You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
int a;
char st[4444];
int sum[4444];
map<int, int> p;
long long ans = 0;
int len, tot;
int main() {
  cin >> a;
  scanf("%s", st);
  for (int i = 0, j = strlen(st); i < j; i++) {
    sum[i + 1] = sum[i] + st[i] - '0';
  }
  for (int i = 1, len = strlen(st); i <= len; i++)
    for (int j = 1; j <= i; j++) {
      p[sum[i] - sum[j - 1]]++;
      tot++;
    }
  if (a == 0) {
    ans = 1ll * p[0] * p[0];
    ans += 2ll * p[0] * (tot - p[0]);
  } else
    for (int i = 1, len = (int)sqrt(a + 1); i <= len; i++) {
      if (a % i != 0) continue;
      int j = a / i;
      long long tmp;
      if (i != j)
        tmp = 2ll * p[i] * p[j];
      else
        tmp = 1ll * p[i] * p[i];
      ans += tmp;
    }
  cout << ans << endl;
}
