#include<bits/stdc++.h>
#include<vector>
#define LL long long
using namespace std;
LL n; int m; vector<int> A;
void solve(LL n)
{
	int p=++m; if(n==1) return ;
	if(n&1) A.push_back(p),solve(n-1);
	else solve(n/2),A.push_back(p);
}
int main()
{
	int i;
	cin>>n; n++,solve(n);
	printf("%d\n",2*A.size());
	for(i=0;i<A.size();i++)
		printf("%d ",A.size()-A[i]+1);
	for(i=0;i<A.size();i++)
		printf("%d ",i+1);
	return 0;
}

### Prompt

Please create a solution in Cpp to the following problem:

We will call a string x good if it satisfies the following condition:

* Condition: x can be represented as a concatenation of two copies of another string y of length at least 1.



For example, `aa` and `bubobubo` are good; an empty string, `a`, `abcabcabc` and `abba` are not good.

Eagle and Owl created a puzzle on good strings. Find one string s that satisfies the following conditions. It can be proved that such a string always exists under the constraints in this problem.

* 1 ≤ |s| ≤ 200
* Each character of s is one of the 100 characters represented by the integers 1 through 100.
* Among the 2^{|s|} subsequences of s, exactly N are good strings.

Constraints

* 1 ≤ N ≤ 10^{12}

Input

Input is given from Standard Input in the following format:


N


Output

In the first line, print |s|, the length of s. In the second line, print the elements in s in order, with spaces in between. Any string that satisfies the above conditions will be accepted.

Examples

Input

7


Output

4
1 1 1 1


Input

299


Output

23
32 11 11 73 45 8 11 83 83 8 45 32 32 10 100 73 32 83 45 73 32 11 10

### Response

```cpp
#include<bits/stdc++.h>
#include<vector>
#define LL long long
using namespace std;
LL n; int m; vector<int> A;
void solve(LL n)
{
	int p=++m; if(n==1) return ;
	if(n&1) A.push_back(p),solve(n-1);
	else solve(n/2),A.push_back(p);
}
int main()
{
	int i;
	cin>>n; n++,solve(n);
	printf("%d\n",2*A.size());
	for(i=0;i<A.size();i++)
		printf("%d ",A.size()-A[i]+1);
	for(i=0;i<A.size();i++)
		printf("%d ",i+1);
	return 0;
}

```