Polycarp wants to buy exactly n shovels. The shop sells packages with shovels. The store has k types of packages: the package of the i-th type consists of exactly i shovels (1 ≤ i ≤ k). The store has an infinite number of packages of each type.

Polycarp wants to choose one type of packages and then buy several (one or more) packages of this type. What is the smallest number of packages Polycarp will have to buy to get exactly n shovels?

For example, if n=8 and k=7, then Polycarp will buy 2 packages of 4 shovels.

Help Polycarp find the minimum number of packages that he needs to buy, given that he: 

  * will buy exactly n shovels in total; 
  * the sizes of all packages he will buy are all the same and the number of shovels in each package is an integer from 1 to k, inclusive. 

Input

The first line contains an integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then, t test cases follow, one per line.

Each test case consists of two positive integers n (1 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 10^9) — the number of shovels and the number of types of packages.

Output

Print t answers to the test cases. Each answer is a positive integer — the minimum number of packages.

Example

Input


5
8 7
8 1
6 10
999999733 999999732
999999733 999999733


Output


2
8
1
999999733
1

Note

The answer to the first test case was explained in the statement.

In the second test case, there is only one way to buy 8 shovels — 8 packages of one shovel.

In the third test case, you need to buy a 1 package of 6 shovels.
import com.sun.org.apache.bcel.internal.generic.ARRAYLENGTH;

import javax.print.DocFlavor;
import java.io.*;
import java.lang.reflect.Array;
import java.net.Inet4Address;
import java.nio.charset.IllegalCharsetNameException;
import java.time.temporal.Temporal;
import java.util.*;
import java.util.concurrent.locks.ReentrantLock;

public class Solution {
    static TreeSet<Long> set = new TreeSet<>();
    public static void main(String[] args) throws IOException{
        Reader.init(System.in);
        int t =Reader.nextInt();
//        int t =1;
//        System.out.println(cnt);
        PrintWriter out = new PrintWriter(System.out);
        int i = 1;
        while (t-->0){
//            out.print("Case #" + i + ": ");
            solve(out);
            i++;
        }
        out.close();
    }
    static void solve(PrintWriter out)throws IOException {
        long n = Reader.nextLong();
        long k = Reader.nextLong();
        long ans = Integer.MAX_VALUE;
        for (int i = 1; i <= Math.min(k , Math.sqrt(n)) ; i++){
            if (n%i==0){
                ans = Math.min(n/i , ans);
                if (n/i <= k ){
                    ans = Math.min(ans, i);
                }
            }
        }
        System.out.println(ans);


    }



    static long gcd(long a, long b)
    {
        if (b == 0)
            return a;
        return gcd(b, a % b);

    }



    public static int stringCompare(String str1, String str2)
    {

        int l1 = str1.length();
        int l2 = str2.length();
        int lmin = Math.min(l1, l2);

        for (int i = 0; i < lmin; i++) {
            int str1_ch = (int)str1.charAt(i);
            int str2_ch = (int)str2.charAt(i);

            if (str1_ch != str2_ch) {
                return str1_ch - str2_ch;
            }
        }

        // Edge case for strings like
        // String 1="Geeks" and String 2="Geeksforgeeks"
        if (l1 != l2) {
            return l1 - l2;
        }

        // If none of the above conditions is true,
        // it implies both the strings are equal
        else {
            return 0;
        }
    }








    static int next(long[] arr, long target)
    {
        int start = 0, end = arr.length - 1;

        int ans = -1;
        while (start <= end) {
            int mid = (start + end) / 2;

            // Move to right side if target is
            // greater.
            if (arr[mid] <= target) {
                start = mid + 1;
            }

            // Move left side.
            else {
                ans = mid;
                end = mid - 1;
            }
        }
        return ans;
    }

//    static int find(int x) {
//        return parent[x] == x ? x : (parent[x] = find(parent[x]));
//    }
//    static boolean merge(int x, int y) {
//        x = find(x);
//        y = find(y);
//        if (x==y){
//            return false;
//        }
//        parent[x] = y;
//        return true;
//    }







    public static void sortbyColumn(int arr[][], int col)
    {
        // Using built-in sort function Arrays.sort
        Arrays.sort(arr, new Comparator<int[]>() {

            @Override
            // Compare values according to columns
            public int compare(final int[] entry1,
                               final int[] entry2) {

                // To sort in descending order revert
                // the '>' Operator
                if (entry1[col] > entry2[col])
                    return 1;
                else
                    return -1;
            }
        });  // End of function call sort().
    }



}


class Reader {
    static BufferedReader reader;
    static StringTokenizer tokenizer;

