#include <cstdio>
int n,s=0;
int main(){
 scanf("%d",&n);
 while(n>0){
  s+=n%10;
  n/=10;
 }
 printf("%d",s==1?10:s);
}
### Prompt

Please create a solution in Cpp to the following problem:

Takahashi has two positive integers A and B.

It is known that A plus B equals N. Find the minimum possible value of "the sum of the digits of A" plus "the sum of the digits of B" (in base 10).

Constraints

* 2 ≤ N ≤ 10^5
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the minimum possible value of "the sum of the digits of A" plus "the sum of the digits of B".

Examples

Input

15


Output

6


Input

100000


Output

10

### Response

```cpp
#include <cstdio>
int n,s=0;
int main(){
 scanf("%d",&n);
 while(n>0){
  s+=n%10;
  n/=10;
 }
 printf("%d",s==1?10:s);
}
```