The Little Elephant has an integer a, written in the binary notation. He wants to write this number on a piece of paper.

To make sure that the number a fits on the piece of paper, the Little Elephant ought to delete exactly one any digit from number a in the binary record. At that a new number appears. It consists of the remaining binary digits, written in the corresponding order (possible, with leading zeroes).

The Little Elephant wants the number he is going to write on the paper to be as large as possible. Help him find the maximum number that he can obtain after deleting exactly one binary digit and print it in the binary notation.

Input

The single line contains integer a, written in the binary notation without leading zeroes. This number contains more than 1 and at most 105 digits.

Output

In the single line print the number that is written without leading zeroes in the binary notation — the answer to the problem.

Examples

Input

101


Output

11


Input

110010


Output

11010

Note

In the first sample the best strategy is to delete the second digit. That results in number 112 = 310.

In the second sample the best strategy is to delete the third or fourth digits — that results in number 110102 = 2610.
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.io.PrintWriter;
import java.util.ArrayDeque;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collections;
import java.util.Deque;
import java.util.HashMap;
import java.util.HashSet;
import java.util.Iterator;
import java.util.List;
import java.util.Map;
import java.util.PriorityQueue;
import java.util.Set;
import java.util.StringTokenizer;
import java.util.TreeMap;

public class Main {

	public static void main(String[] args) {

		InputStream inputStream = System.in;
		OutputStream outputStream = System.out;
		InputReader in = new InputReader(inputStream);
		PrintWriter out = new PrintWriter(outputStream);
		solve(in, out);
		out.close();
	}

	static String reverse(String s) {
		return (new StringBuilder(s)).reverse().toString();
	}

	static void sieveOfEratosthenes(int n, int factors[]) {
		n = 1000000001;
		factors[1] = 1;
		for (int p = 2; p * p <= n; p++) {
			if (factors[p] == 0) {
				factors[p] = p;
				for (int i = p * p; i <= n; i += p)
					factors[i] = p;
			}
		}
	}

	static void sort(int ar[]) {
		int n = ar.length;
		ArrayList<Integer> a = new ArrayList<>();
		for (int i = 0; i < n; i++)
			a.add(ar[i]);
		Collections.sort(a);
		for (int i = 0; i < n; i++)
			ar[i] = a.get(i);
	}

	static void sort1(long ar[]) {
		int n = ar.length;
		ArrayList<Long> a = new ArrayList<>();
		for (int i = 0; i < n; i++)
			a.add(ar[i]);
		Collections.sort(a);
		for (int i = 0; i < n; i++)
			ar[i] = a.get(i);
	}

	static long ncr(long n, long r, long mod) {
		if (r == 0)
			return 1;
		long val = ncr(n - 1, r - 1, mod);
		val = (n * val) % mod;
		val = (val * modInverse(r, mod)) % mod;
		return val;
	}

	public static int convert(String a, String b) {
		int T = 0;
		if (b.charAt(0) == 'P') {
			if (a.charAt(0) == '1' && a.charAt(1) == '2')
				T = 12;
			else
				T = (a.charAt(0) - '0') * 10 + (a.charAt(1) - '0') + 12;
		} else if (b.charAt(0) == 'A') {
			if (a.charAt(0) == '1' && a.charAt(1) == '2')
				T = 0;
			else
				T = (a.charAt(0) - '0') * 10 + (a.charAt(1) - '0');
		}

		T = T * 100 + (a.charAt(3) - '0') * 10 + (a.charAt(4) - '0');
		return T;

	}

	static boolean areBracketsBalanced(String expr) {
		// Using ArrayDeque is faster than using Stack class
		Deque<Character> stack = new ArrayDeque<Character>();

		// Traversing the Expression
		for (int i = 0; i < expr.length(); i++) {
			char x = expr.charAt(i);

			if (x == '(' || x == '[' || x == '{') {
				// Push the element in the stack
				stack.push(x);
				continue;
			}

			// IF current current character is not opening
			// bracket, then it must be closing. So stack
			// cannot be empty at this point.
			if (stack.isEmpty())
				return false;
			char check;
			switch (x) {
			case ')':
				check = stack.pop();
				if (check == '{' || check == '[')
					return false;
				break;

			case '}':
				check = stack.pop();
				if (check == '(' || check == '[')
					return false;
				break;

			case ']':
				check = stack.pop();
				if (check == '(' || check == '{')
					return false;
				break;
			}
		}

		// Check Empty Stack
		return (stack.isEmpty());
	}

	public static int hr(String s) {
		int hh = 0;
		hh = (s.charAt(0) - '0') * 10 + (s.charAt(1) - '0');
		return hh;
	}

	public static int mn(String s) {
		int mm = 0;
		mm = (s.charAt(3) - '0') * 10 + (s.charAt(4) - '0');
		return mm;
	}

	/*
	 * public static void countNumberOfPrimeFactors(){ boolean flag[]=new
	 * boolean[N]; Arrays.fill(flag,true); for(int i=2;i<N;i++){ if(flag[i]){
	 * for(int j=i;j<N;j+=i) { prime[j]++; flag[j]=false; } } } // prime[1]=1; }
	 */

	public static String rev(String s) {
		char[] temp = s.toCharArray();
		for (int i = 0; i < s.length() / 2; i++) {
			char tmp = temp[i];
			temp[i] = temp[s.length() - 1 - i];
			temp[s.length() - 1 - i] = tmp;

