#include <iostream>

using namespace std;


    int main(){
int a;scanf("%d",&a);
int L=a/100;
int R=a%100;
if(1<=L&&L<=12){
if(1<=R&&R<=12)printf("AMBIGUOUS\n");
else printf("MMYY\n");
}else{
if(1<=R&&R<=12) printf("YYMM\n");
else printf("NA\n");



    return 0;

}
    }

### Prompt

Construct a Cpp code solution to the problem outlined:

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

* YYMM format: the last two digits of the year and the two-digit representation of the month (example: `01` for January), concatenated in this order
* MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order



If S is valid in only YYMM format, print `YYMM`; if S is valid in only MMYY format, print `MMYY`; if S is valid in both formats, print `AMBIGUOUS`; if S is valid in neither format, print `NA`.

Constraints

* S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:


S


Output

Print the specified string: `YYMM`, `MMYY`, `AMBIGUOUS` or `NA`.

Examples

Input

1905


Output

YYMM


Input

0112


Output

AMBIGUOUS


Input

1700


Output

NA

### Response

```cpp
#include <iostream>

using namespace std;


    int main(){
int a;scanf("%d",&a);
int L=a/100;
int R=a%100;
if(1<=L&&L<=12){
if(1<=R&&R<=12)printf("AMBIGUOUS\n");
else printf("MMYY\n");
}else{
if(1<=R&&R<=12) printf("YYMM\n");
else printf("NA\n");



    return 0;

}
    }

```