#include<iostream>

using namespace std;

int main(){
  int n,i,j,c=0;
  
  cin>>n;
  
  for(i=n/7;i>=0;i--){
    j=(n-7*i)%4;
    if(j==0)
      c++;
  }
  cout<<(c>0?"Yes":"No")<<endl;
    return 0;
    
}
### Prompt

Your challenge is to write a cpp solution to the following problem:

La Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each. Determine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.

Constraints

* N is an integer between 1 and 100, inclusive.

Input

Input is given from Standard Input in the following format:


N


Output

If there is a way to buy some cakes and some doughnuts for exactly N dollars, print `Yes`; otherwise, print `No`.

Examples

Input

11


Output

Yes


Input

40


Output

Yes


Input

3


Output

No

### Response

```cpp
#include<iostream>

using namespace std;

int main(){
  int n,i,j,c=0;
  
  cin>>n;
  
  for(i=n/7;i>=0;i--){
    j=(n-7*i)%4;
    if(j==0)
      c++;
  }
  cout<<(c>0?"Yes":"No")<<endl;
    return 0;
    
}
```