It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def main():
    current_year = int(input())
    new_year = current_year + 1





    while True :
        input_list = str(new_year)
        if int(input_list[0]) == int(input_list[1]) or int(input_list[0]) == int(input_list[2]) or int(input_list[0]) == int(input_list[3]) or int(input_list[1]) == int(input_list[2]) or int(input_list[1]) == int(input_list[3]) or int(input_list[2]) == int(input_list[3]):
            dist = False
        else:
            dist = True
        if dist is True :
            print(input_list)
            break
        new_year = new_year + 1


if __name__ == '__main__':
    main()
