It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
t=int(input())
def diff_digits(n):
	p=[]
	while n>0:
		k=n%10
		n=n//10
		p.append(k)
	flag=1
	for i in range(4):
		for j in range(4):
			if p[i]==p[j] and i!=j:
				flag=0
				break
	return flag
h=0
i=t+1
while h!=True:
	h=diff_digits(i)
	i+=1
print(i-1)