A bracket sequence is a string that is one of the following:

1. An empty string;
2. The concatenation of `(`, A, and `)` in this order, for some bracket sequence A ;
3. The concatenation of A and B in this order, for some non-empty bracket sequences A and B /



Given are N strings S_i. Can a bracket sequence be formed by concatenating all the N strings in some order?

Constraints

* 1 \leq N \leq 10^6
* The total length of the strings S_i is at most 10^6.
* S_i is a non-empty string consisting of `(` and `)`.

Input

Input is given from Standard Input in the following format:


N
S_1
:
S_N


Output

If a bracket sequence can be formed by concatenating all the N strings in some order, print `Yes`; otherwise, print `No`.

Examples

Input

2
)
(()


Output

Yes


Input

2
)(
()


Output

No


Input

4
((()))
((((((
))))))
()()()


Output

Yes


Input

3
(((
)
)


Output

No
# 折れ線グラフで考えると
# ( : +1
# ) : -1
# 0で終わる
# 0未満にならない → 各文字列で最下点と和を利用
# 和がマイナスの部分と分けて、マイナス部分は反転して考える

n = int(input())
s = [input() for _ in range(n)]
plus = []
minus = []
for i in s:
    min_v = 0
    sum_v = 0
    for j in i:
        sum_v += 1 if j == '(' else -1
        min_v = min(min_v, sum_v)
    if sum_v > 0:
        plus.append((min_v, sum_v))
    else:
        minus.append((min_v-sum_v, -sum_v))

plus.sort(key=lambda x:x[0], reverse=True)
minus.sort(key=lambda x:x[0], reverse=True)

sum_plus = 0
for min_v, sum_v in plus:
    if sum_plus + min_v < 0:
        print("No")
        exit()
    sum_plus += sum_v

sum_minus = 0
for min_v, sum_v in minus:
    if sum_minus + min_v < 0:
        print("No")
        exit()
    sum_minus += sum_v

if sum_plus == sum_minus:
    print("Yes")
else:
    print("No")



