#include<bits/stdc++.h>
using namespace std;
const int N=2e6+5;
bitset<N>V;
int main()
{
    int n,s=0;
    scanf("%d",&n);
    V[0]=1;
    for(int i=0,x; i<n; i++)scanf("%d",&x),s+=x,V|=V<<x;
    for(int i=s/2;;i--)
    if(V[i])
    {
        printf("%d\n",s-i);
        return 0;
    }
}
### Prompt

Generate a cpp solution to the following problem:

You are given N integers A_1, A_2, ..., A_N.

Consider the sums of all non-empty subsequences of A. There are 2^N - 1 such sums, an odd number.

Let the list of these sums in non-decreasing order be S_1, S_2, ..., S_{2^N - 1}.

Find the median of this list, S_{2^{N-1}}.

Constraints

* 1 \leq N \leq 2000
* 1 \leq A_i \leq 2000
* All input values are integers.

Input

Input is given from Standard Input in the following format:


N
A_1 A_2 ... A_N


Output

Print the median of the sorted list of the sums of all non-empty subsequences of A.

Examples

Input

3
1 2 1


Output

2


Input

1
58


Output

58

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;
const int N=2e6+5;
bitset<N>V;
int main()
{
    int n,s=0;
    scanf("%d",&n);
    V[0]=1;
    for(int i=0,x; i<n; i++)scanf("%d",&x),s+=x,V|=V<<x;
    for(int i=s/2;;i--)
    if(V[i])
    {
        printf("%d\n",s-i);
        return 0;
    }
}
```