#include <bits/stdc++.h>
using namespace std;
const int N = 101;
const int MOD = 1000000007;
int main() {
  ios::sync_with_stdio(false);
  cin.tie(NULL);
  int n;
  cin >> n;
  int stars = n - 1;
  bool finished = false;
  for (int i = 0; i < n; ++i) {
    int cnt = n;
    for (int j = 0; j < stars / 2; ++j) {
      cout << "*";
      cnt--;
    }
    cnt -= stars / 2;
    for (int j = 0; j < cnt; ++j) {
      cout << "D";
    }
    for (int j = 0; j < stars / 2; ++j) {
      cout << "*";
    }
    cout << "\n";
    if (stars - 2 == 0 and !finished) {
      finished = true;
      stars -= 2;
      continue;
    }
    if (finished) {
      stars += 2;
    } else {
      stars -= 2;
    }
  }
  cout << "\n";
  return 0;
}

### Prompt

Please create a solution in cpp to the following problem:

Twilight Sparkle once got a crystal from the Crystal Mine. A crystal of size n (n is odd; n > 1) is an n × n matrix with a diamond inscribed into it.

You are given an odd integer n. You need to draw a crystal of size n. The diamond cells of the matrix should be represented by character "D". All other cells of the matrix should be represented by character "*". Look at the examples to understand what you need to draw.

Input

The only line contains an integer n (3 ≤ n ≤ 101; n is odd). 

Output

Output a crystal of size n.

Examples

Input

3


Output

*D*
DDD
*D*


Input

5


Output

**D**
*DDD*
DDDDD
*DDD*
**D**


Input

7


Output

***D***
**DDD**
*DDDDD*
DDDDDDD
*DDDDD*
**DDD**
***D***

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
const int N = 101;
const int MOD = 1000000007;
int main() {
  ios::sync_with_stdio(false);
  cin.tie(NULL);
  int n;
  cin >> n;
  int stars = n - 1;
  bool finished = false;
  for (int i = 0; i < n; ++i) {
    int cnt = n;
    for (int j = 0; j < stars / 2; ++j) {
      cout << "*";
      cnt--;
    }
    cnt -= stars / 2;
    for (int j = 0; j < cnt; ++j) {
      cout << "D";
    }
    for (int j = 0; j < stars / 2; ++j) {
      cout << "*";
    }
    cout << "\n";
    if (stars - 2 == 0 and !finished) {
      finished = true;
      stars -= 2;
      continue;
    }
    if (finished) {
      stars += 2;
    } else {
      stars -= 2;
    }
  }
  cout << "\n";
  return 0;
}

```