It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def distinct(num):
    zero = num%10
    ten = int(num/10)%10
    hund = int(num/100)%10
    thou = int(num/1000)%10
    if(zero==hund or hund==thou or thou==zero or zero==ten or ten==hund or ten==thou or zero==thou):
        return 0
    else:
        return 1
yr = int(input())
while(True):
    yr+=1
    if(distinct(yr)==1):
        print(yr)
        break