#include <bits/stdc++.h>
using namespace std;
int n, l = -1;
long long ans;
string s;
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  cin >> s;
  n = s.size();
  for (int i = 0; i < n; i++) {
    for (int j = 1; i - j - j >= 0; j++) {
      if (s[i] == s[i - j] and s[i] == s[i - j - j]) {
        l = max(l, i - j - j);
        break;
      }
    }
    ans += l + 1;
  }
  cout << ans;
}

### Prompt

Your challenge is to write a cpp solution to the following problem:

Toad Rash has a binary string s. A binary string consists only of zeros and ones.

Let n be the length of s.

Rash needs to find the number of such pairs of integers l, r that 1 ≤ l ≤ r ≤ n and there is at least one pair of integers x, k such that 1 ≤ x, k ≤ n, l ≤ x < x + 2k ≤ r, and s_x = s_{x+k} = s_{x+2k}.

Find this number of pairs for Rash.

Input

The first line contains the string s (1 ≤ |s| ≤ 300 000), consisting of zeros and ones.

Output

Output one integer: the number of such pairs of integers l, r that 1 ≤ l ≤ r ≤ n and there is at least one pair of integers x, k such that 1 ≤ x, k ≤ n, l ≤ x < x + 2k ≤ r, and s_x = s_{x+k} = s_{x+2k}.

Examples

Input


010101


Output


3


Input


11001100


Output


0

Note

In the first example, there are three l, r pairs we need to count: 1, 6; 2, 6; and 1, 5.

In the second example, there are no values x, k for the initial string, so the answer is 0.

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int n, l = -1;
long long ans;
string s;
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  cin >> s;
  n = s.size();
  for (int i = 0; i < n; i++) {
    for (int j = 1; i - j - j >= 0; j++) {
      if (s[i] == s[i - j] and s[i] == s[i - j - j]) {
        l = max(l, i - j - j);
        break;
      }
    }
    ans += l + 1;
  }
  cout << ans;
}

```