The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include<bits/stdc++.h>
using namespace std;
int gs(int a)
{
	int p=0;
	for(int i=1;i<=a;i++)
	if(a%i==0)
	p++;
	return p;
}

int main()
{
	int a,b=0;
	cin>>a;
	for(int i=1;i<=a;i+=2)
	if(gs(i)==8) b++;
	cout<<b;
}