#include<bits/stdc++.h>
using namespace std;

int main(){
	
	int n; cin>>n;
	bitset<4000010> bt;
	bt[0] = 1;
	int sum = 0;
	for(int i=0;i<n;i++){
		int a; cin>>a;
		sum += a;
		bt|=(bt<<a);
	}
	
	for(int i=(sum+1)/2;i<sum+1;i++){
		if(bt[i]){ cout<<i<<endl; return 0; }
	}
	
	
	return 0;
}

### Prompt

Your task is to create a Cpp solution to the following problem:

You are given N integers A_1, A_2, ..., A_N.

Consider the sums of all non-empty subsequences of A. There are 2^N - 1 such sums, an odd number.

Let the list of these sums in non-decreasing order be S_1, S_2, ..., S_{2^N - 1}.

Find the median of this list, S_{2^{N-1}}.

Constraints

* 1 \leq N \leq 2000
* 1 \leq A_i \leq 2000
* All input values are integers.

Input

Input is given from Standard Input in the following format:


N
A_1 A_2 ... A_N


Output

Print the median of the sorted list of the sums of all non-empty subsequences of A.

Examples

Input

3
1 2 1


Output

2


Input

1
58


Output

58

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;

int main(){
	
	int n; cin>>n;
	bitset<4000010> bt;
	bt[0] = 1;
	int sum = 0;
	for(int i=0;i<n;i++){
		int a; cin>>a;
		sum += a;
		bt|=(bt<<a);
	}
	
	for(int i=(sum+1)/2;i<sum+1;i++){
		if(bt[i]){ cout<<i<<endl; return 0; }
	}
	
	
	return 0;
}

```