You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

* In the i-th operation, you replace every element whose value is B_{i} with C_{i}.



For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

* All values in input are integers.
* 1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}
* B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:


N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}


Output

Print Q integers S_{i} to Standard Output in the following format:


S_{1}
S_{2}
\vdots
S_{Q}


Note that S_{i} may not fit into a 32-bit integer.

Examples

Input

4
1 2 3 4
3
1 2
3 4
2 4


Output

11
12
16


Input

4
1 1 1 1
3
1 2
2 1
3 5


Output

8
4
4


Input

2
1 2
3
1 100
2 100
100 1000


Output

102
200
2000
import java.util.*;
import java.util.function.BiConsumer;

class Main {
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		int N = sc.nextInt();
		int A[] = new int[N];
		for(int i=0; i < N; i++) {
			A[i] = sc.nextInt();
		}
		int Q = sc.nextInt();
		
		int B[] = new int[Q];
		int C[] = new int[Q];
		for(int i=0; i < Q; i++) {
			B[i] = sc.nextInt();
			C[i] = sc.nextInt();
		}
		
		long total = 0;
		for(int a : A) {
			total += a;
		}
		
		int[] num = new int[100001];
			for(int j=0; j<N; j++) {
				int a = A[j];
				num[a] ++;
			}
		
		
		for(int i=0; i < Q; i++) {
			int b = B[i];
			int c = C[i];
			int count = num[b];
			total += (c - b) * count;
			num[c] += num[b];
			num[b] = 0;			
			System.out.println(total);
	
		}

		
	}
}
