You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
int n, a;
int D[4009], V[36089], l;
long long ans;
char s[4009];
int main() {
  scanf("%d %s", &a, s);
  n = strlen(s);
  for (int h = 1; h <= n; h++) {
    D[h] = s[h - 1] - '0';
    D[h] += D[h - 1];
  }
  for (int h = 1; h <= n; h++)
    for (int j = h; j <= n; j++) V[D[j] - D[h - 1]]++, l++;
  for (int h = 1; h <= n; h++)
    for (int j = h; j <= n; j++) {
      int k = D[j] - D[h - 1];
      if (!a) {
        if (k)
          ans += V[0];
        else
          ans += l;
        continue;
      }
      if (!k || 36005 < a / k) continue;
      if (a % k == 0) ans += (long long)V[a / k];
    }
  printf("%I64d\n", ans);
}
