There is a rectangular room, covered with square tiles. Each tile is colored either red or black. A man is standing on a black tile. From a tile, he can move to one of four adjacent tiles. But he can't move on red tiles, he can move only on black tiles.

Write a program to count the number of black tiles which he can reach by repeating the moves described above.



Input

The input consists of multiple data sets. A data set starts with a line containing two positive integers W and H; W and H are the numbers of tiles in the x- and y- directions, respectively. W and H are not more than 20.

There are H more lines in the data set, each of which includes W characters. Each character represents the color of a tile as follows.

* '.' - a black tile
* '#' - a red tile
* '@' - a man on a black tile(appears exactly once in a data set)


The end of the input is indicated by a line consisting of two zeros.

Output

For each data set, your program should output a line which contains the number of tiles he can reach from the initial tile (including itself).

Examples

Input

6 9
....#.
.....#
......
......
......
......
......
#@...#
.#..#.
11 9
.#.........
.#.#######.
.#.#.....#.
.#.#.###.#.
.#.#..@#.#.
.#.#####.#.
.#.......#.
.#########.
...........
11 6
..#..#..#..
..#..#..#..
..#..#..###
..#..#..#@.
..#..#..#..
..#..#..#..
7 7
..#.#..
..#.#..
###.###
...@...
###.###
..#.#..
..#.#..
0 0


Output

45
59
6
13


Input

6 9
....#.
.....#
......
......
......
......
......
@...#
.#..#.
11 9
.#.........
.#.#######.
.#.#.....#.
.#.#.###.#.
.#.#..@#.#.
.#.#####.#.
.#.......#.
.#########.
...........
11 6
..#..#..#..
..#..#..#..
..#..#..###
..#..#..#@.
..#..#..#..
..#..#..#..
7 7
..#.#..
..#.#..
.###
...@...
.###
..#.#..
..#.#..
0 0


Output

45
59
6
13
#include<stdio.h>
#include<string.h>
char m[22][22],*p;
int F(int x,int y)
{
	if(m[y][x]=='#')return 0;
	m[y][x]='#';
	return 1+F(x+1,y)+F(x-1,y)+F(x,y+1)+F(x,y-1);
}
int main()
{
	int w,h,i,x,y;
	while(scanf("%d%d",&w,&h),w)
	{
		for(i=1;i<=h;++i)
		{
			scanf("%s",m[i]+1);
			if(p=strchr(m[i]+1,'@'))x=p-m[y=i];
		}
		for(i=0;i<h+2;++i)m[i][0]=m[i][w+1]='#';
		for(i=0;i<w+2;++i)m[0][i]=m[h+1][i]='#';
		printf("%d\n",F(x,y));
	}
	return 0;
}