Helen works in Metropolis airport. She is responsible for creating a departure schedule. There are n flights that must depart today, the i-th of them is planned to depart at the i-th minute of the day.

Metropolis airport is the main transport hub of Metropolia, so it is difficult to keep the schedule intact. This is exactly the case today: because of technical issues, no flights were able to depart during the first k minutes of the day, so now the new departure schedule must be created.

All n scheduled flights must now depart at different minutes between (k + 1)-th and (k + n)-th, inclusive. However, it's not mandatory for the flights to depart in the same order they were initially scheduled to do so — their order in the new schedule can be different. There is only one restriction: no flight is allowed to depart earlier than it was supposed to depart in the initial schedule.

Helen knows that each minute of delay of the i-th flight costs airport ci burles. Help her find the order for flights to depart in the new schedule that minimizes the total cost for the airport.

Input

The first line contains two integers n and k (1 ≤ k ≤ n ≤ 300 000), here n is the number of flights, and k is the number of minutes in the beginning of the day that the flights did not depart.

The second line contains n integers c1, c2, ..., cn (1 ≤ ci ≤ 107), here ci is the cost of delaying the i-th flight for one minute.

Output

The first line must contain the minimum possible total cost of delaying the flights.

The second line must contain n different integers t1, t2, ..., tn (k + 1 ≤ ti ≤ k + n), here ti is the minute when the i-th flight must depart. If there are several optimal schedules, print any of them.

Example

Input

5 2
4 2 1 10 2


Output

20
3 6 7 4 5 

Note

Let us consider sample test. If Helen just moves all flights 2 minutes later preserving the order, the total cost of delaying the flights would be (3 - 1)·4 + (4 - 2)·2 + (5 - 3)·1 + (6 - 4)·10 + (7 - 5)·2 = 38 burles. 

However, the better schedule is shown in the sample answer, its cost is (3 - 1)·4 + (6 - 2)·2 + (7 - 3)·1 + (4 - 4)·10 + (5 - 5)·2 = 20 burles.
import java.io.*;
import java.util.PriorityQueue;

public class CAirport {

  private static final String REGEX = " ";
  private static final Boolean DEBUG = false;
  private static final String FILE_NAME = "input.txt";


  public static void main(String[] args) throws IOException {
    if (DEBUG) {
      generate();
    }
    Solver solver = new Solver();
    solver.readData();
    solver.solve();
    solver.print();
  }

  private static void generate() throws IOException {
//    FileWriter writer = new FileWriter("input.txt");
//    writer.close();
  }

  private static class Solver {
    private StringBuilder myStringBuilder = new StringBuilder();
    int n, k;
    long[] c;
    long tCur = 1;

    void readData() throws IOException {
      Scanner scanner = new Scanner();
      n = scanner.nextInt();
      k = scanner.nextInt();
      c = scanner.nextLongArray(n);
      scanner.close();
    }

    class Plane implements Comparable<Plane> {
      int i;

      public Plane(int i) {
        this.i = i;
      }

      long getCost() {
        return c[i];
      }

      @Override
      public int compareTo(Plane o) {
        return Long.compare(o.getCost(), getCost());
      }
    }

    void solve() {
      PriorityQueue<Plane> queue = new PriorityQueue<>();
      long[] t = new long[n];
      tCur = k + 1;
      for (int i = 0; i < k; i++) {
        queue.offer(new Plane(i));
      }
      long result = 0;
      for (int i = k; i < n; i++) {
        queue.offer(new Plane(i));
        Plane plane = queue.poll();
        result += c[plane.i] * (tCur - plane.i - 1);
        t[plane.i] = tCur;
        tCur++;
      }
      while (!queue.isEmpty()) {
        Plane plane = queue.poll();
        result += c[plane.i] * (tCur - plane.i - 1);
        t[plane.i] = tCur;
        tCur++;
      }
      out(result);
      out('\n');
      for (long l : t) {
        out(l);
        out(' ');
      }
    }

    void print() {
      System.out.println(myStringBuilder);
    }


    void out(Object object) {
      myStringBuilder.append(object);
    }

    void out(String string) {
      myStringBuilder.append(string);
    }

    public void out(boolean b) {
      myStringBuilder.append(b);
    }

    public void out(char c) {
      myStringBuilder.append(c);
    }

    public void out(int i) {
      myStringBuilder.append(i);
    }

    public void out(long lng) {
      myStringBuilder.append(lng);
    }

    public void out(float f) {
      myStringBuilder.append(f);
    }

    public void out(double d) {
      myStringBuilder.append(d);
    }

    public void newLine() {
      myStringBuilder.append("\n");
    }

    @SuppressWarnings("SameParameterValue")
    int[] splitInteger(String string, int n) {
      final String[] split = string.split(REGEX, n);
      int[] result = new int[split.length];
      for (int i = 0; i < n; ++i) {
        result[i] = Integer.parseInt(split[i]);
      }
      return result;
    }

    public int[] splitInteger(String string) {
      return splitInteger(string, 0);
    }


