Developers often face with regular expression patterns. A pattern is usually defined as a string consisting of characters and metacharacters that sets the rules for your search. These patterns are most often used to check whether a particular string meets the certain rules.

In this task, a pattern will be a string consisting of small English letters and question marks ('?'). The question mark in the pattern is a metacharacter that denotes an arbitrary small letter of the English alphabet. We will assume that a string matches the pattern if we can transform the string into the pattern by replacing the question marks by the appropriate characters. For example, string aba matches patterns: ???, ??a, a?a, aba.

Programmers that work for the R1 company love puzzling each other (and themselves) with riddles. One of them is as follows: you are given n patterns of the same length, you need to find a pattern that contains as few question marks as possible, and intersects with each of the given patterns. Two patterns intersect if there is a string that matches both the first and the second pattern. Can you solve this riddle?

Input

The first line contains a single integer n (1 ≤ n ≤ 105) — the number of patterns. Next n lines contain the patterns.

It is guaranteed that the patterns can only consist of small English letters and symbols '?'. All patterns are non-empty and have the same length. The total length of all the patterns does not exceed 105 characters.

Output

In a single line print the answer to the problem — the pattern with the minimal number of signs '?', which intersects with each of the given ones. If there are several answers, print any of them.

Examples

Input

2
?ab
??b


Output

xab


Input

2
a
b


Output

?


Input

1
?a?b


Output

cacb

Note

Consider the first example. Pattern xab intersects with each of the given patterns. Pattern ??? also intersects with each of the given patterns, but it contains more question signs, hence it is not an optimal answer. Clearly, xab is the optimal answer, because it doesn't contain any question sign. There are a lot of other optimal answers, for example: aab, bab, cab, dab and so on.
import javax.print.DocFlavor;
import javax.swing.plaf.basic.BasicInternalFrameTitlePane;
import java.io.*;
import java.lang.reflect.Array;
import java.math.BigInteger;
import java.net.CookieHandler;
import java.nio.Buffer;
import java.nio.charset.IllegalCharsetNameException;
import java.sql.BatchUpdateException;
import java.util.*;
import java.util.stream.Stream;
import java.util.Vector;
import java.io.IOException;
import java.nio.file.Files;
import java.nio.file.Paths;
import static java.lang.Math.*;
import java.util.*;
import java.nio.file.StandardOpenOption;
import java.util.Comparator;
import java.util.LinkedList;
import java.util.PriorityQueue;
import java.util.Iterator;
import java.util.PriorityQueue;

public class icpc
{
    public static void main(String[] args)throws IOException
    {
//        Reader in = new Reader();
        BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
        int n = Integer.parseInt(in.readLine());
        String A[] = new String[n];
        for(int i=0;i<n;i++)
        {
            A[i] = in.readLine();
        }

        int len = A[0].length();
        StringBuilder stringBuilder = new StringBuilder();
        for(int i=0;i<len;i++)
        {
            int count1 = 0;
            HashSet<Character> h = new HashSet<>();
            for(int j=0;j<n;j++)
            {
                if(A[j].charAt(i) == '?')
                    count1++;
                else
                    h.add(A[j].charAt(i));
            }
            if(h.size() == 1)
            {
                Iterator iter = h.iterator();
                stringBuilder.append((char)iter.next());
            }
            else if(count1 == n)
                stringBuilder.append("x");
            else
                stringBuilder.append("?");
        }
        System.out.println(stringBuilder);
    }
}
class StringAlgorithms
{
    public int[] calculateZ(char input[]) {
        int Z[] = new int[input.length];
        int left = 0;
        int right = 0;
        for(int k = 1; k < input.length; k++) {
            if(k > right) {
                left = right = k;
                while(right < input.length && input[right] == input[right - left]) {
                    right++;
                }
                Z[k] = right - left;
                right--;
            } else {
                //we are operating inside box
                int k1 = k - left;
                //if value does not stretches till right bound then just copy it.
                if(Z[k1] < right - k + 1) {
                    Z[k] = Z[k1];
                } else { //otherwise try to see if there are more matches.
                    left = k;
                    while(right < input.length && input[right] == input[right - left]) {
                        right++;
                    }
                    Z[k] = right - left;
                    right--;
                }
            }
        }
        return Z;
    }
    public ArrayList<Integer> matchPattern(char text[], char pattern[]) {
        char newString[] = new char[text.length + pattern.length + 1];
        int i = 0;
        for(char ch : pattern) {
            newString[i] = ch;
            i++;
        }
        newString[i] = '$';
        i++;
        for(char ch : text) {
            newString[i] = ch;
            i++;
        }
        ArrayList<Integer> result = new ArrayList<>();
        int Z[] = calculateZ(newString);

        for(i = 0; i < Z.length ; i++) {
            if(Z[i] == pattern.length) {
                result.add(i - pattern.length - 1);
            }
        }
        return result;
    }
}
class BasicFunctions
{
    public long min(long[] A)
    {
        long min = Long.MAX_VALUE;
        for(int i=0;i<A.length;i++)
        {
            min = Math.min(min, A[i]);
        }
        return min;
    }
    public long max(long[] A)
    {
        long max = Long.MAX_VALUE;
        for(int i=0;i<A.length;i++)
        {
            max = Math.max(max, A[i]);
        }
        return max;
    }
}
class Name implements Comparable<Name>
{
    int x;
    int y;

