In Omkar's last class of math, he learned about the least common multiple, or LCM. LCM(a, b) is the smallest positive integer x which is divisible by both a and b.

Omkar, having a laudably curious mind, immediately thought of a problem involving the LCM operation: given an integer n, find positive integers a and b such that a + b = n and LCM(a, b) is the minimum value possible.

Can you help Omkar solve his ludicrously challenging math problem?

Input

Each test contains multiple test cases. The first line contains the number of test cases t (1 ≤ t ≤ 10). Description of the test cases follows.

Each test case consists of a single integer n (2 ≤ n ≤ 10^{9}).

Output

For each test case, output two positive integers a and b, such that a + b = n and LCM(a, b) is the minimum possible.

Example

Input


3
4
6
9


Output


2 2
3 3
3 6

Note

For the first test case, the numbers we can choose are 1, 3 or 2, 2. LCM(1, 3) = 3 and LCM(2, 2) = 2, so we output 2 \ 2.

For the second test case, the numbers we can choose are 1, 5, 2, 4, or 3, 3. LCM(1, 5) = 5, LCM(2, 4) = 4, and LCM(3, 3) = 3, so we output 3 \ 3.

For the third test case, LCM(3, 6) = 6. It can be shown that there are no other pairs of numbers which sum to 9 that have a lower LCM.
import java.util.*;
import java.util.Map.Entry;
import java.lang.*;
import java.math.*;
import java.text.*;
import java.io.*;
		public final class Solve {
		static PrintWriter out = new PrintWriter(System.out); 
		static void flush() {
	 	out.flush();
	 	}
		static void run(long s, long e) {
		NumberFormat formatter = new DecimalFormat("#0.00000");
		System.out.print("Execution time is " + formatter.format((e - s) / 1000d) + " seconds");
		}
		static int gcd(int a, int b) { 
			if (b == 0) return a; 
			return gcd(b, a % b);  
		}
		static long gcd(long a, long b) { 
			if (b == 0) return a; 
			return gcd(b, a % b);  
		}
		static long lcm(long a, long b) { 
			return a*b/gcd(a, b);  
		}
		static class FastReader {
	    BufferedReader br;
	    StringTokenizer st;
	
	    public FastReader() {
	    br = new BufferedReader(new
	    InputStreamReader(System.in));
	    }
	    static boolean isPalindrome(String str1, String str2) {
	    String str3 = str1+str2;
	    int i = 0, j = str3.length()-1;
	    while(i < j) {
	    char a = str3.charAt(i), b = str3.charAt(j);
	    if(a != b) return false;
	    i++;j--;
	    }	
	    return true;
	    }
	    static boolean isPalindrome(String str) {
	    int i = 0, j = str.length()-1;
	    while(i < j) {
	    char a = str.charAt(i), b = str.charAt(j);
	    if(a != b) return false;
	    i++;j--;
	    }
	    return true;
	    }
	    String next() {
	    while (st == null || !st.hasMoreElements()) {
	    try{st = new StringTokenizer(br.readLine());}
	    catch (IOException  e) {e.printStackTrace();}
	    }
	    return st.nextToken();
	    }
	    int nextInt(){ return Integer.parseInt(next()); }
	    long nextLong() { return Long.parseLong(next());}
	    static int fact(int n) {
	    if(n == 1) return 1;
	    return n * fact(n-1);
	   	}
	    public int[] readIntArray(int n) {
	    int[] arr = new int[n];
		for(int i=0; i<n; ++i)
		arr[i]=nextInt();
		return arr;
		}
	    public long[] readLongArray(int n) {
	    	long[] arr = new long[n];
	    	for(int i=0; i<n; ++i)
	    		arr[i]=nextLong();
	    	return arr;
	    }
	    public int[][] readIntArray(int m, int n){
		int[][] arr = new int[m][n];
		for(int i = 0;i<m;i++) 
		for(int j = 0;j<n;j++) 
		arr[i][j] = nextInt();
		return arr;
	    }
	    public String[] readStringArray(int n) {
		String[] arr = new String[n];
		for(int i=0; i<n; ++i)
		arr[i]= nextLine();
		return arr;	
	    }
	    double nextDouble() {return Double.parseDouble(next());}
	    String nextLine() {
	    String str = "";
	    try{str = br.readLine();}
	    catch (IOException e) {e.printStackTrace();}
	    return str;}
	    }
		static void solve(int n){
			long min = Integer.MAX_VALUE;
			long res = -1;
			for(long i = 2;i*i <= n;i++) {
				if(n%i == 0 && (lcm(i, n - i) < min || (lcm(n/i, n - n/i))< min)) {
					if(lcm(i, n - i) < lcm(n/i, n - n/i)) {
						res = i;
						min = lcm(i, n-i);
					}
					else {
						min = lcm(n/i, n - n/i);
						res = n/i;
					}
				}
			}
			if(res == -1 ) {
				out.println(1+" "+(n-1));
			}
			else {
				out.println(res+" "+(n-res));
			}
		}
		public static void main(String args[]) throws IOException {
	    FastReader sc = new FastReader();
	    long s1 = System.currentTimeMillis();
	    int t = sc.nextInt();
	    while(t-- > 0 ) {
	    int n = sc.nextInt();
	    solve(n);
	    }
	    flush();
	    long e = System.currentTimeMillis();
//	    run(s1,e);
	    }
	}
		
		
		