#include<stdio.h>
int main()
{
    int i,a,b,c,n=0;
    scanf("%d %d %d",&a,&b,&c);
    for (i=a;i<=b;i++)
    {
        if (c%i==0) n++;
    }
    printf("%d\n",n);

}


### Prompt

Develop a solution in cpp to the problem described below:

How Many Divisors?

Write a program which reads three integers a, b and c, and prints the number of divisors of c between a and b.

Constraints

* 1 ≤ a, b, c ≤ 10000
* a ≤ b

Input

Three integers a, b and c are given in a line separated by a single space.

Output

Print the number of divisors in a line.

Example

Input

5 14 80


Output

3

### Response

```cpp
#include<stdio.h>
int main()
{
    int i,a,b,c,n=0;
    scanf("%d %d %d",&a,&b,&c);
    for (i=a;i<=b;i++)
    {
        if (c%i==0) n++;
    }
    printf("%d\n",n);

}


```