It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
void ParseToArray(int* array, int number);
bool CheckRepeatedDigit(int* array);
int main() {
  int year;
  std::cin >> year;
  int testYear[4] = {0};
  for (int i = year + 1;; i++) {
    ParseToArray(testYear, i);
    if (CheckRepeatedDigit(testYear))
      continue;
    else {
      std::cout << i;
      break;
    }
  }
  return 0;
}
void ParseToArray(int* array, int number) {
  int i = 3;
  while (number != 0 && i >= 0) {
    array[i] = number % 10;
    number /= 10;
    i--;
  }
}
bool CheckRepeatedDigit(int* array) {
  for (int i = 0; i < 4; i++)
    for (int k = 0; i != k && k < 4; k++)
      if (array[i] == array[k]) return true;
  return false;
}
