There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
#include <stdio.h>
int main( void )
{
	int N ;
	char s;
	scanf("%d\n", &N ) ;
	int R=0, B=0;
	for( int n = 0 ; n < N ; n++ ) {
		scanf("%c", &s ) ;
		s == 'R' ? R++ : B++ ;
	}
	printf("%s\n", (R>B) ? "Yes" : "No" ) ;
	return 0 ;
}