    @SuppressWarnings("SameParameterValue")
    long[] splitLong(String string, int n) {
      final String[] split = string.split(REGEX, n);
      long[] result = new long[split.length];
      for (int i = 0; i < n; ++i) {
        result[i] = Long.parseLong(split[i]);
      }
      return result;
    }

    public long[] splitLong(String string) {
      return splitLong(string, 0);
    }

    @SuppressWarnings("SameParameterValue")
    double[] splitDouble(String string, int n) {
      final String[] split = string.split(REGEX, n);
      double[] result = new double[split.length];
      for (int i = 0; i < n; ++i) {
        result[i] = Double.parseDouble(split[i]);
      }
      return result;
    }

    public double[] splitDouble(String string) {
      return splitDouble(string, 0);
    }

    @SuppressWarnings("SameParameterValue")
    String[] splitString(String string, int n) {
      return string.split(REGEX, n);
    }

    public int max(int a, int b) {
      return Math.max(a, b);
    }

    public int max(int[] arr) {
      int max = Integer.MIN_VALUE;
      for (int x : arr) {
        max = max(max, x);
      }
      return max;
    }

    public long max(long a, long b) {
      return Math.max(a, b);
    }

    public int min(int a, int b) {
      return Math.min(a, b);
    }

    public long min(long a, long b) {
      return Math.min(a, b);
    }

    public double max(double a, double b) {
      return Math.max(a, b);
    }

    public double min(double a, double b) {
      return Math.min(a, b);
    }

    private final static int MOD = 1000000009;

    int multMod(int a, int b) {
      return ((a % MOD) * (b % MOD)) % MOD;
    }

    int sumMod(int a, int b) {
      return ((a % MOD) + (b % MOD)) % MOD;
    }

    long multMod(long a, long b) {
      return ((a % MOD) * (b % MOD)) % MOD;
    }

    long sumMod(long a, long b) {
      return ((a % MOD) + (b % MOD)) % MOD;
    }

    int sum(int[] arr) {
      int sum = 0;
      for (int i = 0; i < arr.length; i++) {
        sum += arr[i];
      }
      return sum;
    }

    long sum(long[] arr) {
      long sum = 0;
      for (int i = 0; i < arr.length; i++) {
        sum += arr[i];
      }
      return sum;
    }

    private class Scanner {
      private int currentIndex = 0;
      private String[] objects;
      private final BufferedReader myReader;
      private Computable<Character> charComputer;
      private Computable<Double> doubleComputer;
      private Computable<Integer> intComputer;
      private Computable<Long> longComputer;

      Scanner() throws FileNotFoundException {
        InputStream in = DEBUG ? new FileInputStream(FILE_NAME) : System.in;
        myReader = new BufferedReader(new InputStreamReader(in));
        charComputer = () -> objects[currentIndex].charAt(0);
        doubleComputer = () -> Double.parseDouble(objects[currentIndex]);
        intComputer = () -> Integer.parseInt(objects[currentIndex]);
        longComputer = () -> Long.parseLong(objects[currentIndex]);
      }

      String nextLine() throws IOException {
        objects = null;
        currentIndex = 0;
        return myReader.readLine();
      }

      int nextInt() throws IOException {
        return next(intComputer);
      }

      int[] nextIntArray(int n) throws IOException {
        return splitInteger(nextLine(), n);
      }

      long[] nextLongArray(int n) throws IOException {
        return splitLong(nextLine(), n);
      }

      long nextLong() throws IOException {
        return next(longComputer);

      }

      double nextDouble() throws IOException {
        return next(doubleComputer);

      }

      char nextChar() throws IOException {
        return next(charComputer);
      }

      <T> T next(Computable<T> computer) throws IOException {
        T result;
        if (objects == null || currentIndex >= objects.length) {
          String s = myReader.readLine();
          objects = s.split(" ");
          currentIndex = 0;
        }
        result = computer.compute();
        currentIndex++;
        return result;
      }

      public void close() throws IOException {
        myReader.close();
      }

    }

    interface Computable<T> {
      T compute();
    }

  }

}
