A string s of length n can be encrypted by the following algorithm:

  * iterate over all divisors of n in decreasing order (i.e. from n to 1), 
  * for each divisor d, reverse the substring s[1 ... d] (i.e. the substring which starts at position 1 and ends at position d). 



For example, the above algorithm applied to the string s="codeforces" leads to the following changes: "codeforces" → "secrofedoc" → "orcesfedoc" → "rocesfedoc" → "rocesfedoc" (obviously, the last reverse operation doesn't change the string because d=1).

You are given the encrypted string t. Your task is to decrypt this string, i.e., to find a string s such that the above algorithm results in string t. It can be proven that this string s always exists and is unique.

Input

The first line of input consists of a single integer n (1 ≤ n ≤ 100) — the length of the string t. The second line of input consists of the string t. The length of t is n, and it consists only of lowercase Latin letters.

Output

Print a string s such that the above algorithm results in t.

Examples

Input

10
rocesfedoc


Output

codeforces


Input

16
plmaetwoxesisiht


Output

thisisexampletwo


Input

1
z


Output

z

Note

The first example is described in the problem statement.
#!/usr/bin/python3

from __future__ import print_function
from queue import Queue
import sys
import math
import os.path


def log(*args, **kwargs):
    print(*args, file=sys.stderr, **kwargs)


# INPUT
def ni():
    return map(int, input().split())


def nio(offset):
    return map(lambda x: int(x) + offset, input().split())


def nia():
    return list(map(int, input().split()))

# CONVERT


def toString(aList, sep=" "):
    return sep.join(str(x) for x in aList)


def toMapInvertIndex(aList):
    return {k: v for v, k in enumerate(aList)}


# MAIN

n, = ni()
s = input()

for i in range(1,n+1):
    if n % i == 0:
        s = s[0:i][::-1] + s[i:n]

print(s)