It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#! /Library/Frameworks/Python.framework/Versions/2.6/bin/python

def hasSameDigits(num):
	d1 = num % 10
	d2 = (num / 10) % 10
	d3 = (num / 100) % 10
	d4 = (num / 1000) % 10

	if ((d1 == d2) | (d1 == d3) | (d1 == d4) | (d2 == d3) | (d2 == d4) | (d3 == d4)):
		return True
	else:
		return False

y = int(raw_input())

ans = y + 1;
while (hasSameDigits(ans)):
	ans += 1

print ans