#include<bits/stdc++.h>
using namespace std;
const int MOD=1e9+7;
long long power(int m,int n){
	long long res=1,mm=m;
	while(n){
		if(n & 1)res=(res*mm)%MOD;
		mm=(mm*mm)%MOD;
		n>>=1;
	}
	return res;
}
int main(){
	int m,n;
	cin>>m>>n;
	cout<<power(m,n)<<endl;
}

### Prompt

Construct a cpp code solution to the problem outlined:

For given integers m and n, compute mn (mod 1,000,000,007). Here, A (mod M) is the remainder when A is divided by M.

Constraints

* 1 ≤ m ≤ 100
* 1 ≤ n ≤ 109

Input


m n


Two integers m and n are given in a line.

Output

Print mn (mod 1,000,000,007) in a line.

Examples

Input

2 3


Output

8


Input

5 8


Output

390625

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;
const int MOD=1e9+7;
long long power(int m,int n){
	long long res=1,mm=m;
	while(n){
		if(n & 1)res=(res*mm)%MOD;
		mm=(mm*mm)%MOD;
		n>>=1;
	}
	return res;
}
int main(){
	int m,n;
	cin>>m>>n;
	cout<<power(m,n)<<endl;
}

```