It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def check(n):
    s=str(n)
    a=[]
    for b in s:
        a.append(b)
    d=set(a) 
    if len(d)==4:
        return True
    else:
        return False


year = int(input())
num=9999-year
for i in range(1,num+1):
    if check(year+i):
        print(year+i)
        break
    else:
        continue
        
