You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
import java.io.*;
import java.util.*;

public class Matrix {
    public static void main(String[] args) throws IOException {
        BufferedReader f = new BufferedReader(new InputStreamReader(System.in));
        int a = Integer.parseInt(f.readLine());
        String str = f.readLine();
        int[] prefix = new int[str.length()+1];
        prefix[0] = 0;
        for (int i = 1; i <= str.length(); i++)
            prefix[i] = prefix[i-1] + str.charAt(i-1)-'0';
        long[] count = new long[40000];
        for (int i = 0; i < prefix.length; i++)
            for (int j = i+1; j < prefix.length; j++)
                count[prefix[j]-prefix[i]]++;
        if (a == 0) {
            System.out.println(count[0]*str.length()*(str.length()+1)-count[0]*count[0]);
            return;
        }
        long sum = 0;
        for (int i = 1; i < count.length; i++)
            if (a % i == 0 && a/i < count.length)
                sum += count[i]*count[a/i];
        System.out.println(sum);
    }
}