#include <string>
#include <iostream>
#include <stdio.h>
#include <stack>

using namespace std;

int main() {
  ios::sync_with_stdio(false);

  int cmd, index, val;
  int num_stack, num_query;

  cin >> num_stack >> num_query;
  stack<int> st[num_stack];

  for (int i = 0; i < num_query; i++) {
    cin >> cmd;

    switch (cmd) {
      // push
      case 0:
        cin >> index >> val;
        st[index].push(val);

        break;
      // top
      case 1:
        cin >> index;
        if (st[index].empty()) {
          break;
        }
        cout << st[index].top() << endl;
        break;
      // pop
      case 2:
        cin >> index;
        if (st[index].empty()) {
          break;
        }
        st[index].pop();
        break;
    }
  }
}



### Prompt

Generate a CPP solution to the following problem:

Stack is a container of elements that are inserted and deleted according to LIFO (Last In First Out).

For $n$ stack $S_i$ ($i = 0, 1, ..., n-1$), perform a sequence of the following operations.

* push($t$, $x$): Insert an integer $x$ to $S_t$.
* top($t$): Report the value which should be deleted next from $S_t$. If $S_t$ is empty, do nothing.
* pop($t$): Delete an element from $S_t$. If $S_t$ is empty, do nothing.



In the initial state, all stacks are empty.

Constraints

* $1 \leq n \leq 1,000$
* $1 \leq q \leq 200,000$
* $-1,000,000,000 \leq x \leq 1,000,000,000$

Input

The input is given in the following format.


$n \; q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $t$ $x$


or


1 $t$


or


2 $t$


where the first digits 0, 1 and 2 represent push, top and pop operations respectively.

Output

For each top operation, print an integer in a line.

Example

Input

3 9
0 0 1
0 0 2
0 0 3
0 2 4
0 2 5
1 0
1 2
2 0
1 0


Output

3
5
2

### Response

```cpp
#include <string>
#include <iostream>
#include <stdio.h>
#include <stack>

using namespace std;

int main() {
  ios::sync_with_stdio(false);

  int cmd, index, val;
  int num_stack, num_query;

  cin >> num_stack >> num_query;
  stack<int> st[num_stack];

  for (int i = 0; i < num_query; i++) {
    cin >> cmd;

    switch (cmd) {
      // push
      case 0:
        cin >> index >> val;
        st[index].push(val);

        break;
      // top
      case 1:
        cin >> index;
        if (st[index].empty()) {
          break;
        }
        cout << st[index].top() << endl;
        break;
      // pop
      case 2:
        cin >> index;
        if (st[index].empty()) {
          break;
        }
        st[index].pop();
        break;
    }
  }
}



```