You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
int a, b[500000];
long long h[500000];
char s[500000];
int main() {
  while (~scanf("%d", &a)) {
    long long ans = 0;
    scanf("%s", s);
    int len = strlen(s);
    b[0] = 0;
    for (int i = 1; i <= len; i++) b[i] = b[i - 1] + s[i - 1] - '0';
    memset(h, 0, sizeof(h));
    for (int i = 1; i <= len; i++)
      for (int j = 0; j < i; j++) {
        int t = b[i] - b[j];
        h[t]++;
      }
    if (a == 0) {
      ans = h[0] * h[0];
      for (int i = 1; i <= 36000; i++) ans += h[0] * h[i] * 2;
    } else {
      for (int i = 1; i <= 36000; i++)
        if (a % i == 0 && (a / i) <= 36000) {
          ans += h[i] * h[a / i];
        }
    }
    printf("%I64d\n", ans);
  }
  return 0;
}
