It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
# -*- coding: utf-8 -*-
"""
Created on Fri Nov 22 16:02:02 2019

@author: Selene
"""
def a(x):
    if x[0]!=x[1] and x[0]!=x[2] and x[0]!=x[3] and x[1]!=x[2] and x[1]!=x[3] and x[2]!=x[3]:
        return True
    else:
        return False
n=int(input())+1
while a(str(n))==False:
    n=n+1
print(n)