#include <cstdio>

int n;
int a[101];

int main(){
	scanf("%d", &n);
	for(int i=0; i<n; ++i){
		scanf("%d", &a[i]);
	}
	
	for(int i=n-1; i>0; --i){
		printf("%d ", a[i]);
	}
	printf("%d\n", a[0]);
}

### Prompt

Your challenge is to write a Cpp solution to the following problem:

Write a program which reads a sequence and prints it in the reverse order.

Note

解説

Constraints

* n ≤ 100
* 0 ≤ ai < 1000

Input

The input is given in the following format:


n
a1 a2 . . . an


n is the size of the sequence and ai is the ith element of the sequence.

Output

Print the reversed sequence in a line. Print a single space character between adjacent elements (Note that your program should not put a space character after the last element).

Examples

Input

5
1 2 3 4 5


Output

5 4 3 2 1


Input

8
3 3 4 4 5 8 7 9


Output

9 7 8 5 4 4 3 3

### Response

```cpp
#include <cstdio>

int n;
int a[101];

int main(){
	scanf("%d", &n);
	for(int i=0; i<n; ++i){
		scanf("%d", &a[i]);
	}
	
	for(int i=n-1; i>0; --i){
		printf("%d ", a[i]);
	}
	printf("%d\n", a[0]);
}

```