You are given a string S of length N consisting of lowercase English letters.

Process Q queries of the following two types:

* Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)
* Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).

Constraints

* N, Q, i_q, l_q, and r_q are integers.
* S is a string consisting of lowercase English letters.
* c_q is a lowercase English letter.
* 1 \leq N \leq 500000
* 1 \leq Q \leq 20000
* |S| = N
* 1 \leq i_q \leq N
* 1 \leq l_q \leq r_q \leq N
* There is at least one query of type 2 in each testcase.

Input

Input is given from Standard Input in the following format:


N
S
Q
Query_1
\vdots
Query_Q


Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:


1 i_q c_q



2 l_q r_q


Output

For each query of type 2, print a line containing the answer.

Example

Input

7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7


Output

3
1
5
import sys
import bisect

N = int(sys.stdin.readline().rstrip())
S = list(sys.stdin.readline().rstrip())
Q = int(sys.stdin.readline().rstrip())

idx = {chr(ord("a") + i): [] for i in range(26)}

for i, s in enumerate(S):
    idx[s].append(i + 1)

for _ in range(Q):
    t, i, c = sys.stdin.readline().rstrip().split()
    i = int(i)
    if t == "1":
        if S[i - 1] != c:
            idx[S[i - 1]].remove(i)
            bisect.insort(idx[c], i)
            S[i - 1] = c
    else:
        c = int(c)
        ans = 0
        for a, id in idx.items():
            x = bisect.bisect_left(id, i)
            y = bisect.bisect_right(id, c)
            if y - x:
                ans += 1
        print(ans)