You are given an integer sequence of length N, a = {a_1, a_2, …, a_N}, and an integer K.

a has N(N+1)/2 non-empty contiguous subsequences, {a_l, a_{l+1}, …, a_r} (1 ≤ l ≤ r ≤ N). Among them, how many have an arithmetic mean that is greater than or equal to K?

Constraints

* All input values are integers.
* 1 ≤ N ≤ 2 \times 10^5
* 1 ≤ K ≤ 10^9
* 1 ≤ a_i ≤ 10^9

Input

Input is given from Standard Input in the following format:


N K
a_1
a_2
:
a_N


Output

Print the number of the non-empty contiguous subsequences with an arithmetic mean that is greater than or equal to K.

Examples

Input

3 6
7
5
7


Output

5


Input

1 2
1


Output

0


Input

7 26
10
20
30
40
30
20
10


Output

13
from collections import defaultdict
from itertools import accumulate
import sys

input = sys.stdin.buffer.readline

n, k = map(int, input().split())
jisho = defaultdict(int)
A = [int(input()) for _ in range(n)]
A = [0] + A
SA = list(accumulate(A))
T = [0] * (n + 1)
for i in range(n + 1):
    T[i] = (SA[i] - k * i, i)
T.sort()


class SegmentTree:
    ele = 0

    def func(self, a, b):
        return a + b

    # SEG木は1-index
    # Aに関しては0-index

    def __init__(self, n):  # Aは0-idx
        self.n = n
        self.num = 2 ** ((self.n - 1).bit_length())
        self.SEG = [self.ele] * (2 * self.num)

    def search(self, idx):
        return self.SEG[idx + self.num]

    def initialize(self, A):
        for i in range(self.n):
            self.SEG[i + self.num] = A[i]
        for i in range(self.num - 1, 0, -1):
            self.SEG[i] = self.func(self.SEG[2 * i], self.SEG[2 * i + 1])

    def update(self, idx, val):
        idx += self.num
        self.SEG[idx] = val
        idx //= 2
        while idx:
            self.SEG[idx] = self.func(self.SEG[2 * idx], self.SEG[2 * idx + 1])
            idx //= 2

    # def delay(self,):

    def query(self, left, right):
        # maspy式。開区間のママ処理する
        # left, rightで値を分けているのは交換法則不成立のときのため
        # 開区間→Rが奇数→右端が偶数→1ずらしてから計算
        # 　下から上への遷移は2で割る
        # juppy氏は閉区間に直していた
        resleft = self.ele
        resright = self.ele
        left += self.num
        right += self.num
        while right - left > 0:
            if left % 2 == 1:
                resleft = self.func(resleft, self.SEG[left])
                left += 1
            if right % 2 == 1:
                right -= 1
                resright = self.func(resright, self.SEG[right])
            left //= 2
            right //= 2
        return self.func(resleft, resright)


ST = SegmentTree(n + 1)
ans = 0
for val, i in T:
    ans += ST.query(0, i + 1)
    ST.update(i, 1)
print(ans)
