You are given an integer N. Among the divisors of N! (= 1 \times 2 \times ... \times N), how many Shichi-Go numbers (literally "Seven-Five numbers") are there?

Here, a Shichi-Go number is a positive integer that has exactly 75 divisors.

Constraints

* 1 \leq N \leq 100
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of the Shichi-Go numbers that are divisors of N!.

Examples

Input

9


Output

0


Input

10


Output

1


Input

100


Output

543
n=int(input())
d=dict()
for m in range(1,n+1):
    while m>1:
        for i in range(2,int(m**0.5)+1):
            if m%i==0:break
        else:i=m
        d[i]=d.get(i,0)+1
        m/=i
def num(n):
    return len(list(filter(lambda x:x>=n,d.values())))

print(num(74)+ num(24)*(num(2)-1)+ num(14)*(num(4)-1)+ num(4)*(num(4)-1)*(num(2)-2)//2)