It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
# -*- coding: utf-8 -*-
"""
Created on Fri Nov  8 19:55:28 2019

@author: jk Jin
"""
dig = [0,0,0,0]
y = int(input())
while True:
    dig = [0,0,0,0]
    y += 1
    z = y
    for i in range(4):
        dig[i] = z%10
        z = z//10
    stat = 1
    for i in range(3):
        for j in range(i+1,4):
            if dig[i]==dig[j]:
                stat = 0
                break
        if stat == 0:
            break
    if stat == 0:
        continue
    else:
        print(y)
        break