It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def Numero(m):
    a=-1
    i=0
    while(a==-1 and i<len(m)):
        k=i+1
        while k<len(m) and a==-1:
            if m[i]==m[k]:
                a=1
            k+=1
        i+=1
    return a
x=input()
a=1
b=[]
while(a==1):
    x=int(x)
    x+=1
    b=list(map(int, str(x)))
    a=Numero(b)
print(x)

        
