The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include <stdio.h>
int main(){
	int i,j,k=0,n,l;scanf("%d",&n);
	for(i=1;i<=n;i+=2){
	l=0;
	for(j=1;j<=i;j++){
	if(i%j==0)l++;
	}
	if(l==8)k++;
	}
	printf("%d",k);
	return 0;
}