#include <bits/stdc++.h>
using namespace std;
typedef long long ll;

ll modpow(ll a, ll n, ll mod){
    ll res = 1;
    while(n > 0){
        if(n & 1) res = res * a % mod;
        a = a*a % mod;
        n >>= 1;
    }
    return res;
}

int main(){
    ll m, n;
    cin >> m >> n;
    cout << modpow(m, n, 1e9+7) << endl;
}

### Prompt

Generate a Cpp solution to the following problem:

For given integers m and n, compute mn (mod 1,000,000,007). Here, A (mod M) is the remainder when A is divided by M.

Constraints

* 1 ≤ m ≤ 100
* 1 ≤ n ≤ 109

Input


m n


Two integers m and n are given in a line.

Output

Print mn (mod 1,000,000,007) in a line.

Examples

Input

2 3


Output

8


Input

5 8


Output

390625

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;

ll modpow(ll a, ll n, ll mod){
    ll res = 1;
    while(n > 0){
        if(n & 1) res = res * a % mod;
        a = a*a % mod;
        n >>= 1;
    }
    return res;
}

int main(){
    ll m, n;
    cin >> m >> n;
    cout << modpow(m, n, 1e9+7) << endl;
}

```