It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
x = int(input())

i = 1000
j = 0

lst = []

for j in range(9000):
    y = str(i)
    y1 = int(y[0])
    y2 = int(y[1])
    y3 = int(y[2])
    y4 = int(y[3])
    if(y1 != y2 and y1 != y3 and y1 != y4 and y2 != y3 and y2 != y4 and y3 != y4):
        lst.append(int(i))
    i += 1

for j in range(len(lst)-1):
    if(x<lst[j]):
        print(lst[j])
        j+=9000
        break
    j += 1



    


