#include <bits/stdc++.h>
using namespace std;

int main(){
 int X,Y;
  cin>>X>>Y;
  if(Y%2==0&&X<=Y/2&&Y<=4*X)
    cout<<"Yes"<<endl;
  else
    cout<<"No"<<endl;
}
### Prompt

Please provide a CPP coded solution to the problem described below:

There are some animals in a garden. Each of them is a crane with two legs or a turtle with four legs.

Takahashi says: "there are X animals in total in the garden, and they have Y legs in total." Determine whether there is a combination of numbers of cranes and turtles in which this statement is correct.

Constraints

* 1 \leq X \leq 100
* 1 \leq Y \leq 100
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


X Y


Output

If there is a combination of numbers of cranes and turtles in which the statement is correct, print `Yes`; otherwise, print `No`.

Examples

Input

3 8


Output

Yes


Input

2 100


Output

No


Input

1 2


Output

Yes

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;

int main(){
 int X,Y;
  cin>>X>>Y;
  if(Y%2==0&&X<=Y/2&&Y<=4*X)
    cout<<"Yes"<<endl;
  else
    cout<<"No"<<endl;
}
```