Petya loves lucky numbers. We all know that lucky numbers are the positive integers whose decimal representations contain only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.

Unfortunately, not all numbers are lucky. Petya calls a number nearly lucky if the number of lucky digits in it is a lucky number. He wonders whether number n is a nearly lucky number.

Input

The only line contains an integer n (1 ≤ n ≤ 1018).

Please do not use the %lld specificator to read or write 64-bit numbers in С++. It is preferred to use the cin, cout streams or the %I64d specificator.

Output

Print on the single line "YES" if n is a nearly lucky number. Otherwise, print "NO" (without the quotes).

Examples

Input

40047


Output

NO


Input

7747774


Output

YES


Input

1000000000000000000


Output

NO

Note

In the first sample there are 3 lucky digits (first one and last two), so the answer is "NO".

In the second sample there are 7 lucky digits, 7 is lucky number, so the answer is "YES".

In the third sample there are no lucky digits, so the answer is "NO".
from itertools import product
import re

class CustomException(Exception):
    def __init__(self, *args, **kwargs):
        super().__init__(*args, **kwargs)
        self.message = args[0]

def mCheckInputs(*args):
    if ( (args[0].isdigit()) and (1 <= int(args[0]) <= pow(10,18)) ):
        pass

    else:
        exit(1)

def mHandleInputs():
    x = input()
    mCheckInputs(x)
    return x

def mDoThyWork(x):
    result = "YES" if (mIntContainsLuckyNumber(x)) else "NO"
    return result

def mIntContainsLuckyNumber(x):
    luckyNumbersList = [ 
        int(''.join(re.split('[^0-9]',str(item))).replace(" ",""))
        for i in range(15) 
        for item in list(product([4,7], repeat=i+1))
        ]
    
    luckyNumbersCount = x.count('4') + x.count('7')
    return True if (luckyNumbersCount in luckyNumbersList) else False

def mFormatResult(result):
    print(result)


def main():
    x = mHandleInputs()

    result = mDoThyWork(x)

    mFormatResult(result)

if __name__ == "__main__":
    main()