The Free Meteor Association (FMA) has got a problem: as meteors are moving, the Universal Cosmic Descriptive Humorous Program (UCDHP) needs to add a special module that would analyze this movement. 

UCDHP stores some secret information about meteors as an n × m table with integers in its cells. The order of meteors in the Universe is changing. That's why the main UCDHP module receives the following queries:

  * The query to swap two table rows; 
  * The query to swap two table columns; 
  * The query to obtain a secret number in a particular table cell. 



As the main UCDHP module is critical, writing the functional of working with the table has been commissioned to you.

Input

The first line contains three space-separated integers n, m and k (1 ≤ n, m ≤ 1000, 1 ≤ k ≤ 500000) — the number of table columns and rows and the number of queries, correspondingly.

Next n lines contain m space-separated numbers each — the initial state of the table. Each number p in the table is an integer and satisfies the inequality 0 ≤ p ≤ 106.

Next k lines contain queries in the format "si xi yi", where si is one of the characters "с", "r" or "g", and xi, yi are two integers.

  * If si = "c", then the current query is the query to swap columns with indexes xi and yi (1 ≤ x, y ≤ m, x ≠ y); 
  * If si = "r", then the current query is the query to swap rows with indexes xi and yi (1 ≤ x, y ≤ n, x ≠ y); 
  * If si = "g", then the current query is the query to obtain the number that located in the xi-th row and in the yi-th column (1 ≤ x ≤ n, 1 ≤ y ≤ m). 



The table rows are considered to be indexed from top to bottom from 1 to n, and the table columns — from left to right from 1 to m.

Output

For each query to obtain a number (si = "g") print the required number. Print the answers to the queries in the order of the queries in the input.

Examples

Input

3 3 5
1 2 3
4 5 6
7 8 9
g 3 2
r 3 2
c 2 3
g 2 2
g 3 2


Output

8
9
6


Input

2 3 3
1 2 4
3 1 5
c 2 1
r 1 2
g 1 3


Output

5

Note

Let's see how the table changes in the second test case.

After the first operation is fulfilled, the table looks like that:

2 1 4

1 3 5

After the second operation is fulfilled, the table looks like that:

1 3 5

2 1 4

So the answer to the third query (the number located in the first row and in the third column) will be 5.


import java.awt.Point;
import java.io.*;
import java.math.BigInteger;
import java.util.*;

import static java.lang.Math.*;

public class B implements Runnable{
	
	final boolean ONLINE_JUDGE = System.getProperty("ONLINE_JUDGE") != null;
	
	BufferedReader in;
	PrintWriter out;
	StringTokenizer tok = new StringTokenizer("");
	
	void init() throws FileNotFoundException{
		if (ONLINE_JUDGE){
			in = new BufferedReader(new InputStreamReader(System.in));
			out = new PrintWriter(System.out);
		}else{
			in = new BufferedReader(new FileReader("input.txt"));
			out = new PrintWriter("output.txt");
		}
	}
	
	String readString() throws IOException{
		while(!tok.hasMoreTokens()){
			try{
				tok = new StringTokenizer(in.readLine());
			}catch (Exception e){
				return null;
			}
		}
		return tok.nextToken();
	}
	
	int readInt() throws IOException{
		return Integer.parseInt(readString());
	}
	
	long readLong() throws IOException{
		return Long.parseLong(readString());
	}
	
	double readDouble() throws IOException{
		return Double.parseDouble(readString());
	}
	
	public static void main(String[] args){
		new Thread(null, new B(), "", 128 * (1L << 20)).start();
	}
	
	long timeBegin, timeEnd;

	void time(){
		timeEnd = System.currentTimeMillis();
		System.err.println("Time = " + (timeEnd - timeBegin));
	}
	
	long memoryTotal, memoryFree;
	

	void memory(){
		memoryFree = Runtime.getRuntime().freeMemory();
		System.err.println("Memory = " + ((memoryTotal - memoryFree) >> 10) + " KB");
	}
	
	void debug(Object... objects){
		if (DEBUG){
			for (Object o: objects){
				System.err.println(o.toString());
			}
		}
	}
	
	public void run(){
		try{
			timeBegin = System.currentTimeMillis();
			memoryTotal = Runtime.getRuntime().freeMemory();
			init();
			solve();
			out.close();
			time();
			memory();
		}catch (Exception e){
			e.printStackTrace(System.err);
			System.exit(-1);
		}
	}
	
	boolean DEBUG = false;
	
	void solve() throws IOException{
		int n = readInt();
		int m = readInt();
		
		int k = readInt();
		
		int[][] a = new int[n][m];
		for (int i = 0; i < n; ++i){
			for (int j = 0; j < m; ++j){
				a[i][j] = readInt();
			}
		}
		
		int[] row = new int[n];
		for (int i = 0; i < n; ++i){
			row[i] = i;
		}
		
		int[] column = new int[m];
		for (int j = 0; j < m; ++j){
			column[j] = j;
		}
		
		while (k-- > 0){
			char operation = readString().charAt(0);
			
			int x = readInt() - 1;
			int y = readInt() - 1;
			
			if (operation == 'c'){
				int temp = column[x];
				column[x] = column[y];
				column[y] = temp;
			}else if (operation == 'r'){
				int temp = row[x];
				row[x] = row[y];
				row[y] = temp;
			}else{
				out.println(a[row[x]][column[y]]);
			}
		}
	}
}

