#include <bits/stdc++.h>
using namespace std;
int main(){
  int A, B,c=0;
  cin >> A >> B;
  for(int i=A;i<=B;i++){
    if(i/10000==i%10&&(i/1000)%10==(i%100)/10){
      c++;
    }
  }
  cout<<c<<endl;
}
 
### Prompt

Develop a solution in CPP to the problem described below:

Find the number of palindromic numbers among the integers between A and B (inclusive). Here, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.

Constraints

* 10000 \leq A \leq B \leq 99999
* All input values are integers.

Input

Input is given from Standard Input in the following format:


A B


Output

Print the number of palindromic numbers among the integers between A and B (inclusive).

Examples

Input

11009 11332


Output

4


Input

31415 92653


Output

612

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main(){
  int A, B,c=0;
  cin >> A >> B;
  for(int i=A;i<=B;i++){
    if(i/10000==i%10&&(i/1000)%10==(i%100)/10){
      c++;
    }
  }
  cout<<c<<endl;
}
 
```