It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def answer():
    a = int(input())+1
    while True:
        b=list(str(a))
        worked=1
        
        for x in b:
            count=-1
            i=0
            while i<len(b):
                if b[i]==x: count+=1
                i+=1
            if count!=0: 
                worked=0
                break

        if worked:
             j=0
             ans=""
             while j<4:
                 ans+=str(b[j])
                 j+=1
             return int(ans)
        else:
             j=0
             a=""
             while j<4:
                 a+=str(b[j])
                 j+=1
             a=int(a)
             a+=1

print(answer())