The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include<stdio.h>

int count(int a)
{
	int i,cnt=0;
	for(i=1;i<=a;i++){
		if(a%i==0)cnt++;
	}
	return cnt;
}

int main()
{
	int i,n,m=0,cnt;
	scanf("%d",&n);
	
	for(i=1;i<=n;i+=2)
	{
		cnt=count(i);
		if(cnt==8)m++;
	}
	printf("%d\n",m);
}