It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
__author__ = 'Devesh Bajpai'
'''
http://codeforces.com/problemset/problem/271/A
Algorithm: Brute force solution. Keep increasing the year and create a set of its digits.
If all digits are unique, the size of the set will be 4. If such a case if found, return the
current year value.
'''
def solve(year):
    while(True):
        year = str(int(year)+1)
        if(len(set(year))==4):
            return year

if __name__ == "__main__":
    print solve(raw_input())


