Polycarp has an array a consisting of n integers.

He wants to play a game with this array. The game consists of several moves. On the first move he chooses any element and deletes it (after the first move the array contains n-1 elements). For each of the next moves he chooses any element with the only restriction: its parity should differ from the parity of the element deleted on the previous move. In other words, he alternates parities (even-odd-even-odd-... or odd-even-odd-even-...) of the removed elements. Polycarp stops if he can't make a move.

Formally: 

  * If it is the first move, he chooses any element and deletes it; 
  * If it is the second or any next move: 
    * if the last deleted element was odd, Polycarp chooses any even element and deletes it; 
    * if the last deleted element was even, Polycarp chooses any odd element and deletes it. 
  * If after some move Polycarp cannot make a move, the game ends. 



Polycarp's goal is to minimize the sum of non-deleted elements of the array after end of the game. If Polycarp can delete the whole array, then the sum of non-deleted elements is zero.

Help Polycarp find this value.

Input

The first line of the input contains one integer n (1 ≤ n ≤ 2000) — the number of elements of a.

The second line of the input contains n integers a_1, a_2, ..., a_n (0 ≤ a_i ≤ 10^6), where a_i is the i-th element of a.

Output

Print one integer — the minimum possible sum of non-deleted elements of the array after end of the game.

Examples

Input


5
1 5 7 8 2


Output


0


Input


6
5 1 2 4 6 3


Output


0


Input


2
1000000 1000000


Output


1000000

def input_s():
    return raw_input()

def input_i():
    return int(raw_input())

def input_2_i():
    arr = map(int, raw_input().split())
    return arr[0], arr[1]

def input_3_i():
    arr = map(int, raw_input().split())
    return arr[0], arr[1], arr[2]

def input_i_array():
    return map(int, raw_input().split())

def get_presum(n, arr):
    presum = [arr[0]]
    for i in range(1, n):
        presum.append(presum[i - 1] + arr[i])
    return presum

def calc(n, arr):
    odd_nums = [x for x in arr if x % 2 == 1]
    even_nums = [x for x in arr if x % 2 == 0]
    lo = len(odd_nums)
    le = len(even_nums)
    if abs(lo - le) == 1 or abs(lo - le) == 0:
        return 0

    if lo == 0:
        return sum(sorted(even_nums)[:-1])
    if le == 0:
        return sum(sorted(odd_nums)[:-1])
    
    if lo < le:
        return sum(sorted(even_nums)[: le - lo - 1])
    return sum(sorted(odd_nums)[: lo - le - 1])

"""
5
1 5 7 8 2
"""

n = input_i()
arr = input_i_array()
print calc(n, arr)
