It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014





y = int(input())
#print(f"y: {y}")
y += 1
#print(f"y: {y}")

active = True
#print(f"active: {active}")


while active == True:

	year = []
	for i in str(y):
		year.append(i)
	#print(f"firstyear: {year}")

	distinct = True
	#print(f"distinct: {distinct}")
	i = 0
	#print(f"i: {i}")
	#while i is less than 4
	while distinct and i < len(year):
		j = i + 1
		#print(f"j: {j}")
		#while j is less than 4
		while distinct and j < len(year):
			#if year[j] == year[i], nondistinct, move to next year
			#print(f"year[i]: {year[i]}")
			#print(f"year[j]: {year[j]}")
			if year[i] == year[j]:
				distinct = False
				#print(f"distinct: {distinct}")
			j += 1
			#print(f"j: {j}")
		i += 1
		#print(f"i: {i}")
	if distinct == True:
		active = False
		#print(f"active: {active}")
	else:
		y += 1	
		#print(f"y: {y}")

print (y)
#print(f"y: {y}")


