#include <bits/stdc++.h>
using namespace std;
using namespace std;
vector<int> v;
int main() {
  int n, i, j, w, t;
  cin >> n;
  t = n / 2;
  w = n / 2 + 1;
  for (i = 1; i <= n / 2; ++i) {
    for (j = 1; j <= t; ++j) cout << '*';
    for (j = t + 1; j <= w; ++j) cout << 'D';
    for (j = w + 1; j <= n; ++j) cout << '*';
    cout << '\n';
    w++;
    t--;
  }
  for (i = 1; i <= n; ++i) cout << 'D';
  cout << '\n';
  t = 1;
  w = n - 1;
  for (i = 1; i <= n / 2; ++i) {
    for (j = 1; j <= t; ++j) cout << '*';
    for (j = t + 1; j <= w; ++j) cout << 'D';
    for (j = w + 1; j <= n; ++j) cout << '*';
    cout << '\n';
    w--;
    t++;
  }
  return 0;
}

### Prompt

Generate a Cpp solution to the following problem:

Twilight Sparkle once got a crystal from the Crystal Mine. A crystal of size n (n is odd; n > 1) is an n × n matrix with a diamond inscribed into it.

You are given an odd integer n. You need to draw a crystal of size n. The diamond cells of the matrix should be represented by character "D". All other cells of the matrix should be represented by character "*". Look at the examples to understand what you need to draw.

Input

The only line contains an integer n (3 ≤ n ≤ 101; n is odd). 

Output

Output a crystal of size n.

Examples

Input

3


Output

*D*
DDD
*D*


Input

5


Output

**D**
*DDD*
DDDDD
*DDD*
**D**


Input

7


Output

***D***
**DDD**
*DDDDD*
DDDDDDD
*DDDDD*
**DDD**
***D***

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
using namespace std;
vector<int> v;
int main() {
  int n, i, j, w, t;
  cin >> n;
  t = n / 2;
  w = n / 2 + 1;
  for (i = 1; i <= n / 2; ++i) {
    for (j = 1; j <= t; ++j) cout << '*';
    for (j = t + 1; j <= w; ++j) cout << 'D';
    for (j = w + 1; j <= n; ++j) cout << '*';
    cout << '\n';
    w++;
    t--;
  }
  for (i = 1; i <= n; ++i) cout << 'D';
  cout << '\n';
  t = 1;
  w = n - 1;
  for (i = 1; i <= n / 2; ++i) {
    for (j = 1; j <= t; ++j) cout << '*';
    for (j = t + 1; j <= w; ++j) cout << 'D';
    for (j = w + 1; j <= n; ++j) cout << '*';
    cout << '\n';
    w--;
    t++;
  }
  return 0;
}

```