There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.*;

class Main{
    public static void main(String[] args){
        Scanner sc = new Scanner(System.in);

        int a = sc.nextInt();
        String b = sc.next();

        String[] strArray = new String[105];

        int Rcount = 0;
        int Bcount = 0;

        for(int i = 0; i < b.length(); i++){
            strArray[i] = String.valueOf(b.charAt(i));

            if(strArray[i].equals("R")){
                Rcount = Rcount + 1;
            }
            if(strArray[i].equals("B")){
                Bcount = Bcount + 1;
            }
        }
        if(Rcount > Bcount){
            System.out.println("Yes");
        }
        else{
            System.out.println("No");
        }           
    }
}