Vasya has got three integers n, m and k. He'd like to find three integer points (x_1, y_1), (x_2, y_2), (x_3, y_3), such that 0 ≤ x_1, x_2, x_3 ≤ n, 0 ≤ y_1, y_2, y_3 ≤ m and the area of the triangle formed by these points is equal to nm/k.

Help Vasya! Find such points (if it's possible). If there are multiple solutions, print any of them.

Input

The single line contains three integers n, m, k (1≤ n, m ≤ 10^9, 2 ≤ k ≤ 10^9).

Output

If there are no such points, print "NO".

Otherwise print "YES" in the first line. The next three lines should contain integers x_i, y_i — coordinates of the points, one point per line. If there are multiple solutions, print any of them.

You can print each letter in any case (upper or lower).

Examples

Input

4 3 3


Output

YES
1 0
2 3
4 1


Input

4 4 7


Output

NO

Note

In the first example area of the triangle should be equal to nm/k = 4. The triangle mentioned in the output is pictured below: 

<image>

In the second example there is no triangle with area nm/k = 16/7.
#include <bits/stdc++.h>
const int MAXN = 1e5 + 5;
const int MOD = 1e9 + 7;
using namespace std;
bool changed;
long long int val() {
  if (changed)
    return 1;
  else
    return 2;
}
int main() {
  long double n, m, k;
  cin >> n >> m >> k;
  long double area = ((n * m) / k) * 2;
  if (area != ceil(area)) {
    cout << "NO" << '\n';
    return 0;
  }
  long long int N = n;
  long long int M = m;
  long long int K = k;
  long long int AREA = area;
  if (K % 2 == 0) {
    changed = true;
    K /= 2;
  }
  for (long long int i = 1; i * i <= K; i++) {
    if (K % i == 0) {
      long long int x = i;
      long long int y = K / i;
      if (N % x == 0 && M % y == 0 && (N / x) * val() <= N) {
        cout << "YES" << '\n';
        cout << 0 << " " << 0 << '\n';
        cout << 0 << " " << M / y << '\n';
        cout << (N / x) * val() << " " << 0 << '\n';
        return 0;
      } else if (N % x == 0 && M % y == 0 && (M / y) * val() <= M) {
        cout << "YES" << '\n';
        cout << 0 << " " << 0 << '\n';
        cout << 0 << " " << (M / y) * val() << '\n';
        cout << (N / x) << " " << 0 << '\n';
        return 0;
      } else if (N % y == 0 && M % x == 0 && (N / y) * val() <= N) {
        cout << "YES" << '\n';
        cout << 0 << " " << 0 << '\n';
        cout << 0 << " " << (M / x) << '\n';
        cout << (N / y) * val() << " " << 0 << '\n';
        return 0;
      } else if (N % y == 0 && M % x == 0 && (M / x) * val() <= M) {
        cout << "YES" << '\n';
        cout << 0 << " " << 0 << '\n';
        cout << 0 << " " << (M / x) * val() << '\n';
        cout << (N / y) << " " << 0 << '\n';
        return 0;
      }
    }
  }
}
