#include <bits/stdc++.h>  // clang-format off
using Int = long long;
#define REP_(i, a_, b_, a, b, ...) for (Int i = (a), lim##i = (b); i < lim##i; i++)
#define REP(i, ...) REP_(i, __VA_ARGS__, __VA_ARGS__, 0, __VA_ARGS__)
struct SetupIO { SetupIO() { std::cin.tie(nullptr), std::ios::sync_with_stdio(false), std::cout << std::fixed << std::setprecision(13); } } setup_io;
#ifndef dump
#define dump(...)
#endif  // clang-format on

/**
 *    author:  knshnb
 *    created: Sun May 31 15:34:56 JST 2020
 **/

signed main() {
    Int n;
    std::cin >> n;
    std::vector<Int> a(n);
    REP(i, n) std::cin >> a[i];
    // std::sort(a.begin(), a.end());
    a.erase(std::unique(a.begin(), a.end()), a.end());
    REP(i, a.size()) std::cout << a[i] << " \n"[i == a.size() - 1];
}


### Prompt

Develop a solution in CPP to the problem described below:

For a sequence of integers $A = \\{a_0, a_1, ..., a_{n-1}\\}$ which is sorted by ascending order, eliminate all equivalent elements.

Constraints

* $1 \leq n \leq 100,000$
* $-1000,000,000 \leq a_i \leq 1,000,000,000$
* $a_0 \leq a_1 \leq ... \leq a_{n-1}$

Input

A sequence is given in the following format.


$n$
$a_0 \; a_1 \; ,..., \; a_{n-1}$


Output

Print the sequence after eliminating equivalent elements in a line. Separate adjacency elements by a space character.

Example

Input

4
1 2 2 4


Output

1 2 4

### Response

```cpp
#include <bits/stdc++.h>  // clang-format off
using Int = long long;
#define REP_(i, a_, b_, a, b, ...) for (Int i = (a), lim##i = (b); i < lim##i; i++)
#define REP(i, ...) REP_(i, __VA_ARGS__, __VA_ARGS__, 0, __VA_ARGS__)
struct SetupIO { SetupIO() { std::cin.tie(nullptr), std::ios::sync_with_stdio(false), std::cout << std::fixed << std::setprecision(13); } } setup_io;
#ifndef dump
#define dump(...)
#endif  // clang-format on

/**
 *    author:  knshnb
 *    created: Sun May 31 15:34:56 JST 2020
 **/

signed main() {
    Int n;
    std::cin >> n;
    std::vector<Int> a(n);
    REP(i, n) std::cin >> a[i];
    // std::sort(a.begin(), a.end());
    a.erase(std::unique(a.begin(), a.end()), a.end());
    REP(i, a.size()) std::cout << a[i] << " \n"[i == a.size() - 1];
}


```