Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1
import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.StringTokenizer;
import java.io.IOException;
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.InputStream;
import java.util.*;
 
public class A3 {
    public static void main(String[] args) {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        InputReader in = new InputReader(inputStream);
        PrintWriter out = new PrintWriter(outputStream);
        solve(in, out);
        out.close();
    }

    static void printArr(int a[], int n) 
    { 
        // for (int i=0; i<n; i++) 
        //     System.out.print(a[i] + " "); 
        long h=0;
        int i,j;
        for(i=0;i<n;i++){
                int min=a[i],max=a[i];
                for(j=i;j<n;j++){
                    max=Math.max(max,a[j]);
                    min=Math.min(min,a[j]);
                    if(max-min==j-i){
                        h++;
                    }
                    // else
                    //     System.out.println(i+" "+j);
                }
            }
        u+=h;    
        // System.out.println(h);
        // System.out.println(); 
    } 

    static void heapPermutation(int a[], int size, int n) 
    { 
        // if size becomes 1 then prints the obtained 
        // permutation 
        if (size == 1) 
            printArr(a,n); 
  
        for (int i=0; i<size; i++) 
        { 
            heapPermutation(a, size-1, n); 
  
            // if size is odd, swap first and last 
            // element 
            if (size % 2 == 1) 
            { 
                int temp = a[0]; 
                a[0] = a[size-1]; 
                a[size-1] = temp; 
            } 
  
            // If size is even, swap ith and last 
            // element 
            else
            { 
                int temp = a[i]; 
                a[i] = a[size-1]; 
                a[size-1] = temp; 
            } 
        } 
    } 
    static long u=0;

    public static void solve(InputReader sc, PrintWriter pw) {
        int i,j=0;
        int t=1;
        // int t=sc.nextInt();
        u:while(t-->0){
            long n = sc.nextLong();
            long max=n;
            for(i=1;i<=(int)Math.round(Math.sqrt(n));i++){
                if(n%i==0&&gcd(i,n/i)==1){
                    max=Math.min(max,n/i);
                }
            }
            pw.println((n/max)+" "+max);
        }
    }

    static class Pair implements Comparable<Pair>{
        int a;int b;
        Pair(int a,int b){
            this.a=a;
            this.b=b;
            //this.z=z;
        }   
        public int compareTo(Pair p){
            return (a-p.a);
        }
    }

    static boolean isPrime(int n) { 
        if (n <= 1) 
            return false; 
        if (n <= 3) 
            return true; 
        if (n % 2 == 0 || n % 3 == 0) 
            return false; 
        for (int i = 5; i * i <= n; i = i + 6) 
            if (n % i == 0 || n % (i + 2) == 0) 
                return false; 
        return true; 
    } 
    static long gcd(long a, long b) { 
        if (b == 0) 
            return a; 
        return gcd(b, a % b);  
    } 
    static long fast_pow(long base,long n,long M){
        if(n==0)
           return 1;
        if(n==1)
        return base;
        long halfn=fast_pow(base,n/2,M);
        if(n%2==0)
            return ( halfn * halfn ) % M;
        else
            return ( ( ( halfn * halfn ) % M ) * base ) % M;
    }
    static long modInverse(long n,long M){
        return fast_pow(n,M-2,M);
    }
 
    static class InputReader {
        public BufferedReader reader;
        public StringTokenizer tokenizer;
 
        public InputReader(InputStream stream) {
            reader = new BufferedReader(new InputStreamReader(stream), 32768);
            tokenizer = null;
        }
 
        public String next() {
            while (tokenizer == null || !tokenizer.hasMoreTokens()) {
                try {
                    tokenizer = new StringTokenizer(reader.readLine());
                } catch (IOException e) {
                    throw new RuntimeException(e);
                }
            }
            return tokenizer.nextToken();
        }
        public int nextInt() {
            return Integer.parseInt(next());
        }
        public long nextLong() {
            return Long.parseLong(next());
        }
    }
}