Let's call left cyclic shift of some string t_1 t_2 t_3 ... t_{n - 1} t_n as string t_2 t_3 ... t_{n - 1} t_n t_1.

Analogically, let's call right cyclic shift of string t as string t_n t_1 t_2 t_3 ... t_{n - 1}.

Let's say string t is good if its left cyclic shift is equal to its right cyclic shift.

You are given string s which consists of digits 0–9.

What is the minimum number of characters you need to erase from s to make it good?

Input

The first line contains single integer t (1 ≤ t ≤ 1000) — the number of test cases.

Next t lines contains test cases — one per line. The first and only line of each test case contains string s (2 ≤ |s| ≤ 2 ⋅ 10^5). Each character s_i is digit 0–9.

It's guaranteed that the total length of strings doesn't exceed 2 ⋅ 10^5.

Output

For each test case, print the minimum number of characters you need to erase from s to make it good.

Example

Input


3
95831
100120013
252525252525


Output


3
5
0

Note

In the first test case, you can erase any 3 characters, for example, the 1-st, the 3-rd, and the 4-th. You'll get string 51 and it is good.

In the second test case, we can erase all characters except 0: the remaining string is 0000 and it's good.

In the third test case, the given string s is already good.
#https://codeforces.com/contest/1389/problem/C
import sys
reader = (s.rstrip() for s in sys.stdin)
input = reader.__next__
# do magic here

def calc(s,a,b):
    temp = 0
    for i in s:
        if i==a:
            a,b = b,a
            temp+=1
    if temp&1:
        temp-=1
    return temp

t = int(input())
for _ in range(t):
    s = [int(x) for x in input()]
    n = len(s)
    cnt = {}
    for x in range(10):
        cnt[x] = s.count(x)
    ans = n
    for x in range(10):
        for y in range(10):
            if x in cnt and y in cnt:
                if x==y:
                    ans = min(ans, n - cnt[x])
                else:
                    temp1 = calc(s,x,y)
                    temp2 = calc(s,y,x)
                    temp = min(n - temp1, n - temp2)
                    ans = min(ans,temp)
    print(ans)
