#include<iostream>
#include<algorithm>
#include<vector>
using namespace std;
vector<pair<int,int> >G[1<<17];
int N;
long d[1<<17];
void f(int u,int p,long de)
{
	d[u]=de;
	for(pair<int,int>&q:G[u])
	{
		if(q.first==p)continue;
		f(q.first,u,de+q.second);
	}
}
int main(){
	cin>>N;
	for(int i=1;i<N;i++)
	{
		int a,b,c;
		cin>>a>>b>>c;
		a--,b--;
		G[a].push_back(make_pair(b,c));
		G[b].push_back(make_pair(a,c));
		d[i]=9e18;
	}
	f(0,-1,0);
	for(int i=0;i<N;i++)cout<<d[i]%2<<endl;
}

### Prompt

Develop a solution in Cpp to the problem described below:

We have a tree with N vertices numbered 1 to N. The i-th edge in the tree connects Vertex u_i and Vertex v_i, and its length is w_i. Your objective is to paint each vertex in the tree white or black (it is fine to paint all vertices the same color) so that the following condition is satisfied:

* For any two vertices painted in the same color, the distance between them is an even number.



Find a coloring of the vertices that satisfies the condition and print it. It can be proved that at least one such coloring exists under the constraints of this problem.

Constraints

* All values in input are integers.
* 1 \leq N \leq 10^5
* 1 \leq u_i < v_i \leq N
* 1 \leq w_i \leq 10^9

Input

Input is given from Standard Input in the following format:


N
u_1 v_1 w_1
u_2 v_2 w_2
.
.
.
u_{N - 1} v_{N - 1} w_{N - 1}


Output

Print a coloring of the vertices that satisfies the condition, in N lines. The i-th line should contain `0` if Vertex i is painted white and `1` if it is painted black.

If there are multiple colorings that satisfy the condition, any of them will be accepted.

Examples

Input

3
1 2 2
2 3 1


Output

0
0
1


Input

5
2 5 2
2 3 10
1 3 8
3 4 2


Output

1
0
1
0
1

### Response

```cpp
#include<iostream>
#include<algorithm>
#include<vector>
using namespace std;
vector<pair<int,int> >G[1<<17];
int N;
long d[1<<17];
void f(int u,int p,long de)
{
	d[u]=de;
	for(pair<int,int>&q:G[u])
	{
		if(q.first==p)continue;
		f(q.first,u,de+q.second);
	}
}
int main(){
	cin>>N;
	for(int i=1;i<N;i++)
	{
		int a,b,c;
		cin>>a>>b>>c;
		a--,b--;
		G[a].push_back(make_pair(b,c));
		G[b].push_back(make_pair(a,c));
		d[i]=9e18;
	}
	f(0,-1,0);
	for(int i=0;i<N;i++)cout<<d[i]%2<<endl;
}

```