#include <stdio.h>

int main(){
  int N;
  scanf("%d",&N);
  for(int i=0;i<100;i++){
    for(int j=0;j<100;j++){
      if(4*i+7*j==N) {printf("Yes"); return 0;}
    }
  }
  printf("No");
}

### Prompt

Please formulate a cpp solution to the following problem:

La Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each. Determine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.

Constraints

* N is an integer between 1 and 100, inclusive.

Input

Input is given from Standard Input in the following format:


N


Output

If there is a way to buy some cakes and some doughnuts for exactly N dollars, print `Yes`; otherwise, print `No`.

Examples

Input

11


Output

Yes


Input

40


Output

Yes


Input

3


Output

No

### Response

```cpp
#include <stdio.h>

int main(){
  int N;
  scanf("%d",&N);
  for(int i=0;i<100;i++){
    for(int j=0;j<100;j++){
      if(4*i+7*j==N) {printf("Yes"); return 0;}
    }
  }
  printf("No");
}

```