Write a program of a Merge Sort algorithm implemented by the following pseudocode. You should also report the number of comparisons in the Merge function.


Merge(A, left, mid, right)
n1 = mid - left;
n2 = right - mid;
create array L[0...n1], R[0...n2]
for i = 0 to n1-1
do L[i] = A[left + i]
for i = 0 to n2-1
do R[i] = A[mid + i]
L[n1] = SENTINEL
R[n2] = SENTINEL
i = 0;
j = 0;
for k = left to right-1
if L[i] <= R[j]
then A[k] = L[i]
i = i + 1
else A[k] = R[j]
j = j + 1

Merge-Sort(A, left, right){
if left+1 < right
then mid = (left + right)/2;
call Merge-Sort(A, left, mid)
call Merge-Sort(A, mid, right)
call Merge(A, left, mid, right)


Notes

Constraints

* n ≤ 500000
* 0 ≤ an element in S ≤ 109

Input

In the first line n is given. In the second line, n integers are given.

Output

In the first line, print the sequence S. Two consequtive elements should be separated by a space character.

In the second line, print the number of comparisons.

Example

Input

10
8 5 9 2 6 3 7 1 10 4


Output

1 2 3 4 5 6 7 8 9 10
34
n = int(raw_input())
S = map(int,raw_input().strip().split(' '))

comp = 0

def merge_sort(S):
    if len(S) <= 1:
        return S
    S1,S2 = split(S)
    return merge(merge_sort(S1),merge_sort(S2))

def split(S):
    mid = len(S)/2
    return S[:mid],S[mid:]

def merge(S1,S2):
    S = []
    S1.append(100000000000)
    S2.append(100000000000)
    global comp
    i = 0
    j = 0
    for k in range(len(S1)+len(S2)-2):
        comp += 1
        if S1[i] <= S2[j]:
            S.append(S1[i])
            i += 1
        else:
            S.append(S2[j])
            j += 1
    return S

sorted_S = merge_sort(S)
for s in sorted_S:
    print s,
print
print comp