It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
year = int(input())
def year_find(x):
	a = x % 10
	b = (x // 10) % 10
	c = (x // 100) % 10
	d = (x // 1000) % 10
	if(a != b and a != c and a != d and b != c and b != d and c != d):
		return 1
	else:
		return 0

for i in range(year+1, 9999):
	x = year_find(i)
	if(x == 1):
		print(i)
		break