We have a pyramid with N steps, built with blocks. The steps are numbered 1 through N from top to bottom. For each 1≤i≤N, step i consists of 2i-1 blocks aligned horizontally. The pyramid is built so that the blocks at the centers of the steps are aligned vertically.

<image>

A pyramid with N=4 steps

Snuke wrote a permutation of (1, 2, ..., 2N-1) into the blocks of step N. Then, he wrote integers into all remaining blocks, under the following rule:

* The integer written into a block b must be equal to the median of the three integers written into the three blocks directly under b, or to the lower left or lower right of b.



<image>

Writing integers into the blocks

Afterwards, he erased all integers written into the blocks. Now, he only remembers that the integer written into the block of step 1 was x.

Construct a permutation of (1, 2, ..., 2N-1) that could have been written into the blocks of step N, or declare that Snuke's memory is incorrect and such a permutation does not exist.

Constraints

* 2≤N≤10^5
* 1≤x≤2N-1

Input

The input is given from Standard Input in the following format:


N x


Output

If no permutation of (1, 2, ..., 2N-1) could have been written into the blocks of step N, print `No`.

Otherwise, print `Yes` in the first line, then print 2N-1 lines in addition.

The i-th of these 2N-1 lines should contain the i-th element of a possible permutation.

Examples

Input

4 4


Output

Yes
1
6
3
7
4
5
2


Input

2 1


Output

No
#include<bits/stdc++.h>
using namespace std;
const int N=2e5+10;

int n,m,x,ans,v[N],tot,st;

int main(){
	int i,j;
	scanf("%d%d",&n,&x);m=(n<<1)-1;st=1;
	if(m==x || x==1){puts("No");return 0;}
	puts("Yes");v[1]=v[m]=v[x]=1;
	for(i=1;i+1<n;++i) {
	   for(;v[st];++st); printf("%d\n",st),v[st]=1;
	}
	printf("%d\n%d\n1\n",m,x);
	for(i=n+2;i<=m;++i){
		for(;v[st];++st); printf("%d\n",st),v[st]=1;
	}
	return 0;
}