It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n=int(input())
def year(n):
    lst=[]
    for i in range(4):
        lst.append(int(n%10))
        n=n/10
        
    for i in range(4):
        a=lst[i]
        for j in range(4):
            if (a==lst[j])and(i!=j):
                return False
    return True

out=False
while(not out):
    n=n+1
    out=year(n)

print(n)