You are given a string S of length N consisting of lowercase English letters.

Process Q queries of the following two types:

* Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)
* Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).

Constraints

* N, Q, i_q, l_q, and r_q are integers.
* S is a string consisting of lowercase English letters.
* c_q is a lowercase English letter.
* 1 \leq N \leq 500000
* 1 \leq Q \leq 20000
* |S| = N
* 1 \leq i_q \leq N
* 1 \leq l_q \leq r_q \leq N
* There is at least one query of type 2 in each testcase.

Input

Input is given from Standard Input in the following format:


N
S
Q
Query_1
\vdots
Query_Q


Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:


1 i_q c_q



2 l_q r_q


Output

For each query of type 2, print a line containing the answer.

Example

Input

7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7


Output

3
1
5
import bisect
from collections import defaultdict

N = int(input())
# 書き換える時に文字列だと不便なのでリスト化しておく
S = list(input())
Q = int(input())

dict = defaultdict(list)
for i in range(N):
    dict[S[i]].append(i)
# print(dict)

ans = []

for _ in range(Q):
    a, b, c = input().split()
    a = int(a)

    if a == 1:
        b = int(b) - 1
        if S[b] == c:
            continue
        else:
            dict[S[b]].remove(b)
            idx = bisect.bisect_left(dict[c], b)
            dict[c].insert(idx, b)
            S[b] = c

    elif a == 2:
        b = int(b) - 1
        c = int(c) - 1
        char_n = 0
        for key, value in dict.items():
            x1 = bisect.bisect_left(value, b)
            x2 = bisect.bisect_right(value, c)
            if x2 - x1 > 0:
                char_n += 1
        ans.append(char_n)

for i in ans:
    print(i)
