It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
# -*- coding: utf-8 -*-
"""
Created on Mon Aug 27 01:00:25 2018

@author: Sidhu
"""

inp = input()
n = int(inp)
k = n+1
points = 0
while(points < 4):
    points = 0
    temp = k
    a = []
    for i in range(1,5):
        r = temp%10
        if not r in a:
            a.append(r)
            points += 1
            temp -= r
            temp /= 10
    if(points == 4):
        print(k)
        break
    else:
        k += 1
        
