There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		// TODO 自動生成されたメソッド・スタブ

		Scanner sc1 = new Scanner(System.in);
		int N = sc1.nextInt();
		String s = sc1.next();
		int r = 0;
		int b = 0;

		for ( int i = 0 ; i < N ; i++ ) {
			if (s.charAt(i) == 'R') {
				r++;
			}
			else {
				b++;
			}
		}

		if ( r > b ) {
			System.out.println("Yes");
		} else {
			System.out.println("No");
		}

		sc1.close();

	}

}
