It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
int n, a[4];
bool isIt(int x) {
  for (int i = 0; i < 4; ++i) {
    a[i] = x % 10;
    x /= 10;
  }
  for (int i = 0; i < 3; ++i)
    for (int j = i + 1; j < 4; ++j)
      if (a[i] == a[j]) return false;
  return true;
}
int main() {
  scanf("%d", &n);
  for (int i = n + 1; i < 10000; ++i)
    if (isIt(i)) {
      printf("%d\n", i);
      break;
    }
  return 0;
}
