#include <iostream>
#include <iomanip>
#include <string>
#include <sstream>
#include <algorithm>
#include <vector>
#include <utility>
#include <stack>
#include <queue>
#include <map>
#include <set>
#include <functional>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <cmath>
#include <cassert>
 
using namespace std;
 
#define REP(i,s,e) for(int i=(s); i<(int)(e); i++)
#define rep(i,n) REP(i, 0, n)
#define pb push_back
#define mp make_pair
#define all(r) (r).begin(),(r).end()
#define rall(r) (r).rbegin(),(r).rend()
#define fi first
#define se second
#define DBG(X) cout<<" "<<#X<<" : "<<X<<endl
 
typedef long long ll;
typedef vector<int> vi;
typedef vector<ll> vl;
typedef pair<int, int> pii;

const int INF = 1e9;
const double EPS = 1e-8;
const int mod = 1e9 + 7;
const ll LINF = 1e18;

struct Input
{
	int n;char c;char str[10010];string s;ll l;double d;
	int nextInt(){scanf("%d", &n);return n;}
	ll nextLong(){scanf("%lld", &l);return l;}
	double nextDouble(){scanf("%lf", &d);return d;}
	char nextChar(){scanf("%c", &c);return c;}
	string next(){scanf("%s", str);return string(str);}
	string nextLine(){getline(cin, s);return s;}
};
Input in;

ll dp[310];
vector<int> v;

int main(){
	for(int i= 1; i <= 17; i++) v.pb(i * i);
	dp[0] = 1LL;
	for(int i = 0; i < v.size(); i++){
		for(int j = 0; j + v[i] < 310; j++){
			dp[j+v[i]] += dp[j];
		}
	}
	while(1){
		int n = in.nextInt();
		if(n == 0) break;
		printf("%lld\n", dp[n]);
	}
}
### Prompt

Please provide a CPP coded solution to the problem described below:

People in Silverland use square coins. Not only they have square shapes but also their values are square numbers. Coins with values of all square numbers up to 289 (= 172), i.e., 1-credit coins, 4-credit coins, 9-credit coins, ..., and 289-credit coins, are available in Silverland.

There are four combinations of coins to pay ten credits:

* ten 1-credit coins,
* one 4-credit coin and six 1-credit coins,
* two 4-credit coins and two 1-credit coins, and
* one 9-credit coin and one 1-credit coin.



Your mission is to count the number of ways to pay a given amount using coins of Silverland.



Input

The input consists of lines each containing an integer meaning an amount to be paid, followed by a line containing a zero. You may assume that all the amounts are positive and less than 300.

Output

For each of the given amount, one line containing a single integer representing the number of combinations of coins should be output. No other characters should appear in the output.

Example

Input

2
10
30
0


Output

1
4
27

### Response

```cpp
#include <iostream>
#include <iomanip>
#include <string>
#include <sstream>
#include <algorithm>
#include <vector>
#include <utility>
#include <stack>
#include <queue>
#include <map>
#include <set>
#include <functional>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <cmath>
#include <cassert>
 
using namespace std;
 
#define REP(i,s,e) for(int i=(s); i<(int)(e); i++)
#define rep(i,n) REP(i, 0, n)
#define pb push_back
#define mp make_pair
#define all(r) (r).begin(),(r).end()
#define rall(r) (r).rbegin(),(r).rend()
#define fi first
#define se second
#define DBG(X) cout<<" "<<#X<<" : "<<X<<endl
 
typedef long long ll;
typedef vector<int> vi;
typedef vector<ll> vl;
typedef pair<int, int> pii;

const int INF = 1e9;
const double EPS = 1e-8;
const int mod = 1e9 + 7;
const ll LINF = 1e18;

struct Input
{
	int n;char c;char str[10010];string s;ll l;double d;
	int nextInt(){scanf("%d", &n);return n;}
	ll nextLong(){scanf("%lld", &l);return l;}
	double nextDouble(){scanf("%lf", &d);return d;}
	char nextChar(){scanf("%c", &c);return c;}
	string next(){scanf("%s", str);return string(str);}
	string nextLine(){getline(cin, s);return s;}
};
Input in;

ll dp[310];
vector<int> v;

int main(){
	for(int i= 1; i <= 17; i++) v.pb(i * i);
	dp[0] = 1LL;
	for(int i = 0; i < v.size(); i++){
		for(int j = 0; j + v[i] < 310; j++){
			dp[j+v[i]] += dp[j];
		}
	}
	while(1){
		int n = in.nextInt();
		if(n == 0) break;
		printf("%lld\n", dp[n]);
	}
}
```