It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014

n=[int(i) for i in input()]
n[-1]+=1
n[-2]+=n[-1]//10
n[-3]+=n[-2]//10
n[-4]+=n[-3]//10
n[-1]%=10
n[-2]%=10
n[-3]%=10
while n[-1]==n[-2] or n[-3]==n[-2]  or n[-1]==n[-4]  or n[-1]==n[-3]  or n[-3]==n[-4]  or n[-2]==n[-4] or n[-3]==n[-4]:
  n[-1]+=1
  n[-2]+=n[-1]//10
  n[-3]+=n[-2]//10
  n[-4]+=n[-3]//10
  n[-1]%=10
  n[-2]%=10
  n[-3]%=10
print(''.join(str(i) for i in n))