There is an infinitely long street that runs west to east, which we consider as a number line.

There are N roadworks scheduled on this street. The i-th roadwork blocks the point at coordinate X_i from time S_i - 0.5 to time T_i - 0.5.

Q people are standing at coordinate 0. The i-th person will start the coordinate 0 at time D_i, continue to walk with speed 1 in the positive direction and stop walking when reaching a blocked point.

Find the distance each of the Q people will walk.

Constraints

* All values in input are integers.
* 1 \leq N, Q \leq 2 \times 10^5
* 0 \leq S_i < T_i \leq 10^9
* 1 \leq X_i \leq 10^9
* 0 \leq D_1 < D_2 < ... < D_Q \leq 10^9
* If i \neq j and X_i = X_j, the intervals [S_i, T_i) and [S_j, T_j) do not overlap.

Input

Input is given from Standard Input in the following format:


N Q
S_1 T_1 X_1
:
S_N T_N X_N
D_1
:
D_Q


Output

Print Q lines. The i-th line should contain the distance the i-th person will walk or -1 if that person walks forever.

Example

Input

4 6
1 3 2
7 13 10
18 20 13
3 4 2
0
1
2
3
5
8


Output

2
2
10
-1
13
-1
import sys
from bisect import bisect_left
input = sys.stdin.readline

N,Q = map(int, input().split())
STX = [list(map(int, input().split())) for _ in range(N)]
D = [int(input()) for _ in range(Q)]

STX = sorted(STX, key=lambda x: x[2])

MASK = [-1]*Q
ANS = [-1]*Q

for (s,t,x) in STX:
  s2 = (s - x)
  t2 = (t - x)

  start = bisect_left(D, s2)
  end = bisect_left(D, t2, lo=start)

  #print(start, end, DI)
  while (start < end):
    if (-1 == MASK[start]):
      ANS[start] = x
      MASK[start] = end
      start += 1
    else:
      start = MASK[start]


print(*ANS, sep='\n')
