#include <bits/stdc++.h>
using namespace std;
int main() {
  ios::sync_with_stdio(false);
  string sInput;
  bool isAllLine = true;
  int i;
  getline(cin, sInput);
  if (sInput.length() <= 1) {
    cout << sInput;
    goto endapp;
  }
  for (i = 0; i <= sInput.length() - 2; ++i) {
    if (sInput[i] == '/') {
      if (sInput[i + 1] == '/')
        continue;
      else
        cout << sInput[i];
    } else {
      isAllLine = false;
      cout << sInput[i];
    }
  }
  if (sInput[sInput.length() - 1] != '/' || isAllLine)
    cout << sInput[sInput.length() - 1];
endapp:
  return 0;
}

### Prompt

Please formulate a cpp solution to the following problem:

The new operating system BerOS has a nice feature. It is possible to use any number of characters '/' as a delimiter in path instead of one traditional '/'. For example, strings //usr///local//nginx/sbin// and /usr/local/nginx///sbin are equivalent. The character '/' (or some sequence of such characters) at the end of the path is required only in case of the path to the root directory, which can be represented as single character '/'.

A path called normalized if it contains the smallest possible number of characters '/'.

Your task is to transform a given path to the normalized form.

Input

The first line of the input contains only lowercase Latin letters and character '/' — the path to some directory. All paths start with at least one character '/'. The length of the given line is no more than 100 characters, it is not empty.

Output

The path in normalized form.

Examples

Input

//usr///local//nginx/sbin


Output

/usr/local/nginx/sbin

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  ios::sync_with_stdio(false);
  string sInput;
  bool isAllLine = true;
  int i;
  getline(cin, sInput);
  if (sInput.length() <= 1) {
    cout << sInput;
    goto endapp;
  }
  for (i = 0; i <= sInput.length() - 2; ++i) {
    if (sInput[i] == '/') {
      if (sInput[i + 1] == '/')
        continue;
      else
        cout << sInput[i];
    } else {
      isAllLine = false;
      cout << sInput[i];
    }
  }
  if (sInput[sInput.length() - 1] != '/' || isAllLine)
    cout << sInput[sInput.length() - 1];
endapp:
  return 0;
}

```