The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include<cstdio>
using namespace std;
int n;
int main()
{
	scanf("%d",&n);int ans=0;
	for(int i=1;i<=n;i+=2) {int cnt=0;for(int j=1;j<=i;++j) if(!(i%j)) ++cnt;if(cnt==8) ++ans;}
	printf("%d\n",ans);
	return 0;
}