#include <bits/stdc++.h>
using namespace std;
int test(int a) {
  int b = sqrt(a);
  b = b * b;
  if (b == a) {
    return 1;
  } else {
    return 0;
  }
}
int main() {
  int n;
  cin >> n;
  int arr[n];
  for (int i = 0; i <= n - 1; i++) {
    cin >> arr[i];
  }
  sort(arr, arr + n);
  int i = 0;
  while (i <= n - 1) {
    int alpha = test(arr[n - 1 - i]);
    if (alpha == 1) {
      i++;
    } else {
      cout << arr[n - i - 1] << endl;
      break;
    }
  }
  return 0;
}

### Prompt

In cpp, your task is to solve the following problem:

Given an array a1, a2, ..., an of n integers, find the largest number in the array that is not a perfect square.

A number x is said to be a perfect square if there exists an integer y such that x = y2.

Input

The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of elements in the array.

The second line contains n integers a1, a2, ..., an ( - 106 ≤ ai ≤ 106) — the elements of the array.

It is guaranteed that at least one element of the array is not a perfect square.

Output

Print the largest number in the array which is not a perfect square. It is guaranteed that an answer always exists.

Examples

Input

2
4 2


Output

2


Input

8
1 2 4 8 16 32 64 576


Output

32

Note

In the first sample case, 4 is a perfect square, so the largest number in the array that is not a perfect square is 2.

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int test(int a) {
  int b = sqrt(a);
  b = b * b;
  if (b == a) {
    return 1;
  } else {
    return 0;
  }
}
int main() {
  int n;
  cin >> n;
  int arr[n];
  for (int i = 0; i <= n - 1; i++) {
    cin >> arr[i];
  }
  sort(arr, arr + n);
  int i = 0;
  while (i <= n - 1) {
    int alpha = test(arr[n - 1 - i]);
    if (alpha == 1) {
      i++;
    } else {
      cout << arr[n - i - 1] << endl;
      break;
    }
  }
  return 0;
}

```