#include <bits/stdc++.h>
typedef struct {
  int x;
  int y;
} punto;
int main() {
  int i, n, k;
  unsigned long long int j;
  punto Mo, Mj, Aux;
  scanf("%d%I64d", &n, &j);
  punto A[n];
  j = j % (2 * n);
  scanf("%d%d", &Mo.x, &Mo.y);
  Aux.x = Mo.x;
  Aux.y = Mo.y;
  for (i = 0; i < n; i++) {
    scanf("%d%d", &A[i].x, &A[i].y);
  }
  for (i = 1; i <= j; i++) {
    k = (i - 1) % n;
    Aux.x = 2 * A[k].x - Aux.x;
    Aux.y = 2 * A[k].y - Aux.y;
  }
  Mj.x = Aux.x;
  Mj.y = Aux.y;
  printf("%d %d", Mj.x, Mj.y);
  return 0;
}

### Prompt

Create a solution in cpp for the following problem:

You are given the following points with integer coordinates on the plane: M0, A0, A1, ..., An - 1, where n is odd number. Now we define the following infinite sequence of points Mi: Mi is symmetric to Mi - 1 according <image> (for every natural number i). Here point B is symmetric to A according M, if M is the center of the line segment AB. Given index j find the point Mj.

Input

On the first line you will be given an integer n (1 ≤ n ≤ 105), which will be odd, and j (1 ≤ j ≤ 1018), where j is the index of the desired point. The next line contains two space separated integers, the coordinates of M0. After that n lines follow, where the i-th line contain the space separated integer coordinates of the point Ai - 1. The absolute values of all input coordinates will not be greater then 1000.

Output

On a single line output the coordinates of Mj, space separated.

Examples

Input

3 4
0 0
1 1
2 3
-5 3


Output

14 0


Input

3 1
5 5
1000 1000
-1000 1000
3 100


Output

1995 1995

### Response

```cpp
#include <bits/stdc++.h>
typedef struct {
  int x;
  int y;
} punto;
int main() {
  int i, n, k;
  unsigned long long int j;
  punto Mo, Mj, Aux;
  scanf("%d%I64d", &n, &j);
  punto A[n];
  j = j % (2 * n);
  scanf("%d%d", &Mo.x, &Mo.y);
  Aux.x = Mo.x;
  Aux.y = Mo.y;
  for (i = 0; i < n; i++) {
    scanf("%d%d", &A[i].x, &A[i].y);
  }
  for (i = 1; i <= j; i++) {
    k = (i - 1) % n;
    Aux.x = 2 * A[k].x - Aux.x;
    Aux.y = 2 * A[k].y - Aux.y;
  }
  Mj.x = Aux.x;
  Mj.y = Aux.y;
  printf("%d %d", Mj.x, Mj.y);
  return 0;
}

```