There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.Scanner;

public class Main {
  public static void main(String[] args){

    Scanner sc = new Scanner(System.in);

    int N = Integer.parseInt(sc.nextLine());
    int R = 0;
    int B = 0;
    String s = sc.nextLine();
    
    for (int i = 0; i < N;i++){
        if("R".equals(s.substring(i,i+1))){
            R++;
        } else {
            B++;
        }
    }

    if(R>B){
        System.out.println("Yes");
    } else {
        System.out.println("No");
    }
  }

}
