There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.Scanner;

public class Main{
	public static void main(String[] args) {
		// input process
		Scanner scanner = new Scanner(System.in);
		int n = Integer.parseInt(scanner.nextLine());
		String s = scanner.nextLine();

		// initialization
		int redCount = 0;
		int blueCount = 0;

		// count process
		for(int i=0; i<s.length();i++) {
			char c = s.charAt(i);
			if(c == 'R') {
				redCount++;
			}else {
				blueCount++;
			}
		}

		// output process
		if(redCount>blueCount) {
			System.out.println("Yes");
		}else {
			System.out.println("No");
		}

	}
}