You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
long long n;
int c[4005];
long long cnt[9 * 4005];
void pre_sum(string &s) {
  c[0] = 0;
  for (int i = 1; i <= n; i++) {
    c[i] = c[i - 1] + (s[i - 1] - '0');
  }
  for (int i = 0; i < n; i++) {
    for (int j = i; j < n; j++) {
      cnt[c[j + 1] - c[i]]++;
    }
  }
}
int main(int argc, const char *argv[]) {
  int a;
  string s;
  cin >> a >> s;
  n = s.length();
  pre_sum(s);
  if (a == 0) {
    cout << cnt[0] * n * (n + 1) - cnt[0] * cnt[0] << endl;
    return 0;
  }
  int b = ceil(sqrt(a));
  long long total = 0;
  for (int i = 1; i <= b; i++) {
    if (a % i == 0) {
      if (a / i > 4000 * 9 || i > 4000 * 9) {
        continue;
      }
      if (a == i * i) {
        total += cnt[i] * cnt[a / i];
      } else if (i < a / i) {
        total += cnt[i] * cnt[a / i] * 2;
      }
    }
  }
  cout << total << endl;
  return 0;
}
