You are given the string s of length n and the numbers p, q. Split the string s to pieces of length p and q.

For example, the string "Hello" for p = 2, q = 3 can be split to the two strings "Hel" and "lo" or to the two strings "He" and "llo".

Note it is allowed to split the string s to the strings only of length p or to the strings only of length q (see the second sample test).

Input

The first line contains three positive integers n, p, q (1 ≤ p, q ≤ n ≤ 100).

The second line contains the string s consists of lowercase and uppercase latin letters and digits.

Output

If it's impossible to split the string s to the strings of length p and q print the only number "-1".

Otherwise in the first line print integer k — the number of strings in partition of s.

Each of the next k lines should contain the strings in partition. Each string should be of the length p or q. The string should be in order of their appearing in string s — from left to right.

If there are several solutions print any of them.

Examples

Input

5 2 3
Hello


Output

2
He
llo


Input

10 9 5
Codeforces


Output

2
Codef
orces


Input

6 4 5
Privet


Output

-1


Input

8 1 1
abacabac


Output

8
a
b
a
c
a
b
a
c
try:
    import re

    def cg(string, length):
        return re.findall('.{%d}' % length, string)
    n,p,q=list(map(int,input().split(" ")))
    s=input()
    u=0
    if len(s)%p==0:
        u=1   
    elif len(s)%q==0:
        u=2
    else:
        u=3
    if u==1:
        print(n//p)
        k=cg(s,p)
        for i in k:
            print(i)
    elif u==2:
        print(n//q)
        k=cg(s,q)
        for i in k:
            print(i)
    elif u==3:
        flag=0
        for i in range(1,n):
            for j in range(1,n):
                if p*i+q*j==n:
                    op=[i,j]
                    flag=1
                    break
        if flag==1:
            
            print(sum(op))
            
            u=cg(s[0:p*op[0]],p)
            v=cg(s[p*op[0]:],q)
            ko=(u+v)
            for i in ko:
                print(i)
        else:
            print(-1)  
            
            
        
    
except:
    pass