#include <bits/stdc++.h>
using namespace std;
  
int main() {
  string s;
  cin>>s;
  while(s.size()>3) {
    int c[3]={},j;
    for(int i=0;i<s.size();i++)c[s[i]-'A']++;
    vector<int>v;
    for(int i=0;i<s.size()-2;i++)if(s.substr(i,3)=="ABC")v.push_back(i);
    if(!v.size())break;
    for(j=0;j<3;j++)if(c[j]==v.size())break;
    if(j>=3) break;
    string t=s.substr(0,v[0]);
    for(int i=0;i<v.size()-1;i++)t+=(char)('A'+j),t+=s.substr(v[i]+3,v[i+1]-(v[i]+3));
    t+=(char)('A'+j),t+=s.substr(v[v.size()-1]+3);
    s=t;
  }
  cout<<(s=="ABC"?"Yes":"No")<<endl;
  return 0;
}

### Prompt

Your challenge is to write a cpp solution to the following problem:

ABC Gene

There is a gene sequence represented by the string `ABC`. You can rewrite this gene sequence by performing the following operations several times.

* Choose one of the letters `A`,` B`, `C`. Let this be x. Replace all x in the gene sequence with `ABC` at the same time.



Given a string S consisting only of `A`,` B`, and `C`. Determine if the gene sequence can be matched to S.

Constraints

* 1 ≤ | S | ≤ 5,000
* S consists only of `A`,` B`, and `C`.



Input Format

Input is given from standard input in the following format.


S


Output Format

Output `Yes` if the gene sequence can be matched to S, and` No` if it cannot be matched.

Sample Input 1


ABC


Sample Output 1


Yes


The gene sequence is `ABC` from the beginning.

Sample Input 2


AABCC


Sample Output 2


Yes


If you select `B` and perform the operation, it becomes` ABC` → `AABCC`.

Sample Input 3


AABCABC


Sample Output 3


No


For example, even if you select `C` and perform an operation, it does not change from` AABCC` to `AABCABC`. Since all `C`s are replaced with` ABC` at the same time, the actual result is `AABCC` →` AABABCABC`.





Example

Input

ABC


Output

Yes

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
  
int main() {
  string s;
  cin>>s;
  while(s.size()>3) {
    int c[3]={},j;
    for(int i=0;i<s.size();i++)c[s[i]-'A']++;
    vector<int>v;
    for(int i=0;i<s.size()-2;i++)if(s.substr(i,3)=="ABC")v.push_back(i);
    if(!v.size())break;
    for(j=0;j<3;j++)if(c[j]==v.size())break;
    if(j>=3) break;
    string t=s.substr(0,v[0]);
    for(int i=0;i<v.size()-1;i++)t+=(char)('A'+j),t+=s.substr(v[i]+3,v[i+1]-(v[i]+3));
    t+=(char)('A'+j),t+=s.substr(v[v.size()-1]+3);
    s=t;
  }
  cout<<(s=="ABC"?"Yes":"No")<<endl;
  return 0;
}

```