Squirrel Liss lived in a forest peacefully, but unexpected trouble happens. Stones fall from a mountain. Initially Squirrel Liss occupies an interval [0, 1]. Next, n stones will fall and Liss will escape from the stones. The stones are numbered from 1 to n in order.

The stones always fall to the center of Liss's interval. When Liss occupies the interval [k - d, k + d] and a stone falls to k, she will escape to the left or to the right. If she escapes to the left, her new interval will be [k - d, k]. If she escapes to the right, her new interval will be [k, k + d].

You are given a string s of length n. If the i-th character of s is "l" or "r", when the i-th stone falls Liss will escape to the left or to the right, respectively. Find the sequence of stones' numbers from left to right after all the n stones falls.

Input

The input consists of only one line. The only line contains the string s (1 ≤ |s| ≤ 106). Each character in s will be either "l" or "r".

Output

Output n lines — on the i-th line you should print the i-th stone's number from the left.

Examples

Input

llrlr


Output

3
5
4
2
1


Input

rrlll


Output

1
2
5
4
3


Input

lrlrr


Output

2
4
5
3
1

Note

In the first example, the positions of stones 1, 2, 3, 4, 5 will be <image>, respectively. So you should print the sequence: 3, 5, 4, 2, 1.
class TreeNode(object):
    def __init__(self, x):
        self.val = x
        self.left = None
        self.right = None
 
class Solution(object):             
    def inorderTraversal(self, root): 
        stack=[]
        res=[]
        if not root:
            return []
        while root or stack:
            while root:
                stack.append(root)
                root=root.left
            if stack:
                a=stack.pop()
                root=a.right
                res.append(a.val)
        return res

if __name__ == '__main__':
    sol = Solution()
    tree = []
    tree.append(TreeNode(1))
    root = tree[0]
    str = input()
    for i in range(len(str) - 1):
        tree.append(TreeNode(i + 2))
        if str[i] == 'l':
            tree[i].left = tree[i + 1]
        else:
            tree[i].right = tree[i + 1]
    res = sol.inorderTraversal(root)
    for x in res:
        print(x)