#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using VI = vector<int>;
using VL = vector<ll>;
using VS = vector<string>;
using VB = vector<bool>;
using VVB = vector<vector<bool>>;
using VVI = vector<VI>;
using VVL = vector<VL>;
using PII = std::pair<int, int>;
using VPII = std::vector<std::pair<int, int>>;
using PLL = std::pair<ll, ll>;
using VPLL = std::vector<std::pair<ll, ll>>;
using TI3 = std::tuple<int, int, int>;
using TI4 = std::tuple<int, int, int, int>;
using TL3 = std::tuple<ll, ll, ll>;
using TL4 = std::tuple<ll, ll, ll, ll>;
const int mod1 = 1e9 + 7, mod2 = 998244353, mod3 = 1e9 + 9;
const int mod = mod1;
const ll inf = 1e18;
const string wsp = " ";
const string tb = "\t";
const string rt = "\n";
template <typename T>
void show1dvec(const vector<T> &v) {
  if (v.size() == 0) return;
  int n = v.size() - 1;
  for (int i = 0; i < (int)(n); i++) cout << v[i] << wsp;
  cout << v[n] << rt;
  return;
}
template <typename T>
void show2dvec(const vector<vector<T>> &v) {
  int n = v.size();
  for (int i = 0; i < (int)(n); i++) show1dvec(v[i]);
}
template <typename T, typename S>
void show1dpair(const vector<pair<T, S>> &v) {
  int n = v.size();
  for (int i = 0; i < (int)(n); i++)
    cout << v[i].first << wsp << v[i].second << rt;
  return;
}
template <typename T, typename S>
void pairzip(const vector<pair<T, S>> &v, vector<T> &t, vector<T> &s) {
  int n = v.size();
  for (int i = 0; i < (int)(n); i++) {
    t.push_back(v[i].first);
    s.push_back(v[i].second);
  }
  return;
}
template <typename T>
void maxvec(vector<T> &v) {
  T s = v[0];
  int n = v.size();
  for (int i = 0; i < (int)(n - 1); i++) {
    if (s > v[i + 1]) {
      v[i + 1] = s;
    }
    s = v[i + 1];
  }
}
template <typename T, typename S>
bool myfind(T t, S s) {
  return find(t.cbegin(), t.cend(), s) != t.cend();
}
bool check(int y, int x, int h, int w) {
  return 0 <= y && y < h && 0 <= x && x < w;
}
template <typename T>
vector<T> cumsum(const vector<T> &v) {
  T s = 0;
  vector<T> ret;
  for (int i = 0; i < (int)(v.size()); i++) {
    s += v[i];
    s %= mod;
    ret.emplace_back(s);
  }
  return ret;
}
bool iskadomatsu(int a, int b, int c) {
  return (a != b && b != c && c != a) && ((a > b && b < c) || (a < b && b > c));
}
VS split(string s, char c) {
  VS ret;
  string part;
  s += c;
  for (int i = 0; i < (int)(s.length()); i++) {
    if (s[i] == c) {
      ret.emplace_back(part);
      part = "";
    } else if (s[i] != c) {
      part += s[i];
    }
  }
  return ret;
}
template <typename T, typename S, typename R>
ll pow_mod(T p, S q, R mod = 1ll) {
  ll ret = 1, r = p;
  while (q) {
    if (q % 2) ret *= r, ret %= mod;
    r = (r * r) % mod, q /= 2;
  }
  return ret % mod;
}
template <typename T, typename S>
ll pow_no_mod(T p, S q) {
  ll ret = 1, r = p;
  while (q) {
    if (q % 2) ret *= r;
    r = (r * r), q /= 2;
  }
  return ret;
}
void make_frac_tables(VL &frac_list, VL &frac_inv_list) {
  for (int i = 0; i < (int)(frac_list.size() - 1); i++) {
    frac_list[i + 1] *= frac_list[i] * (i + 1);
    frac_list[i + 1] %= mod;
    frac_inv_list[i + 1] *= frac_inv_list[i] * pow_mod(i + 1, mod - 2, mod);
    frac_inv_list[i + 1] %= mod;
  }
}
ll comb(int a, int b, const VL &frac_list, const VL &frac_inv_list) {
  if (a < b) return 0;
  if (b < 0) return 0;
  ll ret = frac_list[a];
  ret *= frac_inv_list[b];
  ret %= mod;
  ret *= frac_inv_list[a - b];
  ret %= mod;
  return ret;
}
const int maxint = 1e9;
VVI connective;
VI bfs(int v, int n) {
  VI shortest(n, 0), search{v}, new_search;
  VB used(n, false);
  used[v] = true;
  while (!search.empty()) {
    for (auto i : search) {
      for (auto j : connective[i]) {
        if (!used[j]) {
          shortest[j] = shortest[i] + 1;
          new_search.emplace_back(j);
          used[j] = true;
        }
      }
    }
    search.clear();
    search = new_search;
    new_search.clear();
  }
  return shortest;
}
int main() {
  cin.tie(0);
  ios::sync_with_stdio(false);
  int n, m, k;
  cin >> n >> m >> k;
  VI chores(n);
  for (int i = (int)(n)-1; i >= 0; i--) cin >> chores[i];
  for (int i = 0; i < (int)(m); i++)
    if (chores[i] > k) chores[i] = k;
  cout << accumulate((chores).cbegin(), (chores).cend(), 0) << rt;
  return 0;
}

