It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
dp=[]
for i in range(1000,9000):
	k1 = i%10
	k2 = (i//10)%10
	k3 = (i//100)%10
	k4 = i//1000
	d={}
	d[k1]=0
	d[k2]=0
	d[k3]=0
	d[k4]=0
	if len(d)==4:
		dp.append(i)
dp.append(9012)
y = int(input())
for i in dp:
	if i>y:
		print(i)
		break
