It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n=input()
n=int(n)+1 
n=str(n)
for i in range(10000):
    s1=n.count(n[0])
    s2=n.count(n[1])
    s3=n.count(n[2])
    s4=n.count(n[3])
    if(s1==s2==s3==s4==1):
        print(n)
        break
    else:
        n=int(n)+1   
        n=str(n)       