#include <bits/stdc++.h>
using namespace std;
vector<pair<long long, long long> > ans;
int main() {
  ios::sync_with_stdio(false);
  cin.tie(0);
  cout.tie(0);
  long long x;
  cin >> x;
  x *= 6;
  long long i, temp;
  for (i = 1; i * i * i <= x; i++) {
    temp = i * (i + 1);
    if (x % temp == 0) {
      temp = x / temp;
      temp = temp + i - 1;
      if (temp % 3 == 0) {
        temp /= 3;
        if (temp > i) {
          ans.push_back(make_pair(i, temp));
          ans.push_back(make_pair(temp, i));
        } else if (temp == i)
          ans.push_back(make_pair(i, temp));
      }
    }
  }
  sort(ans.begin(), ans.end());
  cout << ans.size() << "\n";
  for (i = 0; i < ans.size(); i++)
    cout << ans[i].first << " " << ans[i].second << "\n";
}

### Prompt

Construct a cpp code solution to the problem outlined:

Spongebob is already tired trying to reason his weird actions and calculations, so he simply asked you to find all pairs of n and m, such that there are exactly x distinct squares in the table consisting of n rows and m columns. For example, in a 3 × 5 table there are 15 squares with side one, 8 squares with side two and 3 squares with side three. The total number of distinct squares in a 3 × 5 table is 15 + 8 + 3 = 26.

Input

The first line of the input contains a single integer x (1 ≤ x ≤ 1018) — the number of squares inside the tables Spongebob is interested in.

Output

First print a single integer k — the number of tables with exactly x distinct squares inside.

Then print k pairs of integers describing the tables. Print the pairs in the order of increasing n, and in case of equality — in the order of increasing m.

Examples

Input

26


Output

6
1 26
2 9
3 5
5 3
9 2
26 1


Input

2


Output

2
1 2
2 1


Input

8


Output

4
1 8
2 3
3 2
8 1

Note

In a 1 × 2 table there are 2 1 × 1 squares. So, 2 distinct squares in total.

<image>

In a 2 × 3 table there are 6 1 × 1 squares and 2 2 × 2 squares. That is equal to 8 squares in total.

<image>

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
vector<pair<long long, long long> > ans;
int main() {
  ios::sync_with_stdio(false);
  cin.tie(0);
  cout.tie(0);
  long long x;
  cin >> x;
  x *= 6;
  long long i, temp;
  for (i = 1; i * i * i <= x; i++) {
    temp = i * (i + 1);
    if (x % temp == 0) {
      temp = x / temp;
      temp = temp + i - 1;
      if (temp % 3 == 0) {
        temp /= 3;
        if (temp > i) {
          ans.push_back(make_pair(i, temp));
          ans.push_back(make_pair(temp, i));
        } else if (temp == i)
          ans.push_back(make_pair(i, temp));
      }
    }
  }
  sort(ans.begin(), ans.end());
  cout << ans.size() << "\n";
  for (i = 0; i < ans.size(); i++)
    cout << ans[i].first << " " << ans[i].second << "\n";
}

```