You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

* In the i-th operation, you replace every element whose value is B_{i} with C_{i}.



For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

* All values in input are integers.
* 1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}
* B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:


N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}


Output

Print Q integers S_{i} to Standard Output in the following format:


S_{1}
S_{2}
\vdots
S_{Q}


Note that S_{i} may not fit into a 32-bit integer.

Examples

Input

4
1 2 3 4
3
1 2
3 4
2 4


Output

11
12
16


Input

4
1 1 1 1
3
1 2
2 1
3 5


Output

8
4
4


Input

2
1 2
3
1 100
2 100
100 1000


Output

102
200
2000
import java.util.*;

public class Main {

	private static List<Long> getStrings(Scanner sc, int num) {
		List<Long> stringList = new ArrayList<>();
		while(num>0) {
			long nextInt = sc.nextLong();
			stringList.add(nextInt);
			num--;
		}
		return stringList;
	}

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		int n = sc.nextInt();
		List<Long> array = getStrings(sc, n);
		int q = sc.nextInt();
		long sum = 0;
		Map<Long, Integer> map = new HashMap<>();
		for (int i = 0; i < array.size(); i++) {
			long key = array.get(i);
			if (!map.containsKey(key)) {
				map.put(key, 1);
			} else {
				int times = map.get(key);
				map.put(key, times+1);
			}
			sum+=key;
		}
		while(q > 0) {
			long b = sc.nextLong();
			long c = sc.nextLong();
			if (map.containsKey(b)) {
				int t = map.get(b);
				sum = sum + t*(c-b);
				map.remove(b);
				if (map.containsKey(c)) {
					map.put(c, t+map.get(c));
				} else {
					map.put(c, t);
				}
			}
			System.out.println(sum);
			q--;
		}
	}

}
