You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
int N, M, T;
int main() {
  int i, j, k;
  char s[4005];
  scanf("%d", &N);
  scanf("%s", s);
  map<int, int> mp;
  vector<int> v;
  k = strlen(s);
  v.push_back((0));
  for (i = 1; i <= k; i++) v.push_back((s[i - 1] - '0')), v[i] += v[i - 1];
  ;
  for (i = 1; i <= k; i++)
    for (j = i; j <= k; j++) mp[v[j] - v[i - 1]]++;
  if (N == 0) {
    long long xx = mp[0];
    long long yy = xx * (k * (k + 1) / 2);
    printf("%I64d\n", 2 * yy - xx * xx);
    return 0;
  }
  long long sum = 0, x, y;
  M = (int)sqrt(N);
  for (i = 1; i <= M; i++) {
    if (N % i == 0) {
      x = mp[i];
      y = mp[N / i];
      sum += (x * y);
      if (i != (N / i)) sum += (x * y);
    }
  }
  printf("%I64d\n", sum);
}
