#include<stdio.h>
#include<stdlib.h>
int main(void){
  int N;
  scanf("%d",&N);
  int x = N/7;
  for(int i=0;i<=x;i++){
    if((N-7*i)%4==0){
      printf("Yes");
      exit(0);
    }
  }
  printf("No");
  return 0;
}

### Prompt

Develop a solution in cpp to the problem described below:

La Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each. Determine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.

Constraints

* N is an integer between 1 and 100, inclusive.

Input

Input is given from Standard Input in the following format:


N


Output

If there is a way to buy some cakes and some doughnuts for exactly N dollars, print `Yes`; otherwise, print `No`.

Examples

Input

11


Output

Yes


Input

40


Output

Yes


Input

3


Output

No

### Response

```cpp
#include<stdio.h>
#include<stdlib.h>
int main(void){
  int N;
  scanf("%d",&N);
  int x = N/7;
  for(int i=0;i<=x;i++){
    if((N-7*i)%4==0){
      printf("Yes");
      exit(0);
    }
  }
  printf("No");
  return 0;
}

```