#include <stdio.h>
int main()
{
    int x;
    int f[100];
    f[0]=f[1]=1;
    scanf("%d",&x);
    for(int i=2;i<=x;i++){
      f[i]=f[i-1]+f[i-2];
    }
    printf("%d\n",f[x]);
    return 0;
}
### Prompt

Please create a solution in Cpp to the following problem:

Write a program which prints $n$-th fibonacci number for a given integer $n$. The $n$-th fibonacci number is defined by the following recursive formula:

\begin{equation*} fib(n)= \left \\{ \begin{array}{ll} 1 & (n = 0) \\\ 1 & (n = 1) \\\ fib(n - 1) + fib(n - 2) & \\\ \end{array} \right. \end{equation*}

Constraints

* $0 \leq n \leq 44$

Input

An integer $n$ is given.

Example

Input

3


Output

3

### Response

```cpp
#include <stdio.h>
int main()
{
    int x;
    int f[100];
    f[0]=f[1]=1;
    scanf("%d",&x);
    for(int i=2;i<=x;i++){
      f[i]=f[i-1]+f[i-2];
    }
    printf("%d\n",f[x]);
    return 0;
}
```