You are given a permutation p=[p_1, p_2, …, p_n] of integers from 1 to n. Let's call the number m (1 ≤ m ≤ n) beautiful, if there exists two indices l, r (1 ≤ l ≤ r ≤ n), such that the numbers [p_l, p_{l+1}, …, p_r] is a permutation of numbers 1, 2, …, m.

For example, let p = [4, 5, 1, 3, 2, 6]. In this case, the numbers 1, 3, 5, 6 are beautiful and 2, 4 are not. It is because:

  * if l = 3 and r = 3 we will have a permutation [1] for m = 1; 
  * if l = 3 and r = 5 we will have a permutation [1, 3, 2] for m = 3; 
  * if l = 1 and r = 5 we will have a permutation [4, 5, 1, 3, 2] for m = 5; 
  * if l = 1 and r = 6 we will have a permutation [4, 5, 1, 3, 2, 6] for m = 6; 
  * it is impossible to take some l and r, such that [p_l, p_{l+1}, …, p_r] is a permutation of numbers 1, 2, …, m for m = 2 and for m = 4. 



You are given a permutation p=[p_1, p_2, …, p_n]. For all m (1 ≤ m ≤ n) determine if it is a beautiful number or not.

Input

The first line contains the only integer t (1 ≤ t ≤ 1000) — the number of test cases in the input. The next lines contain the description of test cases.

The first line of a test case contains a number n (1 ≤ n ≤ 2 ⋅ 10^5) — the length of the given permutation p. The next line contains n integers p_1, p_2, …, p_n (1 ≤ p_i ≤ n, all p_i are different) — the given permutation p.

It is guaranteed, that the sum of n from all test cases in the input doesn't exceed 2 ⋅ 10^5.

Output

Print t lines — the answers to test cases in the order they are given in the input. 

The answer to a test case is the string of length n, there the i-th character is equal to 1 if i is a beautiful number and is equal to 0 if i is not a beautiful number.

Example

Input


3
6
4 5 1 3 2 6
5
5 3 1 2 4
4
1 4 3 2


Output


101011
11111
1001

Note

The first test case is described in the problem statement.

In the second test case all numbers from 1 to 5 are beautiful:

  * if l = 3 and r = 3 we will have a permutation [1] for m = 1; 
  * if l = 3 and r = 4 we will have a permutation [1, 2] for m = 2; 
  * if l = 2 and r = 4 we will have a permutation [3, 1, 2] for m = 3; 
  * if l = 2 and r = 5 we will have a permutation [3, 1, 2, 4] for m = 4; 
  * if l = 1 and r = 5 we will have a permutation [5, 3, 1, 2, 4] for m = 5. 
import java.io.*;
import java.util.*;
public final class code
// class code
// public class Solution
{
	static void solve()throws IOException
	{
		int n=nextInt();
		int a[]=new int[n+1];
		for(int i=1;i<=n;i++)
			a[nextInt()]=i;
		int min=inf,max=0;
		for(int i=1;i<=n;i++)
		{
			min=Math.min(min,a[i]);
			max=Math.max(max,a[i]);
			int size=max-min+1;
			if(size==i)
				out.print(1);
			else
				out.print(0);
		}
		out.println();
	}

	///////////////////////////////////////////////////////////
	static final long mod=(long)(1e9+7);
	static final int inf=(int)(1e9+1);
	// static final long inf=(long)(1e18);
	static class Pair implements Comparable<Pair>
	{
		int first,second;
		Pair(int a,int b)
		{
			first=a;
			second=b;
		}
		public int compareTo(Pair p)
		{
			if(this.second==p.second)
				return this.first-p.first;
			return this.second-p.second;
		}
		public boolean equals(Object p)
		{
			Pair p1=(Pair)p;
			return (first==p1.first && second==p1.second);
		}
		public String toString()
		{
			return this.first+" "+this.second;
		}
		public int hashCode()
		{
			return (int)((1l*(inf+1)*this.first+this.second)%mod);
		}
	}
	public static void main(String args[])throws IOException
	{
		br=new BufferedReader(new InputStreamReader(System.in));
		out=new PrintWriter(new BufferedOutputStream(System.out));
		random=new Random();
		// solve();
 
		int t=nextInt();
		for(int i=1;i<=t;i++)
		{
			// out.print("Case #"+i+": ");
			solve();
		}
 
		out.close();
	}
	static void debug(Object ... a)
	{
		System.out.print("> ");
		for(int i=0;i<a.length;i++)
			System.out.print(a[i]+" ");
		System.out.println();
	}
	static void debug(int a[]){debuga(Arrays.stream(a).boxed().toArray());}
	static void debug(long a[]){debuga(Arrays.stream(a).boxed().toArray());}
	static void debuga(Object a[])
	{
		System.out.print("> ");
		for(int i=0;i<a.length;i++)
			System.out.print(a[i]+" ");
		System.out.println();
	}
 
	
	static Random random;
	static BufferedReader br;
	static StringTokenizer st;
	static PrintWriter out;
	static String nextToken()throws IOException
	{
		while(st==null || !st.hasMoreTokens())
			st=new StringTokenizer(br.readLine());
		return st.nextToken();
	}
	static String nextLine()throws IOException
	{
		return br.readLine();
	}
	static int nextInt()throws IOException
	{
		return Integer.parseInt(nextToken());
	}
	static long nextLong()throws IOException
	{
		return Long.parseLong(nextToken());
	}
	static double nextDouble()throws IOException
	{
		return Double.parseDouble(nextToken());
	}
	
}