Assume that a, b, and n are all positive integers. Let f (i) be the i-th fraction of the fraction a / b (0 ≤ f (i) ≤ 9). At this time, let s be the sum of f (i) from i = 1 to n.

s = f (1) + f (2) + ... + f (n)


Create a program that reads a, b, n, outputs s, and exits.



Input

The input consists of multiple datasets. For each dataset, three integers a (1 ≤ a ≤ 1000), b (1 ≤ b ≤ 10000), n (1 ≤ n ≤ 100) are given on one line, separated by blanks.

The number of datasets does not exceed 100.

Output

Prints s on one line for each dataset.

Example

Input

1 2 3
2 3 4
5 4 3
4 3 2


Output

5
24
7
6
#include <cstdio>
#include <algorithm>
#include <iostream>
#include <vector>
#include <string.h>
#include <math.h>
#include <time.h>
#include <stdlib.h>
using namespace std;



int main(){
	int a,b,n,sum;
	while( scanf("%d %d %d",&a,&b,&n) != EOF){
		a = a%b;
		sum = 0;
		for(int i=0;i<n;i++){
			a *= 10;
			sum += a/b;
			a = a%b;
			if(a==0)break;
		}
		printf("%d\n",sum);
	}
			
	return 0;
}
