The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include<bits/stdc++.h>
using namespace std;

int main(){
  int N;cin>>N;
  int ans=0;
  if(N>=105) ans++;
  if(N>=135) ans++;
  if(N>=165) ans++;
  if(N>=189) ans++;
  if(N>=195) ans++;
  cout<<ans<<endl;
}
  
