Write a program which manipulates a sequence A = {a1, a2, . . . , an} with the following operations:

* add(s, t, x): add x to as, as+1, ..., at.
* get(i): output the value of ai.



Note that the initial values of ai (i = 1, 2, . . . , n) are 0.

Constraints

* 1 ≤ n ≤ 100000
* 1 ≤ q ≤ 100000
* 1 ≤ s ≤ t ≤ n
* 1 ≤ i ≤ n
* 0 ≤ x ≤ 1000

Input


n q
query1
query2
:
queryq


In the first line, n (the number of elements in A) and q (the number of queries) are given. Then, ith query queryi is given in the following format:


0 s t x


or


1 t


The first digit represents the type of the query. '0' denotes add(s, t, x) and '1' denotes get(i).

Output

For each get operation, print the value.

Examples

Input

3 5
0 1 2 1
0 2 3 2
0 3 3 3
1 2
1 3


Output

3
5


Input

4 3
1 2
0 1 4 1
1 2


Output

0
1
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
int N=1<<18;
ll Mi[555555],A[555555];
class StarrySkyTree{
public:
  void init(){fill(Mi,Mi+555555,0);fill(A,A+555555,0);}
  void add(int a,int b,int x,int k=0,int l=0,int r=N) {
    if(r<=a||b<=l) return;
    if(a<=l&&r<=b){
      A[k]+=x;
      while(k){
        k=(k-1)/2;
        Mi[k]=min(Mi[k*2+1]+A[k*2+1],Mi[k*2+2]+A[k*2+2]);
      }
      return;
    }
    add(a,b,x,k*2+1,l,(l+r)/2);
    add(a,b,x,k*2+2,(l+r)/2,r);
  }
  ll getMin(int a,int b,int k=0,int l=0,int r=N) {
    if(r<=a||b<=l)return 1<<30;if(a<=l&&r<=b)return Mi[k]+A[k];
    ll left=getMin(a,b,k*2+1,l,(l+r)/2),right=getMin(a,b,k*2+2,(l+r)/2,r);
    return min(left,right)+A[k];
  }
};

StarrySkyTree t;
int main() {
  int n,T;
  cin >> n >> T;
  t.init();
  while(T--) {
    int x,y,l,r;
    cin >> y;
    if(!y) {
      cin >> l >> r >> x;
      t.add(l-1,r,x);
    } else {
      cin >> x;
      cout << t.getMin(x-1,x) << endl;
    }
  }
  return 0;
}
