#include <bits/stdc++.h>

int main()
{
int a=0,b=0,c=0,d=0;
scanf("%d %d %d",&a,&b,&c);
for(a=a;a<=b;a++)
{
if(c%a==0){
d=d+1;
}
}
printf("%d\n",d);
return 0;
}

### Prompt

Generate a CPP solution to the following problem:

How Many Divisors?

Write a program which reads three integers a, b and c, and prints the number of divisors of c between a and b.

Constraints

* 1 ≤ a, b, c ≤ 10000
* a ≤ b

Input

Three integers a, b and c are given in a line separated by a single space.

Output

Print the number of divisors in a line.

Example

Input

5 14 80


Output

3

### Response

```cpp
#include <bits/stdc++.h>

int main()
{
int a=0,b=0,c=0,d=0;
scanf("%d %d %d",&a,&b,&c);
for(a=a;a<=b;a++)
{
if(c%a==0){
d=d+1;
}
}
printf("%d\n",d);
return 0;
}

```