It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n=int(input())

while 1:
    n+=1
    no=n
    l=[]
    while no>0:
        rem=no%10
        l.append(rem)
        no=no//10
    flag=1
    for i in range(4):
        for j in range(4):
            if i!=j:
                if l[i]==l[j]:
                    flag=0
                    break
        if flag==0:
            break
    if flag==1:
        break
if flag:
        print(n)