#include <cstdio>
int main(){
	int n;
	int a[101];
	scanf("%d",&n);
	for(int i=0;i<n;i++) scanf("%d",&a[i]);
	while(n>1){ printf("%d ",a[n-1]); n--; }
	printf("%d\n",a[0]);
}


### Prompt

Please provide a Cpp coded solution to the problem described below:

Write a program which reads a sequence and prints it in the reverse order.

Note

解説

Constraints

* n ≤ 100
* 0 ≤ ai < 1000

Input

The input is given in the following format:


n
a1 a2 . . . an


n is the size of the sequence and ai is the ith element of the sequence.

Output

Print the reversed sequence in a line. Print a single space character between adjacent elements (Note that your program should not put a space character after the last element).

Examples

Input

5
1 2 3 4 5


Output

5 4 3 2 1


Input

8
3 3 4 4 5 8 7 9


Output

9 7 8 5 4 4 3 3

### Response

```cpp
#include <cstdio>
int main(){
	int n;
	int a[101];
	scanf("%d",&n);
	for(int i=0;i<n;i++) scanf("%d",&a[i]);
	while(n>1){ printf("%d ",a[n-1]); n--; }
	printf("%d\n",a[0]);
}


```