#include <iostream>

using namespace std;
using ll = long long;

ll modpow(ll a, ll n, ll mod) {
	ll res = 1;
	while (n > 0) {
		if (n & 1) res = res * a % mod;
		a = a * a % mod;
		n >>= 1;
	}
	return res;
}

int main() {
	ll m, n;
	cin >> m >> n;
	cout << modpow(m, n, 1000000007) << endl;
	return 0;
}

### Prompt

In Cpp, your task is to solve the following problem:

For given integers m and n, compute mn (mod 1,000,000,007). Here, A (mod M) is the remainder when A is divided by M.

Constraints

* 1 ≤ m ≤ 100
* 1 ≤ n ≤ 109

Input


m n


Two integers m and n are given in a line.

Output

Print mn (mod 1,000,000,007) in a line.

Examples

Input

2 3


Output

8


Input

5 8


Output

390625

### Response

```cpp
#include <iostream>

using namespace std;
using ll = long long;

ll modpow(ll a, ll n, ll mod) {
	ll res = 1;
	while (n > 0) {
		if (n & 1) res = res * a % mod;
		a = a * a % mod;
		n >>= 1;
	}
	return res;
}

int main() {
	ll m, n;
	cin >> m >> n;
	cout << modpow(m, n, 1000000007) << endl;
	return 0;
}

```