While swimming at the beach, Mike has accidentally dropped his cellphone into the water. There was no worry as he bought a cheap replacement phone with an old-fashioned keyboard. The keyboard has only ten digital equal-sized keys, located in the following way:

<image>

Together with his old phone, he lost all his contacts and now he can only remember the way his fingers moved when he put some number in. One can formally consider finger movements as a sequence of vectors connecting centers of keys pressed consecutively to put in a number. For example, the finger movements for number "586" are the same as finger movements for number "253":

<image> <image>

Mike has already put in a number by his "finger memory" and started calling it, so he is now worrying, can he be sure that he is calling the correct number? In other words, is there any other number, that has the same finger movements?

Input

The first line of the input contains the only integer n (1 ≤ n ≤ 9) — the number of digits in the phone number that Mike put in.

The second line contains the string consisting of n digits (characters from '0' to '9') representing the number that Mike put in.

Output

If there is no other phone number with the same finger movements and Mike can be sure he is calling the correct number, print "YES" (without quotes) in the only line.

Otherwise print "NO" (without quotes) in the first line.

Examples

Input

3
586


Output

NO


Input

2
09


Output

NO


Input

9
123456789


Output

YES


Input

3
911


Output

YES

Note

You can find the picture clarifying the first sample case in the statement above.
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.*;

public class Codeforces {

    private static final Scanner sc = new Scanner(System.in);
    private static final BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

    public static long GCD(long a,long b){
        if (b == 0)
            return a;
        return GCD(b,a%b);
    }

    static int highestPowerOf2(int n) {
        int p = (int)(Math.log(n) /
                Math.log(2));
        return (int)Math.pow(2, p);
    }

    public static int binSearch(long[] a,long x){
        int l = 0;
        int r = a.length - 1;
        while (l <= r){
            int mid = l + (r-l)/2;
            if (a[mid]==x)
                return 1;
            else if (a[mid] < x)
                l = mid+1;
            else
                r = mid-1;
        }
        return -1;
    }

    public static int upperBound(long[] arr,long key){
        int start=0;int end=arr.length-1;
        int idx=-1;
        int mid;
        while(start<=end){
            int i=(start+end)/2;
            if(arr[i]<key){
                start=i+1;
            }
            else if(arr[i]>key){
                end=i-1;
            }
            else{
                idx=i;
                start=i+1;
            }
        }

        return idx;    }

    public static int lowerBound(long[] arr,long key){
        int start=0;int end=arr.length-1;
        int idx=-1;
        int mid;
        while(start<=end){
            int i=(start+end)/2;
            if(arr[i]<key){
                start=i+1;
            }
            else if(arr[i]>key){
                end=i-1;
            }
            else{
                idx=i;
                end=i-1;
            }
        }
        return idx;
    }

    public static int searchInsert(long[] nums, long target) {
        int s=0,e=nums.length-1;
        int mid;
        if(target<nums[0]){
            return 0;
        }
        while(s<=e){
            mid=(s+e)/2;
            if(nums[mid]>target){
                e=mid-1;
            }
            else if(nums[mid]==target){
                return mid;
            }
            else{
                s=mid+1;
            }
        }
        return s;
    }

    public static class Pair<T1,T2>{
        T1 first;
        T2 second;
        Pair(T1 a,T2 b){
            this.first = a;
            this.second = b;
        }

        @Override
        public String toString() {
            return "[" + first + ", " + second + "]";
        }
    }

    static boolean isPrime(long n) {
        if (n <= 1)
            return false;
        if (n <= 3)
            return true;

        if (n % 2 == 0 || n % 3 == 0)
            return false;

        for (long i = 5; i <= Math.sqrt(n); i = i + 6)
            if (n % i == 0 || n % (i + 2) == 0)
                return false;

        return true;
    }

    public static long fastExpo(long a,int n,int mod){
        if (n == 0)
            return 1;
        else{
            if ((n&1) == 1){
                long x = fastExpo(a,n/2,mod);
                return (((a*x)%mod)*x)%mod;
            }
            else{
                long x = fastExpo(a,n/2,mod);
                return (((x%mod)*(x%mod))%mod)%mod;
            }
        }
    }

    public static long modInverse(long n,int p){
        return fastExpo(n,p-2,p);
    }

    public static long nCr(int n,int r,long[] fact,int mod){
        long val =  (((fact[n] * modInverse(fact[r],mod))%mod)*modInverse(fact[n-r],mod))%mod;
        return val;
    }

    public static void factorial(long[] fact,int n,int mod){
        for (int i=1;i<=n;i++){
            fact[i] = (fact[i-1] * i)%mod;
        }
    }

    public static int log2(long val){
        return (int) Math.floor(Math.log(val)/Math.log(2));
    }

    public static boolean isSubSequence(String s,String t){
        int i = 0;
        int j = 0;
        while (i < s.length() && j < t.length()){
            if (s.charAt(i) == t.charAt(j))
                j++;
            i++;
        }
        return j == t.length();
    }

    public static void solve() throws IOException {
        int n = sc.nextInt();
        String num = sc.next();
        int up,down,left,right;
        up = down = left = right = 0;
        for (int i = 0; i < n; i++) {
            int s = num.charAt(n-1-i) - '0';
            if (s == 1 || s == 4 || s == 7 || s == 0) left = 1;
            if (s == 1 || s == 2 || s == 3) up = 1;
            if (s == 3 || s == 6 || s == 9 || s == 0) right = 1;
            if (s == 9 || s == 7 || s == 0) down = 1;
        }
        if (up == 1 && down == 1 && left == 1 && right == 1)
            System.out.println("YES");
        else
            System.out.println("NO");
    }
    public static void main(String[] args) throws IOException{
        int t;
        //t = sc.nextInt();
        t = 1;
        while (t-- > 0){
            solve();
        }
        System.gc();
    }
}


	    		  	  	 	 	    					  		