You are given a string S consisting of letters `b`, `d`, `p` and `q`. Determine whether S is a mirror string.

Here, a mirror string is a string S such that the following sequence of operations on S results in the same string S:

1. Reverse the order of the characters in S.

2. Replace each occurrence of `b` by `d`, `d` by `b`, `p` by `q`, and `q` by `p`, simultaneously.

Constraints

* 1 \leq |S| \leq 10^5
* S consists of letters `b`, `d`, `p`, and `q`.

Input

The input is given from Standard Input in the following format:


S


Output

If S is a mirror string, print `Yes`. Otherwise, print `No`.

Examples

Input

pdbq


Output

Yes


Input

ppqb


Output

No
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools

sys.setrecursionlimit(10**7)
inf = 10**3
eps = 1.0 / 10**10
mod = 10**9+7

def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def pf(s): return print(s, flush=True)


def main():
    s = S()
    l = len(s)
    h = {'b': 'd', 'd': 'b', 'p': 'q', 'q': 'p'}
    if l % 2 == 1:
        return 'No'
    for i in range(l//2):
        if s[i] != h[s[l-i-1]]:
            return 'No'

    return 'Yes'




print(main())

