It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
bool has_distinct_digits(int num) {
  map<int, bool> digits;
  while (num > 0) {
    int digit = num % 10;
    if (digits[digit]) {
      return false;
    } else {
      digits[digit] = true;
    }
    num /= 10;
  }
  return true;
}
int main() {
  int year;
  cin >> year;
  int num = year + 1;
  while (!has_distinct_digits(num)) {
    num++;
  }
  cout << num;
  return 0;
}
