It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def distinct(year):
    distinct_count = set()
    c = 0
    while year:
        last_num = year%10
        year = year//10
        c = c + 1 
        distinct_count.add(last_num)
    if len(distinct_count) == c :
        return True
    else:
        return False        
    


if __name__ == "__main__":
    year = int(input())
    while True:
        year = year + 1
        if distinct(year) is True:
            break
        else:
            continue
    print(year)    