It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#include <bits/stdc++.h>
using namespace std;
int main() {
  long long v[4], k;
  scanf("%lld", &k);
  for (int i = (k + 1); i <= (9012); i++) {
    v[3] = i % 10;
    v[2] = (int)(i % 100 / 10);
    v[1] = (int)(i % 1000 / 100);
    v[0] = (int)(i / 1000);
    if (v[0] != v[1] && v[2] != v[1] && v[2] != v[3] && v[0] != v[2] &&
        v[0] != v[3] && v[1] != v[3]) {
      cout << i;
      return 0;
    }
  }
  return 0;
}
