It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#----------------------------------------------------
#   = = >  CCCCooodddeeefffooorrrccceeesss  < = =
#----------------------------------------------------
n = int(input())
def per(n):
    t = False
    for i in range(0,len(n)):
        for j in range(i+1,len(n)):
            if n[i] == n[j]:
                return per(str(int(n) + 1))
    return n
print(per(str(int(n)+1)))
