Alice lives on a flat planet that can be modeled as a square grid of size n × n, with rows and columns enumerated from 1 to n. We represent the cell at the intersection of row r and column c with ordered pair (r, c). Each cell in the grid is either land or water.

<image> An example planet with n = 5. It also appears in the first sample test.

Alice resides in land cell (r_1, c_1). She wishes to travel to land cell (r_2, c_2). At any moment, she may move to one of the cells adjacent to where she is—in one of the four directions (i.e., up, down, left, or right).

Unfortunately, Alice cannot swim, and there is no viable transportation means other than by foot (i.e., she can walk only on land). As a result, Alice's trip may be impossible.

To help Alice, you plan to create at most one tunnel between some two land cells. The tunnel will allow Alice to freely travel between the two endpoints. Indeed, creating a tunnel is a lot of effort: the cost of creating a tunnel between cells (r_s, c_s) and (r_t, c_t) is (r_s-r_t)^2 + (c_s-c_t)^2.

For now, your task is to find the minimum possible cost of creating at most one tunnel so that Alice could travel from (r_1, c_1) to (r_2, c_2). If no tunnel needs to be created, the cost is 0.

Input

The first line contains one integer n (1 ≤ n ≤ 50) — the width of the square grid.

The second line contains two space-separated integers r_1 and c_1 (1 ≤ r_1, c_1 ≤ n) — denoting the cell where Alice resides.

The third line contains two space-separated integers r_2 and c_2 (1 ≤ r_2, c_2 ≤ n) — denoting the cell to which Alice wishes to travel.

Each of the following n lines contains a string of n characters. The j-th character of the i-th such line (1 ≤ i, j ≤ n) is 0 if (i, j) is land or 1 if (i, j) is water.

It is guaranteed that (r_1, c_1) and (r_2, c_2) are land.

Output

Print an integer that is the minimum possible cost of creating at most one tunnel so that Alice could travel from (r_1, c_1) to (r_2, c_2).

Examples

Input


5
1 1
5 5
00001
11111
00111
00110
00110


Output


10


Input


3
1 3
3 1
010
101
010


Output


8

Note

In the first sample, a tunnel between cells (1, 4) and (4, 5) should be created. The cost of doing so is (1-4)^2 + (4-5)^2 = 10, which is optimal. This way, Alice could walk from (1, 1) to (1, 4), use the tunnel from (1, 4) to (4, 5), and lastly walk from (4, 5) to (5, 5).

In the second sample, clearly a tunnel between cells (1, 3) and (3, 1) needs to be created. The cost of doing so is (1-3)^2 + (3-1)^2 = 8.
/*Author: Satyajeet Singh, Delhi Technological University*/
import java.io.*;
import java.util.*;
import java.text.*; 
import java.lang.*;

public class Main {
/*********************************************Constants******************************************/
    static PrintWriter out=new PrintWriter(new OutputStreamWriter(System.out));        
    static BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
    static long mod=(long)1e9+7;
    static long mod1=998244353;
    static boolean sieve[];
    static ArrayList<Integer> primes;
    static ArrayList<Long> factorial;
    static HashSet<Integer> graph[];
/****************************************Solutions Begins*****************************************/
    static int n,input[][];
    static boolean vis[][];
    static int dx[]={1,-1,0,0};
    static int dy[]={0,0,-1,1};

    static boolean safe(int x,int y){
        if(x>=0&&y>=0&&x<n&&y<n&&!vis[x][y]&&input[x][y]==0){
            return true;
        }
        return false;
    }

    static void dfs(int i,int j){
        vis[i][j]=true;
        for(int k=0;k<4;k++){
            int x=i+dx[k];
            int y=j+dy[k];
            if(safe(x,y)){
                dfs(x,y);
            }
        }
    }
    public static void main (String[] args) throws Exception {
        String st[]=br.readLine().split(" ");
        n=Integer.parseInt(st[0]);
        st=br.readLine().split(" ");
        int r1=Integer.parseInt(st[0])-1;
        int c1=Integer.parseInt(st[1])-1;
        st=br.readLine().split(" ");
        int r2=Integer.parseInt(st[0])-1;
        int c2=Integer.parseInt(st[1])-1;
        input=new int[n][n];
        for(int i=0;i<n;i++){
            st=br.readLine().split("");
           // debug(st);
            for(int j=0;j<n;j++){
                input[i][j]=Integer.parseInt(st[j]);
            }
        }
        vis=new boolean[n][n];
        dfs(r1,c1);
        ArrayList<Integer> conn=new ArrayList<>();
        for(int i=0;i<n;i++){
            for(int j=0;j<n;j++){
                if(vis[i][j]){
                    if(i==r2&&j==c2){
                        out.println(0);
                        out.flush();
                        return ;
                    }
                    conn.add(i);
                    conn.add(j);
                }
            }
        }
       // debug(vis);
        vis=new boolean[n][n];
        dfs(r2,c2);
        ArrayList<Integer> con=new ArrayList<>();
        for(int i=0;i<n;i++){
            for(int j=0;j<n;j++){
                if(vis[i][j]){
                    con.add(i);
                    con.add(j);
                }
            }
        }
        int ans=Integer.MAX_VALUE;
        //debug(conn);
       // debug(con);
        for(int i=0;i<conn.size();i+=2){
            int x1=conn.get(i);
            int y1=conn.get(i+1);
            for(int j=0;j<con.size();j+=2){
                int x2=con.get(j);
                int y2=con.get(j+1);
                ans=Math.min(ans,((x2-x1)*(x2-x1)+(y2-y1)*(y2-y1)));

