It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def isDistinct(num):
    temp = num
    digit = []
    while(temp != 0):
        if((temp % 10) in digit):
            return False
        else:
            digit.append(temp % 10)
        temp = temp / 10
    if(len(digit) == len(str(num))):
        return True

def findDistinct(num):
    for i in range(num+1, 10000):
        if(isDistinct(i)):
            return i

n = int(raw_input())
print findDistinct(n)
