Tokitsukaze is playing a game derivated from Japanese mahjong. In this game, she has three tiles in her hand. Each tile she owns is a suited tile, which means it has a suit (manzu, pinzu or souzu) and a number (a digit ranged from 1 to 9). In this problem, we use one digit and one lowercase letter, which is the first character of the suit, to represent a suited tile. All possible suited tiles are represented as 1m, 2m, …, 9m, 1p, 2p, …, 9p, 1s, 2s, …, 9s.

In order to win the game, she must have at least one mentsu (described below) in her hand, so sometimes she should draw extra suited tiles. After drawing a tile, the number of her tiles increases by one. She can draw any tiles she wants, including those already in her hand.

Do you know the minimum number of extra suited tiles she needs to draw so that she can win?

Here are some useful definitions in this game:

  * A mentsu, also known as meld, is formed by a koutsu or a shuntsu; 
  * A koutsu, also known as triplet, is made of three identical tiles, such as [1m, 1m, 1m], however, [1m, 1p, 1s] or [1m, 4m, 7m] is NOT a koutsu; 
  * A shuntsu, also known as sequence, is made of three sequential numbered tiles in the same suit, such as [1m, 2m, 3m] and [5s, 7s, 6s], however, [9m, 1m, 2m] or [1m, 2p, 3s] is NOT a shuntsu. 



Some examples: 

  * [2m, 3p, 2s, 4m, 1s, 2s, 4s] — it contains no koutsu or shuntsu, so it includes no mentsu; 
  * [4s, 3m, 3p, 4s, 5p, 4s, 5p] — it contains a koutsu, [4s, 4s, 4s], but no shuntsu, so it includes a mentsu; 
  * [5p, 5s, 9m, 4p, 1s, 7p, 7m, 6p] — it contains no koutsu but a shuntsu, [5p, 4p, 6p] or [5p, 7p, 6p], so it includes a mentsu. 



Note that the order of tiles is unnecessary and you can assume the number of each type of suited tiles she can draw is infinite.

Input

The only line contains three strings — the tiles in Tokitsukaze's hand. For each string, the first character is a digit ranged from 1 to 9 and the second character is m, p or s.

Output

Print a single integer — the minimum number of extra suited tiles she needs to draw.

Examples

Input


1s 2s 3s


Output


0


Input


9m 9m 9m


Output


0


Input


3p 9m 2p


Output


1

Note

In the first example, Tokitsukaze already has a shuntsu.

In the second example, Tokitsukaze already has a koutsu.

In the third example, Tokitsukaze can get a shuntsu by drawing one suited tile — 1p or 4p. The resulting tiles will be [3p, 9m, 2p, 1p] or [3p, 9m, 2p, 4p].
/*
If you want to aim high, aim high
Don't let that studying and grades consume you
Just live life young
******************************
If I'm the sun, you're the moon
Because when I go up, you go down
*******************************
I'm working for the day I will surpass you
****************************************

*/ 
  
import java.util.*;
import java.awt.Point;
import java.lang.Math; 
import java.util.Arrays;
import java.util.Scanner;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.io.OutputStream;
import java.util.Comparator;
import java.math.BigInteger;
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.stream.IntStream;
import java.io.IOException;
import java.util.ArrayList;
import java.util.Collections;
import java.util.StringTokenizer;
 
public class Main {
     
	public static void main(String[] args) {
		FastScanner in=new FastScanner();
		OutputStream outputStream = System.out;
          PrintWriter out = new PrintWriter(outputStream);
        
          int a[][] = new int[26][9];
          for(int i=0;i<3;i++){
               String S = in.n();
               a[S.charAt(1)-'a'][S.charAt(0)-'1']++;
          }
          int max = 0;
          for (int c=0; c<26; c++) {
            for (int d=0; d<9; d++) {
                max = Math.max(max, a[c][d]);
            }
          }
          int minKoutsu = 3-max;
          max = 0;
           for (int c=0; c<26; c++) {
            for (int d=2; d<9; d++) {
                int count = 0;
                for (int i=-2; i<=0; i++) {
                    if (a[c][d+i] > 0) {
                        count++;
                    }
                }
                max = Math.max(max, count);
            }
        }
        int minShuntsu = 3-max;
        int answer = Math.min(minKoutsu, minShuntsu);
        System.out.println(answer);
        
          
	}
     
     private static int sumOfDigits(int number) {
        if (number <= 0) return 0;
        int sum = 0;
        while (number > 0) {
            sum += number%10;
            number /= 10;
        }
        return sum;
    }
     
     static void ruffle_sort(int[] a) {
		//shandom_ruffle
		Random r=new Random();
		int n=a.length;
		for (int i=0; i<n; i++) {
			int oi=r.nextInt(i);
			int temp=a[i];
			a[i]=a[oi];
			a[oi]=temp;
		}
		
