It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
Year = int(input()) + 1


def checkdigits(digits):
    fr = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, ]
    for d in digits:
        fr[d] += 1
    for f in fr:
        if f > 1:
            return False
    return True


while True:
    Digits = []
    for dig in str(Year):
        Digits.append(int(dig))
    if checkdigits(Digits):
        print(str(Year))
        quit()
    else:
        Year += 1
