It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def year(y):
    for i in range(y+1,9999):
        a = (i%10)
        b = ((i%100)/10)
        c = ((i/100)%10)
        d = (i/1000)
        if (a!=b)and(a!=c)and(a!=d)and(b!=c)and(b!=d)and(c!=d):
            #print (a,b,c,d)
            print i
            break
y = input()
year(y)