#include <bits/stdc++.h>
using namespace std;
int main() {
  int n;
  scanf("%d", &n);
  vector<int> A(n);
  for (int i = 0; i < n; ++i) {
    cin >> A[i];
  }
  int leftLen = 1, rightLen = 1;
  for (int i = 1; i < n; ++i) {
    if (A[i] > A[i - 1])
      ++leftLen;
    else
      break;
  }
  for (int i = n - 2; i >= 0; --i) {
    if (A[i] > A[i + 1])
      ++rightLen;
    else
      break;
  }
  (leftLen % 2 || rightLen % 2) ? printf("Alice") : printf("Bob");
  return 0;
}

### Prompt

Construct a CPP code solution to the problem outlined:

Alice and Bob are playing a game. They are given an array A of length N. The array consists of integers. They are building a sequence together. In the beginning, the sequence is empty. In one turn a player can remove a number from the left or right side of the array and append it to the sequence. The rule is that the sequence they are building must be strictly increasing. The winner is the player that makes the last move. Alice is playing first. Given the starting array, under the assumption that they both play optimally, who wins the game?

Input

The first line contains one integer N (1 ≤ N ≤ 2*10^5) - the length of the array A.

The second line contains N integers A_1, A_2,...,A_N (0 ≤ A_i ≤ 10^9)

Output

The first and only line of output consists of one string, the name of the winner. If Alice won, print "Alice", otherwise, print "Bob".

Examples

Input


1
5


Output


Alice


Input


3
5 4 5


Output


Alice


Input


6
5 8 2 1 10 9


Output


Bob

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  int n;
  scanf("%d", &n);
  vector<int> A(n);
  for (int i = 0; i < n; ++i) {
    cin >> A[i];
  }
  int leftLen = 1, rightLen = 1;
  for (int i = 1; i < n; ++i) {
    if (A[i] > A[i - 1])
      ++leftLen;
    else
      break;
  }
  for (int i = n - 2; i >= 0; --i) {
    if (A[i] > A[i + 1])
      ++rightLen;
    else
      break;
  }
  (leftLen % 2 || rightLen % 2) ? printf("Alice") : printf("Bob");
  return 0;
}

```