Lee tried so hard to make a good div.2 D problem to balance his recent contest, but it still doesn't feel good at all. Lee invented it so tediously slow that he managed to develop a phobia about div.2 D problem setting instead. And now he is hiding behind the bushes...

Let's define a Rooted Dead Bush (RDB) of level n as a rooted tree constructed as described below.

A rooted dead bush of level 1 is a single vertex. To construct an RDB of level i we, at first, construct an RDB of level i-1, then for each vertex u: 

  * if u has no children then we will add a single child to it; 
  * if u has one child then we will add two children to it; 
  * if u has more than one child, then we will skip it. 

<image> Rooted Dead Bushes of level 1, 2 and 3.

Let's define a claw as a rooted tree with four vertices: one root vertex (called also as center) with three children. It looks like a claw:

<image> The center of the claw is the vertex with label 1.

Lee has a Rooted Dead Bush of level n. Initially, all vertices of his RDB are green.

In one move, he can choose a claw in his RDB, if all vertices in the claw are green and all vertices of the claw are children of its center, then he colors the claw's vertices in yellow.

He'd like to know the maximum number of yellow vertices he can achieve. Since the answer might be very large, print it modulo 10^9+7.

Input

The first line contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases.

Next t lines contain test cases — one per line.

The first line of each test case contains one integer n (1 ≤ n ≤ 2 ⋅ 10^6) — the level of Lee's RDB.

Output

For each test case, print a single integer — the maximum number of yellow vertices Lee can make modulo 10^9 + 7.

Example

Input


7
1
2
3
4
5
100
2000000


Output


0
0
4
4
12
990998587
804665184

Note

It's easy to see that the answer for RDB of level 1 or 2 is 0.

The answer for RDB of level 3 is 4 since there is only one claw we can choose: \{1, 2, 3, 4\}.

The answer for RDB of level 4 is 4 since we can choose either single claw \{1, 3, 2, 4\} or single claw \{2, 7, 5, 6\}. There are no other claws in the RDB of level 4 (for example, we can't choose \{2, 1, 7, 6\}, since 1 is not a child of center vertex 2).

<image> Rooted Dead Bush of level 4.

import java.util.*;
import java.io.*;
 
public class Mamo {
    static long mod=1000000007;
    static Reader in=new Reader();
    static List<Integer >G[];
    static boolean B=true;
    static StringBuilder Sl=new StringBuilder();
    static int DP[][];
    public static void main(String [] args) {
    	//Dir by MohammedElkady
    	long a[]=new long[2000001];
    	a[1]=0;a[2]=4;a[0]=0;
    	for(int i=3;i<a.length;i++) {
    		a[i]=(2*a[i-2])+a[i-1]+(((i%3==2)?1:0)*4);
    		a[i]%=mod;
    	}
    	int t=in.nextInt();
    	while(t-->0) {
    	int n=in.nextInt();
    	if(n!=3)
    	out.append(a[n-1]+"\n");
    	else  out.append("4 \n");
    	}
    	out.close();
    }
  
    public static boolean done=false;
    public static PrintWriter out = new PrintWriter(new BufferedOutputStream(System.out));
    static long gcd(long g,long x){if(x<1)return g;else return gcd(x,g%x);}
    
    static class Reader 
    { 
        private InputStream mIs;private byte[] buf = new byte[1024];private int curChar,numChars;public Reader() { this(System.in); }public Reader(InputStream is) { mIs = is;} 
        public int read() {if (numChars == -1) throw new InputMismatchException();if (curChar >= numChars) {curChar = 0;try { numChars = mIs.read(buf);} catch (IOException e) { throw new InputMismatchException();}if (numChars <= 0) return -1; }return buf[curChar++];} 
        public String nextLine(){int c = read();while (isSpaceChar(c)) c = read();StringBuilder res = new StringBuilder();do {res.appendCodePoint(c);c = read();}while (!isEndOfLine(c));return res.toString() ;} 
        public String s(){int c = read();while (isSpaceChar(c)) c = read();StringBuilder res = new StringBuilder();do {res.appendCodePoint(c);c = read();}while (!isSpaceChar(c));return res.toString();} 
        public long l(){int c = read();while (isSpaceChar(c)) c = read();int sgn = 1;if (c == '-') { sgn = -1 ; c = read() ; }long res = 0; do{ if (c < '0' || c > '9') throw new InputMismatchException();res *= 10 ; res += c - '0' ; c = read();}while(!isSpaceChar(c));return res * sgn;} 
        public int nextInt(){int c = read() ;while (isSpaceChar(c)) c = read();int sgn = 1;if (c == '-') { sgn = -1 ; c = read() ; }int res = 0;do{if (c < '0' || c > '9') throw new InputMismatchException();res *= 10 ; res += c - '0' ; c = read() ;}while(!isSpaceChar(c));return res * sgn;} 
        public double d() throws IOException {return Double.parseDouble(s()) ;}
        public boolean isSpaceChar(int c) { return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1; } 
        public boolean isEndOfLine(int c) { return c == '\n' || c == '\r' || c == -1; } 
        public int[] arr(int n){int[] ret = new int[n];for (int i = 0; i < n; i++) {ret[i] = nextInt();}return ret;}
    }
}
class node implements Comparable<node>{
int f, e;
node(int tt,int ll){
f=tt;e=ll;
}
    @Override
    public int compareTo(node o) {
    return f-o.f;    
    }
}
class FastReader
    {
        BufferedReader br;
        StringTokenizer st;
 
        public FastReader()
        {
            br = new BufferedReader(new
                     InputStreamReader(System.in));
        }
 
        String next()
        {
            while (st == null || !st.hasMoreElements())
            {
                try
                {
                    st = new StringTokenizer(br.readLine());
                }
                catch (IOException  e)
                {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }
 
        int nextInt()
        {
            return Integer.parseInt(next());
        }
 
        long nextLong()
        {
            return Long.parseLong(next());
        }
 
        double nextDouble()
        {
            return Double.parseDouble(next());
        }
 
        String nextLine()
        {
            String str = "";
            try
            {
                str = br.readLine();
            }
            catch (IOException e)
            {
                e.printStackTrace();
            }
            return str;
        }
}
 
class Sorting{
 
 public static int[] bucketSort(int[] array, int bucketCount) {
 
 if (bucketCount <= 0) throw new IllegalArgumentException("Invalid bucket count");
 
 if (array.length <= 1) return array; //trivially sorted
 
 
 
 int high = array[0];
 
 int low = array[0];
 
 for (int i = 1; i < array.length; i++) { //find the range of input elements
 
 if (array[i] > high) high = array[i];
 
 if (array[i] < low) low = array[i];
 
 }
 
 double interval = ((double)(high - low + 1))/bucketCount; //range of one bucket
 
 
 ArrayList<Integer> buckets[] = new ArrayList[bucketCount];
 
 for (int i = 0; i < bucketCount; i++) { //initialize buckets
 
 buckets[i] = new ArrayList();
 
 }
 
 
 
 for (int i = 0; i < array.length; i++) { //partition the input array
 
 buckets[(int)((array[i] - low)/interval)].add(array[i]);
 
 }
 
 
 int pointer = 0;
 
 for (int i = 0; i < buckets.length; i++) {
 
 Collections.sort(buckets[i]); //mergeSort
 
 for (int j = 0; j < buckets[i].size(); j++) { //merge the buckets
 
 array[pointer] = buckets[i].get(j);
 
 pointer++;
 
 }
 
}
 
return array;
 
}
}