#include <iostream>
using namespace std;

int main(){
	int i, j, n;
	cin >> n;
	
	for(i=0; i<=n/4; i++){
	   if( (n-i*4)%7==0 ){
	      cout << "Yes";
	      return 0;
	   } 
	}
	
	cout << "No";
	return 0;
}
  
### Prompt

Develop a solution in CPP to the problem described below:

La Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each. Determine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.

Constraints

* N is an integer between 1 and 100, inclusive.

Input

Input is given from Standard Input in the following format:


N


Output

If there is a way to buy some cakes and some doughnuts for exactly N dollars, print `Yes`; otherwise, print `No`.

Examples

Input

11


Output

Yes


Input

40


Output

Yes


Input

3


Output

No

### Response

```cpp
#include <iostream>
using namespace std;

int main(){
	int i, j, n;
	cin >> n;
	
	for(i=0; i<=n/4; i++){
	   if( (n-i*4)%7==0 ){
	      cout << "Yes";
	      return 0;
	   } 
	}
	
	cout << "No";
	return 0;
}
  
```