In Omkar's last class of math, he learned about the least common multiple, or LCM. LCM(a, b) is the smallest positive integer x which is divisible by both a and b.

Omkar, having a laudably curious mind, immediately thought of a problem involving the LCM operation: given an integer n, find positive integers a and b such that a + b = n and LCM(a, b) is the minimum value possible.

Can you help Omkar solve his ludicrously challenging math problem?

Input

Each test contains multiple test cases. The first line contains the number of test cases t (1 ≤ t ≤ 10). Description of the test cases follows.

Each test case consists of a single integer n (2 ≤ n ≤ 10^{9}).

Output

For each test case, output two positive integers a and b, such that a + b = n and LCM(a, b) is the minimum possible.

Example

Input


3
4
6
9


Output


2 2
3 3
3 6

Note

For the first test case, the numbers we can choose are 1, 3 or 2, 2. LCM(1, 3) = 3 and LCM(2, 2) = 2, so we output 2 \ 2.

For the second test case, the numbers we can choose are 1, 5, 2, 4, or 3, 3. LCM(1, 5) = 5, LCM(2, 4) = 4, and LCM(3, 3) = 3, so we output 3 \ 3.

For the third test case, LCM(3, 6) = 6. It can be shown that there are no other pairs of numbers which sum to 9 that have a lower LCM.
// package june2020;

import java.util.*;
import java.lang.*;
import java.math.*;
import java.io.*;

public class cf_subs {
	static FastReader scn = new FastReader();
	static OutputStream out = new BufferedOutputStream(System.out);
//	@SuppressWarnings("unchecked")
	public static void main(String[] args) throws IOException {
		// TODO Auto-generated method stub
		int t = scn.nextInt();
		Here:
		while(t-->0) {
			int n =scn.nextInt();
			if(n%2==0) {
				out.write((n/2+" "+(n/2)+"\n").getBytes());
			}else {
				int sf = 1;
				for(int i=2;i*i<=n;i++) {
					if(n%i==0&&(n-i)%i==0) {
						sf=i;
						break;
					}
				}
				if(sf==1) {
					out.write(("1 "+(n-1)+"\n").getBytes());
					continue Here;
				}
				int q = n/sf;
				out.write((q+" "+(n-q)+"\n").getBytes());
			}
		}
		out.close();
	}
	static int lcm(int a, int b) 
    { 
        return (a*b)/gcd(a, b); 
    } 
	static int gcd(int a, int b) 
    { 
    if (a == 0) 
        return b;  
    return gcd(b % a, a);  
    }
	public static int[] merge(int[] one,int[] two){
		int[] res = new int[one.length+two.length];
		int i = 0;
		int j = 0;
		int k = 0;
		
		while(i<one.length&&j<two.length){
			if(one[i]<two[j]){
				res[k] = one[i];
				i++;
				k++;
			}
			else{
				res[k] = two[j];
				j++;
				k++;
			}
		}
		
		if(i==one.length){
			while(j<two.length){
				res[k] = two[j];
				j++;
				k++;
			}
		}
		else{
			while(i<one.length){
				res[k] = one[i];
				k++;
				i++;
			}
		}
		return res;
	}
	public static int[] mergesort(int[] arr, int l, int r){
		if(l==r){
			int[] br = new int[1];
			br[0] = arr[l];
			return br;
		}
		int mid = (l+r)/2;
		int[] fh = mergesort(arr,l,mid);
		int[] sh = mergesort(arr,mid+1,r);
		
		return merge(fh,sh);
	}
//	static int dfs(int idx) {
//		
//	}
	static <T> int upperBound(List<T> ls, T x) throws RuntimeException {
		if (ls.size() == 0)
			return -1;
		if (ls.get(0) instanceof Integer) {
			return ~Collections.binarySearch(ls, x, (t1, t2) -> ((Integer) t1).compareTo((Integer) t2) > 0 ? 1 : -1);
		} else if (ls.get(0) instanceof Long) {
			return ~Collections.binarySearch(ls, x, (t1, t2) -> ((Long) t1).compareTo((Long) t2) > 0 ? 1 : -1);
		} else if (ls.get(0) instanceof Double) {
			return ~Collections.binarySearch(ls, x, (t1, t2) -> ((Double) t1).compareTo((Double) t2) > 0 ? 1 : -1);
		} else {
			System.err.println(
					String.format("%s:Arey Maa chudi padi hai", Thread.currentThread().getStackTrace()[1].getMethodName()));
			throw new RuntimeException();
		}
	}
	static class FastReader 
    { 
        BufferedReader br; 
        StringTokenizer st; 
  
        public FastReader() 
        { 
            br = new BufferedReader(new
                     InputStreamReader(System.in)); 
        } 
  
        String next() 
        { 
            while (st == null || !st.hasMoreElements()) 
            { 
                try
                { 
                    st = new StringTokenizer(br.readLine()); 
                } 
                catch (IOException  e) 
                { 
                    e.printStackTrace(); 
                } 
            } 
            return st.nextToken(); 
        } 
  
        int nextInt() 
        { 
            return Integer.parseInt(next()); 
        } 
  
        long nextLong() 
        { 
            return Long.parseLong(next()); 
        } 
  
        double nextDouble() 
        { 
            return Double.parseDouble(next()); 
        } 
  
        String nextLine() 
        { 
            String str = ""; 
            try
            { 
                str = br.readLine(); 
            } 
            catch (IOException e) 
            { 
                e.printStackTrace(); 
            } 
            return str; 
        } 
    }

}
