It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def find():
    f=int(input())
    while True:
        f+=1
        g=str(f)
        check=0
        for i in range(0,4):
            for j in range(0,4):
                if j==i:
                    continue
                if g[j]==g[i]:
                    check=1
                    break
            if check==1:
                break
        if check==0:
            print(f)
            return

if __name__ == '__main__':
    find()
