It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#182783
#Lucca Jordão

def frequencyDigits(n, d):
    c = 0 
    while (n > 0):  
        if (n % 10 == d): 
            c += 1; 
        n = int(n / 10)
    return c

def checkNumber(n):
    c = 0
    for i in range(10):
        if frequencyDigits(n, i) > 1:
            return 0
    return 1

numero = int(input())
numero += 1
flag = 1
while flag:
    if checkNumber(numero):
        flag = 0
    else:
        numero += 1
print(numero)
    



				   						 		 		  	 	 	 		 	