#include <bits/stdc++.h>
using namespace std;
template <typename T>
inline void read(T& a) {
  a = 0;
  char c;
  bool _MINUS_ = false;
  while (!isdigit(c = getchar())) _MINUS_ |= c == '-';
  do a = a * 10 + (c - '0');
  while (isdigit(c = getchar()));
  if (_MINUS_) a *= -1;
}
string world[8] = {"U", "D", "R", "L", "UL", "UR", "DR", "DL"};
const int rx[8] = {-1, 1, 0, 0, -1, -1, 1, 1};
const int ry[8] = {0, 0, 1, -1, -1, 1, 1, -1};
const long long mod = 1000000007;
int main() {
  ios_base::sync_with_stdio(0);
  int n;
  cin >> n;
  if (n == 1) {
    cout << -1;
    return 0;
  }
  int x = n + 1;
  long long y = n * x / (x - n);
  cout << n << " " << y << " " << x << endl;
  return 0;
}

### Prompt

Please provide a Cpp coded solution to the problem described below:

Vladik and Chloe decided to determine who of them is better at math. Vladik claimed that for any positive integer n he can represent fraction <image> as a sum of three distinct positive fractions in form <image>.

Help Vladik with that, i.e for a given n find three distinct positive integers x, y and z such that <image>. Because Chloe can't check Vladik's answer if the numbers are large, he asks you to print numbers not exceeding 109.

If there is no such answer, print -1.

Input

The single line contains single integer n (1 ≤ n ≤ 104).

Output

If the answer exists, print 3 distinct numbers x, y and z (1 ≤ x, y, z ≤ 109, x ≠ y, x ≠ z, y ≠ z). Otherwise print -1.

If there are multiple answers, print any of them.

Examples

Input

3


Output

2 7 42


Input

7


Output

7 8 56

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
template <typename T>
inline void read(T& a) {
  a = 0;
  char c;
  bool _MINUS_ = false;
  while (!isdigit(c = getchar())) _MINUS_ |= c == '-';
  do a = a * 10 + (c - '0');
  while (isdigit(c = getchar()));
  if (_MINUS_) a *= -1;
}
string world[8] = {"U", "D", "R", "L", "UL", "UR", "DR", "DL"};
const int rx[8] = {-1, 1, 0, 0, -1, -1, 1, 1};
const int ry[8] = {0, 0, 1, -1, -1, 1, 1, -1};
const long long mod = 1000000007;
int main() {
  ios_base::sync_with_stdio(0);
  int n;
  cin >> n;
  if (n == 1) {
    cout << -1;
    return 0;
  }
  int x = n + 1;
  long long y = n * x / (x - n);
  cout << n << " " << y << " " << x << endl;
  return 0;
}

```