#include<iostream>
#include<cstdio>

int A[4];
int B[4];
int main()
{
  while(scanf("%d %d %d %d\n%d %d %d %d",&A[0],&A[1],&A[2],&A[3],&B[0],&B[1],&B[2],&B[3]) != EOF){
  int Hit = 0;
  int Blow = 0;
  for(int i = 0;i < 4;i++){
    for(int j = 0; j < 4;j++){
      if(A[i] == B[j]){
	if(i ==j){
	  Hit++;
	}else
	  Blow++;
      }
    }
  }
    printf("%d %d\n",Hit,Blow);
  }
  return 0;
}
### Prompt

Please provide a Cpp coded solution to the problem described below:

Let's play Hit and Blow game. A imagines four numbers and B guesses the numbers. After B picks out four numbers, A answers:

* The number of numbers which have the same place with numbers A imagined (Hit)
* The number of numbers included (but different place) in the numbers A imagined (Blow)



For example, if A imagined numbers:


9 1 8 2


and B chose:


4 1 5 9


A should say 1 Hit and 1 Blow.

Write a program which reads four numbers A imagined and four numbers B chose and prints the number of Hit and Blow respectively. You may assume that the four numbers are all different and within from 0 to 9.



Input

The input consists of multiple datasets. Each dataset set consists of:


a1 a2 a3 a4
b1 b2 b3 b4


, where ai (0 ≤ ai ≤ 9) is i-th number A imagined and bi (0 ≤ bi ≤ 9) is i-th number B chose.

The input ends with EOF. The number of datasets is less than or equal to 50.

Output

For each dataset, print the number of Hit and Blow in a line. These two numbers should be separated by a space.

Example

Input

9 1 8 2
4 1 5 9
4 6 8 2
4 6 3 2


Output

1 1
3 0

### Response

```cpp
#include<iostream>
#include<cstdio>

int A[4];
int B[4];
int main()
{
  while(scanf("%d %d %d %d\n%d %d %d %d",&A[0],&A[1],&A[2],&A[3],&B[0],&B[1],&B[2],&B[3]) != EOF){
  int Hit = 0;
  int Blow = 0;
  for(int i = 0;i < 4;i++){
    for(int j = 0; j < 4;j++){
      if(A[i] == B[j]){
	if(i ==j){
	  Hit++;
	}else
	  Blow++;
      }
    }
  }
    printf("%d %d\n",Hit,Blow);
  }
  return 0;
}
```