#include <iostream>

using namespace std;

#define MAX 1000000

int main(){
  int n;
  bool p[MAX];
  p[0] = p[1] = false;
  for(int i=2;i<MAX;i++)p[i] = true;
  for(int i=2; i<MAX;i++){
	if(p[i]){
	  for(int j=i+i;j<MAX;j=j+i){
		p[j] = false;
	  }
	}
  }
  
  while(cin >> n){
	int cnt = 0;
	for(int i = 0;i<=n;i++){
	  if(p[i]) cnt++;
	}
	cout << cnt << endl;
  }
  
  return 0;
}
### Prompt

Generate a CPP solution to the following problem:

Write a program which reads an integer n and prints the number of prime numbers which are less than or equal to n. A prime number is a natural number which has exactly two distinct natural number divisors: 1 and itself. For example, the first four prime numbers are: 2, 3, 5 and 7.



Input

Input consists of several datasets. Each dataset has an integer n (1 ≤ n ≤ 999,999) in a line.

The number of datasets is less than or equal to 30.

Output

For each dataset, prints the number of prime numbers.

Example

Input

10
3
11


Output

4
2
5

### Response

```cpp
#include <iostream>

using namespace std;

#define MAX 1000000

int main(){
  int n;
  bool p[MAX];
  p[0] = p[1] = false;
  for(int i=2;i<MAX;i++)p[i] = true;
  for(int i=2; i<MAX;i++){
	if(p[i]){
	  for(int j=i+i;j<MAX;j=j+i){
		p[j] = false;
	  }
	}
  }
  
  while(cin >> n){
	int cnt = 0;
	for(int i = 0;i<=n;i++){
	  if(p[i]) cnt++;
	}
	cout << cnt << endl;
  }
  
  return 0;
}
```