It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def cnt(n):
    a = [0] * 10
    c = 0
    b = 0
    while n != 0:
        a[n % 10] += 1
        if a[n % 10] == 1:
            c += 1
        n //= 10
        b += 1
    if b == c:
        return True
    else:
        return False

n = int(input().strip())
i = 1
while not cnt(n + i):
    i += 1
print(n + i)