It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
a = raw_input()
p = int (a)+1
x=range(p,90000)
years = []
for i in x:
    w = str(i)
    while len(years) < 5:
        if w[0] == w[1]:
            break
        elif w[0] == w[2]:
            break
        elif w[0] == w[3]:
            break
        elif w[1] == w[2]:
            break
        elif w[1] == w[3]:
            break
        elif w[2] == w[3]:
            break
        else:
            years.append(w)
            break

print int(years[0])