    public Name(int x, int y)
    {
        this.x = x;
        this.y = y;
    }
    @Override
    public int compareTo(Name ob)
    {
        if(this.x < ob.x)
            return -1;
        else if(this.x > ob.x)
            return 1;
        return 0;
    }
}
class Matrix
{
    long a;
    long b;
    long c;
    long d;

    public Matrix(long a, long b, long c, long d)
    {
        this.a = a;
        this.b = b;
        this.c = c;
        this.d = d;
    }
}
class Game implements Comparable<Game>
{
    long x;
    long y;

    public Game(long x, long y)
    {
        this.x = x;
        this.y = y;
    }

    @Override
    public int compareTo(Game ob)
    {
        if(this.x < ob.x)
            return -1;
        else if(this.x > ob.x)
            return 1;
        else
        {
            if(this.y < ob.y)
                return -1;
            else if(this.y > ob.y)
                return 1;
            else
                return 0;
        }
    }
}
class MergeSortInt
{
    // Merges two subarrays of arr[].
    // First subarray is arr[l..m]
    // Second subarray is arr[m+1..r]
    void merge(int arr[], int l, int m, int r) {
        // Find sizes of two subarrays to be merged
        int n1 = m - l + 1;
        int n2 = r - m;

        /* Create temp arrays */
        int L[] = new int[n1];
        int R[] = new int[n2];

        /*Copy data to temp arrays*/
        for (int i = 0; i < n1; ++i)
            L[i] = arr[l + i];
        for (int j = 0; j < n2; ++j)
            R[j] = arr[m + 1 + j];


        /* Merge the temp arrays */

        // Initial indexes of first and second subarrays
        int i = 0, j = 0;

        // Initial index of merged subarry array
        int k = l;
        while (i < n1 && j < n2) {
            if (L[i] <= R[j]) {
                arr[k] = L[i];
                i++;
            } else {
                arr[k] = R[j];
                j++;
            }
            k++;
        }

        /* Copy remaining elements of L[] if any */
        while (i < n1) {
            arr[k] = L[i];
            i++;
            k++;
        }

        /* Copy remaining elements of R[] if any */
        while (j < n2) {
            arr[k] = R[j];
            j++;
            k++;
        }
    }

    // Main function that sorts arr[l..r] using
    // merge()
    void sort(int arr[], int l, int r) {
        if (l < r) {
            // Find the middle point
            int m = (l + r) / 2;

            // Sort first and second halves
            sort(arr, l, m);
            sort(arr, m + 1, r);

            // Merge the sorted halves
            merge(arr, l, m, r);
        }
    }

}
class MergeSortLong
{
    // Merges two subarrays of arr[].
    // First subarray is arr[l..m]
    // Second subarray is arr[m+1..r]
    void merge(long arr[], int l, int m, int r) {
        // Find sizes of two subarrays to be merged
        int n1 = m - l + 1;
        int n2 = r - m;

        /* Create temp arrays */
        long L[] = new long[n1];
        long R[] = new long[n2];

        /*Copy data to temp arrays*/
        for (int i = 0; i < n1; ++i)
            L[i] = arr[l + i];
        for (int j = 0; j < n2; ++j)
            R[j] = arr[m + 1 + j];


        /* Merge the temp arrays */

        // Initial indexes of first and second subarrays
        int i = 0, j = 0;

        // Initial index of merged subarry array
        int k = l;
        while (i < n1 && j < n2) {
            if (L[i] <= R[j]) {
                arr[k] = L[i];
                i++;
            } else {
                arr[k] = R[j];
                j++;
            }
            k++;
        }

        /* Copy remaining elements of L[] if any */
        while (i < n1) {
            arr[k] = L[i];
            i++;
            k++;
        }

        /* Copy remaining elements of R[] if any */
        while (j < n2) {
            arr[k] = R[j];
            j++;
            k++;
        }
    }

    // Main function that sorts arr[l..r] using
    // merge()
    void sort(long arr[], int l, int r) {
        if (l < r) {
            // Find the middle point
            int m = (l + r) / 2;

            // Sort first and second halves
            sort(arr, l, m);
            sort(arr, m + 1, r);

            // Merge the sorted halves
            merge(arr, l, m, r);
        }
    }
}
class Node
{
    String a;
    String b;
    Node(String s1,String s2)
    {
        this.a = s1;
        this.b = s2;
    }
    @Override
    public boolean equals(Object ob)
    {
        if(ob == null)
            return false;
        if(!(ob instanceof Node))
            return false;
        if(ob == this)
            return true;
        Node obj = (Node)ob;
        if(this.a.equals(obj.a) && this.b.equals(obj.b))
            return true;
        return false;
    }

