Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1
#include <bits/stdc++.h>
using namespace std;
long long int gcd(long long int a, long long int b) {
  if (b == 0)
    return a;
  else
    return gcd(b, a % b);
}
int main() {
  long long int n, x, ans, ans1, y;
  cin >> y;
  n = (long long int)sqrt((double)y);
  for (long long int i = n; i > 0; i--) {
    if (y % i == 0) {
      x = y / i;
      if (gcd(i, x) == 1) {
        ans = i;
        ans1 = x;
        break;
      }
    }
  }
  if (y != 1)
    cout << ans << ' ' << ans1 << endl;
  else
    cout << 1 << ' ' << 1 << endl;
}
