Tavas is a cheerleader in the new sports competition named "Pashmaks".

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This competition consists of two part: swimming and then running. People will immediately start running R meters after they finished swimming exactly S meters. A winner is a such person that nobody else finishes running before him/her (there may be more than one winner).

Before the match starts, Tavas knows that there are n competitors registered for the match. Also, he knows that i-th person's swimming speed is si meters per second and his/her running speed is ri meters per second. Unfortunately, he doesn't know the values of R and S, but he knows that they are real numbers greater than 0.

As a cheerleader, Tavas wants to know who to cheer up. So, he wants to know all people that might win. We consider a competitor might win if and only if there are some values of R and S such that with these values, (s)he will be a winner.

Tavas isn't really familiar with programming, so he asked you to help him.

Input

The first line of input contains a single integer n (1 ≤ n ≤ 2 × 105).

The next n lines contain the details of competitors. i-th line contains two integers si and ri (1 ≤ si, ri ≤ 104).

Output

In the first and the only line of output, print a sequence of numbers of possible winners in increasing order.

Examples

Input

3
1 3
2 2
3 1


Output

1 2 3 


Input

3
1 2
1 1
2 1


Output

1 3 
#include <bits/stdc++.h>
using namespace std;
const int N = 3e5 + 10;
double INF = 1000000000000.0;
struct node {
  int a, b, id;
} p[N];
int v[N], jd[N];
bool cmp(node a, node b) { return a.a == b.a ? (a.b > b.b) : a.a > b.a; }
int top, sta1[N], top1;
int sta[N];
double calk(int x, int y) {
  return (1.0 * p[x].a * p[y].a * (p[y].b - p[x].b)) /
         (1.0 * p[x].b * p[y].b * (p[y].a - p[x].a));
}
int main() {
  int n;
  scanf("%d", &n);
  for (int i = 1; i <= n; ++i) scanf("%d%d", &p[i].a, &p[i].b);
  for (int i = 1; i <= n; ++i) p[i].id = i;
  sort(p + 1, p + n + 1, cmp);
  int mn = p[1].b;
  for (int i = 2; i <= n; ++i) {
    if (p[i].b <= mn)
      v[i] = 1;
    else
      mn = p[i].b;
  }
  sta[++top] = 1;
  for (int i = 1; i <= n; ++i) {
    if (v[i]) continue;
    while (top > 1 && calk(sta[top], sta[top - 1]) > calk(i, sta[top])) {
      top--;
    }
    sta[++top] = i;
  }
  for (int i = 1; i <= top; ++i) {
    if (jd[p[sta[i]].id]) continue;
    jd[p[sta[i]].id] = 1;
    for (int j = sta[i] + 1;
         j <= n && p[j].a == p[sta[i]].a && p[j].b == p[sta[i]].b; ++j)
      jd[p[j].id] = 1;
  }
  for (int i = 1; i <= n; ++i)
    if (jd[i]) printf("%d ", i);
}
