You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
int a;
char s[4444];
long long sum[4444];
long long n;
long long dem[44444];
long long kq;
int main() {
  scanf("%d\n", &a);
  scanf("%s", s + 1);
  n = strlen(s + 1);
  for (int i = 1; i <= n; i++) {
    sum[i] = sum[i - 1] + (int(s[i]) - 48);
    for (int j = i; j >= 1; j--) {
      dem[sum[i] - sum[j - 1]]++;
    }
  }
  kq = 0;
  if (a == 0) {
    for (int i = 1; i <= 9 * n; i++) {
      kq += dem[i] * dem[0];
    }
    printf("%I64d", kq * 2 + dem[0] * dem[0]);
    return 0;
  }
  for (int i = 1; i <= 9 * n; i++) {
    if (a % i == 0) {
      if (i >= 0 && i <= 9 * n && a / i >= 0 && a / i <= 9 * n)
        kq += dem[i] * dem[a / i];
    }
  }
  printf("%I64d", kq);
  return 0;
}
