You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

import static java.lang.Integer.parseInt;

public class C_Matrix_3 {
    static int a,ar[],prefix[];
    static char st[];
    static long ans;
    public static void main(String[] args) throws IOException {
        BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
        a = parseInt(in.readLine());
        st = in.readLine().toCharArray();
        ar = new int[35000];
        prefix = new int[st.length + 1];
        for (int i = 1; i <= st.length; i++) {
            prefix[i] = prefix[i - 1] + (st[i - 1] - '0');
        }
        for (int i = 0; i < st.length; i++) {
            for (int j = i; j < st.length; j++) {
                ar[prefix[j + 1] - prefix[i]]++;
            }
        }
        if(a == 0) {
            for (int i = 0; i < 35000; i++) {
                ans += 1L * ar[0] * ar[i];
            }
        }
        for (int i = 1; i < 35000; i++) {
            if(a % i == 0 && a / i < 35000){
                ans += 1L * ar[a / i] * ar[i];
            }
        }
        System.out.println(ans);
    }
}
