#include <bits/stdc++.h>
const int inf = 1000000000;
const long long infll = 1000000000000000000;
using namespace std;
void fast_IO() {
  ios_base::sync_with_stdio(false);
  cin.tie(0);
  cout.tie(0);
}
void test() {
  freopen("test.in", "r", stdin);
  freopen("test.out", "w", stdout);
}
void solve() {
  string s;
  cin >> s;
  long long init = 0;
  long long res = 0;
  long long sz = s.size();
  int c = 0;
  while (init <= sz) {
    c++;
    init++;
    for (int i = init - 1; i < init; i++) {
      if (init > sz) break;
      if (s[i] == '+') init += 2;
    }
    res += min(init, sz);
  }
  cout << res << "\n";
}
int main() {
  fast_IO();
  int t = 1;
  cin >> t;
  while (t--) solve();
  return 0;
}

### Prompt

Construct a Cpp code solution to the problem outlined:

You are given a string s consisting only of characters + and -. You perform some process with this string. This process can be described by the following pseudocode: 
    
    
    res = 0  
    for init = 0 to inf  
        cur = init  
        ok = true  
        for i = 1 to |s|  
            res = res + 1  
            if s[i] == '+'  
                cur = cur + 1  
            else  
                cur = cur - 1  
            if cur < 0  
                ok = false  
                break  
        if ok  
            break  
    

Note that the inf denotes infinity, and the characters of the string are numbered from 1 to |s|.

You have to calculate the value of the res after the process ends.

Input

The first line contains one integer t (1 ≤ t ≤ 1000) — the number of test cases.

The only lines of each test case contains string s (1 ≤ |s| ≤ 10^6) consisting only of characters + and -.

It's guaranteed that sum of |s| over all test cases doesn't exceed 10^6.

Output

For each test case print one integer — the value of the res after the process ends.

Example

Input


3
--+-
---
++--+-


Output


7
9
6

### Response

```cpp
#include <bits/stdc++.h>
const int inf = 1000000000;
const long long infll = 1000000000000000000;
using namespace std;
void fast_IO() {
  ios_base::sync_with_stdio(false);
  cin.tie(0);
  cout.tie(0);
}
void test() {
  freopen("test.in", "r", stdin);
  freopen("test.out", "w", stdout);
}
void solve() {
  string s;
  cin >> s;
  long long init = 0;
  long long res = 0;
  long long sz = s.size();
  int c = 0;
  while (init <= sz) {
    c++;
    init++;
    for (int i = init - 1; i < init; i++) {
      if (init > sz) break;
      if (s[i] == '+') init += 2;
    }
    res += min(init, sz);
  }
  cout << res << "\n";
}
int main() {
  fast_IO();
  int t = 1;
  cin >> t;
  while (t--) solve();
  return 0;
}

```