There are n candies in a row, they are numbered from left to right from 1 to n. The size of the i-th candy is a_i.

Alice and Bob play an interesting and tasty game: they eat candy. Alice will eat candy from left to right, and Bob — from right to left. The game ends if all the candies are eaten.

The process consists of moves. During a move, the player eats one or more sweets from her/his side (Alice eats from the left, Bob — from the right).

Alice makes the first move. During the first move, she will eat 1 candy (its size is a_1). Then, each successive move the players alternate — that is, Bob makes the second move, then Alice, then again Bob and so on.

On each move, a player counts the total size of candies eaten during the current move. Once this number becomes strictly greater than the total size of candies eaten by the other player on their previous move, the current player stops eating and the move ends. In other words, on a move, a player eats the smallest possible number of candies such that the sum of the sizes of candies eaten on this move is strictly greater than the sum of the sizes of candies that the other player ate on the previous move. If there are not enough candies to make a move this way, then the player eats up all the remaining candies and the game ends.

For example, if n=11 and a=[3,1,4,1,5,9,2,6,5,3,5], then:

  * move 1: Alice eats one candy of size 3 and the sequence of candies becomes [1,4,1,5,9,2,6,5,3,5]. 
  * move 2: Alice ate 3 on the previous move, which means Bob must eat 4 or more. Bob eats one candy of size 5 and the sequence of candies becomes [1,4,1,5,9,2,6,5,3]. 
  * move 3: Bob ate 5 on the previous move, which means Alice must eat 6 or more. Alice eats three candies with the total size of 1+4+1=6 and the sequence of candies becomes [5,9,2,6,5,3]. 
  * move 4: Alice ate 6 on the previous move, which means Bob must eat 7 or more. Bob eats two candies with the total size of 3+5=8 and the sequence of candies becomes [5,9,2,6]. 
  * move 5: Bob ate 8 on the previous move, which means Alice must eat 9 or more. Alice eats two candies with the total size of 5+9=14 and the sequence of candies becomes [2,6]. 
  * move 6 (the last): Alice ate 14 on the previous move, which means Bob must eat 15 or more. It is impossible, so Bob eats the two remaining candies and the game ends. 



Print the number of moves in the game and two numbers:

  * a — the total size of all sweets eaten by Alice during the game; 
  * b — the total size of all sweets eaten by Bob during the game. 

Input

The first line contains an integer t (1 ≤ t ≤ 5000) — the number of test cases in the input. The following are descriptions of the t test cases.

Each test case consists of two lines. The first line contains an integer n (1 ≤ n ≤ 1000) — the number of candies. The second line contains a sequence of integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 1000) — the sizes of candies in the order they are arranged from left to right.

It is guaranteed that the sum of the values of n for all sets of input data in a test does not exceed 2⋅10^5.

Output

For each set of input data print three integers — the number of moves in the game and the required values a and b.

Example

Input


7
11
3 1 4 1 5 9 2 6 5 3 5
1
1000
3
1 1 1
13
1 2 3 4 5 6 7 8 9 10 11 12 13
2
2 1
6
1 1 1 1 1 1
7
1 1 1 1 1 1 1


Output


6 23 21
1 1000 0
2 1 2
6 45 46
2 2 1
3 4 2
4 4 3
// Utilities
import java.io.*;
import java.util.*;

public class Main {
	static int T;
	static int N;
	static Deque<Integer> dq;
	static int a, b, m;
	
	public static void main(String[] args) throws IOException {
		T = in.iscan();
		for (int t = 0; t < T; t++) {
			N = in.iscan(); dq = new ArrayDeque<Integer>();
			for (int i = 0; i < N; i++) dq.add(in.iscan());
			a = 0; b = 0; m = 0;
			boolean alice = true; int prevA = 0, prevB = 0;
			int sum;
			while (!dq.isEmpty()) {
				if (alice) {
					sum = 0;
					while (sum <= prevB && !dq.isEmpty()) sum += dq.pollFirst();
					prevA = sum; 
					a += sum;
				}
				else {
					sum = 0;
					while (sum <= prevA && !dq.isEmpty()) sum += dq.pollLast();
					prevB = sum;
					b += sum;
				}
				m++;
				alice = !alice;
			}
			out.println(m + " " + a + " " + b);
		}
		
