A permutation of length n is an array consisting of n distinct integers from 1 to n in arbitrary order. For example, [2,3,1,5,4] is a permutation, but [1,2,2] is not a permutation (2 appears twice in the array) and [1,3,4] is also not a permutation (n=3 but there is 4 in the array).

For a positive integer n, we call a permutation p of length n good if the following condition holds for every pair i and j (1 ≤ i ≤ j ≤ n) — 

  * (p_i  OR  p_{i+1}  OR  …  OR  p_{j-1}  OR  p_{j}) ≥ j-i+1, where OR denotes the [bitwise OR operation.](https://en.wikipedia.org/wiki/Bitwise_operation#OR)



In other words, a permutation p is good if for every subarray of p, the OR of all elements in it is not less than the number of elements in that subarray. 

Given a positive integer n, output any good permutation of length n. We can show that for the given constraints such a permutation always exists.

Input

Each test contains multiple test cases. The first line contains the number of test cases t (1 ≤ t ≤ 100). Description of the test cases follows.

The first and only line of every test case contains a single integer n (1 ≤ n ≤ 100).

Output

For every test, output any good permutation of length n on a separate line. 

Example

Input


3
1
3
7


Output


1
3 1 2
4 3 5 2 7 1 6

Note

For n = 3, [3,1,2] is a good permutation. Some of the subarrays are listed below. 

  * 3 OR 1 = 3 ≥ 2 (i = 1,j = 2) 
  * 3 OR 1 OR 2 = 3 ≥ 3 (i = 1,j = 3) 
  * 1 OR 2 = 3 ≥ 2 (i = 2,j = 3) 
  * 1 ≥ 1 (i = 2,j = 2) 



Similarly, you can verify that [4,3,5,2,7,1,6] is also good.
# def checkKey(dict, key): 
# 	if key in dict:
# 		return True
# 	return False
# def helper(s):
# 	l=len(s)
# 	if (l==1):
# 		l=[]
# 		l.append(s)
# 		return l
# 	ch=s[0]
# 	recresult=helper(s[1:])
# 	myresult=[]
# 	myresult.append(ch)
# 	for st in recresult:
# 		myresult.append(st)
# 		ts=ch+st
# 		myresult.append(ts)

# 	return myresult


# mod=1000000000+7
# def helper(s,n,open,close,i):
# 	if(i==2*n):
# 		for i in s:
# 			print(i,end='')
# 		print()
# 		return
# 	if(open<n):
# 		s[i]='('
# 		helper(s,n,open+1,close,i+1)
# 	if(close<open):
# 		s[i]=')'
# 		helper(s,n,open,close+1,i+1)

# def helper(n):
# 	if(len(n)==0):
# 		recresult=['']
# 		return recresult
# 	ch=n[0]
# 	recresult=helper(n[1:])
# 	myresult=[]
# 	for i in recresult:
# 		st=i
# 		for j in range(len(st)):
# 			ss=st[0:j]+ch+st[j:]
# 			myresult.append(ss)
# 		myresult.append(st+ch)
# 	return myresult
# import copy
# n=int(input())
# arr=list(map(int,input().split()))
# ans=[]
# def helper(arr,i,n):
# 	if(i==n-1):
# 		# for a in arr:
# 		# 	print(a,end=" ")
# 		# print()
# 		l=copy.deepcopy(arr)
# 		ans.append(l)
# 		return
# 	for j in range(i,n):
# 		if(i!=j):
# 			if(arr[i]==arr[j]):
# 				continue
# 			else:
# 				arr[i],arr[j]=arr[j],arr[i]
# 				helper(arr,i+1,n)
# 				arr[j],arr[i]=arr[i],arr[j]
# 		else:
# 			arr[i],arr[j]=arr[j],arr[i]
# 			helper(arr,i+1,n)
# 			arr[i],arr[j]=arr[j],arr[i]

t=int(input())
for test in range(t):
	n=int(input())
	while(n>0):
		print(n,end=" ")
		n-=1
	print()
















