#include <bits/stdc++.h>
using namespace std;
int main() {
  int n, m;
  cin >> n >> m;
  if ((n == 1 || n == 3 || n == 5 || n == 7 || n == 8 || n == 10 || n == 12) &&
      (m == 1 || m == 2 || m == 3 || m == 4 || m == 5))
    cout << 5 << endl;
  else if ((n == 1 || n == 3 || n == 5 || n == 7 || n == 8 || n == 10 ||
            n == 12) &&
           (m == 7 || m == 6))
    cout << 6 << endl;
  else if ((n == 4 || n == 6 || n == 9 || n == 11) &&
           (m == 1 || m == 2 || m == 3 || m == 4 || m == 5 || m == 6))
    cout << 5 << endl;
  else if ((n == 4 || n == 6 || n == 9 || n == 11) && (m == 7))
    cout << 6 << endl;
  else if (n == 2 && (m == 2 || m == 3 || m == 4 || m == 5 || m == 6 || m == 7))
    cout << 5 << endl;
  else if (n == 2 && m == 1)
    cout << 4 << endl;
}

### Prompt

Construct a Cpp code solution to the problem outlined:

Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  int n, m;
  cin >> n >> m;
  if ((n == 1 || n == 3 || n == 5 || n == 7 || n == 8 || n == 10 || n == 12) &&
      (m == 1 || m == 2 || m == 3 || m == 4 || m == 5))
    cout << 5 << endl;
  else if ((n == 1 || n == 3 || n == 5 || n == 7 || n == 8 || n == 10 ||
            n == 12) &&
           (m == 7 || m == 6))
    cout << 6 << endl;
  else if ((n == 4 || n == 6 || n == 9 || n == 11) &&
           (m == 1 || m == 2 || m == 3 || m == 4 || m == 5 || m == 6))
    cout << 5 << endl;
  else if ((n == 4 || n == 6 || n == 9 || n == 11) && (m == 7))
    cout << 6 << endl;
  else if (n == 2 && (m == 2 || m == 3 || m == 4 || m == 5 || m == 6 || m == 7))
    cout << 5 << endl;
  else if (n == 2 && m == 1)
    cout << 4 << endl;
}

```