You are given an array a consisting of n integers.

You can remove at most one element from this array. Thus, the final length of the array is n-1 or n.

Your task is to calculate the maximum possible length of the strictly increasing contiguous subarray of the remaining array.

Recall that the contiguous subarray a with indices from l to r is a[l ... r] = a_l, a_{l + 1}, ..., a_r. The subarray a[l ... r] is called strictly increasing if a_l < a_{l+1} < ... < a_r.

Input

The first line of the input contains one integer n (2 ≤ n ≤ 2 ⋅ 10^5) — the number of elements in a.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is the i-th element of a.

Output

Print one integer — the maximum possible length of the strictly increasing contiguous subarray of the array a after removing at most one element.

Examples

Input


5
1 2 5 3 4


Output


4


Input


2
1 2


Output


2


Input


7
6 5 4 3 2 4 3


Output


2

Note

In the first example, you can delete a_3=5. Then the resulting array will be equal to [1, 2, 3, 4] and the length of its largest increasing subarray will be equal to 4.
import java.io.*;
import java.util.*;

public class Template {

	static int mod = 1000000007;

	public static void main(String[] args) {
		FastScanner sc = new FastScanner();
		PrintWriter out = new PrintWriter(System.out);
		int yo = 1;
		while (yo-- > 0) {
			int n = sc.nextInt();
			int[] a = sc.readArray(n);
			
			int max = 0;
			int[] prefix = new int[n];
			prefix[0] = 1;
			for(int i = 1; i < n; i++) {
				if(a[i] > a[i-1]) {
					prefix[i] = prefix[i-1] + 1;
				}
				else {
					prefix[i] = 1;
				}
				max = Math.max(max, prefix[i]);
			}
			
			int[] suffix = new int[n];
			suffix[n-1] = 1;
			for(int i = n-2; i >= 0; i--) {
				if(a[i] < a[i+1]) {
					suffix[i] = suffix[i+1] + 1;
				}
				else {
					suffix[i] = 1;
				}
			} 
			
			for(int i = 0; i < n; i++) {
				if(i == 0) {
					max = Math.max(max, i+1 < n ? suffix[i+1] : 0);
				}
				else if(i == n-1) {
					max = Math.max(max, i-1 >= 0 ? prefix[i-1] : 0);
				}
				else {
					int sum = 0;
					if(a[i-1] < a[i+1]) {
						sum = prefix[i-1] + suffix[i+1];
					}
					max = Math.max(max, sum);
				}
			}
			
			out.println(max);
		}
		out.close();
	}

	static class Pair {
		int x;
		int y;

		public Pair(int x, int y) {
			this.x = x;
			this.y = y;
		}
	}

	static void ruffleSort(int[] a) {
		int n = a.length;
		Random r = new Random();
		for (int i = 0; i < a.length; i++) {
			int oi = r.nextInt(n), temp = a[i];
			a[i] = a[oi];
			a[oi] = temp;
		}
		Arrays.sort(a);
	}

	static long gcd(long a, long b) {
		if (b == 0)
			return a;
		return gcd(b, a % b);
	}

	static boolean[] sieve(int N) {
		boolean[] sieve = new boolean[N + 1];
		for (int i = 2; i <= N; i++)
			sieve[i] = true;

		for (int i = 2; i <= N; i++) {
			if (sieve[i]) {
				for (int j = 2 * i; j <= N; j += i) {
					sieve[j] = false;
				}
			}
		}
		return sieve;
	}

	static long pow(int a, long b) {
		if (b == 0) {
			return 1;
		}
		if (b == 1) {
			return a;
		}
		if (b % 2 == 0) {
			long ans = pow(a, b / 2);
			return ans * ans;
		} else {
			long ans = pow(a, (b - 1) / 2);
			return a * ans * ans;
		}

	}

	static class FastScanner {
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
		StringTokenizer st = new StringTokenizer("");

		String next() {
			while (!st.hasMoreTokens())
				try {
					st = new StringTokenizer(br.readLine());
				} catch (IOException e) {
					e.printStackTrace();
				}
			return st.nextToken();
		}

		int nextInt() {
			return Integer.parseInt(next());
		}

		int[] readArray(int n) {
			int[] a = new int[n];
			for (int i = 0; i < n; i++)
				a[i] = nextInt();
			return a;
		}

		long nextLong() {
			return Long.parseLong(next());
		}
	}

	//	For Input.txt and Output.txt	
	//	FileInputStream in = new FileInputStream("input.txt");
	//	FileOutputStream out = new FileOutputStream("output.txt");
	//	PrintWriter pw = new PrintWriter(out);
	//	Scanner sc = new Scanner(in);
}
