#include<bits/stdc++.h>
using namespace std;

map<int, char> mp;

int main() {
	mp.clear();
	mp[10010] = 'a';
	mp[11020] = 'b';
	mp[20011] = 'c';
	mp[21012] = 'd';
	mp[11011] = 'e';
	mp[21021] = 'f';
	mp[22022] = 'g';
	mp[12021] = 'h';
	// mp[11011] = 'i';
	mp[12012] = 'j';
	mp[10120] = 'k';
	mp[11130] = 'l';
	mp[20121] = 'm';
	mp[21122] = 'n';
	mp[11121] = 'o';
	mp[21131] = 'p';
	mp[22132] = 'q';
	mp[12131] = 'r';
	// mp[11121] = 's';
	mp[12122] = 't';
	mp[10221] = 'u';
	mp[11231] = 'v';
	mp[12113] = 'w';
	mp[20222] = 'x';
	mp[21223] = 'y';
	mp[11222] = 'z';
	
	int n;
	scanf("%d", &n);
	for(int i=0;i<n;i++) {
		int s = 0, x;
		for(int j=0;j<5;j++) {
			scanf("%d", &x);
			s = s*10+x;
		}
		putchar(mp[s]);
	}
	puts("");
	
	return 0;
}
### Prompt

Develop a solution in Cpp to the problem described below:



Input

The first line of the input contains a single integer N (1 ≤ N ≤ 24). The next N lines contain 5 space-separated integers each. The first three integers will be between 0 and 2, inclusive. The last two integers will be between 0 and 3, inclusive. The sum of the first three integers will be equal to the sum of the last two integers.

Output

Output the result – a string of lowercase English letters.

Examples

Input


1
1 0 0 1 0


Output


a


Input


10
2 0 0 1 1
1 1 1 2 1
2 1 0 1 2
1 1 0 1 1
2 1 0 2 1
1 1 1 2 1
1 2 1 3 1
2 0 0 1 1
1 1 0 1 1
1 1 2 2 2


Output


codeforcez

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;

map<int, char> mp;

int main() {
	mp.clear();
	mp[10010] = 'a';
	mp[11020] = 'b';
	mp[20011] = 'c';
	mp[21012] = 'd';
	mp[11011] = 'e';
	mp[21021] = 'f';
	mp[22022] = 'g';
	mp[12021] = 'h';
	// mp[11011] = 'i';
	mp[12012] = 'j';
	mp[10120] = 'k';
	mp[11130] = 'l';
	mp[20121] = 'm';
	mp[21122] = 'n';
	mp[11121] = 'o';
	mp[21131] = 'p';
	mp[22132] = 'q';
	mp[12131] = 'r';
	// mp[11121] = 's';
	mp[12122] = 't';
	mp[10221] = 'u';
	mp[11231] = 'v';
	mp[12113] = 'w';
	mp[20222] = 'x';
	mp[21223] = 'y';
	mp[11222] = 'z';
	
	int n;
	scanf("%d", &n);
	for(int i=0;i<n;i++) {
		int s = 0, x;
		for(int j=0;j<5;j++) {
			scanf("%d", &x);
			s = s*10+x;
		}
		putchar(mp[s]);
	}
	puts("");
	
	return 0;
}
```