There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.Scanner;
import java.util.Arrays;
import java.util.Random;
public class Main 
{
    public static void main(String[] args) 
    {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        Scanner in = new Scanner(inputStream);
        PrintWriter out = new PrintWriter(outputStream);
        TaskC solver = new TaskC();
        solver.solve(2, in, out);
        out.close();
    }

    static class TaskC 
    {
        static boolean prime(int n)
        {
            for(int i=2;i<=Math.sqrt(n);i++)
            {
                if(n%i==0)
                {
                    return false;
                }
            }
            return true;
        }

        static void reverse(long[] a,long start,long end)
        {
            long temp = 0;
            while(start<end)
            {
                temp = a[(int)start];
                a[(int)start] = a[(int)end];
                a[(int)end] = temp;
                start++;
                end--;
            }
        }


   
        
        public void solve(int testNumber, Scanner in, PrintWriter out) 
        {
            long t = in.nextLong();
            char[] s = in.next().toCharArray();
            long r=0;
            long b =0;
            for(int i=0;i<s.length;i++)
            {
                if(s[i]=='R')
                {
                    r++;
                }
                else
                {
                    b++;
                }
            }

            if(r>b)
            {
                System.out.println("Yes");
            }
            else{
                System.out.println("No");
            }
        }


      
        
        
        static long maxdiff(long[] arr,long size)
        {
            long max = arr[1]-arr[0];
            long min = arr[0];
            for(int i=1;i<(int)size;i++)
            {
                if(arr[i]-min>max)
                {
                    max = arr[i]-min;
                }
                if(arr[i]<min)
                {
                    min = arr[i];
                }

            }
            return max;
        }

                
    }

}