It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def check_if_beautiful(year_number):
    year_number_as_string = str(year_number)
    bucket = {}
    for digit in year_number_as_string:
        if digit in bucket:
            return False
        bucket[digit] = 0
    return True


def find_next_beautiful_number(year_number):
    while True:
        year_number += 1
        if check_if_beautiful(year_number):
            return year_number

if __name__ == '__main__':

    year_number = int(input())

    print(find_next_beautiful_number(year_number))
