There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.*;
public class Main {
	public static void main(String[] args){
		Scanner sc = new Scanner(System.in);
      	//数値の入力
      	int n = sc.nextInt();
		String s = sc.next();
      	int count =0;
      	int index = 0;
      	while(true) {
        index = s.indexOf("R", index) + 1;
        if (index == 0) break;
        count++;
		}
        if(count > n-count){
         System.out.println ("Yes");
        }else{
          System.out.println ("No");
      }
     }
}