It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def beu_year(num):
   set_d = []
   set_e = []
   while num > 0:
       rem = num % 10
       set_d.append(rem)
       num = int(num//10)

   for i in set_d :
       if i not in set_e :
          set_e.append(i)

   if len(set_e) == len(set_d):
       return True
   else:
       return False


num = int(input(""))
if beu_year(num+1) is False:
    while beu_year(num+1) is not True:

         num +=1

print(num+1)



