The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include<bits/stdc++.h>
using namespace std;
int main(){
    int n;
    cin >> n;
    int ans = 0;
    int cand[] = {105,135,165,189,195};
    for(int i = 0;i < 5;i++)ans += (n >= cand[i]);
    cout << ans << endl;
}