It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def is_ok(x: int) -> bool:
	d = []
	for i in range(4):
		d.append(x%10)
		x //= 10
	if d[0]!=d[1] and d[0]!=d[2] and d[0]!=d[3] and d[1]!=d[2] and d[1]!=d[3] and d[2]!=d[3]:
		return True
	return False



y = int(input())

i = y+1
while True:
	if is_ok(i):
		print(i)
		break
	i+=1

