It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
# -*- coding: utf-8 -*-
"""
Created on Mon Sep 28 21:35:59 2020

@author: Rahul Kumar
"""
def shred(num):
    double = []
    while(num > 0):
        rem = num%10
        double.append(rem)
        num //= 10
    return(double)

def check_list(double):
    for i in range(len(double)):
        for j in range(len(double)):
            if i != j:
                if double[i] == double[j]:
                    return True
    return False

if __name__ == "__main__":
    y = int(input())
    n = y
    double = []
    double = shred(y)
    out = check_list(double)
    if out == False:
        one_more_time = True
    else:
        one_more_time = False
    while (check_list(double) or one_more_time):
        y += 1
        double = shred(y)
        one_more_time = False

    print(y)