John Doe has found the beautiful permutation formula.

Let's take permutation p = p1, p2, ..., pn. Let's define transformation f of this permutation: 

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where k (k > 1) is an integer, the transformation parameter, r is such maximum integer that rk ≤ n. If rk = n, then elements prk + 1, prk + 2 and so on are omitted. In other words, the described transformation of permutation p cyclically shifts to the left each consecutive block of length k and the last block with the length equal to the remainder after dividing n by k. 

John Doe thinks that permutation f(f( ... f(p = [1, 2, ..., n], 2) ... , n - 1), n) is beautiful. Unfortunately, he cannot quickly find the beautiful permutation he's interested in. That's why he asked you to help him.

Your task is to find a beautiful permutation for the given n. For clarifications, see the notes to the third sample.

Input

A single line contains integer n (2 ≤ n ≤ 106).

Output

Print n distinct space-separated integers from 1 to n — a beautiful permutation of size n.

Examples

Input

2


Output

2 1 


Input

3


Output

1 3 2 


Input

4


Output

4 2 3 1 

Note

A note to the third test sample: 

  * f([1, 2, 3, 4], 2) = [2, 1, 4, 3]
  * f([2, 1, 4, 3], 3) = [1, 4, 2, 3]
  * f([1, 4, 2, 3], 4) = [4, 2, 3, 1]
import static java.lang.Math.*;
import static java.math.BigInteger.*;
import static java.util.Arrays.*;
import static java.util.Collections.*;

public class B {

	final static boolean autoflush = false;

	public B () {
		int N = sc.nextInt();
		int [] P = new int [2*N];
		for (int i : req(1, N))
			P[i] = i;

		for (int k : req(2, N))
			for (int r : seq(0, (N-1)/k)) {
				int X = r*k + (k-1), Y = min(X+k, N+k-1);
				P[Y] = P[X];
			}

		int [] res = copyOfRange(P, N, 2*N);
		exit(res);
	}

	////////////////////////////////////////////////////////////////////////////////////

	static int [] rep(int N) { return rep(0, N); }
	static int [] rep(int S, int T) { int [] res = new int [max(T-S, 0)]; for (int i = S; i < T; ++i) res[i-S] = i; return res; }
	static int [] req(int S, int T) { return rep(S, T+1); }

	static int [] sep(int N) { return sep(0, N); }
	static int [] sep(int S, int T) { int [] res = new int [max(T-S, 0)]; for (int i = S; i < T; ++i) res[T-i-1] = i; return res; }
	static int [] seq(int S, int T) { return sep(S, T+1); }

	////////////////////////////////////////////////////////////////////////////////////

	/* Dear hacker, don't bother reading below this line, unless you want to help me debug my I/O routines :-) */

	final static MyScanner sc = new MyScanner();

	static class MyScanner {
		public String next() {
			newLine();
			return line[index++];
		}

		public char nextChar() {
			return next().charAt(0);
		}

		public int nextInt() {
			return Integer.parseInt(next());
		}

		public long nextLong() {
			return Long.parseLong(next());
		}

		public double nextDouble() {
			return Double.parseDouble(next());
		}

		public String nextLine() {
			line = null;
			return readLine();
		}

		public String [] nextStrings() {
			line = null;
			return readLine().split(" ");
		}

		public char [] nextChars() {
			return next ().toCharArray ();
		}

		public Integer [] nextInts() {
			String [] L = nextStrings();
			Integer [] res = new Integer [L.length];
			for (int i : rep(L.length))
				res[i] = Integer.parseInt(L[i]);
			return res;
		}

		public Long [] nextLongs() {
			String [] L = nextStrings();
			Long [] res = new Long [L.length];
			for (int i : rep(L.length))
				res[i] = Long.parseLong(L[i]);
			return res;
		}

		public Double [] nextDoubles() {
			String [] L = nextStrings();
			Double [] res = new Double [L.length];
			for (int i : rep(L.length))
				res[i] = Double.parseDouble(L[i]);
			return res;
		}

