There is data on sales of your company. Your task is to write a program which identifies good workers.

The program should read a list of data where each item includes the employee ID i, the amount of sales q and the corresponding unit price p. Then, the program should print IDs of employees whose total sales proceeds (i.e. sum of p × q) is greater than or equal to 1,000,000 in the order of inputting. If there is no such employees, the program should print "NA". You can suppose that n < 4000, and each employee has an unique ID. The unit price p is less than or equal to 1,000,000 and the amount of sales q is less than or equal to 100,000.



Input

The input consists of several datasets. The input ends with a line including a single 0. Each dataset consists of:


n (the number of data in the list)
i p q
i p q
:
:
i p q


Output

For each dataset, print a list of employee IDs or a text "NA"

Example

Input

4
1001 2000 520
1002 1800 450
1003 1600 625
1001 200 1220
2
1001 100 3
1005 1000 100
2
2013 5000 100
2013 5000 100
0


Output

1001
1003
NA
2013
#include <cstdio>
#include <iostream>
#include <vector>
#include <utility>
typedef long long ll;
using namespace std;
#define rep(i,n) for(int i = 0; i < (n); ++i)
int main() {
	int n;
	while(scanf("%d\n", &n), n){
		vector<pair<ll, ll> > v;
		rep(i,n) {
			ll x, y, z;
			cin >> x >> y >> z;
			bool f = false;
			for(int j = 0; j < v.size(); ++j) {
				if(v[j].first == x) {
					v[j].second += y * z;
					f = true;
					break;
				}
			}
			if(!f) {
				v.push_back(make_pair(x, y * z));
			}
		}
		bool flag = false;
		for(int j = 0; j < v.size(); ++j) {
			if(v[j].second >= 1000000) {
				flag = true;
				cout << v[j].first << endl;
			}
		}
		if(!flag) cout << "NA" << endl;
	}
	return 0;
}