It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n=input()
n=int(n)+1
n=str(n)
while(True):
    a=[]
    for i in range(4):
        a.append(n[i])
    if int(a[0])!=int(a[1]) and int(a[0])!= int(a[2])and int(a[0])!=int(a[3]) and int(a[1])!=int(a[2]) and int(a[1])!=int(a[3]) and int(a[2])!=int(a[3]):
        break
    else:
        n=int(n)+1
        n=str(n)
for i in range(4):
    print(a[i],end="")
