The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include<cstdio>
int main(void)
{
	int N,ans=0;
	scanf("%d",&N);
	int a=105;
	int b=135;
	int c=165;
	int d=189;
	int e=195;
	
	if(N>=a)ans++;
	if(N>=b)ans++;
	if(N>=c)ans++;
	if(N>=d)ans++;
	if(N>=e)ans++;
	printf("%d\n",ans);
	return 0;
}
