#include<stdio.h>

int main()
{
int a,b,c;
int i,div=0;

scanf("%d %d %d",&a,&b,&c);

for(i=a;i<=b;i++)
 {
 if((c/i*i)==c)div++;
 }

printf("%d\n",div);
}
### Prompt

Please provide a cpp coded solution to the problem described below:

How Many Divisors?

Write a program which reads three integers a, b and c, and prints the number of divisors of c between a and b.

Constraints

* 1 ≤ a, b, c ≤ 10000
* a ≤ b

Input

Three integers a, b and c are given in a line separated by a single space.

Output

Print the number of divisors in a line.

Example

Input

5 14 80


Output

3

### Response

```cpp
#include<stdio.h>

int main()
{
int a,b,c;
int i,div=0;

scanf("%d %d %d",&a,&b,&c);

for(i=a;i<=b;i++)
 {
 if((c/i*i)==c)div++;
 }

printf("%d\n",div);
}
```