#include <iostream>
using namespace std;

long long pow(long long m, long long n, long long p){
  if(n==1) return m%p;
  if(n%2==0) return pow((m*m)%p,n/2,p);
  return (pow((m*m)%p,(n-1)/2,p)*m)%p;
}

int main(){
  long long m,n;
  cin >> m >> n;
  cout << pow(m,n,1000000007) << endl;

  return 0;
}
### Prompt

In cpp, your task is to solve the following problem:

For given integers m and n, compute mn (mod 1,000,000,007). Here, A (mod M) is the remainder when A is divided by M.

Constraints

* 1 ≤ m ≤ 100
* 1 ≤ n ≤ 109

Input


m n


Two integers m and n are given in a line.

Output

Print mn (mod 1,000,000,007) in a line.

Examples

Input

2 3


Output

8


Input

5 8


Output

390625

### Response

```cpp
#include <iostream>
using namespace std;

long long pow(long long m, long long n, long long p){
  if(n==1) return m%p;
  if(n%2==0) return pow((m*m)%p,n/2,p);
  return (pow((m*m)%p,(n-1)/2,p)*m)%p;
}

int main(){
  long long m,n;
  cin >> m >> n;
  cout << pow(m,n,1000000007) << endl;

  return 0;
}
```