The Queen of England has n trees growing in a row in her garden. At that, the i-th (1 ≤ i ≤ n) tree from the left has height ai meters. Today the Queen decided to update the scenery of her garden. She wants the trees' heights to meet the condition: for all i (1 ≤ i < n), ai + 1 - ai = k, where k is the number the Queen chose.

Unfortunately, the royal gardener is not a machine and he cannot fulfill the desire of the Queen instantly! In one minute, the gardener can either decrease the height of a tree to any positive integer height or increase the height of a tree to any positive integer height. How should the royal gardener act to fulfill a whim of Her Majesty in the minimum number of minutes?

Input

The first line contains two space-separated integers: n, k (1 ≤ n, k ≤ 1000). The second line contains n space-separated integers a1, a2, ..., an (1 ≤ ai ≤ 1000) — the heights of the trees in the row. 

Output

In the first line print a single integer p — the minimum number of minutes the gardener needs. In the next p lines print the description of his actions. 

If the gardener needs to increase the height of the j-th (1 ≤ j ≤ n) tree from the left by x (x ≥ 1) meters, then print in the corresponding line "+ j x". If the gardener needs to decrease the height of the j-th (1 ≤ j ≤ n) tree from the left by x (x ≥ 1) meters, print on the corresponding line "- j x".

If there are multiple ways to make a row of trees beautiful in the minimum number of actions, you are allowed to print any of them.

Examples

Input

4 1
1 2 1 5


Output

2
+ 3 2
- 4 1


Input

4 1
1 2 3 4


Output

0
function trim(s) {
	return s.replace(/^\s+|\s+$/gm, '');
}

function tokenize(s) {
	return trim(s).split(/\s+/);
}

function tokenizeIntegers(s) {
	var tokens = tokenize(s);
	for (var i = 0; i < tokens.length; i += 1) {
		tokens[i] = parseInt(tokens[i]);
	};
	return tokens;
}

function main() {
	var integers = tokenizeIntegers(readline());
	var treeNum = integers[0], delta = integers[1];
	var trees = tokenizeIntegers(readline());
	var bestCost = treeNum, bestActions;
		maxStartingHeight = 1000;

	for (var start = 1; start <= maxStartingHeight; ++start) {
		var current = start, cost = 0;
		var actions = [];
		for (var i = 0; i < treeNum; ++i) {
			if (trees[i] != current) {
				cost += 1;
				actions.push([current < trees[i] ? "-" : "+",
						i+1, Math.abs(current-trees[i])].join(" "));
			}
			current += delta;
		}
		if (cost < bestCost) {
			bestCost = cost;
			bestActions = actions;
		}
	}

	print(bestCost);
	if (bestCost > 0) {
		print(bestActions.join("\n"));
	}
}

main();
