It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
a = int(input())
a += 1
a = str(a)
a = list(a)

x = 0
l = ''.join(a)
l = int(l)
while (a[0] == a[1] or a[1] == a[2] or a[2] == a[3] or a[3] == a[0] or a[0] == a[2] or a[1] == a[3] or a[2] == a[0] or a[3] == a[1] or a[0] == a[3] or a[1] == a[0] or a[2] == a[1] or a[3] == a[2]):
         l = ''.join(a)
         l = int(l)
         l += 1
         l = str(l)
         x += 1
         a = list(l)

print(l)