There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
    	try (Scanner in = new Scanner(System.in)) {
    		int N = Integer.parseInt(in.next());
    		char[] s = in.next().toCharArray();
    		int redCounter = 0;
    		int blueCounter = 0;
    		
    		for (int i = 0; i < N; i++) {
    			if (s[i] == 'R') redCounter++;
    				else blueCounter++;
    		}
    		
    		if (blueCounter < redCounter) System.out.println("Yes");
    		else System.out.println("No");
    		
    		
    	} catch (Exception e) {
			// TODO: handle exception
		}
    }
}
