It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#!/bin/python
while True:
	try:
		y=input();
		while True:
			y+=1
			num=[]
			for i in range(0,10):num+=[0]
			temp=y
			for i in range(0,4):
				num[temp%10]+=1
				temp/=10
			flag=True
			for i in range(0,10):
				if num[i]>1:flag=False
			if flag:
				print(y)
				break
	except EOFError:
		break
 			       		  		 			 	   	 	