#include <stdio.h>

int main(){
	int a, b, cnt=0; scanf("%d%d",&a,&b);
	for(int i = a; i <= b; i++){
		if(i%10 == i/10000 && i/1000%10 == i/10%10) cnt++;
	}
	printf("%d",cnt);
	return 0;
}
### Prompt

Please formulate a Cpp solution to the following problem:

Find the number of palindromic numbers among the integers between A and B (inclusive). Here, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.

Constraints

* 10000 \leq A \leq B \leq 99999
* All input values are integers.

Input

Input is given from Standard Input in the following format:


A B


Output

Print the number of palindromic numbers among the integers between A and B (inclusive).

Examples

Input

11009 11332


Output

4


Input

31415 92653


Output

612

### Response

```cpp
#include <stdio.h>

int main(){
	int a, b, cnt=0; scanf("%d%d",&a,&b);
	for(int i = a; i <= b; i++){
		if(i%10 == i/10000 && i/1000%10 == i/10%10) cnt++;
	}
	printf("%d",cnt);
	return 0;
}
```