It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
import math
a = input()
a = int(a)
a = a + 1
while True:
    b = (a/1000)
    b = math.floor(b)
    c = ((a%1000)/100)
    c = math.floor(c)
    d = (((a%1000)%100)/10)
    d = math.floor(d)
    e = (((a%1000)%100)%10)
    e = math.floor(e)

    a = (b*1000) + (c*100) + (d*10) + e
    if((b==c) or (b==d) or (b==e) or (c==d) or (c==e) or (d==e)):
        a = a + 1
        continue
    else:
        
        a = int(a)
        print(a)
        break
