It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
int t, ans, p, p1, p2, p3;
int main() {
  cin >> t;
  for (int i = t + 1; i <= 9100; i++) {
    ans = i;
    p = i;
    p1 = p % 10;
    p /= 10;
    p2 = p % 10;
    p /= 10;
    p3 = p % 10;
    p /= 10;
    if (p != p1 && p != p2 && p != p3 && p1 != p2 && p1 != p3 && p2 != p3)
      break;
  }
  cout << ans;
}
