How many strings can be obtained by applying the following operation on a string S exactly K times: "choose one lowercase English letter and insert it somewhere"?

The answer can be enormous, so print it modulo (10^9+7).

Constraints

* K is an integer between 1 and 10^6 (inclusive).
* S is a string of length between 1 and 10^6 (inclusive) consisting of lowercase English letters.

Input

Input is given from Standard Input in the following format:


K
S


Output

Print the number of strings satisfying the condition, modulo (10^9+7).

Examples

Input

5
oof


Output

575111451


Input

37564
whydidyoudesertme


Output

318008117
#include<stdio.h>
#pragma GCC target("avx")
#pragma GCC optimize("O3")
typedef long long lint;
const int mod=1000000007;
int k,n=-1,cnt=13;
char c[15];
lint fact[2000010],inv[2000010];
int main(){
	while(true){
		*c=getchar_unlocked();
		if(*c=='\n')break;
		k*=10;
		k+=*c-'0';
	}
	while(getchar_unlocked()!=-1)n++;
	fact[0]=1;
	for(int i=1;i<=n+k;i++)fact[i]=fact[i-1]*i%mod;
	inv[n+k]=1;
	lint now=fact[n+k];
	int b=mod-2;
	while(b){
		if(b&1){
			inv[n+k]*=now;
			inv[n+k]%=mod;
		}
		b>>=1;
		now*=now;
		now%=mod;
	}
	for(int i=n+k-1;i>=0;i--)inv[i]=inv[i+1]*(i+1)%mod;
	lint ans=1;now=1;
	for(int i=1;i<=k;i++){
		now*=25;
		now%=mod;
		ans+=fact[n+k]*inv[n+k-i]%mod*inv[i]%mod*now;
		ans%=mod;
	}
	*(c+14)='\n';
	while(ans){
		*(c+cnt)=ans%10+'0';
		ans/=10;
		cnt--;
	}
	fwrite(c+cnt+1,1,14-cnt,stdout);
	return 0;
}