There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.*;
 
public class Main {
	public static void main (String[] args) {
		Scanner sc = new Scanner(System.in);
		
        int N = sc.nextInt();
        String s = sc.next();
        char[] c = s.toCharArray();
        int blue = 0; int red = 0;

        for(int i = 0;i<N;i++){
      if(c[i] == 'R'){red++;}
      if(c[i] == 'B'){blue++;}
}
 if(red>blue){System.out.print("Yes");}
else{System.out.print("No");}
 

	}
}