#include<bits/stdc++.h>
using namespace std;
int main(){
  int n;
  cin>>n;
  
  for(int i=0; i<=n/4; ++i) for(int j=0; j<=n/7; ++j) if(i*4+j*7==n) return cout<<"Yes\n",0;
  cout<<"No\n";
  return 0;
}
### Prompt

Construct a CPP code solution to the problem outlined:

La Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each. Determine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.

Constraints

* N is an integer between 1 and 100, inclusive.

Input

Input is given from Standard Input in the following format:


N


Output

If there is a way to buy some cakes and some doughnuts for exactly N dollars, print `Yes`; otherwise, print `No`.

Examples

Input

11


Output

Yes


Input

40


Output

Yes


Input

3


Output

No

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;
int main(){
  int n;
  cin>>n;
  
  for(int i=0; i<=n/4; ++i) for(int j=0; j<=n/7; ++j) if(i*4+j*7==n) return cout<<"Yes\n",0;
  cout<<"No\n";
  return 0;
}
```