You are given a string S of length N consisting of lowercase English letters.

Process Q queries of the following two types:

* Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)
* Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).

Constraints

* N, Q, i_q, l_q, and r_q are integers.
* S is a string consisting of lowercase English letters.
* c_q is a lowercase English letter.
* 1 \leq N \leq 500000
* 1 \leq Q \leq 20000
* |S| = N
* 1 \leq i_q \leq N
* 1 \leq l_q \leq r_q \leq N
* There is at least one query of type 2 in each testcase.

Input

Input is given from Standard Input in the following format:


N
S
Q
Query_1
\vdots
Query_Q


Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:


1 i_q c_q



2 l_q r_q


Output

For each query of type 2, print a line containing the answer.

Example

Input

7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7


Output

3
1
5
from bisect import bisect_left,bisect_right
import string 

dic = {c:[] for c in string.ascii_lowercase}

n = int(input())
s = list(input())
q = int(input())

for i,c in enumerate(s,start=1):
  dic[c].append(i)
  
for i in range(q):
  p,l,r = map(str,input().split())
  if p =='1':
    j = int(l)
    if r == s[j-1]:
      continue
    c = s[j-1]    
    dic[c].pop(bisect_left(dic[c],j))
    dic[r].insert(bisect_left(dic[r],j),j)
    s[j-1] = r
  else:
    ans = 0
    l = int(l)
    r = int(r)
    for c in string.ascii_lowercase:
      pl = bisect_left(dic[c],l)
      if pl < len(dic[c]):
        if dic[c][pl] <= r:
          ans += 1
    print(ans)
