#include<cstdio>
#include<bitset>
using namespace std;
bitset<4000020>s;
int n,a,i,sum;
int main(){
	s[0]=1;
	scanf("%d",&n);
	for(i=1;i<=n;i++){
		scanf("%d",&a);
		sum+=a;
		s|=s<<a;
	}
	for(i=sum+1>>1;i<=sum;i++)
	if(s[i]){
		printf("%d",i);
		return 0;
	}
}
### Prompt

Generate a cpp solution to the following problem:

You are given N integers A_1, A_2, ..., A_N.

Consider the sums of all non-empty subsequences of A. There are 2^N - 1 such sums, an odd number.

Let the list of these sums in non-decreasing order be S_1, S_2, ..., S_{2^N - 1}.

Find the median of this list, S_{2^{N-1}}.

Constraints

* 1 \leq N \leq 2000
* 1 \leq A_i \leq 2000
* All input values are integers.

Input

Input is given from Standard Input in the following format:


N
A_1 A_2 ... A_N


Output

Print the median of the sorted list of the sums of all non-empty subsequences of A.

Examples

Input

3
1 2 1


Output

2


Input

1
58


Output

58

### Response

```cpp
#include<cstdio>
#include<bitset>
using namespace std;
bitset<4000020>s;
int n,a,i,sum;
int main(){
	s[0]=1;
	scanf("%d",&n);
	for(i=1;i<=n;i++){
		scanf("%d",&a);
		sum+=a;
		s|=s<<a;
	}
	for(i=sum+1>>1;i<=sum;i++)
	if(s[i]){
		printf("%d",i);
		return 0;
	}
}
```