#include<bits/stdc++.h>
#define ll long long
using namespace std;

const int MOD=1000000007;

ll modpow(ll x, ll n, ll mod) {
  if (n==0) return 1;
  ll res=modpow(x*x%mod, n/2, mod);
  if (n & 1) res=res*x%mod;
  return res;
}

int main() {
  ll n,m; cin>>n>>m;
  ll res=modpow(n,m,MOD);
  cout<<res<<endl;
}


### Prompt

Your task is to create a cpp solution to the following problem:

For given integers m and n, compute mn (mod 1,000,000,007). Here, A (mod M) is the remainder when A is divided by M.

Constraints

* 1 ≤ m ≤ 100
* 1 ≤ n ≤ 109

Input


m n


Two integers m and n are given in a line.

Output

Print mn (mod 1,000,000,007) in a line.

Examples

Input

2 3


Output

8


Input

5 8


Output

390625

### Response

```cpp
#include<bits/stdc++.h>
#define ll long long
using namespace std;

const int MOD=1000000007;

ll modpow(ll x, ll n, ll mod) {
  if (n==0) return 1;
  ll res=modpow(x*x%mod, n/2, mod);
  if (n & 1) res=res*x%mod;
  return res;
}

int main() {
  ll n,m; cin>>n>>m;
  ll res=modpow(n,m,MOD);
  cout<<res<<endl;
}


```