Let's call left cyclic shift of some string t_1 t_2 t_3 ... t_{n - 1} t_n as string t_2 t_3 ... t_{n - 1} t_n t_1.

Analogically, let's call right cyclic shift of string t as string t_n t_1 t_2 t_3 ... t_{n - 1}.

Let's say string t is good if its left cyclic shift is equal to its right cyclic shift.

You are given string s which consists of digits 0–9.

What is the minimum number of characters you need to erase from s to make it good?

Input

The first line contains single integer t (1 ≤ t ≤ 1000) — the number of test cases.

Next t lines contains test cases — one per line. The first and only line of each test case contains string s (2 ≤ |s| ≤ 2 ⋅ 10^5). Each character s_i is digit 0–9.

It's guaranteed that the total length of strings doesn't exceed 2 ⋅ 10^5.

Output

For each test case, print the minimum number of characters you need to erase from s to make it good.

Example

Input


3
95831
100120013
252525252525


Output


3
5
0

Note

In the first test case, you can erase any 3 characters, for example, the 1-st, the 3-rd, and the 4-th. You'll get string 51 and it is good.

In the second test case, we can erase all characters except 0: the remaining string is 0000 and it's good.

In the third test case, the given string s is already good.
from sys import stdin

t = int(stdin.readline().strip())
for _ in range(t):                           
    S = stdin.readline().strip()
    #A = list(map(int, stdin.readline().strip().split(' ')))
    mindelete = len(S)
    for i in range(10):
        for j in range(10):
            ichar = str(i)
            jchar = str(j)
            first = True
            delete = len(S)
            for c in S:
                if c == ichar and first:
                    first = False
                elif c == jchar and not first:
                    first = True
                    delete -= 2
            mindelete = min(mindelete, delete)
    for i in range(10):
        ichar = str(i)
        delete = 0
        for c in S:
            if c != ichar:
                delete += 1
        mindelete = min(mindelete, delete)
    print(mindelete)

