You are given a string S of length N consisting of lowercase English letters.

Process Q queries of the following two types:

* Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)
* Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).

Constraints

* N, Q, i_q, l_q, and r_q are integers.
* S is a string consisting of lowercase English letters.
* c_q is a lowercase English letter.
* 1 \leq N \leq 500000
* 1 \leq Q \leq 20000
* |S| = N
* 1 \leq i_q \leq N
* 1 \leq l_q \leq r_q \leq N
* There is at least one query of type 2 in each testcase.

Input

Input is given from Standard Input in the following format:


N
S
Q
Query_1
\vdots
Query_Q


Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:


1 i_q c_q



2 l_q r_q


Output

For each query of type 2, print a line containing the answer.

Example

Input

7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7


Output

3
1
5
N = int(input())
A = [ord(a) - 97 for a in input()]
NN = 19
BIT=[[0]*(2**NN+1) for _ in range(26)]
 
def addbit(t, i, x):
    while i <= 2**NN:
        BIT[t][i] += x
        i += i & (-i)

def getsum(t, i):
    ret = 0
    while i != 0:
        ret += BIT[t][i]
        i -= i&(-i)
    return ret

for i, a in enumerate(A):
    addbit(a, i+2, 1)

Q = int(input())
for _ in range(Q):
    a, b, c = input().rstrip().split()
    if a == "1":
        b = int(b)
        c = ord(c) - 97
        t = A[b-1]
        addbit(t, b+1, -1)
        addbit(c, b+1, 1)
        A[b-1] = c
    else:
        b, c = int(b), int(c)
        s = 0
        for t in range(26):
            s += 1 if getsum(t, c+1) - getsum(t, b) else 0
        print(s)
