In Dwango Co., Ltd., there is a content distribution system named 'Dwango Media Cluster', and it is called 'DMC' for short.
The name 'DMC' sounds cool for Niwango-kun, so he starts to define DMC-ness of a string.

Given a string S of length N and an integer k (k \geq 3), he defines the k-DMC number of S as the number of triples (a, b, c) of integers that satisfy the following conditions:

* 0 \leq a < b < c \leq N - 1
* S[a] = `D`
* S[b] = `M`
* S[c] = `C`
* c-a < k



Here S[a] is the a-th character of the string S. Indexing is zero-based, that is, 0 \leq a \leq N - 1 holds.

For a string S and Q integers k_0, k_1, ..., k_{Q-1}, calculate the k_i-DMC number of S for each i (0 \leq i \leq Q-1).

Constraints

* 3 \leq N \leq 10^6
* S consists of uppercase English letters
* 1 \leq Q \leq 75
* 3 \leq k_i \leq N
* All numbers given in input are integers

Input

Input is given from Standard Input in the following format:


N
S
Q
k_{0} k_{1} ... k_{Q-1}


Output

Print Q lines. The i-th line should contain the k_i-DMC number of the string S.

Examples

Input

18
DWANGOMEDIACLUSTER
1
18


Output

1


Input

18
DDDDDDMMMMMCCCCCCC
1
18


Output

210


Input

54
DIALUPWIDEAREANETWORKGAMINGOPERATIONCORPORATIONLIMITED
3
20 30 40


Output

0
1
2


Input

30
DMCDMCDMCDMCDMCDMCDMCDMCDMCDMC
4
5 10 15 20


Output

10
52
110
140
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <cmath>
#include <iostream>
#include <algorithm>
using namespace std;
typedef long long ll;

template <typename Tp> inline void getint(Tp &num){
	register int ch, neg = 0;
	while(!isdigit(ch = getchar())) if(ch == '-') neg = 1;
	num = ch & 15;
	while(isdigit(ch = getchar())) num = num * 10 + (ch & 15);
	if(neg) num = -num;
}

int N, Q, k;
char S[1000005];

int main(){
	getint(N), scanf("%s", S), getint(Q);
	while(Q--){
		getint(k); ll D = 0, M = 0, DM = 0, ans = 0;
		for(register int i = 0; i < N; i++){
			if(i >= k){
				if(S[i - k] == 'D') D--, DM -= M;
				else if(S[i - k] == 'M') M--;
			}
			if(S[i] == 'D') D++;
			else if(S[i] == 'M') M++, DM += D;
			else if(S[i] == 'C') ans += DM;
		}
		printf("%lld\n", ans);
	}
	return 0;
}
