One

Problem Statement

A beautiful mountain range can be seen from the train window.
The window is a rectangle with the coordinates of the lower left corner (0, 0) and the coordinates of the upper right corner (W, H).
N peaks can be seen from the window, and the i-th peak has the shape of an upwardly convex parabola y = a_i (x-p_i) ^ 2 + q_i.
Find the length of the boundary between the mountain and the sky.

The following three figures correspond to Sample Input. The part shown by the thick line is the boundary between the mountain and the sky.

<image> <image> <image>

Constraints

* 1 ≤ W, H ≤ 100
* 1 ≤ N ≤ 50
* -100 ≤ a_i ≤ -1
* 0 ≤ p_i ≤ W
* 1 ≤ q_i ≤ H
* If i \ neq j, then (a_i, p_i, q_i) \ neq (a_j, p_j, q_j)

Input

Input follows the following format. All given numbers are integers.


W H N
a_1 p_1 q_1
...
a_N p_N q_N

Output

Output the length of the boundary between the mountain and the sky on one line.
The output value must have an absolute or relative error of less than 10 ^ {-6} with the true value.

Examples

Input

20 20 1
-1 10 10


Output

21.520346288593280


Input

20 20 2
-1 10 10
-2 10 5


Output

21.520346288593280


Input

15 100 2
-2 5 100
-2 10 100


Output

126.921542730127873
#include <cstdio>
#include <cmath>
#include <vector>
#include <algorithm>
using namespace std;
#define INTERVAL 2097152
#define EPS 1e-9

int W,H,N;
int yama[101][3];
double xint[101][2];
double quad(double x,int nyama)
{
  double a=yama[nyama][0];
  double p=yama[nyama][1];
  double q=yama[nyama][2];
  return a*(x-p)*(x-p)+q;
}
double x_int(int nyama,int left)
{
  double a=yama[nyama][0];
  double p=yama[nyama][1];
  double q=yama[nyama][2];
  return p+1.0*left*sqrt(-q/a);
}
double q_int(int nyama1, int nyama2, int left)
{
  int a1=yama[nyama1][0];
  int p1=yama[nyama1][1];
  int q1=yama[nyama1][2];
  int a2=yama[nyama2][0];
  int p2=yama[nyama2][1];
  int q2=yama[nyama2][2];
  if (a1==a2)
  {
    if(p1==p2)
      return -1.0;
    else
    {
        double ans=0.5*(p1+p2+(q2-q1)*1.0/(a1*(p2-p1)));
        if (quad(ans,nyama1)>0-EPS)
          return ans;
        else
          return -1.0;
    }

  }
  else
  {
    double A=a1-a2;
    double B=2*(p2*a2-p1*a1);
    double C=a1*p1*p1-a2*p2*p2+q1-q2;
    double delta=B*B-4*A*C;
    if (delta>0-EPS)
    {
      double ans=(-B+1.0*left*sqrt(delta))/(2.0*A);
      if (quad(ans,nyama1)>0-EPS)
        return ans;
      else
        return -1.0;
    }
    else
      return -1.0;
  }
}

double dquad_dx(double x,int nyama)
{
  double a=yama[nyama][0];
  double p=yama[nyama][1];
  return 2.0*a*(x-p);
}

double cir(double x,int nyama)
{
  double fpx=dquad_dx(x,nyama);
  return sqrt(1+fpx*fpx);
}

double integrates(int s, int nyama)
{
  double a=1.0*s/INTERVAL;
  double b=1.0*(s+1)/INTERVAL;
  //return 1.0/6.0/INTERVAL*(cir(a,nyama)+cir(b,nyama)+4*cir((a+b)/2.0,nyama));
  return 1.0/2.0/INTERVAL*(cir(a,nyama)+cir(b,nyama));
}
double integrated(double x, int nyama)
{
  double a=yama[nyama][0];
  double fpx=dquad_dx(x,nyama);
  return (fpx*cir(x,nyama)+log(abs(fpx+cir(x,nyama))))/4.0/a;
}
double integrate(double b,double e,int nyama)
{
/*
  int begin=b*INTERVAL;
  int end=e*INTERVAL;
  double ans=0.0;
  for(int i=begin;i<end;i++)
  {
    ans+=integrates(i,nyama);
  }
  return ans;
  */
  return integrated(e,nyama)-integrated(b,nyama);
}
vector<double> sec;
int main()
{
  scanf("%d%d%d",&W,&H,&N);
  for(int i=0;i<N;i++)
  {
    scanf("%d%d%d",&yama[i][0],&yama[i][1],&yama[i][2]);
    xint[i][0]=x_int(i,-1);
    xint[i][1]=x_int(i,1);
    double tmp1=x_int(i,-1);
    double tmp2=x_int(i,1);
    if (-EPS< tmp1 && tmp1<W+EPS)
      sec.push_back(tmp1);
    if (-EPS< tmp2 && tmp2<W+EPS && fabs(tmp1-tmp2)>EPS)
      sec.push_back(tmp2);
  }
  for(int i=0;i<N;i++)
    for(int j=i+1;j<N;j++)
    {
      double tmp1=q_int(i,j,-1);
      double tmp2=q_int(i,j,1);
      if (-EPS< tmp1 && tmp1<W+EPS)
        sec.push_back(tmp1);
      if (-EPS< tmp2 && tmp2<W+EPS && fabs(tmp1-tmp2)>EPS)
        sec.push_back(tmp2);
    }
  sort(sec.begin(),sec.end());
  sec.erase(unique(sec.begin(),sec.end()), sec.end() );

  double ans=0;
  double mae=0.0;
  //for(vector<double>::iterator it=sec.begin();it!=sec.end();++it)
  vector<double>::iterator it=sec.begin();
  while(1)
  {
    int nyama=-1;
    double max=0.0;
    double now_p;
    if (it==sec.end())
      now_p=1.0*W;
    else
      now_p=(*it);
    //printf("%lf\n",now_p);
    for(int j=0;j<N;j++)
    {
      double x=(mae+now_p)/2.0;
      if (x<xint[j][0]-EPS||x>xint[j][1]+EPS) continue;
      double y=quad(x,j);
      if(y>max+EPS)
      {
        max=y;
        nyama=j;
      }
    }
    if (nyama!=-1)
      ans+=integrate(mae,now_p,nyama);
    if (it==sec.end()) break;
    mae=now_p;
    ++it;
  }

  printf("%lf\n",ans);
}

