It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
import math

class BeautifulYear(object):
    
    def find_year(self,year):
        while(True):
            year += 1
            if self.is_beautiful_year(year):
                return year
    
    def is_beautiful_year(self, year):
        year_str = str(year)
        year_dicts = {}
        for i in range(0, len(year_str)):
            year_dicts[year_str[i]] = 0
        return len(year_dicts.keys()) == 4

if __name__ == "__main__":
    year = int(raw_input())
    beautiful_year = BeautifulYear().find_year(year)
    print beautiful_year
        