		out.close();
	} 
	
	static INPUT in = new INPUT(System.in);
	static PrintWriter out = new PrintWriter(System.out);
	private static class INPUT {

		private InputStream stream;
		private byte[] buf = new byte[1024];
		private int curChar, numChars;

		public INPUT (InputStream stream) {
			this.stream = stream;
		}

		public INPUT (String file) throws IOException {
			this.stream = new FileInputStream (file);
		}

		public int cscan () throws IOException {
			if (curChar >= numChars) {
				curChar = 0;
				numChars = stream.read (buf);
			}
			
			if (numChars == -1)
				return numChars;

			return buf[curChar++];
		}

		public int iscan () throws IOException {
			int c = cscan (), sgn = 1;
			
			while (space (c))
				c = cscan ();

			if (c == '-') {
				sgn = -1;
				c = cscan ();
			}

			int res = 0;

			do {
				res = (res << 1) + (res << 3);
				res += c - '0';
				c = cscan ();
			}
			while (!space (c));

			return res * sgn;
		}

		public String sscan () throws IOException {
			int c = cscan ();
			
			while (space (c))
				c = cscan ();

			StringBuilder res = new StringBuilder ();

			do {
				res.appendCodePoint (c);
				c = cscan ();
			}
			while (!space (c));

			return res.toString ();
		}

		public double dscan () throws IOException {
			int c = cscan (), sgn = 1;
			
			while (space (c))
				c = cscan ();

			if (c == '-') {
				sgn = -1;
				c = cscan ();
			}

			double res = 0;

			while (!space (c) && c != '.') {
				if (c == 'e' || c == 'E')
					return res * UTILITIES.fast_pow (10, iscan ());
				
				res *= 10;
				res += c - '0';
				c = cscan ();
			}

			if (c == '.') {
				c = cscan ();
				double m = 1;

				while (!space (c)) {
					if (c == 'e' || c == 'E')
						return res * UTILITIES.fast_pow (10, iscan ());

					m /= 10;
					res += (c - '0') * m;
					c = cscan ();
				}
			}

			return res * sgn;
		}

		public long lscan () throws IOException {
			int c = cscan (), sgn = 1;
			
			while (space (c))
				c = cscan ();

			if (c == '-') {
				sgn = -1;
				c = cscan ();
			}

			long res = 0;

			do {
				res = (res << 1) + (res << 3);
				res += c - '0';
				c = cscan ();
			}
			while (!space (c));

			return res * sgn;
		}

		public boolean space (int c) {
			return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1;
		}
	}

	public static class UTILITIES {

		static final double EPS = 10e-6;

		public static int lower_bound (int[] arr, int x) {
			int low = 0, high = arr.length, mid = -1;

			while (low < high) {
				mid = (low + high) / 2;

				if (arr[mid] >= x)
					high = mid;
				else
					low = mid + 1;
			}

			return low;
		}

		public static int upper_bound (int[] arr, int x) {
			int low = 0, high = arr.length, mid = -1;

			while (low < high) {
				mid = (low + high) / 2;

				if (arr[mid] > x)
					high = mid;
				else
					low = mid + 1;
			}

			return low;
		}

		public static int gcd (int a, int b) {
			return b == 0 ? a : gcd (b, a % b);
		}

		public static int lcm (int a, int b) {
			return a * b / gcd (a, b);
		}

		public static long fast_pow_mod (long b, long x, int mod) {
			if (x == 0) return 1;
			if (x == 1) return b;
			if (x % 2 == 0) return fast_pow_mod (b * b % mod, x / 2, mod) % mod;

			return b * fast_pow_mod (b * b % mod, x / 2, mod) % mod;
		}

		public static int fast_pow (int b, int x) {
			if (x == 0) return 1;
			if (x == 1) return b;
			if (x % 2 == 0) return fast_pow (b * b, x / 2);

			return b * fast_pow (b * b, x / 2);
		}

		public static long choose (long n, long k) {
			k = Math.min (k, n - k);
			long val = 1;

			for (int i = 0; i < k; ++i)
				val = val * (n - i) / (i + 1);

			return val;
		}

		public static long permute (int n, int k) {
			if (n < k) return 0;
			long val = 1;

			for (int i = 0; i < k; ++i)
				val = (val * (n - i));

			return val;
		}
	}
}