It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def diff(x):
    lst = []
    while x != 0:
        if (x % 10) in lst:
            return -1
        else:
            lst.append(x % 10)
        x = x // 10
    return len(lst)


def main():
    n = int(input())
    i = n + 1
    while 1:
        if diff(i) != -1:
            print(i)
            break
        i = i + 1
#    print(diff(n))


if __name__ == "__main__":
    main()
