There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
#include <bits/stdc++.h>
using namespace std;
int main()
{
int n;string s;
cin>>n>>s;
int red=0;int blue=0;
for(int i=0;i<n;i++)
{ if(s[i]=='R')red++;else blue++;
}
if(red>blue)
cout<<"Yes\n";
else
cout<<"No\n";
}