Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1
x=int(input())
import math
import fractions

#最小公倍数
def union_lcm(lists):
    if len(lists)==1:
        return lists[0]
    elif len(lists)>1:
        num=lists[0]
        for i in range(1,len(lists)):
            num=num*lists[i]//fractions.gcd(num,lists[i])
        return num
    
mini=10**12
minipare=(1,10**12)
sqrt=int(math.sqrt(x))+1
for i in range(1,sqrt+1):
    if x%i==0:
        a=i
        b=x//i
        if union_lcm([a,b])==x and max(a,b)<mini:
            minipare=(a,b)
        
        
    else:
        pass
print(*minipare)
    