You are given the string s of length n and the numbers p, q. Split the string s to pieces of length p and q.

For example, the string "Hello" for p = 2, q = 3 can be split to the two strings "Hel" and "lo" or to the two strings "He" and "llo".

Note it is allowed to split the string s to the strings only of length p or to the strings only of length q (see the second sample test).

Input

The first line contains three positive integers n, p, q (1 ≤ p, q ≤ n ≤ 100).

The second line contains the string s consists of lowercase and uppercase latin letters and digits.

Output

If it's impossible to split the string s to the strings of length p and q print the only number "-1".

Otherwise in the first line print integer k — the number of strings in partition of s.

Each of the next k lines should contain the strings in partition. Each string should be of the length p or q. The string should be in order of their appearing in string s — from left to right.

If there are several solutions print any of them.

Examples

Input

5 2 3
Hello


Output

2
He
llo


Input

10 9 5
Codeforces


Output

2
Codef
orces


Input

6 4 5
Privet


Output

-1


Input

8 1 1
abacabac


Output

8
a
b
a
c
a
b
a
c
rr=raw_input
rrI = lambda: int(rr())
rrM = lambda: map(int,rr().split())
debug=0
if debug:
    fi = open('t.txt','r')
    rr=lambda: fi.readline().replace('\n','')

def solve():
    for i,j in product(xrange(n/p + 1),xrange(n/q+1)):
        if i*p+j*q == n: break
    else: return -1
    cur = 0
    ans = [`i+j`]
    for ix in xrange(i):
        ans.append(s[cur:cur+p])
        cur += p
    for ix in xrange(j):
        ans.append(s[cur:cur+q])
        cur += q
    return "\n".join(ans)

n,p,q = rrM()
s = rr()
from itertools import product
print solve()
