It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def is_unique(year):
    bucket = []
    for i in str(year):
        if i in bucket:
            break
        bucket.append(i)
    return len(bucket) == 4

def beautiful_year(year):

    if year >= 1000 and year <= 9000:
        while True:
            year += 1
            if is_unique(year):
                return year
                break

t = int(input())
x = beautiful_year(t)
print(x)