#include <bits/stdc++.h>
using namespace std;
int main() {
  string str;
  cin >> str;
  int n = str.size();
  int fl = 1;
  vector<char> v;
  for (int i = 0; i < str.size(); i++) {
    if (str[i] == '/') {
      while (str[i] == '/') {
        i++;
      }
      i--;
      v.push_back('/');
    } else {
      v.push_back(str[i]);
    }
  }
  for (int i = 0; i < v.size(); i++) {
    if (v[i] != '/') {
      fl = 0;
      break;
    }
  }
  if (fl == 1) {
    cout << "/" << endl;
  } else {
    int t = v.size();
    for (int i = 0; i < t; i++) {
      if (i == t - 1 && v[i] == '/') {
        continue;
      } else {
        cout << v[i];
      }
    }
  }
  return 0;
}

### Prompt

Please provide a cpp coded solution to the problem described below:

The new operating system BerOS has a nice feature. It is possible to use any number of characters '/' as a delimiter in path instead of one traditional '/'. For example, strings //usr///local//nginx/sbin// and /usr/local/nginx///sbin are equivalent. The character '/' (or some sequence of such characters) at the end of the path is required only in case of the path to the root directory, which can be represented as single character '/'.

A path called normalized if it contains the smallest possible number of characters '/'.

Your task is to transform a given path to the normalized form.

Input

The first line of the input contains only lowercase Latin letters and character '/' — the path to some directory. All paths start with at least one character '/'. The length of the given line is no more than 100 characters, it is not empty.

Output

The path in normalized form.

Examples

Input

//usr///local//nginx/sbin


Output

/usr/local/nginx/sbin

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  string str;
  cin >> str;
  int n = str.size();
  int fl = 1;
  vector<char> v;
  for (int i = 0; i < str.size(); i++) {
    if (str[i] == '/') {
      while (str[i] == '/') {
        i++;
      }
      i--;
      v.push_back('/');
    } else {
      v.push_back(str[i]);
    }
  }
  for (int i = 0; i < v.size(); i++) {
    if (v[i] != '/') {
      fl = 0;
      break;
    }
  }
  if (fl == 1) {
    cout << "/" << endl;
  } else {
    int t = v.size();
    for (int i = 0; i < t; i++) {
      if (i == t - 1 && v[i] == '/') {
        continue;
      } else {
        cout << v[i];
      }
    }
  }
  return 0;
}

```