It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
import sys
x=input()
x= int(x)+1


for i in range(1000,9012):
    list1= [int(x%10),int((x/10)%10),int((x/100)%10),int((x/1000)%10)]
    flag=0
    for j in range(0,len(list1)):
        for k in range(j+1,len(list1)):
            if(list1[j]== list1[k]):
                flag=1
    if(flag==1):
        x+=1
    else:
        print(x)
        sys.exit()          
                     


    
