There is an infinitely long street that runs west to east, which we consider as a number line.

There are N roadworks scheduled on this street. The i-th roadwork blocks the point at coordinate X_i from time S_i - 0.5 to time T_i - 0.5.

Q people are standing at coordinate 0. The i-th person will start the coordinate 0 at time D_i, continue to walk with speed 1 in the positive direction and stop walking when reaching a blocked point.

Find the distance each of the Q people will walk.

Constraints

* All values in input are integers.
* 1 \leq N, Q \leq 2 \times 10^5
* 0 \leq S_i < T_i \leq 10^9
* 1 \leq X_i \leq 10^9
* 0 \leq D_1 < D_2 < ... < D_Q \leq 10^9
* If i \neq j and X_i = X_j, the intervals [S_i, T_i) and [S_j, T_j) do not overlap.

Input

Input is given from Standard Input in the following format:


N Q
S_1 T_1 X_1
:
S_N T_N X_N
D_1
:
D_Q


Output

Print Q lines. The i-th line should contain the distance the i-th person will walk or -1 if that person walks forever.

Example

Input

4 6
1 3 2
7 13 10
18 20 13
3 4 2
0
1
2
3
5
8


Output

2
2
10
-1
13
-1
import heapq
def main():
    N, Q = map(int, input().split())
    l = []
    for _ in range(N):
        s, t, x = map(int, input().split())
        l.append((s-x, 1, x))
        l.append((t-x, 0, x))
    for i in range(Q):
        d = int(input())
        l.append((d, 2, i))
    r = [-1] * Q
    l.sort()
    h = []
    se = set()
    for a, b, c in l:
        if b == 0:
            se.remove(c)
        elif b == 1:
            se.add(c)
            heapq.heappush(h, c)
        else:
            while h and h[0] not in se:
                heapq.heappop(h)
            r[c] = h[0] if h else -1
    print('\n'.join(map(str, r)))
            
main()
