The Free Meteor Association (FMA) has got a problem: as meteors are moving, the Universal Cosmic Descriptive Humorous Program (UCDHP) needs to add a special module that would analyze this movement. 

UCDHP stores some secret information about meteors as an n × m table with integers in its cells. The order of meteors in the Universe is changing. That's why the main UCDHP module receives the following queries:

  * The query to swap two table rows; 
  * The query to swap two table columns; 
  * The query to obtain a secret number in a particular table cell. 



As the main UCDHP module is critical, writing the functional of working with the table has been commissioned to you.

Input

The first line contains three space-separated integers n, m and k (1 ≤ n, m ≤ 1000, 1 ≤ k ≤ 500000) — the number of table columns and rows and the number of queries, correspondingly.

Next n lines contain m space-separated numbers each — the initial state of the table. Each number p in the table is an integer and satisfies the inequality 0 ≤ p ≤ 106.

Next k lines contain queries in the format "si xi yi", where si is one of the characters "с", "r" or "g", and xi, yi are two integers.

  * If si = "c", then the current query is the query to swap columns with indexes xi and yi (1 ≤ x, y ≤ m, x ≠ y); 
  * If si = "r", then the current query is the query to swap rows with indexes xi and yi (1 ≤ x, y ≤ n, x ≠ y); 
  * If si = "g", then the current query is the query to obtain the number that located in the xi-th row and in the yi-th column (1 ≤ x ≤ n, 1 ≤ y ≤ m). 



The table rows are considered to be indexed from top to bottom from 1 to n, and the table columns — from left to right from 1 to m.

Output

For each query to obtain a number (si = "g") print the required number. Print the answers to the queries in the order of the queries in the input.

Examples

Input

3 3 5
1 2 3
4 5 6
7 8 9
g 3 2
r 3 2
c 2 3
g 2 2
g 3 2


Output

8
9
6


Input

2 3 3
1 2 4
3 1 5
c 2 1
r 1 2
g 1 3


Output

5

Note

Let's see how the table changes in the second test case.

After the first operation is fulfilled, the table looks like that:

2 1 4

1 3 5

After the second operation is fulfilled, the table looks like that:

1 3 5

2 1 4

So the answer to the third query (the number located in the first row and in the third column) will be 5.
import java.io.*;
import java.math.BigInteger;
import java.util.*;


public class B
{
        String line;
        StringTokenizer inputParser;
        BufferedReader is;
        FileInputStream fstream;
        DataInputStream in;
        String FInput="";
        
        void openInput(String file)
        {

                if(file==null)is = new BufferedReader(new InputStreamReader(System.in));//stdin
                else
                {
                        try{
                
                                
                        fstream = new FileInputStream(file);
                        in = new DataInputStream(fstream);
                        is = new BufferedReader(new InputStreamReader(in));
                        }catch(Exception e)
                        {
                                System.err.println(e);
                        }
                }

        }
        
        void readNextLine()
    	{
    		try {
    			line = is.readLine();
    			inputParser = new StringTokenizer(line, " ");
    			//System.err.println("Input: " + line);
    		} catch (IOException e) {
    			System.err.println("Unexpected IO ERROR: " + e);
    		}	
    		catch (NullPointerException e)
    		{
    			line=null;
    			
    		}
    		
    	}
        
        long NextLong()
        {
                String n = inputParser.nextToken();
                
                long val = Long.parseLong(n);
                
                 return val;
        }
        
        int NextInt()
        {
                String n = inputParser.nextToken();
                int val = Integer.parseInt(n);
                
                //System.out.println("I read this number: " + val);
                return val;
        }
        
        String NextString()
        {
                String n = inputParser.nextToken();
                return n;
        }
        
        void closeInput()
        {
                try {
                        is.close();
                } catch (IOException e) {
                        System.err.println("Unexpected IO ERROR: " + e);
                }
                        
        }
        
        
        public static void main(String [] argv)
        {
                String filePath=null;
                if(argv.length>0)filePath=argv[0];
                new B(filePath);
        }
        
        public void readFInput()
    	{
    		for(;;)
    		{
    			try
    			{
    				readNextLine();
    				FInput+=line+" ";
    			}
    			catch(Exception e)
    			{
    				break;
    			}
    		}
    		inputParser = new StringTokenizer(FInput, " ");
    	}
        
       
        public B(String inputFile)
        {
        	openInput(inputFile);
        	
        	readNextLine();
    		
    		int n=NextInt(),m=NextInt(),k=NextInt();

    		int [] [] p = new int [n][m];
    		int [] c = new int[m];
    		int [] r = new int[n];
        	for(int i=0; i<n; i++)
        	{	
        		r[i]=i;
        		readNextLine();
        		for(int j=0; j<m; j++)
        		{
        			p[i][j]=NextInt();
        		}
        	}
        	for(int j=0; j<m; j++)
        		c[j]=j;
        	for(int t=0; t<k; t++)
        	{
        		readNextLine();
        		String op=NextString();
        		int x=NextInt()-1, y=NextInt()-1;
        		if(op.charAt(0)=='c')
        		{
        			int tmp=c[x];
        			c[x]=c[y];
        			c[y]=tmp;
        		}
        		else if(op.charAt(0)=='r')
        		{
        			int tmp=r[x];
        			r[x]=r[y];
        			r[y]=tmp;
        		}
        		else System.out.println(p[r[x]][c[y]]);
        	}
    		
            closeInput();		
    	}

       
}