Given is a string S consisting of `L` and `R`.

Let N be the length of S. There are N squares arranged from left to right, and the i-th character of S from the left is written on the i-th square from the left.

The character written on the leftmost square is always `R`, and the character written on the rightmost square is always `L`.

Initially, one child is standing on each square.

Each child will perform the move below 10^{100} times:

* Move one square in the direction specified by the character written in the square on which the child is standing. `L` denotes left, and `R` denotes right.



Find the number of children standing on each square after the children performed the moves.

Constraints

* S is a string of length between 2 and 10^5 (inclusive).
* Each character of S is `L` or `R`.
* The first and last characters of S are `R` and `L`, respectively.

Input

Input is given from Standard Input in the following format:


S


Output

Print the number of children standing on each square after the children performed the moves, in order from left to right.

Examples

Input

RRLRL


Output

0 1 2 1 1


Input

RRLLLLRLRRLL


Output

0 3 3 0 0 0 1 1 0 2 2 0


Input

RRRLLRLLRRRLLLLL


Output

0 0 3 2 0 2 1 0 0 0 4 4 0 0 0 0
#include <bits/stdc++.h>
#define rep(i,a,b) for(ll i=ll(a);i<ll(b);i++)
#define irep(i,a,b) for(ll i=ll(a);i>=ll(b);i--)
using ll = long long;
using namespace std;


int main(){
	string s;
	cin>>s;
	ll st[110000]={0};
	ll x=1,y=0;

	ll p=0;
	rep(i,1,s.length()){
		if (s[i]=='R')x++;
		else if(s[i]=='L'&&x>0) {
			p=i;
			while(s[i]=='L'){y++;i++;}
			st[p-1]=ceil((double)x/2)+y/2;
			st[p]=ceil((double)y/2)+x/2;
			x=0,y=0;
			i--;
		}
	}
	rep(i,0,s.length())cout<<st[i]<<" ";
}