It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def HasDistinctDigits(nstr):
    digs=[]
    for i in nstr:
        digs.append(int(i))
    distinct_digs=[]
    #print digs
    for i in nstr:
        if int(i) not in distinct_digs:
            distinct_digs.append(int(i))
    for i in distinct_digs:
        if int(i) in digs:
            digs.remove(int(i))
    #print digs
    if len(digs)==0:
        return True
    else:
        return False

n=int(input())

for i in range(n+1,10000):
    if HasDistinctDigits(str(i)):
        print i
        break
