It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def fun(num):
    count,temp,set1=0,num,{1,2,3}
    set1.clear()
    while temp!=0:
        count+=1
        temp=temp//10
    temp=num
    while temp!=0:
        set1.add(temp%10)
        temp=temp//10
    if len(set1)==count:
        return 1
    else:
        set1.clear()
        return 0
    
num=int(input())
while True:
    num+=1
    s=fun(num)
    if s==1:
        print(num);
        break;