#include <iostream>
#include <string>
#include <vector>
#include <queue>
#include <set>
#include <map>
#include <utility>
#include <stack>
#include <numeric>
#include <algorithm>
#include <stdio.h>
#include <bitset>
#include <complex>
#include <iomanip>
using namespace std;
#define MM 1000000000
#define MOD MM+7
#define pi pair<int32,int32>
#define pl pair<int64,int64>
#define chmax(a,b) (a<b ? a=b:0)
#define chmin(a,b) (a>b ? a=b:0)
const long double PI = acos(-1);
const long long INF = 1e15;
int dx[8] = {-1,0,1,0,-1,-1,1,1};
int dy[8] = {0,-1,0,1,-1,1,1,-1};
template<typename T>
T GCD(T u,T v){
    return v ? GCD(v,u%v) : u;
}
template<typename T>
T LCM(T x,T y){
    return x*y/(T)GCD(x,y);
}
int main(){
    int n; cin >> n;
    set<long long> st;
    vector<int> v;
    for(int i = 0; i < n; i++){
        long long a; cin >> a;
        v.push_back(a);
    }
    v.erase( unique(v.begin(), v.end()), v.end());
    for(long long i = 0; i < v.size()-1; i++){
        cout << v[i] << " ";
    }
    cout << v[v.size()-1] << endl;
}
  



### Prompt

Construct a cpp code solution to the problem outlined:

For a sequence of integers $A = \\{a_0, a_1, ..., a_{n-1}\\}$ which is sorted by ascending order, eliminate all equivalent elements.

Constraints

* $1 \leq n \leq 100,000$
* $-1000,000,000 \leq a_i \leq 1,000,000,000$
* $a_0 \leq a_1 \leq ... \leq a_{n-1}$

Input

A sequence is given in the following format.


$n$
$a_0 \; a_1 \; ,..., \; a_{n-1}$


Output

Print the sequence after eliminating equivalent elements in a line. Separate adjacency elements by a space character.

Example

Input

4
1 2 2 4


Output

1 2 4

### Response

```cpp
#include <iostream>
#include <string>
#include <vector>
#include <queue>
#include <set>
#include <map>
#include <utility>
#include <stack>
#include <numeric>
#include <algorithm>
#include <stdio.h>
#include <bitset>
#include <complex>
#include <iomanip>
using namespace std;
#define MM 1000000000
#define MOD MM+7
#define pi pair<int32,int32>
#define pl pair<int64,int64>
#define chmax(a,b) (a<b ? a=b:0)
#define chmin(a,b) (a>b ? a=b:0)
const long double PI = acos(-1);
const long long INF = 1e15;
int dx[8] = {-1,0,1,0,-1,-1,1,1};
int dy[8] = {0,-1,0,1,-1,1,1,-1};
template<typename T>
T GCD(T u,T v){
    return v ? GCD(v,u%v) : u;
}
template<typename T>
T LCM(T x,T y){
    return x*y/(T)GCD(x,y);
}
int main(){
    int n; cin >> n;
    set<long long> st;
    vector<int> v;
    for(int i = 0; i < n; i++){
        long long a; cin >> a;
        v.push_back(a);
    }
    v.erase( unique(v.begin(), v.end()), v.end());
    for(long long i = 0; i < v.size()-1; i++){
        cout << v[i] << " ";
    }
    cout << v[v.size()-1] << endl;
}
  



```