It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
fyear = int(input()) + 1


def jud(x):
    k = []
    xxx = list(str(x))
    for y in xxx:
        a = xxx.count(y)
        k.append(a)
    if k == [1, 1, 1, 1]:
        return False
    else:
        return True


while jud(fyear):
    fyear += 1
print(fyear)
