There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
#include<bits/stdc++.h>
using namespace std;

int main(){
	int n, r = 0;
	string s;
	cin >> n;
	cin >> s;
	for(auto i : s){
		if(i == 'R') r++;
	}
	if(2*r > n) cout << "Yes";
	else cout << "No";
	cout << endl;
	return 0;
}