IT City company developing computer games decided to upgrade its way to reward its employees. Now it looks the following way. After a new game release users start buying it actively, and the company tracks the number of sales with precision to each transaction. Every time when the next number of sales is not divisible by any number from 2 to 10 every developer of this game gets a small bonus.

A game designer Petya knows that the company is just about to release a new game that was partly developed by him. On the basis of his experience he predicts that n people will buy the game during the first month. Now Petya wants to determine how many times he will get the bonus. Help him to know it.

Input

The only line of the input contains one integer n (1 ≤ n ≤ 1018) — the prediction on the number of people who will buy the game.

Output

Output one integer showing how many numbers from 1 to n are not divisible by any number from 2 to 10.

Examples

Input

12


Output

2
import java.util.*;
import java.io.*;
public class a 
{
	public static void main(String[] arg) throws IOException
	{
		new a();
	}
	public a() throws IOException
	{
		FastScanner in = new FastScanner(System.in);
		PrintWriter out = new PrintWriter(System.out);
		long n = in.nextLong();
		long[] vs = {2, 3, 5, 7};
		int mask = 1<<4;
		mask--;
		long ret = 0;
		for(int i = mask; i > 0; i = ((i-1)&mask))
		{
			long val = 1;
			for(int j = 0; j < 9; j++)
			{
				if(((1<<j)&i) != 0)
				{
					val *= vs[j];
				}
			}
			if(Integer.bitCount(i)%2 == 0) ret -= n/val;
			else ret += n/val;
		}
		out.println(n-ret);
		in.close(); out.close();
	}
	long gcd(long a, long b)
	{
		return b == 0 ? a:gcd(b, a%b);
	}
	class FastScanner
	{
		BufferedReader br;
		StringTokenizer st;
		public FastScanner(InputStream in)
		{
			br = new BufferedReader(new InputStreamReader(in));
			st = new StringTokenizer("");
		}
		public String next() throws IOException
		{
			while(!st.hasMoreTokens()) st = new StringTokenizer(br.readLine());
			return st.nextToken();
		}
		public int nextInt() throws IOException
		{
			return Integer.parseInt(next());
		}
		public long nextLong() throws IOException
		{
			return Long.parseLong(next());
		}
		public void close() throws IOException
		{
			br.close();
		}
	}
}
