It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
import math

a = []
#n = int(input())
c = 0
#b = int(input())
i = 0
j = 0
b = 0
arr = input()


#for i in range(n):
#    a.append([int(j) for j in input().split()])
    
#a, b, c = map(int, input().split())

#a.append([int(j) for j in input().split()])

c = int(arr) + 1

while c < 10000:
    k = str(c)
    b = 0
    for i in range(len(k)):
        #print(k)
        j = i + 1
        while j < len(k):
            if (k[j] != k[i]):
                b += 1  
                #print(b)
            j += 1
    if (b == 6):
        print(c)
        break
    c += 1