You are given an integer N. Among the divisors of N! (= 1 \times 2 \times ... \times N), how many Shichi-Go numbers (literally "Seven-Five numbers") are there?

Here, a Shichi-Go number is a positive integer that has exactly 75 divisors.

Constraints

* 1 \leq N \leq 100
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of the Shichi-Go numbers that are divisors of N!.

Examples

Input

9


Output

0


Input

10


Output

1


Input

100


Output

543
N=int(input())
pdic={2:0}
for i in range(3,50,2):
    for j in pdic.keys():
        if i%j==0:
            break
    else:
        pdic[i]=0
for i in range(2,N+1):
    for p in pdic.keys():
        while i%p==0:
            pdic[p]+=1
            i//=p
ge={i:sum(x>=i-1 for x in pdic.values()) for i in (3,5,15,25,75)}
if ge[5]<2 and ge[3]<3:
    print(0)
else:
    print(ge[5]*(ge[5]-1)//2*(ge[3]-2)+ge[25]*(ge[3]-1)+ge[15]*(ge[5]-1)+ge[75])