#include <bits/stdc++.h>
#define ll long long
using namespace std;
bitset<4000010>b;
ll n,x,maxn;
int main()
{
	scanf("%d",&n);
	b[0]=1;
	while (n--)
	{
		scanf("%d",&x);
		b|=b<<x;
		maxn+=x;
	}
	ll i=0;
	for(i=(maxn+1)/2;!b[i];i++);
	printf("%d\n",i); 
	return 0;
}
### Prompt

Please create a solution in cpp to the following problem:

You are given N integers A_1, A_2, ..., A_N.

Consider the sums of all non-empty subsequences of A. There are 2^N - 1 such sums, an odd number.

Let the list of these sums in non-decreasing order be S_1, S_2, ..., S_{2^N - 1}.

Find the median of this list, S_{2^{N-1}}.

Constraints

* 1 \leq N \leq 2000
* 1 \leq A_i \leq 2000
* All input values are integers.

Input

Input is given from Standard Input in the following format:


N
A_1 A_2 ... A_N


Output

Print the median of the sorted list of the sums of all non-empty subsequences of A.

Examples

Input

3
1 2 1


Output

2


Input

1
58


Output

58

### Response

```cpp
#include <bits/stdc++.h>
#define ll long long
using namespace std;
bitset<4000010>b;
ll n,x,maxn;
int main()
{
	scanf("%d",&n);
	b[0]=1;
	while (n--)
	{
		scanf("%d",&x);
		b|=b<<x;
		maxn+=x;
	}
	ll i=0;
	for(i=(maxn+1)/2;!b[i];i++);
	printf("%d\n",i); 
	return 0;
}
```