It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n=int(input());z=[];y=0;
while(True):
    n=n+1
    x=n
    y=0
    while(x!=0):
        z.append(x%10)
        x=x//10
    for i in range(len(z)):
        for j in range(i+1,len(z)):
            if(z[i]==z[j]):
                y=1
                break
        if(y==1):
            break
    if(y==1):
        z.clear()
    else:
        print(n)
        break
        