You're given an array a of length 2n. Is it possible to reorder it in such way so that the sum of the first n elements isn't equal to the sum of the last n elements?

Input

The first line contains an integer n (1 ≤ n ≤ 1000), where 2n is the number of elements in the array a.

The second line contains 2n space-separated integers a_1, a_2, …, a_{2n} (1 ≤ a_i ≤ 10^6) — the elements of the array a.

Output

If there's no solution, print "-1" (without quotes). Otherwise, print a single line containing 2n space-separated integers. They must form a reordering of a. You are allowed to not change the order.

Examples

Input


3
1 2 2 1 3 1


Output


2 1 3 1 1 2

Input


1
1 1


Output


-1

Note

In the first example, the first n elements have sum 2+1+3=6 while the last n elements have sum 1+1+2=4. The sums aren't equal.

In the second example, there's no solution.
"""
def fun(l,ln):
      t=ln//2
      i=0
      a=sum(l[0:t])
      b=sum(l[t:])
      while i<=ln:
            if  a==b:        
                  u=l[0]-l[t]
                  a-=u
                  b+=u 
            else :
                  s=''
                  for i in l:
                        s+=str(i)+" "
                  return s           
            temp=l.pop(0)
            l.append(temp)
            i+=1
      return -1
                  
            


x=int(input())
l=list(map(int, input().split()))
print(fun(l, 2*x))
"""
n = int(input())
l = list(map(int,input().split()))
suma = 0
for i in range(n):
    suma += l[i]
if suma * 2 != sum(l):
    for i in range(2*n):
        print(l[i], end = " ")
else:
    c = 0
    for i in range(n, 2*n):
        if l[i] != l[0]:
            a = l[i]
            b = l[0]
            l[0] = a
            l[i] = b
            c = 1
            break
    if c == 0:
        for i in range(n):
            if l[i] != l[0]:
                a = l[i]
                b = l[n]
                l[i] = b
                l[n] = a
                c = 1
                break
    if c == 0:
        print(-1)
    else:
        for i in range(2*n):
            print(l[i], end = " ")