#include<stdio.h>

int main(){
	
	int ntc;
	int coin25 = 0;
	int coin10 = 0;
	int coin5 = 0;
	int coin1 = 0;
		
	scanf("%d",&ntc);
	
		int temp = ntc/25;
		int sisa = ntc % 25;
		if( temp>= 0){
	
			//printf("%d", temp);
			coin25+= temp;
		}
		
	//	printf("Coin 25 : %d\n", coin25);
		//printf("Sisa : %d\n", sisa);
		
		int penampung = ntc % 25;
		
	//	printf("Sisa : %d\n",penampung);
		if(penampung  == 0){
			
			printf("%d\n",coin25);
		}else{
			
			//penampung = penampung / 10;
			coin10 += penampung / 10;
			int sisapenampung = penampung %10;
			
		//	printf("Coin 10 : %d\n", coin10);
			
			//printf("%d\n",sisapenampung);
			
			if(sisapenampung == 0){
				printf("%d\n",coin25+coin10);
			}else{
				
				//printf("%d\n",sisapenampung);
			
				while (sisapenampung>= 5 && sisapenampung<10){
					coin5++;
					sisapenampung-=5;
				}
				
				
				while (sisapenampung >=1 && sisapenampung <=4){
					coin1++;
					sisapenampung--;
				}
				
				if(sisapenampung == 0){
					printf("%d\n",coin25 + coin10+ coin5+coin1);
				}
				
			}
				
		}
		
		return 0;
}

### Prompt

Please create a solution in Cpp to the following problem:

You want to make change for $ n $ cents. Assuming that you have infinite supply of coins of 1, 5, 10 and / or 25 cents coins respectively, find the minimum number of coins you need.

Constraints

* $ 1 \ le n \ le 10 ^ 9 $

Input


$ n $


The integer $ n $ is given in a line.

output

Print the minimum number of coins you need in a line.

Examples

Input

100


Output

4


Input

54321


Output

2175

### Response

```cpp
#include<stdio.h>

int main(){
	
	int ntc;
	int coin25 = 0;
	int coin10 = 0;
	int coin5 = 0;
	int coin1 = 0;
		
	scanf("%d",&ntc);
	
		int temp = ntc/25;
		int sisa = ntc % 25;
		if( temp>= 0){
	
			//printf("%d", temp);
			coin25+= temp;
		}
		
	//	printf("Coin 25 : %d\n", coin25);
		//printf("Sisa : %d\n", sisa);
		
		int penampung = ntc % 25;
		
	//	printf("Sisa : %d\n",penampung);
		if(penampung  == 0){
			
			printf("%d\n",coin25);
		}else{
			
			//penampung = penampung / 10;
			coin10 += penampung / 10;
			int sisapenampung = penampung %10;
			
		//	printf("Coin 10 : %d\n", coin10);
			
			//printf("%d\n",sisapenampung);
			
			if(sisapenampung == 0){
				printf("%d\n",coin25+coin10);
			}else{
				
				//printf("%d\n",sisapenampung);
			
				while (sisapenampung>= 5 && sisapenampung<10){
					coin5++;
					sisapenampung-=5;
				}
				
				
				while (sisapenampung >=1 && sisapenampung <=4){
					coin1++;
					sisapenampung--;
				}
				
				if(sisapenampung == 0){
					printf("%d\n",coin25 + coin10+ coin5+coin1);
				}
				
			}
				
		}
		
		return 0;
}

```