You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
const int maxn = 1e6 + 100;
int f[maxn];
int a[maxn];
char s[maxn];
int main() {
  int d;
  scanf("%d", &d);
  scanf("%s", s);
  int len = strlen(s);
  a[1] = s[0] - '0';
  for (int i = 1; i < len; i++) {
    a[i + 1] = a[i] + (s[i] - '0');
  }
  for (int i = 1; i <= len; i++) {
    for (int j = 0; j < i; j++) {
      f[a[i] - a[j]]++;
    }
  }
  long long ans = 0;
  for (int i = 1; i < maxn; i++) {
    if (d % i) continue;
    if ((d / i) >= maxn) continue;
    ans += (long long)f[i] * f[d / i];
  }
  if (d == 0) {
    ans = 0;
    for (int i = 0; i < maxn; i++) ans += (long long)f[0] * f[i];
    ans *= 2;
    ans -= (long long)f[0] * f[0];
  }
  printf("%I64d\n", ans);
}
