#include <bits/stdc++.h>
using namespace std;
 
int main(){
  int n;
  cin >> n;
  if(n<=3||n==5||n==6||n==9||n==10||n==13||n==17){
    cout << "No";
  }else{
    cout << "Yes";
  }
}

### Prompt

Please provide a Cpp coded solution to the problem described below:

La Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each. Determine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.

Constraints

* N is an integer between 1 and 100, inclusive.

Input

Input is given from Standard Input in the following format:


N


Output

If there is a way to buy some cakes and some doughnuts for exactly N dollars, print `Yes`; otherwise, print `No`.

Examples

Input

11


Output

Yes


Input

40


Output

Yes


Input

3


Output

No

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
 
int main(){
  int n;
  cin >> n;
  if(n<=3||n==5||n==6||n==9||n==10||n==13||n==17){
    cout << "No";
  }else{
    cout << "Yes";
  }
}

```