It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
int main() {
  int n, a[4], i, l, c = 0, k = 0, b, j;
  cin >> n;
  n++;
  while (k != 1) {
    c = 0;
    b = n;
    a[0] = n % 10;
    n /= 10;
    for (i = 1; i <= 3; i++) {
      a[i] = n % 10;
      n /= 10;
      for (j = 0; j < i && c != 1; j++) {
        if (a[i] == a[j]) {
          c = 1;
        }
      }
    }
    if (c == 1) {
      n = ++b;
    } else
      k = 1;
  }
  cout << b;
}
