A bracket sequence is a string that is one of the following:

1. An empty string;
2. The concatenation of `(`, A, and `)` in this order, for some bracket sequence A ;
3. The concatenation of A and B in this order, for some non-empty bracket sequences A and B /



Given are N strings S_i. Can a bracket sequence be formed by concatenating all the N strings in some order?

Constraints

* 1 \leq N \leq 10^6
* The total length of the strings S_i is at most 10^6.
* S_i is a non-empty string consisting of `(` and `)`.

Input

Input is given from Standard Input in the following format:


N
S_1
:
S_N


Output

If a bracket sequence can be formed by concatenating all the N strings in some order, print `Yes`; otherwise, print `No`.

Examples

Input

2
)
(()


Output

Yes


Input

2
)(
()


Output

No


Input

4
((()))
((((((
))))))
()()()


Output

Yes


Input

3
(((
)
)


Output

No
N = int(input())
S = [input() for i in range(N)]

pos = []
neg = []
for s in S:
    sm = 0
    mn = 0
    for c in s:
        if c=='(':
            sm += 1
        else:
            sm -= 1
            mn = min(mn, sm)
    if sm >= 0:
        pos.append((mn,sm))
    else:
        neg.append((mn-sm, -sm))

pos.sort(key=lambda x:-x[0])
neg.sort(key=lambda x:-x[0])

hp = 0
for m,s in pos:
    if hp + m < 0:
        print('No')
        exit()
    hp += s

hn = 0
for m,s in neg:
    if hn + m < 0:
        print('No')
        exit()
    hn += s

print('Yes' if hp==hn else 'No')