#include<bits/stdc++.h>
#define rep(i,n)for(int i=0;i<n;i++)
using namespace std;

int arr[100000];
int main() {
	int n, k;
	while (scanf("%d%d", &n, &k), n) {
		rep(i, k)
			scanf("%d", &arr[i]);
		bool flag = false;
		if (arr[0])flag = true;
		sort(arr, arr + k);
		int Max = 0, cnt = 0;
		for (int i = 1; i <= n; i++) {
			for (int j = i; j <= n; j++) {
				if (!binary_search(arr, arr + k, j)) {
					if (!flag) { flag = true; cnt++; }
					else {
						Max = max(Max, cnt);
						cnt = 0;
						if (!arr[0])
							flag = false;
						break;
					}
				}
				else cnt++;
			}
		}
		printf("%d\n", Max);
	}
	return 0;
}
### Prompt

Please formulate a cpp solution to the following problem:

problem

There are n cards with one integer from 1 to n and one blank card. Of these n + 1 cards, k cards are given, but 1 ≤ k ≤ n. You can write one integer from 1 to n on a blank card. I want to make a continuous sequence of integers as long as possible with just a given card.

Write a program that outputs the maximum length of a contiguous sequence of integers that can be made from a given card when the given card is entered.



input

The input consists of multiple datasets. Each dataset is given in the following format. The input ends on a line containing two zeros.

On the first line, two integers n (1 ≤ n ≤ 100000) and k (1 ≤ k ≤ n) are written in this order, separated by one blank. The following k line contains one integer. Written one by one, representing the integers written on the given k cards. Blank cards are represented by 0.

Of the scoring data, 40% of the points are 1 ≤ n ≤ 1000, 1 ≤ k ≤ 500, 20% of the points are 1 ≤ n ≤ 60000, 1 ≤ k ≤ 50000. Satisfy 1 ≤ n ≤ 100000, 1 ≤ k ≤ 100000.

The number of datasets does not exceed 5.

output

Outputs an integer on one line for each dataset.

Examples

Input

7 5
6
2
4
7
1
7 5
6
2
0
4
7
0 0


Output

2
4


Input

None


Output

None

### Response

```cpp
#include<bits/stdc++.h>
#define rep(i,n)for(int i=0;i<n;i++)
using namespace std;

int arr[100000];
int main() {
	int n, k;
	while (scanf("%d%d", &n, &k), n) {
		rep(i, k)
			scanf("%d", &arr[i]);
		bool flag = false;
		if (arr[0])flag = true;
		sort(arr, arr + k);
		int Max = 0, cnt = 0;
		for (int i = 1; i <= n; i++) {
			for (int j = i; j <= n; j++) {
				if (!binary_search(arr, arr + k, j)) {
					if (!flag) { flag = true; cnt++; }
					else {
						Max = max(Max, cnt);
						cnt = 0;
						if (!arr[0])
							flag = false;
						break;
					}
				}
				else cnt++;
			}
		}
		printf("%d\n", Max);
	}
	return 0;
}
```