Assume that a, b, and n are all positive integers. Let f (i) be the i-th fraction of the fraction a / b (0 ≤ f (i) ≤ 9). At this time, let s be the sum of f (i) from i = 1 to n.

s = f (1) + f (2) + ... + f (n)


Create a program that reads a, b, n, outputs s, and exits.



Input

The input consists of multiple datasets. For each dataset, three integers a (1 ≤ a ≤ 1000), b (1 ≤ b ≤ 10000), n (1 ≤ n ≤ 100) are given on one line, separated by blanks.

The number of datasets does not exceed 100.

Output

Prints s on one line for each dataset.

Example

Input

1 2 3
2 3 4
5 4 3
4 3 2


Output

5
24
7
6
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.math.BigDecimal;
import java.math.RoundingMode;

public class Main {

	public static void main(String[] args) throws IOException {
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
		String line = "";

		while ((line = br.readLine()) != null) {
			BigDecimal a, b, dec;
			String decstr;
			int n, sum = 0;

			n = Integer.parseInt(line.split(" ")[2]);
			a = new BigDecimal(line.split(" ")[0]).setScale(n + 1);
			b = new BigDecimal(line.split(" ")[1]).setScale(n + 1);

			dec = a.divide(b, n + 1, RoundingMode.HALF_UP);
			decstr = dec.toString().split("\\.")[1];

			for (int i = 0; i < n; i++) {
				sum += (decstr.charAt(i) - 48);
			}
			System.out.println(sum);
		}
	}
}