#include<stdio.h>

int main(){
	int a;
	bool b=false;
	scanf("%d",&a);
	for(int c=0;c*4<=a;c++){
		if((a-c*4)%7==0){
			b=true;
			break;
		}
	}
	if(b==true)
	printf("Yes");
	else
	printf("No");
	return 0;
}
### Prompt

Please create a solution in CPP to the following problem:

La Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each. Determine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.

Constraints

* N is an integer between 1 and 100, inclusive.

Input

Input is given from Standard Input in the following format:


N


Output

If there is a way to buy some cakes and some doughnuts for exactly N dollars, print `Yes`; otherwise, print `No`.

Examples

Input

11


Output

Yes


Input

40


Output

Yes


Input

3


Output

No

### Response

```cpp
#include<stdio.h>

int main(){
	int a;
	bool b=false;
	scanf("%d",&a);
	for(int c=0;c*4<=a;c++){
		if((a-c*4)%7==0){
			b=true;
			break;
		}
	}
	if(b==true)
	printf("Yes");
	else
	printf("No");
	return 0;
}
```