It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
int n;
bool check(int n) {
  int a[4];
  a[0] = n / 1000;
  a[1] = (n / 100) % 10;
  a[2] = (n / 10) % 10;
  a[3] = (n % 10);
  for (int i = 0; i < 4; i++)
    for (int j = 0; j < 4; j++)
      if (i != j && a[i] == a[j]) return 0;
  return 1;
}
int main() {
  cin >> n;
  n++;
  while (!check(n)) n++;
  cout << n;
  return 0;
}
