You are given strings S and T consisting of lowercase English letters.

You can perform the following operation on S any number of times:

Operation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.

Determine if S and T can be made equal by performing the operation zero or more times.

Constraints

* 1 \leq |S| \leq 2 \times 10^5
* |S| = |T|
* S and T consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:


S
T


Output

If S and T can be made equal, print `Yes`; otherwise, print `No`.

Examples

Input

azzel
apple


Output

Yes


Input

chokudai
redcoder


Output

No


Input

abcdefghijklmnopqrstuvwxyz
ibyhqfrekavclxjstdwgpzmonu


Output

Yes
#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;

const int N=200000;

int l;
char ts[300],tt[300];
char s[N+5],t[N+5];

int main()
{
	scanf("%s %s",s+1,t+1);
	l=strlen(s+1);
	for(int i=1;i<=l;i++)
	{
		if(!ts[ s[i] ] && !tt[ t[i] ])
		{
			ts[ s[i] ] = t[i];
			tt[ t[i] ] = s[i];
		}
		if(ts[ s[i] ] != t[i] || tt[ t[i] ] != s[i])
		{
			puts("No");
			return 0;
		}
	}
	puts("Yes");
	return 0;
}