There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.



Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:


n (the number of data in the list)
i p q
i p q
:
:
i p q


Output

For each dataset, print a list of employee IDs or a text "NA"

Example

Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0


Output

1001
1003
NA
2013
#include <iostream>
#include <algorithm>
#include <vector>

using namespace std;

typedef long long ll;

int main(){

	int n;
	while(cin>>n&&n!=0){
//		vector<pair<int,int> > v;
		ll info[4001];
		bool appeared[4001];
		fill(info,info+4001,0);
		fill(appeared,appeared+4001,false);
		vector<int> numList;
		for(int i = 0; i < n; i++){
			int num;
			int val;
			int ko;
			cin>>num>>val>>ko;
			if(!appeared[num]){
				appeared[num]=true;
				numList.push_back(num);
			}

			info[num]+=((ll)val)*ko;
		}

		bool f=false;
		for(int i = 0; i < numList.size(); i++){
			if(info[numList[i]]>=1000000){
				cout<<numList[i]<<endl;
				f=true;
			}
		}
		if(!f)
			cout<<"NA"<<endl;
	}

	return 0;
}