#include <bits/stdc++.h>
int main() {
  long int x1, x2, x3, x4;
  scanf("%ld %ld %ld %ld", &x1, &x2, &x3, &x4);
  int max = (x1 > x2)
                ? ((x1 > x3) ? ((x1 > x4) ? x1 : x4) : ((x3 > x4) ? x3 : x4))
                : ((x2 > x3)   ? ((x2 > x4) ? x2 : x4)
                   : (x3 > x4) ? x3
                               : x4);
  int a = max - x1;
  int b = max - x2;
  int c = max - x3;
  int d = max - x4;
  if (a != 0) printf("%d ", a);
  if (b != 0) printf("%d ", b);
  if (c != 0) printf("%d ", c);
  if (d != 0) printf("%d ", d);
}

### Prompt

Please provide a CPP coded solution to the problem described below:

Polycarp has guessed three positive integers a, b and c. He keeps these numbers in secret, but he writes down four numbers on a board in arbitrary order — their pairwise sums (three numbers) and sum of all three numbers (one number). So, there are four numbers on a board in random order: a+b, a+c, b+c and a+b+c.

You have to guess three numbers a, b and c using given numbers. Print three guessed integers in any order.

Pay attention that some given numbers a, b and c can be equal (it is also possible that a=b=c).

Input

The only line of the input contains four positive integers x_1, x_2, x_3, x_4 (2 ≤ x_i ≤ 10^9) — numbers written on a board in random order. It is guaranteed that the answer exists for the given number x_1, x_2, x_3, x_4.

Output

Print such positive integers a, b and c that four numbers written on a board are values a+b, a+c, b+c and a+b+c written in some order. Print a, b and c in any order. If there are several answers, you can print any. It is guaranteed that the answer exists.

Examples

Input


3 6 5 4


Output


2 1 3


Input


40 40 40 60


Output


20 20 20


Input


201 101 101 200


Output


1 100 100

### Response

```cpp
#include <bits/stdc++.h>
int main() {
  long int x1, x2, x3, x4;
  scanf("%ld %ld %ld %ld", &x1, &x2, &x3, &x4);
  int max = (x1 > x2)
                ? ((x1 > x3) ? ((x1 > x4) ? x1 : x4) : ((x3 > x4) ? x3 : x4))
                : ((x2 > x3)   ? ((x2 > x4) ? x2 : x4)
                   : (x3 > x4) ? x3
                               : x4);
  int a = max - x1;
  int b = max - x2;
  int c = max - x3;
  int d = max - x4;
  if (a != 0) printf("%d ", a);
  if (b != 0) printf("%d ", b);
  if (c != 0) printf("%d ", c);
  if (d != 0) printf("%d ", d);
}

```