It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014


def next_beautiful_year(year):
    is_beautiful = False
    while is_beautiful is not True:
        year += 1
        distinct_nums = 0
        for num in str(year):
            if str(year).count(num) == 1:
                distinct_nums += 1
        if distinct_nums == len(str(year)):
            return year


def main():
    y = int(input())
    next_year = next_beautiful_year(y)
    print(next_year)


main()