There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.*;

class Main {
	public static void main(String[] args){
	int a = 0;
	int b = 0;
	int i = 0;
		Scanner sc = new Scanner(System.in);
		int N = sc.nextInt();
		String S = sc.next();
		 
	for(i = 0; i < S.length(); i++){
		if(String.valueOf(S.charAt(i)).equals("R")){
		    a += 1;
		}else{
			b += 1;
	    }
	}
	if(a > b){
	System.out.println("Yes");
	}else{
	System.out.println("No");
}
}
}
