#include <stdio.h>

int main (){
	int N;
	scanf ("%d", &N);
	
	if (N % 10 == 7 || (N/10)%10 == 7 || N /100 == 7){
		puts ("Yes");
	}
	else {
		puts ("No");
	}
	return 0;
}
### Prompt

Please create a solution in Cpp to the following problem:

Given is a three-digit integer N. Does N contain the digit 7?

If so, print `Yes`; otherwise, print `No`.

Constraints

* 100 \leq N \leq 999

Input

Input is given from Standard Input in the following format:


N


Output

If N contains the digit 7, print `Yes`; otherwise, print `No`.

Examples

Input

117


Output

Yes


Input

123


Output

No


Input

777


Output

Yes

### Response

```cpp
#include <stdio.h>

int main (){
	int N;
	scanf ("%d", &N);
	
	if (N % 10 == 7 || (N/10)%10 == 7 || N /100 == 7){
		puts ("Yes");
	}
	else {
		puts ("No");
	}
	return 0;
}
```