F: MOD Rush

problem

Given a positive integer sequence A of length N and a positive integer sequence B of length M.

For all (i, j) (1 \ leq i \ leq N, 1 \ leq j \ leq M), find the remainder of A_i divided by B_j and output the sum of them.

Input format


N M
A_1 A_2 ... A_N
B_1 B_2 ... B_M


Constraint

* 1 \ leq N, M \ leq 2 \ times 10 ^ 5
* 1 \ leq A_i, B_i \ leq 2 \ times 10 ^ 5
* All inputs are given as integers



Output format

Print the answer on one line. Please start a new line at the end.

Input example 1


3 3
5 1 6
2 3 4


Output example 1


9

* Consider the remainder of dividing the first element of sequence A by each element of sequence B. Dividing 5 by 2 gives too much 1, dividing by 3 gives too much 2, and dividing by 4 gives too much 1.
* Similarly, considering the second element, too much is 1, 1, 1, respectively.
* Considering the third element, too much is 0, 0, 2, respectively.
* If you add up too much, you get 1 + 2 + 1 + 1 + 1 + 1 + 0 + 0 + 2 = 9, so 9 is output.



Input example 2


twenty four
2 7
3 3 4 4


Output example 2


16

* The same value may be included more than once in the sequence, but the sum is calculated by calculating too much for each element.



Input example 3


3 1
12 15 21
3


Output example 3


0





Example

Input

3 3
5 1 6
2 3 4


Output

9
// need
#include <iostream>
#include <algorithm>
// data structure
#include <bitset>
#include <map>
#include <queue>
#include <set>
#include <stack>
#include <string>
#include <utility>
#include <vector>
#include <complex>
//#include <deque>
#include <valarray>
#include <unordered_map>
#include <unordered_set>
#include <array>
// etc
#include <cassert>
#include <cmath>
#include <functional>
#include <iomanip>
#include <chrono>
#include <random>
#include <numeric>

// input
#define INIT std::ios::sync_with_stdio(false);std::cin.tie(0);
#define VAR(type, ...)type __VA_ARGS__;MACRO_VAR_Scan(__VA_ARGS__);
template<typename T> void MACRO_VAR_Scan(T& t) { std::cin >> t; }
template<typename First, typename...Rest>void MACRO_VAR_Scan(First& first, Rest& ...rest) { std::cin >> first; MACRO_VAR_Scan(rest...); }
#define VEC_ROW(type, n, ...)std::vector<type> __VA_ARGS__;MACRO_VEC_ROW_Init(n, __VA_ARGS__); for(int w_=0; w_<n; ++w_){MACRO_VEC_ROW_Scan(w_, __VA_ARGS__);}
template<typename T> void MACRO_VEC_ROW_Init(int n, T& t) { t.resize(n); }
template<typename First, typename...Rest>void MACRO_VEC_ROW_Init(int n, First& first, Rest& ...rest) { first.resize(n); MACRO_VEC_ROW_Init(n, rest...); }
template<typename T> void MACRO_VEC_ROW_Scan(int p, T& t) { std::cin >> t[p]; }
template<typename First, typename...Rest>void MACRO_VEC_ROW_Scan(int p, First& first, Rest& ...rest) { std::cin >> first[p]; MACRO_VEC_ROW_Scan(p, rest...); }
#define VEC(type, c, n) std::vector<type> c(n);for(auto& i:c)std::cin>>i;
#define MAT(type, c, m, n) std::vector<std::vector<type>> c(m, std::vector<type>(n));for(auto& R:c)for(auto& w:R)std::cin>>w;
// output
#define OUT(dist) std::cout<<(dist);
#define FOUT(n, dist) std::cout<<std::fixed<<std::setprecision(n)<<(dist);
#define SOUT(n, c, dist) std::cout<<std::setw(n)<<std::setfill(c)<<(dist);
#define SP std::cout<<" ";
#define TAB std::cout<<"\t";
#define BR std::cout<<"\n";
#define SPBR(w, n) std::cout<<(w + 1 == n ? '\n' : ' ');
#define ENDL std::cout<<std::endl;
#define FLUSH std::cout<<std::flush;
#define SHOW(dist) {std::cerr << #dist << "\t:" << (dist) << "\n";}
#define SHOWVECTOR(v) {std::cerr << #v << "\t:";for(const auto& xxx : v){std::cerr << xxx << " ";}std::cerr << "\n";}
#define SHOWVECTOR2(v) {std::cerr << #v << "\t:\n";for(const auto& xxx : v){for(const auto& yyy : xxx){std::cerr << yyy << " ";}std::cerr << "\n";}}
#define SHOWQUEUE(a) {auto tmp(a);std::cerr << #a << "\t:";while(!tmp.empty()){std::cerr << tmp.front() << " ";tmp.pop();}std::cerr << "\n";}
#define SHOWSTACK(a) {auto tmp(a);std::cerr << #a << "\t:";while(!tmp.empty()){std::cerr << tmp.top() << " ";tmp.pop();}std::cerr << "\n";}
// utility
#define ALL(a) (a).begin(),(a).end()
#define FOR(w, a, n) for(int w=(a);w<(n);++w)
#define RFOR(w, a, n) for(int w=(n)-1;w>=(a);--w)
#define REP(w, n) for(int w=0;w<int(n);++w)
#define RREP(w, n) for(int w=int(n)-1;w>=0;--w)
#define IN(a, x, b) (a<=x && x<b)
template<class T> inline T CHMAX(T & a, const T b) { return a = (a < b) ? b : a; }
template<class T> inline T CHMIN(T& a, const T b) { return a = (a > b) ? b : a; }
// test
template<class T> using V = std::vector<T>;
template<class T> using VV = V<V<T>>;

