The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
// B - 105
#include <bits/stdc++.h>
using namespace std;

int main(){
	int N; cin>>N;
	int ans = 0;
	for(int n=1; n<=N; n+=2){
		int c = 0;
		for(int i=1; i<=n; ++i) if(n%i == 0) c++;
		if(c == 8) ans++;
	}
	cout<< ans <<endl;
}