There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class Main {

    public static void main(String[] args) {

        InputStreamReader isr = new InputStreamReader(System.in);
        BufferedReader br = new BufferedReader(isr);

        String str1 = null;
        String str2 = null;
        int cntR = 0;
        int cntB = 0;

        try {
            str1 = br.readLine();
            str2 = br.readLine();
            int intA = Integer.parseInt(str1);

            for (int i = 0 ; i < intA ; i++) {
            	if ( str2.charAt(i) == 'R' ) {
            		cntR++;
            	}else {
            		cntB++;
            	}
            }

            if (cntR > cntB) {
            	System.out.println("Yes");
            }else {
            	System.out.println("No");

            }







        } catch (IOException e) {

        }


    }

}