You are given a string S of length N consisting of lowercase English letters.

Process Q queries of the following two types:

* Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)
* Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).

Constraints

* N, Q, i_q, l_q, and r_q are integers.
* S is a string consisting of lowercase English letters.
* c_q is a lowercase English letter.
* 1 \leq N \leq 500000
* 1 \leq Q \leq 20000
* |S| = N
* 1 \leq i_q \leq N
* 1 \leq l_q \leq r_q \leq N
* There is at least one query of type 2 in each testcase.

Input

Input is given from Standard Input in the following format:


N
S
Q
Query_1
\vdots
Query_Q


Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:


1 i_q c_q



2 l_q r_q


Output

For each query of type 2, print a line containing the answer.

Example

Input

7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7


Output

3
1
5
from bisect import insort_left, bisect_left
n = int(input())
s = list(input())
Q = int(input())
query = [input() for _ in range(Q)]
dic = {chr(i+ord('a')):[] for i in range(26)}
for ind, c in enumerate(s):
    dic[c].append(ind)

for q in query:
    t, a, b = q.split()
    a = int(a)-1
    if t=='1':
        if s[a]==b:
            continue
        ind = bisect_left(dic[s[a]], a)
        dic[s[a]].pop(ind)
        insort_left(dic[b], a)
        s[a] = b
    else:
        b = int(b)-1
        tmp = 0
        for li in dic.values():
            if li and a<=li[-1] and li[bisect_left(li, a)] <= b:
                tmp += 1
        print(tmp)
