#include <bits/stdc++.h>
using namespace std;

const int maxn = 1e6 + 15;
bool is_prime[maxn];
int sieve(int x){
	int res = 0;
	fill(is_prime+2,is_prime+x+1,true);
	for(int i = 2; i <= x; i++) if(is_prime[i]){
		res++;
		for(int j = 2 * i; j <= x; j += i) is_prime[j] = false;
	}
	return res;
}

int main(){
	int n;
	while(scanf("%d", &n) == 1) printf("%d\n", sieve(n));
	return 0;
}
### Prompt

Your task is to create a cpp solution to the following problem:

Write a program which reads an integer n and prints the number of prime numbers which are less than or equal to n. A prime number is a natural number which has exactly two distinct natural number divisors: 1 and itself. For example, the first four prime numbers are: 2, 3, 5 and 7.



Input

Input consists of several datasets. Each dataset has an integer n (1 ≤ n ≤ 999,999) in a line.

The number of datasets is less than or equal to 30.

Output

For each dataset, prints the number of prime numbers.

Example

Input

10
3
11


Output

4
2
5

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;

const int maxn = 1e6 + 15;
bool is_prime[maxn];
int sieve(int x){
	int res = 0;
	fill(is_prime+2,is_prime+x+1,true);
	for(int i = 2; i <= x; i++) if(is_prime[i]){
		res++;
		for(int j = 2 * i; j <= x; j += i) is_prime[j] = false;
	}
	return res;
}

int main(){
	int n;
	while(scanf("%d", &n) == 1) printf("%d\n", sieve(n));
	return 0;
}
```