It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014

def has_dist_numbers(num):
    """ Return True if num has all distinct numbers and False if num hasn't """

    dist = ""
    for number in str(num):
        if number not in dist:
            dist += number
    
    if int(dist) == num:
        return True
    
    return False


y = int(input())
dy = y + 1
while not has_dist_numbers(dy):
    dy += 1

print(dy)
