Let's call left cyclic shift of some string t_1 t_2 t_3 ... t_{n - 1} t_n as string t_2 t_3 ... t_{n - 1} t_n t_1.

Analogically, let's call right cyclic shift of string t as string t_n t_1 t_2 t_3 ... t_{n - 1}.

Let's say string t is good if its left cyclic shift is equal to its right cyclic shift.

You are given string s which consists of digits 0–9.

What is the minimum number of characters you need to erase from s to make it good?

Input

The first line contains single integer t (1 ≤ t ≤ 1000) — the number of test cases.

Next t lines contains test cases — one per line. The first and only line of each test case contains string s (2 ≤ |s| ≤ 2 ⋅ 10^5). Each character s_i is digit 0–9.

It's guaranteed that the total length of strings doesn't exceed 2 ⋅ 10^5.

Output

For each test case, print the minimum number of characters you need to erase from s to make it good.

Example

Input


3
95831
100120013
252525252525


Output


3
5
0

Note

In the first test case, you can erase any 3 characters, for example, the 1-st, the 3-rd, and the 4-th. You'll get string 51 and it is good.

In the second test case, we can erase all characters except 0: the remaining string is 0000 and it's good.

In the third test case, the given string s is already good.
import sys
reader = (s.rstrip() for s in sys.stdin)
input = reader.__next__
nn = "0123456789"
def gift():
    for _ in range(t):
        s=input()
        ans = len(s)
        for fi in nn:
            for sc in nn:
     
                state = 0
                now = 0
     
                for i in s:
                    if i == fi and state == 0:
                        now += 1
                        state = 1
                    elif i == sc and state == 1:
                        now += 1
                        state = 0
     
                if fi == sc:
                    ans = min(ans , len(s) - now)
                else:
                    ans = min(ans , len(s) - now + now%2)
        yield ans
if __name__ == '__main__':
    t= int(input())
    ans = gift()
    print(*ans,sep='\n')
             


#"{} {} {}".format(maxele,minele,minele)
