It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
# import sys
# sys.stdin = open('/home/puneet/Documents/Cpp Programs/input.txt', 'r')
# sys.stdout = open('/home/puneet/Documents/Cpp Programs/output.txt', 'w') 

def isValid(n):
	n=str(n)
	x=set()
	for i in n:
		x.add(i)

	if(len(x)==len(n)):
		return True
	return False
li=[]
for i in range(1000,10000):
	if(isValid(i)):
		li.append(i)


def binary(n):
	low=0
	high=len(li)-1
	ans = n
	while(low<=high):
		mid = (low+high)//2
		if(li[mid]>n):
			ans = li[mid]
			high = mid-1
		else:
			low=mid+1

	return ans
n = int(input())

print(binary(n))