It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n = input()
num = int(n) + 1
while num <= 10000:
    var = str(num)
    c1 = var.count(var[0])
    c2 = var.count(var[1])
    c3 = var.count(var[2])
    c4 = var.count(var[3])
    #print(num, c1, c2, c3, c4, var)
    if c1 == 1 and c2 == 1 and c3 == 1 and c4 == 1:
        print(var)
        break
    num += 1