### Prompt

Your task is to create a CPP solution to the following problem:

Luba has to do n chores today. i-th chore takes ai units of time to complete. It is guaranteed that for every <image> the condition ai ≥ ai - 1 is met, so the sequence is sorted.

Also Luba can work really hard on some chores. She can choose not more than k any chores and do each of them in x units of time instead of ai (<image>).

Luba is very responsible, so she has to do all n chores, and now she wants to know the minimum time she needs to do everything. Luba cannot do two chores simultaneously.

Input

The first line contains three integers n, k, x (1 ≤ k ≤ n ≤ 100, 1 ≤ x ≤ 99) — the number of chores Luba has to do, the number of chores she can do in x units of time, and the number x itself.

The second line contains n integer numbers ai (2 ≤ ai ≤ 100) — the time Luba has to spend to do i-th chore.

It is guaranteed that <image>, and for each <image> ai ≥ ai - 1.

Output

Print one number — minimum time Luba needs to do all n chores.

Examples

Input

4 2 2
3 6 7 10


Output

13


Input

5 2 1
100 100 100 100 100


Output

302

Note

In the first example the best option would be to do the third and the fourth chore, spending x = 2 time on each instead of a3 and a4, respectively. Then the answer is 3 + 6 + 2 + 2 = 13.

In the second example Luba can choose any two chores to spend x time on them instead of ai. So the answer is 100·3 + 2·1 = 302.

