Calculate the value of the third order rate constant. Î½ = k[A][B][C] Thus by using the rules of algebra it is seen that the units of this third order reaction are L mol s. Calculate the value of the third order rate constant. Î½ = k [A][B][C]. Thus by using the rules of algebra it is seen that. the units of this third order reaction are L mol s.
Neutralization Reactions Mixing Acids & Bases Acid/Base Neutralization â¢A salt is any compound that can be derived from the neutralization of an acid and a base. â¢The word neutralization is used because the acid and base properties of H+ and OH- are destroyed or neutralized. â¢In the reaction, H+ and OH- combine to form HOH or H 2 O (water molecules). â¢ A neutralization reaction is a type of double replacement reaction. Writing neutralization equations When acids and bases are mixed, a salt forms NaOH + HCl H 2 O + NaCl base + acid water + salt The cation (metal) from the base and the anion from the acid join to form the salt. The OH from the base and the H from the acid join to form water . + â + â hydroxide Example: Write the chemical reaction when lithium
Re: Acidic and Basic Salts. Ok first of all, you need to work out the acid and base that formed this salt. For NaHSO4, H2SO4 is a strong acid, and NaOH is a strong base, and so the salt formed from these two, NaHSO4, is a neutral salt.For CaCl2, it came from HCl, a strong acid, and Ca(OH)2, a strong base, and therefore the salt, CaCl2, will also be neutral.Thats wrong, Sodium Bisulfate is an acidic salt, its because sulfuric acid is diprotic, So when it forms HSO4, HSO4 is a weak acid.or NaHSO4, H2SO4 is a strong acid, and NaOH is a strong base, and so the salt formed from these two, NaHSO4, is a neutral salt. For CaCl2, it came from HCl, a strong acid, and Ca(OH)2, a strong base, and therefore the salt, CaCl2, will also be neutral. 2011 ATAR: 99.30 Fort Street High Schoool â.