You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

* In the i-th operation, you replace every element whose value is B_{i} with C_{i}.



For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

* All values in input are integers.
* 1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}
* B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:


N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}


Output

Print Q integers S_{i} to Standard Output in the following format:


S_{1}
S_{2}
\vdots
S_{Q}


Note that S_{i} may not fit into a 32-bit integer.

Examples

Input

4
1 2 3 4
3
1 2
3 4
2 4


Output

11
12
16


Input

4
1 1 1 1
3
1 2
2 1
3 5


Output

8
4
4


Input

2
1 2
3
1 100
2 100
100 1000


Output

102
200
2000
import java.util.*;

public class Main {
  public static void main(String args[]) {
    Scanner scanner = new Scanner(System.in);
    HashMap<Integer,Integer> freq = new HashMap<Integer, Integer>();
    int n;
    n = scanner.nextInt();
  	int x;
    long sum = 0;
    for(int i = 0;i < n; i++) {
      x = scanner.nextInt();
      sum+=x;
      if(freq.containsKey(x)) {
        freq.replace(x,freq.get(x) + 1);
      } else {
        freq.put(x,1);
      }
    }
    
    int q;
    q = scanner.nextInt();
    int b,c;
    for(int i = 0;i < q;i++) {
      b = scanner.nextInt();
      c = scanner.nextInt();
      if(freq.containsKey(b)) {
        int freq_b = freq.get(b);
        sum = sum - (long)b * freq_b + (long)c * freq_b;
        System.out.println(sum);
        freq.remove(b,freq_b);
        if(freq.containsKey(c)) {
          freq.replace(c,freq.get(c) + freq_b);
        } else {
          freq.put(c,freq_b);
        }
      } else {
        System.out.println(sum);
    }
    }
  }
}