It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n = int(input())
def checkNumbers(x):
    n1=x//1000
    n2=(x//100)%10
    n3=(x//10)%10
    n4=x%10
    if (n1!=n2 and n1!=n3 and n1!=n4 and n2!=n3 and n2!=n4 and n3!=n4):
        return True
    return False

i = n+1
while (True):
    if checkNumbers(i):
        print (i)
        break
    i+=1
