#include <bits/stdc++.h>
using namespace std;
const int inf = (int)1e9;
const double eps = 1e-9;
const int mod = inf + 7;
int n, m;
vector<pair<int, int> > ans;
int main() {
  cin >> n >> m;
  if (m == 3) {
    if (n <= 4) {
      ans.push_back(make_pair(100, 0));
      ans.push_back(make_pair(-100, 0));
      ans.push_back(make_pair(0, 100));
      if (n == 4) ans.push_back(make_pair(0, 50));
    } else {
      puts("-1");
      return 0;
    }
  } else {
    for (int i = 1; i <= m; i++) ans.push_back(make_pair(i, i * i));
    for (int i = 1; i <= n - m; i++)
      ans.push_back(make_pair(i, -10000 - i * i));
  }
  for (int i = 0; i < n; i++)
    cout << ans[i].first << " " << ans[i].second << "\n";
  return 0;
}

### Prompt

Develop a solution in cpp to the problem described below:

Convexity of a set of points on the plane is the size of the largest subset of points that form a convex polygon. Your task is to build a set of n points with the convexity of exactly m. Your set of points should not contain three points that lie on a straight line.

Input

The single line contains two integers n and m (3 ≤ m ≤ 100, m ≤ n ≤ 2m).

Output

If there is no solution, print "-1". Otherwise, print n pairs of integers — the coordinates of points of any set with the convexity of m. The coordinates shouldn't exceed 108 in their absolute value.

Examples

Input

4 3


Output

0 0
3 0
0 3
1 1


Input

6 3


Output

-1


Input

6 6


Output

10 0
-10 0
10 1
9 1
9 -1
0 -2


Input

7 4


Output

176166 6377
709276 539564
654734 174109
910147 434207
790497 366519
606663 21061
859328 886001

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
const int inf = (int)1e9;
const double eps = 1e-9;
const int mod = inf + 7;
int n, m;
vector<pair<int, int> > ans;
int main() {
  cin >> n >> m;
  if (m == 3) {
    if (n <= 4) {
      ans.push_back(make_pair(100, 0));
      ans.push_back(make_pair(-100, 0));
      ans.push_back(make_pair(0, 100));
      if (n == 4) ans.push_back(make_pair(0, 50));
    } else {
      puts("-1");
      return 0;
    }
  } else {
    for (int i = 1; i <= m; i++) ans.push_back(make_pair(i, i * i));
    for (int i = 1; i <= n - m; i++)
      ans.push_back(make_pair(i, -10000 - i * i));
  }
  for (int i = 0; i < n; i++)
    cout << ans[i].first << " " << ans[i].second << "\n";
  return 0;
}

```