Snuke, who loves animals, built a zoo.

There are N animals in this zoo. They are conveniently numbered 1 through N, and arranged in a circle. The animal numbered i (2≤i≤N-1) is adjacent to the animals numbered i-1 and i+1. Also, the animal numbered 1 is adjacent to the animals numbered 2 and N, and the animal numbered N is adjacent to the animals numbered N-1 and 1.

There are two kinds of animals in this zoo: honest sheep that only speak the truth, and lying wolves that only tell lies.

Snuke cannot tell the difference between these two species, and asked each animal the following question: "Are your neighbors of the same species?" The animal numbered i answered s_i. Here, if s_i is `o`, the animal said that the two neighboring animals are of the same species, and if s_i is `x`, the animal said that the two neighboring animals are of different species.

More formally, a sheep answered `o` if the two neighboring animals are both sheep or both wolves, and answered `x` otherwise. Similarly, a wolf answered `x` if the two neighboring animals are both sheep or both wolves, and answered `o` otherwise.

Snuke is wondering whether there is a valid assignment of species to the animals that is consistent with these responses. If there is such an assignment, show one such assignment. Otherwise, print `-1`.

Constraints

* 3 ≤ N ≤ 10^{5}
* s is a string of length N consisting of `o` and `x`.

Input

The input is given from Standard Input in the following format:


N
s


Output

If there does not exist an valid assignment that is consistent with s, print `-1`. Otherwise, print an string t in the following format. The output is considered correct if the assignment described by t is consistent with s.

* t is a string of length N consisting of `S` and `W`.
* If t_i is `S`, it indicates that the animal numbered i is a sheep. If t_i is `W`, it indicates that the animal numbered i is a wolf.

Examples

Input

6
ooxoox


Output

SSSWWS


Input

3
oox


Output

-1


Input

10
oxooxoxoox


Output

SSWWSSSWWS
#include <cstdio>
#include <iostream>
#include <vector>
using namespace std;

int x[4] = {1, 1, -1, -1};
int y[4] = {1, -1, 1, -1};
string c = "W_S";

int main(){
  int n; cin >> n;
  string ss; cin >> ss;
  vector<int> s;
  for (int i = 0; i < n; i++) {
    int k;
    if (ss[i] == 'o') k = 1;
    else k = -1;
    s.push_back(k);
  }

  for (int p = 0; p < 4; p++) {
    vector<int> v(n+1, 0);
    v[0] = x[p]; v[1] = y[p];
    for (int i = 1; i < n; i++) {
      v[i+1] = v[i-1] * v[i] * s[i];
    }
    if (v[n] == v[0] && v[n-1] == v[1] * v[0] * s[0]) {
      for (int i = 0; i < n; i++) {
        printf("%c", c[v[i]+1]);
      }
      printf("\n");
      return 0;
    }
  }
  printf("-1\n");
  return 0;
}
