#include <cstdio>


int main(){
int i,n;
int c[100];

scanf("%d",&n);
for(i=0;i<n;i++) scanf("%d",&c[i]);
for(i=n;i>0;i--){
if(i!=n)printf(" ");
printf("%d",c[i-1]);
}
puts("");
return 0;
}
### Prompt

Please provide a cpp coded solution to the problem described below:

Write a program which reads a sequence and prints it in the reverse order.

Note

解説

Constraints

* n ≤ 100
* 0 ≤ ai < 1000

Input

The input is given in the following format:


n
a1 a2 . . . an


n is the size of the sequence and ai is the ith element of the sequence.

Output

Print the reversed sequence in a line. Print a single space character between adjacent elements (Note that your program should not put a space character after the last element).

Examples

Input

5
1 2 3 4 5


Output

5 4 3 2 1


Input

8
3 3 4 4 5 8 7 9


Output

9 7 8 5 4 4 3 3

### Response

```cpp
#include <cstdio>


int main(){
int i,n;
int c[100];

scanf("%d",&n);
for(i=0;i<n;i++) scanf("%d",&c[i]);
for(i=n;i>0;i--){
if(i!=n)printf(" ");
printf("%d",c[i-1]);
}
puts("");
return 0;
}
```