#include <iostream>
#include <algorithm>

using namespace std;

int cards[100001];
int dp[1000001];

int main(){
	while(true){
		int n, k;
		cin >> n >> k;
		if(n == 0 && k == 0){ break; }
		int hasWhite = 0;
		for(int i = 0; i < k; i++){
			int tmp;
			cin >> tmp;
			if(tmp == 0){
				hasWhite = 1;
			}else{
				cards[i - hasWhite] = tmp;
			}
		}
		if(hasWhite){ k--; }
		sort(cards, cards + k, less<int>());
		cards[k] = -1;
		int answer = 0, front = 0;
		dp[0] = 1;
		for(int i = 1; i <= k; i++){
			if(cards[i] == cards[i - 1] + 1){
				dp[i] = dp[i - 1] + 1;
			}else{
				if(hasWhite == 0 || front <= 0 || (cards[front - 1] + 2 != cards[front])){
					answer = max(answer, dp[i - 1]);
				}else{
					answer = max(answer, dp[i - 1] + dp[front - 1] + 1);
				}
				front = i;
				dp[i] = 1;
			}
		}
		printf("%d\n", answer);
	}
}
### Prompt

Please formulate a Cpp solution to the following problem:

problem

There are n cards with one integer from 1 to n and one blank card. Of these n + 1 cards, k cards are given, but 1 ≤ k ≤ n. You can write one integer from 1 to n on a blank card. I want to make a continuous sequence of integers as long as possible with just a given card.

Write a program that outputs the maximum length of a contiguous sequence of integers that can be made from a given card when the given card is entered.



input

The input consists of multiple datasets. Each dataset is given in the following format. The input ends on a line containing two zeros.

On the first line, two integers n (1 ≤ n ≤ 100000) and k (1 ≤ k ≤ n) are written in this order, separated by one blank. The following k line contains one integer. Written one by one, representing the integers written on the given k cards. Blank cards are represented by 0.

Of the scoring data, 40% of the points are 1 ≤ n ≤ 1000, 1 ≤ k ≤ 500, 20% of the points are 1 ≤ n ≤ 60000, 1 ≤ k ≤ 50000. Satisfy 1 ≤ n ≤ 100000, 1 ≤ k ≤ 100000.

The number of datasets does not exceed 5.

output

Outputs an integer on one line for each dataset.

Examples

Input

7 5
6
2
4
7
1
7 5
6
2
0
4
7
0 0


Output

2
4


Input

None


Output

None

### Response

```cpp
#include <iostream>
#include <algorithm>

using namespace std;

int cards[100001];
int dp[1000001];

int main(){
	while(true){
		int n, k;
		cin >> n >> k;
		if(n == 0 && k == 0){ break; }
		int hasWhite = 0;
		for(int i = 0; i < k; i++){
			int tmp;
			cin >> tmp;
			if(tmp == 0){
				hasWhite = 1;
			}else{
				cards[i - hasWhite] = tmp;
			}
		}
		if(hasWhite){ k--; }
		sort(cards, cards + k, less<int>());
		cards[k] = -1;
		int answer = 0, front = 0;
		dp[0] = 1;
		for(int i = 1; i <= k; i++){
			if(cards[i] == cards[i - 1] + 1){
				dp[i] = dp[i - 1] + 1;
			}else{
				if(hasWhite == 0 || front <= 0 || (cards[front - 1] + 2 != cards[front])){
					answer = max(answer, dp[i - 1]);
				}else{
					answer = max(answer, dp[i - 1] + dp[front - 1] + 1);
				}
				front = i;
				dp[i] = 1;
			}
		}
		printf("%d\n", answer);
	}
}
```