It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
x=input()
y=x
list=[chr(x) for x in range(ord("0"),ord("9")+1)]
def match(x):
    count=0
    for item in range(len(x)):
        if x.count(x[item])==1:
            continue
        else:
            count+=1 
    if count==0:
        return 0
    else:return 1 
while True:
    x=str(int(x)+1)
    if match(x)==0:
        break

print(x)    
    