It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
year = int(input())
ans = []

def year_f(x):
  a = x % 10
  b = (x // 10) % 10
  c = (x // 100) % 10
  d = (x // 1000) % 10

  if (a != b and a!= c and a != c and a != d and b != c and b!= d and c!=d):
    return 1
  else:
    return 0

for i in range (year+1, 9999):
  x = year_f(i)
  if (x == 1):
    print (i)
    break