Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:

  * if the character w_{i-x} exists and is equal to 1, then s_i is 1 (formally, if i > x and w_{i-x} =  1, then s_i =  1); 
  * if the character w_{i+x} exists and is equal to 1, then s_i is 1 (formally, if i + x ≤ n and w_{i+x} =  1, then s_i =  1); 
  * if both of the aforementioned conditions are false, then s_i is 0. 



You are given the integer x and the resulting string s. Reconstruct the original string w.

Input

The first line contains one integer t (1 ≤ t ≤ 1000) — the number of test cases.

Each test case consists of two lines. The first line contains the resulting string s (2 ≤ |s| ≤ 10^5, each character of s is either 0 or 1). The second line contains one integer x (1 ≤ x ≤ |s| - 1).

The total length of all strings s in the input does not exceed 10^5.

Output

For each test case, print the answer on a separate line as follows:

  * if no string w can produce the string s at the end of the process, print -1; 
  * otherwise, print the binary string w consisting of |s| characters. If there are multiple answers, print any of them. 

Example

Input


3
101110
2
01
1
110
1


Output


111011
10
-1
from sys import stdin, stdout
from sys import maxsize
input = stdin.readline
# def print(n):
#    stdout.write(str(n)+'\n')


def solve():
    pass


test = 1
test = int(input().strip())
for t in range(0, test):
    # n = int(input().strip())
    # String Input, converted to mutable list.
    s = [int(x) for x in list(input().strip())]
    ans = [1]*len(s)
    x = int(input().strip())
    for i in range(len(s)):
        if(s[i] == 0):
            if(i-x >= 0):
                ans[i-x] = 0
            if(i+x < len(s)):
                ans[i+x] = 0
    flag = False
    for i in range(len(s)):
        if(s[i] == 1):
            a, b = 0, 0
            if(i-x >= 0 and ans[i-x] == 1):
                a = 1
            if(i+x < len(s) and ans[i+x] == 1):
                b = 1
            if(a+b == 0):
                flag = True
    if(flag):
        print(-1)
    else:
        print(''.join([str(x) for x in ans]))
    # n, k = list(map(int, input().strip().split()))
    # arr = [int(x) for x in input().strip().split()]
    # brr = [list(map(int,input().strip().split())) for i in range(rows)]              # 2D array row-wise input

    ans = solve()


'''
rows, cols = (5, 5)
arr = [[0]*cols for j in range(rows)]                                         # 2D array initialization
rev_str=s[::-1]                                                               # To reverse given string
b=input().strip().split()                                                     # list created by spliting about spaces
ch = chr(ord(ch) + 1)                                                         # To increment character by one in ASCII
brr = [[int(b[cols*i+j]) for j in range(cols)] for i in range(rows)]          # 2D array Linear Input
rows,cols=len(brr),len(brr[0])                                                # no of rows/cols for 2D array
arr.sort(key = lambda x : x[1])                                               # sort list of tuples by 2nd element, Default priority - 1st Element then 2nd Element
s=set()                                                                       # empty set
a=maxsize                                                                     # initializing infinity
b=-maxsize                                                                    # initializing -infinity
mapped=list(map(function,input))                                              # to apply function to list element-wise
try:                                                                          # Error handling
    #code 1
except:                                                                       # ex. to stop at EOF
    #code 2 , if error occurs
'''
