It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#!/usr/bin/env python
# coding: utf-8

# In[114]:


## Inputs
year = int(input())
# GBGGB
# n, t = list(map(int, input().split()))
# queue = list("".join(input()))


# In[115]:


new_year = year + 1
counter = 0
found = 0

while not found:
    year_list = list("".join(str(new_year)))
    for digit in year_list:
        counter += year_list.count(digit)
    
    if counter == 4:
        print(new_year)
        found = 1
        break
    else:
        counter = 0
        found = 0
        new_year += 1
              


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