You are given a string S of length N consisting of lowercase English letters.

Process Q queries of the following two types:

* Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)
* Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).

Constraints

* N, Q, i_q, l_q, and r_q are integers.
* S is a string consisting of lowercase English letters.
* c_q is a lowercase English letter.
* 1 \leq N \leq 500000
* 1 \leq Q \leq 20000
* |S| = N
* 1 \leq i_q \leq N
* 1 \leq l_q \leq r_q \leq N
* There is at least one query of type 2 in each testcase.

Input

Input is given from Standard Input in the following format:


N
S
Q
Query_1
\vdots
Query_Q


Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:


1 i_q c_q



2 l_q r_q


Output

For each query of type 2, print a line containing the answer.

Example

Input

7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7


Output

3
1
5
f=input
n,s,q=int(f()),list(f()),int(f())
d={chr(97+i):[] for i in range(26)}
for i in range(n):
  d[s[i]]+=[i]
from bisect import *
for i in range(q):
  a,b,c=f().split()
  b=int(b)-1
  if a=='1':
    if s[b]==c: continue
    d[s[b]].pop(bisect(d[s[b]],b)-1)
    s[b]=c
    insort(d[c],b)
  else:
    t=0
    for l in d.values():
      m=bisect(l,b-1)
      if m<len(l) and l[m]<int(c): t+=1
    print(t)