#include <bits/stdc++.h>
using namespace std;
int main() {
  int num;
  cin >> num;
  int ans = (num * num) / 2;
  if (num % 2 != 0) ans += 1;
  if (num % 2 == 0) {
    cout << ans << endl;
    for (int i = 1; i <= num; i++) {
      for (int j = 1; j <= num; j += 2) {
        if (i % 2 != 0)
          printf("C.");
        else
          printf(".C");
      }
      printf("\n");
    }
  } else if (num % 2 != 0) {
    cout << ans << endl;
    for (int i = 1; i <= num; i++) {
      for (int j = 1; j <= num / 2; j++) {
        if (i % 2 != 0)
          printf("C.");
        else
          printf(".C");
      }
      if (i % 2 != 0)
        printf("C");
      else
        printf(".");
      printf("\n");
    }
  }
  return 0;
}

### Prompt

Develop a solution in cpp to the problem described below:

Iahub likes chess very much. He even invented a new chess piece named Coder. A Coder can move (and attack) one square horizontally or vertically. More precisely, if the Coder is located at position (x, y), he can move to (or attack) positions (x + 1, y), (x–1, y), (x, y + 1) and (x, y–1).

Iahub wants to know how many Coders can be placed on an n × n chessboard, so that no Coder attacks any other Coder.

Input

The first line contains an integer n (1 ≤ n ≤ 1000).

Output

On the first line print an integer, the maximum number of Coders that can be placed on the chessboard.

On each of the next n lines print n characters, describing the configuration of the Coders. For an empty cell print an '.', and for a Coder print a 'C'.

If there are multiple correct answers, you can print any.

Examples

Input

2


Output

2
C.
.C

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  int num;
  cin >> num;
  int ans = (num * num) / 2;
  if (num % 2 != 0) ans += 1;
  if (num % 2 == 0) {
    cout << ans << endl;
    for (int i = 1; i <= num; i++) {
      for (int j = 1; j <= num; j += 2) {
        if (i % 2 != 0)
          printf("C.");
        else
          printf(".C");
      }
      printf("\n");
    }
  } else if (num % 2 != 0) {
    cout << ans << endl;
    for (int i = 1; i <= num; i++) {
      for (int j = 1; j <= num / 2; j++) {
        if (i % 2 != 0)
          printf("C.");
        else
          printf(".C");
      }
      if (i % 2 != 0)
        printf("C");
      else
        printf(".");
      printf("\n");
    }
  }
  return 0;
}

```