It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
y = int(raw_input())

y += 1

while True:
	list_digit = []
	m = y
	while (m>0):
		list_digit.append(m%10)
		m = m / 10
	f = True
	for i in range(len(list_digit)):
		flag = True
		for j in range(len(list_digit)):
			if((list_digit[j] == list_digit[i]) and (i != j)):
				flag = False
				break
		if (not flag):
			f = False
			break
	if (f):
		print y
		break
	y += 1