The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include<bits/stdc++.h>
using namespace std;
int main(){
	int n;
	cin>>n;
	cout<<(n<105?0:(n<135?1:(n<165?2:(n<189?3:(n<195?4:5)))))<<endl;
	return 0;
}
