It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#Distinct number years
n = int(input())
n = n + 1
l = []
unique_l = []
while len(unique_l) != 4:
    unique_l.clear()
    l.clear()
    m = n
    i = 0
    for i in range(4):
        k = m%10
        l.append(k)
        m = int(m/10)
    l_set = set(l)
    unique_l = list(l_set)
    if len(unique_l) != 4: n = n + 1
print(n)
