It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#t=int(input())
#for j in range(t):
    #x,y,k=input().split(" ")
    #x,y,k=int(x),int(y),int(k)
    #a=list(map(int,input().split()))

def distinctYear(num):
    s=str(num)
    for i in range(len(s)):
        if(s.count(s[i])>1):
            return 5
    return 10

    
n=int(input())
n+=1
while(distinctYear(n)!=10):
    n+=1
print(n)

