It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def contar(a,n,r):
    f=0
    while r<n:
        t=a.count(a[r])
        f=f+t
        if f>n:
            c=0
            r=r+1
        else:
            c=1
            r=r+1
    return (c)
a=input()
r=0
k=1
while k>0:
    a=int(a)+k
    a=str(a)
    n=len(a)
    r=0
    r1=contar(a,n,r)
    if r1==0:
        k=1
    elif r1==1:
        k=0
        print(a)
    
    
