You're given an array a of length 2n. Is it possible to reorder it in such way so that the sum of the first n elements isn't equal to the sum of the last n elements?

Input

The first line contains an integer n (1 ≤ n ≤ 1000), where 2n is the number of elements in the array a.

The second line contains 2n space-separated integers a_1, a_2, …, a_{2n} (1 ≤ a_i ≤ 10^6) — the elements of the array a.

Output

If there's no solution, print "-1" (without quotes). Otherwise, print a single line containing 2n space-separated integers. They must form a reordering of a. You are allowed to not change the order.

Examples

Input


3
1 2 2 1 3 1


Output


2 1 3 1 1 2

Input


1
1 1


Output


-1

Note

In the first example, the first n elements have sum 2+1+3=6 while the last n elements have sum 1+1+2=4. The sums aren't equal.

In the second example, there's no solution.
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.Arrays;
import java.util.Scanner;

public class CodeForces
{
	public static void main(String[] args)
	{
		Scanner input = new Scanner(new BufferedReader(new InputStreamReader(System.in)));

		int n = input.nextInt();
		int[] array = new int[2 * n];

		for (int i = 0; i < 2 * n; i++)
		{
			array[i] = input.nextInt();
		}
		Arrays.sort(array);
		if (array[0] == array[array.length - 1])
		{
			System.out.println(-1);
		} else
		{
			for (int i = 0; i < 2 * n; i++)
			{
				System.out.print(array[i] + " ");
			}
		}
	}
}