It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#!/usr/bin/python

def createNextNum(num):
	num_len = len(num)
	digits = [str(e) for e in range(10)]
	for e in num:
		if e in digits:
			digits.remove(e)
	return num+''.join(digits[:4-num_len])

def findNextNum(curNum):
	for i in [3,2,1,0]:
		for e in range(10)[int(curNum[i])+1:]:
			if len(set(curNum[:i])) == i and str(e) not in curNum[:i]:
				return curNum[:i] + str(e)


print createNextNum(findNextNum(raw_input()))



