#include <bits/stdc++.h>
using namespace std;
bool isValid(const string s) {
  for (int i = 0; i < s.size(); i++) {
    for (int j = i + 2; j < s.size(); j++) {
      if ((j - i + 1) % 2 == 1 && s[i] == s[j] && s[j] == s[(i + j) / 2])
        return true;
    }
  }
  return false;
}
int main() {
  ios_base::sync_with_stdio(0);
  cin.tie(0);
  string s;
  int i, j;
  long long res = 0;
  cin >> s;
  for (i = 0; i < s.length(); i++) {
    string temp("");
    for (j = i; j < s.length(); j++) {
      temp.push_back(s[j]);
      if (isValid(temp)) {
        res += s.length() - j;
        break;
      }
    }
  }
  cout << res;
}

### Prompt

Construct a CPP code solution to the problem outlined:

Toad Rash has a binary string s. A binary string consists only of zeros and ones.

Let n be the length of s.

Rash needs to find the number of such pairs of integers l, r that 1 ≤ l ≤ r ≤ n and there is at least one pair of integers x, k such that 1 ≤ x, k ≤ n, l ≤ x < x + 2k ≤ r, and s_x = s_{x+k} = s_{x+2k}.

Find this number of pairs for Rash.

Input

The first line contains the string s (1 ≤ |s| ≤ 300 000), consisting of zeros and ones.

Output

Output one integer: the number of such pairs of integers l, r that 1 ≤ l ≤ r ≤ n and there is at least one pair of integers x, k such that 1 ≤ x, k ≤ n, l ≤ x < x + 2k ≤ r, and s_x = s_{x+k} = s_{x+2k}.

Examples

Input


010101


Output


3


Input


11001100


Output


0

Note

In the first example, there are three l, r pairs we need to count: 1, 6; 2, 6; and 1, 5.

In the second example, there are no values x, k for the initial string, so the answer is 0.

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
bool isValid(const string s) {
  for (int i = 0; i < s.size(); i++) {
    for (int j = i + 2; j < s.size(); j++) {
      if ((j - i + 1) % 2 == 1 && s[i] == s[j] && s[j] == s[(i + j) / 2])
        return true;
    }
  }
  return false;
}
int main() {
  ios_base::sync_with_stdio(0);
  cin.tie(0);
  string s;
  int i, j;
  long long res = 0;
  cin >> s;
  for (i = 0; i < s.length(); i++) {
    string temp("");
    for (j = i; j < s.length(); j++) {
      temp.push_back(s[j]);
      if (isValid(temp)) {
        res += s.length() - j;
        break;
      }
    }
  }
  cout << res;
}

```