You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
const int MN = 4040;
map<int, int> m;
char s[MN];
int number(char c) { return c - '0'; }
int main() {
  int a;
  scanf("%d", &a);
  scanf("%s", s);
  int n = strlen(s), i;
  for ((i) = 0; (i) < (int)(n); ++(i)) {
    int sum = 0;
    for (int j = i; j < n; ++j) {
      sum += number(s[j]);
      ++m[sum];
    }
  }
  long long ans = 0;
  for ((i) = 0; (i) < (int)(n); ++(i)) {
    int sum = 0;
    for (int j = i; j < n; ++j) {
      sum += number(s[j]);
      if (sum == 0) {
        if (a == 0) {
          ans += n * (n + 1) / 2;
        }
        continue;
      }
      if (a % sum == 0) {
        if (!m.count(a / sum)) continue;
        ans += m[a / sum];
      }
    }
  }
  cout << ans << endl;
  return 0;
}
