Snuke, who loves animals, built a zoo.

There are N animals in this zoo. They are conveniently numbered 1 through N, and arranged in a circle. The animal numbered i (2≤i≤N-1) is adjacent to the animals numbered i-1 and i+1. Also, the animal numbered 1 is adjacent to the animals numbered 2 and N, and the animal numbered N is adjacent to the animals numbered N-1 and 1.

There are two kinds of animals in this zoo: honest sheep that only speak the truth, and lying wolves that only tell lies.

Snuke cannot tell the difference between these two species, and asked each animal the following question: "Are your neighbors of the same species?" The animal numbered i answered s_i. Here, if s_i is `o`, the animal said that the two neighboring animals are of the same species, and if s_i is `x`, the animal said that the two neighboring animals are of different species.

More formally, a sheep answered `o` if the two neighboring animals are both sheep or both wolves, and answered `x` otherwise. Similarly, a wolf answered `x` if the two neighboring animals are both sheep or both wolves, and answered `o` otherwise.

Snuke is wondering whether there is a valid assignment of species to the animals that is consistent with these responses. If there is such an assignment, show one such assignment. Otherwise, print `-1`.

Constraints

* 3 ≤ N ≤ 10^{5}
* s is a string of length N consisting of `o` and `x`.

Input

The input is given from Standard Input in the following format:


N
s


Output

If there does not exist an valid assignment that is consistent with s, print `-1`. Otherwise, print an string t in the following format. The output is considered correct if the assignment described by t is consistent with s.

* t is a string of length N consisting of `S` and `W`.
* If t_i is `S`, it indicates that the animal numbered i is a sheep. If t_i is `W`, it indicates that the animal numbered i is a wolf.

Examples

Input

6
ooxoox


Output

SSSWWS


Input

3
oox


Output

-1


Input

10
oxooxoxoox


Output

SSWWSSSWWS
#include <iostream>
#define FOR(i,a,b) for(int i=a;i<b;i++)
using namespace std;
int main(){
    int n;
    string s;
    cin>>n>>s;
    int a[100001]={0},b[100001]={0};
    int sum=0;
    FOR(i,0,n){
        a[i]=(s[i]=='o'?0:1);
        sum=(sum+a[i])%2;
    }
    if(n%3==0){
        b[0]=0; b[1]=0;
    }else{
        int t=(n%3==1?2:1);
        FOR(i,0,2){
            int k=0,j=i-t;
            while(j>=0){
                k=(k+a[j])%2;
                j-=3;
            }
            j=i+t;
            while(j<n){
                k=(k+a[j])%2;
                j+=3;
            }
            b[i]=(sum+k)%2;
        }
    }
    b[2]=(a[1]+b[0]+b[1])%2;
    FOR(i,3,n){
        b[i]=(b[i-3]+a[i-1]+a[i-2])%2;
    }
    if((b[n-2]+b[n-1]+b[0]+a[n-1])%2==0&&(b[n-1]+b[0]+b[1]+a[0])%2==0){
        FOR(i,0,n){
            cout<<(b[i]?"W":"S");
        }   
    }else{
        cout<<-1<<endl;
    }
    cout<<endl;
}
