It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
int main() {
  int arr[4], num, i;
  cin >> num;
  int temp = num;
  temp++;
  while (1) {
    num = temp;
    i = 0;
    while (num > 0) {
      arr[i] = num % 10;
      num = num / 10;
      i++;
    }
    if (arr[0] != arr[1] && arr[0] != arr[2] && arr[0] != arr[3] &&
        arr[1] != arr[2] && arr[1] != arr[3] && arr[2] != arr[3]) {
      cout << temp;
      break;
    } else {
      temp++;
    }
  }
  return 0;
}
