problem

AOR Ika is studying to pass the test.

AOR Ika-chan solved the $ N $ question. After that, round the solved problem according to the following procedure.

1. Check the correctness of the answer.
2. If the answer is correct, write a circle mark, and if it is incorrect, write a cross mark on the answer sheet.



AOR Ika faints because of the fear of failing the test the moment she finds that the answer is wrong for $ 2 $ in a row. And no further rounding is possible.

Syncope occurs between steps $ 1 $ and $ 2 $.

You will be given an integer $ N $, which represents the number of questions AOR Ika has solved, and a string $ S $, which is a length $ N $ and represents the correctness of the answer. The string consists of'o'and'x', with'o' indicating the correct answer and'x' indicating the incorrect answer. The $ i $ letter indicates the correctness of the $ i $ question, and AOR Ika-chan rounds the $ 1 $ question in order.

Please output the number of questions that AOR Ika-chan can write the correctness.



output

Output the number of questions that AOR Ika-chan could write in the $ 1 $ line. Also, output a line break at the end.

Example

Input

3
oxx


Output

2
#include<bits/stdc++.h>
#define rep(i,a,b) for(int i=a;i<b;i++)
#define rrep(i,a,b) for(int i=a;i>=b;i--)
#define fore(i,a) for(auto &i:a)
#pragma GCC optimize ("-O3")
using namespace std; void _main(); int main() { cin.tie(0); ios::sync_with_stdio(false); _main(); }
//---------------------------------------------------------------------------------------------------
/*---------------------------------------------------------------------------------------------------
????????????????????????????????? ??§?????§  
??????????????? ??§?????§ ???????´<_??? ?????? Welcome to My Coding Space!
???????????? ??? ?´_???`??????/??? ???i     
?????????????????????????????? ???  |???|     
????????? /?????? /??£??£??£??£/??????|  
??? ???_(__??????/???    ???/ .| .|????????????  
??? ????????????/????????????/??????u??????  
---------------------------------------------------------------------------------------------------*/






int N; string S;
//--------------------------------------------------------------------------------------------------
void _main() {
    cin >> N >> S;

    int ans = N;
    rep(i, 0, N - 1) {
        if (S[i] == 'x' && S[i + 1] == 'x') {
            ans = i + 1;
            break;
        }
    }
    cout << ans << endl;
}