It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
# -*- coding: utf-8 -*-
"""
Created on Mon Nov 25 23:11:06 2019

@author: sihan
"""
def dis(f):
    L=['!']
    for i in range(len(f)):
        for j in L:
            if f[i]==j:
                return True
        L.append(f[i])
    return(False)
i=int(input())+1
while True:
    if dis(str(i))==True:
        i+=1
    else:
        break
print(i)