#include <bits/stdc++.h>
using namespace std;
int main() {
  long long n, a, b, i, j, f = 0;
  scanf("%lld", &n);
  for (i = 1; i <= n; i++) {
    for (j = 1; j <= n; j++) {
      if (i % j == 0 && (i / j) < n && (i * j) > n) {
        a = i;
        b = j;
        f = 1;
      }
    }
  }
  if (f == 0)
    cout << "-1" << endl;
  else
    cout << a << " " << b << endl;
  return 0;
}

### Prompt

Please provide a Cpp coded solution to the problem described below:

Given an integer x, find 2 integers a and b such that: 

  * 1 ≤ a,b ≤ x 
  * b divides a (a is divisible by b). 
  * a ⋅ b>x. 
  * a/b<x. 

Input

The only line contains the integer x (1 ≤ x ≤ 100).

Output

You should output two integers a and b, satisfying the given conditions, separated by a space. If no pair of integers satisfy the conditions above, print "-1" (without quotes).

Examples

Input

10


Output

6 3

Input

1


Output

-1

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  long long n, a, b, i, j, f = 0;
  scanf("%lld", &n);
  for (i = 1; i <= n; i++) {
    for (j = 1; j <= n; j++) {
      if (i % j == 0 && (i / j) < n && (i * j) > n) {
        a = i;
        b = j;
        f = 1;
      }
    }
  }
  if (f == 0)
    cout << "-1" << endl;
  else
    cout << a << " " << b << endl;
  return 0;
}

```