#include<bits/stdc++.h>
using namespace std;
#define f(b) ((s[b]=='0'&&s[b+1]>'0')||(s[b]=='1'&&s[b+1]<'3'))
int main(){
  string s;
  cin>>s;
  if(f(0)&&f(2))cout<<"AMBIGUOUS\n";
  else if(f(0))cout<<"MMYY\n";
  else if(f(2))cout<<"YYMM\n";
  else cout<<"NA\n";
  return 0;
}
### Prompt

Please provide a cpp coded solution to the problem described below:

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

* YYMM format: the last two digits of the year and the two-digit representation of the month (example: `01` for January), concatenated in this order
* MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order



If S is valid in only YYMM format, print `YYMM`; if S is valid in only MMYY format, print `MMYY`; if S is valid in both formats, print `AMBIGUOUS`; if S is valid in neither format, print `NA`.

Constraints

* S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:


S


Output

Print the specified string: `YYMM`, `MMYY`, `AMBIGUOUS` or `NA`.

Examples

Input

1905


Output

YYMM


Input

0112


Output

AMBIGUOUS


Input

1700


Output

NA

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;
#define f(b) ((s[b]=='0'&&s[b+1]>'0')||(s[b]=='1'&&s[b+1]<'3'))
int main(){
  string s;
  cin>>s;
  if(f(0)&&f(2))cout<<"AMBIGUOUS\n";
  else if(f(0))cout<<"MMYY\n";
  else if(f(2))cout<<"YYMM\n";
  else cout<<"NA\n";
  return 0;
}
```