#include<iomanip>
#include<limits>
#include<thread>
#include<utility>
#include<iostream>
#include<string>
#include<algorithm>
#include<set>
#include<map>
#include<vector>
#include<stack>
#include<queue>
#include<cmath>
#include<numeric>
#include<cassert>
#include<random>
#include<chrono>
#include<unordered_set>
#include<unordered_map>
#include<fstream>
#include<list>
#include<functional>
#include<bitset>
#include<complex>
#include<tuple>
using namespace std;

typedef complex<long double> P;

template<typename D=long double,typename P=complex<long double>>
struct Geometry{
    const D EPS=1e-9;
    
    P project(P vec,P x){return vec*(x/vec).real();}
    
    P project(P p1,P p2,P x){return p1+project(p2-p1,x-p1);}
    
    P reflect(P vec,P x){return vec*conj(x/vec);}
    
    P reflect(P p1,P p2,P x){return p1+reflect(p2-p1,x-p1);}
};



int main(){
    Geometry<long double,complex<long double>> G;
    P a[2];
    for(int i=0;i<2;i++){
        long double x,y;
        cin>>x>>y;
        a[i]={x,y};
    }
    int q;
    cin>>q;
    for(int i=0;i<q;i++){
        long double x,y;
        cin>>x>>y;
        P K={x,y};
        P ans=G.reflect(a[0],a[1],K);
        cout<<fixed<<setprecision(12)<<ans.real()<<" "<<ans.imag()<<endl;
    }
    
    
    return 0;
}


### Prompt

Your challenge is to write a CPP solution to the following problem:

For given three points p1, p2, p, find the reflection point x of p onto p1p2.

<image>

Constraints

* 1 ≤ q ≤ 1000
* -10000 ≤ xi, yi ≤ 10000
* p1 and p2 are not identical.

Input


xp1 yp1 xp2 yp2
q
xp0 yp0
xp1 yp1
...
xpq−1 ypq−1


In the first line, integer coordinates of p1 and p2 are given. Then, q queries are given for integer coordinates of p.

Output

For each query, print the coordinate of the reflection point x. The output values should be in a decimal fraction with an error less than 0.00000001.

Examples

Input

0 0 2 0
3
-1 1
0 1
1 1


Output

-1.0000000000 -1.0000000000
0.0000000000 -1.0000000000
1.0000000000 -1.0000000000


Input

0 0 3 4
3
2 5
1 4
0 3


Output

4.2400000000 3.3200000000
3.5600000000 2.0800000000
2.8800000000 0.8400000000

### Response

```cpp
#include<iomanip>
#include<limits>
#include<thread>
#include<utility>
#include<iostream>
#include<string>
#include<algorithm>
#include<set>
#include<map>
#include<vector>
#include<stack>
#include<queue>
#include<cmath>
#include<numeric>
#include<cassert>
#include<random>
#include<chrono>
#include<unordered_set>
#include<unordered_map>
#include<fstream>
#include<list>
#include<functional>
#include<bitset>
#include<complex>
#include<tuple>
using namespace std;

typedef complex<long double> P;

template<typename D=long double,typename P=complex<long double>>
struct Geometry{
    const D EPS=1e-9;
    
    P project(P vec,P x){return vec*(x/vec).real();}
    
    P project(P p1,P p2,P x){return p1+project(p2-p1,x-p1);}
    
    P reflect(P vec,P x){return vec*conj(x/vec);}
    
    P reflect(P p1,P p2,P x){return p1+reflect(p2-p1,x-p1);}
};



int main(){
    Geometry<long double,complex<long double>> G;
    P a[2];
    for(int i=0;i<2;i++){
        long double x,y;
        cin>>x>>y;
        a[i]={x,y};
    }
    int q;
    cin>>q;
    for(int i=0;i<q;i++){
        long double x,y;
        cin>>x>>y;
        P K={x,y};
        P ans=G.reflect(a[0],a[1],K);
        cout<<fixed<<setprecision(12)<<ans.real()<<" "<<ans.imag()<<endl;
    }
    
    
    return 0;
}


```