#include <bits/stdc++.h>

using namespace std;

typedef long long int ll;
typedef pair<ll, ll> pll;

#define FOR(i, n, m) for(ll (i)=(m);(i)<(n);++(i))
#define REP(i, n) FOR(i,n,0)
#define OF64 std::setprecision(10)

const ll MOD = 1000000007;
const ll INF = (ll) 1e15;

ll A[100005];

int main() {
    cin.tie(0);
    ios::sync_with_stdio(false);
    ll N;
    cin >> N;
    REP(i, N) {
        cin >> A[i];
    }

    cout << A[0];
    FOR(i, N, 1) {
        if (A[i] == A[i - 1])
            continue;
        cout << " " << A[i];
    }
    cout << endl;
    return 0;
}

### Prompt

Please provide a cpp coded solution to the problem described below:

For a sequence of integers $A = \\{a_0, a_1, ..., a_{n-1}\\}$ which is sorted by ascending order, eliminate all equivalent elements.

Constraints

* $1 \leq n \leq 100,000$
* $-1000,000,000 \leq a_i \leq 1,000,000,000$
* $a_0 \leq a_1 \leq ... \leq a_{n-1}$

Input

A sequence is given in the following format.


$n$
$a_0 \; a_1 \; ,..., \; a_{n-1}$


Output

Print the sequence after eliminating equivalent elements in a line. Separate adjacency elements by a space character.

Example

Input

4
1 2 2 4


Output

1 2 4

### Response

```cpp
#include <bits/stdc++.h>

using namespace std;

typedef long long int ll;
typedef pair<ll, ll> pll;

#define FOR(i, n, m) for(ll (i)=(m);(i)<(n);++(i))
#define REP(i, n) FOR(i,n,0)
#define OF64 std::setprecision(10)

const ll MOD = 1000000007;
const ll INF = (ll) 1e15;

ll A[100005];

int main() {
    cin.tie(0);
    ios::sync_with_stdio(false);
    ll N;
    cin >> N;
    REP(i, N) {
        cin >> A[i];
    }

    cout << A[0];
    FOR(i, N, 1) {
        if (A[i] == A[i - 1])
            continue;
        cout << " " << A[i];
    }
    cout << endl;
    return 0;
}

```