It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
x=input()
i=1
p=int(x)
if (1000<=p<=9000):
    while (i<2):
        p+=1
        a=int(p/1000)
        b=int((p%1000)/100)
        c=int((p%100)/10)
        d=int(p%10)
        if (a!=b) and (a!=c) and (a!=d) and (b!=c) and (b!=d) and (c!=d):
            print(p)
            if (p<p+1):
                break