#include <bits/stdc++.h>
using namespace std;
const int MAX = 105;
string s, t;
int main() {
  ios::sync_with_stdio(false);
  for (int i = 0; i < MAX; i++) s += '*', t += 'D';
  int n;
  cin >> n;
  for (int i = 0; i < n / 2; i++)
    cout << s.substr(0, n / 2 - i) << t.substr(0, n - 2 * (n / 2 - i))
         << s.substr(0, n / 2 - i) << endl;
  cout << t.substr(0, n) << endl;
  for (int i = n / 2 - 1; i >= 0; i--)
    cout << s.substr(0, n / 2 - i) << t.substr(0, n - 2 * (n / 2 - i))
         << s.substr(0, n / 2 - i) << endl;
  return 0;
}

### Prompt

In CPP, your task is to solve the following problem:

Twilight Sparkle once got a crystal from the Crystal Mine. A crystal of size n (n is odd; n > 1) is an n × n matrix with a diamond inscribed into it.

You are given an odd integer n. You need to draw a crystal of size n. The diamond cells of the matrix should be represented by character "D". All other cells of the matrix should be represented by character "*". Look at the examples to understand what you need to draw.

Input

The only line contains an integer n (3 ≤ n ≤ 101; n is odd). 

Output

Output a crystal of size n.

Examples

Input

3


Output

*D*
DDD
*D*


Input

5


Output

**D**
*DDD*
DDDDD
*DDD*
**D**


Input

7


Output

***D***
**DDD**
*DDDDD*
DDDDDDD
*DDDDD*
**DDD**
***D***

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
const int MAX = 105;
string s, t;
int main() {
  ios::sync_with_stdio(false);
  for (int i = 0; i < MAX; i++) s += '*', t += 'D';
  int n;
  cin >> n;
  for (int i = 0; i < n / 2; i++)
    cout << s.substr(0, n / 2 - i) << t.substr(0, n - 2 * (n / 2 - i))
         << s.substr(0, n / 2 - i) << endl;
  cout << t.substr(0, n) << endl;
  for (int i = n / 2 - 1; i >= 0; i--)
    cout << s.substr(0, n / 2 - i) << t.substr(0, n - 2 * (n / 2 - i))
         << s.substr(0, n / 2 - i) << endl;
  return 0;
}

```