It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
Y = int(input())
Y += 1
while True:
	countlist = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
	for i in range(0, len(str(Y))):
		countlist[int(str(Y)[i])] += 1
	flag = True
	for i in range(0, 10):
		if countlist[i] >= 2:
			flag = False
			break
	if flag:
		print(Y)
		break
	Y += 1