A string s of length n can be encrypted by the following algorithm:

  * iterate over all divisors of n in decreasing order (i.e. from n to 1), 
  * for each divisor d, reverse the substring s[1 ... d] (i.e. the substring which starts at position 1 and ends at position d). 



For example, the above algorithm applied to the string s="codeforces" leads to the following changes: "codeforces" → "secrofedoc" → "orcesfedoc" → "rocesfedoc" → "rocesfedoc" (obviously, the last reverse operation doesn't change the string because d=1).

You are given the encrypted string t. Your task is to decrypt this string, i.e., to find a string s such that the above algorithm results in string t. It can be proven that this string s always exists and is unique.

Input

The first line of input consists of a single integer n (1 ≤ n ≤ 100) — the length of the string t. The second line of input consists of the string t. The length of t is n, and it consists only of lowercase Latin letters.

Output

Print a string s such that the above algorithm results in t.

Examples

Input

10
rocesfedoc


Output

codeforces


Input

16
plmaetwoxesisiht


Output

thisisexampletwo


Input

1
z


Output

z

Note

The first example is described in the problem statement.
import java.io.*;
import java.util.*;
public class have
{
 public static void main(String args[])throws IOException
 {
  InputStreamReader read=new InputStreamReader(System.in);
  BufferedReader in=new BufferedReader(read);
  int i,j,n;
  String s,t;
  n=Integer.parseInt(in.readLine());
  s=in.readLine();
  for(i=2;i<=n;i++)
  {
   if(n%i==0)
   {
    t=s.substring(0,i);
    s=s.substring(i);
    for(j=0;j<i;j++)
    s=t.charAt(j)+s;
   }
  }
  System.out.print(s);
 }
}