It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
y = int(input())

while True:
	y+=1

	s = str(y)

	# print(s[1:].find(s[0]))

	# print((s[0]+s[2:]).find(s[1]))

	# print((s[:2]+s[3:]).find(s[2]))

	# print(s[:3].find(s[3]))

	if s[1:].find(s[0]) >=0:
		# print('s0')
		continue
	elif (s[0]+s[2:]).find(s[1]) >=0:
		# print('s1')
		continue
	elif (s[:2]+s[3:]).find(s[2]) >=0:
		# print('s2')
		continue
	elif s[:3].find(s[3]) >=0:
		# print('s3')
		continue
	else:
		# print(s)
		print(y)
		break


