It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n = int(input())
n = n + 1
while 1:
    t = n
    l = []
    while t > 0:
        l.append(t % 10)
        t = t // 10
    l = l[::-1]
    if (l[-1] == l[1]) or (l[-1] == l[0]) or (l[-1] == l[2]):
        n += 1
        continue
    elif (l[-2] == l[1]) or (l[-2] == l[0]):
        n += 10
        a = n % 10
        n -= a
        continue
    elif l[-3] == l[0]:
        n += 100
        n -= (n % 100)
        continue
    else:
        break
print(n)