It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n = int (input())
def year(a):
    b = str (a)
    b = list(b.split())
    k=0
    for i in range(3):
        
        for j in range(i+1,4):
            if b[0][i]==b[0][j]:
                k=k+1
            else:
                k=k
    if k==0:
        return True
    else:
        return False
n=n+1

y=True
while y:
    if year(n):
        print(n)
        y=False
    else:
        n=n+1