You have a simple undirected graph consisting of n vertices and m edges. The graph doesn't contain self-loops, there is at most one edge between a pair of vertices. The given graph can be disconnected.

Let's make a definition.

Let v_1 and v_2 be two some nonempty subsets of vertices that do not intersect. Let f(v_{1}, v_{2}) be true if and only if all the conditions are satisfied:

  1. There are no edges with both endpoints in vertex set v_1. 
  2. There are no edges with both endpoints in vertex set v_2. 
  3. For every two vertices x and y such that x is in v_1 and y is in v_2, there is an edge between x and y. 



Create three vertex sets (v_{1}, v_{2}, v_{3}) which satisfy the conditions below;

  1. All vertex sets should not be empty. 
  2. Each vertex should be assigned to only one vertex set. 
  3. f(v_{1}, v_{2}), f(v_{2}, v_{3}), f(v_{3}, v_{1}) are all true. 



Is it possible to create such three vertex sets? If it's possible, print matching vertex set for each vertex.

Input

The first line contains two integers n and m (3 ≤ n ≤ 10^{5}, 0 ≤ m ≤ min(3 ⋅ 10^{5}, (n(n-1))/(2))) — the number of vertices and edges in the graph.

The i-th of the next m lines contains two integers a_{i} and b_{i} (1 ≤ a_{i} < b_{i} ≤ n) — it means there is an edge between a_{i} and b_{i}. The graph doesn't contain self-loops, there is at most one edge between a pair of vertices. The given graph can be disconnected.

Output

If the answer exists, print n integers. i-th integer means the vertex set number (from 1 to 3) of i-th vertex. Otherwise, print -1.

If there are multiple answers, print any.

Examples

Input


6 11
1 2
1 3
1 4
1 5
1 6
2 4
2 5
2 6
3 4
3 5
3 6


Output


1 2 2 3 3 3 

Input


4 6
1 2
1 3
1 4
2 3
2 4
3 4


Output


-1

Note

In the first example, if v_{1} = \{ 1 \}, v_{2} = \{ 2, 3 \}, and v_{3} = \{ 4, 5, 6 \} then vertex sets will satisfy all conditions. But you can assign vertices to vertex sets in a different way; Other answers like "2 3 3 1 1 1" will be accepted as well.

<image>

In the second example, it's impossible to make such vertex sets.
import java.util.*;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;

public class r589p4a{

    private static InputReader sc;
    private static PrintWriter pw;

    static class InputReader {
        private final InputStream stream;
        private final byte[] buf = new byte[8192];
        private int curChar, snumChars;
        private SpaceCharFilter filter;

        InputReader(InputStream stream) {
            this.stream = stream;
        }

        int snext() {
            if (snumChars == -1)
                throw new InputMismatchException();
            if (curChar >= snumChars) {
                curChar = 0;
                try {
                    snumChars = stream.read(buf);
                } catch (IOException e) {
                    throw new InputMismatchException();
                }
                if (snumChars <= 0)
                    return -1;
            }
            return buf[curChar++];
        }

        int nextInt() {
            int c = snext();
            while (isSpaceChar(c)) {
                c = snext();
            }
            int sgn = 1;
            if (c == '-') {
                sgn = -1;
                c = snext();
            }
            int res = 0;
            do {
                if (c < '0' || c > '9')
                    throw new InputMismatchException();
                res *= 10;
                res += c - '0';
                c = snext();
            } while (!isSpaceChar(c));
            return res * sgn;
        }

        long nextLong() {
            int c = snext();
            while (isSpaceChar(c)) {
                c = snext();
            }
            int sgn = 1;
            if (c == '-') {
                sgn = -1;
                c = snext();
            }
            long res = 0;
            do {
                if (c < '0' || c > '9')
                    throw new InputMismatchException();
                res *= 10;
                res += c - '0';
                c = snext();
            } while (!isSpaceChar(c));
            return res * sgn;
        }

        String readString() {
            int c = snext();
            while (isSpaceChar(c)) {
                c = snext();
            }
            StringBuilder res = new StringBuilder();
            do {
                res.appendCodePoint(c);
                c = snext();
            } while (!isSpaceChar(c));
            return res.toString();
        }

        String nextLine() {
            int c = snext();
            while (isSpaceChar(c))
                c = snext();
            StringBuilder res = new StringBuilder();
            do {
                res.appendCodePoint(c);
                c = snext();
            } while (!isEndOfLine(c));
            return res.toString();
        }

        boolean isSpaceChar(int c) {
            if (filter != null)
                return filter.isSpaceChar(c);
            return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1;
        }

        private boolean isEndOfLine(int c) {
            return c == '\n' || c == '\r' || c == -1;
        }

        public interface SpaceCharFilter {
            boolean isSpaceChar(int ch);
        }
    }

    public static void main(String args[]) {
        sc = new InputReader(System.in);
        pw = new PrintWriter(System.out);

        int t = 1;
        while(t-->0)
            solve();

        pw.flush();
        pw.close();
    }

    private static void solve(){
        int n = sc.nextInt(), m = sc.nextInt();

        ArrayList<HashSet<Integer>> graph = new ArrayList<>();

        for(int i=0; i<n; i++)
            graph.add(new HashSet<>());

        while(m-->0){
            int u = sc.nextInt()-1, v = sc.nextInt()-1;

            graph.get(u).add(v);
            graph.get(v).add(u);
        }

        int id[] = new int[n], parent[] = {0, -1};

        for(int i=0; i<n; i++){
            if(graph.get(i).size() < 2){
                pw.println(-1);
                return;
            }
        }

        parent[0] = 0;
        parent[1] = graph.get(0).iterator().next();

        id[0] = 1;
        id[parent[1]] = 2;

        int flag = 0;
        for(int i=1; i<n; i++){
            if(parent[1] == i)
                continue;

            if(graph.get(0).contains(i)){
                if(graph.get(parent[1]).contains(i)) {
                    id[i] = 3;
                    flag = 1;
                }
                else
                    id[i] = 2;
            }
            else if(graph.get(parent[1]).contains(i))
                id[i] = 1;
            else{
                pw.println(-1);
                return;
            }
        }
        
        if(flag == 0){
            pw.println(-1);
            return;
        }

        int size[] = {0, 0, 0};
        for(int i=0; i<n; i++){
            size[id[i]-1]++;
        }

        for(int i=0; i<n; i++){
            for(Integer child: graph.get(i)){
                if(id[child] == id[i]){
                    pw.println(-1);
                    return;
                }
            }
            if(graph.get(i).size()+size[id[i]-1] != n){
                pw.println(-1);
                return;
            }
        }

        for(int i=0; i<n; i++)
            pw.print(+id[i]+" ");
        pw.println();
    }


}