The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include"bits/stdc++.h"
using namespace std;
int main(){
    int n,s,a[]={105,135,165,195,189};
  	cin>>n;
    for(int i=0;i-5;)if(n>=a[i++])++s;
    cout<<s<<"\n";
}