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using VI = vector<int>;
using VL = vector<ll>;
using VS = vector<string>;
using VB = vector<bool>;
using VVB = vector<vector<bool>>;
using VVI = vector<VI>;
using VVL = vector<VL>;
using PII = std::pair<int, int>;
using VPII = std::vector<std::pair<int, int>>;
using PLL = std::pair<ll, ll>;
using VPLL = std::vector<std::pair<ll, ll>>;
using TI3 = std::tuple<int, int, int>;
using TI4 = std::tuple<int, int, int, int>;
using TL3 = std::tuple<ll, ll, ll>;
using TL4 = std::tuple<ll, ll, ll, ll>;
const int mod1 = 1e9 + 7, mod2 = 998244353, mod3 = 1e9 + 9;
const int mod = mod1;
const ll inf = 1e18;
const string wsp = " ";
const string tb = "\t";
const string rt = "\n";
template <typename T>
void show1dvec(const vector<T> &v) {
  if (v.size() == 0) return;
  int n = v.size() - 1;
  for (int i = 0; i < (int)(n); i++) cout << v[i] << wsp;
  cout << v[n] << rt;
  return;
}
template <typename T>
void show2dvec(const vector<vector<T>> &v) {
  int n = v.size();
  for (int i = 0; i < (int)(n); i++) show1dvec(v[i]);
}
template <typename T, typename S>
void show1dpair(const vector<pair<T, S>> &v) {
  int n = v.size();
  for (int i = 0; i < (int)(n); i++)
    cout << v[i].first << wsp << v[i].second << rt;
  return;
}
template <typename T, typename S>
void pairzip(const vector<pair<T, S>> &v, vector<T> &t, vector<T> &s) {
  int n = v.size();
  for (int i = 0; i < (int)(n); i++) {
    t.push_back(v[i].first);
    s.push_back(v[i].second);
  }
  return;
}
template <typename T>
void maxvec(vector<T> &v) {
  T s = v[0];
  int n = v.size();
  for (int i = 0; i < (int)(n - 1); i++) {
    if (s > v[i + 1]) {
      v[i + 1] = s;
    }
    s = v[i + 1];
  }
}
template <typename T, typename S>
bool myfind(T t, S s) {
  return find(t.cbegin(), t.cend(), s) != t.cend();
}
bool check(int y, int x, int h, int w) {
  return 0 <= y && y < h && 0 <= x && x < w;
}
template <typename T>
vector<T> cumsum(const vector<T> &v) {
  T s = 0;
  vector<T> ret;
  for (int i = 0; i < (int)(v.size()); i++) {
    s += v[i];
    s %= mod;
    ret.emplace_back(s);
  }
  return ret;
}
bool iskadomatsu(int a, int b, int c) {
  return (a != b && b != c && c != a) && ((a > b && b < c) || (a < b && b > c));
}
VS split(string s, char c) {
  VS ret;
  string part;
  s += c;
  for (int i = 0; i < (int)(s.length()); i++) {
    if (s[i] == c) {
      ret.emplace_back(part);
      part = "";
    } else if (s[i] != c) {
      part += s[i];
    }
  }
  return ret;
}
template <typename T, typename S, typename R>
ll pow_mod(T p, S q, R mod = 1ll) {
  ll ret = 1, r = p;
  while (q) {
    if (q % 2) ret *= r, ret %= mod;
    r = (r * r) % mod, q /= 2;
  }
  return ret % mod;
}
template <typename T, typename S>
ll pow_no_mod(T p, S q) {
  ll ret = 1, r = p;
  while (q) {
    if (q % 2) ret *= r;
    r = (r * r), q /= 2;
  }
  return ret;
}
void make_frac_tables(VL &frac_list, VL &frac_inv_list) {
  for (int i = 0; i < (int)(frac_list.size() - 1); i++) {
    frac_list[i + 1] *= frac_list[i] * (i + 1);
    frac_list[i + 1] %= mod;
    frac_inv_list[i + 1] *= frac_inv_list[i] * pow_mod(i + 1, mod - 2, mod);
    frac_inv_list[i + 1] %= mod;
  }
}
ll comb(int a, int b, const VL &frac_list, const VL &frac_inv_list) {
  if (a < b) return 0;
  if (b < 0) return 0;
  ll ret = frac_list[a];
  ret *= frac_inv_list[b];
  ret %= mod;
  ret *= frac_inv_list[a - b];
  ret %= mod;
  return ret;
}
const int maxint = 1e9;
VVI connective;
VI bfs(int v, int n) {
  VI shortest(n, 0), search{v}, new_search;
  VB used(n, false);
  used[v] = true;
  while (!search.empty()) {
    for (auto i : search) {
      for (auto j : connective[i]) {
        if (!used[j]) {
          shortest[j] = shortest[i] + 1;
          new_search.emplace_back(j);
          used[j] = true;
        }
      }
    }
    search.clear();
    search = new_search;
    new_search.clear();
  }
  return shortest;
}
int main() {
  cin.tie(0);
  ios::sync_with_stdio(false);
  int n, m, k;
  cin >> n >> m >> k;
  VI chores(n);
  for (int i = (int)(n)-1; i >= 0; i--) cin >> chores[i];
  for (int i = 0; i < (int)(m); i++)
    if (chores[i] > k) chores[i] = k;
  cout << accumulate((chores).cbegin(), (chores).cend(), 0) << rt;
  return 0;
}

```