It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n=int(raw_input())

def distinct(s):
    s1=""
    s2=0
    k=0
    for i in s:
        l=s.count(i)
        #print(l)
        if l>1 :
            break
        else:
            s1=s1+i
            if len(s)==len(s1):
                k=int(s1)
            else:
                continue
    return k

q2=[]

for x in range(n+1,90000):
    x1=str(x)
    q=distinct(x1)
    if q==0 :
        continue
    else:
        q2.append(q)



print(min(q2))
