It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
a = int(input())
s = []
k1 = set()
k2 = set()
while 1000 <= a:
    s.clear()
    k1.clear()
    k2.clear()
    a = a + 1
    for i in str(a):
        s.append(int(i))
    for i in s:
        if i not in k1:
            k1.add(i)
        else:
            k2.add(i)
    k3 = k1 & k2
    if k3 == set():
        break
    else:
        continue
G = int(''.join((str(i) for i in s)))
print(G)

