It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
import math, sys
input = sys.stdin.readline

# For taking integer inputs
def inp():
    return(int(input()))
# For taking List inputs
def inlt():
    return(list(map(int,input().split())))
# For taking string inputs
def insr():
    s = input()
    return(list(s[:len(s) - 1]))
# For taking space seperated integer variable inputs
def invr():
    return list(map(int,input().split()))

def diff(n):
    ar = [0] * 10
    while n > 0:
        digit = math.floor(n % 10)
        if (ar[digit]):
            return 0
        ar[digit] = 1
        n = int(n / 10)
    return 1
    
y = inp() + 1

while (not diff(y)):
    y+=1
print(y)
