#include <bits/stdc++.h>
using namespace std;

const int N = 3005;
const int MOD = 1e9 + 7;
int dp[N][N], cnt[2];
char s[N], t[N];

int main() {
    ios::sync_with_stdio(0);
    cin.tie(nullptr);
    int n, m; cin >> n >> m >> (s + 1);
    strcpy(t + 1, s + 1); dp[0][0] = 1;
    for (int i = 1; i <= m; i++) {
        int l, r; cin >> l >> r;
        sort(s + l, s + r + 1);
        sort(t + l, t + r + 1, greater <char> ());
    }
    for (int i = 1; i <= n; i++) {
        cnt[0] += s[i] == '0';
        cnt[1] += t[i] == '0';
        for (int j = cnt[1]; j <= cnt[0]; j++) {
            dp[i][j] = dp[i - 1][j];
            if (j) dp[i][j] += dp[i - 1][j - 1];
            if (dp[i][j] >= MOD) dp[i][j] -= MOD;
        }
    }
    int res = 0;
    for (int j = cnt[1]; j <= cnt[0]; j++) {
        res += dp[n][j];
        if (res >= MOD) res -= MOD;
    }
    cout << res << '\n';
}
### Prompt

Create a solution in CPP for the following problem:

There is a string S of length N consisting of characters `0` and `1`. You will perform the following operation for each i = 1, 2, ..., m:

* Arbitrarily permute the characters within the substring of S starting at the l_i-th character from the left and extending through the r_i-th character.



Here, the sequence l_i is non-decreasing.

How many values are possible for S after the M operations, modulo 1000000007(= 10^9+7)?

Constraints

* 2≦N≦3000
* 1≦M≦3000
* S consists of characters `0` and `1`.
* The length of S equals N.
* 1≦l_i < r_i≦N
* l_i ≦ l_{i+1}

Input

The input is given from Standard Input in the following format:


N M
S
l_1 r_1
:
l_M r_M


Output

Print the number of the possible values for S after the M operations, modulo 1000000007.

Examples

Input

5 2
01001
2 4
3 5


Output

6


Input

9 3
110111110
1 4
4 6
6 9


Output

26


Input

11 6
00101000110
2 4
2 3
4 7
5 6
6 10
10 11


Output

143

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;

const int N = 3005;
const int MOD = 1e9 + 7;
int dp[N][N], cnt[2];
char s[N], t[N];

int main() {
    ios::sync_with_stdio(0);
    cin.tie(nullptr);
    int n, m; cin >> n >> m >> (s + 1);
    strcpy(t + 1, s + 1); dp[0][0] = 1;
    for (int i = 1; i <= m; i++) {
        int l, r; cin >> l >> r;
        sort(s + l, s + r + 1);
        sort(t + l, t + r + 1, greater <char> ());
    }
    for (int i = 1; i <= n; i++) {
        cnt[0] += s[i] == '0';
        cnt[1] += t[i] == '0';
        for (int j = cnt[1]; j <= cnt[0]; j++) {
            dp[i][j] = dp[i - 1][j];
            if (j) dp[i][j] += dp[i - 1][j - 1];
            if (dp[i][j] >= MOD) dp[i][j] -= MOD;
        }
    }
    int res = 0;
    for (int j = cnt[1]; j <= cnt[0]; j++) {
        res += dp[n][j];
        if (res >= MOD) res -= MOD;
    }
    cout << res << '\n';
}
```