There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.Scanner;

class Main{
	public static void main(String[] args){
		Scanner stdin = new Scanner(System.in);

		int redHat = 0;

		int N = stdin.nextInt();
		stdin.nextLine();
		String s = stdin.nextLine();

		for(int i = 0; i < s.length(); i++){
			if(s.charAt(i) == 'R')
				redHat++;
		}

		if(redHat > N-redHat){
			System.out.println("Yes");
		}else{
			System.out.println("No");
		}
	}
}
