You are given an integer N. Among the divisors of N! (= 1 \times 2 \times ... \times N), how many Shichi-Go numbers (literally "Seven-Five numbers") are there?

Here, a Shichi-Go number is a positive integer that has exactly 75 divisors.

Constraints

* 1 \leq N \leq 100
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of the Shichi-Go numbers that are divisors of N!.

Examples

Input

9


Output

0


Input

10


Output

1


Input

100


Output

543
def count(m):
    return len(list(filter(lambda x: x >= m-1, e)))


N = int(input())
# N!の素因数分解を行う
e = [0] * (N+1)  # 0~Nを何個ずつ素因数としてもつかのテーブル

for i in range(2, N+1):
    cur = i
    for j in range(2, i+1):
        while cur % j == 0:
            e[j] += 1
            cur //= j

ans = 0
ans += count(75)
ans += count(25) * (count(3) - 1)
ans += count(15) * (count(5) - 1)
ans += (count(5) * (count(5)-1) * (count(3) - 2)) // 2
print(ans)
