It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
int main() {
  int year;
  cin >> year;
  year = year + 1;
  int j = year, l, m, n, o;
  l = j % 10;
  j = j / 10;
  m = j % 10;
  j = j / 10;
  n = j % 10;
  j = j / 10;
  o = j % 10;
  j = j / 10;
  while (!(l != m && l != n && l != o && m != n && n != o && m != o)) {
    year++;
    j = year;
    l = j % 10;
    j = j / 10;
    m = j % 10;
    j = j / 10;
    n = j % 10;
    j = j / 10;
    o = j % 10;
    j = j / 10;
  }
  cout << o << n << m << l;
}
