It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#!/usr/bin/python
from __future__ import division
from sys import stdout,stdin
#from copy import deepcopy
import math

def solve():
    r=raw_input()
    v=int(r)
    for i in xrange(v,v+9000):
        if i>v:
            s=str(i)
            if s[0]!=s[1] and s[0]!=s[2] and s[0]!=s[3]:
                if s[1]!=s[2] and s[1]!=s[3]:
                    if s[2]!=s[3]:
                        return s
         
print solve()
