The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include<iostream>
using namespace std;
int main()
{int a;
cin>>a;
if(a<105)cout<<"0";
else if(a<135)cout<<"1"<<endl;
else if(a<165)cout<<"2"<<endl;
else if(a<189)cout<<"3"<<endl;
else if(a<195)cout<<"4"<<endl;
else cout<<"5"<<endl;
return 0;}