It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
num=int(input())

for i in range(num+1,10000):
    n = i

    list = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
    count = 0
    a = n % 10
    if a in list:
        list.remove(a)
    n = n // 10
    b = n % 10
    if b in list:
        list.remove(b)
    else:
        count = count + 1
    if count == 0:
        n = n // 10
        c = n % 10
        if c in list:
            list.remove(c)
        else:
            count = count + 1
    if count == 0:
        n = n // 10
        d = n % 10
        if d in list:
            list.remove(d)
        else:
            count = count + 1

    if count == 0:
        print(i)
        break



