It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def check(k):
    l=[]
    while(k>0):
        m=k%10
        l.append(m)
        k=k//10
    for i in range(len(l)):
        for j in range(i+1,len(l)):
            if(l[i]==l[j]):
                return False
    return True

if __name__=='__main__':
    n=int(input())
    i=n+1
    while(i):
        if(check(i)):
            print(i)
            break
        i+=1

    
    

    

        