#include <iostream>

using namespace std;

int main(){
	int n;
	cin >> n;
	while(n){
		if(n%10 == 7){
			cout << "Yes\n";
			return 0;
		}
		n/=10;
	}
	cout << "No\n";
}
### Prompt

Your challenge is to write a Cpp solution to the following problem:

Given is a three-digit integer N. Does N contain the digit 7?

If so, print `Yes`; otherwise, print `No`.

Constraints

* 100 \leq N \leq 999

Input

Input is given from Standard Input in the following format:


N


Output

If N contains the digit 7, print `Yes`; otherwise, print `No`.

Examples

Input

117


Output

Yes


Input

123


Output

No


Input

777


Output

Yes

### Response

```cpp
#include <iostream>

using namespace std;

int main(){
	int n;
	cin >> n;
	while(n){
		if(n%10 == 7){
			cout << "Yes\n";
			return 0;
		}
		n/=10;
	}
	cout << "No\n";
}
```