If there is an integer not less than 0 satisfying the following conditions, print the smallest such integer; otherwise, print `-1`.

* The integer has exactly N digits in base ten. (We assume 0 to be a 1-digit integer. For other integers, leading zeros are not allowed.)
* The s_i-th digit from the left is c_i. \left(i = 1, 2, \cdots, M\right)

Constraints

* All values in input are integers.
* 1 \leq N \leq 3
* 0 \leq M \leq 5
* 1 \leq s_i \leq N
* 0 \leq c_i \leq 9

Input

Input is given from Standard Input in the following format:


N M
s_1 c_1
\vdots
s_M c_M


Output

Print the answer.

Examples

Input

3 3
1 7
3 2
1 7


Output

702


Input

3 2
2 1
2 3


Output

-1


Input

3 1
1 0


Output

-1
import java.util.Scanner;

public class Main {



	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);

		int n = Integer.parseInt(sc.next());
		int m = Integer.parseInt(sc.next());

		int[] s = new int[n];
		for(int i = 0 ; i < n ; i++) {
			s[i] = -1;


		}

		int ans = 0;
		for(int i = 0 ; i < m ; i++) {
			int temp1 = Integer.parseInt(sc.next()) -1;
			int temp2 = Integer.parseInt(sc.next());

			if(s[temp1] == -1) {
				s[temp1] = temp2;
			}else if(s[temp1] != temp2) {
				ans = -1;
				break;
			}

		}


		for(int i = 0 ; i < n ; i++) {
			if(s[i] == -1) {
				if(i == 0 && n != 1) {
					s[i] = 1;
				}else {
					s[i] = 0;
				}
			}
		}

		if(n != 1 && s[0] == 0) {
			ans = -1;
		}

		if(ans != -1) {
			String tmp = "";
			for(int i = 0 ; i < n ; i++ ) {
				tmp += "" + s[i];
			}
			
			ans = Integer.parseInt(tmp);
		}	

		System.out.println(ans);
	}
}