It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#a, b, c = map(int,input().split())
#print (((a+c-1)//c)*((b+c-1)//c))
#a = int(input())
#print("YES" if a>=4 and a % 2 == 0 else "NO")
n = int(input())
n = n + 1
while(True):
    nn = str(n)
    st = set([])
    st.add(nn[0])
    st.add(nn[1])
    st.add(nn[2])
    st.add(nn[3])
    if len(st) == 4: 
        print(n)
        break
    n = n + 1
		 				 			 	  					  						