It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
num = input()
num = int(num)+1

def isdistinct(n):
    n = str(n)

    set_of_numbers = []
    for k in range(0, 10):
        set_of_numbers.append(0)

    for i in n:
        if set_of_numbers[int(i)] ==1:
            return False
        else:
            set_of_numbers[int(i)] = 1
    return True


while num < 9999:
    if isdistinct(num) == True:
        print(str(num))
        break
    num = int(num) + 1


'''
1987

2013

2013

2014
'''