There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.*;

public class Main {
    public static void main(String[] args) throws Exception {
        // Your code here!
        Scanner sc = new Scanner(System.in);
        int N = sc.nextInt();
        String s = sc.next();
        String slist[] = s.split("");
        int count1 = 0;
        int count2 = 0;
        for (int i = 0; i < slist.length; ++i){
            if(slist[i].equals("R")){
                count1 += 1;
            }
            if(slist[i].equals("B")){
                count2 += 1;
            }
        }
        if(count1 > count2){
            System.out.println("Yes");
        }else{
            System.out.println("No");
        }
    }
}