It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def checkdigit(fin):
	final = list(str(fin))
	n = len(final)
	i=0
	while i<n:
		j = i+1
		while j<n:
			if final[i]==final[j]:
				return False
			j+=1
		i+=1
	return True

number = int(input())
found = False
final = number+1
while checkdigit(final)==False:
	final+=1
print(str(final))
