Does $\mathop{\LARGEΣ}_{k = 1}^{n}k^α = \left(\mathop{\LARGEΣ}_{k = 1}^{n}k\right)^β$ for which $α \neq 3, \ β \neq 2$ and $α \neq β$?
Are there $a,b \in \mathbb{N}$ that ${(\sum_{k=1}^n k)}^a = \sum_{k=1}^n k^b $ beside $2,3$