You are given an integer N. Among the divisors of N! (= 1 \times 2 \times ... \times N), how many Shichi-Go numbers (literally "Seven-Five numbers") are there?

Here, a Shichi-Go number is a positive integer that has exactly 75 divisors.

Constraints

* 1 \leq N \leq 100
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of the Shichi-Go numbers that are divisors of N!.

Examples

Input

9


Output

0


Input

10


Output

1


Input

100


Output

543
n = int(input())
from collections import Counter
c = Counter()
for i in range(1,n+1):
    for j in range(2, i+1):
        while i % j == 0:
            c[j] += 1
            i //= j

def num(a):
    ret = 0
    for key, value in c.items():
        if value >= a:
            ret += 1
    return ret

ans = num(74) + num(24) * (num(2)-1) + num(14)*(num(4)-1) + num(4)*(num(4)-1)//2*(num(2) - 2)
print(ans)