There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
#include <cstdio>
#include <iostream>

char s[110];
int main()
{
	int n; scanf("%d", &n);
	scanf("%s", s);
	int c = 0;
	for(int i = 0; i < n; i++)
	{
		if(s[i] == 'R') c++;
		else c--;
	}
	if(c > 0) puts("Yes");
	else puts("No");
}