Valera had two bags of potatoes, the first of these bags contains x (x ≥ 1) potatoes, and the second — y (y ≥ 1) potatoes. Valera — very scattered boy, so the first bag of potatoes (it contains x potatoes) Valera lost. Valera remembers that the total amount of potatoes (x + y) in the two bags, firstly, was not gerater than n, and, secondly, was divisible by k.

Help Valera to determine how many potatoes could be in the first bag. Print all such possible numbers in ascending order.

Input

The first line of input contains three integers y, k, n (1 ≤ y, k, n ≤ 109; <image> ≤ 105).

Output

Print the list of whitespace-separated integers — all possible values of x in ascending order. You should print each possible value of x exactly once.

If there are no such values of x print a single integer -1.

Examples

Input

10 1 10


Output

-1


Input

10 6 40


Output

2 8 14 20 26 
import sys,math
from collections import deque,defaultdict
import operator as op
from functools import reduce
from itertools import permutations

#sys.setrecursionlimit(10**6) 

I=sys.stdin.readline

 #s="abcdefghijklmnopqrstuvwxyz"

"""
x_move=[-1,0,1,0,-1,1,1,-1]
y_move=[0,1,0,-1,1,1,-1,-1]
"""
def ii():
	return int(I().strip())
def li():
	return list(map(int,I().strip().split()))
def mi():
	return map(int,I().strip().split())

"""def ncr(n, r):
    r = min(r, n-r)
    numer = (reduce(op.mul, range(n, n-r, -1), 1))%(10**9+7)
    denom = (reduce(op.mul, range(1, r+1), 1))%(10**9+7)
    return (numer // denom)%(10**9+7)"""
def ncr(n, r, p):
    # initialize numerator
    # and denominator
    num = den = 1
    for i in range(r):
        num = (num * (n - i)) % p
        den = (den * (i + 1)) % p
    return (num * pow(den, 
            p - 2, p)) % p
 

def gcd(x, y):
    while y:
        x, y = y, x % y
    return x

def valid(row,col,rows,cols,rcross,lcross):
 	return rows[row]==0 and cols[col]==0 and rcross[col+row]==0 and lcross[col-row]==0


def div(n):
	tmp=[]
	for i in range(2,int(n**.5)+1):
		if n%i==0:
			cnt=0
			while(n%i==0):
				n=n//i 
				cnt+=1
			tmp.append((i,cnt))
	if n>1:
		tmp.append((n,1))
	return tmp

def isPrime(n):
	if n<=1:
		return False
	elif n<=2:
		return True
	else:
		flag=True
		for i in range(2,int(n**.5)+1):
			if n%i==0:
				flag=False
				break
		return flag

def s(b):
	ans=[]
	while b>0:
		tmp=b%10
		ans.append(tmp)
		b=b//10
	return ans



def main():
	y,k,n=mi()

	
	ans=[]
	z=k
	while z<=n:		
		if z-y>0:
			ans.append(z-y)
		z+=k


	if len(ans)==0:
		print(-1)
	else:
		print(*ans)









	

	


 
	
	








	



	
		




	










	


	

	

		



		

		
		


	
	

		
	

		




		




			












			
		
			



		


	
			
						
			








	





			
		



	
			





	

























	
	
	





if __name__ == '__main__':
	main()