The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include<iostream>
using namespace std;

int main() {
	int n;
	cin >> n;
	int ans = 0;
	for (int i = 1;i <= n;i += 2) {
		int d = 0;
		for (int j = 1;j <= n;j++) {
			if (i%j == 0)d++;
		}
		if (d == 8)ans++;
	}
	cout << ans << endl;
}
