It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def nextYear(n):
    a, b = [], []
    n = str(n)
    for i in n:
        a.append(i)
    for k in a:
        if k not in b:
            b.append(k)
            
    if b == a:
        return True
    else:
        return False
n = int(input())    
if nextYear(n) == False:
    while nextYear(n) == False:
        n+=1
    print(n)
else:
    while True:
        if nextYear(n+1) == True:
            print(n+1)
            break
        n+=1

