#include <bits/stdc++.h>
using namespace std;
const long double E = exp(1.0);
const long long mx = 2e5 + 5;
const long long mod = 1e9 + 7;
const long double esp = 1e-9;
const long double pi = acos(-1.0);
int main() {
  map<int, int> a;
  map<int, int> b;
  int n, t;
  cin >> n;
  int flag = 0;
  int ans = 0;
  for (int i = 1; i <= n; i++) {
    cin >> t;
    a[t]++;
    b[a[t] - 1]--;
    b[a[t]]++;
    flag = max(flag, a[t]);
    if (i == b[1]) ans = max(ans, i);
    if (b[i] == 1) ans = max(ans, i);
    if (b[1] == 1 && flag * b[flag] == i - 1) ans = max(ans, i);
    if (b[flag] == 1 && (b[flag - 1] * (flag - 1) == i - flag))
      ans = max(ans, i);
  }
  cout << ans << endl;
}

### Prompt

Generate a CPP solution to the following problem:

This problem is same as the previous one, but has larger constraints.

Shiro's just moved to the new house. She wants to invite all friends of her to the house so they can play monopoly. However, her house is too small, so she can only invite one friend at a time.

For each of the n days since the day Shiro moved to the new house, there will be exactly one cat coming to the Shiro's house. The cat coming in the i-th day has a ribbon with color u_i. Shiro wants to know the largest number x, such that if we consider the streak of the first x days, it is possible to remove exactly one day from this streak so that every ribbon color that has appeared among the remaining x - 1 will have the same number of occurrences.

For example, consider the following sequence of u_i: [2, 2, 1, 1, 5, 4, 4, 5]. Then x = 7 makes a streak, since if we remove the leftmost u_i = 5, each ribbon color will appear exactly twice in the prefix of x - 1 days. Note that x = 8 doesn't form a streak, since you must remove exactly one day. 

Since Shiro is just a cat, she is not very good at counting and needs your help finding the longest streak.

Input

The first line contains a single integer n (1 ≤ n ≤ 10^5) — the total number of days.

The second line contains n integers u_1, u_2, …, u_n (1 ≤ u_i ≤ 10^5) — the colors of the ribbons the cats wear. 

Output

Print a single integer x — the largest possible streak of days.

Examples

Input


13
1 1 1 2 2 2 3 3 3 4 4 4 5


Output


13

Input


5
10 100 20 200 1


Output


5

Input


1
100000


Output


1

Input


7
3 2 1 1 4 5 1


Output


6

Input


6
1 1 1 2 2 2


Output


5

Note

In the first example, we can choose the longest streak of 13 days, since upon removing the last day out of the streak, all of the remaining colors 1, 2, 3, and 4 will have the same number of occurrences of 3. Note that the streak can also be 10 days (by removing the 10-th day from this streak) but we are interested in the longest streak.

In the fourth example, if we take the streak of the first 6 days, we can remove the third day from this streak then all of the remaining colors 1, 2, 3, 4 and 5 will occur exactly once.

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
const long double E = exp(1.0);
const long long mx = 2e5 + 5;
const long long mod = 1e9 + 7;
const long double esp = 1e-9;
const long double pi = acos(-1.0);
int main() {
  map<int, int> a;
  map<int, int> b;
  int n, t;
  cin >> n;
  int flag = 0;
  int ans = 0;
  for (int i = 1; i <= n; i++) {
    cin >> t;
    a[t]++;
    b[a[t] - 1]--;
    b[a[t]]++;
    flag = max(flag, a[t]);
    if (i == b[1]) ans = max(ans, i);
    if (b[i] == 1) ans = max(ans, i);
    if (b[1] == 1 && flag * b[flag] == i - 1) ans = max(ans, i);
    if (b[flag] == 1 && (b[flag - 1] * (flag - 1) == i - flag))
      ans = max(ans, i);
  }
  cout << ans << endl;
}

```