It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014

def check(str1):
    ch=[0]*10
    for i in range(len(str1)):
        j=int(str1[i])
        ch[j]=ch[j]+1
    for i in range(10):
        if ch[i]>1:
            return False
    return True
        





a=input()
a=a+1
while 1:
    b=str(a)
    if(check(b)):
        print a
        break
    else:
        a=a+1
        
