It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
# -*- coding: utf-8 -*-
"""
Created on Sat Sep 26 21:52:07 2020

@author: feibiaodi
"""
a=int(input())
c=[]
for i in range(1000,9999):
    if str(i)[0]!=str(i)[1] and str(i)[0]!=str(i)[2] and str(i)[0]!=str(i)[3] and str(i)[1]!=str(i)[2] and\
        str(i)[1]!=str(i)[3] and str(i)[2]!=str(i)[3] :
        c.append(i)
if a in c:
    t=c.index(a)
    print(c[t+1])
if a not in c:
    for i in range(0,len(c)):
        if a<c[i]:
            print(c[i])
            break
     
