It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
int main() {
  int x, y;
  cin >> x;
  for (y = x + 1; y <= 9999; y++) {
    int a = y % 1000 % 100 % 10;
    int b = y % 1000 % 100 / 10;
    int c = y % 1000 / 100;
    int d = y / 1000;
    int ans;
    if (y > x && (a != b && a != c && a != d && b != c && b != d && c != d)) {
      int count = 0;
      ans = y;
      count++;
      cout << y << endl;
      if (count == 1) {
        break;
      }
    }
  }
  return 0;
}
