You are given one integer number n. Find three distinct integers a, b, c such that 2 ≤ a, b, c and a ⋅ b ⋅ c = n or say that it is impossible to do it.

If there are several answers, you can print any.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of test cases.

The next n lines describe test cases. The i-th test case is given on a new line as one integer n (2 ≤ n ≤ 10^9).

Output

For each test case, print the answer on it. Print "NO" if it is impossible to represent n as a ⋅ b ⋅ c for some distinct integers a, b, c such that 2 ≤ a, b, c.

Otherwise, print "YES" and any possible such representation.

Example

Input


5
64
32
97
2
12345


Output


YES
2 4 8 
NO
NO
NO
YES
3 5 823 

import bisect
from itertools import accumulate
import os
import sys
import math
from decimal import *
from io import BytesIO, IOBase

BUFSIZE = 8192


class FastIO(IOBase):
    newlines = 0

    def __init__(self, file):
        self._fd = file.fileno()
        self.buffer = BytesIO()
        self.writable = "x" in file.mode or "r" not in file.mode
        self.write = self.buffer.write if self.writable else None

    def read(self):
        while True:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            if not b:
                break
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines = 0
        return self.buffer.read()

    def readline(self):
        while self.newlines == 0:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            self.newlines = b.count(b"\n") + (not b)
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines -= 1
        return self.buffer.readline()

    def flush(self):
        if self.writable:
            os.write(self._fd, self.buffer.getvalue())
            self.buffer.truncate(0), self.buffer.seek(0)


class IOWrapper(IOBase):
    def __init__(self, file):
        self.buffer = FastIO(file)
        self.flush = self.buffer.flush
        self.writable = self.buffer.writable
        self.write = lambda s: self.buffer.write(s.encode("ascii"))
        self.read = lambda: self.buffer.read().decode("ascii")
        self.readline = lambda: self.buffer.readline().decode("ascii")


sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)


def input(): return sys.stdin.readline().rstrip("\r\n")
def factors(n):
    fac=[]
    while(n%2==0):
        fac.append(2)
        n=n//2
    for i in range(3,int(math.sqrt(n))+2):
        while(n%i==0):
            fac.append(i)
            n=n//i
    if n>1:
        fac.append(n)
    return fac
# ------------------- fast io --------------------]]
for _ in range(int(input())):
    n=int(input())
    fac=factors(n)
    if len(fac)<3:
        print("NO")
    else:
        if len(fac)==3 and len(set(fac))==3:
            print("YES")
            print(*fac)
        elif len(fac)==3 and len(set(fac))<3:
            print("NO")
        elif len(set(fac))>=3:
            print("YES")
            ans=[fac[0],fac[-1]]
            c=1
            for i in range(1,len(fac)-1):
                c=c*fac[i]
            ans.append(c)
            print(*ans)
        elif len(set(fac))==1:
            if len(fac)>=6:
                print("YES")
                ans=[fac[0],fac[-1]*fac[-2]]
                c=1
                for i in range(1,len(fac)-2):
                    c=c*fac[i]
                ans.append(c)
                print(*ans)
            else:
                print("NO")
        elif len(set(fac))==2:
            print("YES")
            ans=[fac[0],fac[-1]]
            c=1
            for i in range(1,len(fac)-1):
                c=c*fac[i]
            ans.append(c)
            print(*ans) 
        