#include <stdio.h>
int n,k;
int main(){
    scanf("%d %d",&n,&k);
    while (n>0){
        for (int i=0;i<k;i++){
            printf("%c",'a'+i);
            if (--n<1) return 0;
            for (int j=i+1;j<k;j++){
                printf("%c",'a'+i);
                if (--n<1) return 0;
                printf("%c",'a'+j);
                if (--n<1) return 0;
            }
        }
    }

    return 0;
}

### Prompt

Your challenge is to write a cpp solution to the following problem:

Let's define the cost of a string s as the number of index pairs i and j (1 ≤ i < j < |s|) such that s_i = s_j and s_{i+1} = s_{j+1}.

You are given two positive integers n and k. Among all strings with length n that contain only the first k characters of the Latin alphabet, find a string with minimum possible cost. If there are multiple such strings with minimum cost — find any of them.

Input

The only line contains two integers n and k (1 ≤ n ≤ 2 ⋅ 10^5; 1 ≤ k ≤ 26).

Output

Print the string s such that it consists of n characters, each its character is one of the k first Latin letters, and it has the minimum possible cost among all these strings. If there are multiple such strings — print any of them.

Examples

Input


9 4


Output


aabacadbb


Input


5 1


Output


aaaaa

Input


10 26


Output


codeforces

### Response

```cpp
#include <stdio.h>
int n,k;
int main(){
    scanf("%d %d",&n,&k);
    while (n>0){
        for (int i=0;i<k;i++){
            printf("%c",'a'+i);
            if (--n<1) return 0;
            for (int j=i+1;j<k;j++){
                printf("%c",'a'+i);
                if (--n<1) return 0;
                printf("%c",'a'+j);
                if (--n<1) return 0;
            }
        }
    }

    return 0;
}

```