You are given an angle ang. 

The Jury asks You to find such regular n-gon (regular polygon with n vertices) that it has three vertices a, b and c (they can be non-consecutive) with \angle{abc} = ang or report that there is no such n-gon.

<image>

If there are several answers, print the minimal one. It is guarantied that if answer exists then it doesn't exceed 998244353.

Input

The first line contains single integer T (1 ≤ T ≤ 180) — the number of queries. 

Each of the next T lines contains one integer ang (1 ≤ ang < 180) — the angle measured in degrees. 

Output

For each query print single integer n (3 ≤ n ≤ 998244353) — minimal possible number of vertices in the regular n-gon or -1 if there is no such n.

Example

Input


4
54
50
2
178


Output


10
18
90
180

Note

The answer for the first query is on the picture above.

The answer for the second query is reached on a regular 18-gon. For example, \angle{v_2 v_1 v_6} = 50^{\circ}.

The example angle for the third query is \angle{v_{11} v_{10} v_{12}} = 2^{\circ}.

In the fourth query, minimal possible n is 180 (not 90).
import java.util.*;
import java.io.*;
public class Main {
    public static final double EPSILON = Math.pow(10, -9);
    public static boolean div(double a, double b) {
        double k = a / b;
        return equals(k, Math.floor(k));
    }
    public static boolean equals(double a, double b) {
        return Math.abs(a - b) <= EPSILON;
    }
    public static boolean ok(int cnt, int ang) {
        double one = (360.0 / cnt) / 2.0;
        double k = ang / one;
        if (!equals(k, Math.floor(k))) return false;
        double rest = 180.0 - ang;
        if (!div(rest, one)) return false;
        double sum = rest / one;
        return sum >= 2;
    }
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int t = in.nextInt();
        for (int i = 0; i < t; i++) {
            int n = in.nextInt();
            if (n == 180) {
                System.out.println(-1);
                continue;
            }
            for (int x = 3;; x++) {
                if (ok(x, n)) {
                    System.out.println(x);
                    break;
                }
            }
        }
    }
}