There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.

You want to split all athletes into two teams. Each team must have at least one athlete, and each athlete must be exactly in one team.

You want the strongest athlete from the first team to differ as little as possible from the weakest athlete from the second team. Formally, you want to split the athletes into two teams A and B so that the value |max(A) - min(B)| is as small as possible, where max(A) is the maximum strength of an athlete from team A, and min(B) is the minimum strength of an athlete from team B.

For example, if n=5 and the strength of the athletes is s=[3, 1, 2, 6, 4], then one of the possible split into teams is: 

  * first team: A = [1, 2, 4], 
  * second team: B = [3, 6]. 



In this case, the value |max(A) - min(B)| will be equal to |4-3|=1. This example illustrates one of the ways of optimal split into two teams.

Print the minimum value |max(A) - min(B)|.

Input

The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases in the input. Then t test cases follow.

Each test case consists of two lines. 

The first line contains positive integer n (2 ≤ n ≤ 50) — number of athletes. 

The second line contains n positive integers s_1, s_2, …, s_n (1 ≤ s_i ≤ 1000), where s_i — is the strength of the i-th athlete. Please note that s values may not be distinct.

Output

For each test case print one integer — the minimum value of |max(A) - min(B)| with the optimal split of all athletes into two teams. Each of the athletes must be a member of exactly one of the two teams.

Example

Input


5
5
3 1 2 6 4
6
2 1 3 2 4 3
4
7 9 3 1
2
1 1000
3
100 150 200


Output


1
0
2
999
50

Note

The first test case was explained in the statement. In the second test case, one of the optimal splits is A=[2, 1], B=[3, 2, 4, 3], so the answer is |2-2|=0.
#qn given an arr of size n for every  i position find a min j such that j>i and arr[j]>arr[i]
#it prints the position of the nearest .
import sys
input = sys.stdin.readline
 #qn given an arr of size n for every  i position find a min j such that j>i and arr[j]>arr[i]
#it prints the position of the nearest .
# import sys
import heapq 
import copy
import math
import decimal
from decimal import *
#heapq.heapify(li) 
#
#heapq.heappush(li,4) 
#
#heapq.heappop(li)
#
# &	Bitwise AND Operator	10 & 7 = 2
# |	Bitwise OR Operator	10 | 7 = 15
# ^	Bitwise XOR Operator	10 ^ 7 = 13
 
# <<	Bitwise Left Shift operator	10<<2 = 40
# >>	Bitwise Right Shift Operator
# '''############ ---- Input Functions ---- #######Start#####'''

 
class Node:
    def _init_(self,val):
        self.data = val
        self.left = None
        self.right = None
##to initialize wire : object_name= node(val)##to create a new node
## can also be used to create linked list
class fen_tree:
    """Implementation of a Binary Indexed Tree (Fennwick Tree)"""
    
    #def __init__(self, list):
    #    """Initialize BIT with list in O(n*log(n))"""
    #    self.array = [0] * (len(list) + 1)
    #    for idx, val in enumerate(list):
    #        self.update(idx, val)
 
    def __init__(self, list):
        """"Initialize BIT with list in O(n)"""
        self.array = [0] + list
        for idx in range(1, len(self.array)):
            idx2 = idx + (idx & -idx)
            if idx2 < len(self.array):
                self.array[idx2] += self.array[idx]
 
    def prefix_query(self, idx):
        """Computes prefix sum of up to including the idx-th element"""
        # idx += 1
        result = 0
        while idx:
            result += self.array[idx]
            idx -= idx & -idx
        return result
    def prints(self):
        print(self.array)
        return
        # for i in self.array:
        #     print(i,end = " ")
        # return 
    def range_query(self, from_idx, to_idx):
        """Computes the range sum between two indices (both inclusive)"""
        return self.prefix_query(to_idx) - self.prefix_query(from_idx - 1)
 
    def update(self, idx, add):
        """Add a value to the idx-th element"""
        # idx += 1
        while idx < len(self.array):
            self.array[idx] += add
            idx += idx & -idx
 
