It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
import java.util.*;

public class Main {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        
        int y = Integer.parseInt(in.next());
        DiffYear(y);
        
    }
    public static void DiffYear(int y){
        int a=y+1;
        int b=y+1;
        List<Integer> digits = new ArrayList<Integer>();
        while (a > 0) {
            digits.add(a%10);
            a/=10;
        }
        int i=digits.size()-1;
            int q1=digits.get(i);
            int q2=digits.get(i-1);
            int q3=digits.get(i-2);
            int q4=digits.get(i-3);
            
            if(q1==q2||q1==q3||q1==q4){
                DiffYear(y+1);
            }
            else if(q2==q3||q2==q4){
                DiffYear(y+1);
            }
            else if(q3==q4){
                DiffYear(y+1);
            }
            else System.out.println(b);
        }
    }