You are given a string S of length N consisting of lowercase English letters.

Process Q queries of the following two types:

* Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)
* Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).

Constraints

* N, Q, i_q, l_q, and r_q are integers.
* S is a string consisting of lowercase English letters.
* c_q is a lowercase English letter.
* 1 \leq N \leq 500000
* 1 \leq Q \leq 20000
* |S| = N
* 1 \leq i_q \leq N
* 1 \leq l_q \leq r_q \leq N
* There is at least one query of type 2 in each testcase.

Input

Input is given from Standard Input in the following format:


N
S
Q
Query_1
\vdots
Query_Q


Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:


1 i_q c_q



2 l_q r_q


Output

For each query of type 2, print a line containing the answer.

Example

Input

7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7


Output

3
1
5
import bisect
from collections import defaultdict

N = int(input())
S = list(input())
Q = int(input())

alpha_dic = defaultdict(list)

for i, s in enumerate(S):
    alpha_dic[s].append(i)

for _ in range(Q):
    l, m, n = input().split()

    if l == '1':
        m = int(m) - 1
        c = S[m]

        if c == n:
            continue
        else:
            i = bisect.bisect_left(alpha_dic[c], m)
            del alpha_dic[c][i]

            bisect.insort_left(alpha_dic[n], m)
            S[m] = n
    else:
        m, n = int(m) - 1, int(n) - 1

        cnt = 0
        for _, val in alpha_dic.items():
            if not val:
                continue

            left_idx = bisect.bisect_left(val, m)
            right_idx = bisect.bisect_left(val, n)
            l = len(val)

            if left_idx > right_idx or (left_idx == right_idx and left_idx == l) or (left_idx == right_idx and val[left_idx] != m and val[right_idx] != n):
                continue

            cnt += 1

        print(cnt)
