It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
from __future__ import division
from collections import Counter as ctr
import math
def rl():
	return [int(i) for i in raw_input().split()]

def rm(n=None):
	if n is None:
		n = input()
	return [raw_input() for i in range(n)]

def rlm(n=None):
	if n is None:
		n = input()
	return [rl() for i in range(n)]

def yn(b):
	if b:
		print "YES"
	else:
		print "NO"

n = input()
def distinct(n):
	return len(ctr(str(n))) == len(str(n))

while True:
	n += 1
	if distinct(n):
		print n
		break
