#include <bits/stdc++.h>
using namespace std;
#define REP(i,n) for(int(i)=0;i<(n);i++)

int main(){
  int n,f=0;cin>>n;
  while(n>28) n-=28;
  REP(i,8) REP(j,5) if(n==i*4+j*7) f=1;
  cout<<(f?"Yes":"No");
}
### Prompt

In Cpp, your task is to solve the following problem:

La Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each. Determine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.

Constraints

* N is an integer between 1 and 100, inclusive.

Input

Input is given from Standard Input in the following format:


N


Output

If there is a way to buy some cakes and some doughnuts for exactly N dollars, print `Yes`; otherwise, print `No`.

Examples

Input

11


Output

Yes


Input

40


Output

Yes


Input

3


Output

No

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
#define REP(i,n) for(int(i)=0;i<(n);i++)

int main(){
  int n,f=0;cin>>n;
  while(n>28) n-=28;
  REP(i,8) REP(j,5) if(n==i*4+j*7) f=1;
  cout<<(f?"Yes":"No");
}
```