It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def get_digits_list(data):
    a = []
    while data:
        r = data % 10
        a.append(r)
        data //= 10
    a.reverse()
    return a
    pass


def all_unique_digits(digits):
    for x in digits:
        if digits.count(x) > 1:
            return False
    return True
    pass


def check_if_number_has_unique_digits(data):
    digits = get_digits_list(data)
    return all_unique_digits(digits)
    pass


def main():
    data = int(input())
    data += 1
    while True:
        if check_if_number_has_unique_digits(data):
            print(data)
            break
        data += 1
    pass


if __name__ == '__main__':
    main()
