The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include <stdio.h>

int main(void)
{
	int x,y=0,z,a,b,sum = 0;
	scanf("%d",&x);
	for(a=1;a<=x;a+=2)
	{
		sum = 0;
		for(b=1;b<=a;b++)
		{
			if (a%b==0) sum ++;
		}
		if (sum == 8) y++;
	}
	printf("%d",y);
	return 0;
}