//AOJ NTL_1_B
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;

ll m, n;

ll mod_pow(ll x, ll n, ll mod) {
    ll res = 1;
    
    while (n>0) {
        if (n&1) res = res*x%mod;
        x = x*x%mod;
        n >>= 1;
    }
    
    return res;
}

int main() {
    cin >> m >> n;
    cout << mod_pow(m, n, 1000000007) << endl;
}

### Prompt

Please provide a cpp coded solution to the problem described below:

For given integers m and n, compute mn (mod 1,000,000,007). Here, A (mod M) is the remainder when A is divided by M.

Constraints

* 1 ≤ m ≤ 100
* 1 ≤ n ≤ 109

Input


m n


Two integers m and n are given in a line.

Output

Print mn (mod 1,000,000,007) in a line.

Examples

Input

2 3


Output

8


Input

5 8


Output

390625

### Response

```cpp
//AOJ NTL_1_B
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;

ll m, n;

ll mod_pow(ll x, ll n, ll mod) {
    ll res = 1;
    
    while (n>0) {
        if (n&1) res = res*x%mod;
        x = x*x%mod;
        n >>= 1;
    }
    
    return res;
}

int main() {
    cin >> m >> n;
    cout << mod_pow(m, n, 1000000007) << endl;
}

```