You are given a string S of length N consisting of lowercase English letters.

Process Q queries of the following two types:

* Type 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)
* Type 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).

Constraints

* N, Q, i_q, l_q, and r_q are integers.
* S is a string consisting of lowercase English letters.
* c_q is a lowercase English letter.
* 1 \leq N \leq 500000
* 1 \leq Q \leq 20000
* |S| = N
* 1 \leq i_q \leq N
* 1 \leq l_q \leq r_q \leq N
* There is at least one query of type 2 in each testcase.

Input

Input is given from Standard Input in the following format:


N
S
Q
Query_1
\vdots
Query_Q


Here, Query_i in the 4-th through (Q+3)-th lines is one of the following:


1 i_q c_q



2 l_q r_q


Output

For each query of type 2, print a line containing the answer.

Example

Input

7
abcdbbd
6
2 3 6
1 5 z
2 1 1
1 4 a
1 7 d
2 1 7


Output

3
1
5
from bisect import bisect_left
import string 

dic={c:[] for c in string.ascii_lowercase}
N=int(input())
S=list(input())
Q=int(input())
for i in range(len(S)):
  dic[S[i]].append(i+1)

for i in range(Q):
  a,b,c=map(str,input().split())
  if a=='1':
    if S[int(b)-1]==c:
      continue
    b=int(b)
    f=S[b-1]
    d=bisect_left(dic[f],b)
    e=bisect_left(dic[c],b)
    dic[f].pop(d)
    dic[c].insert(e,b)
    S[b-1]=c
  else:
    ans=0
    b,c=int(b),int(c)
    for j in string.ascii_lowercase:
      d=bisect_left(dic[j],b)
      if d<len(dic[j]):
        if dic[j][d]<=c:
          ans+=1
    print(ans)
