There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.io.BufferedReader;
import java.io.InputStreamReader;
 
public class Main {
    public static void main(String args[]) throws Exception{
        BufferedReader stdR = new BufferedReader(new InputStreamReader(System.in));
        int N = Integer.parseInt(stdR.readLine());
        String str = stdR.readLine();
        int R = 0;
        int B = 0;
        for(int i = 0 ; i < str.length(); i++) {
            if(str.charAt(i) == 'R') {
                R++;
            }else {
                B++;
            }
        }
        if(R > B) {
            System.out.println("Yes");
        }else {
            System.out.println("No");
        }
    }
}