Andrewid the Android is a galaxy-famous detective. He is now investigating the case of vandalism at the exhibition of contemporary art.

The main exhibit is a construction of n matryoshka dolls that can be nested one into another. The matryoshka dolls are numbered from 1 to n. A matryoshka with a smaller number can be nested in a matryoshka with a higher number, two matryoshkas can not be directly nested in the same doll, but there may be chain nestings, for example, 1 → 2 → 4 → 5. 

In one second, you can perform one of the two following operations:

  * Having a matryoshka a that isn't nested in any other matryoshka and a matryoshka b, such that b doesn't contain any other matryoshka and is not nested in any other matryoshka, you may put a in b; 
  * Having a matryoshka a directly contained in matryoshka b, such that b is not nested in any other matryoshka, you may get a out of b. 



According to the modern aesthetic norms the matryoshka dolls on display were assembled in a specific configuration, i.e. as several separate chains of nested matryoshkas, but the criminal, following the mysterious plan, took out all the dolls and assembled them into a single large chain (1 → 2 → ... → n). In order to continue the investigation Andrewid needs to know in what minimum time it is possible to perform this action.

Input

The first line contains integers n (1 ≤ n ≤ 105) and k (1 ≤ k ≤ 105) — the number of matryoshkas and matryoshka chains in the initial configuration.

The next k lines contain the descriptions of the chains: the i-th line first contains number mi (1 ≤ mi ≤ n), and then mi numbers ai1, ai2, ..., aimi — the numbers of matryoshkas in the chain (matryoshka ai1 is nested into matryoshka ai2, that is nested into matryoshka ai3, and so on till the matryoshka aimi that isn't nested into any other matryoshka).

It is guaranteed that m1 + m2 + ... + mk = n, the numbers of matryoshkas in all the chains are distinct, in each chain the numbers of matryoshkas follow in the ascending order.

Output

In the single line print the minimum number of seconds needed to assemble one large chain from the initial configuration.

Examples

Input

3 2
2 1 2
1 3


Output

1


Input

7 3
3 1 3 7
2 2 5
2 4 6


Output

10

Note

In the first sample test there are two chains: 1 → 2 and 3. In one second you can nest the first chain into the second one and get 1 → 2 → 3.

In the second sample test you need to disassemble all the three chains into individual matryoshkas in 2 + 1 + 1 = 4 seconds and then assemble one big chain in 6 seconds.
import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.FileWriter;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.ArrayList;
import java.util.Comparator;
import java.util.HashSet;
import java.util.LinkedList;
import java.util.List;
import java.util.Stack;

public class Main {
	static HashSet<String> set = new HashSet<String>();
	public static void main(String[] args) throws NumberFormatException,
	IOException {
		Solve solve = new Solve();
		solve.solve();
	}
}
class Solve{
	ContestScanner in;
	Solve() throws FileNotFoundException{
		in = new ContestScanner();
	}
	void solve() throws IOException{
		int n = in.nextInt();
		int k = in.nextInt();
		int res = 0;
		int chains = 0;
		for(int i=0; i<k; i++){
			int m = in.nextInt();
			int[] chain = new int[m];
			chains = 0;
			boolean ext = false;
			for(int j=0; j<m; j++){
				chain[j] = in.nextInt();
				if(j==0){
					if(chain[j] != 1) ext = true;
					continue;
				}
				if(chain[j] != chain[j-1]+1){
					ext = true;
				}
				if(ext) chains++;
			}
			res += chains*2+1;
		}
		System.out.println(res-1);
	}
}

class Mt{
	List<Integer> chain = new LinkedList<Integer>();
	
}


class Timer{
	long time;
	public void set(){
		time = System.currentTimeMillis();
	}
	
	public long stop(){
		return System.currentTimeMillis()-time;
	}
}

class Node{
	int id;
	ArrayList<Node> edge = new ArrayList<Node>();
	public Node(int id) {
		this.id = id;
	}
	public void createEdge(Node node) {
		edge.add(node);
	}
}

class MyComp implements Comparator<int[]> {
	final int idx;
	public MyComp(int idx){
		this.idx = idx;
	}
	public int compare(int[] a, int[] b) {
		return a[idx] - b[idx];
	}
}

class Reverse implements Comparator<Integer> {
	public int compare(Integer arg0, Integer arg1) {
		return arg1 - arg0;
	}
}


class ContestWriter {
	private PrintWriter out;

	public ContestWriter(String filename) throws IOException {
		out = new PrintWriter(new BufferedWriter(new FileWriter(filename)));
	}

	public ContestWriter() throws IOException {
		out = new PrintWriter(System.out);
	}

	public void println(String str) {
		out.println(str);
	}
	
	public void println(Object obj) {
		out.println(obj);
	}

	public void print(String str) {
		out.print(str);
	}
	
	public void print(Object obj) {
		out.print(obj);
	}

	public void close() {
		out.close();
	}
}

class ContestScanner {
	private BufferedReader reader;
	private String[] line;
	private int idx;

	public ContestScanner() throws FileNotFoundException {
		reader = new BufferedReader(new InputStreamReader(System.in));
	}

	public ContestScanner(String filename) throws FileNotFoundException {
		reader = new BufferedReader(new InputStreamReader(new FileInputStream(
				filename)));
	}

	public String nextToken() throws IOException {
		if (line == null || line.length <= idx) {
			line = reader.readLine().trim().split(" ");
			idx = 0;
		}
		return line[idx++];
	}
	
	public String readLine() throws IOException{
		return reader.readLine();
	}

	public long nextLong() throws IOException, NumberFormatException {
		return Long.parseLong(nextToken());
	}

	public int nextInt() throws NumberFormatException, IOException {
		return (int) nextLong();
	}

	public double nextDouble() throws NumberFormatException, IOException {
		return Double.parseDouble(nextToken());
	}
}