It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
int main() {
  ios_base::sync_with_stdio(0);
  cin.tie(0);
  cout.tie(0);
  int y, m, c, d, u;
  cin >> y;
  bool by = false;
  while (!by) {
    y++;
    m = floor(y / 1000);
    c = floor(y / 100 - m * 10);
    d = floor(y / 10 - (m * 100 + c * 10));
    u = y - (m * 1000 + c * 100 + d * 10);
    if (m == c || c == d || d == u || m == d || m == u || c == u) {
    } else {
      cout << y << '\n';
      by = true;
    }
  }
  return 0;
}
