There are N slimes standing on a number line. The i-th slime from the left is at position x_i.

It is guaruanteed that 1 \leq x_1 < x_2 < \ldots < x_N \leq 10^{9}.

Niwango will perform N-1 operations. The i-th operation consists of the following procedures:

* Choose an integer k between 1 and N-i (inclusive) with equal probability.
* Move the k-th slime from the left, to the position of the neighboring slime to the right.
* Fuse the two slimes at the same position into one slime.



Find the total distance traveled by the slimes multiplied by (N-1)! (we can show that this value is an integer), modulo (10^{9}+7). If a slime is born by a fuse and that slime moves, we count it as just one slime.

Constraints

* 2 \leq N \leq 10^{5}
* 1 \leq x_1 < x_2 < \ldots < x_N \leq 10^{9}
* x_i is an integer.

Input

Input is given from Standard Input in the following format:


N
x_1 x_2 \ldots x_N


Output

Print the answer.

Examples

Input

3
1 2 3


Output

5


Input

12
161735902 211047202 430302156 450968417 628894325 707723857 731963982 822804784 880895728 923078537 971407775 982631932


Output

750927044
import sys
sys.setrecursionlimit(10**9)
INF=10**18
MOD=10**9+7
def input():
    return sys.stdin.readline().rstrip()

def main():
    def modinv(a, mod):
        b,u,v = mod,1,0
        while b:
            t=a//b
            a-=t*b
            a,b=b,a
            u-=t*v
            u,v=v,u
        u%=mod
        if u < 0:
            u+=mod
        return u
    
    N=int(input())
    x=list(map(int,input().split()))
    z=[0]*N
    z[0]=1
    for i in range(N-1):
        z[0]*=i+1
        z[0]%=MOD
    ans=0
    for i in range(N-1):
        ans+=(x[i+1]-x[i])*z[i]
        ans%=MOD
        z[i+1]=z[i]+z[0]*modinv(i+2,MOD)
        z[i+1]%=MOD
    print(ans)

if __name__ == '__main__':
    main()
