Petya loves lucky numbers. We all know that lucky numbers are the positive integers whose decimal representations contain only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.

Petya wonders eagerly what minimum lucky number has the sum of digits equal to n. Help him cope with the task.

Input

The single line contains an integer n (1 ≤ n ≤ 106) — the sum of digits of the required lucky number.

Output

Print on the single line the result — the minimum lucky number, whose sum of digits equals n. If such number does not exist, print -1.

Examples

Input

11


Output

47


Input

10


Output

-1
import java.util.*;
import java.math.*;
import java.io.*;
public class Main {
    public static StringTokenizer st;
    public static BufferedReader scan;
    public static PrintWriter out;
    public static void main(String[] args) throws  IOException{
        scan = new BufferedReader(new InputStreamReader(System.in));
        out = new PrintWriter(new BufferedWriter(new OutputStreamWriter(System.out)));
        int n = nextInt();
        int _4 = -1, _7 = -1;
        for(int i = 0; i <= n; i++){
            if((n - 4 * i) % 7 == 0){
                _4 = i;
                break;
            }
        }
        _7 = (n - _4 * 4) / 7;
        if(_4 < 0 || _7 < 0){
           out.println(-1);
        }else{
            for(int i = 0; i < _4; i++)out.print(4);
            for(int i = 0; i < _7; i++)out.print(7);
            out.println();
        }
        out.close();
        scan.close();
    }

    public static BigDecimal nextBigDecimal() throws  IOException {
        return new BigDecimal(next());
    }
    public static BigInteger nextBigInteger() throws  IOException {
        return new BigInteger(next());
    }
    public static long nextLong() throws  IOException {
        return Long.parseLong(next());
    }
    public static double nextDouble() throws  IOException {
        return Double.parseDouble(next());
    }
    public static int nextInt() throws  IOException {
        return Integer.parseInt(next());
    }
    public static String next() throws IOException {
        while(st == null || !st.hasMoreTokens()){
            st = new StringTokenizer(scan.readLine());
        }
        return st.nextToken();
    }
}