K: Relief (Angel Relief)

Tenma, an angel, decides to save a city.

The city has a rectangular shape divided into north-south $ H $ parcels x east-west $ W $ parcels, with houses in each parcel.

The $ X $ th section from the north and the $ Y $ th section from the west are represented by $ (X, Y) $.

The house in parcel $ (i, j) $ is inhabited by $ A_ {i, j} $ people.

Tenshin chooses a rectangular area whose sides are parallel or vertical to north-south or east-west, and rescues all the people living in it one by one.

Tenshin does this for every possible rectangle.

Find the total number of times Tenma-san rescues people.

input

The integers $ H, W $ are given on the first line, separated by blanks.

Of the following $ H $ lines, the integers $ A_ {i, 1}, A_ {i, 2}, A_ {i, 3}, \ dots, A_ {i, W} $ are blank on the $ i $ line. Given as a delimiter.

output

Output the total number of times Tenma-san rescues people.

Constraint

* $ H, W $ are integers between $ 1 $ and $ 500 $
* $ A_ {i, j} $ are all integers greater than or equal to $ 1 $ and less than or equal to $ 9 $.



Input example 1


twenty two
1 2
4 8


Output example 1


60


For example, if you choose a rectangular area with $ (1, 1) $ in the upper left and $ (2, 2) $ in the lower right, you will rescue $ 15 $ people there one by one, so a total of $ 15 $ times. Relief.

$ 1, 2, 3, 4, 5, 8, 10, 12, 15 $ relief for each of the $ 9 $ rectangular areas, for a total of $ 60 $.

Input example 2


twenty three
one two Three
4 5 6


Output example 2


140






Example

Input

2 2
1 2
4 8


Output

60
#include <bits/stdc++.h>
using namespace std;

#define int				long long
#define FOR( i, m, n )  for( int (i) = (m); (i) < (n); (i)++ )
#define FORE( i, m, n ) FOR( i, m , n + 1 )
#define REP( i, n )     FOR( i, 0, n )
#define REPE( i, n )	FOR( i, 0, n + 1 )
#define REPA( i, n )	FOR( i, 1, n )
#define FORR( i, m, n ) for( int (i) = (m); (i) >= 0; (i)-- )
#define ALL( a )        (a).begin(), (a).end()             
#define MP( a, b )		make_pair( (a), (b) )
#define fi				first
#define se				second

const int INF = 1e9;
const int MOD = 1e9 + 7;

signed main() {
	int h, w; cin >> h >> w;

	
	int ans = 0;
	REP( i, h ) {
		REP( j, w ) {
			int t; cin >> t;

			int right = w - j;
			int left = j + 1;
			int up = i + 1;
			int down = h - i;

			ans += t * right* left * up * down;

		}
	}

	cout << ans << endl;
}
