#include <stdio.h>

int main(){
  int a,b,c,cnt = 0;
  int i;
  scanf("%d %d %d",&a,&b,&c);
  for(i=a;i<=b;i++)if(!(c%i))cnt++;
  printf("%d\n",cnt);
}
  
### Prompt

Your task is to create a Cpp solution to the following problem:

How Many Divisors?

Write a program which reads three integers a, b and c, and prints the number of divisors of c between a and b.

Constraints

* 1 ≤ a, b, c ≤ 10000
* a ≤ b

Input

Three integers a, b and c are given in a line separated by a single space.

Output

Print the number of divisors in a line.

Example

Input

5 14 80


Output

3

### Response

```cpp
#include <stdio.h>

int main(){
  int a,b,c,cnt = 0;
  int i;
  scanf("%d %d %d",&a,&b,&c);
  for(i=a;i<=b;i++)if(!(c%i))cnt++;
  printf("%d\n",cnt);
}
  
```