It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
# -*- coding: utf-8 -*-
"""
Created on Wed Aug 14 18:23:22 2019

@author: priya

beautiful year
"""

def distinct_digits(num):
    if(len(set(list(str(num)))) == len(str(num))):
        return True
    return False

def larger_num(num):
    num += 1
    while( not distinct_digits(num) ):
        num += 1
    return num

#print("Enter a year: ")
print(larger_num(int(input())))