You are given two strings s and t, both consisting only of lowercase Latin letters.

The substring s[l..r] is the string which is obtained by taking characters s_l, s_{l + 1}, ..., s_r without changing the order.

Each of the occurrences of string a in a string b is a position i (1 ≤ i ≤ |b| - |a| + 1) such that b[i..i + |a| - 1] = a (|a| is the length of string a).

You are asked q queries: for the i-th query you are required to calculate the number of occurrences of string t in a substring s[l_i..r_i].

Input

The first line contains three integer numbers n, m and q (1 ≤ n, m ≤ 10^3, 1 ≤ q ≤ 10^5) — the length of string s, the length of string t and the number of queries, respectively.

The second line is a string s (|s| = n), consisting only of lowercase Latin letters.

The third line is a string t (|t| = m), consisting only of lowercase Latin letters.

Each of the next q lines contains two integer numbers l_i and r_i (1 ≤ l_i ≤ r_i ≤ n) — the arguments for the i-th query.

Output

Print q lines — the i-th line should contain the answer to the i-th query, that is the number of occurrences of string t in a substring s[l_i..r_i].

Examples

Input

10 3 4
codeforces
for
1 3
3 10
5 6
5 7


Output

0
1
0
1


Input

15 2 3
abacabadabacaba
ba
1 15
3 4
2 14


Output

4
0
3


Input

3 5 2
aaa
baaab
1 3
1 1


Output

0
0

Note

In the first example the queries are substrings: "cod", "deforces", "fo" and "for", respectively.
import java.io.*;
import java.util.*;
public class CF1016_B {
    public static void main(String[] args)throws Throwable {
        MyScanner sc=new MyScanner();
        PrintWriter pw=new PrintWriter(System.out);

        int n=sc.nextInt();
        int m=sc.nextInt();
        int q=sc.nextInt();
        char [] s=sc.next().toCharArray();
        char [] t=sc.next().toCharArray();
        boolean [] ok=new boolean[n];
        for(int i=0;i+m-1<n;i++){
            ok[i]=true;
            for(int j=0;j<m;j++)
                if(s[i+j]!=t[j])
                    ok[i]=false;
        }
        int [] c=new int [n];
        c[0]=ok[0]? 1 : 0;
        for(int i=1;i<n;i++)
            c[i]=c[i-1]+(ok[i]? 1 : 0);
        while(q-->0){
            int l=sc.nextInt()-1;
            int r=sc.nextInt()-1-(m-1);
            if(r<l){
                pw.println(0);
                continue;
            }
            int ans =c[r];
            if(l>0)
                ans-=c[l-1];
            pw.println(ans);
        }

        pw.flush();
        pw.close();
    }
    static class MyScanner {
        BufferedReader br;
        StringTokenizer st;
        public MyScanner() {
            br = new BufferedReader(new InputStreamReader(System.in));
        }
        String next() {while (st == null || !st.hasMoreElements()) {
            try {st = new StringTokenizer(br.readLine());}
            catch (IOException e) {e.printStackTrace();}}
            return st.nextToken();}
        int nextInt() {return Integer.parseInt(next());}
        long nextLong() {return Long.parseLong(next());}
        double nextDouble() {return Double.parseDouble(next());}
        String nextLine(){String str = "";
            try {str = br.readLine();}
            catch (IOException e) {e.printStackTrace();}
            return str;}
    }
}