It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
int main(void) {
  int n;
  cin >> n;
  int digits[10] = {0, 0, 0, 0, 0, 0, 0, 0, 0, 0};
  int flag = 0;
  while (flag == 0) {
    n = n + 1;
    int tmp = n;
    int ans = 0;
    while (tmp > 0) {
      int digit = tmp % 10;
      digits[digit] += 1;
      tmp = tmp / 10;
    }
    int flag2 = 0;
    for (int i = 0; i < 10; i++) {
      if (digits[i] >= 2) {
        ans = 0;
        flag2 = 1;
      }
      digits[i] = 0;
    }
    if (flag2 == 0) {
      cout << n;
      flag = 1;
    }
  }
  return 0;
}
