You are given a string S of length N consisting of lowercase English letters.

Process Q queries of the following two types:

* Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)
* Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).

Constraints

* N, Q, i_q, l_q, and r_q are integers.
* S is a string consisting of lowercase English letters.
* c_q is a lowercase English letter.
* 1 \leq N \leq 500000
* 1 \leq Q \leq 20000
* |S| = N
* 1 \leq i_q \leq N
* 1 \leq l_q \leq r_q \leq N
* There is at least one query of type 2 in each testcase.

Input

Input is given from Standard Input in the following format:


N
S
Q
Query_1
\vdots
Query_Q


Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:


1 i_q c_q



2 l_q r_q


Output

For each query of type 2, print a line containing the answer.

Example

Input

7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7


Output

3
1
5
import bisect

n = int(input())
s = list(input())
q = int(input())

alpha_map = {chr(i):[] for i in range(97,123)}
for i,c in enumerate(s):
    bisect.insort(alpha_map[c],i+1)
    
for _ in range(q):
    x,y,z = map(str,input().split())
    if int(x) == 1:
        y = int(y)
        bef = s[y-1]
        if bef == z:
            continue
        alpha_map[bef].pop(bisect.bisect_left(alpha_map[bef],y))
        bisect.insort(alpha_map[z],y)
        s[y-1] = z
    else:
        count = 0
        for i,j in alpha_map.items():
            idx = bisect.bisect_left(j,int(y))
            if idx < len(j) and j[idx] <= int(z):
                    count += 1
        print(count)