#include<iostream>
using namespace std;
int main() {
    int n, ans = 0;
    int cent[] = { 1, 5, 10, 25 };
    cin >> n;
    for (int i = 3; i >= 0; i--) {
        if (n / cent[i] != 0) {
            ans += n / cent[i];
            n = n % cent[i];
        }
    }
    cout << ans << endl;
    return 0;
}


### Prompt

Your challenge is to write a cpp solution to the following problem:

You want to make change for $ n $ cents. Assuming that you have infinite supply of coins of 1, 5, 10 and / or 25 cents coins respectively, find the minimum number of coins you need.

Constraints

* $ 1 \ le n \ le 10 ^ 9 $

Input


$ n $


The integer $ n $ is given in a line.

output

Print the minimum number of coins you need in a line.

Examples

Input

100


Output

4


Input

54321


Output

2175

### Response

```cpp
#include<iostream>
using namespace std;
int main() {
    int n, ans = 0;
    int cent[] = { 1, 5, 10, 25 };
    cin >> n;
    for (int i = 3; i >= 0; i--) {
        if (n / cent[i] != 0) {
            ans += n / cent[i];
            n = n % cent[i];
        }
    }
    cout << ans << endl;
    return 0;
}


```