#include <bits/stdc++.h>
using namespace std;
int main() {
  string s;
  cin >> s;
  stringstream ss;
  bool IsPrevSlash = false;
  for (int i = 0; i < (s.size()); ++i) {
    if (s[i] != '/') {
      IsPrevSlash = false;
      ss << s[i];
    } else {
      if (!IsPrevSlash) {
        IsPrevSlash = true;
        ss << s[i];
      }
    }
  }
  string res;
  ss >> res;
  if (res.size() == 1 && res[0] == '/') {
    cout << "/" << endl;
    return 0;
  }
  for (int i = 0; i < (res.size()); ++i) {
    if (!(i == res.size() - 1 && res[i] == '/')) {
      cout << res[i];
    }
  }
  cout << endl;
  return 0;
}

### Prompt

In CPP, your task is to solve the following problem:

The new operating system BerOS has a nice feature. It is possible to use any number of characters '/' as a delimiter in path instead of one traditional '/'. For example, strings //usr///local//nginx/sbin// and /usr/local/nginx///sbin are equivalent. The character '/' (or some sequence of such characters) at the end of the path is required only in case of the path to the root directory, which can be represented as single character '/'.

A path called normalized if it contains the smallest possible number of characters '/'.

Your task is to transform a given path to the normalized form.

Input

The first line of the input contains only lowercase Latin letters and character '/' — the path to some directory. All paths start with at least one character '/'. The length of the given line is no more than 100 characters, it is not empty.

Output

The path in normalized form.

Examples

Input

//usr///local//nginx/sbin


Output

/usr/local/nginx/sbin

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  string s;
  cin >> s;
  stringstream ss;
  bool IsPrevSlash = false;
  for (int i = 0; i < (s.size()); ++i) {
    if (s[i] != '/') {
      IsPrevSlash = false;
      ss << s[i];
    } else {
      if (!IsPrevSlash) {
        IsPrevSlash = true;
        ss << s[i];
      }
    }
  }
  string res;
  ss >> res;
  if (res.size() == 1 && res[0] == '/') {
    cout << "/" << endl;
    return 0;
  }
  for (int i = 0; i < (res.size()); ++i) {
    if (!(i == res.size() - 1 && res[i] == '/')) {
      cout << res[i];
    }
  }
  cout << endl;
  return 0;
}

```