#include <bits/stdc++.h>
using namespace std;
long long A, B, C, xx, yy;
long long gcd(long long x, long long y) {
  long long i, j;
  if (y == 0) {
    xx = 1;
    yy = 0;
    return x;
  } else {
    i = gcd(y, x % y);
    j = yy;
    yy = xx - x / y * yy;
    xx = j;
    return i;
  }
}
long long Abs(long long x) {
  if (x < 0)
    return -x;
  else
    return x;
}
int main() {
  cin >> A >> B >> C;
  long long w;
  if (Abs(A) > Abs(B)) {
    w = gcd(A, B);
    if (C % w == 0) {
      xx *= (-C / w);
      yy *= (-C / w);
      cout << xx << ' ' << yy << endl;
    } else
      cout << -1 << endl;
  } else {
    w = gcd(B, A);
    if (C % w == 0) {
      xx *= (-C / w);
      yy *= (-C / w);
      cout << yy << ' ' << xx << endl;
    } else
      cout << -1 << endl;
  }
  return 0;
}

### Prompt

Generate a CPP solution to the following problem:

A line on the plane is described by an equation Ax + By + C = 0. You are to find any point on this line, whose coordinates are integer numbers from  - 5·1018 to 5·1018 inclusive, or to find out that such points do not exist.

Input

The first line contains three integers A, B and C ( - 2·109 ≤ A, B, C ≤ 2·109) — corresponding coefficients of the line equation. It is guaranteed that A2 + B2 > 0.

Output

If the required point exists, output its coordinates, otherwise output -1.

Examples

Input

2 5 3


Output

6 -3

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
long long A, B, C, xx, yy;
long long gcd(long long x, long long y) {
  long long i, j;
  if (y == 0) {
    xx = 1;
    yy = 0;
    return x;
  } else {
    i = gcd(y, x % y);
    j = yy;
    yy = xx - x / y * yy;
    xx = j;
    return i;
  }
}
long long Abs(long long x) {
  if (x < 0)
    return -x;
  else
    return x;
}
int main() {
  cin >> A >> B >> C;
  long long w;
  if (Abs(A) > Abs(B)) {
    w = gcd(A, B);
    if (C % w == 0) {
      xx *= (-C / w);
      yy *= (-C / w);
      cout << xx << ' ' << yy << endl;
    } else
      cout << -1 << endl;
  } else {
    w = gcd(B, A);
    if (C % w == 0) {
      xx *= (-C / w);
      yy *= (-C / w);
      cout << yy << ' ' << xx << endl;
    } else
      cout << -1 << endl;
  }
  return 0;
}

```