You are given one integer number n. Find three distinct integers a, b, c such that 2 ≤ a, b, c and a ⋅ b ⋅ c = n or say that it is impossible to do it.

If there are several answers, you can print any.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of test cases.

The next n lines describe test cases. The i-th test case is given on a new line as one integer n (2 ≤ n ≤ 10^9).

Output

For each test case, print the answer on it. Print "NO" if it is impossible to represent n as a ⋅ b ⋅ c for some distinct integers a, b, c such that 2 ≤ a, b, c.

Otherwise, print "YES" and any possible such representation.

Example

Input


5
64
32
97
2
12345


Output


YES
2 4 8 
NO
NO
NO
YES
3 5 823 
def STR(): return list(input())
def INT(): return int(input())
def MAP(): return map(int, input().split())
def MAP2():return map(float,input().split())
def LIST(): return list(map(int, input().split()))
def STRING(): return input()
import string
import sys
from heapq import heappop , heappush
from bisect import *
from collections import deque , Counter , defaultdict
from math import *
from itertools import permutations , accumulate
dx = [-1 , 1 , 0 , 0  ]
dy = [0 , 0  , 1  , - 1]
            
    
for tt in range(INT()):
    n = INT()
    x = []
    c = 0
    for i in range(2 , int(sqrt(n)) + 1):
        if n % i == 0 :
            x.append(i)
            n//= i
            c += 1
            if c == 2 :
                break
 
    #print(n)
    if len(x) < 2 :
        print('NO')
    else:
        if x[0] != n and x[1] != n :
            x.append(n)
 
        if len(x) == 3 :
            print('YES')
            print(*x)
        else:
            print('NO')