It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def check(x):
    s = str(x)
    mas = [0 for i in range(10)]
    for i in range(10):
        mas[i] = 0
    for i in range(len(s)):
        j = int(s[i])
        mas[j]=mas[j]+1
    for i in range(10):
        if mas[i] > 1:
            return 0
    return 1
            
    
y = int(raw_input()) + 1
while (check(y)==0):
    y=y+1
print y
