#include <bits/stdc++.h>
using namespace std;
int main(){
  int a,b,n=0;
  cin >> a >> b;
  for(a;a<=b;a++){
    if((a/10000==a%10)&&(a%10000/1000==a%100/10))
      n++;
    else
      continue;
  }
  cout << n << endl;
}
### Prompt

Construct a Cpp code solution to the problem outlined:

Find the number of palindromic numbers among the integers between A and B (inclusive). Here, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.

Constraints

* 10000 \leq A \leq B \leq 99999
* All input values are integers.

Input

Input is given from Standard Input in the following format:


A B


Output

Print the number of palindromic numbers among the integers between A and B (inclusive).

Examples

Input

11009 11332


Output

4


Input

31415 92653


Output

612

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main(){
  int a,b,n=0;
  cin >> a >> b;
  for(a;a<=b;a++){
    if((a/10000==a%10)&&(a%10000/1000==a%100/10))
      n++;
    else
      continue;
  }
  cout << n << endl;
}
```