There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.*;

public class Main{
  public static void main(String[] args){
    Scanner sc = new Scanner(System.in);
    int n = sc.nextInt();
    String s = sc.next();
    String S[] = s.split("");
    int red = 0;
    int blue = 0;
    String R = "R";
    String B = "B";
    for(int i = 0;i < s.length();i++){
      if(S[i].equals(R)){
        red++;
      }
      else if(S[i].equals(B)){
        blue++;
      }
    }

    if(red > blue){
      System.out.println("Yes");
    }
    else{
      System.out.println("No");
    }
  }
}
