It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def year_checker(year):
    after = str(int(year) + 1)
    a = [int(i) for i in after]
    isNext = False
    for i in range(len(a)):
        if a.count(a[i]) > 1:
            isNext = True

    if isNext:
        year_checker(after)
    else:
        print(after)

year_checker(input())
