#include<bits/stdc++.h>
using namespace std;

int main(){
  int n;
  cin >> n;
  if(n % 10 == 0) cout << 10 << endl;
  else{
    int ans = 0;
    while(n != 0){
      ans += n % 10;
      n /= 10;
    }
    cout << ans << endl;
  }
}
### Prompt

Your task is to create a Cpp solution to the following problem:

Takahashi has two positive integers A and B.

It is known that A plus B equals N. Find the minimum possible value of "the sum of the digits of A" plus "the sum of the digits of B" (in base 10).

Constraints

* 2 ≤ N ≤ 10^5
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the minimum possible value of "the sum of the digits of A" plus "the sum of the digits of B".

Examples

Input

15


Output

6


Input

100000


Output

10

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;

int main(){
  int n;
  cin >> n;
  if(n % 10 == 0) cout << 10 << endl;
  else{
    int ans = 0;
    while(n != 0){
      ans += n % 10;
      n /= 10;
    }
    cout << ans << endl;
  }
}
```