#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using P = pair<int,int>;

vector<vector<P>> g;
vector<int> col;

void dfs(int a, int b, int c){
  col[a] = c;
  for(auto v: g[a]){
    if(col[v.first] != -1) continue;
    if(v.second % 2 == 0) dfs(v.first,a,c);
    else dfs(v.first,a,1-c);
  }
}


int main(){
  int N; cin >> N;
  g.resize(N);
  col.assign(N,-1);
  for(int i = 0; i < N-1; i++){
    int a,b,c; cin >> a >> b >> c;
    a--; b--;
    g[a].push_back(P(b,c));
    g[b].push_back(P(a,c));
  }
  dfs(0,-1,1);
  for(auto v: col){
    cout << v << endl;
  }
  return 0;
}
### Prompt

Create a solution in Cpp for the following problem:

We have a tree with N vertices numbered 1 to N. The i-th edge in the tree connects Vertex u_i and Vertex v_i, and its length is w_i. Your objective is to paint each vertex in the tree white or black (it is fine to paint all vertices the same color) so that the following condition is satisfied:

* For any two vertices painted in the same color, the distance between them is an even number.



Find a coloring of the vertices that satisfies the condition and print it. It can be proved that at least one such coloring exists under the constraints of this problem.

Constraints

* All values in input are integers.
* 1 \leq N \leq 10^5
* 1 \leq u_i < v_i \leq N
* 1 \leq w_i \leq 10^9

Input

Input is given from Standard Input in the following format:


N
u_1 v_1 w_1
u_2 v_2 w_2
.
.
.
u_{N - 1} v_{N - 1} w_{N - 1}


Output

Print a coloring of the vertices that satisfies the condition, in N lines. The i-th line should contain `0` if Vertex i is painted white and `1` if it is painted black.

If there are multiple colorings that satisfy the condition, any of them will be accepted.

Examples

Input

3
1 2 2
2 3 1


Output

0
0
1


Input

5
2 5 2
2 3 10
1 3 8
3 4 2


Output

1
0
1
0
1

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using P = pair<int,int>;

vector<vector<P>> g;
vector<int> col;

void dfs(int a, int b, int c){
  col[a] = c;
  for(auto v: g[a]){
    if(col[v.first] != -1) continue;
    if(v.second % 2 == 0) dfs(v.first,a,c);
    else dfs(v.first,a,1-c);
  }
}


int main(){
  int N; cin >> N;
  g.resize(N);
  col.assign(N,-1);
  for(int i = 0; i < N-1; i++){
    int a,b,c; cin >> a >> b >> c;
    a--; b--;
    g[a].push_back(P(b,c));
    g[b].push_back(P(a,c));
  }
  dfs(0,-1,1);
  for(auto v: col){
    cout << v << endl;
  }
  return 0;
}
```