Little penguin Polo adores strings. But most of all he adores strings of length n.

One day he wanted to find a string that meets the following conditions:

  1. The string consists of n lowercase English letters (that is, the string's length equals n), exactly k of these letters are distinct. 
  2. No two neighbouring letters of a string coincide; that is, if we represent a string as s = s1s2... sn, then the following inequality holds, si ≠ si + 1(1 ≤ i < n). 
  3. Among all strings that meet points 1 and 2, the required string is lexicographically smallest. 



Help him find such string or state that such string doesn't exist.

String x = x1x2... xp is lexicographically less than string y = y1y2... yq, if either p < q and x1 = y1, x2 = y2, ... , xp = yp, or there is such number r (r < p, r < q), that x1 = y1, x2 = y2, ... , xr = yr and xr + 1 < yr + 1. The characters of the strings are compared by their ASCII codes.

Input

A single line contains two positive integers n and k (1 ≤ n ≤ 106, 1 ≤ k ≤ 26) — the string's length and the number of distinct letters.

Output

In a single line print the required string. If there isn't such string, print "-1" (without the quotes).

Examples

Input

7 4


Output

ababacd


Input

4 7


Output

-1
import java.io.*;
import java.util.*;
public final class code
// public class Main
// class code
// public class Solution
{
    static void solve()throws IOException
    {
        int n=nextInt();
        int k=nextInt();
        if(k>n)
        {
            out.println(-1);
            return;
        }
        if(k==1)
        {
            if(n==1)
                out.println("a");
            else
                out.println(-1);
            return;
        }
        StringBuilder s=new StringBuilder();
        for(int i=1;i<=n;i++)
            s.append("ab");
        s=new StringBuilder(s.substring(0,n-k+2));
        char ch='c';
        for(int i=n-k+2;i<n;i++)
            s.append((char)(ch++));
        out.println(s);
    }

     
    ///////////////////////////////////////////////////////////

    static final long mod=(long)(1e9+7);
    static final int inf=(int)(1e9+1);
    static final int maxn=(int)(1e6);
    static final long lim=(long)(1e18);

    public static void main(String args[])throws IOException
    {
        br=new BufferedReader(new InputStreamReader(System.in));
        out=new PrintWriter(new BufferedOutputStream(System.out));
        
        solve();
         
        // int t=nextInt();
        // for(int i=1;i<=t;i++)
        // {
        //    // out.print("Case #"+i+": ");
        //     solve();
        // }
         
        out.close();
    }
    
    static int max(int ... a)
    {
    int ret=a[0];
    for(int i=1;i<a.length;i++)
    ret=Math.max(ret,a[i]);
    return ret;
    }
    static int min(int ... a)
    {
    int ret=a[0];
    for(int i=1;i<a.length;i++)
    ret=Math.min(ret,a[i]);
    return ret;
    }
    static void debug(Object ... a)
    {
    System.out.print("> ");
    for(int i=0;i<a.length;i++)
    System.out.print(a[i]+" ");
    System.out.println();
    }
    static void debug(int a[]){debuga(Arrays.stream(a).boxed().toArray());}
    static void debug(long a[]){debuga(Arrays.stream(a).boxed().toArray());}
    static void debuga(Object a[])
    {
    System.out.print("> ");
    for(int i=0;i<a.length;i++)
    System.out.print(a[i]+" ");
    System.out.println();
    }
    static Random random;
    static BufferedReader br;
    static StringTokenizer st;
    static PrintWriter out;
    static String nextToken()throws IOException
    {
    while(st==null || !st.hasMoreTokens())
    st=new StringTokenizer(br.readLine());
    return st.nextToken();
    }
    static String nextLine()throws IOException
    {
    return br.readLine();
    }
    static int nextInt()throws IOException
    {
    return Integer.parseInt(nextToken());
    }
    static long nextLong()throws IOException
    {
    return Long.parseLong(nextToken());
    }
    static double nextDouble()throws IOException
    {
    return Double.parseDouble(nextToken());
    }
}