You are given an integer N. Among the divisors of N! (= 1 \times 2 \times ... \times N), how many Shichi-Go numbers (literally "Seven-Five numbers") are there?

Here, a Shichi-Go number is a positive integer that has exactly 75 divisors.

Constraints

* 1 \leq N \leq 100
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of the Shichi-Go numbers that are divisors of N!.

Examples

Input

9


Output

0


Input

10


Output

1


Input

100


Output

543
c=[0]*101
for i in range(1,int(input())+1):
    for j in range(2,i+1):
        while i%j==0:
            c[j]+=1
            i//=j
def f(n):
    return sum(i>n-2 for i in c)
print(f(75)+f(25)*(f(3)-1)+f(15)*(f(5)-1)+f(5)*(f(5)-1)*(f(3)-2)//2)