It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def checksame(n): 
    strdig = str(n)
    if ((strdig[0] == strdig[1]) or (strdig[0] == strdig[2]) or (strdig[0] == strdig[3]) or (strdig[1] == strdig[2]) or (strdig[1] == strdig[3]) or (strdig[2] == strdig[3])): 
        return False
    else: 
        return True
    

n = int(input())
solved = False 



while solved == False:
    n+= 1
    digitarray = str(n)
    if (checksame(digitarray)):
        print(n)
        solved= True 

    


