#include <iostream>
using namespace std;
#define M 1000000007

int rec(long m, long n) {
    if(n == 1) return m % M;
    long long m2 = rec((m % M) * (m % M), n / 2);
    if(n % 2 == 1) {
        m2 = ((m2 % M) * (m % M));
    }
    return m2 % M;
}

int main(){
    int m,n;
    cin >> m >> n;
    cout << rec(m, n) << endl;
    return 0;
}

### Prompt

Please formulate a CPP solution to the following problem:

For given integers m and n, compute mn (mod 1,000,000,007). Here, A (mod M) is the remainder when A is divided by M.

Constraints

* 1 ≤ m ≤ 100
* 1 ≤ n ≤ 109

Input


m n


Two integers m and n are given in a line.

Output

Print mn (mod 1,000,000,007) in a line.

Examples

Input

2 3


Output

8


Input

5 8


Output

390625

### Response

```cpp
#include <iostream>
using namespace std;
#define M 1000000007

int rec(long m, long n) {
    if(n == 1) return m % M;
    long long m2 = rec((m % M) * (m % M), n / 2);
    if(n % 2 == 1) {
        m2 = ((m2 % M) * (m % M));
    }
    return m2 % M;
}

int main(){
    int m,n;
    cin >> m >> n;
    cout << rec(m, n) << endl;
    return 0;
}

```