It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
x = int(input())
x = x + 1
import math
First = math.floor(x/1000)
Second = math.floor((x-First*1000)/100)
Third = math.floor((x-First*1000- Second*100)/10)
Fourth = x-First*1000- Second*100 - Third * 10
while True:
    if First == Second or First == Third or First == Fourth or Second == Third or Second == Fourth or Third == Fourth:
        if Fourth != 9:
            Fourth = Fourth + 1
        elif Fourth == 9 and Third == 9 and Second == 9:
            Fourth = 0
            Third = 0
            Second = 0
            First = First + 1
        elif Fourth == 9 and Third == 9:
            Fourth = 0
            Third = 0
            Second = Second + 1
        else:
            Fourth = 0
            Third = Third + 1
    else:
        break

print(First*1000+Second*100+Third*10+Fourth)
