A boy Bob likes to draw. Not long ago he bought a rectangular graph (checked) sheet with n rows and m columns. Bob shaded some of the squares on the sheet. Having seen his masterpiece, he decided to share it with his elder brother, who lives in Flatland. Now Bob has to send his picture by post, but because of the world economic crisis and high oil prices, he wants to send his creation, but to spend as little money as possible. For each sent square of paper (no matter whether it is shaded or not) Bob has to pay 3.14 burles. Please, help Bob cut out of his masterpiece a rectangle of the minimum cost, that will contain all the shaded squares. The rectangle's sides should be parallel to the sheet's sides.

Input

The first line of the input data contains numbers n and m (1 ≤ n, m ≤ 50), n — amount of lines, and m — amount of columns on Bob's sheet. The following n lines contain m characters each. Character «.» stands for a non-shaded square on the sheet, and «*» — for a shaded square. It is guaranteed that Bob has shaded at least one square.

Output

Output the required rectangle of the minimum cost. Study the output data in the sample tests to understand the output format better.

Examples

Input

6 7
.......
..***..
..*....
..***..
..*....
..***..


Output

***
*..
***
*..
***


Input

3 3
***
*.*
***


Output

***
*.*
***
import java.io.*;
import java.util.*;

public class A1008 {
    public static void main(String [] args) /*throws Exception*/ {
        InputStream inputReader = System.in;
        OutputStream outputReader = System.out;
        InputReader in = new InputReader(inputReader);//new InputReader(new FileInputStream(new File("input.txt")));new InputReader(inputReader);
        PrintWriter out = new PrintWriter(outputReader);//new PrintWriter(new FileOutputStream(new File("output.txt")));
        Algorithm solver = new Algorithm();
        solver.solve(in, out);
        out.close();
    }
}

class Algorithm {
    void solve(InputReader ir, PrintWriter pw) {

        int n = ir.nextInt(), m = ir.nextInt();
        char [][] symbols = new char[n][];
        int minX = n, minY = m, maxX = 0, maxY = 0;

        for (int i = 0; i < n; i++) {
            String line = ir.next();
            symbols[i] = line.toCharArray();
        }

        for (int i = 0; i < n; i++) {
            for (int j = 0; j < m; j++) {
                if (symbols[i][j] == '*') {
                    minX = Math.min(i, minX);
                    minY = Math.min(j, minY);
                }
            }
        }

        for (int i = n - 1; i >= 0; i--) {
            for (int j = m - 1; j >= 0; j--) {
                if (symbols[i][j] == '*') {
                    maxX = Math.max(i, maxX);
                    maxY = Math.max(j, maxY);
                }
            }
        }

        for (int i = minX; i <= maxX; i++) {
            for (int j = minY; j <= maxY; j++) {
                pw.print(symbols[i][j]);
            }
            pw.println();
        }

    }

    private static void Qsort(int[] array, int low, int high) {

        int i = low;
        int j = high;
        int x = array[low + (high - low) / 2];

        do {
            while (array[i] < x) ++i;
            while (array[j] > x) --j;
            if (i <= j) {
                int tmp = array[i];
                array[i] = array[j];
                array[j] = tmp;
                i++;
                j--;
            }
        } while (i <= j);

        if (low < j) Qsort(array, low, j);
        if (i < high) Qsort(array, i, high);

    }
}

class InputReader {
    private BufferedReader reader;
    private StringTokenizer tokenizer;

    InputReader(InputStream stream) {
        reader = new BufferedReader(new InputStreamReader(stream), 32768);
        tokenizer = null;
    }

    String next() {
        while (tokenizer == null || !tokenizer.hasMoreTokens()) {
            try {
                tokenizer = new StringTokenizer(reader.readLine());
            } catch (IOException e) {
                throw new RuntimeException(e);
            }
        }
        return tokenizer.nextToken();
    }

    String nextLine(){
        String fullLine = null;
        while (tokenizer == null || !tokenizer.hasMoreTokens()) {
            try {
                fullLine = reader.readLine();
            } catch (IOException e) {
                throw new RuntimeException(e);
            }
            return fullLine;
        }
        return fullLine;
    }

    String [] toArray() {
        return nextLine().split(" ");
    }

    int nextInt() {
        return Integer.parseInt(next());
    }
    double nextDouble() {
        return Double.parseDouble(next());
    }
    long nextLong() {
        return Long.parseLong(next());
    }

}