It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
inp=int(input())
lst=list()
fnl_lst=list()
x=1
while True:
    year=inp+x
    #print(year)
    x=x+1
    s=str(year)
    if s not in lst:
        lst.append(s)
    if year==9019:
        break

#print(lst)

for a in lst:
    if a[0]!=a[1] and a[0]!=a[2] and a[0]!=a[3] and a[1]!=a[2] and a[1]!=a[3] and a[2]!=a[3]:
        fnl_lst.append(a)

#print(fnl_lst)

fnl_lst.sort()

req_year=int(fnl_lst[0])

#sub=req_year-inp
print(req_year)
