It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def Distinct(y):
              y1 = str(y)
              if y1[0] != y1[1] and y1[0] != y1[2] and y1[0] != y1[3]:
                            if y1[1] != y1[2] and y1[1] != y1[3] and y1[2] != y1[3]:
                                          return 1
              else:
                            return 0
             
def Year(y):
              for i in range(y + 1, 1000000000000):
                            if Distinct(i) == 1:
                                          return i
x = int(input())
print(Year(x))