It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n=int(input())
n=n+1
str(n)
k=[]
def tekrar(x):
    c=[]
    x=str(x)
    for i in range(len(x)) :
        a=x.count(x[i])
        c.append(a)

    for i in range(c.count(0)):
         c.remove(0)
    for i in range(c.count(1)):
         c.remove(1)
    if len(c)==0 :
         return True
    else :
         return False
        
if tekrar(n)==True :
    print(n)
elif tekrar(n)==False :
    while tekrar(n)==False :
        int(n)
        n+=1
        str(n)
        k.append(n)
    print(k[-1])    
           
   
