#include <bits/stdc++.h>

using namespace std;

int64_t mod_pow(int64_t x, int64_t n, int64_t mod) {
  int64_t ret = 1;
  while(n > 0) {
    if(n & 1) (ret *= x) %= mod;
    (x *= x) %= mod;
    n >>= 1;
  }
  return ret;
}

int main() {
  int M, N;
  cin >> M >> N;
  cout << mod_pow(M, N, 1e9 + 7) << endl;
}

### Prompt

Develop a solution in cpp to the problem described below:

For given integers m and n, compute mn (mod 1,000,000,007). Here, A (mod M) is the remainder when A is divided by M.

Constraints

* 1 ≤ m ≤ 100
* 1 ≤ n ≤ 109

Input


m n


Two integers m and n are given in a line.

Output

Print mn (mod 1,000,000,007) in a line.

Examples

Input

2 3


Output

8


Input

5 8


Output

390625

### Response

```cpp
#include <bits/stdc++.h>

using namespace std;

int64_t mod_pow(int64_t x, int64_t n, int64_t mod) {
  int64_t ret = 1;
  while(n > 0) {
    if(n & 1) (ret *= x) %= mod;
    (x *= x) %= mod;
    n >>= 1;
  }
  return ret;
}

int main() {
  int M, N;
  cin >> M >> N;
  cout << mod_pow(M, N, 1e9 + 7) << endl;
}

```