There are N children, numbered 1, 2, \ldots, N.

They have decided to share K candies among themselves. Here, for each i (1 \leq i \leq N), Child i must receive between 0 and a_i candies (inclusive). Also, no candies should be left over.

Find the number of ways for them to share candies, modulo 10^9 + 7. Here, two ways are said to be different when there exists a child who receives a different number of candies.

Constraints

* All values in input are integers.
* 1 \leq N \leq 100
* 0 \leq K \leq 10^5
* 0 \leq a_i \leq K

Input

Input is given from Standard Input in the following format:


N K
a_1 a_2 \ldots a_N


Output

Print the number of ways for the children to share candies, modulo 10^9 + 7.

Examples

Input

3 4
1 2 3


Output

5


Input

1 10
9


Output

0


Input

2 0
0 0


Output

1


Input

4 100000
100000 100000 100000 100000


Output

665683269
def p_m():
    n, k = map(int, input().split())
    *a, = map(int, input().split())
    mod = 10 ** 9 + 7
    # dp[i][j]はi番目の子にj個の飴を配る方法が何通りかどうか
    dp = [[0] * (k + 1) for _ in range(n + 1)]
    for i in range(n + 1):
        dp[i][0] = 1

    for i in range(1, n + 1):
        for j in range(1, k + 1):
            if j - 1 - a[i - 1] >= 0:
                dp[i][j] = (dp[i - 1][j] + dp[i][j - 1] - dp[i - 1][j - 1 - a[i - 1]]) % mod
            else:
                dp[i][j] = (dp[i - 1][j] + dp[i][j - 1]) % mod
    print(dp[n][k])


if __name__ == '__main__':
    p_m()
