Let's denote a k-step ladder as the following structure: exactly k + 2 wooden planks, of which

  * two planks of length at least k+1 — the base of the ladder; 
  * k planks of length at least 1 — the steps of the ladder; 



Note that neither the base planks, nor the steps planks are required to be equal.

For example, ladders 1 and 3 are correct 2-step ladders and ladder 2 is a correct 1-step ladder. On the first picture the lengths of planks are [3, 3] for the base and [1] for the step. On the second picture lengths are [3, 3] for the base and [2] for the step. On the third picture lengths are [3, 4] for the base and [2, 3] for the steps. 

<image>

You have n planks. The length of the i-th planks is a_i. You don't have a saw, so you can't cut the planks you have. Though you have a hammer and nails, so you can assemble the improvised "ladder" from the planks.

The question is: what is the maximum number k such that you can choose some subset of the given planks and assemble a k-step ladder using them?

Input

The first line contains a single integer T (1 ≤ T ≤ 100) — the number of queries. The queries are independent.

Each query consists of two lines. The first line contains a single integer n (2 ≤ n ≤ 10^5) — the number of planks you have.

The second line contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^5) — the lengths of the corresponding planks.

It's guaranteed that the total number of planks from all queries doesn't exceed 10^5.

Output

Print T integers — one per query. The i-th integer is the maximum number k, such that you can choose some subset of the planks given in the i-th query and assemble a k-step ladder using them.

Print 0 if you can't make even 1-step ladder from the given set of planks.

Example

Input


4
4
1 3 1 3
3
3 3 2
5
2 3 3 4 2
3
1 1 2


Output


2
1
2
0

Note

Examples for the queries 1-3 are shown at the image in the legend section.

The Russian meme to express the quality of the ladders:

<image>
import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.io.FilterInputStream;
import java.io.BufferedInputStream;
import java.io.InputStream;

/**
 * Built using CHelper plug-in
 * Actual solution is at the top
 *
 * @author Jenish
 */
public class Main {
    public static void main(String[] args) {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        ScanReader in = new ScanReader(inputStream);
        PrintWriter out = new PrintWriter(outputStream);
        ADIYWoodenLadder solver = new ADIYWoodenLadder();
        solver.solve(1, in, out);
        out.close();
    }

    static class ADIYWoodenLadder {
        public void solve(int testNumber, ScanReader in, PrintWriter out) {
            int t = in.scanInt();
            while (t-- > 0) {
                int n = in.scanInt();
                int arr[] = new int[n];
                in.scanInt(arr);
                CodeX.sort(arr);
                CodeX.reveseArray(arr);
                if (n <= 2) {
                    out.println(0);
                } else {
                    int ans = Math.min(arr[0], arr[1]);
                    out.println(Math.min(ans - 1, n - 2));

                }


            }
        }

    }

    static class ScanReader {
        private byte[] buf = new byte[4 * 1024];
        private int INDEX;
        private BufferedInputStream in;
        private int TOTAL;

        public ScanReader(InputStream inputStream) {
            in = new BufferedInputStream(inputStream);
        }

        private int scan() {
            if (INDEX >= TOTAL) {
                INDEX = 0;
                try {
                    TOTAL = in.read(buf);
                } catch (Exception e) {
                    e.printStackTrace();
                }
                if (TOTAL <= 0) return -1;
            }
            return buf[INDEX++];
        }

        public int scanInt() {
            int I = 0;
            int n = scan();
            while (isWhiteSpace(n)) n = scan();
            int neg = 1;
            if (n == '-') {
                neg = -1;
                n = scan();
            }
            while (!isWhiteSpace(n)) {
                if (n >= '0' && n <= '9') {
                    I *= 10;
                    I += n - '0';
                    n = scan();
                }
            }
            return neg * I;
        }

        private boolean isWhiteSpace(int n) {
            if (n == ' ' || n == '\n' || n == '\r' || n == '\t' || n == -1) return true;
            else return false;
        }

        public void scanInt(int[] A) {
            for (int i = 0; i < A.length; i++) A[i] = scanInt();
        }

    }

    static class CodeX {
        public static void reveseArray(int[] arr) {
            int n = arr.length;
            int temp[] = arr.clone();
            for (int i = 0; i < n; i++) arr[i] = temp[n - 1 - i];
        }

        public static void sort(int arr[]) {
            merge_sort(arr, 0, arr.length - 1);
        }

        private static void merge_sort(int A[], int start, int end) {
            if (start < end) {
                int mid = (start + end) / 2;
                merge_sort(A, start, mid);
                merge_sort(A, mid + 1, end);
                merge(A, start, mid, end);
            }

        }

        private static void merge(int A[], int start, int mid, int end) {
            int p = start, q = mid + 1;
            int Arr[] = new int[end - start + 1];
            int k = 0;

            for (int i = start; i <= end; i++) {
                if (p > mid)
                    Arr[k++] = A[q++];

                else if (q > end)
                    Arr[k++] = A[p++];

                else if (A[p] < A[q])
                    Arr[k++] = A[p++];

                else
                    Arr[k++] = A[q++];
            }
            for (int i = 0; i < k; i++) {
                A[start++] = Arr[i];
            }

        }

    }
}

