Lunar New Year is approaching, and you bought a matrix with lots of "crosses".

This matrix M of size n × n contains only 'X' and '.' (without quotes). The element in the i-th row and the j-th column (i, j) is defined as M(i, j), where 1 ≤ i, j ≤ n. We define a cross appearing in the i-th row and the j-th column (1 < i, j < n) if and only if M(i, j) = M(i - 1, j - 1) = M(i - 1, j + 1) = M(i + 1, j - 1) = M(i + 1, j + 1) =  'X'.

The following figure illustrates a cross appearing at position (2, 2) in a 3 × 3 matrix.
    
    
      
    X.X  
    .X.  
    X.X  
    

Your task is to find out the number of crosses in the given matrix M. Two crosses are different if and only if they appear in different rows or columns.

Input

The first line contains only one positive integer n (1 ≤ n ≤ 500), denoting the size of the matrix M.

The following n lines illustrate the matrix M. Each line contains exactly n characters, each of them is 'X' or '.'. The j-th element in the i-th line represents M(i, j), where 1 ≤ i, j ≤ n.

Output

Output a single line containing only one integer number k — the number of crosses in the given matrix M.

Examples

Input


5
.....
.XXX.
.XXX.
.XXX.
.....


Output


1


Input


2
XX
XX


Output


0


Input


6
......
X.X.X.
.X.X.X
X.X.X.
.X.X.X
......


Output


4

Note

In the first sample, a cross appears at (3, 3), so the answer is 1.

In the second sample, no crosses appear since n < 3, so the answer is 0.

In the third sample, crosses appear at (3, 2), (3, 4), (4, 3), (4, 5), so the answer is 4.
#include <bits/stdc++.h>
#pragma GCC optimize("Ofast")
#pragma GCC optimize("unroll-loops")
using namespace std;
template <typename X>
inline X abs(const X& a) {
  return a < 0 ? -a : a;
}
template <typename X>
inline X sqr(const X& a) {
  return a * a;
}
const int size = 1e5 + 5;
const double eps = 0.0001;
const long double PI = 3.1415926535897932384626433832795;
const long long MOD = 1000000007;
const long long INF = 1LL << 62;
const long long MAX5 = 100001;
const long long MAX6 = 1000001;
const long long MAX17 = 99999999999999999;
const double DMAX = 2e18 + 5;
void solution();
void include_file();
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  solution();
  return 0;
}
inline void include_file() {
  ios_base::sync_with_stdio(true);
  freopen("input.txt", "r", stdin);
  freopen("output.txt", "w", stdout);
}
inline bool isPrime(long long n) {
  for (int i = 2; i * i <= n; ++i)
    if (n % i == 0) return false;
  return true;
}
inline string ekv(string a) {
  if (a.size() & 1) return a;
  string x = ekv(a.substr(0, a.size() / 2));
  string y = ekv(a.substr(a.size() / 2));
  return min(x + y, y + x);
}
inline long long cubic_root(long long x) {
  long long l = 0, r = MAX6;
  while (l != r) {
    long long m = (l + r + 1) / 2;
    if (m * m * m > x)
      r = m - 1;
    else
      l = m;
  }
  return l;
}
inline float FastInvSqrt(float x) {
  float xhalf = 0.5f * x;
  int i = *(int*)&x;
  i = 0x5f3759df - (i >> 1);
  x = *(float*)&i;
  x = x * (1.5f - (xhalf * x * x));
  return x;
}
inline long long gcd(long long a, long long b) {
  while (b ^= a ^= b ^= a = a % b)
    ;
  return a;
}
inline long long lcm(long long a, long long b) { return a / gcd(a, b) * b; }
constexpr uint64_t mod = (1ull << 61) - 1;
inline uint64_t modmul(uint64_t a, uint64_t b) {
  uint64_t l1 = (uint32_t)a, h1 = a >> 32, l2 = (uint32_t)b, h2 = b >> 32;
  uint64_t l = l1 * l2, m = l1 * h2 + l2 * h1, h = h1 * h2;
  uint64_t ret =
      (l & mod) + (l >> 61) + (h << 3) + (m >> 29) + (m << 35 >> 3) + 1;
  ret = (ret & mod) + (ret >> 61);
  ret = (ret & mod) + (ret >> 61);
  return ret - 1;
}
void yes() { cout << "YES"; }
void no() { cout << "NO"; }
void yes(bool res, bool small = false) {
  if (!small) {
    if (res)
      cout << "YES";
    else
      cout << "NO";
  } else {
    if (res)
      cout << "Yes";
    else
      cout << "No";
  }
}
void dabl(double x) { printf("%.10lf", x); }
namespace bits {
template <typename X>
inline X MAX(const X& a, const X& b) {
  return b & ((a - b) >> 31) | a & (~(a - b) >> 31);
}
template <typename X>
inline X MIN(const X& a, const X& b) {
  return a & ((a - b) >> 31) | b & (~(a - b) >> 31);
}
inline bool check2(const long long n) { return n > 0 && (n & (n - 1)); }
inline long long ostatok2(const long long n, const long long m) {
  return m & (n - 1);
}
template <typename X>
inline void SWAP(X& a, X& b) {
  a ^= b;
  b ^= a;
  a ^= b;
}
inline size_t count_1_in_LL(unsigned long long n) {
  std::size_t i(0);
  for (; n; ++i) n &= n - 1;
  return i;
}
}  // namespace bits
void debug() { cout << endl; }
template <typename H, typename... T>
void debug(H p, T... t) {
  std::cout << p << " ";
  debug(t...);
}
vector<vector<int> > g;
vector<int> fac(int x) {
  vector<int> res;
  for (long long i = 2; i < x + 1; ++i) {
    if (x % i == 0) res.push_back(i);
  }
  return res;
}
inline void solution() {
  int n;
  cin >> n;
  string s[n];
  for (long long i = 0; i < n; ++i) cin >> s[i];
  ;
  int res = 0;
  if (n >= 3) {
    for (long long i = 1; i < n - 1; ++i) {
      for (long long j = 1; j < n - 1; ++j) {
        if (s[i][j] == 'X' && s[i - 1][j - 1] == 'X' &&
            s[i + 1][j + 1] == 'X' && s[i - 1][j + 1] == 'X' &&
            s[i + 1][j - 1] == 'X')
          res++;
      }
    }
  };
  cout << res;
  ;
}
