It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
y = int(input())

cnt = 0
my_list = []

while len(my_list) < 4 :
    y += 1
    new_year = y
    while new_year:
        rem = int(new_year % 10)
        if rem in my_list :
            my_list = []
            break
        else :
            my_list.append(rem)
        new_year= int(new_year/10)

rev_list = my_list[::-1]
for s in rev_list:
    print(s, end='')
