#include <bits/stdc++.h>

using namespace std;

int n, k;
int cur[26];
vector<int> path;

void dfs(int v) {
    while (cur[v] < k) {
        int u = cur[v]++;
        dfs(u);
        path.push_back(u);
    }
}

int main() {
    cin >> n >> k;
    dfs(0);
    cout << 'a';
    for (int i = 0; i < n - 1; ++i)
        cout << char(path[i % path.size()] + 'a');
}

### Prompt

In CPP, your task is to solve the following problem:

Let's define the cost of a string s as the number of index pairs i and j (1 ≤ i < j < |s|) such that s_i = s_j and s_{i+1} = s_{j+1}.

You are given two positive integers n and k. Among all strings with length n that contain only the first k characters of the Latin alphabet, find a string with minimum possible cost. If there are multiple such strings with minimum cost — find any of them.

Input

The only line contains two integers n and k (1 ≤ n ≤ 2 ⋅ 10^5; 1 ≤ k ≤ 26).

Output

Print the string s such that it consists of n characters, each its character is one of the k first Latin letters, and it has the minimum possible cost among all these strings. If there are multiple such strings — print any of them.

Examples

Input


9 4


Output


aabacadbb


Input


5 1


Output


aaaaa

Input


10 26


Output


codeforces

### Response

```cpp
#include <bits/stdc++.h>

using namespace std;

int n, k;
int cur[26];
vector<int> path;

void dfs(int v) {
    while (cur[v] < k) {
        int u = cur[v]++;
        dfs(u);
        path.push_back(u);
    }
}

int main() {
    cin >> n >> k;
    dfs(0);
    cout << 'a';
    for (int i = 0; i < n - 1; ++i)
        cout << char(path[i % path.size()] + 'a');
}

```