It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
import sys, math
def rs():
    return sys.stdin.readline().strip()
def ri():
    return int(sys.stdin.readline().strip())
def ras():
    return list(sys.stdin.readline().strip())
def rai():
    return map(int,sys.stdin.readline().strip().split())
def main():
    n = ri() + 1
    while True:
        r = True
        l = list(str(n))
        for k in l:
            if l.count(k) != 1:
                r = False
                break
        if not r:
            n+=1
        else:
            print n
            return


    

if __name__ == "__main__":
    main()