There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.



Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:


n (the number of data in the list)
i p q
i p q
:
:
i p q


Output

For each dataset, print a list of employee IDs or a text "NA"

Example

Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0


Output

1001
1003
NA
2013
import java.util.*;

class Main{
        public static void main(String[] args){
                Scanner sc = new Scanner(System.in);
                int n = sc.nextInt();
                do{ 
                        long[][] data = new long[4000][2];
                        for(int i = 0 ; i < n ; i++){
                                imput(data, sc.nextInt(), sc.nextInt(), sc.nextInt());
                        }   
                        boolean NA = true;
                        for(int i = 0 ; i < 4000 ; i++){
                                if(data[i][1] >= 1000000){
                                        System.out.println(data[i][0]);
                                        NA = false;
                                }   
                        }   
                        if(NA) System.out.println("NA");
                        n = sc.nextInt();
                }while(n > 0); 
        }   
        static void imput(long[][] source, int num, int sales, int price){
                for(int i = 0 ; i < 4000 ; i++){
                        if(source[i][0] == num){
                                source[i][1] += (long)sales*price;
                                return;
                        }else if(source[i][0] == 0){ 
                                source[i][0] = num;
                                source[i][1] += (long)sales*price;
                                return;
                        }   
                }   
        }   
}