It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
import time

def checkIfDuplicates(listOfElems):
    if len(listOfElems) == len(set(listOfElems)):
        return False
    else:
        return True

if __name__ == "__main__":
    year = int(input(""))
    j = 0
    my_list = []
    for i in str(year):
        my_list.append(i)
    while True:
        year += 1
        for x in str(year):
            my_list[j] = str(x)
            j += 1
        j = 0
        if not checkIfDuplicates(my_list):
            print(my_list[0]+my_list[1]+my_list[2]+my_list[3])
            break

