You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
// practice with kaiboy
import java.io.*;
import java.util.*;

public class CF365C extends PrintWriter {
	CF365C() { super(System.out, true); }
	Scanner sc = new Scanner(System.in);
	public static void main(String[] $) {
		CF365C o = new CF365C(); o.main(); o.flush();
	}

	void main() {
		int a = sc.nextInt();
		byte[] cc = sc.next().getBytes();
		int n = cc.length;
		int[] kk = new int[n * 9 + 1];
		for (int i = 0; i < n; i++) {
			int sum = 0;
			for (int j = i; j < n; j++) {
				sum += cc[j] - '0';
				kk[sum]++;
			}
		}
		if (a == 0) {
			println((long) kk[0] * n * (n + 1) - (long) kk[0] * kk[0]); 
			return;
		}
		long ans = 0;
		for (int p = 1; p <= a / p; p++)
			if (a % p == 0) {
				int q = a / p;
				if (q <= n * 9) {
					long k = (long) kk[p] * kk[q];
					ans += k;
					if (p != q)
						ans += k;
				}
			}
		println(ans);
	}
}
