We have a square grid with H rows and W columns. Snuke wants to write 0 or 1 in each of the squares. Here, all of the following conditions have to be satisfied:

* For every row, the smaller of the following is A: the number of 0s contained in the row, and the number of 1s contained in the row. (If these two numbers are equal, “the smaller” should be read as “either”.)
* For every column, the smaller of the following is B: the number of 0s contained in the column, and the number of 1s contained in the column.



Determine if these conditions can be satisfied by writing 0 or 1 in each of the squares. If the answer is yes, show one way to fill the squares so that the conditions are satisfied.

Constraints

* 1 \leq H,W \leq 1000
* 0 \leq A
* 2 \times A \leq W
* 0 \leq B
* 2 \times B \leq H
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


H W A B


Output

If the conditions cannot be satisfied by writing 0 or 1 in each of the squares, print -1.

If the conditions can be satisfied, print one way to fill the squares so that the conditions are satisfied, in the following format:


s_{11}s_{12}\cdots s_{1W}
s_{21}s_{22}\cdots s_{2W}
\vdots
s_{H1}s_{H2}\cdots s_{HW}


Here s_{ij} is the digit written in the square at the i-th row from the top and the j-th column from the left in the grid.

If multiple solutions exist, printing any of them will be accepted.

Examples

Input

3 3 1 1


Output

100
010
001


Input

1 5 2 0


Output

01010
//第 4 問: ABC 087 B - Coins (200 点)

import java.util.Scanner;

public class Main{

	public static void main(String[] args){

		Scanner scan = new Scanner(System.in);

		int H,W,A,B = 0;

		H = scan.nextInt();
		W = scan.nextInt();
		A = scan.nextInt();
		B = scan.nextInt();

		scan.close();

		String x = "";
		String y = "";

		int arr[] = new int[W];
		int arr2[] = new int[W];

		for(int j=0; j < W; j++)
		{
			if(j<A){
				x= x.concat("1");
				y= y.concat("0");

			}

			else
			{
				x= x.concat("0");
				y= y.concat("1");
			}
		}


		for(int i=0; i < H; i++)
		{

			if(i<B){
				System.out.println(x);
			}
			else {
				System.out.println(y);

			}
		}
	}
}

