You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

* 1 \leq |S| \leq 2 \times 10^5
* |S| = |T|
* S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:


S
T


Output

If S and T can be made equal, print `Yes`; otherwise, print `No`.

Examples

Input

azzel
apple


Output

Yes


Input

chokudai
redcoder


Output

No


Input

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu


Output

Yes
#include <bits/stdc++.h>
#define rep(i,n) for (int i = 0; i < (n); i++)
#define rng(a) a.begin(),a.end()
using namespace std;
using ll = long long;
using P = pair<int,int>;


int main() {
  string s, t;
  cin >> s >> t;
  vector<int> a(26), b(26);
  for(int i=0; i<s.size(); i++) a[s[i]-'a']++;
  for(int j=0; j<t.size(); j++) b[t[j]-'a']++;
  sort(rng(a));
  sort(rng(b));
  cout << (a==b? "Yes": "No") << endl;
  return 0;
}