		//sort
		Arrays.sort(a);
	}
  
	static class FastScanner {
		BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
		StringTokenizer st=new StringTokenizer("");
		String next() {
			while (!st.hasMoreTokens())
				try {
					st=new StringTokenizer(br.readLine());
				} catch (IOException e) {
					e.printStackTrace();
				}
			return st.nextToken();
		}
		
		int ni() {
			return Integer.parseInt(next());
		}
		void print(int a){
		     System.out.println(a);
		}
		String n(){
		     return next();
		}
		void ps(String a) {
		        System.out.print(a);
		}
		void pls(String a) {
		        System.out.println(a);
		}
		int[] ria(int n) {
			int[] a=new int[n];
			for (int i=0; i<n; i++) a[i]=ni();
			return a;
		}
		char[] rca(int n, String S){
		     char a[] = S. toCharArray();
		     return a;
		}
		int [][] rda(int n, int m){
		    int a[][] = new int[n][m];
		    for(int i=0;i<n;i++){
		        for(int j=0;j<m;j++){
		            a[i][j]=ni();
		        }
		    }
		    return a;
		}
		void pa(int [] a) {
			for (int i=0; i<a.length; i++)
		        System.out.print(a[i]+" ");
		}
	
		
	     void pla(int [] a) {
			for (int i=0; i<a.length; i++)
		        System.out.println(a[i]);
		}
		
		long nl() {
			return Long.parseLong(next());
		}
	}
 
	
    static int max(){
         return Integer.MAX_VALUE;
    }
    	
 
    public int factorial(int n) {
            int fact = 1;
            int i = 1;
           while(i <= n) {
             fact *= i;
             i++;
           }
            return fact;
    }
    
    

    public static long gcd(long x,long y)
    {
    	if(x%y==0)
    		return y;
    	else
    		return gcd(y,x%y);
    }
    public static int gcd(int x,int y)
    {
    	if(x%y==0)
    		return y;
    	else 
    		return gcd(y,x%y);
    }
    public static int abs(int a,int b)
    {
    	return (int)Math.abs(a-b);
    }
    public static long abs(long a,long b)
    {
    	return (long)Math.abs(a-b);
    }
    public static int max(int a,int b)
    {
    	if(a>b)
    		return a;
    	else
    		return b;
    }
    public static int min(int a,int b)
    {
    	if(a>b)
    		return b;
    	else 
    		return a;
    }
    public static long max(long a,long b)
    {
    	if(a>b)
    		return a;
    	else
    		return b;
    }
    public static long min(long a,long b)
    {
    	if(a>b)
    		return b;
    	else 
    		return a;
    }
     
     
    public static long pow(long n,long p,long m)
    {
    	 long  result = 1;
    	  if(p==0)
    	    return 1;
    	if (p==1)
    	    return n;
    	while(p!=0)
    	{
    	    if(p%2==1)
    	        result *= n;
    	    if(result>=m)
    	    result%=m;
    	    p >>=1;
    	    n*=n;
    	    if(n>=m)
    	    n%=m;
    	}
    	return result;
    }
    public static long pow(long n,long p)
    {
    	long  result = 1;
    	  if(p==0)
    	    return 1;
    	if (p==1)
    	    return n;
    	while(p!=0)
    	{
    	    if(p%2==1)
    	        result *= n;	    
    	    p >>=1;
    	    n*=n;	    
    	}
    	return result;
     
    }
     
    static long sort(int a[]){  
         int n=a.length;
    	int b[]=new int[n];	
    	return mergeSort(a,b,0,n-1);
         
    }
     
    static long mergeSort(int a[],int b[],long left,long right){
         long c=0;
         if(left<right){   
          long mid=left+(right-left)/2;
    	 c= mergeSort(a,b,left,mid);
    	 c+=mergeSort(a,b,mid+1,right);
    	 c+=merge(a,b,left,mid+1,right); 
         }	
    	return c;	 
    }
    static long merge(int a[],int  b[],long left,long mid,long right){
         long c=0;int i=(int)left;int j=(int)mid; int k=(int)left;
         while(i<=(int)mid-1&&j<=(int)right){ 
              if(a[i]<=a[j]){
                   b[k++]=a[i++]; 
              }
              else{ 
                   b[k++]=a[j++];c+=mid-i;
              }
         }
         
         while (i <= (int)mid - 1)   
                 b[k++] = a[i++]; 
         while (j <= (int)right)
                 b[k++] = a[j++];
         for (i=(int)left; i <= (int)right; i++) 
    	        a[i] = b[i];
    	        return c; 
         }
         
      static class InputReader extends BufferedReader {
        public InputReader(InputStream st) {
            super(new InputStreamReader(st));
        }
 
        public String readLine() {
            try {
                return super.readLine();
            } catch (IOException e) {
                return null;
            }
        }
 
        private int readByte() {
            try {
                return read();
            } catch (IOException e) {
                throw new RuntimeException();
            }
        }
 
        public int ni() {
            int num = 0, b;
            boolean minus = false;
            while ((b = readByte()) != -1 && !((b >= '0' && b <= '9') || b == '-')) ;
            if (b == '-') {
                minus = true;
                b = readByte();
            }
 
            while (true) {
                if (b >= '0' && b <= '9') {
                    num = num * 10 + (b - '0');
                } else {
                    return minus ? -num : num;
                }
                b = readByte();
            }
        }
 
      
 
    } 
     
  } 