It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
ip = str(int(input())+1)
count = 0;
while(count != 1):
    in1 = list(map(int,ip)) 
    unq = []
    for x in in1:
        if x not in unq:
            unq.append(x)
    if(len(ip) == len(unq)):
        print(''.join(map(str, unq)))
        count = 1
    else:
        ip = int(ip)+1
        ip = str(ip)