You are given an integer N. Among the divisors of N! (= 1 \times 2 \times ... \times N), how many Shichi-Go numbers (literally "Seven-Five numbers") are there?

Here, a Shichi-Go number is a positive integer that has exactly 75 divisors.

Constraints

* 1 \leq N \leq 100
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of the Shichi-Go numbers that are divisors of N!.

Examples

Input

9


Output

0


Input

10


Output

1


Input

100


Output

543
def num(m):
    return len(tuple(filter(lambda x: x >= m - 1, e)))


N = int(input())
e = [0 for _ in range(N + 1)]

for i in range(2, N + 1):
    for j in range(2, i + 1):
        while i % j == 0:
            i //= j
            e[j] += 1

ans = 0
ans += num(75)
ans += num(25) * (num(3) - 1)
ans += num(15) * (num(5) - 1)
ans += num(5) * (num(5) - 1) * (num(3) - 2) // 2
print(ans)
