It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
### codeforce_gen_9
def check(y):
    y = list(str(y))
    for i in range(0, len(y)):
        y[i] = int(y[i])
    c = 0
    mem = []
    for i in y:
        if i in mem:
            c += 1
            break
        mem.append(i)
    if c == 0:
        mem.clear()
        return True
    else:
        mem.clear()
        return False


year = int(input())
year = year + 1
while not check(year):
    year += 1
print(year)
