You have a string s of length n consisting of only characters > and <. You may do some operations with this string, for each operation you have to choose some character that still remains in the string. If you choose a character >, the character that comes right after it is deleted (if the character you chose was the last one, nothing happens). If you choose a character <, the character that comes right before it is deleted (if the character you chose was the first one, nothing happens).

For example, if we choose character > in string > > < >, the string will become to > > >. And if we choose character < in string > <, the string will become to <.

The string is good if there is a sequence of operations such that after performing it only one character will remain in the string. For example, the strings >, > > are good. 

Before applying the operations, you may remove any number of characters from the given string (possibly none, possibly up to n - 1, but not the whole string). You need to calculate the minimum number of characters to be deleted from string s so that it becomes good.

Input

The first line contains one integer t (1 ≤ t ≤ 100) – the number of test cases. Each test case is represented by two lines.

The first line of i-th test case contains one integer n (1 ≤ n ≤ 100) – the length of string s.

The second line of i-th test case contains string s, consisting of only characters > and <.

Output

For each test case print one line.

For i-th test case print the minimum number of characters to be deleted from string s so that it becomes good.

Example

Input


3
2
&lt;&gt;
3
&gt;&lt;&lt;
1
&gt;


Output


1
0
0

Note

In the first test case we can delete any character in string <>.

In the second test case we don't need to delete any characters. The string > < < is good, because we can perform the following sequence of operations: > < < → < < → <.
#include <bits/stdc++.h>
using namespace std;
template <typename T>
T gcd(T a, T b) {
  if (a == 0) return b;
  return gcd(b % a, a);
}
template <typename P>
P dectobin(P a) {
  if (a == 0)
    return 0;
  else
    return (a % 2 + 10 * dectobin(a / 2));
}
template <typename Y>
Y bintodec(Y a) {
  long long ans = 0, b = 1, t = a;
  while (t) {
    long long ld = t % 10;
    t /= 10;
    ans += ld * b;
    b = b * 2;
  }
  return ans;
}
template <typename H>
H modExp(H x, H n) {
  long long r = 1;
  while (n > 0) {
    if (n % 2 == 1) {
      r = (r * x) % 1000000007;
    }
    x = (x * x) % 1000000007;
    n /= 2;
  }
  return r;
}
template <typename T>
T isPowerOfTwo(T x) {
  return x && (!(x & (x - 1)));
}
template <typename T>
T lcm(T a, T b) {
  return a * b / gcd(a, b);
}
int32_t main() {
  ios_base::sync_with_stdio(0);
  cin.tie(0);
  cout.tie(0);
  ostream_iterator<long long> output(cout, " ");
  long long t;
  cin >> t;
  while (t--) {
    long long n, cnt1 = 0, cnt2 = 0;
    cin >> n;
    string second;
    cin >> second;
    for (long long(i) = (0); i < (n); i++) {
      if (second[i] != '>')
        cnt1++;
      else
        break;
    }
    for (long long i = n - 1; i >= 0; i--) {
      if (second[i] != '<')
        cnt2++;
      else
        break;
    }
    if (n == 2) {
      if (cnt1 == 1 && cnt2 == 1) {
        cout << 1 << '\n';
      } else {
        cout << 0 << '\n';
      }
    } else if (n == 1) {
      cout << 0 << '\n';
    } else {
      if (cnt1 == 0 || cnt2 == 0)
        cout << 0 << '\n';
      else
        cout << min(cnt1, cnt2) << '\n';
    }
  }
  return 0;
}
