You are given an integer N. Among the divisors of N! (= 1 \times 2 \times ... \times N), how many Shichi-Go numbers (literally "Seven-Five numbers") are there?

Here, a Shichi-Go number is a positive integer that has exactly 75 divisors.

Constraints

* 1 \leq N \leq 100
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of the Shichi-Go numbers that are divisors of N!.

Examples

Input

9


Output

0


Input

10


Output

1


Input

100


Output

543
n = int(input())
p = [0]*(n+1)
for i in range(2,n+1):
    for j in range(2,n+1):
        while i%j == 0:
            p[j] += 1
            i //= j
a,b,c,e,d = 0,0,0,0,0
for prime in p:
    if prime >= 74:
        a += 1
    if prime >= 24:
        b += 1
    if prime >= 14:
        c += 1
    if prime >= 4:
        d += 1
    if prime >= 2:
        e += 1
print(a+b*(e-1)+c*(d-1)+(e-2)*d*(d-1)//2)