Given is a string S consisting of `L` and `R`.

Let N be the length of S. There are N squares arranged from left to right, and the i-th character of S from the left is written on the i-th square from the left.

The character written on the leftmost square is always `R`, and the character written on the rightmost square is always `L`.

Initially, one child is standing on each square.

Each child will perform the move below 10^{100} times:

* Move one square in the direction specified by the character written in the square on which the child is standing. `L` denotes left, and `R` denotes right.



Find the number of children standing on each square after the children performed the moves.

Constraints

* S is a string of length between 2 and 10^5 (inclusive).
* Each character of S is `L` or `R`.
* The first and last characters of S are `R` and `L`, respectively.

Input

Input is given from Standard Input in the following format:


S


Output

Print the number of children standing on each square after the children performed the moves, in order from left to right.

Examples

Input

RRLRL


Output

0 1 2 1 1


Input

RRLLLLRLRRLL


Output

0 3 3 0 0 0 1 1 0 2 2 0


Input

RRRLLRLLRRRLLLLL


Output

0 0 3 2 0 2 1 0 0 0 4 4 0 0 0 0
#include <bits/stdc++.h>

#define rep(i, n) for (int i = 0; i < (n); i++)
#define repr(i, n) for (int i = (n)-1; i >= 0; i--)
using namespace std;
typedef long long ll;
const int INF = 1e9;

string s;
int a[1 << 17], b, n, i;
int main() {
  cin >> s;
  n = s.size();
  for (i = n - 1; i >= 0; i--)
    if (s[i] == 'L')
      b = i;
    else
      a[b - ((b - i) & 1)]++;
  
  for (i = 0; i < n; i++)
    if (s[i] == 'R')
      b = i;
    else
      a[b + ((i - b) & 1)]++;
  
  for (i = 0; i < n; i++) cout << a[i] << " ";
}