The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include <iostream>
using namespace std;

int main()
{
    int n; cin>>n;
    int res=0;
    for(int i=1; i<=n; i+=2) {
        int c=0;
        for(int j=1; j<=i; ++j) if (i%j==0) ++c;
        if (c==8) ++res;
    }
    cout<<res<<endl;
}
