#include <iostream>
using namespace std;
int main(void){

int a[1000];
int n;

cin>>n;
int i;
for(i=0;i<=n;i=i+1)
{cin>>a[i];}

int j;
for(j=n-1;j>-1;j=j-1){
cout<<a[j];
if(j>0) {cout<<" ";}
if(j==0){cout<<endl;}
}
}




### Prompt

Please create a solution in CPP to the following problem:

Write a program which reads a sequence and prints it in the reverse order.

Note

解説

Constraints

* n ≤ 100
* 0 ≤ ai < 1000

Input

The input is given in the following format:


n
a1 a2 . . . an


n is the size of the sequence and ai is the ith element of the sequence.

Output

Print the reversed sequence in a line. Print a single space character between adjacent elements (Note that your program should not put a space character after the last element).

Examples

Input

5
1 2 3 4 5


Output

5 4 3 2 1


Input

8
3 3 4 4 5 8 7 9


Output

9 7 8 5 4 4 3 3

### Response

```cpp
#include <iostream>
using namespace std;
int main(void){

int a[1000];
int n;

cin>>n;
int i;
for(i=0;i<=n;i=i+1)
{cin>>a[i];}

int j;
for(j=n-1;j>-1;j=j-1){
cout<<a[j];
if(j>0) {cout<<" ";}
if(j==0){cout<<endl;}
}
}




```