You are given an integer N. Among the divisors of N! (= 1 \times 2 \times ... \times N), how many Shichi-Go numbers (literally "Seven-Five numbers") are there?

Here, a Shichi-Go number is a positive integer that has exactly 75 divisors.

Constraints

* 1 \leq N \leq 100
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of the Shichi-Go numbers that are divisors of N!.

Examples

Input

9


Output

0


Input

10


Output

1


Input

100


Output

543
prime=[2,3,5,7,11,13,17,19,23,29,31,37,41,43,47]
s=[0 for i in range(15)]
N=int(input())
for i in range(15):
  j=1
  while N//(prime[i]**j)>0:
    s[i]+=N//(prime[i]**j)
    j+=1
o3,o5,o15,o25,o75=0,0,0,0,0
for item in s:
  if item>=2:
    o3+=1
    if item>=4:
      o5+=1
      if item>=14:
        o15+=1
        if item>=24:
          o25+=1
          if item>=74:
            o75+=1
ans=[0,0,0,0]
if o75>0:
  ans[0]+=1
if o25>0:
  ans[1]+=o25*(o3-1)
if o15>0:
  ans[2]+=o15*(o5-1)
if o5>1 and o3>2:
  ans[3]+=o5*(o5-1)//2*(o3-2)
print(sum(ans))
