You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

* In the i-th operation, you replace every element whose value is B_{i} with C_{i}.



For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

* All values in input are integers.
* 1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}
* B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:


N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}


Output

Print Q integers S_{i} to Standard Output in the following format:


S_{1}
S_{2}
\vdots
S_{Q}


Note that S_{i} may not fit into a 32-bit integer.

Examples

Input

4
1 2 3 4
3
1 2
3 4
2 4


Output

11
12
16


Input

4
1 1 1 1
3
1 2
2 1
3 5


Output

8
4
4


Input

2
1 2
3
1 100
2 100
100 1000


Output

102
200
2000
import java.util.HashMap;
import java.util.Map;
import java.util.Map.Entry;
import java.util.Scanner;

public class Main {

	public static Map<Long, Long> map = new HashMap<>();

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		int N = sc.nextInt();
		for (int i = 0; i < N; i++) {
			long a = sc.nextLong();
			map.put(a, map.getOrDefault(a, 0L) + 1);
		}
		long ans = sumListA();
		int Q = sc.nextInt();
		for (int i = 0; i < Q; i++) {
			long b = sc.nextLong();
			long c = sc.nextLong();
			ans = changeKey(b, c, ans);
			System.out.println(ans);
		}
	}

	public static long sumListA() {
		long ret = 0L;
		for (Entry<Long, Long> entry : map.entrySet()) {
			ret += entry.getKey() * entry.getValue();
		}
		return ret;
	}

	public static long changeKey(long b, long c, long sum) {
		long count = map.getOrDefault(b, 0L);
		map.put(b, 0L);
		map.put(c, map.getOrDefault(c, 0L) + count);
		sum += (c - b) * count;
		return sum;
	}

}
