There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.*;
 
public class Main {
 	public static void main(String[] args){
    	Scanner sc = new Scanner(System.in);
		int N = sc.nextInt();
		String str = sc.next();
		int Rcount = 0;
		int Bcount = 0;

		for (int i = 0; i < N; i++) {
			String str2 = String.valueOf(str.charAt(i));
			if(str2.equals("R")){
				Rcount++;
            }else{
				Bcount++;
            }
		}
		if(Rcount>Bcount){
			System.out.println("Yes");
        }else{
			System.out.println("No");
        }
	}
}
