There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.Scanner;
class Main{
 public static void main(String args[] ){
   
   Scanner in = new Scanner (System.in);
   int letter = in.nextInt();
   String a = in.next();
   int red =0,blue=0;
   for(int i =0;i<a.length();i++)
   {
   		if(a.charAt(i)=='R')red++;
     else if(a.charAt(i)=='B') blue++;
   }
   if(red>blue) System.out.println("Yes");
   else System.out.println("No");
}
}