It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
int main() {
  int y;
  cin >> y;
  y++;
  int q, l;
  int r[10] = {0};
  int t = y;
  int c = 0;
  while (c != 1) {
    int count = 0;
    int r[10] = {0};
    for (int i = 1; i <= 4; i++) {
      l = t % 10;
      if (r[l] == 1) {
        break;
      } else if (r[l] == 0) {
        r[l] = 1;
      }
      t = t / 10;
      count++;
    }
    if (count == 4) {
      cout << y << endl;
      c = 1;
    }
    y++;
    t = y;
  }
}
