You are given an array of integers a_1,a_2,…,a_n. Find the maximum possible value of a_ia_ja_ka_la_t among all five indices (i, j, k, l, t) (i<j<k<l<t).

Input

The input consists of multiple test cases. The first line contains an integer t (1≤ t≤ 2 ⋅ 10^4) — the number of test cases. The description of the test cases follows.

The first line of each test case contains a single integer n (5≤ n≤ 10^5) — the size of the array.

The second line of each test case contains n integers a_1,a_2,…,a_n (-3× 10^3≤ a_i≤ 3× 10^3) — given array.

It's guaranteed that the sum of n over all test cases does not exceed 2⋅ 10^5.

Output

For each test case, print one integer — the answer to the problem.

Example

Input


4
5
-1 -2 -3 -4 -5
6
-1 -2 -3 1 2 -1
6
-1 0 0 0 -1 -1
6
-9 -7 -5 -3 -2 1


Output


-120
12
0
945

Note

In the first test case, choosing a_1,a_2,a_3,a_4,a_5 is a best choice: (-1)⋅ (-2) ⋅ (-3)⋅ (-4)⋅ (-5)=-120.

In the second test case, choosing a_1,a_2,a_3,a_5,a_6 is a best choice: (-1)⋅ (-2) ⋅ (-3)⋅ 2⋅ (-1)=12.

In the third test case, choosing a_1,a_2,a_3,a_4,a_5 is a best choice: (-1)⋅ 0⋅ 0⋅ 0⋅ (-1)=0.

In the fourth test case, choosing a_1,a_2,a_3,a_4,a_6 is a best choice: (-9)⋅ (-7) ⋅ (-5)⋅ (-3)⋅ 1=945.
import java.util.*;
import java.io.*;
public class EdB {

	public static void main(String[] args) throws Exception{
		int num = 998244353;

		// TODO Auto-generated method stub
 		BufferedReader bf = new BufferedReader(new InputStreamReader(System.in));
 		PrintWriter out = new PrintWriter(System.out);
 		int t = Integer.parseInt(bf.readLine());
 		for(int i = 0;i<t;i++){
//	 		String input1 = bf.readLine().trim();
//	 		String input2 = bf.readLine().trim();
	 		int n = Integer.parseInt(bf.readLine());
	 		ArrayList<Integer> array = new ArrayList<Integer>();
	 		StringTokenizer st2 = new StringTokenizer(bf.readLine());
	 		int negative = 0;
	 		int positive = 0;
	 		int zero = 0;
	 		for(int j=0;j<n;j++){
	 			array.add(Integer.parseInt(st2.nextToken()));
	 			if (array.get(j) < 0)
	 				negative++;
	 			else if (array.get(j) > 0)
	 				positive++;
	 			else
	 				zero++;
	 		}
	 		Collections.sort(array);
	 		long max = Long.MIN_VALUE;
	 		for(int j =0;j<=5;j++){
	 			long prod = 1;
	 			for(int k=0;k<j;k++){
	 				prod*=(long)(array.get(k));
	 			}
	 			for(int k=array.size()-1;k>=(array.size()-(5-j));k--){
	 				prod*=(long)(array.get(k));
	 			}
	 			max = Math.max(max,  prod);
	 		}
	 		if (zero > 0 && max < 0)
	 			max = 0;
	 		out.println(max);
	 		
	 		
	 		
 		}
 		
 		
 		out.println();
	 		
 		out.close();
 		
 		
 		
 	}
}
 	
 
//StringJoiner sj = new StringJoiner(" "); 
//sj.add(strings)
//sj.toString() gives string of those stuff w spaces or whatever that sequence is

 		
 		
 		
 		
	


