Solve the mystery.  
Input:
String which consists of words(all the characters of any word are lower case letters) and punctuation marks(consists of {'.' , ',' , '?' , '!'}). Also every input string consists of one '*' in it.
It is guaranteed that strings doesn't start or end with space(' ') and only one answer exists for each case.  

Output:
Lower case letter.  

Constrains:
1 ≤ t ≤ 1000
2 ≤ length of string(n) ≤ 100  

Problem Setter : Vinay Kumar

SAMPLE INPUT
7
k! cats s*ack.
ah, s*tan sees natasha!
aibohphobi*
al lets della call ed ste*la.
amy, must i jujitsu *y ma?
aerata pat a*ea.
lollipop i * lol.

SAMPLE OUTPUT
t
a
a
l
m
r
l
'''
# Read input from stdin and provide input before running code

name = raw_input('What is your name?\n')
print 'Hi, %s.' % name
'''
alpha=[chr(i) for i in range(97,123)]
t=int(raw_input())
pun=['.',',','?','!',' ']
for i in range(t):
	strin=list(raw_input())
	for k in pun:
		v=strin.count(k)
		for d in range(v):
			strin.remove(k)
	n=strin.index('*')
	n+=1
	num=len(strin)-n
	print(strin[num])