The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include<stdio.h>
int main(){
    int c=0,n,l=0,i,j;
    scanf("%d",&n);
    for(i=105;i<=n;i+=2){
        l=0;
        for(j=3;j<i;j++){
            if(i%j==0) l++;
        }
        if(l==6) c++;
    }
    printf("%d\n",c);
    return 0;
}
