There are N gems. The value of the i-th gem is V_i.

You will choose some of these gems, possibly all or none, and get them.

However, you need to pay a cost of C_i to get the i-th gem.

Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid.

Find the maximum possible value of X-Y.

Constraints

* All values in input are integers.
* 1 \leq N \leq 20
* 1 \leq C_i, V_i \leq 50

Input

Input is given from Standard Input in the following format:


N
V_1 V_2 ... V_N
C_1 C_2 ... C_N


Output

Print the maximum possible value of X-Y.

Examples

Input

3
10 2 5
6 3 4


Output

5


Input

4
13 21 6 19
11 30 6 15


Output

6


Input

1
1
50


Output

0
import java.util.*;
import java.math.*;
import java.lang.*;

public class Main {
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		// 整数の入力
		int n = sc.nextInt();
		List<Integer> nList = new ArrayList<>();

		int total = 0;
		for (int i = 0; i < n; i++) {
			nList.add(sc.nextInt());
		}
		for (int i = 0; i < n; i++) {
			int cost = sc.nextInt();
			int currentValue = nList.get(i);

			if(currentValue>cost){
				total += currentValue - cost;
			}
		}

		System.out.println(total);


	}
}
