Today, Osama gave Fadi an integer X, and Fadi was wondering about the minimum possible value of max(a, b) such that LCM(a, b) equals X. Both a and b should be positive integers.

LCM(a, b) is the smallest positive integer that is divisible by both a and b. For example, LCM(6, 8) = 24, LCM(4, 12) = 12, LCM(2, 3) = 6.

Of course, Fadi immediately knew the answer. Can you be just like Fadi and find any such pair?

Input

The first and only line contains an integer X (1 ≤ X ≤ 10^{12}).

Output

Print two positive integers, a and b, such that the value of max(a, b) is minimum possible and LCM(a, b) equals X. If there are several possible such pairs, you can print any.

Examples

Input


2


Output


1 2


Input


6


Output


2 3


Input


4


Output


1 4


Input


1


Output


1 1
import math
n,=map(int,input().split())
s=[]
for i in range(2,math.ceil(math.sqrt(n))):
    if n%i==0 and i*(n//i)//math.gcd(i,n//i)==n:
        s.append([i,n//i])
if len(s)>0:
    k=1000000000000
    s.sort()
    ind=0
    for i in range(len(s)):
        if k >max(s[i][0],s[i][1]):
            k=max(s[i][0],s[i][1])
            ind=i
    print(s[ind][0],s[ind][1])
else:
    print(1,n)