The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include <stdio.h>
int main()
{
	int m,n,count=0,No=0;
	scanf("%d",&m);
	for(int i=1;i<=m;i++){
		for(int j=1;j<=i;j++){
			if(i%j==0){count++;}
			}
		if(count==8&&i%2==1){
			No++;
			}
		count=0;
		}
	printf("%d",No);
	
	return 0;
}