Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.

A little later they found a string s, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the temple and read the string aloud. However, nothing happened. Then Asterix supposed that a password is some substring t of the string s.

Prefix supposed that the substring t is the beginning of the string s; Suffix supposed that the substring t should be the end of the string s; and Obelix supposed that t should be located somewhere inside the string s, that is, t is neither its beginning, nor its end.

Asterix chose the substring t so as to please all his companions. Besides, from all acceptable variants Asterix chose the longest one (as Asterix loves long strings). When Asterix read the substring t aloud, the temple doors opened. 

You know the string s. Find the substring t or determine that such substring does not exist and all that's been written above is just a nice legend.

Input

You are given the string s whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters.

Output

Print the string t. If a suitable t string does not exist, then print "Just a legend" without the quotes.

Examples

Input

fixprefixsuffix


Output

fix

Input

abcdabc


Output

Just a legend
from sys import stdin
from collections import deque
from math import sqrt, floor, ceil, log, log2, log10, pi, gcd, sin, cos, asin
def ii(): return int(stdin.readline())
def fi(): return float(stdin.readline())
def mi(): return map(int, stdin.readline().split())
def fmi(): return map(float, stdin.readline().split())
def li(): return list(mi())
def lsi():
    x=list(stdin.readline())
    x.pop()
    return x
def si(): return stdin.readline()
res=['YES', 'NO']
############# CODE STARTS HERE #############
a=lsi()
l=len(a)
kmp=[-1]*l
j=-1
#print(a)
for i in range(1, l):
    while j>=0 and a[i]!=a[j+1]:
        j=kmp[j]
    if a[i]==a[j+1]:
        j+=1
    kmp[i]=j
m=kmp[-1]
if kmp.count(m)==1:
    m=kmp[m]
#print(kmp, m)
if m<0:
    print('Just a legend')
else:
    print(*a[:m+1], sep='')
	 				 	 	 		 		 	 	 	    	