There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.*;

public class Main {
    public static void main(String[] args) throws Exception {
        Scanner sc = new Scanner(System.in);
           
            int N = sc.nextInt();
            String s = sc.next();
            int red = 0;
            
            for (int i=0; i<s.length() ; i++) {
              if(s.charAt(i) == 'R'){
                red++;
              }
            }
   
            if (N/2 < red) {
                System.out.println("Yes");
            } else {
                System.out.println("No");
            }
    }
}