You have a digit sequence S of length 4. You are wondering which of the following formats S is in:

* YYMM format: the last two digits of the year and the two-digit representation of the month (example: `01` for January), concatenated in this order
* MMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order



If S is valid in only YYMM format, print `YYMM`; if S is valid in only MMYY format, print `MMYY`; if S is valid in both formats, print `AMBIGUOUS`; if S is valid in neither format, print `NA`.

Constraints

* S is a digit sequence of length 4.

Input

Input is given from Standard Input in the following format:


S


Output

Print the specified string: `YYMM`, `MMYY`, `AMBIGUOUS` or `NA`.

Examples

Input

1905


Output

YYMM


Input

0112


Output

AMBIGUOUS


Input

1700


Output

NA
#include <bits/stdc++.h>
using namespace std;

int main(){
	int s;
	cin>>s;
	int b=s%100,a=(s-b)/100;
	if(a<=12&&a>0&&b<=12&&b>0) cout<<"AMBIGUOUS";
	if(a<=12&&a>0&&(b>12||b==0)) cout<<"MMYY";
	if((a>12||a==0)&&(b<=12&&b>0)) cout<<"YYMM";
	if((a>12||a==0)&&(b>12||b==0)) cout<<"NA"; 
	return 0;
}
