Let's call left cyclic shift of some string t_1 t_2 t_3 ... t_{n - 1} t_n as string t_2 t_3 ... t_{n - 1} t_n t_1.

Analogically, let's call right cyclic shift of string t as string t_n t_1 t_2 t_3 ... t_{n - 1}.

Let's say string t is good if its left cyclic shift is equal to its right cyclic shift.

You are given string s which consists of digits 0–9.

What is the minimum number of characters you need to erase from s to make it good?

Input

The first line contains single integer t (1 ≤ t ≤ 1000) — the number of test cases.

Next t lines contains test cases — one per line. The first and only line of each test case contains string s (2 ≤ |s| ≤ 2 ⋅ 10^5). Each character s_i is digit 0–9.

It's guaranteed that the total length of strings doesn't exceed 2 ⋅ 10^5.

Output

For each test case, print the minimum number of characters you need to erase from s to make it good.

Example

Input


3
95831
100120013
252525252525


Output


3
5
0

Note

In the first test case, you can erase any 3 characters, for example, the 1-st, the 3-rd, and the 4-th. You'll get string 51 and it is good.

In the second test case, we can erase all characters except 0: the remaining string is 0000 and it's good.

In the third test case, the given string s is already good.
from itertools import count
import sys
from array import array  # noqa: F401
import typing as Tp  # noqa: F401


def input():
    return sys.stdin.buffer.readline().decode('utf-8')


def output(*args):
    sys.stdout.buffer.write(
        ('\n'.join(map(str, args)) + '\n').encode('utf-8')
    )


def main():
    t = int(input())
    ans_a = [''] * t
    digits = '0123456789'

    for ti in range(t):
        s = input().rstrip()
        ans = 10**9

        for d1 in digits:
            for d2 in digits:
                x, y = d1, d2
                cnt = 0
                for c in s:
                    if c == x:
                        x, y = y, x
                    else:
                        cnt += 1
                ans = min(ans, cnt + (1 if d1 != d2 and d2 == x else 0))

        ans_a[ti] = str(ans)

    output(*ans_a)


if __name__ == '__main__':
    main()
