It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
if __name__ == '__main__':
    n=int(input())
    a=[]
    if n  in range(1987,2013):
        print("2013")
    else:
        flag=1
        while flag!=0:
            flag=0
            n=n+1
            i=n
            a.clear()
            while i>0:
               v=i%10
               if v in a:
                  flag=1
                  break
               a.append(v)
               i//=10
            if flag==0:
                if n>1987 and n<2013:
                  print(2013)
                else:
                  print(n)
                
            