#include <bits/stdc++.h>
using namespace std;
long long t, n, m;
long long nxt;
bool Check(long long s) {
  long long ret = 0;
  while (s) {
    ret += (s % 10);
    if (ret > m) return false;
    s /= 10;
  }
  return true;
}
signed main() {
  cin >> t;
  while (t--) {
    cin >> n >> m;
    nxt = 1;
    long long Copy = n;
    while (!Check(n)) {
      n = (n + nxt - 1) / nxt * nxt;
      nxt *= 10;
    }
    cout << n - Copy << endl;
  }
  return 0;
}

### Prompt

Your task is to create a CPP solution to the following problem:

You are given a positive integer n. In one move, you can increase n by one (i.e. make n := n + 1). Your task is to find the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers n and s (1 ≤ n ≤ 10^{18}; 1 ≤ s ≤ 162).

Output

For each test case, print the answer: the minimum number of moves you need to perform in order to make the sum of digits of n be less than or equal to s.

Example

Input


5
2 1
1 1
500 4
217871987498122 10
100000000000000001 1


Output


8
0
500
2128012501878
899999999999999999

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
long long t, n, m;
long long nxt;
bool Check(long long s) {
  long long ret = 0;
  while (s) {
    ret += (s % 10);
    if (ret > m) return false;
    s /= 10;
  }
  return true;
}
signed main() {
  cin >> t;
  while (t--) {
    cin >> n >> m;
    nxt = 1;
    long long Copy = n;
    while (!Check(n)) {
      n = (n + nxt - 1) / nxt * nxt;
      nxt *= 10;
    }
    cout << n - Copy << endl;
  }
  return 0;
}

```