The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include <bits/stdc++.h>
using namespace std;

int main()
{ 
  int n;
  cin >> n;
  cout << (n < 105 ? 0 : n < 135 ? 1 : n < 165 ? 2 : n < 189 ? 3 : n < 195 ? 4 : 5) << endl;
}