#include <bits/stdc++.h>
using namespace std;
int main() {
  int n, m;
  cin >> n;
  m = n;
  int arr[2];
  arr[1] = n % 10;
  n = n / 10;
  arr[0] = n % 10;
  if (arr[0] == 1 || arr[0] == 2 || arr[0] == 9 || arr[0] == 7) {
    if (arr[0] == 1) {
      if (arr[1] == 2)
        cout << "YES" << endl;
      else
        cout << "NO" << endl;
    } else
      cout << "NO" << endl;
  } else {
    if (arr[1] == 1 || arr[1] == 7 || arr[1] == 9)
      cout << "NO" << endl;
    else
      cout << "YES" << endl;
  }
  return 0;
}

### Prompt

Please formulate a cpp solution to the following problem:



Input

The input contains a single integer a (1 ≤ a ≤ 99).

Output

Output "YES" or "NO".

Examples

Input


5


Output


YES


Input


13


Output


NO


Input


24


Output


NO


Input


46


Output


YES

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  int n, m;
  cin >> n;
  m = n;
  int arr[2];
  arr[1] = n % 10;
  n = n / 10;
  arr[0] = n % 10;
  if (arr[0] == 1 || arr[0] == 2 || arr[0] == 9 || arr[0] == 7) {
    if (arr[0] == 1) {
      if (arr[1] == 2)
        cout << "YES" << endl;
      else
        cout << "NO" << endl;
    } else
      cout << "NO" << endl;
  } else {
    if (arr[1] == 1 || arr[1] == 7 || arr[1] == 9)
      cout << "NO" << endl;
    else
      cout << "YES" << endl;
  }
  return 0;
}

```