You're given an array a of length 2n. Is it possible to reorder it in such way so that the sum of the first n elements isn't equal to the sum of the last n elements?

Input

The first line contains an integer n (1 ≤ n ≤ 1000), where 2n is the number of elements in the array a.

The second line contains 2n space-separated integers a_1, a_2, …, a_{2n} (1 ≤ a_i ≤ 10^6) — the elements of the array a.

Output

If there's no solution, print "-1" (without quotes). Otherwise, print a single line containing 2n space-separated integers. They must form a reordering of a. You are allowed to not change the order.

Examples

Input


3
1 2 2 1 3 1


Output


2 1 3 1 1 2

Input


1
1 1


Output


-1

Note

In the first example, the first n elements have sum 2+1+3=6 while the last n elements have sum 1+1+2=4. The sums aren't equal.

In the second example, there's no solution.
import sys
# from bisect import bisect_left
# gcd
# from fractions import gcd
# from math import ceil, floor
# from copy import deepcopy
# from itertools import accumulate
# l = ['a', 'b', 'b', 'c', 'b', 'a', 'c', 'c', 'b', 'c', 'b', 'a']
# print(S.most_common(2))  # [('b', 5), ('c', 4)]
# print(S.keys())  # dict_keys(['a', 'b', 'c'])
# print(S.values())  # dict_values([3, 5, 4])
# print(S.items())  # dict_items([('a', 3), ('b', 5), ('c', 4)])
# from collections import Counter
# import math
# from functools import reduce
#
# fin = open('in_1.txt', 'r')
# sys.stdin = fin
input = sys.stdin.readline
def ii(): return int(input())
def mi(): return map(int, input().rstrip().split())
def lmi(): return list(map(int, input().rstrip().split()))
def li(): return list(input().rstrip())
# template


if __name__ == '__main__':

    # write code
    n = ii()
    a = lmi()
    a.sort()
    if sum(a[:n]) == sum(a[n:]):
        print(-1)
    else:
        for i in a:
            print(i, end=" ")
        print()
    
    