#include <bits/stdc++.h>
int main() {
  char s[200];
  scanf("%s", s);
  for (int i = 0; i < strlen(s);) {
    if (s[i] == '.') {
      printf("0");
      i++;
    } else if (s[i + 1] == '.') {
      printf("1");
      i += 2;
    } else if (s[i + 1] == '-') {
      printf("2");
      i += 2;
    }
  }
}

### Prompt

Generate a CPP solution to the following problem:

Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet.

Input

The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes).

Output

Output the decoded ternary number. It can have leading zeroes.

Examples

Input

.-.--


Output

012

Input

--.


Output

20

Input

-..-.--


Output

1012

### Response

```cpp
#include <bits/stdc++.h>
int main() {
  char s[200];
  scanf("%s", s);
  for (int i = 0; i < strlen(s);) {
    if (s[i] == '.') {
      printf("0");
      i++;
    } else if (s[i + 1] == '.') {
      printf("1");
      i += 2;
    } else if (s[i + 1] == '-') {
      printf("2");
      i += 2;
    }
  }
}

```