It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
import math

year = list(input())

year_val = ""

year_val = int(year_val.join(year)) + 1



while(True):
    flag_br = 0
    year_val_new = list(str(year_val))
    for i in range(len(year_val_new)-1):
        for j in range(i+1, len(year_val_new)):
            if(year_val_new[i]==year_val_new[j]):
                flag_br = 1
                break
    
    if(flag_br==1):
        year_val+=1
    
    else:
        print(year_val)
        break
    

