You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

* 1 \leq |S| \leq 2 \times 10^5
* |S| = |T|
* S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:


S
T


Output

If S and T can be made equal, print `Yes`; otherwise, print `No`.

Examples

Input

azzel
apple


Output

Yes


Input

chokudai
redcoder


Output

No


Input

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu


Output

Yes
import java.util.*;

class Main{
    public static void main(String[] args){
        Scanner sc = new Scanner(System.in);
        String s = sc.next();
        String t = sc.next();
        String ans = helper(s,t);
        System.out.println(ans);
    }
    static String helper(String s, String t){
        ArrayList<Integer>[] S = new ArrayList[26];
        ArrayList<Integer>[] T = new ArrayList[26];
        for(int i=0;i<26;i++){
            S[i]=new ArrayList<>();
            T[i]=new ArrayList<>();
        }
        for(int i=0;i<s.length();i++){
            S[s.charAt(i)-'a'].add(i);
            T[t.charAt(i)-'a'].add(i);
        }
        boolean[] used = new boolean[26];
        HashSet<Integer> check = new HashSet<>();
        for(int i=0;i<26;i++){
            for(int j=0;j<26;j++){
                if(used[j]) continue;
                if(solve(S[i],T[j])){
                    check.add(i);
                    used[j] = true;
                    break;
                }
            }
        }
        if(check.size()==26) return "Yes";
        else return "No";
    }
    static boolean solve(ArrayList<Integer> a, ArrayList<Integer> b){
        if(a.size()!=b.size()) return false;
        for(int i=0;i<a.size();i++){
            if((int)a.get(i)!=(int)b.get(i)) return false;
        }
        return true;
    }
}
