The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include <bits/stdc++.h>
using namespace std;

int main(){
	int a;
	cin>>a;
	int d=0;
	for(int i=1;i<=a;i+=2){
		int b=0;
	for(int j=1;j<=i;j++){
		if(i%j==0){
			b++;
		}
		
	}
	if(b==8){
		d++;
	}
	
}
cout<<d<<endl;

}
