It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
import math

def num2digits(num):
    i=0;
    digits=[];
    while num>0:
        digits.append(i);
        digits[i]=num%10;
        num=math.floor(num/10);
        i=i+1;
    return digits;

n=int(input());
while 1:
    n=n+1;
    digits=num2digits(n);
    digits.sort();
    flag=1;
    for i in range (1,len(digits)):
        if digits[i]==digits[i-1]:
            flag=0;
            break;
    if flag>0:
        break;
print(n);