It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n=int(input())
for i in range(n+1,10000):
    a=[]
    d=i
    while(d>0):
        b=d%10
        a.append(b)
        d//=10
    count=0
    countb=0
    for j in range(3):
        for k in range(j+1,4):
            if(a[j]==a[k]):
                countb=1
                break
            elif(k==3 and a[j]!=a[k]):
                count+=1
        if(countb==1):
            break
    if(count==3):
        print(i)
        break
