Tavas is a cheerleader in the new sports competition named "Pashmaks".

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This competition consists of two part: swimming and then running. People will immediately start running R meters after they finished swimming exactly S meters. A winner is a such person that nobody else finishes running before him/her (there may be more than one winner).

Before the match starts, Tavas knows that there are n competitors registered for the match. Also, he knows that i-th person's swimming speed is si meters per second and his/her running speed is ri meters per second. Unfortunately, he doesn't know the values of R and S, but he knows that they are real numbers greater than 0.

As a cheerleader, Tavas wants to know who to cheer up. So, he wants to know all people that might win. We consider a competitor might win if and only if there are some values of R and S such that with these values, (s)he will be a winner.

Tavas isn't really familiar with programming, so he asked you to help him.

Input

The first line of input contains a single integer n (1 ≤ n ≤ 2 × 105).

The next n lines contain the details of competitors. i-th line contains two integers si and ri (1 ≤ si, ri ≤ 104).

Output

In the first and the only line of output, print a sequence of numbers of possible winners in increasing order.

Examples

Input

3
1 3
2 2
3 1


Output

1 2 3 


Input

3
1 2
1 1
2 1


Output

1 3 
#include <bits/stdc++.h>
inline int gi() {
  int x = 0, f = 1;
  char ch = getchar();
  while (!isdigit(ch)) {
    if (ch == '-') f = -1;
    ch = getchar();
  }
  while (isdigit(ch)) x = x * 10 + ch - '0', ch = getchar();
  return x * f;
}
std::set<std::pair<int, int> > M;
struct yyb {
  int x, y, i;
  long double k, b;
} s[300010], stk[300010];
inline bool cmp_k(const yyb& a, const yyb& b) {
  if (a.y != b.y)
    return a.y < b.y;
  else
    return a.x > b.x;
}
inline bool cmp_i(const yyb& a, const yyb& b) { return a.i < b.i; }
int main() {
  int n = gi();
  for (int i = 1; i <= n; ++i)
    s[i].x = gi(), s[i].y = gi(), s[i].i = i, s[i].k = 1000000000.0 / s[i].y,
    s[i].b = 1000000000.0 / s[i].x;
  std::sort(s + 1, s + n + 1, cmp_k);
  int top = 0;
  stk[++top] = (yyb){0, 0, 0, 1e18, 0};
  for (int i = 1; i <= n; ++i) {
    if (s[i].y == s[i - 1].y) continue;
    while (top > 1 && stk[top].y != stk[top - 1].y &&
           (-(s[i].b - stk[top].b) / (s[i].k - stk[top].k) + 1e-15 <
            -(stk[top].b - stk[top - 1].b) / (stk[top].k - stk[top - 1].k))) {
      --top;
    }
    stk[++top] = s[i];
  }
  std::sort(s + 1, s + n + 1, cmp_i);
  for (int i = 1; i <= top; ++i) M.insert(std::make_pair(stk[i].x, stk[i].y));
  for (int i = 1; i <= n; ++i)
    if (M.find(std::make_pair(s[i].x, s[i].y)) != M.end()) printf("%d ", i);
  return 0;
}
