You are given the array a consisting of n positive (greater than zero) integers.

In one move, you can choose two indices i and j (i ≠ j) such that the absolute difference between a_i and a_j is no more than one (|a_i - a_j| ≤ 1) and remove the smallest of these two elements. If two elements are equal, you can remove any of them (but exactly one).

Your task is to find if it is possible to obtain the array consisting of only one element using several (possibly, zero) such moves or not.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 1000) — the number of test cases. Then t test cases follow.

The first line of the test case contains one integer n (1 ≤ n ≤ 50) — the length of a. The second line of the test case contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the i-th element of a.

Output

For each test case, print the answer: "YES" if it is possible to obtain the array consisting of only one element using several (possibly, zero) moves described in the problem statement, or "NO" otherwise.

Example

Input


5
3
1 2 2
4
5 5 5 5
3
1 2 4
4
1 3 4 4
1
100


Output


YES
YES
NO
NO
YES

Note

In the first test case of the example, we can perform the following sequence of moves:

  * choose i=1 and j=3 and remove a_i (so a becomes [2; 2]); 
  * choose i=1 and j=2 and remove a_j (so a becomes [2]). 



In the second test case of the example, we can choose any possible i and j any move and it doesn't matter which element we remove.

In the third test case of the example, there is no way to get rid of 2 and 4.
import java.io.*;
import java.util.*;
public class MyClass {
    
    public static void main(String args[]) {
      FastReader sc = new FastReader();     //For Fast IO
      //func f = new func();                  //Call func for swap , permute, upper bound and for sort.
      StringBuilder sb = new StringBuilder();
      int t = sc.nextInt();
      while(t-->0){
          int n = sc.nextInt();
          int c=0;
          long sum=0;
          for(int i=0;i<n;i++){
              long x = sc.nextInt();
              if(x%2==1){
                  c++;
              }
              sum += x;
          }
          if(sum%2==1){
              sb.append("YES\n");
          }
          else if(c==n && n%2==0){
              sb.append("NO\n");
          }
          else if(c>0){
              sb.append("YES\n");
          }
          else{
              sb.append("NO\n");
          }
      }
      System.out.println(sb);
      
      
    }
}
class FastReader 
	{ 
		BufferedReader br; 
		StringTokenizer st; 
 
		public FastReader() 
		{ 
			br = new BufferedReader(new
					InputStreamReader(System.in)); 
		} 
 
		String next() 
		{ 
			while (st == null || !st.hasMoreElements()) 
			{ 
				try
				{ 
					st = new StringTokenizer(br.readLine()); 
				} 
				catch (IOException e) 
				{ 
					e.printStackTrace(); 
				} 
			} 
			return st.nextToken(); 
		} 
 
		int nextInt() 
		{ 
			return Integer.parseInt(next()); 
		} 
 
		long nextLong() 
		{ 
			return Long.parseLong(next()); 
		} 
 
		double nextDouble() 
		{ 
			return Double.parseDouble(next()); 
		} 
 
		String nextLine() 
		{ 
			String str = ""; 
			try
			{ 
				str = br.readLine(); 
			} 
			catch (IOException e) 
			{ 
				e.printStackTrace(); 
			} 
			return str; 
		} 
	}
class func{
    static ArrayList<String> al = new ArrayList<>();
        public static void sort(long[] arr) {
            int n = arr.length, mid, h, s, l, i, j, k;
            long[] res = new long[n];
            for (s = 1; s < n; s <<= 1) {
                for (l = 0; l < n - 1; l += (s << 1)) {
                    h = Math.min(l + (s << 1) - 1, n - 1);
                    mid = Math.min(l + s - 1, n - 1);
                    i = l;
                    j = mid + 1;
                    k = l;
                    while (i <= mid && j <= h) res[k++] = (arr[i] <= arr[j] ? arr[i++] : arr[j++]);
                    while (i <= mid) res[k++] = arr[i++];
                    while (j <= h) res[k++] = arr[j++];
                    for (k = l; k <= h; k++) arr[k] = res[k];
                }
            }
        }
        public static void permute(char a[] , int i , int n){
            if(i==n-1){
                String s = new String(a);
                al.add(s);                      // al stores all permutations of string. 
                return;
            }
            for(int j=i;j<n;j++){
                swap(a,i,j);
                permute(a,i+1,n);
                swap(a,i,j);
            }
        }
        public static void swap(char a[],int i, int j){
            char temp = a[i];
            a[i] = a[j];
            a[j] = temp;
        }
        public static void swap(int a[],int i, int j){
            int temp = a[i];
            a[i] = a[j];
            a[j] = temp;
        }
		//-It returns index of first element which is strictly greater than searched value.
		public static int upperBound(long[] array, int length, long value) {
            int low = 0;
            int high = length;
            while (low < high) {
                final int mid = (low + high) / 2;
                if (value >= array[mid]) {
                    low = mid + 1;
                } else {
                    high = mid;
                }
        }
        return low;
    }
	/*If searched element doesn't exist function returns index of first element which is bigger than searched value.<br>
 * -If searched element is bigger than any array element function returns first index after last element.<br>
 * -If searched element is lower than any array element function returns index of first element.<br>
 * -If there are many values equals searched value function returns first occurrence.<br>*/
	public static int lowerBound(long[] array, int length, long value) {
        int low = 0;
        int high = length;
        while (low < high) {
            final int mid = (low + high) / 2;
            if (value <= array[mid]) {
                high = mid;
            } else {
                low = mid + 1;
            }
        }
        return low;
    }
        
 
}



	 	 
