#include<bits/stdc++.h>
using namespace std;

int solve(int n){
	int ans = 0;

	do{
		ans += (n%10);
		n /= 10;
	}while(n);

	return ans == 1 ? 10 : ans;
}

int main(){
	int n;

	cin>>n;

	auto ans = solve(n);

	cout<<ans<<'\n';

	return 0;
}
### Prompt

Generate a Cpp solution to the following problem:

Takahashi has two positive integers A and B.

It is known that A plus B equals N. Find the minimum possible value of "the sum of the digits of A" plus "the sum of the digits of B" (in base 10).

Constraints

* 2 ≤ N ≤ 10^5
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the minimum possible value of "the sum of the digits of A" plus "the sum of the digits of B".

Examples

Input

15


Output

6


Input

100000


Output

10

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;

int solve(int n){
	int ans = 0;

	do{
		ans += (n%10);
		n /= 10;
	}while(n);

	return ans == 1 ? 10 : ans;
}

int main(){
	int n;

	cin>>n;

	auto ans = solve(n);

	cout<<ans<<'\n';

	return 0;
}
```