#include <bits/stdc++.h>
using namespace std;
int main() {
  int n, x = 0;
  cin >> n;
  string s;
  for (int i = 0; i < n; i++) {
    cin >> s;
    if ((s[0] == 'X' && s[1] == '+') || (s[0] == '+'))
      x++;
    else
      x--;
  }
  cout << x;
  return 0;
}

### Prompt

Your task is to create a cpp solution to the following problem:

The classic programming language of Bitland is Bit++. This language is so peculiar and complicated.

The language is that peculiar as it has exactly one variable, called x. Also, there are two operations:

  * Operation ++ increases the value of variable x by 1. 
  * Operation -- decreases the value of variable x by 1. 



A statement in language Bit++ is a sequence, consisting of exactly one operation and one variable x. The statement is written without spaces, that is, it can only contain characters "+", "-", "X". Executing a statement means applying the operation it contains.

A programme in Bit++ is a sequence of statements, each of them needs to be executed. Executing a programme means executing all the statements it contains.

You're given a programme in language Bit++. The initial value of x is 0. Execute the programme and find its final value (the value of the variable when this programme is executed).

Input

The first line contains a single integer n (1 ≤ n ≤ 150) — the number of statements in the programme.

Next n lines contain a statement each. Each statement contains exactly one operation (++ or --) and exactly one variable x (denoted as letter «X»). Thus, there are no empty statements. The operation and the variable can be written in any order.

Output

Print a single integer — the final value of x.

Examples

Input

1
++X


Output

1


Input

2
X++
--X


Output

0

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  int n, x = 0;
  cin >> n;
  string s;
  for (int i = 0; i < n; i++) {
    cin >> s;
    if ((s[0] == 'X' && s[1] == '+') || (s[0] == '+'))
      x++;
    else
      x--;
  }
  cout << x;
  return 0;
}

```