There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.Scanner;

public  class Main  {

	public static void main(String args[]) {
		Scanner sc = new Scanner(System.in);
	 int N = sc.nextInt();
	 String s = sc.next();
	 char[] s_i= s.toCharArray();
	int redcounter = 0;
	for(int i = 0; i<s_i.length; i++) {
		if(s_i[i]=='R')redcounter++;
		else redcounter--;
	}
	System.out.println(redcounter>0 ? "Yes":"No");
}

		
	}

