It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def is_duplicate(y):
    digits = set()
    while y:
        digits.add(y % 10)
        y = y // 10

    return True if len(digits) == 4 else False


def find_next_beautiful_year(y):
    while True:
        if is_duplicate(y):
            return y
        y += 1


if __name__ == '__main__':
    year = int(input())
    print(find_next_beautiful_year(year + 1))
