#include <bits/stdc++.h>
using namespace std;
int main() {
  int n;
  cin >> n;
  if (n < 20) {
    if (n == 2 || n == 3 || n == 4 || n == 5 || n == 6 || n == 8 || n == 12) {
      cout << "YES" << endl;
    } else {
      cout << "NO" << endl;
    }
  } else {
    int a = n / 10;
    int b = n % 10;
    if (a == 2 || a == 7 || a == 9 || b == 1 || b == 7 || b == 9) {
      cout << "NO" << endl;
    } else {
      cout << "YES" << endl;
    }
  }
}

### Prompt

Please formulate a cpp solution to the following problem:



Input

The input contains a single integer a (1 ≤ a ≤ 99).

Output

Output "YES" or "NO".

Examples

Input


5


Output


YES


Input


13


Output


NO


Input


24


Output


NO


Input


46


Output


YES

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  int n;
  cin >> n;
  if (n < 20) {
    if (n == 2 || n == 3 || n == 4 || n == 5 || n == 6 || n == 8 || n == 12) {
      cout << "YES" << endl;
    } else {
      cout << "NO" << endl;
    }
  } else {
    int a = n / 10;
    int b = n % 10;
    if (a == 2 || a == 7 || a == 9 || b == 1 || b == 7 || b == 9) {
      cout << "NO" << endl;
    } else {
      cout << "YES" << endl;
    }
  }
}

```