The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include <bits/stdc++.h>
using namespace std;

int main(){
  int N,j=0;
  cin>>N;
  for(int i=0;i<=N;i++){
    int l=0;
    for(int k=1;k<=i;k++)
      if(i%k==0)
        l++;
    if(l==8 && i%2==1){
      j++;
    }
  }
  cout<<j<<endl;
}