#include<bits/stdc++.h>
using namespace std;



 int main()
{
	int x,n;
	cin>>x>>n;
	vector<int> take(102,0);
	
	for(int i=0;i<n;i++){
		int a;
		cin>>a;
		take[a]++;
	}
	int i=x;
	int j=x;
	while(true){
		if(take[j]==0){
			cout<<j;
			return 0;
		}
		if(take[i]==0){
			cout<<i;
			return 0;
		}
		i++;
		j--;
	}
	
}

### Prompt

Construct a Cpp code solution to the problem outlined:

Given are an integer X and an integer sequence of length N: p_1, \ldots, p_N.

Among the integers not contained in the sequence p_1, \ldots, p_N (not necessarily positive), find the integer nearest to X, that is, find the integer whose absolute difference with X is the minimum. If there are multiple such integers, report the smallest such integer.

Constraints

* 1 \leq X \leq 100
* 0 \leq N \leq 100
* 1 \leq p_i \leq 100
* p_1, \ldots, p_N are all distinct.
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


X N
p_1 ... p_N


Output

Print the answer.

Examples

Input

6 5
4 7 10 6 5


Output

8


Input

10 5
4 7 10 6 5


Output

9


Input

100 0


Output

100

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;



 int main()
{
	int x,n;
	cin>>x>>n;
	vector<int> take(102,0);
	
	for(int i=0;i<n;i++){
		int a;
		cin>>a;
		take[a]++;
	}
	int i=x;
	int j=x;
	while(true){
		if(take[j]==0){
			cout<<j;
			return 0;
		}
		if(take[i]==0){
			cout<<i;
			return 0;
		}
		i++;
		j--;
	}
	
}

```