#include<iostream>
#include<cstdio>
using namespace std;
int main(){
	int i,j,n,f=1;
	cin>>n;
	for(i=0;i<=n/7;i++)
		for(j=0;j<=n/4;j++)
			if(i*7+j*4==n)f=0;
	if(f)cout<<"No";
	else cout<<"Yes";
	return 0;
}
### Prompt

Construct a cpp code solution to the problem outlined:

La Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each. Determine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.

Constraints

* N is an integer between 1 and 100, inclusive.

Input

Input is given from Standard Input in the following format:


N


Output

If there is a way to buy some cakes and some doughnuts for exactly N dollars, print `Yes`; otherwise, print `No`.

Examples

Input

11


Output

Yes


Input

40


Output

Yes


Input

3


Output

No

### Response

```cpp
#include<iostream>
#include<cstdio>
using namespace std;
int main(){
	int i,j,n,f=1;
	cin>>n;
	for(i=0;i<=n/7;i++)
		for(j=0;j<=n/4;j++)
			if(i*7+j*4==n)f=0;
	if(f)cout<<"No";
	else cout<<"Yes";
	return 0;
}
```