It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
import sys
import math as mt
input=sys.stdin.buffer.readline  
#t=int(input())
t=1
for __ in range(t):
    #n,m=map(int,input().split())
    #n=int(input())
    y=int(input())
    
    for i in range(y+1,9013):
        l1=[]
        j=i
        
        while j>0:
            l1.append(j%10)
            j//=10
        if len(set(l1))==4:
            print(i)
            break
            
    #l=list(map(int,input().split()))
    