It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
if __name__ == '__main__':
    def is_year_beautiful(year):
        year_string = str(year)
        year_digits = {'0' : 0, '1' : 0, '2' : 0, '3' : 0, '4' : 0, '5' : 0, '6' : 0, '7' : 0, '8' : 0, '9' : 0}
        for char in year_string:
            if year_digits[char] <= 0:
                year_digits[char] += 1
            else:
                return False
        return True
    
    y = input()
    y_int = int(y)
    beautiful_year = y_int + 1
    while not is_year_beautiful(beautiful_year):
        beautiful_year += 1
    print(beautiful_year)
