It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
import sys
def diff(num):
    lit = []
    for v in range(4):
        lit.append(num%10)
        num /=10
    if len(lit) == len(set(lit)):
        return 1
    else:
        return 0

if __name__ == '__main__':

    num1 = map(int,sys.stdin.readline().split())
    num = num1[0]
    while True:
        num+=1
        if diff(num) == 1:
            print num
            break
        else:
            pass