#include <bits/stdc++.h>
using namespace std;
const long long N = 4e6 + 5;
struct Node {
  long long x, y;
} a[N], m[N];
long long n, j;
int main() {
  cin >> n >> j;
  cin >> m[0].x >> m[0].y;
  for (register long long i = 0; i <= n - 1; i++) cin >> a[i].x >> a[i].y;
  for (register long long i = 0; i <= 2 * n - 1; i++) {
    m[i + 1].x = 2 * a[i % n].x - m[i].x;
    m[i + 1].y = 2 * a[i % n].y - m[i].y;
  }
  return printf("%lld %lld\n", m[j % (2 * n)].x, m[j % (2 * n)].y), 0;
}

### Prompt

Your task is to create a Cpp solution to the following problem:

You are given the following points with integer coordinates on the plane: M0, A0, A1, ..., An - 1, where n is odd number. Now we define the following infinite sequence of points Mi: Mi is symmetric to Mi - 1 according <image> (for every natural number i). Here point B is symmetric to A according M, if M is the center of the line segment AB. Given index j find the point Mj.

Input

On the first line you will be given an integer n (1 ≤ n ≤ 105), which will be odd, and j (1 ≤ j ≤ 1018), where j is the index of the desired point. The next line contains two space separated integers, the coordinates of M0. After that n lines follow, where the i-th line contain the space separated integer coordinates of the point Ai - 1. The absolute values of all input coordinates will not be greater then 1000.

Output

On a single line output the coordinates of Mj, space separated.

Examples

Input

3 4
0 0
1 1
2 3
-5 3


Output

14 0


Input

3 1
5 5
1000 1000
-1000 1000
3 100


Output

1995 1995

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
const long long N = 4e6 + 5;
struct Node {
  long long x, y;
} a[N], m[N];
long long n, j;
int main() {
  cin >> n >> j;
  cin >> m[0].x >> m[0].y;
  for (register long long i = 0; i <= n - 1; i++) cin >> a[i].x >> a[i].y;
  for (register long long i = 0; i <= 2 * n - 1; i++) {
    m[i + 1].x = 2 * a[i % n].x - m[i].x;
    m[i + 1].y = 2 * a[i % n].y - m[i].y;
  }
  return printf("%lld %lld\n", m[j % (2 * n)].x, m[j % (2 * n)].y), 0;
}

```