You are given a string S of length N consisting of lowercase English letters.

Process Q queries of the following two types:

* Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)
* Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).

Constraints

* N, Q, i_q, l_q, and r_q are integers.
* S is a string consisting of lowercase English letters.
* c_q is a lowercase English letter.
* 1 \leq N \leq 500000
* 1 \leq Q \leq 20000
* |S| = N
* 1 \leq i_q \leq N
* 1 \leq l_q \leq r_q \leq N
* There is at least one query of type 2 in each testcase.

Input

Input is given from Standard Input in the following format:


N
S
Q
Query_1
\vdots
Query_Q


Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:


1 i_q c_q



2 l_q r_q


Output

For each query of type 2, print a line containing the answer.

Example

Input

7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7


Output

3
1
5
def main():
  import sys
  input=sys.stdin.buffer.readline
  n=int(input())+1
  data=[[0]*n*2for _ in range(26)]
  def update(i,x):
    i+=n
    for d in data:
      j=i
      if d[j]:
        d[j]=0
        j//=2
        while j:
          d[j]=d[j+j]|d[j-~j]
          j//=2
        break
    d=data[x]
    d[i]=1
    i//=2
    while i:
      d[i]=d[i+i]|d[i-~i]
      i//=2
  def query(l,r):
    l+=n
    r+=n
    s=[0]*26
    while l<r:
      if l&1:
        for i,d in enumerate(data):
          s[i]|=d[l]
        l+=1
      if r&1:
        r-=1
        for i,d in enumerate(data):
          s[i]|=d[r]
      l//=2
      r//=2
    return sum(s)
  for i,c in enumerate(input()[:-1]):
    update(i,c-97)
  s=[]
  for _ in range(int(input())):
    q,a,b=input().split()
    if q[0]>49:
      s+=query(int(a)-1,int(b)),
    else:
      update(int(a)-1,b[0]-97)
  print('\n'.join(map(str,s)))
main()