There are given n men and n women.
Each woman ranks all men in order of her preference
(her first choice, her second choice, and so on).
Similarly, each man sorts all women according to
his preference. The goal is to arrange n
marriages in such a way that if a man m
prefers some woman w more than his wife, and w prefers m more then her husband a new marriage occurs between w and m.  If w prefers her husband more, then she stays married to him.  This problem always has a solution and your task is to find one.


Input
The first line contains a positive integer t ≤ 100
indicating the number of test cases. Each test case is an
instance of the stable marriage problem defined above.
The first line of each test case is a positive integer
n ≤ 500 (the number of marriages to find).
The next n lines are the woman's preferences: ith
line contains the number i (which means that this is the list given
by the ith woman) and the numbers of men
(the first choice of ith woman, the second choice,...).
Then, the men's preferences follow in the same format.


Output
For each test case print n lines, where each line
contains two numbers m and w, which means that
the man number m and the woman number w should get married.


Example

Input:
2
4
1 4 3 1 2
2 2 1 3 4
3 1 3 4 2
4 4 3 1 2
1 3 2 4 1
2 2 3 1 4
3 3 1 2 4
4 3 2 4 1
7
1 3 4 2 1 6 7 5
2 6 4 2 3 5 1 7
3 6 3 5 7 2 4 1
4 1 6 3 2 4 7 5
5 1 6 5 3 4 7 2
6 1 7 3 4 5 6 2
7 5 6 2 4 3 7 1
1 4 5 3 7 2 6 1
2 5 6 4 7 3 2 1
3 1 6 5 4 3 7 2
4 3 5 6 7 2 4 1
5 1 7 6 4 3 5 2
6 6 3 7 5 2 4 1
7 1 7 4 2 6 5 3



Output:
1 3
2 2
3 1
4 4
1 4
2 5
3 1
4 3
5 7
6 6
7 2


Warning: large Input/Output data, be careful with certain languages
"""
The stable marriage problem from CodeChef
"""
from collections import defaultdict

def revdict(dic):
    for key in dic.keys():
        dic[key] = dic[key][::-1]
    return dic

def smp(boy_prefs, girl_prefs):
    stable = {}

    ranks = dict()
    for girl, gpref in girl_prefs.items():
        for i, boy in enumerate(gpref):
            ranks[(girl, boy)] = i

    free_boys = set(boy_prefs.keys())
    free_girls = set(girl_prefs.keys())

    n = len(boy_prefs)
    # Reverse orders
    boy_prefs = revdict(boy_prefs)
    while free_boys:
        boy = free_boys.pop()
        if not boy_prefs.has_key(boy):
            continue
        girl = boy_prefs[boy].pop()
        if girl in free_girls:
            stable[girl] = (boy, ranks[(girl, boy)])
            free_girls.remove(girl)
        elif ranks[(girl, boy)] < stable[girl][1]:
            free_boys.add(stable[girl][0])
            stable[girl] = (boy, ranks[(girl, boy)])
        else:
            free_boys.add(boy)

    results = sorted((boy, girl) for girl, (boy, rank) in stable.items())
    return results    

def test():
    gprefs = { 1: [4, 3, 1, 2],
               2: [2, 1, 3, 4],
               3: [1, 3, 4, 2],
               4: [4, 3, 1, 2]
               }

    bprefs = {
        1: [3, 2, 4, 1],
        2: [2, 3, 1, 4],
        3: [3, 1, 2, 4],
        4: [3, 2, 4, 1]
    }

    print smp(bprefs, gprefs)

def main():
    cases = int(raw_input())
    for i in range(cases):
        k = int(raw_input())
        gprefs, bprefs = {}, {}
        for a in range(k):
            gprefs[a+1] = map(int, raw_input().split())[1:]
        for b in range(k):
            bprefs[b+1] = map(int, raw_input().split())[1:]
        for boy, girl in smp(bprefs, gprefs):
            print boy, girl

if __name__ == '__main__':
    main()