It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#!/bin/python3

import os
import sys
t=0
s=input()
l=len(s)
c=int(s)
c=c+1
s=str(c)
for k in range(1,10000):
    for i in range(0,l-1):
        for j in range(i+1,l):
            t=0
            #print(s[i],s[j])
            #print("\n")
            if s[i]==s[j]:
                t=5
                #print("break1")
                break
        if t==5:
            #print("break2")
            break
    if t!=5:
        print(s)
        #print("finalbreak")
        break
    else:
        p=int(s)
        p=p+1
        s=str(p)

