Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1
import java.util.*;

public class Solution {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        long x = sc.nextLong();
        long toCheck = (long) Math.sqrt(x);
        long max = 1; long min = 1;
        for(int i=1;i<=toCheck;i++){
            if(x%i==0){
                long num2 = x/i;
                if(hcf(i,num2)==1){
                    max = num2;min=i;
                }
            }
        }
        System.out.println(max + " "+min);
    }

    private static long hcf(long i, long num2) {
        if(num2==0) return i;
        return hcf(num2,i%num2);
    }
}
