You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
const int maxn = 4005;
const int maxSum = 40000 + 5;
long long sum[maxn], b[maxn], Hash[maxSum];
char str[maxn];
int main() {
  int a;
  long long ans, val;
  while (scanf("%d%s", &a, str) == 2) {
    int len = strlen(str);
    for (int i = 1; i <= len; i++) {
      sum[i] = sum[i - 1] + str[i - 1] - '0';
    }
    for (int i = 1; i <= len; i++) {
      for (int j = i; j <= len; j++) {
        Hash[sum[j] - sum[i - 1]]++;
      }
    }
    ans = 0;
    for (int i = 1; i <= len; i++) {
      for (int j = i; j <= len; j++) {
        val = sum[j] - sum[i - 1];
        if (a == 0 && val == 0) {
          ans += (len + 1) * len / 2;
        } else if (val != 0 && a % val == 0 && a / val < maxSum) {
          ans += (Hash[a / val]);
        }
      }
    }
    printf("%I64d\n", ans);
  }
  return 0;
}
