There are N slimes standing on a number line. The i-th slime from the left is at position x_i.

It is guaruanteed that 1 \leq x_1 < x_2 < \ldots < x_N \leq 10^{9}.

Niwango will perform N-1 operations. The i-th operation consists of the following procedures:

* Choose an integer k between 1 and N-i (inclusive) with equal probability.
* Move the k-th slime from the left, to the position of the neighboring slime to the right.
* Fuse the two slimes at the same position into one slime.



Find the total distance traveled by the slimes multiplied by (N-1)! (we can show that this value is an integer), modulo (10^{9}+7). If a slime is born by a fuse and that slime moves, we count it as just one slime.

Constraints

* 2 \leq N \leq 10^{5}
* 1 \leq x_1 < x_2 < \ldots < x_N \leq 10^{9}
* x_i is an integer.

Input

Input is given from Standard Input in the following format:


N
x_1 x_2 \ldots x_N


Output

Print the answer.

Examples

Input

3
1 2 3


Output

5


Input

12
161735902 211047202 430302156 450968417 628894325 707723857 731963982 822804784 880895728 923078537 971407775 982631932


Output

750927044
def ext_euc(a, b):
    if b == 0:
        return 1, 0, a
    y, x, v = ext_euc(b, a % b)
    y -= (a // b) * x
    return x, y, v


def mod_inv(a, mod):
    x, _, _ = ext_euc(a, mod)
    return x % mod


def mod_fac(a, mod):
    ret = 1
    for aa in range(1, a + 1):
        ret *= aa
        ret %= mod
    return ret


def main():
    MOD = 10**9 + 7
    N = int(input())
    X = list(map(int, input().split()))
    ans = 0
    for n in range(N - 1):
        ans += (X[N - 1] - X[n]) * mod_inv(n + 1, MOD)
    ans *= mod_fac(N - 1, MOD)
    print(ans % MOD)


if __name__ == '__main__':
    main()
