It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def abc():
    t=int(input())
    t=t+1
    flag=0
    while t<=90012:
        st=list(str(t))
        i=0
        count=0
        while i < 4:
            a=st.pop()
            if a in st:
                break
            else:
                count=count+1
            
            if count==4:
                print(t)
                flag=1
                break
            i=i+1
        t=t+1    
        if flag == 1:
            break
    return 
        
abc()