#include "bits/stdc++.h"

typedef long long ll;

using namespace std;

vector<vector<pair<int, int>>> G;
vector<int> res;
void dfs(int v, int p, int c) {
	res[v] = c;
	for (auto e : G[v]) {
		if (e.first == p) {continue;}
		if (e.second & 1) { dfs(e.first, v, 1 - c); }
		else { dfs(e.first, v, c); }
	}
}

int main() {
	int N;
	cin >> N;
	G.assign(N, vector<pair<int, int>>());
	for (int i = 0; i < N - 1; ++i) {
		int u, v, w; 
		cin >> u >> v >> w;
		--u, --v;
		G[u].push_back(pair<int, int>(v, w));
		G[v].push_back(pair<int, int>(u, w));
	}
	res.assign(N, 0);
	dfs(0, -1, 1);
	for (auto v : res) cout << v << endl;
}
### Prompt

Develop a solution in CPP to the problem described below:

We have a tree with N vertices numbered 1 to N. The i-th edge in the tree connects Vertex u_i and Vertex v_i, and its length is w_i. Your objective is to paint each vertex in the tree white or black (it is fine to paint all vertices the same color) so that the following condition is satisfied:

* For any two vertices painted in the same color, the distance between them is an even number.



Find a coloring of the vertices that satisfies the condition and print it. It can be proved that at least one such coloring exists under the constraints of this problem.

Constraints

* All values in input are integers.
* 1 \leq N \leq 10^5
* 1 \leq u_i < v_i \leq N
* 1 \leq w_i \leq 10^9

Input

Input is given from Standard Input in the following format:


N
u_1 v_1 w_1
u_2 v_2 w_2
.
.
.
u_{N - 1} v_{N - 1} w_{N - 1}


Output

Print a coloring of the vertices that satisfies the condition, in N lines. The i-th line should contain `0` if Vertex i is painted white and `1` if it is painted black.

If there are multiple colorings that satisfy the condition, any of them will be accepted.

Examples

Input

3
1 2 2
2 3 1


Output

0
0
1


Input

5
2 5 2
2 3 10
1 3 8
3 4 2


Output

1
0
1
0
1

### Response

```cpp
#include "bits/stdc++.h"

typedef long long ll;

using namespace std;

vector<vector<pair<int, int>>> G;
vector<int> res;
void dfs(int v, int p, int c) {
	res[v] = c;
	for (auto e : G[v]) {
		if (e.first == p) {continue;}
		if (e.second & 1) { dfs(e.first, v, 1 - c); }
		else { dfs(e.first, v, c); }
	}
}

int main() {
	int N;
	cin >> N;
	G.assign(N, vector<pair<int, int>>());
	for (int i = 0; i < N - 1; ++i) {
		int u, v, w; 
		cin >> u >> v >> w;
		--u, --v;
		G[u].push_back(pair<int, int>(v, w));
		G[v].push_back(pair<int, int>(u, w));
	}
	res.assign(N, 0);
	dfs(0, -1, 1);
	for (auto v : res) cout << v << endl;
}
```