It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
year=int(input())+1
year1=year
while True:
	year1=str(year1)                                # Input year in int is converted to string to use list() in the next line
	lis=list(year1)
	c={}
	for item in lis:
		c[item] = c.get(item, 0) + 1               # I am creating a dictionary that assigns the digit and the frequency of each digit 
	n=max(c.values())                              # to the key:value pair in the dictionary
	if(n>1):
		year1 = int(year1)+1
	else:
		print(year1)
		break