The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include<bits/stdc++.h>
using namespace std;

int n, l, odp;

int main(){
	cin>>n;
	for(int k=1; k<=n; k++){
		l=0;
		for(int i=1; i<=k; i+=2){
			if(k%i==0) l++;
		}
		if(l==8) odp++;
	}
	cout<<odp;
}