It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
y = input()


num=int(y)+1
year=''+str(num)

def check(x):
    _size = len(x)
    repeated = []
    flag = 0
    for i in range(_size):
        k = i + 1
        for j in range(k, _size):
            if x[i] == x[j] and x[i] not in repeated:
                flag = 1
                break
        if flag == 1:
            break
    return flag

while True:
    if check(year) == 1:
        num = num + 1
        year = '' + str(num)
    else:

        print(year)
        break









