You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
import java.util.*;
public class C {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int a, n;
        a = sc.nextInt();
        String s = sc.nextLine();
        s = sc.nextLine();
        n = s.length();
        long ret = 0;
        int calc[] = new int[37231];
        for(int i = 0; i < n; ++i) {
            int sums = (s.charAt(i) - 48);
            calc[sums]++;
            for(int j = i + 1; j < n; ++j) {
                sums = sums + s.charAt(j) - 48;
                calc[sums]++;
            }
        }
        if(a == 0) {
            for(int i = 1; i < 9*4001; ++i) {
                ret += (long)calc[i]*(long)calc[0];
            }
            ret *= 2;
            ret += (long)calc[0]*(long)calc[0];
        }
        else 
            {
            for(int i = 1; i <= 9*4001; ++i) {
                if(a % i != 0 || a/i > 9*4001) continue;
                ret = ret + (long)calc[i] * (long)calc[a / i];
            }
        }
        System.out.println(ret);
    }
}