You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
long long total[100000];
int A[4000 + 5];
int main() {
  long long a;
  string s;
  cin >> a;
  cin >> s;
  int n = s.length();
  for (int i = 0; i < n; ++i) {
    A[i] = s[i] - '0';
  }
  long long sum = 0;
  for (int i = 0; i < n; ++i) {
    sum = 0LL;
    for (int j = i; j < n; ++j) {
      sum += A[j];
      total[sum]++;
    }
  }
  long long acum = 0LL, res = 0LL;
  for (int i = 0; i < 100000; ++i) acum += total[i];
  for (int i = 0; i < 100000; ++i) {
    if (total[i] > 0) {
      if (i == 0) {
        if (a == 0) res += (2 * total[i] * acum - total[0] * total[0]);
      } else {
        if (a >= i && a % i == 0) {
          long long b = a / i;
          if (b < 100000) {
            res += (total[i] * total[b]);
          }
        }
      }
    }
  }
  cout << res << endl;
}
