#include <bits/stdc++.h>
using namespace std;
int main() {
  long long r, g, b, res1 = 0, res2 = 0, res3 = 0, ans = 0, sum = 0, r1, g1, b1;
  cin >> r >> g >> b;
  r1 = r;
  g1 = g;
  b1 = b;
  res1 += r / 3 + g / 3 + b / 3;
  if (r > 0 && g > 0 && b > 0) {
    r1--;
    g1--;
    b1--;
    res2 = 1;
  }
  if (r > 1 && g > 1 && b > 1) {
    r -= 2;
    g -= 2;
    b -= 2;
    res3 = 2;
  }
  res2 += r1 / 3 + g1 / 3 + b1 / 3;
  res3 += r / 3 + g / 3 + b / 3;
  ans = max(max(res1, res2), res3);
  printf("%lld\n", ans);
  return 0;
}

### Prompt

Generate a Cpp solution to the following problem:

Fox Ciel has some flowers: r red flowers, g green flowers and b blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:

  * To make a "red bouquet", it needs 3 red flowers. 
  * To make a "green bouquet", it needs 3 green flowers. 
  * To make a "blue bouquet", it needs 3 blue flowers. 
  * To make a "mixing bouquet", it needs 1 red, 1 green and 1 blue flower. 



Help Fox Ciel to find the maximal number of bouquets she can make.

Input

The first line contains three integers r, g and b (0 ≤ r, g, b ≤ 109) — the number of red, green and blue flowers.

Output

Print the maximal number of bouquets Fox Ciel can make.

Examples

Input

3 6 9


Output

6


Input

4 4 4


Output

4


Input

0 0 0


Output

0

Note

In test case 1, we can make 1 red bouquet, 2 green bouquets and 3 blue bouquets.

In test case 2, we can make 1 red, 1 green, 1 blue and 1 mixing bouquet.

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  long long r, g, b, res1 = 0, res2 = 0, res3 = 0, ans = 0, sum = 0, r1, g1, b1;
  cin >> r >> g >> b;
  r1 = r;
  g1 = g;
  b1 = b;
  res1 += r / 3 + g / 3 + b / 3;
  if (r > 0 && g > 0 && b > 0) {
    r1--;
    g1--;
    b1--;
    res2 = 1;
  }
  if (r > 1 && g > 1 && b > 1) {
    r -= 2;
    g -= 2;
    b -= 2;
    res3 = 2;
  }
  res2 += r1 / 3 + g1 / 3 + b1 / 3;
  res3 += r / 3 + g / 3 + b / 3;
  ans = max(max(res1, res2), res3);
  printf("%lld\n", ans);
  return 0;
}

```