Given is a string S consisting of `L` and `R`.

Let N be the length of S. There are N squares arranged from left to right, and the i-th character of S from the left is written on the i-th square from the left.

The character written on the leftmost square is always `R`, and the character written on the rightmost square is always `L`.

Initially, one child is standing on each square.

Each child will perform the move below 10^{100} times:

* Move one square in the direction specified by the character written in the square on which the child is standing. `L` denotes left, and `R` denotes right.



Find the number of children standing on each square after the children performed the moves.

Constraints

* S is a string of length between 2 and 10^5 (inclusive).
* Each character of S is `L` or `R`.
* The first and last characters of S are `R` and `L`, respectively.

Input

Input is given from Standard Input in the following format:


S


Output

Print the number of children standing on each square after the children performed the moves, in order from left to right.

Examples

Input

RRLRL


Output

0 1 2 1 1


Input

RRLLLLRLRRLL


Output

0 3 3 0 0 0 1 1 0 2 2 0


Input

RRRLLRLLRRRLLLLL


Output

0 0 3 2 0 2 1 0 0 0 4 4 0 0 0 0
#include <bits/stdc++.h>
#include <math.h>
using namespace std;
int main(void){
    string s;
    cin>>s;
    int n=s.size();
    int a[n];
    for(int i=0;i<n;i++) a[i]=1; 
    for(int i=0;i<n-2;i++){
        if(s.at(i)=='R'&&s.at(i+1)=='R'){
            a[i+2]+=a[i];
            a[i]=0;
        }
    }
    for(int i=n-1;i>=2;i--){
        if(s.at(i)=='L'&&s.at(i-1)=='L'){
            a[i-2]+=a[i];
            a[i]=0;
        }
    }
    for(int i=0;i<n;i++) cout<<a[i]<<" ";
}
