parameters: (x, name=None)
docstring: Returns `True` if `x` is strictly increasing.
  
    Elements of `x` are compared in row-major order.  The tensor `[x[0],...]`
    is strictly increasing if for every adjacent pair we have `x[i] < x[i+1]`.
    If `x` has less than two elements, it is trivially strictly increasing.
  
    See also:  `is_non_decreasing`
  
    Args:
      x: Numeric `Tensor`.
      name: A name for this operation (optional).
        Defaults to "is_strictly_increasing"
  
    Returns:
      Boolean `Tensor`, equal to `True` iff `x` is strictly increasing.
  
    Raises:
      TypeError: if `x` is not a numeric tensor.
docstring_summary: Returns `True` if `x` is strictly increasing.
docstring_tokens: Returns True if x is strictly increasing .
function: def is_strictly_increasing(x, name=None):
    """Returns `True` if `x` is strictly increasing.
  
    Elements of `x` are compared in row-major order.  The tensor `[x[0],...]`
    is strictly increasing if for every adjacent pair we have `x[i] < x[i+1]`.
    If `x` has less than two elements, it is trivially strictly increasing.
  
    See also:  `is_non_decreasing`
  
    Args:
      x: Numeric `Tensor`.
      name: A name for this operation (optional).
        Defaults to "is_strictly_increasing"
  
    Returns:
      Boolean `Tensor`, equal to `True` iff `x` is strictly increasing.
  
    Raises:
      TypeError: if `x` is not a numeric tensor.
    """
    with ops.name_scope(name, 'is_strictly_increasing', [x]):
      diff = _get_diff_for_monotonic_comparison(x)
      # When len(x) = 1, diff = [], less = [], and reduce_all([]) = True.
      zero = ops.convert_to_tensor(0, dtype=diff.dtype)
      return math_ops.reduce_all(math_ops.less(zero, diff))
function_tokens: def is_strictly_increasing ( x , name = None ) : with ops . name_scope ( name , 'is_strictly_increasing' , [ x ] ) : diff = _get_diff_for_monotonic_comparison ( x ) # When len(x) = 1, diff = [], less = [], and reduce_all([]) = True. zero = ops . convert_to_tensor ( 0 , dtype = diff . dtype ) return math_ops . reduce_all ( math_ops . less ( zero , diff ) )