#include <bits/stdc++.h>
using namespace std;
int main() {
  int n;
  cin >> n;
  vector<string> ans(n, string(n, '.'));
  for (int r = 0; r < (int)(n); ++r)
    for (int c = 0; c < (int)(n); ++c)
      if (abs(c - n / 2) + abs(r - n / 2) > n / 2)
        ans[r][c] = '*';
      else
        ans[r][c] = 'D';
  for (string s : ans) cout << s << endl;
}

### Prompt

In CPP, your task is to solve the following problem:

Twilight Sparkle once got a crystal from the Crystal Mine. A crystal of size n (n is odd; n > 1) is an n × n matrix with a diamond inscribed into it.

You are given an odd integer n. You need to draw a crystal of size n. The diamond cells of the matrix should be represented by character "D". All other cells of the matrix should be represented by character "*". Look at the examples to understand what you need to draw.

Input

The only line contains an integer n (3 ≤ n ≤ 101; n is odd). 

Output

Output a crystal of size n.

Examples

Input

3


Output

*D*
DDD
*D*


Input

5


Output

**D**
*DDD*
DDDDD
*DDD*
**D**


Input

7


Output

***D***
**DDD**
*DDDDD*
DDDDDDD
*DDDDD*
**DDD**
***D***

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  int n;
  cin >> n;
  vector<string> ans(n, string(n, '.'));
  for (int r = 0; r < (int)(n); ++r)
    for (int c = 0; c < (int)(n); ++c)
      if (abs(c - n / 2) + abs(r - n / 2) > n / 2)
        ans[r][c] = '*';
      else
        ans[r][c] = 'D';
  for (string s : ans) cout << s << endl;
}

```