Problem statement

Of the string set $ S $ that meets the following conditions, configure $ 1 $ with the largest number of elements.

* The length of the string contained in $ S $ is $ 1 $ or more and $ N $ or less.
* The lengths of the strings contained in $ S $ are different.
* The string contained in $ S $ consists only of the characters `0` and` 1`.
* For any $ 2 $ string contained in $ S $, one is not a substring of the other.



However, the substring of the string $ x $ is the string obtained by removing more than $ 0 $ characters from the beginning and end of $ x $.

Constraint

* $ 1 \ leq N \ leq 300 $
* $ N $ is an integer



* * *

input

Input is given from standard input in the following format.


$ N $


output

Output $ 1 $ of the string set $ S $ that satisfies the condition with the maximum number of elements. There may be multiple such $ S $, but any output will be correct.

Specifically, output in the following format.

Output $ K $, the number of elements of $ S $, on the $ 1 $ line.

Output all $ S $ elements from the $ 2 $ line to the $ K + 1 $ line. Print $ 1 $ of $ S $ elements on each line.


$ K $
$ S_1 $
$ S_2 $
$ \ vdots $
$ S_K $


* * *

Input example 1


2


Output example 1


2
0
11


The string set $ \\ {0, 11 \\} $ is the set with the largest number of elements that meets the conditions.

* * *

Input example 2


1


Output example 2


1
0






Example

Input

2


Output

2
0
11
#include <iostream> // cin, cout, cerr
#include <algorithm> // minmax, sort, swap
#include <numeric> // iota
#include <cstdio> // printf, scanf
#include <string> // string, stoi, to_string
#include <vector> // vector
#include <queue> // queue, priority_queue
#include <deque> // deque
#include <map> // key-value pairs sorted by keys
#include <set> // set
#include <iomanip> // cout<<setprecision(n)
#include <functional> // function<void(int)>
#include <cmath>
#include <cassert>
#include <bitset>

#ifdef DEBUG
#include "debug.hpp"
#else
#define debug(...)
#endif

#define int long long // at least int64 > 9*10^18
#define EL '\n'
#define rep(i,n) for(int i = 0; i < (n); i++)
#define print(i) std::cout << (i) << '\n'
#define all(v) (v).begin(), (v).end()
/* libraries */

signed main() {
	int n;
	std::cin >> n;
	if(n==1) {
		print(1);
		print(0);
		return 0;
	}
	if(n==2) {
		print(2);
		print(0);
		print(11);
		return 0;
	}
	print(n-1);
	for(int i=0;i<=n-2;i++) {
		std::string s(i,'0');
		print('1'+s+'1');
	}
	return 0;
}

