It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014

def checa_digitos_distintos(n):
    n = int(n)
    global digitos
    while n > 0:
        ult_digito = n%10
        if digitos[ult_digito] == 1:
            return False
        else:
            digitos[ult_digito] = 1
        n = int(n/10)
    return True


y = int(input()) + 1

digitos = [0] * 10
aux = checa_digitos_distintos(y)

while(aux == False):
    y = y + 1
    digitos = [0] * 10
    aux = checa_digitos_distintos(y) 
print(y)


	 			 			  	 	   	 					 	  		