In BerSoft n programmers work, the programmer i is characterized by a skill r_i.

A programmer a can be a mentor of a programmer b if and only if the skill of the programmer a is strictly greater than the skill of the programmer b (r_a > r_b) and programmers a and b are not in a quarrel.

You are given the skills of each programmers and a list of k pairs of the programmers, which are in a quarrel (pairs are unordered). For each programmer i, find the number of programmers, for which the programmer i can be a mentor.

Input

The first line contains two integers n and k (2 ≤ n ≤ 2 ⋅ 10^5, 0 ≤ k ≤ min(2 ⋅ 10^5, (n ⋅ (n - 1))/(2))) — total number of programmers and number of pairs of programmers which are in a quarrel.

The second line contains a sequence of integers r_1, r_2, ..., r_n (1 ≤ r_i ≤ 10^{9}), where r_i equals to the skill of the i-th programmer.

Each of the following k lines contains two distinct integers x, y (1 ≤ x, y ≤ n, x ≠ y) — pair of programmers in a quarrel. The pairs are unordered, it means that if x is in a quarrel with y then y is in a quarrel with x. Guaranteed, that for each pair (x, y) there are no other pairs (x, y) and (y, x) in the input.

Output

Print n integers, the i-th number should be equal to the number of programmers, for which the i-th programmer can be a mentor. Programmers are numbered in the same order that their skills are given in the input.

Examples

Input

4 2
10 4 10 15
1 2
4 3


Output

0 0 1 2 


Input

10 4
5 4 1 5 4 3 7 1 2 5
4 6
2 1
10 8
3 5


Output

5 4 0 5 3 3 9 0 2 5 

Note

In the first example, the first programmer can not be mentor of any other (because only the second programmer has a skill, lower than first programmer skill, but they are in a quarrel). The second programmer can not be mentor of any other programmer, because his skill is minimal among others. The third programmer can be a mentor of the second programmer. The fourth programmer can be a mentor of the first and of the second programmers. He can not be a mentor of the third programmer, because they are in a quarrel.
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.PrintWriter;

import java.lang.management.MemoryType;
import java.math.BigInteger;
import java.util.*;


public class Main {
    static final int INF = Integer.MAX_VALUE;
    private int i;


    static int mergeSort(int[] a,int [] c, int begin, int end)
    {
        int inversion=0;
        if(begin < end)
        {
            inversion=0;
            int mid = (begin + end) >>1;
            inversion+= mergeSort(a,c, begin, mid);
            inversion+=mergeSort(a, c,mid + 1, end);
            inversion+=merge(a,c, begin, mid, end);
        }
        return inversion;
    }

    static int  merge(int[] a,int[]c, int b, int mid, int e)
    {
        int n1 = mid - b + 1;
        int n2 = e - mid;
        int[] L = new int[n1+1], R = new int[n2+1];
        int[] L1 = new int[n1+1], R1 = new int[n2+1];
        //inversion
        int inversion=0;

        for(int i = 0; i < n1; i++) {
            L[i] = a[b + i];
            L1[i] = c[b + i];
        }
        for(int i = 0; i < n2; i++)  {
            R[i] = a[mid + 1 + i];
            R1[i] = c[mid + 1 + i];
        }
        L[n1] = R[n2] = INF;

        for(int k = b, i = 0, j = 0; k <= e; k++)
            if(L[i] <= R[j]){
                a[k] = L[i];
                c[k] = L1[i++];
            }

            else
            {
                a[k] = R[j];
                c[k] = R1[j++];
                inversion=inversion+(n1-i);

            }
        return inversion;

    }

    static int bs(ArrayList<Integer>list,int n){
        int s=0,e=list.size()-1,mid=0,ans=-1;
        while (s<=e){
            mid=(s+e)/2;
           if (list.get(mid)<n){
               ans=mid;
               e=mid-1;
           }else s=mid+1;
        }
        return ans;

    }
    static int bs2(ArrayList<Integer>list,int n){
        int s=0,e=list.size()-1,mid=0,ans=-1;
        while (s<=e){
            mid=(s+e)/2;
            if (list.get(mid)<n){
                ans=mid;
                s=mid+1;
            }else e=mid-1;
        }
        return ans;

    }

    public static void main (String[]args) throws IOException {
        Scanner in = new Scanner(System.in);
        try (PrintWriter or = new PrintWriter(System.out)) {

            int n = in.nextInt();
            int k = in.nextInt();
            ArrayList<prog> tab = new ArrayList<>(n);
            Map<Integer, Integer> map = new HashMap<>(n);
            for (int i = 0; i < n; i++) {
                prog p = new prog(in.nextInt(), i);
                tab.add(p);
                if (!map.containsKey(p.skill)) {
                    map.put(p.skill, 1);
                } else {
                    map.put(p.skill, map.get(p.skill) + 1);
                }
            }
            for (int i = 0; i < k; i++) {
                int x = in.nextInt() - 1;
                int y = in.nextInt() - 1;
                if (tab.get(x).skill > tab.get(y).skill) {
                    tab.get(x).pp++;
                } else if (tab.get(x).skill < tab.get(y).skill) {
                    tab.get(y).pp++;
                }
            }
            tab.sort((prog o1, prog o2) -> o2.skill - o1.skill);
            int[] res = new int[n];
            for (int i = 0; i < n; i++) {
                prog p = tab.get(i);
                res[p.indx] = (n - i - 1) - Math.max((map.get(p.skill) - 1), 0) - p.pp;
                map.put(p.skill, map.get(p.skill) - 1);
            }
            for (int re : res) {
                or.print(re + " ");
            }

        }

    }





    static class Scanner {

        StringTokenizer st;
        BufferedReader br;

        public Scanner(InputStream s) {
            br = new BufferedReader(new InputStreamReader(s));
        }

        public String next() throws IOException {
            while (st == null || !st.hasMoreTokens()) {
                st = new StringTokenizer(br.readLine());
            }
            return st.nextToken();
        }

        public int nextInt() throws IOException {
            return Integer.parseInt(next());
        }

        public long nextLong() throws IOException {
            return Long.parseLong(next());
        }

        public String nextLine() throws IOException {
            return br.readLine();
        }

        public double nextDouble() throws IOException {
            String x = next();
            StringBuilder sb = new StringBuilder("0");
            double res = 0, f = 1;
            boolean dec = false, neg = false;
            int start = 0;
            if (x.charAt(0) == '-') {
                neg = true;
                start++;
            }
            for (int i = start; i < x.length(); i++) {
                if (x.charAt(i) == '.') {
                    res = Long.parseLong(sb.toString());
                    sb = new StringBuilder("0");
                    dec = true;
                } else {
                    sb.append(x.charAt(i));
                    if (dec) {
                        f *= 10;
                    }
                }
            }
            res += Long.parseLong(sb.toString()) / f;
            return res * (neg ? -1 : 1);
        }

        public boolean ready() throws IOException {
            return br.ready();
        }

    }
}

 class prog {

    int skill;
    int indx;
    int pp;

    public prog(int skill, int indx) {
        this.skill = skill;
        this.indx = indx;
        pp = 0;
    }

    @Override
    public String toString() {
        return "prog{" + "skill=" + skill + ", indx=" + indx + ", pp=" + pp + '}';
    }

}