There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.*;

public class Main{
 public static void main(String args[]){
  Scanner scn = new Scanner(System.in);
  int N = scn.nextInt();
  String s = scn.next();
  int R =0;
  int B =0;

for(int i=0;i<N;i++){
if(s.charAt(i)=='R'){
R++;
}else{
B++;
}
}
if(R-B>0){
System.out.print("Yes");
}else{
System.out.print("No");
}

    }
}
