#include <bits/stdc++.h>
using namespace std;
int main() {
  int i, m, s, sum = 0, flag = 0;
  char a[105], b[105];
  cin >> m >> s;
  sum = s;
  if (ceil((float(s) / float(9)) > m || (s == 0 && m != 1)))
    cout << -1 << " " << -1;
  else {
    for (i = m - 1; i >= 0; i--) {
      if (sum > 9) {
        a[i] = '9';
        sum -= 9;
      } else if (sum > 0 && i != 0) {
        a[i] = char(sum + '0' - 1);
        flag = 1;
        sum = 0;
      } else if (sum > 0) {
        a[i] = sum + 48;
      } else if (flag == 0) {
        a[i] = '0';
      } else if (flag == 1 && i != 0)
        a[i] = '0';
      else
        a[i] = '1';
    }
    for (i = 0; i < m; i++) cout << a[i];
    cout << " ";
    for (i = 0; i < m; i++) {
      if (s >= 9) {
        b[i] = '9';
        s -= 9;
      } else if (s > 0) {
        b[i] = s + 48;
        s = 0;
      } else {
        b[i] = '0';
      }
    }
    for (i = 0; i < m; i++) {
      cout << b[i];
    }
  }
}

### Prompt

Your task is to create a cpp solution to the following problem:

You have a positive integer m and a non-negative integer s. Your task is to find the smallest and the largest of the numbers that have length m and sum of digits s. The required numbers should be non-negative integers written in the decimal base without leading zeroes.

Input

The single line of the input contains a pair of integers m, s (1 ≤ m ≤ 100, 0 ≤ s ≤ 900) — the length and the sum of the digits of the required numbers.

Output

In the output print the pair of the required non-negative integer numbers — first the minimum possible number, then — the maximum possible number. If no numbers satisfying conditions required exist, print the pair of numbers "-1 -1" (without the quotes).

Examples

Input

2 15


Output

69 96


Input

3 0


Output

-1 -1

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  int i, m, s, sum = 0, flag = 0;
  char a[105], b[105];
  cin >> m >> s;
  sum = s;
  if (ceil((float(s) / float(9)) > m || (s == 0 && m != 1)))
    cout << -1 << " " << -1;
  else {
    for (i = m - 1; i >= 0; i--) {
      if (sum > 9) {
        a[i] = '9';
        sum -= 9;
      } else if (sum > 0 && i != 0) {
        a[i] = char(sum + '0' - 1);
        flag = 1;
        sum = 0;
      } else if (sum > 0) {
        a[i] = sum + 48;
      } else if (flag == 0) {
        a[i] = '0';
      } else if (flag == 1 && i != 0)
        a[i] = '0';
      else
        a[i] = '1';
    }
    for (i = 0; i < m; i++) cout << a[i];
    cout << " ";
    for (i = 0; i < m; i++) {
      if (s >= 9) {
        b[i] = '9';
        s -= 9;
      } else if (s > 0) {
        b[i] = s + 48;
        s = 0;
      } else {
        b[i] = '0';
      }
    }
    for (i = 0; i < m; i++) {
      cout << b[i];
    }
  }
}

```