#include <iostream>
#include <algorithm>
using namespace std;
int main(){
int n;
int k;
int b;
int c;
int d;
int e;//ワイルドカードの値
while(cin >>n){
cin >>k;
if(n==0){break;}
int a[k];
b=0;
while(b<k){
cin >>a[b];
b=b+1;}
sort(a,a+b);
c=1;
d=0;
if(a[0]!=0){
b=1;
while(b<k){
if(a[b]==a[b-1]+1){c=c+1;}
else{if(d<c){d=c;} c=1;}
b=b+1;}}
if(a[0]==0){
e=0;
b=2;
if(a[1]!=1){c=2; e=a[1]-1;}
while(b<k){
if(a[b]==a[b-1]+1){c=c+1;}
else if(a[b]==a[b-1]+2){c=a[b]-e; e=a[b]-1;}
else{c=2; e=a[b]-1;}
if(d<c){d=c;}
b=b+1;}
if(a[k-1]!=n){c=a[b]+1-e; if(d<c){d=c;}}}
cout <<d<<endl;}}
### Prompt

Create a solution in CPP for the following problem:

problem

There are n cards with one integer from 1 to n and one blank card. Of these n + 1 cards, k cards are given, but 1 ≤ k ≤ n. You can write one integer from 1 to n on a blank card. I want to make a continuous sequence of integers as long as possible with just a given card.

Write a program that outputs the maximum length of a contiguous sequence of integers that can be made from a given card when the given card is entered.



input

The input consists of multiple datasets. Each dataset is given in the following format. The input ends on a line containing two zeros.

On the first line, two integers n (1 ≤ n ≤ 100000) and k (1 ≤ k ≤ n) are written in this order, separated by one blank. The following k line contains one integer. Written one by one, representing the integers written on the given k cards. Blank cards are represented by 0.

Of the scoring data, 40% of the points are 1 ≤ n ≤ 1000, 1 ≤ k ≤ 500, 20% of the points are 1 ≤ n ≤ 60000, 1 ≤ k ≤ 50000. Satisfy 1 ≤ n ≤ 100000, 1 ≤ k ≤ 100000.

The number of datasets does not exceed 5.

output

Outputs an integer on one line for each dataset.

Examples

Input

7 5
6
2
4
7
1
7 5
6
2
0
4
7
0 0


Output

2
4


Input

None


Output

None

### Response

```cpp
#include <iostream>
#include <algorithm>
using namespace std;
int main(){
int n;
int k;
int b;
int c;
int d;
int e;//ワイルドカードの値
while(cin >>n){
cin >>k;
if(n==0){break;}
int a[k];
b=0;
while(b<k){
cin >>a[b];
b=b+1;}
sort(a,a+b);
c=1;
d=0;
if(a[0]!=0){
b=1;
while(b<k){
if(a[b]==a[b-1]+1){c=c+1;}
else{if(d<c){d=c;} c=1;}
b=b+1;}}
if(a[0]==0){
e=0;
b=2;
if(a[1]!=1){c=2; e=a[1]-1;}
while(b<k){
if(a[b]==a[b-1]+1){c=c+1;}
else if(a[b]==a[b-1]+2){c=a[b]-e; e=a[b]-1;}
else{c=2; e=a[b]-1;}
if(d<c){d=c;}
b=b+1;}
if(a[k-1]!=n){c=a[b]+1-e; if(d<c){d=c;}}}
cout <<d<<endl;}}
```