It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
y=int(input())
yay=0
def valid(x):
	diff=True
	for j in range(0,4):
		for k in range(0,4):
			if (j==k):
				diff=diff and True
			else:
				diff=diff and (str(x)[j]!=str(x)[k])
	return(diff)
for a in range(1000,9013):
	if valid(a) and (a>y):
		if (yay==0):
			print(a)
			yay=1
		else:
			break
