#include <iostream>
using namespace std;

int main(void) {

	int n,m,l;
	cin >> n >> m >> l;

	int A[n][m];
	int B[m][l];
	for(int i=0;i<n;i++) {
		for(int j=0;j<m;j++) {
			cin >> A[i][j];
		}
	}

	for(int i=0;i<m;i++) {
		for(int j=0;j<l;j++) {
			cin >> B[i][j];
		}
	}

	for(int i=0;i<n;i++) {
		for(int j=0;j<l;j++) {
			long long tmp = 0;
			for(int k=0;k<m;k++) {
				tmp += A[i][k] * B[k][j];
			}
			if(j != l-1) {
				cout << tmp << " ";
			} else {
				cout << tmp;
			}
		}
		cout << endl;
	}

}
### Prompt

Your task is to create a cpp solution to the following problem:

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\\[ c_{ij} = \sum_{k=1}^m a_{ik}b_{kj} \\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Note

解説

Constraints

* $1 \leq n, m, l \leq 100$
* $0 \leq a_{ij}, b_{ij} \leq 10000$

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Example

Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2


Output

1 8 5
0 9 6
4 23 14

### Response

```cpp
#include <iostream>
using namespace std;

int main(void) {

	int n,m,l;
	cin >> n >> m >> l;

	int A[n][m];
	int B[m][l];
	for(int i=0;i<n;i++) {
		for(int j=0;j<m;j++) {
			cin >> A[i][j];
		}
	}

	for(int i=0;i<m;i++) {
		for(int j=0;j<l;j++) {
			cin >> B[i][j];
		}
	}

	for(int i=0;i<n;i++) {
		for(int j=0;j<l;j++) {
			long long tmp = 0;
			for(int k=0;k<m;k++) {
				tmp += A[i][k] * B[k][j];
			}
			if(j != l-1) {
				cout << tmp << " ";
			} else {
				cout << tmp;
			}
		}
		cout << endl;
	}

}
```