It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
import sys

sy = input()
iy = int(sy)

iy += 1
sy = str(iy)

d = [False] * 10

while True: 
    find = True
    for i in range(len(sy)):
        if d[int(sy[i])] is False:
            d[int(sy[i])] = True
        else:
            find = False
            iy += 1
            sy = str(iy)
            d = [False] * 10
            break;
    if find:
        print(sy)
        sys.exit(0)
