Takahashi, Aoki and Snuke love cookies. They have A, B and C cookies, respectively. Now, they will exchange those cookies by repeating the action below:

* Each person simultaneously divides his cookies in half and gives one half to each of the other two persons.



This action will be repeated until there is a person with odd number of cookies in hand.

How many times will they repeat this action? Note that the answer may not be finite.

Constraints

* 1 ≤ A,B,C ≤ 10^9

Input

Input is given from Standard Input in the following format:


A B C


Output

Print the number of times the action will be performed by the three people, if this number is finite. If it is infinite, print `-1` instead.

Examples

Input

4 12 20


Output

3


Input

14 14 14


Output

-1


Input

454 414 444


Output

1
import java.util.*;
import java.io.*;

public class Main implements Runnable {
    public static void main(String[] args) {
        Thread.setDefaultUncaughtExceptionHandler((t,e)->System.exit(1));
        // keep stack
        new Thread(null, new Main(), "", 16 * 1024 * 1024).start();
    }
    public void run() {
        FastScanner sc = new FastScanner();
        PrintWriter out = new PrintWriter(System.out);
        int A = sc.nextInt();
        int B = sc.nextInt();
        int C = sc.nextInt();

        int Aorg = A;
        int Borg = B;
        int Corg = C;
        // out.printf("ORG A:%d B:%d C:%d\n", Aorg, Borg, Corg);
        int count = 0;
        while(A % 2 == 0 && B % 2 == 0 && C % 2 == 0) {
            int Atemp = A;
            int Btemp = B;
            int Ctemp = C;
            A = (Btemp + Ctemp) / 2;
            B = (Ctemp + Atemp) / 2;
            C = (Atemp + Btemp) / 2;
            count++;
            // out.printf("(%d) A:%d B:%d C:%d\n", count, A, B, C);
            if (Aorg == A && Borg == B && Corg == C) {
                count = -1;
                break;
            }
        }
        out.printf("%d\n", count);
        out.flush();
    }
}

class FastScanner {
    private final InputStream in = System.in;
    private final byte[] buffer = new byte[1024];
    private int ptr = 0;
    private int buflen = 0;

    private boolean hasNextByte() {
        if (ptr < buflen) {
            return true;
        } else {
            ptr = 0;
            try {
                buflen = in.read(buffer);
            } catch (IOException e) {
                e.printStackTrace();
            }
            if (buflen <= 0) {
                return false;
            }
        }
        return true;
    }

    private int readByte() {
        if (hasNextByte()) {
            return buffer[ptr++];
        }
        else {
            return -1;
        }
    }

    private static boolean isPrintableChar(int c) {
        return 33 <= c && c <= 126;
    }

    private void skipUnprintable() {
        while (hasNextByte() && !isPrintableChar(buffer[ptr])) {
            ptr++;
        }
    }

    public boolean hasNext() {
        skipUnprintable();
        return hasNextByte();
    }

    public String next() {
        if (!hasNext()) {
            throw new NoSuchElementException();
        }
        StringBuilder sb = new StringBuilder();
        int b = readByte();
        while (isPrintableChar(b)) {
            sb.appendCodePoint(b);
            b = readByte();
        }
        return sb.toString();
    }

    public int nextInt() {
        if (!hasNext()) {
            throw new NoSuchElementException();
        }
        int n = 0;
        boolean minus = false;
        int b = readByte();
        if (b == '-') {
            minus = true;
            b = readByte();
        }
        if (b < '0' || '9' < b) {
            throw new NumberFormatException();
        }
        while (true) {
            if ('0' <= b && b <= '9') {
                n *= 10;
                n += b - '0';
            } else if (b == -1 || !isPrintableChar(b)) {
                return minus ? -n : n;
            } else {
                throw new NumberFormatException();
            }
            b = readByte();
        }
    }

    public long nextLong() {
        if (!hasNext()) {
            throw new NoSuchElementException();
        }
        long n = 0;
        boolean minus = false;
        int b = readByte();
        if (b == '-') {
            minus = true;
            b = readByte();
        }
        if (b < '0' || '9' < b) {
            throw new NumberFormatException();
        }
        while (true) {
            if ('0' <= b && b <= '9') {
                n *= 10;
                n += b - '0';
            } else if (b == -1 || !isPrintableChar(b)) {
                return minus ? -n : n;
            } else {
                throw new NumberFormatException();
            }
            b = readByte();
        }
    }
}