#include <iostream>
#include <algorithm>
#include <cmath>
#include <string>
using namespace std;
using ll = long long;
string al = "abcdefghijklmnopqrstuvwxyz";
int main() {
	ios_base::sync_with_stdio(false);
	cin.tie(0);
	int n, k;
	cin >> n >> k;
	string s = "";
	for (int i = 0; i < k; i++)
	{
		s += al[i];
		for (int j = i + 1; j < k; j++)
		{
			s += al[i];
			s += al[j];
		}
	}
	while (s.size() < n)s += s;
	for (int i = 0; i < n; i++)
		cout << s[i];
}
### Prompt

Construct a Cpp code solution to the problem outlined:

Let's define the cost of a string s as the number of index pairs i and j (1 ≤ i < j < |s|) such that s_i = s_j and s_{i+1} = s_{j+1}.

You are given two positive integers n and k. Among all strings with length n that contain only the first k characters of the Latin alphabet, find a string with minimum possible cost. If there are multiple such strings with minimum cost — find any of them.

Input

The only line contains two integers n and k (1 ≤ n ≤ 2 ⋅ 10^5; 1 ≤ k ≤ 26).

Output

Print the string s such that it consists of n characters, each its character is one of the k first Latin letters, and it has the minimum possible cost among all these strings. If there are multiple such strings — print any of them.

Examples

Input


9 4


Output


aabacadbb


Input


5 1


Output


aaaaa

Input


10 26


Output


codeforces

### Response

```cpp
#include <iostream>
#include <algorithm>
#include <cmath>
#include <string>
using namespace std;
using ll = long long;
string al = "abcdefghijklmnopqrstuvwxyz";
int main() {
	ios_base::sync_with_stdio(false);
	cin.tie(0);
	int n, k;
	cin >> n >> k;
	string s = "";
	for (int i = 0; i < k; i++)
	{
		s += al[i];
		for (int j = i + 1; j < k; j++)
		{
			s += al[i];
			s += al[j];
		}
	}
	while (s.size() < n)s += s;
	for (int i = 0; i < n; i++)
		cout << s[i];
}
```