The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include <stdio.h>
int main(){
int n,ans=0,cnt;
scanf("%d",&n);
for(int i=1;i<=n;i+=2){
cnt=0;
for(int j=1;j<=i;j++)if(i%j==0)cnt++;
if(cnt==8)ans++;
}
printf("%d\n",ans);
}