The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include<iostream>
using namespace std;
int main()
{
	int n;
	cin>>n;
	int ans=0;
	for(int i=1;i<=n;i++){
		int sum=0;
		if(i%2!=0){
		for(int j=1;j<=i;j++){
			if(i%j==0){
				sum++;
			}
		}
		if(sum==8){
			ans++;
		}
		}
	}
	cout<<ans;
}