The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include <bits/stdc++.h>
using namespace std;

int main() {
	int n, a = 0;
	cin >> n;
	if (n >= 105) a++;
	if (n >= 135) a++;
	if (n >= 165) a++;
	if (n >= 189) a++;
	if (n >= 195) a++;
	cout << a << endl;
}