#include <bits/stdc++.h>
using namespace std;
string s;
long long ans;
inline bool judge(string str) {
  for (int i = 0; i < str.length(); i++)
    for (int j = 1; i + j * 2 < str.length(); j++)
      if (str[i] == str[i + j] && str[i + j] == str[i + j * 2]) return true;
  return false;
}
int main() {
  cin >> s;
  for (int i = 0; i < s.length(); i++) {
    for (int j = 3; j <= min((int)s.length() - i, 8); j++)
      if (judge(s.substr(i, j))) ans++;
    ans += max(0, (int)s.length() - i - 8);
  }
  cout << ans;
  return 0;
}

### Prompt

Please provide a cpp coded solution to the problem described below:

Toad Rash has a binary string s. A binary string consists only of zeros and ones.

Let n be the length of s.

Rash needs to find the number of such pairs of integers l, r that 1 ≤ l ≤ r ≤ n and there is at least one pair of integers x, k such that 1 ≤ x, k ≤ n, l ≤ x < x + 2k ≤ r, and s_x = s_{x+k} = s_{x+2k}.

Find this number of pairs for Rash.

Input

The first line contains the string s (1 ≤ |s| ≤ 300 000), consisting of zeros and ones.

Output

Output one integer: the number of such pairs of integers l, r that 1 ≤ l ≤ r ≤ n and there is at least one pair of integers x, k such that 1 ≤ x, k ≤ n, l ≤ x < x + 2k ≤ r, and s_x = s_{x+k} = s_{x+2k}.

Examples

Input


010101


Output


3


Input


11001100


Output


0

Note

In the first example, there are three l, r pairs we need to count: 1, 6; 2, 6; and 1, 5.

In the second example, there are no values x, k for the initial string, so the answer is 0.

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
string s;
long long ans;
inline bool judge(string str) {
  for (int i = 0; i < str.length(); i++)
    for (int j = 1; i + j * 2 < str.length(); j++)
      if (str[i] == str[i + j] && str[i + j] == str[i + j * 2]) return true;
  return false;
}
int main() {
  cin >> s;
  for (int i = 0; i < s.length(); i++) {
    for (int j = 3; j <= min((int)s.length() - i, 8); j++)
      if (judge(s.substr(i, j))) ans++;
    ans += max(0, (int)s.length() - i - 8);
  }
  cout << ans;
  return 0;
}

```