#include<bits/stdc++.h>
using namespace std;

int f[1000001];
int main(){
    fill_n(f,1000001,1);
    f[0]=f[1]=0;
    
    for(int i=2;i<1000001;i++){
        f[i]+=f[i-1];
        if(!f[i])continue;
        for(int j=i+i;j<1000001;j+=i)f[j]=0;
    }
    
    int N;
    
    while(scanf("%d",&N)!=EOF){
        printf("%d\n",f[N]);
    }
    
    return 0;
    
}
### Prompt

In Cpp, your task is to solve the following problem:

Write a program which reads an integer n and prints the number of prime numbers which are less than or equal to n. A prime number is a natural number which has exactly two distinct natural number divisors: 1 and itself. For example, the first four prime numbers are: 2, 3, 5 and 7.



Input

Input consists of several datasets. Each dataset has an integer n (1 ≤ n ≤ 999,999) in a line.

The number of datasets is less than or equal to 30.

Output

For each dataset, prints the number of prime numbers.

Example

Input

10
3
11


Output

4
2
5

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;

int f[1000001];
int main(){
    fill_n(f,1000001,1);
    f[0]=f[1]=0;
    
    for(int i=2;i<1000001;i++){
        f[i]+=f[i-1];
        if(!f[i])continue;
        for(int j=i+i;j<1000001;j+=i)f[j]=0;
    }
    
    int N;
    
    while(scanf("%d",&N)!=EOF){
        printf("%d\n",f[N]);
    }
    
    return 0;
    
}
```