//37
#include<iostream>
#include<vector>

using namespace std;

int main(){
  int cmp[1121]={};
  vector<int> prm;
  for(int i=2;i<=1120;i++){
    if(!cmp[i]){
      prm.push_back(i);
      for(int j=2;i*j<=1120;j++){
	cmp[i*j]=true;
      }
    }
  }
  static int dp[1121][200][15];
  dp[0][0][0]=1;
  for(int i=0;i<1121;i++){
    for(int j=0;j<=prm.size();j++){
      for(int l=j+1;l<=prm.size();l++){
	for(int k=0;k<14;k++){
	  if(i+prm[l-1]<=1120){
	    dp[i+prm[l-1]][l][k+1]+=dp[i][j][k];
	  }
	}
      }
    }
  }
  for(int n,k;cin>>n>>k,n|k;){
    int a=0;
    for(int i=0;i<=prm.size();i++){
      a+=dp[n][i][k];
    }
    cout<<a<<endl;
  }
  return 0;
}
### Prompt

Construct a CPP code solution to the problem outlined:

A positive integer may be expressed as a sum of different prime numbers (primes), in one way or another. Given two positive integers n and k, you should count the number of ways to express n as a sum of k different primes. Here, two ways are considered to be the same if they sum up the same set of the primes. For example, 8 can be expressed as 3 + 5 and 5+ 3 but they are not distinguished.

When n and k are 24 and 3 respectively, the answer is two because there are two sets {2, 3, 19} and {2, 5, 17} whose sums are equal to 24. There are no other sets of three primes that sum up to 24. For n = 24 and k = 2, the answer is three, because there are three sets {5, 19}, {7,17} and {11, 13}. For n = 2 and k = 1, the answer is one, because there is only one set {2} whose sum is 2. For n = 1 and k = 1, the answer is zero. As 1 is not a prime, you shouldn't count {1}. For n = 4 and k = 2, the answer is zero, because there are no sets of two diffrent primes whose sums are 4.

Your job is to write a program that reports the number of such ways for the given n and k.



Input

The input is a sequence of datasets followed by a line containing two zeros separated by a space. A dataset is a line containing two positive integers n and k separated by a space. You may assume that n ≤ 1120 and k ≤ 14.

Output

The output should be composed of lines, each corresponding to an input dataset. An output line should contain one non-negative integer indicating the number of ways for n and k specified in the corresponding dataset. You may assume that it is less than 231.

Example

Input

24 3
24 2
2 1
1 1
4 2
18 3
17 1
17 3
17 4
100 5
1000 10
1120 14
0 0


Output

2
3
1
0
0
2
1
0
1
55
200102899
2079324314

### Response

```cpp
//37
#include<iostream>
#include<vector>

using namespace std;

int main(){
  int cmp[1121]={};
  vector<int> prm;
  for(int i=2;i<=1120;i++){
    if(!cmp[i]){
      prm.push_back(i);
      for(int j=2;i*j<=1120;j++){
	cmp[i*j]=true;
      }
    }
  }
  static int dp[1121][200][15];
  dp[0][0][0]=1;
  for(int i=0;i<1121;i++){
    for(int j=0;j<=prm.size();j++){
      for(int l=j+1;l<=prm.size();l++){
	for(int k=0;k<14;k++){
	  if(i+prm[l-1]<=1120){
	    dp[i+prm[l-1]][l][k+1]+=dp[i][j][k];
	  }
	}
      }
    }
  }
  for(int n,k;cin>>n>>k,n|k;){
    int a=0;
    for(int i=0;i<=prm.size();i++){
      a+=dp[n][i][k];
    }
    cout<<a<<endl;
  }
  return 0;
}
```