It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
x = list(map(int,input()))
i = 1
t = 0
while i :
    if x[3] <= 10 :
        x[3] = x[3] + 1
        if x[3] == 10 :
            x[3] = 0
            x[2] += 1
    if x[2] == 10 :
        x[2] = 0
        x[1] = x[1] + 1
    if x[1] == 10 :
        x[1] = 0
        x[0] += 1
    if x[0] != x[1] and x[0] != x[2] and x[0] != x[3] and x[1] != x[2] and x[1] != x[3] and x[2] != x[3]:
        i = 0

x = map(str,x)
print("".join(x))
