#include<stdio.h>
 
int main(){
  int a,b,c,i,z=0;
  scanf("%d %d %d",&a,&b,&c);
  for(i=a;i<=b;i++)
    if(c%i==0)
      z+=1;
  printf("%d\n",z);
    return 0;
}
### Prompt

Please formulate a cpp solution to the following problem:

How Many Divisors?

Write a program which reads three integers a, b and c, and prints the number of divisors of c between a and b.

Constraints

* 1 ≤ a, b, c ≤ 10000
* a ≤ b

Input

Three integers a, b and c are given in a line separated by a single space.

Output

Print the number of divisors in a line.

Example

Input

5 14 80


Output

3

### Response

```cpp
#include<stdio.h>
 
int main(){
  int a,b,c,i,z=0;
  scanf("%d %d %d",&a,&b,&c);
  for(i=a;i<=b;i++)
    if(c%i==0)
      z+=1;
  printf("%d\n",z);
    return 0;
}
```