It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
import sys
import math
s = int(input())
s += 1
def distinct(number):
        a = [0,0,0,0]
        for i in range(4):
                a[i] = number % 10
                number = int(number / 10)
        # print(a)
        if len(set(a)) != 4:
                return False
        else:
                return True

while distinct(s) == False:
        s +=1
print(s)
