You are given one integer number n. Find three distinct integers a, b, c such that 2 ≤ a, b, c and a ⋅ b ⋅ c = n or say that it is impossible to do it.

If there are several answers, you can print any.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of test cases.

The next n lines describe test cases. The i-th test case is given on a new line as one integer n (2 ≤ n ≤ 10^9).

Output

For each test case, print the answer on it. Print "NO" if it is impossible to represent n as a ⋅ b ⋅ c for some distinct integers a, b, c such that 2 ≤ a, b, c.

Otherwise, print "YES" and any possible such representation.

Example

Input


5
64
32
97
2
12345


Output


YES
2 4 8 
NO
NO
NO
YES
3 5 823 
#include <bits/stdc++.h>
using namespace std;
int main() {
  ios_base::sync_with_stdio(false);
  cout.tie(NULL);
  cout.tie(NULL);
  ;
  long long tt;
  cin >> tt;
  while (tt--) {
    long long n;
    cin >> n;
    long long a = -1;
    for (long long i = 2; i * i <= n; i++) {
      if (n % i == 0) {
        a = i;
        n /= a;
        break;
      }
    }
    if (a != -1) {
      long long l = 0;
      for (long long i = 2; i * i <= n; i++) {
        if (n % i == 0 && i != a && a != n / i && i != n / i) {
          cout << "YES\n";
          cout << a << " " << n / i << " " << i << "\n";
          l = 1;
          break;
        }
      }
      if (l == 0) cout << "NO\n";
    } else
      cout << "NO\n";
  }
}
