It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def check_year(x):
    b = []
    for i in range(1,5):
        t = x%10
        if ( t in b):
            return False       
        b.append(t)
        x -= t
        x /= 10
    return True
  
a = int(raw_input()) +1
const = a
for i in range(const,9013):
    if((check_year(a))):
        print a
        break
    else :
        a+=1
