It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def check(old):
    judge = 1
    s = str(old)
    for i in range(3):
        j = i + 1
        while j < 4:
            if s[i] == s [j]:
                judge = 0
                break
            j += 1
        if not judge:
            break
    return judge
old = int(input())
j = 0
while not j:
    old = old + 1
    j = check(old)
print(old)
