#include<stdio.h>
int main(){
  int a,b,c,i=0,j;
  scanf("%d %d %d",&a,&b,&c);
  for(j=a;j<=b;j++){
    if(c%j==0){
      i++;
    }
  }
  printf("%d\n",i);
  return(0);
}
### Prompt

Construct a Cpp code solution to the problem outlined:

How Many Divisors?

Write a program which reads three integers a, b and c, and prints the number of divisors of c between a and b.

Constraints

* 1 ≤ a, b, c ≤ 10000
* a ≤ b

Input

Three integers a, b and c are given in a line separated by a single space.

Output

Print the number of divisors in a line.

Example

Input

5 14 80


Output

3

### Response

```cpp
#include<stdio.h>
int main(){
  int a,b,c,i=0,j;
  scanf("%d %d %d",&a,&b,&c);
  for(j=a;j<=b;j++){
    if(c%j==0){
      i++;
    }
  }
  printf("%d\n",i);
  return(0);
}
```