#include <iostream>
#include <vector>
#include <string>
#include <algorithm>
#include <cstdio>
#include <cstring>

using namespace std;

int solve( vector< int > num ) {
	int s = 1, t = 1, ans = 0, sum = num[1] == 0;
	int cap = num[0];
	int N = num.size();

	while( s < N ) {
		while( t + 1 < N && sum <= cap) {
			sum += num[++t] == 0;
		}

		ans = max(ans, t - s);
		sum -= num[s++] == 0;

	}

	return ans;
}

int main() {
	int n, k;

	while( true ) {
		cin >> n >> k;
		if( !n && !k ) {
			break;
		}

		vector< int > num(1000001, 0);

		for(int i = 0; i < k; i++) {
			int tmp;
			cin >> tmp;
			num[tmp] = 1;
		}

		cout << solve( num ) << endl;
	}
}
### Prompt

Generate a cpp solution to the following problem:

problem

There are n cards with one integer from 1 to n and one blank card. Of these n + 1 cards, k cards are given, but 1 ≤ k ≤ n. You can write one integer from 1 to n on a blank card. I want to make a continuous sequence of integers as long as possible with just a given card.

Write a program that outputs the maximum length of a contiguous sequence of integers that can be made from a given card when the given card is entered.



input

The input consists of multiple datasets. Each dataset is given in the following format. The input ends on a line containing two zeros.

On the first line, two integers n (1 ≤ n ≤ 100000) and k (1 ≤ k ≤ n) are written in this order, separated by one blank. The following k line contains one integer. Written one by one, representing the integers written on the given k cards. Blank cards are represented by 0.

Of the scoring data, 40% of the points are 1 ≤ n ≤ 1000, 1 ≤ k ≤ 500, 20% of the points are 1 ≤ n ≤ 60000, 1 ≤ k ≤ 50000. Satisfy 1 ≤ n ≤ 100000, 1 ≤ k ≤ 100000.

The number of datasets does not exceed 5.

output

Outputs an integer on one line for each dataset.

Examples

Input

7 5
6
2
4
7
1
7 5
6
2
0
4
7
0 0


Output

2
4


Input

None


Output

None

### Response

```cpp
#include <iostream>
#include <vector>
#include <string>
#include <algorithm>
#include <cstdio>
#include <cstring>

using namespace std;

int solve( vector< int > num ) {
	int s = 1, t = 1, ans = 0, sum = num[1] == 0;
	int cap = num[0];
	int N = num.size();

	while( s < N ) {
		while( t + 1 < N && sum <= cap) {
			sum += num[++t] == 0;
		}

		ans = max(ans, t - s);
		sum -= num[s++] == 0;

	}

	return ans;
}

int main() {
	int n, k;

	while( true ) {
		cin >> n >> k;
		if( !n && !k ) {
			break;
		}

		vector< int > num(1000001, 0);

		for(int i = 0; i < k; i++) {
			int tmp;
			cin >> tmp;
			num[tmp] = 1;
		}

		cout << solve( num ) << endl;
	}
}
```