You are given two strings s and t, both consisting only of lowercase Latin letters.

The substring s[l..r] is the string which is obtained by taking characters s_l, s_{l + 1}, ..., s_r without changing the order.

Each of the occurrences of string a in a string b is a position i (1 ≤ i ≤ |b| - |a| + 1) such that b[i..i + |a| - 1] = a (|a| is the length of string a).

You are asked q queries: for the i-th query you are required to calculate the number of occurrences of string t in a substring s[l_i..r_i].

Input

The first line contains three integer numbers n, m and q (1 ≤ n, m ≤ 10^3, 1 ≤ q ≤ 10^5) — the length of string s, the length of string t and the number of queries, respectively.

The second line is a string s (|s| = n), consisting only of lowercase Latin letters.

The third line is a string t (|t| = m), consisting only of lowercase Latin letters.

Each of the next q lines contains two integer numbers l_i and r_i (1 ≤ l_i ≤ r_i ≤ n) — the arguments for the i-th query.

Output

Print q lines — the i-th line should contain the answer to the i-th query, that is the number of occurrences of string t in a substring s[l_i..r_i].

Examples

Input

10 3 4
codeforces
for
1 3
3 10
5 6
5 7


Output

0
1
0
1


Input

15 2 3
abacabadabacaba
ba
1 15
3 4
2 14


Output

4
0
3


Input

3 5 2
aaa
baaab
1 3
1 1


Output

0
0

Note

In the first example the queries are substrings: "cod", "deforces", "fo" and "for", respectively.
import java.util.*;
import java.io.*;
import java.text.*;
/**
 *
 * @author alanl
 */
public class Main{
    static BufferedReader input = new BufferedReader(new InputStreamReader(System.in));
    static StringTokenizer st;
    static PrintWriter pr = new PrintWriter(new BufferedWriter(new OutputStreamWriter(System.out)));
    public static void main(String[] args) throws IOException{
        int n = readInt(), m = readInt(), q = readInt();
        ArrayList<Integer>arr = new ArrayList();
        String s = readLine(), t = readLine();
        StringBuilder sb = new StringBuilder();
        if(m>n){
            for(int i = 0; i<q; i++){
                System.out.println(0);
            }
            return;
        }
        for(int i = 0; i<=n; i++){
            if(sb.length()==m){
                if(sb.toString().equals(t)){
                    arr.add(i);
                }
                if(i==n)break;
                sb.deleteCharAt(0);
                sb.append(s.charAt(i));
            }
            else sb.append(s.charAt(i));
        }
        for(int i = 0; i<q; i++){
            int a = readInt(), b = readInt(), ans = 0;
            for(int j = 0; j<arr.size(); j++){
                if(b>=arr.get(j) && a<=arr.get(j)-m+1)ans++;
            }
            System.out.println(ans);
        }
    }
    static String next () throws IOException {
        while (st == null || !st.hasMoreTokens())
                st = new StringTokenizer(input.readLine().trim());
        return st.nextToken();
    }
    static long readLong () throws IOException {
        return Long.parseLong(next());
    }
    static int readInt () throws IOException {
        return Integer.parseInt(next());
    }
    static double readDouble () throws IOException {
        return Double.parseDouble(next());
    }
    static char readChar () throws IOException {
        return next().charAt(0);
    }
    static String readLine () throws IOException {
        return input.readLine().trim();
    }
    /* stuff you should look for
	* int overflow, array bounds
	* special cases (n=1?)
	* do smth instead of nothing and stay organized
	* WRITE STUFF DOWN
	* DON'T GET STUCK ON ONE APPROACH
    // Did you read the bounds?
    // Did you make typos?
    // Are there edge cases (N=1?)
    // Are array sizes proper (scaled by proper constant, for example 2* for koosaga tree)
    // Integer overflow?
    // DS reset properly between test cases?
    // Is using long longs causing TLE?
    // Are you using floating points?
    */
}
