#include<stdio.h>

int main(void)
{

 int a,b,c,d,e;

 e=0;

 scanf("%d %d %d",&a,&b,&c);

 for(d=a;d<=b;d++)
{
 if(c%d==0)
  {e++;}
}

printf("%d\n",e);
return 0;
}


### Prompt

Develop a solution in cpp to the problem described below:

How Many Divisors?

Write a program which reads three integers a, b and c, and prints the number of divisors of c between a and b.

Constraints

* 1 ≤ a, b, c ≤ 10000
* a ≤ b

Input

Three integers a, b and c are given in a line separated by a single space.

Output

Print the number of divisors in a line.

Example

Input

5 14 80


Output

3

### Response

```cpp
#include<stdio.h>

int main(void)
{

 int a,b,c,d,e;

 e=0;

 scanf("%d %d %d",&a,&b,&c);

 for(d=a;d<=b;d++)
{
 if(c%d==0)
  {e++;}
}

printf("%d\n",e);
return 0;
}


```