#include<bits/stdc++.h>
using namespace std; 

int main(){
	int n; cin>>n; 
	for(int x=0;;x++){
		int y=n-4*x;
		if(y<0) break; 
		if(y%7==0){
			cout<<"Yes"; return 0; 
		}
	}
	cout<<"No"; 
}
### Prompt

Construct a CPP code solution to the problem outlined:

La Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each. Determine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.

Constraints

* N is an integer between 1 and 100, inclusive.

Input

Input is given from Standard Input in the following format:


N


Output

If there is a way to buy some cakes and some doughnuts for exactly N dollars, print `Yes`; otherwise, print `No`.

Examples

Input

11


Output

Yes


Input

40


Output

Yes


Input

3


Output

No

### Response

```cpp
#include<bits/stdc++.h>
using namespace std; 

int main(){
	int n; cin>>n; 
	for(int x=0;;x++){
		int y=n-4*x;
		if(y<0) break; 
		if(y%7==0){
			cout<<"Yes"; return 0; 
		}
	}
	cout<<"No"; 
}
```