The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include <iostream>
using namespace std;

int main() {
  int n;
  cin >> n;
  int s=0;
  for(int x=1; x<=n; x+=2){
    int k=0;
    for(int i=1; i<=n; i++){
      if (x%i==0) k++;
    }
    if (k==8) s++;
  }
  cout << s << endl;
}