You are given an array a consisting of n integers.

You can remove at most one element from this array. Thus, the final length of the array is n-1 or n.

Your task is to calculate the maximum possible length of the strictly increasing contiguous subarray of the remaining array.

Recall that the contiguous subarray a with indices from l to r is a[l ... r] = a_l, a_{l + 1}, ..., a_r. The subarray a[l ... r] is called strictly increasing if a_l < a_{l+1} < ... < a_r.

Input

The first line of the input contains one integer n (2 ≤ n ≤ 2 ⋅ 10^5) — the number of elements in a.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is the i-th element of a.

Output

Print one integer — the maximum possible length of the strictly increasing contiguous subarray of the array a after removing at most one element.

Examples

Input


5
1 2 5 3 4


Output


4


Input


2
1 2


Output


2


Input


7
6 5 4 3 2 4 3


Output


2

Note

In the first example, you can delete a_3=5. Then the resulting array will be equal to [1, 2, 3, 4] and the length of its largest increasing subarray will be equal to 4.

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.StringTokenizer;

/*
 * To change this license header, choose License Headers in Project Properties.
 * To change this template file, choose Tools | Templates
 * and open the template in the editor.
 */

/**
 *
 * @author Andy Phan
 */
public class d {
    public static void main(String[] args) {
        FS in = new FS(System.in);
        PrintWriter out = new PrintWriter(System.out);

        int n = in.nextInt();
        
        int[] arr = new int[n];
        int max = 0;
        for(int i = 0; i < n; i++) arr[i] = in.nextInt();
        int[] longL = new int[n];
        longL[0] = 1;
        for(int i = 1; i < n; i++) max = Math.max(max, longL[i] = ((arr[i] > arr[i-1]) ? longL[i-1]+1 : 1));
        int[] longR = new int[n];
        longR[n-1] = 1;
        for(int i = n-2; i >= 0; i--) max = Math.max(max, longR[i] = ((arr[i] < arr[i+1]) ? longR[i+1]+1 : 1));
        for(int i = 1; i < n-1; i++) {
            if(arr[i-1] < arr[i+1]) max = Math.max(max, longL[i-1]+longR[i+1]);
        }
        System.out.println(max);
        
        out.close();
    }
    
    static class FS {

        BufferedReader in;
        StringTokenizer token;
        
        public FS(InputStream str) {
            in = new BufferedReader(new InputStreamReader(str));
        }
        
        public String next() {
            if (token == null || !token.hasMoreElements()) {
                try {
                    token = new StringTokenizer(in.readLine());
                } catch (IOException ex) {
                }
                return next();
            }
            return token.nextToken();
        }
        
        public int nextInt() {
            return Integer.parseInt(next());
        }
    }
}
