It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def year(y):
    res = y + 1

    for i in range(res, 90001):
        aux = 0
        number = list(map(int, str(res))) 
        for j in range(len(number)):
            if number.count(number[j]) > 1:
                aux = 1
        if aux == 0:
            print(res)
            return
        else:
            res+=1


y = int(input())
year(y)
			 	      	   						  	 		 			