//Problem B
#include<bits/stdc++.h>
using namespace std;

char str[22];
int c,n;
#define oops {printf("WA");return 0;}
int main(){
    scanf("%s",str),n=strlen(str);
    if(str[0]!='A')oops
    int f=1;
    for(int i=2;i<n-1;i++)if(str[i]=='C')f=0;
    if(f)oops
    for(int i=0;i<n;i++)if('a'<=str[i]&&str[i]<='z')++c;
    if(c+2!=n)oops
    printf("AC");
    return 0;
}
### Prompt

Construct a Cpp code solution to the problem outlined:

You are given a string S. Each character of S is uppercase or lowercase English letter. Determine if S satisfies all of the following conditions:

* The initial character of S is an uppercase `A`.
* There is exactly one occurrence of `C` between the third character from the beginning and the second to last character (inclusive).
* All letters except the `A` and `C` mentioned above are lowercase.

Constraints

* 4 ≤ |S| ≤ 10 (|S| is the length of the string S.)
* Each character of S is uppercase or lowercase English letter.

Input

Input is given from Standard Input in the following format:


S


Output

If S satisfies all of the conditions in the problem statement, print `AC`; otherwise, print `WA`.

Examples

Input

AtCoder


Output

AC


Input

ACoder


Output

WA


Input

AcycliC


Output

WA


Input

AtCoCo


Output

WA


Input

Atcoder


Output

WA

### Response

```cpp
//Problem B
#include<bits/stdc++.h>
using namespace std;

char str[22];
int c,n;
#define oops {printf("WA");return 0;}
int main(){
    scanf("%s",str),n=strlen(str);
    if(str[0]!='A')oops
    int f=1;
    for(int i=2;i<n-1;i++)if(str[i]=='C')f=0;
    if(f)oops
    for(int i=0;i<n;i++)if('a'<=str[i]&&str[i]<='z')++c;
    if(c+2!=n)oops
    printf("AC");
    return 0;
}
```