It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
yr = input()
iter = int(yr) + 1
flag = 1
while flag == 1:
	unq = 1
	arr = [0]*10
	x = list(str(iter))
	for ch in x:
	#	print(ch + ':', end = '')
		ch = int(ch)
		if(arr[ch] == 0):
			arr[ch] = 1
		else:
			unq = 0
	if(unq == 1):
		print(str(iter))
		break
	#	print(x)
	iter = iter + 1
	
	
	
	

