There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.*;
public class Main{
	public static void main(String[] args){
		Scanner scan = new Scanner(System.in);
		int N = Integer.parseInt(scan.nextLine());
		String S = scan.nextLine();
		String[] s = S.split("",0);
		int r = 0;
		int b = 0;
		for(int i=0;i<N;i++){
			if(s[i].equals("R")){
				r++;
			}
			else{
				b++;
			}
		}
		if(r>b){
			System.out.println("Yes");
		}
		else{
			System.out.println("No");
		}
	}
}