You are given the string s of length n and the numbers p, q. Split the string s to pieces of length p and q.

For example, the string "Hello" for p = 2, q = 3 can be split to the two strings "Hel" and "lo" or to the two strings "He" and "llo".

Note it is allowed to split the string s to the strings only of length p or to the strings only of length q (see the second sample test).

Input

The first line contains three positive integers n, p, q (1 ≤ p, q ≤ n ≤ 100).

The second line contains the string s consists of lowercase and uppercase latin letters and digits.

Output

If it's impossible to split the string s to the strings of length p and q print the only number "-1".

Otherwise in the first line print integer k — the number of strings in partition of s.

Each of the next k lines should contain the strings in partition. Each string should be of the length p or q. The string should be in order of their appearing in string s — from left to right.

If there are several solutions print any of them.

Examples

Input

5 2 3
Hello


Output

2
He
llo


Input

10 9 5
Codeforces


Output

2
Codef
orces


Input

6 4 5
Privet


Output

-1


Input

8 1 1
abacabac


Output

8
a
b
a
c
a
b
a
c
#!usr/bin/python

import sys
import math

x = input().split()
length = int(x[0])
p = int(x[1])
q = int(x[2])
inStr = input()
outList = []

strlen = length
while strlen > 0:
    outList.append(min(p, q))
    strlen -= outList[-1]
    if strlen % max(p, q) == 0 and strlen > 0:
        while not strlen == 0:
            outList.append(max(p, q))
            strlen -= outList[-1]
    

if strlen != 0:
    strlen = length
    outList = []
    while strlen > 0:
        outList.append(max(p, q))
        strlen -= outList[-1]
        if strlen % min(p, q) == 0 and strlen > 0:
            while not strlen == 0:
                outList.append(min(p, q))
                strlen -= outList[-1]

if strlen != 0:
   print(-1)
   
else:
    print(len(outList))
    for i in outList:
        for count in range(strlen, strlen + i):
            print(inStr[count], end='', flush = True)
        strlen += i
        print()
            

