It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
int checkYear(int num) {
  int arr[4];
  int n = 0, temp, r;
  temp = num;
  while (temp != 0) {
    r = temp % 10;
    arr[n] = r;
    temp = temp / 10;
    n++;
  }
  for (int i = 0; i < 4; i++) {
    for (int j = i + 1; j < 4; j++) {
      if (arr[j] == arr[i]) {
        return 0;
      }
    }
  }
  return 1;
}
int main() {
  int number;
  scanf("%d", &number);
  number++;
  while (1) {
    if (checkYear(number)) {
      printf("%d\n", number);
      break;
    }
    number++;
  }
}
