There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.*;
 
public class Main {
  public static void main(final String[] args) {
    Scanner sc = new Scanner(System.in);
    int N = sc.nextInt();
    String s = sc.next();
    int r = 0;
    int b = 0;
    
    for(int i=0; i<N; i++){
      if(s.charAt(i)=='R'){
        r++;
      }
      if(s.charAt(i)=='B'){
        b++;
      }
    }
    if(r>b){
    System.out.println("Yes");
    }else{
      System.out.println("No");
    }
  }
}