		public String [] next (int N) {
			String [] res = new String [N];
			for (int i : rep(N))
				res[i] = sc.next();
			return res;
		}

		public Integer [] nextInt (int N) {
			Integer [] res = new Integer [N];
			for (int i : rep(N))
				res[i] = sc.nextInt();
			return res;
		}

		public Long [] nextLong (int N) {
			Long [] res = new Long [N];
			for (int i : rep(N))
				res[i] = sc.nextLong();
			return res;
		}

		public Double [] nextDouble (int N) {
			Double [] res = new Double [N];
			for (int i : rep(N))
				res[i] = sc.nextDouble();
			return res;
		}

		public String [][] nextStrings (int N) {
			String [][] res = new String [N][];
			for (int i : rep(N))
				res[i] = sc.nextStrings();
			return res;
		}

		public Integer [][] nextInts (int N) {
			Integer [][] res = new Integer [N][];
			for (int i : rep(N))
				res[i] = sc.nextInts();
			return res;
		}

		public Long [][] nextLongs (int N) {
			Long [][] res = new Long [N][];
			for (int i : rep(N))
				res[i] = sc.nextLongs();
			return res;
		}

		public Double [][] nextDoubles (int N) {
			Double [][] res = new Double [N][];
			for (int i : rep(N))
				res[i] = sc.nextDoubles();
			return res;
		}

		//////////////////////////////////////////////

		private boolean eol() {
			return index == line.length;
		}

		private String readLine() {
			try {
				return r.readLine();
			} catch (Exception e) {
				throw new Error (e);
			}
		}
		private final java.io.BufferedReader r;

		MyScanner () {
			this(new java.io.BufferedReader(new java.io.InputStreamReader(System.in)));
		}

		MyScanner (java.io.BufferedReader r) {
			try {
				this.r = r;
				while (!r.ready())
					Thread.sleep(1);
				start();
			} catch (Exception e) {
				throw new Error(e);
			}
		}

		private String [] line;
		private int index;

		private void newLine() {
			if (line == null || eol()) {
				line = readLine().split(" ");
				index = 0;
			}
		}
	}

	static void print (Object o, Object... a) {
		printDelim(" ", o, a);
	}

	static void cprint (Object o, Object... a) {
		printDelim("", o, a);
	}

	static void printDelim (String delim, Object o, Object... a) {
		pw.println(build(delim, o, a));
	}

	static void exit (Object o, Object... a) {
		print(o, a);
		exit();
	}

	static void exit() {
		pw.close();
		System.out.flush();
		System.err.println("------------------");
		System.err.println("Time: " + ((millis() - t) / 1000.0));
		System.exit(0);
	}

	static void NO() {
		throw new Error("NO!");
	}

	////////////////////////////////////////////////////////////////////////////////////

	static String build (String delim, Object o, Object... a) {
		StringBuilder b = new StringBuilder();
		append(b, o, delim);
		for (Object p : a)
			append(b, p, delim);
		return b.toString().trim();
	}

	static void append(StringBuilder b, Object o, String delim) {
		if (o.getClass().isArray()) {
			int L = java.lang.reflect.Array.getLength(o);
			for (int i : rep(L))
				append(b, java.lang.reflect.Array.get(o, i), delim);
		} else if (o instanceof Iterable<?>)
			for (Object p : (Iterable<?>)o)
				append(b, p, delim);
		else
			b.append(delim).append(o);
	}

	////////////////////////////////////////////////////////////////////////////////////

	static void statics() {
		abs(0);
		valueOf(0);
		asList(new Object [0]);
		reverseOrder();
	}

	public static void main (String[] args) {
		new B();
		exit();
	}

	static void start() {
		t = millis();
	}

	static java.io.PrintWriter pw = new java.io.PrintWriter(System.out, autoflush);

	static long t;

	static long millis() {
		return System.currentTimeMillis();
	}
}
