It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014


def check(num, num2):
	year = str(num)
	year2 = str(num2)
	for i in range(0, len(year2)):
		for j in range(0, len(year2)):
			if i == j:
				continue
			elif year2[i] == year2[j]:
				return False
	return True
def main():
	num = int(input())
	plus = 1
	while (not check(num, num+plus)):
		plus+=1
	print(num + plus)



main()