#include <bits/stdc++.h>
using namespace std;

int main(){
  int s;
  cin>>s;
  if((s==0||s>=1300)&&(s%100>12||s%100==0)) cout<<"NA";
  if(s>99&&s<1300&&s%100<13&&s%100!=0) cout<<"AMBIGUOUS";
  if(s>0&&s<1300&&(s%100>12||s%100==0)) cout<<"MMYY";
  if(((s>0&&s<13)||s>=1300)&&s%100<13&&s%100>0) cout<<"YYMM";
}
### Prompt

Develop a solution in cpp to the problem described below:

You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

* YYMM format: the last two digits of the year and the two-digit representation of the month (example: `01` for January), concatenated in this order
* MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order



If S is valid in only YYMM format, print `YYMM`; if S is valid in only MMYY format, print `MMYY`; if S is valid in both formats, print `AMBIGUOUS`; if S is valid in neither format, print `NA`.

Constraints

* S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:


S


Output

Print the specified string: `YYMM`, `MMYY`, `AMBIGUOUS` or `NA`.

Examples

Input

1905


Output

YYMM


Input

0112


Output

AMBIGUOUS


Input

1700


Output

NA

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;

int main(){
  int s;
  cin>>s;
  if((s==0||s>=1300)&&(s%100>12||s%100==0)) cout<<"NA";
  if(s>99&&s<1300&&s%100<13&&s%100!=0) cout<<"AMBIGUOUS";
  if(s>0&&s<1300&&(s%100>12||s%100==0)) cout<<"MMYY";
  if(((s>0&&s<13)||s>=1300)&&s%100<13&&s%100>0) cout<<"YYMM";
}
```