It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def chPathToThis(f=None):
    import os
    f = __file__ if f is None else f
    os.chdir(os.path.dirname(f))

fle = None

def input():
    global fle
    def inner():
        if fle is None:
            from sys import stdin
            for line in stdin:
                yield line
            raise EOFError
        else:
            for line in fle:
                yield line.replace('\r', '').replace('\n', '')
            raise EOFError
    o = inner()
    return next(o)

def main():
    y = int(input()) + 1
    def check(n):
        st = set()
        for i in str(n):
            st.add(i)
        return len(st) == len(str(n))
    while not check(y):
        y += 1
    print(y)


try:
    import time, numpy
    chPathToThis(__file__)
    begin, fle = time.clock(), open('pytest.txt')
    main()
    fle.close()
    print(time.clock() - begin)
except ImportError:
    main()
