#include <bits/stdc++.h>
using namespace std;
int main() {
  int t, a, b;
  cin >> t;
  vector<int> res;
  for (int i = 0; i < t; i++) {
    cin >> a >> b;
    int count;
    if (a % b == 0) {
      count = 0;
    } else {
      count = b - (a % b);
    }
    res.push_back(count);
  }
  for (int i = 0; i < t; i++) cout << res[i] << endl;
  return 0;
}

### Prompt

Construct a Cpp code solution to the problem outlined:

You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  int t, a, b;
  cin >> t;
  vector<int> res;
  for (int i = 0; i < t; i++) {
    cin >> a >> b;
    int count;
    if (a % b == 0) {
      count = 0;
    } else {
      count = b - (a % b);
    }
    res.push_back(count);
  }
  for (int i = 0; i < t; i++) cout << res[i] << endl;
  return 0;
}

```