It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def minimum_distinct_year(year):
    is_distinct = False
    distinct_year = year

    while not is_distinct:
        distinct_year += 1
        if is_unique(distinct_year):
            return distinct_year



def is_unique(num):
    same_digit = {}
    while num > 0:
        temp = num % 10
        num //= 10
        if temp in same_digit:
            return False
        same_digit[temp] = True

    return True

def main():
    year = int(input())

    print(minimum_distinct_year(year))

if __name__ == "__main__":
    main()
