#include <bits/stdc++.h>
using namespace std;
int main() {
  char ch_prev = NULL;
  bool first = false;
  string normal, finall;
  cin >> normal;
  int len = normal.length();
  for (int i = 0; len; i++, len--) {
    if (isalpha(normal.at(i)) && ch_prev == '/') {
      finall += '/';
      finall += normal.at(i);
      first = true;
    } else if (isalpha(normal.at(i)) && isalpha(ch_prev)) {
      finall += normal.at(i);
    }
    ch_prev = normal.at(i);
  }
  if (first == false) {
    cout << '/' << endl;
  } else {
    cout << finall << endl;
  }
  return 0;
}

### Prompt

Develop a solution in CPP to the problem described below:

The new operating system BerOS has a nice feature. It is possible to use any number of characters '/' as a delimiter in path instead of one traditional '/'. For example, strings //usr///local//nginx/sbin// and /usr/local/nginx///sbin are equivalent. The character '/' (or some sequence of such characters) at the end of the path is required only in case of the path to the root directory, which can be represented as single character '/'.

A path called normalized if it contains the smallest possible number of characters '/'.

Your task is to transform a given path to the normalized form.

Input

The first line of the input contains only lowercase Latin letters and character '/' — the path to some directory. All paths start with at least one character '/'. The length of the given line is no more than 100 characters, it is not empty.

Output

The path in normalized form.

Examples

Input

//usr///local//nginx/sbin


Output

/usr/local/nginx/sbin

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  char ch_prev = NULL;
  bool first = false;
  string normal, finall;
  cin >> normal;
  int len = normal.length();
  for (int i = 0; len; i++, len--) {
    if (isalpha(normal.at(i)) && ch_prev == '/') {
      finall += '/';
      finall += normal.at(i);
      first = true;
    } else if (isalpha(normal.at(i)) && isalpha(ch_prev)) {
      finall += normal.at(i);
    }
    ch_prev = normal.at(i);
  }
  if (first == false) {
    cout << '/' << endl;
  } else {
    cout << finall << endl;
  }
  return 0;
}

```