The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include <bits/stdc++.h>
using namespace std;
int main()
{
int a,b,c;
cin>>a;
for(int i=1;i<=a;)
{b=0;
for(int j=1;j<=i;)
{if(i%j==0)
b++;
j=j+2;}
if(b==8)
c++;
i=i+2;}
cout<<c;
}
