It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def checkDistinct(n):
    t = []
    for i in range(4):
        t.append(n % 10)
        n //= 10
    for i in range(2):
        t[i], t[3-i] = t[3-i], t[i]
    for i in range(4):
        for j in range(i+1, 4):
            if t[i] == t[j]:
                return 0
    return t        
y = int(input())
num = 0
for i in range(1,150):
    x = y + i
    check = checkDistinct(x)
    if check != 0:
        for i in range(4):
            num *= 10
            num += check[i]
        print(num)
        break
    