It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def Distinct(n): 
    a= [0] * 10
    count = 0
    while (n != 0): 
        b= int(n % 10)
        a[b] = 1
        n//= 10
    for i in range(10): 
        if (a[i] != 0): 
            count += 1
    return count
def countDigit(n): 
    c = 0
    while (n != 0): 
        r = n % 10
        c+=1
        n //= 10
    return c
def nextDistinctYear(n): 
    while (n): 
        x =Distinct(n + 1)
        y= countDigit(n + 1)
        if (x==y): 
            return n + 1 
        else: 
            n += 1
    return -1
n=int(input())
print(nextDistinctYear(n) )