A tennis tournament with n participants is running. The participants are playing by an olympic system, so the winners move on and the losers drop out.

The tournament takes place in the following way (below, m is the number of the participants of the current round):

  * let k be the maximal power of the number 2 such that k ≤ m, 
  * k participants compete in the current round and a half of them passes to the next round, the other m - k participants pass to the next round directly, 
  * when only one participant remains, the tournament finishes. 



Each match requires b bottles of water for each participant and one bottle for the judge. Besides p towels are given to each participant for the whole tournament.

Find the number of bottles and towels needed for the tournament.

Note that it's a tennis tournament so in each match two participants compete (one of them will win and the other will lose).

Input

The only line contains three integers n, b, p (1 ≤ n, b, p ≤ 500) — the number of participants and the parameters described in the problem statement.

Output

Print two integers x and y — the number of bottles and towels need for the tournament.

Examples

Input

5 2 3


Output

20 15


Input

8 2 4


Output

35 32

Note

In the first example will be three rounds:

  1. in the first round will be two matches and for each match 5 bottles of water are needed (two for each of the participants and one for the judge), 
  2. in the second round will be only one match, so we need another 5 bottles of water, 
  3. in the third round will also be only one match, so we need another 5 bottles of water. 



So in total we need 20 bottles of water.

In the second example no participant will move on to some round directly.
/*
 * Code Author: Anamika Modi
 * DA-IICT
 */
import java.io.*;
import java.math.BigInteger;
import java.math.RoundingMode;
import java.text.DecimalFormat;
import java.util.*;


public class code {

	static double eps=(double)1e-6;
	static long mod=(int)1e9+7;
	public static void main(String args[]){
		InputReader in = new InputReader(System.in);
		OutputStream outputStream = System.out;
		PrintWriter out = new PrintWriter(outputStream);
	//----------My Code----------
	int p=in.nextInt();
	int b=in.nextInt();
	int t=in.nextInt();
	int c=p;
	int match=0;
	int tb=0;
	int tp= c*t ;
	
	for(int j=0;;j++){
		
		c=(int)(Math.log(p)/Math.log(2));
		match+=c;
		p=(c+p-2*c);
		if(p==1){
			break;
		}
		
		
		
	}
	tb=match*(2*b+1);
	System.out.println(tb+" "+tp);
	
	
	
	//---------------The End------------------
	

	} 

	static int recursiveBinarySearch(int[][] sortedArray, int start, int end, int key) {

		if (start <= end) {
			int mid = start + (end - start) / 2; 
			if (key < sortedArray[mid][0]) {
				return recursiveBinarySearch(sortedArray, start, mid, key);

			} else if (key > sortedArray[mid][0]) {
				return recursiveBinarySearch(sortedArray, mid+1, end , key);

			} else {
				return mid;  
			}
		}
		return -(start + 1); 
	}

	static long modulo(long a,long b,long c) {
		long x=1;
		long y=a;
		while(b > 0){
			if(b%2 == 1){
				x=(x*y)%c;
			}
			y = (y*y)%c; // squaring the base
			b /= 2;
		}
		return  x%c;
	}
	static long gcd(long x, long y)
	{
		long r=0, a, b;
		a = (x > y) ? x : y; // a is greater number
		b = (x < y) ? x : y; // b is smaller number
		r = b;
		while(a % b != 0)
		{
			r = a % b;
			a = b;
			b = r;
		}
		return r;
	}
	static class Pair implements Comparable<Pair>{
		long x;
		long y;
		int i;
		Pair(long xx,long yy,int ii){
			x=xx;
			y=yy;
			i=ii;
		}
		@Override
		public int compareTo(Pair o) {
			if(this.y>=o.y)
				return 1;
			else
				return 0;

		}
	}

	static class InputReader {
		public BufferedReader reader;
		public StringTokenizer tokenizer;

		public InputReader(InputStream inputstream) {
			reader = new BufferedReader(new InputStreamReader(inputstream));
			tokenizer = null;
		}

		public String nextLine(){
			String fullLine=null;
			while (tokenizer == null || !tokenizer.hasMoreTokens()) {
				try {
					fullLine=reader.readLine();
				} catch (IOException e) {
					throw new RuntimeException(e);
				}
				return fullLine;
			}
			return fullLine;
		}
		public String next() {
			while (tokenizer == null || !tokenizer.hasMoreTokens()) {
				try {
					tokenizer = new StringTokenizer(reader.readLine());
				} catch (IOException e) {
					throw new RuntimeException(e);
				}
			}
			return tokenizer.nextToken();
		}
		public long nextLong() {
			return Long.parseLong(next());
		}
		public int nextInt() {
			return Integer.parseInt(next());
		}
	}
} 