You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
long long a, n, s[4005][4005], t;
char v[4005];
map<long long, int> ma;
int main() {
  scanf("%lld", &a);
  scanf("%s", v);
  t = 0;
  n = strlen(v);
  for (int i = 0; i < n; i++) {
    s[i][i] = v[i] - 48;
    ma[s[i][i]]++;
    t++;
    for (int j = i + 1; j < n; j++) {
      s[i][j] = s[i][j - 1] + v[j] - 48;
      ma[s[i][j]]++;
      t++;
    }
  }
  long long pew, ans = 0;
  for (int i = 0; i < n; i++) {
    for (int j = i; j < n; j++) {
      if (s[i][j] == 0) {
        if (a == 0) ans += t;
        continue;
      }
      if (a % s[i][j]) continue;
      pew = a / s[i][j];
      ans += ma[pew];
    }
  }
  printf("%lld\n", ans);
  return 0;
}
