There are N slimes standing on a number line. The i-th slime from the left is at position x_i.

It is guaruanteed that 1 \leq x_1 < x_2 < \ldots < x_N \leq 10^{9}.

Niwango will perform N-1 operations. The i-th operation consists of the following procedures:

* Choose an integer k between 1 and N-i (inclusive) with equal probability.
* Move the k-th slime from the left, to the position of the neighboring slime to the right.
* Fuse the two slimes at the same position into one slime.



Find the total distance traveled by the slimes multiplied by (N-1)! (we can show that this value is an integer), modulo (10^{9}+7). If a slime is born by a fuse and that slime moves, we count it as just one slime.

Constraints

* 2 \leq N \leq 10^{5}
* 1 \leq x_1 < x_2 < \ldots < x_N \leq 10^{9}
* x_i is an integer.

Input

Input is given from Standard Input in the following format:


N
x_1 x_2 \ldots x_N


Output

Print the answer.

Examples

Input

3
1 2 3


Output

5


Input

12
161735902 211047202 430302156 450968417 628894325 707723857 731963982 822804784 880895728 923078537 971407775 982631932


Output

750927044
def extgcd(a,b):
    r = [1,0,a]
    w = [0,1,b]
    while w[2]!=1:
        q = r[2]//w[2]
        r2 = w
        w2 = [r[0]-q*w[0],r[1]-q*w[1],r[2]-q*w[2]]
        r = r2
        w = w2
    return [w[0],w[1]]
def mod_inv(a,m):
    x = extgcd(a,m)[0]
    return (m+x%m)%m
    
n=int(input())
x=list(map(int,input().split()))
mod=10**9+7
l=[]
z=1
for i in range(1,n):
  z*=i
  z%=mod
l2=[z for i in range(n-1)]
for i in range(n-1):
  l.append(x[i+1]-x[i])
for i in range(n-1):
  l2[i]*=mod_inv((i+1),mod)
  l2[i]%=mod
l3=[]
l3.append(l2[0])
for i in range(n-2):
  l3.append(l3[-1]+l2[i+1])
ans=0
for i in range(n-1):
  ans+=l3[i]*l[i]
  ans%=mod
print(ans)