It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def appropriate(y):
    for i in range(3):
        for j in range(i+1, 4):
            if y[i]==y[j]: return False
    return True
def inc(y):
    for i in range(3, -1, -1):
        if y[i]<9: 
            y[i]+=1
            return y
        else:
            y[i]=0
        
y = [int(c) for c in input()]
inc(y)
while (not appropriate(y)):
    inc(y)
for c in y:
    print(c, end="")