You are wandering in the explorer space of the 2050 Conference.

The explorer space can be viewed as an undirected weighted grid graph with size n× m. The set of vertices is \{(i, j)|1≤ i≤ n, 1≤ j≤ m\}. Two vertices (i_1,j_1) and (i_2, j_2) are connected by an edge if and only if |i_1-i_2|+|j_1-j_2|=1.

At each step, you can walk to any vertex connected by an edge with your current vertex. On each edge, there are some number of exhibits. Since you already know all the exhibits, whenever you go through an edge containing x exhibits, your boredness increases by x.

For each starting vertex (i, j), please answer the following question: What is the minimum possible boredness if you walk from (i, j) and go back to it after exactly k steps?

You can use any edge for multiple times but the boredness on those edges are also counted for multiple times. At each step, you cannot stay on your current vertex. You also cannot change direction while going through an edge. Before going back to your starting vertex (i, j) after k steps, you can visit (i, j) (or not) freely.

Input

The first line contains three integers n, m and k (2≤ n, m≤ 500, 1≤ k≤ 20).

The j-th number (1≤ j ≤ m - 1) in the i-th line of the following n lines is the number of exibits on the edge between vertex (i, j) and vertex (i, j+1). 

The j-th number (1≤ j≤ m) in the i-th line of the following n-1 lines is the number of exibits on the edge between vertex (i, j) and vertex (i+1, j). 

The number of exhibits on each edge is an integer between 1 and 10^6.

Output

Output n lines with m numbers each. The j-th number in the i-th line, answer_{ij}, should be the minimum possible boredness if you walk from (i, j) and go back to it after exactly k steps.

If you cannot go back to vertex (i, j) after exactly k steps, answer_{ij} should be -1. 

Examples

Input


3 3 10
1 1
1 1
1 1
1 1 1
1 1 1


Output


10 10 10
10 10 10
10 10 10


Input


2 2 4
1
3
4 2


Output


4 4
10 6


Input


2 2 3
1
2
3 4


Output


-1 -1
-1 -1

Note

In the first example, the answer is always 10 no matter how you walk.

In the second example, answer_{21} = 10, the path is (2,1) → (1,1) → (1,2) → (2,2) → (2,1), the boredness is 4 + 1 + 2 + 3 = 10.
import java.util.*;
import java.io.*;
import java.math.*;

public class Main

{ 
	 static FastReader sc=new FastReader(); 
	 static long dp[][][];
	 static int mod=1000000007;
	 
	  public static void main(String[] args)  throws IOException
{
		    //CHECK FOR N=1
       	//CHECK FOR N=1
	    //CHECK FOR N=1			
       	//CHECK FOR N=1
		  
		  
		  
		   PrintWriter out=new PrintWriter(System.out);
		  // StringBuffer sb=new StringBuffer("");
		  int ttt=1;
		//  ttt =i(); 	
		   
	        outer :while (ttt-- > 0) 
			{

	        	int n=i();
	        	int m=i();
	        	int k=i();
	        	int A[][]=input(n,m-1);
	        	int B[][]=input(n-1, m);
	        	dp=new long[n+1][m+1][k+1];
	        	for(int ii=0;ii<n;ii++) {
	        		for(int jj=0;jj<m;jj++) {
	        			Arrays.fill(dp[ii][jj],-1);
	        		}
	        	}
	        	if(k%2!=0) {
	        		for(int i=0;i<n;i++) {
	        			for(int j=0;j<m;j++) {
	        				System.out.print("-1 ");
	        			}
	        			System.out.println();
	        		}
	        	}
	        	else {
	        	go(A, B, 0, 0, k/2, n, m);
	        	for(int i=0;i<n;i++) {
        			for(int j=0;j<m;j++) {
        				System.out.print(dp[i][j][k/2]*2+" ");
        			}
        			System.out.println();
        		}
	        	}
	        	
			}
		     out.close();
    	//System.out.println(sb.toString());
	     
	     
	    //CHECK FOR N=1                    //CHECK FOR M=0
        //CHECK FOR N=1                    //CHECK FOR M=0
       	//CHECK FOR N=1
       	//CHECK FOR N=1
       	//CHECK FOR N=1
		        	
    }
	  static long go(int A[][],int B[][],int i,int j,int k,int l,int p) {
		 if(k==0)
			 return 0;
		 if(i>=l || j>=p)
			 return Integer.MAX_VALUE;
		  if(dp[i][j][k]!=-1)
			  return dp[i][j][k];
//		  if(i==m && j==n && k<org) {
//			  return Integer.MAX_VALUE;
//		  }
		  long op1=Long.MAX_VALUE;
		  if(i+1<l)
		  op1=Math.min(op1,go(A, B, i+1, j, k-1,l,p)+B[i][j]);
		  if(i-1>=0)
		 op1=Math.min(op1,go(A, B, i-1, j, k-1,l,p)+B[i-1][j]);
		  if(j+1<p)
		  op1=Math.min(op1,go(A, B, i, j+1, k-1,l,p)+A[i][j]);
		  if(j-1>=0)
		   op1=Math.min(op1,go(A, B, i, j-1, k-1,l,p)+A[i][j-1]);
		  go(A, B, i+1, j, k, l, p);
		  go(A, B, i, j+1, k, l, p);
		  return dp[i][j][k]=op1;
	  }
		  
