It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
a=raw_input()
liste=[]
def beaut(year):
	for i in range(len(year)):
		s=year[i]
		if year[i+1:].find(s)!=-1: return False
	return True

for i in range(1000,9100):
	liste.append(str(i))
b=int(a)
liste=filter(beaut,liste)
if beaut(a): print liste[liste.index(a)+1]
else:
	while str(b) not in liste : b+=1
        print b
	
