The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include<stdio.h>
int f(int n)
{int sum=0;
	for(int i=1;i<=n;i++)
	if(n%i==0)
	if(i%2==1)
	sum++;
	return sum;
	
}
int main()
{
	int n;
	scanf("%d",&n);
	int sum=0;
	for(int i=1;i<=n;i++)
	if(f(i)==8)sum++;
	printf("%d",sum);
	
	
	
}