The Fair Nut found a string s. The string consists of lowercase Latin letters. The Nut is a curious guy, so he wants to find the number of strictly increasing sequences p_1, p_2, …, p_k, such that: 

  1. For each i (1 ≤ i ≤ k), s_{p_i} = 'a'. 
  2. For each i (1 ≤ i < k), there is such j that p_i < j < p_{i + 1} and s_j = 'b'. 



The Nut is upset because he doesn't know how to find the number. Help him.

This number should be calculated modulo 10^9 + 7.

Input

The first line contains the string s (1 ≤ |s| ≤ 10^5) consisting of lowercase Latin letters.

Output

In a single line print the answer to the problem — the number of such sequences p_1, p_2, …, p_k modulo 10^9 + 7.

Examples

Input

abbaa


Output

5

Input

baaaa


Output

4

Input

agaa


Output

3

Note

In the first example, there are 5 possible sequences. [1], [4], [5], [1, 4], [1, 5].

In the second example, there are 4 possible sequences. [2], [3], [4], [5].

In the third example, there are 3 possible sequences. [1], [3], [4].
import java.util.*;
import java.io.*;

// Solution

public class Main 
{    
  public static void main (String[] argv) 
  {
	  new Main();
  } 
     
     
  
  boolean test = false;  
  
  final int MOD = 1000000007;
  
  
  
  
  public Main()   {
	 FastReader in = new FastReader(new BufferedReader(new InputStreamReader(System.in)));
	 //FastReader in = new FastReader(new BufferedReader(new FileReader("Main.in")));
     
     char[] a = in.next().toCharArray();
     
     int sum_preb = 0;
     int sum_afterb = 0;
     int tot = 0;
     for (char c : a) {
         if (c == 'a') {
             int cur = 1 + sum_preb;
             
             tot = mod_add(tot, cur);
             sum_afterb = mod_add(sum_afterb, cur);
         }else if (c == 'b') {
             sum_preb = mod_add(sum_preb, sum_afterb);
             sum_afterb = 0;
         }
         
     }
     System.out.println(tot);
  }
  
  private int mod_add(int a, int b) {
      int v = a + b;
      if (v >= MOD) v -= MOD;
      return v;
  }
  
  private boolean ok(int[] a, long s, int r) {
      for (int v : a) {
          if (v < r) return false;
          
          s -= v - r;          
      }
      return s <= 0;
  }
  
  private long overlap(int x1, int y1, int x2, int y2, int x3, int y3, int x4, int y4) {
      if (x1 > x3) return overlap(x3, y3, x4, y4, x1, y1, x2, y2);
      
      if (x3 > x2 || y4 < y1 || y3 > y2) return 0L;
      
      //(x3, ?, x2, ?)
      int yL = Math.max(y1, y3);
      int yH = Math.min(y2, y4);
      int xH = Math.min(x2, x4);
      
      return f(x3, yL, xH, yH);
  }
  //return #black cells in rectangle
  private long f(int x1, int y1, int x2, int y2) {
      long dx = 1L + x2 - x1;
      long dy = 1L + y2 - y1;
      if (dx % 2 == 0 || dy % 2 == 0 || (x1 + y1) % 2 == 0) 
          return 1L * dx * dy / 2;
      return 1L * dx * dy / 2 + 1;
  }
  
  private int dist(int x, int y, int xx, int yy) {
      return abs(x - xx) + abs(y - yy);
  }
  
  private boolean less(int x, int y, int xx, int yy) {
      return x < xx || y > yy;
  }
  
  private int mul(int x, int y) {
      return (int)(1L * x * y % MOD);
  }
  
  private int add(int x, int y) {
      return (x + y) % MOD;
  }
  
 
  
  private int nBit1(int v) {
      int v0 = v;
      int c = 0;
      while (v != 0) {
          ++c;
          v = v & (v - 1);
      }
      return c;
  }
  
  private long abs(long v) {
      return v > 0 ? v : -v;
  }
  
  private int abs(int v) {
      return v > 0 ? v : -v;
  }
  
  private int common(int v) {
      int c = 0;
      while (v != 1) {
          v = (v >>> 1);
          ++c;
      }
      
      return c;
  }
  
  private void reverse(char[] a, int i, int j) {
      while (i < j) {
          swap(a, i++, j--);
      }
  }
  
  private void swap(char[] a, int i, int j) {
      char t = a[i];
      a[i] = a[j];
      a[j] = t;
  }
  
  private int gcd(int x, int y) {
      if (y == 0) return x;
      return gcd(y, x % y);
  }
  private long gcd(long x, long y) {
      if (y == 0) return x;
      return gcd(y, x % y);
  }
  private int max(int a, int b) {
      return a >  b ? a : b;
  }
  
  private long max(long a, long b) {
      return a >  b ? a : b;
  }
  
  private int min(int a, int b) {
      return a >  b ? b : a;
  }
  
  private long min(long a, long b) {
      return a >  b ? b : a;
  }
  
  static class FastReader
    {
        BufferedReader br;
        StringTokenizer st;
 
        public FastReader(BufferedReader in)
        {            
            br = in;
        }
 
        String next()
        {
            while (st == null || !st.hasMoreElements())
            {
                try
                {
                    String line = br.readLine();
                    if (line == null || line.length() == 0) return "";
                    st = new StringTokenizer(line);
                }
                catch (IOException  e)
                {
                    return "";
                    //e.printStackTrace();
                }
            }
            return st.nextToken();
        }
 
        int nextInt()
        {
            return Integer.parseInt(next());
        }
 
        long nextLong()
        {
            return Long.parseLong(next());
        }
 
        double nextDouble()
        {
            return Double.parseDouble(next());
        }
 
        String nextLine()
        {
            String str = "";
            try
            {
                str = br.readLine();
            }
            catch (IOException e)
            {
                return "";
                //e.printStackTrace();
            }
            return str;
        }
    }
}