It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
Input_year = input()
# Input_year = "2013"
intano = int(Input_year) + 1

texto_ano = list(str(intano))

cont1 = texto_ano.count(texto_ano[0])
cont2 = texto_ano.count(texto_ano[1])
cont3 = texto_ano.count(texto_ano[2])
cont4 = texto_ano.count(texto_ano[3])

achou = False
while (achou != True):
    if(cont1+cont2+cont3+cont4 == 4):
        resposta = texto_ano[0] + texto_ano[1] + texto_ano[2] + texto_ano[3]   
        print(resposta)
        achou = True

    else:
        intano += 1
        texto_ano = list(str(intano))
        cont1 = texto_ano.count(texto_ano[0])
        cont2 = texto_ano.count(texto_ano[1])
        cont3 = texto_ano.count(texto_ano[2])
        cont4 = texto_ano.count(texto_ano[3])
		   		   	 					   	    	 		 	