There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.Scanner;
public class Main{
    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        int a = scan.nextInt();
        String str = scan.next();
        String[] strArray = new String[str.length()];
        String r = "R";
        int redcount = 0;
        int bulecount = 0;

        for (int i = 0; i < str.length(); i++) {
            String str2 = String.valueOf(str.charAt(i));
            strArray[i] = str2;

            if(strArray[i].equals(r)){
                redcount++;
            }
            
            else{
                bulecount++;
            }

        }

        if((redcount - bulecount) > 0){            
            System.out.println("Yes");
        }
        else{
            System.out.println("No");
        }
    }
}
