Valera had two bags of potatoes, the first of these bags contains x (x ≥ 1) potatoes, and the second — y (y ≥ 1) potatoes. Valera — very scattered boy, so the first bag of potatoes (it contains x potatoes) Valera lost. Valera remembers that the total amount of potatoes (x + y) in the two bags, firstly, was not gerater than n, and, secondly, was divisible by k.

Help Valera to determine how many potatoes could be in the first bag. Print all such possible numbers in ascending order.

Input

The first line of input contains three integers y, k, n (1 ≤ y, k, n ≤ 109; <image> ≤ 105).

Output

Print the list of whitespace-separated integers — all possible values of x in ascending order. You should print each possible value of x exactly once.

If there are no such values of x print a single integer -1.

Examples

Input

10 1 10


Output

-1


Input

10 6 40


Output

2 8 14 20 26 
# cook your dish here
from sys import stdin, stdout
import math
from itertools import permutations, combinations
from collections import defaultdict
from bisect import bisect_left 
from bisect import bisect_right
 
def L():
    return list(map(int, stdin.readline().split()))
 
def In():
    return map(int, stdin.readline().split())
 
def I():
    return int(stdin.readline())
 
P = 1000000007
def main():
    y, k, n = In()
    arr = []
    for i in range(((y//k)+1)*k, n+1, k):
        arr.append(i-y)
    if len(arr):
        print(*arr)
    else:
        print(-1)
        
    
if __name__ == '__main__':
    main()
