It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014


def differ_digit(a_year):
    a_year = str(a_year)

    for i in range(len(a_year)):
        for j in range(i+1,len(a_year)):
            if a_year[i] ==a_year[j]:
                return False
    return True
def beautifulYear(a_year):
    a_year = int(a_year)
    result_year = a_year+1
    while not (differ_digit(result_year)):
        result_year+=1
    print(result_year)

a_year = input()

beautifulYear(a_year)


