A permutation of length n is a sequence of integers from 1 to n of length n containing each number exactly once. For example, [1], [4, 3, 5, 1, 2], [3, 2, 1] are permutations, and [1, 1], [0, 1], [2, 2, 1, 4] are not.

There was a permutation p[1 ... n]. It was merged with itself. In other words, let's take two instances of p and insert elements of the second p into the first maintaining relative order of elements. The result is a sequence of the length 2n.

For example, if p=[3, 1, 2] some possible results are: [3, 1, 2, 3, 1, 2], [3, 3, 1, 1, 2, 2], [3, 1, 3, 1, 2, 2]. The following sequences are not possible results of a merging: [1, 3, 2, 1, 2, 3], [3, 1, 2, 3, 2, 1], [3, 3, 1, 2, 2, 1].

For example, if p=[2, 1] the possible results are: [2, 2, 1, 1], [2, 1, 2, 1]. The following sequences are not possible results of a merging: [1, 1, 2, 2], [2, 1, 1, 2], [1, 2, 2, 1].

Your task is to restore the permutation p by the given resulting sequence a. It is guaranteed that the answer exists and is unique.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 400) — the number of test cases. Then t test cases follow.

The first line of the test case contains one integer n (1 ≤ n ≤ 50) — the length of permutation. The second line of the test case contains 2n integers a_1, a_2, ..., a_{2n} (1 ≤ a_i ≤ n), where a_i is the i-th element of a. It is guaranteed that the array a represents the result of merging of some permutation p with the same permutation p.

Output

For each test case, print the answer: n integers p_1, p_2, ..., p_n (1 ≤ p_i ≤ n), representing the initial permutation. It is guaranteed that the answer exists and is unique.

Example

Input


5
2
1 1 2 2
4
1 3 1 4 3 4 2 2
5
1 2 1 2 3 4 3 5 4 5
3
1 2 3 1 2 3
4
2 3 2 4 1 3 4 1


Output


1 2 
1 3 4 2 
1 2 3 4 5 
1 2 3 
2 3 4 1 
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.math.BigInteger;
import java.nio.Buffer;
import java.util.*;

public class ssss {
    public static void main(String[] args){
        try {
            PrintWriter out=new PrintWriter(System.out,true);
            BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
            int t=Integer.parseInt(br.readLine());
            for(int i=0;i<t;i++){
                int n=Integer.parseInt(br.readLine());
                String[] ss=br.readLine().split(" ");
                int[] arr=new int[2*n];
                for(int j=0;j<2*n;j++){
                    arr[j]=Integer.parseInt(ss[j]);
                }
                HashSet<Integer> set=new HashSet<>();
                StringBuilder str=new StringBuilder("");
                for(int j=0;j<2*n;j++){
                    if(!set.contains(arr[j])){
                        str.append(arr[j]+" ");
                        set.add(arr[j]);
                    }
                }
                out.println(str);
            }
            out.close();
        } catch (Exception e) {
            System.out.println("kkkk "+ e.getMessage());
        }

    }
    static boolean isPal(String s){
        StringBuilder str=new StringBuilder(s);
        str=str.reverse();
        String ss=String.valueOf(str);
        if (ss.equals(s)) {
            return true;
        }
        return false;
    }
    static int mod(int a,int b){
        if (a>b){
            return a-b;
        }
        return b-a;
    }
    static void shuffle(int[] a) {
        Random get = new Random();
        for (int i = 0; i < a.length; i++) {
            int r = get.nextInt(a.length);
            int temp = a[i];
            a[i] = a[r];
            a[r] = temp;
        }
    }
    static int lcm(int a,int b){
        long c=a*b;
        return (int)(c/hcf(a,b));
    }
    static int hcf(int a,int b){
        if(a==0){
            return b;
        }
        if(b==0){
            return a;
        }
        if(a>b)
            return hcf(a%b,b);

        return hcf(a,b%a);
    }
    static void dfs(ArrayList<HashSet<Integer>> list,boolean[] vis,int i){
        vis[i]=true;
        Iterator<Integer> it=list.get(i).iterator();
        while(it.hasNext()){
            int u=it.next();
            if(!vis[u]){
                dfs(list,vis,u);
            }
        }
    }
    static int modInverse(int x,int m){
        return power(x,m-2,m);
    }
    static int power(int x, int y, int m)
    {
        if (y == 0)
            return 1;

        long p = power(x, y / 2, m) % m;
        p = (p * p) % m;

        return (int)((y%2==0)? p : (x*p)%m);
    }
    static class pair{
        int a,b;
        public pair(int a,int b){
            this.a=a;
            this.b=b;
        }
    }
}
