It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def check(s):
    l=[]
    while s!=0:
        b=s%10
        l.append(b)
        s=s//10
    flag=0    
    for i in l:
        count=l.count(i)
        if count>1:
            flag=1
        else:
            continue
    return flag    
s=int(input())
t=1
while t!=0:
    s=s+1
    t=check(s)
print(s) 