#include<stdio.h>
 
int main(void){
  int a,b,c,cnt=0;
 
  scanf("%d%d%d",&a,&b,&c);
  for(;a<=b;a++){
    cnt+=c%a?0:1;
  }
  printf("%d\n",cnt);
  return 0;
}
### Prompt

Construct a Cpp code solution to the problem outlined:

How Many Divisors?

Write a program which reads three integers a, b and c, and prints the number of divisors of c between a and b.

Constraints

* 1 ≤ a, b, c ≤ 10000
* a ≤ b

Input

Three integers a, b and c are given in a line separated by a single space.

Output

Print the number of divisors in a line.

Example

Input

5 14 80


Output

3

### Response

```cpp
#include<stdio.h>
 
int main(void){
  int a,b,c,cnt=0;
 
  scanf("%d%d%d",&a,&b,&c);
  for(;a<=b;a++){
    cnt+=c%a?0:1;
  }
  printf("%d\n",cnt);
  return 0;
}
```