It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n=int(input())
a=[0]*4
n=n+1
while n<9013:
    t=n
    for i in range(4):
        a[i]=t%10
        t=t//10
    if a[0]!=a[1] and a[0]!=a[2] and a[0]!=a[3] and a[1]!=a[2] and a[1]!=a[3] and a[2]!=a[3]:
        print(n)
        break
    else:
        n=n+1
    