It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def is_beautiful_year(year: int) -> bool:
    year_string = "%d" % year
    year_digits = set()

    for digit in year_string:
        year_digits.add(digit)

    return len(year_digits) == len(year_string)

def find_next_beautiful_year(year: int) -> int:
    next_year = year + 1

    while (not is_beautiful_year(next_year)):
        next_year += 1

    return next_year

print(find_next_beautiful_year(int(input())))