#include<bits/stdc++.h>
using namespace std;

#define to(x) ((x)-'a'+1)
typedef pair<int,int> pii;
priority_queue<pii,vector<pii>,greater<pii> > q[27];

int main(){
	int n,k;
	scanf("%d%d",&n,&k);
	for(int i=1;i<=k;++i){
		for(int j=1;j<=k;++j){
			q[i].push(pii(0,j));
		}
	}
	int pre=k;
	for(int i=1;i<=n;++i){
		pii t=q[pre].top();
		q[pre].pop();
		putchar('a'+t.second-1);
		q[pre].push(pii(t.first+1,t.second));
		pre=t.second;
	}
	return 0;
}

### Prompt

Your task is to create a CPP solution to the following problem:

Let's define the cost of a string s as the number of index pairs i and j (1 ≤ i < j < |s|) such that s_i = s_j and s_{i+1} = s_{j+1}.

You are given two positive integers n and k. Among all strings with length n that contain only the first k characters of the Latin alphabet, find a string with minimum possible cost. If there are multiple such strings with minimum cost — find any of them.

Input

The only line contains two integers n and k (1 ≤ n ≤ 2 ⋅ 10^5; 1 ≤ k ≤ 26).

Output

Print the string s such that it consists of n characters, each its character is one of the k first Latin letters, and it has the minimum possible cost among all these strings. If there are multiple such strings — print any of them.

Examples

Input


9 4


Output


aabacadbb


Input


5 1


Output


aaaaa

Input


10 26


Output


codeforces

### Response

```cpp
#include<bits/stdc++.h>
using namespace std;

#define to(x) ((x)-'a'+1)
typedef pair<int,int> pii;
priority_queue<pii,vector<pii>,greater<pii> > q[27];

int main(){
	int n,k;
	scanf("%d%d",&n,&k);
	for(int i=1;i<=k;++i){
		for(int j=1;j<=k;++j){
			q[i].push(pii(0,j));
		}
	}
	int pre=k;
	for(int i=1;i<=n;++i){
		pii t=q[pre].top();
		q[pre].pop();
		putchar('a'+t.second-1);
		q[pre].push(pii(t.first+1,t.second));
		pre=t.second;
	}
	return 0;
}

```