#include <iostream>

using namespace std;

int main(){
int a;
cin>>a;
int v[109]={};
v[0]=1;
for(int i=0;i<=100;i++){
v[i+4]|=v[i];
v[i+7]|=v[i];
}
if(v[a])cout<<"Yes\n";
else cout<<"No\n";
}
### Prompt

Develop a solution in cpp to the problem described below:

La Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each. Determine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.

Constraints

* N is an integer between 1 and 100, inclusive.

Input

Input is given from Standard Input in the following format:


N


Output

If there is a way to buy some cakes and some doughnuts for exactly N dollars, print `Yes`; otherwise, print `No`.

Examples

Input

11


Output

Yes


Input

40


Output

Yes


Input

3


Output

No

### Response

```cpp
#include <iostream>

using namespace std;

int main(){
int a;
cin>>a;
int v[109]={};
v[0]=1;
for(int i=0;i<=100;i++){
v[i+4]|=v[i];
v[i+7]|=v[i];
}
if(v[a])cout<<"Yes\n";
else cout<<"No\n";
}
```