#include<cstdio>
#define ll long long int
using namespace std;
const int mod = 1000000007;

ll qpow(ll x, ll y)
{
    ll res=1;
    while(y)
    {
        if(y&1) res=res*x%mod;
        y>>=1;
        x=x*x%mod;
    }
    return res;
}

int main()
{
    ll m, n;
    scanf("%lld%lld", &m, &n);
    printf("%lld\n", qpow(m, n));
    return 0;
}
### Prompt

Create a solution in CPP for the following problem:

For given integers m and n, compute mn (mod 1,000,000,007). Here, A (mod M) is the remainder when A is divided by M.

Constraints

* 1 ≤ m ≤ 100
* 1 ≤ n ≤ 109

Input


m n


Two integers m and n are given in a line.

Output

Print mn (mod 1,000,000,007) in a line.

Examples

Input

2 3


Output

8


Input

5 8


Output

390625

### Response

```cpp
#include<cstdio>
#define ll long long int
using namespace std;
const int mod = 1000000007;

ll qpow(ll x, ll y)
{
    ll res=1;
    while(y)
    {
        if(y&1) res=res*x%mod;
        y>>=1;
        x=x*x%mod;
    }
    return res;
}

int main()
{
    ll m, n;
    scanf("%lld%lld", &m, &n);
    printf("%lld\n", qpow(m, n));
    return 0;
}
```