It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def checkano():
	for e in range(1,4):
		if lista[0] == lista[e]:
			return False
	for e in range(2,4):
		if lista[1] == lista[e]:
			return False
	if lista[2] == lista[3]:
		return False
	return True


n = raw_input()
lista = []
for e in n:
	lista.append(int(e))

lista[3] += 1

while not checkano():
	lista[3] += 1
	if lista[3] >= 10:
		lista[3] = 0
		lista[2] += 1
		if lista[2] == 10:
			lista[2] = 0
			lista[1] += 1
			if lista[1] == 10:
				lista[1] = 0
				lista[0] += 1

n = ''
for e  in lista:
	n = n + str(e)

print n



