciel has some flowers: r red flowers, g green flowers and b blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:

  * To make a "red bouquet", it needs 3 red flowers. 
  * To make a "green bouquet", it needs 3 green flowers. 
  * To make a "blue bouquet", it needs 3 blue flowers. 
  * To make a "mixing bouquet", it needs 1 red, 1 green and 1 blue flower. 



Help Fox Ciel to find the maximal number of bouquets she can make.

Input

The first line contains three integers r, g and b (0 ≤ r, g, b ≤ 109) — the number of red, green and blue flowers.

Output

Print the maximal number of bouquets Fox Ciel can make.

Examples

Input

3 6 9


Output

6


Input

4 4 4


Output

4


Input

0 0 0


Output

0

Note

In test case 1, we can make 1 red bouquet, 2 green bouquets and 3 blue bouquets.

In test case 2, we can make 1 red, 1 green, 1 blue and 1 mixing bouquet.

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
long long gcd(long long a, long long b) { return !b ? a : gcd(b, a % b); }
const int LM = 1e3 + 5;
class problem {
 public:
  void init() {
    ios::sync_with_stdio(false);
    long long R, G, B;
    cin >> R >> G >> B;
    long long ans = R / 3 + G / 3 + B / 3;
    for (int i = 0; i < min(3LL, min(R, min(G, B))); i += 1)
      ans = max(ans, i + (R - i) / 3 + (G - i) / 3 + (B - i) / 3);
    cout << ans << endl;
  }
};
int main() {
  problem obj;
  obj.init();
  return 0;
}

```