#include "bits/stdc++.h"
using namespace std;

int main() {
    int n = 0, ans = 0;
    cin >> n;
    if(n%10){
        while(n){
            ans += n%10;
            n /= 10;
        }
    }
    else ans = 10;
    printf("%d\n", ans);
    return 0;
}
### Prompt

Your task is to create a Cpp solution to the following problem:

Takahashi has two positive integers A and B.

It is known that A plus B equals N. Find the minimum possible value of "the sum of the digits of A" plus "the sum of the digits of B" (in base 10).

Constraints

* 2 ≤ N ≤ 10^5
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the minimum possible value of "the sum of the digits of A" plus "the sum of the digits of B".

Examples

Input

15


Output

6


Input

100000


Output

10

### Response

```cpp
#include "bits/stdc++.h"
using namespace std;

int main() {
    int n = 0, ans = 0;
    cin >> n;
    if(n%10){
        while(n){
            ans += n%10;
            n /= 10;
        }
    }
    else ans = 10;
    printf("%d\n", ans);
    return 0;
}
```