There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
#include <iostream>
using namespace std;

int main() {
	int n,cR=0,cB=0;
	cin>>n;
	while(n--)
	{
	    char s;
	    cin>>s;
	    if(s=='R')
	    cR++;
	    else
	    cB++;
	}
	if(cR>cB)
	cout<<"Yes";
	else
	cout<<"No";
	return 0;
}