Organic acids are ubiquitous throughout the field of chemistry. Whether used as a solvent, a substrate, a strong acid, or in a catalytic amount as a Bronsted acid source, organic acids are as commonplace as glassware for the researcher.
where p is the frequency of the A allele and q is the frequency of the a allele in the population. In the equation, p 2 represents the frequency of the homozygous genotype AA, q 2 represents the frequency of the homozygous genotype aa, and 2pq represents the frequency of the heterozygous genotype Aa.
Start with the known genotype, bb. It makes up 0.25 of the population, the frequency of the b allele is sqrt(0.25) = 0.5. If the frequency of b = 0.5, then the frequency of B is 1-0.5 = 0.5. Using the H-W equations, q = 0.5 and p = 1 - q = 0.5.Equation #2, pâ2 + 2pq + qâ2 = 1 becomes 0.25 + 0.5 + 0.25 = 1.ince you know that q^2 = 25/100 = 0.25, just take the square root to find the allele frequency of q. (q^2)^1/2 = 0.5 Lastly, since p + q = 1 always, the frequency of the dominant allele p is 1 - q = 1 -.5 = 0.5. Source(s): green_commander Â· 5 years ago.