One day Ms Swan bought an orange in a shop. The orange consisted of n·k segments, numbered with integers from 1 to n·k. 

There were k children waiting for Ms Swan at home. The children have recently learned about the orange and they decided to divide it between them. For that each child took a piece of paper and wrote the number of the segment that he would like to get: the i-th (1 ≤ i ≤ k) child wrote the number ai (1 ≤ ai ≤ n·k). All numbers ai accidentally turned out to be different.

Now the children wonder, how to divide the orange so as to meet these conditions:

  * each child gets exactly n orange segments; 
  * the i-th child gets the segment with number ai for sure; 
  * no segment goes to two children simultaneously. 



Help the children, divide the orange and fulfill the requirements, described above.

Input

The first line contains two integers n, k (1 ≤ n, k ≤ 30). The second line contains k space-separated integers a1, a2, ..., ak (1 ≤ ai ≤ n·k), where ai is the number of the orange segment that the i-th child would like to get.

It is guaranteed that all numbers ai are distinct.

Output

Print exactly n·k distinct integers. The first n integers represent the indexes of the segments the first child will get, the second n integers represent the indexes of the segments the second child will get, and so on. Separate the printed numbers with whitespaces.

You can print a child's segment indexes in any order. It is guaranteed that the answer always exists. If there are multiple correct answers, print any of them.

Examples

Input

2 2
4 1


Output

2 4 
1 3 


Input

3 1
2


Output

3 2 1 
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.FileWriter;
import java.io.IOException;
import java.io.PrintWriter;
import java.util.Scanner;
import java.util.TreeSet;

public class A {
    Scanner in;
    PrintWriter out;

    void solve() {
        int n=in.nextInt();
        int k=in.nextInt();
        int[][] m=new int[k+1][n+1];
        TreeSet<Integer> set=new TreeSet<Integer>();
        for (int i=1;i<k+1;i++) {
            m[i][1]=in.nextInt();
            set.add(m[i][1]);
        }
        int number=1;
        for (int i=1;i<k+1;i++) {
            for (int j=2;j<n+1;j++) {
                while (set.contains(number)) {
                    number++;
                }
                m[i][j]=number;
                number++;
            }
        }
        for (int i=1;i<k+1;i++) {
            for (int j=1;j<n+1;j++) {
                out.print(m[i][j]+" ");
            }
            out.println();
        }
    }

    void run() {
            in = new Scanner(System.in);
            out = new PrintWriter(System.out);
        try {
            solve();
        } finally {
            out.close();
        }
    }

    public static void main(String args[]) {
        new A().run();
    }

}
