You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
int a, n;
char s[4040];
int f[36363];
int main() {
  scanf("%d", &a);
  scanf("%s", s + 1);
  n = strlen(s + 1);
  memset(f, 0, sizeof f);
  for (int i = 1; i <= n; i++) {
    int sum = 0;
    for (int j = i; j <= n; j++) {
      sum += s[j] - '0';
      f[sum]++;
    }
  }
  long long ret = 0;
  for (int i = 1; i <= n; i++) {
    int sum = 0;
    for (int j = i; j <= n; j++) {
      sum += s[j] - '0';
      if (!a && !sum)
        ret += (n + 1) * n / 2;
      else if (sum && a % sum == 0 && a / sum <= n * 9)
        ret += f[a / sum];
    }
  }
  printf("%I64d\n", ret);
  return 0;
}
