You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

* In the i-th operation, you replace every element whose value is B_{i} with C_{i}.



For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

* All values in input are integers.
* 1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}
* B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:


N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}


Output

Print Q integers S_{i} to Standard Output in the following format:


S_{1}
S_{2}
\vdots
S_{Q}


Note that S_{i} may not fit into a 32-bit integer.

Examples

Input

4
1 2 3 4
3
1 2
3 4
2 4


Output

11
12
16


Input

4
1 1 1 1
3
1 2
2 1
3 5


Output

8
4
4


Input

2
1 2
3
1 100
2 100
100 1000


Output

102
200
2000
import java.math.BigDecimal;
import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);

		Map<Integer, Integer> a = new HashMap<Integer, Integer>();
		BigDecimal sum = new BigDecimal(0);

		int n = Integer.parseInt(sc.next());
		for (int i = 0; i < n; i++) {
			int m = Integer.parseInt(sc.next());

			if (a.containsKey(m))
				a.replace(m, a.get(m) + 1);
			else
				a.put(m, 1);

			sum = sum.add(new BigDecimal(m));
		}

		int b, c, b_num, c_num;
		int q = Integer.parseInt(sc.next());
		for (int i = 0; i < q; i++) {
			b = Integer.parseInt(sc.next());
			c = Integer.parseInt(sc.next());

			b_num = 0;
			if (a.containsKey(b)) {
				b_num = a.remove(b);
				BigDecimal diff = new BigDecimal((c - b) * b_num);

				c_num = b_num;
				if (a.containsKey(c)) {
					c_num += a.get(c);
					a.replace(c, c_num);
				} else {
					a.put(c, c_num);
				}

				sum = sum.add(diff);
			}
			System.out.println(sum);
		}
	}

}
