Jamie loves sleeping. One day, he decides that he needs to wake up at exactly hh: mm. However, he hates waking up, so he wants to make waking up less painful by setting the alarm at a lucky time. He will then press the snooze button every x minutes until hh: mm is reached, and only then he will wake up. He wants to know what is the smallest number of times he needs to press the snooze button.

A time is considered lucky if it contains a digit '7'. For example, 13: 07 and 17: 27 are lucky, while 00: 48 and 21: 34 are not lucky.

Note that it is not necessary that the time set for the alarm and the wake-up time are on the same day. It is guaranteed that there is a lucky time Jamie can set so that he can wake at hh: mm.

Formally, find the smallest possible non-negative integer y such that the time representation of the time x·y minutes before hh: mm contains the digit '7'.

Jamie uses 24-hours clock, so after 23: 59 comes 00: 00.

Input

The first line contains a single integer x (1 ≤ x ≤ 60).

The second line contains two two-digit integers, hh and mm (00 ≤ hh ≤ 23, 00 ≤ mm ≤ 59).

Output

Print the minimum number of times he needs to press the button.

Examples

Input

3
11 23


Output

2


Input

5
01 07


Output

0

Note

In the first sample, Jamie needs to wake up at 11:23. So, he can set his alarm at 11:17. He would press the snooze button when the alarm rings at 11:17 and at 11:20.

In the second sample, Jamie can set his alarm at exactly at 01:07 which is lucky.
import java.io.*;

public class CFR457A {
    static int n, h, m, ans = 0;
    static String ins[];
    public static void main(String[] args) throws IOException {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(System.out));
        n = Integer.parseInt(br.readLine());
        ins = br.readLine().split(" ");
        h = Integer.parseInt(ins[0]);
        m = Integer.parseInt(ins[1]);
        if (ins[0].charAt(0) != '7' && ins[0].charAt(1) != '7'
        && ins[1].charAt(0) != '7' && ins[1].charAt(1) != '7') {

            while (true) {
                m -= n;ans++;
                if (m < 0) {
                    m += 60;h--;
                }
                if (h < 0) h += 24;
                String sh = h + "", mh = m + "";
                boolean isSeven = false;
                for (int i = 0; i < sh.length(); i++) {
                    if (sh.charAt(i) == '7') isSeven = true;
                }
                for (int i = 0; i < mh.length(); i++) {
                    if (mh.charAt(i) == '7') isSeven = true;
                }
                if (isSeven) break;
            }

        }
        bw.write(ans + "\n");
        bw.flush();bw.close();
    }
}
