You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
string s;
long long int a;
long long int n, sum, p[4007], f[40007];
long long int res = 0;
long long int gs(long long int l, long long int r) {
  if (!l) return p[r];
  return p[r] - p[l - 1];
}
int main() {
  std::cin >> a >> s;
  n = s.size();
  memset(p, 0, sizeof(p));
  memset(f, 0, sizeof(f));
  p[0] = (s[0] - '0');
  for (int i = 1; i < n; i++) p[i] = p[i - 1] + (s[i] - '0');
  for (int i = 0; i < n; i++)
    for (int j = i; j < n; j++) f[gs(i, j)]++;
  for (int i = 1; i < 40007; i++)
    if (!(a % i) && (a / i < 40006)) res += f[i] * f[a / i];
  if (!a)
    std::cout << f[0] * ((long long int)n * n + n - f[0]) << '\n';
  else
    cout << res;
}
