A bracket sequence is a string that is one of the following:

1. An empty string;
2. The concatenation of `(`, A, and `)` in this order, for some bracket sequence A ;
3. The concatenation of A and B in this order, for some non-empty bracket sequences A and B /



Given are N strings S_i. Can a bracket sequence be formed by concatenating all the N strings in some order?

Constraints

* 1 \leq N \leq 10^6
* The total length of the strings S_i is at most 10^6.
* S_i is a non-empty string consisting of `(` and `)`.

Input

Input is given from Standard Input in the following format:


N
S_1
:
S_N


Output

If a bracket sequence can be formed by concatenating all the N strings in some order, print `Yes`; otherwise, print `No`.

Examples

Input

2
)
(()


Output

Yes


Input

2
)(
()


Output

No


Input

4
((()))
((((((
))))))
()()()


Output

Yes


Input

3
(((
)
)


Output

No
from sys import stdin

def main():
    readline = stdin.readline
    n = int(readline())
    s = tuple(readline().strip() for _ in range(n))

    plus, minus = [], []
    for c in s:
        if 2 * c.count('(') - len(c) > 0:
            plus.append(c)
        else:
            minus.append(c)

    plus.sort(key = lambda x: x.count(')'))
    minus.sort(key = lambda x: x.count('('), reverse = True)
    plus.extend(minus)
    sum = 0
    for v in plus:
        for vv in v:
            sum = sum + (1 if vv == '(' else -1)
            if sum < 0 : return print('No')
    if sum != 0:
        return print('No')

    return print('Yes')

if __name__ == '__main__':
    main()
