At a geometry lesson Gerald was given a task: to get vector B out of vector A. Besides, the teacher permitted him to perform the following operations with vector А:

  * Turn the vector by 90 degrees clockwise.
  * Add to the vector a certain vector C.



Operations could be performed in any order any number of times.

Can Gerald cope with the task?

Input

The first line contains integers x1 и y1 — the coordinates of the vector A ( - 108 ≤ x1, y1 ≤ 108). The second and the third line contain in the similar manner vectors B and C (their coordinates are integers; their absolute value does not exceed 108).

Output

Print "YES" (without the quotes) if it is possible to get vector B using the given operations. Otherwise print "NO" (without the quotes).

Examples

Input

0 0
1 1
0 1


Output

YES


Input

0 0
1 1
1 1


Output

YES


Input

0 0
1 1
2 2


Output

NO
#include <bits/stdc++.h>
using namespace std;
const int N = 1e5 + 10, INF = 0x3f3f3f3f, MOD = 1e9 + 7;
struct P {
  long long x, y;
  P() {}
  P(long long x, long long y) : x(x), y(y) {}
  P rotate() { return P(-y, x); }
  P operator-(const P& rhs) const { return P(x - rhs.x, y - rhs.y); }
  long long operator*(const P& rhs) const { return x * rhs.x + y * rhs.y; }
  bool operator==(const P& rhs) const { return x == rhs.x && y == rhs.y; }
};
bool judge(P& u, P& v) {
  if (v == P(0, 0)) return u == P(0, 0);
  long long w = v.x * v.x + v.y * v.y;
  return u * v % w == 0 && u * v.rotate() % w == 0;
}
P a, b, c;
int main() {
  ios_base::sync_with_stdio(0);
  while (cin >> a.x >> a.y >> b.x >> b.y >> c.x >> c.y) {
    bool ok = false;
    for (int i = 0; i < 4; ++i) {
      P d = b - a;
      if (judge(d, c)) {
        ok = true;
        break;
      }
      a = a.rotate();
    }
    cout << (ok ? "YES" : "NO") << '\n';
  }
  return 0;
}
