Polycarp plays a well-known computer game (we won't mention its name). In this game, he can craft tools of two types — shovels and swords. To craft a shovel, Polycarp spends two sticks and one diamond; to craft a sword, Polycarp spends two diamonds and one stick.

Each tool can be sold for exactly one emerald. How many emeralds can Polycarp earn, if he has a sticks and b diamonds?

Input

The first line contains one integer t (1 ≤ t ≤ 1000) — the number of test cases.

The only line of each test case contains two integers a and b (0 ≤ a, b ≤ 10^9) — the number of sticks and the number of diamonds, respectively.

Output

For each test case print one integer — the maximum number of emeralds Polycarp can earn.

Example

Input


4
4 4
1000000000 0
7 15
8 7


Output


2
0
7
5

Note

In the first test case Polycarp can earn two emeralds as follows: craft one sword and one shovel.

In the second test case Polycarp does not have any diamonds, so he cannot craft anything.
import sys
input = sys.stdin.readline
import math

############ ---- Input Functions ---- ############
def inp():
    return(int(input()))
def inlt():
    return(list(map(int,input().split())))
def insr():
    s = input().strip()
    return(list(s[:len(s)]))
def invr():
    return(map(int,input().strip().split()))



def from_file(f):
    return f.readline


def solve(a, b):
    if a < b:
        a, b = b, a

    #  a >= b
    k = a-b

    if k >= b:
        return b
    # k < b
    left = 2 * b - a

    res = left // 3
    res *= 2
    if left % 3 == 2:
        res += 1

    res += k
    return res





# with open('1.txt') as f:
#     input = from_file(f)
t = inp()
for _ in range(t):
    a, b= invr()
    print(solve(a,b))