#include <iostream>
#include <vector>
using namespace std;

int main() {
	vector<int> p;
	int n;
	p.push_back(2);
	for(int i=3;i<999999;i++){
		for(int j=0;;j++){
			if(i%p[j]==0)
			break;
			if(i<p[j]*p[j]){
			p.push_back(i);
			break;
			}
		}
	}
	p.push_back(9999999);
	while(cin >> n){
		int i=0;
		while(n>=p[i]){
			i++;
		}
		cout << i << endl;
	}
	return 0;
}
### Prompt

Please provide a CPP coded solution to the problem described below:

Write a program which reads an integer n and prints the number of prime numbers which are less than or equal to n. A prime number is a natural number which has exactly two distinct natural number divisors: 1 and itself. For example, the first four prime numbers are: 2, 3, 5 and 7.



Input

Input consists of several datasets. Each dataset has an integer n (1 ≤ n ≤ 999,999) in a line.

The number of datasets is less than or equal to 30.

Output

For each dataset, prints the number of prime numbers.

Example

Input

10
3
11


Output

4
2
5

### Response

```cpp
#include <iostream>
#include <vector>
using namespace std;

int main() {
	vector<int> p;
	int n;
	p.push_back(2);
	for(int i=3;i<999999;i++){
		for(int j=0;;j++){
			if(i%p[j]==0)
			break;
			if(i<p[j]*p[j]){
			p.push_back(i);
			break;
			}
		}
	}
	p.push_back(9999999);
	while(cin >> n){
		int i=0;
		while(n>=p[i]){
			i++;
		}
		cout << i << endl;
	}
	return 0;
}
```