#include<bits/stdc++.h>
using namespace std;
int a;
bool y,m;
int main()
{
	cin>>a;
	if(a%100<=12&&a%100>=1) y=1;
	if(a/100<=12&&a/100>=1) m=1;
	if(y==1&&m==1)
	{
		cout<<"AMBIGUOUS";
		return 0;
	}
	if(y==1) cout<<"YYMM";
	else if(m==1) cout<<"MMYY";
	else cout<<"NA";
	return 0;
}
### Prompt

Create a solution in Cpp for the following problem:

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

* YYMM format: the last two digits of the year and the two-digit representation of the month (example: `01` for January), concatenated in this order
* MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order



If S is valid in only YYMM format, print `YYMM`; if S is valid in only MMYY format, print `MMYY`; if S is valid in both formats, print `AMBIGUOUS`; if S is valid in neither format, print `NA`.

Constraints

* S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:


S


Output

Print the specified string: `YYMM`, `MMYY`, `AMBIGUOUS` or `NA`.

Examples

Input

1905


Output

YYMM


Input

0112


Output

AMBIGUOUS


Input

1700


Output

NA

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;
int a;
bool y,m;
int main()
{
	cin>>a;
	if(a%100<=12&&a%100>=1) y=1;
	if(a/100<=12&&a/100>=1) m=1;
	if(y==1&&m==1)
	{
		cout<<"AMBIGUOUS";
		return 0;
	}
	if(y==1) cout<<"YYMM";
	else if(m==1) cout<<"MMYY";
	else cout<<"NA";
	return 0;
}
```