You are given an integer sequence a_1, a_2, ..., a_n.

Find the number of pairs of indices (l, r) (1 ≤ l ≤ r ≤ n) such that the value of median of a_l, a_{l+1}, ..., a_r is exactly the given number m.

The median of a sequence is the value of an element which is in the middle of the sequence after sorting it in non-decreasing order. If the length of the sequence is even, the left of two middle elements is used.

For example, if a=[4, 2, 7, 5] then its median is 4 since after sorting the sequence, it will look like [2, 4, 5, 7] and the left of two middle elements is equal to 4. The median of [7, 1, 2, 9, 6] equals 6 since after sorting, the value 6 will be in the middle of the sequence.

Write a program to find the number of pairs of indices (l, r) (1 ≤ l ≤ r ≤ n) such that the value of median of a_l, a_{l+1}, ..., a_r is exactly the given number m.

Input

The first line contains integers n and m (1 ≤ n,m ≤ 2⋅10^5) — the length of the given sequence and the required value of the median.

The second line contains an integer sequence a_1, a_2, ..., a_n (1 ≤ a_i ≤ 2⋅10^5).

Output

Print the required number.

Examples

Input

5 4
1 4 5 60 4


Output

8


Input

3 1
1 1 1


Output

6


Input

15 2
1 2 3 1 2 3 1 2 3 1 2 3 1 2 3


Output

97

Note

In the first example, the suitable pairs of indices are: (1, 3), (1, 4), (1, 5), (2, 2), (2, 3), (2, 5), (4, 5) and (5, 5).
#include <bits/stdc++.h>
using namespace std;
#pragma optimize("-O3")
string to_string(string s) { return '"' + s + '"'; }
string to_string(const char* s) { return to_string((string)s); }
string to_string(const bool& b) { return (b ? "true" : "false"); }
template <typename A, typename B>
string to_string(pair<A, B> p) {
  return "(" + to_string(p.first) + ", " + to_string(p.second) + ")";
}
template <typename A>
string to_string(const A& v) {
  bool first = true;
  string res = "{";
  for (const auto& x : v) {
    if (!first) res += ", ";
    first = false;
    res += to_string(x);
  }
  res += "}";
  return res;
}
void debug_out() { cerr << endl; }
template <typename Head, typename... Tail>
void debug_out(Head H, Tail... T) {
  cerr << " " << to_string(H);
  debug_out(T...);
}
template <typename T>
inline void _read(T& x) {
  cin >> x;
}
template <typename A, typename B>
inline void _read(pair<A, B>& x) {
  _read(x.first);
  _read(x.second);
}
template <typename T>
inline void _read(vector<T>& x) {
  for (auto& v : x) _read(v);
}
void R() {}
template <typename T, typename... U>
void R(T& head, U&... tail) {
  _read(head);
  R(tail...);
}
template <typename T>
inline void _write(const T& x) {
  cout << x << ' ';
}
template <typename A, typename B>
inline void _write(const pair<A, B>& x) {
  _write(x.first);
  _write(x.second);
}
template <typename T>
inline void _write(const vector<T>& in) {
  for (const auto& x : in) _write(x);
}
void W() { cout << '\n'; }
template <typename T, typename... U>
void W(const T& head, const U&... tail) {
  _write(head);
  W(tail...);
}
void go();
int main() {
  ios::sync_with_stdio(false);
  cin.tie(nullptr);
  cout.tie(nullptr);
  go();
  return 0;
}
void go() {
  int n, m;
  R(n, m);
  vector<int> a(n);
  R(a);
  auto solve = [&](int m) {
    vector<int> s(n << 1 | 1);
    int sum = n;
    long long ret = 0, add = 0;
    s[sum] = 1;
    for (auto& t : a) {
      if (t < m)
        --sum, add -= s[sum];
      else
        add += s[sum], sum++;
      ret += add;
      s[sum]++;
    }
    return ret;
  };
  W(solve(m) - solve(m + 1));
}
