It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
a = input()
a = int(a)
a +=1
a = str(a)
b = int(a)
flag = True
def check(a):
    count = 0
    for i in range(len(a)):
        for j in range(len(a)):
            if a[i] == a[j]:
                count +=1
        if count > 1:
            return False
        count = 0
    return True

while flag == True:
    if check(a) == True:
        print(a)
        flag = False
        break
    else:
        b+=1
        a = str(b)
        