#include <bits/stdc++.h>
int max(int a, int b) { return a > b ? a : b; }
int main() {
  int t, b, p, f, h, c;
  scanf("%d", &t);
  while (t) {
    int profit = 0;
    scanf("%d %d %d", &b, &p, &f);
    scanf("%d %d", &h, &c);
    if (b / 2 >= p + f) {
      profit = p * h + f * c;
    } else {
      int m = max(h, c);
      int m1;
      if (m == h)
        m1 = p;
      else
        m1 = f;
      if (b / 2 > m1) {
        if (m == h)
          profit = p * h + (b / 2 - p) * c;
        else
          profit = f * c + (b / 2 - f) * h;
      } else {
        if (m == h)
          profit = b / 2 * h;
        else
          profit = b / 2 * c;
      }
    }
    printf("%d\n", profit);
    t--;
  }
}

### Prompt

Please formulate a Cpp solution to the following problem:

There are two types of burgers in your restaurant — hamburgers and chicken burgers! To assemble a hamburger you need two buns and a beef patty. To assemble a chicken burger you need two buns and a chicken cutlet. 

You have b buns, p beef patties and f chicken cutlets in your restaurant. You can sell one hamburger for h dollars and one chicken burger for c dollars. Calculate the maximum profit you can achieve.

You have to answer t independent queries.

Input

The first line contains one integer t (1 ≤ t ≤ 100) – the number of queries.

The first line of each query contains three integers b, p and f (1 ≤ b, ~p, ~f ≤ 100) — the number of buns, beef patties and chicken cutlets in your restaurant.

The second line of each query contains two integers h and c (1 ≤ h, ~c ≤ 100) — the hamburger and chicken burger prices in your restaurant.

Output

For each query print one integer — the maximum profit you can achieve.

Example

Input


3
15 2 3
5 10
7 5 2
10 12
1 100 100
100 100


Output


40
34
0

Note

In first query you have to sell two hamburgers and three chicken burgers. Your income is 2 ⋅ 5 + 3 ⋅ 10 = 40.

In second query you have to ell one hamburgers and two chicken burgers. Your income is 1 ⋅ 10 + 2 ⋅ 12 = 34.

In third query you can not create any type of burgers because because you have only one bun. So your income is zero.

### Response

```cpp
#include <bits/stdc++.h>
int max(int a, int b) { return a > b ? a : b; }
int main() {
  int t, b, p, f, h, c;
  scanf("%d", &t);
  while (t) {
    int profit = 0;
    scanf("%d %d %d", &b, &p, &f);
    scanf("%d %d", &h, &c);
    if (b / 2 >= p + f) {
      profit = p * h + f * c;
    } else {
      int m = max(h, c);
      int m1;
      if (m == h)
        m1 = p;
      else
        m1 = f;
      if (b / 2 > m1) {
        if (m == h)
          profit = p * h + (b / 2 - p) * c;
        else
          profit = f * c + (b / 2 - f) * h;
      } else {
        if (m == h)
          profit = b / 2 * h;
        else
          profit = b / 2 * c;
      }
    }
    printf("%d\n", profit);
    t--;
  }
}

```