A: Taking a Seat-Taking a Seat-

story

Mr. A entered the classroom at the examination site to take an examination. However, Mr. A is a very nervous type. Therefore, depending on the situation, there may be seats that Mr. A does not want to sit in. Therefore, Mr. A decided to find out how many seats he could sit on based on certain conditions.

problem

Mr. A is a nervous type of person. First of all, Mr. A cannot sit in the first row from the front. Because when I sit near the proctor, I get nervous and can't solve the problem. Also, if there is a person on the right or left, Mr. A cannot sit down. This is because the sound of the pencil next to me makes it impossible to concentrate during the test. In addition, you can't sit near a noisy guy (near 8 diagonally up, down, left, and right). This is because my voice echoes in my head during the break and I can't rest. Also, it's natural, but I can't sit in the seat where the students are already sitting.

Is there a place where Mr. A can sit under these conditions? Assuming that M x N seats are lined up in the classroom, let's find the number.

Input format

The first row gives M (number of rows: number of vertical seats) and N (number of columns: number of horizontal seats). From the second line, M lines and a character string of length N are given line by line. The j character of the i-th character string represents the state of the seat in the i-th row and the j-th column. Each letter is either'-',' x'or'o', vacant seats'-', noisy students sitting during breaks'x', other students sitting' Let it be o'.

Constraint

* 0 <M ≤ 100
* 0 <N ≤ 100



Output format

Output the number of seats that Mr. A can sit in one line depending on the conditions. Don't forget the line break at the end.

Input example 1


5 5
--o--
--xo-
--x--
o --- x
--xoo


Output example 1


3

Input example 2


2 6
--oooo
x--o--


Output example 2


1

Input example 3


3 5
-----
-----
-----


Output example 3


Ten

Input example 4


4 6
o-oxoo
oo-ooo
oooxo-
o-ooox


Output example 4


0





Example

Input

5 5
--o--
--xo-
--x--
o---x
--xoo


Output

3
#include <cstdio>
#include <cstring>
int dx[] = {-1, -1, -1, 0, 0, 1, 1, 1};
int dy[] = {1, 0, -1,    1, -1, 1, 0, -1};
int main(){
	int M;
	int N;
	int data[102][102];
	char tmp[1000];

	scanf("%d %d", &M, &N);
	for(int i = 1; i <= M; i++){
		data[i][0] = 0;
		data[i][N] = 0;
		scanf("%s", tmp);
		for(int j = 1; j <= N; j++){
			if(tmp[j - 1] == 'o'){
				data[i][j] = 1;
			}else if(tmp[j - 1] == 'x'){
				data[i][j] = 2;
			}else{
				data[i][j] = 0;
			}
		}
	}
	for(int i = 0; i <= N + 1; i++){
		data[0][i] = 0;
		data[M + 1][i] = 0;
	}
	int ans = 0;
	for(int i = 2; i <= M; i++){
		for(int j = 1; j <= N; j++){
			if(data[i][j] != 0) continue;
			int flg = 0;
			for(int k = 0; k < 8; k++){
				if(data[i + dy[k]][j + dx[k]] == 2){
					flg = 1;
					break;
				}
			}
			if(flg) continue;
			if(data[i][j - 1] == 1 || data[i][j + 1] == 1) continue;
			ans++;
		}
	}
	printf("%d\n", ans);
}
	