It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
int main() {
  int t;
  cin >> t;
  int k = t + 1;
  bool b = 0, f;
  while (1) {
    f = 0;
    if (b) {
      cout << k << endl;
      return 0;
    } else {
      vector<int> s;
      int c = k;
      while (c) {
        int p = c % 10;
        s.push_back(p);
        c /= 10;
      }
      sort(s.begin(), s.end());
      for (int z = 0; z < s.size() - 1; z++) {
        if (s[z] == s[z + 1]) {
          f = 1;
        }
      }
      if (f)
        k++;
      else
        b = 1;
    }
  }
}
