It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
int main() {
  int x, y, in = 0;
  int s[4];
  cin >> y;
  y++;
  for (int i = y; i <= 10000; i++) {
    int q = 10000;
    in = i;
    for (int j = 0; j < 4; j++) {
      q = q / 10;
      s[j] = in / q;
      in = (int)i % (int)q;
    }
    if (s[0] != s[1] && s[2] != s[0] && s[0] != s[3] && s[1] != s[2] &&
        s[1] != s[3] && s[2] != s[3])
      break;
    else
      continue;
  }
  cout << s[0] << s[1] << s[2] << s[3];
  return 0;
}
