#include <bits/stdc++.h>
#define int long long
using namespace std;

signed main(){
	int n,keta = 0;
	vector<int> ans;
	cin >> n;
	int tmp = n + 1;
	while(tmp){
		tmp /= 2;
		keta++;
	}
	for(int i = 0;i < keta - 1;i++){
		if(((n + 1) >> i) & 1) ans.push_back(100 - i);
		ans.push_back(i + 1);
	}
	cout << ans.size() + 100 << endl;
	for(int i = 0;i < ans.size();i++) cout << (i ? " " : "") << ans[i];
	for(int i = 1;i <= 100;i++) cout << " " << i;
	cout << endl;
	return 0;
}
### Prompt

Please formulate a cpp solution to the following problem:

We will call a string x good if it satisfies the following condition:

* Condition: x can be represented as a concatenation of two copies of another string y of length at least 1.



For example, `aa` and `bubobubo` are good; an empty string, `a`, `abcabcabc` and `abba` are not good.

Eagle and Owl created a puzzle on good strings. Find one string s that satisfies the following conditions. It can be proved that such a string always exists under the constraints in this problem.

* 1 ≤ |s| ≤ 200
* Each character of s is one of the 100 characters represented by the integers 1 through 100.
* Among the 2^{|s|} subsequences of s, exactly N are good strings.

Constraints

* 1 ≤ N ≤ 10^{12}

Input

Input is given from Standard Input in the following format:


N


Output

In the first line, print |s|, the length of s. In the second line, print the elements in s in order, with spaces in between. Any string that satisfies the above conditions will be accepted.

Examples

Input

7


Output

4
1 1 1 1


Input

299


Output

23
32 11 11 73 45 8 11 83 83 8 45 32 32 10 100 73 32 83 45 73 32 11 10

### Response

```cpp
#include <bits/stdc++.h>
#define int long long
using namespace std;

signed main(){
	int n,keta = 0;
	vector<int> ans;
	cin >> n;
	int tmp = n + 1;
	while(tmp){
		tmp /= 2;
		keta++;
	}
	for(int i = 0;i < keta - 1;i++){
		if(((n + 1) >> i) & 1) ans.push_back(100 - i);
		ans.push_back(i + 1);
	}
	cout << ans.size() + 100 << endl;
	for(int i = 0;i < ans.size();i++) cout << (i ? " " : "") << ans[i];
	for(int i = 1;i <= 100;i++) cout << " " << i;
	cout << endl;
	return 0;
}
```