    @Override
    public int hashCode()
    {
        return (int)this.a.length();
    }
}
class Reader
{
    final private int BUFFER_SIZE = 1 << 16;
    private DataInputStream din;
    private byte[] buffer;
    private int bufferPointer, bytesRead;

    public Reader()
    {
        din = new DataInputStream(System.in);
        buffer = new byte[BUFFER_SIZE];
        bufferPointer = bytesRead = 0;
    }

    public Reader(String file_name) throws IOException
    {
        din = new DataInputStream(new FileInputStream(file_name));
        buffer = new byte[BUFFER_SIZE];
        bufferPointer = bytesRead = 0;
    }

    public String readLine() throws IOException
    {
        byte[] buf = new byte[64]; // line length
        int cnt = 0, c;
        while ((c = read()) != -1)
        {
            if (c == '\n')
                break;
            buf[cnt++] = (byte) c;
        }
        return new String(buf, 0, cnt);
    }

    public int nextInt() throws IOException
    {
        int ret = 0;
        byte c = read();
        while (c <= ' ')
            c = read();
        boolean neg = (c == '-');
        if (neg)
            c = read();
        do
        {
            ret = ret * 10 + c - '0';
        }  while ((c = read()) >= '0' && c <= '9');

        if (neg)
            return -ret;
        return ret;
    }

    public long nextLong() throws IOException
    {
        long ret = 0;
        byte c = read();
        while (c <= ' ')
            c = read();
        boolean neg = (c == '-');
        if (neg)
            c = read();
        do {
            ret = ret * 10 + c - '0';
        }
        while ((c = read()) >= '0' && c <= '9');
        if (neg)
            return -ret;
        return ret;
    }

    public double nextDouble() throws IOException
    {
        double ret = 0, div = 1;
        byte c = read();
        while (c <= ' ')
            c = read();
        boolean neg = (c == '-');
        if (neg)
            c = read();

        do {
            ret = ret * 10 + c - '0';
        }
        while ((c = read()) >= '0' && c <= '9');

        if (c == '.')
        {
            while ((c = read()) >= '0' && c <= '9')
            {
                ret += (c - '0') / (div *= 10);
            }
        }

        if (neg)
            return -ret;
        return ret;
    }

    private void fillBuffer() throws IOException
    {
        bytesRead = din.read(buffer, bufferPointer = 0, BUFFER_SIZE);
        if (bytesRead == -1)
            buffer[0] = -1;
    }

    private byte read() throws IOException
    {
        if (bufferPointer == bytesRead)
            fillBuffer();
        return buffer[bufferPointer++];
    }

    public void close() throws IOException
    {
        if (din == null)
            return;
        din.close();
    }
}
class FenwickTree
{
    public void update(long[] fenwickTree,long delta,int index)
    {
        index += 1;
        while(index < fenwickTree.length)
        {
            fenwickTree[index] += delta;
            index = index + (index & (-index));
        }
    }
    public long prefixSum(long[] fenwickTree,int index)
    {
        long sum = 0L;
        index += 1;
        while(index > 0)
        {
            sum += fenwickTree[index];
            index -= (index & (-index));
        }
        return sum;
    }
}
class SegmentTree
{
    public int nextPowerOfTwo(int num)
    {
        if(num == 0)
            return 1;
        if(num > 0 && (num & (num - 1)) == 0)
            return num;
        while((num &(num - 1)) > 0)
        {
            num = num & (num - 1);
        }
        return num << 1;
    }
    public int[] createSegmentTree(int[] input)
    {
        int np2 = nextPowerOfTwo(input.length);
        int[] segmentTree = new int[np2 * 2 - 1];

        for(int i=0;i<segmentTree.length;i++)
            segmentTree[i] = Integer.MIN_VALUE;

        constructSegmentTree(segmentTree,input,0,input.length-1,0);
        return segmentTree;

    }
    private void constructSegmentTree(int[] segmentTree,int[] input,int low,int high,int pos)
    {
        if(low == high)
        {
            segmentTree[pos] = input[low];
            return;
        }
        int mid = (low + high)/ 2;
        constructSegmentTree(segmentTree,input,low,mid,2*pos + 1);
        constructSegmentTree(segmentTree,input,mid+1,high,2*pos + 2);
        segmentTree[pos] = Math.max(segmentTree[2*pos + 1],segmentTree[2*pos + 2]);
    }
    public int rangeMinimumQuery(int []segmentTree,int qlow,int qhigh,int len)
    {
        return rangeMinimumQuery(segmentTree,0,len-1,qlow,qhigh,0);
    }
    private int rangeMinimumQuery(int segmentTree[],int low,int high,int qlow,int qhigh,int pos)
    {
        if(qlow <= low && qhigh >= high){
            return segmentTree[pos];
        }
        if(qlow > high || qhigh < low){
            return Integer.MIN_VALUE;
        }
        int mid = (low+high)/2;
        return Math.max(rangeMinimumQuery(segmentTree, low, mid, qlow, qhigh, 2 * pos + 1),
                rangeMinimumQuery(segmentTree, mid + 1, high, qlow, qhigh, 2 * pos + 2));
    }
}