It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
""" 
    Codeforces #166 A
    Beautiful Year.
"""
import math, sys, os, re

def f(year):
    a=[0]
    for x in range(10):
        a.append(0)
    while year>0:
        a[year%10]=a[year%10]+1
        year=int(year/10)
    for x in range(10):
        if a[x]>=2:
            return 0
    return 1

given=int(raw_input())
for x in range(given+1, 10000):
    if f(x) is 1:
        print(x)
        break