It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#*****DO NOT COPY*****
#F
#U       ___                     ___                         ___           ___           ___           ___          _____
#C      /  /\      ___          /  /\          ___          /__/\         /  /\         /  /\         /  /\        /  /::\
#K     /  /::\    /  /\        /  /:/_        /  /\         \  \:\       /  /::\       /  /::\       /  /:/_      /  /:/\:\
#     /  /:/\:\  /  /:/       /  /:/ /\      /  /::\         \  \:\     /  /:/\:\     /  /:/\:\     /  /:/ /\    /  /:/  \:\
#Y   /  /:/~/:/ /__/::\      /  /:/ /::\    /  /:/\:\    ___  \  \:\   /  /:/~/::\   /  /:/~/:/    /  /:/ /:/_  /__/:/ \__\:|
#O  /__/:/ /:/  \__\/\:\__  /__/:/ /:/\:\  /  /:/~/::\  /__/\  \__\:\ /__/:/ /:/\:\ /__/:/ /:/___ /__/:/ /:/ /\ \  \:\ /  /:/
#U  \  \:\/:/      \  \:\/\ \  \:\/:/~/:/ /__/:/ /:/\:\ \  \:\ /  /:/ \  \:\/:/__\/ \  \:\/:::::/ \  \:\/:/ /:/  \  \:\  /:/
#    \  \::/        \__\::/  \  \::/ /:/  \  \:\/:/__\/  \  \:\  /:/   \  \::/       \  \::/~~~~   \  \::/ /:/    \  \:\/:/
#A    \  \:\        /__/:/    \__\/ /:/    \  \::/        \  \:\/:/     \  \:\        \  \:\        \  \:\/:/      \  \::/
#L     \  \:\       \__\/       /__/:/      \__\/          \  \::/       \  \:\        \  \:\        \  \::/        \__\/
#L      \__\/                   \__\/                       \__\/         \__\/         \__\/         \__\/
#
#
#*****DO NOT COPY*****

year = int(input())

f = 0

while f == 0:
    year += 1
    count = 0

    for i in range(4):
        for j in range(4):
            if str(year)[i] == str(year)[j]:
                count += 1

    if count == 4:
        f = 1

print(year)