It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
s = raw_input()
s = int(s) + 1
l = [0,0,0,0,0,0,0,0,0,0,0]
s = list(str(s))    


check = 1

while check:
    
    for i in range(len(s)):
        
        temp = int(s[i])
        l[temp] += 1
        
        
        if l[temp] == 2:
            
            check = 1
            
            s = int("".join(s))
            s += 1
            s = list(str(s))
            
            for t in range(len(l)):
                l[t] = 0
                
            break
        else:
            check = 0
            
print "".join(s)
            

 
       