#include <stdio.h>
#include <string.h>
int num[100005],rev[100005];
int main(){
	for(;;){
		int n,k,ret=0,cnt=0,id=1;scanf("%d%d",&n,&k);if(!n) return 0;
		memset(rev,0,sizeof(rev));
		for(int i=1;i<=k;i++) { scanf("%d",&num[i]); rev[num[i]]=i; }
		if(!rev[0]){
			while(id<=n){
				if(!rev[id]) { id++; continue;}
				while(id<=n&&rev[id]){id++;cnt++;}
				ret=ret<cnt?cnt:ret; cnt=0;
			}
		}
		else{
			int prev=0; int prex=-1;
			while(id<=n){
				if(!rev[id]) { id++; continue;}
				bool ok=(prex+2==id);
				while(id<=n&&rev[id]){id++;cnt++;}
				if(ok) ret=ret<cnt+prev+1?cnt+prev+1:ret;
				else ret=ret<cnt+1?cnt+1:ret;
				prev=cnt;prex=id-1;cnt=0;
			}
		}
		printf("%d\n",ret);
	}
}
### Prompt

Generate a Cpp solution to the following problem:

problem

There are n cards with one integer from 1 to n and one blank card. Of these n + 1 cards, k cards are given, but 1 ≤ k ≤ n. You can write one integer from 1 to n on a blank card. I want to make a continuous sequence of integers as long as possible with just a given card.

Write a program that outputs the maximum length of a contiguous sequence of integers that can be made from a given card when the given card is entered.



input

The input consists of multiple datasets. Each dataset is given in the following format. The input ends on a line containing two zeros.

On the first line, two integers n (1 ≤ n ≤ 100000) and k (1 ≤ k ≤ n) are written in this order, separated by one blank. The following k line contains one integer. Written one by one, representing the integers written on the given k cards. Blank cards are represented by 0.

Of the scoring data, 40% of the points are 1 ≤ n ≤ 1000, 1 ≤ k ≤ 500, 20% of the points are 1 ≤ n ≤ 60000, 1 ≤ k ≤ 50000. Satisfy 1 ≤ n ≤ 100000, 1 ≤ k ≤ 100000.

The number of datasets does not exceed 5.

output

Outputs an integer on one line for each dataset.

Examples

Input

7 5
6
2
4
7
1
7 5
6
2
0
4
7
0 0


Output

2
4


Input

None


Output

None

### Response

```cpp
#include <stdio.h>
#include <string.h>
int num[100005],rev[100005];
int main(){
	for(;;){
		int n,k,ret=0,cnt=0,id=1;scanf("%d%d",&n,&k);if(!n) return 0;
		memset(rev,0,sizeof(rev));
		for(int i=1;i<=k;i++) { scanf("%d",&num[i]); rev[num[i]]=i; }
		if(!rev[0]){
			while(id<=n){
				if(!rev[id]) { id++; continue;}
				while(id<=n&&rev[id]){id++;cnt++;}
				ret=ret<cnt?cnt:ret; cnt=0;
			}
		}
		else{
			int prev=0; int prex=-1;
			while(id<=n){
				if(!rev[id]) { id++; continue;}
				bool ok=(prex+2==id);
				while(id<=n&&rev[id]){id++;cnt++;}
				if(ok) ret=ret<cnt+prev+1?cnt+prev+1:ret;
				else ret=ret<cnt+1?cnt+1:ret;
				prev=cnt;prex=id-1;cnt=0;
			}
		}
		printf("%d\n",ret);
	}
}
```