You are given an integer N. Among the divisors of N! (= 1 \times 2 \times ... \times N), how many Shichi-Go numbers (literally "Seven-Five numbers") are there?

Here, a Shichi-Go number is a positive integer that has exactly 75 divisors.

Constraints

* 1 \leq N \leq 100
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of the Shichi-Go numbers that are divisors of N!.

Examples

Input

9


Output

0


Input

10


Output

1


Input

100


Output

543
n=int(input());c=[1]*101
for i in range(2,n+1):
    for j in range(2,n+1):
        while i%j==0:i/=j;c[j]+=1
def N(M):return len([0 for x in c if x>=M])
print(N(75)+N(25)*~-N(3)+N(15)*~-N(5)+N(5)*~-N(5)//2*~-~-N(3))