#include <iostream>
using namespace std;

int n;
bool f;

int main(){
	cin >> n;
	f = false;
	for (int k = 0; k <= n/4; ++k){
		if ((n - 4*k) % 7 == 0){
			f = true;
			break;
		}
	}
	cout << (f ? "Yes" : "No");
}
### Prompt

In cpp, your task is to solve the following problem:

La Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each. Determine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.

Constraints

* N is an integer between 1 and 100, inclusive.

Input

Input is given from Standard Input in the following format:


N


Output

If there is a way to buy some cakes and some doughnuts for exactly N dollars, print `Yes`; otherwise, print `No`.

Examples

Input

11


Output

Yes


Input

40


Output

Yes


Input

3


Output

No

### Response

```cpp
#include <iostream>
using namespace std;

int n;
bool f;

int main(){
	cin >> n;
	f = false;
	for (int k = 0; k <= n/4; ++k){
		if ((n - 4*k) % 7 == 0){
			f = true;
			break;
		}
	}
	cout << (f ? "Yes" : "No");
}
```