There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
#include <cstdio>

int N, C;
char s[105];

int main() {
  scanf("%d", &N);
  scanf("%s", s + 1);
  for (int i = 1; i <= N; ++i)
    C += s[i] == 'R' ? 1 : -1;
  puts(C > 0 ? "Yes" : "No");
  return 0;
}