#include <bits/stdc++.h>

using namespace std;
int main() {
	int n;
	cin >> n;
	int ans = 0;
	if (n % 10 == 0) cout << 10 << endl;
	else {
		while(n > 0) {
			ans += n % 10;
			n /= 10;
		}
		cout << ans << endl;
	}
	return 0;
}

### Prompt

Your task is to create a Cpp solution to the following problem:

Takahashi has two positive integers A and B.

It is known that A plus B equals N. Find the minimum possible value of "the sum of the digits of A" plus "the sum of the digits of B" (in base 10).

Constraints

* 2 ≤ N ≤ 10^5
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the minimum possible value of "the sum of the digits of A" plus "the sum of the digits of B".

Examples

Input

15


Output

6


Input

100000


Output

10

### Response

```cpp
#include <bits/stdc++.h>

using namespace std;
int main() {
	int n;
	cin >> n;
	int ans = 0;
	if (n % 10 == 0) cout << 10 << endl;
	else {
		while(n > 0) {
			ans += n % 10;
			n /= 10;
		}
		cout << ans << endl;
	}
	return 0;
}

```