You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
const int MAXN = 4100;
char s[MAXN];
long long int pre[MAXN];
map<long long int, int> m;
int main() {
#pragma warning(disable : 4996)
  int a, len;
  long long int ans = 0;
  scanf("%d %s", &a, s);
  len = strlen(s);
  for (int i = 1; i <= len; i++) {
    pre[i] = pre[i - 1] + (s[i - 1] - '0');
  }
  for (int i = 1; i <= len; i++) {
    for (int j = 1; j <= i; j++) {
      m[pre[i] - pre[j - 1]]++;
    }
  }
  for (auto p : m) {
    if (p.first == 0) {
      if (a == 0) ans += (len * (len + 1) / 2) * (long long int)p.second;
      continue;
    }
    if (a % p.first != 0) continue;
    auto it = m.lower_bound(a / p.first);
    if (it != m.end() && it->first == a / p.first) {
      ans += it->second * (long long int)p.second;
    }
  }
  printf("%lld", ans);
  return 0;
}
