K: Relief (Angel Relief)

Tenma, an angel, decides to save a city.

The city has a rectangular shape divided into north-south $ H $ parcels x east-west $ W $ parcels, with houses in each parcel.

The $ X $ th section from the north and the $ Y $ th section from the west are represented by $ (X, Y) $.

The house in parcel $ (i, j) $ is inhabited by $ A_ {i, j} $ people.

Tenshin chooses a rectangular area whose sides are parallel or vertical to north-south or east-west, and rescues all the people living in it one by one.

Tenshin does this for every possible rectangle.

Find the total number of times Tenma-san rescues people.

input

The integers $ H, W $ are given on the first line, separated by blanks.

Of the following $ H $ lines, the integers $ A_ {i, 1}, A_ {i, 2}, A_ {i, 3}, \ dots, A_ {i, W} $ are blank on the $ i $ line. Given as a delimiter.

output

Output the total number of times Tenma-san rescues people.

Constraint

* $ H, W $ are integers between $ 1 $ and $ 500 $
* $ A_ {i, j} $ are all integers greater than or equal to $ 1 $ and less than or equal to $ 9 $.



Input example 1


twenty two
1 2
4 8


Output example 1


60


For example, if you choose a rectangular area with $ (1, 1) $ in the upper left and $ (2, 2) $ in the lower right, you will rescue $ 15 $ people there one by one, so a total of $ 15 $ times. Relief.

$ 1, 2, 3, 4, 5, 8, 10, 12, 15 $ relief for each of the $ 9 $ rectangular areas, for a total of $ 60 $.

Input example 2


twenty three
one two Three
4 5 6


Output example 2


140






Example

Input

2 2
1 2
4 8


Output

60
#include <bits/stdc++.h>
using namespace std;
#define rep(i,n) for(int i=0;i<n;i++)
#define MOD 1000000007
typedef long long ll;
typedef pair<int,int> P;
#define int long long
int gcd(int a, int b) {
	if (b == 0)return a;
	return gcd(b, a%b);
}
int lcm(int a, int b) {
	return a / gcd(a, b)*b;
}
int modpow(int a,int b){
    if(!b)return 1;
    if(b%2)return modpow(a,b-1)*a%MOD;
    return modpow(a,b/2)*modpow(a,b/2)%MOD;
}
int fac(int a){
    int Ans=1;
    for(int i=1;i<=a;i++){
        Ans*=i;
        Ans%=MOD;
    }
    return Ans;
}//kaijo
int comb(int a,int b){
    return fac(a)*modpow(fac(a-b),MOD-2)%MOD*modpow(fac(b),MOD-2)%MOD;
}
signed main(){
	int h,w;
	int a[1000][1000];
	int x,y;
	cin>>h>>w;
	int ans=0;
	rep(i,h){
		rep(j,w){
			cin>>a[i][j];
			x=i+1,y=j+1;
			ans+=(h-x+1)*(w-y+1)*x*y*a[i][j];
		}
	}
	cout<<ans<<endl;
	return 0;
}


