#include <bits/stdc++.h>
using namespace std;

int main(){ 
	int x,n,a,d = 0;
	map<int,bool> ok;
	cin >> x >> n;
	for(int i = 1;i <= n;++i){
		cin >> a;
		ok[a] = 1;
	}

	while(1){
		if(!ok[x-d]){
			cout << x-d;
			break;
		}
		if(!ok[x+d]){
			cout << x+d;
			break;
		}
		d++;
	}
}
### Prompt

Generate a Cpp solution to the following problem:

Given are an integer X and an integer sequence of length N: p_1, \ldots, p_N.

Among the integers not contained in the sequence p_1, \ldots, p_N (not necessarily positive), find the integer nearest to X, that is, find the integer whose absolute difference with X is the minimum. If there are multiple such integers, report the smallest such integer.

Constraints

* 1 \leq X \leq 100
* 0 \leq N \leq 100
* 1 \leq p_i \leq 100
* p_1, \ldots, p_N are all distinct.
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


X N
p_1 ... p_N


Output

Print the answer.

Examples

Input

6 5
4 7 10 6 5


Output

8


Input

10 5
4 7 10 6 5


Output

9


Input

100 0


Output

100

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;

int main(){ 
	int x,n,a,d = 0;
	map<int,bool> ok;
	cin >> x >> n;
	for(int i = 1;i <= n;++i){
		cin >> a;
		ok[a] = 1;
	}

	while(1){
		if(!ok[x-d]){
			cout << x-d;
			break;
		}
		if(!ok[x+d]){
			cout << x+d;
			break;
		}
		d++;
	}
}
```