template<typename S, typename T>
std::ostream& operator<<(std::ostream& os, std::pair<S, T> p) {
	os << "(" << p.first << ", " << p.second << ")"; return os;
}

#define random_shuffle "USE std::shuffle!";

// type/const
//#define int ll
using ll = long long;
using ull = unsigned long long;
using ld = long double;
using PAIR = std::pair<int, int>;
using PAIRLL = std::pair<ll, ll>;
constexpr int INFINT = (1 << 30) - 1;                    // 1.07x10^ 9
constexpr int INFINT_LIM = (1LL << 31) - 1;              // 2.15x10^ 9
constexpr ll INFLL = 1LL << 60;                          // 1.15x10^18
constexpr ll INFLL_LIM = (1LL << 62) - 1 + (1LL << 62);  // 9.22x10^18
constexpr double EPS = 1e-10;
constexpr int MOD = 1000000007;
constexpr double PI = 3.141592653589793238462643383279;
template<class T, size_t N> void FILL(T(&a)[N], const T & val) { for (auto& x : a) x = val; }
template<class ARY, size_t N, size_t M, class T> void FILL(ARY(&a)[N][M], const T & val) { for (auto& b : a) FILL(b, val); }
template<class T> void FILL(std::vector<T> & a, const T & val) { for (auto& x : a) x = val; }
template<class ARY, class T> void FILL(std::vector<std::vector<ARY>> & a, const T & val) { for (auto& b : a) FILL(b, val); }
// ------------>8------------------------------------->8------------



signed main() {
	INIT;

	VAR(int, n, m);
	VEC(int, a, n);
	VEC(int, b, m);

	std::sort(ALL(a));
	{
		std::sort(b.rbegin(), b.rend());
		while (!b.empty() && b.back() == 1) b.pop_back();
		if (b.empty()) {
			OUT(0)BR;
			return 0;
		}
		std::reverse(ALL(b));
	}
	m = b.size();

	V<int> cnt(200005, 0);
	REP(j, m) ++cnt[b[j]];

	V<std::set<int>> pos(n);
	FOR(j, 2, 200005) {
		if (cnt[j] == 0) continue;
		for (int x = j; x < 200005; x += j) {
			auto it = std::lower_bound(ALL(a), x);
			if (it == a.end()) continue;
			pos[it - a.begin()].emplace(j);
		}
	}

	ll ans = 0, sum = 0;
	REP(j, m) sum += a[0] % b[j];
	ans += sum;

	FOR(i, 1, n) {
		sum += (a[i] - a[i - 1]) * m;
		for (auto& x : pos[i]) {
			sum -= cnt[x] * (a[i] - a[i - 1] + a[i - 1] % x - a[i] % x);
		}
		ans += sum;
	}
	OUT(ans)BR;

	return 0;
}
