It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
bool Answer(int n) {
  int tmp = n, l;
  vector<int> dig;
  while (tmp != 0) {
    dig.push_back(tmp % 10);
    tmp /= 10;
  }
  l = dig.size();
  for (int i = 0; i < l - 1; i++) {
    for (int j = 0; j < l; j++) {
      if (i == j) continue;
      if (dig[i] == dig[j]) return false;
    }
  }
  return true;
}
int main() {
  int n;
  cin >> n;
  bool tmp;
  n++;
  while (true) {
    tmp = Answer(n);
    if (tmp) {
      break;
    }
    n++;
  }
  cout << n << endl;
}
