#include <bits/stdc++.h>
using namespace std;
template <class T>
inline T Max(T a, T b) {
  if (a > b)
    return a;
  else
    return b;
}
template <class T>
inline T Min(T a, T b) {
  if (a < b)
    return a;
  else
    return b;
}
template <class T>
inline T gcd(T a, T b) {
  if (a < 0) return gcd(-a, b);
  if (b < 0) return gcd(a, -b);
  return (b == 0) ? a : gcd(b, a % b);
}
template <class T>
inline T lcm(T a, T b) {
  if (a < 0) return lcm(-a, b);
  if (b < 0) return lcm(a, -b);
  return a * (b / gcd(a, b));
}
template <class T>
inline T TripleMax(T a, T b, T c) {
  return Max(Max(a, b), c);
}
template <class T>
inline T TripleMin(T a, T b, T c) {
  return Min(Min(a, b), c);
}
int x;
int n;
int main(int argc, const char* argv[]) {
  cin >> x;
  if (x <= 5) {
    if (x == 1) {
      cout << 1 << endl;
    } else if (x == 3) {
      cout << 5 << endl;
    } else {
      cout << 3 << endl;
    }
  } else {
    n = 3;
    while (x > n * n / 2 + 1) {
      n += 2;
    }
    cout << n << endl;
  }
  return 0;
}

### Prompt

Your challenge is to write a Cpp solution to the following problem:

Consider some square matrix A with side n consisting of zeros and ones. There are n rows numbered from 1 to n from top to bottom and n columns numbered from 1 to n from left to right in this matrix. We'll denote the element of the matrix which is located at the intersection of the i-row and the j-th column as Ai, j.

Let's call matrix A clear if no two cells containing ones have a common side.

Let's call matrix A symmetrical if it matches the matrices formed from it by a horizontal and/or a vertical reflection. Formally, for each pair (i, j) (1 ≤ i, j ≤ n) both of the following conditions must be met: Ai, j = An - i + 1, j and Ai, j = Ai, n - j + 1.

Let's define the sharpness of matrix A as the number of ones in it.

Given integer x, your task is to find the smallest positive integer n such that there exists a clear symmetrical matrix A with side n and sharpness x.

Input

The only line contains a single integer x (1 ≤ x ≤ 100) — the required sharpness of the matrix.

Output

Print a single number — the sought value of n.

Examples

Input

4


Output

3


Input

9


Output

5

Note

The figure below shows the matrices that correspond to the samples:

<image>

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
template <class T>
inline T Max(T a, T b) {
  if (a > b)
    return a;
  else
    return b;
}
template <class T>
inline T Min(T a, T b) {
  if (a < b)
    return a;
  else
    return b;
}
template <class T>
inline T gcd(T a, T b) {
  if (a < 0) return gcd(-a, b);
  if (b < 0) return gcd(a, -b);
  return (b == 0) ? a : gcd(b, a % b);
}
template <class T>
inline T lcm(T a, T b) {
  if (a < 0) return lcm(-a, b);
  if (b < 0) return lcm(a, -b);
  return a * (b / gcd(a, b));
}
template <class T>
inline T TripleMax(T a, T b, T c) {
  return Max(Max(a, b), c);
}
template <class T>
inline T TripleMin(T a, T b, T c) {
  return Min(Min(a, b), c);
}
int x;
int n;
int main(int argc, const char* argv[]) {
  cin >> x;
  if (x <= 5) {
    if (x == 1) {
      cout << 1 << endl;
    } else if (x == 3) {
      cout << 5 << endl;
    } else {
      cout << 3 << endl;
    }
  } else {
    n = 3;
    while (x > n * n / 2 + 1) {
      n += 2;
    }
    cout << n << endl;
  }
  return 0;
}

```