#include <iostream>
using namespace std;
typedef long long ll;
const ll mod = 1000000007;
ll pow(ll m, ll n) {
  if (!n) return 1;
  if (n & 1) return m * pow(m, n -1) % mod;
  return pow(m * m % mod, n / 2);
}
int main() {
  ll m, n;
  cin >> m >> n;
  cout << pow(m, n) << endl;
}
### Prompt

Please provide a CPP coded solution to the problem described below:

For given integers m and n, compute mn (mod 1,000,000,007). Here, A (mod M) is the remainder when A is divided by M.

Constraints

* 1 ≤ m ≤ 100
* 1 ≤ n ≤ 109

Input


m n


Two integers m and n are given in a line.

Output

Print mn (mod 1,000,000,007) in a line.

Examples

Input

2 3


Output

8


Input

5 8


Output

390625

### Response

```cpp
#include <iostream>
using namespace std;
typedef long long ll;
const ll mod = 1000000007;
ll pow(ll m, ll n) {
  if (!n) return 1;
  if (n & 1) return m * pow(m, n -1) % mod;
  return pow(m * m % mod, n / 2);
}
int main() {
  ll m, n;
  cin >> m >> n;
  cout << pow(m, n) << endl;
}
```