You are given several queries. In the i-th query you are given a single positive integer ni. You are to represent ni as a sum of maximum possible number of composite summands and print this maximum number, or print -1, if there are no such splittings.

An integer greater than 1 is composite, if it is not prime, i.e. if it has positive divisors not equal to 1 and the integer itself.

Input

The first line contains single integer q (1 ≤ q ≤ 105) — the number of queries.

q lines follow. The (i + 1)-th line contains single integer ni (1 ≤ ni ≤ 109) — the i-th query.

Output

For each query print the maximum possible number of summands in a valid splitting to composite summands, or -1, if there are no such splittings.

Examples

Input

1
12


Output

3


Input

2
6
8


Output

1
2


Input

3
1
2
3


Output

-1
-1
-1

Note

12 = 4 + 4 + 4 = 4 + 8 = 6 + 6 = 12, but the first splitting has the maximum possible number of summands.

8 = 4 + 4, 6 can't be split into several composite summands.

1, 2, 3 are less than any composite number, so they do not have valid splittings.
n=int(input())
for i in range(n):
    a=int(input())
    if a % 4==0:
        print(a//4)
    elif a%2==1:
        if a<9:
            print(-1)
        elif a==9:
            print(1)
        else:
            a=a-9
            x=a%4
            k=3
            while x < a:
                x+=4
                k=0
                for i in range(2,int(x**0.5+1)):
                    if x % i ==0:
                        k=1
                        break
                if k==1:
                    print((a-x)//4+2)
                    k=2
                    break
            if x > a or k==3 or k==0:
                print(-1)
            elif x==a and k!=2:
                print(2)
    else:
        x=a%4
        k=3
        while x < a:
            x+=4
            k=0
            for i in range(2,int(x**0.5+1)):
                if x % i ==0:
                    k=1
                    break
            if k==1:
                print((a-x)//4+1)
                k=2
                break
        if x > a or k==3 or k==0:
            print(-1)
        elif x==a and k!=2:
            print(1)
    
                    
