#include<stdio.h>
int main()
{
	int a,b,c,d=0;
	scanf("%d %d %d",&a,&b,&c);
	for(a;a<=b;a++){
		if(c%a==0){
			d++;
		}
	}
	printf("%d\n",d);
	return 0;
}
### Prompt

Please create a solution in Cpp to the following problem:

How Many Divisors?

Write a program which reads three integers a, b and c, and prints the number of divisors of c between a and b.

Constraints

* 1 ≤ a, b, c ≤ 10000
* a ≤ b

Input

Three integers a, b and c are given in a line separated by a single space.

Output

Print the number of divisors in a line.

Example

Input

5 14 80


Output

3

### Response

```cpp
#include<stdio.h>
int main()
{
	int a,b,c,d=0;
	scanf("%d %d %d",&a,&b,&c);
	for(a;a<=b;a++){
		if(c%a==0){
			d++;
		}
	}
	printf("%d\n",d);
	return 0;
}
```