#include <bits/stdc++.h>
using namespace std;
int flag[1234];
void f(char C, int t) {
  int cnt = 0;
  while (t > 1) {
    if (t & 1) {
      if (C == '|') {
        flag[cnt] = 1;
      } else if (C == '^') {
        if (flag[cnt] == 1)
          flag[cnt] = -1;
        else if (flag[cnt] == -1)
          flag[cnt] = 1;
        else if (flag[cnt] == 2)
          flag[cnt] = 0;
        else
          flag[cnt] = 2;
      }
    } else {
      if (C == '&') flag[cnt] = -1;
    }
    t >>= 1;
    cnt++;
  }
}
int main() {
  int n, t;
  char C;
  scanf("%d ", &n);
  for (int i = 0; i < n; i++) {
    scanf("%c %d ", &C, &t);
    f(C, t + 1024);
  }
  int a = 1023, b = 0, c = 0;
  for (int i = 0; i < 15; i++) {
    if (flag[i] == -1) {
      a -= pow(2, i);
    } else if (flag[i] == 1) {
      b += pow(2, i);
    } else if (flag[i] == 2) {
      c += pow(2, i);
    }
  }
  cout << 3 << endl;
  cout << '&' << ' ' << a << '\n';
  cout << '|' << ' ' << b << '\n';
  cout << '^' << ' ' << c << '\n';
}

### Prompt

Construct a Cpp code solution to the problem outlined:

Petya learned a new programming language CALPAS. A program in this language always takes one non-negative integer and returns one non-negative integer as well.

In the language, there are only three commands: apply a bitwise operation AND, OR or XOR with a given constant to the current integer. A program can contain an arbitrary sequence of these operations with arbitrary constants from 0 to 1023. When the program is run, all operations are applied (in the given order) to the argument and in the end the result integer is returned.

Petya wrote a program in this language, but it turned out to be too long. Write a program in CALPAS that does the same thing as the Petya's program, and consists of no more than 5 lines. Your program should return the same integer as Petya's program for all arguments from 0 to 1023.

Input

The first line contains an integer n (1 ≤ n ≤ 5·105) — the number of lines.

Next n lines contain commands. A command consists of a character that represents the operation ("&", "|" or "^" for AND, OR or XOR respectively), and the constant xi 0 ≤ xi ≤ 1023.

Output

Output an integer k (0 ≤ k ≤ 5) — the length of your program.

Next k lines must contain commands in the same format as in the input.

Examples

Input

3
| 3
^ 2
| 1


Output

2
| 3
^ 2


Input

3
&amp; 1
&amp; 3
&amp; 5


Output

1
&amp; 1


Input

3
^ 1
^ 2
^ 3


Output

0

Note

You can read about bitwise operations in <https://en.wikipedia.org/wiki/Bitwise_operation>.

Second sample:

Let x be an input of the Petya's program. It's output is ((x&1)&3)&5 = x&(1&3&5) = x&1. So these two programs always give the same outputs.

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int flag[1234];
void f(char C, int t) {
  int cnt = 0;
  while (t > 1) {
    if (t & 1) {
      if (C == '|') {
        flag[cnt] = 1;
      } else if (C == '^') {
        if (flag[cnt] == 1)
          flag[cnt] = -1;
        else if (flag[cnt] == -1)
          flag[cnt] = 1;
        else if (flag[cnt] == 2)
          flag[cnt] = 0;
        else
          flag[cnt] = 2;
      }
    } else {
      if (C == '&') flag[cnt] = -1;
    }
    t >>= 1;
    cnt++;
  }
}
int main() {
  int n, t;
  char C;
  scanf("%d ", &n);
  for (int i = 0; i < n; i++) {
    scanf("%c %d ", &C, &t);
    f(C, t + 1024);
  }
  int a = 1023, b = 0, c = 0;
  for (int i = 0; i < 15; i++) {
    if (flag[i] == -1) {
      a -= pow(2, i);
    } else if (flag[i] == 1) {
      b += pow(2, i);
    } else if (flag[i] == 2) {
      c += pow(2, i);
    }
  }
  cout << 3 << endl;
  cout << '&' << ' ' << a << '\n';
  cout << '|' << ' ' << b << '\n';
  cout << '^' << ' ' << c << '\n';
}

```