A permutation of length n is an array consisting of n distinct integers from 1 to n in arbitrary order. For example, [2,3,1,5,4] is a permutation, but [1,2,2] is not a permutation (2 appears twice in the array) and [1,3,4] is also not a permutation (n=3 but there is 4 in the array).

Consider a permutation p of length n, we build a graph of size n using it as follows: 

  * For every 1 ≤ i ≤ n, find the largest j such that 1 ≤ j < i and p_j > p_i, and add an undirected edge between node i and node j 
  * For every 1 ≤ i ≤ n, find the smallest j such that i < j ≤ n and p_j > p_i, and add an undirected edge between node i and node j 



In cases where no such j exists, we make no edges. Also, note that we make edges between the corresponding indices, not the values at those indices.

For clarity, consider as an example n = 4, and p = [3,1,4,2]; here, the edges of the graph are (1,3),(2,1),(2,3),(4,3).

A permutation p is cyclic if the graph built using p has at least one simple cycle. 

Given n, find the number of cyclic permutations of length n. Since the number may be very large, output it modulo 10^9+7.

Please refer to the Notes section for the formal definition of a simple cycle

Input

The first and only line contains a single integer n (3 ≤ n ≤ 10^6).

Output

Output a single integer 0 ≤ x < 10^9+7, the number of cyclic permutations of length n modulo 10^9+7.

Examples

Input


4


Output


16

Input


583291


Output


135712853

Note

There are 16 cyclic permutations for n = 4. [4,2,1,3] is one such permutation, having a cycle of length four: 4 → 3 → 2 → 1 → 4.

Nodes v_1, v_2, …, v_k form a simple cycle if the following conditions hold: 

  * k ≥ 3. 
  * v_i ≠ v_j for any pair of indices i and j. (1 ≤ i < j ≤ k) 
  * v_i and v_{i+1} share an edge for all i (1 ≤ i < k), and v_1 and v_k share an edge. 
//  package cp;
import java.io.*;
import java.math.*;
import java.util.*;
public class Cf_three {
	long gcd(long a,long b) {if(b==0)return a;else return gcd(b,a%b);}
	void swap(long a,long b) {long temp=a;a=b;b=temp;}
	StringBuilder sb=new StringBuilder();
	BigInteger RES=new BigInteger("0");
//	StringBuilder temp=new StringBuilder(str[i-1]);
//	String rev=temp.reverse().toString(); convert sb to string
//	if(str[i].compareTo(rev)>=0)minn=0;-compare two Strings
	//(Initialize as string) - (a.add(b)) - (array initialized with null and not 0)
	Integer[] ARR=new Integer[5];
	//Integer sort-TLE-Initialize object elements i.e a[0].
	long ceil(double d) {return (long)Math.ceil(1.0*d);}
	void divisor(long n,int start) {
		int cnt=0;for(int i=start;i<=Math.sqrt(n);i++) {
		if(n%i==0) {if(i==n/i)cnt++;else cnt+=2;}}}
	static final int mod = 1000000007;
	public static void main(String[] args) throws IOException {	
		PrintWriter out = new PrintWriter(System.out);
		Readers.init(System.in);
		Cf_three obj=new Cf_three();
		int n=Readers.nextInt();
		long res=1;
		long[] fac=new long[n+1];
		fac[0]=1;fac[1]=1;
		for (int i = 1; i <=n; i++) {
			fac[i]=(1L*(fac[i-1]%mod)*(i%mod))%mod;
		}
		for (int i = 1; i <n; i++) {
			res=(1L*(res%mod)*(2%mod))%mod;
		}
//		System.out.println(((fac%m)-(res%m)+m)%m);
		System.out.println((fac[n]-res+mod)%mod);
	}
}
class Readers {
 
    static BufferedReader reader;
 
    static StringTokenizer tokenizer;
 
 
 
    /** call this method to initialize reader for InputStream */
 
    static void init(InputStream input) {
 
        reader = new BufferedReader(
 
                     new InputStreamReader(input) );
 
        tokenizer = new StringTokenizer("");
 
    }
 
 
 
    /** get next word */
 
    static String next() throws IOException {
 
        while ( ! tokenizer.hasMoreTokens() ) {
 
            //TODO add check for eof if necessary
 
            tokenizer = new StringTokenizer(
 
                   reader.readLine() );
 
        }
 
        return tokenizer.nextToken();
 
    }
 
 
 
    static int nextInt() throws IOException {
 
        return Integer.parseInt( next() );
 
    }
 
	
 
    static double nextDouble() throws IOException {
 
        return Double.parseDouble( next() );
 
    }
    
    
    static long nextLong() throws IOException{
    	
		return Long.parseLong(next());
	}
 
}