It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
s=int(input())

flag=0
def test(s,i=0,summ=0):
    s=str(s)
    for i in range(0,3):
        for j in range(i+1,4):
            if s[i]!=s[j]:
                summ+=1
    if summ==6:
        return 1
    else:
        return 0
if test(s)==1:
    s=s+1
while flag==0:
    if test(s)==1:
        flag=1
        print(s)
        break
    else :
        s+=1
    
    
