It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def f(y):
    d = {}
    while y > 0:
        r = y%10
        if r not in d:
            d[r] = 1
        else:
            d[r] += 1
        y = y//10
    if len(d) == 4:
        return 1
    else:
        return 0
y = int(input())
an = 0
while an != 1:
    y+=1
    an = f(y)
print(y)