You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

* In the i-th operation, you replace every element whose value is B_{i} with C_{i}.



For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

* All values in input are integers.
* 1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}
* B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:


N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}


Output

Print Q integers S_{i} to Standard Output in the following format:


S_{1}
S_{2}
\vdots
S_{Q}


Note that S_{i} may not fit into a 32-bit integer.

Examples

Input

4
1 2 3 4
3
1 2
3 4
2 4


Output

11
12
16


Input

4
1 1 1 1
3
1 2
2 1
3 5


Output

8
4
4


Input

2
1 2
3
1 100
2 100
100 1000


Output

102
200
2000
import java.util.*;
class Main{
  public static void main(String[] args){
Scanner sc=new Scanner(System.in);
		    int n=sc.nextInt();
		    long sum=0;
      Long f=new Long(1);
		    Map<Integer,Long> m=new HashMap<>();
		    for(int i=0;i<n;i++){
		    		int c=sc.nextInt();
		    		sum+=c;
            
		    		if(!m.containsKey(c)) {
		    			m.put(c,f);
		    		}else {
		    			m.put(c,m.get(c)+f);
		    		}
		    }int k=sc.nextInt();
		    for(int i=0;i<k;i++) {
		    	 int prev=sc.nextInt();
				    int fill=sc.nextInt();
				    if(m.containsKey(prev)) {
				    long g=m.get(prev);
				    sum=sum-prev*g;
				    sum=sum+fill*g;
				  				    m.remove(prev);
				    
				    if(!m.containsKey(fill)) {
		    			m.put(fill,g);
		    		}else {
		    			m.put(fill,m.get(fill)+g);
		    		}
				    
                    }
				    System.out.println(sum);
		    }
		    
		   
		 

  }
    
  }
