It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def isDistinct(year):
    digList = list()
    year = str(year)
    for dig in year:
        if dig not in digList:
            digList.append(dig)
    if len(digList)<4:
        return False
    else:
        return True
year = int(input())
distinctYears = list()
for i in range(1000,9000):
    if isDistinct(i):
        distinctYears.append(i)
if isDistinct(year):
    for i in range(len(distinctYears)):
        if distinctYears[i] == year:
            print(distinctYears[i+1])

else:
    while(not(isDistinct(year))):
        year +=1
    print(year)




