It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def beautifulYear(n):
    m = []
    for digit in str(n):
        m.append(int(digit))
    numbers = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
    for i in range(4):
        numbers[m[i]] = numbers[m[i]] + 1
    for i in range(10):
        if numbers[i] >= 2:
            return False
    return True


n = int(input())
n = n + 1
while beautifulYear(n) != True:
    n = n + 1

print(n)
