Polycarp has a string s[1 ... n] of length n consisting of decimal digits. Polycarp performs the following operation with the string s no more than once (i.e. he can perform operation 0 or 1 time): 

  * Polycarp selects two numbers i and j (1 ≤ i ≤ j ≤ n) and removes characters from the s string at the positions i, i+1, i+2, …, j (i.e. removes substring s[i ... j]). More formally, Polycarp turns the string s into the string s_1 s_2 … s_{i-1} s_{j+1} s_{j+2} … s_{n}. 



For example, the string s = "20192020" Polycarp can turn into strings: 

  * "2020" (in this case (i, j)=(3, 6) or (i, j)=(1, 4)); 
  * "2019220" (in this case (i, j)=(6, 6)); 
  * "020" (in this case (i, j)=(1, 5)); 
  * other operations are also possible, only a few of them are listed above. 



Polycarp likes the string "2020" very much, so he is wondering if it is possible to turn the string s into a string "2020" in no more than one operation? Note that you can perform zero operations.

Input

The first line contains a positive integer t (1 ≤ t ≤ 1000 ) — number of test cases in the test. Then t test cases follow.

The first line of each test case contains an integer n (4 ≤ n ≤ 200) — length of the string s. The next line contains a string s of length n consisting of decimal digits. It is allowed that the string s starts with digit 0.

Output

For each test case, output on a separate line: 

  * "YES" if Polycarp can turn the string s into a string "2020" in no more than one operation (i.e. he can perform 0 or 1 operation); 
  * "NO" otherwise. 



You may print every letter of "YES" and "NO" in any case you want (so, for example, the strings yEs, yes, Yes and YES will all be recognized as positive answer).

Example

Input


6
8
20192020
8
22019020
4
2020
5
20002
6
729040
6
200200


Output


YES
YES
YES
NO
NO
NO

Note

In the first test case, Polycarp could choose i=3 and j=6.

In the second test case, Polycarp could choose i=2 and j=5.

In the third test case, Polycarp did not perform any operations with the string.
import java.util.*;
import java.io.*;
public class MainClass
{
    public static void main(String[] args)throws IOException
    {
        //Reader in = new Reader();
        BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
        int t = Integer.parseInt(in.readLine());
        StringBuilder stringBuilder = new StringBuilder();
        while (t-- > 0)
        {
            int n = Integer.parseInt(in.readLine());
            String s = in.readLine();
            boolean ff = false;
            if (s.substring(0, 4).equals("2020") || s.substring(s.length() - 4).equals("2020"))
                ff = true;
            String ss = "2020";
            for (int i=0;i<4;i++)
            {
                String ss1 = s.substring(0, i + 1);
                String ss2 = s.substring(s.length() - 2 + i - 1);
                String sss = ss1 + ss2;
                if (sss.equals("2020"))
                    ff = true;
            }
            if (ff)
                stringBuilder.append("YES\n");
            else
                stringBuilder.append("NO\n");
//            System.out.println("DONE");
        }

        System.out.println(stringBuilder);
    }
}
class Reader
{
    final private int BUFFER_SIZE = 1 << 16;
    private DataInputStream din;
    private byte[] buffer;
    private int bufferPointer, bytesRead;

    public Reader()
    {
        din = new DataInputStream(System.in);
        buffer = new byte[BUFFER_SIZE];
        bufferPointer = bytesRead = 0;
    }

    public Reader(String file_name) throws IOException
    {
        din = new DataInputStream(new FileInputStream(file_name));
        buffer = new byte[BUFFER_SIZE];
        bufferPointer = bytesRead = 0;
    }

    public String readLine() throws IOException
    {
        byte[] buf = new byte[64]; // line length
        int cnt = 0, c;
        while ((c = read()) != -1)
        {
            if (c == '\n')
                break;
            buf[cnt++] = (byte) c;
        }
        return new String(buf, 0, cnt);
    }

    public int nextInt() throws IOException
    {
        int ret = 0;
        byte c = read();
        while (c <= ' ')
            c = read();
        boolean neg = (c == '-');
        if (neg)
            c = read();
        do
        {
            ret = ret * 10 + c - '0';
        }  while ((c = read()) >= '0' && c <= '9');

        if (neg)
            return -ret;
        return ret;
    }

    public long nextLong() throws IOException
    {
        long ret = 0;
        byte c = read();
        while (c <= ' ')
            c = read();
        boolean neg = (c == '-');
        if (neg)
            c = read();
        do {
            ret = ret * 10 + c - '0';
        }
        while ((c = read()) >= '0' && c <= '9');
        if (neg)
            return -ret;
        return ret;
    }

    public double nextDouble() throws IOException
    {
        double ret = 0, div = 1;
        byte c = read();
        while (c <= ' ')
            c = read();
        boolean neg = (c == '-');
        if (neg)
            c = read();

        do {
            ret = ret * 10 + c - '0';
        }
        while ((c = read()) >= '0' && c <= '9');

        if (c == '.')
        {
            while ((c = read()) >= '0' && c <= '9')
            {
                ret += (c - '0') / (div *= 10);
            }
        }

        if (neg)
            return -ret;
        return ret;
    }

    private void fillBuffer() throws IOException
    {
        bytesRead = din.read(buffer, bufferPointer = 0, BUFFER_SIZE);
        if (bytesRead == -1)
            buffer[0] = -1;
    }

    private byte read() throws IOException
    {
        if (bufferPointer == bytesRead)
            fillBuffer();
        return buffer[bufferPointer++];
    }

    public void close() throws IOException
    {
        if (din == null)
            return;
        din.close();
    }
}