#include<stdio.h>
#include<math.h>

using namespace std;

int main(){
    const double dTolerance = 1.0e-10;
    double x1, x2, y1, y2;
    scanf("%lf %lf %lf %lf", &x1, &y1, &x2, &y2);
    int q;
    scanf("%d", &q);
    
    for (int i = 0; i < q; i++){
        double x, y;
        scanf("%lf %lf", &x, &y);
        if (fabs(x1 - x2) < dTolerance) {
            printf("%.10lf %.10lf\n", 2 * x1 - x, y);
        } else if (fabs(y1 - y2) < dTolerance){
            printf("%.10lf %.10lf\n", x, 2 * y1 - y);
        } else {
            double dt = ((x2 - x1) * (x2 - x) + (y2 - y1) * (y2 - y)) / ((x2 - x1) * (x2 - x1) + (y2 - y1) * (y2 - y1));
            double ds = ((x2 - x1) * (x - x1) + (y2 - y1) * (y - y1)) / ((x2 - x1) * (x2 - x1) + (y2 - y1) * (y2 - y1));
            printf("%.10lf %.10lf\n", 2 * (dt * x1 + ds * x2) - x, 2 * (dt * y1 + ds * y2) - y);
        }
    }
    return 0;
}

### Prompt

Construct a CPP code solution to the problem outlined:

For given three points p1, p2, p, find the reflection point x of p onto p1p2.

<image>

Constraints

* 1 ≤ q ≤ 1000
* -10000 ≤ xi, yi ≤ 10000
* p1 and p2 are not identical.

Input


xp1 yp1 xp2 yp2
q
xp0 yp0
xp1 yp1
...
xpq−1 ypq−1


In the first line, integer coordinates of p1 and p2 are given. Then, q queries are given for integer coordinates of p.

Output

For each query, print the coordinate of the reflection point x. The output values should be in a decimal fraction with an error less than 0.00000001.

Examples

Input

0 0 2 0
3
-1 1
0 1
1 1


Output

-1.0000000000 -1.0000000000
0.0000000000 -1.0000000000
1.0000000000 -1.0000000000


Input

0 0 3 4
3
2 5
1 4
0 3


Output

4.2400000000 3.3200000000
3.5600000000 2.0800000000
2.8800000000 0.8400000000

### Response

```cpp
#include<stdio.h>
#include<math.h>

using namespace std;

int main(){
    const double dTolerance = 1.0e-10;
    double x1, x2, y1, y2;
    scanf("%lf %lf %lf %lf", &x1, &y1, &x2, &y2);
    int q;
    scanf("%d", &q);
    
    for (int i = 0; i < q; i++){
        double x, y;
        scanf("%lf %lf", &x, &y);
        if (fabs(x1 - x2) < dTolerance) {
            printf("%.10lf %.10lf\n", 2 * x1 - x, y);
        } else if (fabs(y1 - y2) < dTolerance){
            printf("%.10lf %.10lf\n", x, 2 * y1 - y);
        } else {
            double dt = ((x2 - x1) * (x2 - x) + (y2 - y1) * (y2 - y)) / ((x2 - x1) * (x2 - x1) + (y2 - y1) * (y2 - y1));
            double ds = ((x2 - x1) * (x - x1) + (y2 - y1) * (y - y1)) / ((x2 - x1) * (x2 - x1) + (y2 - y1) * (y2 - y1));
            printf("%.10lf %.10lf\n", 2 * (dt * x1 + ds * x2) - x, 2 * (dt * y1 + ds * y2) - y);
        }
    }
    return 0;
}

```