#include<bits/stdc++.h>
using namespace std;

int main(){
	int num, total=0;

	cin>>num;

	while(num){
		total += (num%10);
		num = num/10;
	}

	cout<<(total == 1 ? 10 : total)<<'\n';

	return 0;
}
### Prompt

Develop a solution in CPP to the problem described below:

Takahashi has two positive integers A and B.

It is known that A plus B equals N. Find the minimum possible value of "the sum of the digits of A" plus "the sum of the digits of B" (in base 10).

Constraints

* 2 ≤ N ≤ 10^5
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the minimum possible value of "the sum of the digits of A" plus "the sum of the digits of B".

Examples

Input

15


Output

6


Input

100000


Output

10

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;

int main(){
	int num, total=0;

	cin>>num;

	while(num){
		total += (num%10);
		num = num/10;
	}

	cout<<(total == 1 ? 10 : total)<<'\n';

	return 0;
}
```