//00
#include<iostream>
#include<algorithm>

using namespace std;

int calc(bool *f,bool *l,bool *m){
  int r=0;
  for(bool *n=m-1;n!=f&&*n;n--){
    r++;
  }
  for(m++;m!=l&&*m;m++){
    r++;
  }
  return r+1;
}

int main(){
  for(int n,k;cin>>n>>k,n|k;){
    bool c[100001]={};
    while(k--){
      int r;
      cin>>r;
      c[r]=true;
    }
    int ans=0;
    if(c[0]){
      for(int i=1;i<=n;i++){
	if(!c[i]){
	  ans=max(ans,calc(c,c+n+1,c+i));
	}
      }
    }else{
      int cc=0;
      for(int i=1;i<=n;i++){
	if(c[i]){
	  cc++;
	}else{
	  cc=0;
	}
	ans=max(ans,cc);
      }
    }
    cout<<ans<<endl;
  }
  return 0;
}
	
	
### Prompt

In Cpp, your task is to solve the following problem:

problem

There are n cards with one integer from 1 to n and one blank card. Of these n + 1 cards, k cards are given, but 1 ≤ k ≤ n. You can write one integer from 1 to n on a blank card. I want to make a continuous sequence of integers as long as possible with just a given card.

Write a program that outputs the maximum length of a contiguous sequence of integers that can be made from a given card when the given card is entered.



input

The input consists of multiple datasets. Each dataset is given in the following format. The input ends on a line containing two zeros.

On the first line, two integers n (1 ≤ n ≤ 100000) and k (1 ≤ k ≤ n) are written in this order, separated by one blank. The following k line contains one integer. Written one by one, representing the integers written on the given k cards. Blank cards are represented by 0.

Of the scoring data, 40% of the points are 1 ≤ n ≤ 1000, 1 ≤ k ≤ 500, 20% of the points are 1 ≤ n ≤ 60000, 1 ≤ k ≤ 50000. Satisfy 1 ≤ n ≤ 100000, 1 ≤ k ≤ 100000.

The number of datasets does not exceed 5.

output

Outputs an integer on one line for each dataset.

Examples

Input

7 5
6
2
4
7
1
7 5
6
2
0
4
7
0 0


Output

2
4


Input

None


Output

None

### Response

```cpp
//00
#include<iostream>
#include<algorithm>

using namespace std;

int calc(bool *f,bool *l,bool *m){
  int r=0;
  for(bool *n=m-1;n!=f&&*n;n--){
    r++;
  }
  for(m++;m!=l&&*m;m++){
    r++;
  }
  return r+1;
}

int main(){
  for(int n,k;cin>>n>>k,n|k;){
    bool c[100001]={};
    while(k--){
      int r;
      cin>>r;
      c[r]=true;
    }
    int ans=0;
    if(c[0]){
      for(int i=1;i<=n;i++){
	if(!c[i]){
	  ans=max(ans,calc(c,c+n+1,c+i));
	}
      }
    }else{
      int cc=0;
      for(int i=1;i<=n;i++){
	if(c[i]){
	  cc++;
	}else{
	  cc=0;
	}
	ans=max(ans,cc);
      }
    }
    cout<<ans<<endl;
  }
  return 0;
}
	
	
```