#include<iostream>
int main(){
  int n;
  std::cin>>n;
  int a=4,b=7;
  for(int i=0;i<=100;++i)
    for(int j=0;j<=100;++j)
      if(a*i+b*j==n){
        puts("Yes");
        return 0;
      }
  puts("No");
}
### Prompt

Create a solution in CPP for the following problem:

La Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each. Determine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.

Constraints

* N is an integer between 1 and 100, inclusive.

Input

Input is given from Standard Input in the following format:


N


Output

If there is a way to buy some cakes and some doughnuts for exactly N dollars, print `Yes`; otherwise, print `No`.

Examples

Input

11


Output

Yes


Input

40


Output

Yes


Input

3


Output

No

### Response

```cpp
#include<iostream>
int main(){
  int n;
  std::cin>>n;
  int a=4,b=7;
  for(int i=0;i<=100;++i)
    for(int j=0;j<=100;++j)
      if(a*i+b*j==n){
        puts("Yes");
        return 0;
      }
  puts("No");
}
```