You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
char s[4000 + 10];
int A;
int mas[4000];
long long summ[4000 * 10];
int N;
int main() {
  scanf("%d", &A);
  scanf("%s", s);
  N = strlen(s);
  for (int i = 0; i < N; i++) {
    mas[i] = s[i] - '0';
    if (i > 0) mas[i] += mas[i - 1];
  }
  for (int i = 0; i < 4000 * 10; i++) summ[i] = 0;
  for (int i = 0; i < N; i++)
    for (int j = 0; j <= i; j++) {
      int a = mas[i];
      if (j > 0) a -= mas[j - 1];
      summ[a]++;
    }
  long long res = 0;
  if (A > 0) {
    for (int i = 1; i * i <= A; i++)
      if (A % i == 0) {
        int p = i;
        int q = A / i;
        if (p < 4000 * 10 && q < 4000 * 10) {
          if (p != q)
            res += summ[p] * summ[q] * 2;
          else
            res += summ[p] * summ[q];
        }
      }
  } else {
    res = summ[0] * N * (N + 1) - summ[0] * summ[0];
  }
  cout << res << "\n";
  return 0;
}
