It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
int main() {
  int y, i;
  cin >> y;
  for (i = y + 1;; i++) {
    int n = i, d1, d2, d3, d4;
    d1 = n % 10;
    n /= 10;
    d2 = n % 10;
    n /= 10;
    d3 = n % 10;
    n /= 10;
    d4 = n;
    if (d1 != d2 && d1 != d3 && d1 != d4 && d2 != d3 && d2 != d4 && d3 != d4) {
      cout << i << "\n";
      break;
    }
  }
  return 0;
}
