It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
# https://codeforces.com/problemset/problem/271/A

"""
2013 is the first year after 1987 in which all its digits are distinct

Given a year number, find the smallest year after it in which all digits are distinct
"""


def is_distinct(number):
    # Checks if its digits are distinct
    number = str(number)
    n = len(str(number))

    for i in range(n):
        for j in range(n):
            if i < j and number[i] == number[j]:
                return False

    return True

def main():
    import sys

    year = int(sys.stdin.readline())

    candidate_year = year + 1

    # Reason that the first valid year is the minimum year
    while not is_distinct(candidate_year):
        candidate_year += 1

    sys.stdout.write(str(candidate_year))


if __name__ == '__main__':
    main()
