It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
from sys import stdin , stdout


year = int(stdin.readline())
year+=1

def digit(num):
    l = []
    while(num):
        l.append(num%10)
        num = num //10
    s = set(l)
    if len(s)==len(l):
        return True
    else:
        return False
        

while(True):
    if(digit(year)):
        stdout.write(str(year)+"\n")
        break
    else:
        year+=1
    
    
    
    


    