#include <cstdio>

int main(void) {
    int i, n;
    scanf("%d", &n);
    int fib[n+1];
    fib[0] = fib[1] = 1;
    for (i = 2; i <= n; i++) fib[i] = fib[i-2] + fib[i-1];
    printf("%d\n", fib[n]);

    return 0;
}
### Prompt

Please formulate a Cpp solution to the following problem:

Write a program which prints $n$-th fibonacci number for a given integer $n$. The $n$-th fibonacci number is defined by the following recursive formula:

\begin{equation*} fib(n)= \left \\{ \begin{array}{ll} 1 & (n = 0) \\\ 1 & (n = 1) \\\ fib(n - 1) + fib(n - 2) & \\\ \end{array} \right. \end{equation*}

Constraints

* $0 \leq n \leq 44$

Input

An integer $n$ is given.

Example

Input

3


Output

3

### Response

```cpp
#include <cstdio>

int main(void) {
    int i, n;
    scanf("%d", &n);
    int fib[n+1];
    fib[0] = fib[1] = 1;
    for (i = 2; i <= n; i++) fib[i] = fib[i-2] + fib[i-1];
    printf("%d\n", fib[n]);

    return 0;
}
```