You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

* In the i-th operation, you replace every element whose value is B_{i} with C_{i}.



For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

* All values in input are integers.
* 1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}
* B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:


N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}


Output

Print Q integers S_{i} to Standard Output in the following format:


S_{1}
S_{2}
\vdots
S_{Q}


Note that S_{i} may not fit into a 32-bit integer.

Examples

Input

4
1 2 3 4
3
1 2
3 4
2 4


Output

11
12
16


Input

4
1 1 1 1
3
1 2
2 1
3 5


Output

8
4
4


Input

2
1 2
3
1 100
2 100
100 1000


Output

102
200
2000
import java.util.*;

public class Main {


    public static void main(String[] args) {

        Scanner sc = new Scanner(System.in);
        int N = sc.nextInt();
        int[] A = new int[N];

        Map<Long,Long> m = new HashMap<>();

        long sum = 0;
        for (int i = 0; i < N; i++) {
            long num = sc.nextInt();
            sum += num;
            if(m.containsKey(num)){
                m.put(num,m.get(num)+1);
            }else{
                m.put(num,1L);
            }
        }
        int Q = sc.nextInt();

        for (int i = 0; i < Q ; i++) {
            long from = sc.nextInt();
            long to = sc.nextInt();

            if(m.containsKey(from)){
                long n = (long)m.get(from);
                sum = sum - n * from + n * to;

                if(m.containsKey(to)){
                    m.put(to,m.get(to)+n);
                }else{
                    m.put(to,n);
                }
                m.put(from,0L);
            }else{

            }
            System.out.println(sum);
        }

    }

}