It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
int main() {
  int n, temp, i, z = 0, k, j, m, p = 0, o;
  cin >> n;
  int x[4];
  for (i = n; i < 10000; i++) {
    k = i + 1;
    temp = k;
    for (j = 0; j < 4; j++) {
      x[j] = k % 10;
      k = k / 10;
      if (k == 0)
        break;
      else
        continue;
    }
    for (o = 0; o < 4; o++) {
      for (m = o + 1; m < 4; m++) {
        if (x[o] == x[m]) {
          z++;
          p = z + p;
          break;
        } else {
          z = 0;
          continue;
        }
      }
    }
    if (p < 1) {
      cout << temp;
      break;
    } else {
      p = 0;
      continue;
    }
  }
}
