It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n =  int(input()) + 1
while n < 99999:
    m = n
    ok = 0
    arr = []
    while m > 0:
        r = m % 10;
        if arr.count(r) > 0:
            ok = 1 
            break
        else:
            arr.append(r)
        m = m // 10;
    if ok == 1:
        n += 1
    else:
        break
print(n)
    
    
        

