It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def ok(x):
	a = []
	while x:
		a.append(x % 10)
		x /= 10
	for i in range(4):
		for j in range(i + 1, 4):
			if a[i] == a[j]:
				return False
	return True
	
a = int(raw_input())
while True: 
	a += 1
	if ok(a):
		print a
		break

