It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def f(god):
    c1 = god // 1000
    c2 = (god // 100) % 10
    c3 = (god // 10) % 10
    c4 = god % 10
    if c1 == c2 or c1 == c3 or c1 == c4 or c2 == c3 or c2 == c4 or c3 == c4:
        return False
    if c1 != c2 != c3 != c4:
        return True


g = int(input())
g += 1
while not f(g):
    g += 1
print(g)
