It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def main():

    n = input()

    while True:
        n = str(int(n) + 1)
        
        list_year = [int(i) for i in n]
        
        if list_year.count(list_year[0]) == 1 and list_year.count(list_year[1]) == 1 and list_year.count(list_year[2]) == 1 and list_year.count(list_year[3]) == 1 :
            print(n)
            break
            
if __name__ == '__main__':
    main()
	 		  					 	 		 	   	  	  		