You are given two strings s and t, both consisting only of lowercase Latin letters.

The substring s[l..r] is the string which is obtained by taking characters s_l, s_{l + 1}, ..., s_r without changing the order.

Each of the occurrences of string a in a string b is a position i (1 ≤ i ≤ |b| - |a| + 1) such that b[i..i + |a| - 1] = a (|a| is the length of string a).

You are asked q queries: for the i-th query you are required to calculate the number of occurrences of string t in a substring s[l_i..r_i].

Input

The first line contains three integer numbers n, m and q (1 ≤ n, m ≤ 10^3, 1 ≤ q ≤ 10^5) — the length of string s, the length of string t and the number of queries, respectively.

The second line is a string s (|s| = n), consisting only of lowercase Latin letters.

The third line is a string t (|t| = m), consisting only of lowercase Latin letters.

Each of the next q lines contains two integer numbers l_i and r_i (1 ≤ l_i ≤ r_i ≤ n) — the arguments for the i-th query.

Output

Print q lines — the i-th line should contain the answer to the i-th query, that is the number of occurrences of string t in a substring s[l_i..r_i].

Examples

Input

10 3 4
codeforces
for
1 3
3 10
5 6
5 7


Output

0
1
0
1


Input

15 2 3
abacabadabacaba
ba
1 15
3 4
2 14


Output

4
0
3


Input

3 5 2
aaa
baaab
1 3
1 1


Output

0
0

Note

In the first example the queries are substrings: "cod", "deforces", "fo" and "for", respectively.
import java.io.*;
import java.util.*;
public class Asd {
static PrintWriter w=new PrintWriter(System.out);
static FastScanner s=new FastScanner();

	public static void main(String[] args) {
		
		//int t=s.nextInt();
              int t=1;
		while(t-->0)
                {
		    solve();
		}
	       w.close();
        }
        /* Function to print all the permutations of the string
        static String swap(String str, int i, int j)
        {
        char ch;
        char[] array = str.toCharArray();
        ch = array[i];
        array[i] = array[j];
        array[j] = ch;
        return String.valueOf(array);
       }
    
      static void permute(String str,int low,int high)
    {
        if(low == high)
            list.add(Long.parseLong(str));
 
        int i;
        for(i = low; i<=high; i++){
            str = swap(str,low,i);
            permute(str, low+1,high);
            str = swap(str,low,i);
        }
    }
        use  permute(str2,0,str2.length()-1); to perform combinations
        */
           public static void solve()
        {
          int n=s.nextInt(); int m=s.nextInt(); int q=s.nextInt();
           String str1=s.next();
           String str2=s.next();
           ArrayList<Integer> list=new ArrayList<>();
           for(int i=0;i<=n-m;i++)
           {
               if(str1.substring(i,i+m).equals(str2))
               {list.add(i);}
           }
               
           while(q-->0)
           {
               int a=s.nextInt()-1;int count=0;
               int b=s.nextInt();int flag=3;
               for(int i=0;i<list.size();i++)
               {
                   
                  
                  if(list.get(i)>=a&&list.get(i)+m<=b)
                      count++;
               }
               w.println(count);
               
           }
        }          
        static int noofdivisors(int n)
        {
            //it counts no of divisors of every number upto number n
            
            int arr[]=new int[n+1];
              for(int i=1;i<=(n);i++)
			for(int j=i;j<=(n);j=j+i)
				arr[j]++;
             return arr[0];
        }
           
        
       
        static char[] reverse(char arr[])
        {
            char[] b = new char[arr.length]; 
        int j = arr.length; 
        for (int i = 0; i < arr.length; i++) { 
            b[j - 1] = arr[i]; 
            j = j - 1; 
        }
        return b;
        }
        
        
	static long factorial(int n)
        {
            long su=1;
            for(int i=1;i<=n;i++)
                su*=(long)i;
            return su;
        }
	static class FastScanner {
		BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
		StringTokenizer st=new StringTokenizer("");
		public String next() {
			while (!st.hasMoreElements())
				try {
					st=new StringTokenizer(br.readLine());
				} catch (IOException e) {
					e.printStackTrace();
				}
			return st.nextToken();
		}
		int[] readArray(int n) {
			int[] a=new int[n]; 
			for (int i=0; i<n; i++) a[i]=nextInt();
			return a;
		}
		
		int nextInt () {
			return Integer.parseInt(next());
		}
                long nextLong () {
			return Long.parseLong(next());
		}
                double nextDouble () {
			return Double.parseDouble(next());
		}
	}

}
