A bracket sequence is a string that is one of the following:

1. An empty string;
2. The concatenation of `(`, A, and `)` in this order, for some bracket sequence A ;
3. The concatenation of A and B in this order, for some non-empty bracket sequences A and B /



Given are N strings S_i. Can a bracket sequence be formed by concatenating all the N strings in some order?

Constraints

* 1 \leq N \leq 10^6
* The total length of the strings S_i is at most 10^6.
* S_i is a non-empty string consisting of `(` and `)`.

Input

Input is given from Standard Input in the following format:


N
S_1
:
S_N


Output

If a bracket sequence can be formed by concatenating all the N strings in some order, print `Yes`; otherwise, print `No`.

Examples

Input

2
)
(()


Output

Yes


Input

2
)(
()


Output

No


Input

4
((()))
((((((
))))))
()()()


Output

Yes


Input

3
(((
)
)


Output

No
def kton(S):
    r = 0
    m = 0
    for s in S:
        r += 1 if s == '(' else -1
        m = min(m, r)
    return r, m
        
def main():
    N = int(input())
    RM = [kton(input()) for _ in range(N)]
    pos = 0
    negp = []
    negn = []
    posn = []
    for r, m in RM:
        if m < 0:
            if r >= 0:
                negp.append((-m, r))
            else:
                negn.append((-(r-m), -r, m))
        else:
            pos += r
 
    negp.sort()
    for m, r in negp:
        if pos - m < 0:
            return False
        pos += r
    negn.sort()
    for _, r, m in negn:
        if pos + m < 0:
            return False
        pos -= r
    return pos == 0
 
print('Yes' if main() else 'No')