#include <stdio.h>
#include <iostream>
#include <vector>
#define LIMIT 1000000

int main(){
	int num;
	while( scanf("%d",&num)!=EOF ){
		bool sosu[LIMIT]={0};
		int now=2,count=0;
		while(now<=num){
			if(!sosu[now]){
				count++;
				for(int i=now;i<LIMIT;i+=now){
					sosu[i] = true;
				}
			}
			now++;
		}
		std::cout << count << std::endl;
	}
	return 0;
}
### Prompt

Please formulate a CPP solution to the following problem:

Write a program which reads an integer n and prints the number of prime numbers which are less than or equal to n. A prime number is a natural number which has exactly two distinct natural number divisors: 1 and itself. For example, the first four prime numbers are: 2, 3, 5 and 7.



Input

Input consists of several datasets. Each dataset has an integer n (1 ≤ n ≤ 999,999) in a line.

The number of datasets is less than or equal to 30.

Output

For each dataset, prints the number of prime numbers.

Example

Input

10
3
11


Output

4
2
5

### Response

```cpp
#include <stdio.h>
#include <iostream>
#include <vector>
#define LIMIT 1000000

int main(){
	int num;
	while( scanf("%d",&num)!=EOF ){
		bool sosu[LIMIT]={0};
		int now=2,count=0;
		while(now<=num){
			if(!sosu[now]){
				count++;
				for(int i=now;i<LIMIT;i+=now){
					sosu[i] = true;
				}
			}
			now++;
		}
		std::cout << count << std::endl;
	}
	return 0;
}
```