It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n=input()
N=int(n)
A=[0,0,0,0]
flag=False
while flag==False:
    if A[0]!=A[1] and A[0]!=A[2] and A[0]!=A[3] and A[1]!=A[2] and A[1]!=A[3] and A[2]!=A[3]:
        flag=True
        break
    else:
        N+=1
        N1=str(N)
        A=list(N1)
print(''.join(A))