Nikephoros and Polycarpus play rock-paper-scissors. The loser gets pinched (not too severely!).

Let us remind you the rules of this game. Rock-paper-scissors is played by two players. In each round the players choose one of three items independently from each other. They show the items with their hands: a rock, scissors or paper. The winner is determined by the following rules: the rock beats the scissors, the scissors beat the paper and the paper beats the rock. If the players choose the same item, the round finishes with a draw.

Nikephoros and Polycarpus have played n rounds. In each round the winner gave the loser a friendly pinch and the loser ended up with a fresh and new red spot on his body. If the round finished in a draw, the players did nothing and just played on.

Nikephoros turned out to have worked out the following strategy: before the game began, he chose some sequence of items A = (a1, a2, ..., am), and then he cyclically showed the items from this sequence, starting from the first one. Cyclically means that Nikephoros shows signs in the following order: a1, a2, ..., am, a1, a2, ..., am, a1, ... and so on. Polycarpus had a similar strategy, only he had his own sequence of items B = (b1, b2, ..., bk).

Determine the number of red spots on both players after they've played n rounds of the game. You can consider that when the game began, the boys had no red spots on them.

Input

The first line contains integer n (1 ≤ n ≤ 2·109) — the number of the game's rounds.

The second line contains sequence A as a string of m characters and the third line contains sequence B as a string of k characters (1 ≤ m, k ≤ 1000). The given lines only contain characters "R", "S" and "P". Character "R" stands for the rock, character "S" represents the scissors and "P" represents the paper.

Output

Print two space-separated integers: the numbers of red spots Nikephoros and Polycarpus have.

Examples

Input

7
RPS
RSPP


Output

3 2

Input

5
RRRRRRRR
R


Output

0 0

Note

In the first sample the game went like this:

  * R - R. Draw. 
  * P - S. Nikephoros loses. 
  * S - P. Polycarpus loses. 
  * R - P. Nikephoros loses. 
  * P - R. Polycarpus loses. 
  * S - S. Draw. 
  * R - P. Nikephoros loses. 



Thus, in total Nikephoros has 3 losses (and 3 red spots), and Polycarpus only has 2.
import javax.swing.*;
import java.awt.*;
import java.io.*;
import java.util.*;

import static java.lang.Math.max;
import static java.lang.Math.min;
import static java.lang.Math.round;

public class Code implements Runnable {

    public static void main(String[] args) throws IOException {
        new Thread(new Code()).start();
    }

    private void solve() throws IOException {
        int n = nextInt();
        String first = nextToken(), second = nextToken();

        int nik = 0, pol = 0;
        byte[][] rounds = new byte[2][first.length() * second.length()];
        for(int i = 0; i < first.length() * second.length(); ++i) {
            if(first.charAt(i % first.length()) == second.charAt(i % second.length()))  continue;
            else if(winner(first.charAt(i % first.length()), second.charAt(i % second.length())))    rounds[0][i] = 1;
            else    rounds[1][i] = 1;
            nik += rounds[0][i];
            pol += rounds[1][i];
        }

        nik = n / rounds[0].length * nik;
        pol = n / rounds[0].length * pol;
        for(int i = 0; i < n % rounds[0].length; ++i) {
            nik += rounds[0][i];
            pol += rounds[1][i];
        }

        writer.println(pol + " " + nik);
    }

    private boolean winner(char f, char s) {
        if(f == 'R')
            if(s == 'S')    return true;
            else    return false;
        else if(f == 'S')
            if(s == 'R')    return false;
            else    return true;
        else if(s == 'S')   return false;
        else    return true;
    }

    private class Pair<E extends Comparable, V extends Comparable> implements Comparable<Pair<E, V>> {
        public Pair(E first, V second) {
            this.first = first;
            this.second = second;
        }

        @Override
        public int compareTo(Pair<E, V> obj) {
            if(first == obj.first)  return second.compareTo(obj.second);
            return first.compareTo(obj.first);
        }

        @Override
        public boolean equals(Object obj) {
            Pair other = (Pair)obj;
            return first.equals(other.first) && second.equals(other.second);
        }

        public E first;
        public V second;
    }

    @Override
    public void run() {
        try {
            if(in.equals(""))   reader = new BufferedReader(new InputStreamReader(System.in));
            else    reader = new BufferedReader(new FileReader(in));

            if(out.equals(""))  writer = new PrintWriter(new OutputStreamWriter(System.out));
            else    writer = new PrintWriter(new FileWriter(out));
            solve();
        } catch(IOException e) {
            e.printStackTrace();
        } finally {
            try {
                reader.close();
                writer.close();
            } catch(IOException e) {
                e.printStackTrace();
            }
        }
    }

    private int nextInt() throws IOException {
        return Integer.parseInt(nextToken());
    }

    private long nextLong() throws IOException {
        return Long.parseLong(nextToken());
    }

    private double nextDouble() throws IOException {
        return Double.parseDouble(nextToken());
    }

    private float nextFloat() throws IOException {
        return Float.parseFloat(nextToken());
    }

    private String nextToken() throws IOException {
        while(st == null || !st.hasMoreTokens())    st = new StringTokenizer(reader.readLine());
        return st.nextToken();
    }

    private String in = "", out = "";
    private BufferedReader reader;
    private PrintWriter writer;
    private StringTokenizer st;
}