There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
//金桥 傅思程
#include <bits/stdc++.h>
using namespace std;

int main()
{
	int a,ans=0;
	char c;
	cin>>a;
	for(int i=0;i<a;i++){
		cin>>c;
		if(c=='R')ans++;
		else ans--;
	}
	if(ans>0)cout<<"Yes";
	else cout<<"No";
	return 0;
}