#include <bits/stdc++.h>
using namespace std;

typedef long long ll;

int ModPow(int a,int r,int m)
{
	int x=1;
	for(;r;r>>=1){
		if(r&1) x=(ll)x*a%m;
		a=(ll)a*a%m;
	}
	return x;
}

int main()
{
	constexpr int MOD=1e9+7;
	for(int m,n;cin>>m>>n && m|n;){
		cout<<ModPow(m,n,MOD)<<endl;;
	}
}
### Prompt

In CPP, your task is to solve the following problem:

For given integers m and n, compute mn (mod 1,000,000,007). Here, A (mod M) is the remainder when A is divided by M.

Constraints

* 1 ≤ m ≤ 100
* 1 ≤ n ≤ 109

Input


m n


Two integers m and n are given in a line.

Output

Print mn (mod 1,000,000,007) in a line.

Examples

Input

2 3


Output

8


Input

5 8


Output

390625

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;

typedef long long ll;

int ModPow(int a,int r,int m)
{
	int x=1;
	for(;r;r>>=1){
		if(r&1) x=(ll)x*a%m;
		a=(ll)a*a%m;
	}
	return x;
}

int main()
{
	constexpr int MOD=1e9+7;
	for(int m,n;cin>>m>>n && m|n;){
		cout<<ModPow(m,n,MOD)<<endl;;
	}
}
```