It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def check_digits(n):
    first = n%10
    second = (n//10)%10
    third = (n//100)%10
    fourth = n//1000
    if first!=second and second!=third and third!=fourth and first!= fourth and first!=third and second!=fourth:
        return True
    else:
        return False
    
def main():
    year = input()
    while True:
        year = int(year) + 1
        if check_digits(year):
            break
    print(year)
    
main()