#include <bits/stdc++.h>
using namespace std;
const int N = 5e4 + 5;
long long n;
int main() {
  cin >> n;
  if (n & 1) {
    printf("%lld\n", (n - 3) / 2 + 1);
    n -= 3;
    printf("3 ");
  } else
    printf("%lld\n", n / 2);
  for (int i = 1; i <= n / 2; ++i) printf("2 ");
  return 0;
}

### Prompt

Your challenge is to write a Cpp solution to the following problem:

Bachgold problem is very easy to formulate. Given a positive integer n represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any integer greater than 1.

Recall that integer k is called prime if it is greater than 1 and has exactly two positive integer divisors — 1 and k. 

Input

The only line of the input contains a single integer n (2 ≤ n ≤ 100 000).

Output

The first line of the output contains a single integer k — maximum possible number of primes in representation.

The second line should contain k primes with their sum equal to n. You can print them in any order. If there are several optimal solution, print any of them.

Examples

Input

5


Output

2
2 3


Input

6


Output

3
2 2 2

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
const int N = 5e4 + 5;
long long n;
int main() {
  cin >> n;
  if (n & 1) {
    printf("%lld\n", (n - 3) / 2 + 1);
    n -= 3;
    printf("3 ");
  } else
    printf("%lld\n", n / 2);
  for (int i = 1; i <= n / 2; ++i) printf("2 ");
  return 0;
}

```