You are given the array a consisting of n elements and the integer k ≤ n.

You want to obtain at least k equal elements in the array a. In one move, you can make one of the following two operations:

  * Take one of the minimum elements of the array and increase its value by one (more formally, if the minimum value of a is mn then you choose such index i that a_i = mn and set a_i := a_i + 1); 
  * take one of the maximum elements of the array and decrease its value by one (more formally, if the maximum value of a is mx then you choose such index i that a_i = mx and set a_i := a_i - 1). 



Your task is to calculate the minimum number of moves required to obtain at least k equal elements in the array.

Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 2 ⋅ 10^5) — the number of elements in a and the required number of equal elements.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is the i-th element of a.

Output

Print one integer — the minimum number of moves required to obtain at least k equal elements in the array.

Examples

Input


6 5
1 2 2 4 2 3


Output


3


Input


7 5
3 3 2 1 1 1 3


Output


4
n,k = [int(j) for j in input().split()]
l = [int(j) for j in input().split()]
num = int(2*1e5+5)
arr = [[] for i in range(num)]

for i in range(n):
	cnt = 0
	tmp = l[i]
	while(tmp>0):
		arr[tmp].append(cnt)
		tmp=tmp//2
		cnt+=1
ans = 1e12
# print(len(arr))
for i in range(1,num):
	if len(arr[i])>=k:
		arr[i].sort()
		ans = min(ans, sum(arr[i][:k]))
print(ans)