You have a string s of length n consisting of only characters > and <. You may do some operations with this string, for each operation you have to choose some character that still remains in the string. If you choose a character >, the character that comes right after it is deleted (if the character you chose was the last one, nothing happens). If you choose a character <, the character that comes right before it is deleted (if the character you chose was the first one, nothing happens).

For example, if we choose character > in string > > < >, the string will become to > > >. And if we choose character < in string > <, the string will become to <.

The string is good if there is a sequence of operations such that after performing it only one character will remain in the string. For example, the strings >, > > are good. 

Before applying the operations, you may remove any number of characters from the given string (possibly none, possibly up to n - 1, but not the whole string). You need to calculate the minimum number of characters to be deleted from string s so that it becomes good.

Input

The first line contains one integer t (1 ≤ t ≤ 100) – the number of test cases. Each test case is represented by two lines.

The first line of i-th test case contains one integer n (1 ≤ n ≤ 100) – the length of string s.

The second line of i-th test case contains string s, consisting of only characters > and <.

Output

For each test case print one line.

For i-th test case print the minimum number of characters to be deleted from string s so that it becomes good.

Example

Input


3
2
&lt;&gt;
3
&gt;&lt;&lt;
1
&gt;


Output


1
0
0

Note

In the first test case we can delete any character in string <>.

In the second test case we don't need to delete any characters. The string > < < is good, because we can perform the following sequence of operations: > < < → < < → <.
#include <bits/stdc++.h>
using namespace std;
mt19937 gen_rand;
template <typename T, typename U>
ostream &operator<<(ostream &os, pair<T, U> &a) {
  os << "(";
  os << a.first << ", ";
  os << a.second;
  os << ")";
  return os;
}
template <typename T>
ostream &operator<<(ostream &os, vector<T> &a) {
  os << "{";
  bool was = false;
  for (auto &x : a) {
    if (was) {
      os << ", ";
    }
    was = true;
    os << x;
  }
  os << "}";
  return os;
}
template <typename T>
inline void debug(const char *sdbg, T x) {
  cerr << "The value of " << sdbg << " is " << x << "\n";
};
template <typename T, typename... U>
inline void debug(const char *sdbg, T h, U... t) {
  cerr << "The value of ";
  while (*sdbg != ',') {
    cerr << *sdbg++;
  }
  cerr << " is " << h << "\n";
  debug(sdbg + 1, t...);
  cerr << "\n";
}
template <typename T>
T abs(T x) {
  if (x < 0) {
    return -x;
  } else {
    return x;
  }
}
template <typename T>
T sqr(T x) {
  return x * x;
};
const long long INF_FOR_SHORT_TIME = (long long)(1e9);
template <typename T>
T mul(T a, T b, T m) {
  if (a <= INF_FOR_SHORT_TIME && b <= INF_FOR_SHORT_TIME) {
    return (a * b) % m;
  }
  T q = (long long)((long double)a * (long double)b / (long double)m);
  T r = a * b - q * m;
  return (r + 5 * m) % m;
}
template <typename T, typename U>
T binpow(T a, U n, T MOD) {
  T res = 1;
  while (n) {
    if (n & 1) {
      res = mul(res, a, MOD);
    }
    a = mul(a, a, MOD);
    n >>= 1;
  }
  return res;
};
template <typename T>
int sign(T x) {
  if (x < 0) {
    return -1;
  } else if (x > 0) {
    return 1;
  } else {
    return 0;
  }
};
template <typename T>
T gcd(T a, T b) {
  if (a > b) {
    swap(a, b);
  }
  while (a) {
    b %= a;
    swap(a, b);
  }
  return b;
};
template <typename T>
bool uin(T &a, T b) {
  if (a > b) {
    a = b;
    return true;
  }
  return false;
};
template <typename T>
bool uax(T &a, T b) {
  if (a < b) {
    a = b;
    return true;
  }
  return false;
};
void solve() {
  int n;
  string s;
  cin >> n >> s;
  int res = n;
  for (int i = 0; i < n; ++i) {
    if (s[i] == '>') {
      uin(res, i);
    } else {
      uin(res, n - (i + 1));
    }
  }
  cout << res << "\n";
}
int main() {
  gen_rand.seed(time(0));
  ios_base::sync_with_stdio(false);
  cin.tie(nullptr);
  cout.tie(nullptr);
  int q;
  cin >> q;
  while (q--) {
    solve();
  }
  return 0;
}
