It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014


def test(num):
	str1 = str(num)
	a,b,c,d = str1
	if (str1.count(a) == 1) and  (str1.count(b) == 1) and (str1.count(c)==1) and (str1.count(d) == 1):
		return True
	else:
		return False





def main():
	year = input() + 1
	while(True):
		if (test(year)):
			print year
			return
		year+=1




main()