#include <iostream>
using namespace std;

long long Pow(long long m, int n) {
  if (n == 0)
    return 1;
  long long res = Pow(m * m % 1000000007, n / 2);
  if (n % 2 == 1)
    res = res * m % 1000000007;
  return res;
}

int main() {
  int m, n;
  cin >> m >> n;
  cout << Pow(m, n) << endl;
}

### Prompt

Develop a solution in cpp to the problem described below:

For given integers m and n, compute mn (mod 1,000,000,007). Here, A (mod M) is the remainder when A is divided by M.

Constraints

* 1 ≤ m ≤ 100
* 1 ≤ n ≤ 109

Input


m n


Two integers m and n are given in a line.

Output

Print mn (mod 1,000,000,007) in a line.

Examples

Input

2 3


Output

8


Input

5 8


Output

390625

### Response

```cpp
#include <iostream>
using namespace std;

long long Pow(long long m, int n) {
  if (n == 0)
    return 1;
  long long res = Pow(m * m % 1000000007, n / 2);
  if (n % 2 == 1)
    res = res * m % 1000000007;
  return res;
}

int main() {
  int m, n;
  cin >> m >> n;
  cout << Pow(m, n) << endl;
}

```