There is a country with n citizens. The i-th of them initially has a_{i} money. The government strictly controls the wealth of its citizens. Whenever a citizen makes a purchase or earns some money, they must send a receipt to the social services mentioning the amount of money they currently have.

Sometimes the government makes payouts to the poor: all citizens who have strictly less money than x are paid accordingly so that after the payout they have exactly x money. In this case the citizens don't send a receipt.

You know the initial wealth of every citizen and the log of all events: receipts and payouts. Restore the amount of money each citizen has after all events.

Input

The first line contains a single integer n (1 ≤ n ≤ 2 ⋅ 10^{5}) — the numer of citizens.

The next line contains n integers a_1, a_2, ..., a_n (0 ≤ a_{i} ≤ 10^{9}) — the initial balances of citizens.

The next line contains a single integer q (1 ≤ q ≤ 2 ⋅ 10^{5}) — the number of events.

Each of the next q lines contains a single event. The events are given in chronological order.

Each event is described as either 1 p x (1 ≤ p ≤ n, 0 ≤ x ≤ 10^{9}), or 2 x (0 ≤ x ≤ 10^{9}). In the first case we have a receipt that the balance of the p-th person becomes equal to x. In the second case we have a payoff with parameter x.

Output

Print n integers — the balances of all citizens after all events.

Examples

Input


4
1 2 3 4
3
2 3
1 2 2
2 1


Output


3 2 3 4 


Input


5
3 50 2 1 10
3
1 2 0
2 8
1 3 20


Output


8 8 20 8 10 

Note

In the first example the balances change as follows: 1 2 3 4 → 3 3 3 4 → 3 2 3 4 → 3 2 3 4

In the second example the balances change as follows: 3 50 2 1 10 → 3 0 2 1 10 → 8 8 8 8 10 → 8 8 20 8 10
n = int(input().strip())
a = list(map(int, input().split()))
q = int(input().strip())
queries = []
last_balance = [-1]*n
last_balance_id = [-1]*n

for i in range(q):
    query = list(map(int, input().split()))
    queries.append(query)
    if query[0]==1:
        p = query[1]-1
        last_balance[p] = query[2]
        last_balance_id[p] = i


#print(last_balance)
#print(last_balance_id)

max_pay = [0]*(q+1)
for i in range(q-1,-1,-1):
    query = queries[i]
    if query[0]==2:
        max_pay[i]=max(query[1], max_pay[i+1])
    else:
        max_pay[i]=max_pay[i+1]

#print(max_pay)

for p in range(n):
    #print("person: ",p)
    if last_balance_id[p]>=0:
        id = last_balance_id[p]
        pay = max_pay[id]
        #print(id, pay)
        a[p] = max(pay, last_balance[p])
    else:
        a[p] = max(a[p], max_pay[0])

print(" ".join([str(x) for x in a]))