There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.Arrays;
import java.util.List;
import java.util.Scanner;

public class Main{

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		int personNum = Integer.parseInt(sc.nextLine());
		List<String> elements = Arrays.asList(sc.nextLine().split(""));
		
		long red_count = elements.stream().filter( s -> s.equals("R") ).count();
		int harfNum = personNum%2 == 0 ? personNum/2 + 1 : (personNum+1)/2;
		String result = harfNum <= red_count ? "Yes" : "No";
		System.out.println(result);
		sc.close();
	}
}
