Lunar New Year is approaching, and you bought a matrix with lots of "crosses".

This matrix M of size n × n contains only 'X' and '.' (without quotes). The element in the i-th row and the j-th column (i, j) is defined as M(i, j), where 1 ≤ i, j ≤ n. We define a cross appearing in the i-th row and the j-th column (1 < i, j < n) if and only if M(i, j) = M(i - 1, j - 1) = M(i - 1, j + 1) = M(i + 1, j - 1) = M(i + 1, j + 1) =  'X'.

The following figure illustrates a cross appearing at position (2, 2) in a 3 × 3 matrix.
    
    
      
    X.X  
    .X.  
    X.X  
    

Your task is to find out the number of crosses in the given matrix M. Two crosses are different if and only if they appear in different rows or columns.

Input

The first line contains only one positive integer n (1 ≤ n ≤ 500), denoting the size of the matrix M.

The following n lines illustrate the matrix M. Each line contains exactly n characters, each of them is 'X' or '.'. The j-th element in the i-th line represents M(i, j), where 1 ≤ i, j ≤ n.

Output

Output a single line containing only one integer number k — the number of crosses in the given matrix M.

Examples

Input


5
.....
.XXX.
.XXX.
.XXX.
.....


Output


1


Input


2
XX
XX


Output


0


Input


6
......
X.X.X.
.X.X.X
X.X.X.
.X.X.X
......


Output


4

Note

In the first sample, a cross appears at (3, 3), so the answer is 1.

In the second sample, no crosses appear since n < 3, so the answer is 0.

In the third sample, crosses appear at (3, 2), (3, 4), (4, 3), (4, 5), so the answer is 4.
"Template made by : https://codeforces.com/profile/c1729 , github repo : https://github.com/cheran-senthil/PyRival"
from __future__ import division, print_function
import bisect
import math
import itertools
import sys
from atexit import register

if sys.version_info[0] < 3:
    from io import BytesIO as stream
else:
    from io import StringIO as stream


if sys.version_info[0] < 3:
    class dict(dict):
        """dict() -> new empty dictionary"""
        def items(self):
            """D.items() -> a set-like object providing a view on D's items"""
            return dict.iteritems(self)

        def keys(self):
            """D.keys() -> a set-like object providing a view on D's keys"""
            return dict.iterkeys(self)

        def values(self):
            """D.values() -> an object providing a view on D's values"""
            return dict.itervalues(self)

    input = raw_input
    range = xrange

    filter = itertools.ifilter
    map = itertools.imap
    zip = itertools.izip


def sync_with_stdio(sync=True):
    """Set whether the standard Python streams are allowed to buffer their I/O.

    Args:
        sync (bool, optional): The new synchronization setting.

    """
    global input, flush

    if sync:
        flush = sys.stdout.flush
    else:
        sys.stdin = stream(sys.stdin.read())
        input = lambda: sys.stdin.readline().rstrip('\r\n')

        sys.stdout = stream()
        register(lambda: sys.__stdout__.write(sys.stdout.getvalue()))

def main():
    n=int(input())
    l1=[]
    count=0
    for i in range(0,n):
        s=input()
        l1.append(s)
    for i in range(1,n-1):
        for j in range(1,n-1):
            if l1[i][j]=='X':
                if l1[i+1][j+1]=='X' and l1[i+1][j-1]=='X' and l1[i-1][j+1]=='X' and l1[i-1][j-1]=='X':
                    count+=1
    print(count)
            
if __name__ == '__main__':
    sync_with_stdio(False)
    main()