It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n=list(input())
n[0]=int(n[0])
n[1]=int(n[1])
n[2]=int(n[2])
n[3]=int(n[3])+1
while(1):
    if((n[0]==n[1])or(n[1]==n[2])or(n[2]==n[3])or(n[0]==n[2])or(n[0]==n[3])or(n[1]==n[3])or(n[3]>=10)):
        n[3]=n[3]+1
        if(n[3]>=10):
            n[2]=n[2]+1
            n[3]=0
            if(n[2]==10):
                n[1]=n[1]+1
                n[2]=0
                if(n[1]==10):
                    n[0]=n[0]+1
                    n[1]=0
    else:
        no=(n[0]*1000)+(n[1]*100)+(n[2]*10)+n[3]
        break
    

print(no)