#include <iostream>

long long mod_pow(long long m, long long n, long long mod)
{
	long long res = 1;
	while (n > 0)
	{
		if (n & 1)
		{
			res = res * m % mod;
		}
		m = m * m % mod;
		n >>= 1;
	}
	return res;
}

int main()
{
	long long m, n;
	std::cin >> m >> n;
	std::cout << mod_pow(m, n, 1000000007) << '\n';;
}


### Prompt

Construct a cpp code solution to the problem outlined:

For given integers m and n, compute mn (mod 1,000,000,007). Here, A (mod M) is the remainder when A is divided by M.

Constraints

* 1 ≤ m ≤ 100
* 1 ≤ n ≤ 109

Input


m n


Two integers m and n are given in a line.

Output

Print mn (mod 1,000,000,007) in a line.

Examples

Input

2 3


Output

8


Input

5 8


Output

390625

### Response

```cpp
#include <iostream>

long long mod_pow(long long m, long long n, long long mod)
{
	long long res = 1;
	while (n > 0)
	{
		if (n & 1)
		{
			res = res * m % mod;
		}
		m = m * m % mod;
		n >>= 1;
	}
	return res;
}

int main()
{
	long long m, n;
	std::cin >> m >> n;
	std::cout << mod_pow(m, n, 1000000007) << '\n';;
}


```