It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
int main() {
  bool outer = true;
  int n, a[4], temp, ans;
  cin >> n;
  while (outer) {
    bool isbreak = false;
    n++;
    temp = n;
    int i = 0, j, k;
    while (temp != 0) {
      a[i] = temp % 10;
      temp = temp / 10;
      i++;
    }
    for (j = 0; j < 3 && !isbreak; j++)
      for (k = j + 1; k < 4 && !isbreak; k++) {
        if (a[j] == a[k]) {
          isbreak = true;
          break;
        }
      }
    if (j == 3 && k == 4) {
      ans = n;
      outer = false;
    }
  }
  cout << ans;
  return 0;
}
