It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
year_counter = int(raw_input()) + 1


def special_year(current_year):
    seen_number = {}
    while current_year > 9:
        current_digit = current_year % 10
        current_year /= 10
        if current_digit in seen_number.keys():
            return False
        else:
            seen_number[current_digit] = 1
    return current_year not in seen_number.keys()


while not special_year(year_counter):
    year_counter += 1
print(year_counter)
