"Pizza At", a fast food chain, offers three kinds of pizza: "A-pizza", "B-pizza" and "AB-pizza". A-pizza and B-pizza are completely different pizzas, and AB-pizza is one half of A-pizza and one half of B-pizza combined together. The prices of one A-pizza, B-pizza and AB-pizza are A yen, B yen and C yen (yen is the currency of Japan), respectively.

Nakahashi needs to prepare X A-pizzas and Y B-pizzas for a party tonight. He can only obtain these pizzas by directly buying A-pizzas and B-pizzas, or buying two AB-pizzas and then rearrange them into one A-pizza and one B-pizza. At least how much money does he need for this? It is fine to have more pizzas than necessary by rearranging pizzas.

Constraints

* 1 ≤ A, B, C ≤ 5000
* 1 ≤ X, Y ≤ 10^5
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


A B C X Y


Output

Print the minimum amount of money required to prepare X A-pizzas and Y B-pizzas.

Examples

Input

1500 2000 1600 3 2


Output

7900


Input

1500 2000 1900 3 2


Output

8500


Input

1500 2000 500 90000 100000


Output

100000000
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class Main {

	public static void main(String args[]) throws IOException {
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

		String str[] = br.readLine().split(" ");

		int a = Integer.parseInt(str[0]);
		int b = Integer.parseInt(str[1]);
		int c = Integer.parseInt(str[2]);
		int x = Integer.parseInt(str[3]);
		int y = Integer.parseInt(str[4]);

		int max = Math.max(x, y);

		long ans = Long.MAX_VALUE;
		for (int i = 0; i <= max * 2; i += 2) {
			int X = (x - i / 2) < 0 ? 0 : (x - i / 2);
			int Y = (y - i / 2) < 0 ? 0 : (y - i / 2);

			ans = Math.min(ans, i * c + X * a + Y * b);
		}

		System.out.println(ans);
	}
}