It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
y = int(input())

Y = []
y += 1
for x in str(y):
    Y.append(x)

def myfunc():
    n = y
    j = 0
    i =0
    equal = False
    while(i<4):
        while(j<4):
            if(i == j):
                j+= 1
                continue
            else:
                if(Y[i] == Y[j]):
                    n+= 1
                    Y.clear()
                    for x in str(n):
                        Y.append(x)
                        i = 0
                        j = 0
                else:
                    equal = True
            j+=1
        j = 0
        i+= 1

        if(equal == True and i == 3):
            print(n)
            return

myfunc()
