It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def dgt(n):
    a=int(n%10)
    b=int(n/10)%10
    c=int(n/100)%10
    d=int(n/1000)%10
    
    if(a!=b and a!=c and a!=d and b!=c and b!=d and c!=d):
        return 1
    else:
        return 0

n=int(input())
for i in range(n+1,10000):
    a=dgt(i)
    if a==1:
        print(i)
        break
    

	 	 	   	 		 	  	 		   			 			