There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.Scanner;
public class Main {
	public static void main(String[] args) throws Exception {
		Scanner scan=new Scanner(System.in);
		int n=scan.nextInt();
		String b=scan.next();
		int R=0;
		int B=0;
		for(int i=0;i<n;i++) {
			char ch=b.charAt(i);
			if(ch=='B') {
				B++;
			}
			else {
				R++;
			}
		}
		System.out.println(R>B?"Yes":"No");
	}
}