It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n = int(input())
a = n + 1
while True:
    used = []
    b = a
    a0 = b // 1000
    b = b % 1000
    a1 = b // 100
    b = b % 100
    a2 = b // 10
    b = b % 10
    a3 = b // 1
    used.append(a0)
    if a1 not in used:
        used.append(a1)
    if a2 not in used:    
        used.append(a2)
    if a3 not in used:    
        used.append(a3)
    if len(used) == 4:
        print(a)
        break
    else:
        a += 1