The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include<bits/stdc++.h>
using namespace std;
int main()
{
int i,j,k,n,s=0,s1=0,x,y;
cin>>n;
for(i=1;i<=n;i+=2)
{
s=0;
for(j=1;j<=(i/2);j++)
{
if(i%j==0)
s++;
}
s++;
if(s==8)
s1++;
}
cout<<s1;
}