#include <cstdio>
using namespace std;
 
int y[27] = {10010,11020,20011,21012,11011,21021,22022,12021,11011,12012,10120,11130,20121,21122,11121,21131,22132,12131,11121,12122,10221,11231,12113,20222,21223,11222};
char x[30000];
 
int main()
{
    for(int i = 0; i < 26; ++i)
        if (!x[y[i]])
            x[y[i]] = i + 'a';
    int T;
    scanf("%d", &T);
    while(T--)
    {
        int z = 0;
        for (int s, i = 0; i < 5; ++i)
        {
            scanf("%d", &s);
            z = z * 10 + s;
        }
        putchar(x[z]);
    }
    return 0;
}

### Prompt

Your challenge is to write a CPP solution to the following problem:



Input

The first line of the input contains a single integer N (1 ≤ N ≤ 24). The next N lines contain 5 space-separated integers each. The first three integers will be between 0 and 2, inclusive. The last two integers will be between 0 and 3, inclusive. The sum of the first three integers will be equal to the sum of the last two integers.

Output

Output the result – a string of lowercase English letters.

Examples

Input


1
1 0 0 1 0


Output


a


Input


10
2 0 0 1 1
1 1 1 2 1
2 1 0 1 2
1 1 0 1 1
2 1 0 2 1
1 1 1 2 1
1 2 1 3 1
2 0 0 1 1
1 1 0 1 1
1 1 2 2 2


Output


codeforcez

### Response

```cpp
#include <cstdio>
using namespace std;
 
int y[27] = {10010,11020,20011,21012,11011,21021,22022,12021,11011,12012,10120,11130,20121,21122,11121,21131,22132,12131,11121,12122,10221,11231,12113,20222,21223,11222};
char x[30000];
 
int main()
{
    for(int i = 0; i < 26; ++i)
        if (!x[y[i]])
            x[y[i]] = i + 'a';
    int T;
    scanf("%d", &T);
    while(T--)
    {
        int z = 0;
        for (int s, i = 0; i < 5; ++i)
        {
            scanf("%d", &s);
            z = z * 10 + s;
        }
        putchar(x[z]);
    }
    return 0;
}

```