#include <bits/stdc++.h>
using namespace std;
const long long N = 5e5 + 10;
const long long M = 1e6 + 11;
const long long big = 1e17;
const long long hsh2 = 1964325029;
const long long mod = 998244353;
const double EPS = 1e-9;
const long long block = 1e14;
const long long shift = 2e3;
const double pi = acos(-1.0);
long long n, q;
long long a[N], b[N], c[N];
vector<pair<long long, long long> > g[N];
struct DSU {
  long long p[N], sz[N];
  void init(long long n) {
    for (int i = 1; i <= n; i++) p[i] = i, sz[i] = 1;
  }
  long long fnd(long long a) { return p[a] = (p[a] == a ? a : fnd(p[a])); }
  void unt(long long a, long long b) {
    a = fnd(a), b = fnd(b);
    if (a == b) return;
    if (sz[a] < sz[b]) swap(a, b);
    p[b] = a;
    sz[a] += sz[b];
  }
} ds;
struct seg {
  long long t[4 * N] = {0};
  long long u[4 * N] = {0};
  void push(long long v, long long l, long long r) {
    if (u[v]) {
      t[v] = u[v];
      if (l != r) u[v * 2] = u[v * 2 + 1] = u[v];
    }
  }
  void upd(long long l, long long r, long long v = 1, long long tl = 1,
           long long tr = n + 10) {
    push(v, tl, tr);
    if (l > tr || tl > r || l > r) return;
    if (l <= tl && tr <= r) {
      u[v] = 1;
      push(v, tl, tr);
      return;
    }
    long long m = (tl + tr) >> 1ll;
    upd(l, r, v * 2, tl, m);
    upd(l, r, v * 2 + 1, m + 1, tr);
    t[v] = max(t[v * 2], t[v * 2 + 1]);
  }
  long long get(long long l, long long r, long long v = 1, long long tl = 1,
                long long tr = n + 10) {
    push(v, tl, tr);
    if (l > tr || tl > r || l > r) return 0;
    if (l <= tl && tr <= r) return t[v];
    long long m = (tl + tr) >> 1ll;
    return max(get(l, r, v * 2, tl, m), get(l, r, v * 2 + 1, m + 1, tr));
  }
} rt;
long long bp[N][21], xr[N], sz[N], tin[N], tout[N];
long long hp[N];
void dfs(long long v, long long p) {
  for (int i = 1; i < 20; i++) bp[v][i] = bp[bp[v][i - 1]][i - 1];
  sz[v] = 1;
  for (auto u : g[v])
    if (u.first != p)
      bp[u.first][0] = v, xr[u.first] = u.second ^ xr[v], dfs(u.first, v),
      sz[v] += sz[u.first];
}
void hldfs(long long v, long long p, long long pr) {
  hp[v] = pr;
  tin[v] = tout[0]++;
  for (auto u : g[v])
    if (u.first != p && sz[u.first] * 2 > sz[v]) hldfs(u.first, v, pr);
  for (auto u : g[v])
    if (u.first != p && sz[u.first] * 2 <= sz[v]) hldfs(u.first, v, u.first);
  tout[v] = tout[0];
}
bool upper(long long a, long long b) {
  return (tin[a] <= tin[b] && tout[b] <= tout[a]);
}
long long LCA(long long a, long long b) {
  if (upper(a, b)) return a;
  if (upper(b, a)) return b;
  for (int j = 19; j >= 0; j--)
    if (!upper(bp[a][j], b)) a = bp[a][j];
  return bp[a][0];
}
long long pLCA(long long a, long long b) {
  if (upper(a, b)) return -1;
  for (int j = 19; j >= 0; j--)
    if (!upper(bp[a][j], b)) a = bp[a][j];
  return a;
}
long long pxr(long long x, long long y) { return xr[x] ^ xr[y]; }
void UpdBamboo(long long v, long long x) {
  while (1) {
    long long hm = hp[v];
    if (hm == hp[x]) hm = x;
    rt.upd(tin[hm], tin[v]);
    if (hm == x) break;
    v = bp[hm][0];
  }
}
long long GetBamboo(long long v, long long x) {
  long long z = 0;
  while (1) {
    long long hm = hp[v];
    if (hm == hp[x]) hm = x;
    z = max(z, rt.get(tin[hm], tin[v]));
    if (hm == x) break;
    v = bp[hm][0];
  }
  return z;
}
void UpdPath(long long x, long long y) {
  long long z = pLCA(x, y);
  if (z != -1) UpdBamboo(x, z);
  z = pLCA(y, x);
  if (z != -1) UpdBamboo(y, z);
}
long long getPath(long long x, long long y) {
  long long z = pLCA(x, y);
  long long ans = 0;
  if (z != -1) ans = max(ans, GetBamboo(x, z));
  z = pLCA(y, x);
  if (z != -1) ans = max(ans, GetBamboo(y, z));
  return ans;
}
bool READY[N];
int main() {
  ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);
  cin >> n >> q;
  ds.init(n);
  tout[0] = 1ll;
  for (int i = 1; i <= q; i++) cin >> a[i] >> b[i] >> c[i];
  for (int i = 1; i <= q; i++) {
    if (ds.fnd(a[i]) != ds.fnd(b[i]))
      ds.unt(a[i], b[i]), g[a[i]].push_back(make_pair(b[i], c[i])),
          g[b[i]].push_back(make_pair(a[i], c[i])), READY[i] = 1;
  }
  for (int j = 1; j <= n; j++)
    if (tin[j] == 0) dfs(j, 0), hldfs(j, 0, j);
  for (int i = 1; i <= q; i++) {
    if (READY[i])
      cout << "YES\n";
    else {
      long long z = pxr(a[i], b[i]);
      if (z == c[i] || getPath(a[i], b[i])) {
        cout << "NO\n";
        continue;
      }
      UpdPath(a[i], b[i]);
      cout << "YES\n";
    }
  }
}

