#include <bits/stdc++.h>
using namespace std;
int main() {
  int t;
  cin >> t;
  while (t--) {
    string s;
    queue<char> q;
    cin >> s;
    int n = s.size();
    if (n % 2 == 0) {
      int cond = 0;
      int i;
      for (i = 0; i < n / 2; i++) {
        q.push(s[i]);
      }
      for (; i < n; i++) {
        if (q.front() == s[i]) {
          q.pop();
        } else {
          cond = 1;
          break;
        }
      }
      if (cond == 1) {
        cout << "NO" << endl;
      } else {
        cout << "YES" << endl;
      }
    } else {
      cout << "NO" << endl;
    }
  }
}

### Prompt

Please provide a cpp coded solution to the problem described below:

A string is called square if it is some string written twice in a row. For example, the strings "aa", "abcabc", "abab" and "baabaa" are square. But the strings "aaa", "abaaab" and "abcdabc" are not square.

For a given string s determine if it is square.

Input

The first line of input data contains an integer t (1 ≤ t ≤ 100) —the number of test cases.

This is followed by t lines, each containing a description of one test case. The given strings consist only of lowercase Latin letters and have lengths between 1 and 100 inclusive.

Output

For each test case, output on a separate line:

  * YES if the string in the corresponding test case is square, 
  * NO otherwise. 



You can output YES and NO in any case (for example, strings yEs, yes, Yes and YES will be recognized as a positive response).

Example

Input


10
a
aa
aaa
aaaa
abab
abcabc
abacaba
xxyy
xyyx
xyxy


Output


NO
YES
NO
YES
YES
YES
NO
NO
NO
YES

### Response

```cpp
#include <bits/stdc++.h>
using namespace std;
int main() {
  int t;
  cin >> t;
  while (t--) {
    string s;
    queue<char> q;
    cin >> s;
    int n = s.size();
    if (n % 2 == 0) {
      int cond = 0;
      int i;
      for (i = 0; i < n / 2; i++) {
        q.push(s[i]);
      }
      for (; i < n; i++) {
        if (q.front() == s[i]) {
          q.pop();
        } else {
          cond = 1;
          break;
        }
      }
      if (cond == 1) {
        cout << "NO" << endl;
      } else {
        cout << "YES" << endl;
      }
    } else {
      cout << "NO" << endl;
    }
  }
}

```