You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
int gcd(int a, int b) { return a % b == 0 ? b : gcd(b, a % b); }
const int MAXN = 4010;
long long sum[MAXN];
long long cnt[MAXN * 10];
long long a;
char str[MAXN];
int main() {
  while (scanf("%I64d%s", &a, str + 1) != EOF) {
    int N = strlen(str + 1);
    sum[0] = 0;
    for (int i = 1; i <= N; i++) sum[i] = sum[i - 1] + str[i] - '0';
    memset(cnt, 0, sizeof(cnt));
    for (int i = 0; i <= N; i++)
      for (int j = i + 1; j <= N; j++) cnt[sum[j] - sum[i]]++;
    long long ans = 0;
    if (a != 0)
      for (int i = 1; i <= MAXN * 9; i++) {
        if (a % i == 0 && a / i <= MAXN * 9) ans += cnt[a / i] * cnt[i];
      }
    else {
      ans += cnt[0] * cnt[0];
      for (int i = 1; i <= MAXN * 9; i++) ans += cnt[0] * cnt[i] * 2;
    }
    printf("%I64d\n", ans);
  }
  return 0;
}
