Suppose that you are in a campus and have to go for classes day by day. As you may see, when you hurry to a classroom, you surprisingly find that many seats there are already occupied. Today you and your friends went for class, and found out that some of the seats were occupied.

The classroom contains n rows of seats and there are m seats in each row. Then the classroom can be represented as an n × m matrix. The character '.' represents an empty seat, while '*' means that the seat is occupied. You need to find k consecutive empty seats in the same row or column and arrange those seats for you and your friends. Your task is to find the number of ways to arrange the seats. Two ways are considered different if sets of places that students occupy differs.

Input

The first line contains three positive integers n,m,k (1 ≤ n, m, k ≤ 2 000), where n,m represent the sizes of the classroom and k is the number of consecutive seats you need to find.

Each of the next n lines contains m characters '.' or '*'. They form a matrix representing the classroom, '.' denotes an empty seat, and '*' denotes an occupied seat.

Output

A single number, denoting the number of ways to find k empty seats in the same row or column.

Examples

Input

2 3 2
**.
...


Output

3


Input

1 2 2
..


Output

1


Input

3 3 4
.*.
*.*
.*.


Output

0

Note

In the first sample, there are three ways to arrange those seats. You can take the following seats for your arrangement. 

  * (1,3), (2,3) 
  * (2,2), (2,3) 
  * (2,1), (2,2) 
#Fast IO Region
import os
import sys
from io import BytesIO,IOBase
BUFSIZE = 8192
class FastIO(IOBase):
    newlines = 0
    def __init__(self, file):
        self._fd = file.fileno()
        self.buffer = BytesIO()
        self.writable = "x" in file.mode or "r" not in file.mode
        self.write = self.buffer.write if self.writable else None
    def read(self):
        while True:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            if not b:
                break
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines = 0
        return self.buffer.read()
    def readline(self):
        while self.newlines == 0:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            self.newlines = b.count(b"\n") + (not b)
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines -= 1
        return self.buffer.readline()
    def flush(self):
        if self.writable:
            os.write(self._fd, self.buffer.getvalue())
            self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
    def __init__(self, file):
        self.buffer = FastIO(file)
        self.flush = self.buffer.flush
        self.writable = self.buffer.writable
        self.write = lambda s: self.buffer.write(s.encode("ascii"))
        self.read = lambda: self.buffer.read().decode("ascii")
        self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")

# Get out of main functoin
def main():
    pass
# decimal to binary
def binary(n):
    return (bin(n).replace("0b", ""))
# binary to decimal
def decimal(s):
    return (int(s, 2))
# power of a number base 2
def pow2(n):
    p = 0
    while n > 1:
        n //= 2
        p += 1
    return (p)
# if  number is prime in √n time
def isPrime(n):
    if (n == 1):
        return (False)
    else:
        root = int(n ** 0.5)
        root += 1
        for i in range(2, root):
            if (n % i == 0):
                return (False)
        return (True)
# list to string ,no spaces
def lts(l):
    s = ''.join(map(str, l))
    return s
# String to list
def stl(s):
    # for each character in string to list with no spaces -->
    l = list(s)
    # for space in string  -->
    # l=list(s.split(" "))
    return l
# Returns list of numbers with a particular sum
def sq(a, target, arr=[]):
    s = sum(arr)
    if (s == target):
        return arr
    if (s >= target):
        return
    for i in range(len(a)):
        n = a[i]
        remaining = a[i + 1:]
        ans = sq(remaining, target, arr + [n])
        if (ans):
            return ans
# Sieve for prime numbers in a range
def SieveOfEratosthenes(n):
    cnt = 0
    prime = [True for i in range(n + 1)]
    p = 2
    while (p * p <= n):
        if (prime[p] == True):
            for i in range(p * p, n + 1, p):
                prime[i] = False
        p += 1
    for p in range(2, n + 1):
        if prime[p]:
            cnt += 1
            # print(p)
    return (cnt)
# for positive integerse only
def nCr(n, r):
    f = math.factorial
    return f(n) // f(r) // f(n - r)
# 1000000007
mod = int(1e9) + 7
def ssinp(): return input()
# s=input()
def iinp(): return int(input())
# n=int(input())
def nninp(): return map(int,input().split())
#a,b,c=map(int,input().split())
def llinp(): return list(map(int,input().split()))
# a=list(map(int,input().split()))
def p(xyz): print(xyz)
def p2(a,b): print(a,b)
import math
#import random
#sys.setrecursionlimit(300000)
#from fractions import Fraction
#from collections import OrderedDict
#from collections import deque
########################                         mat=[[0 for i in range(n)] for j in range(m)]                      ########################
########################                         list.sort(key=lambda x:x[1]) for sorting a list according to second element in sublist            ########################
########################                         Speed: STRING < LIST < SET,DICTIONARY                      ########################
########################                         from collections import deque                              ########################
########################                         ASCII of A-Z= 65-90                                        ########################
########################                         ASCII of a-z= 97-122                                       ########################
########################                         d1.setdefault(key, []).append(value)                       ########################
#for __ in range(iinp()):
n,m,k=nninp()
mat=[]
ans=0
for i in range(n):
    a=stl(ssinp())
    mat.append(a)
if(k==1):
    for i in range(n):
        for j in range(m):
            if(mat[i][j]=="."):
                ans+=1
    p(ans)
else:
    for i in range(n):
        tot=0
        for j in range(m):
            if(mat[i][j]=="."):
                tot+=1
            elif(mat[i][j]=="*"):
                if(tot>=k):
                    ans=ans+(tot-k+1)
                tot=0
        if(tot >= k):
            ans = ans + (tot - k + 1)
            tot = 0
    for i in range(m):
        tot=0
        for j in range(n):
            if(mat[j][i]=="."):
                tot+=1
            elif(mat[j][i]=="*"):
                if(tot>=k):
                    ans=ans+(tot-k+1)
                tot=0
        if (tot >= k):
            ans = ans + (tot - k + 1)
            tot = 0
    p(ans)






""" Stuff you should look for
    1.int overflow, array bounds
    2.special cases (n=1?)
    3. do something instead of nothing and stay organized
    4. WRITE STUFF DOWN (MAIN)
	5. DON'T GET STUCK ON ONE APPROACH"""








