It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n = int(input())
num = [0, 0, 0, 0]
def calc(x):
    num[0] = x // 1000
    x %= 1000
    num[1] = x // 100
    x %= 100
    num[2] = x // 10
    x %= 10
    num[3] = x

calc(n)
ans = 0
for i in range(n+1, 10000):
    calc(i)
    if (num[0] != num[1] and num[0] != num[2] and num[0] != num[3] and num[1] != num[2] and num[1] != num[3] and num[2] != num[3]):
        ans = i
        break;
print(ans)