There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.*;

public class Main{
	public static void main(String[] args){
    	Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        String s = sc.next();
        String si[] = new String[n];
        int red = 0;
        int blue = 0;
        for(int i = 0; i < n; i++){
        	si[i] = s.substring(i, i + 1);
            if(si[i].equals("R")){
            	red++;
            }else if(si[i].equals("B")){
            	blue++;
            }
        }
        if(red > blue){
        	System.out.println("Yes");
        }else{
        	System.out.println("No");
        }
    }
}