#include <stdio.h>
int main(void){
int n,i;
scanf("%d",&n);
int a[n];
for(i=0;i<n;i++){
    scanf("%d",&a[i]);
}
printf("%d",a[n-1]);
for(i=n-2;i>=0;i--){
    printf(" %d",a[i]);
}
printf("\n");
return 0;
}
### Prompt

Create a solution in cpp for the following problem:

Write a program which reads a sequence and prints it in the reverse order.

Note

解説

Constraints

* n ≤ 100
* 0 ≤ ai < 1000

Input

The input is given in the following format:


n
a1 a2 . . . an


n is the size of the sequence and ai is the ith element of the sequence.

Output

Print the reversed sequence in a line. Print a single space character between adjacent elements (Note that your program should not put a space character after the last element).

Examples

Input

5
1 2 3 4 5


Output

5 4 3 2 1


Input

8
3 3 4 4 5 8 7 9


Output

9 7 8 5 4 4 3 3

### Response

```cpp
#include <stdio.h>
int main(void){
int n,i;
scanf("%d",&n);
int a[n];
for(i=0;i<n;i++){
    scanf("%d",&a[i]);
}
printf("%d",a[n-1]);
for(i=n-2;i>=0;i--){
    printf(" %d",a[i]);
}
printf("\n");
return 0;
}
```