#include <bits/stdc++.h>
using namespace std;

#define rep(i, u) for (int i = 0; i < u; i++)

using ll = long long;
using ull = unsigned long long;

int main() {
  int n, m, l;
  ll a[100][100] = {}, b[100][100] = {};
  cin >> n >> m >> l;
  rep(i, n) rep(j, m) cin >> a[i][j];
  rep(i, m) rep(j, l) cin >> b[i][j];
  rep(i, n) {
    rep(j, l) {
      ll ans = 0;
      rep(k, m) ans += a[i][k] * b[k][j];
      cout << ans;
      if (j == l - 1) cout << endl;
      else cout << ' ';
    }
  } 
  return 0;
}


### Prompt

In cpp, your task is to solve the following problem:

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\\[ c_{ij} = \sum_{k=1}^m a_{ik}b_{kj} \\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Note

解説

Constraints

* $1 \leq n, m, l \leq 100$
* $0 \leq a_{ij}, b_{ij} \leq 10000$

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Example

Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2


Output

1 8 5
0 9 6
4 23 14

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;

#define rep(i, u) for (int i = 0; i < u; i++)

using ll = long long;
using ull = unsigned long long;

int main() {
  int n, m, l;
  ll a[100][100] = {}, b[100][100] = {};
  cin >> n >> m >> l;
  rep(i, n) rep(j, m) cin >> a[i][j];
  rep(i, m) rep(j, l) cin >> b[i][j];
  rep(i, n) {
    rep(j, l) {
      ll ans = 0;
      rep(k, m) ans += a[i][k] * b[k][j];
      cout << ans;
      if (j == l - 1) cout << endl;
      else cout << ' ';
    }
  } 
  return 0;
}


```