You are given a string S of length N consisting of lowercase English letters.

Process Q queries of the following two types:

* Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)
* Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).

Constraints

* N, Q, i_q, l_q, and r_q are integers.
* S is a string consisting of lowercase English letters.
* c_q is a lowercase English letter.
* 1 \leq N \leq 500000
* 1 \leq Q \leq 20000
* |S| = N
* 1 \leq i_q \leq N
* 1 \leq l_q \leq r_q \leq N
* There is at least one query of type 2 in each testcase.

Input

Input is given from Standard Input in the following format:


N
S
Q
Query_1
\vdots
Query_Q


Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:


1 i_q c_q



2 l_q r_q


Output

For each query of type 2, print a line containing the answer.

Example

Input

7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7


Output

3
1
5
f=input
from bisect import bisect_left as g, insort as h
n,s=int(f()),list(f())
d={chr(97+i):[] for i in range(26)}
for i in range(n): d[s[i]]+=[i]
for _ in range(int(f())):
  a,b,c=f().split(); b=int(b)-1
  if a>'1': print(sum(1 for l in d.values() if g(l,b)<len(l) and l[g(l,b)]<int(c)))
  elif s[b]!=c: l=d[s[b]]; l.pop(g(l,b)); s[b]=c; h(d[c],b)