There are N children, numbered 1, 2, \ldots, N.

They have decided to share K candies among themselves. Here, for each i (1 \leq i \leq N), Child i must receive between 0 and a_i candies (inclusive). Also, no candies should be left over.

Find the number of ways for them to share candies, modulo 10^9 + 7. Here, two ways are said to be different when there exists a child who receives a different number of candies.

Constraints

* All values in input are integers.
* 1 \leq N \leq 100
* 0 \leq K \leq 10^5
* 0 \leq a_i \leq K

Input

Input is given from Standard Input in the following format:


N K
a_1 a_2 \ldots a_N


Output

Print the number of ways for the children to share candies, modulo 10^9 + 7.

Examples

Input

3 4
1 2 3


Output

5


Input

1 10
9


Output

0


Input

2 0
0 0


Output

1


Input

4 100000
100000 100000 100000 100000


Output

665683269
from itertools import accumulate

def f(k, A):
    n = len(A)

    mod = int(1e9 + 7)
    dp = [0] * (k + 1)

    # init for last column
    for j in range(min(A[n - 1], k) + 1):
        dp[j] = 1

    for i in range(n - 2, -1, -1):
        dp = list(accumulate(dp))
        a = A[i]
        dp[a+1:] = [x - y for x, y in zip(dp[a + 1:], dp)]
        dp = [x % mod for x in dp]

    return dp[-1] % mod

assert f(4, [2, 3]) == 2
assert f(4, [1, 2, 3]) == 5
assert f(10, [9]) == 0
assert f(0, [0, 0]) == 1
assert f(100000, [100000, 100000, 100000, 100000]) == 665683269

n, k = map(int, input().split())
A = list(map(int, input().split()))
ans = f(k, A)
print(ans)
