You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
signed long long int pre[4005], m1, m2;
int sum, d[4005], fre[4005 * 4005];
signed long long int a;
char str[4005];
int main() {
  cin >> a >> str;
  int l = strlen(str);
  for (int i = 0; i < l; ++i) d[i + 1] = str[i] - '0';
  for (int i = 1; i <= l; ++i) pre[i] = pre[i - 1] + d[i];
  for (int i = 1; i <= l; ++i) {
    for (int j = i; j <= l; ++j) {
      sum = pre[j] - pre[i - 1];
      fre[sum]++;
    }
  }
  signed long long int ans = 0;
  for (int i = 1; i <= l; ++i) {
    for (int j = i; j <= l; ++j) {
      m1 = pre[j] - pre[i - 1];
      if (m1 != 0) {
        if (a % m1 == 0) {
          signed long long int m2 = a / m1;
          if (m2 <= 4005 * 4005) ans += fre[m2];
        }
      } else if (m1 == 0 && a == 0) {
        ans += ((l * (l - 1)) / 2) + l;
      }
    }
  }
  cout << ans;
}
