It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
a=int(input())
def bea(a):
            a=list(str(a))
            c=len(a)
            i=0
            j=1
            while c-1>i:
                        while c>j:
                                    if a[i]==a[j]:
                                                return 0
                                    j=j+1
                        j=1
                        i=i+1
                        j=j+i
            return 1
while bea(a+1)!=1:
            a=a+1
print(a+1)
            
