You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
int x[4010];
int drept[100010];
int main() {
  int a, n;
  int total = 0;
  string s;
  cin >> a >> s;
  n = s.size();
  for (int i = 1; i <= s.size(); i++) x[i] = x[i - 1] + s[i - 1] - '0';
  for (int i = 1; i <= n; i++)
    for (int j = i; j <= n; j++) drept[x[j] - x[i - 1]]++, total++;
  long long rez = 0;
  for (int i = 1; i < 10 * s.size(); i++) {
    if (drept[i] != 0 && a % i == 0 && a / i < 10 * s.size())
      rez += 1ll * drept[i] * drept[a / i];
  }
  if (a == 0) rez += 1ll * drept[0] * total;
  cout << rez;
  return 0;
}
