There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.*;

public class Main {
  public static void main(final String[] args) throws Exception {
    final Scanner scanner = new Scanner(System.in);
    try {
      int n = scanner.nextInt();
      String s = scanner.next();
      int a = count(s, 'R', n);
      int b = count(s, 'B', n);
      if (a > b) {
        System.out.println("Yes");
      } else {
        System.out.println("No");
      }
    } finally {
      scanner.close();
    }
  }

  private static int count(String s, char c, int n) {
    int result = 0;
    for (int i = 0; i < n; i++) {
      if (s.charAt(i) == c) result++;
    }
    return result;
  }
}
