#include <bits/stdc++.h>
using namespace std;
int main() {
  int r, g, b, max = 0, min = 0;
  cin >> r >> g >> b;
  max = r / 3 + g / 3 + b / 3;
  if (r == 0 || g == 0 || b == 0) {
  } else {
    r = r % 3;
    g = g % 3;
    b = b % 3;
    if ((r * b * g == 0) && ((r + b + g) == 4)) max++;
    min = r;
    if (min > g) min = g;
    if (min > b) min = b;
    max = max + min;
  }
  cout << max;
  return 0;
}

### Prompt

Please formulate a cpp solution to the following problem:

Fox Ciel has some flowers: r red flowers, g green flowers and b blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:

  * To make a "red bouquet", it needs 3 red flowers. 
  * To make a "green bouquet", it needs 3 green flowers. 
  * To make a "blue bouquet", it needs 3 blue flowers. 
  * To make a "mixing bouquet", it needs 1 red, 1 green and 1 blue flower. 



Help Fox Ciel to find the maximal number of bouquets she can make.

Input

The first line contains three integers r, g and b (0 ≤ r, g, b ≤ 109) — the number of red, green and blue flowers.

Output

Print the maximal number of bouquets Fox Ciel can make.

Examples

Input

3 6 9


Output

6


Input

4 4 4


Output

4


Input

0 0 0


Output

0

Note

In test case 1, we can make 1 red bouquet, 2 green bouquets and 3 blue bouquets.

In test case 2, we can make 1 red, 1 green, 1 blue and 1 mixing bouquet.

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  int r, g, b, max = 0, min = 0;
  cin >> r >> g >> b;
  max = r / 3 + g / 3 + b / 3;
  if (r == 0 || g == 0 || b == 0) {
  } else {
    r = r % 3;
    g = g % 3;
    b = b % 3;
    if ((r * b * g == 0) && ((r + b + g) == 4)) max++;
    min = r;
    if (min > g) min = g;
    if (min > b) min = b;
    max = max + min;
  }
  cout << max;
  return 0;
}

```