There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
def int_raw():
    return int(raw_input())

def ss_raw():
    return raw_input().split()

def ints_raw():
    return map(int, ss_raw())

INF = 1 << 29

N  = int_raw()
S = raw_input()



def ans():
    Nr = S.count("R")
    if Nr*2 > N:
        return "Yes"
    else:
        return "No"


print ans()
