//misosoupさんの写経
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
#define rep(i,a) for(int i = 0 ; i<(a) ; i++)
const ll MOD = 1e9 +7;

int color[101010]; 
vector<vector<pair<int,int>>> G(101010);//辺と辺の長さ

void solve(int v,int P, int c){//頂点、P、色
	color[v] = c;
	for(auto p:G[v]){
		if(p.first == P) continue;
		solve(p.first,v,(c+p.second)%2);
	}
}

int main(){
	int N; 
	cin >> N; 
	rep(i,N-1){
		int a,b,w;
		cin >> a>>b>>w;
		a--;b--;
		G[a].push_back({b,w});
		G[b].push_back({a,w});
	}
	solve(0,-1,0);
	rep(i,N) cout << color[i] << endl;
	return 0 ;
}

### Prompt

Construct a Cpp code solution to the problem outlined:

We have a tree with N vertices numbered 1 to N. The i-th edge in the tree connects Vertex u_i and Vertex v_i, and its length is w_i. Your objective is to paint each vertex in the tree white or black (it is fine to paint all vertices the same color) so that the following condition is satisfied:

* For any two vertices painted in the same color, the distance between them is an even number.



Find a coloring of the vertices that satisfies the condition and print it. It can be proved that at least one such coloring exists under the constraints of this problem.

Constraints

* All values in input are integers.
* 1 \leq N \leq 10^5
* 1 \leq u_i < v_i \leq N
* 1 \leq w_i \leq 10^9

Input

Input is given from Standard Input in the following format:


N
u_1 v_1 w_1
u_2 v_2 w_2
.
.
.
u_{N - 1} v_{N - 1} w_{N - 1}


Output

Print a coloring of the vertices that satisfies the condition, in N lines. The i-th line should contain `0` if Vertex i is painted white and `1` if it is painted black.

If there are multiple colorings that satisfy the condition, any of them will be accepted.

Examples

Input

3
1 2 2
2 3 1


Output

0
0
1


Input

5
2 5 2
2 3 10
1 3 8
3 4 2


Output

1
0
1
0
1

### Response

```cpp
//misosoupさんの写経
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
#define rep(i,a) for(int i = 0 ; i<(a) ; i++)
const ll MOD = 1e9 +7;

int color[101010]; 
vector<vector<pair<int,int>>> G(101010);//辺と辺の長さ

void solve(int v,int P, int c){//頂点、P、色
	color[v] = c;
	for(auto p:G[v]){
		if(p.first == P) continue;
		solve(p.first,v,(c+p.second)%2);
	}
}

int main(){
	int N; 
	cin >> N; 
	rep(i,N-1){
		int a,b,w;
		cin >> a>>b>>w;
		a--;b--;
		G[a].push_back({b,w});
		G[b].push_back({a,w});
	}
	solve(0,-1,0);
	rep(i,N) cout << color[i] << endl;
	return 0 ;
}

```