The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
  #include<bits/stdc++.h>
using namespace std;
int main(){
 int n, cn=0; cin>>n;  
 for(int i=1; i<=n;i++){int c=0;
  for(int j=1; j<=n;j++){
   if(i%2==1 && i%j==0)c++; if(c==8)break;
  }
 if(i%2==1 && c==8) cn++;
 
 } 
  cout<<cn;
}