It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
y = input()
check = True
yes = True
yep = True
count = 0
while yep:
    while yes and count < 3:
        count = 0
        cont = True
        y_ = int(y)
        y_ += 1
        y = str(y_)
        for i in range(1, 3):
            if cont:
                for j in range(i+1, 4):
                    if y[i] == y[j]:
                        yes = True
                        cont = False
                        continue
                    else:
                        count += 1
            else:
                continue
    if y[0] == y[1] or y[0] == y[2] or y[0] == y[3]:
        yes = True
        count = 0
    else:
        print(y)
        yep = False
