You're given an array a of length 2n. Is it possible to reorder it in such way so that the sum of the first n elements isn't equal to the sum of the last n elements?

Input

The first line contains an integer n (1 ≤ n ≤ 1000), where 2n is the number of elements in the array a.

The second line contains 2n space-separated integers a_1, a_2, …, a_{2n} (1 ≤ a_i ≤ 10^6) — the elements of the array a.

Output

If there's no solution, print "-1" (without quotes). Otherwise, print a single line containing 2n space-separated integers. They must form a reordering of a. You are allowed to not change the order.

Examples

Input


3
1 2 2 1 3 1


Output


2 1 3 1 1 2

Input


1
1 1


Output


-1

Note

In the first example, the first n elements have sum 2+1+3=6 while the last n elements have sum 1+1+2=4. The sums aren't equal.

In the second example, there's no solution.
import java.io.*;
import java.util.*;

public class Solution {
	
	
	public static final long mod = (long)Math.pow(10, 9) + 7;
	
	public static void main (String[] args) throws IOException{
    	FastReader f=new FastReader();
    	int n = f.nextInt();
    	int[] a = new int[2*n];
    	for (int i=0;i<a.length;i++) a[i] = f.nextInt();
    	
    	Arrays.sort(a);
    	int sum1 = 0;
    	int sum2=0;
    	for (int i=0;i<n;i++) sum1+=a[i];
    	for (int i=n;i<a.length;i++) sum2+=a[i];
    	
    	if (sum1==sum2) System.out.println(-1);
    	else {
    		for (int i=0;i<a.length;i++) System.out.print(a[i]+" ");
    	}
    	
    }
	
	
	
	public static int binlog( int bits ){
        int log = 0;
        if( ( bits & 0xffff0000 ) != 0 ) { bits >>>= 16; log = 16; }
        if( bits >= 256 ) { bits >>>= 8; log += 8; }
        if( bits >= 16  ) { bits >>>= 4; log += 4; }
        if( bits >= 4   ) { bits >>>= 2; log += 2; }
        return log + ( bits >>> 1 );
    }
	static class FastReader 
    { 
        BufferedReader br; 
        StringTokenizer st; 
  
        public FastReader() 
        { 
            br = new BufferedReader(new
                     InputStreamReader(System.in)); 
        } 
  
        String next() 
        { 
            while (st == null || !st.hasMoreElements()) 
            { 
                try
                { 
                    st = new StringTokenizer(br.readLine()); 
                } 
                catch (IOException  e) 
                { 
                    e.printStackTrace(); 
                } 
            } 
            return st.nextToken(); 
        } 
  
        int nextInt() 
        { 
            return Integer.parseInt(next()); 
        } 
  
        long nextLong() 
        { 
            return Long.parseLong(next()); 
        } 
  
        double nextDouble() 
        { 
            return Double.parseDouble(next()); 
        } 
  
        String nextLine() 
        { 
            String str = ""; 
            try
            { 
                str = br.readLine(); 
            } 
            catch (IOException e) 
            { 
                e.printStackTrace(); 
            } 
            return str; 
        } 
    } 
  
}