It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#/usr/bin/python3

# MC721A
# 03 de abril de 2020
# Rogério Meirelles - RA160245

n = int(input())

isUnique = False

while not isUnique:
    n += 1
    digits = [int(x) for x in str(n)]
    digits.sort()

    isUnique = True
    prev = digits[0]
    for i in digits[1:]:
        if i == prev:
            isUnique = False
        prev = i

print(n)
 	    					       	 	 		 			  	