You're given an array a of length 2n. Is it possible to reorder it in such way so that the sum of the first n elements isn't equal to the sum of the last n elements?

Input

The first line contains an integer n (1 ≤ n ≤ 1000), where 2n is the number of elements in the array a.

The second line contains 2n space-separated integers a_1, a_2, …, a_{2n} (1 ≤ a_i ≤ 10^6) — the elements of the array a.

Output

If there's no solution, print "-1" (without quotes). Otherwise, print a single line containing 2n space-separated integers. They must form a reordering of a. You are allowed to not change the order.

Examples

Input


3
1 2 2 1 3 1


Output


2 1 3 1 1 2

Input


1
1 1


Output


-1

Note

In the first example, the first n elements have sum 2+1+3=6 while the last n elements have sum 1+1+2=4. The sums aren't equal.

In the second example, there's no solution.
from sys import stdin
# stdin=open('input.txt')

def input():
	return stdin.readline().strip()


# from sys import stdout
# stdout=open('input.txt',mode='w+')

# def print1(x, end='\n'):
# 	stdout.write(str(x) +end)


# a, b = map(int, input().split())

# l = list(map(int, input().split()))


# CODE BEGINS HERE.................

import math

n = int(input())

l = list(map(int, input().split()))

if l.count(l[0]) == 2*n:
	print(-1)
else:
	print(*sorted(l))

# CODE ENDS HERE....................
# stdout.close()

