It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
num = int(input()) + 1

def differentDigits(num):
    digits = []
    numb = str(num)

    for i in range(len(numb)):

        if numb[i] not in digits:
            
            digits.append(numb[i])
            #print(numb[i])
            #print(digits)

        else:
            return False

    return True

while differentDigits(num) != True:

    num += 1

print(num)
