The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include <bits/stdc++.h>
using namespace std;
int main()
{
    int i,j,n,a=0,b=0;
    cin>>n;
    for(i=1;i<=n;i+=2)
    {
    	for(j=1;j<=n;j++)
    	{
            if(i%j==0) a++;
		}
		if(a==8) b++;
		a=0;
	}
	cout<<b;
	return 0;
}
