It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#!/usr/bin/env python3
# -*- coding: utf-8 -*-
"""
Created on Mon Mar 30 23:00:18 2020

@author: mac
"""


y = int(input())
i = 0
for i in range(y+1, 9100):
    x = []
    j = i
    flag = 0
    while j > 0:
        k = j % 10
        if k in x:
            flag = 1
            break
        x.append(k)
        j = j // 10
    if flag == 0:
        break
print(i)
