#include <iostream>

using namespace std;

int func(int n, int s)
{
	if(n >= 0 && s == 1){
		return 1;
	}
	if(n == 0){
		return 1;
	}
	if(n < 0){
		return 0;
	}
	int r = 0;
	for(int i = s; i > 0; i--){
		r += func(n-i*i, i);
	}
	
	return r;
}

int main()
{
	int n, c, t;
	
	while(1){
		cin >> n;
		if(n == 0){
			break;
		}
		c = 0;
		
		for(int i = 1; i*i <= n; i++){
			t = i;
		}
		
		for(int i = t; i > 0; i--){
			c += func(n-i*i, i);
		}
		
		cout << c << endl;
	}
	
	return 0;
}
### Prompt

Develop a solution in Cpp to the problem described below:

People in Silverland use square coins. Not only they have square shapes but also their values are square numbers. Coins with values of all square numbers up to 289 (= 172), i.e., 1-credit coins, 4-credit coins, 9-credit coins, ..., and 289-credit coins, are available in Silverland.

There are four combinations of coins to pay ten credits:

* ten 1-credit coins,
* one 4-credit coin and six 1-credit coins,
* two 4-credit coins and two 1-credit coins, and
* one 9-credit coin and one 1-credit coin.



Your mission is to count the number of ways to pay a given amount using coins of Silverland.



Input

The input consists of lines each containing an integer meaning an amount to be paid, followed by a line containing a zero. You may assume that all the amounts are positive and less than 300.

Output

For each of the given amount, one line containing a single integer representing the number of combinations of coins should be output. No other characters should appear in the output.

Example

Input

2
10
30
0


Output

1
4
27

### Response

```cpp
#include <iostream>

using namespace std;

int func(int n, int s)
{
	if(n >= 0 && s == 1){
		return 1;
	}
	if(n == 0){
		return 1;
	}
	if(n < 0){
		return 0;
	}
	int r = 0;
	for(int i = s; i > 0; i--){
		r += func(n-i*i, i);
	}
	
	return r;
}

int main()
{
	int n, c, t;
	
	while(1){
		cin >> n;
		if(n == 0){
			break;
		}
		c = 0;
		
		for(int i = 1; i*i <= n; i++){
			t = i;
		}
		
		for(int i = t; i > 0; i--){
			c += func(n-i*i, i);
		}
		
		cout << c << endl;
	}
	
	return 0;
}
```