It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def check(n):
    a=[]
    while n>0:
        r=n%10
        x=r in a
        if x==False:
            a.append(r)
        else:
            return 0
        n=n/10
    return 1
n=input()
flag=0
n=n+1
while flag==0:
    x=check(n)
    if x==1:
        print n
        flag=1
    n=n+1
