It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
t = int(input())
t+=1
while True:
    y = []
    n = t
    while(n!=0):
        if n%10 not in y:
            y.append(n%10)
        else:
            break
        n//=10
    t1 = str(t)
    if len(y) == len(t1):
        print(t)
        break
    t+=1

#
# t = 2013
# y = []
# n = t
# while(n!=0):
#     if n%10 not in y:
#         y.append(n%10)
#     else:
#         break
#     n//=10
#
# print(len(y))
