The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include <bits/stdc++.h>
using namespace std;

int main() {
  int cnt,ans=0;
  int n; cin>>n;
  for(int i=1;i<=n;i+=2) {
    cnt=0;
    for(int j=1;j<=i;j++) {
      if(i%j==0) cnt++;
    }

    if(cnt==8) ans++;
  }
  cout<<ans<<endl;
}
