Jamie loves sleeping. One day, he decides that he needs to wake up at exactly hh: mm. However, he hates waking up, so he wants to make waking up less painful by setting the alarm at a lucky time. He will then press the snooze button every x minutes until hh: mm is reached, and only then he will wake up. He wants to know what is the smallest number of times he needs to press the snooze button.

A time is considered lucky if it contains a digit '7'. For example, 13: 07 and 17: 27 are lucky, while 00: 48 and 21: 34 are not lucky.

Note that it is not necessary that the time set for the alarm and the wake-up time are on the same day. It is guaranteed that there is a lucky time Jamie can set so that he can wake at hh: mm.

Formally, find the smallest possible non-negative integer y such that the time representation of the time x·y minutes before hh: mm contains the digit '7'.

Jamie uses 24-hours clock, so after 23: 59 comes 00: 00.

Input

The first line contains a single integer x (1 ≤ x ≤ 60).

The second line contains two two-digit integers, hh and mm (00 ≤ hh ≤ 23, 00 ≤ mm ≤ 59).

Output

Print the minimum number of times he needs to press the button.

Examples

Input

3
11 23


Output

2


Input

5
01 07


Output

0

Note

In the first sample, Jamie needs to wake up at 11:23. So, he can set his alarm at 11:17. He would press the snooze button when the alarm rings at 11:17 and at 11:20.

In the second sample, Jamie can set his alarm at exactly at 01:07 which is lucky.

ReadIntList = lambda: list(map(int, input().split()))
ReadStrList = lambda: list(map(str, input().split()))
ReadInt = lambda: int(input())
ReadMultipleValues = lambda: map(int, input().split())
ReadMultipleValuesStr = lambda: map(str, input().split())
month = {'Jan':"01", 'feb':"02",'Mar':"03",'Apr':"04",'May':"05",'Jun':"06", 'Jul':"07",'Aug':"08",
 'Sep':"09",'Oct':"10",'Nov':"11",'Dec':"12"}

# maximum=dict(sorted(maximum.items(), key=operator.itemgetter(1),reverse=True))
# >>>>>>>>>>>>  MAIN >>>>>>>>>>>>

x = ReadInt()
hh,mm =ReadMultipleValues()
output = 0
while hh%10 !=7 and mm%10 !=7:
    output +=1
    mm -=x 
    if mm <0:
        mm +=60
        hh -=1
    if hh<0:
        hh+=24
print(output)