You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
int num[36010] = {0};
int a[4010];
int f[4010];
char s[4010];
int N = 0, A;
char c;
int main() {
  scanf("%d\n", &A);
  scanf("%s", s + 1);
  for (N = 1; s[N]; N++) a[N] = s[N] - '0';
  N--;
  f[0] = 0;
  for (int i = 1; i <= N; i++) f[i] = a[i] + f[i - 1];
  for (int i = 1; i <= N; i++)
    for (int j = i; j <= N; j++) num[f[j] - f[i - 1]]++;
  long long ans = 0;
  if (!A) {
    ans = 1ll * num[0] * (1 + N) * N;
    ans -= 1ll * num[0] * num[0];
  } else
    for (int i = 1; i <= 36000; i++) {
      if (!num[i]) continue;
      if (A % i) continue;
      if (A / i > 36000) continue;
      ans += 1ll * num[i] * num[A / i];
    }
  cout << ans << endl;
}
