We have a rectangular parallelepiped of size A×B×C, built with blocks of size 1×1×1. Snuke will paint each of the A×B×C blocks either red or blue, so that:

* There is at least one red block and at least one blue block.
* The union of all red blocks forms a rectangular parallelepiped.
* The union of all blue blocks forms a rectangular parallelepiped.



Snuke wants to minimize the difference between the number of red blocks and the number of blue blocks. Find the minimum possible difference.

Constraints

* 2≤A,B,C≤10^9

Input

The input is given from Standard Input in the following format:


A B C


Output

Print the minimum possible difference between the number of red blocks and the number of blue blocks.

Examples

Input

3 3 3


Output

9


Input

2 2 4


Output

0


Input

5 3 5


Output

15
import java.util.*;

public class Main {

	public static void main(String[] args) {
		// TODO Auto-generated method stub
		Scanner sc = new Scanner(System.in);
		long[] a = new long[3];
		a[0] = sc.nextLong();
		a[1] = sc.nextLong();
		a[2] = sc.nextLong();
		Arrays.sort(a);
		long b = a[2]/2;
		long c = a[2]-b;
		System.out.println(Math.abs(a[0]*a[1]*b-a[0]*a[1]*c));
	}
	
	// print
	static void print(String s) {
		System.out.println(s);
	}
	
	// union find lib
	// usage:
	// 最初にinitを呼ぶ
	// root: 直接は呼ばないで
	// unite: まとめる
	// same: グループ判定
	static void init(int par[], int N) {
		for(int i=0; i<N; i++) {
			par[i] = i;
		}
	}
	
	static int root(int x, int [] par) {
		if(par[x] == x) {
			return x;
		} else {
			return (par[x] = root(par[x], par));
		}
	}
	
	static boolean same(int x, int y, int[] par) {
		return root(x, par) == root(y, par);
	}
	
	static void unite(int x, int y, int[] par) {
		x = root(x, par);
		y = root(y, par);
		if(x == y) return;
		par[x] = y;
	}
	
	// end union find lib
	
	// number lib
	
	static long lcm(long a, long b) {
		return a*(b/gcd(a, b));
	}
	
	static long gcd(long a, long b) {
		long ta = Math.max(a, b);
		long tb = Math.min(a, b);
		long tmp;
		while((tmp = ta%tb) != 0) {
			ta = tb;
			tb = tmp;
		}
		return tb;
	}
	
	static long modcomb(long n, long k, long mod) {
		if(k==1) {
			return n;
		}
		
		long ans = 1;
		for(long i=n; i>=n-k+1; i--) {
			ans = (ans * i)%mod;
		}
		for(long i=k; 0<i; i--) {
			ans = (ans * modpow(i, mod-2, mod)) % mod;
		}
		return ans;
	}
	
	static long modpow(long a, long b, long mod) {
		if(b==0) return 1;
		if(b%2==0) {
			long d = modpow(a, b/2, mod);
			return (d*d)%mod;
		} else {
			return (a*modpow(a, b-1, mod))%mod;
		}
	}
	
	static int disit(long a, long d) {
		int count = 0;
		while(a!=0) {
			a = a/d;
			count++;
		}
		return count;
	}
	
	// end number lib
}