Alice and Bob have received three big piles of candies as a gift. Now they want to divide these candies as fair as possible. To do this, Alice takes one pile of candies, then Bob takes one of the other two piles. The last pile is split between Alice and Bob as they want: for example, it is possible that Alice takes the whole pile, and Bob gets nothing from it.

After taking the candies from the piles, if Alice has more candies than Bob, she discards some candies so that the number of candies she has is equal to the number of candies Bob has. Of course, Bob does the same if he has more candies.

Alice and Bob want to have as many candies as possible, and they plan the process of dividing candies accordingly. Please calculate the maximum number of candies Alice can have after this division process (of course, Bob will have the same number of candies).

You have to answer q independent queries.

Let's see the following example: [1, 3, 4]. Then Alice can choose the third pile, Bob can take the second pile, and then the only candy from the first pile goes to Bob — then Alice has 4 candies, and Bob has 4 candies.

Another example is [1, 10, 100]. Then Alice can choose the second pile, Bob can choose the first pile, and candies from the third pile can be divided in such a way that Bob takes 54 candies, and Alice takes 46 candies. Now Bob has 55 candies, and Alice has 56 candies, so she has to discard one candy — and after that, she has 55 candies too.

Input

The first line of the input contains one integer q (1 ≤ q ≤ 1000) — the number of queries. Then q queries follow.

The only line of the query contains three integers a, b and c (1 ≤ a, b, c ≤ 10^{16}) — the number of candies in the first, second and third piles correspondingly.

Output

Print q lines. The i-th line should contain the answer for the i-th query — the maximum number of candies Alice can have after the division, if both Alice and Bob act optimally (of course, Bob will have the same number of candies).

Example

Input


4
1 3 4
1 10 100
10000000000000000 10000000000000000 10000000000000000
23 34 45


Output


4
55
15000000000000000
51
''' CODED WITH LOVE BY SATYAM KUMAR '''

from sys import stdin, stdout
import cProfile, math
from collections import Counter,defaultdict,deque
from bisect import bisect_left,bisect,bisect_right
import itertools
from copy import deepcopy
from fractions import Fraction
import sys, threading
import operator as op
from functools import reduce
sys.setrecursionlimit(10**6) # max depth of recursion
threading.stack_size(2**27)  # new thread will get stack of such size
fac_warmup = False
printHeap = str()
memory_constrained = False
P = 10**9+7
import sys

class merge_find:
    def __init__(self,n):
        self.parent = list(range(n))
        self.size = [1]*n
        self.num_sets = n
        self.lista = [[_] for _ in range(n)]
    def find(self,a):
        to_update = []
        while a != self.parent[a]:
            to_update.append(a)
            a = self.parent[a]
        for b in to_update:
            self.parent[b] = a
        return self.parent[a]
    def merge(self,a,b):
        a = self.find(a)
        b = self.find(b)
        if a==b:
            return
        if self.size[a]<self.size[b]:
            a,b = b,a
        self.num_sets -= 1
        self.parent[b] = a
        self.size[a] += self.size[b]
        self.lista[a] += self.lista[b]
    def set_size(self, a):
        return self.size[self.find(a)]
    def __len__(self):
        return self.num_sets

def display(string_to_print):
    stdout.write(str(string_to_print) + "\n")

def primeFactors(n): #n**0.5 complex 
    factors = dict()
    for i in range(2,math.ceil(math.sqrt(n))+1):  
        while n % i== 0: 
            if i in factors:
                factors[i]+=1
            else: factors[i]=1
            n = n // i 
    if n>2:
        factors[n]=1
    return (factors)

def all_factors(n):    
    return set(reduce(list.__add__, 
                ([i, n//i] for i in range(1, int(n**0.5) + 1) if n % i == 0)))

def fibonacci_modP(n,MOD):
    if n<2: return 1
    #print (n,MOD)
    return (cached_fn(fibonacci_modP, (n+1)//2, MOD)*cached_fn(fibonacci_modP, n//2, MOD) + cached_fn(fibonacci_modP, (n-1) // 2, MOD)*cached_fn(fibonacci_modP, (n-2) // 2, MOD)) % MOD

