#include<bits/stdc++.h>
#define N 100005
using namespace std;

int n,A[N];

int main(){
  
  cin>>n;
  for(int i=0;i<n;i++) cin>>A[i];
  
    
  int ans=1,f=0;
    
  for(int i=0;i<n-1;i++){
    
    if(!f){
      if(A[i]<A[i+1])f=1;
      if(A[i]>A[i+1])f=2;
    }
    else if(f==1){
      if(A[i]>A[i+1])ans++,f=0;
    }
    else if(f==2){
      if(A[i]<A[i+1])ans++,f=0;
    }
    
  }
    
  cout<<ans<<endl;
  return 0;
}

### Prompt

Create a solution in CPP for the following problem:

You are given an array A of length N. Your task is to divide it into several contiguous subarrays. Here, all subarrays obtained must be sorted in either non-decreasing or non-increasing order. At least how many subarrays do you need to divide A into?

Constraints

* 1 \leq N \leq 10^5
* 1 \leq A_i \leq 10^9
* Each A_i is an integer.

Input

Input is given from Standard Input in the following format:


N
A_1 A_2 ... A_N


Output

Print the minimum possible number of subarrays after division of A.

Examples

Input

6
1 2 3 2 2 1


Output

2


Input

9
1 2 1 2 1 2 1 2 1


Output

5


Input

7
1 2 3 2 1 999999999 1000000000


Output

3

### Response

```cpp
#include<bits/stdc++.h>
#define N 100005
using namespace std;

int n,A[N];

int main(){
  
  cin>>n;
  for(int i=0;i<n;i++) cin>>A[i];
  
    
  int ans=1,f=0;
    
  for(int i=0;i<n-1;i++){
    
    if(!f){
      if(A[i]<A[i+1])f=1;
      if(A[i]>A[i+1])f=2;
    }
    else if(f==1){
      if(A[i]>A[i+1])ans++,f=0;
    }
    else if(f==2){
      if(A[i]<A[i+1])ans++,f=0;
    }
    
  }
    
  cout<<ans<<endl;
  return 0;
}

```