It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def check(x):
    a,b=0,0
    i=1
    s=0
    r=[]
    hell=1
    while x>9:
        b=(x%(10*i))/i
        x=x-(b*i)
        r.append(b)
    
        i=i*10
    r.sort()
    for i in range(len(r)-1):
        if r[i+1]==r[i]:
            hell=0
    return hell
year=int(input(""))
p=0
while p!=1:
    year+=1  
    p=check(year)
    
print(year)