It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
int main() {
  int y;
  cin >> y;
  for (int i = y + 1;; i++) {
    int p1, p2, p3, p4;
    p1 = i % 10;
    p2 = (i / 10) % 10;
    p3 = (i / 100) % 10;
    p4 = i / 1000;
    if (p1 != p2 && p1 != p3 && p1 != p4 && p2 != p3 && p2 != p4 && p3 != p4) {
      cout << i;
      break;
    }
  }
  return 0;
}
