There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.Scanner;
public class Main {
public static void main(String[]args) {
	Scanner t = new Scanner (System.in);
	int num,cont = 0, cont1=0;
	num =t.nextInt();
	String v;
	v=t.next();
	for(int i = 0;i<v.length();i++) {

	if(v.charAt(i)=='R'){
		cont++;
	}
		if(v.charAt(i)=='B') {
			cont1++;
		
	}
	}
		if(cont>cont1) {
			System.out.println("Yes");
		}else {
			System.out.println("No");
		}
	}
}