#include <bits/stdc++.h>
using namespace std;
int main() {
  int num, a = 1, b, j;
  cin >> num;
  b = num / 2;
  bool ana = true;
  for (int i = 0; i < num; i++) {
    for (j = 0; j < b; j++) cout << "*";
    for (j = 0; j < a; j++) cout << "D";
    for (j = 0; j < b; j++) cout << "*";
    if (a == num) ana = false;
    if (a < num && ana) {
      a += 2;
      b--;
    } else {
      a -= 2;
      b++;
    }
    cout << endl;
  }
  return 0;
}

### Prompt

Please provide a cpp coded solution to the problem described below:

Twilight Sparkle once got a crystal from the Crystal Mine. A crystal of size n (n is odd; n > 1) is an n × n matrix with a diamond inscribed into it.

You are given an odd integer n. You need to draw a crystal of size n. The diamond cells of the matrix should be represented by character "D". All other cells of the matrix should be represented by character "*". Look at the examples to understand what you need to draw.

Input

The only line contains an integer n (3 ≤ n ≤ 101; n is odd). 

Output

Output a crystal of size n.

Examples

Input

3


Output

*D*
DDD
*D*


Input

5


Output

**D**
*DDD*
DDDDD
*DDD*
**D**


Input

7


Output

***D***
**DDD**
*DDDDD*
DDDDDDD
*DDDDD*
**DDD**
***D***

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  int num, a = 1, b, j;
  cin >> num;
  b = num / 2;
  bool ana = true;
  for (int i = 0; i < num; i++) {
    for (j = 0; j < b; j++) cout << "*";
    for (j = 0; j < a; j++) cout << "D";
    for (j = 0; j < b; j++) cout << "*";
    if (a == num) ana = false;
    if (a < num && ana) {
      a += 2;
      b--;
    } else {
      a -= 2;
      b++;
    }
    cout << endl;
  }
  return 0;
}

```