#include<bits/stdc++.h>
using namespace std;
int main(){
  long long int n,a=2,b=1,c=3,d;
  cin>>n;
  for(int i=0;i<n;i++){
    c=c+b;
    d=b;
    b=b+a;
    a=d;
  }
  cout<<a<<endl;
}
### Prompt

Construct a CPP code solution to the problem outlined:

It is November 18 now in Japan. By the way, 11 and 18 are adjacent Lucas numbers.

You are given an integer N. Find the N-th Lucas number.

Here, the i-th Lucas number L_i is defined as follows:

* L_0=2
* L_1=1
* L_i=L_{i-1}+L_{i-2} (i≥2)

Constraints

* 1≤N≤86
* It is guaranteed that the answer is less than 10^{18}.
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the N-th Lucas number.

Examples

Input

5


Output

11


Input

86


Output

939587134549734843

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;
int main(){
  long long int n,a=2,b=1,c=3,d;
  cin>>n;
  for(int i=0;i<n;i++){
    c=c+b;
    d=b;
    b=b+a;
    a=d;
  }
  cout<<a<<endl;
}
```