You are given an integer N. Among the divisors of N! (= 1 \times 2 \times ... \times N), how many Shichi-Go numbers (literally "Seven-Five numbers") are there?

Here, a Shichi-Go number is a positive integer that has exactly 75 divisors.

Constraints

* 1 \leq N \leq 100
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of the Shichi-Go numbers that are divisors of N!.

Examples

Input

9


Output

0


Input

10


Output

1


Input

100


Output

543
n = int(input())
lis=[2,3,5,7,11,13,17,19,23,29,31,37,41,43,47]
li=[]
a=0
b=0
c=0
d=0
e=0
for i in range(15):
    p=n
    q=0
    while(p>0):
        q+=p//lis[i]
        p=p//lis[i]
    if q>=74:
        e+=1
    if q>=24:
        a+=1
    if q>=14:
        b+=1
    if q>=4:
        c+=1
    if q>=2:
        d+=1
ans=a*(d-1)+b*(c-1)+(c*(c-1))//2*(d-2)+e
print(ans)