It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
#!usr/bin/python

n = input();

while(1):
	n += 1;
	d =  n % 10;
	b = (n / 10) % 10;
	c = (n / 100) % 10;
	a = (n / 1000) % 10;
	if(a != b and b != c and c != d and d != a and a != c and b != d):
		print n;
		break;	