It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
import sys

class Scanner:

    def __init__(self):
        self.current_tokens = []

    def remaining_tokens(self):
        return len(self.current_tokens)

    def nextline(self):
        assert self.remaining_tokens() == 0, "Reading next line with remaining tokens"
        return input()

    def nexttokens(self):
        return self.nextline().split()
    
    def nexttoken(self):
        if len(self.current_tokens) == 0:
            self.current_tokens = self.nexttokens()
        assert self.remaining_tokens() > 0, "Not enough tokens to parse."
        return self.current_tokens.pop(0)

    def nextints(self, n=-1):
        if n == -1:
            return list(map(int, self.nexttokens()))
        else:
            return (self.nextint() for i in range(n))
    
    def nextint(self):
        return int(self.nexttoken())

def quit():
    sys.exit(0)

stdin = Scanner()
nextint = stdin.nextint
nextints = stdin.nextints
nextline = stdin.nextline
n = nextint()

def isdistinct(n):
    seen = []
    for i in str(n):
        if i in seen:
            return False
        seen.append(i)
    return True

while True:
    n += 1
    if isdistinct(n):
        print(n)
        quit()
