Let S(n) denote the sum of the digits in the decimal notation of n. For example, S(123) = 1 + 2 + 3 = 6.

We will call an integer n a Snuke number when, for all positive integers m such that m > n, \frac{n}{S(n)} \leq \frac{m}{S(m)} holds.

Given an integer K, list the K smallest Snuke numbers.

Constraints

* 1 \leq K
* The K-th smallest Snuke number is not greater than 10^{15}.

Input

Input is given from Standard Input in the following format:


K


Output

Print K lines. The i-th line should contain the i-th smallest Snuke number.

Example

Input

10


Output

1
2
3
4
5
6
7
8
9
19
#include<bits/stdc++.h>
#define F first
#define S second
#define int long long
#define double long double
using namespace std;
typedef pair<int,int> P;
typedef pair<int,P> iP;
typedef pair<P,int> Pi;
typedef pair<P,P> PP;
double eps=1e-8;
int mod=1e9+7;
int inf=1LL<<55;

priority_queue<P,vector<P>,greater<P> > pq;

template <typename T>
int Count(const vector<T> &v, T l,T r){
  //counting [l,r]
  auto L = lower_bound(v.begin(), v.end(), l );
  auto R = upper_bound(v.begin(), v.end(), r );
  // [l,r) change upper -> lower
  return R-L;
}

double cal(int a){
  int b=a,c=0;
  while(b)c+=b%10,b/=10;
  return 1.0*a/c;
}

signed main(){
  int k;
  cin>>k;
  int a=1,b=1;
  for(int i=0;i<k;i++){
    if(cal(a)>cal(a+b))a-=b,b*=10,i--;
    else cout<<a<<endl;
    a+=b;
  }
  
  return 0;
}
