It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def unique_digits(number):
    visited_numbers = [0 for i in range(10)]
    digits = list(str(number))
    #print(digits)
    for num in digits:
        num = int(num)
        if visited_numbers[num] == 1:
            return False
        else:
            visited_numbers[num] += 1
    return True

year_number = int(input())

while True:
    year_number += 1
    if unique_digits(year_number):
        break

print(year_number)
	 			 	 	     		     		   		  	