It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def check(x):
    n1 = x // 1000
    n2 = (x // 100) % 10
    n3 = (x // 10) % 10
    n4 = x % 10
    
    return (n1 != n2) and (n1 != n3) and (n1 != n4)and (n2 != n3) and(n2 != n4) and(n3 != n4) 
    
    
    
    
    
    
    
    
    
    

y = int(input())
res = y + 1
while not check(res):
    res+=1
print(res)