The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include<bits/stdc++.h>
using namespace std;
int main(){
  long N;cin>>N;long a=0;
  for(long i=1;i<=N;i+=2){
    long b=0;
    for(long j=1;j<=i;j++)if(i%j==0)b++;
    if(b==8)a++;
  }
  cout<<a<<endl;
  
}

