The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include<bits/stdc++.h>
using namespace std;
int main()
{
	int n,an=0;
	scanf("%d",&n);
	for (int i=2;i<=n;i++)
		{
			int p=0;
			for (int j=1;j<=i;j++)
				if (i%j==0) p++;
			if (p==8 && i%2==1) an++;
		}
	cout<<an;
	return 0;
}