It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
bool rez(int n) {
  int mass[4];
  for (int i = 3; i >= 0; i--) {
    mass[i] = n % 10;
    n /= 10;
  }
  if (mass[0] != mass[1] && mass[0] != mass[2] && mass[0] != mass[3] &&
      mass[1] != mass[2] && mass[1] != mass[3] && mass[2] != mass[3]) {
    return true;
  } else {
    return false;
  }
}
int main() {
  int n = 0;
  cin >> n;
  n++;
  while (rez(n) != true) {
    n++;
  }
  cout << n;
}
