It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#!/usr/bin/env python

def is_distinct(y):
	ans = True
	for i in xrange(len(y)):
		for z in xrange(i+1,len(y)):
			if y[i] == y[z]:
				ans = False
				break
		if not ans:
			break
	return ans

year = raw_input()

ans = None
# for i in xrange(int(year)+1,9001):
i = int(year) + 1
while True:
	if is_distinct(str(i)):
		ans = i
		break
	i += 1
print ans

