#include <bits/stdc++.h>
using namespace std;
int main() {
  int n;
  cin >> n;
  string s;
  s = "";
  for (int i = 1; i <= n; i++) {
    if (i <= 9)
      s.push_back(i + '0');
    else {
      string s1 = "";
      int p = i;
      while (p != 0) {
        int r = p % 10;
        s1.push_back(r + '0');
        p = p / 10;
      }
      reverse(s1.begin(), s1.end());
      s += s1;
    }
  }
  cout << s[n - 1];
}

### Prompt

Please create a solution in cpp to the following problem:

Let's write all the positive integer numbers one after another from 1 without any delimiters (i.e. as a single string). It will be the infinite sequence starting with 123456789101112131415161718192021222324252627282930313233343536...

Your task is to print the k-th digit of this sequence.

Input

The first and only line contains integer k (1 ≤ k ≤ 10000) — the position to process (1-based index).

Output

Print the k-th digit of the resulting infinite sequence.

Examples

Input


7


Output


7


Input


21


Output


5

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  int n;
  cin >> n;
  string s;
  s = "";
  for (int i = 1; i <= n; i++) {
    if (i <= 9)
      s.push_back(i + '0');
    else {
      string s1 = "";
      int p = i;
      while (p != 0) {
        int r = p % 10;
        s1.push_back(r + '0');
        p = p / 10;
      }
      reverse(s1.begin(), s1.end());
      s += s1;
    }
  }
  cout << s[n - 1];
}

```