It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
y1=int(input())
all=list()
for y in range(1000,10000):
    flag1=0
    for i in range(1,4):
        if str(y)[i]==str(y)[0]:
            flag1=1
    flag2=0
    for i in range(2,4):
        if str(y)[i]==str(y)[1]:
            flag2=1
    flag3=0
    if str(y)[3]==str(y)[2]:
        flag3=1
    if flag1==0 and flag2==0 and flag3==0:
        all.append(y)
if y1 in all:
    th=all.index(y1)
    y2=all[th+1]
else:
    all.append(y1)
    all.sort()
    th=all.index(y1)
    y2=all[th+1]
print(y2)