A bracket sequence is a string that is one of the following:

1. An empty string;
2. The concatenation of `(`, A, and `)` in this order, for some bracket sequence A ;
3. The concatenation of A and B in this order, for some non-empty bracket sequences A and B /



Given are N strings S_i. Can a bracket sequence be formed by concatenating all the N strings in some order?

Constraints

* 1 \leq N \leq 10^6
* The total length of the strings S_i is at most 10^6.
* S_i is a non-empty string consisting of `(` and `)`.

Input

Input is given from Standard Input in the following format:


N
S_1
:
S_N


Output

If a bracket sequence can be formed by concatenating all the N strings in some order, print `Yes`; otherwise, print `No`.

Examples

Input

2
)
(()


Output

Yes


Input

2
)(
()


Output

No


Input

4
((()))
((((((
))))))
()()()


Output

Yes


Input

3
(((
)
)


Output

No
import sys
n = int(input())
ss =[]
for _ in range(n):
    ss.append(input())
cnt_p = []
cnt_m = []
for i in range(n):
    left = 0
    right = 0
    for s in ss[i]:
        if(s == '('):
            left += 1
        elif(s == ')'):
            if(left > 0):
                left -= 1
            else:
                right += 1
    if(left-right > 0):
        cnt_p.append((right,left))
    else:
        cnt_m.append((right,left))
 
 
cnt_p = sorted(cnt_p, key=lambda x: (x[0]))
cnt_m = sorted(cnt_m, key=lambda x: (x[1]*-1))
cnt = cnt_p + cnt_m
num = 0
for right,left in cnt:
    num -= right
    if(num < 0):
        print('No')
        sys.exit()
    num += left
if(num==0):
    print('Yes')
else:
    print('No')