It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
year = int(raw_input())

def check(yr):
    count = 0
    for i in yr:
        for x in yr:
            if i == x:
                count += 1 #up to 4
    return count

i = year + 1
while True:
    count2 = check(str(i))
    if count2 == 4:
        print(i)
        break
    i += 1