n soldiers stand in a circle. For each soldier his height ai is known. A reconnaissance unit can be made of such two neighbouring soldiers, whose heights difference is minimal, i.e. |ai - aj| is minimal. So each of them will be less noticeable with the other. Output any pair of soldiers that can form a reconnaissance unit.

Input

The first line contains integer n (2 ≤ n ≤ 100) — amount of soldiers. Then follow the heights of the soldiers in their order in the circle — n space-separated integers a1, a2, ..., an (1 ≤ ai ≤ 1000). The soldier heights are given in clockwise or counterclockwise direction.

Output

Output two integers — indexes of neighbouring soldiers, who should form a reconnaissance unit. If there are many optimum solutions, output any of them. Remember, that the soldiers stand in a circle.

Examples

Input

5
10 12 13 15 10


Output

5 1


Input

4
10 20 30 40


Output

1 2
import java.util.*;
import java.lang.*;
import java.io.*;

	public class FastIO{
			
		BufferedReader br;
		StringTokenizer st;
		
		public FastIO(){ // constructor
			
			br = new BufferedReader(new InputStreamReader(System.in));
		}
		
		String next(){
			
			while (st == null || !st.hasMoreElements()){
				try{
					st = new StringTokenizer(br.readLine());
				}
				
				catch (IOException e){
					e.printStackTrace();
				}
			}
			return st.nextToken();
		}
		
		int nextInt(){
			
			return Integer.parseInt(next());
		}
		
		long nextLong(){
			
			return Long.parseLong(next());
		}
		
		double nextDouble(){
			return Double.parseDouble(next());
		}

		String nextLine(){
			
			String str = "";
			try{
				
				str = br.readLine();
			}
			catch (IOException e){
				
				e.printStackTrace();
			}
			return str;
		}
		
		static int gcd(int a, int b) {
			
			if(b == 0) {
				return a;
			}
			
			return gcd(b, a % b);
		}
		
	public static void main(String[] args) throws IOException {
		
		FastIO io = new FastIO();
		
		// int n = io.nextInt(); -> for int
		// double d = io.nextDouble(); -> for double
		// String ch = io.next(); -> for one word
		// String str = io.nextLine(); -> for the entire line
		
		int n = io.nextInt();
		int ht[] = new int[n];
		for(int i = 0; i < n; i++) {
			ht[i] = io.nextInt();
		}
		
		int min = (int)1e9;
		int l = 0;
		int m = 0;
		
		for(int i = 0; i < n - 1; i++) {
			if(Math.abs(ht[i] - ht[i + 1]) < min){
				l = i + 1;
				m = i + 1 + 1;
				min = Math.abs(ht[i] - ht[i + 1]);
			}
		}
		if(Math.abs(ht[0] - ht[n - 1]) < min) {
			l = 1;
			m = n;  
		}
		System.out.println(l + " " + m);
	}
}