There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.io.BufferedReader;
import java.io.InputStreamReader;

public class Main {
	public static void main(String[] args) throws Exception {

		BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
		int N = Integer.parseInt(reader.readLine());
		String[] rb = reader.readLine().split("");
		int r_count = 0;
		for (int i = 0; i < N; i++) {
			if (rb[i].equals("R")) {
				r_count++;
			}
		}
		int b_count = N - r_count;
		if (r_count > b_count) {
			System.out.println("Yes");
		}
		else {
			System.out.println("No");
		}
	}
}