"Pizza At", a fast food chain, offers three kinds of pizza: "A-pizza", "B-pizza" and "AB-pizza". A-pizza and B-pizza are completely different pizzas, and AB-pizza is one half of A-pizza and one half of B-pizza combined together. The prices of one A-pizza, B-pizza and AB-pizza are A yen, B yen and C yen (yen is the currency of Japan), respectively.

Nakahashi needs to prepare X A-pizzas and Y B-pizzas for a party tonight. He can only obtain these pizzas by directly buying A-pizzas and B-pizzas, or buying two AB-pizzas and then rearrange them into one A-pizza and one B-pizza. At least how much money does he need for this? It is fine to have more pizzas than necessary by rearranging pizzas.

Constraints

* 1 ≤ A, B, C ≤ 5000
* 1 ≤ X, Y ≤ 10^5
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


A B C X Y


Output

Print the minimum amount of money required to prepare X A-pizzas and Y B-pizzas.

Examples

Input

1500 2000 1600 3 2


Output

7900


Input

1500 2000 1900 3 2


Output

8500


Input

1500 2000 500 90000 100000


Output

100000000
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class Main {

	public static void main(String[] args) throws IOException {
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
		String[] get = br.readLine().split(" ");
		int a = Integer.parseInt(get[0]);
		int b = Integer.parseInt(get[1]);
		int c = Integer.parseInt(get[2]);
		int x = Integer.parseInt(get[3]);
		int y = Integer.parseInt(get[4]);

		int money = (int)Math.pow(10, 10);

		money = Math.min((a*x) + (b*y),Math.max(x, y)*2*c);
		int add = 0;

		if(x>y)add = (y*2*c) + ((x-y)*a);
		else add = (x*2*c) + ((y-x)*b);

		money = Math.min(money,add);

		System.out.println(money);
	}

}
