You have n coins, each of the same value of 1.

Distribute them into packets such that any amount x (1 ≤ x ≤ n) can be formed using some (possibly one or all) number of these packets.

Each packet may only be used entirely or not used at all. No packet may be used more than once in the formation of the single x, however it may be reused for the formation of other x's.

Find the minimum number of packets in such a distribution.

Input

The only line contains a single integer n (1 ≤ n ≤ 10^9) — the number of coins you have.

Output

Output a single integer — the minimum possible number of packets, satisfying the condition above.

Examples

Input

6


Output

3

Input

2


Output

2

Note

In the first example, three packets with 1, 2 and 3 coins can be made to get any amount x (1≤ x≤ 6).

  * To get 1 use the packet with 1 coin. 
  * To get 2 use the packet with 2 coins. 
  * To get 3 use the packet with 3 coins. 
  * To get 4 use packets with 1 and 3 coins. 
  * To get 5 use packets with 2 and 3 coins 
  * To get 6 use all packets. 



In the second example, two packets with 1 and 1 coins can be made to get any amount x (1≤ x≤ 2).
/*input
2
*/

import java.util.*;
import java.io.*;
import java.math.*;
public class MCFA
{
    static long findS(long s)
    {
        long l = 1, r = s;
     
        // Apply Binary search
        while (l <= r) {
     
            // Find mid
            long mid = (l + r) / 2;
     
            // find sum of 1 to mid natural
            // numbers using formula
            long sum = (mid * (mid + 1)) / 2;
            long sum2=((mid+1)*(mid+2))/2;
     
            // If sum is equal to n
            // return mid
            if (sum == s)
                return mid;
     
            // If greater than n
            // do r = mid-1
            else if (sum > s)
                r = mid - 1;
     
            // else do l = mid + 1
            else if(sum<s && sum2>s)
            {
                return mid+s-sum;
                // l = mid + 1;
            }
            else
            {
                l=mid+1;
            }
        }
     
        // If not possible, return -1
        return -1;
    }
	public static void main(String[] args) throws Exception
	{
		StringBuffer sb = new StringBuffer();
		Bolt sc = new Bolt(System.in);	
		int n=sc.nextInt();
        
          
        System.out.println((int)(Math.log(n)/Math.log(2))+1);
    }
}

class Bolt
{
        private InputStream stream;
        private byte[] buf = new byte[1024];
        private int curChar;
        private int numChars;
 
        public Bolt(InputStream stream) {
            this.stream = stream;
        }
 
        public int read() {
            if (numChars == -1)
                throw new UnknownError();
            if (curChar >= numChars) {
                curChar = 0;
                try {
                    numChars = stream.read(buf);
                } catch (IOException e) {
                    throw new UnknownError();
                }
                if (numChars <= 0)
                    return -1;
            }
            return buf[curChar++];
        }
 
        public int peek() {
            if (numChars == -1)
                return -1;
            if (curChar >= numChars) {
                curChar = 0;
                try {
                    numChars = stream.read(buf);
                } catch (IOException e) {
                    return -1;
                }
                if (numChars <= 0)
                    return -1;
            }
            return buf[curChar];
        }
 
        public void skip(int x) {
            while (x-- > 0)
                read();
        }
 
        public int nextInt() {
            return Integer.parseInt(next());
        }
 
        public long nextLong() {
            return Long.parseLong(next());
        }
 
        public String nextString() {
            return next();
        }
 
        public String next() {
            int c = read();
            while (isSpaceChar(c))
                c = read();
            StringBuffer res = new StringBuffer();
            do {
                res.appendCodePoint(c);
                c = read();
            } while (!isSpaceChar(c));
 
            return res.toString();
        }
 
        public String nextLine() {
            StringBuffer buf = new StringBuffer();
            int c = read();
            while (c != '\n' && c != -1) {
                if (c != '\r')
                    buf.appendCodePoint(c);
                c = read();
            }
            return buf.toString();
        }
 
        public double nextDouble() {
            int c = read();
            while (isSpaceChar(c))
                c = read();
            int sgn = 1;
            if (c == '-') {
                sgn = -1;
                c = read();
            }
            double res = 0;
            while (!isSpaceChar(c) && c != '.') {
                if (c == 'e' || c == 'E')
                    return res * Math.pow(10, nextInt());
                if (c < '0' || c > '9')
                    throw new InputMismatchException();
                res *= 10;
                res += c - '0';
                c = read();
            }
            if (c == '.') {
                c = read();
                double m = 1;
                while (!isSpaceChar(c)) {
                    if (c == 'e' || c == 'E')
                        return res * Math.pow(10, nextInt());
                    if (c < '0' || c > '9')
                        throw new InputMismatchException();
                    m /= 10;
                    res += (c - '0') * m;
                    c = read();
                }
            }
            return res * sgn;
        }
 
        public boolean hasNext() {
            int value;
            while (isSpaceChar(value = peek()) && value != -1)
                read();
            return value != -1;
        }
 
        private boolean isSpaceChar(int c) {
            return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1;
        }
}
