It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
year = int (raw_input())

def distinctDigits(n):
    ok = True
    a = []
    while n > 0:
        k = n % 10
        a.append(k)
        n /= 10
    for i in range(0, len(a)):
        for j in range(0, len(a)):
            if i is not j:
                if a[i] == a[j]:
                    ok = False
    return ok

while True:
    year += 1
    if distinctDigits(year) is True:
        print year
        break


