It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
year=int(raw_input())
i=year+1
flag=0
l=[]
while(i):
	k=str(i)
	#l=map(int,i.split())
	#print l
	l=list(k)
	#print l
	#for j in range(0,len(k)):
	#	l.append(k[j])
	#print l
	for j in l:
		#print l.count(j)

		#if(l.count(j)>1):
			if(l[0]!=l[1] and l[0]!=l[2] and l[0]!=l[3] and l[1]!=l[2] and l[2]!=l[3] and l[1]!=l[3] ):
			#print j
				flag=1
				break
	if(flag==1):
		print i
		exit()
	else:
		#print i
		i=i+1	