It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def jud(n):
    num = list(n)
    l = len(num)
    flagg = True
    for i in range(l):
        if num.count(num[i]) >= 2:
            flagg = False
    return flagg

y = int(input())
x = y + 1

while jud(str(x)) == False:
        x=x+1

print(str(x))