The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include <iostream>
using namespace std;
int main(){
  int n; cin >> n;
  int p=0;
  
  for(int i=1;i<=n;i+=2){
    int o=0; 
    for(int j=1;j<=i;j++)
        if(i%j==0) o++;
    if(o==8)p++;
  }
  
  cout << p << endl;

  return 0;
}