#include<bits/stdc++.h>
using namespace std;

int isPrime(int n){
	for(int i=2; i*i<=n; ++i){
		if(n % i == 0){
			return 0;
		}
	}
	return 1;
}

#define MAX_N 1000000

int ans[MAX_N];

int main(){
	ans[0] = 0;
	ans[1] = 0;
	for(int i=2; i<MAX_N; i++){
		ans[i] = ans[i-1] + isPrime(i);
	}
	
	int n;
	while(cin>>n){
		cout << ans[n] << endl;
	}
}


### Prompt

Please create a solution in cpp to the following problem:

Write a program which reads an integer n and prints the number of prime numbers which are less than or equal to n. A prime number is a natural number which has exactly two distinct natural number divisors: 1 and itself. For example, the first four prime numbers are: 2, 3, 5 and 7.



Input

Input consists of several datasets. Each dataset has an integer n (1 ≤ n ≤ 999,999) in a line.

The number of datasets is less than or equal to 30.

Output

For each dataset, prints the number of prime numbers.

Example

Input

10
3
11


Output

4
2
5

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;

int isPrime(int n){
	for(int i=2; i*i<=n; ++i){
		if(n % i == 0){
			return 0;
		}
	}
	return 1;
}

#define MAX_N 1000000

int ans[MAX_N];

int main(){
	ans[0] = 0;
	ans[1] = 0;
	for(int i=2; i<MAX_N; i++){
		ans[i] = ans[i-1] + isPrime(i);
	}
	
	int n;
	while(cin>>n){
		cout << ans[n] << endl;
	}
}


```