Given is a string S consisting of `L` and `R`.

Let N be the length of S. There are N squares arranged from left to right, and the i-th character of S from the left is written on the i-th square from the left.

The character written on the leftmost square is always `R`, and the character written on the rightmost square is always `L`.

Initially, one child is standing on each square.

Each child will perform the move below 10^{100} times:

* Move one square in the direction specified by the character written in the square on which the child is standing. `L` denotes left, and `R` denotes right.



Find the number of children standing on each square after the children performed the moves.

Constraints

* S is a string of length between 2 and 10^5 (inclusive).
* Each character of S is `L` or `R`.
* The first and last characters of S are `R` and `L`, respectively.

Input

Input is given from Standard Input in the following format:


S


Output

Print the number of children standing on each square after the children performed the moves, in order from left to right.

Examples

Input

RRLRL


Output

0 1 2 1 1


Input

RRLLLLRLRRLL


Output

0 3 3 0 0 0 1 1 0 2 2 0


Input

RRRLLRLLRRRLLLLL


Output

0 0 3 2 0 2 1 0 0 0 4 4 0 0 0 0
#include <bits/stdc++.h>
using namespace std;
int main(){
  string S;
  cin>>S;
  int r = 0,l = 0;
  for(int i = 0;i<S.size();i++){
    if(S.at(i) == 'R' && S.at(i+1) == 'R'){
      cout << 0 << " ";
      r++;
    }
    else if(S.at(i) == 'R' && S.at(i+1) == 'L'){
      r++;
      while( i<S.size()-1 && S.at(i+1) == 'L'){
        l++;
        i++;
      }
      cout << l/2+r-r/2 << " " << r/2+l-l/2 << " ";
      for(int k = 0;k<l-1;k++){
        cout << 0 << " ";
      }
      r = 0;
      l = 0;
    }
  }
  return 0;
}
