It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
a=int(input())
flag1=0
while flag1==0:
    a+=1
    dig=[]
    dig2=set()
    n=a
    if n<10:
        dig.append(n%10)
        n//10
    while n//10>0:
        dig.append(n%10)
        n=n//10
        if n//10==0:
            dig.append(n)
            
    for i in range(len(dig)):
        dig2.add(dig[i])
        
    if len(dig)==len(dig2):
        flag1=1
        
print(a)     
