It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
# -*- coding: utf-8 -*-
"""
Created on Sun Sep 10 09:14:03 2017

@author: svpopo18
"""


def Check(s):
    flag = True
    for i in s:
        if s.count(i) > 1:
            flag = False
            break
    return flag


def Year(s):
    s = str(int(s) + 1)
    while Check(s) is not True:
        s = str(int(s) + 1)
    return s

y = input()

print(Year(y))
