It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n = int(input())
k = 1
while True:
	n = n+k
	s = str(n)
	li = list(s)
	if li[0] != li[1] and li[0] != li[2] and li[0] != li[3] and li[1] != li[2] and li[1] != li[3] and li[2]!=li[3]:
		st = ''.join(li)
		print(int(st))
		break
	else:
		pass