It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
p=int(input())+1
a=p%10
b=(p%100-(1*a))//10
c=(p%1000-(10*b+1*a))//100
d=(p-(100*c+10*b+a))//1000
while a==b or a==c or a==d or b==c or b==d or c==d:
    p+=1
    a = p % 10
    b = (p % 100 - (1 * a)) // 10
    c = (p % 1000 - (10 * b + 1 * a)) // 100
    d = (p - (100 * c + 10 * b + a)) // 1000
print(p)


