#include<cstdio>

int main(){
	int n;
	scanf("%d", &n);
	int a[n];
	for(int i = 0; i < n; i++){
		scanf("%d", &a[i]);
	}

	for(int i = n - 1; i > 0; i--){
		printf("%d ", a[i]);
	}
	printf("%d\n", a[0]);
}
### Prompt

Construct a Cpp code solution to the problem outlined:

Write a program which reads a sequence and prints it in the reverse order.

Note

解説

Constraints

* n ≤ 100
* 0 ≤ ai < 1000

Input

The input is given in the following format:


n
a1 a2 . . . an


n is the size of the sequence and ai is the ith element of the sequence.

Output

Print the reversed sequence in a line. Print a single space character between adjacent elements (Note that your program should not put a space character after the last element).

Examples

Input

5
1 2 3 4 5


Output

5 4 3 2 1


Input

8
3 3 4 4 5 8 7 9


Output

9 7 8 5 4 4 3 3

### Response

```cpp
#include<cstdio>

int main(){
	int n;
	scanf("%d", &n);
	int a[n];
	for(int i = 0; i < n; i++){
		scanf("%d", &a[i]);
	}

	for(int i = n - 1; i > 0; i--){
		printf("%d ", a[i]);
	}
	printf("%d\n", a[0]);
}
```