It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
int distinct(int n) {
  int temp, b[5], k = 0;
  while (n != 0) {
    temp = n % 10;
    b[k++] = temp;
    n /= 10;
  }
  for (int i = 0; i < 4; i++)
    for (int j = i + 1; j < 4; j++)
      if (b[i] == b[j]) return 0;
  return 1;
}
int main() {
  int y;
  cin >> y;
  for (int i = y + 1; i < 9013; i++)
    if (distinct(i) == 1) {
      cout << i;
      break;
    }
  cout << endl;
  return 0;
}
