It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def compare(s,a):
     s=str(s)
     c=1
     for b in range(0,4):
         if a!=b and s[b]==s[a]:
             c=0
             break

     if c==1:
         return True
     else:
         return False
            

s=int(input())

count=s+1
c=0
b=0
while c==0:
    for a in range(0,4):
        if compare(count,a)==False:
            b=1
    if b==1:
         count+=1
       
         b=0
    else:
        c=1
         
             
        

        
                
print(count)                
