A permutation of length n is a sequence of integers from 1 to n of length n containing each number exactly once. For example, [1], [4, 3, 5, 1, 2], [3, 2, 1] are permutations, and [1, 1], [0, 1], [2, 2, 1, 4] are not.

There was a permutation p[1 ... n]. It was merged with itself. In other words, let's take two instances of p and insert elements of the second p into the first maintaining relative order of elements. The result is a sequence of the length 2n.

For example, if p=[3, 1, 2] some possible results are: [3, 1, 2, 3, 1, 2], [3, 3, 1, 1, 2, 2], [3, 1, 3, 1, 2, 2]. The following sequences are not possible results of a merging: [1, 3, 2, 1, 2, 3], [3, 1, 2, 3, 2, 1], [3, 3, 1, 2, 2, 1].

For example, if p=[2, 1] the possible results are: [2, 2, 1, 1], [2, 1, 2, 1]. The following sequences are not possible results of a merging: [1, 1, 2, 2], [2, 1, 1, 2], [1, 2, 2, 1].

Your task is to restore the permutation p by the given resulting sequence a. It is guaranteed that the answer exists and is unique.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 400) — the number of test cases. Then t test cases follow.

The first line of the test case contains one integer n (1 ≤ n ≤ 50) — the length of permutation. The second line of the test case contains 2n integers a_1, a_2, ..., a_{2n} (1 ≤ a_i ≤ n), where a_i is the i-th element of a. It is guaranteed that the array a represents the result of merging of some permutation p with the same permutation p.

Output

For each test case, print the answer: n integers p_1, p_2, ..., p_n (1 ≤ p_i ≤ n), representing the initial permutation. It is guaranteed that the answer exists and is unique.

Example

Input


5
2
1 1 2 2
4
1 3 1 4 3 4 2 2
5
1 2 1 2 3 4 3 5 4 5
3
1 2 3 1 2 3
4
2 3 2 4 1 3 4 1


Output


1 2 
1 3 4 2 
1 2 3 4 5 
1 2 3 
2 3 4 1 
#*****DO NOT COPY*****
#F
#U       ___                     ___                         ___           ___           ___           ___          _____
#C      /  /\      ___          /  /\          ___          /__/\         /  /\         /  /\         /  /\        /  /::\
#K     /  /::\    /  /\        /  /:/_        /  /\         \  \:\       /  /::\       /  /::\       /  /:/_      /  /:/\:\
#     /  /:/\:\  /  /:/       /  /:/ /\      /  /::\         \  \:\     /  /:/\:\     /  /:/\:\     /  /:/ /\    /  /:/  \:\
#Y   /  /:/~/:/ /__/::\      /  /:/ /::\    /  /:/\:\    ___  \  \:\   /  /:/~/::\   /  /:/~/:/    /  /:/ /:/_  /__/:/ \__\:|
#O  /__/:/ /:/  \__\/\:\__  /__/:/ /:/\:\  /  /:/~/::\  /__/\  \__\:\ /__/:/ /:/\:\ /__/:/ /:/___ /__/:/ /:/ /\ \  \:\ /  /:/
#U  \  \:\/:/      \  \:\/\ \  \:\/:/~/:/ /__/:/ /:/\:\ \  \:\ /  /:/ \  \:\/:/__\/ \  \:\/:::::/ \  \:\/:/ /:/  \  \:\  /:/
#    \  \::/        \__\::/  \  \::/ /:/  \  \:\/:/__\/  \  \:\  /:/   \  \::/       \  \::/~~~~   \  \::/ /:/    \  \:\/:/
#A    \  \:\        /__/:/    \__\/ /:/    \  \::/        \  \:\/:/     \  \:\        \  \:\        \  \:\/:/      \  \::/
#L     \  \:\       \__\/       /__/:/      \__\/          \  \::/       \  \:\        \  \:\        \  \::/        \__\/
#L      \__\/                   \__\/                       \__\/         \__\/         \__\/         \__\/
#
#
#*****DO NOT COPY*****

def solve(n, arr):
    out = []
    for i in range(2 * n):
        if arr[i] not in out:
            out.append(arr[i])
            if len(out) == n:
                out = map(str , out)
                return " ".join(out)


for _ in range(int(input())):
    n = int(input())
    arr = list(map(int , input().split()))
    print(solve(n, arr))