#include <stdio.h>
int main(void) {
	int n;
	long long int a,b=-1,c=2;
	scanf("%d", &n);
	for (int i = 0;i < n;i++) {
		a = b;
		b = c;
		c = a + b;
	}
	printf("%lld\n", c);
	return 0;
}
### Prompt

Generate a CPP solution to the following problem:

It is November 18 now in Japan. By the way, 11 and 18 are adjacent Lucas numbers.

You are given an integer N. Find the N-th Lucas number.

Here, the i-th Lucas number L_i is defined as follows:

* L_0=2
* L_1=1
* L_i=L_{i-1}+L_{i-2} (i≥2)

Constraints

* 1≤N≤86
* It is guaranteed that the answer is less than 10^{18}.
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the N-th Lucas number.

Examples

Input

5


Output

11


Input

86


Output

939587134549734843

### Response

```cpp
#include <stdio.h>
int main(void) {
	int n;
	long long int a,b=-1,c=2;
	scanf("%d", &n);
	for (int i = 0;i < n;i++) {
		a = b;
		b = c;
		c = a + b;
	}
	printf("%lld\n", c);
	return 0;
}
```