You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

* In the i-th operation, you replace every element whose value is B_{i} with C_{i}.



For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

* All values in input are integers.
* 1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}
* B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:


N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}


Output

Print Q integers S_{i} to Standard Output in the following format:


S_{1}
S_{2}
\vdots
S_{Q}


Note that S_{i} may not fit into a 32-bit integer.

Examples

Input

4
1 2 3 4
3
1 2
3 4
2 4


Output

11
12
16


Input

4
1 1 1 1
3
1 2
2 1
3 5


Output

8
4
4


Input

2
1 2
3
1 100
2 100
100 1000


Output

102
200
2000
import java.util.*;
public class Main{
    public static void main(String[] args){
    Scanner sc = new Scanner(System.in);
    int N = Integer.parseInt(sc.next());
    // Long A[] = new Long[N];
    HashMap<Long,Integer> map = new HashMap<Long,Integer>();
    Long sum = 0L;
    for(int i=0;i<N;i++){
      Long tmp = sc.nextLong();
      sum += tmp; 
      if(map.containsKey(tmp)){
        map.put(tmp,map.get(tmp)+1);
      }else{
        map.put(tmp,1);
      }
    }
    int Q = Integer.parseInt(sc.next());
    // System.out.println(Q+"q");
    Long A[] = new Long[Q];
    for(int i=0;i<Q;i++){
      // System.out.println(i+"i");
      Long B = sc.nextLong();
      Long C = sc.nextLong();
      if(map.containsKey(C) && map.containsKey(B)){
        int tmp2 = map.get(B);
        sum += (C - B)*tmp2;
        map.put(C,map.get(C)+tmp2);
        map.put(B,0);
      }else if(map.containsKey(C) && !map.containsKey(B)){
      }else if(!map.containsKey(C) && map.containsKey(B)){
        int tmp3 = map.get(B);
        sum += (C - B)*tmp3;
        map.put(C,tmp3);
        map.put(B,0);
      }
      A[i] = sum;
    }
    for(int i=0;i<Q;i++){
      System.out.println(A[i]);
    }


    // System.out.println(count);
  }
}