It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
# -*- coding: utf-8 -*-
year=input()
num=int(year)
year=list(year)
old_year=year[:]
ist=year[0]
ond=year[1]
ird=year[2]
rth=year[3]
ok=True    
while ok:
    num+=1
    year=list(str(num))
    ist=year[0]
    ond=year[1]
    ird=year[2]
    rth=year[3]
        
    if ist!=ond and ist!=ird and ist!=rth and ond!=ird and ond!=rth and ird!=rth:
        ok=False
new_year=''.join(year)
print(new_year)