#include <iostream>
#include <climits>
using namespace std;

int main() {
	int N;
	cin >> N;

	int a[44];
	a[0] = a[1] = 1;

	for (int i=2; i<=N; i++)
		a[i] = a[i-1] + a[i-2];

	cout << a[N] << endl;

	return 0;
}


### Prompt

Please provide a Cpp coded solution to the problem described below:

Write a program which prints $n$-th fibonacci number for a given integer $n$. The $n$-th fibonacci number is defined by the following recursive formula:

\begin{equation*} fib(n)= \left \\{ \begin{array}{ll} 1 & (n = 0) \\\ 1 & (n = 1) \\\ fib(n - 1) + fib(n - 2) & \\\ \end{array} \right. \end{equation*}

Constraints

* $0 \leq n \leq 44$

Input

An integer $n$ is given.

Example

Input

3


Output

3

### Response

```cpp
#include <iostream>
#include <climits>
using namespace std;

int main() {
	int N;
	cin >> N;

	int a[44];
	a[0] = a[1] = 1;

	for (int i=2; i<=N; i++)
		a[i] = a[i-1] + a[i-2];

	cout << a[N] << endl;

	return 0;
}


```