It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n = input()
year = [int(x) for x in str(n)]
numbers = []

for i in  range (int(n)+1, 9013):
    a= (i-i%1000)/1000
    b= (i%1000 -i%100)/100
    c= (i%100 - i%10)/10
    d= i%10
    if a!= b and a!= c and a!=d and b!=c and b!=d and c!=d:
        numbers.append(i)

numbers.sort()
print(numbers[0])







