It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014

def is_distinct(a):
    a = str(a)
#     count_0 = 0
#     count_1 = 0
#     count_2 = 0
#     count_3 = 0
#     count_4 = 0
#     count_5 = 0
#     count_6 = 0
#     count_7 = 0
#     count_8 = 0
#     count_9 = 0
    cnt = []
    for i in range(10):
        cnt.append(0)
    a = list(a)
    for i in range(len(a)):
        x = a[i]
        x = int(x)
        cnt[x] = cnt[x]+1
        if cnt[x]==2 :
            return False
    return True
a = int(input())
while True:
    a = a+1
    if is_distinct(a) == True:
        print(a)
        break