#include <bits/stdc++.h>
using namespace std;
int main() {
  long long x;
  while (cin >> x) {
    long long i, a, b, arr[10005];
    for (i = 1; i <= x; i++) {
      arr[i] = i;
    }
    for (a = 1; a <= x; a++) {
      for (b = 1; b <= x; b++) {
        if (a % b == 0 && a * b > x && a / b < x) {
          cout << a << " " << b << endl;
          return 0;
        }
      }
    }
    cout << "-1" << endl;
  }
  return 0;
}

### Prompt

Create a solution in Cpp for the following problem:

Given an integer x, find 2 integers a and b such that: 

  * 1 ≤ a,b ≤ x 
  * b divides a (a is divisible by b). 
  * a ⋅ b>x. 
  * a/b<x. 

Input

The only line contains the integer x (1 ≤ x ≤ 100).

Output

You should output two integers a and b, satisfying the given conditions, separated by a space. If no pair of integers satisfy the conditions above, print "-1" (without quotes).

Examples

Input

10


Output

6 3

Input

1


Output

-1

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  long long x;
  while (cin >> x) {
    long long i, a, b, arr[10005];
    for (i = 1; i <= x; i++) {
      arr[i] = i;
    }
    for (a = 1; a <= x; a++) {
      for (b = 1; b <= x; b++) {
        if (a % b == 0 && a * b > x && a / b < x) {
          cout << a << " " << b << endl;
          return 0;
        }
      }
    }
    cout << "-1" << endl;
  }
  return 0;
}

```