# include <stdio.h>
int main()
{
    long long int t,a,i,p,m=1000000007,r;

    while(scanf("%lld %lld",&a,&p)==2)
    {
        r = 1;

        while(p)
        {
            if(p%2)
                r = (r*a)%m;
            a = (a*a)%m;
            p/=2;
        }

        printf("%lld\n",r);
    }

    return 0;
}
### Prompt

Your task is to create a Cpp solution to the following problem:

For given integers m and n, compute mn (mod 1,000,000,007). Here, A (mod M) is the remainder when A is divided by M.

Constraints

* 1 ≤ m ≤ 100
* 1 ≤ n ≤ 109

Input


m n


Two integers m and n are given in a line.

Output

Print mn (mod 1,000,000,007) in a line.

Examples

Input

2 3


Output

8


Input

5 8


Output

390625

### Response

```cpp
# include <stdio.h>
int main()
{
    long long int t,a,i,p,m=1000000007,r;

    while(scanf("%lld %lld",&a,&p)==2)
    {
        r = 1;

        while(p)
        {
            if(p%2)
                r = (r*a)%m;
            a = (a*a)%m;
            p/=2;
        }

        printf("%lld\n",r);
    }

    return 0;
}
```