It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def jud(n):
    s=str(n)
    a=[0,0,0,0,0,0,0,0,0,0,0]
    for i in s:
        a[ord(i)-48]+=1
    for i in range(10):
        if a[i]>=2:
            return False
    return True

n=int(input())
n+=1
while not jud(n):
    n+=1
print(n)