It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
# -*- coding: utf-8 -*-
"""
Created on Mon Oct  5 12:37:03 2020

@author: 章斯岚
"""
a=0
x=int(input())+1
def judgement(p):
    for i in str(p):
        if str(p).count(i)>1:
            global a
            a=1
            return(False)
            break
    if a==0:
        return(True)
while judgement(x)==False:
    x+=1
print(x)