#include<bits/stdc++.h>
using namespace std;

#define int long long
typedef vector<int>vint;
typedef pair<int,int>pint;
typedef vector<pint>vpint;
#define rep(i,n) for(int i=0;i<(n);i++)
#define reps(i,f,n) for(int i=(f);i<(n);i++)
#define all(v) (v).begin(),(v).end()
#define each(it,v) for(__typeof((v).begin()) it=(v).begin();it!=(v).end();it++)
#define pb push_back
#define fi first
#define se second
template<typename A,typename B>inline void chmin(A &a,B b){if(a>b)a=b;}
template<typename A,typename B>inline void chmax(A &a,B b){if(a<b)a=b;}

int N,M;
int l[200000],r[200000];
signed main(){
    cin>>N;
    rep(i,N)l[i]=i,r[i]=i+1;

    cin>>M;
    vpint vec;
    rep(i,M){
        int x,y;
        cin>>x>>y;
        y--;
        vec.pb(pint(x,y));
    }
    sort(all(vec));
    rep(i,vec.size()){
        int a=vec[i].se;
        int b=vec[i].se+1;
        l[b]=l[a];
        r[a]=r[b];
    }

    rep(i,N){
        if(i)printf(" ");
        printf("%lld",r[i]-l[i]);
    }
    puts("");

    return 0;
}
### Prompt

Generate a cpp solution to the following problem:

Example

Input

4 3
1000 1
2000 2
3000 3


Output

2 3 4 4

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;

#define int long long
typedef vector<int>vint;
typedef pair<int,int>pint;
typedef vector<pint>vpint;
#define rep(i,n) for(int i=0;i<(n);i++)
#define reps(i,f,n) for(int i=(f);i<(n);i++)
#define all(v) (v).begin(),(v).end()
#define each(it,v) for(__typeof((v).begin()) it=(v).begin();it!=(v).end();it++)
#define pb push_back
#define fi first
#define se second
template<typename A,typename B>inline void chmin(A &a,B b){if(a>b)a=b;}
template<typename A,typename B>inline void chmax(A &a,B b){if(a<b)a=b;}

int N,M;
int l[200000],r[200000];
signed main(){
    cin>>N;
    rep(i,N)l[i]=i,r[i]=i+1;

    cin>>M;
    vpint vec;
    rep(i,M){
        int x,y;
        cin>>x>>y;
        y--;
        vec.pb(pint(x,y));
    }
    sort(all(vec));
    rep(i,vec.size()){
        int a=vec[i].se;
        int b=vec[i].se+1;
        l[b]=l[a];
        r[a]=r[b];
    }

    rep(i,N){
        if(i)printf(" ");
        printf("%lld",r[i]-l[i]);
    }
    puts("");

    return 0;
}
```