You are given an array of integers a_1,a_2,…,a_n. Find the maximum possible value of a_ia_ja_ka_la_t among all five indices (i, j, k, l, t) (i<j<k<l<t).

Input

The input consists of multiple test cases. The first line contains an integer t (1≤ t≤ 2 ⋅ 10^4) — the number of test cases. The description of the test cases follows.

The first line of each test case contains a single integer n (5≤ n≤ 10^5) — the size of the array.

The second line of each test case contains n integers a_1,a_2,…,a_n (-3× 10^3≤ a_i≤ 3× 10^3) — given array.

It's guaranteed that the sum of n over all test cases does not exceed 2⋅ 10^5.

Output

For each test case, print one integer — the answer to the problem.

Example

Input


4
5
-1 -2 -3 -4 -5
6
-1 -2 -3 1 2 -1
6
-1 0 0 0 -1 -1
6
-9 -7 -5 -3 -2 1


Output


-120
12
0
945

Note

In the first test case, choosing a_1,a_2,a_3,a_4,a_5 is a best choice: (-1)⋅ (-2) ⋅ (-3)⋅ (-4)⋅ (-5)=-120.

In the second test case, choosing a_1,a_2,a_3,a_5,a_6 is a best choice: (-1)⋅ (-2) ⋅ (-3)⋅ 2⋅ (-1)=12.

In the third test case, choosing a_1,a_2,a_3,a_4,a_5 is a best choice: (-1)⋅ 0⋅ 0⋅ 0⋅ (-1)=0.

In the fourth test case, choosing a_1,a_2,a_3,a_4,a_6 is a best choice: (-9)⋅ (-7) ⋅ (-5)⋅ (-3)⋅ 1=945.
import math, sys
from collections import defaultdict, Counter, deque
from functools import reduce

INF = float('inf')
MOD = int(1e9) + 7
 
def gcd(a, b):
	while b:
		a, b = b, a%b
	return a
 
def isPrime(n):
	if (n <= 1): 
		return False
	i = 2
	while i ** 2 <= n:
		if n % i == 0:
			return False
		i += 1
	return True
 
def primeFactors(n):
	factors = defaultdict(int)
	i = 2
	while i ** 2 <= n:
		while n % i == 0:
			factors[i] += 1
			n //= i 
		i += 1
	if n > 1:
		factors[n] += 1 
	return factors

def a():
	n = int(input())
	arr = array()

	m = Counter(arr)

	mex1 = -1
	mex2 = -1

	for k in sorted(m.keys()):
		if mex1 + 1 != k:
			break
		mex1 += 1
		if mex2 + 1 == k and m[k] >= 2:
			mex2 += 1 

	print(mex1 + mex2 + 2) 


def b():
	n = int(input())
	arr = array()

	arr.sort()
	ans = -INF

	for i in range(6):
		mul = 1 

		l = i 
		r = n - (5 - i)

		for i in range(0, l):
			mul *= arr[i]
		
		for i in range(r, n):
			mul *= arr[i]

		ans = max(ans, mul)


	print(ans)



class DSU:
	def __init__(self, n):
		self.p = [i for i in range(n + 1)]
		self.size = [1 for i in range(n + 1)]
		self.minmax = [[i, i] for i in range(n + 1)]
		self.n = n

	def find(self, node):
		if self.p[node] != node:
			self.p[node] = self.find(self.p[node])

		return self.p[node]

	def union(self, source, dest):
		source = self.find(source)
		dest = self.find(dest)

		if source != dest:
			if self.size[source] < self.size[dest]:
				source, dest = dest, source
			self.p[dest] = source
			self.size[source] += self.size[dest]
			mini = min(self.minmax[source][0], self.minmax[dest][0])
			maxi = max(self.minmax[source][1], self.minmax[dest][1])
			self.minmax[source] = [mini, maxi]



def input():
	return sys.stdin.readline().rstrip('\n')

def print(*args, sep=' ', end='\n'):
	first = True
	for arg in args:
		if not first:
			sys.stdout.write(sep)
		sys.stdout.write(str(arg))
		first = False 

	sys.stdout.write(end)

def vars():
	return map(int, input().split())
 
def array():
	return list(map(int, input().split()))

if __name__ == "__main__":
	t = 1
	t = int(input())
	for _ in range(t):
		b()
