It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
start = int(input(''))
def get_digits(x):
    result = []
    while x > 0:
        result.append(x%10)
        x = int( x / 10)
    return result

def is_different(x):
    for i in range(len(x)):
        for j in range(i+1,len(x)):
            if x[i] == x[j]:
                return False
    return True

start+=1
while not is_different(get_digits(start)):
    start +=1

print(str(start))