Two little greedy bears have found two pieces of cheese in the forest of weight a and b grams, correspondingly. The bears are so greedy that they are ready to fight for the larger piece. That's where the fox comes in and starts the dialog: "Little bears, wait a little, I want to make your pieces equal" "Come off it fox, how are you going to do that?", the curious bears asked. "It's easy", said the fox. "If the mass of a certain piece is divisible by two, then I can eat exactly a half of the piece. If the mass of a certain piece is divisible by three, then I can eat exactly two-thirds, and if the mass is divisible by five, then I can eat four-fifths. I'll eat a little here and there and make the pieces equal". 

The little bears realize that the fox's proposal contains a catch. But at the same time they realize that they can not make the two pieces equal themselves. So they agreed to her proposal, but on one condition: the fox should make the pieces equal as quickly as possible. Find the minimum number of operations the fox needs to make pieces equal.

Input

The first line contains two space-separated integers a and b (1 ≤ a, b ≤ 109). 

Output

If the fox is lying to the little bears and it is impossible to make the pieces equal, print -1. Otherwise, print the required minimum number of operations. If the pieces of the cheese are initially equal, the required number is 0.

Examples

Input

15 20


Output

3


Input

14 8


Output

-1


Input

6 6


Output

0
import java.util.*;
import java.io.*;
import java.math.BigInteger;
public class Main {
	public static long mod= (long) (1e9 +7);
	public static void main(String args[])
	{
		InputReader s= new InputReader(System.in);
		//Scanner s= new Scanner(System.in);
		OutputStream outputStream= System.out;
		PrintWriter out= new PrintWriter(outputStream);
		int numa= s.nextInt();
		int numb= s.nextInt();
		if(numa==numb){
			out.println("0");
		}
		else{
			int a= numa;
			int b= numb;
			ArrayList<Integer> arr= primeFactors(a);
			ArrayList<Integer> brr= primeFactors(b);
			//out.println(arr+" "+brr);
		int counta2=0,counta3=0,counta5=0,countb2=0,countb3=0,countb5=0;
		for(int i=0;i<arr.size();i++){
			if(arr.get(i)==2) counta2++;
			if(arr.get(i)==3) counta3++;
			if(arr.get(i)==5) counta5++;
		}
		for(int i=0;i<brr.size();i++){
			if(brr.get(i)==2) countb2++;
			if(brr.get(i)==3) countb3++;
			if(brr.get(i)==5) countb5++;
		}
		int x= numa/(expo(2,counta2)*expo(3,counta3)*expo(5,counta5));
		int y= numb/(expo(2,countb2)*expo(3,countb3)*expo(5,countb5));
		if(x!=y){
			out.println("-1");
		}
		else{
			out.println(Math.abs(counta2-countb2) + Math.abs(counta3-countb3) + Math.abs(counta5-countb5));
		}
		}
		out.close();
	}
	
	static ArrayList<Integer> primeFactors(int n)
	{
	    // Print the number of 2s that divide n
		ArrayList<Integer> arr= new ArrayList<>();
	    while (n%2 == 0)
	    {
	        arr.add(2);
	        n = n/2;
	    }
	 
	    // n must be odd at this point.  So we can skip one element (Note i = i +2)
	    for (int i = 3; i <= Math.sqrt(n); i = i+2)
	    {
	        // While i divides n, print i and divide n
	        while (n%i == 0)
	        {
	            arr.add(i);
	            n = n/i;
	        }
	    }
	 
	    // This condition is to handle the case when n is a prime number
	    // greater than 2
	    if (n > 2)
	        arr.add(n);
	    
	    return arr;
	}
	static class InputReader {

	    public BufferedReader reader;
	    public StringTokenizer tokenizer;
 
	    public InputReader(InputStream inputstream) {
	      reader = new BufferedReader(new InputStreamReader(inputstream));
	      tokenizer = null;
	    }
	    
	    public String nextLine(){
	    	String fullLine=null;
	    	while (tokenizer == null || !tokenizer.hasMoreTokens()) {
	            try {
	              fullLine=reader.readLine();
	            } catch (IOException e) {
	              throw new RuntimeException(e);
	            }
	            return fullLine;
	          }
	          return fullLine;
	    }
		public String next() {
	      while (tokenizer == null || !tokenizer.hasMoreTokens()) {
	        try {
	          tokenizer = new StringTokenizer(reader.readLine());
	        } catch (IOException e) {
	          throw new RuntimeException(e);
	        }
	      }
	      return tokenizer.nextToken();
	    }
		public long nextLong() {
		      return Long.parseLong(next());
		    }
	    public int nextInt() {
	      return Integer.parseInt(next());
	    }
	  }
	public static int expo(int a, int b){
		if (b==0)
	        return 1;
	    if (b==1)
	        return a;
	    if (b==2)
	        return a*a;

	    if (b%2==0){
	            return expo(expo(a,b/2),2);
	    }
	    else{
	        return a*expo(expo(a,(b-1)/2),2);
	    }
	}
	static class Pair implements Comparable<Pair>
	{
		long f,s;
		Pair(long ii, long cc)
		{
			f=ii;
			s=cc;
		}
		
		public int compareTo(Pair o) 
		{
			return Long.compare(this.f, o.f);
		}
		
	}
	public static int gcd(int number1, int number2) {  
		if(number2 == 0){
			return number1;
		} 
		return gcd(number2, number1%number2); 
	}
	public static int combinations(int n,int r){
		if(n==r) return 1;
		if(r==1) return n;
		if(r==0) return 1;
		return combinations(n-1,r)+ combinations(n-1,r-1);
	}
	public static long binomialCoeff(int n, int k)
	{
	    long C[][]= new long[n+1][k+1];
	    int i, j;
	 
	    // Caculate value of Binomial Coefficient in bottom up manner
	    for (i = 0; i <= n; i++)
	    {
	        for (j = 0; j <= Math.min(i, k); j++)
	        {
	            // Base Cases
	            if (j == 0 || j == i)
	                C[i][j] = 1;
	 
	            // Calculate value using previosly stored values
	            else
	                C[i][j] = C[i-1][j-1] + C[i-1][j];
	        }
	    }
	 
	    return C[n][k];
	}
	
	public static int[] sieve(int N){
		int arr[]= new int[N+1];
		for(int i=2;i<Math.sqrt(N);i++){
			if(arr[i]==0){
				for(int j= i*i;j<= N;j= j+i){
					arr[j]=1;
				}
			}
		}
		return arr;
		// All the i for which arr[i]==0 are prime numbers.
	}
}