It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
y_string = input()
# y = list(map(int,list(str(int(y) + 1))))
y = int(y_string)
y += 1
# while True:
#     output += 1
#     # print(output)
#     if len(set(str(output))) == len(y):
#         print(output)
#         break

while True:
    # print(y)
    if len(set(str(y))) != len(str(y)):
        if y_string[0] == y_string[1]:
            y += 100
            y_string = list(str(y))
            y_string[2] = y_string[3] = '0'
            y = int(''.join(y_string))
        elif y_string[1] == y_string[2]:
            y += 10
            y_string = list(str(y))
            y_string[3] = '0'
            y = int(''.join(y_string))
        else:
            y += 1
        # break
    else:
        print(y)
        break