Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderings that achieve it.

Constraints

* 1\leq N \leq 2 \times 10^5
* 1\leq A_i,B_i \leq N
* A and B are each sorted in the ascending order.
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N
A_1 A_2 \cdots A_N
B_1 B_2 \cdots B_N


Output

If there exist no reorderings that satisfy the condition, print `No`.

If there exists a reordering that satisfies the condition, print `Yes` on the first line. After that, print a reordering of B on the second line, separating terms with a whitespace.

If there are multiple reorderings that satisfy the condition, you can print any of them.

Examples

Input

6
1 1 1 2 2 3
1 1 1 2 2 3


Output

Yes
2 2 3 1 1 1


Input

3
1 1 2
1 1 3


Output

No


Input

4
1 1 2 3
1 2 3 3


Output

Yes
3 3 1 2
n = int(input())
a = list(map(int,input().split()))
b = list(map(int,input().split()))
b = b[::-1]
s = 0
e = 0
for i in range(n):
    if s == 0 and a[i] == b[i]:
        s = i+1
    if s > 0 and a[i] != b[i]:
        e = i+1
        break
if s == 0:
    print("Yes")
    print(*b)
    quit()
cl = a[s-1]
k = e-s
j = 0
for i in range(n):
    if s-1 <= i < e-1:
        continue
    if cl != b[i] and cl != a[i]:
        b[s-1+j] = b[i]
        b[i] = cl
        j += 1
    if j == k:
        break
for i in range(n):
    if a[i] == b[i]:
        print("No")
        quit()
print("Yes")
print(*b)