It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
int main() {
  int n, x, r1, r2, r3, q1, q2, q3;
  vector<int> v;
  cin >> n;
  for (int i = 1; i < 1000; i++) {
    x = n + i;
    r1 = x % 10;
    q1 = x / 10;
    q2 = q1 / 10;
    r2 = q1 % 10;
    r3 = q2 % 10;
    q3 = q2 / 10;
    if (r1 != r2 && r1 != q3 && r1 != r3 && r2 != r3 && r2 != q3 && r3 != q3) {
      cout << x;
      break;
    }
  }
}
