It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def check(t):
    a = t % 10
    b = (t // 10) % 10
    c = (t // 100) % 10
    d = (t // 1000) % 10

    if a == b or a == c or a == d or b == c or b == d or c == d:
        return False
    else:
        return True


n = int(input())

n += 1

while True:
    if check(n):
        print(n)
        exit()
    n += 1