#include <stdio.h>

int main() {
	int a,b,c,i,x,s;
	scanf("%d %d %d",&a,&b,&c);
	for(i=a;i<=b;i++)
	{
		x=c%i;
		if(x==0) {s++;continue;}
	}
	
	printf("%d\n",s);
}

### Prompt

Develop a solution in cpp to the problem described below:

How Many Divisors?

Write a program which reads three integers a, b and c, and prints the number of divisors of c between a and b.

Constraints

* 1 ≤ a, b, c ≤ 10000
* a ≤ b

Input

Three integers a, b and c are given in a line separated by a single space.

Output

Print the number of divisors in a line.

Example

Input

5 14 80


Output

3

### Response

```cpp
#include <stdio.h>

int main() {
	int a,b,c,i,x,s;
	scanf("%d %d %d",&a,&b,&c);
	for(i=a;i<=b;i++)
	{
		x=c%i;
		if(x==0) {s++;continue;}
	}
	
	printf("%d\n",s);
}

```