It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
inp=input()
b=str(inp)

def digit_differ(x):
    a=str(x)
    flag=1
    for i in range(4):
        for j in range(4):
            if i!=j:
                if a[i]==a[j]:
                    return 0
    return 1


inp=inp+1
while True:
    if digit_differ(inp):
        break
    inp=inp+1

print inp
