Polycarp has a string s[1 ... n] of length n consisting of decimal digits. Polycarp performs the following operation with the string s no more than once (i.e. he can perform operation 0 or 1 time): 

  * Polycarp selects two numbers i and j (1 ≤ i ≤ j ≤ n) and removes characters from the s string at the positions i, i+1, i+2, …, j (i.e. removes substring s[i ... j]). More formally, Polycarp turns the string s into the string s_1 s_2 … s_{i-1} s_{j+1} s_{j+2} … s_{n}. 



For example, the string s = "20192020" Polycarp can turn into strings: 

  * "2020" (in this case (i, j)=(3, 6) or (i, j)=(1, 4)); 
  * "2019220" (in this case (i, j)=(6, 6)); 
  * "020" (in this case (i, j)=(1, 5)); 
  * other operations are also possible, only a few of them are listed above. 



Polycarp likes the string "2020" very much, so he is wondering if it is possible to turn the string s into a string "2020" in no more than one operation? Note that you can perform zero operations.

Input

The first line contains a positive integer t (1 ≤ t ≤ 1000 ) — number of test cases in the test. Then t test cases follow.

The first line of each test case contains an integer n (4 ≤ n ≤ 200) — length of the string s. The next line contains a string s of length n consisting of decimal digits. It is allowed that the string s starts with digit 0.

Output

For each test case, output on a separate line: 

  * "YES" if Polycarp can turn the string s into a string "2020" in no more than one operation (i.e. he can perform 0 or 1 operation); 
  * "NO" otherwise. 



You may print every letter of "YES" and "NO" in any case you want (so, for example, the strings yEs, yes, Yes and YES will all be recognized as positive answer).

Example

Input


6
8
20192020
8
22019020
4
2020
5
20002
6
729040
6
200200


Output


YES
YES
YES
NO
NO
NO

Note

In the first test case, Polycarp could choose i=3 and j=6.

In the second test case, Polycarp could choose i=2 and j=5.

In the third test case, Polycarp did not perform any operations with the string.
from __future__ import division, print_function

MOD = 998244353
mod = 10**9 + 7

# import resource
# resource.setrlimit(resource.RLIMIT_STACK, [0x100000000, resource.RLIM_INFINITY])

def prepare_factorial():
    fact = [1]
    for i in range(1, 20):
        fact.append((fact[-1] * i) % mod)
    ifact = [0] * 105
    ifact[104] = pow(fact[104], mod - 2, mod)
    for i in range(104, 0, -1):
        ifact[i - 1] = (i * ifact[i]) % mod

    return fact, ifact

# import threading
# threading.stack_size(1<<27)
import sys
# sys.setrecursionlimit(10000)

from bisect import bisect_left, bisect_right, insort
from math import floor, ceil, sqrt, degrees, atan, pi, log, sin, radians, factorial
from heapq import heappop, heapify, heappush
from collections import Counter, defaultdict, deque
# from itertools import permutations


def modinv(n, p):
    return pow(n, p - 2, p)

def ncr(n, r, fact, ifact):    # for using this uncomment the lines calculating fact and ifact
    t = (fact[n] * (ifact[r] * ifact[n-r]) % mod) % mod
    return t

def get_ints(): return map(float, sys.stdin.readline().strip().split())
def get_array(): return list(map(int, sys.stdin.readline().strip().split()))
def input(): return sys.stdin.readline().strip()

"""*****************************************************************************************"""

def GCD(x, y):
    while y:
        x, y = y, x % y
    return x

def lcm(x, y):
    return (x * y)//(GCD(x, y))

def get_xor(n):
    return [n, 1, n+1, 0][n % 4]

def get_n(P):    # this function returns the maximum n for which Summation(n) <= Sum
    ans = (-1 + sqrt(1 + 8*P))//2
    return ans

""" ********************************************************************************************* """

def main():

    T = int(input())
    while T:
        n = int(input())
        string = input()

        flag = 0
        if '2020' == string:
            flag = 1
        elif string[:4] == '2020':
            flag = 1
        elif string[n-4:] == '2020':
            flag = 1
        elif string[0] == '2' and string[n-3:] == '020':
            flag = 1
        elif string[:2] == '20' and string[n-2:] == '20':
            flag = 1
        elif string[:3] == '202' and string[-1] == '0':
            flag = 1

        if flag == 1:
            print('YES')
        else:
            print('NO')
        T -= 1


""" -------- Python 2 and 3 footer by Pajenegod and c1729 ---------"""

py2 = round(0.5)
if py2:
    from future_builtins import ascii, filter, hex, map, oct, zip
    range = xrange

import os, sys
from io import IOBase, BytesIO

BUFSIZE = 8192

class FastIO(BytesIO):
    newlines = 0

    def __init__(self, file):
        self._file = file
        self._fd = file.fileno()
        self.writable = "x" in file.mode or "w" in file.mode
        self.write = super(FastIO, self).write if self.writable else None

    def _fill(self):
        s = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
        self.seek((self.tell(), self.seek(0, 2), super(FastIO, self).write(s))[0])
        return s

    def read(self):
        while self._fill(): pass
        return super(FastIO, self).read()

    def readline(self):
        while self.newlines == 0:
            s = self._fill();
            self.newlines = s.count(b"\n") + (not s)
        self.newlines -= 1
        return super(FastIO, self).readline()

    def flush(self):
        if self.writable:
            os.write(self._fd, self.getvalue())
            self.truncate(0), self.seek(0)


class IOWrapper(IOBase):

    def __init__(self, file):
        self.buffer = FastIO(file)
        self.flush = self.buffer.flush
        self.writable = self.buffer.writable
        if py2:
            self.write = self.buffer.write
            self.read = self.buffer.read
            self.readline = self.buffer.readline
        else:
            self.write = lambda s: self.buffer.write(s.encode('ascii'))
            self.read = lambda: self.buffer.read().decode('ascii')
            self.readline = lambda: self.buffer.readline().decode('ascii')


sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip('\r\n')

# sys.stdin = open('input.txt', 'r')
# sys.stdout = open('output.txt', 'w')

if __name__ == '__main__':
    main()
    # threading.Thread(target=main).start()