#include<iostream>
using namespace std;

int main(){
while(1){
	bool a[100000+2];
	fill(a,a+100002,false);
	int n,k,b,ans=0;
	scanf("%d%d",&n,&k);
if(n==0&&k==0)break;
	for(int i=0;i<k;i++){
		scanf("%d",&b);
		a[b]=true;
	}
	int c=0,d=0;
	if(a[0]){
		for(int i=1;i<n+1;i++){
			if(a[i])d++;
			if(!a[i]){
				if(c+d+1>ans)ans=c+d+1;
				if(a[i+1]){
					c=d;
					d=1;
				}
				if(!a[i+1]){
					c=0;
					d=0;
				}
				i++;
			}
		}
		if(c+d+1>ans)ans=c+d+1;
	}
	if(!a[0]){
		for(int i=1;i<n+1;i++){
			if(a[i])d++;
			if(!a[i]){
				if(ans<d)ans=d;
				d=0;
			}
		}
	}
	printf("%d\n",ans);
}
}
### Prompt

Your task is to create a cpp solution to the following problem:

problem

There are n cards with one integer from 1 to n and one blank card. Of these n + 1 cards, k cards are given, but 1 ≤ k ≤ n. You can write one integer from 1 to n on a blank card. I want to make a continuous sequence of integers as long as possible with just a given card.

Write a program that outputs the maximum length of a contiguous sequence of integers that can be made from a given card when the given card is entered.



input

The input consists of multiple datasets. Each dataset is given in the following format. The input ends on a line containing two zeros.

On the first line, two integers n (1 ≤ n ≤ 100000) and k (1 ≤ k ≤ n) are written in this order, separated by one blank. The following k line contains one integer. Written one by one, representing the integers written on the given k cards. Blank cards are represented by 0.

Of the scoring data, 40% of the points are 1 ≤ n ≤ 1000, 1 ≤ k ≤ 500, 20% of the points are 1 ≤ n ≤ 60000, 1 ≤ k ≤ 50000. Satisfy 1 ≤ n ≤ 100000, 1 ≤ k ≤ 100000.

The number of datasets does not exceed 5.

output

Outputs an integer on one line for each dataset.

Examples

Input

7 5
6
2
4
7
1
7 5
6
2
0
4
7
0 0


Output

2
4


Input

None


Output

None

### Response

```cpp
#include<iostream>
using namespace std;

int main(){
while(1){
	bool a[100000+2];
	fill(a,a+100002,false);
	int n,k,b,ans=0;
	scanf("%d%d",&n,&k);
if(n==0&&k==0)break;
	for(int i=0;i<k;i++){
		scanf("%d",&b);
		a[b]=true;
	}
	int c=0,d=0;
	if(a[0]){
		for(int i=1;i<n+1;i++){
			if(a[i])d++;
			if(!a[i]){
				if(c+d+1>ans)ans=c+d+1;
				if(a[i+1]){
					c=d;
					d=1;
				}
				if(!a[i+1]){
					c=0;
					d=0;
				}
				i++;
			}
		}
		if(c+d+1>ans)ans=c+d+1;
	}
	if(!a[0]){
		for(int i=1;i<n+1;i++){
			if(a[i])d++;
			if(!a[i]){
				if(ans<d)ans=d;
				d=0;
			}
		}
	}
	printf("%d\n",ans);
}
}
```