We have a tree with N vertices numbered 1 to N. The i-th edge in this tree connects Vertex a_i and b_i. For each k=1, ..., N, solve the problem below:

* Consider writing a number on each vertex in the tree in the following manner:
* First, write 1 on Vertex k.
* Then, for each of the numbers 2, ..., N in this order, write the number on the vertex chosen as follows:
* Choose a vertex that still does not have a number written on it and is adjacent to a vertex with a number already written on it. If there are multiple such vertices, choose one of them at random.
* Find the number of ways in which we can write the numbers on the vertices, modulo (10^9+7).

Constraints

* 2 \leq N \leq 2 \times 10^5
* 1 \leq a_i,b_i \leq N
* The given graph is a tree.

Input

Input is given from Standard Input in the following format:


N
a_1 b_1
:
a_{N-1} b_{N-1}


Output

For each k=1, 2, ..., N in this order, print a line containing the answer to the problem.

Examples

Input

3
1 2
1 3


Output

2
1
1


Input

2
1 2


Output

1
1


Input

5
1 2
2 3
3 4
3 5


Output

2
8
12
3
3


Input

8
1 2
2 3
3 4
3 5
3 6
6 7
6 8


Output

40
280
840
120
120
504
72
72

import sys
sys.setrecursionlimit(10**6)
input = sys.stdin.readline
mod = 10**9+7
 
fact = [1,1]
finv = [1,1]
inv = [0,1]
 
for i in range(2,2*10**5+5):
    fact.append((fact[-1]*i)%mod)
    inv.append((inv[mod%i]*(mod-mod//i))%mod)
    finv.append((finv[-1]*inv[-1])%mod)
 
def nCr(n,r,mod):
      
    return (fact[n]*finv[r])%mod*finv[n-r]%mod

n = int(input())
e = [[] for i in range(n)]
for i in range(n-1):
    a,b = map(int,input().split())
    e[a-1].append(b-1)
    e[b-1].append(a-1)

numl = [0]*n
resl = [0]*n
def dfs(x,pre):
    num = 0
    res = 1
    for nex in e[x]:
        if nex == pre:
            continue
        dfs(nex,x)
        num += numl[nex]
        res *= nCr(num,numl[nex],mod)*resl[nex]
        res %= mod
    numl[x] = num+1
    resl[x] = res

    return 

dfs(0,-1)

ans = [0]*n
ans[0] = resl[0]
def dfs2(x,pre):
    
    for nex in e[x]:
        if nex == pre:
            continue
        pres = [resl[x], numl[x], resl[nex], numl[nex]]
        resl[x] *= pow(nCr(numl[x]-1,numl[nex],mod)*resl[nex],mod-2,mod)
        resl[x] %= mod
        numl[x] -= numl[nex]
        resl[nex] *=  nCr(numl[x]+numl[nex]-1,numl[x],mod)*resl[x]
        resl[nex] %= mod
        numl[nex] += numl[x]
        ans[nex] = resl[nex]
        dfs2(nex,x)
        resl[x], numl[x], resl[nex], numl[nex] = pres
    return
dfs2(0,-1)
for i in ans:
    print(i)