#include<bits/stdc++.h>
using namespace std;
typedef long long ll;


int main(){
    string s;   cin >> s;
    string ans="AC";
    int cnt=0;
    if(s[0]!='A') ans = "WA";

    for(int i=1; i<s.size(); i++){
        if(s[i]=='C' && 2<=i && i<=s.size()-2) cnt +=1;
        else if('A'<=s[i] && s[i]<='Z') ans = "WA";
    }
    if(cnt!=1) ans="WA";
    cout << ans << endl;
    
    
}
### Prompt

Please provide a Cpp coded solution to the problem described below:

You are given a string S. Each character of S is uppercase or lowercase English letter. Determine if S satisfies all of the following conditions:

* The initial character of S is an uppercase `A`.
* There is exactly one occurrence of `C` between the third character from the beginning and the second to last character (inclusive).
* All letters except the `A` and `C` mentioned above are lowercase.

Constraints

* 4 ≤ |S| ≤ 10 (|S| is the length of the string S.)
* Each character of S is uppercase or lowercase English letter.

Input

Input is given from Standard Input in the following format:


S


Output

If S satisfies all of the conditions in the problem statement, print `AC`; otherwise, print `WA`.

Examples

Input

AtCoder


Output

AC


Input

ACoder


Output

WA


Input

AcycliC


Output

WA


Input

AtCoCo


Output

WA


Input

Atcoder


Output

WA

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;


int main(){
    string s;   cin >> s;
    string ans="AC";
    int cnt=0;
    if(s[0]!='A') ans = "WA";

    for(int i=1; i<s.size(); i++){
        if(s[i]=='C' && 2<=i && i<=s.size()-2) cnt +=1;
        else if('A'<=s[i] && s[i]<='Z') ans = "WA";
    }
    if(cnt!=1) ans="WA";
    cout << ans << endl;
    
    
}
```