Let's call an array a consisting of n positive (greater than 0) integers beautiful if the following condition is held for every i from 1 to n: either a_i = 1, or at least one of the numbers a_i - 1 and a_i - 2 exists in the array as well.

For example: 

  * the array [5, 3, 1] is beautiful: for a_1, the number a_1 - 2 = 3 exists in the array; for a_2, the number a_2 - 2 = 1 exists in the array; for a_3, the condition a_3 = 1 holds; 
  * the array [1, 2, 2, 2, 2] is beautiful: for a_1, the condition a_1 = 1 holds; for every other number a_i, the number a_i - 1 = 1 exists in the array; 
  * the array [1, 4] is not beautiful: for a_2, neither a_2 - 2 = 2 nor a_2 - 1 = 3 exists in the array, and a_2 ≠ 1; 
  * the array [2] is not beautiful: for a_1, neither a_1 - 1 = 1 nor a_1 - 2 = 0 exists in the array, and a_1 ≠ 1; 
  * the array [2, 1, 3] is beautiful: for a_1, the number a_1 - 1 = 1 exists in the array; for a_2, the condition a_2 = 1 holds; for a_3, the number a_3 - 2 = 1 exists in the array. 



You are given a positive integer s. Find the minimum possible size of a beautiful array with the sum of elements equal to s.

Input

The first line contains one integer t (1 ≤ t ≤ 5000) — the number of test cases.

Then t lines follow, the i-th line contains one integer s (1 ≤ s ≤ 5000) for the i-th test case.

Output

Print t integers, the i-th integer should be the answer for the i-th testcase: the minimum possible size of a beautiful array with the sum of elements equal to s.

Example

Input


4
1
8
7
42


Output


1
3
3
7

Note

Consider the example test:

  1. in the first test case, the array [1] meets all conditions; 
  2. in the second test case, the array [3, 4, 1] meets all conditions; 
  3. in the third test case, the array [1, 2, 4] meets all conditions; 
  4. in the fourth test case, the array [1, 4, 6, 8, 10, 2, 11] meets all conditions. 
import java.io.BufferedReader;
import java.util.StringTokenizer;
import java.io.InputStreamReader;
import java.io.IOException;
import java.io.PrintWriter;
import java.util.*;
public class A {


    static int[] seen;
    public static void main(String[] args) {
        FastReader fr = new FastReader();
        PrintWriter out = new PrintWriter(System.out, true);
        int cases = fr.nextInt();
        seen = new int[5001];
        buildAll();
        for(int c = 0; c < cases; c++) {
            int cur = fr.nextInt();
            out.write(seen[cur] + "\n");
        }
       
        out.close();
    }

    
    static void buildAll() {
        ArrayList<Integer> start = new ArrayList<Integer>();
        int sum = 1;
        start.add(1);
        while(sum <= 5000) {
            seen[sum] = start.size();
            // for(int x: start) {
            //     System.out.print(x + " ");
            // }
            // System.out.println("");
            if(start.size() == 1) {
                start.add(1);
               
            } else {
                int a = start.get(start.size()-1);
                int b = start.get(start.size()-2);
                // /System.out.println(a + " " + b);
                if(b+2 == a) {
                    start.add(1);
                
                } else{
                    start.set(start.size()-1, a+1);
                }
            }
            sum++;
        }
    } 

        
    

    static class FastReader {

        BufferedReader br;
        StringTokenizer st;

        public FastReader() {
            this.br = new BufferedReader(new InputStreamReader(System.in));
        }

        String next() { 
            while (st == null || !st.hasMoreElements()) {
                try{
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }

        int nextInt() { return Integer.parseInt(next()); }

        long nextLong() { return Long.parseLong(next()); }

        double nextDouble() { return Double.parseDouble(next()); }

        String nextLine() {
            String str = "";
            try {
                str = br.readLine();
            } catch (IOException e) {
                e.printStackTrace();
            }
            return str;
        }
    }
}
