#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;

int main(){
	int n,a,b,c;
	cin >> n >> a >> b >> c;
	vector<string> q(n);
	for(int i=0; i<n; i++){
		cin >> q[i];
	}

	string ans = "";
	for(int i=0; i<n; i++){
		int &x = (q[i]=="AB")?a: (q[i]=="BC")?b: a;
		int &y = (q[i]=="AB")?b: (q[i]=="BC")?c: c;
		if(x==0 and y==0){
			cout << "No" << endl;
			return 0;
		}
		if(x==1 and y==1 and i<n-1){
			int &xx = (q[i+1]=="AB")?a: (q[i+1]=="BC")?b: c;
			int &yy = (q[i+1]=="AB")?b: (q[i+1]=="BC")?c: a;
			x++;
			y--;
			if(xx==0 and yy==0){
				x-=2;
				y+=2;
				ans += q[i][1];
			}else{
				ans += q[i][0];
			}
		}else if(x < y){
			ans += q[i][0];
			x++;
			y--;
		}else{
			ans += q[i][1];
			y++;
			x--;
		}
	}
	cout << "Yes" << endl;
	for(char c: ans){
		cout << c << endl;
	}
	return 0;
}

### Prompt

Create a solution in cpp for the following problem:

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

### Response

```cpp
#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;

int main(){
	int n,a,b,c;
	cin >> n >> a >> b >> c;
	vector<string> q(n);
	for(int i=0; i<n; i++){
		cin >> q[i];
	}

	string ans = "";
	for(int i=0; i<n; i++){
		int &x = (q[i]=="AB")?a: (q[i]=="BC")?b: a;
		int &y = (q[i]=="AB")?b: (q[i]=="BC")?c: c;
		if(x==0 and y==0){
			cout << "No" << endl;
			return 0;
		}
		if(x==1 and y==1 and i<n-1){
			int &xx = (q[i+1]=="AB")?a: (q[i+1]=="BC")?b: c;
			int &yy = (q[i+1]=="AB")?b: (q[i+1]=="BC")?c: a;
			x++;
			y--;
			if(xx==0 and yy==0){
				x-=2;
				y+=2;
				ans += q[i][1];
			}else{
				ans += q[i][0];
			}
		}else if(x < y){
			ans += q[i][0];
			x++;
			y--;
		}else{
			ans += q[i][1];
			y++;
			x--;
		}
	}
	cout << "Yes" << endl;
	for(char c: ans){
		cout << c << endl;
	}
	return 0;
}

```