You are given an integer sequence a_1, a_2, ..., a_n.

Find the number of pairs of indices (l, r) (1 ≤ l ≤ r ≤ n) such that the value of median of a_l, a_{l+1}, ..., a_r is exactly the given number m.

The median of a sequence is the value of an element which is in the middle of the sequence after sorting it in non-decreasing order. If the length of the sequence is even, the left of two middle elements is used.

For example, if a=[4, 2, 7, 5] then its median is 4 since after sorting the sequence, it will look like [2, 4, 5, 7] and the left of two middle elements is equal to 4. The median of [7, 1, 2, 9, 6] equals 6 since after sorting, the value 6 will be in the middle of the sequence.

Write a program to find the number of pairs of indices (l, r) (1 ≤ l ≤ r ≤ n) such that the value of median of a_l, a_{l+1}, ..., a_r is exactly the given number m.

Input

The first line contains integers n and m (1 ≤ n,m ≤ 2⋅10^5) — the length of the given sequence and the required value of the median.

The second line contains an integer sequence a_1, a_2, ..., a_n (1 ≤ a_i ≤ 2⋅10^5).

Output

Print the required number.

Examples

Input

5 4
1 4 5 60 4


Output

8


Input

3 1
1 1 1


Output

6


Input

15 2
1 2 3 1 2 3 1 2 3 1 2 3 1 2 3


Output

97

Note

In the first example, the suitable pairs of indices are: (1, 3), (1, 4), (1, 5), (2, 2), (2, 3), (2, 5), (4, 5) and (5, 5).


n, m = map(int, input().split())
a = list(map(int, input().split()))


class BIT:
    def __init__(self, n):
        self.n = n
        self.data = [0]*(n+1)

    def to_sum(self, i):
        s = 0
        while i > 0:
            s += self.data[i]
            i -= (i & -i)
        return s

    def add(self, i, x):
        while i <= self.n:
            self.data[i] += x
            i += (i & -i)

    def get(self, i, j):
        #[i,j](1<=i<=j<=N)
        return self.to_sum(j) - self.to_sum(i - 1)


def f(x, V):
    if x < V:
        return -1
    return 1


def calc_median(M):
    b = [f(v, M) for v in a]
    res = 0
    c = [0]
    for x in b:
        c.append(c[-1] + x)
    d = [(c[i], i) for i in range(n + 1)]
    bit = BIT(2*n + 10)
    for value, index in d:
        if index == 0:
            bit.add(value + n + 1, 1)
            continue
        res += bit.get(1, value + n)
        bit.add(value + n + 1, 1)

    return res


print(calc_median(m) - calc_median(m + 1))

