It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
try:
    n = int(input())
    
    n1 = n+1
    
    while True:
       
        r1 = n1 // 1000
        r2 = (n1 //100) % 10
        r3 = (n1 // 10) % 10
        r4 = n1 % 10
        
        if r1!=r2 and r2!=r3 and r3!=r4 and r2!=r4 and r1!=r4 and r1!=r3:
            break
        n1 +=1
        
    print(n1)
    
        
except Exception as e:
    print(e)