You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

* In the i-th operation, you replace every element whose value is B_{i} with C_{i}.



For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

* All values in input are integers.
* 1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}
* B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:


N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}


Output

Print Q integers S_{i} to Standard Output in the following format:


S_{1}
S_{2}
\vdots
S_{Q}


Note that S_{i} may not fit into a 32-bit integer.

Examples

Input

4
1 2 3 4
3
1 2
3 4
2 4


Output

11
12
16


Input

4
1 1 1 1
3
1 2
2 1
3 5


Output

8
4
4


Input

2
1 2
3
1 100
2 100
100 1000


Output

102
200
2000
N = raw_input()
ns = raw_input()
ns = ns.split(' ')

data = {}
for i in ns:
    i = int(i)
    if i in data:
        data[i] += 1
    else:
        data[i] = 1

Q = raw_input()
opr = []
for _ in range(int(Q)):
    tmp = raw_input()
    tmp = tmp.split(' ')
    opr.append([int(tmp[0]), int(tmp[1])])

ans = 0
for k, v in data.iteritems():
    ans += k * v
for op in opr:
    if op[0] not in data:
        print ans
        continue

    old1 = data[op[0]]
    del data[op[0]]

    old2 = 0
    if op[1] in data:
        old2 = data[op[1]]
    ans -= old1 * op[0] + old2 * op[1]

    data[op[1]] = old1 + old2
    ans += data[op[1]] * op[1]

    print ans
