Mr. Takahashi has a string s consisting of lowercase English letters. He repeats the following operation on s exactly K times.

* Choose an arbitrary letter on s and change that letter to the next alphabet. Note that the next letter of `z` is `a`.



For example, if you perform an operation for the second letter on `aaz`, `aaz` becomes `abz`. If you then perform an operation for the third letter on `abz`, `abz` becomes `aba`.

Mr. Takahashi wants to have the lexicographically smallest string after performing exactly K operations on s. Find the such string.

Constraints

* 1≤|s|≤10^5
* All letters in s are lowercase English letters.
* 1≤K≤10^9

Input

The input is given from Standard Input in the following format:


s
K


Output

Print the lexicographically smallest string after performing exactly K operations on s.

Examples

Input

xyz
4


Output

aya


Input

a
25


Output

z


Input

codefestival
100


Output

aaaafeaaivap
import java.io.*;
import java.util.*;

class Main{
	public void run(){
		String s = next();
		int k = ni();
	
		StringBuilder sb = new StringBuilder();
		for(int i=0;i<s.length();i++){
			char c = s.charAt(i);
			int numA = ('z' - c + 1) % 26;
			if(numA <= k){
				k -= numA;
				sb.append('a');
			}else{
				sb.append(c);
			}
		}
		k %= 26;
		char c = sb.charAt(s.length() - 1);
		c -= 'a';
		c = (char)(c + k);
		c %= 26;
		c += 'a';
		sb.setCharAt(s.length()-1, c);

		out.println(sb.toString());
	}

	private static PrintWriter out;
	public static void main(String[] args){
		out = new PrintWriter(System.out);
		new Main().run();
		out.flush();
	}

	public Main(){
	}

	int ni(){
		int num = 0;
		String str = next();
		boolean minus = false;
		int i = 0;
		if(str.charAt(0) == '-'){
			minus = true;
			i++;
		}
		int len = str.length();
		for(;i < len; i++){
			char c = str.charAt(i);
			if(!('0' <= c && c <= '9')) throw new RuntimeException();
			num = num * 10 + (c - '0');
		}
		return minus ? -num : num;	}

	long nl(){
		long num = 0;
		String str = next();
		boolean minus = false;
		int i = 0;
		if(str.charAt(0) == '-'){
			minus = true;
			i++;
		}
		int len = str.length();
		for(;i < len; i++){
			char c = str.charAt(i);
			if(!('0' <= c && c <= '9')) throw new RuntimeException();
			num = num * 10l + (c - '0');
		}
		return minus ? -num : num;
	}

	double nd(){
		return Double.parseDouble(next());
	}

	String next(){
		int c;
		while(!isAlNum(c = read()));
		StringBuilder build = new StringBuilder();
		build.append((char)c);
		while(isAlNum(c = read())){
			build.append((char)c);
		}
		return build.toString();
	}
	String nextLine(){
		int c;
		while(!isAlNumOrSpace(c = read()));
		StringBuilder build = new StringBuilder();
		build.append((char)c);
		while(isAlNumOrSpace(c = read())){
			build.append((char)c);
		}
		return build.toString();
	}
	private static byte[] inputBuffer = new byte[1024];
	private static int bufferLength = 0;
	private static int bufferIndex = 0;
	
	private static int read(){
		if(bufferLength < 0) throw new RuntimeException();
		if(bufferIndex >= bufferLength){
			try{
				bufferLength = System.in.read(inputBuffer);
				bufferIndex = 0;
			}catch(IOException e){
				throw new RuntimeException(e);
			}
			if(bufferLength <= 0) return (bufferLength = -1);
		}
		return inputBuffer[bufferIndex++];
	}
	
	private static boolean isAlNum(int c){
		return '!' <= c && c <= '~';
	}
	private static boolean isAlNumOrSpace(int c){
		return isAlNum(c) || c == ' ' || c == '\t';
	}
	void debug(Object... os){
		out.println(Arrays.deepToString(os));
	}
}