You are given three sequences: a_1, a_2, …, a_n; b_1, b_2, …, b_n; c_1, c_2, …, c_n.

For each i, a_i ≠ b_i, a_i ≠ c_i, b_i ≠ c_i.

Find a sequence p_1, p_2, …, p_n, that satisfy the following conditions:

  * p_i ∈ \\{a_i, b_i, c_i\}
  * p_i ≠ p_{(i mod n) + 1}.



In other words, for each element, you need to choose one of the three possible values, such that no two adjacent elements (where we consider elements i,i+1 adjacent for i<n and also elements 1 and n) will have equal value.

It can be proved that in the given constraints solution always exists. You don't need to minimize/maximize anything, you need to find any proper sequence.

Input

The first line of input contains one integer t (1 ≤ t ≤ 100): the number of test cases.

The first line of each test case contains one integer n (3 ≤ n ≤ 100): the number of elements in the given sequences.

The second line contains n integers a_1, a_2, …, a_n (1 ≤ a_i ≤ 100).

The third line contains n integers b_1, b_2, …, b_n (1 ≤ b_i ≤ 100).

The fourth line contains n integers c_1, c_2, …, c_n (1 ≤ c_i ≤ 100).

It is guaranteed that a_i ≠ b_i, a_i ≠ c_i, b_i ≠ c_i for all i.

Output

For each test case, print n integers: p_1, p_2, …, p_n (p_i ∈ \\{a_i, b_i, c_i\}, p_i ≠ p_{i mod n + 1}).

If there are several solutions, you can print any.

Example

Input


5
3
1 1 1
2 2 2
3 3 3
4
1 2 1 2
2 1 2 1
3 4 3 4
7
1 3 3 1 1 1 1
2 4 4 3 2 2 4
4 2 2 2 4 4 2
3
1 2 1
2 3 3
3 1 2
10
1 1 1 2 2 2 3 3 3 1
2 2 2 3 3 3 1 1 1 2
3 3 3 1 1 1 2 2 2 3


Output


1 2 3
1 2 1 2
1 3 4 3 2 4 2
1 3 2
1 2 3 1 2 3 1 2 3 2

Note

In the first test case p = [1, 2, 3].

It is a correct answer, because:

  * p_1 = 1 = a_1, p_2 = 2 = b_2, p_3 = 3 = c_3 
  * p_1 ≠ p_2 , p_2 ≠ p_3 , p_3 ≠ p_1 



All possible correct answers to this test case are: [1, 2, 3], [1, 3, 2], [2, 1, 3], [2, 3, 1], [3, 1, 2], [3, 2, 1].

In the second test case p = [1, 2, 1, 2].

In this sequence p_1 = a_1, p_2 = a_2, p_3 = a_3, p_4 = a_4. Also we can see, that no two adjacent elements of the sequence are equal.

In the third test case p = [1, 3, 4, 3, 2, 4, 2].

In this sequence p_1 = a_1, p_2 = a_2, p_3 = b_3, p_4 = b_4, p_5 = b_5, p_6 = c_6, p_7 = c_7. Also we can see, that no two adjacent elements of the sequence are equal.
import java.sql.SQLOutput;
import java.util.*;
import java.io.*;
import java.math.*;

public class MyProgram {
    public static FastIO file = new FastIO();

    private static void solve() {
        int tt = nextInt();
        while (tt-- > 0) {
            int n = nextInt();
            int[]arr1 = nextArray(n), arr2 = nextArray(n), arr3 = nextArray(n);
            int previous = arr1[0];
            System.out.print(arr1[0] + " ");
            for (int i = 1; i < n-1; i++) {
                if (arr1[i] == previous) {
                    System.out.print(arr2[i] + " ");
                    previous = arr2[i];
                }
                else {
                    System.out.print(arr1[i] + " ");
                    previous = arr1[i];
                }
            }
            if (arr1[n-1] != arr1[0] && arr1[n-1]!= previous) System.out.println(arr1[n-1]);
            else if (arr2[n-1] != arr1[0] && arr2[n-1] != previous) System.out.println(arr2[n-1]);
            else System.out.println(arr3[n-1]);
        }
    }

    private static int[] nextArray(int n) {
        int[] a = new int[n];
        for (int i = 0; i < n; i++) a[i] = nextInt();
        return a;
    }

    public static int[][] nextArray2D(int n, int m) {
        int[][] result = new int[n][];
        for (int i = 0; i < n; i++) {
            result[i] = nextArray(m);
        }
        return result;
    }

    public static long pow(long n, long p) {
        long ret = 1L;
        while (p > 0) {
            if (p % 2 != 0L)
                ret *= n;
            n *= n;
            p >>= 1L;
        }
        return ret;
    }

    public static String next() {
        return file.next();
    }

    public static int nextInt() {
        return file.nextInt();
    }

    public static long nextLong() {
        return file.nextLong();
    }

    public static double nextDouble() {
        return file.nextDouble();
    }

    public static String nextLine() {
        return file.nextLine();
    }

    public static class FastIO {
        BufferedReader br;
        StringTokenizer st;
        PrintWriter out;

        public FastIO() {
            br = new BufferedReader(new InputStreamReader(System.in));
            out = new PrintWriter(System.out);
        }

        String next() {
            while (st == null || !st.hasMoreElements()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }

        int nextInt() {
            return Integer.parseInt(next());
        }

        long nextLong() {
            return Long.parseLong(next());
        }

        double nextDouble() {
            return Double.parseDouble(next());
        }

        String nextLine() {
            String str = "";
            try {
                str = br.readLine();
            } catch (IOException e) {
                e.printStackTrace();
            }
            return str;
        }

    }

    public static void main(String[] args) {
        solve();
    }


}