It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
int main() {
  int n;
  int B[4];
  cin >> n;
  while (1) {
    n++;
    B[0] = n / 1000;
    B[1] = ((n / 100) % 10);
    B[2] = ((n / 10) % 10);
    B[3] = n % 10;
    if (B[0] != B[1] && B[0] != B[2] && B[0] != B[3] && B[1] != B[2] &&
        B[2] != B[3] && B[1] != B[3]) {
      cout << n;
      break;
    }
  }
  return 0;
}
