A bracket sequence is a string that is one of the following:

1. An empty string;
2. The concatenation of `(`, A, and `)` in this order, for some bracket sequence A ;
3. The concatenation of A and B in this order, for some non-empty bracket sequences A and B /



Given are N strings S_i. Can a bracket sequence be formed by concatenating all the N strings in some order?

Constraints

* 1 \leq N \leq 10^6
* The total length of the strings S_i is at most 10^6.
* S_i is a non-empty string consisting of `(` and `)`.

Input

Input is given from Standard Input in the following format:


N
S_1
:
S_N


Output

If a bracket sequence can be formed by concatenating all the N strings in some order, print `Yes`; otherwise, print `No`.

Examples

Input

2
)
(()


Output

Yes


Input

2
)(
()


Output

No


Input

4
((()))
((((((
))))))
()()()


Output

Yes


Input

3
(((
)
)


Output

No
#!/usr/bin/env python3
import sys
input = sys.stdin.readline

n = int(input())
increasing = []
decreasing = []
for _ in range(n):
    s = input().rstrip()
    minima = 0
    fin = 0
    for ch in s:
        if ch == ")":
            fin -= 1
            if fin < minima:
                minima = fin
        else:
            fin += 1
    if fin >= 0:
        increasing.append((minima, fin))
    else:
        decreasing.append((minima - fin, fin))

increasing.sort(reverse=True)
decreasing.sort()

current = 0
for minima, diff in increasing:
    if current + minima < 0:
        print("No")
        exit()
    current += diff
for minima, diff in decreasing:
    if current + minima + diff < 0:
        print("No")
        exit()
    current += diff
if current != 0:
    print("No")
else:
    print("Yes")