The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include<bits/stdc++.h>
using namespace std;
int main()
{
	int n;
	cin>>n;
	int sum = 0;
	for(int i=1;i<=n;i+=2)
	{
		int chu = 0;
		for(int j=i;j;j--)
		{
			if(i%j == 0)chu++; 
		}
		if(chu == 8)
			sum++;
	 } 
	 cout<<sum<<endl; 
 } 