#include <iostream>
using namespace std;

bool prime[1000001];

void era(){
	for(int i=2;i<1000000;i++)prime[i]=true;
	for(int i=2;i*i<1000000;i++){
		if(prime[i]==true){
			for(int j=i*2;j<1000000;j+=i){
				prime[j]=0;
			}
		}
	}
}

int main(){
	era();
	int n,ans;
	while(cin>>n){
		ans=0;
		for(int i=0;i<=n;i++){
			if(prime[i]==1)ans++;
		}
		cout<<ans<<endl;
	}
	return 0;
}
### Prompt

Please provide a cpp coded solution to the problem described below:

Write a program which reads an integer n and prints the number of prime numbers which are less than or equal to n. A prime number is a natural number which has exactly two distinct natural number divisors: 1 and itself. For example, the first four prime numbers are: 2, 3, 5 and 7.



Input

Input consists of several datasets. Each dataset has an integer n (1 ≤ n ≤ 999,999) in a line.

The number of datasets is less than or equal to 30.

Output

For each dataset, prints the number of prime numbers.

Example

Input

10
3
11


Output

4
2
5

### Response

```cpp
#include <iostream>
using namespace std;

bool prime[1000001];

void era(){
	for(int i=2;i<1000000;i++)prime[i]=true;
	for(int i=2;i*i<1000000;i++){
		if(prime[i]==true){
			for(int j=i*2;j<1000000;j+=i){
				prime[j]=0;
			}
		}
	}
}

int main(){
	era();
	int n,ans;
	while(cin>>n){
		ans=0;
		for(int i=0;i<=n;i++){
			if(prime[i]==1)ans++;
		}
		cout<<ans<<endl;
	}
	return 0;
}
```