It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
import sys
readInts = lambda : map(int, raw_input().strip().split())
readArgs = lambda : raw_input().strip().split()
write = lambda *s: sys.stdout.write(' '.join(map(str, s)))

def ok(t):
	e = {}
	while t > 0:
		d = t % 10
		if e.has_key(d):
			return False
		e[d] = 1
		t = t / 10
	return True

n = readInts()[0] + 1
while not ok(n):
	n += 1

print n
