It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def ch(d):
    d = str(d)
    l = []
    for i in d:
        l.append (i)
    if l.count(l[0]) == 1 and l.count(l[1]) ==1 and l.count(l[2]) == 1 and l.count(l[3]) == 1:
        return True 
    else:
        return False
        
def incr(x):
    x += 1
    while ch(x) == False:
         x+=1
    print(x)
 
x = int(input())
incr(x)