Find the edit distance between given two words s1 and s2.

The disntace is the minimum number of single-character edits required to change one word into the other. The edits including the following operations:

* insertion: Insert a character at a particular position.
* deletion: Delete a character at a particular position.
* substitution: Change the character at a particular position to a different character

Constraints

* 1 ≤ length of s1 ≤ 1000
* 1 ≤ length of s2 ≤ 1000

Input


s1
s2


Two words s1 and s2 are given in the first line and the second line respectively. The words will consist of lower case characters.

Output

Print the edit distance in a line.

Examples

Input

acac
acm


Output

2


Input

icpc
icpc


Output

0
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.StringTokenizer;

public class Main {

    static BufferedReader in;
    static PrintWriter out;
    static StringTokenizer tok;

    void solve() throws IOException {
        String s1 = ns();
        String s2 = ns();

        int n1 = s1.length();
        int n2 = s2.length();

        int[][] dp = new int[n1 + 1][n2 + 1];

        for (int i = 1; i <= n1; i++) {
            dp[i][0] = i;
        }
        for (int i = 1; i <= n2; i++) {
            dp[0][i] = i;
        }

        for (int i = 1; i <= n1; i++) {
            for (int j = 1; j <= n2; j++) {
                dp[i][j] = Math.min(dp[i - 1][j] + 1, dp[i][j - 1] + 1);
                dp[i][j] = Math.min(dp[i][j], dp[i - 1][j - 1] + (s1.charAt(i - 1) == s2.charAt(j - 1) ? 0 : 1));
            }
        }

        out.println(dp[n1][n2]);
    }

    String ns() throws IOException {
        while (!tok.hasMoreTokens()) {
            tok = new StringTokenizer(in.readLine(), " ");
        }
        return tok.nextToken();
    }

    int ni() throws IOException {
        return Integer.parseInt(ns());
    }

    long nl() throws IOException {
        return Long.parseLong(ns());
    }

    double nd() throws IOException {
        return Double.parseDouble(ns());
    }

    String[] nsa(int n) throws IOException {
        String[] res = new String[n];
        for (int i = 0; i < n; i++) {
            res[i] = ns();
        }
        return res;
    }

    int[] nia(int n) throws IOException {
        int[] res = new int[n];
        for (int i = 0; i < n; i++) {
            res[i] = ni();
        }
        return res;
    }

    long[] nla(int n) throws IOException {
        long[] res = new long[n];
        for (int i = 0; i < n; i++) {
            res[i] = nl();
        }
        return res;
    }

    public static void main(String[] args) throws IOException {
        in = new BufferedReader(new InputStreamReader(System.in));
        out = new PrintWriter(System.out);
        tok = new StringTokenizer("");
        Main main = new Main();
        main.solve();
        out.close();
    }
}