It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n = int(input())
ans = 0
for i in range(n+1, 9500):
    N = str(i)
    if N.count('0') > 1 or N.count('1') > 1 or N.count('2') > 1 or N.count('3') > 1 or N.count('4') > 1 or N.count('5') > 1 or N.count('6') > 1 or N.count('7') > 1 or N.count('8') > 1 or N.count('9') > 1:
        continue
    else:
        ans = i
        break
print(ans)