n people came to a party. Then those, who had no friends among people at the party, left. Then those, who had exactly 1 friend among those who stayed, left as well. Then those, who had exactly 2, 3, ..., n - 1 friends among those who stayed by the moment of their leaving, did the same.

What is the maximum amount of people that could stay at the party in the end? 

Input

The first input line contains one number t — amount of tests (1 ≤ t ≤ 105). Each of the following t lines contains one integer number n (1 ≤ n ≤ 105).

Output

For each test output in a separate line one number — the maximum amount of people that could stay in the end.

Examples

Input

1
3


Output

1
import java.util.*;
import java.io.*;

public class B0023 {

    public static void main(String args[]) throws Exception {
        new B0023();
    }

    B0023() throws Exception {
        PandaScanner sc = null;
        PrintWriter out = null;
        try {
            sc = new PandaScanner(System.in);
            out = new PrintWriter(System.out);
        } catch (Exception ignored) {
        }

        int t = sc.nextInt();
        for (int i = 0; i < t; i++) {
            int n = sc.nextInt();
            out.println(Math.max(0, n - 2));
        }

        out.close();
        System.exit(0);
    }


    //The PandaScanner class, for Panda fast scanning!
    public class PandaScanner {
        BufferedReader br;
        StringTokenizer st;
        InputStream in;

        PandaScanner(InputStream in) throws Exception {
            br = new BufferedReader(new InputStreamReader(this.in = in));
        }

        public String next() throws Exception {
            if (st == null || !st.hasMoreTokens()) {
                st = new StringTokenizer(br.readLine().trim());
                return next();
            }
            return st.nextToken();
        }

        public boolean hasNext() throws Exception {
            return (st != null && st.hasMoreTokens()) || in.available() > 0;
        }

        public long nextLong() throws Exception {
            return Long.parseLong(next());
        }

        public int nextInt() throws Exception {
            return Integer.parseInt(next());
        }
    }
}
