Little C loves number «3» very much. He loves all things about it.

Now he has a positive integer n. He wants to split n into 3 positive integers a,b,c, such that a+b+c=n and none of the 3 integers is a multiple of 3. Help him to find a solution.

Input

A single line containing one integer n (3 ≤ n ≤ 10^9) — the integer Little C has.

Output

Print 3 positive integers a,b,c in a single line, such that a+b+c=n and none of them is a multiple of 3.

It can be proved that there is at least one solution. If there are multiple solutions, print any of them.

Examples

Input

3


Output

1 1 1

Input

233

Output

77 77 79
from sys import stdin,stdout,exit
def sin(): 
	return stdin.readline().rstrip()
def listInput():
	return list(map(int,sin().split()))
def printBS(li):
	if not li: return
	for i in range(len(li)-1):
		stdout.write("%d "%(li[i]))
	stdout.write("%d\n"%(li[-1]))

n = int(sin())

if n%3==0 or n%3==1:
	print(1,1,n-2)
else:
	print(1,2,n-3)