It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#!/usr/bin/env python3
# -*- coding: utf-8 -*-
"""
Created on Tue Dec  3 22:37:14 2019

@author: wwy
"""

start = int(input())
for i in range(8000):
    year = start + i+1
    x = str(year)
    if x[0] != x[1] and x[0] != x[2] and x[0] != x[3] and x[1] != x[2] and x[1] != x[3] and x[2] != x[3]:
        print(x)
        break