The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include <iostream>
using namespace std;

int main() {
	int a,b;
	cin>>a;
	if(a<105)b=0;
	else if(a<135)b=1;
	else if(a<165)b=2;
	else if(a<189)b=3;
	else if(a<195)b=4;
	else b=5;
	cout<<b<<endl;
	return 0;
}
