#include<bits/stdc++.h>
#define rep(i, n) for (int i = 0; i < (n); i++)
#define P pair<int, int>
using namespace std;

int n;
vector<vector<P>> G;
vector<int> ans;

void dfs(int v, int p, int c) {
  ans[v]=c;
  for (auto nv : G[v]) {
    if (nv.first==p) continue;
    if (nv.second & 1) dfs(nv.first, v, 1-c);
    else dfs(nv.first, v, c);
  }
}

int main() {
  cin>>n;
  G.assign(n, vector<P>());
  rep(i, n-1) {
    int a,b,c; cin>>a>>b>>c;
    a--; b--;
    G[a].push_back(P(b, c));
    G[b].push_back(P(a, c));
  }
  ans.assign(n, 0);
  dfs(0, -1, 1);
  rep(i, n) cout<<ans[i]<<endl;
  return 0;
}

### Prompt

In CPP, your task is to solve the following problem:

We have a tree with N vertices numbered 1 to N. The i-th edge in the tree connects Vertex u_i and Vertex v_i, and its length is w_i. Your objective is to paint each vertex in the tree white or black (it is fine to paint all vertices the same color) so that the following condition is satisfied:

* For any two vertices painted in the same color, the distance between them is an even number.



Find a coloring of the vertices that satisfies the condition and print it. It can be proved that at least one such coloring exists under the constraints of this problem.

Constraints

* All values in input are integers.
* 1 \leq N \leq 10^5
* 1 \leq u_i < v_i \leq N
* 1 \leq w_i \leq 10^9

Input

Input is given from Standard Input in the following format:


N
u_1 v_1 w_1
u_2 v_2 w_2
.
.
.
u_{N - 1} v_{N - 1} w_{N - 1}


Output

Print a coloring of the vertices that satisfies the condition, in N lines. The i-th line should contain `0` if Vertex i is painted white and `1` if it is painted black.

If there are multiple colorings that satisfy the condition, any of them will be accepted.

Examples

Input

3
1 2 2
2 3 1


Output

0
0
1


Input

5
2 5 2
2 3 10
1 3 8
3 4 2


Output

1
0
1
0
1

### Response

```cpp
#include<bits/stdc++.h>
#define rep(i, n) for (int i = 0; i < (n); i++)
#define P pair<int, int>
using namespace std;

int n;
vector<vector<P>> G;
vector<int> ans;

void dfs(int v, int p, int c) {
  ans[v]=c;
  for (auto nv : G[v]) {
    if (nv.first==p) continue;
    if (nv.second & 1) dfs(nv.first, v, 1-c);
    else dfs(nv.first, v, c);
  }
}

int main() {
  cin>>n;
  G.assign(n, vector<P>());
  rep(i, n-1) {
    int a,b,c; cin>>a>>b>>c;
    a--; b--;
    G[a].push_back(P(b, c));
    G[b].push_back(P(a, c));
  }
  ans.assign(n, 0);
  dfs(0, -1, 1);
  rep(i, n) cout<<ans[i]<<endl;
  return 0;
}

```