Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.

A little later they found a string s, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the temple and read the string aloud. However, nothing happened. Then Asterix supposed that a password is some substring t of the string s.

Prefix supposed that the substring t is the beginning of the string s; Suffix supposed that the substring t should be the end of the string s; and Obelix supposed that t should be located somewhere inside the string s, that is, t is neither its beginning, nor its end.

Asterix chose the substring t so as to please all his companions. Besides, from all acceptable variants Asterix chose the longest one (as Asterix loves long strings). When Asterix read the substring t aloud, the temple doors opened. 

You know the string s. Find the substring t or determine that such substring does not exist and all that's been written above is just a nice legend.

Input

You are given the string s whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters.

Output

Print the string t. If a suitable t string does not exist, then print "Just a legend" without the quotes.

Examples

Input

fixprefixsuffix


Output

fix

Input

abcdabc


Output

Just a legend
from collections import Counter
import sys
def alele(): return list(map(int, sys.stdin.readline().strip().split()))
def ilele(): return map(int, sys.stdin.readline().strip().split())
def input(): return sys.stdin.readline().strip()
def computeLPSArray(pat, M, lps): 
    len = 0
    lps[0] 
    i = 1
    while i < M: 
        if pat[i]== pat[len]: 
            len += 1
            lps[i] = len
            i += 1
        else: 
            if len != 0: 
                len = lps[len-1] 
            else: 
                lps[i] = 0
                i += 1
text=input();n=len(text);lps=[0]*n;computeLPSArray(text,n,lps)#;print(lps)
t=lps[-1]
if lps.count(t)<2:
    t=lps[t-1]
print(text[:t] if t>0 else 'Just a legend')

