It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def check_input(y):
    while y<1000 or y >9000:
        y = int(input())
    return y

def executee(y):
	
    test = False
    i = y + 1
 
    s = str(i)
    a = int(s[0])
    b = int(s[1])
    c = int(s[2])
    d = int(s[3])
   
    while test == False:
        s = str(i)
        a = int(s[0])
        b = int(s[1])
        c = int(s[2])
        d = int(s[3])
        if a!=b and a!=c and a!=d and b!=c and b!=d and c!=d:
            test = True
        else:
            i +=1
          
            
    return i            

y = int(input())
y = check_input(y)

i= executee(y)
print(i)
