#include<stdio.h>
int main(void)
{
int a,b,c;
int count;
int i;
scanf("%d %d %d",&a,&b,&c);

for(i=a;i<=b;i++)
{
if(c%i==0) count++;
}

printf("%d\n",count);

return 0;
}
### Prompt

Please provide a cpp coded solution to the problem described below:

How Many Divisors?

Write a program which reads three integers a, b and c, and prints the number of divisors of c between a and b.

Constraints

* 1 ≤ a, b, c ≤ 10000
* a ≤ b

Input

Three integers a, b and c are given in a line separated by a single space.

Output

Print the number of divisors in a line.

Example

Input

5 14 80


Output

3

### Response

```cpp
#include<stdio.h>
int main(void)
{
int a,b,c;
int count;
int i;
scanf("%d %d %d",&a,&b,&c);

for(i=a;i<=b;i++)
{
if(c%i==0) count++;
}

printf("%d\n",count);

return 0;
}
```