Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.

Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to be the maximum number of times that some number occurs in this array. He wants to choose the smallest subsegment of this array such that the beauty of it will be the same as the original array.

Help Amr by choosing the smallest subsegment possible.

Input

The first line contains one number n (1 ≤ n ≤ 105), the size of the array.

The second line contains n integers ai (1 ≤ ai ≤ 106), representing elements of the array.

Output

Output two integers l, r (1 ≤ l ≤ r ≤ n), the beginning and the end of the subsegment chosen respectively.

If there are several possible answers you may output any of them. 

Examples

Input

5
1 1 2 2 1


Output

1 5

Input

5
1 2 2 3 1


Output

2 3

Input

6
1 2 2 1 1 2


Output

1 5

Note

A subsegment B of an array A from l to r is an array of size r - l + 1 where Bi = Al + i - 1 for all 1 ≤ i ≤ r - l + 1
#!/usr/bin/env python
#-*- coding:utf-8 -*-

import sys, math, random, operator
from string import ascii_lowercase
from string import ascii_uppercase
from fractions import Fraction, gcd
from decimal import Decimal, getcontext
from itertools import product, permutations, combinations
from Queue import Queue, PriorityQueue
from collections import deque, defaultdict, Counter
getcontext().prec = 100

MOD = 10**9 + 7
INF = float("+inf")

if sys.subversion[0] != "CPython":  # PyPy?
    raw_input = lambda: sys.stdin.readline().rstrip()
pr = lambda *args: sys.stdout.write(" ".join(str(x) for x in args) + "\n")

read_str = raw_input
read_strs = lambda: raw_input().split()
read_int = lambda: int(raw_input())
read_ints = lambda: map(int, raw_input().split())
read_float = lambda: float(raw_input())
read_floats = lambda: map(float, raw_input().split())

"---------------------------------------------------------------"

n = read_int()
arr = read_ints()
cnt = {}
mxcnt = 0
left = {}
right = {}
for i, x in enumerate(arr):
    cnt.setdefault(x, 0)
    cnt[x] += 1
    if x not in left:
        left[x] = i
    right[x] = i
    mxcnt = max(mxcnt, cnt[x])

ans = n
al = 0
ar = n - 1
for x, c in cnt.items():
    if c == mxcnt:
        dist = right[x] - left[x] + 1
        if dist < ans:
            ans = dist
            al = left[x]
            ar = right[x]

print al + 1, ar + 1

# print ans

