#include <bits/stdc++.h>
using namespace std;

int main() {
  int A, B;
  cin >> A >> B;
  cout << ((A*B) % 2 == 1 ? "Yes" : "No") << endl;
}
### Prompt

Develop a solution in Cpp to the problem described below:

You are given integers A and B, each between 1 and 3 (inclusive).

Determine if there is an integer C between 1 and 3 (inclusive) such that A \times B \times C is an odd number.

Constraints

* All values in input are integers.
* 1 \leq A, B \leq 3

Input

Input is given from Standard Input in the following format:


A B


Output

If there is an integer C between 1 and 3 that satisfies the condition, print `Yes`; otherwise, print `No`.

Examples

Input

3 1


Output

Yes


Input

1 2


Output

No


Input

2 2


Output

No

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;

int main() {
  int A, B;
  cin >> A >> B;
  cout << ((A*B) % 2 == 1 ? "Yes" : "No") << endl;
}
```