#include<bits/stdc++.h>
using namespace std;
#define inf 1e9
#define ll long long
#define ull unsigned long long
#define M 1000000007
#define P pair<int,int>
#define PLL pair<ll,ll>
#define FOR(i,m,n) for(int i=m;i<n;i++)
#define RFOR(i,m,n) for(int i=m;i>=n;i--)
#define rep(i,n) FOR(i,0,n)
#define rrep(i,n) RFOR(i,n,0)
#define all(a) a.begin(),a.end()
const int vx[4] = {0,1,0,-1};
const int vy[4] = {1,0,-1,0};
#define PI 3.14159265


int main(){
  double x1, y1, x2, y2, x3, y3;
  cin >> x1 >> y1 >> x2 >> y2 >> x3 >> y3;
  double d1 = hypot(x1 - x2, y1 - y2);
  double d2 = hypot(x2 - x3, y2 - y3);
  double d3 = hypot(x3 - x1, y3 - y1);
  double s = (d1 + d2 + d3) * 0.5;
  s = sqrt(s * (s - d1) * (s - d2) * (s - d3));
  double r = 2 * s / (d1 + d2 + d3);
  double p = max(d1, max(d2, d3));
  cout << fixed << setprecision(10) << r * p / (p + 2 * r) << endl;

  return 0;
}
### Prompt

Generate a cpp solution to the following problem:

Snuke received a triangle as a birthday present. The coordinates of the three vertices were (x_1, y_1), (x_2, y_2), and (x_3, y_3).

He wants to draw two circles with the same radius inside the triangle such that the two circles do not overlap (but they may touch). Compute the maximum possible radius of the circles.

Constraints

* 0 ≤ x_i, y_i ≤ 1000
* The coordinates are integers.
* The three points are not on the same line.

Input

The input is given from Standard Input in the following format:


x_1 y_1
x_2 y_2
x_3 y_3


Output

Print the maximum possible radius of the circles. The absolute error or the relative error must be at most 10^{-9}.

Examples

Input

0 0
1 1
2 0


Output

0.292893218813


Input

3 1
1 5
4 9


Output

0.889055514217

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;
#define inf 1e9
#define ll long long
#define ull unsigned long long
#define M 1000000007
#define P pair<int,int>
#define PLL pair<ll,ll>
#define FOR(i,m,n) for(int i=m;i<n;i++)
#define RFOR(i,m,n) for(int i=m;i>=n;i--)
#define rep(i,n) FOR(i,0,n)
#define rrep(i,n) RFOR(i,n,0)
#define all(a) a.begin(),a.end()
const int vx[4] = {0,1,0,-1};
const int vy[4] = {1,0,-1,0};
#define PI 3.14159265


int main(){
  double x1, y1, x2, y2, x3, y3;
  cin >> x1 >> y1 >> x2 >> y2 >> x3 >> y3;
  double d1 = hypot(x1 - x2, y1 - y2);
  double d2 = hypot(x2 - x3, y2 - y3);
  double d3 = hypot(x3 - x1, y3 - y1);
  double s = (d1 + d2 + d3) * 0.5;
  s = sqrt(s * (s - d1) * (s - d2) * (s - d3));
  double r = 2 * s / (d1 + d2 + d3);
  double p = max(d1, max(d2, d3));
  cout << fixed << setprecision(10) << r * p / (p + 2 * r) << endl;

  return 0;
}
```