Let S(n) denote the sum of the digits in the decimal notation of n. For example, S(123) = 1 + 2 + 3 = 6.

We will call an integer n a Snuke number when, for all positive integers m such that m > n, \frac{n}{S(n)} \leq \frac{m}{S(m)} holds.

Given an integer K, list the K smallest Snuke numbers.

Constraints

* 1 \leq K
* The K-th smallest Snuke number is not greater than 10^{15}.

Input

Input is given from Standard Input in the following format:


K


Output

Print K lines. The i-th line should contain the i-th smallest Snuke number.

Example

Input

10


Output

1
2
3
4
5
6
7
8
9
19
from math import log10
def nsn(N):
    K = sum( list( map( int, list( str(N)))))
    return N/K

def snuke(N):
    k = int( log10(N))+1
    s = N
    now = nsn(N)
    for d in range(k+1):
        x = (10**(d+1))*(N//(10**(d+1)) + 1) - 1
        y = nsn(x)
        if y < now:
            s = x
            now = y
    return s

K = int( input())
ans = 1
print(1)
for i in range(K-1):
    ans = snuke( ans + 1)
    print(ans)

