The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include <iostream>
using namespace std;
int main(){
	int a=0,n,b=0;
	cin >> n;
	for (int i=1;i<n+1;i++)
	{
	  if(i%2!=0){ 
		for(int j=1;j<i+1;j++){
		   if(i%j==0)a++;
		}
      }
		if(a==8)b++;
		a=0;
	}
	cout << b << endl;
}