It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Examples

Input

1987


Output

2013


Input

2013


Output

2014
def check(x):
	x = str(x)
	x = list(x)
	for i in range(len(x)):
		if x[i] not in x[:i] and x[i] not in x[i+1:]:
			a = 1
		else:
			a = 0
			return False
	if a == 1:
		return True

def y():
	year = raw_input("")
	year = ''.join(year)
	year = int(year)
	found = True

	while found:
		year += 1
		if check(year):
			print year
			found = False

	#print year




y()