You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
const long long INF = 1ll * 1e13;
const long long st = (1ll << 31);
const long long MOD = 1000000007;
int main() {
  ios_base::sync_with_stdio(0);
  int a;
  string s;
  cin >> a >> s;
  map<int, int> m;
  int n = s.length();
  vector<int> p(n);
  p[0] = (int)(s[0] - '0');
  for (int i = 1; i < n; i++) p[i] = p[i - 1] + (int)(s[i] - '0');
  for (int i = 0; i < n; i++) {
    for (int j = i; j < n; j++) {
      int sm = p[j] - (i > 0 ? p[i - 1] : 0);
      m[sm]++;
    }
  }
  long long ans = 0;
  if (a == 0) {
    if (m.count(0)) {
      for (auto it : m) {
        int y = it.second;
        if (it.first == 0)
          ans += 1ll * y * y;
        else
          ans += 1ll * y * m[0] * 2;
      }
    }
  } else {
    for (auto it : m) {
      int x = it.first;
      int y = it.second;
      if (x == 0) continue;
      if (a % x == 0 && m.count(a / x)) ans += 1ll * y * m[a / x];
    }
  }
  cout << ans << endl;
  return 0;
}
