It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
year = int(raw_input())

def isok(nr):
    l = {}
    for x in "0123456789":
        l[int(x)] = 0
    while nr >= 1:
        l[nr%10] += 1
        nr/=10
    for x in l:
        if l[x] > 1:
            return 0
    return 1

for i in range(year + 1, 9876):
    if isok(i):
        print i
        break