It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def isdistinct(n):
    l = []
    while n > 0:
        digit = n % 10
        if digit not in l:
            l.append(digit)
        n = n//10
    return len(l) == 4


t = int(input())
if t>1987 and t < 2013:
    print(2013)
else:
    for j in range(1, 9000):
        if isdistinct(t+j):
            print(t+j)
            exit()



