It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def checking(year):
	first_d = int(year / 1000)
	second_d = int((year / 100) % 10)
	third_d = int((year / 10) % 10)
	fourth_d = int(year % 10)

	if first_d != second_d and first_d != third_d and first_d != fourth_d and second_d != third_d and second_d != fourth_d and third_d != fourth_d:
		return True
	else:
		return False


year = int(input())
year = year + 1
while True:
	isDistinct = checking(year)
	if isDistinct == True:
		print(year)
		break
	else:
		year = year + 1