#include <iostream>
#include <algorithm>
#define REP(i, a, n) for(int i = a; i < n; i++)
using namespace std;


int n, k;
int a[100000];
int w;

int main(void) {
  while(cin >> n >> k, !(n == 0 && k == 0)) {
    w = 0;
    REP(i, 0, k) {
      cin >> a[i];
      if(a[i] == 0) {
        w = 1;
        i--;
        k--;
      }
    }

    sort(a, a + k);

    int i = 0;
    int m = 0;
    while(i < k) {
      int j = i;
      while(j < k && a[j + 1] - a[j] == 1) j++;
      if(w == 1 && a[j + 1] - a[j] == 2) {
        int l = j + 1;
        while(l < k && a[l + 1] - a[l] == 1) l++;
        m = max(m, l - i + 2);
      } else {
        m = max(m, j - i + 1);
      }
      i = j + 1;
    }

    cout << m << endl;
  }

  return 0;
}
### Prompt

Please create a solution in Cpp to the following problem:

problem

There are n cards with one integer from 1 to n and one blank card. Of these n + 1 cards, k cards are given, but 1 ≤ k ≤ n. You can write one integer from 1 to n on a blank card. I want to make a continuous sequence of integers as long as possible with just a given card.

Write a program that outputs the maximum length of a contiguous sequence of integers that can be made from a given card when the given card is entered.



input

The input consists of multiple datasets. Each dataset is given in the following format. The input ends on a line containing two zeros.

On the first line, two integers n (1 ≤ n ≤ 100000) and k (1 ≤ k ≤ n) are written in this order, separated by one blank. The following k line contains one integer. Written one by one, representing the integers written on the given k cards. Blank cards are represented by 0.

Of the scoring data, 40% of the points are 1 ≤ n ≤ 1000, 1 ≤ k ≤ 500, 20% of the points are 1 ≤ n ≤ 60000, 1 ≤ k ≤ 50000. Satisfy 1 ≤ n ≤ 100000, 1 ≤ k ≤ 100000.

The number of datasets does not exceed 5.

output

Outputs an integer on one line for each dataset.

Examples

Input

7 5
6
2
4
7
1
7 5
6
2
0
4
7
0 0


Output

2
4


Input

None


Output

None

### Response

```cpp
#include <iostream>
#include <algorithm>
#define REP(i, a, n) for(int i = a; i < n; i++)
using namespace std;


int n, k;
int a[100000];
int w;

int main(void) {
  while(cin >> n >> k, !(n == 0 && k == 0)) {
    w = 0;
    REP(i, 0, k) {
      cin >> a[i];
      if(a[i] == 0) {
        w = 1;
        i--;
        k--;
      }
    }

    sort(a, a + k);

    int i = 0;
    int m = 0;
    while(i < k) {
      int j = i;
      while(j < k && a[j + 1] - a[j] == 1) j++;
      if(w == 1 && a[j + 1] - a[j] == 2) {
        int l = j + 1;
        while(l < k && a[l + 1] - a[l] == 1) l++;
        m = max(m, l - i + 2);
      } else {
        m = max(m, j - i + 1);
      }
      i = j + 1;
    }

    cout << m << endl;
  }

  return 0;
}
```