It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def isDistinctYear(year):
    digits = dict()
    i = year
    while(i > 0):
        digits[i%10] = 0
        i //= 10
    i = year
    while(i > 0):
        digits[i%10] += 1
        i //= 10
    for i in digits:
        if(digits[i] > 1):
            return False
    return True

year = int(input())
distinctYear = False
while(distinctYear == False):
    year += 1
    if(isDistinctYear(year)):
        distinctYear = True
print(year)