"Pizza At", a fast food chain, offers three kinds of pizza: "A-pizza", "B-pizza" and "AB-pizza". A-pizza and B-pizza are completely different pizzas, and AB-pizza is one half of A-pizza and one half of B-pizza combined together. The prices of one A-pizza, B-pizza and AB-pizza are A yen, B yen and C yen (yen is the currency of Japan), respectively.

Nakahashi needs to prepare X A-pizzas and Y B-pizzas for a party tonight. He can only obtain these pizzas by directly buying A-pizzas and B-pizzas, or buying two AB-pizzas and then rearrange them into one A-pizza and one B-pizza. At least how much money does he need for this? It is fine to have more pizzas than necessary by rearranging pizzas.

Constraints

* 1 ≤ A, B, C ≤ 5000
* 1 ≤ X, Y ≤ 10^5
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


A B C X Y


Output

Print the minimum amount of money required to prepare X A-pizzas and Y B-pizzas.

Examples

Input

1500 2000 1600 3 2


Output

7900


Input

1500 2000 1900 3 2


Output

8500


Input

1500 2000 500 90000 100000


Output

100000000
import java.util.*;
import static java.lang.Math.*;
import java.math.BigInteger;

public class Main {
	public static void main(String[] args){
		Scanner sc = new Scanner(System.in);
		
		// 入力
		int a = sc.nextInt();
		int b = sc.nextInt();
		int c = sc.nextInt();
		int x = sc.nextInt();
		int y = sc.nextInt();

		// 計算
		int result = 0;
		if(a + b <= 2*c){
		    result = a*x + b*y;
		}else{
		    int c_cnt = min(x, y);
		    result += c*c_cnt*2;
		    int r_cnt = max(x, y) - c_cnt;
		    int r_price = a;
		    if(x < y) r_price = b;
		    if(r_price < 2*c){
		        result += r_cnt * r_price;
		    }else{
		        result += r_cnt * 2 * c;
		    }
		}
		
		// 出力
		System.out.println(result);
	}
}

