You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
import java.util.Scanner;


public class C_213 {

	/**
	 * @param args
	 */
	public static void main(String[] args) {
		Scanner in = new Scanner(System.in);
		int a = in.nextInt();
		String s = in.next();
		int csum[] = new int[s.length()];
		csum[0] = s.charAt(0) - '0';
		for(int i = 1; i < s.length(); i++){
			csum[i] = csum[i-1] + s.charAt(i) -  '0';
		}
		long count[] = new long[(int)1e6 +1];
		long intervals = 0;
		for(int i = 0; i < s.length(); i++){
			count[csum[i]]++;
			intervals++;
			for(int j = i+1; j < s.length(); j++){
				int sum = csum[j] - csum[i];
				count[sum]++;
				intervals++;
			}
		}
		long sum = 0;
		for(int i = 0; i < count.length; i++){
			if(i == 0) continue;
			if(a%i != 0) continue;
			int inv = a/i;
			if(inv > 1000000) continue;
			sum += count[i] * count[inv];
			
		}
		if(a == 0){
			long cnt = count[0] * intervals * 2 - count[0]*count[0];
			System.out.println(cnt);
			return;
		}
		System.out.println(sum);
	}

}
