We have a tree with N vertices numbered 1 to N. The i-th edge in this tree connects Vertex a_i and b_i. For each k=1, ..., N, solve the problem below:

* Consider writing a number on each vertex in the tree in the following manner:
* First, write 1 on Vertex k.
* Then, for each of the numbers 2, ..., N in this order, write the number on the vertex chosen as follows:
* Choose a vertex that still does not have a number written on it and is adjacent to a vertex with a number already written on it. If there are multiple such vertices, choose one of them at random.
* Find the number of ways in which we can write the numbers on the vertices, modulo (10^9+7).

Constraints

* 2 \leq N \leq 2 \times 10^5
* 1 \leq a_i,b_i \leq N
* The given graph is a tree.

Input

Input is given from Standard Input in the following format:


N
a_1 b_1
:
a_{N-1} b_{N-1}


Output

For each k=1, 2, ..., N in this order, print a line containing the answer to the problem.

Examples

Input

3
1 2
1 3


Output

2
1
1


Input

2
1 2


Output

1
1


Input

5
1 2
2 3
3 4
3 5


Output

2
8
12
3
3


Input

8
1 2
2 3
3 4
3 5
3 6
6 7
6 8


Output

40
280
840
120
120
504
72
72
import sys
sys.setrecursionlimit(10**7)

N = int(input())
AB = [list(map(int,input().split())) for _ in [0]*(N-1)]

mod = 10**9+7

m = 10**5*2 +10 
fac = [1]*m
ninv = [1]*m
finv = [1]*m
for i in range(2,m):
    fac[i] = fac[i-1]*i%mod
    ninv[i] = (-(mod//i)*ninv[mod%i])%mod
    finv[i] = finv[i-1]*ninv[i]%mod

E = [[] for _ in [0]*N]
Ef = [[] for _ in [0]*N]
Eb = [[] for _ in [0]*N]
for a,b in AB:
    a-=1
    b-=1
    E[a].append(b)
    E[b].append(a)
done = [False]*N
done[0] = True
q = [0]
while q:
    j = q.pop()
    for k in E[j]:
        if done[k]: continue
        done[k] = True
        q.append(k)
        Ef[j].append(k)
        Eb[k].append(j)
Vf = [None]*N
Mf = [None]*N
def getf(i):
    if Mf[i]!=None:
        return Mf[i]
    Mc = [getf(j) for j in Ef[i]]
    Vc = [Vf[j] for j in Ef[i]]
    Vf[i] = 1 + sum(Vc)
    Mf[i] = fac[Vf[i]-1]
    for mc,vc in zip(Mc,Vc):
        Mf[i] *= (mc*finv[vc])%mod
        Mf[i] %= mod
    return Mf[i]

def getp(i):
    if i==0: return 0
    p = Eb[i][0]
    vp = Vf[p]
    vi = Vf[i]
    ret = ans[p]
    ret *= (((fac[vi]*fac[N-1-vi])%mod)*finv[N-1])%mod
    ret %= mod
    ret *= pow(Mf[i],mod-2,mod)
    ret %= mod
    return ret

ans = [0]*N
ans[0] = getf(0)
q = Ef[0][:]

while q:
    i = q.pop()
    V = [N - Vf[i]]
    M = [getp(i)]
    for j in Ef[i]:
        q.append(j)
        V.append(Vf[j])
        M.append(Mf[j])
    tmp = fac[N-1]
    for mc,vc in zip(M,V):
        tmp *= (mc*finv[vc])%mod
        tmp %= mod
    ans[i] = tmp

for out in ans:
    print(out)