Today Peter has got an additional homework for tomorrow. The teacher has given three integers to him: n, m and k, and asked him to mark one or more squares on a square grid of size n × m. 

The marked squares must form a connected figure, and there must be exactly k triples of marked squares that form an L-shaped tromino — all three squares are inside a 2 × 2 square.

The set of squares forms a connected figure if it is possible to get from any square to any other one if you are allowed to move from a square to any adjacent by a common side square.

Peter cannot fulfill the task, so he asks you for help. Help him to create such figure.

Input

Input data contains one or more test cases. The first line contains the number of test cases t (1 ≤ t ≤ 100).

Each of the following t test cases is described by a line that contains three integers: n, m and k (3 ≤ n, m, n × m ≤ 105, 0 ≤ k ≤ 109).

The sum of values of n × m for all tests in one input data doesn't exceed 105.

Output

For each test case print the answer.

If it is possible to create such figure, print n lines, m characters each, use asterisk '*' to denote the marked square, and dot '.' to denote the unmarked one.

If there is no solution, print -1.

Print empty line between test cases.

Example

Input

3
3 3 4
3 3 5
3 3 3


Output

.*.
***
.*.

**.
**.
*..

.*.
***
*..
#include <bits/stdc++.h>
using namespace std;
template <typename T>
inline bool chkmin(T &a, const T &b) {
  return a > b ? a = b, 1 : 0;
}
template <typename T>
inline bool chkmax(T &a, const T &b) {
  return a < b ? a = b, 1 : 0;
}
const int oo = 0x3f3f3f3f;
const int maxn = 100000;
int n, m, K;
vector<int> ret[maxn + 5];
const int walk[4][2] = {{0, 1}, {0, -1}, {1, 0}, {-1, 0}};
bool vis[5][5];
bool g[5][5];
void dfs(int first, int second) {
  vis[first][second] = 1;
  for (int i = (0), i_end_ = (4); i < i_end_; ++i) {
    int u = first + walk[i][0], v = second + walk[i][1];
    if (u < 0 || u >= n || v < 0 || v >= m) continue;
    if (g[u][v] && !vis[u][v]) dfs(u, v);
  }
}
int main() {
  int T;
  scanf("%d", &T);
  while (T--) {
    scanf("%d%d%d", &n, &m, &K);
    if (n <= 4 && m <= 4) {
      bool find = 0;
      for (int i = (1), i_end_ = ((1 << (n * m))); i < i_end_; ++i) {
        for (int j = (0), j_end_ = (n); j < j_end_; ++j)
          for (int k = (0), k_end_ = (m); k < k_end_; ++k)
            g[j][k] = (i >> (j * m + k) & 1);
        int cnt = 0;
        memset(vis, 0, sizeof vis);
        for (int j = (0), j_end_ = (n); j < j_end_; ++j)
          for (int k = (0), k_end_ = (m); k < k_end_; ++k)
            if (g[j][k] && !vis[j][k]) dfs(j, k), ++cnt;
        if (cnt > 1) continue;
        int tot = 0;
        for (int j = (0), j_end_ = (n - 1); j < j_end_; ++j)
          for (int k = (0), k_end_ = (m - 1); k < k_end_; ++k) {
            int tmp = g[j][k] + g[j + 1][k] + g[j][k + 1] + g[j + 1][k + 1];
            if (tmp == 3)
              ++tot;
            else if (tmp == 4)
              tot += 4;
          }
        if (tot == K) {
          find = 1;
          for (int j = (0), j_end_ = (n); j < j_end_; ++j) {
            for (int k = (0), k_end_ = (m); k < k_end_; ++k) {
              if (g[j][k])
                putchar('*');
              else
                putchar('.');
            }
            putchar('\n');
          }
          putchar('\n');
          break;
        }
      }
      if (!find) puts("-1\n");
      continue;
    }
    if (K > ((n - 1) * (m - 1) << 2)) {
      puts("-1\n");
      continue;
    } else if (K == ((n - 1) * (m - 1) << 2)) {
      for (int i = (0), i_end_ = (n); i < i_end_; ++i) {
        for (int j = (0), j_end_ = (m); j < j_end_; ++j) putchar('*');
        putchar('\n');
      }
      putchar('\n');
      continue;
    } else if (K == ((n - 1) * (m - 1) << 2) - 8) {
      if (n == 3) {
        for (int i = (0), i_end_ = (n); i < i_end_; ++i) {
          for (int j = (0), j_end_ = (m); j < j_end_; ++j)
            putchar(!j ? '.' : '*');
          putchar('\n');
        }
      } else if (m == 3) {
        for (int i = (0), i_end_ = (n); i < i_end_; ++i) {
          for (int j = (0), j_end_ = (m); j < j_end_; ++j)
            putchar(!i ? '.' : '*');
          putchar('\n');
        }
      } else
        puts("-1");
      putchar('\n');
      continue;
    } else if (!K) {
      for (int i = (0), i_end_ = (n); i < i_end_; ++i) {
        for (int j = (0), j_end_ = (m); j < j_end_; ++j)
          putchar((!i && !j ? '*' : '.'));
        putchar('\n');
      }
      putchar('\n');
      continue;
    }
    bool rev = 0;
    if (n > m) swap(n, m), rev = 1;
    for (int i = (0), i_end_ = (n); i < i_end_; ++i) ret[i] = vector<int>(m, 0);
    bool failed = 0;
    --K;
    for (int i = (0), i_end_ = (m); i < i_end_; ++i) ret[0][i] = 1;
    int px = 0, py = m - 1;
    for (int i = (1), i_end_ = (n); i < i_end_; ++i)
      for (int j = (1), j_end_ = (m); j < j_end_; ++j) {
        if (K < 4) break;
        px = i, py = j;
        ret[i][j] = 1;
        K -= 4;
      }
    if (py == m - 1) ++px, py = 0;
    for (int i = (0), i_end_ = (px + 1); i < i_end_; ++i) ret[i][0] = 1;
    if (K == 1) {
      if (px != n - 1) {
        if (py >= 1)
          ret[px + 1][0] = 1;
        else
          ret[px][m - 1] = 1;
      } else if (py < m - 2)
        ret[n - 1][m - 1] = 1;
      else
        failed = 1;
    } else if (K == 2) {
      if (px != n - 1) {
        if (py >= 2)
          ret[px + 1][1] = 1;
        else
          ret[px][m - 2] = 1;
      } else if (py < m - 3)
        ret[px][m - 2] = 1;
      else
        failed = 1;
    } else if (K == 3) {
      if (px != n - 1) {
        if (py >= 3)
          ret[px + 1][0] = ret[px + 1][py - 1] = 1;
        else if (py == 2)
          ret[px + 1][1] = ret[px][m - 1] = 1;
        else if (py == 1)
          ret[px + 1][0] = ret[px][m - 2] = 1;
        else
          ret[px][m - 3] = ret[px][m - 1] = 1;
      } else if (py < m - 4)
        ret[px][m - 3] = ret[px][m - 1] = 1;
      else
        failed = 1;
    }
    if (rev) swap(n, m);
    if (failed) {
      puts("-1");
    } else {
      for (int i = (0), i_end_ = (n); i < i_end_; ++i) {
        for (int j = (0), j_end_ = (m); j < j_end_; ++j)
          putchar((rev ? ret[j][i] : ret[i][j]) ? '*' : '.');
        putchar('\n');
      }
    }
    putchar('\n');
  }
  return 0;
}
