You are given a string S of length N consisting of lowercase English letters.

Process Q queries of the following two types:

* Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)
* Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).

Constraints

* N, Q, i_q, l_q, and r_q are integers.
* S is a string consisting of lowercase English letters.
* c_q is a lowercase English letter.
* 1 \leq N \leq 500000
* 1 \leq Q \leq 20000
* |S| = N
* 1 \leq i_q \leq N
* 1 \leq l_q \leq r_q \leq N
* There is at least one query of type 2 in each testcase.

Input

Input is given from Standard Input in the following format:


N
S
Q
Query_1
\vdots
Query_Q


Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:


1 i_q c_q



2 l_q r_q


Output

For each query of type 2, print a line containing the answer.

Example

Input

7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7


Output

3
1
5
from bisect import bisect_left, insort_left
N = int(input())
S = [c for c in input()]
Q = int(input())
d = {i: [] for i in range(26)}
for i, c in enumerate(S):
    d[ord(c) - ord("a")].append(i)

# print(d)
for _ in range(Q):
    q = input().split()
    if int(q[0]) == 1:
        iq, cq = int(q[1]), q[2]
        iq -= 1
        if S[iq] == cq:
            continue
        else:
            idx = bisect_left(d[ord(S[iq]) - ord("a")], iq)
            d[ord(S[iq]) - ord("a")].pop(idx)
            S[iq] = cq
            insort_left(d[ord(cq) - ord("a")], iq)
    else:
        l, r = int(q[1]), int(q[2])
        l -= 1
        ans = 0
        for i in range(26):
            idx = bisect_left(d[i], l)
            if d[i] and l <= d[i][-1] and d[i][idx] < r:
                ans += 1
        print(ans)