		}
		String str = "";
		for (char ch : temp) {
			str += ch;
		}
		return str;
	}

	static boolean isP(String str) {

		// Pointers pointing to the beginning
		// and the end of the string
		int i = 0, j = str.length() - 1;

		// While there are characters to compare
		while (i < j) {

			// If there is a mismatch
			if (str.charAt(i) != str.charAt(j))
				return false;

			// Increment first pointer and
			// decrement the other
			i++;
			j--;
		}

		// Given string is a palindrome
		return true;
	}

	public static boolean isSorted(List<Integer> l) {
		int n = l.size(), i = 0;
		for (i = 1; i < l.size(); i++) {
			if (l.get(i - 1) < l.get(i))
				return false;
		}
		return true;
	}

	public static boolean ln(long n, int c) {
		int l = 0;
		long t = n;
		while (t != 0) {

			t /= 10;
			l++;
		}
		return l == c;
	}
	

	public static void solve(InputReader sc, PrintWriter pw) {
//		
//	  int t=sc.nextInt();
//		  
//		  while(t-->0)
//		  {
			String s=sc.next();
			int z=0,o=0,in=0;
			for(char c: s.toCharArray()) if(c=='0') z++; else o++;
			if(o==0) pw.print(0);
			else if(z==0) {
				pw.print(s.substring(0,s.length()-1));
			}
			else if(z>0&&o>0)
			{
				for(int i=0;i<s.length();i++)
				{
					if(s.charAt(i)=='0')
					{
						in=i;
						break;
					}
				}
				pw.print(s.substring(0,in)+s.substring(in+1));
			}
			
				
		    
			
//		  }
		
		
		
		
		
		 

	}
	public static int[] fun(String s)
	{
		int h[]=new int[256];
		for(char c: s.toCharArray())
		{
			if(c!=' ') h[c]++;
		}
		return h;
	}
	static int getPrev(int n)
	{
	    // Compute c0 and
	    // c1 and store N
	    int temp = n;
	    int c0 = 0;
	    int c1= 0;
	 
	    while((temp & 1) == 1)
	    {
	        c1++;
	        temp = temp >> 1;
	    }
	 
	    if(temp == 0)
	        return -1;
	 
	    while(((temp & 1) == 0) &&
	           (temp!= 0))
	    {
	        c0++;
	        temp = temp >> 1;
	    }
	 
	    // position of rightmost
	    // non-trailing one.
	    int p = c0 + c1;
	 
	    // clears from bit p onwards
	    n = n & ((~0) << (p + 1));
	 
	    // Sequence of (c1+1) ones
	    int mask = (1 << (c1 + 1)) - 1;
	 
	    n = n | mask << (c0 - 1);
	 
	    return n;
	}
	 static boolean isPowerOfTwo(int n)
	    {
	        if (n == 0)
	            return false;
	  
	        while (n != 1) {
	            if (n % 2 != 0)
	                return false;
	            n = n / 2;
	        }
	        return true;
	    }

	



	static class Pair1 {
		long a;
		long b;

		Pair1(long a, long b) {
			this.a = a;
			this.b = b;
		}
	}

	static class Pair implements Comparable<Pair> {
		int a;
		int b;

		Pair(int a, int b) {
			this.a = a;
			this.b = b;
		}

		public int compareTo(Pair p) {
			if (a != p.a)
				return p.a - a;
			return b - p.b;
		}
	}

	static boolean isPrime(int n) {
		if (n <= 1)
			return false;
		if (n <= 3)
			return true;
		if (n % 2 == 0 || n % 3 == 0)
			return false;
		for (int i = 5; i * i <= n; i = i + 6)
			if (n % i == 0 || n % (i + 2) == 0)
				return false;
		return true;
	}

	static long gcd(long a, long b) {
		if (b == 0)
			return a;
		return gcd(b, a % b);
	}

	static int _gcd(int a, int b) {
		if (b == 0)
			return a;
		return _gcd(b, a % b);
	}

	static long fast_pow(long base, long n, long M) {
		if (n == 0)
			return 1;
		if (n == 1)
			return base % M;
		long halfn = fast_pow(base, n / 2, M);
		if (n % 2 == 0)
			return (halfn * halfn) % M;
		else
			return (((halfn * halfn) % M) * base) % M;
	}

	static long modInverse(long n, long M) {
		return fast_pow(n, M - 2, M);
	}

	public static int LowerBound(int a[], int x) {
		int l = -1, r = a.length;
		while (l + 1 < r) {
			int m = (l + r) >>> 1;
			if (a[m] >= x)
				r = m;
			else
				l = m;
		}
		return r;
	}

	public static int UpperBound(int a[], int x) {
		int l = -1, r = a.length;
		while (l + 1 < r) {
			int m = (l + r) >>> 1;
			if (a[m] <= x)
				l = m;
			else
				r = m;
		}
		return l + 1;
	}
	

	static class InputReader {
		public BufferedReader reader;
		public StringTokenizer tokenizer;

		public InputReader(InputStream stream) {
			reader = new BufferedReader(new InputStreamReader(stream), 32768);
			tokenizer = null;
		}

		public String nextLine() {
			return null;
		}

		public String next() {
			while (tokenizer == null || !tokenizer.hasMoreTokens()) {
				try {
					tokenizer = new StringTokenizer(reader.readLine());
				} catch (IOException e) {
					throw new RuntimeException(e);
				}
			}
			return tokenizer.nextToken();
		}

		public int nextInt() {
			return Integer.parseInt(next());
		}

		public long nextLong() {
			return Long.parseLong(next());
		}
	}
}
