It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def ziba(a):
    a = str(a)
    b = 0
    l = [0,0,0,0,0,0,0,0,0,0]
    for j in range(10):
        for i in range(len(a)):
            if(int(a[i]) == j):
                l[j] = l[j] + 1
    for z in range(10):
        if(l[z] >= 2):
            b = b + 1
    if(b == 0):
        return True 
    else:
        return False
a = int(input())
while True:
    a = a + 1
    if(ziba(a) == True):
        print(a)
        break
