Palo Alto is an unusual city because it is an endless coordinate line. It is also known for the office of Lyft Level 5.

Lyft has become so popular so that it is now used by all m taxi drivers in the city, who every day transport the rest of the city residents — n riders.

Each resident (including taxi drivers) of Palo-Alto lives in its unique location (there is no such pair of residents that their coordinates are the same).

The Lyft system is very clever: when a rider calls a taxi, his call does not go to all taxi drivers, but only to the one that is the closest to that person. If there are multiple ones with the same distance, then to taxi driver with a smaller coordinate is selected.

But one morning the taxi drivers wondered: how many riders are there that would call the given taxi driver if they were the first to order a taxi on that day? In other words, you need to find for each taxi driver i the number a_{i} — the number of riders that would call the i-th taxi driver when all drivers and riders are at their home?

The taxi driver can neither transport himself nor other taxi drivers.

Input

The first line contains two integers n and m (1 ≤ n,m ≤ 10^5) — number of riders and taxi drivers.

The second line contains n + m integers x_1, x_2, …, x_{n+m} (1 ≤ x_1 < x_2 < … < x_{n+m} ≤ 10^9), where x_i is the coordinate where the i-th resident lives. 

The third line contains n + m integers t_1, t_2, …, t_{n+m} (0 ≤ t_i ≤ 1). If t_i = 1, then the i-th resident is a taxi driver, otherwise t_i = 0.

It is guaranteed that the number of i such that t_i = 1 is equal to m.

Output

Print m integers a_1, a_2, …, a_{m}, where a_i is the answer for the i-th taxi driver. The taxi driver has the number i if among all the taxi drivers he lives in the i-th smallest coordinate (see examples for better understanding).

Examples

Input

3 1
1 2 3 10
0 0 1 0


Output

3 

Input

3 2
2 3 4 5 6
1 0 0 0 1


Output

2 1 

Input

1 4
2 4 6 10 15
1 1 1 1 0


Output

0 0 0 1 

Note

In the first example, we have only one taxi driver, which means an order from any of n riders will go to him.

In the second example, the first taxi driver lives at the point with the coordinate 2, and the second one lives at the point with the coordinate 6. Obviously, the nearest taxi driver to the rider who lives on the 3 coordinate is the first one, and to the rider who lives on the coordinate 5 is the second one. The rider who lives on the 4 coordinate has the same distance to the first and the second taxi drivers, but since the first taxi driver has a smaller coordinate, the call from this rider will go to the first taxi driver.

In the third example, we have one rider and the taxi driver nearest to him is the fourth one.
import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.io.PrintStream;
import java.util.StringTokenizer;
import java.io.IOException;
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.InputStream;

/**
 * Built using CHelper plug-in
 * Actual solution is at the top
 *
 * @author Wolfgang Beyer
 */
public class Main {
    public static void main(String[] args) {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        InputReader in = new InputReader(inputStream);
        PrintWriter out = new PrintWriter(outputStream);
        TaskB solver = new TaskB();
        solver.solve(1, in, out);
        out.close();
    }

    static class TaskB {
        public void solve(int testNumber, InputReader in, PrintWriter out) {
            int n = in.nextInt();
            int m = in.nextInt();
            int[] x = in.readIntArray(n + m);
            int[] t = in.readIntArray(n + m);
            int[] result = new int[m];

            int[] xDriver = new int[m];
            int current = 0;
            for (int i = 0; i < n + m; i++) {
                if (t[i] == 1) {
                    xDriver[current] = x[i];
                    current++;
                }
            }

            int left = -1;
            for (int i = 0; i < n + m; i++) {

                if (t[i] == 0) {
                    if (left == -1) result[0]++;
                    else if (left == m - 1) result[m - 1]++;
                    else {
                        if (Math.abs(x[i] - xDriver[left]) <= Math.abs(xDriver[left + 1] - x[i])) {
                            result[left]++;
                        } else {
                            result[left + 1]++;
                        }
                    }
                } else {
                    left++;
                }
            }

            for (int i = 0; i < m; i++) {
                out.print(result[i] + " ");
            }

        }

    }

    static class InputReader {
        private static BufferedReader in;
        private static StringTokenizer tok;

        public InputReader(InputStream in) {
            this.in = new BufferedReader(new InputStreamReader(in));
        }

        public int nextInt() {
            return Integer.parseInt(next());
        }

        public int[] readIntArray(int n) {
            int[] ar = new int[n];
            for (int i = 0; i < n; i++) {
                ar[i] = nextInt();
            }
            return ar;
        }

        public String next() {
            try {
                while (tok == null || !tok.hasMoreTokens()) {
                    tok = new StringTokenizer(in.readLine());
                    //tok = new StringTokenizer(in.readLine(), ", \t\n\r\f"); //adds commas as delimeter
                }
            } catch (IOException ex) {
                System.err.println("An IOException was caught :" + ex.getMessage());
            }
            return tok.nextToken();
        }

    }
}

