You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

* In the i-th operation, you replace every element whose value is B_{i} with C_{i}.



For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

* All values in input are integers.
* 1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}
* B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:


N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}


Output

Print Q integers S_{i} to Standard Output in the following format:


S_{1}
S_{2}
\vdots
S_{Q}


Note that S_{i} may not fit into a 32-bit integer.

Examples

Input

4
1 2 3 4
3
1 2
3 4
2 4


Output

11
12
16


Input

4
1 1 1 1
3
1 2
2 1
3 5


Output

8
4
4


Input

2
1 2
3
1 100
2 100
100 1000


Output

102
200
2000
import java.io.*;
import java.util.*;
public class Main{
	public static void main(String args[]) throws IOException{
               BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));	
		int n= Integer.parseInt(reader.readLine());
		long[] list = Arrays.stream(reader.readLine().split(" ")).mapToLong(Long::parseLong).toArray();
		int q = Integer.parseInt(reader.readLine());
		HashMap<Long,Long> hm = new HashMap<>();
		long sum = 0;
		for(long o:list){
			hm.put(o,hm.getOrDefault(o,(long)0)+1);
			sum+=o;
		}
		for(int i=0;i<q;i++){
			String[] pol = reader.readLine().split(" ");
			long a = Long.parseLong(pol[0]);
			long b = Long.parseLong(pol[1]);
			if(hm.containsKey(a)){
				long p = hm.get(a);
				hm.put(b,hm.getOrDefault(b,(long)0)+p);
				hm.remove(a);
				sum-=p*a;
				sum+=p*b;
			}
			System.out.println(sum);
		}		
	}
}
