#include <bits/stdc++.h>
using namespace std;
template <class T>
inline bool fs(T &x) {
  int c = getchar();
  int sgn = 1;
  while (~c && c < '0' || c > '9') {
    if (c == '-') sgn = -1;
    c = getchar();
  }
  for (x = 0; ~c && '0' <= c && c <= '9'; c = getchar()) x = x * 10 + c - '0';
  x *= sgn;
  return ~c;
}
int main() {
  long long int n, m, cnt = 0;
  fs(n);
  fs(m);
  for (long long int i = 1; i * i <= m; i++) {
    if (m % i == 0 && m / i <= n) {
      if (m / i != i) cnt++;
      cnt++;
    }
  }
  cout << cnt << endl;
  return 0;
}

### Prompt

Please create a solution in CPP to the following problem:

Let's consider a table consisting of n rows and n columns. The cell located at the intersection of i-th row and j-th column contains number i × j. The rows and columns are numbered starting from 1.

You are given a positive integer x. Your task is to count the number of cells in a table that contain number x.

Input

The single line contains numbers n and x (1 ≤ n ≤ 105, 1 ≤ x ≤ 109) — the size of the table and the number that we are looking for in the table.

Output

Print a single number: the number of times x occurs in the table.

Examples

Input

10 5


Output

2


Input

6 12


Output

4


Input

5 13


Output

0

Note

A table for the second sample test is given below. The occurrences of number 12 are marked bold. 

<image>

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
template <class T>
inline bool fs(T &x) {
  int c = getchar();
  int sgn = 1;
  while (~c && c < '0' || c > '9') {
    if (c == '-') sgn = -1;
    c = getchar();
  }
  for (x = 0; ~c && '0' <= c && c <= '9'; c = getchar()) x = x * 10 + c - '0';
  x *= sgn;
  return ~c;
}
int main() {
  long long int n, m, cnt = 0;
  fs(n);
  fs(m);
  for (long long int i = 1; i * i <= m; i++) {
    if (m % i == 0 && m / i <= n) {
      if (m / i != i) cnt++;
      cnt++;
    }
  }
  cout << cnt << endl;
  return 0;
}

```