There are N children, numbered 1, 2, ..., N.

Snuke has decided to distribute x sweets among them. He needs to give out all the x sweets, but some of the children may get zero sweets.

For each i (1 \leq i \leq N), Child i will be happy if he/she gets exactly a_i sweets. Snuke is trying to maximize the number of happy children by optimally distributing the sweets. Find the maximum possible number of happy children.

Constraints

* All values in input are integers.
* 2 \leq N \leq 100
* 1 \leq x \leq 10^9
* 1 \leq a_i \leq 10^9

Input

Input is given from Standard Input in the following format:


N x
a_1 a_2 ... a_N


Output

Print the maximum possible number of happy children.

Examples

Input

3 70
20 30 10


Output

2


Input

3 10
20 30 10


Output

1


Input

4 1111
1 10 100 1000


Output

4


Input

2 10
20 20


Output

0
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.Arrays;
import java.util.StringTokenizer;

public class Main {
	
	public static void main(String[] args) throws IOException {
		MyScanner sc = new MyScanner();
		PrintWriter out = new PrintWriter(System.out);
		int N = sc.nextInt();
		int x = sc.nextInt();
		int[] vals = new int[N];
		for (int i = 0; i < vals.length; i++) {
			vals[i] = sc.nextInt();
		}
		Arrays.sort(vals);
		int ans = 0;
		for (int i = 0; i < N; i++) {
			if (x >= vals[i] && ( i + 1 < N || x == vals[i])) {
				ans++;
				x -= vals[i];
			}
		}
		out.println(ans);
		
		out.flush();
	}
	
	static class MyScanner {
		private BufferedReader br;
		private StringTokenizer tokenizer;
		
		public MyScanner() {
			br = new BufferedReader(new InputStreamReader(System.in));
		}
		
		public String next() {
			while (tokenizer == null || !tokenizer.hasMoreTokens()) {
				try {
					tokenizer = new StringTokenizer(br.readLine());
				} catch (IOException e) {
					throw new RuntimeException(e);
				}
			}
			return tokenizer.nextToken();
		}
		
		public int nextInt() {
			return Integer.parseInt(next());
		}
		
		public long nextLong() {
			return Long.parseLong(next());
		}
	}
}
