#include <bits/stdc++.h>
using namespace std;
#pragma GCC optimize("O3")
#pragma GCC optimize("no-stack-protector")
#pragma GCC optimize("unroll-loops")
#pragma GCC optimize("fast-math")
#pragma GCC target("sse,sse2,sse3,ssse3,popcnt,abm,mmx,tune=native")
mt19937 rng(time(NULL));
const int inf = 1e9 + 100;
const long long linf = 2e18;
const long long maxn = 3e5 + 100;
const int mod = 1e9 + 7;
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(0);
  string s;
  cin >> s;
  int n = s.size();
  long long ans = 0;
  for (int l = 0; l < n; ++l) {
    int r = 1e9;
    for (int x = l; x < l + 10 && x < n; ++x) {
      for (int k = 1; x + 2 * k < l + 10 && x + 2 * k < n; ++k) {
        if (s[x] == s[x + k] && s[x + k] == s[x + 2 * k]) r = min(r, x + 2 * k);
      }
    }
    ans += max(0, n - r);
  }
  cout << ans;
  return 0;
}

### Prompt

Please formulate a cpp solution to the following problem:

Toad Rash has a binary string s. A binary string consists only of zeros and ones.

Let n be the length of s.

Rash needs to find the number of such pairs of integers l, r that 1 ≤ l ≤ r ≤ n and there is at least one pair of integers x, k such that 1 ≤ x, k ≤ n, l ≤ x < x + 2k ≤ r, and s_x = s_{x+k} = s_{x+2k}.

Find this number of pairs for Rash.

Input

The first line contains the string s (1 ≤ |s| ≤ 300 000), consisting of zeros and ones.

Output

Output one integer: the number of such pairs of integers l, r that 1 ≤ l ≤ r ≤ n and there is at least one pair of integers x, k such that 1 ≤ x, k ≤ n, l ≤ x < x + 2k ≤ r, and s_x = s_{x+k} = s_{x+2k}.

Examples

Input


010101


Output


3


Input


11001100


Output


0

Note

In the first example, there are three l, r pairs we need to count: 1, 6; 2, 6; and 1, 5.

In the second example, there are no values x, k for the initial string, so the answer is 0.

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
#pragma GCC optimize("O3")
#pragma GCC optimize("no-stack-protector")
#pragma GCC optimize("unroll-loops")
#pragma GCC optimize("fast-math")
#pragma GCC target("sse,sse2,sse3,ssse3,popcnt,abm,mmx,tune=native")
mt19937 rng(time(NULL));
const int inf = 1e9 + 100;
const long long linf = 2e18;
const long long maxn = 3e5 + 100;
const int mod = 1e9 + 7;
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(0);
  string s;
  cin >> s;
  int n = s.size();
  long long ans = 0;
  for (int l = 0; l < n; ++l) {
    int r = 1e9;
    for (int x = l; x < l + 10 && x < n; ++x) {
      for (int k = 1; x + 2 * k < l + 10 && x + 2 * k < n; ++k) {
        if (s[x] == s[x + k] && s[x + k] == s[x + 2 * k]) r = min(r, x + 2 * k);
      }
    }
    ans += max(0, n - r);
  }
  cout << ans;
  return 0;
}

```