You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
const int N = 4440;
char s[N];
int cnt[N * 100], c[N], sum[N];
int main() {
  int a, n;
  while (scanf("%d", &a) != EOF) {
    scanf("%s", s);
    n = strlen(s);
    for (int i = 0; i < n; i++) c[i] = s[i] - '0';
    sum[0] = 0;
    for (int i = 1; i < n + 1; i++) {
      sum[i] = sum[i - 1] + c[i - 1];
    }
    memset(cnt, 0, sizeof(cnt));
    for (int i = 1; i < n + 1; i++)
      for (int j = i; j < n + 1; j++) {
        int tmp = sum[j] - sum[i - 1];
        cnt[tmp]++;
      }
    long long ans = 0;
    for (int i = 1; i < n * 10; i++) {
      if (a % i == 0 && a / i < n * 10) {
        ans += (long long)cnt[i] * cnt[a / i];
      }
      if (a == 0) {
        ans += (long long)cnt[i] * cnt[0];
      }
    }
    if (a == 0) ans += (long long)cnt[0] * cnt[0];
    printf("%I64d\n", ans);
  }
}
