It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
q=int(input())
n=q+1
d1 = n % 10
d2 = n % 10000 // 1000
d3 = n % 100 // 10
d4 = n % 1000 // 100
b=[]
if d1 not in b:
    b.append(d1)
if d2 not in b:
    b.append(d2)
if d4 not in b:
    b.append(d4)
if d3 not in b:
    b.append(d3)
while len(b)<4:
    n+=1
    d1 = n % 10
    d2 = n % 10000 // 1000
    d3 = n % 100 // 10
    d4 = n % 1000 // 100
    b=[]
    if d1 not in b:
        b.append(d1)
    if d2 not in b:
        b.append(d2)
    if d4 not in b:
        b.append(d4)
    if d3 not in b:
        b.append(d3)
print(n)
