You have an array a of length n. For every positive integer x you are going to perform the following operation during the x-th second:

  * Select some distinct indices i_{1}, i_{2}, …, i_{k} which are between 1 and n inclusive, and add 2^{x-1} to each corresponding position of a. Formally, a_{i_{j}} := a_{i_{j}} + 2^{x-1} for j = 1, 2, …, k. Note that you are allowed to not select any indices at all.



You have to make a nondecreasing as fast as possible. Find the smallest number T such that you can make the array nondecreasing after at most T seconds.

Array a is nondecreasing if and only if a_{1} ≤ a_{2} ≤ … ≤ a_{n}.

You have to answer t independent test cases.

Input

The first line contains a single integer t (1 ≤ t ≤ 10^{4}) — the number of test cases.

The first line of each test case contains single integer n (1 ≤ n ≤ 10^{5}) — the length of array a. It is guaranteed that the sum of values of n over all test cases in the input does not exceed 10^{5}.

The second line of each test case contains n integers a_{1}, a_{2}, …, a_{n} (-10^{9} ≤ a_{i} ≤ 10^{9}).

Output

For each test case, print the minimum number of seconds in which you can make a nondecreasing.

Example

Input


3
4
1 7 6 5
5
1 2 3 4 5
2
0 -4


Output


2
0
3

Note

In the first test case, if you select indices 3, 4 at the 1-st second and 4 at the 2-nd second, then a will become [1, 7, 7, 8]. There are some other possible ways to make a nondecreasing in 2 seconds, but you can't do it faster.

In the second test case, a is already nondecreasing, so answer is 0.

In the third test case, if you do nothing at first 2 seconds and select index 2 at the 3-rd second, a will become [0, 0].
import java.io.*;
import java.util.*;
import static java.lang.Math.*;

public class Main implements Runnable
{
    boolean multiple = true;
    long MOD;

    @SuppressWarnings({"Duplicates", "ConstantConditions"})
    void solve() throws Exception
    {   
        int n = sc.nextInt();
        /*read int arr a of size n*/ int[] a = new int[n]; for (int I = 0; I < n; I++) a[I] = sc.nextInt();
        long max = a[0];
        long ans = 0;
        for (int i = 1; i < n; i++)
        {
            long val = a[i];
            long diff = max - val;
            while ((1L << ans) - 1 < diff) ans++;
            max = max(max, val);
        }
        pl(ans);
    }

    StringBuilder ANS = new StringBuilder();
    void p(Object s) { ANS.append(s); } void p(double s) {ANS.append(s); } void p(long s) {ANS.append(s); } void p(char s) {ANS.append(s); }
    void pl(Object s) { ANS.append(s); ANS.append('\n'); } void pl(double s) { ANS.append(s); ANS.append('\n'); } void pl(long s) { ANS.append(s); ANS.append('\n'); } void pl(char s) { ANS.append(s); ANS.append('\n'); } void pl() { ANS.append(('\n')); }
    /*I/O, and other boilerplate*/ @Override public void run() { try { in = new BufferedReader(new InputStreamReader(System.in));out = new PrintWriter(System.out);sc = new FastScanner(in);if (multiple) { int q = sc.nextInt();for (int i = 0; i < q; i++) solve(); } else solve(); System.out.print(ANS); } catch (Throwable uncaught) { Main.uncaught = uncaught; } finally { out.close(); }} public static void main(String[] args) throws Throwable{ Thread thread = new Thread(null, new Main(), "", (1 << 26));thread.start();thread.join();if (Main.uncaught != null) {throw Main.uncaught;} } static Throwable uncaught; BufferedReader in; FastScanner sc; PrintWriter out; } class FastScanner { BufferedReader in; StringTokenizer st; public FastScanner(BufferedReader in) {this.in = in;}public String nextToken() throws Exception { while (st == null || !st.hasMoreTokens()) { st = new StringTokenizer(in.readLine()); }return st.nextToken(); }public int nextInt() throws Exception { return Integer.parseInt(nextToken()); }public long nextLong() throws Exception { return Long.parseLong(nextToken()); }public double nextDouble() throws Exception { return Double.parseDouble(nextToken()); }
}