It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
year = int(input())
y = year + 1
while y > year:
    y_list = list(str(y))
    a = y_list[0]
    b = y_list[1]
    c = y_list[2]
    d = y_list[3]
    if y_list.count(a)>1 or y_list.count(b)>1 or y_list.count(c)>1 or y_list.count(d)>1:
        y += 1
    else:
        break

print(y)