Alice and Bob are playing a game with n piles of stones. It is guaranteed that n is an even number. The i-th pile has a_i stones.

Alice and Bob will play a game alternating turns with Alice going first.

On a player's turn, they must choose exactly n/2 nonempty piles and independently remove a positive number of stones from each of the chosen piles. They can remove a different number of stones from the piles in a single turn. The first player unable to make a move loses (when there are less than n/2 nonempty piles).

Given the starting configuration, determine who will win the game.

Input

The first line contains one integer n (2 ≤ n ≤ 50) — the number of piles. It is guaranteed that n is an even number.

The second line contains n integers a_1, a_2, …, a_n (1 ≤ a_i ≤ 50) — the number of stones in the piles.

Output

Print a single string "Alice" if Alice wins; otherwise, print "Bob" (without double quotes).

Examples

Input


2
8 8


Output


Bob


Input


4
3 1 4 1


Output


Alice

Note

In the first example, each player can only remove stones from one pile (2/2=1). Alice loses, since Bob can copy whatever Alice does on the other pile, so Alice will run out of moves first.

In the second example, Alice can remove 2 stones from the first pile and 3 stones from the third pile on her first move to guarantee a win.
#include <bits/stdc++.h>
#pragma GCC optimize(2)
using namespace std;
const int maxn = 50;
const int INF = 0x7fffffff;
const int mod = 1e9 + 7;
const double eps = 1e-7;
const double Pi = acos(-1.0);
inline int read_int() {
  char c;
  int ret = 0, sgn = 1;
  do {
    c = getchar();
  } while ((c < '0' || c > '9') && c != '-');
  if (c == '-')
    sgn = -1;
  else
    ret = c - '0';
  while ((c = getchar()) >= '0' && c <= '9') ret = ret * 10 + (c - '0');
  return sgn * ret;
}
inline long long read_ll() {
  char c;
  long long ret = 0, sgn = 1;
  do {
    c = getchar();
  } while ((c < '0' || c > '9') && c != '-');
  if (c == '-')
    sgn = -1;
  else
    ret = c - '0';
  while ((c = getchar()) >= '0' && c <= '9') ret = ret * 10 + (c - '0');
  return sgn * ret;
}
int arr[maxn + 5], mn, cnt, n;
int main() {
  n = read_int();
  for (int i = 1; i <= n; ++i) arr[i] = read_int();
  sort(arr + 1, arr + 1 + n);
  mn = arr[1];
  for (int i = 1; i <= n; ++i)
    if (arr[i] == mn) ++cnt;
  if (cnt <= n / 2)
    cout << "Alice" << endl;
  else
    cout << "Bob" << endl;
  return 0;
}
