The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include <iostream>
using namespace std;

int main(){
int N;
  int c=0;
  int a=0;
  cin>>N;
  for(int i=1;i<=N;i++){
  for(int j=1;j<=i;j++){
  if(i%j==0) a++ ;
  }
  if(a==8 && i%2==1) c++;
    a=0;
  }
cout<<c<<endl;
return 0;}