The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include<stdio.h>
int main(){
	int N,i,k,a,b=0;
	scanf("%d",&N);
	for(i=1;i<=N;i+=2){
		a=0;
		for(k=1;k<=i;k++){
			if(i%k==0)a++;
			if(a==9)break;
		}
		if(a==8)b++;
	}
	printf("%d",b);
	return 0;
}