For a set $S$ of integers, perform a sequence of the following operations. Note that multiple elements can have equivalent values in $S$.

* insert($x$): Insert $x$ to $S$ and report the number of elements in $S$ after the operation.
* find($x$): Report the number of $x$ in $S$.
* delete($x$): Delete all $x$ from $S$.
* dump($L$, $R$): Print elements $x$ in $S$ such that $L \leq x \leq R$.

Constraints

* $1 \leq q \leq 200,000$
* $0 \leq x \leq 1,000,000,000$
* The total number of elements printed by dump operations does not exceed $1,000,000$
* The sum of numbers printed by find operations does not exceed $2,000,000$

Input

The input is given in the following format.


$q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $x$


or


1 $x$


or


2 $x$


or


3 $L$ $R$


where the first digits 0, 1, 2 and 3 represent insert, find, delete and dump operations respectively.

Output

For each insert operation, print the number of elements in $S$.
For each find operation, print the number of specified elements in $S$.
For each dump operation, print the corresponding elements in ascending order. Print an element in a line.

Example

Input

10
0 1
0 1
0 2
0 3
2 2
1 1
1 2
1 3
0 4
3 1 4


Output

1
2
3
4
2
0
1
4
1
1
3
4
#include <iostream>
#include <vector>
#include <algorithm>
#include <string>
#include <sstream>
#include <functional>
#include <set>

#define INPUT_FROM_FILE (0) 
#if INPUT_FROM_FILE
#include <fstream>
#endif


int main(){
	int q, com;
	long x;
	long L, R;
	std::multiset<long> s;

#if INPUT_FROM_FILE
	std::ifstream ifs("test.txt");
#endif

#if INPUT_FROM_FILE
	ifs >> q;
#else
	std::cin >> q;
#endif
	
	for(int i = 0; i < q; i++){
#if INPUT_FROM_FILE
		ifs >> com >> x;
#else
		std::cin >> com >> x;
#endif
		if(com == 0){
			s.insert(x);
			std::cout << s.size() << std::endl;
		}
		else if(com == 1){
			std::cout << s.count(x) << std::endl;
		}
		else if(com == 2){
			s.erase(x);
		}
		else{
			L = x;
#if INPUT_FROM_FILE
			ifs >> R;
#else
			std::cin >> R;
#endif
			std::set<long>::iterator it = s.lower_bound(L);
			while(it != s.end() && *it <= R){
				std::cout <<  *it << std::endl;
				it++;
			}
		}
	}
	return 0;
}
