#include<bits/stdc++.h>
using namespace std;
#define rep(i, n) for (int i = 0; i < (int)(n); ++i)
typedef vector<vector<pair<int,int>>> vp;
void color(vp &v,int s[],int i){
   rep(j,v[i].size()){
      int f=v[i][j].first;
      if(s[f]==2) {
         s[f]=v[i][j].second? !s[i]:s[i];
         color(v,s,f); 
      }
   } 
}
int main() {
  int n,a,b,c;
  cin >> n;
  int s[n];
  fill(s,s+n,2);
  s[0]=1;
  vp v(n);
  rep(i,n-1){
     cin>>a>>b>>c;
     a--;b--;c&=1;
     v[b].push_back(make_pair(a,c));
     v[a].push_back(make_pair(b,c));
  }
  color(v,s,0);
  rep(i,n)
    cout<<s[i]<<endl;
  return 0;
}

### Prompt

Create a solution in Cpp for the following problem:

We have a tree with N vertices numbered 1 to N. The i-th edge in the tree connects Vertex u_i and Vertex v_i, and its length is w_i. Your objective is to paint each vertex in the tree white or black (it is fine to paint all vertices the same color) so that the following condition is satisfied:

* For any two vertices painted in the same color, the distance between them is an even number.



Find a coloring of the vertices that satisfies the condition and print it. It can be proved that at least one such coloring exists under the constraints of this problem.

Constraints

* All values in input are integers.
* 1 \leq N \leq 10^5
* 1 \leq u_i < v_i \leq N
* 1 \leq w_i \leq 10^9

Input

Input is given from Standard Input in the following format:


N
u_1 v_1 w_1
u_2 v_2 w_2
.
.
.
u_{N - 1} v_{N - 1} w_{N - 1}


Output

Print a coloring of the vertices that satisfies the condition, in N lines. The i-th line should contain `0` if Vertex i is painted white and `1` if it is painted black.

If there are multiple colorings that satisfy the condition, any of them will be accepted.

Examples

Input

3
1 2 2
2 3 1


Output

0
0
1


Input

5
2 5 2
2 3 10
1 3 8
3 4 2


Output

1
0
1
0
1

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;
#define rep(i, n) for (int i = 0; i < (int)(n); ++i)
typedef vector<vector<pair<int,int>>> vp;
void color(vp &v,int s[],int i){
   rep(j,v[i].size()){
      int f=v[i][j].first;
      if(s[f]==2) {
         s[f]=v[i][j].second? !s[i]:s[i];
         color(v,s,f); 
      }
   } 
}
int main() {
  int n,a,b,c;
  cin >> n;
  int s[n];
  fill(s,s+n,2);
  s[0]=1;
  vp v(n);
  rep(i,n-1){
     cin>>a>>b>>c;
     a--;b--;c&=1;
     v[b].push_back(make_pair(a,c));
     v[a].push_back(make_pair(b,c));
  }
  color(v,s,0);
  rep(i,n)
    cout<<s[i]<<endl;
  return 0;
}

```