It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014

def se(x):
    b = []
    for j in range(4):
        y = int(x % 10)
        x /= 10
        b.append(y)
    if len(set(b)) == len(b):
        return True


a = int(input()) + 1
while True:
    if se(a) is True:
        print(a)
        exit()
    else:
        a += 1
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