#include<iostream>
int main(){
  int n,i,*A;
  std::cin >> n;
  A = new int [n];
  for(i=n-1; i>=0; i--) std::cin >> A[i];
  for(i=0; i<n; i++) std::cout << A[i] << (n - 1 == i ? "\n" : " ");
  return 0;
}
### Prompt

Construct a CPP code solution to the problem outlined:

Write a program which reads a sequence and prints it in the reverse order.

Note

解説

Constraints

* n ≤ 100
* 0 ≤ ai < 1000

Input

The input is given in the following format:


n
a1 a2 . . . an


n is the size of the sequence and ai is the ith element of the sequence.

Output

Print the reversed sequence in a line. Print a single space character between adjacent elements (Note that your program should not put a space character after the last element).

Examples

Input

5
1 2 3 4 5


Output

5 4 3 2 1


Input

8
3 3 4 4 5 8 7 9


Output

9 7 8 5 4 4 3 3

### Response

```cpp
#include<iostream>
int main(){
  int n,i,*A;
  std::cin >> n;
  A = new int [n];
  for(i=n-1; i>=0; i--) std::cin >> A[i];
  for(i=0; i<n; i++) std::cout << A[i] << (n - 1 == i ? "\n" : " ");
  return 0;
}
```