It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
int cnt[10];
bool IsDis(int s) {
  int fst, snd, rd, frd;
  frd = s % 10;
  s /= 10;
  rd = s % 10;
  s /= 10;
  snd = s % 10;
  fst = s / 10;
  cnt[frd]++;
  cnt[rd]++;
  cnt[snd]++;
  cnt[fst]++;
  for (int i = 0; i <= 9; i++) {
    if (cnt[i] > 1) {
      for (int i = 0; i <= 9; i++) {
        cnt[i] = 0;
      }
      return false;
    }
  }
  for (int i = 0; i <= 9; i++) {
    cnt[i] = 0;
  }
  return true;
}
int main() {
  int s;
  cin >> s;
  for (int i = s + 1;; i++) {
    if (IsDis(i)) {
      cout << i;
      return 0;
    }
  }
  return 0;
}
