It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
Year=int(input()) 
Year=Year+1
Beautiful_year=True
while Beautiful_year:
	st=str(Year)
	List=[0]*len(st)
	List_1=[]
	for i in range(len(st)) :
		List[i] =st[i] 
	count=0
	for k in range(len(st)) :
		if List[k] not in List_1:
			List_1.append(List[k])
			count+=1
		elif List[k] in List_1:
			Year+=1
			continue
	if count==len(st) :
		Beautiful_year=False
print(Year) 