It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
num=int(input())
def unique_year(n):
    unique=[]
    for i in str(n):
        if i not in unique:
            unique.append(i)
    if len(unique)==4:
        return True
years=[]
for i in range(1000,10000):
    if unique_year(i):
        years.append(i)
if num in years:
    x=years.index(num)
    print(years[x+1])
else:
    for i in years:
        if i>num:
            print(i)
            break
