#include <iostream>

using namespace std;

int main(void)
{
	int n;
	int *a;

	cin >> n;
	a = new int[n];

	for (int i = 0; i < n; i++)
		cin >> a[i];

	while (--n > 0)
		cout << a[n] << ' ';

	cout << a[n] << endl;
}
### Prompt

Please provide a Cpp coded solution to the problem described below:

Write a program which reads a sequence and prints it in the reverse order.

Note

解説

Constraints

* n ≤ 100
* 0 ≤ ai < 1000

Input

The input is given in the following format:


n
a1 a2 . . . an


n is the size of the sequence and ai is the ith element of the sequence.

Output

Print the reversed sequence in a line. Print a single space character between adjacent elements (Note that your program should not put a space character after the last element).

Examples

Input

5
1 2 3 4 5


Output

5 4 3 2 1


Input

8
3 3 4 4 5 8 7 9


Output

9 7 8 5 4 4 3 3

### Response

```cpp
#include <iostream>

using namespace std;

int main(void)
{
	int n;
	int *a;

	cin >> n;
	a = new int[n];

	for (int i = 0; i < n; i++)
		cin >> a[i];

	while (--n > 0)
		cout << a[n] << ' ';

	cout << a[n] << endl;
}
```