#include<bits/stdc++.h>
using namespace std;

const int MOD = 1e9+7;

long long modpow(long long a, long long b){
	long long c = 1;
	while(b > 0){
		if(b & 1) c = c * a % MOD;
		a = a * a % MOD;
		b >>= 1;
	}
	return c;
}

int main() {
	
	int m,n;
	cin >> m >> n;
	cout << modpow(m,n) << endl;
}


### Prompt

Create a solution in Cpp for the following problem:

For given integers m and n, compute mn (mod 1,000,000,007). Here, A (mod M) is the remainder when A is divided by M.

Constraints

* 1 ≤ m ≤ 100
* 1 ≤ n ≤ 109

Input


m n


Two integers m and n are given in a line.

Output

Print mn (mod 1,000,000,007) in a line.

Examples

Input

2 3


Output

8


Input

5 8


Output

390625

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;

const int MOD = 1e9+7;

long long modpow(long long a, long long b){
	long long c = 1;
	while(b > 0){
		if(b & 1) c = c * a % MOD;
		a = a * a % MOD;
		b >>= 1;
	}
	return c;
}

int main() {
	
	int m,n;
	cin >> m >> n;
	cout << modpow(m,n) << endl;
}


```