4 come back to your fridge in 60 minutes and the ice should have started melting away enough so that you can gently i said gently pull the ice away don t try to stick a screwdriver in and wedge the ice out this can wreck the sides of the appliance and then you ll be angry 5 come back to your fridge in 60 minutes and the ice should have started melting away enough so that you can gently i said gently pull the ice away don t try to stick a screwdriver in and wedge the ice out this can wreck the sides of the appliance and then you ll be angry 5
Report Abuse. When we say percentage, we express the term as a fraction of 100. Since you have already mentioned the fraction is 5/6, there is just one thing missing, we just need to multiply it with 100.It will be done like this: Â­Â­5 Ã 100 6 = 83.33% This means that 5 is 83.33 % of 6.eport Abuse. When we say percentage, we express the term as a fraction of 100. Since you have already mentioned the fraction is 5/6, there is just one thing missing, we just need to multiply it with 100.
Bala Marish replied to vijayan c on 05-Jul-11 02:27 AM. first you calculate individual percentage of the all sudent and stored it one variable... and next use this type of operation. find the total number if of student percentage and store it to one variable....tep1- First calculate percentage of each student like. Vijay-- (50+60+12+40+50)*100/500 = 42.4%. Step2- add all percentage in another variable and take a count no of student in variable in loop where loop run from 1 to no of student.