It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#!/usr/bin/env python3

input_year = int(input())
test_year = input_year
# input year is 4 digits, so we create a dictionary and add each digit.
# if len is 4, then the digits are all different.

def distinct_digits_check(n):
    n_str = str(n)
    digit_dict = {}
    for s in n_str:
        digit_dict[s] = 0
    return len(digit_dict)

year_digits = 0

while year_digits != 4:
    test_year += 1
    year_digits = distinct_digits_check(test_year)
print(test_year)