It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
int main() {
  float x;
  int y, z, h, i;
  scanf("%f", &x);
  if (x >= 1000 && x <= 9000 && (int)x - x == 0) {
    x++;
    y = x / 1000;
    z = (x / 100) - (10 * y);
    h = (x / 10) - (100 * y) - (10 * z);
    i = (int)x % 10;
    while (y == z || y == h || y == i || z == h || z == i || h == i) {
      x++;
      y = x / 1000;
      z = (x / 100) - (10 * y);
      h = (x / 10) - (100 * y) - (10 * z);
      i = (int)x % 10;
    }
    printf("%.0f", x);
  } else
    printf("Error");
  return 0;
}
