You are given an array of integers a_1,a_2,…,a_n. Find the maximum possible value of a_ia_ja_ka_la_t among all five indices (i, j, k, l, t) (i<j<k<l<t).

Input

The input consists of multiple test cases. The first line contains an integer t (1≤ t≤ 2 ⋅ 10^4) — the number of test cases. The description of the test cases follows.

The first line of each test case contains a single integer n (5≤ n≤ 10^5) — the size of the array.

The second line of each test case contains n integers a_1,a_2,…,a_n (-3× 10^3≤ a_i≤ 3× 10^3) — given array.

It's guaranteed that the sum of n over all test cases does not exceed 2⋅ 10^5.

Output

For each test case, print one integer — the answer to the problem.

Example

Input


4
5
-1 -2 -3 -4 -5
6
-1 -2 -3 1 2 -1
6
-1 0 0 0 -1 -1
6
-9 -7 -5 -3 -2 1


Output


-120
12
0
945

Note

In the first test case, choosing a_1,a_2,a_3,a_4,a_5 is a best choice: (-1)⋅ (-2) ⋅ (-3)⋅ (-4)⋅ (-5)=-120.

In the second test case, choosing a_1,a_2,a_3,a_5,a_6 is a best choice: (-1)⋅ (-2) ⋅ (-3)⋅ 2⋅ (-1)=12.

In the third test case, choosing a_1,a_2,a_3,a_4,a_5 is a best choice: (-1)⋅ 0⋅ 0⋅ 0⋅ (-1)=0.

In the fourth test case, choosing a_1,a_2,a_3,a_4,a_6 is a best choice: (-9)⋅ (-7) ⋅ (-5)⋅ (-3)⋅ 1=945.
# @uthor : Kaleab Asfaw
from sys import stdin, stdout
# Fast IO
# from math import gcd

def input():
	a = stdin.readline()
	if a[-1] == "\n": a = a[:-1]
	return a
def print(*argv, end="\n", sep=" "):
	n = len(argv)
	for i in range(n):
		if i == n-1: stdout.write(str(argv[i]))
		else: stdout.write(str(argv[i]) + sep)
	stdout.write(end)
# Others
mod = 10**9+7
def lcm(x, y): return (x * y) / (gcd(x, y))
def fact(x, mod=mod):
	ans = 1
	for i in range(1, x+1): ans = (ans * i) % mod
	return ans
def arr2D(n, m, default=0):
	lst = []
	for i in range(n): temp = [default] * m; lst.append(temp)
	return lst
def sortDictV(x): return {k: v for k, v in sorted(x.items(), key = lambda item : item[1])}

def prod(lst):
	ans = 1
	for i in lst:
		ans *= i
	return ans

def solve(n, lst):
	lst = sorted(lst, reverse= True)
	pos, neg = [], []
	for i in lst:
		if i < 0: neg.append(i)
		else: pos.append(i)

	pos = sorted(pos, reverse=True)
	neg = sorted(neg)

	if len(pos) == 0:
		return prod(neg[-5:])
	else:
		poss = []
		for i in range(-1, min(5, len(pos))):
			rest = 5 - i-1
			if len(pos[:i+1] + neg[:rest]) == 5:
				poss.append(prod(pos[:i+1] + neg[:rest]))
		return max(poss)

for _ in range(int(input())): # Multicase
	n = int(input())
	lst = list(map(int, input().split()))
	print(solve(n, lst))