It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def isDistinct(num):
    #returns true if distinct digits
    list1=[0]*10
    for i in range(0,len(num)):
        if list1[int(num[i])-1]==0 :
            list1[int(num[i])-1]+=1
        else:
            return 0
            break
    return 1
if __name__=="__main__":
    num1=input()
    x=int(num1)+1
    list1=[]
    found=0
    while found!=1:
        if(isDistinct(list(str(x)))==0):
            x+=1
        else:
            print(x)
            found=1
        