#include <iostream>
#include <cmath>
using namespace std;

struct vec{
    double x,y;
};

double inner_product(vec& a, vec& b){
    return a.x*b.x+a.y*b.y;
}

int main(void){
    vec p1,p2,p,p12;
    int q;
    cin >> p1.x >> p1.y >> p2.x >> p2.y;
    p12.x=p2.x-p1.x; p12.y=p2.y-p1.y;
    cin >> q;
    cout.precision(10);
    cout.setf(std::ios::showpoint);
    for(int i=0;i<q;i++){
        cin >> p.x >> p.y;
        p.x-=p1.x; p.y-=p1.y;
        double k=2*inner_product(p,p12)/inner_product(p12,p12);
        cout << fixed << p1.x+k*p12.x-p.x << " " << p1.y+k*p12.y-p.y << endl;
    }
    return 0;
}
### Prompt

Your task is to create a CPP solution to the following problem:

For given three points p1, p2, p, find the reflection point x of p onto p1p2.

<image>

Constraints

* 1 ≤ q ≤ 1000
* -10000 ≤ xi, yi ≤ 10000
* p1 and p2 are not identical.

Input


xp1 yp1 xp2 yp2
q
xp0 yp0
xp1 yp1
...
xpq−1 ypq−1


In the first line, integer coordinates of p1 and p2 are given. Then, q queries are given for integer coordinates of p.

Output

For each query, print the coordinate of the reflection point x. The output values should be in a decimal fraction with an error less than 0.00000001.

Examples

Input

0 0 2 0
3
-1 1
0 1
1 1


Output

-1.0000000000 -1.0000000000
0.0000000000 -1.0000000000
1.0000000000 -1.0000000000


Input

0 0 3 4
3
2 5
1 4
0 3


Output

4.2400000000 3.3200000000
3.5600000000 2.0800000000
2.8800000000 0.8400000000

### Response

```cpp
#include <iostream>
#include <cmath>
using namespace std;

struct vec{
    double x,y;
};

double inner_product(vec& a, vec& b){
    return a.x*b.x+a.y*b.y;
}

int main(void){
    vec p1,p2,p,p12;
    int q;
    cin >> p1.x >> p1.y >> p2.x >> p2.y;
    p12.x=p2.x-p1.x; p12.y=p2.y-p1.y;
    cin >> q;
    cout.precision(10);
    cout.setf(std::ios::showpoint);
    for(int i=0;i<q;i++){
        cin >> p.x >> p.y;
        p.x-=p1.x; p.y-=p1.y;
        double k=2*inner_product(p,p12)/inner_product(p12,p12);
        cout << fixed << p1.x+k*p12.x-p.x << " " << p1.y+k*p12.y-p.y << endl;
    }
    return 0;
}
```