Snuke, who loves animals, built a zoo.

There are N animals in this zoo. They are conveniently numbered 1 through N, and arranged in a circle. The animal numbered i (2≤i≤N-1) is adjacent to the animals numbered i-1 and i+1. Also, the animal numbered 1 is adjacent to the animals numbered 2 and N, and the animal numbered N is adjacent to the animals numbered N-1 and 1.

There are two kinds of animals in this zoo: honest sheep that only speak the truth, and lying wolves that only tell lies.

Snuke cannot tell the difference between these two species, and asked each animal the following question: "Are your neighbors of the same species?" The animal numbered i answered s_i. Here, if s_i is `o`, the animal said that the two neighboring animals are of the same species, and if s_i is `x`, the animal said that the two neighboring animals are of different species.

More formally, a sheep answered `o` if the two neighboring animals are both sheep or both wolves, and answered `x` otherwise. Similarly, a wolf answered `x` if the two neighboring animals are both sheep or both wolves, and answered `o` otherwise.

Snuke is wondering whether there is a valid assignment of species to the animals that is consistent with these responses. If there is such an assignment, show one such assignment. Otherwise, print `-1`.

Constraints

* 3 ≤ N ≤ 10^{5}
* s is a string of length N consisting of `o` and `x`.

Input

The input is given from Standard Input in the following format:


N
s


Output

If there does not exist an valid assignment that is consistent with s, print `-1`. Otherwise, print an string t in the following format. The output is considered correct if the assignment described by t is consistent with s.

* t is a string of length N consisting of `S` and `W`.
* If t_i is `S`, it indicates that the animal numbered i is a sheep. If t_i is `W`, it indicates that the animal numbered i is a wolf.

Examples

Input

6
ooxoox


Output

SSSWWS


Input

3
oox


Output

-1


Input

10
oxooxoxoox


Output

SSWWSSSWWS
#include<cstdio>
#include<iostream>
using namespace std;
const int MR=100010;


char a[MR];
char ans[MR];
bool check(int a1,int a2,int n){
	a[0]='S'+a1*('W'-'S');a[1]='S'+a2*('W'-'S');
	for(int i=1;i<=n;i++){
		if((a[i]=='S' && ans[i]=='o')||(a[i]=='W' && ans[i]=='x')) a[i+1]=a[i-1];
		if((a[i]=='S' && ans[i]=='x')||(a[i]=='W' && ans[i]=='o')) a[i+1]='S'+'W'-a[i-1];
	}
	if(a[n]==a[0] && a[n+1]==a[1]){
		a[n]=0;
		return true;
	}
	else return false;
	
}

int main(){
	int n;
	scanf("%d",&n);
	cin.getline(ans,n+1);
	cin.getline(ans,n+1);
	ans[n]=ans[0];
	int a1,a2;
	bool ok=false;
	for(a1=0;a1<2;a1++){
		for(a2=0;a2<2;a2++){
			if(check(a1,a2,n)){
				ok=true;
				break;
			}
		}
		if(ok)break;
	}
	if(ok)printf("%s\n",a);
	else printf("-1\n");
	return 0;
}