It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
a = input();
sol = a + 1

def arr( x ):
	ret = []
	while x != 0:
		ret.append( x % 10 )
		x = x / 10
	return ret

def distinto( x ):
	y = arr( x )
	z = []
	for i in range( 10 ):
		z.append( 0 )
	for i in y:
		if z[i] != 0:
			return False
		z[i] = 1
	return True

while not distinto( sol ):
	sol = sol + 1

print sol
