There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.Scanner;

public class Main {
    private static Scanner input = new Scanner(System.in);
    private static int q    ;

    public static void main(String[] args) {
        int a = input.nextInt();
        String b = input.next();

        for(int i = 0; i < b.length(); i++) {
            Character c = b.charAt(i);

            if (c.equals('R')) {
                q = q + 1;
            }
        }

            if (q > (a/2)) {
                System.out.println("Yes");
            }
            else {
                System.out.println("No");
            }
    }
}
