It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
int main() {
  int a[4] = {};
  int y, b = 0, i, j, m = 1;
  cin >> y;
  while (b != 2) {
    y = y + 1;
    a[0] = y % 10;
    a[1] = (y % 100) / 10;
    a[2] = (y % 1000) / 100;
    a[3] = y / 1000;
    for (i = 0; i < 4; i++) {
      for (j = i + 1; j < 4; j++) {
        if (a[i] == a[j]) {
          b = 0;
          break;
        } else
          b = 1;
      }
      if (b == 0) break;
    }
    if (i == 4) b = 2;
  }
  cout << y;
  return 0;
}
