It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n = str(input())
y = int(n)
list1 = []
list2 = []
for char in n:
  list1.append(char)
while True:
  y += 1
  n1 = str(y)
  for char1 in n1:
    list2.append(char1)
  if list2[0] != list2[1] and list2[1] != list2[2] and list2[2] != list2[3] and list2[0] != list2[2] and list2[0] != list2[3] and list2[1] != list2[3]:
    print(y)
    break
  else:
    list2.clear()
    continue

