#include<iostream>

using namespace std;

typedef long long ll;

ll mod_pow(ll x,ll n,ll mod){
	ll res=1;
	while(n>0){
		if(n&1) res=res*x%mod;
		x=x*x%mod;
		n>>=1;
	}
	return res;
}

int main(){

	ll n,m;
	cin>>m>>n;
	cout<<mod_pow(m,n,1000000007)<<endl;
}
### Prompt

Create a solution in Cpp for the following problem:

For given integers m and n, compute mn (mod 1,000,000,007). Here, A (mod M) is the remainder when A is divided by M.

Constraints

* 1 ≤ m ≤ 100
* 1 ≤ n ≤ 109

Input


m n


Two integers m and n are given in a line.

Output

Print mn (mod 1,000,000,007) in a line.

Examples

Input

2 3


Output

8


Input

5 8


Output

390625

### Response

```cpp
#include<iostream>

using namespace std;

typedef long long ll;

ll mod_pow(ll x,ll n,ll mod){
	ll res=1;
	while(n>0){
		if(n&1) res=res*x%mod;
		x=x*x%mod;
		n>>=1;
	}
	return res;
}

int main(){

	ll n,m;
	cin>>m>>n;
	cout<<mod_pow(m,n,1000000007)<<endl;
}
```