There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.*;
public class Main {
    public static void main(String[] args) throws Exception {
        try (Scanner sc = new Scanner(System.in)) {
            while (sc.hasNextInt()) {
                int a = Integer.parseInt(sc.next());
                String s = sc.next();
                String ans = "No";
                int count = 0;
                char c = 'R';
                for(char x:s.toCharArray()){
                  if(x == c){
                    count++;
                  }
                }
                if(count>a-count) ans = "Yes";
                System.out.println(ans);
            }
        }
    }
}