There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
#include <stdio.h>

int main()
{
  char  s[101], tmp;
  int N, r=0, b=0;
  scanf("%d\n",&N);
  for(int i=0; i<N; i++){
    scanf("%c", &tmp);
    if(tmp=='R')r++;
    if(tmp=='B')b++;
  }
  if(r>b)printf("Yes\n");
  else printf("No\n");
}