You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
long long ps[1000000];
long long sums[1000000];
long long get_sum(long long l, long long r) { return ps[r] - ps[l - 1]; }
long long ans = 0;
int main() {
  long long a;
  cin >> a;
  string s;
  cin >> s;
  s = 'a' + s;
  long long n = s.size() - 1;
  for (long long i = 1; i <= n; ++i) {
    ps[i] = ps[i - 1] + (s[i] - '0');
  }
  for (long long i = 1; i <= n; ++i) {
    for (long long j = i; j <= n; ++j) {
      long long cur_sum = get_sum(i, j);
      sums[cur_sum]++;
    }
  }
  for (long long i = 1; i <= n; ++i) {
    for (long long j = i; j <= n; ++j) {
      long long cur_sum = get_sum(i, j);
      if (!cur_sum) {
        if (!a) ans += (n + 1) * n / 2;
        continue;
      }
      long long ss = a / cur_sum;
      if (ss * cur_sum == a) {
        if (ss >= 4000 * 9) {
          continue;
        }
        ans += sums[ss];
      }
    }
  }
  cout << ans << endl;
}
