You are given an integer N. Among the divisors of N! (= 1 \times 2 \times ... \times N), how many Shichi-Go numbers (literally "Seven-Five numbers") are there?

Here, a Shichi-Go number is a positive integer that has exactly 75 divisors.

Constraints

* 1 \leq N \leq 100
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of the Shichi-Go numbers that are divisors of N!.

Examples

Input

9


Output

0


Input

10


Output

1


Input

100


Output

543
import math
n=int(input())
p=[0]*101
dp=[0]*101
for i in range(2,n+1):
  for j in range(2,i+1):
    while i%j==0:
      i//=j
      p[j]+=1
for i in range(101):
  if p[i]!=0:
    dp[p[i]]+=1
ans=sum(dp[74:])+sum(dp[24:])*(sum(dp[2:])-1)+sum(dp[14:])*(sum(dp[4:])-1)+sum(dp[4:])*(sum(dp[4:])-1)//2*(sum(dp[2:])-2)
print(ans)