#include<bits/stdc++.h>
using namespace std;
using ll = long long;

#define FOR(i,a,b) for(ll i=(a);i<(b);++i)
#define ALL(v) (v).begin(), (v).end()
#define p(s) cout<<(s)<<endl
#define p2(s, t) cout << (s) << " " << (t) << endl
#define br() p("")
#define pn(s) cout << (#s) << " " << (s) << endl

void vprint(vector<ll> A){
    if(A.size()==0){
        p("");
    }else{
        cout << A[0];
        FOR(i, 1, A.size()){
            cout << " " << A[i];
        }
        cout << endl;
    }
}

int main(){
    cin.tie(0);
    ios::sync_with_stdio(false);

    // input
    ll N, Q;
    cin >> N >> Q;

    queue<ll> que[N];

    while(Q--){
        ll a;
        cin >> a;
        ll t, x;

        // enq
        if(a==0){
            cin >> t >> x;
            que[t].push(x);
        }
        // front
        else if(a==1){
            cin >> t;
            if(que[t].size()>0){
                p(que[t].front());
            }
        }
        // deq
        else{
            cin >> t;
            if(que[t].size()>0){
                que[t].pop();
            }
        }
    }
    
    return 0;
}

### Prompt

Your challenge is to write a Cpp solution to the following problem:

Queue is a container of elements that are inserted and deleted according to FIFO (First In First Out).

For $n$ queues $Q_i$ ($i = 0, 1, ..., n-1$), perform a sequence of the following operations.

* enqueue($t$, $x$): Insert an integer $x$ to $Q_t$.
* front($t$): Report the value which should be deleted next from $Q_t$. If $Q_t$ is empty, do nothing.
* dequeue($t$): Delete an element from $Q_t$. If $Q_t$ is empty, do nothing.



In the initial state, all queues are empty.

Constraints

* $1 \leq n \leq 1,000$
* $1 \leq q \leq 200,000$
* $-1,000,000,000 \leq x \leq 1,000,000,000$

Input

The input is given in the following format.


$n \; q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $t$ $x$


or


1 $t$


or


2 $t$


where the first digits 0, 1 and 2 represent enqueue, front and dequeue operations respectively.

Output

For each front operation, print an integer in a line.

Example

Input

3 9
0 0 1
0 0 2
0 0 3
0 2 4
0 2 5
1 0
1 2
2 0
1 0


Output

1
4
2

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;
using ll = long long;

#define FOR(i,a,b) for(ll i=(a);i<(b);++i)
#define ALL(v) (v).begin(), (v).end()
#define p(s) cout<<(s)<<endl
#define p2(s, t) cout << (s) << " " << (t) << endl
#define br() p("")
#define pn(s) cout << (#s) << " " << (s) << endl

void vprint(vector<ll> A){
    if(A.size()==0){
        p("");
    }else{
        cout << A[0];
        FOR(i, 1, A.size()){
            cout << " " << A[i];
        }
        cout << endl;
    }
}

int main(){
    cin.tie(0);
    ios::sync_with_stdio(false);

    // input
    ll N, Q;
    cin >> N >> Q;

    queue<ll> que[N];

    while(Q--){
        ll a;
        cin >> a;
        ll t, x;

        // enq
        if(a==0){
            cin >> t >> x;
            que[t].push(x);
        }
        // front
        else if(a==1){
            cin >> t;
            if(que[t].size()>0){
                p(que[t].front());
            }
        }
        // deq
        else{
            cin >> t;
            if(que[t].size()>0){
                que[t].pop();
            }
        }
    }
    
    return 0;
}

```