It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#https://codeforces.com/problemset/problem/271/A
current_year = int(input())

def find_year(current_year):
  unique = False
  current_check = current_year +1
  lst_digits = []
  while unique == False:
    for current_num in str(current_check):
      lst_digits.append(int(current_num))
  
    if len(lst_digits) == len(set(lst_digits)):
      unique = True
      print (current_check)
    else:
      lst_digits = []
      current_check += 1


find_year(current_year)
    
  
