The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include<bits/stdc++.h>
using namespace std;

signed main() {
  int n; cin >> n;
  int ans = 0;
  for(int i=105; i<=n; i+=2) {
    int c = 1;
    for(int j=2; j<=i; j++) if(i % j == 0) c++;
    if(c==8) ans++;
  }
  cout << ans << endl;
}
