It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def solve(n):
	a=n%10
	b=(int(n/10))%10
	c=(int(n/100))%10
	d=(int(n/1000))%10
	if(a!=b and a!=c and a!=d and b!=c and b!=d and c!=d):
		return 1
	else:
		return 0
z=int(input())
y=z
while(1):
	y+=1
	x=solve(y)
	if(x==1):
		print(y)
		break

