It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def isDistinct(year):
    year = str(year)
    count = 0
    a = [0]*10
    for i in range(len(year)):
        a[int(year[i])-1] += 1
    for j in range(10):
        if a[j] == 1:
            count += 1
    if count == len(year):
        return True
    else:
        return False
        
num = int(input())
i = 0
num = num + 1
while not isDistinct(num):
    num += 1
print(num)