#include <bits/stdc++.h>
using namespace std;
int main() {
  string s, s1;
  int x;
  vector<string> str;
  bool b = true;
  cin >> s;
  x = 0;
  str.clear();
  s1 = "";
  for (int i = 0; i < s.size(); i++) {
    if (s[i] != '/') {
      s1 += s[i];
    } else {
      x++;
      str.push_back(s1);
      s1 = "";
    }
    if ((i == s.size() - 1) && s.size() - 1 != '/') {
      str.push_back(s1);
    }
  }
  if (x == s.size()) {
    cout << "/" << endl;
  } else {
    for (int i = 0; i < str.size(); i++) {
      if (str[i] == "")
        continue;
      else
        cout << "/" << str[i];
    }
    cout << endl;
  }
  return 0;
}

### Prompt

In cpp, your task is to solve the following problem:

The new operating system BerOS has a nice feature. It is possible to use any number of characters '/' as a delimiter in path instead of one traditional '/'. For example, strings //usr///local//nginx/sbin// and /usr/local/nginx///sbin are equivalent. The character '/' (or some sequence of such characters) at the end of the path is required only in case of the path to the root directory, which can be represented as single character '/'.

A path called normalized if it contains the smallest possible number of characters '/'.

Your task is to transform a given path to the normalized form.

Input

The first line of the input contains only lowercase Latin letters and character '/' — the path to some directory. All paths start with at least one character '/'. The length of the given line is no more than 100 characters, it is not empty.

Output

The path in normalized form.

Examples

Input

//usr///local//nginx/sbin


Output

/usr/local/nginx/sbin

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  string s, s1;
  int x;
  vector<string> str;
  bool b = true;
  cin >> s;
  x = 0;
  str.clear();
  s1 = "";
  for (int i = 0; i < s.size(); i++) {
    if (s[i] != '/') {
      s1 += s[i];
    } else {
      x++;
      str.push_back(s1);
      s1 = "";
    }
    if ((i == s.size() - 1) && s.size() - 1 != '/') {
      str.push_back(s1);
    }
  }
  if (x == s.size()) {
    cout << "/" << endl;
  } else {
    for (int i = 0; i < str.size(); i++) {
      if (str[i] == "")
        continue;
      else
        cout << "/" << str[i];
    }
    cout << endl;
  }
  return 0;
}

```