A permutation of length n is a sequence of integers from 1 to n of length n containing each number exactly once. For example, [1], [4, 3, 5, 1, 2], [3, 2, 1] are permutations, and [1, 1], [0, 1], [2, 2, 1, 4] are not.

There was a permutation p[1 ... n]. It was merged with itself. In other words, let's take two instances of p and insert elements of the second p into the first maintaining relative order of elements. The result is a sequence of the length 2n.

For example, if p=[3, 1, 2] some possible results are: [3, 1, 2, 3, 1, 2], [3, 3, 1, 1, 2, 2], [3, 1, 3, 1, 2, 2]. The following sequences are not possible results of a merging: [1, 3, 2, 1, 2, 3], [3, 1, 2, 3, 2, 1], [3, 3, 1, 2, 2, 1].

For example, if p=[2, 1] the possible results are: [2, 2, 1, 1], [2, 1, 2, 1]. The following sequences are not possible results of a merging: [1, 1, 2, 2], [2, 1, 1, 2], [1, 2, 2, 1].

Your task is to restore the permutation p by the given resulting sequence a. It is guaranteed that the answer exists and is unique.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 400) — the number of test cases. Then t test cases follow.

The first line of the test case contains one integer n (1 ≤ n ≤ 50) — the length of permutation. The second line of the test case contains 2n integers a_1, a_2, ..., a_{2n} (1 ≤ a_i ≤ n), where a_i is the i-th element of a. It is guaranteed that the array a represents the result of merging of some permutation p with the same permutation p.

Output

For each test case, print the answer: n integers p_1, p_2, ..., p_n (1 ≤ p_i ≤ n), representing the initial permutation. It is guaranteed that the answer exists and is unique.

Example

Input


5
2
1 1 2 2
4
1 3 1 4 3 4 2 2
5
1 2 1 2 3 4 3 5 4 5
3
1 2 3 1 2 3
4
2 3 2 4 1 3 4 1


Output


1 2 
1 3 4 2 
1 2 3 4 5 
1 2 3 
2 3 4 1 
import java.io.* ;
import java.util.* ;
 
 
public class App {
    public static void main (String[] args) throws java.lang.Exception {
		BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
        //reader = new BufferedReader(new FileReader(new File("C:\\Users\\Anjali\\Desktop\\projects\\HelloWorld\\src\\input.txt")));
		BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(System.out));
        //writer = new BufferedWriter(new FileWriter(new File("C:\\Users\\Anjali\\Desktop\\projects\\HelloWorld\\src\\output.txt")));
		//int tests = Integer.parseInt(reader.readLine());
        int tests = 1;
		//StringBuilder sb = new StringBuilder(tests);
		while (tests-- > 0){
		    solve(reader, writer);
            writer.write("\n");
		}
		reader.close();
        writer.flush();
        writer.close();
    }

 
    static void solve(BufferedReader reader, BufferedWriter writer) throws  IOException {
		int tests = Integer.parseInt(reader.readLine());
		for (int l = 0; l < tests; l++) {
			int n = Integer.parseInt(reader.readLine());
			int a = 2 * n;
			int[] arr = new int[a];
			String[] input = reader.readLine().split(" ");
			for (int i = 0; i < a; i++) {
				arr[i] = Integer.parseInt(input[i]);
			}
			for (int i = 0; i < a; i++) {
				for (int k = i + 1; k < a; k++) {
					if (arr[i] == arr[k]) {
						for (int j = k + 1; j < a; j++) {
							arr[j - 1] = arr[j];
						}
						a--;
					}
				}
			}
			for(int i = 0; i < a; i++) {
				writer.write(arr[i] + " ");
			}
			writer.write("\n");
		}
    }
}

