You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
long long t, s1, s2, a[4444], n, b[4444], leng, ans, tt[5555555];
string s;
int main() {
  cin >> n;
  cin >> s;
  leng = s.length();
  t = 0;
  for (long long i = 0; i < s.length(); i++) {
    a[i + 1] = int(s[i] - 48);
    t += a[i + 1];
  }
  for (long long i = 1; i <= leng; i++) b[i] = b[i - 1] + a[i];
  tt[0] = 0;
  for (long long i = 1; i <= leng; i++) {
    for (long long j = i; j <= leng; j++) {
      tt[b[j] - b[i - 1]]++;
    }
  }
  ans = 0;
  if (n != 0) {
    for (long long i = 1; i <= 36000; i++) {
      if (n % i == 0) {
        if (n / i <= 36000) {
          s1 = tt[i];
          s2 = tt[n / i];
          ans += (s1 * s2);
        }
      }
    }
    cout << ans;
  }
  long long c;
  if (n == 0) {
    c = 0;
    for (long long i = 0; i <= t; i++) {
      c += tt[i];
      if (i >= 1) ans += tt[i] * tt[0];
    }
    cout << tt[0] * c + ans;
  }
}
