It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def nextDistinctYear(y):
    y += 1
    while True:
        if isDistinct(y):
            return y
        y += 1

def isDistinct(y):
    yl = list(map(int, str(y)))
    distinct = True
    
    for i in range(len(yl)):
        for j in range(len(yl)):
            if i == j:
                continue
            if yl[i] == yl[j]:
                distinct = False

    return distinct


if __name__ == "__main__":
    year = int(input())
    print(nextDistinctYear(year))