Write a program of a Merge Sort algorithm implemented by the following pseudocode. You should also report the number of comparisons in the Merge function.


Merge(A, left, mid, right)
n1 = mid - left;
n2 = right - mid;
create array L[0...n1], R[0...n2]
for i = 0 to n1-1
do L[i] = A[left + i]
for i = 0 to n2-1
do R[i] = A[mid + i]
L[n1] = SENTINEL
R[n2] = SENTINEL
i = 0;
j = 0;
for k = left to right-1
if L[i] <= R[j]
then A[k] = L[i]
i = i + 1
else A[k] = R[j]
j = j + 1

Merge-Sort(A, left, right){
if left+1 < right
then mid = (left + right)/2;
call Merge-Sort(A, left, mid)
call Merge-Sort(A, mid, right)
call Merge(A, left, mid, right)


Notes

Constraints

* n ≤ 500000
* 0 ≤ an element in S ≤ 109

Input

In the first line n is given. In the second line, n integers are given.

Output

In the first line, print the sequence S. Two consequtive elements should be separated by a space character.

In the second line, print the number of comparisons.

Example

Input

10
8 5 9 2 6 3 7 1 10 4


Output

1 2 3 4 5 6 7 8 9 10
34
# coding: utf-8
from itertools import count

def merge(A, left, mid, right):
  global counter
  n1, n2 = mid - left, right - mid
  L, R = list(A[left:left+n1]+[float("inf")]), list(A[mid:mid+n2]+[float("inf")])
  i = j = 0
  for k in range(left, right):
    if L[i] <= R[j]:
      A[k] = L[i]
      i = i + 1
    else:
      A[k] = R[j]
      j = j + 1
  counter += right - left
def mergeSort(A, left, right):
  if left+1 < right:
    mid = (left + right)//2;
    mergeSort(A, left, mid)
    mergeSort(A, mid, right)
    merge(A, left, mid, right)

N = int(input())
A = [int(i) for i in input().split()]
counter = 0
mergeSort(A, 0, len(A))
print(*A)
print(counter)