def factorial_modP_Wilson(n , p): 
    if (p <= n): 
        return 0
    res = (p - 1) 
    for i in range (n + 1, p): 
        res = (res * cached_fn(InverseEuler,i, p)) % p 
    return res 

def binary(n,digits = 20):
    b = bin(n)[2:]
    b = '0'*(digits-len(b))+b
    return b

def isprime(n):
    """Returns True if n is prime."""
    if n < 4:
        return True
    if n % 2 == 0:
        return False
    if n % 3 == 0:
        return False
    i = 5
    w = 2
    while i * i <= n:
        if n % i == 0:
            return False
        i += w
        w = 6 - w
    return True

def generate_primes(n):
    prime = [True for i in range(n+1)] 
    p = 2
    while (p * p <= n): 
        if (prime[p] == True): 
            for i in range(p * 2, n+1, p): 
                prime[i] = False
        p += 1
    return prime

factorial_modP = []
def warm_up_fac(MOD):
    global factorial_modP,fac_warmup
    if fac_warmup: return
    factorial_modP= [1 for _ in range(fac_warmup_size+1)]
    for i in range(2,fac_warmup_size):
        factorial_modP[i]= (factorial_modP[i-1]*i) % MOD
    fac_warmup = True

def InverseEuler(n,MOD):
    return pow(n,MOD-2,MOD)

def nCr(n, r, MOD):
    global fac_warmup,factorial_modP
    if not fac_warmup:
        warm_up_fac(MOD)
        fac_warmup = True
    return (factorial_modP[n]*((pow(factorial_modP[r], MOD-2, MOD) * pow(factorial_modP[n-r], MOD-2, MOD)) % MOD)) % MOD

def test_print(*args):
    if testingMode:
        print(args)

def display_list(list1, sep=" "):
    stdout.write(sep.join(map(str, list1)) + "\n")

def display_2D_list(li):
    for i in li:
        print(i)
def prefix_sum(li):
    sm = 0
    res = []
    for i in li:
        sm+=i
        res.append(sm)
    return res

def get_int():
    return int(stdin.readline().strip())

def get_tuple():
    return map(int, stdin.readline().split())

def get_list():
    return list(map(int, stdin.readline().split()))
import heapq,itertools
pq = []                         # list of entries arranged in a heap
entry_finder = {}               # mapping of tasks to entries
REMOVED = '<removed-task>' 
def add_task(task, priority=0):
    'Add a new task or update the priority of an existing task'
    if task in entry_finder:
        remove_task(task)
    count = next(counter)
    entry = [priority, count, task]
    entry_finder[task] = entry
    heapq.heappush(pq, entry)

def remove_task(task):
    'Mark an existing task as REMOVED.  Raise KeyError if not found.'
    entry = entry_finder.pop(task)
    entry[-1] = REMOVED

def pop_task():
    'Remove and return the lowest priority task. Raise KeyError if empty.'
    while pq:
        priority, count, task = heapq.heappop(pq)
        if task is not REMOVED:
            del entry_finder[task]
            return task
    raise KeyError('pop from an empty priority queue')
memory = dict()
def clear_cache():
    global memory
    memory = dict()
def cached_fn(fn, *args):
    global memory
    if args in memory:
        return memory[args]
    else:
        result = fn(*args)
        memory[args] = result
        return result

def ncr (n,r):
    return math.factorial(n)/(math.factorial(n-r)*math.factorial(r))
def binary_serach(i,li):
    #print("Search for ",i)
    fn = lambda x: li[x]-x//i
    x = -1
    b = len(li)
    while b>=1:
        #print(b,x)
        while b+x<len(li) and fn(b+x)>0: #Change this condition 2 to whatever you like
            x+=b
        b=b//2
    return x

# -------------------------------------------------------------- MAIN PROGRAM
TestCases = True
testingMode = False
fac_warmup_size = 10**5+100
optimiseForReccursion = False #Can not be used clubbed with TestCases # WHen using recursive functions, use Python 3
from math import factorial

def main():
    li = get_list()
    print(sum(li)//2)



# --------------------------------------------------------------------- END=


if TestCases: 
    for i in range(get_int()): 
        cProfile.run('main()') if testingMode else main() 
else: (cProfile.run('main()') if testingMode else main()) if not optimiseForReccursion else threading.Thread(target=main).start()