#include <stdio.h>

int main(){
  int a[4], b[4];
  while(scanf("%d%d%d%d%d%d%d%d", a,a+1,a+2,a+3,b,b+1,b+2,b+3)!=EOF){
    int x[10];
    int i;
    for(i=0;i<10;i++) x[i] = 0;

    for(i=0;i<4;i++) x[a[i]] = i+1;

    int hit=0, blow=0;

    for(i=0;i<4;i++){
      if(x[b[i]]){
        if(x[b[i]] == i+1) hit++;
        else blow++;
      }
    }
    printf("%d %d\n", hit, blow);
  }
}
      
### Prompt

Your challenge is to write a CPP solution to the following problem:

Let's play Hit and Blow game. A imagines four numbers and B guesses the numbers. After B picks out four numbers, A answers:

* The number of numbers which have the same place with numbers A imagined (Hit)
* The number of numbers included (but different place) in the numbers A imagined (Blow)



For example, if A imagined numbers:


9 1 8 2


and B chose:


4 1 5 9


A should say 1 Hit and 1 Blow.

Write a program which reads four numbers A imagined and four numbers B chose and prints the number of Hit and Blow respectively. You may assume that the four numbers are all different and within from 0 to 9.



Input

The input consists of multiple datasets. Each dataset set consists of:


a1 a2 a3 a4
b1 b2 b3 b4


, where ai (0 ≤ ai ≤ 9) is i-th number A imagined and bi (0 ≤ bi ≤ 9) is i-th number B chose.

The input ends with EOF. The number of datasets is less than or equal to 50.

Output

For each dataset, print the number of Hit and Blow in a line. These two numbers should be separated by a space.

Example

Input

9 1 8 2
4 1 5 9
4 6 8 2
4 6 3 2


Output

1 1
3 0

### Response

```cpp
#include <stdio.h>

int main(){
  int a[4], b[4];
  while(scanf("%d%d%d%d%d%d%d%d", a,a+1,a+2,a+3,b,b+1,b+2,b+3)!=EOF){
    int x[10];
    int i;
    for(i=0;i<10;i++) x[i] = 0;

    for(i=0;i<4;i++) x[a[i]] = i+1;

    int hit=0, blow=0;

    for(i=0;i<4;i++){
      if(x[b[i]]){
        if(x[b[i]] == i+1) hit++;
        else blow++;
      }
    }
    printf("%d %d\n", hit, blow);
  }
}
      
```