#include <bits/stdc++.h>
using namespace std;
long n,a,b,c;
string ansyn="Yes";
int main() {
  cin >> n >> a >> b >> c;
  vector<string> s(n+1);
  vector<string> ans(n);
  for(long i=0;i<n;i++) cin >> s[i];
  for(long i=0;i<n;i++) {
    if(s[i]=="AB") {
      if(a==0&&b==0){
        ansyn="No";
        break;
      }
      if((a==1&&b==1)&&s[i+1]=="BC") a--,b++,ans[i]="B";
      else if(a>b) a--,b++,ans[i]="B";
      else a++,b--,ans[i]="A";
    } else if (s[i]=="AC") {
      if(a==0&&c==0){
        ansyn="No";
        break;
      }
      if((a==1&&c==1)&&s[i+1]=="BC") a--,c++,ans[i]="C";
      else if(a>c) a--,c++,ans[i]="C";
      else a++,c--,ans[i]="A";
    } else {
      if(b==0&&c==0){
        ansyn="No";
        break;
      }
      if((b==1&&c==1)&&s[i+1]=="AC") b--,c++,ans[i]="C";
      else if(b>c) b--,c++,ans[i]="C";
      else b++,c--,ans[i]="B";
    }
  }

  cout << ansyn << endl;
  if(ansyn=="Yes") for(long i=0;i<n;i++) cout << ans[i] << endl;
}
### Prompt

In Cpp, your task is to solve the following problem:

There is a game that involves three variables, denoted A, B, and C.

As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.

After each choice, none of A, B, and C should be negative.

Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.

Constraints

* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.

Input

Input is given from Standard Input in the following format:


N A B C
s_1
s_2
:
s_N


Output

If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.

Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.

Examples

Input

2 1 3 0
AB
AC


Output

Yes
A
C


Input

3 1 0 0
AB
BC
AB


Output

No


Input

1 0 9 0
AC


Output

No


Input

8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB


Output

Yes
C
B
B
C
C
B
A
A

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
long n,a,b,c;
string ansyn="Yes";
int main() {
  cin >> n >> a >> b >> c;
  vector<string> s(n+1);
  vector<string> ans(n);
  for(long i=0;i<n;i++) cin >> s[i];
  for(long i=0;i<n;i++) {
    if(s[i]=="AB") {
      if(a==0&&b==0){
        ansyn="No";
        break;
      }
      if((a==1&&b==1)&&s[i+1]=="BC") a--,b++,ans[i]="B";
      else if(a>b) a--,b++,ans[i]="B";
      else a++,b--,ans[i]="A";
    } else if (s[i]=="AC") {
      if(a==0&&c==0){
        ansyn="No";
        break;
      }
      if((a==1&&c==1)&&s[i+1]=="BC") a--,c++,ans[i]="C";
      else if(a>c) a--,c++,ans[i]="C";
      else a++,c--,ans[i]="A";
    } else {
      if(b==0&&c==0){
        ansyn="No";
        break;
      }
      if((b==1&&c==1)&&s[i+1]=="AC") b--,c++,ans[i]="C";
      else if(b>c) b--,c++,ans[i]="C";
      else b++,c--,ans[i]="B";
    }
  }

  cout << ansyn << endl;
  if(ansyn=="Yes") for(long i=0;i<n;i++) cout << ans[i] << endl;
}
```