Given an integer n, find the maximum value of integer k such that the following condition holds: 

n & (n-1) & (n-2) & (n-3) & ... (k) = 0  where & denotes the [bitwise AND operation.](https://en.wikipedia.org/wiki/Bitwise_operation#AND)

Input

The first line contains a single integer t (1 ≤ t ≤ 3 ⋅ 10^4). Then t test cases follow.

The first line of each test case contains a single integer n (1 ≤ n ≤ 10^9).

Output

For each test case, output a single integer — the required integer k.

Example

Input


3
2
5
17


Output


1
3
15

Note

In the first testcase, the maximum value for which the continuous & operation gives 0 value, is 1.

In the second testcase, the maximum value for which the continuous & operation gives 0 value, is 3. No value greater then 3, say for example 4, will give the & sum 0. 

  * 5   \&   4 ≠ 0, 
  * 5   \&   4   \&   3 = 0. 



Hence, 3 is the answer.
import java.io.*;
import java.util.*;

public class Main {
    /************************************************** FAST INPUT IMPLEMENTATION *********************************************/
    static class Reader {
        final private int BUFFER_SIZE = 1 << 16;
        private DataInputStream din;
        private byte[] buffer;
        private int bufferPointer, bytesRead;
        private int line_length;

        public Reader(int ll) {
            din = new DataInputStream(System.in);
            buffer = new byte[BUFFER_SIZE];
            bufferPointer = bytesRead = 0;
            line_length = ll;
        }

        public Reader(String file_name) throws IOException {
            din = new DataInputStream(
                    new FileInputStream(file_name));
            buffer = new byte[BUFFER_SIZE];
            bufferPointer = bytesRead = 0;
        }

        public String readLine() throws IOException {
            byte[] buf = new byte[line_length]; // line length
            int cnt = 0, c;
            while ((c = read()) != -1) {
                if (c == '\n') {
                    if (cnt != 0) {
                        break;
                    } else {
                        continue;
                    }
                }
                buf[cnt++] = (byte) c;
            }
            return new String(buf, 0, cnt);
        }

        public int nextInt() throws IOException {
            int ret = 0;
            byte c = read();
            while (c <= ' ') {
                c = read();
            }
            boolean neg = (c == '-');
            if (neg)
                c = read();
            do {
                ret = ret * 10 + c - '0';
            } while ((c = read()) >= '0' && c <= '9');

            if (neg)
                return -ret;
            return ret;
        }

        public long nextLong() throws IOException {
            long ret = 0;
            byte c = read();
            while (c <= ' ')
                c = read();
            boolean neg = (c == '-');
            if (neg)
                c = read();
            do {
                ret = ret * 10 + c - '0';
            } while ((c = read()) >= '0' && c <= '9');
            if (neg)
                return -ret;
            return ret;
        }

        public double nextDouble() throws IOException {
            double ret = 0, div = 1;
            byte c = read();
            while (c <= ' ')
                c = read();
            boolean neg = (c == '-');
            if (neg)
                c = read();

            do {
                ret = ret * 10 + c - '0';
            } while ((c = read()) >= '0' && c <= '9');

            if (c == '.') {
                while ((c = read()) >= '0' && c <= '9') {
                    ret += (c - '0') / (div *= 10);
                }
            }

            if (neg)
                return -ret;
            return ret;
        }

        private void fillBuffer() throws IOException {
            bytesRead = din.read(buffer, bufferPointer = 0,
                    BUFFER_SIZE);
            if (bytesRead == -1)
                buffer[0] = -1;
        }

        private byte read() throws IOException {
            if (bufferPointer == bytesRead)
                fillBuffer();
            return buffer[bufferPointer++];
        }

        public void close() throws IOException {
            if (din == null)
                return;
            din.close();
        }
    }
    /********************************************************* USE FULL CODE **************************************************/

    /* https://www.geeksforgeeks.org/java-tricks-competitive-programming-java-8/ */
    static class Util{
        public static final int MOD=1000000007;
        public static <T>  void swap(T[] arr,int i,int j){
            T temp=arr[i];
            arr[i]=arr[j];
            arr[j]=temp;
        }
        public static <T> void printArray(T[] arr){
            for(int i=0;i<arr.length;i++){
                System.out.print(arr[i]);
            }
            System.out.println("");
        }

    }

    /***************************************************************************************************************************
     *********************************************************** MAIN CODE ******************************************************
     ****************************************************************************************************************************/

    public static void main(String[] args) throws IOException{
        Reader rd = new Reader(1000000);  //Enter Required Line Length
        int t=rd.nextInt();
        while (t-->0){
            long val=rd.nextLong();
            solve(val);
        }




    }

    /********************************************************* MAIN LOGIC HERE ****************************************************/

    public static void solve(long val) {
        long ans=val;
        while ((ans & (ans-1)) !=0){
            ans=ans & (ans-1);
        }
        System.out.println(ans-1);
    }

}