It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def does_year_have_distinct_digits(y):
    digits = []
    while y:
        digits.append(y%10)
        y = y // 10
    Is_it = True
    for i in range(len(digits)):
        for j in range(len(digits)):
            if digits[i] == digits[j] and i != j:
                Is_it = False
                break
    return Is_it

def main():
    year = int(input())
    if 1000 <= year <= 9000:
        while True:
            if does_year_have_distinct_digits(year+1):
                break
            year += 1
        print(year+1)
main()