#include <bits/stdc++.h>
using namespace std;

int n,k,ren[100005],ans;
bool ch[100005];

int main(){
	while(1){
		scanf("%d%d",&n,&k);
		if(n+k == 0)break;
		ans = 0;
		for(int i = 0;i <= n+1;i++) ch[i]=false,ren[i]=0;
		for(int i = 1;i <= k;i++){
			int t;
			scanf("%d",&t);
			ch[t] = true;
		}

		for(int i = 1;i <= n;i++){
			if(ch[i] == true){
				ren[i] = ren[i-1] + 1;
			}else{
				ren[i-ren[i-1]] = ren[i-1];
			}
			ans = max(ans,ren[i]);
		}
		ren[n+1-ren[n]] = ren[n];

		if(ch[0] == true){
			for(int i = 1;i <= n;i++){
				if(ch[i] == true)continue;
				ans = max(ans,ren[i-1]+1+ren[i+1]);
			}
		}
		printf("%d\n",ans);
	}
	return 0;
}

### Prompt

Your challenge is to write a Cpp solution to the following problem:

problem

There are n cards with one integer from 1 to n and one blank card. Of these n + 1 cards, k cards are given, but 1 ≤ k ≤ n. You can write one integer from 1 to n on a blank card. I want to make a continuous sequence of integers as long as possible with just a given card.

Write a program that outputs the maximum length of a contiguous sequence of integers that can be made from a given card when the given card is entered.



input

The input consists of multiple datasets. Each dataset is given in the following format. The input ends on a line containing two zeros.

On the first line, two integers n (1 ≤ n ≤ 100000) and k (1 ≤ k ≤ n) are written in this order, separated by one blank. The following k line contains one integer. Written one by one, representing the integers written on the given k cards. Blank cards are represented by 0.

Of the scoring data, 40% of the points are 1 ≤ n ≤ 1000, 1 ≤ k ≤ 500, 20% of the points are 1 ≤ n ≤ 60000, 1 ≤ k ≤ 50000. Satisfy 1 ≤ n ≤ 100000, 1 ≤ k ≤ 100000.

The number of datasets does not exceed 5.

output

Outputs an integer on one line for each dataset.

Examples

Input

7 5
6
2
4
7
1
7 5
6
2
0
4
7
0 0


Output

2
4


Input

None


Output

None

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;

int n,k,ren[100005],ans;
bool ch[100005];

int main(){
	while(1){
		scanf("%d%d",&n,&k);
		if(n+k == 0)break;
		ans = 0;
		for(int i = 0;i <= n+1;i++) ch[i]=false,ren[i]=0;
		for(int i = 1;i <= k;i++){
			int t;
			scanf("%d",&t);
			ch[t] = true;
		}

		for(int i = 1;i <= n;i++){
			if(ch[i] == true){
				ren[i] = ren[i-1] + 1;
			}else{
				ren[i-ren[i-1]] = ren[i-1];
			}
			ans = max(ans,ren[i]);
		}
		ren[n+1-ren[n]] = ren[n];

		if(ch[0] == true){
			for(int i = 1;i <= n;i++){
				if(ch[i] == true)continue;
				ans = max(ans,ren[i-1]+1+ren[i+1]);
			}
		}
		printf("%d\n",ans);
	}
	return 0;
}

```