Takahashi has two positive integers A and B.

It is known that A plus B equals N. Find the minimum possible value of "the sum of the digits of A" plus "the sum of the digits of B" (in base 10).

Constraints

* 2 ≤ N ≤ 10^5
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the minimum possible value of "the sum of the digits of A" plus "the sum of the digits of B".

Examples

Input

15


Output

6


Input

100000


Output

10
import java.util.*;
import java.io.*;
import java.lang.*;
import java.math.BigInteger;

public class Main {

    public static void main(String[] args) {
        try {
            InputReader in;
            PrintWriter out;
            boolean useOutput = false;
            // if (System.getProperty("ONLINE_JUDGE") == null) useOutput = true;
            if (useOutput) {
                FileInputStream fin = new FileInputStream(new File("src/testdata.in"));
                in = new InputReader(fin);
                FileOutputStream fout = new FileOutputStream(new File("src/testData.out"));
                out = new PrintWriter(fout);
            } else {
                InputStream inputStream = System.in;
                in = new InputReader(inputStream);
                OutputStream outputStream = System.out;
                out = new PrintWriter(outputStream);
            }
            Solver solver = new Solver();
            solver.solve(in, out);
            out.close();
            // fin.close();
            // fout.close();
        } catch (Exception e) {
            e.printStackTrace();
        }
    }

    static class Solver
    {

        public void solve (InputReader cin, PrintWriter cout)
        {
            try {
                int n;
                n = cin.nextInt();
                int sum = 0;
                while (n > 0) {
                    sum += n % 10;
                    n = n / 10;
                }
                if (sum == 1) {
                    sum = 10;
                }
                cout.println(sum);
            } catch (RuntimeException e) {
                e.printStackTrace();
                return;
            } catch (Exception e) {
                e.printStackTrace();
                return;
            }

        }
    }

    static class InputReader {
        public BufferedReader reader;
        public StringTokenizer tokenizer;

        public InputReader(InputStream stream) {
            reader = new BufferedReader(new InputStreamReader(stream));
            tokenizer = null;
        }

        public String next() {
            while (tokenizer == null || !tokenizer.hasMoreTokens()) {
                try {
                    tokenizer = new StringTokenizer(reader.readLine());
                } catch (IOException e) {
                    throw new RuntimeException(e);
                }
            }
            return tokenizer.nextToken();
        }

        public int nextInt() {
            return Integer.parseInt(next());
        }

        public long nextLong () {
            return Long.parseLong(next());
        }

        public double nextDouble () {
            return Double.parseDouble(next());
        }

    }

}