It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#!/usr/bin/python

import sys


y = int(raw_input())
ans = y + 1
unique = 0

while unique != 1:
	
	yy = list(str(ans))
	digits = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]

	for c in yy:
		digits[int(c)] += 1

	if digits.count(1) == 4:
		unique = 1
		break
	else:
		ans += 1

print ans

