It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def check_equality():
    if a not in [b, c, d] and b not in [c, d] and c != d:
        print(int(''.join(str(i) for i in [a, b, c, d])))
        exit()


digit = str(int(input()) + 1)
a, b, c, d = [int(x) for x in digit]

for a in range(a, 10):
    check_equality()
    for b in range(b, 10):
        check_equality()
        for c in range(c, 10):
            check_equality()
            for d in range(d, 10):
                check_equality()
            d = 0
        c = 0
    b = 0
