Nikephoros and Polycarpus play rock-paper-scissors. The loser gets pinched (not too severely!).

Let us remind you the rules of this game. Rock-paper-scissors is played by two players. In each round the players choose one of three items independently from each other. They show the items with their hands: a rock, scissors or paper. The winner is determined by the following rules: the rock beats the scissors, the scissors beat the paper and the paper beats the rock. If the players choose the same item, the round finishes with a draw.

Nikephoros and Polycarpus have played n rounds. In each round the winner gave the loser a friendly pinch and the loser ended up with a fresh and new red spot on his body. If the round finished in a draw, the players did nothing and just played on.

Nikephoros turned out to have worked out the following strategy: before the game began, he chose some sequence of items A = (a1, a2, ..., am), and then he cyclically showed the items from this sequence, starting from the first one. Cyclically means that Nikephoros shows signs in the following order: a1, a2, ..., am, a1, a2, ..., am, a1, ... and so on. Polycarpus had a similar strategy, only he had his own sequence of items B = (b1, b2, ..., bk).

Determine the number of red spots on both players after they've played n rounds of the game. You can consider that when the game began, the boys had no red spots on them.

Input

The first line contains integer n (1 ≤ n ≤ 2·109) — the number of the game's rounds.

The second line contains sequence A as a string of m characters and the third line contains sequence B as a string of k characters (1 ≤ m, k ≤ 1000). The given lines only contain characters "R", "S" and "P". Character "R" stands for the rock, character "S" represents the scissors and "P" represents the paper.

Output

Print two space-separated integers: the numbers of red spots Nikephoros and Polycarpus have.

Examples

Input

7
RPS
RSPP


Output

3 2

Input

5
RRRRRRRR
R


Output

0 0

Note

In the first sample the game went like this:

  * R - R. Draw. 
  * P - S. Nikephoros loses. 
  * S - P. Polycarpus loses. 
  * R - P. Nikephoros loses. 
  * P - R. Polycarpus loses. 
  * S - S. Draw. 
  * R - P. Nikephoros loses. 



Thus, in total Nikephoros has 3 losses (and 3 red spots), and Polycarpus only has 2.
#include <bits/stdc++.h>
using namespace std;
int main() {
  int games;
  cin >> games;
  char a[1001], b[1001];
  scanf("%s %s", a, b);
  int alen = strlen(a);
  int blen = strlen(b);
  int loop_game = alen * blen;
  int loop_num = games / loop_game;
  int last_game = games % loop_game;
  int last_a_point = 0;
  int last_b_point = 0;
  int loop_a_point = 0;
  int loop_b_point = 0;
  for (int i = 0; i < loop_game; i++) {
    int ai = i % alen;
    int bi = i % blen;
    if (last_game == i) {
      last_a_point = loop_a_point;
      last_b_point = loop_b_point;
    }
    switch (a[ai] - b[bi]) {
      case 'R' - 'S':
      case 'S' - 'P':
      case 'P' - 'R':
        loop_b_point++;
        break;
      case 0:
        break;
      default:
        loop_a_point++;
    }
  }
  printf("%d %d\n", loop_a_point * loop_num + last_a_point,
         loop_b_point * loop_num + last_b_point);
}
