It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def distinct(n):
    n+=1
    m=n
    while True:
        lst=[]
        m=list(str(m))
        for i in range(len(m)):
            if m[i] not in lst:
                lst.append(m[i])
        if len(lst)==len(str(n)):
            return n
        n+=1
        m=n



t=int(input())
print(distinct(t))