There are N slimes standing on a number line. The i-th slime from the left is at position x_i.

It is guaruanteed that 1 \leq x_1 < x_2 < \ldots < x_N \leq 10^{9}.

Niwango will perform N-1 operations. The i-th operation consists of the following procedures:

* Choose an integer k between 1 and N-i (inclusive) with equal probability.
* Move the k-th slime from the left, to the position of the neighboring slime to the right.
* Fuse the two slimes at the same position into one slime.



Find the total distance traveled by the slimes multiplied by (N-1)! (we can show that this value is an integer), modulo (10^{9}+7). If a slime is born by a fuse and that slime moves, we count it as just one slime.

Constraints

* 2 \leq N \leq 10^{5}
* 1 \leq x_1 < x_2 < \ldots < x_N \leq 10^{9}
* x_i is an integer.

Input

Input is given from Standard Input in the following format:


N
x_1 x_2 \ldots x_N


Output

Print the answer.

Examples

Input

3
1 2 3


Output

5


Input

12
161735902 211047202 430302156 450968417 628894325 707723857 731963982 822804784 880895728 923078537 971407775 982631932


Output

750927044
import sys
input = sys.stdin.buffer.readline
import copy

def main():
    N = int(input())
    x = list(map(int,input().split()))
    MOD = 10**9+7
    fac = [0 for _ in range(N+1)]
    fac[0],fac[1] = 1,1
    inv = copy.deepcopy(fac)
    invfac = copy.deepcopy(fac)
    
    for i in range(2,N+1):
        fac[i] = (fac[i-1]*i)%MOD
        inv[i] = MOD-(MOD//i)*inv[MOD%i]%MOD
        invfac[i] = (invfac[i-1]*inv[i])%MOD

    cum = [0]
    for i in range(N):
        cum.append(cum[-1]+inv[i+1])

    ans = 0
    for i in range(N-1):
        d = x[i+1]-x[i]
        ans += (d*cum[i+1])%MOD
        
    print((ans*fac[N-1])%MOD)

if __name__ == "__main__":
    main()
