#include<iostream>
using namespace std;

int main(){
  int n, i, flag = 0;
  cin >> n;
  for(i = 0; i*7 <= n; i++) if(!((n-7*i)%4)) flag = 1;
  if(flag) cout << "Yes" << endl;
  else cout << "No" << endl;
}
### Prompt

Generate a cpp solution to the following problem:

La Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each. Determine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.

Constraints

* N is an integer between 1 and 100, inclusive.

Input

Input is given from Standard Input in the following format:


N


Output

If there is a way to buy some cakes and some doughnuts for exactly N dollars, print `Yes`; otherwise, print `No`.

Examples

Input

11


Output

Yes


Input

40


Output

Yes


Input

3


Output

No

### Response

```cpp
#include<iostream>
using namespace std;

int main(){
  int n, i, flag = 0;
  cin >> n;
  for(i = 0; i*7 <= n; i++) if(!((n-7*i)%4)) flag = 1;
  if(flag) cout << "Yes" << endl;
  else cout << "No" << endl;
}
```