#include<iostream>
#include<cstdio>
#include<vector>

using namespace std;

int w,h;
int ans=1;
char tile[21][21];

void saiki(int x,int y){
	if(x<0 | x>h | y<0 | y>w)return;
	tile[x][y]='#';
	if(tile[x-1][y]=='.')ans++,saiki(x-1,y);
	if(tile[x+1][y]=='.')ans++,saiki(x+1,y);
	if(tile[x][y-1]=='.')ans++,saiki(x,y-1);
	if(tile[x][y+1]=='.')ans++,saiki(x,y+1);
}

int main(void){
	int a,b; 
	while(1){
		for(a=0;a<21;a++){
			for(b=0;b<21;b++){
				tile[a][b]='\0';
			}
		}
		scanf("%d %d",&w,&h);
		if(w==0 && h==0)break;
		ans=1;
		for(a=0;a<h;a++){
			scanf("%s",tile[a]);
		}
		for(a=0;a<h;a++){
			for(b=0;b<w;b++){
				if(tile[a][b]=='@')saiki(a,b);
			}
		}
		printf("%d\n",ans);
	}
	return 0;
}
### Prompt

Your task is to create a CPP solution to the following problem:

There is a rectangular room, covered with square tiles. Each tile is colored either red or black. A man is standing on a black tile. From a tile, he can move to one of four adjacent tiles. But he can't move on red tiles, he can move only on black tiles.

Write a program to count the number of black tiles which he can reach by repeating the moves described above.



Input

The input consists of multiple data sets. A data set starts with a line containing two positive integers W and H; W and H are the numbers of tiles in the x- and y- directions, respectively. W and H are not more than 20.

There are H more lines in the data set, each of which includes W characters. Each character represents the color of a tile as follows.

* '.' - a black tile
* '#' - a red tile
* '@' - a man on a black tile(appears exactly once in a data set)


The end of the input is indicated by a line consisting of two zeros.

Output

For each data set, your program should output a line which contains the number of tiles he can reach from the initial tile (including itself).

Examples

Input

6 9
....#.
.....#
......
......
......
......
......
#@...#
.#..#.
11 9
.#.........
.#.#######.
.#.#.....#.
.#.#.###.#.
.#.#..@#.#.
.#.#####.#.
.#.......#.
.#########.
...........
11 6
..#..#..#..
..#..#..#..
..#..#..###
..#..#..#@.
..#..#..#..
..#..#..#..
7 7
..#.#..
..#.#..
###.###
...@...
###.###
..#.#..
..#.#..
0 0


Output

45
59
6
13


Input

6 9
....#.
.....#
......
......
......
......
......
@...#
.#..#.
11 9
.#.........
.#.#######.
.#.#.....#.
.#.#.###.#.
.#.#..@#.#.
.#.#####.#.
.#.......#.
.#########.
...........
11 6
..#..#..#..
..#..#..#..
..#..#..###
..#..#..#@.
..#..#..#..
..#..#..#..
7 7
..#.#..
..#.#..
.###
...@...
.###
..#.#..
..#.#..
0 0


Output

45
59
6
13

### Response

```cpp
#include<iostream>
#include<cstdio>
#include<vector>

using namespace std;

int w,h;
int ans=1;
char tile[21][21];

void saiki(int x,int y){
	if(x<0 | x>h | y<0 | y>w)return;
	tile[x][y]='#';
	if(tile[x-1][y]=='.')ans++,saiki(x-1,y);
	if(tile[x+1][y]=='.')ans++,saiki(x+1,y);
	if(tile[x][y-1]=='.')ans++,saiki(x,y-1);
	if(tile[x][y+1]=='.')ans++,saiki(x,y+1);
}

int main(void){
	int a,b; 
	while(1){
		for(a=0;a<21;a++){
			for(b=0;b<21;b++){
				tile[a][b]='\0';
			}
		}
		scanf("%d %d",&w,&h);
		if(w==0 && h==0)break;
		ans=1;
		for(a=0;a<h;a++){
			scanf("%s",tile[a]);
		}
		for(a=0;a<h;a++){
			for(b=0;b<w;b++){
				if(tile[a][b]=='@')saiki(a,b);
			}
		}
		printf("%d\n",ans);
	}
	return 0;
}
```