Jamie loves sleeping. One day, he decides that he needs to wake up at exactly hh: mm. However, he hates waking up, so he wants to make waking up less painful by setting the alarm at a lucky time. He will then press the snooze button every x minutes until hh: mm is reached, and only then he will wake up. He wants to know what is the smallest number of times he needs to press the snooze button.

A time is considered lucky if it contains a digit '7'. For example, 13: 07 and 17: 27 are lucky, while 00: 48 and 21: 34 are not lucky.

Note that it is not necessary that the time set for the alarm and the wake-up time are on the same day. It is guaranteed that there is a lucky time Jamie can set so that he can wake at hh: mm.

Formally, find the smallest possible non-negative integer y such that the time representation of the time x·y minutes before hh: mm contains the digit '7'.

Jamie uses 24-hours clock, so after 23: 59 comes 00: 00.

Input

The first line contains a single integer x (1 ≤ x ≤ 60).

The second line contains two two-digit integers, hh and mm (00 ≤ hh ≤ 23, 00 ≤ mm ≤ 59).

Output

Print the minimum number of times he needs to press the button.

Examples

Input

3
11 23


Output

2


Input

5
01 07


Output

0

Note

In the first sample, Jamie needs to wake up at 11:23. So, he can set his alarm at 11:17. He would press the snooze button when the alarm rings at 11:17 and at 11:20.

In the second sample, Jamie can set his alarm at exactly at 01:07 which is lucky.
import java.util.*;
import java.lang.*;
import java.io.*;
public class Ideone
{
	public static void main (String[] args) throws java.lang.Exception
	{
		Scanner sc=new Scanner(System.in);
		int a=sc.nextInt();
		int b=sc.nextInt();
		int c=sc.nextInt();
		int b2=b%10;
		int a2=c%10;
		int b1=b/10;
		int k=0;
		int a1=c/10;
		if(a1==7||a2==7||b1==7|b2==7)
		System.out.println(0);
		while(!(a1==7||a2==7||b1==7|b2==7))
		{
			
				k++;
				c-=a;
				if(c<0)
				{
				c+=60;
				b-=1;
				if(b<0)
				b+=24;
				}
				 b2=b%10;
		 a2=c%10;
		 b1=b/10;
		
		 a1=c/10;
				
				if(a1==7||a2==7||b1==7|b2==7)
	                        	System.out.println(k);
			
		}
	}
}