#include<stdio.h>
int dp[18][301];
int main(){
	dp[0][0]=1;
	for(int i=1;i<=17;i++){
		for(int j=0;j<=300;j++){
			dp[i][j]=dp[i-1][j];
			if(j>=i*i)dp[i][j]+=dp[i][j-i*i];
		}
	}
	int a;
	while(scanf("%d",&a),a)printf("%d\n",dp[17][a]);
}
### Prompt

Please create a solution in Cpp to the following problem:

People in Silverland use square coins. Not only they have square shapes but also their values are square numbers. Coins with values of all square numbers up to 289 (= 172), i.e., 1-credit coins, 4-credit coins, 9-credit coins, ..., and 289-credit coins, are available in Silverland.

There are four combinations of coins to pay ten credits:

* ten 1-credit coins,
* one 4-credit coin and six 1-credit coins,
* two 4-credit coins and two 1-credit coins, and
* one 9-credit coin and one 1-credit coin.



Your mission is to count the number of ways to pay a given amount using coins of Silverland.



Input

The input consists of lines each containing an integer meaning an amount to be paid, followed by a line containing a zero. You may assume that all the amounts are positive and less than 300.

Output

For each of the given amount, one line containing a single integer representing the number of combinations of coins should be output. No other characters should appear in the output.

Example

Input

2
10
30
0


Output

1
4
27

### Response

```cpp
#include<stdio.h>
int dp[18][301];
int main(){
	dp[0][0]=1;
	for(int i=1;i<=17;i++){
		for(int j=0;j<=300;j++){
			dp[i][j]=dp[i-1][j];
			if(j>=i*i)dp[i][j]+=dp[i][j-i*i];
		}
	}
	int a;
	while(scanf("%d",&a),a)printf("%d\n",dp[17][a]);
}
```