It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def helper(s):
    i=0
    j=i+1
    while i<len(s)-1:
        while j<len(s):
            if s[i]==s[j]:
                return 0
            else:
                j=j+1
        i=i+1
        j=i+1
    return 1
n=input()
num=int(n)
ans=0
val=0
while ans!=1:
    num=num+1
    n=str(num)
    if helper(n)==1:
        ans=1
        val=num
print(val)    
