
//be naame khodaa
#include <bits/stdc++.h>
using namespace std;

typedef long long ll;
typedef long double ld;
typedef pair <int, int> pii;
#define F first
#define S second

inline int in(){int x, y; y = scanf("%d", &x); return x; }

const int N = -1;

struct PT{
	ld x, y;
	PT (ld x = 0, ld y = 0) : x(x), y(y) {}
	PT operator + (PT ro) const{
		return PT(x+ro.x, y+ro.y);
	}
	PT operator - (PT ro) const{
		return PT(x-ro.x, y-ro.y);
	}
	PT operator * (ld co) const{
		return PT(x*co, y*co);
	}
	PT operator / (ld co) const{
		return PT(x/co, y/co);
	}
	ld operator * (PT ro) const{
		return x*ro.x + y*ro.y;
	}
	ld operator ^ (PT ro) const{
		return x*ro.y - y*ro.x;
	}
};

PT operator * (ld co, PT p){
	return p*co;
}

ld len(PT a){
	return sqrt(a*a);
}

PT unit(PT a){
	return a/len(a);
}

PT perp(PT a){
	return PT(-a.y, a.x);
}

PT proj(PT a, PT b, PT c){
	b = b-a, c = c-a;
	return a + (b*c)/(b*b)*b;
}

PT reflect(PT a, PT b, PT c){
	PT d = c;
	b = b-a, c = c-a;
	return d + (c^b)/len(b)*perp(unit(b))*2;
}

int main(){
	PT a, b;;
	cin >> a.x >> a.y >> b.x >> b.y;
	PT p;
	cout << setprecision(10) << fixed;
	for (int i = in(); i; i--){
		cin >> p.x >> p.y;
		PT img = reflect(a, b, p);
		cout << img.x << ' ' << img.y << '\n';
	}
	return 0;
}

### Prompt

In Cpp, your task is to solve the following problem:

For given three points p1, p2, p, find the reflection point x of p onto p1p2.

<image>

Constraints

* 1 ≤ q ≤ 1000
* -10000 ≤ xi, yi ≤ 10000
* p1 and p2 are not identical.

Input


xp1 yp1 xp2 yp2
q
xp0 yp0
xp1 yp1
...
xpq−1 ypq−1


In the first line, integer coordinates of p1 and p2 are given. Then, q queries are given for integer coordinates of p.

Output

For each query, print the coordinate of the reflection point x. The output values should be in a decimal fraction with an error less than 0.00000001.

Examples

Input

0 0 2 0
3
-1 1
0 1
1 1


Output

-1.0000000000 -1.0000000000
0.0000000000 -1.0000000000
1.0000000000 -1.0000000000


Input

0 0 3 4
3
2 5
1 4
0 3


Output

4.2400000000 3.3200000000
3.5600000000 2.0800000000
2.8800000000 0.8400000000

### Response

```cpp

//be naame khodaa
#include <bits/stdc++.h>
using namespace std;

typedef long long ll;
typedef long double ld;
typedef pair <int, int> pii;
#define F first
#define S second

inline int in(){int x, y; y = scanf("%d", &x); return x; }

const int N = -1;

struct PT{
	ld x, y;
	PT (ld x = 0, ld y = 0) : x(x), y(y) {}
	PT operator + (PT ro) const{
		return PT(x+ro.x, y+ro.y);
	}
	PT operator - (PT ro) const{
		return PT(x-ro.x, y-ro.y);
	}
	PT operator * (ld co) const{
		return PT(x*co, y*co);
	}
	PT operator / (ld co) const{
		return PT(x/co, y/co);
	}
	ld operator * (PT ro) const{
		return x*ro.x + y*ro.y;
	}
	ld operator ^ (PT ro) const{
		return x*ro.y - y*ro.x;
	}
};

PT operator * (ld co, PT p){
	return p*co;
}

ld len(PT a){
	return sqrt(a*a);
}

PT unit(PT a){
	return a/len(a);
}

PT perp(PT a){
	return PT(-a.y, a.x);
}

PT proj(PT a, PT b, PT c){
	b = b-a, c = c-a;
	return a + (b*c)/(b*b)*b;
}

PT reflect(PT a, PT b, PT c){
	PT d = c;
	b = b-a, c = c-a;
	return d + (c^b)/len(b)*perp(unit(b))*2;
}

int main(){
	PT a, b;;
	cin >> a.x >> a.y >> b.x >> b.y;
	PT p;
	cout << setprecision(10) << fixed;
	for (int i = in(); i; i--){
		cin >> p.x >> p.y;
		PT img = reflect(a, b, p);
		cout << img.x << ' ' << img.y << '\n';
	}
	return 0;
}

```