It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n = input()

def chek(s):
	c = 0
	for i in range(len(s)):
		for j in range(len(s)-1-i):
			if s[i] == s[i+j+1]:
				c += 1
	
	if c == 0:
		return True
	else:
		return False

b = int(n)+1
b = str(b)

while True:

	if chek(b) == True:
		print(b)
		break
	
	b = str(int(b)+1)
				
	

