It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def distinct(n):
	ni = n
	ns = str(n)
	n1,ni = str(ni%10),ni//10
	n2,ni = str(ni%10),ni//10
	n3,ni = str(ni%10),ni//10
	n4 = str(ni)
	if(ns.count(n1)==1 and ns.count(n2)==1 and ns.count(n3)==1 and ns.count(n4)==1):
		return 1
	else:
		return 0
	
a = int(input().strip())

a += 1
while(distinct(a)==0):
	a += 1
print(a)
