It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def lista(a):
    al = list()
    al.append(int(a/1000))
    a -= int(a/1000)*1000 
    al.append(int(a/100))
    a -= int(a/100)*100 
    al.append(int(a/10))
    a -= int(a/10)*10 
    al.append(int(a))
    return al

a = int(input())

while (1):
   a += 1 
   al = lista(a)
   if ((al[0]!=al[1]) and (al[0]!=al[2]) and (al[0]!=al[3]) and (al[1]!=al[2]) and (al[1]!=al[3]) and (al[2]!=al[3])):
            break;

print(a)
