
#include <bits/stdc++.h>
#define REP(i,n) for(int i=0;i<(n);i++)
#define l long long
using namespace std;
const l mod = 1000000007;

l my_pow(l m, int n){
	l res = 1;
	while(n>0){
	if(n&1)res = m*res % mod;
		n >>= 1;
		m = m*m % mod;
	}
	return res;
}
int main(){
	int m,n;
	cin >> m >> n;
	cout << my_pow(m,n) % mod<< endl;
	return 0;
}
### Prompt

Generate a Cpp solution to the following problem:

For given integers m and n, compute mn (mod 1,000,000,007). Here, A (mod M) is the remainder when A is divided by M.

Constraints

* 1 ≤ m ≤ 100
* 1 ≤ n ≤ 109

Input


m n


Two integers m and n are given in a line.

Output

Print mn (mod 1,000,000,007) in a line.

Examples

Input

2 3


Output

8


Input

5 8


Output

390625

### Response

```cpp

#include <bits/stdc++.h>
#define REP(i,n) for(int i=0;i<(n);i++)
#define l long long
using namespace std;
const l mod = 1000000007;

l my_pow(l m, int n){
	l res = 1;
	while(n>0){
	if(n&1)res = m*res % mod;
		n >>= 1;
		m = m*m % mod;
	}
	return res;
}
int main(){
	int m,n;
	cin >> m >> n;
	cout << my_pow(m,n) % mod<< endl;
	return 0;
}
```