It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
mass = []
count = 1

year = int(input())

while count == 1:
          year += 1
          mass = []
          mass.append(year//1000)
          mass.append((year//100)%10)
          mass.append((year%100)//10)
          mass.append(year%10)
          for i in range(len(mass)):
                    for j in range(len(mass)):
                              if mass[i] == mass[j] and i != j:
                                        count = 1
                                        break
                              else:
                                        count = 0
                    if count == 1:
                              break
print(year)
          
