You are given matrix with n rows and n columns filled with zeroes. You should put k ones in it in such a way that the resulting matrix is symmetrical with respect to the main diagonal (the diagonal that goes from the top left to the bottom right corner) and is lexicographically maximal.

One matrix is lexicographically greater than the other if the first different number in the first different row from the top in the first matrix is greater than the corresponding number in the second one.

If there exists no such matrix then output -1.

Input

The first line consists of two numbers n and k (1 ≤ n ≤ 100, 0 ≤ k ≤ 106).

Output

If the answer exists then output resulting matrix. Otherwise output -1.

Examples

Input

2 1


Output

1 0 
0 0 


Input

3 2


Output

1 0 0 
0 1 0 
0 0 0 


Input

2 5


Output

-1
import math,string,itertools,collections,re,fractions,array,copy
import bisect
import heapq
from itertools import chain, dropwhile, permutations, combinations
from collections import deque, defaultdict, OrderedDict, namedtuple, Counter, ChainMap


# Guide:
#   1. construct complex data types while reading (e.g. graph adj list)
#   2. avoid any non-necessary time/memory usage
#   3. avoid templates and write more from scratch
#   4. switch to "flat" implementations

def VI(): return list(map(int,input().split()))
def I(): return int(input())
def LIST(n,m=None): return [0]*n if m is None else [[0]*m for i in range(n)]
def ELIST(n): return [[] for i in range(n)]
def MI(n=None,m=None): # input matrix of integers
    if n is None: n,m = VI()
    arr = LIST(n)
    for i in range(n): arr[i] = VI()
    return arr
def MS(n=None,m=None): # input matrix of strings
    if n is None: n,m = VI()
    arr = LIST(n)
    for i in range(n): arr[i] = input()
    return arr
def MIT(n=None,m=None): # input transposed matrix/array of integers
    if n is None: n,m = VI()
    a = MI(n,m)
    arr = LIST(m,n)
    for i,l in enumerate(a):
        for j,x in enumerate(l):
            arr[j][i] = x
    return arr

def main(info=0):
    n,k = VI()
    if k>n*n:
        print("-1")
    else:
        m = [["0" for _ in range(n)] for _ in range(n)]
        i,j = 0,0
        for i in range(n):
            for j in range(i, n):
                if k==0: break
                if i==j:
                    m[i][j] = "1"
                    k -= 1
                else:
                    if k==1: continue
                    m[i][j] = "1"
                    m[j][i] = "1"
                    k -= 2
            if k==0: break
        for l in m:
            print(" ".join(l))




if __name__ == "__main__":
    main()
