The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include<iostream>
using namespace std;

int main(){
	int n;
	cin>>n;

	int ans=0;

	int cd[5]= {105, 135, 165, 189, 195};

	for(int i=0; i<5; i++)
		if(n>= cd[i])
			ans++;

	cout<< ans<<endl;

	return 0;
}