You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
const int SIZE = 4444;
long long a;
int len;
char val[SIZE];
map<long long, int> mp;
int main() {
  while (cin >> a) {
    long long ans = 0;
    cin >> val;
    len = strlen(val);
    mp.clear();
    int sumall = 0;
    for (int i = 0; i < len; i++) {
      val[i] -= '0';
    }
    for (int i = 1; i <= len; i++) {
      long long t = 0;
      for (int j = 0; j < i; j++) {
        t += val[j];
      }
      mp[t]++;
      sumall++;
      for (int j = i; j < len; j++) {
        t -= val[j - i];
        t += val[j];
        mp[t]++;
        sumall++;
      }
    }
    for (map<long long, int>::iterator iter = mp.begin(); iter != mp.end();
         ++iter) {
      long long x = iter->first;
      int y = iter->second;
      if (!x) {
        if (!a) {
          ans += (long long)sumall * y;
        }
        continue;
      }
      if (a % x == 0) {
        int z = mp[a / x];
        ans += (long long)y * z;
      }
    }
    cout << ans << endl;
  }
  return 0;
}
