#include<iostream>
using namespace std;
int main(){
int a=0;cin>>a;
int c[4][14]={0};
for(int i=0;i<a;i++){
  char z;
  cin>>z;
  int n;
  cin>>n;
  if(z=='S')
c[0][n]=1;
   else if(z=='H')
c[1][n]=1;
   else if(z=='C')
c[2][n]=1;
   else if(z=='D')
  c[3][n]=1;
  
}

for(int i=0;i<4;i++){
  for(int j=1;j<14;j++){
  if(c[i][j]==0){
    char z;
    if(i==0)
    z='S';
    else if(i==1)
    z='H';
      else if(i==2)
    z='C';
      else if(i==3)
    z='D';
    cout<<z<<' '<<j<<'\n';
  }
  }
}
return 0;
}
### Prompt

Develop a solution in cpp to the problem described below:

Taro is going to play a card game. However, now he has only n cards, even though there should be 52 cards (he has no Jokers).

The 52 cards include 13 ranks of each of the four suits: spade, heart, club and diamond.

Note

解説



Input

In the first line, the number of cards n (n ≤ 52) is given.

In the following n lines, data of the n cards are given. Each card is given by a pair of a character and an integer which represent its suit and rank respectively. A suit is represented by 'S', 'H', 'C' and 'D' for spades, hearts, clubs and diamonds respectively. A rank is represented by an integer from 1 to 13.

Output

Print the missing cards. The same as the input format, each card should be printed with a character and an integer separated by a space character in a line. Arrange the missing cards in the following priorities:

* Print cards of spades, hearts, clubs and diamonds in this order.
* If the suits are equal, print cards with lower ranks first.

Example

Input

47
S 10
S 11
S 12
S 13
H 1
H 2
S 6
S 7
S 8
S 9
H 6
H 8
H 9
H 10
H 11
H 4
H 5
S 2
S 3
S 4
S 5
H 12
H 13
C 1
C 2
D 1
D 2
D 3
D 4
D 5
D 6
D 7
C 3
C 4
C 5
C 6
C 7
C 8
C 9
C 10
C 11
C 13
D 9
D 10
D 11
D 12
D 13


Output

S 1
H 3
H 7
C 12
D 8

### Response

```cpp
#include<iostream>
using namespace std;
int main(){
int a=0;cin>>a;
int c[4][14]={0};
for(int i=0;i<a;i++){
  char z;
  cin>>z;
  int n;
  cin>>n;
  if(z=='S')
c[0][n]=1;
   else if(z=='H')
c[1][n]=1;
   else if(z=='C')
c[2][n]=1;
   else if(z=='D')
  c[3][n]=1;
  
}

for(int i=0;i<4;i++){
  for(int j=1;j<14;j++){
  if(c[i][j]==0){
    char z;
    if(i==0)
    z='S';
    else if(i==1)
    z='H';
      else if(i==2)
    z='C';
      else if(i==3)
    z='D';
    cout<<z<<' '<<j<<'\n';
  }
  }
}
return 0;
}
```