You have a simple undirected graph consisting of n vertices and m edges. The graph doesn't contain self-loops, there is at most one edge between a pair of vertices. The given graph can be disconnected.

Let's make a definition.

Let v_1 and v_2 be two some nonempty subsets of vertices that do not intersect. Let f(v_{1}, v_{2}) be true if and only if all the conditions are satisfied:

  1. There are no edges with both endpoints in vertex set v_1. 
  2. There are no edges with both endpoints in vertex set v_2. 
  3. For every two vertices x and y such that x is in v_1 and y is in v_2, there is an edge between x and y. 



Create three vertex sets (v_{1}, v_{2}, v_{3}) which satisfy the conditions below;

  1. All vertex sets should not be empty. 
  2. Each vertex should be assigned to only one vertex set. 
  3. f(v_{1}, v_{2}), f(v_{2}, v_{3}), f(v_{3}, v_{1}) are all true. 



Is it possible to create such three vertex sets? If it's possible, print matching vertex set for each vertex.

Input

The first line contains two integers n and m (3 ≤ n ≤ 10^{5}, 0 ≤ m ≤ min(3 ⋅ 10^{5}, (n(n-1))/(2))) — the number of vertices and edges in the graph.

The i-th of the next m lines contains two integers a_{i} and b_{i} (1 ≤ a_{i} < b_{i} ≤ n) — it means there is an edge between a_{i} and b_{i}. The graph doesn't contain self-loops, there is at most one edge between a pair of vertices. The given graph can be disconnected.

Output

If the answer exists, print n integers. i-th integer means the vertex set number (from 1 to 3) of i-th vertex. Otherwise, print -1.

If there are multiple answers, print any.

Examples

Input


6 11
1 2
1 3
1 4
1 5
1 6
2 4
2 5
2 6
3 4
3 5
3 6


Output


1 2 2 3 3 3 

Input


4 6
1 2
1 3
1 4
2 3
2 4
3 4


Output


-1

Note

In the first example, if v_{1} = \{ 1 \}, v_{2} = \{ 2, 3 \}, and v_{3} = \{ 4, 5, 6 \} then vertex sets will satisfy all conditions. But you can assign vertices to vertex sets in a different way; Other answers like "2 3 3 1 1 1" will be accepted as well.

<image>

In the second example, it's impossible to make such vertex sets.
import java.util.*;
import java.io.*;

public class Hello {
    static InputReader in;
    static PrintWriter out;

    public static void main(String[] args) {
        new Hello().run();
    }

    static class InputReader {
        private final InputStream is;
        private final byte[] inbuf = new byte[1024];
        private int lenbuf = 0;
        private int ptrbuf = 0;

        public InputReader(InputStream stream) {
            is = stream;
        }

        private int readByte() {
            if (lenbuf == -1)
                throw new InputMismatchException();
            if (ptrbuf >= lenbuf) {
                ptrbuf = 0;
                try {
                    lenbuf = is.read(inbuf);
                } catch (IOException e) {
                    throw new InputMismatchException();
                }
                if (lenbuf <= 0)
                    return -1;
            }
            return inbuf[ptrbuf++];
        }

        private boolean isSpaceChar(int c) {
            return !(c >= 33 && c <= 126);
        }

        private int skip() {
            int b;
            while ((b = readByte()) != -1 && isSpaceChar(b))
                ;
            return b;
        }

        public double nextDouble() {
            return Double.parseDouble(nextString());
        }

        public char nextChar() {
            return (char) skip();
        }

        public String nextString() {
            int b = skip();
            StringBuilder sb = new StringBuilder();
            while (!(isSpaceChar(b))) { // when nextLine, (isSpaceChar(b) && b != ' ')
                sb.appendCodePoint(b);
                b = readByte();
            }
            return sb.toString();
        }

        public char[] nextString(int n) {
            char[] buf = new char[n];
            int b = skip(), p = 0;
            while (p < n && !(isSpaceChar(b))) {
                buf[p++] = (char) b;
                b = readByte();
            }
            return n == p ? buf : Arrays.copyOf(buf, p);
        }

        public char[][] nm(int n, int m) {
            char[][] map = new char[n][];
            for (int i = 0; i < n; i++)
                map[i] = nextString(m);
            return map;
        }

        public int[] nextIntArray(int n) {
            int[] a = new int[n];
            for (int i = 0; i < n; i++)
                a[i] = nextInt();
            return a;
        }

        public int nextInt() {
            int num = 0, b;
            boolean minus = false;
            while ((b = readByte()) != -1 && !((b >= '0' && b <= '9') || b == '-'))
                ;
            if (b == '-') {
                minus = true;
                b = readByte();
            }

            while (true) {
                if (b >= '0' && b <= '9') {
                    num = num * 10 + (b - '0');
                } else {
                    return minus ? -num : num;
                }
                b = readByte();
            }
        }

        public long nextLong() {
            long num = 0;
            int b;
            boolean minus = false;
            while ((b = readByte()) != -1 && !((b >= '0' && b <= '9') || b == '-'))
                ;
            if (b == '-') {
                minus = true;
                b = readByte();
            }

            while (true) {
                if (b >= '0' && b <= '9') {
                    num = num * 10 + (b - '0');
                } else {
                    return minus ? -num : num;
                }
                b = readByte();
            }
        }
    }

    private static final boolean oj = System.getProperty("ONLINE_JUDGE") != null;

    public static void debug(Object... o) {
        if (!oj) {
            System.out.println(Arrays.deepToString(o));
        }
    }

    // ============================================================================================================
    
    void solve() {
        int n = in.nextInt();
        int m = in.nextInt();
        List<Integer>[] adj = new List[n + 1];
        Arrays.setAll(adj, i -> new ArrayList<>());
        for (int it = 0; it < m; it++) {
            int u = in.nextInt();
            int v = in.nextInt();
            adj[u].add(v);
            adj[v].add(u);
        }

        int[] ans = new int[n + 1];
        Arrays.fill(ans, 1);
        for (int v : adj[1]) {
            ans[v] = 2;
        }

        if (adj[1].isEmpty()) {
            out.println(-1);
            return;
        }

        int u = adj[1].get(0);
        for (int v : adj[u]) {
            if (ans[v] == ans[u]) {
                ans[v] = 3;
            }
        }

        int[] sz = new int[4];
        for (int i = 1; i <= n; i++) {
            sz[ans[i]]++;
        }

        if (sz[1] == 0 || sz[2] == 0 || sz[3] == 0) {
            out.println(-1);
            return;
        }

        for (int i = 1; i <= n; i++) {
            int[] cnt = new int[4];
            for (int j : adj[i]) {
                cnt[ans[j]]++;
            }
            boolean ok = true;
            for (int k = 1; k <= 3; k++) {
                if (k == ans[i]) {
                    if (cnt[k] > 0) {
                        ok = false;
                    }
                } else {
                    if (cnt[k] < sz[k]) {
                        ok = false;
                    }
                }
            }
            if (!ok) {
                out.print(-1);
                return;
            }
        }

        for (int i = 1; i <= n; i++) {
            out.print(ans[i] + " ");
        }
        out.println();
    }

    public void run() {
        in = new InputReader(System.in);
        out = new PrintWriter(System.out);
        int tt = 1;
        // int tt = in.nextInt();
        for (int i = 1; i <= tt; i++) {
            solve();
        }
        out.flush();
    }
}