#include <bits/stdc++.h>
using namespace std;
int main() {
	int n;cin >> n;
  	int ans = 0;
  	if (n==10||n==100||n==1000||n==10000||n==100000) ans = 10;
  	else while(n) {
    	ans += n%10;
      	n/=10;
    }
  	cout << ans << endl;
}
### Prompt

Please create a solution in Cpp to the following problem:

Takahashi has two positive integers A and B.

It is known that A plus B equals N. Find the minimum possible value of "the sum of the digits of A" plus "the sum of the digits of B" (in base 10).

Constraints

* 2 ≤ N ≤ 10^5
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the minimum possible value of "the sum of the digits of A" plus "the sum of the digits of B".

Examples

Input

15


Output

6


Input

100000


Output

10

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
	int n;cin >> n;
  	int ans = 0;
  	if (n==10||n==100||n==1000||n==10000||n==100000) ans = 10;
  	else while(n) {
    	ans += n%10;
      	n/=10;
    }
  	cout << ans << endl;
}
```