Today, you have been given the task of handling the entire Taxi Network of Berland City. Berland city has a huge number of taxi travellers, and you need to help them in transportation in the most efficient manner. 

To be precise, this city consists of N users who want to travel via a Taxi today. You have a total of M taxis and need to cater to the users using these taxis. Each user has two parameters associated with them, S_{i} and J_{i}, denoting the time at which a user requests a taxi and the travel time required to reach the destination of this particular user. Each taxi can be used by a maximum of 1 user at each point in time.

If, at any point in time a user requests a taxi and all M taxis are busy, then this user's request is rejected. If multiple taxis are available at the time of the request of a user, the taxi with the lowest index that is available is alloted to them. Now, you need to find for each user, the index of the taxi alloted to them. If a particular user's request is rejected, print "-1" (without quotes) for them. 

Note: For the purpose of the problem, we consider a user gets their taxi immediately if their request is accepted. The taxi's are enumerated from 1 to M. A taxi is considered to be free as soon as the previous user's journey ends. It is guaranteed that the request time of each user is unique.

Input Format:

The first line contains two integers N  and M denoting the number of users and the number of taxis respectively. Each of the next N lines contains 2 space separated integers S_{i} and  J_{i} denoting the request and journey time of the i^{th} user.   

Output Format:

For each user from 1 to N, print the index number of the taxi alloted to them. If a user's request is rejected , print "-1"(without quotes)  for them. 

Constraints:

 1 ≤ N ≤ 10^5 

 1 ≤ M ≤ 100 

 1 ≤ S_{i} ,J_{i} ≤ 10^9   

SAMPLE INPUT
5 5
1 100
2 100
3 100
4 100
5 100

SAMPLE OUTPUT
1 2 3 4 5

Explanation

Here, user 1 is given taxi 1, user 2 is given taxi 2, user 3 is given taxi 3 and so on for user 4and 5.
from collections import defaultdict

n, m = map(int, raw_input().split(' '))

A = []
for i in range(n):
	s, j = map(int, raw_input().split(' '))
	A.append((s, s+j, i))

A.sort(key=lambda x: x[0])

alloted = {i:0 for i in range(1, m+1)}
# avail = defaultdict(int)
result = [-1] * n

for i in range(n):
	for j in alloted:
		if alloted[j] <= A[i][0]:
			result[A[i][2]] = j
			alloted[j] = A[i][1]
			break
			

# for i in range(n):
	# keys = [j for j in avail if j<=A[i][0]]
	# for k in keys:
	# 	alloted -= avail[k]
	# 	del avail[k]
	# if alloted < m:
	# 	alloted += 1
	# 	avail[A[i][1]] += 1 
	# 	result[A[i][2]] = alloted

print ' '.join(map(str, result))