It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
year = int(input())
num = []
loop = True
while loop == True and year <= 9012:
    year += 1
    num.append(str(year)[0])
    num.append(str(year)[1])
    num.append(str(year)[2])
    num.append(str(year)[3])
    if num.count(num[0]) == 1 and num.count(num[1]) == 1 and num.count(num[2]) == 1 and num.count(num[3]) == 1:
        loop = False
    else:
        loop = True
        num.clear()
print(num[0] + num[1] + num[2] + num[3])    
               
    
