The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include <bits/stdc++.h>
using namespace std;
int main(void){
  int N;
  cin >> N;
  int list[5]={135,189,165,105,195};
  sort(list,list+5);
  int i;
  for(i=0;i<5;i++){
    if(N<list[i]) break;
  }
  cout<<i;
}
