You are given an integer N. Among the divisors of N! (= 1 \times 2 \times ... \times N), how many Shichi-Go numbers (literally "Seven-Five numbers") are there?

Here, a Shichi-Go number is a positive integer that has exactly 75 divisors.

Constraints

* 1 \leq N \leq 100
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of the Shichi-Go numbers that are divisors of N!.

Examples

Input

9


Output

0


Input

10


Output

1


Input

100


Output

543
N = int(input())
p = [
    sum(N // (i**k) for k in range(1, 8))
    for i in range(2, 97 + 1)
    if all(i % j != 0 for j in range(2, i))
]
def f(m):
  return len([i for i in p if i >= m])
ans = f(74) + f(24) * (f(2) - 1) + f(14) * (f(4) - 1) + f(4) * (f(4) - 1) * (f(2) - 2) // 2
print(ans)
