It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
import math

year = int(input()) + 1

def check(year):
    answer = True
    digits = [0 for _ in range(10)]
    while year !=0:
        digit = year % 10
        if digits[digit] != 0:
            answer = False
            break
        digits[digit] = 1

        year = math.floor(year / 10)

    return answer

answer = 0

while answer == 0:
    if check(year):
        answer = year
    year += 1

print(answer)