It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014

y=input()

count=0

while len(set(str(y)))!=len(str(y)):
    x=''.join(y)
    x=int(x)
    x+=1
    y=str(x)
    count+=1
else:
    if len(set(str(y)))==len(str(y)) and count!=0:
        print(x)
    elif len(set(str(y)))==len(str(y)) and count==0:
        while True:
            x=''.join(y)
            x=int(x)
            x+=1
            y=str(x)
            if len(set(str(y)))==len(str(y)):
                print(x)
                break
