We have N integers. The i-th number is A_i.

\\{A_i\\} is said to be pairwise coprime when GCD(A_i,A_j)=1 holds for every pair (i, j) such that 1\leq i < j \leq N.

\\{A_i\\} is said to be setwise coprime when \\{A_i\\} is not pairwise coprime but GCD(A_1,\ldots,A_N)=1.

Determine if \\{A_i\\} is pairwise coprime, setwise coprime, or neither.

Here, GCD(\ldots) denotes greatest common divisor.

Constraints

* 2 \leq N \leq 10^6
* 1 \leq A_i\leq 10^6

Input

Input is given from Standard Input in the following format:


N
A_1 \ldots A_N


Output

If \\{A_i\\} is pairwise coprime, print `pairwise coprime`; if \\{A_i\\} is setwise coprime, print `setwise coprime`; if neither, print `not coprime`.

Examples

Input

3
3 4 5


Output

pairwise coprime


Input

3
6 10 15


Output

setwise coprime


Input

3
6 10 16


Output

not coprime
import math


def primes(N):
    p = [False, False] + [True] * (N - 1)
    for i in range(2, int(N ** 0.5) + 1):
        if p[i]:
            for j in range(i * 2, N + 1, i):
                p[j] = False
    return [i for i in range(N + 1) if p[i]]


N = int(input())
A = list(map(int, input().split()))
maxA = max(A) + 1
g, Ac = A[0], [0] * maxA
P = primes(maxA)

for a in A:
    Ac[a] += 1

ans = "pairwise"
for p in P:
    if sum(Ac[p:maxA:p]) > 1:
        ans = "setwise"
for a in A:
    g = math.gcd(g, a)
print(ans if g == 1 else "not", "coprime")
