#include<bits/stdc++.h>
using namespace std;
#define fo(i,n) for(i=0;i<n;i++)
#define pb push_back
#define F first
#define S second
typedef pair<int, int>  pii;
typedef vector<int>     vi;
typedef vector<pii>     vpii;
typedef vector<vi>      vvi;
 

 
int main() 
{
    ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);
    srand(chrono::high_resolution_clock::now().time_since_epoch().count());
 
    #ifndef ONLINE_JUDGE
    freopen("input.txt", "r", stdin);
    freopen("output.txt", "w", stdout);
    #endif
 
    int n,k,i,j;
    cin>>n>>k;
    string s;
    fo(i,k)
    {
    	s+=('a'+i);
        for(j=i+1;j<k;j++)
        {
        	s+=('a'+i);
            s+=('a'+j);
        }
    }
    //cout<<s;
    int x=k*k;
    string ans;
    fo(i,(n/x))
    ans+=s;
    fo(i,n%x)
    ans+=s[i];
    cout<<ans<<endl;
    return 0;
}
### Prompt

Please create a solution in Cpp to the following problem:

Let's define the cost of a string s as the number of index pairs i and j (1 ≤ i < j < |s|) such that s_i = s_j and s_{i+1} = s_{j+1}.

You are given two positive integers n and k. Among all strings with length n that contain only the first k characters of the Latin alphabet, find a string with minimum possible cost. If there are multiple such strings with minimum cost — find any of them.

Input

The only line contains two integers n and k (1 ≤ n ≤ 2 ⋅ 10^5; 1 ≤ k ≤ 26).

Output

Print the string s such that it consists of n characters, each its character is one of the k first Latin letters, and it has the minimum possible cost among all these strings. If there are multiple such strings — print any of them.

Examples

Input


9 4


Output


aabacadbb


Input


5 1


Output


aaaaa

Input


10 26


Output


codeforces

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;
#define fo(i,n) for(i=0;i<n;i++)
#define pb push_back
#define F first
#define S second
typedef pair<int, int>  pii;
typedef vector<int>     vi;
typedef vector<pii>     vpii;
typedef vector<vi>      vvi;
 

 
int main() 
{
    ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);
    srand(chrono::high_resolution_clock::now().time_since_epoch().count());
 
    #ifndef ONLINE_JUDGE
    freopen("input.txt", "r", stdin);
    freopen("output.txt", "w", stdout);
    #endif
 
    int n,k,i,j;
    cin>>n>>k;
    string s;
    fo(i,k)
    {
    	s+=('a'+i);
        for(j=i+1;j<k;j++)
        {
        	s+=('a'+i);
            s+=('a'+j);
        }
    }
    //cout<<s;
    int x=k*k;
    string ans;
    fo(i,(n/x))
    ans+=s;
    fo(i,n%x)
    ans+=s[i];
    cout<<ans<<endl;
    return 0;
}
```