Nezzar designs a brand new game "Hidden Permutations" and shares it with his best friend, Nanako.

At the beginning of the game, Nanako and Nezzar both know integers n and m. The game goes in the following way:

  * Firstly, Nezzar hides two permutations p_1,p_2,…,p_n and q_1,q_2,…,q_n of integers from 1 to n, and Nanako secretly selects m unordered pairs (l_1,r_1),(l_2,r_2),…,(l_m,r_m); 
  * After that, Nanako sends his chosen pairs to Nezzar; 
  * On receiving those m unordered pairs, Nezzar checks if there exists 1 ≤ i ≤ m, such that (p_{l_i}-p_{r_i}) and (q_{l_i}-q_{r_i}) have different signs. If so, Nezzar instantly loses the game and gets a score of -1. Otherwise, the score Nezzar gets is equal to the number of indices 1 ≤ i ≤ n such that p_i ≠ q_i. 



However, Nezzar accidentally knows Nanako's unordered pairs and decides to take advantage of them. Please help Nezzar find out two permutations p and q such that the score is maximized.

Input

The first line contains a single integer t (1 ≤ t ≤ 5 ⋅ 10^5) — the number of test cases.

The first line of each test case contains two integers n,m (1 ≤ n ≤ 5 ⋅ 10^5, 0 ≤ m ≤ min((n(n-1))/(2),5 ⋅ 10^5)). 

Then m lines follow, i-th of them contains two integers l_i,r_i (1 ≤ l_i,r_i ≤ n, l_i ≠ r_i), describing the i-th unordered pair Nanako chooses. It is guaranteed that all m unordered pairs are distinct.

It is guaranteed that the sum of n for all test cases does not exceed 5 ⋅ 10^5, and the sum of m for all test cases does not exceed 5⋅ 10^5.

Output

For each test case, print two permutations p_1,p_2,…,p_n and q_1,q_2,…,q_n such that the score Nezzar gets is maximized.

Example

Input


3
4 2
1 2
3 4
6 4
1 2
1 3
3 5
3 6
2 1
1 2


Output


1 2 3 4
3 4 1 2
2 3 4 1 6 5
1 4 3 2 5 6
1 2
1 2

Note

For first test case, for each pair given by Nanako:

  * for the first pair (1,2): p_1 - p_2 = 1 - 2 = -1, q_1 - q_2 = 3 - 4 = -1, they have the same sign; 
  * for the second pair (3,4): p_3 - p_4 = 3 - 4 = -1, q_3 - q_4 = 1 - 2 = -1, they have the same sign. 



As Nezzar does not lose instantly, Nezzar gains the score of 4 as p_i ≠ q_i for all 1 ≤ i ≤ 4. Obviously, it is the maximum possible score Nezzar can get.
#include <bits/stdc++.h>
 
using namespace std;
 
typedef long long ll;
typedef long double ld;
typedef unsigned long long ull;
#define rint register int
#define rll register ll 
#define pii pair<int, int>
#define pll pair<ll, ll>
//#define p1 first
//#define p2 second
#define fors(i, a, b) for (ll i = (a); i <= (b); ++i)
#define _fors(i, a, b) for (ll i = (a); i >= (b); --i)
#define mp(a, b) make_pair(a, b)
#define mt(a, b, c) make_tuple(a, b, c)
#define mem(A, b) memset(A, b, sizeof(A))
#define all(X) (X).begin(), (X).end()
#define pb push_back

static struct FastInput {
  static constexpr int BUF_SIZE = 1 << 20;
  char buf[BUF_SIZE];
  size_t chars_read = 0;
  size_t buf_pos = 0;
  FILE *in = stdin;
  char cur = 0;
 
  inline char get_char() {
    if (buf_pos >= chars_read) {
      chars_read = fread(buf, 1, BUF_SIZE, in);
      buf_pos = 0;
      buf[0] = (chars_read == 0 ? -1 : buf[0]);
    }
    return cur = buf[buf_pos++];
  }
 
  inline void tie(int) {}
 
  inline explicit operator bool() {
    return cur != -1;
  }
 
  inline static bool is_blank(char c) {
    return c <= ' ';
  }
 
  inline bool skip_blanks() {
    while (is_blank(cur) && cur != -1) {
      get_char();
    }
    return cur != -1;
  }
 
  inline FastInput& operator>>(char& c) {
    skip_blanks();
    c = cur;
    return *this;
  }
  
  inline FastInput& operator>>(string& s) {
    if (skip_blanks()) {
      s.clear();
      do {
        s += cur;
      } while (!is_blank(get_char()));
    }
    return *this;
  }
 
  template <typename T>
  inline FastInput& read_integer(T& n) {
    // unsafe, doesn't check that characters are actually digits
    n = 0;
    if (skip_blanks()) {
      int sign = +1;
      if (cur == '-') {
        sign = -1;
        get_char();
      }
      do {
        n += n + (n << 3) + cur - '0';
      } while (!is_blank(get_char()));
      n *= sign;
    }
    return *this;
  }
 
  template <typename T>
  inline typename enable_if<is_integral<T>::value, FastInput&>::type operator>>(T& n) {
    return read_integer(n);
  }
  
