#include <bits/stdc++.h>
int main() {
  int na, nb, i, j, a[200000], b[200000], k, m, ca = 0, cb = 0, cb1, x, y, z;
  scanf("%d %d", &na, &nb);
  scanf("%d %d", &k, &m);
  x = na - k;
  y = nb - m;
  for (i = 1; i <= na; i++) {
    scanf("%d", &a[i]);
  }
  for (i = 1; i <= nb; i++) {
    scanf("%d", &b[i]);
  }
  if (a[na] < b[1]) {
    printf("YES\n");
    return 0;
  }
  if (a[1] >= b[nb]) {
    printf("NO\n");
    return 0;
  }
  if (k < x || m < y) {
    for (j = nb; j >= 1; j--) {
      ca = 0;
      cb1 = 0;
      for (i = 1; i <= na; i++) {
        if (a[i] < b[j]) {
          ca++;
        }
        if (ca >= k) {
          cb1++;
          cb++;
          break;
        }
      }
      if (cb >= m) {
        printf("YES\n");
        return 0;
      }
      if (cb1 == 0) {
        printf("NO\n");
        return 0;
      }
    }
    printf("NO\n");
    return 0;
  } else {
    for (j = na; j >= 1; j--) {
      cb = 0;
      cb1 = 0;
      for (i = 1; i <= nb; i++) {
        if (a[j] >= b[i]) {
          cb++;
        }
        if (cb > y) {
          cb1++;
          ca++;
          break;
        }
      }
      if (ca > x) {
        printf("NO\n");
        return 0;
      }
      if (cb1 == 0) {
        printf("YES\n");
        return 0;
      }
    }
    printf("YES\n");
    return 0;
  }
  return 0;
}

### Prompt

Your challenge is to write a CPP solution to the following problem:

You are given two arrays A and B consisting of integers, sorted in non-decreasing order. Check whether it is possible to choose k numbers in array A and choose m numbers in array B so that any number chosen in the first array is strictly less than any number chosen in the second array.

Input

The first line contains two integers nA, nB (1 ≤ nA, nB ≤ 105), separated by a space — the sizes of arrays A and B, correspondingly.

The second line contains two integers k and m (1 ≤ k ≤ nA, 1 ≤ m ≤ nB), separated by a space.

The third line contains nA numbers a1, a2, ... anA ( - 109 ≤ a1 ≤ a2 ≤ ... ≤ anA ≤ 109), separated by spaces — elements of array A.

The fourth line contains nB integers b1, b2, ... bnB ( - 109 ≤ b1 ≤ b2 ≤ ... ≤ bnB ≤ 109), separated by spaces — elements of array B.

Output

Print "YES" (without the quotes), if you can choose k numbers in array A and m numbers in array B so that any number chosen in array A was strictly less than any number chosen in array B. Otherwise, print "NO" (without the quotes).

Examples

Input

3 3
2 1
1 2 3
3 4 5


Output

YES


Input

3 3
3 3
1 2 3
3 4 5


Output

NO


Input

5 2
3 1
1 1 1 1 1
2 2


Output

YES

Note

In the first sample test you can, for example, choose numbers 1 and 2 from array A and number 3 from array B (1 < 3 and 2 < 3).

In the second sample test the only way to choose k elements in the first array and m elements in the second one is to choose all numbers in both arrays, but then not all the numbers chosen in A will be less than all the numbers chosen in B: <image>.

### Response

```cpp
#include <bits/stdc++.h>
int main() {
  int na, nb, i, j, a[200000], b[200000], k, m, ca = 0, cb = 0, cb1, x, y, z;
  scanf("%d %d", &na, &nb);
  scanf("%d %d", &k, &m);
  x = na - k;
  y = nb - m;
  for (i = 1; i <= na; i++) {
    scanf("%d", &a[i]);
  }
  for (i = 1; i <= nb; i++) {
    scanf("%d", &b[i]);
  }
  if (a[na] < b[1]) {
    printf("YES\n");
    return 0;
  }
  if (a[1] >= b[nb]) {
    printf("NO\n");
    return 0;
  }
  if (k < x || m < y) {
    for (j = nb; j >= 1; j--) {
      ca = 0;
      cb1 = 0;
      for (i = 1; i <= na; i++) {
        if (a[i] < b[j]) {
          ca++;
        }
        if (ca >= k) {
          cb1++;
          cb++;
          break;
        }
      }
      if (cb >= m) {
        printf("YES\n");
        return 0;
      }
      if (cb1 == 0) {
        printf("NO\n");
        return 0;
      }
    }
    printf("NO\n");
    return 0;
  } else {
    for (j = na; j >= 1; j--) {
      cb = 0;
      cb1 = 0;
      for (i = 1; i <= nb; i++) {
        if (a[j] >= b[i]) {
          cb++;
        }
        if (cb > y) {
          cb1++;
          ca++;
          break;
        }
      }
      if (ca > x) {
        printf("NO\n");
        return 0;
      }
      if (cb1 == 0) {
        printf("YES\n");
        return 0;
      }
    }
    printf("YES\n");
    return 0;
  }
  return 0;
}

```