#include<cstdio>
#define SQ(x) ((x)*(x))
int x1, y1, x2, y2;
void solve(int x, int y){
	const int x2m1 = x2 - x1;
	const int y2m1 = y2 - y1;
	int xm1 = x-x1;
	int ym1 = y-y1;
	int x2m = x2-x;
	int y2m = y2-y;
	double temp1 = SQ(xm1)+SQ(ym1)+SQ(x2m1)+SQ(y2m1)-SQ(x2m)-SQ(y2m);
	double temp2 = SQ(x2m1)*2+SQ(y2m1)*2;
	double res = temp1/temp2;
	double xMid = x2m1*res+x1, yMid = y2m1*res+y1;
	printf("%.10f %.10f\n", 2*xMid-x, 2*yMid-y);
}
int main(){
	int x, y, q;
	scanf("%d%d%d%d%d", &x1, &y1, &x2, &y2, &q);
	while(q--){
		scanf("%d%d", &x,&y);
		solve(x, y);
	}
}

### Prompt

Your challenge is to write a CPP solution to the following problem:

For given three points p1, p2, p, find the reflection point x of p onto p1p2.

<image>

Constraints

* 1 ≤ q ≤ 1000
* -10000 ≤ xi, yi ≤ 10000
* p1 and p2 are not identical.

Input


xp1 yp1 xp2 yp2
q
xp0 yp0
xp1 yp1
...
xpq−1 ypq−1


In the first line, integer coordinates of p1 and p2 are given. Then, q queries are given for integer coordinates of p.

Output

For each query, print the coordinate of the reflection point x. The output values should be in a decimal fraction with an error less than 0.00000001.

Examples

Input

0 0 2 0
3
-1 1
0 1
1 1


Output

-1.0000000000 -1.0000000000
0.0000000000 -1.0000000000
1.0000000000 -1.0000000000


Input

0 0 3 4
3
2 5
1 4
0 3


Output

4.2400000000 3.3200000000
3.5600000000 2.0800000000
2.8800000000 0.8400000000

### Response

```cpp
#include<cstdio>
#define SQ(x) ((x)*(x))
int x1, y1, x2, y2;
void solve(int x, int y){
	const int x2m1 = x2 - x1;
	const int y2m1 = y2 - y1;
	int xm1 = x-x1;
	int ym1 = y-y1;
	int x2m = x2-x;
	int y2m = y2-y;
	double temp1 = SQ(xm1)+SQ(ym1)+SQ(x2m1)+SQ(y2m1)-SQ(x2m)-SQ(y2m);
	double temp2 = SQ(x2m1)*2+SQ(y2m1)*2;
	double res = temp1/temp2;
	double xMid = x2m1*res+x1, yMid = y2m1*res+y1;
	printf("%.10f %.10f\n", 2*xMid-x, 2*yMid-y);
}
int main(){
	int x, y, q;
	scanf("%d%d%d%d%d", &x1, &y1, &x2, &y2, &q);
	while(q--){
		scanf("%d%d", &x,&y);
		solve(x, y);
	}
}

```