You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible.

Input

Each test contains one or more test cases. The first line contains the number of test cases t (1 ≤ t ≤ 100).

The first line of each test case consists of one integer n — the number of elements in the sequence b (1 ≤ n ≤ 100).

The second line of each test case consists of n different integers b_1, …, b_n — elements of the sequence b (1 ≤ b_i ≤ 2n).

It is guaranteed that the sum of n by all test cases doesn't exceed 100.

Output

For each test case, if there is no appropriate permutation, print one number -1.

Otherwise, print 2n integers a_1, …, a_{2n} — required lexicographically minimal permutation of numbers from 1 to 2n.

Example

Input


5
1
1
2
4 1
3
4 1 3
4
2 3 4 5
5
1 5 7 2 8


Output


1 2 
-1
4 5 1 2 3 6 
-1
1 3 5 6 7 9 2 4 8 10 
test=int(input())
for i in range(test):
	n = int(input())
	b = list(map(int, input().split()))
	a = [0 for i in range(n+n)]
	l = [0 for i in range(n+n+1)]
	for i in range(n):
		a[2*i] = b[i]
		l[b[i]] = 1
	ans = 1
	for i in range(n):
		bool = 0
		for j in range(b[i]+1, n+n+1):
			if l[j] == 1:
				continue
			a[2*i+1] = j
			l[j] = 1
			bool = 1;
			break
		if bool == 0:
			ans = 0
			break
	if ans == 0:
		print(-1)
	else:
		for i in range(n+n):
			print(a[i], end = ' ')
		print()