It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
PROBLEM = 1
FILE = "P%i" %(PROBLEM) 
outFile = None
#outFile = "P%i_output" %(PROBLEM)
try:
    inFile = open(FILE+".txt")
except:
    pass
if outFile is not None:
    outFile = open(outFile+".txt","w")

def read():
    try:
        return inFile.readline().strip()
    except:
        return raw_input().strip()

def write(*args):
    newline = True
    if type(args[-1]) == bool:
        newline = args[-1]
        args = args[:-1]
    
    output = ""
    for i in xrange(len(args)):
        if i > 0:
            output += " "
        output += str(args[i])
        
    if outFile is None:
        if newline:
            print output
        else:
            print output,
            
    else:
        if newline:
            outFile.write(output+"\n")
        else:
            outFile.write(output+" ")

def check(year):
    year = str(year)
    for d in  year:
        if year.count(d) != 1:
            return False
    return True
            
y = int(read())
y += 1
while not check(y):
    y += 1
write(y)



if outFile is not None:
    outFile.close()
