#include<iostream>
using namespace std;
int main()
{
	string s;
	cin>>s;
	for(int i=0;i<3;i++)
	{
		if(s[i]=='7')
		{
			cout<<"Yes";
			return 0;
		}
	}

	cout<<"No";
}
### Prompt

Please provide a Cpp coded solution to the problem described below:

Given is a three-digit integer N. Does N contain the digit 7?

If so, print `Yes`; otherwise, print `No`.

Constraints

* 100 \leq N \leq 999

Input

Input is given from Standard Input in the following format:


N


Output

If N contains the digit 7, print `Yes`; otherwise, print `No`.

Examples

Input

117


Output

Yes


Input

123


Output

No


Input

777


Output

Yes

### Response

```cpp
#include<iostream>
using namespace std;
int main()
{
	string s;
	cin>>s;
	for(int i=0;i<3;i++)
	{
		if(s[i]=='7')
		{
			cout<<"Yes";
			return 0;
		}
	}

	cout<<"No";
}
```