You are given an integer N. Among the divisors of N! (= 1 \times 2 \times ... \times N), how many Shichi-Go numbers (literally "Seven-Five numbers") are there?

Here, a Shichi-Go number is a positive integer that has exactly 75 divisors.

Constraints

* 1 \leq N \leq 100
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of the Shichi-Go numbers that are divisors of N!.

Examples

Input

9


Output

0


Input

10


Output

1


Input

100


Output

543
n=int(input())
e=[0 for i in range(n+1)]
for i in range(2,n+1):
  for j in range(2,i+1):
    if i==1:
      break
    while i%j==0:
      i//=j
      e[j]+=1

def num(k):
  ret=0
  for i in range(n):
    if e[i]>=k-1:
      ret += 1
  return ret
print(num(75) + num(25) * (num(3) - 1) + num(15) * (num(5) - 1) + num(5) * (num(5) - 1) * (num(3) - 2) // 2)