It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
t = int(input())
n = 4
def place_1(n):
    return n%10
def place_10(n):
    return (n%100)//10
def place_100(n):
    return (n%1000)//100
def place_1000(n):
    return (n%10000)//1000
t += 1
while(len(set([place_1(t),place_10(t),place_100(t),place_1000(t)]))!=4):
        t += 1
print(t)
