It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
import datetime

def beauty_year(inyear):
    for year in range(inyear+1,9013):
        tmp = year
        found = True
        digits=[]
        for i in range(4):
            d = tmp % 10
            if d in digits:
                found = False
                break
            digits.append(d)
            tmp /= 10
        if found:
            return year
   

if __name__ == "__main__":
    inyear = int(raw_input())
    print beauty_year(inyear)
