The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include<stdio.h>
int main()
{
	int i,j,n;
	int a,b,t;
	int sum=0;
	scanf("%d",&n);
	for(i=1;i<=n;i++)
	{
		t=0;
		for(j=1;j<=i;j++)
		{
			if(i%j==0&&i%2==1)t++;
		}
		if(t==8)sum++;
	}
	printf("%d",sum);
	return 0;
}