It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
a=int(input())
z1=0
for i in range(a+1,a+1000):
    b=[]
    c=i
    while c!=0:
        r=c%10
        b.append(r)
        c=c//10
    b1=b[::-1]
    b.sort();
    z=0
    for j in range(len(b)-1):
        if b[j]!=b[j+1]:
            z=z+1
        else:
            break
    if z==len(b)-1:
        print(*b1,sep='')
        z1=z1+1
        break
