It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
b = int(input())


while b < 9500:
  b = b+1
  a1 = b//1000
  a2 = (b - (a1*1000))//100
  a3 = (b - (a1*1000) - (a2*100))//10
  a4 = (b - (a1*1000) - (a2*100) - (a3*10))
  if a1 != a2 and a1 != a3 and a1 != a4 and a2 != a3 and a2 != a4 != a3 != a4:
    break
  
print(b)