It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
int main() {
  int n, i, temp, flag, d[10] = {0};
  scanf("%d", &n);
  while (1) {
    n++;
    temp = n;
    while (temp) {
      d[temp % 10]++;
      temp /= 10;
    }
    flag = 0;
    for (i = 0; i < 10; i++)
      if (d[i] > 1) {
        flag = 1;
      }
    for (i = 0; i < 10; i++) d[i] = 0;
    if (!flag) {
      printf("%d\n", n);
      return 0;
    }
  }
  return 0;
}
