The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include<bits/stdc++.h>
using namespace std;

int main(){
	int N;
    cin>>N;
    if(N<105)cout<<0;
    if(104<N&&N<135)cout<<1;
    if(134<N&&N<165)cout<<2;
    if(164<N&&N<189)cout<<3;
    if(188<N&&N<195)cout<<4;
    if(194<N)cout<<5;
}
