It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def findNumber(n): 
    # looping through numbers less than n 
    i = n+1
    while(i>=0): 
        # initializing a hash array 
        count = [0 for i in range(10)]  
  
        x = i 
        # creating a copy of i 
  
        # initializing variables to compare lengths of digits 
        count1 = 0
        count2 = 0
  
        # counting frequency of the digits 
        while (x): 
          
            count[x%10] += 1
            x = int(x / 10) 
            count1 += 1
          
        # checking if each digit is present once 
        for j in range(0,10,1): 
            if (count[j] == 1): 
                count2 += 1
                  
        if (count1 == count2): 
            return i 
        i += 1
      
# Driver code 
if __name__ == '__main__': 
  
    n = int(input())
    print(findNumber(n)) 