### Prompt

Please provide a CPP coded solution to the problem described below:

You have an undirected graph consisting of n vertices with weighted edges.

A simple cycle is a cycle of the graph without repeated vertices. Let the weight of the cycle be the [XOR](https://en.wikipedia.org/wiki/Bitwise_operation#XOR) of weights of edges it consists of.

Let's say the graph is good if all its simple cycles have weight 1. A graph is bad if it's not good.

Initially, the graph is empty. Then q queries follow. Each query has the next type: 

  * u v x — add edge between vertices u and v of weight x if it doesn't make the graph bad. 



For each query print, was the edge added or not.

Input

The first line contains two integers n and q (3 ≤ n ≤ 3 ⋅ 10^5; 1 ≤ q ≤ 5 ⋅ 10^5) — the number of vertices and queries.

Next q lines contain queries — one per line. Each query contains three integers u, v and x (1 ≤ u, v ≤ n; u ≠ v; 0 ≤ x ≤ 1) — the vertices of the edge and its weight.

It's guaranteed that there are no multiple edges in the input.

Output

For each query, print YES if the edge was added to the graph, or NO otherwise (both case-insensitive).

Example

Input


9 12
6 1 0
1 3 1
3 6 0
6 2 0
6 4 1
3 4 1
2 4 0
2 5 0
4 5 0
7 8 1
8 9 1
9 7 0


Output


YES
YES
YES
YES
YES
NO
YES
YES
NO
YES
YES
NO

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
const long long N = 5e5 + 10;
const long long M = 1e6 + 11;
const long long big = 1e17;
const long long hsh2 = 1964325029;
const long long mod = 998244353;
const double EPS = 1e-9;
const long long block = 1e14;
const long long shift = 2e3;
const double pi = acos(-1.0);
long long n, q;
long long a[N], b[N], c[N];
vector<pair<long long, long long> > g[N];
struct DSU {
  long long p[N], sz[N];
  void init(long long n) {
    for (int i = 1; i <= n; i++) p[i] = i, sz[i] = 1;
  }
  long long fnd(long long a) { return p[a] = (p[a] == a ? a : fnd(p[a])); }
  void unt(long long a, long long b) {
    a = fnd(a), b = fnd(b);
    if (a == b) return;
    if (sz[a] < sz[b]) swap(a, b);
    p[b] = a;
    sz[a] += sz[b];
  }
} ds;
struct seg {
  long long t[4 * N] = {0};
  long long u[4 * N] = {0};
  void push(long long v, long long l, long long r) {
    if (u[v]) {
      t[v] = u[v];
      if (l != r) u[v * 2] = u[v * 2 + 1] = u[v];
    }
  }
  void upd(long long l, long long r, long long v = 1, long long tl = 1,
           long long tr = n + 10) {
    push(v, tl, tr);
    if (l > tr || tl > r || l > r) return;
    if (l <= tl && tr <= r) {
      u[v] = 1;
      push(v, tl, tr);
      return;
    }
    long long m = (tl + tr) >> 1ll;
    upd(l, r, v * 2, tl, m);
    upd(l, r, v * 2 + 1, m + 1, tr);
    t[v] = max(t[v * 2], t[v * 2 + 1]);
  }
  long long get(long long l, long long r, long long v = 1, long long tl = 1,
                long long tr = n + 10) {
    push(v, tl, tr);
    if (l > tr || tl > r || l > r) return 0;
