You are given a sequence of n integers S and a sequence of different q integers T. Write a program which outputs C, the number of integers in T which are also in the set S.

Notes

Constraints

* Elements in S is sorted in ascending order
* n ≤ 100000
* q ≤ 50000
* 0 ≤ an element in S ≤ 109
* 0 ≤ an element in T ≤ 109

Input

In the first line n is given. In the second line, n integers are given. In the third line q is given. Then, in the fourth line, q integers are given.

Output

Print C in a line.

Examples

Input

5
1 2 3 4 5
3
3 4 1


Output

3


Input

3
1 2 3
1
5


Output

0


Input

5
1 1 2 2 3
2
1 2


Output

2
import java.util.Scanner;
class Main {
    public static void main(String[] args){
		Scanner scan = new Scanner(System.in);
		int n = scan.nextInt();
		int[] S = new int[n]; 
		
		for(int i = 0; i < n; i++){
			S[i] = scan.nextInt();
		}
		
		int q = scan.nextInt();
		int[] T = new int[q];
		
		for(int i = 0; i < q; i++){
			T[i] = scan.nextInt();
		}
		
		int result = 0;
		for(int i = 0; i < T.length; i++){
			result += BinarySearch(S, T[i]);
		}
		
		System.out.println(result);
	}

	static int BinarySearch(int data[], int serch){
		
		int min = 0;
		int max = data.length - 1;
		
		while(min <= max){
			
			int middle = (min + max) / 2;
			if(serch == data[middle]){
				return 1;
			}else if(serch < data[middle]){
				max = middle - 1;
			}else{
				min = middle + 1;
			}
		}
		return 0;
	}
}