The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include <stdio.h>
#define N 5

int a[N] = {105, 135, 165, 189, 195}, c = 0;

int main()
{		
	int n, i;
	
	scanf("%d", &n);
	for(i = 0; i < N; i++){
		if(a[i] <= n) c++;
	}
	printf("%d\n", c);
			
	return 0;
}