The HR manager was disappointed again. The last applicant failed the interview the same way as 24 previous ones. "Do I give such a hard task?" — the HR manager thought. "Just raise number 5 to the power of n and get last two digits of the number. Yes, of course, n can be rather big, and one cannot find the power using a calculator, but we need people who are able to think, not just follow the instructions."

Could you pass the interview in the machine vision company in IT City?

Input

The only line of the input contains a single integer n (2 ≤ n ≤ 2·1018) — the power in which you need to raise number 5.

Output

Output the last two digits of 5n without spaces between them.

Examples

Input

2


Output

25
import java.util.*;

public class AgainTwentyFive{
  public static void main(String[] args){
    Scanner gd = new Scanner(System.in);
    int g = 0;
    IO.pl("25");
  }
}

// Template
class IO{
  static Scanner gd = new Scanner(System.in);
  public static long rl(){
    return gd.nextLong();
  }
  public static int ri(){
    return gd.nextInt();
  }
  public static String rs(){
    return gd.next();
  }
  public static int[] rai(int len){
    int[] temp = new int[len];
    for(int i=0;i<len;i++){
      temp[i] = gd.nextInt();
    }
    return temp;
  }
  public static long[] ral(int len){
    long[] temp = new long[len];
    for(int i=0;i<len;i++){
      temp[i] = gd.nextLong();
    }
    return temp;
  }
  public static void pf(String format,Object... args){
    System.out.printf(format,args);
  }
  public static void pl(Object data){
    System.out.println(data);
  }
  public static void pai(int arr[]){
    for(int i=0;i<arr.length;i++){
      System.out.printf("%d ",arr[i]);
    }
    System.out.println();
  }
  public static void pal(long arr[]){
    for(int i=0;i<arr.length;i++){
      System.out.printf("%d ",arr[i]);
    }
    System.out.println();
  }
  public static void pas(String arr[]){
    for(int i=0;i<arr.length;i++){
      System.out.printf("%s ",arr[i]);
    }
    System.out.println();
  }
}

