It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
y = int(raw_input().strip())

def dig_count(n):
    was = [False for _ in xrange(10)]

    while n > 0:
        was[n % 10] = True
        n = (n - n % 10) / 10

    ret = 0
    for i in xrange(10):
        if was[i]:
            ret += 1

    return ret

x = y + 1
while dig_count(x) != 4:
    x += 1
print x