The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include<cstdio>
int main(){
	int n;
	scanf("%d",&n);
	int sum1=0;
	for(int i=1;i<=n;i=i+2){
		int sum=0;
		for(int j=1;j<=i;j++)
		   if(i%j==0)sum++;
		if(sum==8)sum1++;   
	}
	printf("%d\n",sum1);
}