You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

* In the i-th operation, you replace every element whose value is B_{i} with C_{i}.



For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

* All values in input are integers.
* 1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}
* B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:


N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}


Output

Print Q integers S_{i} to Standard Output in the following format:


S_{1}
S_{2}
\vdots
S_{Q}


Note that S_{i} may not fit into a 32-bit integer.

Examples

Input

4
1 2 3 4
3
1 2
3 4
2 4


Output

11
12
16


Input

4
1 1 1 1
3
1 2
2 1
3 5


Output

8
4
4


Input

2
1 2
3
1 100
2 100
100 1000


Output

102
200
2000
import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;
import java.util.stream.IntStream;

public class Main {

	public static void main(String[] args) {
		try (Scanner scanner = new Scanner(System.in)) {
			int n = scanner.nextInt();
			// 個々の数字の出現回数を保存するマップ
			Map<Integer, Integer> map = new HashMap<>();
			long sum = IntStream.range(0, n).mapToLong(i -> {
				int a = scanner.nextInt();
				map.put(a, map.getOrDefault(a, 0) + 1);
				return a;
			}).sum();
			int q = scanner.nextInt();
			for (int i = 0; i < q; i++) {
				int b = scanner.nextInt(), c = scanner.nextInt();
				int count = map.getOrDefault(b, 0);
				if (count > 0) {
					map.remove(b);
					map.put(c, map.getOrDefault(c, 0) + count);
					sum = sum + (c - b) * (long) count;
				}
				System.out.println(sum);
			}
		}
	}
}
