A: Taking a Seat-Taking a Seat-

story

Mr. A entered the classroom at the examination site to take an examination. However, Mr. A is a very nervous type. Therefore, depending on the situation, there may be seats that Mr. A does not want to sit in. Therefore, Mr. A decided to find out how many seats he could sit on based on certain conditions.

problem

Mr. A is a nervous type of person. First of all, Mr. A cannot sit in the first row from the front. Because when I sit near the proctor, I get nervous and can't solve the problem. Also, if there is a person on the right or left, Mr. A cannot sit down. This is because the sound of the pencil next to me makes it impossible to concentrate during the test. In addition, you can't sit near a noisy guy (near 8 diagonally up, down, left, and right). This is because my voice echoes in my head during the break and I can't rest. Also, it's natural, but I can't sit in the seat where the students are already sitting.

Is there a place where Mr. A can sit under these conditions? Assuming that M x N seats are lined up in the classroom, let's find the number.

Input format

The first row gives M (number of rows: number of vertical seats) and N (number of columns: number of horizontal seats). From the second line, M lines and a character string of length N are given line by line. The j character of the i-th character string represents the state of the seat in the i-th row and the j-th column. Each letter is either'-',' x'or'o', vacant seats'-', noisy students sitting during breaks'x', other students sitting' Let it be o'.

Constraint

* 0 <M ≤ 100
* 0 <N ≤ 100



Output format

Output the number of seats that Mr. A can sit in one line depending on the conditions. Don't forget the line break at the end.

Input example 1


5 5
--o--
--xo-
--x--
o --- x
--xoo


Output example 1


3

Input example 2


2 6
--oooo
x--o--


Output example 2


1

Input example 3


3 5
-----
-----
-----


Output example 3


Ten

Input example 4


4 6
o-oxoo
oo-ooo
oooxo-
o-ooox


Output example 4


0





Example

Input

5 5
--o--
--xo-
--x--
o---x
--xoo


Output

3
import java.util.*;
import java.io.*;

public class Main {

	static void solve (FastScanner in, PrintWriter out, Methods ms) {
		
		int h = in.nextInt(), w = in.nextInt();
		char[][] map = new char[h+2][w+2];
		
		for (int i=1; i<h+1; i++) {
			String temp = in.next();
			for (int j=0; j<w; j++) {
				map[i][j+1] = temp.charAt(j);
			}
		}
		
		int ans = 0;
		
		//最前列は最初から除外
		for (int i=2; i<h+1; i++) {
			loop : for (int j=1; j<w+1; j++) {
				
				if (map[i][j] == '-') { //空き席のみ探索する
					
					boolean b = true;
					
					if (map[i][j-1]=='o' || map[i][j+1]=='o') {
						b = false;
					}
					else {
						for (int k=0; k<8; k++) {
							if (map[i+dy[k]][j+dx[k]] == 'x') {
								b = false;
								break;
							}
						}
					}
					
					if (b == true) {
						ans++;
					}
					
				}
				
			}
		}
		
		out.println(ans);
		
	}
	
	static int[] dx = {1, -1, 0,  0, 1,  1, -1, -1};
	static int[] dy = {0,  0, 1, -1, 1, -1,  1, -1};



	public static void main(String[] args) {
		FastScanner in = new FastScanner(System.in);
		PrintWriter out = new PrintWriter(System.out);
		Methods ms = new Methods();
		solve(in, out, ms);
		in.close();
		out.close();
	}

	static class Methods {

		public void print (Object... ar) {System.out.println(Arrays.deepToString(ar));}

		public int max (int... ar) {Arrays.sort(ar); return ar[ar.length-1];}

		public int min (int... ar) {Arrays.sort(ar); return ar[0];}

		public long gcd (long a, long b) {return b>0?gcd(b,a%b):a;}

		public long lcm (long a, long b) {return a/gcd(a,b)*b;}

		public long factorial (int i) {
			if (i==1) return 1;
			else return i*factorial(i-1);
		}

		public int manhat (int x1, int y1, int x2, int y2) {
			return Math.abs(x1-x2)+Math.abs(y1-y2);
		}

		public double euclid (double x1, double y1, double x2, double y2) {
			return Math.sqrt((x2-x1)*(x2-x1)+(y2-y1)*(y2-y1));
		}

		public boolean isPrime (int n) {
			if (n==2) return true;
			if (n<2 || n%2==0) return false;
			for (int i=3; i<=Math.sqrt(n); i+=2) if(n%i==0) return false;
			return true;
		}

	}

	static class FastScanner {

		private InputStream in;
		private byte[] buffer = new byte[1024];
		private  int length = 0, p = 0;

		public FastScanner (InputStream stream) {
			in = stream;
		}

		public boolean hasNextByte () {
			if (p < length) return true;
			else {
				p = 0;
				try {length = in.read(buffer);}
				catch (Exception e) {e.printStackTrace();}
				if (length <= 0) return false;
			}
			return true;
		}

		public int readByte () {
			if (hasNextByte() == true) return buffer[p++];
			return -1;
		}

		public boolean isPrintable (int n) {return 33<=n&&n<=126;}

		public void skip () {
			while (hasNextByte() && !isPrintable(buffer[p])) p++;
		}

		public boolean hasNext () {skip(); return hasNextByte();}

		public String next () {
			if (!hasNext()) throw new NoSuchElementException();
			StringBuilder sb = new StringBuilder();
			int t = readByte();
			while (isPrintable(t)) {
				sb.appendCodePoint(t);
				t = readByte();
			}
			return sb.toString();
		}

		public String[] nextArray (int n) {
			String[] ar = new String[n];
			for (int i=0; i<n; i++) ar[i] = next();
			return ar;
		}

		public int nextInt () {return Math.toIntExact(nextLong());}

		public int[] nextIntArray (int n) {
			int[] ar = new int[n];
			for (int i=0; i<n; i++) ar[i] = nextInt();
			return ar;
		}

		public long nextLong () {
			if (!hasNext()) throw new NoSuchElementException();
			boolean minus = false;
			int temp = readByte();
			if (temp == '-') {
				minus = true;
				temp = readByte();
			}
			if (temp<'0' || '9'<temp) throw new NumberFormatException();
			long n = 0;
			while (isPrintable(temp)) {
				if ('0'<=temp && temp<='9') {
					n *= 10;
					n += temp - '0';
				}
				else throw new NumberFormatException();
				temp = readByte();
			}
			return minus? -n : n;
		}

		public long[] nextLongArray (int n) {
			long[] ar = new long[n];
			for (int i=0; i<n; i++) ar[i] = nextLong();
			return ar;
		}

		public double nextDouble () {
			return Double.parseDouble(next());
		}

		public double[] nextDoubleArray (int n) {
			double[] ar = new double[n];
			for (int i=0; i<n; i++) ar[i] = nextDouble();
			return ar;
		}

		public void close () {
			try {in.close();}
			catch(Exception e){}
		}

	}

}
