You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

* In the i-th operation, you replace every element whose value is B_{i} with C_{i}.



For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

* All values in input are integers.
* 1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}
* B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:


N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}


Output

Print Q integers S_{i} to Standard Output in the following format:


S_{1}
S_{2}
\vdots
S_{Q}


Note that S_{i} may not fit into a 32-bit integer.

Examples

Input

4
1 2 3 4
3
1 2
3 4
2 4


Output

11
12
16


Input

4
1 1 1 1
3
1 2
2 1
3 5


Output

8
4
4


Input

2
1 2
3
1 100
2 100
100 1000


Output

102
200
2000
import java.util.*;
public class Main{
  public static void main(String[] args)
  {
    Scanner sc=new Scanner(System.in);
     long n=sc.nextLong();
      ArrayList<Long> a1=new ArrayList<Long>();
      HashMap<Long,Long>  map=new HashMap<Long,Long>();
	long a[]=new long[(int)n];
	long s=0;
       for(int i=0;i<n;i++)
      {
	    a[i]=sc.nextLong();
	    s=s+a[i];
               if(map.containsKey(a[i]))
	                 map.put(a[i],map.get(a[i])+1);
              else
  	                map.put(a[i],1l);
      }
       int q=sc.nextInt();
    Long sum=s;
      for(int i=0;i<q;i++)
      {
	long x1=sc.nextLong();
	long x2=sc.nextLong();
                 if(map.containsKey(x1))
                {
	                  sum=sum+((x2-x1)*map.get(x1));
	                  if(map.containsKey(x2))
	                         map.put(x2,map.get(x2)+map.get(x1));
                          else
	                  {
		                  map.put(x2,map.get(x1));
	                  }
                          map.remove(x1);
	           }
                   a1.add(sum);
    }     
   for(int t=0;t<a1.size();t++)
	     System.out.println(a1.get(t));
  }
}