It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def check_distinct_digit(y):
    digit = []
    flag = True
    while y > 0:
        d = y % 10
        y = y // 10
        if d not in digit:
            digit.append(d)
        else:
            flag = False
            break
    return flag

y = int(input())

while True:
    y = y + 1
    if check_distinct_digit(y):
        print(y)
        break
    