It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
# author : sudoer

x = int(raw_input())

def distinct(n):
    s = str(n)
    ss = set()
    l = [int(i) for i in s]
    ln = len(l)
    for i in l:
        ss.add(i)
    sl = len(ss)
    if ln == sl:
        return True
    else:
        return False

year = 0
for i in range(x + 1, 90000):
    y = i
    if distinct(y) == True:
        year = y
        break
print year