#include<cstdio>

int main(){
  int fib[45],n;
  fib[0] = 1;
  fib[1] = 1;
  for(int i=2;i<45;i++){
    fib[i] = fib[i-1] + fib[i-2];
  }
  scanf("%d",&n);
  printf("%d\n",fib[n]);
  return 0;
}
### Prompt

Please provide a cpp coded solution to the problem described below:

Write a program which prints $n$-th fibonacci number for a given integer $n$. The $n$-th fibonacci number is defined by the following recursive formula:

\begin{equation*} fib(n)= \left \\{ \begin{array}{ll} 1 & (n = 0) \\\ 1 & (n = 1) \\\ fib(n - 1) + fib(n - 2) & \\\ \end{array} \right. \end{equation*}

Constraints

* $0 \leq n \leq 44$

Input

An integer $n$ is given.

Example

Input

3


Output

3

### Response

```cpp
#include<cstdio>

int main(){
  int fib[45],n;
  fib[0] = 1;
  fib[1] = 1;
  for(int i=2;i<45;i++){
    fib[i] = fib[i-1] + fib[i-2];
  }
  scanf("%d",&n);
  printf("%d\n",fib[n]);
  return 0;
}
```