It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
input_number=input()

number=int(input_number)
number+=1

def digits(n):
    return([int(x) for x in str(n)])

        
def distinct_digits(number):
    digs=digits(number)
    if digs[0]!=digs[1] and digs[2]!=digs[1] and digs[2]!=digs[3] and digs[3]!=digs[0] and digs[0]!=digs[2] and digs[1]!=digs[3]:
        return(0)
    else:
        return(1)
        
    

while distinct_digits(number)==1:
    number +=1
    
print(number)