It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def distinct_digits(year):
	rem, d0 = divmod(year, 10)
	rem, d1 = divmod(rem, 10)
	rem, d2 = divmod(rem, 10)
	digits = {d0, d1, d2, rem}
	if len(digits) == 4:
		return True
	return False

year = int(input()) + 1
while not distinct_digits(year):
	year += 1
print(year)
