It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def beYear() :
    n=int(input())
    z=n
    r1=r2=r3=r4=0
    if ( 1000 <= n and n <= 9000) :
        while (r1 == r2 or r1== r3 or r1== r4 or r2==r3 or r2==r4 or r3==r4) :
            n=z=z+1
            r1 = n % 10
            n=n//10
            r2 = n % 10
            n=n//10
            r3 = n % 10
            n=n//10
            r4 = n % 10
            n=n//10
        print (z)
beYear()
