There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);

        int N = sc.nextInt();
        String s = sc.next();

        int r=0,b=0;
        String ans;

        for(int i = 0; i<s.length(); i++) {
            switch (s.charAt(i)) {
                case 'R':
                    r++;
                    break;
                case 'B':
                    b++;
                    break;
            }
        }
        if (r > b) {
            ans = "Yes";
        } else {
            ans = "No";
        }

        System.out.println(ans);

    }
}