#include <cstdio>
#include <utility>
#include <vector>
#include <list>
using namespace std;

#define gcu getchar_unlocked
#define pcu putchar_unlocked
#define _il inline
#define _in _il int in
#define _sc _il bool scan
_in(int c){int n=0;bool m=false;if(c=='-')m=true,c=gcu();
	do{n=10*n+(c-'0'),c=gcu();}while(c>='0');return m?-n:n;} //&&c<='9'
_in() {return in(gcu());}
_sc(int &n){int c=gcu();return c==EOF?false:(n=in(c),true);}
_sc(char &c){c=gcu();gcu();return c!=EOF;}
//_sc(string &s){int c;s="";
//	for(;;){c=gcu();if(c=='\n'||c==' ')return true;else if(c==EOF)return false;s+=c;}}
template <typename H,typename... T> _sc(H &h, T&&... t){return scan(h)&&scan(t...);}
#define _vo _il void out
#define _vl _il void outl
template <typename T>
_vo(T n){static char buf[20];char *p=buf;
	if(n<0)pcu('-'),n*=-1;if(!n)*p++='0';else while(n)*p++=n%10+'0',n/=10;
	while (p!=buf)pcu(*--p);}
_vo(const char *s){while(*s)pcu(*s++);}
_vo(char c){pcu(c);}
//_vo(string &s){for (char c: s) pcu(c);}
template <typename H,typename... T> _vo(H&& h, T&&... t){out(h);out(move(t)...);}
template <typename T> _vo(vector<T> &v){for(T &x:v)out(&x == &v[0]?"":" "),out(x);out('\n');}
_vl(){out('\n');}
template <typename... T> _vl(T&&... t){out(move(t)...);outl();}

int main() {
	vector<list<int>> v(in());
	for (int q = in(); q; q--) {
		int o = in();
		auto &t = v[in()];
		switch(o) {
		case 0:
			t.push_back(in());
			break;
		case 1:
			{
				int  i = 0;
				for (int x: t) {
					if (i++)
						out(" ");
					out(x);
				}
				outl();
				break;
			}
		default:
			{
				auto &i = v[in()];
				i.splice(i.end(), move(t));
			}
		}
	}
}


### Prompt

Please provide a Cpp coded solution to the problem described below:

For $n$ lists $L_i$ $(i = 0, 1, ..., n-1)$, perform a sequence of the following operations.

* insert($t$, $x$): Insert an integer $x$ at the end of $L_t$.
* dump($t$): Print all elements in $L_t$.
* splice($s$, $t$): Transfer elements of $L_s$ to the end of $L_t$. $L_s$ becomes empty.



In the initial state, $L_i$ $(i = 0, 1, ..., n-1)$ are empty.

Constraints

* $1 \leq n \leq 1,000$
* $1 \leq q \leq 500,000$
* For a splice operation, $s \ne t$
* For a splice operation, $L_s$ is not empty
* The total number of elements printed by dump operations do not exceed 1,000,000
* $-1,000,000,000 \leq x \leq 1,000,000,000$

Input

The input is given in the following format.


$n \; q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $t$ $x$


or


1 $t$


or


2 $s$ $t$


where the first digits 0, 1 and 2 represent insert, dump and splice operations respectively.

Output

For each dump operation, print elements of the corresponding list in a line. Separete adjacency elements by a space character (do not print the space after the last element). Note that, if the list is empty, an empty line should be printed.

Example

Input

3 10
0 0 1
0 0 2
0 0 3
0 1 4
0 1 5
2 1 0
0 2 6
1 0
1 1
1 2


Output

1 2 3 4 5

6

### Response

```cpp
#include <cstdio>
#include <utility>
#include <vector>
#include <list>
using namespace std;

#define gcu getchar_unlocked
#define pcu putchar_unlocked
#define _il inline
#define _in _il int in
#define _sc _il bool scan
_in(int c){int n=0;bool m=false;if(c=='-')m=true,c=gcu();
	do{n=10*n+(c-'0'),c=gcu();}while(c>='0');return m?-n:n;} //&&c<='9'
_in() {return in(gcu());}
_sc(int &n){int c=gcu();return c==EOF?false:(n=in(c),true);}
_sc(char &c){c=gcu();gcu();return c!=EOF;}
//_sc(string &s){int c;s="";
//	for(;;){c=gcu();if(c=='\n'||c==' ')return true;else if(c==EOF)return false;s+=c;}}
template <typename H,typename... T> _sc(H &h, T&&... t){return scan(h)&&scan(t...);}
#define _vo _il void out
#define _vl _il void outl
template <typename T>
_vo(T n){static char buf[20];char *p=buf;
	if(n<0)pcu('-'),n*=-1;if(!n)*p++='0';else while(n)*p++=n%10+'0',n/=10;
	while (p!=buf)pcu(*--p);}
_vo(const char *s){while(*s)pcu(*s++);}
_vo(char c){pcu(c);}
//_vo(string &s){for (char c: s) pcu(c);}
template <typename H,typename... T> _vo(H&& h, T&&... t){out(h);out(move(t)...);}
template <typename T> _vo(vector<T> &v){for(T &x:v)out(&x == &v[0]?"":" "),out(x);out('\n');}
_vl(){out('\n');}
template <typename... T> _vl(T&&... t){out(move(t)...);outl();}

int main() {
	vector<list<int>> v(in());
	for (int q = in(); q; q--) {
		int o = in();
		auto &t = v[in()];
		switch(o) {
		case 0:
			t.push_back(in());
			break;
		case 1:
			{
				int  i = 0;
				for (int x: t) {
					if (i++)
						out(" ");
					out(x);
				}
				outl();
				break;
			}
		default:
			{
				auto &i = v[in()];
				i.splice(i.end(), move(t));
			}
		}
	}
}


```