Snuke, who loves animals, built a zoo.

There are N animals in this zoo. They are conveniently numbered 1 through N, and arranged in a circle. The animal numbered i (2≤i≤N-1) is adjacent to the animals numbered i-1 and i+1. Also, the animal numbered 1 is adjacent to the animals numbered 2 and N, and the animal numbered N is adjacent to the animals numbered N-1 and 1.

There are two kinds of animals in this zoo: honest sheep that only speak the truth, and lying wolves that only tell lies.

Snuke cannot tell the difference between these two species, and asked each animal the following question: "Are your neighbors of the same species?" The animal numbered i answered s_i. Here, if s_i is `o`, the animal said that the two neighboring animals are of the same species, and if s_i is `x`, the animal said that the two neighboring animals are of different species.

More formally, a sheep answered `o` if the two neighboring animals are both sheep or both wolves, and answered `x` otherwise. Similarly, a wolf answered `x` if the two neighboring animals are both sheep or both wolves, and answered `o` otherwise.

Snuke is wondering whether there is a valid assignment of species to the animals that is consistent with these responses. If there is such an assignment, show one such assignment. Otherwise, print `-1`.

Constraints

* 3 ≤ N ≤ 10^{5}
* s is a string of length N consisting of `o` and `x`.

Input

The input is given from Standard Input in the following format:


N
s


Output

If there does not exist an valid assignment that is consistent with s, print `-1`. Otherwise, print an string t in the following format. The output is considered correct if the assignment described by t is consistent with s.

* t is a string of length N consisting of `S` and `W`.
* If t_i is `S`, it indicates that the animal numbered i is a sheep. If t_i is `W`, it indicates that the animal numbered i is a wolf.

Examples

Input

6
ooxoox


Output

SSSWWS


Input

3
oox


Output

-1


Input

10
oxooxoxoox


Output

SSWWSSSWWS
#include <iostream>
#include <vector>

using namespace std;

int main(void) {
	int N;
	cin >> N;
	vector<int> res(N),sign(N);
	for (int i = 0; i < N; ++i) {
		char c;
		cin >> c;
		if (c == 'o') {
			sign[i] = 1;
		}
		else {
			sign[i] = -1;
		}
	}
	bool find = false;
	for (int fv = 0; !find && fv < 2; ++fv) {
		res[0] = 1 - (2*fv);
		for (int sv = 0; !find && sv < 2; ++sv) {
			res[1] = 1 - (2*sv);
			for (int i = 1; i < N-1; ++i) {
				res[i+1] = res[i]*sign[i]*res[i-1];
			}
			if ((res[0] == res[N-1]*sign[N-1]*res[N-2])&&(res[1] == res[0]*sign[0]*res[N-1])) {
				for (int i = 0; i < N; ++i) {
					if (res[i] > 0) {
						cout << "S";
					}
					else {
						cout << "W";
					}
				}
				cout << endl;
				find = true;
			}
		}
	}
	if (!find) {
		cout << -1 << endl;
	}
	return 0;
}

