There are N slimes standing on a number line. The i-th slime from the left is at position x_i.

It is guaruanteed that 1 \leq x_1 < x_2 < \ldots < x_N \leq 10^{9}.

Niwango will perform N-1 operations. The i-th operation consists of the following procedures:

* Choose an integer k between 1 and N-i (inclusive) with equal probability.
* Move the k-th slime from the left, to the position of the neighboring slime to the right.
* Fuse the two slimes at the same position into one slime.



Find the total distance traveled by the slimes multiplied by (N-1)! (we can show that this value is an integer), modulo (10^{9}+7). If a slime is born by a fuse and that slime moves, we count it as just one slime.

Constraints

* 2 \leq N \leq 10^{5}
* 1 \leq x_1 < x_2 < \ldots < x_N \leq 10^{9}
* x_i is an integer.

Input

Input is given from Standard Input in the following format:


N
x_1 x_2 \ldots x_N


Output

Print the answer.

Examples

Input

3
1 2 3


Output

5


Input

12
161735902 211047202 430302156 450968417 628894325 707723857 731963982 822804784 880895728 923078537 971407775 982631932


Output

750927044
# https://atcoder.jp/contests/dwacon6th-prelims/submissions/9426910


def solve():
    MOD = 10**9 + 7

    N = int(input())
    xs = list(map(int, input().split()))

    ds = []
    for i in range(N-1):
        d = xs[i+1] - xs[i]
        ds.append(d)

    nums = [1, 1]
    num = 1
    for i in range(2, N-1):
        num *= i
        num %= MOD
        nums.append(num)

    ms = [N-1]
    m = N-1
    for i in reversed(range(2, N-1)):
        m *= i
        m %= MOD
        ms.append(m)
    ms.reverse()
    ms.append(1)

    ks = []
    k = 0
    for num, m in zip(nums, ms):
        k += num*m % MOD
        k %= MOD
        ks.append(k)

    ans = 0
    for d, k in zip(ds, ks):
        ans += d*k % MOD
        ans %= MOD

    print(ans)

solve()
