It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def dif(n):
  lista = []
  n = str(n)
  for i in n:
    n = int(n) 
    i = int(i)
    lista.append(i)
  if lista[1] == lista[0]:
    n += 100
    n -= lista[2]*10 + lista[3]
    dif(n)
  elif lista[2] == lista[0]:
    n += 10
    n -= lista[3]
    dif(n)
  elif lista[2] == lista[1]:
    n += 10
    n -= lista[3]
    dif(n)
  elif lista[3] == lista[0]:
    n += 1
    dif(n)
  elif lista[3] == lista[1]:
    n += 1
    dif(n)
  elif lista[3] == lista[2]:
    n += 1
    dif(n)
  else:
    print(n)
n = int(input()) + 1
dif(n)