There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.*;

public class Main {
  public static void main(String[] args) {
    Scanner sc = new Scanner(System.in);
    Main m = new Main(sc);
    m.show(m.solve());
    // m.debug();
  }

  Scanner sc;
  int N = 0;
  String s = null;
  boolean answer = true;

  // 標準入力用のコンストラクタ
  public Main(Scanner sc) {
    this.sc = sc;
    N = sc.nextInt();
    s = sc.next();
  }

  // 判定処理
  boolean solve() {
      int countR = 0;
      int countB = 0;
      for (int i = 0; i < N; ++i){
        if (s.charAt(i) == 'R'){
            ++countR ;
        } else {
            ++countB;
        }
      }
      if (countR <= countB){ //赤と青が同じか、青のほうが多かったら
        answer = false; 
      }
      
      return answer;
  }

  // 回答の表示
  void show(boolean answer) {
      if (answer){
        System.out.println("Yes");
      } else {
        System.out.println("No");
      }
      
  }
    
}
