It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
x = input()
x = str(int(x) + 1)
def check(n):
    count = 0
    for a in range(0,3):
        if n[a] not in n[a+1:]:
            count += 1
        else:
            n = str(int(n) + 1)
            return check(n)
        if a == 2 and count == 3:
            print(n)
check(x)

 		 				  		  		  		    							