It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
import re
def inp():
    return(int(input()))
def inlt():
    return(list(map(int,input().split())))
def insr():
    s = input()
    return(list(s[:len(s) - 1]))
def invr():
    return(map(int,input().split()))
def distinct(n):
    for i in n:
        if n.count(i)>1:
            return False
    return True
def ntol(n):
    a=[]
    while n>0:
        x=n%10
        a.append(x)
        n//=10
    return a
n=inp()
i=n+1
while True:
    if distinct(ntol(i))==True:
        print(i)
        break
    else:
        i+=1
    