#include <bits/stdc++.h>
using namespace std;
int main() {
  int n, center;
  cin >> n;
  center = n / 2;
  for (int row = 0; row < n; row++) {
    for (int col = 0; col < n; col++) {
      if (col >= center - row && col <= center + row) {
        cout << "D";
      } else if (col < center - row || col > center + row) {
        cout << "*";
      }
    }
    cout << endl;
    if (row == center) break;
  }
  for (int row = center - 1; row >= 0; row--) {
    for (int col = 0; col < n; col++) {
      if (col >= (center - row) && col <= (center + row)) {
        cout << "D";
      } else {
        cout << "*";
      }
    }
    cout << endl;
  }
  return 0;
}

### Prompt

Your task is to create a Cpp solution to the following problem:

Twilight Sparkle once got a crystal from the Crystal Mine. A crystal of size n (n is odd; n > 1) is an n × n matrix with a diamond inscribed into it.

You are given an odd integer n. You need to draw a crystal of size n. The diamond cells of the matrix should be represented by character "D". All other cells of the matrix should be represented by character "*". Look at the examples to understand what you need to draw.

Input

The only line contains an integer n (3 ≤ n ≤ 101; n is odd). 

Output

Output a crystal of size n.

Examples

Input

3


Output

*D*
DDD
*D*


Input

5


Output

**D**
*DDD*
DDDDD
*DDD*
**D**


Input

7


Output

***D***
**DDD**
*DDDDD*
DDDDDDD
*DDDDD*
**DDD**
***D***

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  int n, center;
  cin >> n;
  center = n / 2;
  for (int row = 0; row < n; row++) {
    for (int col = 0; col < n; col++) {
      if (col >= center - row && col <= center + row) {
        cout << "D";
      } else if (col < center - row || col > center + row) {
        cout << "*";
      }
    }
    cout << endl;
    if (row == center) break;
  }
  for (int row = center - 1; row >= 0; row--) {
    for (int col = 0; col < n; col++) {
      if (col >= (center - row) && col <= (center + row)) {
        cout << "D";
      } else {
        cout << "*";
      }
    }
    cout << endl;
  }
  return 0;
}

```