#include <bits/stdc++.h>
using namespace std;


int main(){
    int n,k;
    cin >> n >> k;

    string s = "";
    while (s.size() < n)
    {
        for(int i = 0; i < k && s.size() < n; i++){
            for(int j = i; j < k && s.size() < n; j++){
                s += ('a' + j);
                if(s.size() < n && j != k - 1) s+=('a' + i);
            }
        }
    }

    cout << s << endl;
}
### Prompt

Please formulate a CPP solution to the following problem:

Let's define the cost of a string s as the number of index pairs i and j (1 ≤ i < j < |s|) such that s_i = s_j and s_{i+1} = s_{j+1}.

You are given two positive integers n and k. Among all strings with length n that contain only the first k characters of the Latin alphabet, find a string with minimum possible cost. If there are multiple such strings with minimum cost — find any of them.

Input

The only line contains two integers n and k (1 ≤ n ≤ 2 ⋅ 10^5; 1 ≤ k ≤ 26).

Output

Print the string s such that it consists of n characters, each its character is one of the k first Latin letters, and it has the minimum possible cost among all these strings. If there are multiple such strings — print any of them.

Examples

Input


9 4


Output


aabacadbb


Input


5 1


Output


aaaaa

Input


10 26


Output


codeforces

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;


int main(){
    int n,k;
    cin >> n >> k;

    string s = "";
    while (s.size() < n)
    {
        for(int i = 0; i < k && s.size() < n; i++){
            for(int j = i; j < k && s.size() < n; j++){
                s += ('a' + j);
                if(s.size() < n && j != k - 1) s+=('a' + i);
            }
        }
    }

    cout << s << endl;
}
```