It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
import sys

def year():
    listyear = []
    year = input().split()
    k = True
    for i in range(len(year[0])):
        listyear.append(int(year[0][i]))
    listyear.reverse()
    return(listyear)

def nextyear(listyear):
    if listyear[0] == 9:
        listyear[0] = 0
        if listyear[1] == 9:
            listyear[1] = 0
            if listyear[2] == 9:
                listyear[2] = 0
                if listyear[3] == 9:
                    listyear[3] = 0
                else:
                    listyear[3] += 1
            else:
                listyear[2] += 1
        else:
            listyear[1] += 1
    else:
        listyear[0] += 1
    return listyear

def rightyear(listyear):
    nextyear(listyear)
    while len(set(listyear)) != 4:
        listyear = nextyear(listyear)
    listyear.reverse()

    for i in listyear:
        print(i,end="")
    
rightyear(year())
