It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#!/usr/bin/env python
# coding: utf-8

# In[18]:


y=int(input())
y+=1
sy=str(y)
if sy.count(sy[0])==1 and sy.count(sy[1])==1 and sy.count(sy[2])==1 and sy.count(sy[3])==1:
    print(y)
else:
    while sy.count(sy[0])!=1 or sy.count(sy[1])!=1 or sy.count(sy[2])!=1 or sy.count(sy[3])!=1:
        y+=1
        sy=str(y)
        
    print(y)

