N different natural numbers are given. If you select four different ones and set them as $ A $, $ B $, $ C $, $ D $, the following formula

$ \ Frac {A + B} {C --D} $



I want to find the maximum value of.




Given N different natural numbers, choose 4 different from them and create a program to find the maximum value of the above formula.



Input

The input is given in the following format.


N
a1 a2 ... aN


The number N (4 ≤ N ≤ 1000) of natural numbers is given in the first line. The value ai (1 ≤ ai ≤ 108) of each natural number is given in the second line. However, the same natural number does not appear more than once (ai ≠ aj for i ≠ j).

Output

Outputs the maximum value of the above formula as a real number for a given N natural numbers. However, the error must not exceed plus or minus 10-5.

Examples

Input

10
1 2 3 4 5 6 7 8 9 10


Output

19.00000


Input

5
22 100 42 3 86


Output

9.78947


Input

6
15 21 36 10 34 5


Output

18.00000


Input

4
100000 99999 8 1


Output

28571.285714
#include <bits/stdc++.h>
using namespace std;
#define rep(i,n) for (int (i)=(0);(i)<(int)(n);++(i))
using ll = long long;
using P = pair<int, int>;
using namespace std;

template<class T> void vin(vector<T>& v, int n) {
    v.resize(n);
    for (int i = 0; i < n; ++i) {
        cin >> v[i];
    }
}

int main() {
    int N;
    cin >> N;
    vector<double> a(N);
    rep(i, N) cin >> a[i];
    sort(a.rbegin(), a.rend());

    double ans = -1e10;
    rep(i, N) rep(j, N) {
        if (i == j) continue;
        double tmp = a[i]-a[j];
        int cur = 0;
        double tmp2 = 0;
        rep(k, N) {
            if (k == i or k == j) continue;
            tmp2 += a[k];
            cur++;
            if (cur == 2) break;
        }
        ans = max(ans, tmp2/tmp);
    }

    printf("%.10f\n", ans);

    return 0;
}

