It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#xyz = str(input()+1)
#def check_freq(a):
#    freq = {}
#    for c in a:
#       freq[c] = a.count(c)
#    return freq
#ab = check_freq(xyz)
#val = ab.values()
#k = []
#def fun(xyz):
#        if val[0] == 1 and val[1] == 1 and val[2] == 1 and val[3] == 1:
#            k.append(1)
#        else:
#            return(str(int(xyz)+1))
#fun(xyz)
#print k
y = int(input())
i = y + 1
while True:
    n = str(i)
    m = list(n)
    if len(m) == len(set(m)):
        print(i)
        break
    i += 1
