#include <bits/stdc++.h>
using namespace std;
const int inf = 1 << 30;
const long long INF = 1ll << 60;
const double pi = acos(-1);
const double eps = 1e-9;
const long long mod = 1e9 + 7;
const int dx[4] = {0, 1, 0, -1}, dy[4] = {1, 0, -1, 0};
int n, m;
vector<string> a;
int main() {
  ios::sync_with_stdio(0);
  cin.tie(0);
  cin >> n >> m;
  a = vector<string>(n);
  for (int i = 0; i < n; i++) {
    if (i % 2 == 0)
      a[i] = string(m, '#');
    else {
      a[i] = string(m, '.');
      if (i / 2 % 2 == 0)
        a[i][m - 1] = '#';
      else
        a[i][0] = '#';
    }
  }
  for (int i = 0; i < n; i++) cout << a[i] << endl;
}

### Prompt

Please formulate a CPP solution to the following problem:

Fox Ciel starts to learn programming. The first task is drawing a fox! However, that turns out to be too hard for a beginner, so she decides to draw a snake instead.

A snake is a pattern on a n by m table. Denote c-th cell of r-th row as (r, c). The tail of the snake is located at (1, 1), then it's body extends to (1, m), then goes down 2 rows to (3, m), then goes left to (3, 1) and so on.

Your task is to draw this snake for Fox Ciel: the empty cells should be represented as dot characters ('.') and the snake cells should be filled with number signs ('#').

Consider sample tests in order to understand the snake pattern.

Input

The only line contains two integers: n and m (3 ≤ n, m ≤ 50). 

n is an odd number.

Output

Output n lines. Each line should contain a string consisting of m characters. Do not output spaces.

Examples

Input

3 3


Output

###
..#
###


Input

3 4


Output

####
...#
####


Input

5 3


Output

###
..#
###
#..
###


Input

9 9


Output

#########
........#
#########
#........
#########
........#
#########
#........
#########

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
const int inf = 1 << 30;
const long long INF = 1ll << 60;
const double pi = acos(-1);
const double eps = 1e-9;
const long long mod = 1e9 + 7;
const int dx[4] = {0, 1, 0, -1}, dy[4] = {1, 0, -1, 0};
int n, m;
vector<string> a;
int main() {
  ios::sync_with_stdio(0);
  cin.tie(0);
  cin >> n >> m;
  a = vector<string>(n);
  for (int i = 0; i < n; i++) {
    if (i % 2 == 0)
      a[i] = string(m, '#');
    else {
      a[i] = string(m, '.');
      if (i / 2 % 2 == 0)
        a[i][m - 1] = '#';
      else
        a[i][0] = '#';
    }
  }
  for (int i = 0; i < n; i++) cout << a[i] << endl;
}

```