It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def u(l1):
    u1=[]
    for i in l1:
        if i not in u1:
            u1.append(i)
    return u1
t=int(input())
if t==9000:
    print('9012')
else:
    for i in range(t+1,9013):
        i=str(i)
        i=list(i)
        l1=len(i)
        i=u(i)
        f=''.join(map(str,i))
        f=int(f)
        if l1==len(i):
            print(f)
            break
