#include <bits/stdc++.h>
using namespace std;
#define rep(i,n) for(int i=0;i<n;++i)

int main(){
    int n,A,B,C; cin >> n >> A >> B >> C;
    map<char,int> mp;
    mp['A'] = A; mp['B'] = B; mp['C'] = C;
    vector<char> ans(n);
    vector<string> sn(n);
    rep(i,n) cin >> sn[i];
    rep(i,n){
        string s = sn[i];
        char s0 = s[0];
        char s1 = s[1];

        if(mp[s0]==0 && mp[s1]==0){
            cout << "No" << endl;
            return 0;;
        }
        else if(mp[s0]==0){
            mp[s0]++; mp[s1]--;
            ans[i] = s0;
        }
        else if(mp[s1]==0){
            mp[s1]++; mp[s0]--;
            ans[i] = s1;
        }
        else if(i==n-1){
            ans[i] = s0;
        }
        else if(sn[i+1][0]==s0 || sn[i+1][1]==s0){
            mp[s0]++; mp[s1]--;
            ans[i] = s0;
        }
        else{
            mp[s0]--; mp[s1]++;
            ans[i] = s1;
        }
    }
    cout << "Yes" << endl;
    rep(i,n) cout << ans[i] << endl;
    return 0;
}

### Prompt

Please formulate a cpp solution to the following problem:

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
#define rep(i,n) for(int i=0;i<n;++i)

int main(){
    int n,A,B,C; cin >> n >> A >> B >> C;
    map<char,int> mp;
    mp['A'] = A; mp['B'] = B; mp['C'] = C;
    vector<char> ans(n);
    vector<string> sn(n);
    rep(i,n) cin >> sn[i];
    rep(i,n){
        string s = sn[i];
        char s0 = s[0];
        char s1 = s[1];

        if(mp[s0]==0 && mp[s1]==0){
            cout << "No" << endl;
            return 0;;
        }
        else if(mp[s0]==0){
            mp[s0]++; mp[s1]--;
            ans[i] = s0;
        }
        else if(mp[s1]==0){
            mp[s1]++; mp[s0]--;
            ans[i] = s1;
        }
        else if(i==n-1){
            ans[i] = s0;
        }
        else if(sn[i+1][0]==s0 || sn[i+1][1]==s0){
            mp[s0]++; mp[s1]--;
            ans[i] = s0;
        }
        else{
            mp[s0]--; mp[s1]++;
            ans[i] = s1;
        }
    }
    cout << "Yes" << endl;
    rep(i,n) cout << ans[i] << endl;
    return 0;
}

```