It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
""" http://codeforces.com/problemset/problem/271/A """

def diff_digits(year):
    year_check = str(year)
    check_list = []
    for n in year_check:
        if n not in check_list:
            check_list.append(n)
        else:
            return False
    return True

year = int(input())

counter = 0
while not diff_digits(year) or counter == 0:
    counter = 1
    year += 1

print(year)




