It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
# your code goes here
y=int(input())
arr=[]
for i in range(y,9013):
	num = i
	visited = [0,0,0,0,0,0,0,0,0,0]
	while (num):
		if visited[num % 10] == 1:
			break
		visited[num % 10] = 1
		num = (int)(num // 10) 
	if num == 0:
		arr.append(i)
print(arr[list(map(lambda i: i> y, arr)).index(True)])