It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
bool yearCheck(int year) {
  vector<int> a(4);
  int i = 3;
  do {
    a[i] = year % 10;
    year /= 10;
    i--;
  } while (i >= 0);
  sort(a.begin(), a.end());
  if (binary_search(a.begin() + 1, a.end(), a[0]))
    return false;
  else if (binary_search(a.begin() + 2, a.end(), a[1]))
    return false;
  else if (binary_search(a.begin() + 3, a.end(), a[2]))
    return false;
  else
    return true;
}
int main() {
  int year;
  cin >> year;
  year++;
  while (!yearCheck(year)) {
    year++;
  }
  cout << year;
}
