The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include <bits/stdc++.h>
using namespace std;

int main() {
  int N;
  cin>>N;
  int Z=0;
  if(N>=105){
    Z++;
  }
  if(N>=135){
    Z++;
  }
  if(N>=165){
    Z++;
  }
  if(N>=189){
    Z++;
  }
  if(N>=195){
    Z++;
  }
  cout<<Z<<endl;
}