 
def pre_sum(arr):
	#"""returns the prefix sum inclusive ie ith position in ans  represent sum from 0 to ith position"""
	p = [0]
	for i in arr:
		p.append(p[-1] + i)
	p.pop(0)
	return p
 
def pre_back(arr):
	#"""returns the prefix sum inclusive ie ith position in ans  represent sum from 0 to ith position"""
	p = [0]
	for i in arr:
		p.append(p[-1] + i)
	p.pop(0)
	return p
def bin_search(arr,l,r,val):#strickly greater
	if arr[r] <= val:
		return r+1	
	if r-l < 2:
		if arr[l]>val:
			return l
		else:
			return r
	mid = int((l+r)/2)
	if arr[mid] <= val:
		return bin_search(arr,mid,r,val)
	else:
		return bin_search(arr,l,mid,val)
def search_leftmost(arr,val):
	def helper(arr,l,r,val):
		# print(arr)
		print(l,r)
		if arr[l] == val:
			return l
		if r -l <=1:
			if arr[r] == val:
				return r
			else:
				print("not found")
				return
		mid = int((r+l)/2)
		if arr[mid] >= val:
			return helper(arr,l,mid,val)
		else:
			return helper(arr,mid,r,val)
	return helper(arr,0,len(arr)-1,val)
def search_rightmost(arr,val):
	def helper(arr,l,r,val):
		# print(arr)
		print(l,r)
		if arr[r] == val:
			return r
		if r -l <=1:
			if arr[l] == val:
				return r
			else:
				print("not found")
				return
		mid = int((r+l)/2)
		if arr[mid] > val:
			return helper(arr,l,mid,val)
		else:
			return helper(arr,mid,r,val)
	return helper(arr,0,len(arr)-1,val)
def preorder_postorder(root,paths,parent,left,level):
	# if len(paths[node]) ==1 and node !=1 :
	# 	return [parent,left,level]
	l = 0
	queue = [root]
	while(queue!=[]):
		node = queue[-1]
		# print(queue,node)
		flag = 0
		for i in paths[node]:
			if i!=parent[node] and level[i]== sys.maxsize:
				parent[i] = node
				level[i] = level[node]+1
				flag = 1
				queue.append(i)
		if flag == 0:
			left[parent[node]] +=(1+left[node])
			queue.pop()
	# 		[parent,left,level] = helper(i,paths,parent,left,level)
	# 		l = left[i] + l +1
	# left[node] = l
	return [parent,left,level]
def nCr(n, r, p): 
    # initialize numerator 
    # and denominator 
	if r == 0:
		return 1
	num = den = 1 
	for i in range(r): 
		num = (num * (n - i)) % p 
		den = (den * (i + 1)) % p 
	return (num * pow(den,p - 2, p)) % p 
def inp():
	return(int(input()))
def inlt(): 
	return(list(map(int,input().split())))
def insr():
	s = input()
	return(list(s[:len(s) - 1]))
def invr():
	return(map(int,input().split()))
 ############ ---- Input Functions ---- #######End
 # #####   
def pr_list(a):
	print(*a, sep=" ")
def main():
	tests =  inp()
	# tests = 1
	# mod = 1000000007
	mod = 998244353
	limit = 10**18
	# nCrModp(1332,42,mod)
	# return
	for test in range(tests):
		n = inp()
		a = inlt()
		a.sort()
		ans = sys.maxsize
		for i in range(1,n):
			ans = min(abs(a[i] - a[i-1]), ans)
		print(ans)







		# print(ans)
		# a = 499979
		
		# print(Decimal(a*h + (a-1) *c)/Decimal(2*a - 1),(a*h + (a-1) *c)/(2*a - 1))
		# a = 499981
		# print(Decimal(a*h + (a-1) *c)/Decimal(2*a - 1),(a*h + (a-1) *c)/(2*a - 1))
		
 
if __name__== "__main__":
	main()