You are given a string S of length N consisting of lowercase English letters.

Process Q queries of the following two types:

* Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)
* Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).

Constraints

* N, Q, i_q, l_q, and r_q are integers.
* S is a string consisting of lowercase English letters.
* c_q is a lowercase English letter.
* 1 \leq N \leq 500000
* 1 \leq Q \leq 20000
* |S| = N
* 1 \leq i_q \leq N
* 1 \leq l_q \leq r_q \leq N
* There is at least one query of type 2 in each testcase.

Input

Input is given from Standard Input in the following format:


N
S
Q
Query_1
\vdots
Query_Q


Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:


1 i_q c_q



2 l_q r_q


Output

For each query of type 2, print a line containing the answer.

Example

Input

7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7


Output

3
1
5
import bisect
n = int(input())
s = list(input())
alp = 'abcdefghijklmnopqrstuvwxyz'
cnt = {c: [] for c in alp}

for i, c in enumerate(s):
    cnt[c].append(i)

q = int(input())
for _ in range(q):
    t, x, y = input().split()
    ans = 0
    if t == '1':
        i, c = int(x) - 1, y
        if s[i] == c:
            continue
        a = bisect.bisect_left(cnt[s[i]], i)
        cnt[s[i]].pop(a)
        s[i] = c
        b = bisect.bisect_left(cnt[c], i)
        cnt[c].insert(b, i)
    else:
        l, r = int(x) - 1, int(y) - 1
        for c in alp:
            a = bisect.bisect_left(cnt[c], l)
            if a < len(cnt[c]) and cnt[c][a] <= r:
                ans += 1

        print(ans)