It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
# List = ["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u",
# "v", "w", "x", "y", "z"]


n = input()
t = int(n)
t = t + 1
n = str(t)
while True:
    if n[0] != n[1] and n[2] != n[3] and n[1] != n[3] and n[2] != n[0] and n[0] != n[3] and n[1] != n[2]:
        print(n)
        exit()
    else:
        t = int(n)
        t = t+1
        n = str(t)
