You are given an integer N. Among the divisors of N! (= 1 \times 2 \times ... \times N), how many Shichi-Go numbers (literally "Seven-Five numbers") are there?

Here, a Shichi-Go number is a positive integer that has exactly 75 divisors.

Constraints

* 1 \leq N \leq 100
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of the Shichi-Go numbers that are divisors of N!.

Examples

Input

9


Output

0


Input

10


Output

1


Input

100


Output

543
import math
from collections import defaultdict

N=input()

C=defaultdict(lambda: 0)

#L=(2,3,5,7)
L=range(2,101)


for i in range(N,0,-1):
	for l in L:
		while i%l==0:
			i/=l
			C[l]+=1

D=defaultdict(lambda: 0)

for x,y in C.items():
	if y>=4:	D[4]+=1
	if y>=2:	D[2]+=1
	if y>=24:D[24]+=1
	if y>=14:D[14]+=1
	if y>=74:D[74]+=1

ans=0

ans+=D[4]*(D[4]-1)/2*(D[2]-2)
ans+=D[24]*(D[2]-1)
ans+=D[14]*(D[4]-1)
ans+=D[74]
print ans
