#include <stdio.h>

int main() {
  int a, b, c, d = 0;
  scanf("%d%d%d", &a, &b, &c);
  for (int i = a; i <= b; ++i) {
    if (c % i == 0) ++d;
  }
  printf("%d\n", d);
}

### Prompt

Please provide a cpp coded solution to the problem described below:

How Many Divisors?

Write a program which reads three integers a, b and c, and prints the number of divisors of c between a and b.

Constraints

* 1 ≤ a, b, c ≤ 10000
* a ≤ b

Input

Three integers a, b and c are given in a line separated by a single space.

Output

Print the number of divisors in a line.

Example

Input

5 14 80


Output

3

### Response

```cpp
#include <stdio.h>

int main() {
  int a, b, c, d = 0;
  scanf("%d%d%d", &a, &b, &c);
  for (int i = a; i <= b; ++i) {
    if (c % i == 0) ++d;
  }
  printf("%d\n", d);
}

```