It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
int str_to_int(string);
string int_to_str(int);
int main() {
  string x;
  bool bol;
  cin >> x;
  x = int_to_str(str_to_int(x) + 1);
  while (true) {
    for (int i = 0; i < 4; i++) {
      for (int j = 0; j < 4; j++) {
        if (i == j) {
          bol = true;
        } else if (x[i] != x[j]) {
          bol = true;
        } else {
          bol = false;
          i = 3;
          break;
        }
      }
    }
    if (bol == true) {
      cout << x << endl;
      break;
    } else {
      x = int_to_str(str_to_int(x) + 1);
    }
  }
}
int str_to_int(string s) {
  int i = 0;
  for (unsigned int j = 0; j < s.length(); j++) {
    char c = s[j];
    i *= 10;
    i += ((int)c - 48);
  }
  return i;
}
string int_to_str(int i) {
  char s[5];
  for (int j = 0; j < 4; j++) {
    int z = i % 10;
    i /= 10;
    s[3 - j] = (char)(z + 48);
  }
  s[4] = '\0';
  return s;
}
