In the case $g(x)=x$, this reduces to the familiar formula for the derivative of $f(x)$ with respect to $x$, $$\lim_{h\to0}{f(x+h)-f(x)\over h}$$ In the case where $g(x)$ is a constant, the denominator $g(x+h)-g(x)$ is identically zero, so the limit n'existe pas.hat I would like to understand is: Why does (derivative with respect to x) make sense but $(\text{derivative with respect to} (\lambda x \to 2))$ and. $(\text{derivative with respect to} (\lambda x \to \ln(x)) $ do not seem to make any sense to me.
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Purdue University's West Lafayette campus been host to fraternities and sororities. Today, Purdue boasts one of the nation's largest Fraternity and Sorority Communities, with over 5,000 students holding membership in over 80 organizations.About 20% of Purdue's undergraduates are members of a fraternity or sorority.Cooperatives have been a Purdue tradition for more than 75 yeas as well. With almost 400 members the community continues to thrive as an integral part of many students' experiences.oday, Purdue boasts one of the nation's largest Fraternity and Sorority Communities, with over 5,000 students holding membership in over 80 organizations. About 20% of Purdue's undergraduates are members of a fraternity or sorority.