You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
const int MAXN = 5000;
int cntarr[MAXN * 10];
long long ans;
int arr[MAXN];
char s[MAXN];
int a, ln;
void fillmap(int x) { cntarr[x]++; }
void getans(int x) {
  if (x == 0) {
    if (a == 0) ans += (ln * (ln + 1)) / 2;
  } else if (a % x == 0 && a / x < MAXN * 9)
    ans += cntarr[a / x];
}
void loop(void (*fun)(int)) {
  int sm = 0;
  for (int i = 0; i < ln; i++) {
    sm = arr[i];
    for (int j = i; j < ln; j++) {
      if (j != i) sm += arr[j];
      fun(sm);
    }
  }
  return;
}
int main() {
  scanf("%d %s", &a, s);
  ans = 0;
  ln = strlen(s);
  for (int i = 0; i < ln; i++) arr[i] = s[i] - '0';
  loop(fillmap);
  loop(getans);
  cout << ans << endl;
}
