It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n=int(input())
c=False
def distinct(n):
    s=str(n)
    c=False
    for x in range(0,len(s)-1):
        if(c==False):
            for y in range(x+1,len(s)):
                if(s[x]==s[y]):
                    c=True
                    break
                else:c=False
        else:
            break
    return(c)
n=n+1
c=distinct(n)
while(c==True):
    n=n+1
    c=distinct(n)
print(n)
