You are given an array of integers a_1,a_2,…,a_n. Find the maximum possible value of a_ia_ja_ka_la_t among all five indices (i, j, k, l, t) (i<j<k<l<t).

Input

The input consists of multiple test cases. The first line contains an integer t (1≤ t≤ 2 ⋅ 10^4) — the number of test cases. The description of the test cases follows.

The first line of each test case contains a single integer n (5≤ n≤ 10^5) — the size of the array.

The second line of each test case contains n integers a_1,a_2,…,a_n (-3× 10^3≤ a_i≤ 3× 10^3) — given array.

It's guaranteed that the sum of n over all test cases does not exceed 2⋅ 10^5.

Output

For each test case, print one integer — the answer to the problem.

Example

Input


4
5
-1 -2 -3 -4 -5
6
-1 -2 -3 1 2 -1
6
-1 0 0 0 -1 -1
6
-9 -7 -5 -3 -2 1


Output


-120
12
0
945

Note

In the first test case, choosing a_1,a_2,a_3,a_4,a_5 is a best choice: (-1)⋅ (-2) ⋅ (-3)⋅ (-4)⋅ (-5)=-120.

In the second test case, choosing a_1,a_2,a_3,a_5,a_6 is a best choice: (-1)⋅ (-2) ⋅ (-3)⋅ 2⋅ (-1)=12.

In the third test case, choosing a_1,a_2,a_3,a_4,a_5 is a best choice: (-1)⋅ 0⋅ 0⋅ 0⋅ (-1)=0.

In the fourth test case, choosing a_1,a_2,a_3,a_4,a_6 is a best choice: (-9)⋅ (-7) ⋅ (-5)⋅ (-3)⋅ 1=945.
from sys import stdin, stdout,stderr, maxsize;  # mod = int(1e9 + 7);#import re  # can use multiple splits

# input = stdin.buffer.readline
tup = lambda: map(int, stdin.readline().split())
I = lambda: int(stdin.readline())
lint = lambda: [int(x) for x in stdin.readline().split()]
S = lambda: stdin.readline().replace('\n', '').strip()
# def grid(r, c): return [lint() for i in range(r)]
# def debug(*args, c=6): print('\033[3{}m'.format(c), *args, '\033[0m', file=stderr)
stpr = lambda x: stdout.write(f'{x}' + '\n')
star = lambda x: print(' '.join(map(str, x)))
from math import ceil, floor
from _collections import defaultdict
from bisect import bisect_left, bisect_right
for _ in range(I()):
    n = I()
    ls = lint()
    ne , po ,ze  = 0 ,0 , 0
    for i in ls:
        if i <0:
            ne+=1
    ans = 1
    if ne ==n:
        ls.sort(reverse=True)
        for i in range(5):
            ans*=ls[i]
        print(ans)
    else:
        l = sorted(ls)
        ans = max(l[-1]*l[-2]*l[-3]*l[-4] * l[-5] , l[-1]*l[-2] *l[-3] * l[0] * l[1] , l[0] * l[1] * l[2]*l[3]*l[-1])
        print(ans)

























