It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def Beautiful(n):
	a=[0]*10
	b=[0,1,2,3,4,5,6,7,8,9]
	s=str(n)
	for i in s:
		for j in range(10):
			if(int(i)==b[j]):
				a[j]+=1
	count=0
	for k in range(10):
		if(a[k]==1):
			count=count+1
	if(count==4):
		return True
	else:
		return False	
y=input()
if(1000<=y<=9000):
	x=y+1
	while(Beautiful(x)!=True):
		x=x+1
	print x
