It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
num = int(input())

ctr = num+1
marmota = True
while marmota:
	test = str(ctr)
	halp = []
	for n in range(0, 4):
		halp.append(test[n])
	if halp[0] == halp[1] or halp[0] == halp[2] or halp[0] == halp[3] or halp[1] == halp[2] or halp[1] == halp[3] or halp[2] == halp[3]:
		ctr += 1
	else:
		print(ctr)
		marmota = False