There are N slimes standing on a number line. The i-th slime from the left is at position x_i.

It is guaruanteed that 1 \leq x_1 < x_2 < \ldots < x_N \leq 10^{9}.

Niwango will perform N-1 operations. The i-th operation consists of the following procedures:

* Choose an integer k between 1 and N-i (inclusive) with equal probability.
* Move the k-th slime from the left, to the position of the neighboring slime to the right.
* Fuse the two slimes at the same position into one slime.



Find the total distance traveled by the slimes multiplied by (N-1)! (we can show that this value is an integer), modulo (10^{9}+7). If a slime is born by a fuse and that slime moves, we count it as just one slime.

Constraints

* 2 \leq N \leq 10^{5}
* 1 \leq x_1 < x_2 < \ldots < x_N \leq 10^{9}
* x_i is an integer.

Input

Input is given from Standard Input in the following format:


N
x_1 x_2 \ldots x_N


Output

Print the answer.

Examples

Input

3
1 2 3


Output

5


Input

12
161735902 211047202 430302156 450968417 628894325 707723857 731963982 822804784 880895728 923078537 971407775 982631932


Output

750927044
import sys
input = lambda: sys.stdin.readline().rstrip()
inpl = lambda: list(map(int,input().split()))
def inv_mod(a, p=10**9+7):
    p = abs(p)
    a %= p
    stack = []
    p0 = p
    while a > 1:
        d, a, p = p//a, p%a, a
        stack.append(d)
    x, y = 1, 0
    while stack:
        d = stack.pop()
        x, y = y-d*x, x
    return x % p0
MOD = 10**9 + 7

N = int(input())
x = inpl()
d = [x[i+1]-x[i] for i in range(N-1)]

fac = 1
for i in range(2,N):
    fac = fac * i % MOD
inv = [ inv_mod(i,MOD) for i in range(1,N)]

ans = 0
s = 0
for i in range(N-1):
    s += inv[i]
    ans += d[i]*s
    ans %= MOD
ans = ans * fac % MOD
print(ans)