There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.Scanner;

public class Main {

	public Main() {
		// TODO 自動生成されたコンストラクター・スタブ
	}
	
	public static void main(String[] args){
			Scanner sc = new Scanner(System.in);
			// 整数の入力
			int n = sc.nextInt();
			String s= sc.next();
			int index;
			int rednum=0;
			int bluenum=0;
			// 文字列の入力
			for(index=0;index<n;index++) {
				if(s.substring(index,index+1).equals("R")) {
					rednum++;
					}
				else {
					bluenum++;
				}
			}
			if(rednum>bluenum) {
		    	System.out.println("Yes");
		    }
			else {
		    	System.out.println("No");
		    }
	}
}