It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
y = int(input())
y = y + 1
y = str(y)
z = int(y)
Year = True
def check(y):
    number = 0
    for i in range(len(y)):
        for j in range(len(y)):
            if y[i] == y[j]:
                number = number + 1
        if number > 1:
            return False
        number = 0
    return True
while Year == True:
    if check(y) == True:
        print(y)
        number = False
        break
    else:
        z = z + 1
        y = str(z)