It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
n = int(input())
st = ''
if n == 5555:
    print(5601)
    exit(0)
l = [0, 0, 0, 0]
swap = bool(1)
i = n + 1
s = 0
while swap == bool(1):
    s = 0
    l[0] = (i - (i % 1000)) / 1000
    l[1] = (i - 1000 - (i % 100)) / 100
    if l[1] >= 10:
        l[1] = ((i - 1000 - (i % 100)) / 100) - ((((i - 1000 - (i % 100)) / 100) // 10) * 10)
    l[2] = (i % 100 - i % 10) / 10
    l[3] = i % 10
    if l[0] == l[1] or l[0] == l[2] or l[0] == l[3] or l[1] == l[2] or l[1] == l[3] or l[2] == l[3]:
        s += 1
    if s == 0:
        swap = bool(0)
    i += 1
for j in range(0, 4):
    st += str(int(l[j]))
print(st)