It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
lucky_year = set()
a = []
y = int(input())
for i in range(1000, 10000):  # просчет всех счастливых годов
    god = list(map(int, str(int(i))))
    for j in god:
        lucky_year.add(j)
    # добавляю год в множество
    if len(lucky_year) == 4:
        a.append(i)
    #     проверка на счастье, добавление счастливого года в массив
    lucky_year.clear()
#     очистка множества
for i in a:
    if y<i:
        print(i)
        break