n soldiers stand in a circle. For each soldier his height ai is known. A reconnaissance unit can be made of such two neighbouring soldiers, whose heights difference is minimal, i.e. |ai - aj| is minimal. So each of them will be less noticeable with the other. Output any pair of soldiers that can form a reconnaissance unit.

Input

The first line contains integer n (2 ≤ n ≤ 100) — amount of soldiers. Then follow the heights of the soldiers in their order in the circle — n space-separated integers a1, a2, ..., an (1 ≤ ai ≤ 1000). The soldier heights are given in clockwise or counterclockwise direction.

Output

Output two integers — indexes of neighbouring soldiers, who should form a reconnaissance unit. If there are many optimum solutions, output any of them. Remember, that the soldiers stand in a circle.

Examples

Input

5
10 12 13 15 10


Output

5 1


Input

4
10 20 30 40


Output

1 2
#import math

#n, m = input().split()
#n = int (n)
#m = int (m)
#n, m, k = input().split()
#n = int (n)
#m = int (m)
#k = int (k)
n = int(input())
#m = int(input())
#s = input()
#t = input()
a = list(map(int, input().split()))
#print(l)
#c = list(map(int, input().split()))

#x1, y1, x2, y2 =map(int,input().split())
#n = int(input())
#f = []
#t = [0]*n
#f = [(int(s1[0]),s1[1]), (int(s2[0]),s2[1]), (int(s3[0]), s3[1])]
m = abs(a[0]-a[n-1])
p1 = 1
p2 = n

for i in range(n-1):
    if (abs (a[i] - a[i+1])< m):
        m = abs(a[i]-a[i+1])
        p1 = i + 1
        p2 = i +2
print(p1, p2)
#h = [""] * n
#f1 = sorted(f, key = lambda tup: tup[0])


#f1 = sorted(t, key = lambda tup: tup[0])
