#include <iostream>
#include <algorithm>
#include <vector>
#include <tuple>
#include <string>

using namespace std;

using ll = long long;

int main() {
  int n;
  cin >> n;
  vector<tuple<int, int, char, ll, string> > vec;
  for(int i = 0; i < n; ++i) {
    int v, w;
    char t;
    ll d;
    string s;
    cin >> v >> w >> t >> d >> s;
    vec.emplace_back(v, w, t, d, s);
  }
  sort(vec.begin(), vec.end());
  for(auto p : vec) {
    int v, w;
    char t;
    ll d;
    string s;
    tie(v, w, t, d, s) = p;
    cout << v << " " << w << " " << t << " " << d << " " << s << endl;
  }
  return 0;
}


### Prompt

Please formulate a cpp solution to the following problem:

Queue is a container of elements that are inserted and deleted according to FIFO (First In First Out).

For $n$ queues $Q_i$ ($i = 0, 1, ..., n-1$), perform a sequence of the following operations.

* enqueue($t$, $x$): Insert an integer $x$ to $Q_t$.
* front($t$): Report the value which should be deleted next from $Q_t$. If $Q_t$ is empty, do nothing.
* dequeue($t$): Delete an element from $Q_t$. If $Q_t$ is empty, do nothing.



In the initial state, all queues are empty.

Constraints

* $1 \leq n \leq 1,000$
* $1 \leq q \leq 200,000$
* $-1,000,000,000 \leq x \leq 1,000,000,000$

Input

The input is given in the following format.


$n \; q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $t$ $x$


or


1 $t$


or


2 $t$


where the first digits 0, 1 and 2 represent enqueue, front and dequeue operations respectively.

Output

For each front operation, print an integer in a line.

Example

Input

3 9
0 0 1
0 0 2
0 0 3
0 2 4
0 2 5
1 0
1 2
2 0
1 0


Output

1
4
2

### Response

```cpp
#include <iostream>
#include <algorithm>
#include <vector>
#include <tuple>
#include <string>

using namespace std;

using ll = long long;

int main() {
  int n;
  cin >> n;
  vector<tuple<int, int, char, ll, string> > vec;
  for(int i = 0; i < n; ++i) {
    int v, w;
    char t;
    ll d;
    string s;
    cin >> v >> w >> t >> d >> s;
    vec.emplace_back(v, w, t, d, s);
  }
  sort(vec.begin(), vec.end());
  for(auto p : vec) {
    int v, w;
    char t;
    ll d;
    string s;
    tie(v, w, t, d, s) = p;
    cout << v << " " << w << " " << t << " " << d << " " << s << endl;
  }
  return 0;
}


```