It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n=int(input())
s=[]
n=n+1
i=3
f=0
l=n
while(n!=0):
    k=n//10**i
    n=n%10**i
    s.append(k)
    i=i-1
  
while(len(set(s))!=4):
    f=1
    del(s)
    s=[]
    n=l
    i=3
    p=4
    while(p!=0):
        k=n//10**i
        n=n%10**i
        s.append(k)
        i=i-1
        p=p-1

    l=l+1
if(f==0):
    print(l)
else:
    print(l-1)
    
    
