It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
a = int(input())
a = a +1
z = True

def check(a):
    count = 0
    s = str(a)
    b = list(s)
    c = len(b)
    for i in range(c):
        j = i + 1
        for j in range(j,c):
            if b[i] == b[j]:
                count = count + 1

    if count == 0:
        z = False
    else:
        z = True
    return z

while check(a):
    a = a +1

print(a)
