It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
# funktioniert, ist aber nicht schön
t = list(input())
t = int(''.join(t))
t += 1
t = list(str(t))
while t[0] == t[1] or t[0] == t[2] or t[0] == t[3] or t[1] == t[2] or t[1] == t[3] or t[2] == t[3]:
    t = int(''.join(t))
    t += 1
    t = list(str(t))

print(''.join(t))

# t = int(input())
# t += 1
# while len(set(str(t))) != 4:
#     t += 1

# print(t)


