parameters: (self, a, b)
return_statement: return a.remainder_near(b, context=self)
docstring: Returns to be "a - b * n", where n is the integer nearest the exact
          value of "x / b" (if two integers are equally near then the even one
          is chosen).  If the result is equal to 0 then its sign will be the
          sign of a.
  
          This operation will fail under the same conditions as integer division
          (that is, if integer division on the same two operands would fail, the
          remainder cannot be calculated).
  
          >>> ExtendedContext.remainder_near(Decimal('2.1'), Decimal('3'))
          Decimal('-0.9')
          >>> ExtendedContext.remainder_near(Decimal('10'), Decimal('6'))
          Decimal('-2')
          >>> ExtendedContext.remainder_near(Decimal('10'), Decimal('3'))
          Decimal('1')
          >>> ExtendedContext.remainder_near(Decimal('-10'), Decimal('3'))
          Decimal('-1')
          >>> ExtendedContext.remainder_near(Decimal('10.2'), Decimal('1'))
          Decimal('0.2')
          >>> ExtendedContext.remainder_near(Decimal('10'), Decimal('0.3'))
          Decimal('0.1')
          >>> ExtendedContext.remainder_near(Decimal('3.6'), Decimal('1.3'))
          Decimal('-0.3')
          >>> ExtendedContext.remainder_near(3, 11)
          Decimal('3')
          >>> ExtendedContext.remainder_near(Decimal(3), 11)
          Decimal('3')
          >>> ExtendedContext.remainder_near(3, Decimal(11))
          Decimal('3')
docstring_summary: Returns to be "a - b * n", where n is the integer nearest the exact
          value of "x / b" (if two integers are equally near then the even one
          is chosen).  If the result is equal to 0 then its sign will be the
          sign of a.
docstring_tokens: Returns to be a - b * n where n is the integer nearest the exact value of x / b ( if two integers are equally near then the even one is chosen ) . If the result is equal to 0 then its sign will be the sign of a .
function: def remainder_near(self, a, b):
          """Returns to be "a - b * n", where n is the integer nearest the exact
          value of "x / b" (if two integers are equally near then the even one
          is chosen).  If the result is equal to 0 then its sign will be the
          sign of a.
  
          This operation will fail under the same conditions as integer division
          (that is, if integer division on the same two operands would fail, the
          remainder cannot be calculated).
  
          >>> ExtendedContext.remainder_near(Decimal('2.1'), Decimal('3'))
          Decimal('-0.9')
          >>> ExtendedContext.remainder_near(Decimal('10'), Decimal('6'))
          Decimal('-2')
          >>> ExtendedContext.remainder_near(Decimal('10'), Decimal('3'))
          Decimal('1')
          >>> ExtendedContext.remainder_near(Decimal('-10'), Decimal('3'))
          Decimal('-1')
          >>> ExtendedContext.remainder_near(Decimal('10.2'), Decimal('1'))
          Decimal('0.2')
          >>> ExtendedContext.remainder_near(Decimal('10'), Decimal('0.3'))
          Decimal('0.1')
          >>> ExtendedContext.remainder_near(Decimal('3.6'), Decimal('1.3'))
          Decimal('-0.3')
          >>> ExtendedContext.remainder_near(3, 11)
          Decimal('3')
          >>> ExtendedContext.remainder_near(Decimal(3), 11)
          Decimal('3')
          >>> ExtendedContext.remainder_near(3, Decimal(11))
          Decimal('3')
          """
          a = _convert_other(a, raiseit=True)
          return a.remainder_near(b, context=self)
function_tokens: def remainder_near ( self , a , b ) : a = _convert_other ( a , raiseit = True ) return a . remainder_near ( b , context = self )