The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include <bits/stdc++.h>
using namespace std;

int main(){
  int c,ans;
  ans=0;
  int N;
  cin>>N;
  for(int i=1;i<=N;i+=2){
    c=0;
    for(int j=1;j<=i;j++){
      if(i%j==0)c++;
    }
    if(c==8)ans++;
  }
  cout<<ans<<endl;
}

