It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
year = int(input())
def areDigitsDistinct(number):
    digits = []
    while number//10 != 0:
        digits.append(number%10)
        number = number//10
    if number//10 == 0:
        digits.append(number)
    for i in range(len(digits)):
        for j in range(i+1,len(digits)):
            if digits[i] == digits[j]:
                return False
            else:
                continue

    return True


startYear = year + 1
while areDigitsDistinct(startYear) != True:
    startYear = startYear + 1

print(startYear)




