It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
# -*-coding:utf-8 -*-
def add(y):
    y[len(y)-1]+=1
    for i in range(len(y)-1,-1,-1):
        if y[i]>=10:
            y[i]=y[i]-10
            y[i-1]+=1
        else:
            break
y_temp=raw_input()
y=[]
for i in y_temp:
    y.append(int(i))
add(y)
while True:
    flag=True
    for i in range(len(y)-1,-1,-1):
        if y.count(y[i])>1:
            flag=False
            break
    if flag:
        break
    add(y)
y_out=''
for i in y:
    y_out+=str(i)
print y_out
