#include <cstdio>
#include <iostream>
using namespace std;
typedef long long ll;
#define MOD 1000000007ll
ll modpow(ll a,ll x){
	ll ret = 1ll;
	while(x){
		if(x&1)ret=ret*a%MOD;
		a = a*a%MOD;
		x >>= 1;
	}
	return ret;
}
int main(){
	ll m,n;
	cin >> m >> n;
	cout << modpow(m,n) << endl;
	return 0;
}
### Prompt

Please provide a Cpp coded solution to the problem described below:

For given integers m and n, compute mn (mod 1,000,000,007). Here, A (mod M) is the remainder when A is divided by M.

Constraints

* 1 ≤ m ≤ 100
* 1 ≤ n ≤ 109

Input


m n


Two integers m and n are given in a line.

Output

Print mn (mod 1,000,000,007) in a line.

Examples

Input

2 3


Output

8


Input

5 8


Output

390625

### Response

```cpp
#include <cstdio>
#include <iostream>
using namespace std;
typedef long long ll;
#define MOD 1000000007ll
ll modpow(ll a,ll x){
	ll ret = 1ll;
	while(x){
		if(x&1)ret=ret*a%MOD;
		a = a*a%MOD;
		x >>= 1;
	}
	return ret;
}
int main(){
	ll m,n;
	cin >> m >> n;
	cout << modpow(m,n) << endl;
	return 0;
}
```