#include<bits/stdc++.h>
using namespace std;

int main(){
    int n,total=0;

    cin>>n;

    while(n){
        total += n%10;
        n = n/10;
    }

    if(total==1)
        cout<<10<<endl;
    else
        cout<<total<<endl;

    return 0;
}
### Prompt

Create a solution in cpp for the following problem:

Takahashi has two positive integers A and B.

It is known that A plus B equals N. Find the minimum possible value of "the sum of the digits of A" plus "the sum of the digits of B" (in base 10).

Constraints

* 2 ≤ N ≤ 10^5
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the minimum possible value of "the sum of the digits of A" plus "the sum of the digits of B".

Examples

Input

15


Output

6


Input

100000


Output

10

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;

int main(){
    int n,total=0;

    cin>>n;

    while(n){
        total += n%10;
        n = n/10;
    }

    if(total==1)
        cout<<10<<endl;
    else
        cout<<total<<endl;

    return 0;
}
```