It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def dup_c(n):
    b = str(n)
    i = 0
    for x in b:
        if b.count(x) < 2:
            i = i + 1
    if i == 4:
        return True
    else:
        return False

a = input()
b = int(a)
for x in range(b+1,90000):
    if dup_c(x) == True:
        print(x)
        break
