You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
template <typename T>
inline T sqr(T t) {
  return t * t;
}
inline void files() {
  ios_base::sync_with_stdio(0);
  cin.tie(0);
  cout.tie(0);
}
int a;
long long p[5000];
map<long long, int> dp;
long long ans;
string s;
int main() {
  cin >> a >> s;
  for (int i = 0; i < s.size(); i++) {
    long long cursum = 0;
    for (int j = i; j < s.size(); j++) {
      cursum += (s[j] - '0');
      dp[cursum]++;
    }
  }
  for (int i = 0; i < s.size(); i++) {
    long long cursum = 0;
    for (int j = i; j < s.size(); j++) {
      cursum += (s[j] - '0');
      if (a == 0) {
        if (cursum == 0)
          ans += (s.size() * (s.size() + 1)) / 2;
        else
          ans += dp[0];
      } else if (cursum > 0 && a % cursum == 0)
        ans += dp[a / cursum];
    }
  }
  cout << ans;
}
