There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.

You want to split all athletes into two teams. Each team must have at least one athlete, and each athlete must be exactly in one team.

You want the strongest athlete from the first team to differ as little as possible from the weakest athlete from the second team. Formally, you want to split the athletes into two teams A and B so that the value |max(A) - min(B)| is as small as possible, where max(A) is the maximum strength of an athlete from team A, and min(B) is the minimum strength of an athlete from team B.

For example, if n=5 and the strength of the athletes is s=[3, 1, 2, 6, 4], then one of the possible split into teams is: 

  * first team: A = [1, 2, 4], 
  * second team: B = [3, 6]. 



In this case, the value |max(A) - min(B)| will be equal to |4-3|=1. This example illustrates one of the ways of optimal split into two teams.

Print the minimum value |max(A) - min(B)|.

Input

The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases in the input. Then t test cases follow.

Each test case consists of two lines. 

The first line contains positive integer n (2 ≤ n ≤ 50) — number of athletes. 

The second line contains n positive integers s_1, s_2, …, s_n (1 ≤ s_i ≤ 1000), where s_i — is the strength of the i-th athlete. Please note that s values may not be distinct.

Output

For each test case print one integer — the minimum value of |max(A) - min(B)| with the optimal split of all athletes into two teams. Each of the athletes must be a member of exactly one of the two teams.

Example

Input


5
5
3 1 2 6 4
6
2 1 3 2 4 3
4
7 9 3 1
2
1 1000
3
100 150 200


Output


1
0
2
999
50

Note

The first test case was explained in the statement. In the second test case, one of the optimal splits is A=[2, 1], B=[3, 2, 4, 3], so the answer is |2-2|=0.
from math import *
from copy import *
from string import *				# alpha = ascii_lowercase
from random import *
from sys import stdin
from sys import maxsize
from operator import *				# d = sorted(d.items(), key=itemgetter(1))
from itertools import *
from collections import Counter		# d = dict(Counter(l))
import math
import math
import time

def bin1(l,r,k,t,b,val,ans):
	if(l>r):
		return ans
	else:
		mid=(l+r)//2
		v=k**mid
		if(v==val):
			return v
		elif(v>val):
			ans=mid
			return bin1(mid+1,r,k,t,b,val,ans)
		else:
			return bin1(l,mid-1,k,t,b,val,ans)
		
def bin2(l,r,k,t,b,val,ans):
	if(l>r):
		return ans
	else:
		mid=(l+r)//2
		v=t*(k**mid)+b*(mid)
		if(v==val):
			return v
		elif(v>val):
			ans=mid
			return bin2(l,mid-1,k,t,b,val,ans)
		else:
			return bin2(mid+1,r,k,t,b,val,ans)

def SieveOfEratosthenes(n): 
      
    # Create a boolean array "prime[0..n]" and initialize 
    #  all entries it as true. A value in prime[i] will 
    # finally be false if i is Not a prime, else true. 
    prime = [-1 for i in range(n+1)] 
    p = 2
    while (p * p <= n): 
          
        # If prime[p] is not changed, then it is a prime 
        if (prime[p] == -1): 
              
            # Update all multiples of p 
            for i in range(p * p, n+1, p): 
                prime[i] = p
        p += 1
    for i in range(2,n+1):
    	if(prime[i]==-1):
    		prime[i]=i
    return prime
def bin(l,r,ll,val):
	if(l>r):
		return -1
	else:
		mid=(l+r)//2
		if(val>=ll[mid][0] and val<=ll[mid][1]):
			return mid
		elif(val<ll[mid][0]):
			return bin(l,mid-1,ll,val)
		else:
			return bin(mid+1,r,ll,val)
def deci(n):
	s=""
	while(n!=0):
		if(n%2==0):
			n=n//2
			s="0"+s
		else:
			n=n//2
			s="1"+s
	return s
def diff(s1,s2):
	if(len(s1)<len(s2)):
		v=len(s1)
		while(v!=len(s2)):
			s1="0"+s1
			v=v+1
	else:
		v=len(s2)
		while(v!=len(s1)):
			s2="0"+s2
			v=v+1
	c=0
	for i in range(len(s1)):
		if(s1[i:i+1]!=s2[i:i+1]):
			c=c+1
	return c
from sys import stdin, stdout 
def fac(a,b):
	v=a
	while(a!=b):
		v*=a-1
		a=a-1
	return v
def bino(l,r,n):
	if(l>r):
		return -1
	else:
		mid=(l+r)//2
		val1=math.log((n/mid)+1,2)
		val2=int(val1)
		if(val1==val2):
			return val1
		elif(val1<1.0):
			return bino(l,mid-1,n)
		else:
			return bino(mid+1,r,n)

def binary(l,r,val,ans):
	if(l>r):
		return -1
	else:
		mid=(l+r)//2
		v=val**5-mid**5
		print(v)
		if(v==ans):
			print("HOHOHOH")
			return mid
		elif(v<ans):
			return binary(mid+1,r,val,ans)
		else:
			return binary(l,mid-1,val,ans)
def check(n):
	v=1
	while(n!=0):
		if(n%10==0 or n%10==1):
			n=n//10
		else:
			v=0
			break
	return v
def stairs(n,m,val,c,l):
	if(val>n):
		return 100000
	elif(val==n):
		if(l[val]!=-1):
			return l[val]
		elif(c%m==0):
			l[val]=c
			return l[val];
		else:
			l[val]=100000
			return l[val]
	else:
		# if(l[val]!=-1):
		# 	return l[val]
		# else:
		l[val]=min(stairs(n,m,val+1,c+1,l),stairs(n,m,val+2,c+1,l))
		return l[val]
def fact(n):
	if(n==0 or n==1):
		return 1
	else:
		return n*fact(n-1)

def some(n):
	s=0
	while(n!=0):
		s+=fact(n%10)
		n//=10
	return s
def bin(l,r,val,ll):
    if(l>r):
        return -1
    else:
        mid=(l+r)//2
        if(ll[mid]==val):
            return mid
        elif(ll[mid]>val):
            return bin(l,mid-1,val,ll)
        else:
            return bin(mid+1,r,val,ll)
def fn(n):
	c=-1
	for i in range(2,int(sqrt(n))+1):
		if(n%2==0):
			c=i
			break
	if(c==-1):
		c=n
	return c
def check(n):
	val=0
	while(n!=0):
		if(n%10>1):
			val=-1
			break
		n=n//10
	return val


if __name__ == '__main__':
	t=int(input())
	for i in range(t):
		n=int(input())
		l=sorted(list(map(int,input().split())))
		mini=100000
		for j in range(1,n):
			if(mini>l[j]-l[j-1]):
				mini=l[j]-l[j-1]
		print(mini)