Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1
#include <bits/stdc++.h>
using namespace std;
long long a;
int gcd(long long a, long long b) {
  if (b == 0) return a;
  a %= b;
  return gcd(b, a);
}
void solve(long long a) {
  long long mn = 1e8;
  long long mx = 0LL;
  for (long long i = 1; i * i <= a; i++) {
    if (a % i == 0) {
      if (a == ((i * a / i) / (gcd(i, a / i)))) {
        mx = i;
        mn = a / i;
      }
    }
  }
  cout << mx << " " << mn << "\n";
}
int main() {
  scanf("%lld", &a);
  solve(a);
  return 0;
}
