#include <stdio.h>
int main(){
	int i,a,b,c,kazu=0;
	scanf("%d %d %d",&a,&b,&c);
	for(i=a;i<=b;i++){
		if((c%i)==0){
			kazu++;
		}
	}
	printf("%d\n",kazu);	
	return 0 ;
}
### Prompt

Please provide a CPP coded solution to the problem described below:

How Many Divisors?

Write a program which reads three integers a, b and c, and prints the number of divisors of c between a and b.

Constraints

* 1 ≤ a, b, c ≤ 10000
* a ≤ b

Input

Three integers a, b and c are given in a line separated by a single space.

Output

Print the number of divisors in a line.

Example

Input

5 14 80


Output

3

### Response

```cpp
#include <stdio.h>
int main(){
	int i,a,b,c,kazu=0;
	scanf("%d %d %d",&a,&b,&c);
	for(i=a;i<=b;i++){
		if((c%i)==0){
			kazu++;
		}
	}
	printf("%d\n",kazu);	
	return 0 ;
}
```