The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include <bits/stdc++.h>
using namespace std;

int main() {
  int N;
  cin >> N;
  int cnt = 0;
  cnt += (N/105);
  cnt += (N/165);
  cnt += (N/135);
  cnt += (N/189);
  cnt += (N/195);
  cout << cnt << endl;
}
