#include <iostream>
using namespace std;
int A, B;
int main() {
	cin >> A >> B;
	cout << (A * B % 2 == 0 ? "No" : "Yes") << endl;
	return 0;
}
### Prompt

Create a solution in CPP for the following problem:

You are given integers A and B, each between 1 and 3 (inclusive).

Determine if there is an integer C between 1 and 3 (inclusive) such that A \times B \times C is an odd number.

Constraints

* All values in input are integers.
* 1 \leq A, B \leq 3

Input

Input is given from Standard Input in the following format:


A B


Output

If there is an integer C between 1 and 3 that satisfies the condition, print `Yes`; otherwise, print `No`.

Examples

Input

3 1


Output

Yes


Input

1 2


Output

No


Input

2 2


Output

No

### Response

```cpp
#include <iostream>
using namespace std;
int A, B;
int main() {
	cin >> A >> B;
	cout << (A * B % 2 == 0 ? "No" : "Yes") << endl;
	return 0;
}
```