#include<bits/stdc++.h>
using namespace std;

int main() {
  int n; cin >> n;
  int f[45]; f[0] = 1; f[1] = 1;
  for (int i =2; i<=n; i++) {
    f[i] = f[i-1] + f[i-2];
  }
  cout << f[n] << endl; 
}


### Prompt

Please create a solution in Cpp to the following problem:

Write a program which prints $n$-th fibonacci number for a given integer $n$. The $n$-th fibonacci number is defined by the following recursive formula:

\begin{equation*} fib(n)= \left \\{ \begin{array}{ll} 1 & (n = 0) \\\ 1 & (n = 1) \\\ fib(n - 1) + fib(n - 2) & \\\ \end{array} \right. \end{equation*}

Constraints

* $0 \leq n \leq 44$

Input

An integer $n$ is given.

Example

Input

3


Output

3

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;

int main() {
  int n; cin >> n;
  int f[45]; f[0] = 1; f[1] = 1;
  for (int i =2; i<=n; i++) {
    f[i] = f[i-1] + f[i-2];
  }
  cout << f[n] << endl; 
}


```