#include <bits/stdc++.h>
using namespace std;
int main() {
  string cadena, salida;
  int aux = 0;
  cin >> cadena;
  for (int i = 0; i < cadena.length(); i++) {
    if (cadena[i] == '/' && aux == 0) {
      aux++;
      salida += cadena[i];
    } else if (cadena[i] != '/') {
      aux = 0;
      salida += cadena[i];
    } else if (cadena[i] == '/' && aux > 0) {
      cadena[i] = ' ';
    }
  }
  int longitud = salida.length();
  if (salida[longitud - 1] == '/' && longitud > 1) {
    salida[longitud - 1] = ' ';
  }
  cout << salida << endl;
  return 0;
}

### Prompt

Please provide a cpp coded solution to the problem described below:

The new operating system BerOS has a nice feature. It is possible to use any number of characters '/' as a delimiter in path instead of one traditional '/'. For example, strings //usr///local//nginx/sbin// and /usr/local/nginx///sbin are equivalent. The character '/' (or some sequence of such characters) at the end of the path is required only in case of the path to the root directory, which can be represented as single character '/'.

A path called normalized if it contains the smallest possible number of characters '/'.

Your task is to transform a given path to the normalized form.

Input

The first line of the input contains only lowercase Latin letters and character '/' — the path to some directory. All paths start with at least one character '/'. The length of the given line is no more than 100 characters, it is not empty.

Output

The path in normalized form.

Examples

Input

//usr///local//nginx/sbin


Output

/usr/local/nginx/sbin

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  string cadena, salida;
  int aux = 0;
  cin >> cadena;
  for (int i = 0; i < cadena.length(); i++) {
    if (cadena[i] == '/' && aux == 0) {
      aux++;
      salida += cadena[i];
    } else if (cadena[i] != '/') {
      aux = 0;
      salida += cadena[i];
    } else if (cadena[i] == '/' && aux > 0) {
      cadena[i] = ' ';
    }
  }
  int longitud = salida.length();
  if (salida[longitud - 1] == '/' && longitud > 1) {
    salida[longitud - 1] = ' ';
  }
  cout << salida << endl;
  return 0;
}

```