If there is an integer not less than 0 satisfying the following conditions, print the smallest such integer; otherwise, print `-1`.

* The integer has exactly N digits in base ten. (We assume 0 to be a 1-digit integer. For other integers, leading zeros are not allowed.)
* The s_i-th digit from the left is c_i. \left(i = 1, 2, \cdots, M\right)

Constraints

* All values in input are integers.
* 1 \leq N \leq 3
* 0 \leq M \leq 5
* 1 \leq s_i \leq N
* 0 \leq c_i \leq 9

Input

Input is given from Standard Input in the following format:


N M
s_1 c_1
\vdots
s_M c_M


Output

Print the answer.

Examples

Input

3 3
1 7
3 2
1 7


Output

702


Input

3 2
2 1
2 3


Output

-1


Input

3 1
1 0


Output

-1
import java.util.*;
import java.math.*;

public class Main {
  public static void main(String[] args) {
    Scanner sc = new Scanner(System.in);
    int N = sc.nextInt();
    int M = sc.nextInt();
    int[] s = new int[M];
    int[] c = new int[M];
    for (int i = 0; i < M; i++) {
      s[i] = sc.nextInt();
      c[i] = sc.nextInt();

    }
    sc.close();

    int ans = -1;

    int n0 = (int) Math.pow(10, N - 1);
    if (n0 == 1) n0 = 0;
    int n1 = (int) Math.pow(10, N) - 1;
    for (int i = n0; i <= n1; i++) {
      String v = String.valueOf(i);
      boolean m = true;
      for (int j = 0; j < M; j++) {
        int d = v.charAt(s[j] - 1) - '0';
        if (c[j] != d) {
          m = false;
          break;
        }
      }
      if (m) {
        ans = i;
        break;
      }
    }

    System.out.println(ans);
  }
}