#include <algorithm>
#include <iostream>
#include <cstring>
using namespace std;
#define FOR(i,a,b) for (int i=(a);i<(b);i++)
#define REP(i,n) for (int i=0;i<(n);i++)
#define PB push_back
#define MP make_pair
#define LL long long 
const int INF = 1145141919;

int main(){
	while (1){
		int n, k, memo, steps, ans = 0;
		bool flag = 0, used;
		int deta[100002];
		cin >> n >> k;
		if (n == 0 && k == 0) return 0;
		REP (i, k) cin >> deta[i];
		sort (deta, deta + k);
		if (deta[0] == 0) flag = 1;
		FOR (i, flag, k){
			memo = deta[i];
			steps = 1;
			used = 0;
			FOR (j, i + 1, k){
				if (memo + 1 == deta[j]){
					memo++;
					steps++;
				}else if (flag == 1 && used == 0){
					memo++;
					steps++;
					j--;
					used = 1;
				}else{
					break;
				}
			}
			ans = max (ans, steps);
		}
		cout << ans << endl;
	}	
}
### Prompt

Develop a solution in cpp to the problem described below:

problem

There are n cards with one integer from 1 to n and one blank card. Of these n + 1 cards, k cards are given, but 1 ≤ k ≤ n. You can write one integer from 1 to n on a blank card. I want to make a continuous sequence of integers as long as possible with just a given card.

Write a program that outputs the maximum length of a contiguous sequence of integers that can be made from a given card when the given card is entered.



input

The input consists of multiple datasets. Each dataset is given in the following format. The input ends on a line containing two zeros.

On the first line, two integers n (1 ≤ n ≤ 100000) and k (1 ≤ k ≤ n) are written in this order, separated by one blank. The following k line contains one integer. Written one by one, representing the integers written on the given k cards. Blank cards are represented by 0.

Of the scoring data, 40% of the points are 1 ≤ n ≤ 1000, 1 ≤ k ≤ 500, 20% of the points are 1 ≤ n ≤ 60000, 1 ≤ k ≤ 50000. Satisfy 1 ≤ n ≤ 100000, 1 ≤ k ≤ 100000.

The number of datasets does not exceed 5.

output

Outputs an integer on one line for each dataset.

Examples

Input

7 5
6
2
4
7
1
7 5
6
2
0
4
7
0 0


Output

2
4


Input

None


Output

None

### Response

```cpp
#include <algorithm>
#include <iostream>
#include <cstring>
using namespace std;
#define FOR(i,a,b) for (int i=(a);i<(b);i++)
#define REP(i,n) for (int i=0;i<(n);i++)
#define PB push_back
#define MP make_pair
#define LL long long 
const int INF = 1145141919;

int main(){
	while (1){
		int n, k, memo, steps, ans = 0;
		bool flag = 0, used;
		int deta[100002];
		cin >> n >> k;
		if (n == 0 && k == 0) return 0;
		REP (i, k) cin >> deta[i];
		sort (deta, deta + k);
		if (deta[0] == 0) flag = 1;
		FOR (i, flag, k){
			memo = deta[i];
			steps = 1;
			used = 0;
			FOR (j, i + 1, k){
				if (memo + 1 == deta[j]){
					memo++;
					steps++;
				}else if (flag == 1 && used == 0){
					memo++;
					steps++;
					j--;
					used = 1;
				}else{
					break;
				}
			}
			ans = max (ans, steps);
		}
		cout << ans << endl;
	}	
}
```