#include <iostream>
#include <vector>
using namespace std;
#define rep(i,n) for(int i=0;i<n;i++)
int main(){
	int n,k;
	while( cin >> k >> n , k){
		bool no = false;
		int ret = 0;
		int data[100001] = {0};
	//	int memo[100000] = {0};
		
		vector<int> t;
		
		rep(i,n){
			int c; cin >> c;
			if(!c)no = true;
			else data[c-1] = 1;
		}
		
		int c = 0;
		
		rep(i,k+1){
			if(data[i]){
				c++;
			}else{
				if(i && c == 0){	
					if(t.back() != 0)t.push_back(0);
				}else{
					ret = max(ret,c);
					t.push_back(c);
					c = 0;
				}
			}
		}
		if(no){
			if(t.size() == 1)ret = max(ret,t[0]+1);
			else rep(i,t.size()-1)ret = max(ret,t[i]+t[i+1]+1);
		}
		cout << ret << endl;
	}
}
### Prompt

Develop a solution in CPP to the problem described below:

problem

There are n cards with one integer from 1 to n and one blank card. Of these n + 1 cards, k cards are given, but 1 ≤ k ≤ n. You can write one integer from 1 to n on a blank card. I want to make a continuous sequence of integers as long as possible with just a given card.

Write a program that outputs the maximum length of a contiguous sequence of integers that can be made from a given card when the given card is entered.



input

The input consists of multiple datasets. Each dataset is given in the following format. The input ends on a line containing two zeros.

On the first line, two integers n (1 ≤ n ≤ 100000) and k (1 ≤ k ≤ n) are written in this order, separated by one blank. The following k line contains one integer. Written one by one, representing the integers written on the given k cards. Blank cards are represented by 0.

Of the scoring data, 40% of the points are 1 ≤ n ≤ 1000, 1 ≤ k ≤ 500, 20% of the points are 1 ≤ n ≤ 60000, 1 ≤ k ≤ 50000. Satisfy 1 ≤ n ≤ 100000, 1 ≤ k ≤ 100000.

The number of datasets does not exceed 5.

output

Outputs an integer on one line for each dataset.

Examples

Input

7 5
6
2
4
7
1
7 5
6
2
0
4
7
0 0


Output

2
4


Input

None


Output

None

### Response

```cpp
#include <iostream>
#include <vector>
using namespace std;
#define rep(i,n) for(int i=0;i<n;i++)
int main(){
	int n,k;
	while( cin >> k >> n , k){
		bool no = false;
		int ret = 0;
		int data[100001] = {0};
	//	int memo[100000] = {0};
		
		vector<int> t;
		
		rep(i,n){
			int c; cin >> c;
			if(!c)no = true;
			else data[c-1] = 1;
		}
		
		int c = 0;
		
		rep(i,k+1){
			if(data[i]){
				c++;
			}else{
				if(i && c == 0){	
					if(t.back() != 0)t.push_back(0);
				}else{
					ret = max(ret,c);
					t.push_back(c);
					c = 0;
				}
			}
		}
		if(no){
			if(t.size() == 1)ret = max(ret,t[0]+1);
			else rep(i,t.size()-1)ret = max(ret,t[i]+t[i+1]+1);
		}
		cout << ret << endl;
	}
}
```