#include <iostream>
using namespace std;
 
int
main()
{
int N;
 
cin >> N;
 
int n = 0;
while(n <= N)
{
if((N-n) % 7 == 0)
{
cout << "Yes\n";
return 0;
}
n += 4;
}
 
cout << "No\n";
 
return 0;
}
### Prompt

Develop a solution in Cpp to the problem described below:

La Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each. Determine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.

Constraints

* N is an integer between 1 and 100, inclusive.

Input

Input is given from Standard Input in the following format:


N


Output

If there is a way to buy some cakes and some doughnuts for exactly N dollars, print `Yes`; otherwise, print `No`.

Examples

Input

11


Output

Yes


Input

40


Output

Yes


Input

3


Output

No

### Response

```cpp
#include <iostream>
using namespace std;
 
int
main()
{
int N;
 
cin >> N;
 
int n = 0;
while(n <= N)
{
if((N-n) % 7 == 0)
{
cout << "Yes\n";
return 0;
}
n += 4;
}
 
cout << "No\n";
 
return 0;
}
```