You are given a string S of length N consisting of lowercase English letters.

Process Q queries of the following two types:

* Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)
* Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).

Constraints

* N, Q, i_q, l_q, and r_q are integers.
* S is a string consisting of lowercase English letters.
* c_q is a lowercase English letter.
* 1 \leq N \leq 500000
* 1 \leq Q \leq 20000
* |S| = N
* 1 \leq i_q \leq N
* 1 \leq l_q \leq r_q \leq N
* There is at least one query of type 2 in each testcase.

Input

Input is given from Standard Input in the following format:


N
S
Q
Query_1
\vdots
Query_Q


Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:


1 i_q c_q



2 l_q r_q


Output

For each query of type 2, print a line containing the answer.

Example

Input

7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7


Output

3
1
5
#include<bits/stdc++.h>
using namespace std;
set<int>q[26];
int n,t,x,l,r,cnt,i,j,len;
string s;
char c;
int main(){
	cin>>n>>s;
	len=s.size();
	for(i=0;i<len;i++)q[s[i]-97].insert(i);
	cin>>n;
	while(n--){
		cin>>t;
		if(t==1){
			cin>>x>>c;
			x--;
			q[s[x]-97].erase(x);
			s[x]=c;
			q[c-97].insert(x);
		}
		else{
			cin>>l>>r;
			l--;r--;
			cnt=0;
			for(j=0;j<26;j++)if(*q[j].lower_bound(l)<=r&&q[j].lower_bound(l)!=q[j].end())cnt++;
			cout<<cnt<<endl;
		}
	}
}
