Given is a string S consisting of `L` and `R`.

Let N be the length of S. There are N squares arranged from left to right, and the i-th character of S from the left is written on the i-th square from the left.

The character written on the leftmost square is always `R`, and the character written on the rightmost square is always `L`.

Initially, one child is standing on each square.

Each child will perform the move below 10^{100} times:

* Move one square in the direction specified by the character written in the square on which the child is standing. `L` denotes left, and `R` denotes right.



Find the number of children standing on each square after the children performed the moves.

Constraints

* S is a string of length between 2 and 10^5 (inclusive).
* Each character of S is `L` or `R`.
* The first and last characters of S are `R` and `L`, respectively.

Input

Input is given from Standard Input in the following format:


S


Output

Print the number of children standing on each square after the children performed the moves, in order from left to right.

Examples

Input

RRLRL


Output

0 1 2 1 1


Input

RRLLLLRLRRLL


Output

0 3 3 0 0 0 1 1 0 2 2 0


Input

RRRLLRLLRRRLLLLL


Output

0 0 3 2 0 2 1 0 0 0 4 4 0 0 0 0
#include <bits/stdc++.h>
using namespace std;
#define rep(i,n) for(int i=0;i<(n);i++)
#define REP(i,n) for(int i=1;i<=(n);i++)
typedef long long ll;
typedef pair<int,int> pii;

const int M=1e5+5;
int ans[M];

int main(){
    string s;
    cin >> s;
    int n=s.size();
    int i=0;
    while(i<n){
        int cntl=0,cntr=0;
        while(i<n&&s[i]=='R') cntr++,i++;
        int lp=i;
        while(i<n&&s[i]=='L') cntl++,i++;
        ans[lp]=(cntl+1)/2+cntr/2;
        ans[lp-1]=cntl/2+(cntr+1)/2;
    }
    rep(i,n) cout<<ans[i]<<" ";
    cout<<endl;
}