It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def distinct_num(year):
    unique_year = 0
    new_year = year
    while unique_year == 0:
        checker = []
        new_year += 1
        for i in range(len(str(new_year))):
            if str(new_year)[i] in checker:
                break
            else:
                checker.append(str(new_year)[i])
        
        if len(checker) == 4:
            unique_year = int("".join(checker))  
    return unique_year

if __name__ == "__main__":
    year = int(input())
    print(distinct_num(year))