There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.Scanner;

public class Main {
    public static void main(String... args) {
        // 入力
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        char[] cArr = sc.next().toCharArray();
        int r = 0;
        int b = 0;

        for (char c : cArr) {
            if (c == 'R') r++;
            if (c == 'B') b++;
        }

        if (r > b) System.out.println("Yes");
        else System.out.println("No");
    }
}