There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.Scanner;
class Main{
    public static void main(String[] args){
        Scanner scan = new Scanner(System.in);

        int n = Integer.parseInt(scan.nextLine());
        String inp = scan.nextLine();

        int red = 0;
        int blue = 0;


        for(int i = 0; i < n; i++){
            if(inp.charAt(i) == 'R'){
                red = red + 1;
            } else {
                blue = blue + 1;
            }
        }
        
        if( red > blue){
            System.out.println("Yes");
        } else {
            System.out.println("No");
        }
        

  
    }
}