#include<iostream>
#include<math.h>
using namespace std;
bool n[1000000]={0};
bool prime(int n){
	for(int i=2;i<=sqrt ((double)n);i++){
		if(n%i==0)return false;
	}
	return true;
}
int main(){
	for(int k=2;k<=999999;k++){
		if(prime(k))n[k]=true;
	}


	int a,sum=0;
	while(cin>>a){
	for(int j=2;j<=a;j++){
		if(n[j])sum++;
	}
	cout<<sum<<endl;
	sum=0;
	}
}
### Prompt

Create a solution in cpp for the following problem:

Write a program which reads an integer n and prints the number of prime numbers which are less than or equal to n. A prime number is a natural number which has exactly two distinct natural number divisors: 1 and itself. For example, the first four prime numbers are: 2, 3, 5 and 7.



Input

Input consists of several datasets. Each dataset has an integer n (1 ≤ n ≤ 999,999) in a line.

The number of datasets is less than or equal to 30.

Output

For each dataset, prints the number of prime numbers.

Example

Input

10
3
11


Output

4
2
5

### Response

```cpp
#include<iostream>
#include<math.h>
using namespace std;
bool n[1000000]={0};
bool prime(int n){
	for(int i=2;i<=sqrt ((double)n);i++){
		if(n%i==0)return false;
	}
	return true;
}
int main(){
	for(int k=2;k<=999999;k++){
		if(prime(k))n[k]=true;
	}


	int a,sum=0;
	while(cin>>a){
	for(int j=2;j<=a;j++){
		if(n[j])sum++;
	}
	cout<<sum<<endl;
	sum=0;
	}
}
```