You came to the exhibition and one exhibit has drawn your attention. It consists of n stacks of blocks, where the i-th stack consists of a_i blocks resting on the surface.

The height of the exhibit is equal to m. Consequently, the number of blocks in each stack is less than or equal to m.

There is a camera on the ceiling that sees the top view of the blocks and a camera on the right wall that sees the side view of the blocks.

<image>

Find the maximum number of blocks you can remove such that the views for both the cameras would not change.

Note, that while originally all blocks are stacked on the floor, it is not required for them to stay connected to the floor after some blocks are removed. There is no gravity in the whole exhibition, so no block would fall down, even if the block underneath is removed. It is not allowed to move blocks by hand either.

Input

The first line contains two integers n and m (1 ≤ n ≤ 100 000, 1 ≤ m ≤ 10^9) — the number of stacks and the height of the exhibit.

The second line contains n integers a_1, a_2, …, a_n (1 ≤ a_i ≤ m) — the number of blocks in each stack from left to right.

Output

Print exactly one integer — the maximum number of blocks that can be removed.

Examples

Input

5 6
3 3 3 3 3


Output

10

Input

3 5
1 2 4


Output

3

Input

5 5
2 3 1 4 4


Output

9

Input

1 1000
548


Output

0

Input

3 3
3 1 1


Output

1

Note

The following pictures illustrate the first example and its possible solution.

Blue cells indicate removed blocks. There are 10 blue cells, so the answer is 10.

<image>
from __future__ import division, print_function
 
import os,sys
from io import BytesIO, IOBase
 
if sys.version_info[0] < 3:
    from __builtin__ import xrange as range
    from future_builtins import ascii, filter, hex, map, oct, zip
from itertools import permutations 
 
def ii():  return int(input())
def si():  return input()
def mi():  return map(int,input().split(" "))
def msi(): return map(str,input().split(" "))
def li():  return list(mi())
 
def dmain():
    sys.setrecursionlimit(1000000)
    threading.stack_size(1024000)
    thread = threading.Thread(target=main)
    thread.start()
    
import math
def getSum(n): 
    sum = 0
    while(n > 0): 
        sum += int(n%10) 
        n = int(n/10) 
  
    return sum

def isPowerOfTwo (x): return (x and (not(x & (x - 1))) )
 
def gcd(x, y):
    while y:
        x, y = y, x % y
    return x
def egcd(a, b):  
    if a == 0 :   
        return b, 0, 1
    gcd, x1, y1 = egcd(b%a, a)
    x = y1 - (b//a) * x1  
    y = x1  
     
    return gcd, x, y 
    
def checkPrime(n) : # Check Prime Number or not 
    if (n <= 1) : return False
    if (n <= 3) : return True
    if (n % 2 == 0 or n % 3 == 0) : return False
    i = 5
    while(i * i <= n) : 
        if (n % i == 0 or n % (i + 2) == 0) : 
            return False
        i = i + 6
    return True
def fib(n):
    if n==0:
        return (0,1)
    p=fib(n>>1)
    c=p[0]*(2*p[1]-p[0])
    d=p[0]*p[0]+p[1]*p[1]
    if (n&1):
        return c+2*d 
    else:
        return c+d 
def read():
    sys.stdin = open('input.txt', 'r')  
def powLog(x,y):
    res=1
    while y>0:
        if y&1:
            res=res*x
        x=x*x
        y>>=1
    return res


def main():
    n,m=mi()
    a=sorted(li())
    count=max(a)
    present=0
    for i in range(len(a)):
        if a[i]>present:
            present+=1
        else:
            count+=1
    print(sum(a)-count)
# region fastio
# template taken from https://github.com/cheran-senthil/PyRival/blob/master/templates/template.py
 
BUFSIZE = 8192
 
 
class FastIO(IOBase):
    newlines = 0
 
    def __init__(self, file):
        self._fd = file.fileno()
        self.buffer = BytesIO()
        self.writable = "x" in file.mode or "r" not in file.mode
        self.write = self.buffer.write if self.writable else None
 
    def read(self):
        while True:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            if not b:
                break
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines = 0
        return self.buffer.read()
 
    def readline(self):
        while self.newlines == 0:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            self.newlines = b.count(b"\n") + (not b)
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines -= 1
        return self.buffer.readline()
 
    def flush(self):
        if self.writable:
            os.write(self._fd, self.buffer.getvalue())
            self.buffer.truncate(0), self.buffer.seek(0)
 
 
class IOWrapper(IOBase):
    def __init__(self, file):
        self.buffer = FastIO(file)
        self.flush = self.buffer.flush
        self.writable = self.buffer.writable
        self.write = lambda s: self.buffer.write(s.encode("ascii"))
        self.read = lambda: self.buffer.read().decode("ascii")
        self.readline = lambda: self.buffer.readline().decode("ascii")
 
 
def print(*args, **kwargs):
    """Prints the values to a stream, or to sys.stdout by default."""
    sep, file = kwargs.pop("sep", " "), kwargs.pop("file", sys.stdout)
    at_start = True
    for x in args:
        if not at_start:
            file.write(sep)
        file.write(str(x))
        at_start = False
    file.write(kwargs.pop("end", "\n"))
    if kwargs.pop("flush", False):
        file.flush()
 
 
if sys.version_info[0] < 3:
    sys.stdin, sys.stdout = FastIO(sys.stdin), FastIO(sys.stdout)
else:
    sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
 
input = lambda: sys.stdin.readline().rstrip("\r\n")
 
# endregion
 
 
if __name__ == "__main__":
    #read()
    main()
    #dmain()
 
# Comment Read()