It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
year=int(input())
a1=year%10;
a2=(year%100)//10;
a3=(year%1000)//100;
a4=(year)//1000;

condition= True;

while(condition):
    year+=1;
    a1=year%10;
    a2=(year%100)//10;
    a3=(year%1000)//100;
    a4=(year)//1000;
    
    if(a1!=a2 and a1!=a3 and a1!=a4 and a2!=a3 and a3!=a4 and a2!=a4):
        condition=False;
        
print(a4,a3,a2,a1,sep='');