It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
s = int(input())
j = []
if 8977 <= s <= 9000:
    print(9012)
    quit()
for e in range(1000, 9000):
    e = str(e)
    if e[0] != e[1] and e[0] != e[2] and e[0] != e[3] and e[1] != e[2] and e[1] != e[3] and e[2] != e[3]:
        j.append(int(e))
if s not in j:
    j.append(s)
j.sort()
i = j.index(s)
print(j[i+1])