#include<stdio.h>

int main(void){
int n,i;
scanf("%d",&n);
int a[n];

for(i=1;i<=n;i++){
	scanf("%d",&a[i]);
}

for(i=n;i>1;i--){
printf("%d ",a[i]);
}

printf("%d\n",a[1]);


return 0;
}

### Prompt

Please provide a Cpp coded solution to the problem described below:

Write a program which reads a sequence and prints it in the reverse order.

Note

解説

Constraints

* n ≤ 100
* 0 ≤ ai < 1000

Input

The input is given in the following format:


n
a1 a2 . . . an


n is the size of the sequence and ai is the ith element of the sequence.

Output

Print the reversed sequence in a line. Print a single space character between adjacent elements (Note that your program should not put a space character after the last element).

Examples

Input

5
1 2 3 4 5


Output

5 4 3 2 1


Input

8
3 3 4 4 5 8 7 9


Output

9 7 8 5 4 4 3 3

### Response

```cpp
#include<stdio.h>

int main(void){
int n,i;
scanf("%d",&n);
int a[n];

for(i=1;i<=n;i++){
	scanf("%d",&a[i]);
}

for(i=n;i>1;i--){
printf("%d ",a[i]);
}

printf("%d\n",a[1]);


return 0;
}

```