It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n=int(input())
n+=1
ctr=0
def i2l(k):
    x=[]
    while(k>0):
        t=k%10
        x.append(t)
        k=k//10
    x.reverse()
    return x


while 1000<=n<=9100:
    i=[]
    i=i2l(n)
    for j in range(4):
        for k in range(4):
            if ((i[j]==i[k]) and (j!=k)):
                ctr+=1

    if ctr==0:
        break
    else:
        n+=1
        ctr=0
print(n)
