You are given two strings s and t, both consisting only of lowercase Latin letters.

The substring s[l..r] is the string which is obtained by taking characters s_l, s_{l + 1}, ..., s_r without changing the order.

Each of the occurrences of string a in a string b is a position i (1 ≤ i ≤ |b| - |a| + 1) such that b[i..i + |a| - 1] = a (|a| is the length of string a).

You are asked q queries: for the i-th query you are required to calculate the number of occurrences of string t in a substring s[l_i..r_i].

Input

The first line contains three integer numbers n, m and q (1 ≤ n, m ≤ 10^3, 1 ≤ q ≤ 10^5) — the length of string s, the length of string t and the number of queries, respectively.

The second line is a string s (|s| = n), consisting only of lowercase Latin letters.

The third line is a string t (|t| = m), consisting only of lowercase Latin letters.

Each of the next q lines contains two integer numbers l_i and r_i (1 ≤ l_i ≤ r_i ≤ n) — the arguments for the i-th query.

Output

Print q lines — the i-th line should contain the answer to the i-th query, that is the number of occurrences of string t in a substring s[l_i..r_i].

Examples

Input

10 3 4
codeforces
for
1 3
3 10
5 6
5 7


Output

0
1
0
1


Input

15 2 3
abacabadabacaba
ba
1 15
3 4
2 14


Output

4
0
3


Input

3 5 2
aaa
baaab
1 3
1 1


Output

0
0

Note

In the first example the queries are substrings: "cod", "deforces", "fo" and "for", respectively.
import sys
input = sys.stdin.readline


class BIT():
    def __init__(self, n):
        self.size = n
        self.bit = [0] * (n + 1)

    def _sum(self, i):
        s = 0
        while i > 0:
            s += self.bit[i]
            i -= i & -i
        return s

    def add(self, i, val):
        i += 1
        while i <= self.size:
            self.bit[i] += val
            i += i & -i

    def get_sum(self, l, r):
        return self._sum(r) - self._sum(l)

def z_algo(s):
    res = [0] * len(s)
    res[0] = len(s)
    i = 1
    j = 0
    while i < len(s):
        while i + j < len(s) and s[j] == s[i + j]:
            j += 1
        res[i] = j
        if j == 0:
            i += 1
            continue
        k = 1
        while i + k < len(s) and k + res[k] < j:
            res[i + k] = res[k]
            k += 1
        i += k
        j -= k
    return res


n, m, q = map(int, input().split())
s = input()[:-1]
t = input()[:-1]
query = [list(map(int, input().split())) for i in range(q)]

ss = t + s
tmp = z_algo(ss)
ans = [0] * n
for i in range(m, n + m):
    if tmp[i] >= len(t):
        ans[i - m] = 1

bit = BIT(n)
for i in range(n):
    bit.add(i, ans[i])

for l, r in query:
    l -= 1
    if l > r - len(t) + 1:
        print(0)
    else:
        print(bit.get_sum(l, r - len(t) + 1))