It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
year = int(raw_input())
ye_ar = year+1
cnt = 0
while True:
    Year = list(str(ye_ar))
    i = 0
    while i in range(len(Year)):
        if Year.count(Year[i])>1:
            cnt = cnt+1
        i = i+1
    if cnt ==0:
        print ye_ar
        break
    ye_ar = ye_ar+1
    cnt = 0