It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def year(n):
	a=str(n+1)
	l=[]
	for i in range(0,len(a)):
		l.append(int(a[i]))
	#print(l)
	i=0
	while(i>=0):
		l1=[]
		for i in range(0,len(l)):
			l1.append(l.count(l[i]))

		if l1.count(1)==len(l):
			break
		else:
			n+=1
			a=str(n)
			l=[]
			for i in range(0,len(a)):
				l.append(int(a[i]))
			i+=1

	for j in range(0,len(l)):
		print(l[j],end="")

n=int(input())
year(n)


	
