It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def main():
    
    y = int(input()) + 1
    
    while y <= 9012:
        if (isDifferent(y)):
            print(y)
            break
        
        y = y + 1
    
def isDifferent(year):
    
    number = year
    
    d0 = number // 1000
    number = number % 1000
    d1 = number // 100
    number = number % 100
    d2 = number // 10
    d3 = number % 10
    
    if ((d0 != d1) and (d0 != d2) and (d0 != d3) and (d1 != d2) and (d1 != d3) and (d2 != d3)):
        return True
    else:
        return False
    
main()
   			  	 	 					 	   			 					