It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
date = input()
date = int(date)
nd = date + 1
pall = False
while pall == False:
    nd = str(nd)
    if nd.count("1") > 1 or nd.count("2") > 1 or nd.count("3") > 1 or nd.count("4") > 1 or nd.count("5") > 1 or nd.count("6") > 1 or nd.count("7") > 1 or nd.count("8") > 1 or nd.count("9") > 1 or nd.count("0") > 1:
        nd = int(nd)
        nd +=1
    else:
        pall = True
print(nd)
