#include <iostream>
#include <cmath>
using namespace std;
typedef long long ll;

ll pow(ll m, ll n, ll mod) {
  ll res = 1;
  while(n > 0) {
	if(n & 1) {
	  res = res * m % mod;
	}
	m = m * m % mod;
	n >>= 1;
  }
  return res;
}
int main() {
  ll a, b;
  cin >> a >> b;
  cout << pow(a, b, 1000000007) << endl;
  return 0;
}
### Prompt

Construct a Cpp code solution to the problem outlined:

For given integers m and n, compute mn (mod 1,000,000,007). Here, A (mod M) is the remainder when A is divided by M.

Constraints

* 1 ≤ m ≤ 100
* 1 ≤ n ≤ 109

Input


m n


Two integers m and n are given in a line.

Output

Print mn (mod 1,000,000,007) in a line.

Examples

Input

2 3


Output

8


Input

5 8


Output

390625

### Response

```cpp
#include <iostream>
#include <cmath>
using namespace std;
typedef long long ll;

ll pow(ll m, ll n, ll mod) {
  ll res = 1;
  while(n > 0) {
	if(n & 1) {
	  res = res * m % mod;
	}
	m = m * m % mod;
	n >>= 1;
  }
  return res;
}
int main() {
  ll a, b;
  cin >> a >> b;
  cout << pow(a, b, 1000000007) << endl;
  return 0;
}
```