Two people are playing a game with a string s, consisting of lowercase latin letters. 

On a player's turn, he should choose two consecutive equal letters in the string and delete them. 

For example, if the string is equal to "xaax" than there is only one possible turn: delete "aa", so the string will become "xx". A player not able to make a turn loses.

Your task is to determine which player will win if both play optimally.

Input

The only line contains the string s, consisting of lowercase latin letters (1 ≤ |s| ≤ 100 000), where |s| means the length of a string s.

Output

If the first player wins, print "Yes". If the second player wins, print "No".

Examples

Input


abacaba


Output


No


Input


iiq


Output


Yes


Input


abba


Output


No

Note

In the first example the first player is unable to make a turn, so he loses.

In the second example first player turns the string into "q", then second player is unable to move, so he loses.
import java.io.*;

import java.util.*;
 public class Solution {
	 
	 //static Long dp[];
	 public static void main(String[] args) throws Exception
    {
		 FastReader fr=new FastReader();
		 String s=fr.next();
		 boolean first=true;
		 Stack<Character> stack=new Stack<>();
		 for(int i=0;i<s.length();i++) {
			 char c=s.charAt(i);
			 if(stack.isEmpty())
				 stack.push(c);
			 else if(stack.peek()==c)
			 {
				stack.pop();
				first=!first;
			 }
			 else
				 stack.push(c);
		 }
		 if(first)
			 System.out.println("No");
		 else
			 System.out.println("Yes");
		
		  
		
		 
	}
	 
	 
	 
	
	public static long gcd(long n1,long n2) {
		 if (n2 == 0) {
		        return n1;
		    }
		    return gcd(n2, n1 % n2);
	}
	 public static boolean isPali(String s) {
		 int i=0;
		 int j=s.length()-1;
		 while(i<=j) {
			 if(s.charAt(i)!=s.charAt(j))
				 return false;
			 i++;
			 j--;
		 }
		 return true;
	 }
	 public static String reverse(String s) {
		 String res="";
		 for(int i=0;i<s.length();i++) {
			 res+=s.charAt(i);
		 }
		 return res;
	 }
	
		
	 
	 public static int bsearch(long suf[],long val) {
		 int i=0;
		 int j=suf.length-1;
		 while(i<=j) {
			 int mid=(i+j)/2;
			 if(suf[mid]==val)
				 return mid;
			 else if(suf[mid]<val)
				 j=mid-1;
			 else
				 i=mid+1;
		 }
		 return -1;
	 }
	 
	 
	 
	
	 
	 
	public static int[] getFreq(String s) {
		int a[]=new int[26];
		for(int i=0;i<s.length();i++) {
			a[s.charAt(i)-'a']++;
		}
		return a;
		
	}
	 
	 public static boolean isPrime(int n) {
		 
		 for(int i=2;(i*i)<=n;i++) {
			 if(n%i==0)
				 return false;
		 }
		 return true;
	 }
            	  
             
             
    }
class Pair implements Comparable<Pair>{
	int cost;
	int type;
	
	Pair(int cost,int type){
		this.cost=cost;
		
		this.type=type;
	}
	public int compareTo(Pair o) {
		return o.type-this.type;
	}
}

	
	 
	
	

	 
 
  

class FastReader
{
    BufferedReader br;
    StringTokenizer st;
 
    public FastReader()
    {
        br = new BufferedReader(new
                InputStreamReader(System.in));
    }
 
    String next()
    {
        while (st == null || !st.hasMoreElements())
        {
            try
            {
                st = new StringTokenizer(br.readLine());
            }
            catch (IOException e)
            {
                e.printStackTrace();
            }
        }
        return st.nextToken();
    }
 
    int nextInt()
    {
        return Integer.parseInt(next());
    }
 
    long nextLong()
    {
        return Long.parseLong(next());
    }
 
    double nextDouble()
    {
        return Double.parseDouble(next());
    }
 
    String nextLine()
    {
        String str = "";
        try
        {
            str = br.readLine();
        }
        catch (IOException e)
        {
            e.printStackTrace();
        }
        return str;
    }
}

