There are N boxes arranged in a circle. The i-th box contains A_i stones.

Determine whether it is possible to remove all the stones from the boxes by repeatedly performing the following operation:

* Select one box. Let the box be the i-th box. Then, for each j from 1 through N, remove exactly j stones from the (i+j)-th box. Here, the (N+k)-th box is identified with the k-th box.



Note that the operation cannot be performed if there is a box that does not contain enough number of stones to be removed.

Constraints

* 1 ≦ N ≦ 10^5
* 1 ≦ A_i ≦ 10^9

Input

The input is given from Standard Input in the following format:


N
A_1 A_2 … A_N


Output

If it is possible to remove all the stones from the boxes, print `YES`. Otherwise, print `NO`.

Examples

Input

5
4 5 1 2 3


Output

YES


Input

5
6 9 12 10 8


Output

YES


Input

4
1 2 3 1


Output

NO
import sys
N=int(input())
A=list(map(int,input().split()))
total=0
for i in range(N):
  total+=A[i]
if total*2/((N+1)*N)%1!=0:
  print("NO")
  sys.exit()
times=int(total*2/((N+1)*N))
if (times-A[0]+A[N-1])/N%1!=0 or times-A[0]+A[N-1]<0:
  print("NO")
  sys.exit()
B=(times-A[0]+A[N-1])/N
for i in range(N-1):
  B+=(times-A[i+1]+A[i])/N
  if (times-A[i+1]+A[i])/N%1!=0 or times-A[i+1]+A[i]<0:
    print("NO")
    sys.exit()
if B==times:
  print("YES")
else:
  print("NO")