#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
const int MOD = 1e9 + 7;
int power(ll x, ll y){
    ll res = 1; 
    while(y > 0){
        if (y & 1) res = res * x % MOD;
        x = x * x % MOD;
        y >>= 1;
    }
    return res;
}
int main(){
    ll m, n; cin >> m >> n;
    cout << power(m, n) << endl;
}

### Prompt

Please create a solution in Cpp to the following problem:

For given integers m and n, compute mn (mod 1,000,000,007). Here, A (mod M) is the remainder when A is divided by M.

Constraints

* 1 ≤ m ≤ 100
* 1 ≤ n ≤ 109

Input


m n


Two integers m and n are given in a line.

Output

Print mn (mod 1,000,000,007) in a line.

Examples

Input

2 3


Output

8


Input

5 8


Output

390625

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
const int MOD = 1e9 + 7;
int power(ll x, ll y){
    ll res = 1; 
    while(y > 0){
        if (y & 1) res = res * x % MOD;
        x = x * x % MOD;
        y >>= 1;
    }
    return res;
}
int main(){
    ll m, n; cin >> m >> n;
    cout << power(m, n) << endl;
}

```