You are given two strings s and t, both consisting only of lowercase Latin letters.

The substring s[l..r] is the string which is obtained by taking characters s_l, s_{l + 1}, ..., s_r without changing the order.

Each of the occurrences of string a in a string b is a position i (1 ≤ i ≤ |b| - |a| + 1) such that b[i..i + |a| - 1] = a (|a| is the length of string a).

You are asked q queries: for the i-th query you are required to calculate the number of occurrences of string t in a substring s[l_i..r_i].

Input

The first line contains three integer numbers n, m and q (1 ≤ n, m ≤ 10^3, 1 ≤ q ≤ 10^5) — the length of string s, the length of string t and the number of queries, respectively.

The second line is a string s (|s| = n), consisting only of lowercase Latin letters.

The third line is a string t (|t| = m), consisting only of lowercase Latin letters.

Each of the next q lines contains two integer numbers l_i and r_i (1 ≤ l_i ≤ r_i ≤ n) — the arguments for the i-th query.

Output

Print q lines — the i-th line should contain the answer to the i-th query, that is the number of occurrences of string t in a substring s[l_i..r_i].

Examples

Input

10 3 4
codeforces
for
1 3
3 10
5 6
5 7


Output

0
1
0
1


Input

15 2 3
abacabadabacaba
ba
1 15
3 4
2 14


Output

4
0
3


Input

3 5 2
aaa
baaab
1 3
1 1


Output

0
0

Note

In the first example the queries are substrings: "cod", "deforces", "fo" and "for", respectively.
#!/usr/bin/env python2
"""
This file is part of https://github.com/cheran-senthil/PyRival
Copyright 2019 Cheran Senthilkumar <hello@cheran.io>

"""
from __future__ import division, print_function

import itertools
import os
import sys
from atexit import register
from collections import deque
from io import BytesIO


class dict(dict):
    """dict() -> new empty dictionary"""

    def items(self):
        """D.items() -> a set-like object providing a view on D's items"""
        return dict.iteritems(self)

    def keys(self):
        """D.keys() -> a set-like object providing a view on D's keys"""
        return dict.iterkeys(self)

    def values(self):
        """D.values() -> an object providing a view on D's values"""
        return dict.itervalues(self)


def gcd(x, y):
    """greatest common divisor of x and y"""
    while y:
        x, y = y, x % y
    return x


range = xrange

filter = itertools.ifilter
map = itertools.imap
zip = itertools.izip

sys.stdin = BytesIO(os.read(0, os.fstat(0).st_size))
sys.stdout = BytesIO()
register(lambda: os.write(1, sys.stdout.getvalue()))

input = lambda: sys.stdin.readline().rstrip('\r\n')


def main():
    n, m, q = map(int, input().split())
    if m > n:
        for _ in range(q):
            print(0)
        return

    s = input()
    t = deque(input())

    window = deque(s[:m])
    pref_sums = [0] * (n - m + 2)
    pref_sums[1] = 1 if window == t else 0

    for i in range(m, n):
        window.append(s[i])
        window.popleft()
        pref_sums[i - m + 2] = pref_sums[i - m + 1] + (1 if window == t else 0)

    for i in range(q):
        l, r = map(int, input().split())
        if r - l < m - 1:
            print(0)
        else:
            print(pref_sums[r - m + 1] - pref_sums[l - 1])


if __name__ == '__main__':
    main()
