You're given an array a of length 2n. Is it possible to reorder it in such way so that the sum of the first n elements isn't equal to the sum of the last n elements?

Input

The first line contains an integer n (1 ≤ n ≤ 1000), where 2n is the number of elements in the array a.

The second line contains 2n space-separated integers a_1, a_2, …, a_{2n} (1 ≤ a_i ≤ 10^6) — the elements of the array a.

Output

If there's no solution, print "-1" (without quotes). Otherwise, print a single line containing 2n space-separated integers. They must form a reordering of a. You are allowed to not change the order.

Examples

Input


3
1 2 2 1 3 1


Output


2 1 3 1 1 2

Input


1
1 1


Output


-1

Note

In the first example, the first n elements have sum 2+1+3=6 while the last n elements have sum 1+1+2=4. The sums aren't equal.

In the second example, there's no solution.
# coding: UTF-8
import sys
#sys.setrecursionlimit(n)
import heapq
import re
import bisect
import random
import math
import itertools
from collections import defaultdict, deque
from copy import deepcopy
from decimal import *

readl= lambda: list(map(int, sys.stdin.readline().split()))
readt= lambda: tuple(map(int, sys.stdin.readline().split()))
read = lambda: sys.stdin.readline().rstrip()
readi = lambda: int(read())
readmi = lambda: map(int, sys.stdin.readline().split())
readms = lambda: map(str, sys.stdin.readline().split())

n = readi()
s = readl()
s.sort()
a = 0
for i in range(n):
    a += s[i]
b = 0
for i in range(n, 2 * n):
    b += s[i]
if a != b:
    for i in s:
        print(i,end=" ")
    print("")
else:
    print(-1)

