It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
year = input()

def checkDuplicates(arr):
  for i in range(len(arr)):
    for j in range(i+1,len(arr)):
      if arr[i]==arr[j]:
        return 0
  return 1

def check(year):
  arr = [item for item in str(year)]
  if checkDuplicates(arr)==1:
    print(''.join(arr))
    return 1
  else:
    return 0

for i in range(int(year)+1,9013):
  if check(i)==1:
    break