There are N children, numbered 1, 2, \ldots, N.

They have decided to share K candies among themselves. Here, for each i (1 \leq i \leq N), Child i must receive between 0 and a_i candies (inclusive). Also, no candies should be left over.

Find the number of ways for them to share candies, modulo 10^9 + 7. Here, two ways are said to be different when there exists a child who receives a different number of candies.

Constraints

* All values in input are integers.
* 1 \leq N \leq 100
* 0 \leq K \leq 10^5
* 0 \leq a_i \leq K

Input

Input is given from Standard Input in the following format:


N K
a_1 a_2 \ldots a_N


Output

Print the number of ways for the children to share candies, modulo 10^9 + 7.

Examples

Input

3 4
1 2 3


Output

5


Input

1 10
9


Output

0


Input

2 0
0 0


Output

1


Input

4 100000
100000 100000 100000 100000


Output

665683269
import sys
sys.setrecursionlimit(2147483647)
INF=float("inf")
MOD=10**9+7
input=lambda :sys.stdin.readline().rstrip()
def resolve():
    n,k=map(int,input().split())
    A=list(map(int,input().split()))
    dp=[0]*(k+1)
    dp[k]=1
    for i in range(n):
        ndp=[0]*(k+1)
        # dpの累積和を取っておく
        S=[0]*(k+2)
        for j in range(k+1):
            S[j+1]=S[j]+dp[j]
            S[j+1]%=MOD
        # iterete
        for j in range(k+1):
            ndp[j]=S[min(j+A[i]+1,k+1)]-S[j]
            ndp[j]%=MOD
        dp=ndp
    print(dp[0])
resolve()