There is an infinitely long street that runs west to east, which we consider as a number line.

There are N roadworks scheduled on this street. The i-th roadwork blocks the point at coordinate X_i from time S_i - 0.5 to time T_i - 0.5.

Q people are standing at coordinate 0. The i-th person will start the coordinate 0 at time D_i, continue to walk with speed 1 in the positive direction and stop walking when reaching a blocked point.

Find the distance each of the Q people will walk.

Constraints

* All values in input are integers.
* 1 \leq N, Q \leq 2 \times 10^5
* 0 \leq S_i < T_i \leq 10^9
* 1 \leq X_i \leq 10^9
* 0 \leq D_1 < D_2 < ... < D_Q \leq 10^9
* If i \neq j and X_i = X_j, the intervals [S_i, T_i) and [S_j, T_j) do not overlap.

Input

Input is given from Standard Input in the following format:


N Q
S_1 T_1 X_1
:
S_N T_N X_N
D_1
:
D_Q


Output

Print Q lines. The i-th line should contain the distance the i-th person will walk or -1 if that person walks forever.

Example

Input

4 6
1 3 2
7 13 10
18 20 13
3 4 2
0
1
2
3
5
8


Output

2
2
10
-1
13
-1
def main():
    from bisect import bisect_left
    I=10**9+1
    n,q,*t=map(int,open(0).read().split())
    d=tuple(t[-q:])
    t=t[:-q]
    N0=2**(q-1).bit_length()
    data=[I]*2*N0
    for x,l,r in sorted(((x,bisect_left(d,s-x)+N0,bisect_left(d,t-x)+N0)for s,t,x in zip(t[::3],t[1::3],t[2::3])),reverse=1):
        while l<r:
            if r&1:
                r-=1
                data[r-1]=x
            if l&1:
                data[l-1]=x
                l+=1
            l//=2
            r//=2
    a=[]
    for k in range(N0-1,q+N0-1):
        s=I
        while~k:
            if data[k]<s:s=data[k]
            k=(k-1)//2
        a.append(-(s==I)or s)
    print('\n'.join(map(str,a)))
if __name__=='__main__':
    main()