It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def CheckBeautifulYear(x):
    set1 = set()
    while x > 0:
        y = x % 10
        set1.add(y)
        x /= 10
    len1 = len(set1)
    return len1
    
n = int(raw_input())

year = n+1
flag = 1
while flag:
    ans = CheckBeautifulYear(year)
    
    if ans == 4:
        break
    else:
        year += 1
        
print year

