n soldiers stand in a circle. For each soldier his height ai is known. A reconnaissance unit can be made of such two neighbouring soldiers, whose heights difference is minimal, i.e. |ai - aj| is minimal. So each of them will be less noticeable with the other. Output any pair of soldiers that can form a reconnaissance unit.

Input

The first line contains integer n (2 ≤ n ≤ 100) — amount of soldiers. Then follow the heights of the soldiers in their order in the circle — n space-separated integers a1, a2, ..., an (1 ≤ ai ≤ 1000). The soldier heights are given in clockwise or counterclockwise direction.

Output

Output two integers — indexes of neighbouring soldiers, who should form a reconnaissance unit. If there are many optimum solutions, output any of them. Remember, that the soldiers stand in a circle.

Examples

Input

5
10 12 13 15 10


Output

5 1


Input

4
10 20 30 40


Output

1 2
#include <bits/stdc++.h>
using namespace std;
int main() {
  int n, arr[100000], min, min_index;
  cin >> n;
  for (int i = 0; i < n; i++) {
    cin >> arr[i];
  }
  min = abs(arr[0] - arr[n - 1]);
  min_index = 1;
  int min_index2 = n;
  for (int i = 0; i < n - 1; i++) {
    int result = abs(arr[i] - arr[i + 1]);
    if (min > result) {
      min = result;
      min_index = i + 1;
      min_index2 = i + 2;
    }
  }
  cout << min_index << "  " << min_index2 << endl;
}
