#include <algorithm>
#include <cmath>
#include <deque>
#include <iomanip>
#include <iostream>
#include <map>
#include <numeric>
#include <queue>
#include <set>
#include <stack>
#include <string>
#include <utility>
#include <vector>
using ll = long long;
#define rep(i, n) for (int i = 0; i < n; i++)
#define repk(i, k, n) for (int i = k; i < n; i++)
#define MOD 1000000007
#define INF 1e9
#define PIE 3.14159265358979323

template <class T>
inline bool chmin(T &a, T b) {
    if (a > b) {
        a = b;
        return true;
    }
    return false;
}
template <class T>
inline bool chmax(T &a, T b) {
    if (a < b) {
        a = b;
        return true;
    }
    return false;
}
template <class T>
T GCD(T a, T b) {
    if (b == 0)
        return a;
    else
        return GCD(b, a % b);
}
template <class T>
inline T LCM(T a, T b) {
    return (a * b) / GCD(a, b);
}

using namespace std;
//#inculude <bits/stdc++.h>
//#define int long long

signed main() {
    int n, q;
    cin >> n >> q;
    vector<queue<int>> que(n);
    int k, t, x;
    rep(i, q) {
        cin >> k >> t;
        if (k == 0) {
            cin >> x;
            que[t].push(x);
        }
        else if (k == 1) {
            if (!que[t].empty())
                cout << que[t].front() << endl;
        }
        else {
            if (!que[t].empty())
                que[t].pop();
        }
    }
}

### Prompt

Your challenge is to write a cpp solution to the following problem:

Queue is a container of elements that are inserted and deleted according to FIFO (First In First Out).

For $n$ queues $Q_i$ ($i = 0, 1, ..., n-1$), perform a sequence of the following operations.

* enqueue($t$, $x$): Insert an integer $x$ to $Q_t$.
* front($t$): Report the value which should be deleted next from $Q_t$. If $Q_t$ is empty, do nothing.
* dequeue($t$): Delete an element from $Q_t$. If $Q_t$ is empty, do nothing.



In the initial state, all queues are empty.

Constraints

* $1 \leq n \leq 1,000$
* $1 \leq q \leq 200,000$
* $-1,000,000,000 \leq x \leq 1,000,000,000$

Input

The input is given in the following format.


$n \; q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $t$ $x$


or


1 $t$


or


2 $t$


where the first digits 0, 1 and 2 represent enqueue, front and dequeue operations respectively.

Output

For each front operation, print an integer in a line.

Example

Input

3 9
0 0 1
0 0 2
0 0 3
0 2 4
0 2 5
1 0
1 2
2 0
1 0


Output

1
4
2

### Response

```cpp
#include <algorithm>
#include <cmath>
#include <deque>
#include <iomanip>
#include <iostream>
#include <map>
#include <numeric>
#include <queue>
#include <set>
#include <stack>
#include <string>
#include <utility>
#include <vector>
using ll = long long;
#define rep(i, n) for (int i = 0; i < n; i++)
#define repk(i, k, n) for (int i = k; i < n; i++)
#define MOD 1000000007
#define INF 1e9
#define PIE 3.14159265358979323

template <class T>
inline bool chmin(T &a, T b) {
    if (a > b) {
        a = b;
        return true;
    }
    return false;
}
template <class T>
inline bool chmax(T &a, T b) {
    if (a < b) {
        a = b;
        return true;
    }
    return false;
}
template <class T>
T GCD(T a, T b) {
    if (b == 0)
        return a;
    else
        return GCD(b, a % b);
}
template <class T>
inline T LCM(T a, T b) {
    return (a * b) / GCD(a, b);
}

using namespace std;
//#inculude <bits/stdc++.h>
//#define int long long

signed main() {
    int n, q;
    cin >> n >> q;
    vector<queue<int>> que(n);
    int k, t, x;
    rep(i, q) {
        cin >> k >> t;
        if (k == 0) {
            cin >> x;
            que[t].push(x);
        }
        else if (k == 1) {
            if (!que[t].empty())
                cout << que[t].front() << endl;
        }
        else {
            if (!que[t].empty())
                que[t].pop();
        }
    }
}

```