The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include<stdio.h>
int main(){
	int a,b=0,c=0,n,j,i;
	scanf("%d",&n);
	for(j=1;j<=n;j+=2)
	{for(i=1;i<=j;i++)
	{
		if(j%i==0)
		{b++;}
		
		
		
	}
	if(b==8)
	{c++;}
    b=0;
}
	

printf("%d\n",c);
return 0;
}
	

	
