The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include<iostream>
using namespace std;
int main(){
	int N;
	cin >> N;
	int num[] = {105,135,165,189,195};
	for(int i = 0; i <= 4;i++){
		if(N<num[i]){
			cout << i;
			return 0;
		}
	}
	cout << 5;
	return 0;
}