You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

* 1 \leq |S| \leq 2 \times 10^5
* |S| = |T|
* S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:


S
T


Output

If S and T can be made equal, print `Yes`; otherwise, print `No`.

Examples

Input

azzel
apple


Output

Yes


Input

chokudai
redcoder


Output

No


Input

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu


Output

Yes
#include<bits/stdc++.h>
#define REP(i,n) for(int i=0;i<(n);i++)
#define ALL(v) (v).begin(),(v).end()
#define int long long
using namespace std;
typedef vector<int>   vint;
typedef pair<int,int> pint;

signed main()
{
    string s,t; cin>>s>>t;

    vector<int> a(26),b(26);
    REP(i,s.size()) a[s[i]-'a']++;
    REP(i,t.size()) b[t[i]-'a']++;
    sort(ALL(a)); sort(ALL(b));

    cout<<(a==b? "Yes":"No")<<endl;
}
