You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

* In the i-th operation, you replace every element whose value is B_{i} with C_{i}.



For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

* All values in input are integers.
* 1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}
* B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:


N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}


Output

Print Q integers S_{i} to Standard Output in the following format:


S_{1}
S_{2}
\vdots
S_{Q}


Note that S_{i} may not fit into a 32-bit integer.

Examples

Input

4
1 2 3 4
3
1 2
3 4
2 4


Output

11
12
16


Input

4
1 1 1 1
3
1 2
2 1
3 5


Output

8
4
4


Input

2
1 2
3
1 100
2 100
100 1000


Output

102
200
2000
import java.util.*;

public class Main{
	
  public static void main(String[] args){
    Scanner sc = new Scanner(System.in);
  	int n=sc.nextInt(),q;
    long sum=0;
    int[] a=new int[n],x=new int[100001];
    for(int i=0;i<n;i++){
      a[i]=sc.nextInt();
      x[a[i]]++;
      sum+=(long)a[i];
    }
    
    q=sc.nextInt();
    int[] b=new int[q],c=new int[q],d=new int[q];
    for(int i=0;i<q;i++){
      b[i]=sc.nextInt();
      c[i]=sc.nextInt();
      d[i]=c[i]-b[i];
      sum=sum+(long)(x[b[i]]*d[i]);
      System.out.println(sum);
      x[c[i]]+=x[b[i]];
      x[b[i]]=0;
    }
  }
}
