It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n = input()
newN = n + 1
nstr = ""
n0 = '0'
n1 = '0'
n2 = '0'
n3 = '0'

while newN > n:
    nstr = str(newN)
    n0 = int(nstr[0])
    n1 = int(nstr[1])
    n2 = int(nstr[2])
    n3 = int(nstr[3])
    
    if n0 != n1 and n0 != n2 and n0 != n3:
        if n1 != n2 and n1 != n3:
            if n2 != n3:
                print nstr
                break
    
    newN += 1
    