It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def digit(n):
    check = [0] * 4
    x = 3
    while n > 9:
        check[x] += (n % 10)
        n = n // 10
        x -= 1
    if n <= 9:
        check[0] += n
    mark = [0] * 10
    for i in check:
        mark[i - 1] += 1
        if mark [i - 1] == 2:
            return False
    return True
n = int(input())
while True:
    n += 1
    if digit(n):
        print(n)
        break
    
    
    
    