You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
//package round213;

import java.util.Scanner;

public class c {

	public static void main(String[] args) {
		Scanner leer= new Scanner(System.in);
		int x = leer.nextInt();
		String s = leer.next();
		leer.close();
		int n = s.length();
		int[] a = new int[5000];
		for (int i=1; i<=n; i++)
			a[i] = s.charAt(i-1)-48;
		int[] b = new int[5000];
		for (int i=1; i<=n; i++)
			b[i] = b[i-1] + a[i];
		int[] c = new int[500000];
		for (int i=1; i<=n; i++)
			for (int j=0; j<i; j++)
				c[b[i]-b[j]]++;
		long m = 0;
		for (int i=1; i<=n; i++)
			for (int j=0; j<i; j++){
				int y = b[i]-b[j];
				if (y == 0 && x == 0) m += n*(n+1)/2;
				else if (x == 0) m += c[0];
				else if (y != 0 && x % y == 0 && x/y<=40000) m += c[x/y];
			}
		System.out.println(m);

	}

}
