It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
int main() {
  int y;
  std::cin >> y;
  int divideri = 1, dividerj = 1, digit, cnt = 0;
  while (true) {
    y++;
    divideri = 1;
    for (int i = 0; i < 4; i++) {
      if (i > 0) {
        divideri *= 10;
      }
      digit = (y / divideri) % 10;
      dividerj = divideri * 10;
      for (int j = i + 1; j < 4; j++) {
        if (digit != (y / dividerj) % 10) {
          cnt++;
        }
        dividerj *= 10;
      }
    }
    if (cnt == 6) {
      break;
    }
    cnt = 0;
  }
  std::cout << y << std::endl;
  return 0;
}
