It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
import sys,os,io,time
if os.path.exists('input.txt'):
    sys.stdin = open('input.txt', 'r')
    sys.stdout = open('output.txt', 'w')

def distinct(n):
    m=n
    dic={}
    while m>0:
        x=m%10
        m=m//10
        if x in dic:
            return False
        else:
            dic[x]=1
    return True

def main():
    n=int(input())
    i=n+1
    while True:
        if distinct(i):
            print(i)
            break
        i+=1

main()