It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def seperateints(x):  
    k=''
    l=[]
    for i in x :
        if i==' ' :
            l.append(int(k))
            k=''
            continue 
        k=k+i
    l.append(int(k))   
    return(l)
def luckynum(x):
    for i in x : 
        if i!='4' and i!='7' :
            return False
    return True 
x=int(input())+1
s=str(x)
while True :
        if s[0]!=s[1] and s[0]!=s[2] and s[0]!=s[3] and s[1]!=s[2] and s[1]!=s[3] and s[2]!=s[3] :
            print(s)
            break
        x+=1
        s=str(x)
