It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n=int(input())
status=-1
temp=n+1
arr=["0","1","2","3","4","5","6","7","8","9"]

while(status==-1):
    temp2=str(temp)
    total=[0]*10
    cek=0
    for i in range(len(temp2)):
        for j in range(len(arr)):
            if(temp2[i]==arr[j]):
                total[j]+=1
    for i in range(len(total)):
        if(total[i]==1):
            cek+=1
    if(cek==4):
        print(temp2)
        status=0
        break
    temp+=1
            
