#include<stdio.h>
int main(){
	int a, b, c;
	int counter = 0;
	scanf("%d%d%d", &a, &b, &c);
	for(int i=a; i<=b; i++){
		if(c%i==0)counter++;
	}
	printf("%d\n", counter);
}

### Prompt

Create a solution in CPP for the following problem:

How Many Divisors?

Write a program which reads three integers a, b and c, and prints the number of divisors of c between a and b.

Constraints

* 1 ≤ a, b, c ≤ 10000
* a ≤ b

Input

Three integers a, b and c are given in a line separated by a single space.

Output

Print the number of divisors in a line.

Example

Input

5 14 80


Output

3

### Response

```cpp
#include<stdio.h>
int main(){
	int a, b, c;
	int counter = 0;
	scanf("%d%d%d", &a, &b, &c);
	for(int i=a; i<=b; i++){
		if(c%i==0)counter++;
	}
	printf("%d\n", counter);
}

```