The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include <bits/stdc++.h>
using namespace std;

int main(){
  int N;
  cin >> N;
  
  int x=0;
  for (int i=0 ; i<N ;i++){
    if (i+1==3*5*7 || i+1==3*3*3*5 || i+1==3*3*3*7 || i+1==3*5*11 || i+1==3*5*13)
      x++;
  }
  
  cout << x << endl;
}