#include <bits/stdc++.h>
using namespace std;

int main() {
  int N;
  cin >> N;
  int ans = 0;
  while (N > 0) {
    ans += N % 10;
    N /= 10;
  }
  if (ans > 1) cout << ans << endl;
  else cout << 10 << endl;
}


### Prompt

Your task is to create a Cpp solution to the following problem:

Takahashi has two positive integers A and B.

It is known that A plus B equals N. Find the minimum possible value of "the sum of the digits of A" plus "the sum of the digits of B" (in base 10).

Constraints

* 2 ≤ N ≤ 10^5
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the minimum possible value of "the sum of the digits of A" plus "the sum of the digits of B".

Examples

Input

15


Output

6


Input

100000


Output

10

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;

int main() {
  int N;
  cin >> N;
  int ans = 0;
  while (N > 0) {
    ans += N % 10;
    N /= 10;
  }
  if (ans > 1) cout << ans << endl;
  else cout << 10 << endl;
}


```