#include<bits/stdc++.h>
using namespace std;

int main()
{
    cin.tie(0);
    ios::sync_with_stdio(false);

    int N; cin>>N;
    int ans=0;
    int a[4]={25,10,5,1};  
    for(int i=0;i<4;i++){
        ans+=N/a[i];
        N%=a[i];
    }
    cout<<ans<<endl;
    return 0;
}

### Prompt

In cpp, your task is to solve the following problem:

You want to make change for $ n $ cents. Assuming that you have infinite supply of coins of 1, 5, 10 and / or 25 cents coins respectively, find the minimum number of coins you need.

Constraints

* $ 1 \ le n \ le 10 ^ 9 $

Input


$ n $


The integer $ n $ is given in a line.

output

Print the minimum number of coins you need in a line.

Examples

Input

100


Output

4


Input

54321


Output

2175

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;

int main()
{
    cin.tie(0);
    ios::sync_with_stdio(false);

    int N; cin>>N;
    int ans=0;
    int a[4]={25,10,5,1};  
    for(int i=0;i<4;i++){
        ans+=N/a[i];
        N%=a[i];
    }
    cout<<ans<<endl;
    return 0;
}

```