It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
y=int(input())
y1=['0','0','0','0']
y=y+1
while y<=100000:
    y1[0]=int(y/1000)
    y1[1]=int(int(y/100)%10)
    y1[2]=int(int(y/10)%10)
    y1[3]=int(y%10)
    if y1[0]!=y1[1]and y1[0]!=y1[2]and y1[0]!=y1[3]and y1[1]!=y1[2]and y1[1]!=y1[3]and y1[2]!=y1[3]:
        print(y)
        break
    else:
        y=y+1


    
    
            
