You came to the exhibition and one exhibit has drawn your attention. It consists of n stacks of blocks, where the i-th stack consists of a_i blocks resting on the surface.

The height of the exhibit is equal to m. Consequently, the number of blocks in each stack is less than or equal to m.

There is a camera on the ceiling that sees the top view of the blocks and a camera on the right wall that sees the side view of the blocks.

<image>

Find the maximum number of blocks you can remove such that the views for both the cameras would not change.

Note, that while originally all blocks are stacked on the floor, it is not required for them to stay connected to the floor after some blocks are removed. There is no gravity in the whole exhibition, so no block would fall down, even if the block underneath is removed. It is not allowed to move blocks by hand either.

Input

The first line contains two integers n and m (1 ≤ n ≤ 100 000, 1 ≤ m ≤ 10^9) — the number of stacks and the height of the exhibit.

The second line contains n integers a_1, a_2, …, a_n (1 ≤ a_i ≤ m) — the number of blocks in each stack from left to right.

Output

Print exactly one integer — the maximum number of blocks that can be removed.

Examples

Input

5 6
3 3 3 3 3


Output

10

Input

3 5
1 2 4


Output

3

Input

5 5
2 3 1 4 4


Output

9

Input

1 1000
548


Output

0

Input

3 3
3 1 1


Output

1

Note

The following pictures illustrate the first example and its possible solution.

Blue cells indicate removed blocks. There are 10 blue cells, so the answer is 10.

<image>
import java.util.*;import java.io.*;import java.math.*;

public class Main
{

    public static void process()throws IOException
    {
        int n=ni(),m=ni();
        Long arr[]=new Long[n+1];arr[0]=0l;
        long tot=0l,res=0l,ht;
        for(int i=1;i<=n;i++){
        	tot+=(arr[i]=nl());
        }

        if(n==1){
        	pn(0);
        	return;
        }

        r_sort(arr,n+1);
        
        res=0l;ht=arr[n];

        for(int i=n;i>=2;i--){
        	if(ht==1){
        		res++;
        		continue;
        	}

        	if(arr[i]>=ht){
        		res++;
        		ht--;
        		ht=Math.max(1, ht);
        		continue;
        	}

        	res+=(ht-arr[i]+1l);
        	ht=arr[i]-1;
        	ht=Math.max(ht, 1);
        }

        res+=ht;
        
        pn(tot-res);
    }	


    static FastReader sc;
    static PrintWriter out;
    public static void main(String[]args)throws IOException
    {
        out = new PrintWriter(System.out);
        sc=new FastReader();

        long s = System.currentTimeMillis();
        int t=1;
        //t=ni();
        while(t-->0)
            process();

        out.flush();
        System.err.println(System.currentTimeMillis()-s+"ms");
        System.out.close();  
    }
    
    
    static void pn(Object o){out.println(o);}
    static void p(Object o){out.print(o);}
    static void pni(Object o){out.println(o);System.out.flush();}
    static int ni()throws IOException{return Integer.parseInt(sc.next());}
    static long nl()throws IOException{return Long.parseLong(sc.next());}
    static double nd()throws IOException{return Double.parseDouble(sc.next());}
    static String nln()throws IOException{return sc.nextLine();}
    static long gcd(long a, long b)throws IOException{return (b==0)?a:gcd(b,a%b);}
    static int gcd(int a, int b)throws IOException{return (b==0)?a:gcd(b,a%b);}
    static int bit(long n)throws IOException{return (n==0)?0:(1+bit(n&(n-1)));}
    static boolean multipleTC=false;
    static long mod=(long)1e9+7l;

    static<T> void r_sort(T arr[],int n){
        Random r = new Random(); 
        for (int i = n-1; i > 0; i--){ 
            int j = r.nextInt(i+1); 
                  
            T temp = arr[i]; 
            arr[i] = arr[j]; 
            arr[j] = temp; 
        } 
        Arrays.sort(arr); 
    }
    
/////////////////////////////////////////////////////////////////////////////////////////////////////////

    static class FastReader 
    { 
        BufferedReader br; 
        StringTokenizer st; 
  
        public FastReader() { 
            br = new BufferedReader(new
                     InputStreamReader(System.in)); 
        } 
  
        String next(){ 
            while (st == null || !st.hasMoreElements()) 
            { 
                try
                { 
                    st = new StringTokenizer(br.readLine()); 
                } 
                catch (IOException  e) 
                { 
                    e.printStackTrace(); 
                } 
            } 
            return st.nextToken(); 
        } 
  
        String nextLine() { 
            String str = ""; 
            try{ 
                str = br.readLine(); 
            } 
            catch (IOException e) { 
                e.printStackTrace(); 
            } 
            return str; 
        } 
    } 
/////////////////////////////////////////////////////////////////////////////////////////////////////////////
}