You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
const long long mod = 998244353;
int main() {
  int a;
  cin >> a;
  map<long long, long long> m, m1;
  for (int i = 1; i <= sqrt(a); i++) {
    if (a % i == 0) {
      m[i] = 1;
      m[a / i] = 1;
    }
  }
  string s;
  cin >> s;
  long long ans = 0, s1 = 0;
  long long cnt = 0, cnt1 = 0;
  for (int i = 0; i < s.size(); i++) {
    int s2 = 0;
    s1 += s[i] - '0';
    for (int j = 0; j <= i; j++) {
      m1[s1 - s2]++;
      cnt += s1 - s2 != 0;
      cnt1 += s1 - s2 == 0;
      s2 += s[j] - '0';
    }
  }
  cerr << cnt << ' ' << m1[0];
  if (!a) {
    cout << (m1[0] * cnt) * 2 + m1[0] * cnt1;
    return 0;
  }
  for (auto i : m1) {
    if (i.first) {
      if (m[i.first] && m1[a / i.first]) {
        ans += i.second * m1[a / i.first];
      }
    }
  }
  cout << ans;
  return 0;
}
