A student of z-school found a kind of sorting called z-sort. The array a with n elements are z-sorted if two conditions hold:

  1. ai ≥ ai - 1 for all even i, 
  2. ai ≤ ai - 1 for all odd i > 1. 



For example the arrays [1,2,1,2] and [1,1,1,1] are z-sorted while the array [1,2,3,4] isn’t z-sorted.

Can you make the array z-sorted?

Input

The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of elements in the array a.

The second line contains n integers ai (1 ≤ ai ≤ 109) — the elements of the array a.

Output

If it's possible to make the array a z-sorted print n space separated integers ai — the elements after z-sort. Otherwise print the only word "Impossible".

Examples

Input

4
1 2 2 1


Output

1 2 1 2


Input

5
1 3 2 2 5


Output

1 5 2 3 2
#include <bits/stdc++.h>
using namespace std;
template <class T>
const T& max(const T& a, const T& b, const T& c) {
  return max(a, max(b, c));
}
template <class T>
const T& min(const T& a, const T& b, const T& c) {
  return min(a, min(b, c));
}
long long stoi(string& str) {
  istringstream second(str);
  long long i;
  second >> i;
  return i;
}
string itos(long long i) {
  stringstream second;
  second << i;
  return second.str();
}
long long gcd(long long a, long long b) {
  if (b == 0) return a;
  return gcd(b, a % b);
}
long long lcm(long long a, long long b) { return (a * b) / gcd(a, b); }
long long poww(long long a, long long b) {
  if (b == 0) return 1;
  long long tmp = poww(a, b / 2);
  return (b & 1 ? a * tmp * tmp : tmp * tmp);
}
long long sumOfDigs(string s) {
  long long sum = 0;
  for (int i = 0; i < s.length(); i++) sum += s[i] - '0';
  return sum;
}
long long sumOfDigs(long long n) {
  return (n < 10 ? n : n % 10 + sumOfDigs(n / 10));
}
long long mod = poww(10, 6) + 3;
int months[13] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
using namespace std;
void t() { freopen("test.txt", "r", stdin); }
int a[1001];
int main() {
  int n;
  cin >> n;
  vector<int> v(n);
  for (int i = 0; i < n; i++) cin >> v[i];
  sort(v.begin(), v.end());
  int j = 0;
  for (int i = 1; i <= n; i += 2) {
    a[i] = v[j++];
  }
  for (int i = 2; i <= n; i += 2) {
    a[i] = v[j++];
  }
  for (int i = 1; i <= n; i++) cout << a[i] << " ";
  cout << endl;
  return 0;
}
