You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
long long a;
string s;
long long todos[4000 * 10];
int val[5000];
long long get_suma(int x, int y) {
  long long r = val[y];
  if (x) r -= val[x - 1];
  return r;
}
int main() {
  cin >> a;
  cin >> s;
  int tam = (int)s.size();
  val[0] = (s[0] - '0');
  for (int i = 1; i < tam; i++) val[i] = (val[i - 1]) + (s[i] - '0');
  for (int i = 0; i < tam; i++)
    for (int j = i; j < tam; j++) {
      todos[get_suma(i, j)]++;
    }
  long long res = 0;
  if (a == 0) {
    if (todos[0] > 0) {
      res = todos[0] * tam * (tam + 1) / 2;
      for (int i = 1; i < 40000; i++) res += todos[i] * todos[0];
    }
  } else {
    for (int i = 1; i < 40000; i++) {
      if (todos[i] > 0) {
        long long a1 = i;
        if (a % a1 == 0) {
          long long b1 = a / a1;
          if (b1 >= 4000 * 10) continue;
          res += todos[a1] * todos[b1];
        }
      }
    }
  }
  cout << res << endl;
  return 0;
}
