The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include<iostream>
using namespace std;
int main(){
	int n;cin>>n;
	if(n<105)cout<<0<<endl;
	else if(n<135)cout<<1<<endl;
	else if(n<165)cout<<2<<endl;
	else if(n<189)cout<<3<<endl;
	else if(n<195)cout<<4<<endl;
	else cout<<5<<endl;
}