We have N cards numbered 1, 2, ..., N. Card i (1 \leq i \leq N) has an integer A_i written in red ink on one side and an integer B_i written in blue ink on the other side. Initially, these cards are arranged from left to right in the order from Card 1 to Card N, with the red numbers facing up.

Determine whether it is possible to have a non-decreasing sequence facing up from left to right (that is, for each i (1 \leq i \leq N - 1), the integer facing up on the (i+1)-th card from the left is not less than the integer facing up on the i-th card from the left) by repeating the operation below. If the answer is yes, find the minimum number of operations required to achieve it.

* Choose an integer i (1 \leq i \leq N - 1). Swap the i-th and (i+1)-th cards from the left, then flip these two cards.

Constraints

* 1 \leq N \leq 18
* 1 \leq A_i, B_i \leq 50 (1 \leq i \leq N)
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N
A_1 A_2 ... A_N
B_1 B_2 ... B_N


Output

If it is impossible to have a non-decreasing sequence, print `-1`. If it is possible, print the minimum number of operations required to achieve it.

Examples

Input

3
3 4 3
3 2 3


Output

1


Input

2
2 1
1 2


Output

-1


Input

4
1 2 3 4
5 6 7 8


Output

0


Input

5
28 15 22 43 31
20 22 43 33 32


Output

-1


Input

5
4 46 6 38 43
33 15 18 27 37


Output

3
n=int(input())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
ab=lambda i,j:a[i] if abs(i-j)%2==0 else b[i]
inf=10**9
dp=[n*[inf]for _ in range(1<<n)]
dp[0][0]=0
for i in range(n):dp[1<<i][i]=i
for bit in range(1,1<<n):
  m=[0]*n
  ii=0
  for i in range(n):
    if bit&1<<i:
      m[i]=ii
      ii+=1
  bit_count=ii
  for i in range(n):
    if bit&1<<i==0:
      m[i]=ii
      ii+=1
  for i in range(n):
    if bit&1<<i:continue
    ci=ab(i,bit_count)
    for j in range(n):
      if bit&1<<j==0:continue
      cj=ab(j,bit_count-1)
      if cj>ci:continue
      dp[bit|(1<<i)][i]=min(dp[bit|(1<<i)][i],dp[bit][j]+m[i]-bit_count)
ans=inf
for i in range(n):ans=min(ans,dp[-1][i])
if ans==inf:ans=-1
print(ans)