#include <iostream>
using namespace std;

long long fn(long long m, long long n)
{
	if(n == 0)
	{
		return 1;
	}
	else if(n % 2 == 0)
	{
		return fn((m * m) % 1000000007, n / 2);
	}
	else
	{
		return (m * fn(m, n - 1)) % 1000000007;
	}
}

int main()
{
	long long M, N;
	cin >> M >> N;		
	cout << fn(M, N) << endl;

    return 0;
}


### Prompt

Please provide a CPP coded solution to the problem described below:

For given integers m and n, compute mn (mod 1,000,000,007). Here, A (mod M) is the remainder when A is divided by M.

Constraints

* 1 ≤ m ≤ 100
* 1 ≤ n ≤ 109

Input


m n


Two integers m and n are given in a line.

Output

Print mn (mod 1,000,000,007) in a line.

Examples

Input

2 3


Output

8


Input

5 8


Output

390625

### Response

```cpp
#include <iostream>
using namespace std;

long long fn(long long m, long long n)
{
	if(n == 0)
	{
		return 1;
	}
	else if(n % 2 == 0)
	{
		return fn((m * m) % 1000000007, n / 2);
	}
	else
	{
		return (m * fn(m, n - 1)) % 1000000007;
	}
}

int main()
{
	long long M, N;
	cin >> M >> N;		
	cout << fn(M, N) << endl;

    return 0;
}


```