If there is an integer not less than 0 satisfying the following conditions, print the smallest such integer; otherwise, print `-1`.

* The integer has exactly N digits in base ten. (We assume 0 to be a 1-digit integer. For other integers, leading zeros are not allowed.)
* The s_i-th digit from the left is c_i. \left(i = 1, 2, \cdots, M\right)

Constraints

* All values in input are integers.
* 1 \leq N \leq 3
* 0 \leq M \leq 5
* 1 \leq s_i \leq N
* 0 \leq c_i \leq 9

Input

Input is given from Standard Input in the following format:


N M
s_1 c_1
\vdots
s_M c_M


Output

Print the answer.

Examples

Input

3 3
1 7
3 2
1 7


Output

702


Input

3 2
2 1
2 3


Output

-1


Input

3 1
1 0


Output

-1
#!/usr/bin/env python

from collections import deque, defaultdict
import itertools as ite
import sys
import math
from decimal import *

sys.setrecursionlimit(1000000)

INF = 10 ** 18
MOD = 10 ** 9 + 7

N, M = map(int, raw_input().split())
s = []
c = []
for i in range(M):
    s_, c_ = map(int, raw_input().split())
    s += [s_]
    c += [c_]

for num in range(1000):
    if len(str(num)) != N:
        continue
    ls = map(int, list(str(num)))
    flag = True
    for i in range(M):
        if ls[s[i] - 1] != c[i]:
            flag = False
    if flag:
        print num
        exit()

print -1