There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.Scanner;
public class Main{

	public static void main (String [] args) {

		Main main = new Main ();
		main.solve();
	}

	private void solve() {

		Scanner scanner = new Scanner(System.in);
		int N = scanner.nextInt();
		String s = scanner.next();

		String [] list = new String [N];
		list=s.split("");

		int countR = 0;
		int countB = 0;

		for (int index=0; index<N; index++) {
		if (list[index].equals("R")) {
			countR++;
		} else {
			countB++;
		}
		}
		if (countR>countB) {
			System.out.println("Yes");
		} else {
			System.out.println("No");
		}
	}
}