It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def check(x):
    x1 = x % 10
    x //= 10
    x2 = x % 10
    x //= 10
    x3 = x % 10
    x //= 10
    if x != x1 and x != x2 and x != x3 and x1 != x2 and x1 != x3 and x2 != x3:
        return True
    return False


def year(n):
    n += 1
    while not check(n):
        n += 1
    return n


print(year(int(input())))
