It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def check_diff_year(year):
    u = year % 10
    d = int((year % 100) / 10)
    c = int((year % 1000) / 100)
    t = int(year / 1000)
    if ((u == d) or (u == c) or (u == t) or (d == c) or (d == t) or (c == t)):
    	return True
    else:
    	return False

y = int(input())
y = y + 1
while (check_diff_year(y)):
	y = y + 1
print(y)
