It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
import io;
import sys;
import math;

def read_int():
	return map(int, raw_input().split());
	pass

if __name__ == '__main__':
	
	a = input();

	# jawab #
	def is_distinct(num) :
		ori = len(str(num));
		visited = set();
		while num > 0 :
			visited.add(num%10);
			num /= 10;
			pass
		if len(visited) == ori :
			return True;
		else :
			return False;
		pass
	a +=1 ;
	while True :
		if is_distinct(a) :
			print a;
			break;
		else :
			a += 1;

	pass