There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.math.BigInteger;
import java.util.Scanner;

public class Main {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);

        int N = sc.nextInt();
        String s = sc.next();

        sc.close();

        char[] charArray = s.toCharArray();


        int R = 0;
        int B = 0;
        for(int i=0; i<N; i++){
            char tmp = charArray[i];
            if(tmp == 'R'){
                R++;
            }else{
                B++;
            }
        }

        String result = R>B ? "Yes" : "No";

        System.out.println(result);

    }
}
