You are given one integer number n. Find three distinct integers a, b, c such that 2 ≤ a, b, c and a ⋅ b ⋅ c = n or say that it is impossible to do it.

If there are several answers, you can print any.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of test cases.

The next n lines describe test cases. The i-th test case is given on a new line as one integer n (2 ≤ n ≤ 10^9).

Output

For each test case, print the answer on it. Print "NO" if it is impossible to represent n as a ⋅ b ⋅ c for some distinct integers a, b, c such that 2 ≤ a, b, c.

Otherwise, print "YES" and any possible such representation.

Example

Input


5
64
32
97
2
12345


Output


YES
2 4 8 
NO
NO
NO
YES
3 5 823 
''' Hey stalker :) '''
INF = 10**10
def main():
    #print = out.append
    ''' Cook your dish here! '''
    n = get_int()
    factors = prime_factors(n)
    keys = list(factors.keys())
    if len(factors)>=2:
        a, b = keys[:2]
        c = n // (a * b)
        if c==a or c==b or c<2:
            print("NO")
            return
    else:
        if factors[keys[0]]>5:
            a = keys[0]
            b = keys[0]**2
        else:
            print("NO")
            return
    c = n // (a * b)
    print("YES")
    print(a,b,c)

def prime_factors(n):  # n**0.5 complex
    factors = dict()
    for i in range(2, math.ceil(math.sqrt(n)) + 1):
        while n % i == 0:
            if i in factors:
                factors[i] += 1
            else:
                factors[i] = 1
            n = n // i
    if n > 2:
        factors[n] = 1
    return (factors)

''' Pythonista fLite 1.1 '''
import sys
from collections import defaultdict, Counter
from bisect import bisect_left, bisect_right
#from functools import reduce
import math
input = iter(sys.stdin.buffer.read().decode().splitlines()).__next__
out = []
get_int = lambda: int(input())
get_list = lambda: list(map(int, input().split()))
#main()
[main() for _ in range(int(input()))]
print(*out, sep='\n')