    /** call this method to initialize reader for InputStream */
    static void init(InputStream input) {
        reader = new BufferedReader(
                new InputStreamReader(input) );
        tokenizer = new StringTokenizer("");
    }
    /** get next word */
    static String next() throws IOException {
        while ( ! tokenizer.hasMoreTokens() ) {
            //TODO add check for eof if necessary
            tokenizer = new StringTokenizer(
                    reader.readLine() );
        }
        return tokenizer.nextToken();
    }

    static int nextInt() throws IOException {
        return Integer.parseInt( next() );
    }
    static long nextLong() throws IOException {
        return Long.parseLong( next() );
    }

    static double nextDouble() throws IOException {
        return Double.parseDouble( next() );
    }
}
class Pair{
    int a;
    int b;

    public Pair(int a, int b) {
        this.a = a;
        this.b = b;
    }
}
class MergeSort
{
    // Merges two subarrays of arr[].
    // First subarray is arr[l..m]
    // Second subarray is arr[m+1..r]

    void merge(int arr[], int l, int m, int r)
    {
        // Find sizes of two subarrays to be merged
        int n1 = m - l + 1;
        int n2 = r - m;

        /* Create temp arrays */
        int L[] = new int [n1];
        int R[] = new int [n2];

        /*Copy data to temp arrays*/
        for (int i=0; i<n1; ++i)
            L[i] = arr[l + i];
        for (int j=0; j<n2; ++j)
            R[j] = arr[m + 1+ j];


        /* Merge the temp arrays */

        // Initial indexes of first and second subarrays
        int i = 0, j = 0;

        // Initial index of merged subarry array
        int k = l;
        while (i < n1 && j < n2)
        {
            if (L[i] <= R[j])
            {
                arr[k] = L[i];
                i++;
            }
            else
            {
                arr[k] = R[j];
                j++;
            }
            k++;
        }

        /* Copy remaining elements of L[] if any */
        while (i < n1)
        {
            arr[k] = L[i];
            i++;
            k++;
        }

        /* Copy remaining elements of R[] if any */
        while (j < n2)
        {
            arr[k] = R[j];
            j++;
            k++;
        }
    }

    // Main function that sorts arr[l..r] using
    // merge()
    void sort(int arr[], int l, int r)
    {
        if (l < r)
        {
            // Find the middle point
            int m = (l+r)/2;

            // Sort first and second halves
            sort(arr, l, m);
            sort(arr , m+1, r);

            // Merge the sorted halves
            merge(arr, l, m, r);
        }
    }

    /* A utility function to print array of size n */
    static void printArray(int arr[])
    {
        int n = arr.length;
        for (int i=0; i<n; ++i)
            System.out.print(arr[i] + " ");
        System.out.println();
    }

    // Driver method

}

class Node implements Comparable<Node>{
    int a;
    int b;
    Node (int a , int b){
        this.a = a;
        this.b = b;
    }



    public int compareTo(Node o) {
        if ((this.a%2) == (o.a%2)){
            return (this.b - o.b);
        }
        else{
            return this.a - o.a;
        }
    }
}
class Graph
{
    int V;// No. of vertices

    //An Array of List which contains
    //references to the Adjacency List of
    //each vertex
    List <Integer> adj[];
    public Graph(int V)// Constructor
    {
        this.V = V;
        adj = new ArrayList[V];
        for(int i = 0; i < V; i++)
            adj[i]=new ArrayList<Integer>();
    }

    // function to add an edge to graph
    public void addEdge(int u,int v)
    {
        adj[u].add(v);
    }
    // prints a Topological Sort of the complete graph
    public void topologicalSort(PrintWriter out,TreeSet set)
    {
        // Create a array to store indegrees of all
        // vertices. Initialize all indegrees as 0.
        int indegree[] = new int[V];

        // Traverse adjacency lists to fill indegrees of
        // vertices. This step takes O(V+E) time
        for(int i = 0; i < V; i++)
        {
            ArrayList<Integer> temp = (ArrayList<Integer>) adj[i];
            for(int node : temp)
            {
                indegree[node]++;
            }
        }

        // Create a queue and enqueue all vertices with
        // indegree 0
        Queue<Integer> q = new LinkedList<Integer>();
        for(int i = 0;i < V; i++)
        {
            if(indegree[i]==0)
                q.add(i);
        }

        // Initialize count of visited vertices
        int cnt = 0;

        // Create a vector to store result (A topological
        // ordering of the vertices)
        Vector <Integer> topOrder=new Vector<Integer>();
        while(!q.isEmpty())
        {
            // Extract front of queue (or perform dequeue)
            // and add it to topological order
            int u=q.poll();
            topOrder.add(u);

            // Iterate through all its neighbouring nodes
            // of dequeued node u and decrease their in-degree
            // by 1
            for(int node : adj[u])
            {
                // If in-degree becomes zero, add it to queue
                if(--indegree[node] == 0)
                    q.add(node);
            }
            cnt++;
        }

        // Check if there was a cycle
        if(cnt != V)
        {
            out.println(-1);
            return ;
        }

        // Print topological order
        for(int i : topOrder)
        {
            if (set.contains((char)('A'+i))) {
                out.print((char) ('A' + i));
            }
        }
        out.println();
    }
}
// Driver program to test above functions
