You are given an array a of length 2n. Consider a partition of array a into two subsequences p and q of length n each (each element of array a should be in exactly one subsequence: either in p or in q).

Let's sort p in non-decreasing order, and q in non-increasing order, we can denote the sorted versions by x and y, respectively. Then the cost of a partition is defined as f(p, q) = ∑_{i = 1}^n |x_i - y_i|.

Find the sum of f(p, q) over all correct partitions of array a. Since the answer might be too big, print its remainder modulo 998244353.

Input

The first line contains a single integer n (1 ≤ n ≤ 150 000).

The second line contains 2n integers a_1, a_2, …, a_{2n} (1 ≤ a_i ≤ 10^9) — elements of array a.

Output

Print one integer — the answer to the problem, modulo 998244353.

Examples

Input


1
1 4


Output


6

Input


2
2 1 2 1


Output


12

Input


3
2 2 2 2 2 2


Output


0

Input


5
13 8 35 94 9284 34 54 69 123 846


Output


2588544

Note

Two partitions of an array are considered different if the sets of indices of elements included in the subsequence p are different.

In the first example, there are two correct partitions of the array a:

  1. p = [1], q = [4], then x = [1], y = [4], f(p, q) = |1 - 4| = 3; 
  2. p = [4], q = [1], then x = [4], y = [1], f(p, q) = |4 - 1| = 3. 



In the second example, there are six valid partitions of the array a: 

  1. p = [2, 1], q = [2, 1] (elements with indices 1 and 2 in the original array are selected in the subsequence p); 
  2. p = [2, 2], q = [1, 1]; 
  3. p = [2, 1], q = [1, 2] (elements with indices 1 and 4 are selected in the subsequence p); 
  4. p = [1, 2], q = [2, 1]; 
  5. p = [1, 1], q = [2, 2]; 
  6. p = [2, 1], q = [2, 1] (elements with indices 3 and 4 are selected in the subsequence p). 
import java.io.*;
import java.util.*;
public class Main {
    public static void main(String args[])
    {
        FastReader input=new FastReader();
        PrintWriter out=new PrintWriter(System.out);
        int T=1;
        while(T-->0)
        {
            int n=input.nextInt();
            int a[]=new int[2*n];
            long sum2=0;
            long fac[]=new long[2*n+1];
            fac[0]=1;
            long m=998244353;
            for(int i=1;i<=2*n;i++)
            {
                a[i-1]=input.nextInt();
                sum2+=a[i-1];
                fac[i]=(i*fac[i-1])%m;
            }
            mergeSort(a,0,2*n-1);
            long sum1=0;
            for(int i=0;i<n;i++)
            {
                sum1+=a[i];
            }
            sum2-=sum1;
            long dif=sum2-sum1;
            dif%=m;
            long comb=comb(fac,2*n,n,m);
            long ans=(dif*comb)%m;
            out.println(ans);
        }
        out.close();
    }
    public static long comb(long fac[],int nu,int b,long m)
    {
        long x=fac[nu];
        long y=(fac[b]%m*fac[nu-b]%m)%m;
        long v=power(y,m-2,m);
        long z=(x%m*v%m)%m;
        return z;
    }
    public static long power(long a,long b,long m)
    {
        long res=1;
        while(b>0)
        {
            if(b%2!=0)
            {
                res=(res%m*a%m)%m;
            }
            b=b/2;
            a=(a%m*a%m)%m;
        }
        return res;
    }
    public static void mergeSort(int a[],int p,int r)
    {
        if(p<r)
        {
            int q=(p+r)/2;
            mergeSort(a,p,q);
            mergeSort(a,q+1,r);
            merge(a,p,q,r);
        }
    }
    public static void merge(int a[],int p,int q,int r)
    {
        int n1=q-p+2;
        int L[]=new int[n1];
        int n2=r-q+1;
        int R[]=new int[n2];
        for(int i=p;i<=q;i++)
        {
            L[i-p]=a[i];
        }
        L[n1-1]=Integer.MAX_VALUE;
        for(int i=q+1;i<=r;i++)
        {
            R[i-q-1]=a[i];
        }
        R[n2-1]=Integer.MAX_VALUE;
        int x=0,y=0;
        for(int i=p;i<=r;i++)
        {
            if(L[x]<=R[y])
            {
                a[i]=L[x];
                x++;
            }
            else
            {
                a[i]=R[y];
                y++;
            }
        }
    }
    static class FastReader
    {
        BufferedReader br;
        StringTokenizer st;
        public FastReader()
        {
            br = new BufferedReader(new InputStreamReader(System.in));
        }
        String next()
        {
            while (st == null || !st.hasMoreElements())
            {
                try
                {
                    st = new StringTokenizer(br.readLine());
                }
                catch (IOException e)
                {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }
        int nextInt()
        {
            return Integer.parseInt(next());
        }
        long nextLong()
        {
            return Long.parseLong(next());
        }
        double nextDouble()
        {
            return Double.parseDouble(next());
        }
        String nextLine()
        {
            String str="";
            try
            {
                str=br.readLine();
            }
            catch (IOException e)
            {
                e.printStackTrace();
            }
            return str;
        }
    }
}