It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def year(y):
    y += 1
    while True:
        c0 = y // 1000
        c1 = y // 100 % 10
        c2 = y % 100 // 10
        c3 = y % 10
        if c0!=c1 and c0!=c2 and c0!=c3 and c1!=c2 and c1!=c3 and c2!=c3:
            c0 = y // 1000
            c1 = y // 100 % 10
            c2 = y % 100 // 10
            c3 = y % 10
            return y
        y += 1
print(year(int(input())))