It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n = int(input()) #y given
y = str(n + 1) # y to find in str format

def btf_year(y=y):
	while(True):
		v = True
		for i in range(len(y)):
			for j in range(i + 1, len(y)):
				if y[i] == y[j]:
					v = False
					y = str(int(y) + 1)
				if v:
					if j == 3 and i == 2:
						return y
print(btf_year())