You are given a string S of length N consisting of lowercase English letters.

Process Q queries of the following two types:

* Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)
* Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).

Constraints

* N, Q, i_q, l_q, and r_q are integers.
* S is a string consisting of lowercase English letters.
* c_q is a lowercase English letter.
* 1 \leq N \leq 500000
* 1 \leq Q \leq 20000
* |S| = N
* 1 \leq i_q \leq N
* 1 \leq l_q \leq r_q \leq N
* There is at least one query of type 2 in each testcase.

Input

Input is given from Standard Input in the following format:


N
S
Q
Query_1
\vdots
Query_Q


Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:


1 i_q c_q



2 l_q r_q


Output

For each query of type 2, print a line containing the answer.

Example

Input

7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7


Output

3
1
5
def segfunc(x,y):
  return set(x)|set(y)
ide_ele=set()
class SegTree():
  def __init__(self,init_val,segfunc,ide_ele):
    n=len(init_val)
    self.segfunc=segfunc
    self.ide_ele=ide_ele
    self.num=1<<(n-1).bit_length()
    self.tree=[ide_ele]*2*self.num
    for i in range(n):
      self.tree[self.num+i]=init_val[i]
    for i in range(self.num-1,0,-1):
      self.tree[i]=self.segfunc(self.tree[2*i], self.tree[2*i+1])
  def update(self,k,x):
    k+=self.num
    self.tree[k]=x
    while k>1:
      self.tree[k>>1]=self.segfunc(self.tree[k],self.tree[k^1])
      k>>=1
  def query(self,l,r):
    res=self.ide_ele
    l+=self.num
    r+=self.num
    while l<r:
      if l&1:
        res=self.segfunc(res,self.tree[l])
        l+=1
      if r&1:
        res=self.segfunc(res,self.tree[r-1])
      l>>=1
      r>>=1
    return res
n=int(input())
s=input()
q=int(input())
st=SegTree(s,segfunc,ide_ele)
for _ in range(q):
  q,c,r=input().split()
  if q=='1':st.update(int(c)-1,r)
  else:print(len(st.query(int(c)-1,int(r))))