You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
const int MAXN = 50000;
int w[50005];
int sum[50005];
int main() {
  string s;
  int a;
  while (cin >> a) {
    cin >> s;
    int len = s.size();
    memset(w, 0, sizeof(w));
    memset(sum, 0, sizeof(sum));
    for (int i = 1; i <= len; i++) {
      sum[i] = s[i - 1] - '0';
    }
    for (int i = 1; i <= len; i++) sum[i] = sum[i - 1] + sum[i];
    for (int i = 1; i <= len; i++)
      for (int j = 1; j <= i; j++) w[sum[i] - sum[j - 1]]++;
    long long ans = 0L;
    if (a > 0) {
      for (int i = 1; i <= MAXN; i++) {
        if (a % i == 0) {
          if (a / i >= MAXN) continue;
          ans += (long long)w[i] * (long long)w[a / i];
        }
      }
    } else {
      for (int i = 1; i <= MAXN; i++) {
        if (w[i]) ans += (long long)w[i] * (long long)w[0];
      }
      ans *= 2L;
      ans += (long long)w[0] * (long long)w[0];
    }
    cout << ans << endl;
  }
}
