It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n = int(input())
ok = False
curr = n
while not ok:
    curr = curr + 1
    count = [0]*10
    tmp = curr
    while tmp > 0:
        count[tmp % 10] += 1
        if count[tmp % 10] >= 2:
            break
        tmp = tmp // 10
    if all(elm <= 1 for elm in count):
        ok = True
print(curr)