You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
char ss[41000];
long long pp[41000];
long long sum[40010];
long long ff[400100];
long long a;
long long ans = 0;
int main() {
  cin >> a;
  cin >> ss;
  sum[0] = 0;
  memset(ff, 0, sizeof(ff));
  int len = strlen(ss);
  for (int i = 0; i < len; i++) pp[i] = ss[i] - '0';
  for (int i = 1; i <= len; i++) sum[i] = sum[i - 1] + pp[i - 1];
  for (int i = 1; i <= len; i++) {
    for (int j = 0; j < i; j++) {
      ff[sum[i] - sum[j]]++;
    }
  }
  if (a == 0) {
    cout << ff[0] * (len * (len - 1) / 2 + len) * 2 - ff[0] * ff[0];
    return 0;
  } else {
    for (int i = 1; i <= 400000; i++)
      if (ff[i] != 0 && a % i == 0 && a / i <= 400000 && ff[a / i] != 0) {
        ans += ff[i] * ff[a / i];
      }
    cout << ans << endl;
  }
}
