The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include <cstdio>

int solve(int n) {
    return (n < 105) ? 0 : (n < 135) ? 1 : (n < 165) ? 2 : (n < 189) ? 3 : (n < 195) ? 4 : 5;
}

int main() {
    int n;
    scanf("%d", &n);
    printf("%d\n", solve(n));
    return 0;
}
