It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
'''x = input()
new_num = int(x) + 1
new_str = str(new_num)
y = 0

for i in range(2):
	for i in range(4):
		y = new_str.count(new_str[i]) 
		if y >= 2:
			while y >= 2:
				new_num += 1
				new_str = str(new_num)
				y = new_str.count(new_str[i])

		
print(new_num)
'''

def distinct_digits(year):
	str_year = str(year)
	my_nums = {}
	for char in str_year:
		if char in my_nums:
			my_nums[char] += 1
		else:
			my_nums[char] = 1
	for value in my_nums.values():
		if value > 1:
			return False
	return True

year = int(input())+1
while(not distinct_digits(year)):
	year += 1
print(year)


