You are given two integers a and b.

In one move, you can choose some integer k from 1 to 10 and add it to a or subtract it from a. In other words, you choose an integer k ∈ [1; 10] and perform a := a + k or a := a - k. You may use different values of k in different moves.

Your task is to find the minimum number of moves required to obtain b from a.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.

The only line of the test case contains two integers a and b (1 ≤ a, b ≤ 10^9).

Output

For each test case, print the answer: the minimum number of moves required to obtain b from a.

Example

Input


6
5 5
13 42
18 4
1337 420
123456789 1000000000
100500 9000


Output


0
3
2
92
87654322
9150

Note

In the first test case of the example, you don't need to do anything.

In the second test case of the example, the following sequence of moves can be applied: 13 → 23 → 32 → 42 (add 10, add 9, add 10).

In the third test case of the example, the following sequence of moves can be applied: 18 → 10 → 4 (subtract 8, subtract 6).
import sys
import math

# Constants
mod = 998244353

# Program Settings
cases = True


# Functions Settings
dynamic_factorial = False



# Pre-defined function
# Begin

# Testcase handler
def main(test_case = False):
    n = int(input()) if test_case else 1
    for _ in range(n):
        test()

# Binary method of power
def fast_pow(a:int, b:int):
    res = 1
    while b > 0:
        if b & 1:
            res *= a
        a *= a
        b >>= 1
    return res

# Combination of 2
def c2(n):
    return n * (n-1) // 2

# Get the list form of input
def get():
    return list(map(int, input().split()))

# Number of 1s in binary form
def bits(n: int):
    return list(bin(n)).count('1')

# For interactive problems
def flush():
    sys.stdout.flush()

# Print array and split it with space
def parr(arr):
    print(*arr, sep=' ')

# GCD (int a, int b)
# Return: value of GCD(a, b)
def gcd(a, b):
    while b:
        if b % a == 0:
            break
        tmp = a
        a = b % a
        b = tmp
    return a

# Extended GCD (int a, int b)
# Return: array of [GCD(a, b), [x0, y0]]
# Where a * x0 + b * y0 = 1
# If GCD(a, b) != 1 then return False
def ext_gcd(a: int, b: int):
    if (b == 0):
        return [a, [1, 0]]
 
    res = ext_gcd(b, a % b)
    g = res[0]
    if g != 1:
        return False
    x1 = res[1][0]
    y1 = res[1][1]
    x = y1
    y = x1 - y1 * (a // b)
 
    return [g, [x, y]]

# Get all different values of array a with their count
def get_set(a):
    res = {}
    for x in a:
        if x in res:
            res[x] += 1
        else:
            res[x] = 1
    return res

# Factorial
fact = {0: 1}
def factorial(n):
    if dynamic_factorial:
        if n not in fact:
            fact[n] = factorial(n-1) * n
        return fact[n]
    else:
        res = 1
        while n > 0:
            res = (res * n) % mod
            n -= 1
        return res

# Sum of array
def sum_of(a):
    res = 0
    for x in a:
        res = (res + x) % mod
    return res

# Prod of array
def prod_of(a):
    res = 1
    for x in a:
        res = (res * x) % mod
    return res

# End

def test():
    a, b = get()
    print((max(a-b, b-a)+9) // 10)

main(cases)