The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include<stdio.h>

int main(void){
int no , tem=0 ,res=0;
scanf("%d",&no);
for(int i=1;i<=no;i+=2){
tem=0;
for(int cot=1;cot<=i;cot++){
if (i%cot==0){
tem++;
}
}
if(tem==8){
res++;
}
}
printf("%d",res);
return 0;
}