The number 105 is quite special - it is odd but still it has eight divisors. Now, your task is this: how many odd numbers with exactly eight positive divisors are there between 1 and N (inclusive)?

Constraints

* N is an integer between 1 and 200 (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the count.

Examples

Input

105


Output

1


Input

7


Output

0
#include<bits/stdc++.h>
using namespace std;
int main(){
int n;cin>>n;int count=0;
for(int i=1;i<=n;i++){
int c=0;
     for(int j=1;j<=i;j++){
         if(i%j==0)c++;
     }
 
if(c==8&&i%2!=0)count++;
}
cout<<count;
}