Jamie loves sleeping. One day, he decides that he needs to wake up at exactly hh: mm. However, he hates waking up, so he wants to make waking up less painful by setting the alarm at a lucky time. He will then press the snooze button every x minutes until hh: mm is reached, and only then he will wake up. He wants to know what is the smallest number of times he needs to press the snooze button.

A time is considered lucky if it contains a digit '7'. For example, 13: 07 and 17: 27 are lucky, while 00: 48 and 21: 34 are not lucky.

Note that it is not necessary that the time set for the alarm and the wake-up time are on the same day. It is guaranteed that there is a lucky time Jamie can set so that he can wake at hh: mm.

Formally, find the smallest possible non-negative integer y such that the time representation of the time x·y minutes before hh: mm contains the digit '7'.

Jamie uses 24-hours clock, so after 23: 59 comes 00: 00.

Input

The first line contains a single integer x (1 ≤ x ≤ 60).

The second line contains two two-digit integers, hh and mm (00 ≤ hh ≤ 23, 00 ≤ mm ≤ 59).

Output

Print the minimum number of times he needs to press the button.

Examples

Input

3
11 23


Output

2


Input

5
01 07


Output

0

Note

In the first sample, Jamie needs to wake up at 11:23. So, he can set his alarm at 11:17. He would press the snooze button when the alarm rings at 11:17 and at 11:20.

In the second sample, Jamie can set his alarm at exactly at 01:07 which is lucky.
n = int(input())
a = map(str,raw_input().split(' '))

a[0] = int(a[0])
a[1] = int(a[1])

a1 = a[0]//10
a2 = a[0]%10
b1 = a[1]//10
b2 = a[1]%10

if(a1 == 7 or a2 == 7 or b1 == 7 or b2 == 7 ):
    print "0"
else:
    count = 0
    while(not(a1 == 7 or a2 == 7 or b1 == 7 or b2 == 7)):
        a[1]-=n
        count+=1
        #print(count)
        if(a[1]<0):
            a[1]+=60
            a[0]-=1
            if(a[0]<0):
                a[0]+=24
        a1 = a[0]//10
        a2 = a[0]%10
        b1 = a[1]//10
        b2 = a[1]%10
        continue
    #print(count,str(a[0])+str(a[1]))
    print(count)
