It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def findYear(c):
    t = c
    while True:
        t += 1
        a1 = t // 1000
        a2 = (t - a1 * 1000) // 100
        a3 = (t - a1 * 1000 - a2 * 100) // 10
        a4 = (t - a1 * 1000 - a2 * 100 - a3 * 10)

        if a1 != a2 and a1 != a3 and a1 != a4 and a2 != a3 and a2 != a4 and a3 != a4:
            return t


a = int(input())
c = findYear(a)
print(c)