It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
"""
if __name__ == '__main__':
    n = [int(__) for __ in list(input().strip())]
    spotted = None
    for i in range(len(n) - 1, -1, -1):
        num = n[i] + 1
        while num in n[:i] and num != 10:
            num += 1
        if num != 10:
            spotted = i
            n[spotted] = num
            break
    for i in range(spotted + 1, len(n)):
        n[i] = i - spotted - 1
        num = n[i]
        while num in n[:i]:
            num += 1
        n[i] = num
    for i in range(1, len(n)):
        if n[i] in n[:i]:
            dup = i
            num = n[i] + 1
            while num in n[:i]:
                num += 1
            n[i] = num
            for j in range(dup + 1, len(n)):
                n[j] = j - dup - 1
                num = n[j]
                while num in n[:j]:
                    num += 1
                n[j] = num
            break
    print(''.join([str(i) for i in n]))

"""
if __name__ == '__main__':
    n = int(input().strip()) + 1
    while True:
        if len(set(str(n))) == 4:
            print(n)
            break
        n += 1