It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
"""
  ____          _      _____
 / ___|___   __| | ___|  ___|__  _ __ ___ ___  ___
| |   / _ \ / _` |/ _ \ |_ / _ \| '__/ __/ _ \/ __|
| |__| (_) | (_| |  __/  _| (_) | | | (_|  __/\__ \
 \____\___/ \__,_|\___|_|  \___/|_|  \___\___||___/

"""
"""
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"""

import sys
import math
import collections
from collections import deque

#sys.stdin = open('input.txt', 'r')
#sys.stdout = open('output.txt', 'w')

from functools import reduce
from sys import stdin, stdout, setrecursionlimit
setrecursionlimit(2**20)


def isPowerOfTwo(x):
    return (x and (not(x & (x - 1))))


def factors(n):
    return list(set(reduce(list.__add__, ([i, n // i] for i in range(1, int(n**0.5) + 1) if n % i == 0))))

T = 1
#T = int(stdin.readline())
for _ in range(T):
    #s = str(stdin.readline().strip('\n'))
    #a, b = list(map(int, stdin.readline().split()))
    #s = list(stdin.readline().strip('\n'))
    #b = list(stdin.readline().strip('\n'))
    #a = list(map(int, stdin.readline().split()))
    #a = str(stdin.readline().strip('\n'))
    #n, m = list(map(int, stdin.readline().split()))
    n = int(stdin.readline().strip('\n'))
    n = n + 1
    flag = True
    while flag:
        if len(str(n)) == len(set(str(n))):
            print(n)
            break
        else:
            n += 1
