#include <stdio.h>
#include <string.h>

int dots[][5] = {
	{ 1, 0, 0, 1, 0 }, { 1, 1, 0, 2, 0 }, { 2, 0, 0, 1, 1 }, { 2, 1, 0, 1, 2 },
	{ 1, 1, 0, 1, 1 }, { 2, 1, 0, 2, 1 }, { 2, 2, 0, 2, 2 }, { 1, 2, 0, 2, 1 },
	{ 1, 1, 0, 1, 1 }, { 1, 2, 0, 1, 2 }, { 1, 0, 1, 2, 0 }, { 1, 1, 1, 3, 0 },
	{ 2, 0, 1, 2, 1 }, { 2, 1, 1, 2, 2 }, { 1, 1, 1, 2, 1 }, { 2, 1, 1, 3, 1 },
	{ 2, 2, 1, 3, 2 }, { 1, 2, 1, 3, 1 }, { 1, 1, 1, 2, 1 }, { 1, 2, 1, 2, 2 },
	{ 1, 0, 2, 2, 1 }, { 1, 1, 2, 3, 1 }, { 1, 2, 1, 1, 3 }, { 2, 0, 2, 2, 2 },
	{ 2, 1, 2, 2, 3 }, { 1, 1, 2, 2, 2 }
};

int main() {
	int n;

	scanf("%d", &n);
	while (n--) {
		static int aa[5];
		int i, a;

		for (i = 0; i < 5; i++)
			scanf("%d", &aa[i]);
		for (a = 0; a < 26; a++)
			if (memcmp(dots[a], aa, 5 * sizeof *aa) == 0) {
				printf("%c", a + 'a');
				break;
			}
	}
	printf("\n");
	return 0;
}

### Prompt

In CPP, your task is to solve the following problem:



Input

The first line of the input contains a single integer N (1 ≤ N ≤ 24). The next N lines contain 5 space-separated integers each. The first three integers will be between 0 and 2, inclusive. The last two integers will be between 0 and 3, inclusive. The sum of the first three integers will be equal to the sum of the last two integers.

Output

Output the result – a string of lowercase English letters.

Examples

Input


1
1 0 0 1 0


Output


a


Input


10
2 0 0 1 1
1 1 1 2 1
2 1 0 1 2
1 1 0 1 1
2 1 0 2 1
1 1 1 2 1
1 2 1 3 1
2 0 0 1 1
1 1 0 1 1
1 1 2 2 2


Output


codeforcez

### Response

```cpp
#include <stdio.h>
#include <string.h>

int dots[][5] = {
	{ 1, 0, 0, 1, 0 }, { 1, 1, 0, 2, 0 }, { 2, 0, 0, 1, 1 }, { 2, 1, 0, 1, 2 },
	{ 1, 1, 0, 1, 1 }, { 2, 1, 0, 2, 1 }, { 2, 2, 0, 2, 2 }, { 1, 2, 0, 2, 1 },
	{ 1, 1, 0, 1, 1 }, { 1, 2, 0, 1, 2 }, { 1, 0, 1, 2, 0 }, { 1, 1, 1, 3, 0 },
	{ 2, 0, 1, 2, 1 }, { 2, 1, 1, 2, 2 }, { 1, 1, 1, 2, 1 }, { 2, 1, 1, 3, 1 },
	{ 2, 2, 1, 3, 2 }, { 1, 2, 1, 3, 1 }, { 1, 1, 1, 2, 1 }, { 1, 2, 1, 2, 2 },
	{ 1, 0, 2, 2, 1 }, { 1, 1, 2, 3, 1 }, { 1, 2, 1, 1, 3 }, { 2, 0, 2, 2, 2 },
	{ 2, 1, 2, 2, 3 }, { 1, 1, 2, 2, 2 }
};

int main() {
	int n;

	scanf("%d", &n);
	while (n--) {
		static int aa[5];
		int i, a;

		for (i = 0; i < 5; i++)
			scanf("%d", &aa[i]);
		for (a = 0; a < 26; a++)
			if (memcmp(dots[a], aa, 5 * sizeof *aa) == 0) {
				printf("%c", a + 'a');
				break;
			}
	}
	printf("\n");
	return 0;
}

```