It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n=int(input())
e=n
for i in range(n+1,10000):
    N=list(str(i))
    a0=N.count('0')
    if a0>=1:
        a0=1
    a1=N.count('1')
    if a1>=1:
        a1=1
    a2=N.count('2')
    if a2>=1:
        a2=1
    a3=N.count('3')
    if a3>=1:
        a3=1
    a4=N.count('4')
    if a4>=1:
        a4=1
    a5=N.count('5')
    if a5>=1:
        a5=1
    a6=N.count('6')
    if a6>=1:
        a6=1
    a7=N.count('7')
    if a7>=1:
        a7=1
    a8=N.count('8')
    if a8>=1:
        a8=1
    a9=N.count('9')
    if a9>=1:
        a9=1
    if a1+a2+a3+a4+a5+a6+a7+a9+a8+a0==4:
        e=i
        break
print(e)
        
