It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
int distinct(int n) {
  int temp = n;
  int no_of_digits = 0;
  while (n > 0) {
    n /= 10;
    no_of_digits++;
  }
  int a[no_of_digits];
  int counter = 0;
  while (temp > 0) {
    a[counter] = temp % 10;
    temp /= 10;
    counter++;
  }
  for (int i = 0; i < no_of_digits; i++) {
    for (int j = i + 1; j < no_of_digits; j++) {
      if (a[i] == a[j]) {
        return -1;
      }
    }
  }
  return 1;
}
int main() {
  int n;
  cin >> n;
  for (n = n + 1; distinct(n) != 1; n++) {
  }
  cout << n;
  return 0;
}
