#include<stdio.h>
int main()
{
	int n;
	scanf("%d",&n);
	int flag=0;
	for(int i=0;i<=25;i++)
	for(int j=0;j<=15;j++)
	if(4*i+7*j==n) {
		flag=1;
		break;
		
	}
	if(flag) printf("Yes");
	else  printf("No");
	
	
	
}
### Prompt

Please provide a CPP coded solution to the problem described below:

La Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each. Determine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.

Constraints

* N is an integer between 1 and 100, inclusive.

Input

Input is given from Standard Input in the following format:


N


Output

If there is a way to buy some cakes and some doughnuts for exactly N dollars, print `Yes`; otherwise, print `No`.

Examples

Input

11


Output

Yes


Input

40


Output

Yes


Input

3


Output

No

### Response

```cpp
#include<stdio.h>
int main()
{
	int n;
	scanf("%d",&n);
	int flag=0;
	for(int i=0;i<=25;i++)
	for(int j=0;j<=15;j++)
	if(4*i+7*j==n) {
		flag=1;
		break;
		
	}
	if(flag) printf("Yes");
	else  printf("No");
	
	
	
}
```