You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
int main() {
  long long a;
  string s;
  cin >> a >> s;
  int n = s.size();
  long long ans = 0, all = 0;
  map<long long, long long> cnt;
  vector<int> v;
  for (int i = 0; i < n; ++i) {
    v.push_back(s[i] - '0');
  }
  for (int i = 0; i < n; ++i) {
    long long cur = 0;
    for (int j = i; j < n; ++j) {
      cur += v[j];
      if (cur > a) break;
      ++cnt[cur], ++all;
    }
  }
  for (int i = 0; i < n; ++i) {
    long long cur = 0;
    for (int j = i; j < n; ++j) {
      cur += v[j];
      if (!a) {
        if (!cur)
          ans += all;
        else
          ans += cnt[0];
      }
      if (!cur) continue;
      if (a % cur) continue;
      ans += cnt[a / cur];
    }
  }
  cout << ans << endl;
  return 0;
}
