#include <bits/stdc++.h>
using namespace std;

int64_t	modpow(int64_t a, int64_t n, const int64_t mod)
{
	int64_t	result = 1;
	while (n) {
		if (n & 1) result = result * a % mod;
		a = a * a % mod;
		n >>= 1;
	}
	return result;
}

int	main()
{
	const static int64_t	mod = 1000000007;
	int64_t	m, n;
	cin >> m >> n;
	cout << modpow(m, n, mod) << endl;
}

### Prompt

Your challenge is to write a CPP solution to the following problem:

For given integers m and n, compute mn (mod 1,000,000,007). Here, A (mod M) is the remainder when A is divided by M.

Constraints

* 1 ≤ m ≤ 100
* 1 ≤ n ≤ 109

Input


m n


Two integers m and n are given in a line.

Output

Print mn (mod 1,000,000,007) in a line.

Examples

Input

2 3


Output

8


Input

5 8


Output

390625

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;

int64_t	modpow(int64_t a, int64_t n, const int64_t mod)
{
	int64_t	result = 1;
	while (n) {
		if (n & 1) result = result * a % mod;
		a = a * a % mod;
		n >>= 1;
	}
	return result;
}

int	main()
{
	const static int64_t	mod = 1000000007;
	int64_t	m, n;
	cin >> m >> n;
	cout << modpow(m, n, mod) << endl;
}

```