The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include <iostream>
using namespace std;

int main() {
	int n;
	cin>>n;
	int ans=0;
	int cool =0;
	for(int i=1;i<=n;i++)
	{
		ans=0;
	for(int j=1;j<=i/2;j++)
	{
		if((i&1)&&(i%j==0)){ans++;}
	}
	ans+=1;
	
	if(ans==8){cool++;}
	}
	cout<<cool;
}