#include <stdio.h>
int n;
int main() {
	scanf("%d", &n);
	for (int i = 1; i < 10; i++) {
		for (int j = 1; j < 10; j++) {
			if (n == i*j)n = 0;
		}
	}
	if (n)printf("No\n");
	else printf("Yes\n");
}
### Prompt

Generate a cpp solution to the following problem:

Having learned the multiplication table, Takahashi can multiply two integers between 1 and 9 (inclusive) together.

Given an integer N, determine whether N can be represented as the product of two integers between 1 and 9. If it can, print `Yes`; if it cannot, print `No`.

Constraints

* 1 \leq N \leq 100
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

If N can be represented as the product of two integers between 1 and 9 (inclusive), print `Yes`; if it cannot, print `No`.

Examples

Input

10


Output

Yes


Input

50


Output

No


Input

81


Output

Yes

### Response

```cpp
#include <stdio.h>
int n;
int main() {
	scanf("%d", &n);
	for (int i = 1; i < 10; i++) {
		for (int j = 1; j < 10; j++) {
			if (n == i*j)n = 0;
		}
	}
	if (n)printf("No\n");
	else printf("Yes\n");
}
```