JATC loves Banh-mi (a Vietnamese food). His affection for Banh-mi is so much that he always has it for breakfast. This morning, as usual, he buys a Banh-mi and decides to enjoy it in a special way.

First, he splits the Banh-mi into n parts, places them on a row and numbers them from 1 through n. For each part i, he defines the deliciousness of the part as x_i ∈ \{0, 1\}. JATC's going to eat those parts one by one. At each step, he chooses arbitrary remaining part and eats it. Suppose that part is the i-th part then his enjoyment of the Banh-mi will increase by x_i and the deliciousness of all the remaining parts will also increase by x_i. The initial enjoyment of JATC is equal to 0.

For example, suppose the deliciousness of 3 parts are [0, 1, 0]. If JATC eats the second part then his enjoyment will become 1 and the deliciousness of remaining parts will become [1, \\_, 1]. Next, if he eats the first part then his enjoyment will become 2 and the remaining parts will become [\\_, \\_, 2]. After eating the last part, JATC's enjoyment will become 4.

However, JATC doesn't want to eat all the parts but to save some for later. He gives you q queries, each of them consisting of two integers l_i and r_i. For each query, you have to let him know what is the maximum enjoyment he can get if he eats all the parts with indices in the range [l_i, r_i] in some order.

All the queries are independent of each other. Since the answer to the query could be very large, print it modulo 10^9+7.

Input

The first line contains two integers n and q (1 ≤ n, q ≤ 100 000).

The second line contains a string of n characters, each character is either '0' or '1'. The i-th character defines the deliciousness of the i-th part.

Each of the following q lines contains two integers l_i and r_i (1 ≤ l_i ≤ r_i ≤ n) — the segment of the corresponding query.

Output

Print q lines, where i-th of them contains a single integer — the answer to the i-th query modulo 10^9 + 7.

Examples

Input

4 2
1011
1 4
3 4


Output

14
3


Input

3 2
111
1 2
3 3


Output

3
1

Note

In the first example: 

  * For query 1: One of the best ways for JATC to eats those parts is in this order: 1, 4, 3, 2. 
  * For query 2: Both 3, 4 and 4, 3 ordering give the same answer. 



In the second example, any order of eating parts leads to the same answer.


import org.omg.PortableInterceptor.SYSTEM_EXCEPTION;

import java.io.*;
import java.math.*;
import java.util.*;


// author @mdazmat9
public class CodeForces_C {
    public static void main(String[] args) throws IOException {
        Scanner sc = new Scanner(System.in);
        int n=sc.nextInt();
        int q=sc.nextInt();
        String s=sc.next();
        int one=0;
        List<Integer> list=new ArrayList<>();
        list.add(0);
        for(int i=0;i<n;i++){
           if( s.charAt(i)=='1')
               one++;
           list.add(one);
        }
        for(int ind=0;ind<q;ind++) {
            int l=sc.nextInt();
            int r=sc.nextInt();
            int o=list.get(r)-list.get(l-1);
            int z=r-l+1-o;
            long ans=(pow(2,z,m)*(pow(2,o,m)-1))%m;
            System.out.println(ans);
            
        }
    }
    static long m=(long) (Math.pow(10,9)+7);
    static long pow(long  x, long  y, long  p){
        long res = 1;
        x = x % p;
        while (y > 0)
        {
            if ((y & 1)==1)
                res = (res*x) % p;
            y = y>>1;
            x = (x*x) % p;
        }
        return res;
    }


    static long gcd(long a , long b)
    {
        if(b == 0)
            return a;
        return gcd(b , a % b);
    }

}
class Scanner {
    public BufferedReader reader;
    public StringTokenizer st;

    public Scanner(InputStream stream) {
        reader = new BufferedReader(new InputStreamReader(stream));
        st = null;
    }

    public String next() {
        while (st == null || !st.hasMoreTokens()) {
            try {
                String line = reader.readLine();
                if (line == null) return null;
                st = new StringTokenizer(line);
            } catch (Exception e) {
                throw (new RuntimeException());
            }
        }
        return st.nextToken();
    }

    public int nextInt() {
        return Integer.parseInt(next());
    }

    public long nextLong() {
        return Long.parseLong(next());
    }

    public double nextDouble() {
        return Double.parseDouble(next());
    }
}

class OutputWriter {
    BufferedWriter writer;

    public OutputWriter(OutputStream stream) {
        writer = new BufferedWriter(new OutputStreamWriter(stream));
    }

    public void print(int i) throws IOException {
        writer.write(i);
    }

    public void print(String s) throws IOException {
        writer.write(s);
    }

    public void print(char[] c) throws IOException {
        writer.write(c);
    }

    public void close() throws IOException {
        writer.close();
    }

}