It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
int main() {
  long n, i, j, c, p, a[10];
  while (cin >> n) {
    j = 0;
    for (i = n + 1;; i++) {
      c = 0;
      p = i;
      j = 0;
      while (p != 0) {
        a[j++] = p % 10;
        p /= 10;
      }
      sort(a, a + j);
      for (int k = 0; k < j - 1; k++) {
        if (a[k] == a[k + 1]) {
          c = 1;
          break;
        }
      }
      if (c == 0) {
        cout << i << endl;
        break;
      }
    }
  }
  return 0;
}
