#include <bits/stdc++.h>
using namespace std;
int main() {
  int x, y;
  cin >> x >> y;
  for (int i = 1; i <= x; i++) {
    if (i % 2 == 1) {
      for (int j = 0; j < y; j++) {
        cout << "#";
      }
    } else {
      if ((i / 2) % 2 == 0) {
        cout << "#";
        for (int j = 0; j < y - 1; j++) {
          cout << ".";
        }
      } else {
        for (int j = 0; j < y - 1; j++) {
          cout << ".";
        }
        cout << "#";
      }
    }
    cout << "\n";
  }
  return 0;
}

### Prompt

Construct a CPP code solution to the problem outlined:

Fox Ciel starts to learn programming. The first task is drawing a fox! However, that turns out to be too hard for a beginner, so she decides to draw a snake instead.

A snake is a pattern on a n by m table. Denote c-th cell of r-th row as (r, c). The tail of the snake is located at (1, 1), then it's body extends to (1, m), then goes down 2 rows to (3, m), then goes left to (3, 1) and so on.

Your task is to draw this snake for Fox Ciel: the empty cells should be represented as dot characters ('.') and the snake cells should be filled with number signs ('#').

Consider sample tests in order to understand the snake pattern.

Input

The only line contains two integers: n and m (3 ≤ n, m ≤ 50). 

n is an odd number.

Output

Output n lines. Each line should contain a string consisting of m characters. Do not output spaces.

Examples

Input

3 3


Output

###
..#
###


Input

3 4


Output

####
...#
####


Input

5 3


Output

###
..#
###
#..
###


Input

9 9


Output

#########
........#
#########
#........
#########
........#
#########
#........
#########

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  int x, y;
  cin >> x >> y;
  for (int i = 1; i <= x; i++) {
    if (i % 2 == 1) {
      for (int j = 0; j < y; j++) {
        cout << "#";
      }
    } else {
      if ((i / 2) % 2 == 0) {
        cout << "#";
        for (int j = 0; j < y - 1; j++) {
          cout << ".";
        }
      } else {
        for (int j = 0; j < y - 1; j++) {
          cout << ".";
        }
        cout << "#";
      }
    }
    cout << "\n";
  }
  return 0;
}

```