The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include <bits/stdc++.h>
using namespace std;
 
int main() {
  int N,c=0;cin>>N;
  for(int i=1; i<=N; i++){
    int d=0;
    if(i%2==1){
    for(int j=i; j>0; j--){
      if(i%j==0)d++;
    }}
    if(d==8)c++;
  }  
  cout<<c<<endl;
}