You are given an integer N. Among the divisors of N! (= 1 \times 2 \times ... \times N), how many Shichi-Go numbers (literally "Seven-Five numbers") are there?

Here, a Shichi-Go number is a positive integer that has exactly 75 divisors.

Constraints

* 1 \leq N \leq 100
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of the Shichi-Go numbers that are divisors of N!.

Examples

Input

9


Output

0


Input

10


Output

1


Input

100


Output

543
n = int(input())
l = [0]*101
i = 2
for i in range(2,n+1):
    j = 2
    while i >= 2:
        while i % j == 0:
            i = i//j
            l[j] += 1
        j += 1

ans = sum(x >= 74 for x in l)

a = sum(x >= 2 for x in l)
b = sum(x >= 24 for x in l)
ans += b*(a-1)

a = sum(x >= 4 for x in l)
b = sum(x >= 14 for x in l)
ans += b*(a-1)

a = sum(x >= 2 for x in l)
b = sum(x >= 4 for x in l)
ans += b*(b-1)*(a-2)//2

print(ans)