It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def distinctYear(yearly):
    nums = list(str(yearly))
    if nums[0] != nums[1] and nums[0] != nums[2] and nums[0] != nums[3]:
        if nums[1] != nums[2] and nums[1] != nums[3]:
            if nums[2] != nums[3]:
                return False
    return True


if __name__ == '__main__':
    year = int(input())
    year += 1
    while distinctYear(year):
        year += 1

    print(year)