    if (l <= tl && tr <= r) return t[v];
    long long m = (tl + tr) >> 1ll;
    return max(get(l, r, v * 2, tl, m), get(l, r, v * 2 + 1, m + 1, tr));
  }
} rt;
long long bp[N][21], xr[N], sz[N], tin[N], tout[N];
long long hp[N];
void dfs(long long v, long long p) {
  for (int i = 1; i < 20; i++) bp[v][i] = bp[bp[v][i - 1]][i - 1];
  sz[v] = 1;
  for (auto u : g[v])
    if (u.first != p)
      bp[u.first][0] = v, xr[u.first] = u.second ^ xr[v], dfs(u.first, v),
      sz[v] += sz[u.first];
}
void hldfs(long long v, long long p, long long pr) {
  hp[v] = pr;
  tin[v] = tout[0]++;
  for (auto u : g[v])
    if (u.first != p && sz[u.first] * 2 > sz[v]) hldfs(u.first, v, pr);
  for (auto u : g[v])
    if (u.first != p && sz[u.first] * 2 <= sz[v]) hldfs(u.first, v, u.first);
  tout[v] = tout[0];
}
bool upper(long long a, long long b) {
  return (tin[a] <= tin[b] && tout[b] <= tout[a]);
}
long long LCA(long long a, long long b) {
  if (upper(a, b)) return a;
  if (upper(b, a)) return b;
  for (int j = 19; j >= 0; j--)
    if (!upper(bp[a][j], b)) a = bp[a][j];
  return bp[a][0];
}
long long pLCA(long long a, long long b) {
  if (upper(a, b)) return -1;
  for (int j = 19; j >= 0; j--)
    if (!upper(bp[a][j], b)) a = bp[a][j];
  return a;
}
long long pxr(long long x, long long y) { return xr[x] ^ xr[y]; }
void UpdBamboo(long long v, long long x) {
  while (1) {
    long long hm = hp[v];
    if (hm == hp[x]) hm = x;
    rt.upd(tin[hm], tin[v]);
    if (hm == x) break;
    v = bp[hm][0];
  }
}
long long GetBamboo(long long v, long long x) {
  long long z = 0;
  while (1) {
    long long hm = hp[v];
    if (hm == hp[x]) hm = x;
    z = max(z, rt.get(tin[hm], tin[v]));
    if (hm == x) break;
    v = bp[hm][0];
  }
  return z;
}
void UpdPath(long long x, long long y) {
  long long z = pLCA(x, y);
  if (z != -1) UpdBamboo(x, z);
  z = pLCA(y, x);
  if (z != -1) UpdBamboo(y, z);
}
long long getPath(long long x, long long y) {
  long long z = pLCA(x, y);
  long long ans = 0;
  if (z != -1) ans = max(ans, GetBamboo(x, z));
  z = pLCA(y, x);
  if (z != -1) ans = max(ans, GetBamboo(y, z));
  return ans;
}
bool READY[N];
int main() {
  ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);
  cin >> n >> q;
  ds.init(n);
  tout[0] = 1ll;
  for (int i = 1; i <= q; i++) cin >> a[i] >> b[i] >> c[i];
  for (int i = 1; i <= q; i++) {
    if (ds.fnd(a[i]) != ds.fnd(b[i]))
      ds.unt(a[i], b[i]), g[a[i]].push_back(make_pair(b[i], c[i])),
          g[b[i]].push_back(make_pair(a[i], c[i])), READY[i] = 1;
  }
  for (int j = 1; j <= n; j++)
    if (tin[j] == 0) dfs(j, 0), hldfs(j, 0, j);
  for (int i = 1; i <= q; i++) {
    if (READY[i])
      cout << "YES\n";
    else {
      long long z = pxr(a[i], b[i]);
      if (z == c[i] || getPath(a[i], b[i])) {
        cout << "NO\n";
        continue;
      }
      UpdPath(a[i], b[i]);
      cout << "YES\n";
    }
  }
}

```