You are given an integer N. Among the divisors of N! (= 1 \times 2 \times ... \times N), how many Shichi-Go numbers (literally "Seven-Five numbers") are there?

Here, a Shichi-Go number is a positive integer that has exactly 75 divisors.

Constraints

* 1 \leq N \leq 100
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of the Shichi-Go numbers that are divisors of N!.

Examples

Input

9


Output

0


Input

10


Output

1


Input

100


Output

543
n = int(input())

def f_pf(n):
    pf = {}
    for i in range(2, n + 1):
        for j in range(2, i + 1):
            while i % j == 0:
                pf[j] = pf.get(j, 0) + 1
                i //= j
    return pf

def cnt(x):
    cnt = 0
    for v in f_pf(n).values():
        if v >= x - 1:
            cnt += 1
    return cnt
        
ans = cnt(75) + cnt(25) * (cnt(3) - 1) + cnt(15) * (cnt(5) - 1) + cnt(5) * (cnt(5) - 1) * (cnt(3) - 2) // 2

print(ans)