It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def checkDistinctNumbers(number):
    numbers_dict = dict()
    while number > 0:
        rest = number % 10
        if rest in numbers_dict:
            return False
        else:
            numbers_dict[rest] = 1
        number = number // 10

    return True

def main():
    y = int(input())
    for i in range(y + 1, 10000):
        if checkDistinctNumbers(i):
            print(i)
            return
    return

if __name__ == "__main__":
    main()
	 	 	 	 				 	 				 	 		 	  			