You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

* In the i-th operation, you replace every element whose value is B_{i} with C_{i}.



For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

* All values in input are integers.
* 1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}
* B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:


N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}


Output

Print Q integers S_{i} to Standard Output in the following format:


S_{1}
S_{2}
\vdots
S_{Q}


Note that S_{i} may not fit into a 32-bit integer.

Examples

Input

4
1 2 3 4
3
1 2
3 4
2 4


Output

11
12
16


Input

4
1 1 1 1
3
1 2
2 1
3 5


Output

8
4
4


Input

2
1 2
3
1 100
2 100
100 1000


Output

102
200
2000
import java.util.Arrays;
import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;

public class Main {

  public static void main(String[] args) {
    final Scanner scanner = new Scanner(System.in);

    scanner.nextLine();
    final String[] a = scanner.nextLine().split(" ");
    Map<Integer, Long> counts = new HashMap<>();
    long sum = 0;
    for (int i = 0; i < a.length; i++) {
      final int num = Integer.parseInt(a[i]);
      counts.put(
          num,
          counts.getOrDefault(num, 0L) + 1
      );
      sum += num;
    }

    final int q = scanner.nextInt();
    final int[][] bc = new int[q][2];

    for (int i = 0; i < q; i++) {
      bc[i][0] = scanner.nextInt();
      bc[i][1] = scanner.nextInt();

      final long replaceCount = counts.getOrDefault(bc[i][0], 0L);
      counts.put(
          bc[i][1],
          counts.getOrDefault(bc[i][1], 0L) + replaceCount
      );
      counts.remove(bc[i][0]);

      sum += replaceCount * (bc[i][1] - bc[i][0]);

      System.out.println(sum);
    }
  }
}
