#include <bits/stdc++.h>
using namespace std;
const int maxn = 5e5 + 5;
int ans[maxn];
int main() {
  int T;
  scanf("%d", &T);
  for (int jsq = 1; jsq <= T; jsq++) {
    int n, a, b;
    scanf("%d%d%d", &n, &a, &b);
    if (a + b > n - 2 || abs(a - b) > 1) {
      puts("-1");
      continue;
    }
    if (a == b) {
      for (int i = 1; i <= a + 1; i++) {
        ans[i * 2 - 1] = i;
        ans[i * 2] = i + a + 1;
      }
      for (int i = 2 * a + 3; i <= n; i++) ans[i] = i;
      for (int i = 1; i <= n; i++) printf("%d ", ans[i]);
      puts("");
      continue;
    }
    bool flag = 0;
    if (a < b) {
      flag = 1;
      swap(a, b);
    }
    for (int i = 1; i <= a; i++) {
      ans[i * 2] = i;
      ans[i * 2 - 1] = i + a;
    }
    for (int i = 2 * a + 1; i <= n; i++) ans[i] = i;
    for (int i = 1; i <= n; i++) printf("%d ", flag ? ans[i] : n - ans[i] + 1);
    puts("");
  }
  return 0;
}

### Prompt

Develop a solution in cpp to the problem described below:

You are given three integers n, a, b. Determine if there exists a permutation p_1, p_2, …, p_n of integers from 1 to n, such that:

  * There are exactly a integers i with 2 ≤ i ≤ n-1 such that p_{i-1} < p_i > p_{i+1} (in other words, there are exactly a local maximums).

  * There are exactly b integers i with 2 ≤ i ≤ n-1 such that p_{i-1} > p_i < p_{i+1} (in other words, there are exactly b local minimums).




If such permutations exist, find any such permutation.

Input

The first line of the input contains a single integer t (1 ≤ t ≤ 10^4) — the number of test cases. The description of test cases follows.

The only line of each test case contains three integers n, a and b (2 ≤ n ≤ 10^5, 0 ≤ a,b ≤ n).

The sum of n over all test cases doesn't exceed 10^5.

Output

For each test case, if there is no permutation with the requested properties, output -1.

Otherwise, print the permutation that you are found. If there are several such permutations, you may print any of them.

Example

Input


3
4 1 1
6 1 2
6 4 0


Output


1 3 2 4
4 2 3 1 5 6
-1

Note

In the first test case, one example of such permutations is [1, 3, 2, 4]. In it p_1 < p_2 > p_3, and 2 is the only such index, and p_2> p_3 < p_4, and 3 the only such index.

One can show that there is no such permutation for the third test case.

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
const int maxn = 5e5 + 5;
int ans[maxn];
int main() {
  int T;
  scanf("%d", &T);
  for (int jsq = 1; jsq <= T; jsq++) {
    int n, a, b;
    scanf("%d%d%d", &n, &a, &b);
    if (a + b > n - 2 || abs(a - b) > 1) {
      puts("-1");
      continue;
    }
    if (a == b) {
      for (int i = 1; i <= a + 1; i++) {
        ans[i * 2 - 1] = i;
        ans[i * 2] = i + a + 1;
      }
      for (int i = 2 * a + 3; i <= n; i++) ans[i] = i;
      for (int i = 1; i <= n; i++) printf("%d ", ans[i]);
      puts("");
      continue;
    }
    bool flag = 0;
    if (a < b) {
      flag = 1;
      swap(a, b);
    }
    for (int i = 1; i <= a; i++) {
      ans[i * 2] = i;
      ans[i * 2 - 1] = i + a;
    }
    for (int i = 2 * a + 1; i <= n; i++) ans[i] = i;
    for (int i = 1; i <= n; i++) printf("%d ", flag ? ans[i] : n - ans[i] + 1);
    puts("");
  }
  return 0;
}

```