It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#Beautiful Year


def compare_digits(year):
    temp = year+1
    while True:
        curr = [int(d) for d in str(temp)]
        #dankest if statement ever
        if (curr[0] != curr[1]
            and curr[0] != curr[2]
            and curr[0] != curr[3]
            and curr[1] != curr[2]
            and curr[1] != curr[3]
            and curr[2] != curr[3]):
            return temp
        else:
            temp += 1


year = int(input())
print(compare_digits(year))
