You are given a string S of length N consisting of lowercase English letters.

Process Q queries of the following two types:

* Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)
* Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).

Constraints

* N, Q, i_q, l_q, and r_q are integers.
* S is a string consisting of lowercase English letters.
* c_q is a lowercase English letter.
* 1 \leq N \leq 500000
* 1 \leq Q \leq 20000
* |S| = N
* 1 \leq i_q \leq N
* 1 \leq l_q \leq r_q \leq N
* There is at least one query of type 2 in each testcase.

Input

Input is given from Standard Input in the following format:


N
S
Q
Query_1
\vdots
Query_Q


Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:


1 i_q c_q



2 l_q r_q


Output

For each query of type 2, print a line containing the answer.

Example

Input

7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7


Output

3
1
5
import sys
import bisect
n = int(sys.stdin.readline().strip())
s = list(sys.stdin.readline().strip())
alpha = "abcdefghijklmnopqrstuvwxyz"
dict = {i:[] for i in alpha}
for i, _s in enumerate(s):
    dict[_s].append(i)
q = int(sys.stdin.readline().strip())
for i in range(q):
    type, first, last = [i for i in sys.stdin.readline().split()]
    if type == "2":
        first = int(first)
        last = int(last)
        first -= 1
        last -= 1
        cnt = 0
        for ls in dict.values():
            if bisect.bisect_left(ls, first) != bisect.bisect_right(ls, last):
                cnt += 1
        print(cnt)
    else:
        first = int(first)
        first -= 1
        _s = s[first]
        if _s == last:
            continue
        del dict[_s][(bisect.bisect_left(dict[_s], first))]
        s[first] = last
        bisect.insort_left(dict[last], first)