#include <iostream>
#include <vector>
#include <algorithm>
#include <string>
#include <sstream>
#include <cstring>
#include <cstdio>
#include <cstdlib>
#include <cmath>
#include <queue>
#include <stack>
#include <map>
#include <set>
#include <numeric>
#include <cctype>
#include <tuple>
#include <array>

#ifdef _MSC_VER
#include <agents.h>
#endif

#define FOR(i, a, b) for(int i = (a); i < (int)(b); ++i)
#define rep(i, n) FOR(i, 0, n)
#define ALL(v) v.begin(), v.end()
#define REV(v) v.rbegin(), v.rend()
#define MEMSET(v, s) memset(v, s, sizeof(v))
#define X first
#define Y second

using namespace std;

typedef long long ll;

int dp[500][20];

int rec(int cost, int coin){
	if (cost < 0) return 0;
	if (cost <= 3) return 1;
	int &res = dp[cost][coin];
	if (res >= 1) return res;

	res = 1;
	for (int i = coin; i >= 2; --i){
		res += rec(cost - i*i, i);
	}
	return res;
}

int main(){
	int n;
	while (cin >> n, n){
		cout << rec(n, 17) << endl;
	}

	return 0;
}
### Prompt

Your task is to create a Cpp solution to the following problem:

People in Silverland use square coins. Not only they have square shapes but also their values are square numbers. Coins with values of all square numbers up to 289 (= 172), i.e., 1-credit coins, 4-credit coins, 9-credit coins, ..., and 289-credit coins, are available in Silverland.

There are four combinations of coins to pay ten credits:

* ten 1-credit coins,
* one 4-credit coin and six 1-credit coins,
* two 4-credit coins and two 1-credit coins, and
* one 9-credit coin and one 1-credit coin.



Your mission is to count the number of ways to pay a given amount using coins of Silverland.



Input

The input consists of lines each containing an integer meaning an amount to be paid, followed by a line containing a zero. You may assume that all the amounts are positive and less than 300.

Output

For each of the given amount, one line containing a single integer representing the number of combinations of coins should be output. No other characters should appear in the output.

Example

Input

2
10
30
0


Output

1
4
27

### Response

```cpp
#include <iostream>
#include <vector>
#include <algorithm>
#include <string>
#include <sstream>
#include <cstring>
#include <cstdio>
#include <cstdlib>
#include <cmath>
#include <queue>
#include <stack>
#include <map>
#include <set>
#include <numeric>
#include <cctype>
#include <tuple>
#include <array>

#ifdef _MSC_VER
#include <agents.h>
#endif

#define FOR(i, a, b) for(int i = (a); i < (int)(b); ++i)
#define rep(i, n) FOR(i, 0, n)
#define ALL(v) v.begin(), v.end()
#define REV(v) v.rbegin(), v.rend()
#define MEMSET(v, s) memset(v, s, sizeof(v))
#define X first
#define Y second

using namespace std;

typedef long long ll;

int dp[500][20];

int rec(int cost, int coin){
	if (cost < 0) return 0;
	if (cost <= 3) return 1;
	int &res = dp[cost][coin];
	if (res >= 1) return res;

	res = 1;
	for (int i = coin; i >= 2; --i){
		res += rec(cost - i*i, i);
	}
	return res;
}

int main(){
	int n;
	while (cin >> n, n){
		cout << rec(n, 17) << endl;
	}

	return 0;
}
```