#include <bits/stdc++.h>
using namespace std;

int a[12][12];

int main(){
	int n,m,x;
	cin >> n >> m >> x;
	vector<int> c(n);
	for(int i=0;i<n;i++){
		cin >> c[i];
		for(int j=0;j<m;j++){
			cin >> a[i][j];
		}
	}

	int ans = 1001001001;

	for(int s=0;s<1<<n;s++){ 
		int cost = 0;
		vector<int> d(m);
		for(int i=0;i<n;i++){
			if(s>>i&1) {
				cost += c[i];
				for(int j=0;j<m;j++){
					d[j] += a[i][j];
				}
			}
		}
		bool ok = true;
		for(int j=0;j<m;j++){
			if(d[j] < x){
				ok = false;
			}
		}
		if(ok){
			ans = min(ans,cost);
		}
	}
	if(ans==1001001001){
		cout << -1 << endl;
	}else{
		cout << ans << endl;
	}
	return 0;

}
### Prompt

Construct a cpp code solution to the problem outlined:

Constraints

* All values in input are integers.
* 1\leq N, M\leq 12
* 1\leq X\leq 10^5
* 1\leq C_i \leq 10^5
* 0\leq A_{i, j} \leq 10^5

Input

Input is given from Standard Input in the following format:


N M X
C_1 A_{1,1} A_{1,2} \cdots A_{1,M}
C_2 A_{2,1} A_{2,2} \cdots A_{2,M}
\vdots
C_N A_{N,1} A_{N,2} \cdots A_{N,M}


Output

If the objective is not achievable, print `-1`; otherwise, print the minimum amount of money needed to achieve it.

Examples

Input

3 3 10
60 2 2 4
70 8 7 9
50 2 3 9


Output

120


Input

3 3 10
100 3 1 4
100 1 5 9
100 2 6 5


Output

-1


Input

8 5 22
100 3 7 5 3 1
164 4 5 2 7 8
334 7 2 7 2 9
234 4 7 2 8 2
541 5 4 3 3 6
235 4 8 6 9 7
394 3 6 1 6 2
872 8 4 3 7 2


Output

1067

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;

int a[12][12];

int main(){
	int n,m,x;
	cin >> n >> m >> x;
	vector<int> c(n);
	for(int i=0;i<n;i++){
		cin >> c[i];
		for(int j=0;j<m;j++){
			cin >> a[i][j];
		}
	}

	int ans = 1001001001;

	for(int s=0;s<1<<n;s++){ 
		int cost = 0;
		vector<int> d(m);
		for(int i=0;i<n;i++){
			if(s>>i&1) {
				cost += c[i];
				for(int j=0;j<m;j++){
					d[j] += a[i][j];
				}
			}
		}
		bool ok = true;
		for(int j=0;j<m;j++){
			if(d[j] < x){
				ok = false;
			}
		}
		if(ok){
			ans = min(ans,cost);
		}
	}
	if(ans==1001001001){
		cout << -1 << endl;
	}else{
		cout << ans << endl;
	}
	return 0;

}
```