It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
from math import *
from copy import *
from string import *				# alpha = ascii_lowercase
from random import *
from sys import stdin
from sys import maxsize
from operator import *				# d = sorted(d.items(), key=itemgetter(1))
from itertools import *
from collections import Counter		# d = dict(Counter(l))
import math

s=str(input())
n=int(s)
n=n+1
while(True):
	s1=str(n)
	if(s1[0:1]!=s1[1:2] and s1[0:1]!=s1[2:3] and s1[0:1]!=s1[3:4] and s1[1:2]!=s1[3:4] and s1[2:3]!=s1[1:2] and s1[2:3]!=s1[3:4]):
		break
	else:
		n=n+1
print(n)
