It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
import math

def get_num(): return list(map(int, input().rstrip().split()))


def isLucky(num):
    array = [0]*10

    while(num>1):
        digit = math.floor(num%10)

        if (array[digit]):
            return 0

        array[digit]=1
        num = num/10

    return 1

def main():
    num = int(input())

    num += 1
    var = isLucky(num)
    while(var == 0):
        num+=1
        var = isLucky(num)
    print(num)


main()

