It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n = int(input())
numbs = []
for i in range(1000,9001):
  i = str(i)
  if i.count('0') < 2 and i.count('1') < 2 and i.count('2') < 2 and i.count('3') < 2 and i.count('4') < 2 and i.count('5') < 2 and i.count('6') < 2 and i.count('7') < 2 and i.count('8') < 2 and i.count('9') < 2 :
    numbs.append(int(i))
numbs.append(9012)    
for i in numbs:
  if n < i:
    print(i)
    break