The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include <bits/stdc++.h>

using namespace std;


int main(){
 int n;
  cin>>n;
  
  int total=0;
  if(n>=105) total++;
   if(n>=135) total++;
    if(n>=165) total++;
    if(n>=189) total++;
  if(n>=195) total++;
  cout<<total<<endl;
}