It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
int main() {
  int year, count = 0, i, j, flag = 1, a[4] = {-1, -1, -1, -1};
  do {
    scanf("%d", &year);
  } while (year < 0 || year > 9000);
  while (year < 10000) {
    year++;
    i = year;
    count = 0;
    while (i != 0) {
      a[count++] = i % 10;
      i = i / 10;
    }
    flag = 1;
    for (i = 0; i < 4; i++)
      for (j = i + 1; j < 4; j++) {
        if (a[i] == a[j]) {
          flag = 0;
        }
      }
    if (flag == 1) {
      printf("%d", year);
      break;
    }
  }
  return 0;
}
