It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
y = int (input())



def check(a):
	l=[]
	while a!=0:
		x = a %10
		l.append(x)
		a =a// 10
		
	for i in l:
		n = l.count(i)
		if n>1:
			return False
	return True

while y<10000:
	y+=1 
	if check(y):
		break

print(y)


