There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.



Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:


n (the number of data in the list)
i p q
i p q
:
:
i p q


Output

For each dataset, print a list of employee IDs or a text "NA"

Example

Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0


Output

1001
1003
NA
2013
public class Main{
  static int N = 4000;
  static int M = 1000000;
  public void run(java.io.InputStream in, java.io.PrintStream out){
    java.util.Scanner sc = new java.util.Scanner(in);
    int[] a, b, c;
    int i, n, x, count;
    int y, z;

    a = new int[N]; b = new int[N]; c = new int[N];
    for(;;){
      n = sc.nextInt();
      if(n == 0)break;
      for(i = 0;i < N;i++){
        a[i] = 0; b[i] = 0; c[i] = 0;
      }
      count = 0;
      for(i = 0;i < n;i++){
        x = sc.nextInt(); y = sc.nextInt(); z = sc.nextInt();
        if(z != 0 && ((M - a[x - 1]) / z < y ||
         ((M - a[x - 1]) / z == y && ((M - a[x - 1]) % z) == 0)))b[x - 1]++;
        else a[x - 1] += y * z;
        if((b[x - 1] > 0 || a[x - 1] >= M) && c[x - 1] == 0){
          out.println(x); count++; c[x - 1] = 1;
        }
      }

      if(count == 0)out.println("NA");
    }

    sc.close();
  }
  public static void main(String[] args){
    (new Main()).run(System.in, System.out);
  }
}