It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014

def unique(number):
	List = []
	while number != 0:
		Mod = number%10
		if Mod in List:
			return False
		List.append(Mod)
		number = int(number/10)
	return True

now = int(input())
year = now+1
while year < 9013:
	if unique(year):
		print(year)
		exit(0)
	else:
		year += 1
