It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
year=int(input())

def isDistinct(num):
    list_num=[]
    while num>0:
        list_num.append(num%10)
        num=int(num/10)
    for i in range(0,len(list_num)-1):
        for j in range(i+1, len(list_num)):
            if list_num[i]==list_num[j]:
                return False
    return True

while isDistinct(year+1)!=True:
    year+=1
print(year+1)

        