It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#!/usr/bin/python
# -*- coding: utf-8 -*-

import sys

def is_distinct(x):
    s = str(x)
    mp = {}
    for x in s:
        if x in mp:
            return False
        mp[x] = 1
    return True

y = int(sys.stdin.readline().strip())

while True:
    y += 1
    if is_distinct(y):
        print y
        break
