It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
import math
def beautifulYear(lines):
    n = int(lines[0])
    n += 1
    while not isBeautiful(n):
        n += 1
    print n

def isBeautiful(n):
    digits = {}
    s = str(n)
    for ch in s:
        d = int(ch)
        if digits.has_key(d):
            digits[d] = digits[d] + 1
        else:
            digits[d] = 1
    for d in digits.keys():
        if digits[d] > 1:
            return False
    return True

import sys
f = sys.stdin
#f = open('c:/temp/test.txt', 'r')
lines = f.readlines()
beautifulYear(lines)