You're given an array a of length 2n. Is it possible to reorder it in such way so that the sum of the first n elements isn't equal to the sum of the last n elements?

Input

The first line contains an integer n (1 ≤ n ≤ 1000), where 2n is the number of elements in the array a.

The second line contains 2n space-separated integers a_1, a_2, …, a_{2n} (1 ≤ a_i ≤ 10^6) — the elements of the array a.

Output

If there's no solution, print "-1" (without quotes). Otherwise, print a single line containing 2n space-separated integers. They must form a reordering of a. You are allowed to not change the order.

Examples

Input


3
1 2 2 1 3 1


Output


2 1 3 1 1 2

Input


1
1 1


Output


-1

Note

In the first example, the first n elements have sum 2+1+3=6 while the last n elements have sum 1+1+2=4. The sums aren't equal.

In the second example, there's no solution.
import java.util.*;
public class EhabFailsTobeThanos {

	public static void main(String[] args) {
		Scanner sc=new Scanner(System.in);
		int n=sc.nextInt();int a[]=new int[2*n];for(int i=0;i<2*n;i++)a[i]=sc.nextInt();
		Arrays.sort(a);
		long sum1=0,sum2=0;
		for(int i=0;i<2*n;i++) {
			if(i<n)sum1+=a[i];
			else if(i>n-1)sum2+=a[i];
		}
		if(sum1!=sum2) {
			for(int e:a)System.out.print(e+" ");
		}else System.out.println(-1);

	}

}
