#include <bits/stdc++.h>
using namespace std;
int main() {
  int n, m;
  cin >> n;
  m = n;
  int a = 1;
  string x[n][m];
  string p = "C";
  string e = ".";
  for (int i = n - 1; i >= 0; i--) {
    for (int j = m - 1; j >= 0; j--) {
      if (a % 2 != 0) {
        x[i][j] = p;
      } else {
        x[i][j] = e;
      }
      a++;
    }
    a = 1;
    string aux = p;
    p = e;
    e = aux;
  }
  int c = 0;
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < m; j++) {
      if (x[i][j] == "C") {
        c++;
      }
    }
  }
  cout << c << endl;
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < m; j++) {
      cout << x[i][j];
    }
    cout << "\n";
  }
  return 0;
}

### Prompt

In cpp, your task is to solve the following problem:

Iahub likes chess very much. He even invented a new chess piece named Coder. A Coder can move (and attack) one square horizontally or vertically. More precisely, if the Coder is located at position (x, y), he can move to (or attack) positions (x + 1, y), (x–1, y), (x, y + 1) and (x, y–1).

Iahub wants to know how many Coders can be placed on an n × n chessboard, so that no Coder attacks any other Coder.

Input

The first line contains an integer n (1 ≤ n ≤ 1000).

Output

On the first line print an integer, the maximum number of Coders that can be placed on the chessboard.

On each of the next n lines print n characters, describing the configuration of the Coders. For an empty cell print an '.', and for a Coder print a 'C'.

If there are multiple correct answers, you can print any.

Examples

Input

2


Output

2
C.
.C

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  int n, m;
  cin >> n;
  m = n;
  int a = 1;
  string x[n][m];
  string p = "C";
  string e = ".";
  for (int i = n - 1; i >= 0; i--) {
    for (int j = m - 1; j >= 0; j--) {
      if (a % 2 != 0) {
        x[i][j] = p;
      } else {
        x[i][j] = e;
      }
      a++;
    }
    a = 1;
    string aux = p;
    p = e;
    e = aux;
  }
  int c = 0;
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < m; j++) {
      if (x[i][j] == "C") {
        c++;
      }
    }
  }
  cout << c << endl;
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < m; j++) {
      cout << x[i][j];
    }
    cout << "\n";
  }
  return 0;
}

```