#include<bits/stdc++.h>
using namespace std;


int main()
{
	int n,f=0;
	scanf("%d",&n);
	while(n) {
		if(n%10==7) f=1;
		n/=10;
	}
	puts(f?"Yes":"No");
}
### Prompt

Develop a solution in cpp to the problem described below:

Given is a three-digit integer N. Does N contain the digit 7?

If so, print `Yes`; otherwise, print `No`.

Constraints

* 100 \leq N \leq 999

Input

Input is given from Standard Input in the following format:


N


Output

If N contains the digit 7, print `Yes`; otherwise, print `No`.

Examples

Input

117


Output

Yes


Input

123


Output

No


Input

777


Output

Yes

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;


int main()
{
	int n,f=0;
	scanf("%d",&n);
	while(n) {
		if(n%10==7) f=1;
		n/=10;
	}
	puts(f?"Yes":"No");
}
```