It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
import sys
n=int(sys.stdin.readline())

n+=1
n1=0
n2=0
n3=0
n4=0
while True:
    n4=n%10
    n3=(n/10)%10
    n2=(n/100)%10
    n1=(n/1000)%10
    if(n1==n2):
        n+=2
        continue
    if(n1==n3 or n1==n4):
        n+=1
        continue
    if(n2==n3 or n2==n4):
        n+=1
        continue
    if(n3==n4):
        n+=1
        continue
    break

print n