#include <bits/stdc++.h>
using namespace std;
int main() {
  int tve, dge;
  cin >> tve >> dge;
  switch (tve) {
    case 1:
      if (dge == 1 || dge == 2 || dge == 3 || dge == 4 || dge == 5) {
        cout << 5;
      } else {
        cout << 6;
      }
      break;
    case 3:
      if (dge == 1 || dge == 2 || dge == 3 || dge == 4 || dge == 5) {
        cout << 5;
      } else {
        cout << 6;
      }
      break;
    case 5:
      if (dge == 1 || dge == 2 || dge == 3 || dge == 4 || dge == 5) {
        cout << 5;
      } else {
        cout << 6;
      }
      break;
    case 7:
      if (dge == 1 || dge == 2 || dge == 3 || dge == 4 || dge == 5) {
        cout << 5;
      } else {
        cout << 6;
      }
      break;
    case 8:
      if (dge == 1 || dge == 2 || dge == 3 || dge == 4 || dge == 5) {
        cout << 5;
      } else {
        cout << 6;
      }
      break;
    case 10:
      if (dge == 1 || dge == 2 || dge == 3 || dge == 4 || dge == 5) {
        cout << 5;
      } else {
        cout << 6;
      }
      break;
    case 12:
      if (dge == 1 || dge == 2 || dge == 3 || dge == 4 || dge == 5) {
        cout << 5;
      } else {
        cout << 6;
      }
      break;
    case 4:
      if (dge == 1 || dge == 2 || dge == 3 || dge == 4 || dge == 5 ||
          dge == 6) {
        cout << 5;
      } else {
        cout << 6;
      }
      break;
    case 6:
      if (dge == 1 || dge == 2 || dge == 3 || dge == 4 || dge == 5 ||
          dge == 6) {
        cout << 5;
      } else {
        cout << 6;
      }
      break;
    case 9:
      if (dge == 1 || dge == 2 || dge == 3 || dge == 4 || dge == 5 ||
          dge == 6) {
        cout << 5;
      } else {
        cout << 6;
      }
      break;
    case 11:
      if (dge == 1 || dge == 2 || dge == 3 || dge == 4 || dge == 5 ||
          dge == 6) {
        cout << 5;
      } else {
        cout << 6;
      }
      break;
    case 2:
      if (dge == 1) {
        cout << 4;
      } else {
        cout << 5;
      }
      break;
  }
  return 0;
}

### Prompt

Please provide a Cpp coded solution to the problem described below:

Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  int tve, dge;
  cin >> tve >> dge;
  switch (tve) {
    case 1:
      if (dge == 1 || dge == 2 || dge == 3 || dge == 4 || dge == 5) {
        cout << 5;
      } else {
        cout << 6;
      }
      break;
    case 3:
      if (dge == 1 || dge == 2 || dge == 3 || dge == 4 || dge == 5) {
        cout << 5;
      } else {
        cout << 6;
      }
      break;
    case 5:
      if (dge == 1 || dge == 2 || dge == 3 || dge == 4 || dge == 5) {
        cout << 5;
      } else {
        cout << 6;
      }
      break;
    case 7:
      if (dge == 1 || dge == 2 || dge == 3 || dge == 4 || dge == 5) {
        cout << 5;
      } else {
        cout << 6;
      }
      break;
    case 8:
      if (dge == 1 || dge == 2 || dge == 3 || dge == 4 || dge == 5) {
        cout << 5;
      } else {
        cout << 6;
      }
      break;
    case 10:
      if (dge == 1 || dge == 2 || dge == 3 || dge == 4 || dge == 5) {
        cout << 5;
      } else {
        cout << 6;
      }
      break;
    case 12:
      if (dge == 1 || dge == 2 || dge == 3 || dge == 4 || dge == 5) {
        cout << 5;
      } else {
        cout << 6;
      }
      break;
    case 4:
      if (dge == 1 || dge == 2 || dge == 3 || dge == 4 || dge == 5 ||
          dge == 6) {
        cout << 5;
      } else {
        cout << 6;
      }
      break;
    case 6:
      if (dge == 1 || dge == 2 || dge == 3 || dge == 4 || dge == 5 ||
          dge == 6) {
        cout << 5;
      } else {
        cout << 6;
      }
      break;
    case 9:
      if (dge == 1 || dge == 2 || dge == 3 || dge == 4 || dge == 5 ||
          dge == 6) {
        cout << 5;
      } else {
        cout << 6;
      }
      break;
    case 11:
      if (dge == 1 || dge == 2 || dge == 3 || dge == 4 || dge == 5 ||
          dge == 6) {
        cout << 5;
      } else {
        cout << 6;
      }
      break;
    case 2:
      if (dge == 1) {
        cout << 4;
      } else {
        cout << 5;
      }
      break;
  }
  return 0;
}

```