You are given a string S of length N consisting of lowercase English letters.

Process Q queries of the following two types:

* Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)
* Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).

Constraints

* N, Q, i_q, l_q, and r_q are integers.
* S is a string consisting of lowercase English letters.
* c_q is a lowercase English letter.
* 1 \leq N \leq 500000
* 1 \leq Q \leq 20000
* |S| = N
* 1 \leq i_q \leq N
* 1 \leq l_q \leq r_q \leq N
* There is at least one query of type 2 in each testcase.

Input

Input is given from Standard Input in the following format:


N
S
Q
Query_1
\vdots
Query_Q


Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:


1 i_q c_q



2 l_q r_q


Output

For each query of type 2, print a line containing the answer.

Example

Input

7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7


Output

3
1
5
from bisect import bisect_left, insort
def main():
    n = int(input())
    s = list(input().rstrip())
    q = int(input())
    ans = []
    al = [[] for _ in range(26)]
    for i, c in enumerate(s):
        al[ord(c) - ord("a")].append(i)
    for _ in range(q):
        x, y, z = map(str, input().rstrip().split())
        if x == "1":
            y = int(y) - 1
            if s[y] == z:
                continue
            p = bisect_left(al[ord(s[y])-ord("a")],y)
            al[ord(s[y])-ord("a")].pop(p)
            insort(al[ord(z)-ord("a")],y)
            s[y] = z
        else:
            y = int(y) - 1
            z = int(z)
            cnt = 0
            for i in range(26):
                index = bisect_left(al[i], y)
                if index < len(al[i]) and al[i][index] < z:
                    cnt += 1
            ans.append(cnt)
    for v in ans:
        print(v)

if __name__ == "__main__":
    main()