It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def check_unique(year: int):
    xs = [0]*4
    for i in range(4):
        xs[i] = year//10**(3-i)
        year = year%10**(3-i)
    find = {}
    for digit in xs:
        if find.get(digit, 0):
            return False
        find[digit] = 1
    return True

def next_unique_year(year: int):
    year += 1
    while not check_unique(year):
        year += 1
    return year

n = int(input())
print(next_unique_year(n))
     	 	   			 	  		 	 		  		 	