It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
from sys import stdin


def is_distinct(N):
    dig = []
    for i in range(4):
        r = N % 10
        if r in dig:
            return False
        else:
            dig.append(r)
        N = N/10

    return True


def func_name(N):
    N += 1
    while not is_distinct(N):
        N += 1
    return N

if __name__ == '__main__':
    '''
    - Use following methods
        * stdin.readlines() to read all lines
        * stdin.readline() to read a line
        * stdin.read()
        * rstrip()
        * split()
    '''
    N = int(stdin.readline().rstrip())
    print func_name(N)
