You're given an array a of length 2n. Is it possible to reorder it in such way so that the sum of the first n elements isn't equal to the sum of the last n elements?

Input

The first line contains an integer n (1 ≤ n ≤ 1000), where 2n is the number of elements in the array a.

The second line contains 2n space-separated integers a_1, a_2, …, a_{2n} (1 ≤ a_i ≤ 10^6) — the elements of the array a.

Output

If there's no solution, print "-1" (without quotes). Otherwise, print a single line containing 2n space-separated integers. They must form a reordering of a. You are allowed to not change the order.

Examples

Input


3
1 2 2 1 3 1


Output


2 1 3 1 1 2

Input


1
1 1


Output


-1

Note

In the first example, the first n elements have sum 2+1+3=6 while the last n elements have sum 1+1+2=4. The sums aren't equal.

In the second example, there's no solution.
def foo():
    a = int(input())
    b = [int(i) for i in str(input()).split(" ")]

    if len(set(b)) == 1:
        return ["-1"]
    b.sort()
    b = [str(i) for i in b]
    # fhs = 0
    # shs = 0
    # fhm = float("-Inf")
    # fhmx = float("Inf")
    # fhmi = 0
    # fhmix = 0
    # shm = float("Inf")
    # shmx = float("-Inf")
    # shmi = 0
    # shmix = 0
    # for i in range(a*2):
    #     if i < a:
    #         if int(b[i]) > fhm:
    #             fhm = int(b[i])
    #             fhmi = i
    #         if int(b[i]) < fhmx:
    #             fhm = int(b[i])
    #             fhmix = i
    #         fhs = fhs + int(b[i])
    #     else:
    #         if int(b[i]) < shm:
    #             shm = int(b[i])
    #             shmi = i
    #         if int(b[i]) > shmx:
    #             shm = int(b[i])
    #             shmix = i
    #         shs = shs + int(b[i])

    # if shs == fhs:
    #     if b[shmi] != b[fhmi]:
    #         b[shmi], b[fhmi] = b[fhmi], b[shmi]
    #         return b
    #     if b[shmix] != b[fhmix]:
    #         b[shmix], b[fhmix] = b[fhmix], b[shmix]
    #         return b
    #     if b[shmix] != b[fhmi]:
    #         b[shmix], b[fhmi] = b[fhmi], b[shmix]
    #         return b
    #     if b[shmi] != b[fhmix]:
    #         b[shmi], b[fhmix] = b[fhmix], b[shmi]
    #         return b
    return b


print(" ".join(foo()))
