It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def f(a):
	if a[0] != a[1] and a[0] != a[2] and a[0] != a[3] and a[1] != a[2] and a[1] != a[3] and a[2] != a[3]:
		print(a[0]+a[1]+a[2]+a[3])
		return
	else:
		if a[0]== a[1]:
			a[1]= str(int(a[1])+1)
			a[2]=a[3]="0"
		if a[1]== a[2] or a[0]== a[2]:
			if a[2]== "9":
				a[0]= str(int(a[0])+1)
				a[3]=a[2]=a[1]="0"
			else:
				a[2]= str(int(a[2])+1)
				a[3]="0"
		if a[0] == a[3] or a[1]== a[3] or a[2]== a[3]:
			if a[1]== a[3]=="9":
				a[2]=str(int(a[2])+1)
				a[3]= "0"
			elif a[2]== a[3]=="9":
				a[1]=str(int(a[1])+1)
				a[2]== a[3]=="0"
			else:
				a[3]= str(int(a[3])+1)
		f(a)
a= list(input())
if a[3]== a[2]== a[1]== "9":
	a[0]= str(int(a[0])+1)
	a[3]= a[2]= a[1]= "0"
elif a[3]== a[2]== "9":
	a[1]= str(int(a[1])+1)
	a[3]= a[2]= "0"
elif a[3]== "9":
	a[2]= str(int(a[2])+1)
	a[3]="0"
else:
	a[3]= str(int(a[3])+1)
f(a)