#include <bits/stdc++.h>
using namespace std;

using ll=long long;
const ll MOD=1e9+7;

ll pw(ll n,ll k){
    ll res=1;
    while(k){
        if(k&1)(res*=n)%=MOD;
        (n*=n)%=MOD;
        k>>=1;
    }
    return res;
}

int main(){
    int n,m;cin>>n>>m;
    cout<<pw(n,m)<<endl;
}

### Prompt

Please provide a Cpp coded solution to the problem described below:

For given integers m and n, compute mn (mod 1,000,000,007). Here, A (mod M) is the remainder when A is divided by M.

Constraints

* 1 ≤ m ≤ 100
* 1 ≤ n ≤ 109

Input


m n


Two integers m and n are given in a line.

Output

Print mn (mod 1,000,000,007) in a line.

Examples

Input

2 3


Output

8


Input

5 8


Output

390625

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;

using ll=long long;
const ll MOD=1e9+7;

ll pw(ll n,ll k){
    ll res=1;
    while(k){
        if(k&1)(res*=n)%=MOD;
        (n*=n)%=MOD;
        k>>=1;
    }
    return res;
}

int main(){
    int n,m;cin>>n>>m;
    cout<<pw(n,m)<<endl;
}

```