It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
num=int(input())
a=list(range(1000, 9100))
b=list()
for i in a:
  
  for a, s, w, e in str(i).split(' '):
    if a!=s and a!=w and a!=e and s!=w and s!=e and w!=e:
      c=(f'{a}{s}{w}{e}')
      b.append(int(c))
b.append(num)
sorted_list=sorted(b)

if sorted_list[sorted_list.index(num)] != sorted_list[sorted_list.index(num)+1]:
  print(sorted_list[sorted_list.index(num)+1])
else:
  print(sorted_list[sorted_list.index(num)+2])