The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0

#include <bits/stdc++.h>
using namespace std;

int main() {
 int n;cin>>n;
  
  if(n<105)cout<<0<<endl;
  else if(n<135)cout<<1;
  else if(n<165)cout<<2;
  else if(n<189)cout<<3;
  else if(n<195)cout<<4;
  else cout<<5;
  
}