It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def get_beautiful_year(year):
    current_year = year + 1
    while 1:
        if distinct_digits(current_year):
            return current_year
        current_year += 1


def distinct_digits(num):
    numbers = set()
    while 1:
        remainder = num % 10
        if remainder in numbers:
            return False
        numbers.add(remainder)
        num = num // 10
        if num < 1:
            return True


print(get_beautiful_year(int(input(""))))

