It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def eq(a,b,c,d):
    return (a==b or a==c or a==d or b==c or b==d or c==d)


def parcala(year):
    ones = year%10
    tens = int(((year - ones)/10)%10)
    hundreds = int(((year - tens*10 - ones)/100)%10)
    thousands = int(((year - hundreds*100 - tens*10 - ones)/1000)%10)
    return eq(ones,tens,hundreds,thousands)


year = int(input())
year += 1
while True:
    if parcala(year):
        year +=1
    else:
        print(year)
        break

