#include "bits/stdc++.h"
using namespace std;
typedef long long LL;
const LL MOD = 1000000007LL;
LL mod_pow(LL a, LL n) {
	if (n == 0) return 1;
	if (n % 2 == 0) {
		LL b = mod_pow(a, n / 2);
		return (b*b) % MOD;
	}
	return (a*mod_pow(a, n - 1)) % MOD;
}
int main() {
	LL m, n;
	cin >> m >> n;
	cout << mod_pow(m, n) << endl;
}

### Prompt

In cpp, your task is to solve the following problem:

For given integers m and n, compute mn (mod 1,000,000,007). Here, A (mod M) is the remainder when A is divided by M.

Constraints

* 1 ≤ m ≤ 100
* 1 ≤ n ≤ 109

Input


m n


Two integers m and n are given in a line.

Output

Print mn (mod 1,000,000,007) in a line.

Examples

Input

2 3


Output

8


Input

5 8


Output

390625

### Response

```cpp
#include "bits/stdc++.h"
using namespace std;
typedef long long LL;
const LL MOD = 1000000007LL;
LL mod_pow(LL a, LL n) {
	if (n == 0) return 1;
	if (n % 2 == 0) {
		LL b = mod_pow(a, n / 2);
		return (b*b) % MOD;
	}
	return (a*mod_pow(a, n - 1)) % MOD;
}
int main() {
	LL m, n;
	cin >> m >> n;
	cout << mod_pow(m, n) << endl;
}

```