#include <bits/stdc++.h>
using namespace std;
int main() {
  char c;
  vector<char> line;
  while (cin >> c) {
    line.push_back(c);
  }
  int s = line.size();
  vector<int> result;
  for (int i = 0; i < s; i++) {
    if (line[i] == '.') {
      result.push_back(0);
    } else {
      if (line[i + 1] == '.') {
        result.push_back(1);
        i++;
      } else {
        result.push_back(2);
        i++;
      }
    }
  }
  for (int i = 0; i < result.size(); i++) {
    cout << result[i];
  }
  cout << endl;
  return 0;
}

### Prompt

Generate a Cpp solution to the following problem:

Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet.

Input

The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes).

Output

Output the decoded ternary number. It can have leading zeroes.

Examples

Input

.-.--


Output

012

Input

--.


Output

20

Input

-..-.--


Output

1012

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  char c;
  vector<char> line;
  while (cin >> c) {
    line.push_back(c);
  }
  int s = line.size();
  vector<int> result;
  for (int i = 0; i < s; i++) {
    if (line[i] == '.') {
      result.push_back(0);
    } else {
      if (line[i + 1] == '.') {
        result.push_back(1);
        i++;
      } else {
        result.push_back(2);
        i++;
      }
    }
  }
  for (int i = 0; i < result.size(); i++) {
    cout << result[i];
  }
  cout << endl;
  return 0;
}

```