You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
const int INF = 1000000000;
const int MAXN = 5006;
long long C[MAXN];
long long M[MAXN * 11];
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  long long a;
  string s;
  while (cin >> a >> s) {
    C[0] = 0;
    for (int i = 0; i < (int)s.size(); ++i) C[i + 1] = C[i] + (s[i] - '0');
    memset(M, 0, sizeof M);
    long long todos = 0LL;
    for (int i = 0; i < (int)s.size(); ++i) {
      for (int j = i; j < (int)s.size(); ++j) {
        todos++;
        M[C[j + 1] - C[i]]++;
      }
    }
    long long res = 0LL;
    for (int i = 0; i < (int)s.size(); ++i) {
      for (int j = i; j < (int)s.size(); ++j) {
        long long tmp = C[j + 1] - C[i];
        if (tmp == 0) {
          if (a) continue;
          res += todos;
          continue;
        }
        if (a % tmp) continue;
        if (a / tmp > 10 * MAXN) continue;
        res += M[a / tmp];
      }
    }
    cout << res << endl;
  }
}
