It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n = str(int(input())+1)

pole=list(n)

pom=len(pole)

pom_2=0

def unique(n,pole,pom,pom_2):
    for i in range(pom):
        for j in range(pom):
            if pole[j] == pole[i] and j!=i:
                pom_2+=1
                break
    if pom_2==0:
        print(n)
        
    if pom_2>0:
        pom_2=0
        n = str(int(n)+1)
        pole=list(n)
        pom=len(pole)
        unique(n,pole,pom,pom_2)

unique(n,pole,pom,pom_2)
