Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1

# -*- coding: utf-8 -*-
# @Date    : 2020-01-11 07:14:43
# @Author  : raj lath (oorja.halt@gmail.com)
# @Link    : link
# @Version : 1.0.0

import sys
sys.setrecursionlimit(10**5+1)

inf     =  int(10 ** 20)
max_val =  inf
min_val = -inf

RW  = lambda : sys.stdin.readline().strip()
RI  = lambda : int(RW())
RMI = lambda : [int(x) for x in sys.stdin.readline().strip().split()]
RWI = lambda : [x for x in sys.stdin.readline().strip().split()]

from math import gcd, floor


n = RI()
limit = floor(n ** 0.5)
for i in range(limit, 0, -1):
    a, b = i, n // i
    if a * b / gcd(a, b) == n:
        print(a, b)
        break

