#include<bits/stdc++.h>
using namespace std;
int main(){
  int n;
  cin>>n;
  while(n){
  	int t=n%10;
    if(t==7){cout<<"Yes"; return 0;}
    n/=10;
  }
  cout<<"No";
}
### Prompt

Please formulate a CPP solution to the following problem:

Given is a three-digit integer N. Does N contain the digit 7?

If so, print `Yes`; otherwise, print `No`.

Constraints

* 100 \leq N \leq 999

Input

Input is given from Standard Input in the following format:


N


Output

If N contains the digit 7, print `Yes`; otherwise, print `No`.

Examples

Input

117


Output

Yes


Input

123


Output

No


Input

777


Output

Yes

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;
int main(){
  int n;
  cin>>n;
  while(n){
  	int t=n%10;
    if(t==7){cout<<"Yes"; return 0;}
    n/=10;
  }
  cout<<"No";
}
```