You are given an array a, consisting of n positive integers.

Let's call a concatenation of numbers x and y the number that is obtained by writing down numbers x and y one right after another without changing the order. For example, a concatenation of numbers 12 and 3456 is a number 123456.

Count the number of ordered pairs of positions (i, j) (i ≠ j) in array a such that the concatenation of a_i and a_j is divisible by k.

Input

The first line contains two integers n and k (1 ≤ n ≤ 2 ⋅ 10^5, 2 ≤ k ≤ 10^9).

The second line contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9).

Output

Print a single integer — the number of ordered pairs of positions (i, j) (i ≠ j) in array a such that the concatenation of a_i and a_j is divisible by k.

Examples

Input

6 11
45 1 10 12 11 7


Output

7


Input

4 2
2 78 4 10


Output

12


Input

5 2
3 7 19 3 3


Output

0

Note

In the first example pairs (1, 2), (1, 3), (2, 3), (3, 1), (3, 4), (4, 2), (4, 3) suffice. They produce numbers 451, 4510, 110, 1045, 1012, 121, 1210, respectively, each of them is divisible by 11.

In the second example all n(n - 1) pairs suffice.

In the third example no pair is sufficient.
#include <bits/stdc++.h>
#pragma GCC optimize(3)
#pragma GCC optimize("Ofast")
const int inf = 0x3f3f3f3f, Inf = 0x7fffffff;
const long long INF = 0x7ffffffffffffff;
const double eps = 1e-8;
unsigned int seed = 19260817;
__inline__ __attribute__((always_inline)) unsigned int Rand() {
  return seed = seed * 998244353u + 1000000007u;
}
template <typename _Tp>
_Tp gcd(const _Tp &a, const _Tp &b) {
  return (!b) ? a : gcd(b, a % b);
}
template <typename _Tp>
__inline__ __attribute__((always_inline)) _Tp abs(const _Tp &a) {
  return a > 0 ? a : -a;
}
template <typename _Tp>
__inline__ __attribute__((always_inline)) _Tp max(const _Tp &a, const _Tp &b) {
  return a < b ? b : a;
}
template <typename _Tp>
__inline__ __attribute__((always_inline)) _Tp min(const _Tp &a, const _Tp &b) {
  return a < b ? a : b;
}
template <typename _Tp>
__inline__ __attribute__((always_inline)) void chmax(_Tp &a, const _Tp &b) {
  (a < b) && (a = b);
}
template <typename _Tp>
__inline__ __attribute__((always_inline)) void chmin(_Tp &a, const _Tp &b) {
  (a > b) && (a = b);
}
template <typename _Tp>
__inline__ __attribute__((always_inline)) bool _cmp(const double &a,
                                                    const double &b) {
  return abs(a - b) <= eps;
}
template <typename _Tp>
__inline__ __attribute__((always_inline)) void read(_Tp &x) {
  register char ch(getchar());
  bool f(false);
  while (ch < 48 || ch > 57) f |= ch == 45, ch = getchar();
  x = ch & 15, ch = getchar();
  while (ch >= 48 && ch <= 57)
    x = (((x << 2) + x) << 1) + (ch & 15), ch = getchar();
  if (f) x = -x;
}
template <typename _Tp, typename... Args>
__inline__ __attribute__((always_inline)) void read(_Tp &t, Args &...args) {
  read(t);
  read(args...);
}
__inline__ __attribute__((always_inline)) int read_str(char *s) {
  register char ch(getchar());
  while (ch < 65 || ch > 122 || (ch > 90 && ch < 97)) ch = getchar();
  register char *tar = s;
  *tar = ch, ch = getchar();
  while ((ch >= 65 && ch <= 90) || (ch >= 97 && ch <= 122))
    *(++tar) = ch, ch = getchar();
  return tar - s + 1;
}
const int N = 200005;
struct custom_hash {
  __inline__ __attribute__((always_inline)) static uint64_t splitmix64(
      uint64_t x) {
    x += 0x9e3779b97f4a7c15;
    x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9;
    x = (x ^ (x >> 27)) * 0x94d049bb133111eb;
    return x ^ (x >> 31);
  }
  __inline__ __attribute__((always_inline)) size_t operator()(
      uint64_t x) const {
    static const uint64_t FIXED_RANDOM =
        std::chrono::steady_clock::now().time_since_epoch().count();
    return splitmix64(x + FIXED_RANDOM);
  }
};
int a[N];
std::unordered_map<long long, int, custom_hash> mp[11];
int len[N];
int main() {
  int n, k;
  read(n, k);
  for (int i = 1; i <= n; ++i) {
    read(a[i]);
    int x = a[i];
    while (x) {
      ++len[i];
      x /= 10;
    }
    a[i] %= k;
  }
  long long ans = 0;
  for (int i = 1; i <= n; ++i) {
    int tmp = 10;
    for (int _ = 1; _ <= 10; ++_) {
      long long t = (k - 1ll * a[i] * tmp % k) % k;
      if (mp[_].find(t) != mp[_].end()) ans += mp[_][t];
      tmp = tmp * 10 % k;
    }
    ++mp[len[i]][a[i]];
  }
  for (int i = 1; i <= 10; ++i) mp[i].clear();
  for (int i = n; i >= 1; --i) {
    int tmp = 10;
    for (int _ = 1; _ <= 10; ++_) {
      long long t = (k - 1ll * a[i] * tmp % k) % k;
      if (mp[_].find(t) != mp[_].end()) ans += mp[_][t];
      tmp = tmp * 10 % k;
    }
    ++mp[len[i]][a[i]];
  }
  printf("%lld\n", ans);
  return 0;
}
