It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
import sys
import itertools

""" sys.stdin = open("/Users/isym444/Desktop/PythonCP/cpp.in", "r")
sys.stdout = open("/Users/isym444/Desktop/PythonCP/cpp.out", "w") """

""" sys.stdin = open("shell.in", "r")
sys.stdout = open("shell.out", "w") """

a = int(input())
b = 1
while b == 1:
    c = set()
    a += 1
    d = map(int, str(a))
    for i in range(len(str(a))):
        c.add(next(d))
    if len(c) == 4:
        print(a)
        b = 0