#include <bits/stdc++.h>
using namespace std;
#define MAX 100

int matA[MAX][MAX];
int matB[MAX][MAX];

int main(){
	int l, m, n;
	
	cin >> n >> m >> l;
	
	for(int i=0; i<n; i++){
		for(int j=0; j<m; j++){
			cin >> matA[i][j];
		}
	}
	for(int i=0; i<m; i++){
		for(int j=0; j<l; j++){
			cin >> matB[i][j];
		}
	}
	for(int i=0; i<n; i++){
		for(int j=0; j<l; j++){
			long int c = 0;
			for(int k=0; k<m; k++){
				c += matA[i][k] * matB[k][j];
			}
			if(j) cout << " ";
			cout << c;
		}
		cout << "\n";
	}
	
	return 0;
}

### Prompt

Please formulate a cpp solution to the following problem:

Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:

\\[ c_{ij} = \sum_{k=1}^m a_{ik}b_{kj} \\]

where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Note

解説

Constraints

* $1 \leq n, m, l \leq 100$
* $0 \leq a_{ij}, b_{ij} \leq 10000$

Input

In the first line, three integers $n$, $m$ and $l$ are given separated by space characters

In the following lines, the $n \times m$ matrix $A$ and the $m \times l$ matrix $B$ are given.

Output

Print elements of the $n \times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.

Example

Input

3 2 3
1 2
0 3
4 5
1 2 1
0 3 2


Output

1 8 5
0 9 6
4 23 14

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
#define MAX 100

int matA[MAX][MAX];
int matB[MAX][MAX];

int main(){
	int l, m, n;
	
	cin >> n >> m >> l;
	
	for(int i=0; i<n; i++){
		for(int j=0; j<m; j++){
			cin >> matA[i][j];
		}
	}
	for(int i=0; i<m; i++){
		for(int j=0; j<l; j++){
			cin >> matB[i][j];
		}
	}
	for(int i=0; i<n; i++){
		for(int j=0; j<l; j++){
			long int c = 0;
			for(int k=0; k<m; k++){
				c += matA[i][k] * matB[k][j];
			}
			if(j) cout << " ";
			cout << c;
		}
		cout << "\n";
	}
	
	return 0;
}

```