You are given an integer sequence a_1, a_2, ..., a_n.

Find the number of pairs of indices (l, r) (1 ≤ l ≤ r ≤ n) such that the value of median of a_l, a_{l+1}, ..., a_r is exactly the given number m.

The median of a sequence is the value of an element which is in the middle of the sequence after sorting it in non-decreasing order. If the length of the sequence is even, the left of two middle elements is used.

For example, if a=[4, 2, 7, 5] then its median is 4 since after sorting the sequence, it will look like [2, 4, 5, 7] and the left of two middle elements is equal to 4. The median of [7, 1, 2, 9, 6] equals 6 since after sorting, the value 6 will be in the middle of the sequence.

Write a program to find the number of pairs of indices (l, r) (1 ≤ l ≤ r ≤ n) such that the value of median of a_l, a_{l+1}, ..., a_r is exactly the given number m.

Input

The first line contains integers n and m (1 ≤ n,m ≤ 2⋅10^5) — the length of the given sequence and the required value of the median.

The second line contains an integer sequence a_1, a_2, ..., a_n (1 ≤ a_i ≤ 2⋅10^5).

Output

Print the required number.

Examples

Input

5 4
1 4 5 60 4


Output

8


Input

3 1
1 1 1


Output

6


Input

15 2
1 2 3 1 2 3 1 2 3 1 2 3 1 2 3


Output

97

Note

In the first example, the suitable pairs of indices are: (1, 3), (1, 4), (1, 5), (2, 2), (2, 3), (2, 5), (4, 5) and (5, 5).
import javax.swing.plaf.synth.SynthEditorPaneUI;
import java.io.*;
import java.math.BigInteger;
import java.util.*;

public class Contest1 {
    static int[]a ;
    static long calc(int v){
        FenwickTree fn = new FenwickTree(3*a.length);
        int offset = a.length+1;
        int add=0;
        long ans =0;
        for (int i =0;i<a.length;i++){
            int cur = a[i]>=v?1:-1;
            add+=cur;
            int upd = cur-add;
            fn.point_update(upd+offset,1);
            ans+=fn.rsq(1-add+offset,3*a.length);
        }
        return ans;
    }
    public static void main(String[] args) throws Exception {
        Scanner sc = new Scanner(System.in);
        PrintWriter pw = new PrintWriter(System.out);
        int n = sc.nextInt();
        int m = sc.nextInt();
        a= new int[n];
        for (int i =0;i<n;i++)a[i]=sc.nextInt();
        long ans = calc(m)-calc(m+1);
        pw.println(ans);
        pw.flush();
    }
    static long gcd(long a,long b){
        if (a==0)
            return b;
        return gcd(b%a,a);
    }
    static class FenwickTree { // one-based DS

        int n;
        int[] ft;

        FenwickTree(int size) { n = size; ft = new int[n+1]; }

        int rsq(int b) //O(log n)
        {
            int sum = 0;
            while(b > 0) { sum += ft[b]; b -= b & -b;}		//min?
            return sum;
        }

        int rsq(int a, int b) { return rsq(b) - rsq(a-1); }

        void point_update(int k, int val)	//O(log n), update = increment
        {
            while(k <= n) { ft[k] += val; k += k & -k; }		//min?
        }
    }
    static class Scanner {
        StringTokenizer st;
        BufferedReader br;

        public Scanner(FileReader r) {
            br = new BufferedReader(r);
        }

        public Scanner(InputStream s) {
            br = new BufferedReader(new InputStreamReader(s));
        }

        public String next() throws IOException {
            while (st == null || !st.hasMoreTokens())
                st = new StringTokenizer(br.readLine());
            return st.nextToken();
        }

        public int nextInt() throws IOException {
            return Integer.parseInt(next());
        }

        public long nextLong() throws IOException {
            return Long.parseLong(next());
        }

        public String nextLine() throws IOException {
            return br.readLine();
        }

        public double nextDouble() throws IOException {
            String x = next();
            StringBuilder sb = new StringBuilder("0");
            double res = 0, f = 1;
            boolean dec = false, neg = false;
            int start = 0;
            if (x.charAt(0) == '-') {
                neg = true;
                start++;
            }
            for (int i = start; i < x.length(); i++)
                if (x.charAt(i) == '.') {
                    res = Long.parseLong(sb.toString());
                    sb = new StringBuilder("0");
                    dec = true;
                } else {
                    sb.append(x.charAt(i));
                    if (dec)
                        f *= 10;
                }
            res += Long.parseLong(sb.toString()) / f;
            return res * (neg ? -1 : 1);
        }

        public boolean ready() throws IOException {
            return br.ready();
        }
    }
}