We have a tree with N vertices numbered 1 to N. The i-th edge in this tree connects Vertex a_i and b_i. For each k=1, ..., N, solve the problem below:

* Consider writing a number on each vertex in the tree in the following manner:
* First, write 1 on Vertex k.
* Then, for each of the numbers 2, ..., N in this order, write the number on the vertex chosen as follows:
* Choose a vertex that still does not have a number written on it and is adjacent to a vertex with a number already written on it. If there are multiple such vertices, choose one of them at random.
* Find the number of ways in which we can write the numbers on the vertices, modulo (10^9+7).

Constraints

* 2 \leq N \leq 2 \times 10^5
* 1 \leq a_i,b_i \leq N
* The given graph is a tree.

Input

Input is given from Standard Input in the following format:


N
a_1 b_1
:
a_{N-1} b_{N-1}


Output

For each k=1, 2, ..., N in this order, print a line containing the answer to the problem.

Examples

Input

3
1 2
1 3


Output

2
1
1


Input

2
1 2


Output

1
1


Input

5
1 2
2 3
3 4
3 5


Output

2
8
12
3
3


Input

8
1 2
2 3
3 4
3 5
3 6
6 7
6 8


Output

40
280
840
120
120
504
72
72
import sys

def solve():
    input = lambda: sys.stdin.readline().rstrip()
    sys.setrecursionlimit(10 ** 7)
    mod = 10 ** 9 + 7

    def comb(n, r):
        if r > n: return 0
        return fac[n] * inv[r] * inv[n - r] % mod

    def dfs(v, Pa=-1):
        for u in to[v]:
            if u == Pa: continue
            dfs(u, v)
            size[v] += size[u]
            dp[v] *= dp[u] % mod
            dp[v] *= inv[size[u]] % mod
        dp[v] *= fac[size[v]] % mod
        size[v] += 1

    def bfs(v, Pa=-1, P_val=1, P_sz=0):
        ans[v] = P_val * dp[v] * comb(n - 1, P_sz) % mod
        for u in to[v]:
            if u == Pa: continue
            val = ans[v] * INV(dp[u] * comb(n - 1, size[u])) % mod
            bfs(u, v, val, n - size[u])

    n = int(input())
    to = [[] for _ in range(n)]
    for _ in range(n - 1):
        a, b = map(lambda x: int(x) - 1, input().split())
        to[a].append(b)
        to[b].append(a)

    fac = [1] * (n + 2)
    inv = [1] * (n + 2)

    for i in range(2, n + 1):
        fac[i] = fac[i - 1] * i % mod
    INV = lambda x: pow(x, mod - 2, mod)
    inv[n] = INV(fac[n])
    for i in range(n - 1, 1, -1):
        inv[i] = inv[i + 1] * (i + 1) % mod

    dp = [1] * n
    size = [0] * n
    ans = [0] * n

    dfs(0)
    bfs(0)
    print(*ans, sep='\n')

if __name__ == '__main__':
    solve()