It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def check(number):
	value = False
	sequence = tuple(map(int,str(number)))
	x=sequence[0]
	count=0
	for i in range(len(sequence)):
		for j in range(1,len(sequence)):
			if sequence[i] == sequence[j]:
				count+=1

	return count

def main():
	y=int(input())

	count=0

	while count!=3:
		y+=1
		count=check(y)

	print(y)


if __name__ == '__main__':
	main()





