It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def no_rep(num):
    num_str = str(num)
    hash = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
    for letter in num_str:
        hash[int(letter)] = hash[int(letter)] + 1
        if hash[int(letter)] > 1 :
            return False
    return True

n = input()
n_int = int(n)
n_int = n_int + 1
while True:
    if (no_rep(n_int)):
        print(n_int)
        exit()
    n_int = n_int + 1
