You are given the string s of length n and the numbers p, q. Split the string s to pieces of length p and q.

For example, the string "Hello" for p = 2, q = 3 can be split to the two strings "Hel" and "lo" or to the two strings "He" and "llo".

Note it is allowed to split the string s to the strings only of length p or to the strings only of length q (see the second sample test).

Input

The first line contains three positive integers n, p, q (1 ≤ p, q ≤ n ≤ 100).

The second line contains the string s consists of lowercase and uppercase latin letters and digits.

Output

If it's impossible to split the string s to the strings of length p and q print the only number "-1".

Otherwise in the first line print integer k — the number of strings in partition of s.

Each of the next k lines should contain the strings in partition. Each string should be of the length p or q. The string should be in order of their appearing in string s — from left to right.

If there are several solutions print any of them.

Examples

Input

5 2 3
Hello


Output

2
He
llo


Input

10 9 5
Codeforces


Output

2
Codef
orces


Input

6 4 5
Privet


Output

-1


Input

8 1 1
abacabac


Output

8
a
b
a
c
a
b
a
c
n,p,q = raw_input().split()
n,p,q = int(n), int(p), int(q)
s = raw_input()
k=0
output = []
sPosition = 0

def textSplitter():
	global sPosition
	for i in range(n/p+1):
		for j in range(n/q+1):
			if(i*p+j*q == n):
				# print "i:",i,"j:",j
				if(i==0):
					for jj in range(1,j+1):
						temp = s[sPosition:jj*q]
						sPosition =jj*q
						if(temp != ''):
							output.append(temp)
					return
				elif(j==0):
					for ii in range(1,i+1):
						temp = s[sPosition:ii*p]
						sPosition =ii*p
						if(temp != ''):
							output.append(temp)
					return
				else:
					for ii in range(1,i+1):
						temp = s[sPosition:sPosition+p]
						sPosition =sPosition+p
						if(temp != ''):
							output.append(temp)
					for jj in range(1,j+1):
						temp = s[sPosition:sPosition+q]
						sPosition =sPosition+q
						if(temp != ''):
							output.append(temp)
					return

textSplitter()
if(len(output) == 0):
	print -1
else:
	print len(output)
	for x in output:
		print x



