It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
int year(int n) {
  int c = 1, i;
  vector<int> vec;
  while (n) {
    vec.push_back(n % 10);
    n = n / 10;
  }
  sort(vec.begin(), vec.end());
  for (i = 0; i < vec.size() - 1; i++) {
    if (vec[i] != vec[i + 1]) {
      c++;
    }
  }
  return c;
}
int main() {
  int a, d;
  cin >> a;
  a++;
  while (year(a) != 4) {
    a++;
  }
  cout << a;
  return 0;
}
