#include<bits/stdc++.h>
using namespace std;
bitset<4000020>dp;
int n,x,s;
int main(void){
    scanf("%d",&n);
    dp[0]=1;
    for(int i=0;i<n;++i){
    	scanf("%d",&x);
    	dp|=dp<<x;
    	s+=x;
    }
    for(int i=(s+1)/2;i<=s;++i){
        if(dp[i]){
            printf("%d",i);
            break;
        }
    }
}

### Prompt

Please create a solution in Cpp to the following problem:

You are given N integers A_1, A_2, ..., A_N.

Consider the sums of all non-empty subsequences of A. There are 2^N - 1 such sums, an odd number.

Let the list of these sums in non-decreasing order be S_1, S_2, ..., S_{2^N - 1}.

Find the median of this list, S_{2^{N-1}}.

Constraints

* 1 \leq N \leq 2000
* 1 \leq A_i \leq 2000
* All input values are integers.

Input

Input is given from Standard Input in the following format:


N
A_1 A_2 ... A_N


Output

Print the median of the sorted list of the sums of all non-empty subsequences of A.

Examples

Input

3
1 2 1


Output

2


Input

1
58


Output

58

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;
bitset<4000020>dp;
int n,x,s;
int main(void){
    scanf("%d",&n);
    dp[0]=1;
    for(int i=0;i<n;++i){
    	scanf("%d",&x);
    	dp|=dp<<x;
    	s+=x;
    }
    for(int i=(s+1)/2;i<=s;++i){
        if(dp[i]){
            printf("%d",i);
            break;
        }
    }
}

```