It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
a = int(input())
b = list(map(int,*str(a+1).split()))

def seet(v):
    c = []
    for i in range(len(v)):
        if v[i] not in c:
            c.append(v[i])
    return c

while seet(b) != b:
    a +=1
    b = list(map(int,*str(a).split()))
print(*b,sep = "")