If there is an integer not less than 0 satisfying the following conditions, print the smallest such integer; otherwise, print `-1`.

* The integer has exactly N digits in base ten. (We assume 0 to be a 1-digit integer. For other integers, leading zeros are not allowed.)
* The s_i-th digit from the left is c_i. \left(i = 1, 2, \cdots, M\right)

Constraints

* All values in input are integers.
* 1 \leq N \leq 3
* 0 \leq M \leq 5
* 1 \leq s_i \leq N
* 0 \leq c_i \leq 9

Input

Input is given from Standard Input in the following format:


N M
s_1 c_1
\vdots
s_M c_M


Output

Print the answer.

Examples

Input

3 3
1 7
3 2
1 7


Output

702


Input

3 2
2 1
2 3


Output

-1


Input

3 1
1 0


Output

-1
#include <bits/stdc++.h>
using namespace std;
int main() {
    int N,M; cin >> N >> M;
    int ans = -1;
    vector<int> s(M);
    vector<char> c(M);
    for (int i=0;i<M;i++) cin >> s[i] >> c[i];
    for (int i = (N==1) ? 0 : pow(10, N-1);i<pow(10,N);i++){
        string x = to_string(i);
        bool can = true;
        for (int j=0;j<M;j++){
            if (x[s[j]-1]!=c[j]) can = false;
        }
        if (can) {
            ans = i;
            break;
        }
    }
    cout << ans << endl;
    return 0;
}