#include<stdio.h>
int main() {
int cnt=0,a,b,c;scanf("%d%d%d",&a,&b,&c); for(int i=a;i<=b;i++)cnt+=c%i==0; printf("%d\n",cnt);return 0;
}
### Prompt

Generate a Cpp solution to the following problem:

How Many Divisors?

Write a program which reads three integers a, b and c, and prints the number of divisors of c between a and b.

Constraints

* 1 ≤ a, b, c ≤ 10000
* a ≤ b

Input

Three integers a, b and c are given in a line separated by a single space.

Output

Print the number of divisors in a line.

Example

Input

5 14 80


Output

3

### Response

```cpp
#include<stdio.h>
int main() {
int cnt=0,a,b,c;scanf("%d%d%d",&a,&b,&c); for(int i=a;i<=b;i++)cnt+=c%i==0; printf("%d\n",cnt);return 0;
}
```