You are given a string S of length N consisting of lowercase English letters.

Process Q queries of the following two types:

* Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)
* Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).

Constraints

* N, Q, i_q, l_q, and r_q are integers.
* S is a string consisting of lowercase English letters.
* c_q is a lowercase English letter.
* 1 \leq N \leq 500000
* 1 \leq Q \leq 20000
* |S| = N
* 1 \leq i_q \leq N
* 1 \leq l_q \leq r_q \leq N
* There is at least one query of type 2 in each testcase.

Input

Input is given from Standard Input in the following format:


N
S
Q
Query_1
\vdots
Query_Q


Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:


1 i_q c_q



2 l_q r_q


Output

For each query of type 2, print a line containing the answer.

Example

Input

7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7


Output

3
1
5
import bisect
n = int(input().strip())
S = list(input().strip())
L=[[] for _ in range(26)]
for i,s in enumerate(S):
    L[ord(s)-ord("a")].append(i)

q = int(input().strip())
for _ in range(q):
    query=input().strip().split()
    if query[0]=="1":
        i=int(query[1])
        i-=1
        c=query[2]
        if S[i]!=c:
            delInd=bisect.bisect_left(L[ord(S[i])-ord("a")],i)
            del L[ord(S[i])-ord("a")][delInd]
            bisect.insort(L[ord(c)-ord("a")], i)
            S[i]=c
    else:
        l,r=map(int,[query[1],query[2]])
        l-=1; r-=1
        ans=0
        for j in range(26):
            ind=bisect.bisect_left(L[j],l)
            if ind<len(L[j]) and L[j][ind]<=r:
                ans+=1
        print(ans)