It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
a=int(input())+1
a1=a//1000
a2=a//100%10
a3=a//10%10
a4=a%10
while not(a1!=a2 and a1!=a3 and a1!=a4 and a2!=a3 and a2!=a4 and a3!=a4):
    a+=1
    a1=a//1000
    a2=a//100%10
    a3=a//10%10
    a4=a%10
print(str(a1)+str(a2)+str(a3)+str(a4),sep='') 