We say that a odd number N is similar to 2017 when both N and (N+1)/2 are prime.

You are given Q queries.

In the i-th query, given two odd numbers l_i and r_i, find the number of odd numbers x similar to 2017 such that l_i ≤ x ≤ r_i.

Constraints

* 1≤Q≤10^5
* 1≤l_i≤r_i≤10^5
* l_i and r_i are odd.
* All input values are integers.

Input

Input is given from Standard Input in the following format:


Q
l_1 r_1
:
l_Q r_Q


Output

Print Q lines. The i-th line (1≤i≤Q) should contain the response to the i-th query.

Examples

Input

1
3 7


Output

2


Input

4
13 13
7 11
7 11
2017 2017


Output

1
0
0
1


Input

6
1 53
13 91
37 55
19 51
73 91
13 49


Output

4
4
1
1
1
2
#include <bits/stdc++.h>
using namespace std;
using ll = long long;

bool isprime(ll x) {
  if (x <= 1) return false;
  for (ll i = 2; i * i <= x; i++)
    if (x % i == 0) return false;
  return true;
}

int main() {
  const ll n = 2e5;
  vector<ll> s(n);
  for (ll i = 1; i < n; i++)
    s[i] = s[i - 1] + ((i & 1) && isprime(i) && isprime((i + 1) / 2));
  ll q;
  cin >> q;
  for (ll i = 0; i < q; i++) {
    ll l, r;
    cin >> l >> r;
    cout << s[r] - s[l - 1] << endl;
  }
  return 0;
}
