The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include <bits/stdc++.h>
using namespace std;

int main() {
  int N,X,ans;
ans=0;
  X=0;
  cin >>N;
  for(int i=1;i<N+1;i++){
for(int j=1;j<i+1;j++){
if(i%j==0){
X++;
}
}
    if(X==8&&i%2==1){
ans++;
    }
    X=0;
}
  cout <<ans<< endl;
}