#include<stdio.h>

int main(){
  int a,b,c,count=0;
  scanf("%d %d %d", &a, &b, &c);
  for(int i=a; i <= b; i++){
    if(c%i == 0)count++;
  }
  printf("%d\n",count);
}


### Prompt

Construct a Cpp code solution to the problem outlined:

How Many Divisors?

Write a program which reads three integers a, b and c, and prints the number of divisors of c between a and b.

Constraints

* 1 ≤ a, b, c ≤ 10000
* a ≤ b

Input

Three integers a, b and c are given in a line separated by a single space.

Output

Print the number of divisors in a line.

Example

Input

5 14 80


Output

3

### Response

```cpp
#include<stdio.h>

int main(){
  int a,b,c,count=0;
  scanf("%d %d %d", &a, &b, &c);
  for(int i=a; i <= b; i++){
    if(c%i == 0)count++;
  }
  printf("%d\n",count);
}


```