#include <cstdio>
using namespace std;
int main(){
  int N;
  scanf("%d",&N);
  N%=28;
  for(int i=0;i<=N;i+=7){
    if((N-i)%4==0){
      printf("Yes\n");
      return 0;
    }
  }
  printf("No\n");
  return 0;
}
### Prompt

Your task is to create a Cpp solution to the following problem:

La Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each. Determine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.

Constraints

* N is an integer between 1 and 100, inclusive.

Input

Input is given from Standard Input in the following format:


N


Output

If there is a way to buy some cakes and some doughnuts for exactly N dollars, print `Yes`; otherwise, print `No`.

Examples

Input

11


Output

Yes


Input

40


Output

Yes


Input

3


Output

No

### Response

```cpp
#include <cstdio>
using namespace std;
int main(){
  int N;
  scanf("%d",&N);
  N%=28;
  for(int i=0;i<=N;i+=7){
    if((N-i)%4==0){
      printf("Yes\n");
      return 0;
    }
  }
  printf("No\n");
  return 0;
}
```