            }

        }
        out.println(ans);                
/****************************************Solutions Ends**************************************************/
        out.flush();
        out.close();
    }
/****************************************Template Begins************************************************/
/***************************************Precision Printing**********************************************/
    static void printPrecision(double d){
        DecimalFormat ft = new DecimalFormat("0.00000000000000000"); 
        out.println(ft.format(d));
    }
/******************************************Graph*********************************************************/
    static void Makegraph(int n){
        graph=new HashSet[n];
        for(int i=0;i<n;i++){
            graph[i]=new HashSet<>();
        }
    }
    static void addEdge(int a,int b){
        graph[a].add(b);
    }    

/*********************************************PAIR********************************************************/
    static class PairComp implements Comparator<Pair>{
        public int compare(Pair p1,Pair p2){
            if(p1.u>p2.u){
                return 1;
            }
            else if(p1.u<p2.u){
                return -1;
            }
            else{
                return p1.v-p2.v;
            }
        }
    }
    static class Pair implements Comparable<Pair> {
        int u;
        int v;
        int index=-1;
        public Pair(int u, int v) {
            this.u = u;
            this.v = v;
        }
 
        public int hashCode() {
            int hu = (int) (u ^ (u >>> 32));
            int hv = (int) (v ^ (v >>> 32));
            return 31 * hu + hv;
        }
 
        public boolean equals(Object o) {
            Pair other = (Pair) o;
            return u == other.u && v == other.v;
        }
 
        public int compareTo(Pair other) {
            if(index!=other.index)
                return Long.compare(index, other.index);
            return Long.compare(v, other.v)!=0?Long.compare(v, other.v):Long.compare(u, other.u);
        }
 
        public String toString() {
            return "[u=" + u + ", v=" + v + "]";
        }
    }

    static class PairCompL implements Comparator<Pairl>{
        public int compare(Pairl p1,Pairl p2){
            if(p1.u>p2.u){
                return 1;
            }
            else if(p1.u<p2.u){
                return -1;
            }
            else{
                return 0;
            }
        }
    }
    static class Pairl implements Comparable<Pair> {
            long u;
            long v;
            int index=-1;
            public Pairl(long u, long v) {
                this.u = u;
                this.v = v;
            }
    
            public int hashCode() {
                int hu = (int) (u ^ (u >>> 32));
                int hv = (int) (v ^ (v >>> 32));
                return 31 * hu + hv;
            }
    
            public boolean equals(Object o) {
                Pair other = (Pair) o;
                return u == other.u && v == other.v;
            }
    
            public int compareTo(Pair other) {
                if(index!=other.index)
                    return Long.compare(index, other.index);
                return Long.compare(v, other.v)!=0?Long.compare(v, other.v):Long.compare(u, other.u);
            }
    
            public String toString() {
                return "[u=" + u + ", v=" + v + "]";
            }
        }
/*****************************************DEBUG***********************************************************/
    public static void debug(Object... o) {
        System.out.println(Arrays.deepToString(o));
    }
/************************************MODULAR EXPONENTIATION***********************************************/
    static long modulo(long a,long b,long c) {
        long x=1;
        long y=a;
        while(b > 0){
            if(b%2 == 1){
                x=(x*y)%c;
            }
            y = (y*y)%c; // squaring the base
            b /= 2;
        }
        return  x%c;
    }
/********************************************GCD**********************************************************/
    static long gcd(long x, long y)
    {
        if(x==0)
            return y;
        if(y==0)
            return x;
        long r=0, a, b;
        a = (x > y) ? x : y; // a is greater number
        b = (x < y) ? x : y; // b is smaller number
        r = b;
        while(a % b != 0)
        {
            r = a % b;
            a = b;
            b = r;
        }
        return r;
    }
/******************************************SIEVE**********************************************************/
    static void sieveMake(int n){
        sieve=new boolean[n];
        Arrays.fill(sieve,true);
        sieve[0]=false;
        sieve[1]=false;
        for(int i=2;i*i<n;i++){
            if(sieve[i]){
                for(int j=i*i;j<n;j+=i){
                    sieve[j]=false;
                }
            }
        }
        primes=new ArrayList<Integer>();
        for(int i=0;i<n;i++){
            if(sieve[i]){
                primes.add(i);
            }
        }        
    }
/********************************************End***********************************************************/
}