On the way to school, Karen became fixated on the puzzle game on her phone!

<image>

The game is played as follows. In each level, you have a grid with n rows and m columns. Each cell originally contains the number 0.

One move consists of choosing one row or column, and adding 1 to all of the cells in that row or column.

To win the level, after all the moves, the number in the cell at the i-th row and j-th column should be equal to gi, j.

Karen is stuck on one level, and wants to know a way to beat this level using the minimum number of moves. Please, help her with this task!

Input

The first line of input contains two integers, n and m (1 ≤ n, m ≤ 100), the number of rows and the number of columns in the grid, respectively.

The next n lines each contain m integers. In particular, the j-th integer in the i-th of these rows contains gi, j (0 ≤ gi, j ≤ 500).

Output

If there is an error and it is actually not possible to beat the level, output a single integer -1.

Otherwise, on the first line, output a single integer k, the minimum number of moves necessary to beat the level.

The next k lines should each contain one of the following, describing the moves in the order they must be done:

  * row x, (1 ≤ x ≤ n) describing a move of the form "choose the x-th row". 
  * col x, (1 ≤ x ≤ m) describing a move of the form "choose the x-th column". 



If there are multiple optimal solutions, output any one of them.

Examples

Input

3 5
2 2 2 3 2
0 0 0 1 0
1 1 1 2 1


Output

4
row 1
row 1
col 4
row 3


Input

3 3
0 0 0
0 1 0
0 0 0


Output

-1


Input

3 3
1 1 1
1 1 1
1 1 1


Output

3
row 1
row 2
row 3

Note

In the first test case, Karen has a grid with 3 rows and 5 columns. She can perform the following 4 moves to beat the level:

<image>

In the second test case, Karen has a grid with 3 rows and 3 columns. It is clear that it is impossible to beat the level; performing any move will create three 1s on the grid, but it is required to only have one 1 in the center.

In the third test case, Karen has a grid with 3 rows and 3 columns. She can perform the following 3 moves to beat the level:

<image>

Note that this is not the only solution; another solution, among others, is col 1, col 2, col 3.
import java.util.*;
import java.io.*;

public class CF419C 
{
	static boolean check(int[][] a)
	{
		for(int i=0;i<a.length;i++)
		{
			for(int j=0;j<a[i].length;j++)
			{
				if(a[i][j]!=0)
					return false;
			}
		}
		return true;
	}
	public static void main(String args[]) {
		InputReader in = new InputReader(System.in);
		OutputStream outputStream = System.out;
		PrintWriter out = new PrintWriter(outputStream);
		/*------------------------------My Code starts here------------------------------*/
		int n=in.nextInt(),m=in.nextInt(),i,j,min=Integer.MAX_VALUE,k;
		int[][] a=nextIntMatrix(in, n, m);
		List<String> al=new ArrayList<>();
		if(n<m)
		{
			for(i=0;i<n;i++)
			{
				min=Integer.MAX_VALUE;
				for(j=0;j<m;j++)
					min=Math.min(a[i][j], min);
				if(min!=0)
				{
					for(j=0;j<min;j++)
						al.add("row "+(i+1));
					for(j=0;j<m;j++)
						a[i][j]-=min;
				}
			}
			for(j=0;j<m;j++)
			{
				min=Integer.MAX_VALUE;
				for(i=0;i<n;i++)
					min=Math.min(a[i][j], min);
				if(min!=0)
				{
					for(i=0;i<min;i++)
						al.add("col "+(j+1));
					for(i=0;i<n;i++)
						a[i][j]-=min;
				}
			}
		}
		else
		{
			for(j=0;j<m;j++)
			{
				min=Integer.MAX_VALUE;
				for(i=0;i<n;i++)
					min=Math.min(a[i][j], min);
				if(min!=0)
				{
					for(i=0;i<min;i++)
						al.add("col "+(j+1));
					for(i=0;i<n;i++)
						a[i][j]-=min;
				}
			}
			for(i=0;i<n;i++)
			{
				min=Integer.MAX_VALUE;
				for(j=0;j<m;j++)
					min=Math.min(a[i][j], min);
				if(min!=0)
				{
					for(j=0;j<min;j++)
						al.add("row "+(i+1));
					for(j=0;j<m;j++)
						a[i][j]-=min;
				}
			}
		}
		if(check(a))
		{
			out.println(al.size());
			for(i=0;i<al.size();i++)
				out.println(al.get(i));
		}
		else
			out.println("-1");
		out.close();
		/*------------------------------The End------------------------------------------*/
	}

	public static final long l = (int) (1e9 + 7);

	private static int[] nextIntArray(InputReader in, int n) {
		int[] a = new int[n];
		for (int i = 0; i < n; i++)
			a[i] = in.nextInt();
		return a;
	}

	private static long[] nextLongArray(InputReader in, int n) {
		long[] a = new long[n];
		for (int i = 0; i < n; i++)
			a[i] = in.nextLong();
		return a;
	}

	private static int[][] nextIntMatrix(InputReader in, int n, int m) {
		int[][] a = new int[n][m];
		for (int i = 0; i < n; i++) {
			for (int j = 0; j < m; j++)
				a[i][j] = in.nextInt();
		}
		return a;
	}

	private static void show(int[] a) {
		for (int i = 0; i < a.length; i++)
			System.out.print(a[i] + " ");
		System.out.println();
	}

	private static void show2DArray(char[][] a) {
		for (int i = 0; i < a.length; i++) {
			for (int j = 0; j < a[0].length; j++)
				System.out.print(a[i][j]);
			System.out.println();
		}
	}

	static class Pair {
		private int first;
		private int second;

		public Pair(int i, int j) {
			this.first = i;
			this.second = j;
		}

		public int getFirst() {
			return first;
		}

		public int getSecond() {
			return second;
		}

		public void setFirst(int k) {
			this.first = k;
		}

		public void setSecond(int k) {
			this.second = k;
		}
	}

	static int modPow(int a, int b, int p) {
		int result = 1;
		a %= p;
		while (b > 0) {
			if ((b & 1) != 0)
				result = (result * a) % p;
			b = b >> 1;
		a = (a * a) % p;
		}
		return result;
	}

	public static void SieveOfEratosthenes(int n) {
		boolean[] prime = new boolean[n + 1];
		Arrays.fill(prime, true);
		prime[1] = false;
		int i, j;
		for (i = 2; i * i <= n; i++) {
			if (prime[i]) {
				for (j = i; j <= n; j += i) {
					if (j != i)
						prime[j] = false;
				}
			}
		}
	}

	static class InputReader {
		public BufferedReader reader;
		public StringTokenizer tokenizer;

		public InputReader(InputStream inputstream) {
			reader = new BufferedReader(new InputStreamReader(inputstream));
			tokenizer = null;
		}

		public String nextLine() {
			String fullLine = null;
			while (tokenizer == null || !tokenizer.hasMoreTokens()) {
				try {
					fullLine = reader.readLine();
				} catch (IOException e) {
					throw new RuntimeException(e);
				}
				return fullLine;
			}
			return fullLine;
		}

		public String next() {
			while (tokenizer == null || !tokenizer.hasMoreTokens()) {
				try {
					tokenizer = new StringTokenizer(reader.readLine());
				} catch (IOException e) {
					throw new RuntimeException(e);
				}
			}
			return tokenizer.nextToken();
		}

		public long nextLong() {
			return Long.parseLong(next());
		}

		public int nextInt() {
			return Integer.parseInt(next());
		}
	}

}
