There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.Scanner;

public class Main {
	
    public static void main(String[] args) {
    	Scanner sc = new Scanner(System.in);
    	int N = sc.nextInt();
    	String s = sc.next();
    	int[] cnt = new int[2];
    	
    	for( int i = 0; i < N; i++ ) {
    		if( s.charAt(i) == 'R' ) {
    			cnt[0]++;
    		}
    		else {
    			cnt[1]++;
    		}
    	}
    	
    	if( cnt[0] > cnt[1] ) {
    		System.out.println( "Yes" );
    	}
    	else {
    		System.out.println( "No" );
    	}
    	
    	sc.close();
    }
}