You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

* In the i-th operation, you replace every element whose value is B_{i} with C_{i}.



For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

* All values in input are integers.
* 1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}
* B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:


N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}


Output

Print Q integers S_{i} to Standard Output in the following format:


S_{1}
S_{2}
\vdots
S_{Q}


Note that S_{i} may not fit into a 32-bit integer.

Examples

Input

4
1 2 3 4
3
1 2
3 4
2 4


Output

11
12
16


Input

4
1 1 1 1
3
1 2
2 1
3 5


Output

8
4
4


Input

2
1 2
3
1 100
2 100
100 1000


Output

102
200
2000
import java.util.*;
import java.io.*;

class Main{
    public static void main(String[] args) throws IOException {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        StringTokenizer st  = new StringTokenizer(br.readLine());

        int N = Integer.parseInt(st.nextToken());
        
        long ans=0;
        HashMap<Integer, Integer> countMap = new HashMap();
        st  = new StringTokenizer(br.readLine());
        for (int i=1; i<=N; i++) {
            int x = Integer.parseInt(st.nextToken());
            countMap.put(x, countMap.getOrDefault(x, 0)+1);
            ans+=x;
        }

        st  = new StringTokenizer(br.readLine());

        int Q = Integer.parseInt(st.nextToken());

        while(Q--!=0){
            st  = new StringTokenizer(br.readLine());
            int a = Integer.parseInt(st.nextToken());
            int b = Integer.parseInt(st.nextToken());

            int ca = countMap.getOrDefault(a, 0);
            ans-=(long)a*(long)ca;
            ans+=(long)b*(long)ca;
            countMap.put(a, 0);
            countMap.put(b, countMap.getOrDefault(b, 0)+ca);
            System.out.println(ans);

        }


    }

}