It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def distinct(a):
 b=int(a%10) 
 b=int(b)
 a=a/10
      
 c=int(a%10) 
 c=int(c)
 a=a/10
 
 d=int(a%10) 
 d=int(d)
 a=a/10

 e=int(a%10) 
 e=int(e)
 a=a/10
     

 if c!=b and b!=d and b!=e and c!=d and c!=e and d!=e :
        return 1
 else :
      return 0


a=int(input())
a=a+1
while distinct(a)==False :
   a+=1

print(a)
