#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const ll mod = 1000000007;

ll modpow(ll m, ll n)
{
  ll res = 1;
  while (n > 0)
  {
    if (n & 1)
    {
      res = res * m % mod;
    }
    m = m * m % mod;
    n >>= 1;
  }
  return res;
}

int main()
{
  ll m, n;
  cin >> m >> n;
  cout << modpow(m, n) << endl;
}

### Prompt

Please formulate a cpp solution to the following problem:

For given integers m and n, compute mn (mod 1,000,000,007). Here, A (mod M) is the remainder when A is divided by M.

Constraints

* 1 ≤ m ≤ 100
* 1 ≤ n ≤ 109

Input


m n


Two integers m and n are given in a line.

Output

Print mn (mod 1,000,000,007) in a line.

Examples

Input

2 3


Output

8


Input

5 8


Output

390625

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const ll mod = 1000000007;

ll modpow(ll m, ll n)
{
  ll res = 1;
  while (n > 0)
  {
    if (n & 1)
    {
      res = res * m % mod;
    }
    m = m * m % mod;
    n >>= 1;
  }
  return res;
}

int main()
{
  ll m, n;
  cin >> m >> n;
  cout << modpow(m, n) << endl;
}

```