It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def thou(x):
    return x // 1000
def hun(x):
    return (x - 1000 * thou(x)) // 100
def ten(x):
    return (x % 100) // 10
def dig(x):
    return x % 10
x = int(input()) + 1
i = 0
while i == 0:
    if thou(x) != hun(x) and hun(x) != ten(x) and ten(x) != dig(x) and thou(x) != ten(x) and hun(x) != dig(x) and thou(x) != dig(x):
        i = 1
    else:
        x += 1
print(x)