#include <stdio.h>

char s[11];

int main()
{	 
	int ans = 0, i;
	
	scanf("%s", s);
	for(i = 0; s[i]; i++) ans += s[i] - 48;
	if(ans == 1) ans = 10;
	printf("%d\n", ans);
		
	return 0;
}
### Prompt

Please create a solution in Cpp to the following problem:

Takahashi has two positive integers A and B.

It is known that A plus B equals N. Find the minimum possible value of "the sum of the digits of A" plus "the sum of the digits of B" (in base 10).

Constraints

* 2 ≤ N ≤ 10^5
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the minimum possible value of "the sum of the digits of A" plus "the sum of the digits of B".

Examples

Input

15


Output

6


Input

100000


Output

10

### Response

```cpp
#include <stdio.h>

char s[11];

int main()
{	 
	int ans = 0, i;
	
	scanf("%s", s);
	for(i = 0; s[i]; i++) ans += s[i] - 48;
	if(ans == 1) ans = 10;
	printf("%d\n", ans);
		
	return 0;
}
```