It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
import sys
import math

n = str(int(input())+1)

def unique(n,pole):

    pole=list(n)
    
    for i in range(len(pole)):
        pom = pole.count(pole[i])
        if i==len(pole)-1:
            print(n)
            break
        if pom>1:
            unique(str(int(n)+1),0)
            break


unique(n,0)
