You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using ld = long double;
using pii = pair<int, int>;
using vi = vector<int>;
const int N = 4e5;
vi cnt(N, 0);
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  cout.tie(NULL);
  int a;
  cin >> a;
  string s;
  cin >> s;
  int n = s.size();
  for (int i = 0; i < n; i++) {
    int sum = 0;
    for (int j = i; j < n; j++) {
      sum += int(s[j] - '0');
      cnt[sum]++;
    }
  }
  ll ans = 0;
  if (a == 0) {
    for (int i = 0; i < N; i++) ans += cnt[i];
    ans = 2 * cnt[0] * ans - 1LL * cnt[0] * cnt[0];
  } else {
    for (int i = 1; i < N; i++) {
      if (a % i) continue;
      int b = a / i;
      if (b >= N) continue;
      ans += 1LL * cnt[i] * cnt[b];
    }
  }
  cout << ans << '\n';
}