		  
		  
		


static int[] input(int n) {
	int A[]=new int[n];
	   for(int i=0;i<n;i++) {
		   A[i]=sc.nextInt();
	   }
	   return A;
   }
static long[] inputL(int n) {
	long A[]=new long[n];
	   for(int i=0;i<n;i++) {
		   A[i]=sc.nextLong();
	   }
	   return A;
   }
static String[] inputS(int n) {
	String A[]=new String[n];
	   for(int i=0;i<n;i++) {
		   A[i]=sc.next();
	   }
	   return A;
   }
static long sum(int A[]) {
	long sum=0;
	for(int i : A) {
		sum+=i;
	}
	return sum;
}
static long sum(long A[]) {
	long sum=0;
	for(long i : A) {
		sum+=i;
	}
	return sum;
}
static void reverse(long A[]) {
	int n=A.length;
	long B[]=new long[n];
	for(int i=0;i<n;i++) {
		B[i]=A[n-i-1];
	}
	for(int i=0;i<n;i++)
		A[i]=B[i];
	
}
static void reverse(int A[]) {
	int n=A.length;
	int B[]=new int[n];
	for(int i=0;i<n;i++) {
		B[i]=A[n-i-1];
	}
	for(int i=0;i<n;i++)
		A[i]=B[i];
	
}
static void input(int A[],int B[]) {
	   for(int i=0;i<A.length;i++) {
		   A[i]=sc.nextInt();
		   B[i]=sc.nextInt();
	   }
}
static int[][] input(int n,int m){
	int A[][]=new int[n][m];
	for(int i=0;i<n;i++) {
		for(int j=0;j<m;j++) {
			A[i][j]=i();
		}
	}
	return A;
}
static char[][] charinput(int n,int m){
	char A[][]=new char[n][m];
	for(int i=0;i<n;i++) {
		String s=s();
		for(int j=0;j<m;j++) {
			A[i][j]=s.charAt(j);
		}
	}
	return A;
}
static int max(int A[]) {
	int max=Integer.MIN_VALUE;
	for(int i=0;i<A.length;i++) {
		max=Math.max(max, A[i]);
	}
	return max;
}
static int min(int A[]) {
	int min=Integer.MAX_VALUE;
	for(int i=0;i<A.length;i++) {
		min=Math.min(min, A[i]);
	}
	return min;
}
static long max(long A[]) {
	long max=Long.MIN_VALUE;
	for(int i=0;i<A.length;i++) {
		max=Math.max(max, A[i]);
	}
	return max;
}
static long min(long A[]) {
	long min=Long.MAX_VALUE;
	for(int i=0;i<A.length;i++) {
		min=Math.min(min, A[i]);
	}
	return min;
}
static long [] prefix(long A[]) {
	long p[]=new long[A.length];
	p[0]=A[0];
	for(int i=1;i<A.length;i++)
		p[i]=p[i-1]+A[i];
	return p;
}
static long [] prefix(int A[]) {
	long p[]=new long[A.length];
	p[0]=A[0];
	for(int i=1;i<A.length;i++)
		p[i]=p[i-1]+A[i];
	return p;
}
static long [] suffix(long A[]) {
	long p[]=new long[A.length];
	p[A.length-1]=A[A.length-1];
	for(int i=A.length-2;i>=0;i--)
		p[i]=p[i+1]+A[i];
	return p;
}
static long [] suffix(int A[]) {
	long p[]=new long[A.length];
	p[A.length-1]=A[A.length-1];
	for(int i=A.length-2;i>=0;i--)
		p[i]=p[i+1]+A[i];
	return p;
}
static void print(int A[]) {
	for(int i : A) {
		System.out.print(i+" ");
	}
	System.out.println();
}
static void print(long A[]) {
	for(long i : A) {
		System.out.print(i+" ");
	}
	System.out.println();
}
static long mod(long x) {
	 int mod=1000000007;
	  return ((x%mod + mod)%mod);
}
static String reverse(String s) {
	StringBuffer p=new StringBuffer(s);
	p.reverse();
	return p.toString();
}

