The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include <bits/stdc++.h>

using namespace std;

int main()
{
	int n;
	cin >> n;
	int ans=0;
	for(int i=1;i<=n;i+=2)
	{
		int dv=0;
		for(int j=1;j<=i;j++)
			dv+=(i%j==0);
		if(dv==8) ans++;
	}
	cout << ans << endl;
	return 0;
}