It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014

# def gcd(lft, rght):
#     if lft < rght:
#         rght, lft = lft, rght
#     if rght == 0:
#         return lft
#     return gcd(rght, lft % rght)
#
#
# def lcm(lft, rght):
#     return (lft * rght) / gcd(lft, rght)




init_year = int(input())

for year in range(init_year + 1, 9013):
    if len(set(str(year))) == len(list(str(year))):
        print(year)
        break
