Snuke has a string S consisting of three kinds of letters: `a`, `b` and `c`.

He has a phobia for palindromes, and wants to permute the characters in S so that S will not contain a palindrome of length 2 or more as a substring. Determine whether this is possible.

Constraints

* 1 \leq |S| \leq 10^5
* S consists of `a`, `b` and `c`.

Input

Input is given from Standard Input in the following format:


S


Output

If the objective is achievable, print `YES`; if it is unachievable, print `NO`.

Examples

Input

abac


Output

YES


Input

aba


Output

NO


Input

babacccabab


Output

YES
import java.io.*;
import java.util.*;
import java.util.Map.Entry;
import java.util.stream.Collectors;

@SuppressWarnings("unused")
public class Main {
	String fileName = "input.txt";
	final boolean isDebug = false;
	//final boolean isDebug = true;
	FastScanner in = new FastScanner(System.in);
	PrintWriter out = new PrintWriter(System.out);
	final int MOD = (int)1e9+7;
	final long INF = Long.MAX_VALUE / 2;
	//final int INF = Integer.MAX_VALUE / 2;
	
	void solve() throws Exception{
		//System.out.println();はつかわない！！
		char[] S = in.nextStr().toCharArray();
		int[] num = new int[3];
		for(char c : S) num[c-'a']++;
		Arrays.sort(num);
		
		boolean tf;
		if(num[1] == 0){
			//1種類
			if(num[2] == 1) tf = true;
			else tf = false;
		}else if(num[0] == 0){
			//2種類
			if(num[2] == 1) tf = true;
			else tf = false;
		}else{
			//3種類
			if(num[2] - 1 <= num[1] && num[2] + 1 >= num[1] && num[2] - 1 <= num[0] && num[2] + 1 >= num[0] && Math.abs(num[1] - num[0]) <= 1) tf = true;
			else tf = false;
		}
		
		out.println(tf ? "YES" : "NO");
	}
	
	/* end solve */
	
	/* main */
	public static void main(String[] args) throws Exception {
		new Main().m();
	}
	
	void m() throws Exception {
		if(isDebug) in = new FastScanner(new FileInputStream(fileName));
		solve();
		out.flush();
	}
	/* end main */
}
/* end Main */

class FastScanner {
	Reader input;

	FastScanner() {this(System.in);}
	FastScanner(InputStream stream) {this.input = new BufferedReader(new InputStreamReader(stream));}
	
	int nextInt() {return (int) nextLong();}

	long nextLong() {
		try {
			int sign = 1;
			int b = input.read();
			while ((b < '0' || '9' < b) && b != '-' && b != '+') {
				b = input.read();
			}
			if (b == '-') {
				sign = -1;
				b = input.read();
			} else if (b == '+') {
				b = input.read();
			}
			long ret = b - '0';
			while (true) {
				b = input.read();
				if (b < '0' || '9' < b) return ret * sign;
				ret *= 10;
				ret += b - '0';
			}
		} catch (IOException e) {
			e.printStackTrace();
			return -1;
		}
	}

	double nextDouble() {
		try {
			double sign = 1;
			int b = input.read();
			while ((b < '0' || '9' < b) && b != '-' && b != '+') {
				b = input.read();
			}
			if (b == '-') {
				sign = -1;
				b = input.read();
			} else if (b == '+') {
				b = input.read();
			}
			double ret = b - '0';
			while (true) {
				b = input.read();
				if (b < '0' || '9' < b) break;
				ret *= 10;
				ret += b - '0';
			}
			if (b != '.') return sign * ret;
			double div = 1;
			b = input.read();
			while ('0' <= b && b <= '9') {
				ret *= 10;
				ret += b - '0';
				div *= 10;
				b = input.read();
			}
			return sign * ret / div;
		} catch (IOException e) {
			e.printStackTrace();
			return Double.NaN;
		}
	}

	char nextChar() {
		try {
			int b = input.read();
			while (Character.isWhitespace(b)) {
				b = input.read();
			}
			return (char) b;
		} catch (IOException e) {
			e.printStackTrace();
			return 0;
		}
	}

	String nextStr() {
		try {
			StringBuilder sb = new StringBuilder();
			int b = input.read();
			while (Character.isWhitespace(b)) {
				b = input.read();
			}
			while (b != -1 && !Character.isWhitespace(b)) {
				sb.append((char) b);
				b = input.read();
			}
			return sb.toString();
		} catch (IOException e) {
			e.printStackTrace();
			return "";
		}
	}
}