It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def check_duplicates(year):
    sorted_year = sorted(str(year))
    duplicated_digits = False
    for i in range(len(sorted_year) - 1):
        if (sorted_year[i] == sorted_year[i + 1]):
            duplicated_digits = True
            break
    return duplicated_digits

last_year = int(input()) + 1
find_it = 0
while find_it == 0:
    is_duplicated = check_duplicates(last_year)
    if (is_duplicated):
        last_year = last_year + 1
    else:
        find_it = find_it + 1
print(last_year)