     static int i() {
    	 return sc.nextInt();
     }
     static String s() {
    	 return sc.next();
     }
     static long l() {
    	 return sc.nextLong();
     }  
     static void sort(int[] A){
        int n = A.length;
        Random rnd = new Random();
        for(int i=0; i<n; ++i){
            int tmp = A[i];
            int randomPos = i + rnd.nextInt(n-i);
            A[i] = A[randomPos];
            A[randomPos] = tmp;
        }
        Arrays.sort(A);
     }
     static void sort(long[] A){
	        int n = A.length;
	        Random rnd = new Random();
	        for(int i=0; i<n; ++i){
	            long tmp = A[i];
	            int randomPos = i + rnd.nextInt(n-i);
	            A[i] = A[randomPos];
	            A[randomPos] = tmp;
	        }
	        Arrays.sort(A);
	     }
  static String sort(String s) {
 	 Character ch[]=new Character[s.length()];
 	 for(int i=0;i<s.length();i++) {
 		 ch[i]=s.charAt(i);
 	 }
 	 Arrays.sort(ch);
 	 StringBuffer st=new StringBuffer("");
 	 for(int i=0;i<s.length();i++) {
 		 st.append(ch[i]);
 	 }
 	 return st.toString();
  }
  static HashMap<Integer,Integer> hash(int A[]){
	  HashMap<Integer,Integer> map=new HashMap<Integer, Integer>();
	  for(int i : A) {
		  if(map.containsKey(i)) {
			  map.put(i, map.get(i)+1);
		  }
		  else {
			  map.put(i, 1);
		  }
	  }
	  return map;
  }
  static TreeMap<Integer,Integer> tree(int A[]){
	  TreeMap<Integer,Integer> map=new TreeMap<Integer, Integer>();
	  for(int i : A) {
		  if(map.containsKey(i)) {
			  map.put(i, map.get(i)+1);
		  }
		  else {
			  map.put(i, 1);
		  }
	  }
	  return map;
  }
     static boolean prime(int n) 
	    { 
	        if (n <= 1) 
	            return false; 
	        if (n <= 3) 
	            return true; 
	        if (n % 2 == 0 || n % 3 == 0) 
	            return false; 
	        double sq=Math.sqrt(n);
	  
	        for (int i = 5; i <= sq; i = i + 6) 
	            if (n % i == 0 || n % (i + 2) == 0) 
	                return false; 
	        return true; 
	    } 
     static boolean prime(long n) 
	    { 
	        if (n <= 1) 
	            return false; 
	        if (n <= 3) 
	            return true; 
	        if (n % 2 == 0 || n % 3 == 0) 
	            return false; 
	        double sq=Math.sqrt(n);
	  
	        for (int i = 5; i <= sq; i = i + 6) 
	            if (n % i == 0 || n % (i + 2) == 0) 
	                return false; 
	        return true; 
	    } 
     static int gcd(int a, int b) 
     { 
         if (a == 0) 
             return b; 
         return gcd(b % a, a); 
     } 
     static long gcd(long a, long b) 
     { 
         if (a == 0) 
             return b; 
         return gcd(b % a, a); 
     } 
     static class Pair implements Comparable<Pair>
     {
    	 int x;
    	 int y;
    	 int z;
    	 Pair(int x,int y,int z){
    		 this.x=x;
    		 this.y=y;
    		 this.z=z;
    	 }
		@Override
//		public int compareTo(Pair o) {
//			if(this.x>o.x)
//				return 1;
//			else if(this.x<o.x)
//				return -1;
//			else {
//				if(this.y>o.y)
//					return 1;
//				else if(this.y<o.y)
//					return -1;
//				else
//					return 0;
//			}
//		}
		
		
		public int compareTo(Pair o) {
			int p=this.x-this.y;
			int q=o.x-o.y;
		if(p>q)
			return 1;
		else if(p<q)
			return -1;
			
				return 0;
		
	}
     }
        
    static class FastReader 
    { 
        BufferedReader br; 
        StringTokenizer st; 
  
        public FastReader() 
        { 
            br = new BufferedReader(new
                     InputStreamReader(System.in)); 
        } 
  
        String next() 
        { 
            while (st == null || !st.hasMoreElements()) 
            { 
                try
                { 
                    st = new StringTokenizer(br.readLine()); 
                } 
                catch (IOException  e) 
                { 
                    e.printStackTrace(); 
                } 
            } 
            return st.nextToken(); 
        } 
  
        int nextInt() 
        { 
            return Integer.parseInt(next()); 
        } 
  
        long nextLong() 
        { 
            return Long.parseLong(next()); 
        } 
  
        double nextDouble() 
        { 
            return Double.parseDouble(next()); 
        } 
  
        String nextLine() 
        { 
            String str = ""; 
            try
            { 
                str = br.readLine(); 
            } 
            catch (IOException e) 
            { 
                e.printStackTrace(); 
            } 
            return str; 
        } 
    } 
} 