  #if !defined(_WIN32) || defined(_WIN64)
  inline FastInput& operator>>(__int128& n) {
    return read_integer(n);
  }
  #endif
 
  template <typename T>
  inline typename enable_if<is_floating_point<T>::value, FastInput&>::type operator>>(T& n) {
    // not sure if really fast, for compatibility only
    n = 0;
    if (skip_blanks()) {
      string s;
      (*this) >> s;
      sscanf(s.c_str(), "%lf", &n);
    }
    return *this;
  }
} fast_input;
 
#define cin fast_input
 
static struct FastOutput {
  static constexpr int BUF_SIZE = 1 << 20;
  char buf[BUF_SIZE];
  size_t buf_pos = 0;
  static constexpr int TMP_SIZE = 1 << 20;
  char tmp[TMP_SIZE];
  FILE *out = stdout;
 
  inline void put_char(char c) {
    buf[buf_pos++] = c;
    if (buf_pos == BUF_SIZE) {
      fwrite(buf, 1, buf_pos, out);
      buf_pos = 0;
    }
  }
 
  ~FastOutput() {
    fwrite(buf, 1, buf_pos, out);
  }
 
  inline FastOutput& operator<<(char c) {
    put_char(c);
    return *this;
  }
 
  inline FastOutput& operator<<(const char* s) {
    while (*s) {
      put_char(*s++);
    }
    return *this;
  }
 
  inline FastOutput& operator<<(const string& s) {
    for (int i = 0; i < (int) s.size(); i++) {
      put_char(s[i]);
    }
    return *this;
  }
 
  template <typename T>
  inline char* integer_to_string(T n) {
    // beware of TMP_SIZE
    char* p = tmp + TMP_SIZE - 1;
    if (n == 0) {
      *--p = '0';
    } else {
      bool is_negative = false;
      if (n < 0) {
        is_negative = true;
        n = -n;
      }
      while (n > 0) {
        *--p = (char) ('0' + n % 10);
        n /= 10;
      }
      if (is_negative) {
        *--p = '-';
      }
    }
    return p;
  }
 
  template <typename T>
  inline typename enable_if<is_integral<T>::value, char*>::type stringify(T n) {
    return integer_to_string(n);
  }
 
  #if !defined(_WIN32) || defined(_WIN64)
  inline char* stringify(__int128 n) {
    return integer_to_string(n);
  }
  #endif
 
  template <typename T>
  inline typename enable_if<is_floating_point<T>::value, char*>::type stringify(T n) {
    sprintf(tmp, "%.17f", n);
    return tmp;
  }
 
  template <typename T>
  inline FastOutput& operator<<(const T& n) {
    auto p = stringify(n);
    for (; *p != 0; p++) {
      put_char(*p);
    }
    return *this;
  }
} fast_output;

#define cout fast_output
#define endl '\n'

const int _ = 5e5 + 10;

int n, m;
int sm[_];
vector<int> lik[_];
int p[_], q[_];
set<int> sik[_];
int vis[_], fa[_], siz[_];
int top[_];
vector<int> dq[_];

signed main() {  
  //freopen("in.txt", "r", stdin);
 //freopen("out.txt", "w", stdout);
  ios::sync_with_stdio(false);
  cin.tie(0);
  int start_time = clock();
  int T;
  cin >> T;
  while (T--) {
    cin >> n >> m;
    fors(i, 1, n) sm[i] = 1;
    fors(i, 1, n) lik[i].clear(), sik[i].clear(), dq[i].clear();
    fors(i, 1, n) vis[i] = 0, siz[i] = 0;
    fors(i, 1, m) {
      int u, v;
      cin >> u >> v;
      lik[u].pb(v);
      lik[v].pb(u);
    }
    fors(i, 1, n) lik[i].pb(i);
    fors(i, 1, n) {
      sort(all(lik[i]));
      for (auto v : lik[i]) {
        if (sm[i] == v) sm[i]++;
      }
    }
    int val = n;
    fors(i, 1, n) {
      if (sm[i] == n + 1) { p[i] = val; q[i] = val; val--; }
      else {
        sik[i].insert(sm[i]);
        sik[sm[i]].insert(i);
      }
    }
    int star = 1;
    fors(i, 1, n) {
      if (sm[i] == n + 1) continue;
      if (!vis[i]) {
        int ok = 0;
        for (auto v : sik[i]) {
          if (!vis[v]) { vis[v] = star; fa[v] = i; ok = 1; siz[i]++; }
        }
        if (ok) { vis[i] = -star; star++; }
        else {
          int u = *sik[i].begin();
          siz[fa[u]]--;
          if (!siz[fa[u]]) { vis[u] = vis[fa[u]]; vis[fa[u]] = 0; }
          else { vis[u] = -star; star++; }
          for (auto v : sik[u]) {
            if (!vis[v]) { vis[v] = -vis[u]; fa[v] = u; siz[u]++; }
          }
        }
      }
    }
    fors(i, 1, n) {
      if (sm[i] == n + 1) continue;
      if (vis[i] < 0) top[-vis[i]] = i;
      if (vis[i] > 0) dq[vis[i]].pb(i);
    }
    val = 0;
    fors(i, 1, star-1) {
      val++;
      p[top[i]] = val;
      q[top[i]] = val + dq[i].size();
      for (auto v : dq[i]) {
        q[v] = val;
        p[v] = ++val;
      }
    }
    fors(i, 1, n) cout << p[i] << ' ';
    cout << endl;
    fors(i, 1, n) cout << q[i] << ' ';
    cout << endl;
  }
  //cout << "time = " << clock() - start_time << endl;
  return 0;
}