#include <stdio.h>
int main()
{
 int n;
 scanf("%d",&n);
 for(int i=0;4*i<=n;i++)
  if((n-4*i)%7==0)
  {
   puts("Yes");
   return 0;
  }
 puts("No");
 return 0;
}
### Prompt

In CPP, your task is to solve the following problem:

La Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each. Determine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.

Constraints

* N is an integer between 1 and 100, inclusive.

Input

Input is given from Standard Input in the following format:


N


Output

If there is a way to buy some cakes and some doughnuts for exactly N dollars, print `Yes`; otherwise, print `No`.

Examples

Input

11


Output

Yes


Input

40


Output

Yes


Input

3


Output

No

### Response

```cpp
#include <stdio.h>
int main()
{
 int n;
 scanf("%d",&n);
 for(int i=0;4*i<=n;i++)
  if((n-4*i)%7==0)
  {
   puts("Yes");
   return 0;
  }
 puts("No");
 return 0;
}
```