It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
y = eval(input(""))

if (y >= 1000) and (y <= 9000):
    while 1:
        y += 1

        n1 = y // 1000
        n2 = (y % 1000) // 100
        n3 = (y % 100) // 10
        n4 = y % 10

        if (n1 != n2) and (n1 != n3) and (n1 != n4) and (n2 != n3) and (n2 != n4) and (n3 != n4):
            break

    print(str(n1) + str(n2) + str(n3) + str(n4))
