It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
y=int(input())

def is_b_year(x):
	s=set()
	for c in str(x):
		s.add(c)
	if len(s) == 4:
		return True
	else :
		return False

for x in range(y+1,2**31-1):
	if is_b_year(x):
		print(x)
		break
	
	
	

