#include <bits/stdc++.h>
using namespace std;
template <class T>
inline T bigmod(T p, T e, T M) {
  if (e == 0) return 1;
  if (e % 2 == 0) {
    T t = bigmod(p, e / 2, M);
    return (t * t) % M;
  }
  return (bigmod(p, e - 1, M) * p) % M;
}
template <class T>
inline T gcd(T a, T b) {
  if (b == 0) return a;
  return gcd(b, a % b);
}
template <class T>
inline T modinverse(T a, T M) {
  return bigmod(a, M - 2, M);
}
template <class T>
inline T multimod(T a, T b, T m) {
  T ans = 0ll;
  a %= m, b %= m;
  while (b) {
    if (b & 1ll) ans = m - ans > a ? (ans + a) : (ans + a - m);
    b >>= 1ll;
    a = (m - a) > a ? a + a : a + a - m;
  }
  return (T)ans;
}
int main() {
  int i, j, k;
  int n, m;
  cin >> m >> n;
  int cnt = 0;
  int sq = sqrt(n);
  for (i = 1; i <= sq && i <= m; i++) {
    if (n % i == 0 && n / i <= m) cnt += 2;
    if (i * i == n) cnt--;
  }
  cout << cnt << endl;
  return 0;
}

### Prompt

Your task is to create a CPP solution to the following problem:

Let's consider a table consisting of n rows and n columns. The cell located at the intersection of i-th row and j-th column contains number i × j. The rows and columns are numbered starting from 1.

You are given a positive integer x. Your task is to count the number of cells in a table that contain number x.

Input

The single line contains numbers n and x (1 ≤ n ≤ 105, 1 ≤ x ≤ 109) — the size of the table and the number that we are looking for in the table.

Output

Print a single number: the number of times x occurs in the table.

Examples

Input

10 5


Output

2


Input

6 12


Output

4


Input

5 13


Output

0

Note

A table for the second sample test is given below. The occurrences of number 12 are marked bold. 

<image>

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
template <class T>
inline T bigmod(T p, T e, T M) {
  if (e == 0) return 1;
  if (e % 2 == 0) {
    T t = bigmod(p, e / 2, M);
    return (t * t) % M;
  }
  return (bigmod(p, e - 1, M) * p) % M;
}
template <class T>
inline T gcd(T a, T b) {
  if (b == 0) return a;
  return gcd(b, a % b);
}
template <class T>
inline T modinverse(T a, T M) {
  return bigmod(a, M - 2, M);
}
template <class T>
inline T multimod(T a, T b, T m) {
  T ans = 0ll;
  a %= m, b %= m;
  while (b) {
    if (b & 1ll) ans = m - ans > a ? (ans + a) : (ans + a - m);
    b >>= 1ll;
    a = (m - a) > a ? a + a : a + a - m;
  }
  return (T)ans;
}
int main() {
  int i, j, k;
  int n, m;
  cin >> m >> n;
  int cnt = 0;
  int sq = sqrt(n);
  for (i = 1; i <= sq && i <= m; i++) {
    if (n % i == 0 && n / i <= m) cnt += 2;
    if (i * i == n) cnt--;
  }
  cout << cnt << endl;
  return 0;
}

```