#include <bits/stdc++.h>
using namespace std;
const double PI = acos(-1.0);
const int INF = 0x3f3f3f3f;
const long long mod = 1e9;
const double eps = 1e-15;
const int N = 110;
int n;
string s[N];
int cmp(string a, string b) { return a.size() < b.size(); }
void solve() {
  cin >> n;
  for (int i = 0; i < n; i++) {
    cin >> s[i];
  }
  sort(s, s + n, cmp);
  bool ok = 1;
  for (int i = 0; i < n - 1; i++) {
    if (s[i + 1].find(s[i]) == -1) {
      ok = 0;
      break;
    }
  }
  if (ok) {
    cout << "YES" << endl;
    for (int i = 0; i < n; i++) cout << s[i] << endl;
  } else
    cout << "NO" << endl;
  return;
}
int main() {
  solve();
  return 0;
}

### Prompt

Please create a solution in Cpp to the following problem:

You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.

String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".

Input

The first line contains an integer n (1 ≤ n ≤ 100) — the number of strings.

The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.

Some strings might be equal.

Output

If it is impossible to reorder n given strings in required order, print "NO" (without quotes).

Otherwise print "YES" (without quotes) and n given strings in required order.

Examples

Input

5
a
aba
abacaba
ba
aba


Output

YES
a
ba
aba
aba
abacaba


Input

5
a
abacaba
ba
aba
abab


Output

NO


Input

3
qwerty
qwerty
qwerty


Output

YES
qwerty
qwerty
qwerty

Note

In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
const double PI = acos(-1.0);
const int INF = 0x3f3f3f3f;
const long long mod = 1e9;
const double eps = 1e-15;
const int N = 110;
int n;
string s[N];
int cmp(string a, string b) { return a.size() < b.size(); }
void solve() {
  cin >> n;
  for (int i = 0; i < n; i++) {
    cin >> s[i];
  }
  sort(s, s + n, cmp);
  bool ok = 1;
  for (int i = 0; i < n - 1; i++) {
    if (s[i + 1].find(s[i]) == -1) {
      ok = 0;
      break;
    }
  }
  if (ok) {
    cout << "YES" << endl;
    for (int i = 0; i < n; i++) cout << s[i] << endl;
  } else
    cout << "NO" << endl;
  return;
}
int main() {
  solve();
  return 0;
}

```