#include<cstdio>
#include<algorithm>
using namespace std;
int prime[1000005],cur;
bool isprime[1000005];
int main()
{
	isprime[1]=1;
	for(int i=2;i<1000000;i++)
		if(!isprime[i])
		{
			prime[cur++]=i;
			for(long long j=1LL*i*i;j<1000000LL;j+=1LL*i)
				isprime[j]=1;
		}
	int n;
	while(~scanf("%d",&n))
		printf("%d\n",lower_bound(prime,prime+cur,n)-prime+(!isprime[n]));
	return 0;
}
### Prompt

Your task is to create a CPP solution to the following problem:

Write a program which reads an integer n and prints the number of prime numbers which are less than or equal to n. A prime number is a natural number which has exactly two distinct natural number divisors: 1 and itself. For example, the first four prime numbers are: 2, 3, 5 and 7.



Input

Input consists of several datasets. Each dataset has an integer n (1 ≤ n ≤ 999,999) in a line.

The number of datasets is less than or equal to 30.

Output

For each dataset, prints the number of prime numbers.

Example

Input

10
3
11


Output

4
2
5

### Response

```cpp
#include<cstdio>
#include<algorithm>
using namespace std;
int prime[1000005],cur;
bool isprime[1000005];
int main()
{
	isprime[1]=1;
	for(int i=2;i<1000000;i++)
		if(!isprime[i])
		{
			prime[cur++]=i;
			for(long long j=1LL*i*i;j<1000000LL;j+=1LL*i)
				isprime[j]=1;
		}
	int n;
	while(~scanf("%d",&n))
		printf("%d\n",lower_bound(prime,prime+cur,n)-prime+(!isprime[n]));
	return 0;
}
```