You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
#pragma comment(linker, "/STACK:256000000")
int a;
string s;
int sum[4005][4005];
map<int, int> cnt;
long long ans;
map<int, int>::iterator it;
int cntz;
int find(int x) {
  it = cnt.find(x);
  if (it == cnt.end()) return 0;
  return it->second;
}
int main() {
  cin >> a >> s;
  s = "#" + s;
  int slen = s.length();
  for (int i = 1; i < slen; ++i) {
    for (int j = i; j < slen; ++j) {
      sum[i][j] = sum[i][j - 1] + s[j] - '0';
      ++cnt[sum[i][j]];
      cntz += !sum[i][j];
    }
  }
  if (a == 0) {
    for (int i = 1; i < slen; ++i) {
      for (int j = i; j < slen; ++j) {
        if (sum[i][j] == 0) {
          ans += slen * (slen - 1) / 2;
        } else
          ans += cntz;
      }
    }
  } else {
    for (int i = 1; i < slen; ++i) {
      for (int j = i; j < slen; ++j) {
        if (sum[i][j] && a % sum[i][j] == 0) {
          ans += find(a / sum[i][j]);
        }
      }
    }
  }
  cout << ans << endl;
  return 0;
}
