#include<stdio.h>
int flg[1000000];
int main(void)
{
	int n,i,j,c;
	while(scanf("%d",&n)!=EOF){
	c=0;
		for(i=2;i<n;i++){
			flg[i]=0;
		}	
			for(i=2;i*i<=n;i++){
				for(j=2;i*j<=n;j++){
						flg[i*j]=1;	
				}
			}
		for(i=2;i<=n;i++){
			if(flg[i]==0){
					c++;
			}		
		}
	printf("%d\n",c);
	}
	return 0;
}	
### Prompt

In cpp, your task is to solve the following problem:

Write a program which reads an integer n and prints the number of prime numbers which are less than or equal to n. A prime number is a natural number which has exactly two distinct natural number divisors: 1 and itself. For example, the first four prime numbers are: 2, 3, 5 and 7.



Input

Input consists of several datasets. Each dataset has an integer n (1 ≤ n ≤ 999,999) in a line.

The number of datasets is less than or equal to 30.

Output

For each dataset, prints the number of prime numbers.

Example

Input

10
3
11


Output

4
2
5

### Response

```cpp
#include<stdio.h>
int flg[1000000];
int main(void)
{
	int n,i,j,c;
	while(scanf("%d",&n)!=EOF){
	c=0;
		for(i=2;i<n;i++){
			flg[i]=0;
		}	
			for(i=2;i*i<=n;i++){
				for(j=2;i*j<=n;j++){
						flg[i*j]=1;	
				}
			}
		for(i=2;i<=n;i++){
			if(flg[i]==0){
					c++;
			}		
		}
	printf("%d\n",c);
	}
	return 0;
}	
```