There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.*;

public class Main{
  
  public static void main(String[] args){
    
    Scanner sc = new Scanner(System.in);
    int N = Integer.parseInt(sc.next());
    String S = sc.next();
    
    char[] RB = S.toCharArray();
    int redCount = 0;
    int blueCount = 0;
    for(int i = 0 ; i < N ; i++){
      char rb = RB[i];
      if(rb == 'R'){
        redCount++;
      }else{
        blueCount++;
      }
    }
    
    if(redCount > blueCount){
      System.out.println("Yes");
    }else{
      System.out.println("No");
    }

  }  
}