Let's call left cyclic shift of some string t_1 t_2 t_3 ... t_{n - 1} t_n as string t_2 t_3 ... t_{n - 1} t_n t_1.

Analogically, let's call right cyclic shift of string t as string t_n t_1 t_2 t_3 ... t_{n - 1}.

Let's say string t is good if its left cyclic shift is equal to its right cyclic shift.

You are given string s which consists of digits 0–9.

What is the minimum number of characters you need to erase from s to make it good?

Input

The first line contains single integer t (1 ≤ t ≤ 1000) — the number of test cases.

Next t lines contains test cases — one per line. The first and only line of each test case contains string s (2 ≤ |s| ≤ 2 ⋅ 10^5). Each character s_i is digit 0–9.

It's guaranteed that the total length of strings doesn't exceed 2 ⋅ 10^5.

Output

For each test case, print the minimum number of characters you need to erase from s to make it good.

Example

Input


3
95831
100120013
252525252525


Output


3
5
0

Note

In the first test case, you can erase any 3 characters, for example, the 1-st, the 3-rd, and the 4-th. You'll get string 51 and it is good.

In the second test case, we can erase all characters except 0: the remaining string is 0000 and it's good.

In the third test case, the given string s is already good.
import sys

T = int(sys.stdin.readline().strip())
for t in range (0, T):
    s = sys.stdin.readline().strip()
    l = len(s)
    S = [int(s[i]) for i in range (0, l)]
    ans = l
    for i in range (0, 10):
        for j in range (0, 10):
            if i == j:
                ans = min(ans, l - S.count(i))
            else:
                v = True
                c = 0
                for k in range (0, l):
                    if v == True and S[k] == i:
                        v = False
                    elif v == False and S[k] == j:
                        v = True
                        c = c + 1
                ans = min(ans, l - 2 * c)
    print(ans)