It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
int main() {
  int n;
  cin >> n;
  bool f = true;
  for (int i = 1; i <= n; i++) {
    n = n + 1;
    int d = n;
    for (; d != 0;) {
      int c = d / 10;
      for (; c != 0;) {
        if (d % 10 == c % 10) {
          f = false;
          break;
        }
        c = c / 10;
      }
      d /= 10;
      if (f == false) {
        break;
      }
    }
    if (f) {
      cout << n << endl;
      break;
    } else
      f = true;
  }
}
