There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
#include <bits/stdc++.h>
using namespace std;

int main() {
  int n;
  string s;
  cin >> n >> s;
  int r=0;
 for(int i=0;i<n;i++){
     if(s.at(i)== 'R') r++;
     else r--;
 }  
 if(r>0) cout << "Yes" << endl;
 else cout << "No" << endl;
}
