#include<iostream>
using namespace std;
int a[1000000];
int sum[1000000];
int n;
int main(){
 for (int i=2;i<1000000;i++){
  if (!a[i])
   for (int j=i*2;j<1000000;j+=i)
    a[j]=1;
 }
 for (int i=2;i<1000000;i++) sum[i]=sum[i-1]+(a[i]==0?1:0);
 while (cin>>n)
  cout<<sum[n]<<endl;
 return 0;
}

### Prompt

Please provide a Cpp coded solution to the problem described below:

Write a program which reads an integer n and prints the number of prime numbers which are less than or equal to n. A prime number is a natural number which has exactly two distinct natural number divisors: 1 and itself. For example, the first four prime numbers are: 2, 3, 5 and 7.



Input

Input consists of several datasets. Each dataset has an integer n (1 ≤ n ≤ 999,999) in a line.

The number of datasets is less than or equal to 30.

Output

For each dataset, prints the number of prime numbers.

Example

Input

10
3
11


Output

4
2
5

### Response

```cpp
#include<iostream>
using namespace std;
int a[1000000];
int sum[1000000];
int n;
int main(){
 for (int i=2;i<1000000;i++){
  if (!a[i])
   for (int j=i*2;j<1000000;j+=i)
    a[j]=1;
 }
 for (int i=2;i<1000000;i++) sum[i]=sum[i-1]+(a[i]==0?1:0);
 while (cin>>n)
  cout<<sum[n]<<endl;
 return 0;
}

```