#include <bits/stdc++.h>
using namespace std;
void r(int b, int p, int f, int h, int c);
int main() {
  int b, p, f, h, c, t;
  cin >> t;
  while (t--) {
    cin >> b >> p >> f >> h >> c;
    r(b, p, f, h, c);
  }
}
void r(int b, int p, int f, int h, int c) {
  int i, j, k, t = 0;
  i = b / 2;
  if (i == 0) {
    cout << 0 << endl;
  } else {
    if (i >= (p + f)) {
      t = (p * h) + (c * f);
      cout << t << endl;
    } else {
      if (h >= c) {
        if (p >= i) {
          t = (i * h);
          cout << t << endl;
        } else {
          t = (h * p);
          i = i - p;
          t = t + (i * c);
          cout << t << endl;
        }
      } else {
        if (f >= i) {
          t = (i * c);
          cout << t << endl;
        } else {
          t = (c * f);
          i = i - f;
          t = t + (i * h);
          cout << t << endl;
        }
      }
    }
  }
}

### Prompt

Please create a solution in CPP to the following problem:

There are two types of burgers in your restaurant — hamburgers and chicken burgers! To assemble a hamburger you need two buns and a beef patty. To assemble a chicken burger you need two buns and a chicken cutlet. 

You have b buns, p beef patties and f chicken cutlets in your restaurant. You can sell one hamburger for h dollars and one chicken burger for c dollars. Calculate the maximum profit you can achieve.

You have to answer t independent queries.

Input

The first line contains one integer t (1 ≤ t ≤ 100) – the number of queries.

The first line of each query contains three integers b, p and f (1 ≤ b, ~p, ~f ≤ 100) — the number of buns, beef patties and chicken cutlets in your restaurant.

The second line of each query contains two integers h and c (1 ≤ h, ~c ≤ 100) — the hamburger and chicken burger prices in your restaurant.

Output

For each query print one integer — the maximum profit you can achieve.

Example

Input


3
15 2 3
5 10
7 5 2
10 12
1 100 100
100 100


Output


40
34
0

Note

In first query you have to sell two hamburgers and three chicken burgers. Your income is 2 ⋅ 5 + 3 ⋅ 10 = 40.

In second query you have to ell one hamburgers and two chicken burgers. Your income is 1 ⋅ 10 + 2 ⋅ 12 = 34.

In third query you can not create any type of burgers because because you have only one bun. So your income is zero.

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
void r(int b, int p, int f, int h, int c);
int main() {
  int b, p, f, h, c, t;
  cin >> t;
  while (t--) {
    cin >> b >> p >> f >> h >> c;
    r(b, p, f, h, c);
  }
}
void r(int b, int p, int f, int h, int c) {
  int i, j, k, t = 0;
  i = b / 2;
  if (i == 0) {
    cout << 0 << endl;
  } else {
    if (i >= (p + f)) {
      t = (p * h) + (c * f);
      cout << t << endl;
    } else {
      if (h >= c) {
        if (p >= i) {
          t = (i * h);
          cout << t << endl;
        } else {
          t = (h * p);
          i = i - p;
          t = t + (i * c);
          cout << t << endl;
        }
      } else {
        if (f >= i) {
          t = (i * c);
          cout << t << endl;
        } else {
          t = (c * f);
          i = i - f;
          t = t + (i * h);
          cout << t << endl;
        }
      }
    }
  }
}

```