#include <stdio.h>
int main(void){
	int k,j,a;
	char flag[1000000]={1,1};//0,1は除外する
	for(k=2;k<1000;k++){
		if(flag[k]==0){
			for(j=k*k;j<1000000;j+=k)
				flag[j]=1;
		}
	}
	while(~scanf("%d",&a)){
		k=0;
		for(j=2;j<=a;j++) if(flag[j]==0) k++;
		printf("%d\n",k);
	}
}
### Prompt

Generate a CPP solution to the following problem:

Write a program which reads an integer n and prints the number of prime numbers which are less than or equal to n. A prime number is a natural number which has exactly two distinct natural number divisors: 1 and itself. For example, the first four prime numbers are: 2, 3, 5 and 7.



Input

Input consists of several datasets. Each dataset has an integer n (1 ≤ n ≤ 999,999) in a line.

The number of datasets is less than or equal to 30.

Output

For each dataset, prints the number of prime numbers.

Example

Input

10
3
11


Output

4
2
5

### Response

```cpp
#include <stdio.h>
int main(void){
	int k,j,a;
	char flag[1000000]={1,1};//0,1は除外する
	for(k=2;k<1000;k++){
		if(flag[k]==0){
			for(j=k*k;j<1000000;j+=k)
				flag[j]=1;
		}
	}
	while(~scanf("%d",&a)){
		k=0;
		for(j=2;j<=a;j++) if(flag[j]==0) k++;
		printf("%d\n",k);
	}
}
```