#include<cstdio>

int main(){
	int n;
	scanf("%d ",&n);
	int a[n];
	for(int i=0;i<n;i++) scanf("%d",&a[i]);
	for(int i=0;i<n;i++){
		if(i!=n-1)	printf("%d ",a[n-1-i]);
		else printf("%d", a[n-1-i]);
	}
	printf("\n");
}


### Prompt

Your task is to create a cpp solution to the following problem:

Write a program which reads a sequence and prints it in the reverse order.

Note

解説

Constraints

* n ≤ 100
* 0 ≤ ai < 1000

Input

The input is given in the following format:


n
a1 a2 . . . an


n is the size of the sequence and ai is the ith element of the sequence.

Output

Print the reversed sequence in a line. Print a single space character between adjacent elements (Note that your program should not put a space character after the last element).

Examples

Input

5
1 2 3 4 5


Output

5 4 3 2 1


Input

8
3 3 4 4 5 8 7 9


Output

9 7 8 5 4 4 3 3

### Response

```cpp
#include<cstdio>

int main(){
	int n;
	scanf("%d ",&n);
	int a[n];
	for(int i=0;i<n;i++) scanf("%d",&a[i]);
	for(int i=0;i<n;i++){
		if(i!=n-1)	printf("%d ",a[n-1-i]);
		else printf("%d", a[n-1-i]);
	}
	printf("\n");
}


```