#include <bits/stdc++.h>
using namespace std;

int main() {
  int A,B;
  cin >> A >> B;
  int x = 0;
  for(int i = A;i <= B;i++){
   if(i / 1000 == i % 10 *10 + i % 100 / 10){
     x += 1;
   }
  }
    cout << x << endl;
}
### Prompt

Generate a Cpp solution to the following problem:

Find the number of palindromic numbers among the integers between A and B (inclusive). Here, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.

Constraints

* 10000 \leq A \leq B \leq 99999
* All input values are integers.

Input

Input is given from Standard Input in the following format:


A B


Output

Print the number of palindromic numbers among the integers between A and B (inclusive).

Examples

Input

11009 11332


Output

4


Input

31415 92653


Output

612

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;

int main() {
  int A,B;
  cin >> A >> B;
  int x = 0;
  for(int i = A;i <= B;i++){
   if(i / 1000 == i % 10 *10 + i % 100 / 10){
     x += 1;
   }
  }
    cout << x << endl;
}
```