You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
string st;
long long a;
long long s[200000];
long long calc[1000000];
long long temp, ans;
long long gett(long long x) {
  if (x > 66666) return 0;
  return calc[x];
}
long long parts;
int main() {
  ios_base::sync_with_stdio(0);
  cin >> a;
  cin >> st;
  for (int i = 0; i < st.size(); i++) {
    s[i + 1] = s[i] + st[i] - 48;
  }
  for (int i = 0; i < st.size(); i++)
    for (int j = i + 1; j <= st.size(); j++) {
      parts++;
      calc[s[j] - s[i]]++;
    }
  for (int i = 1; i * i <= a; i++) {
    if (a % i == 0) {
      temp = gett(i) * gett(a / i);
      if (a / i == i)
        ans += temp;
      else
        ans += 2 * temp;
    }
  }
  if (a == 0) ans = parts * calc[0] + calc[0] * parts - calc[0] * calc[0];
  cout << ans << endl;
  cin.get();
  cin.get();
  return 0;
}
