The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include <bits/stdc++.h>
#include <cmath>
using namespace std;
int main(){
  int N;
  cin>>N;
  	if(N<105) cout<<0;
  else if(N<135) cout<<1;
  else if(N<165) cout<<2;
  else if(N<189) cout<<3;
  else if(N<195) cout<<4;
  else cout<<5;
}
