It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def digitos_diferentes(num):
	if num[0] == num[1]: return False
	if num[0] == num[2]: return False
	if num[0] == num[3]: return False
	if num[1] == num[2]: return False
	if num[1] == num[3]: return False
	if num[2] == num[3]: return False
	return True

filho_do_coqueiro = int(raw_input())

for n in xrange(1000,9013,1):
	if digitos_diferentes(str(n)):
		if n > filho_do_coqueiro:
			print n
			break
