It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
# -*- coding: utf-8 -*-
"""
Created on Thu Sep  6 13:24:39 2018

@author: ankit
"""
y = input()
y = int(y)
y = y+1
while y <= 9999 :
    ind = 0
    s = str(y)
    l = list(s)
    for i in range(len(l)-1):
        for j in range(i+1, (len(l))):
            if l[i] == l[j]:
                ind = 1
            else:
                 pass
    if ind == 0:
        print (y)
        break        
    y = y+1