Tavas is a cheerleader in the new sports competition named "Pashmaks".

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This competition consists of two part: swimming and then running. People will immediately start running R meters after they finished swimming exactly S meters. A winner is a such person that nobody else finishes running before him/her (there may be more than one winner).

Before the match starts, Tavas knows that there are n competitors registered for the match. Also, he knows that i-th person's swimming speed is si meters per second and his/her running speed is ri meters per second. Unfortunately, he doesn't know the values of R and S, but he knows that they are real numbers greater than 0.

As a cheerleader, Tavas wants to know who to cheer up. So, he wants to know all people that might win. We consider a competitor might win if and only if there are some values of R and S such that with these values, (s)he will be a winner.

Tavas isn't really familiar with programming, so he asked you to help him.

Input

The first line of input contains a single integer n (1 ≤ n ≤ 2 × 105).

The next n lines contain the details of competitors. i-th line contains two integers si and ri (1 ≤ si, ri ≤ 104).

Output

In the first and the only line of output, print a sequence of numbers of possible winners in increasing order.

Examples

Input

3
1 3
2 2
3 1


Output

1 2 3 


Input

3
1 2
1 1
2 1


Output

1 3 
#include <bits/stdc++.h>
using namespace std;
const double eps = 1e-8;
int n;
bool vis[220000];
int dcmp(double x) {
  if (fabs(x) < eps) return 0;
  return x < 0 ? -1 : 1;
}
struct Point {
  double x, y;
  int id;
  Point() {}
  Point(double _x, double _y, int _z) : x(_x), y(_y), id(_z) {}
  Point operator-(const Point& b) const { return Point(x - b.x, y - b.y, 0); }
  double operator*(const Point& b) const { return (x * b.y - y * b.x); }
  double operator^(const Point& b) const { return (x * b.x + y * b.y); }
  bool operator<(const Point& b) const {
    if (dcmp(x - b.x) == 0) return y < b.y;
    return x < b.x;
  }
} p[220000], stk[220000];
int Graham(int n) {
  sort(p, p + n);
  int top = 0;
  for (int i = 0; i < n; i++) {
    if (i && !dcmp(p[i].x - p[i - 1].x)) continue;
    while (top > 1 &&
           dcmp((stk[top - 1] - stk[top - 2]) * (p[i] - stk[top - 2])) < 0)
      top--;
    stk[top++] = p[i];
  }
  return top;
}
int main() {
  scanf("%d", &n);
  for (int i = 0; i < n; i++) {
    double x, y;
    scanf("%lf%lf", &x, &y);
    x = 10000 / x;
    y = 10000 / y;
    p[i] = {x, y, i};
  }
  int top = Graham(n);
  for (int i = 0; i < top; i++) {
    if (!i || dcmp(stk[i].y - stk[i - 1].y) < 0) vis[stk[i].id] = 1;
  }
  for (int i = 0; i < n; i++) {
    if (i && !dcmp(p[i].x - p[i - 1].x) && !dcmp(p[i].y - p[i - 1].y) &&
        vis[p[i - 1].id])
      vis[p[i].id] = 1;
  }
  for (int i = 0; i < n; i++) {
    if (vis[i]) printf("%d ", i + 1);
  }
  return 0;
}
