You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

* In the i-th operation, you replace every element whose value is B_{i} with C_{i}.



For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

* All values in input are integers.
* 1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}
* B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:


N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}


Output

Print Q integers S_{i} to Standard Output in the following format:


S_{1}
S_{2}
\vdots
S_{Q}


Note that S_{i} may not fit into a 32-bit integer.

Examples

Input

4
1 2 3 4
3
1 2
3 4
2 4


Output

11
12
16


Input

4
1 1 1 1
3
1 2
2 1
3 5


Output

8
4
4


Input

2
1 2
3
1 100
2 100
100 1000


Output

102
200
2000
import java.math.BigDecimal;
import java.util.*;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();

        Map<Long, Integer> noMap = new HashMap<>();
        for (int i=1;i<=n;i++) {
            long x = sc.nextLong();
            if (!noMap.containsKey(x)) {
                noMap.put(x,1);
            } else {
                int a = noMap.get(x);
                noMap.put(x,a+1);
            }
        }

        int q = sc.nextInt();
        long ans = 0;
        for (long key : noMap.keySet()) {
            int sub = noMap.get(key);
            ans+=key*sub;
        }
        for (int i=1;i<=q;i++) {
            long x = sc.nextLong();
            long y = sc.nextLong();
            if (noMap.containsKey(x)) {
                int a = noMap.get(x);
                int b = 0;
                if (noMap.containsKey(y)) {
                    b = noMap.get(y);
                }
                noMap.put(y,a+b);
                noMap.remove(x);
                long z = y-x;
                ans += z*a;
            }

            System.out.println(ans);
        }
    }
}
