You are given the string s of length n and the numbers p, q. Split the string s to pieces of length p and q.

For example, the string "Hello" for p = 2, q = 3 can be split to the two strings "Hel" and "lo" or to the two strings "He" and "llo".

Note it is allowed to split the string s to the strings only of length p or to the strings only of length q (see the second sample test).

Input

The first line contains three positive integers n, p, q (1 ≤ p, q ≤ n ≤ 100).

The second line contains the string s consists of lowercase and uppercase latin letters and digits.

Output

If it's impossible to split the string s to the strings of length p and q print the only number "-1".

Otherwise in the first line print integer k — the number of strings in partition of s.

Each of the next k lines should contain the strings in partition. Each string should be of the length p or q. The string should be in order of their appearing in string s — from left to right.

If there are several solutions print any of them.

Examples

Input

5 2 3
Hello


Output

2
He
llo


Input

10 9 5
Codeforces


Output

2
Codef
orces


Input

6 4 5
Privet


Output

-1


Input

8 1 1
abacabac


Output

8
a
b
a
c
a
b
a
c

def calc_splits(n, q, p):
    max_q = int(n/q) + 1
    max_p = int(n/p) + 1

    for k in range(0, max_q):
        value = q * k
        if (n - value) % p == 0:
            return (k, q, int((n - value) / p), p)

    for i in range(0, max_p):
        value = p * i
        if (n - value) % q == 0:
            return (k, p, int((n - value) / q), q)

    return -1

if __name__ == "__main__":



    _in = input()
    n, p, q = _in.split(" ")
    n, p, q = int(n), int(p), int(q)

    string = input()
    value = calc_splits(n, p, q)

    if value == -1:
        print(-1)
    else:
        k1, v1, k2, v2 = value
        print(k1 + k2)
        #print(value)
        counter = 0
        for i in range(1, k1 + k2 + 1):
            if i <= k1:
                print(string[counter: counter + v1])
                counter += v1
            else:
                print(string[counter : counter + v2])
                counter += v2

