#include <iostream>
using namespace std;

long long power(long long m, long long n, long long mod) {
    long long res = 1;
    while (n > 0) {
        if (n % 2 == 1) res = res * m % mod;
        m = m * m % mod;
        n /= 2;
    }
    return res;
}

int main() {
    int m, n;
    cin >> m >> n;
    cout << power(m, n, 1000000007) << endl;
    return 0;
}

### Prompt

Create a solution in cpp for the following problem:

For given integers m and n, compute mn (mod 1,000,000,007). Here, A (mod M) is the remainder when A is divided by M.

Constraints

* 1 ≤ m ≤ 100
* 1 ≤ n ≤ 109

Input


m n


Two integers m and n are given in a line.

Output

Print mn (mod 1,000,000,007) in a line.

Examples

Input

2 3


Output

8


Input

5 8


Output

390625

### Response

```cpp
#include <iostream>
using namespace std;

long long power(long long m, long long n, long long mod) {
    long long res = 1;
    while (n > 0) {
        if (n % 2 == 1) res = res * m % mod;
        m = m * m % mod;
        n /= 2;
    }
    return res;
}

int main() {
    int m, n;
    cin >> m >> n;
    cout << power(m, n, 1000000007) << endl;
    return 0;
}

```