It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
int main() {
  int x;
  cin >> x;
  int o, t, th, f;
  for (int i = x + 1;; i++) {
    o = i % 10;
    t = ((i % 100) - o) / 10;
    th = ((i % 1000) - ((t * 10) + o)) / 100;
    f = ((i % 10000) - ((t * 10) + o + (th * 100))) / 1000;
    if ((o != t && o != th && o != f) && (t != th && t != f) && (th != f)) {
      cout << (f * 1000) + (th * 100) + (t * 10) + (o) << endl;
      break;
    }
  }
  return 0;
}
