There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.*;

public class Main {
    public static void main(String[] args) throws Exception {
        
        Scanner sc = new Scanner(System.in);
        
        
		int N =sc.nextInt();
		
		String s =sc.next();
		String[] split = new String[N];
		int countR=0;
	
        
        String[] spt = s.split("");
        
        for(int i=0;i<N;i++){
            if(spt[i].equals("R")){
                countR++;
            }
        }
        if((N/2)<countR){
            System.out.println("Yes");
        }else{
            System.out.println("No");
        }
        
        
        
        
    }
}

