It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#!/usr/bin/env python3
# -*- coding: utf-8 -*-
"""
Created on Fri Mar 27 04:02:50 2020

@author: maruf
"""

def isUniqueChars(st): 
 
    if len(st) > 4: 
        return False
    char_set = [False] * 128 
    for i in range(0, len(st)):  
        val = ord(st[i]) 
        if char_set[val]: 
            return False
  
        char_set[val] = True
  
    return True

#flag=0
y=int(input())
y+=1
m=str(y)
while(not (isUniqueChars(m))):
    y+=1
    m=str(y)
print(y)



'''
year=list(str(y))
print(year)
while(flag<1):
  flag = len(set(year)) == len(year)
  if(flag):
      print(y)
  else : y+=1    
  '''