There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.Scanner;
public class Main {

	public static void main(String[] args) {
	Scanner sc = new Scanner(System.in);
    int n = sc.nextInt();
 
    String s = sc.next();
 String[]ss = s.split("");
 sc.close();
 int r = 0; int b =0;
 for(int i=0; i<n; i++) {
	 if(ss[i].equals("R")) {r++;}
	 else if(ss[i].equals("B")) {b++;}
 }


  if(r>b) {System.out.println("Yes");}
  else {System.out.println("No");}
 
    		}
}
