It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def Main():
    m = int(input())
    m +=1

    while True:
        cnt = [0]*10

        cnt[m%10] +=1
        cnt[(m//10)%10] +=1
        cnt[(m//100)%10] +=1
        cnt[m//1000] +=1

        for i in range(10):
            if cnt[i] > 1:
                cnt[0] = -1
                break
        
        if cnt[0] != -1:
            print(m)
            break

        m +=1

if __name__ == "__main__":
    Main()
