You are given an integer n from 1 to 10^{18} without leading zeroes.

In one move you can swap any two adjacent digits in the given number in such a way that the resulting number will not contain leading zeroes. In other words, after each move the number you have cannot contain any leading zeroes.

What is the minimum number of moves you have to make to obtain a number that is divisible by 25? Print -1 if it is impossible to obtain a number that is divisible by 25.

Input

The first line contains an integer n (1 ≤ n ≤ 10^{18}). It is guaranteed that the first (left) digit of the number n is not a zero.

Output

If it is impossible to obtain a number that is divisible by 25, print -1. Otherwise print the minimum number of moves required to obtain such number.

Note that you can swap only adjacent digits in the given number.

Examples

Input

5071


Output

4


Input

705


Output

1


Input

1241367


Output

-1

Note

In the first example one of the possible sequences of moves is 5071 → 5701 → 7501 → 7510 → 7150.

// Problem : E. Divisibility by 25
// Contest : Codeforces - Codeforces Round #486 (Div. 3)
// URL : https://codeforces.com/contest/988/problem/E
// Memory Limit : 256 MB
// Time Limit : 1000 ms
// Powered by CP Editor (https://github.com/cpeditor/cpeditor)

import java.io.*;
import java.util.*;
import java.util.stream.*;

public class a implements Runnable{
	
    public static void main(String[] args) {
        new Thread(null, new a(), "process", 1<<26).start();
    }
	public void run() {
		FastReader scan = new FastReader();
        PrintWriter out = new PrintWriter(new OutputStreamWriter(System.out));
		//PrintWriter out = new PrintWriter("file.out");
		Task solver = new Task();
		//int t = scan.nextInt();
		int t = 1;
		for(int i = 1; i <= t; i++) solver.solve(i, scan, out);
		out.close();
	}

	static class Task {
		static final int inf = Integer.MAX_VALUE;

		public void solve(int testNumber, FastReader sc, PrintWriter pw) {
			//CHECK FOR QUICKSORT TLE
			//***********************//
			//CHECK FOR INT OVERFLOW
			//***********************//
			String str = sc.nextLine();
			int[] pos = new int[5];
			Arrays.fill(pos, -1);
			for(int i = 0; i < str.length(); i++) {
				if(str.charAt(i) == '0') {
					pos[4] = pos[0];
					pos[0] = i;
				}
				if(str.charAt(i) == '2') {
					pos[1] = i;
				}
				if(str.charAt(i) == '5') {
					pos[2] = i;
				}
				if(str.charAt(i) == '7') {
					pos[3] = i;
				}
			}
			int n = str.length();
			int min = inf;
			if(pos[0] > -1 && pos[4] > -1) {
				min = Math.min(min, str.length() - pos[0] + str.length() - pos[4] - 3);
			}
			if(pos[1] > -1 && pos[2] > -1) {
				int addend = 0;
				if(pos[2] < pos[1]) {
					addend = 1;
				}
				if(pos[1] == 0 || pos[2] == 0) {
					for(int i = 1; i < n; i++) {
						if(str.charAt(i) != '0') {
							break;
						}
						addend++;
					}
				}
				if(pos[1] == n - 1 && pos[2] == n - 2) {
					min = Math.min(1, min);
				}
				min = Math.min(min, n - pos[1] + n - pos[2] - 3 + addend);
			}
			if(pos[0] > -1 && pos[2] > -1) {
				int addend = 0;
				if(pos[0] < pos[2]) {
					addend = 1;
				}
				if(pos[0] == 0 || pos[2] == 0) {
					for(int i = 1; i < n; i++) {
						if(str.charAt(i) != '0') {
							break;
						}
						if(i != pos[0])
						addend++;
					}
				}
				if(pos[2] == n - 1 && pos[0] == n - 2) {
					min = Math.min(1, min);
				}
				min = Math.min(min, n - pos[2] + n - pos[0] - 3 + addend);
			}
			if(pos[3] > -1 && pos[2] > -1) {
				int addend = 0;
				if(pos[2] < pos[3]) {
					addend = 1;
				}
				if(pos[3] == 0 || pos[2] == 0) {
					for(int i = 1; i < n; i++) {
						if(str.charAt(i) != '0') {
							break;
						}
						addend++;
					}
				}
				if(pos[3] == n - 1 && pos[2] == n - 2) {
					min = Math.min(1, min);
				}
				min = Math.min(min, n - pos[3] + n - pos[2] - 3 + addend);
			}
			if(min == inf) {
				pw.println(-1);
			}
			else{
				pw.println(min);
			}
			
		}
	}
	static long binpow(long a, long b, long m) {
		a %= m;
		long res = 1;
		while (b > 0) {
			if ((b & 1) == 1)
				res = res * a % m;
			a = a * a % m;
			b >>= 1;
		}
		return res;
	}
	static void sort(int[] x){
		shuffle(x);
		Arrays.sort(x);
	}
	static void sort(long[] x){
		shuffle(x);
		Arrays.sort(x);
	}
	static class tup implements Comparable<tup>{
		int a, b;
		tup(int a,int b){
			this.a=a;
			this.b=b;
		}
		@Override
		public int compareTo(tup o){
			return Integer.compare(o.b,b);
		}
	}
	static void shuffle(int[] a) {
		Random get = new Random();
		for (int i = 0; i < a.length; i++) {
			int r = get.nextInt(i + 1);
			int temp = a[i];
			a[i] = a[r];
			a[r] = temp;
		}
	}

	static void shuffle(long[] a) {
		Random get = new Random();
		for (int i = 0; i < a.length; i++) {
			int r = get.nextInt(i + 1);
			long temp = a[i];
			a[i] = a[r];
			a[r] = temp;
		}
	}

	static class FastReader {
		BufferedReader br;
		StringTokenizer st;

		public FastReader() {
			br = new BufferedReader(new InputStreamReader(System.in));
		}

		public FastReader(String s) throws FileNotFoundException {
			br = new BufferedReader(new FileReader(new File(s)));
		}

		String next() {
			while (st == null || !st.hasMoreElements()) {
				try {
					st = new StringTokenizer(br.readLine());
				} catch (IOException e) {
					e.printStackTrace();
				}
			}
			return st.nextToken();
		}

		int nextInt() {
			return Integer.parseInt(next());
		}

		long nextLong() {
			return Long.parseLong(next());
		}

		double nextDouble() {
			return Double.parseDouble(next());
		}

		String nextLine() {
			String str = "";
			try {
				str = br.readLine();
			} catch (IOException e) {
				e.printStackTrace();
			}
			return str;
		}
	}

}