It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def min(n):
    n+=1
    while True:
        l=[0]*10
        count=0
        for c in str(n):
            l[int(c)]+=1
        for d in l:
            if d>1:
                count+=1
        if count==0:
            return n
        n+=1

n=input()
print min(n)