It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def main():
	year = input()
	print(next_unique_year(year,int(year)))

def next_unique_year(year,next_year):
	next_year = str(next_year)
	storage = []
	for i in range(4):
		if next_year[i] in storage:
			return next_unique_year(year, int(next_year) + 1)
			break;
		else:
			storage.append(next_year[i])
	if int(next_year) > int(year):
		return int(next_year)
	elif int(next_year) < int(year):
		return next_unique_year(year, int(next_year) + 1)
	else:
		return next_unique_year(year, int(next_year) + 1)

if __name__ == '__main__':
	main()