It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
'''                              Hariom_Pandey
                                  12.11.2019                                       '''
import math as mt
import sys as sy
class abc:
    def mkl(self,):
        n = int(input())
        for i in range(n+1,9013):
            l=sorted(list(str(i)))
            if(l[0]!=l[1] and l[1]!=l[2] and l[2]!=l[3] and l[3]!=l[0]):
                print(i)
                break
 
b=abc()
b.mkl()