It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
from collections import Counter


def isAllUnique(year):
    results = Counter(year)
    values = results.values()
    onces = [y for y in values if y == 1]
    if len(onces) == 4:
        return True
    else:
        return False


year = int(input())
nextYear = year + 1

while not isAllUnique(str(nextYear)):
    nextYear += 1

print(nextYear)
