It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
import math


def good(data):
    for i in range (4):
        for j in range(i+1,4):
            if data[i]==data[j]:
                return 0
    return 1

def plus(data,pos):
    #print(pos)
    if data[pos]<9:
        data[pos]+=1
    else:
        data[pos]=0
        plus(data,pos-1)

data=list(input())
data=[int(data[i]) for i in range (4)]
#print(data)
plus(data,3)



while not good(data):
    plus(data,3)

for i in range(4):
    print(data[i],sep='',end='')

print()
