It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def solve(num):
	num = str(num)

	l = {}

	for i in "1234567890":
		l[i] = 0

	for i in num:
		l[i] += 1

		if(l[i] > 1):
			return False

	return True


n = int(raw_input())
m = n + 1

while not solve(m):
	m += 1

print m

