It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
year = input()
year = list(year)

for i,v in enumerate(year): year[i] = int(v)

flag = True

while(flag):
	year[3] += 1
	if year[3] == 10:
		year[3] = 0
		year[2] += 1
		if year[2] == 10:
			year[2] = 0
			year[1] += 1
			if year[1] == 10:
				year[1] = 0
				year[0] += 1

	lets_break = False
	for i in range(0,4):
		for j in range (i+1, 4):
			if year[i] == year[j]:
				lets_break = True 
				break
		if lets_break: break

	if not lets_break:
		flag = False
		for i,v in enumerate(year): year[i] = str(v)
		print(''.join(year))

