It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
int num[5];
bool check();
int main() {
  int n;
  cin >> n;
  for (int i = n + 1; i < 10000; i++) {
    num[0] = i % 10;
    num[1] = i / 10 % 10;
    num[2] = i / 100 % 10;
    num[3] = i / 1000;
    if (check()) {
      cout << i << endl;
      break;
    }
  }
  return 0;
}
bool check() {
  for (int i = 0; i < 4; i++) {
    for (int j = i + 1; j < 4; j++) {
      if (num[i] == num[j]) {
        return false;
      }
    }
  }
  return true;
}
