#include<bits/stdc++.h>
using namespace std;
int main() {
	int ans=0,a,b;
	cin>>a>>b;
	b--;
	a--;
	ans=b/a;
	if(b%a!=0) ans++;
	cout<<ans;
}
### Prompt

Develop a solution in Cpp to the problem described below:

Takahashi's house has only one socket.

Takahashi wants to extend it with some number of power strips, each with A sockets, into B or more empty sockets.

One power strip with A sockets can extend one empty socket into A empty sockets.

Find the minimum number of power strips required.

Constraints

* All values in input are integers.
* 2 \leq A \leq 20
* 1 \leq B \leq 20

Input

Input is given from Standard Input in the following format:


A B


Output

Print the minimum number of power strips required.

Examples

Input

4 10


Output

3


Input

8 9


Output

2


Input

8 8


Output

1

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;
int main() {
	int ans=0,a,b;
	cin>>a>>b;
	b--;
	a--;
	ans=b/a;
	if(b%a!=0) ans++;
	cout<<ans;
}
```