There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.*;
public class Main {
	public static void main(String[] args){
		Scanner sc = new Scanner(System.in);
		// 整数の入力
		int n = sc.nextInt();
      	String k = sc.next();
		String hat[] = k.split("");
        int i;
        int ans = 0;
        for(i = 0;i < n;i++){
          if(hat[i].equals("R")){
            ans++;
          }else{
            ans--;
          }
        }
      if(ans > 0){
            System.out.println("Yes");   
      }else{
        	System.out.println("No"); 
      }
 
 
    }
}