#include <cstdio>
int main(){
  int n, num, i, j, vec[4][13];
  char card;
  scanf("%d%*c", &n);
  for (i=0; i<n; i++) {
    scanf("%c %d%*c", &card, &num);
    if (card=='S') vec[0][num-1]=num;
    else if (card=='H') vec[1][num-1]=num;
    else if (card=='C') vec[2][num-1]=num;
    else vec[3][num-1]=num;
  }

  for (i=0; i<4; i++) {
    if (i==0) card='S';
    else if (i==1) card='H';
    else if (i==2) card='C';
    else card='D';
    for (j=0; j<13; j++) {
      if (vec[i][j]!=j+1) {
        printf("%c %d\n", card, j+1);
      }
    }
  }
}

### Prompt

Please provide a cpp coded solution to the problem described below:

Taro is going to play a card game. However, now he has only n cards, even though there should be 52 cards (he has no Jokers).

The 52 cards include 13 ranks of each of the four suits: spade, heart, club and diamond.

Note

解説



Input

In the first line, the number of cards n (n ≤ 52) is given.

In the following n lines, data of the n cards are given. Each card is given by a pair of a character and an integer which represent its suit and rank respectively. A suit is represented by 'S', 'H', 'C' and 'D' for spades, hearts, clubs and diamonds respectively. A rank is represented by an integer from 1 to 13.

Output

Print the missing cards. The same as the input format, each card should be printed with a character and an integer separated by a space character in a line. Arrange the missing cards in the following priorities:

* Print cards of spades, hearts, clubs and diamonds in this order.
* If the suits are equal, print cards with lower ranks first.

Example

Input

47
S 10
S 11
S 12
S 13
H 1
H 2
S 6
S 7
S 8
S 9
H 6
H 8
H 9
H 10
H 11
H 4
H 5
S 2
S 3
S 4
S 5
H 12
H 13
C 1
C 2
D 1
D 2
D 3
D 4
D 5
D 6
D 7
C 3
C 4
C 5
C 6
C 7
C 8
C 9
C 10
C 11
C 13
D 9
D 10
D 11
D 12
D 13


Output

S 1
H 3
H 7
C 12
D 8

### Response

```cpp
#include <cstdio>
int main(){
  int n, num, i, j, vec[4][13];
  char card;
  scanf("%d%*c", &n);
  for (i=0; i<n; i++) {
    scanf("%c %d%*c", &card, &num);
    if (card=='S') vec[0][num-1]=num;
    else if (card=='H') vec[1][num-1]=num;
    else if (card=='C') vec[2][num-1]=num;
    else vec[3][num-1]=num;
  }

  for (i=0; i<4; i++) {
    if (i==0) card='S';
    else if (i==1) card='H';
    else if (i==2) card='C';
    else card='D';
    for (j=0; j<13; j++) {
      if (vec[i][j]!=j+1) {
        printf("%c %d\n", card, j+1);
      }
    }
  }
}

```