It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def f(n):
    b=n
    i=0
    a=[]
    while (n>0):
        a.append(n%10)
        n=n//10
    a.reverse()
    while True:
        if(a.count(a[i])<=1):
            i=i+1
            if(i==(len(a)-1)):
                return b
        else:
            break
    return f(b+1)
n=int(input())
x=f(n+1)
print(x)
            
