The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include<cstdio>
using namespace std;
int n,m,cnt;
int main(){
	scanf("%d",&n);
	for (int i=1;i<=n;++i){
		if (i%2==0) continue;
		int t=0;
		for (int j=1;j<=i;++j){
			if (i%j==0) ++t;
		}
		if (t==8) ++cnt;
	}
	printf("%d",cnt);
	return 0;
}