It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
import math

year = int(raw_input())


while(1):
    year += 1
    a = math.floor(year/1000)
    b = math.floor((year/100)%10)
    c = math.floor((year/10)%10)
    d = math.floor(year%10)

    if((a!=b)and(a!=c)and(a!=d)and(b!=c)and(b!=d)and(c!=d)):
        break

print year
