#include <bits/stdc++.h>
#define qio ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0)
#define debug(x) cerr<<#x<<" "<<x<<endl
#define ll long long 
#define st first
#define nd second
using namespace std;

int n, t, a, sum, res, res1;
int main()
{
	qio;
	cin >> a;
	while (a > 0) {
		res += a % 10;
		a /= 10;
	}
	a = res;
	res = 0;
	while (a > 0) {
		res += a % 10;
		a /= 10;
	}
	a = res;
	res = 0;

	while (a > 0) {
		res += a % 10;
		a /= 10;
	}
	a = res;
	res = 0;

	while (a > 0) {
		res += a % 10;
		a /= 10;
	}
	a = res;
	res = 0;

	while (a > 0) {
		res += a % 10;
		a /= 10;
	}
	a = res;
	res = 0;

	while (a > 0) {
		res += a % 10;
		a /= 10;
	}
	a = res;
	res = 0;

	while (a > 0) {
		res += a % 10;
		a /= 10;
	}
	a = res;
	res = 0;

	while (a > 0) {
		res += a % 10;
		a /= 10;
	}
	a = res;
	res = 0;

	cout << a;





}

### Prompt

Please formulate a CPP solution to the following problem:

Many people are aware of DMCA – Digital Millennium Copyright Act. But another recently proposed DMCA – Digital Millennium Calculation Act – is much less known.

In this problem you need to find a root of a number according to this new DMCA law.

Input

The input contains a single integer a (1 ≤ a ≤ 1000000).

Output

Output the result – an integer number.

Examples

Input


1


Output


1


Input


81


Output


9

### Response

```cpp
#include <bits/stdc++.h>
#define qio ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0)
#define debug(x) cerr<<#x<<" "<<x<<endl
#define ll long long 
#define st first
#define nd second
using namespace std;

int n, t, a, sum, res, res1;
int main()
{
	qio;
	cin >> a;
	while (a > 0) {
		res += a % 10;
		a /= 10;
	}
	a = res;
	res = 0;
	while (a > 0) {
		res += a % 10;
		a /= 10;
	}
	a = res;
	res = 0;

	while (a > 0) {
		res += a % 10;
		a /= 10;
	}
	a = res;
	res = 0;

	while (a > 0) {
		res += a % 10;
		a /= 10;
	}
	a = res;
	res = 0;

	while (a > 0) {
		res += a % 10;
		a /= 10;
	}
	a = res;
	res = 0;

	while (a > 0) {
		res += a % 10;
		a /= 10;
	}
	a = res;
	res = 0;

	while (a > 0) {
		res += a % 10;
		a /= 10;
	}
	a = res;
	res = 0;

	while (a > 0) {
		res += a % 10;
		a /= 10;
	}
	a = res;
	res = 0;

	cout << a;





}

```