#include<stdio.h>
int main()
{
  int a,b,c,i,j;
  scanf("%d%d%d",&a,&b,&c);
  for(i=a;i<=b;i++){
    if(c%i==0)
      j++;
  }
  printf("%d\n",j);
   return 0;
 }
### Prompt

Your challenge is to write a cpp solution to the following problem:

How Many Divisors?

Write a program which reads three integers a, b and c, and prints the number of divisors of c between a and b.

Constraints

* 1 ≤ a, b, c ≤ 10000
* a ≤ b

Input

Three integers a, b and c are given in a line separated by a single space.

Output

Print the number of divisors in a line.

Example

Input

5 14 80


Output

3

### Response

```cpp
#include<stdio.h>
int main()
{
  int a,b,c,i,j;
  scanf("%d%d%d",&a,&b,&c);
  for(i=a;i<=b;i++){
    if(c%i==0)
      j++;
  }
  printf("%d\n",j);
   return 0;
 }
```