#include <bits/stdc++.h>
using namespace std;
signed main() {
  ios::sync_with_stdio(0);
  cin.tie(0);
  cout.tie(0);
  ;
  long long t;
  cin >> t;
  while (t--) {
    long long b, p, f;
    cin >> b >> p >> f;
    long long h, c;
    cin >> h >> c;
    long long ans = 0;
    if (h > c) {
      if (b / 2 > p) {
        ans += h * p;
        b = b - p * 2;
        ans += c * min(f, b / 2);
      } else {
        ans += (b / 2) * h;
      }
      cout << ans << "\n";
    } else {
      if (b / 2 > f) {
        ans += c * f;
        b = b - f * 2;
        ans += h * min(p, b / 2);
      } else {
        ans += (b / 2) * c;
      }
      cout << ans << "\n";
    }
  }
}

### Prompt

Generate a Cpp solution to the following problem:

There are two types of burgers in your restaurant — hamburgers and chicken burgers! To assemble a hamburger you need two buns and a beef patty. To assemble a chicken burger you need two buns and a chicken cutlet. 

You have b buns, p beef patties and f chicken cutlets in your restaurant. You can sell one hamburger for h dollars and one chicken burger for c dollars. Calculate the maximum profit you can achieve.

You have to answer t independent queries.

Input

The first line contains one integer t (1 ≤ t ≤ 100) – the number of queries.

The first line of each query contains three integers b, p and f (1 ≤ b, ~p, ~f ≤ 100) — the number of buns, beef patties and chicken cutlets in your restaurant.

The second line of each query contains two integers h and c (1 ≤ h, ~c ≤ 100) — the hamburger and chicken burger prices in your restaurant.

Output

For each query print one integer — the maximum profit you can achieve.

Example

Input


3
15 2 3
5 10
7 5 2
10 12
1 100 100
100 100


Output


40
34
0

Note

In first query you have to sell two hamburgers and three chicken burgers. Your income is 2 ⋅ 5 + 3 ⋅ 10 = 40.

In second query you have to ell one hamburgers and two chicken burgers. Your income is 1 ⋅ 10 + 2 ⋅ 12 = 34.

In third query you can not create any type of burgers because because you have only one bun. So your income is zero.

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
signed main() {
  ios::sync_with_stdio(0);
  cin.tie(0);
  cout.tie(0);
  ;
  long long t;
  cin >> t;
  while (t--) {
    long long b, p, f;
    cin >> b >> p >> f;
    long long h, c;
    cin >> h >> c;
    long long ans = 0;
    if (h > c) {
      if (b / 2 > p) {
        ans += h * p;
        b = b - p * 2;
        ans += c * min(f, b / 2);
      } else {
        ans += (b / 2) * h;
      }
      cout << ans << "\n";
    } else {
      if (b / 2 > f) {
        ans += c * f;
        b = b - f * 2;
        ans += h * min(p, b / 2);
      } else {
        ans += (b / 2) * c;
      }
      cout << ans << "\n";
    }
  }
}

```