#include <bits/stdc++.h>
using namespace std;
int main() {
  vector<int> secret(4);
  for (int i = 0; i < 4; i++) {
    cin >> secret[i];
  }
  sort(secret.begin(), secret.end());
  int a = secret[3] - secret[1];
  int b = secret[3] - secret[2];
  int c = secret[3] - secret[0];
  printf("%d %d %d\n", a, b, c);
  return 0;
}

### Prompt

Your challenge is to write a cpp solution to the following problem:

Polycarp has guessed three positive integers a, b and c. He keeps these numbers in secret, but he writes down four numbers on a board in arbitrary order — their pairwise sums (three numbers) and sum of all three numbers (one number). So, there are four numbers on a board in random order: a+b, a+c, b+c and a+b+c.

You have to guess three numbers a, b and c using given numbers. Print three guessed integers in any order.

Pay attention that some given numbers a, b and c can be equal (it is also possible that a=b=c).

Input

The only line of the input contains four positive integers x_1, x_2, x_3, x_4 (2 ≤ x_i ≤ 10^9) — numbers written on a board in random order. It is guaranteed that the answer exists for the given number x_1, x_2, x_3, x_4.

Output

Print such positive integers a, b and c that four numbers written on a board are values a+b, a+c, b+c and a+b+c written in some order. Print a, b and c in any order. If there are several answers, you can print any. It is guaranteed that the answer exists.

Examples

Input


3 6 5 4


Output


2 1 3


Input


40 40 40 60


Output


20 20 20


Input


201 101 101 200


Output


1 100 100

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  vector<int> secret(4);
  for (int i = 0; i < 4; i++) {
    cin >> secret[i];
  }
  sort(secret.begin(), secret.end());
  int a = secret[3] - secret[1];
  int b = secret[3] - secret[2];
  int c = secret[3] - secret[0];
  printf("%d %d %d\n", a, b, c);
  return 0;
}

```