#include <iostream>
#include <algorithm>
#include <vector>

using namespace std;

int main() {
  
  int N, K;
  while(cin >> N >> K && (N|K)) {
    int cnt = 0;
    vector<int> v(K);
    for(int i=0; i<K; i++) cin >> v[i];
    sort(v.begin(), v.end());
    bool zflag = false;
    if(v[0] == 0) zflag = true;
    int fst = 0, snd = 0;
    int len = 0;
    int zerocnt = 1;
    int prev = v[zflag];
    for(int i=1+zflag; i<K+1; i++) {
      if(i<K && prev+1 == v[i]) { snd = i; prev = v[i]; }
      else if(i < K && zflag && zerocnt) { zerocnt--; fst --; i--; prev ++; }
      else {
        len = max(len, snd-fst+1);
        fst = i;
        if(zflag) { zerocnt = 1; }
        prev = v[i];
      }
    }
    cout << len << endl;
  }
  
  return 0;
}
### Prompt

Please create a solution in cpp to the following problem:

problem

There are n cards with one integer from 1 to n and one blank card. Of these n + 1 cards, k cards are given, but 1 ≤ k ≤ n. You can write one integer from 1 to n on a blank card. I want to make a continuous sequence of integers as long as possible with just a given card.

Write a program that outputs the maximum length of a contiguous sequence of integers that can be made from a given card when the given card is entered.



input

The input consists of multiple datasets. Each dataset is given in the following format. The input ends on a line containing two zeros.

On the first line, two integers n (1 ≤ n ≤ 100000) and k (1 ≤ k ≤ n) are written in this order, separated by one blank. The following k line contains one integer. Written one by one, representing the integers written on the given k cards. Blank cards are represented by 0.

Of the scoring data, 40% of the points are 1 ≤ n ≤ 1000, 1 ≤ k ≤ 500, 20% of the points are 1 ≤ n ≤ 60000, 1 ≤ k ≤ 50000. Satisfy 1 ≤ n ≤ 100000, 1 ≤ k ≤ 100000.

The number of datasets does not exceed 5.

output

Outputs an integer on one line for each dataset.

Examples

Input

7 5
6
2
4
7
1
7 5
6
2
0
4
7
0 0


Output

2
4


Input

None


Output

None

### Response

```cpp
#include <iostream>
#include <algorithm>
#include <vector>

using namespace std;

int main() {
  
  int N, K;
  while(cin >> N >> K && (N|K)) {
    int cnt = 0;
    vector<int> v(K);
    for(int i=0; i<K; i++) cin >> v[i];
    sort(v.begin(), v.end());
    bool zflag = false;
    if(v[0] == 0) zflag = true;
    int fst = 0, snd = 0;
    int len = 0;
    int zerocnt = 1;
    int prev = v[zflag];
    for(int i=1+zflag; i<K+1; i++) {
      if(i<K && prev+1 == v[i]) { snd = i; prev = v[i]; }
      else if(i < K && zflag && zerocnt) { zerocnt--; fst --; i--; prev ++; }
      else {
        len = max(len, snd-fst+1);
        fst = i;
        if(zflag) { zerocnt = 1; }
        prev = v[i];
      }
    }
    cout << len << endl;
  }
  
  return 0;
}
```