The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include <stdio.h>
int calc(int num)
{
 int cnt=0;
 for(int i=1;i<=num;i++)
  if(num%i==0)cnt++;
 return cnt;
}
int main()
{
 int n,ans=0;
 scanf("%d",&n);
 for(int i=1;i<=n;i+=2)
  if(calc(i)==8)ans++;
 printf("%d",ans);
 return 0;
}