It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
y = int(input())+1
num = y
while 1:
    list = []
    for x in range(1, 5):
        list.append(int(y%10))
        y=int(y/10)
    count = 0
    for a in list:
        for b in list:
            if a!=b:
                count+=1
    if count == 12:
        break
    num += 1
    y = num
print(num)

