The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include<stdio.h>
int main()
{
int n,i,j,l=0,m=0;
scanf("%d",&n);
for(i=1;i<=n;i++)
{
if(i%2!=0)
{
l=0;
for(j=1;j<=i;j++)
{
if(i%j==0)
{
l++;
}



}

if(l==8)
{

m++;

}




}





}
printf("%d\n",m);
return 0;

}
