#include<bits/stdc++.h>
using namespace std;
int main()
{
	string s;
	cin>>s;
	int t=0,k=s.length()-1;
	if(s[0]!='A'||(int(s[1])>64&&int(s[1])<91)||s[k]=='C') cout<<"WA";
	else
	{
		for(int i=2;i<k+1;i++)
		{
			if(t!=1&&s[i]=='C') t=1;
			else if(int(s[i])>64&&int(s[i])<91)
			{
				cout<<"WA";
				return 0;
			}
		}
		if(t==0) cout<<"WA";
		else cout<<"AC";
	}
	return 0;
}
### Prompt

Your challenge is to write a cpp solution to the following problem:

You are given a string S. Each character of S is uppercase or lowercase English letter. Determine if S satisfies all of the following conditions:

* The initial character of S is an uppercase `A`.
* There is exactly one occurrence of `C` between the third character from the beginning and the second to last character (inclusive).
* All letters except the `A` and `C` mentioned above are lowercase.

Constraints

* 4 ≤ |S| ≤ 10 (|S| is the length of the string S.)
* Each character of S is uppercase or lowercase English letter.

Input

Input is given from Standard Input in the following format:


S


Output

If S satisfies all of the conditions in the problem statement, print `AC`; otherwise, print `WA`.

Examples

Input

AtCoder


Output

AC


Input

ACoder


Output

WA


Input

AcycliC


Output

WA


Input

AtCoCo


Output

WA


Input

Atcoder


Output

WA

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;
int main()
{
	string s;
	cin>>s;
	int t=0,k=s.length()-1;
	if(s[0]!='A'||(int(s[1])>64&&int(s[1])<91)||s[k]=='C') cout<<"WA";
	else
	{
		for(int i=2;i<k+1;i++)
		{
			if(t!=1&&s[i]=='C') t=1;
			else if(int(s[i])>64&&int(s[i])<91)
			{
				cout<<"WA";
				return 0;
			}
		}
		if(t==0) cout<<"WA";
		else cout<<"AC";
	}
	return 0;
}
```