#include<stdio.h>
int main(){
int n=0, x;

	scanf("%d", &x);
	for(n=0;n<x;n+=1000){
	n;
	}
printf("%d", n-x);



return 0;
}
### Prompt

Create a solution in cpp for the following problem:

We will buy a product for N yen (the currency of Japan) at a shop.

If we use only 1000-yen bills to pay the price, how much change will we receive?

Assume we use the minimum number of bills required.

Constraints

* 1 \leq N \leq 10000
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the amount of change as an integer.

Examples

Input

1900


Output

100


Input

3000


Output

0

### Response

```cpp
#include<stdio.h>
int main(){
int n=0, x;

	scanf("%d", &x);
	for(n=0;n<x;n+=1000){
	n;
	}
printf("%d", n-x);



return 0;
}
```