It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
y=input()+1
def chek(y):
    z=0
    s=str(y)
    l=list(s)
    l.sort()
    for i in range(0,3):
        if(l[i]!=l[i+1]):
            z=z+1    
            if(z==3):
                return 1
while(1):
    if(chek(y)==1):
        print int(y)
        break
    else:
        y=y+1
    