It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def f(l,i):
	k = [0]*(len(l)-1)
	j = 0
	for jj in range(len(l)):
		if jj!=i:
			k[j] = l[jj]
			j += 1
	return k
def dis(n):
	l = []
	while n:
		l.append(n%10)
		n//=10
	for i in range(len(l)):
		k = f(l,i)
		if l[i] in k:
			return 0
	return 1
n = int(raw_input())+1
while True:
	if dis(n):
		print(n)
		break
	n += 1
