It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def getdic(n):
    d={}
    while n!=0:
        #print(n)
        digit = n%10
        d[digit] = d.get(digit,0)+1
        n = n//10
    return d 
n=int(input())
flag = False
n+=1
for i in range(500):
    #print(n+i)
    d = getdic(n+i)
    c=0
    for val in d.values():
        
        if val == 1:
            c+=1
    if c==4:
        print(n+i)
        break