Find the symmetric difference of two sets $A = \\{a_0, a_1, ..., a_{n-1}\\}$ and $B = \\{b_0, b_1, ..., b_{m-1}\\}$.

Constraints

* $1 \leq n, m \leq 200,000$
* $0 \leq a_0 < a_1 < ... < a_{n-1} \leq 10^9$
* $0 \leq b_0 < b_1 < ... < b_{m-1} \leq 10^9$

Input

The input is given in the following format.


$n$
$a_0 \; a_1 \; ... \; a_{n-1}$
$m$
$b_0 \; b_1 \; ... \; b_{m-1}$


Elements in $A$ and $B$ are given in ascending order. There are no duplicate elements in each set.

Output

Print elements in the symmetric difference in ascending order. Print an element in a line.

Example

Input

7
1 2 3 4 5 6 7
4
2 4 6 8


Output

1
3
5
7
8
#include <bits/stdc++.h>

using namespace std;

typedef long long int ll;
typedef pair<ll, ll> pll;

#define FOR(i, n, m) for(ll (i)=(m);(i)<(n);++(i))
#define REP(i, n) FOR(i,n,0)
#define OF64 std::setprecision(10)

const ll MOD = 1000000007;
const ll INF = (ll) 1e15;

ll A[200005];
ll B[200005];

int main() {
    cin.tie(0);
    ios::sync_with_stdio(false);
    ll N, M;
    cin >> N;
    REP(i, N) {
        cin >> A[i];
    }
    cin >> M;
    REP(i, M) {
        cin >> B[i];
    }

    vector<ll> v;
    REP(i, N) {
        auto it = lower_bound(B, B + M, A[i]);
        if (A[i] != *it)
            v.push_back(A[i]);
    }
    REP(i, M) {
        auto it = lower_bound(A, A + N, B[i]);
        if (B[i] != *it)
            v.push_back(B[i]);
    }
    sort(v.begin(), v.end());
    REP(i, v.size()) {
        cout << v[i] << endl;
    }
    return 0;
}
