It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
import sys
def checkBeautifulYear(yearN):
    yearN = str(yearN)
    if(yearN[0] in yearN[1:]): return False
    if(yearN[1] in yearN[0] + yearN[2:]): return False
    if(yearN[2] in yearN[:2] + yearN[3]): return False
    if(yearN[3] in yearN[:3]): return False
    return True
yearN = int(sys.stdin.readline())
while True:
    yearN = yearN + 1
    if checkBeautifulYear(yearN): 
        print yearN
        break