Sereja owns a restaurant for n people. The restaurant hall has a coat rack with n hooks. Each restaurant visitor can use a hook to hang his clothes on it. Using the i-th hook costs ai rubles. Only one person can hang clothes on one hook.

Tonight Sereja expects m guests in the restaurant. Naturally, each guest wants to hang his clothes on an available hook with minimum price (if there are multiple such hooks, he chooses any of them). However if the moment a guest arrives the rack has no available hooks, Sereja must pay a d ruble fine to the guest. 

Help Sereja find out the profit in rubles (possibly negative) that he will get tonight. You can assume that before the guests arrive, all hooks on the rack are available, all guests come at different time, nobody besides the m guests is visiting Sereja's restaurant tonight.

Input

The first line contains two integers n and d (1 ≤ n, d ≤ 100). The next line contains integers a1, a2, ..., an (1 ≤ ai ≤ 100). The third line contains integer m (1 ≤ m ≤ 100).

Output

In a single line print a single integer — the answer to the problem.

Examples

Input

2 1
2 1
2


Output

3


Input

2 1
2 1
10


Output

-5

Note

In the first test both hooks will be used, so Sereja gets 1 + 2 = 3 rubles.

In the second test both hooks will be used but Sereja pays a fine 8 times, so the answer is 3 - 8 = - 5.
import java.awt.Point;
import java.io.BufferedOutputStream;
import java.io.BufferedReader;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.io.OutputStreamWriter;
import java.io.PrintWriter;
import java.math.BigInteger;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collections;
import java.util.Comparator;
import java.util.Currency;
import java.util.HashSet;
import java.util.Iterator;
import java.util.LinkedList;
import java.util.List;
import java.util.PriorityQueue;
import java.util.Set;
import java.util.SortedSet;
import java.util.Stack;
import java.util.StringTokenizer;
import java.util.TreeSet;

import javax.naming.directory.DirContext;

/**
 * @author Jens Staahl
 */

public class Prac {

	// some local config
	// static boolean test = false ;
	private boolean test = System.getProperty("ONLINE_JUDGE") == null;
	static String testDataFile = "testdata.txt";
	// static String testDataFile = "testdata.txt";
	private static String ENDL = "\n";
	// Just solves the acutal kattis-problem

	ZKattio io;
	private void solve() throws Throwable {
		io = new ZKattio(stream);
		int n = io.rint(), d = io.rint();
		int[] val = new int[n];
		for (int i = 0; i < n; i++) {
			val[i] = io.rint();
		}
		Arrays.sort(val);
		int nump = io.rint();
		int curPos = 0;
		int ans = 0;
		for (int i = 0; i < nump; i++) {
			if(curPos < n) {
				ans += val[curPos];
			} else {
				ans -= d;
			}
			curPos ++;
		}
		System.out.println(ans);

	}


	public static void main(String[] args) throws Throwable {
		Prac prac = new Prac();
		prac.solve();
		prac.out.flush();
	}

	public Prac() throws Throwable {
		if (test) {
			stream = new FileInputStream(testDataFile);
		}
	}

	InputStream stream = System.in;
	PrintWriter out = new PrintWriter(new OutputStreamWriter(System.out));// outStream

	public class ZKattio extends PrintWriter {
		public ZKattio(InputStream i) {
			super(new BufferedOutputStream(System.out));
			r = new BufferedReader(new InputStreamReader(i));
		}

		public ZKattio(InputStream i, OutputStream o) {
			super(new BufferedOutputStream(o));
			r = new BufferedReader(new InputStreamReader(i));
		}

		public boolean hasMoreTokens() {
			return peekToken() != null;
		}

		public int rint() {
			return Integer.parseInt(nextToken());
		}

		public double rdouble() {
			return Double.parseDouble(nextToken());
		}

		public long rlong() {
			return Long.parseLong(nextToken());
		}

		public String rstring() {
			return nextToken();
		}

		private BufferedReader r;
		private String line;
		private StringTokenizer st;
		private String token;

		private String peekToken() {
			if (token == null)
				try {
					while (st == null || !st.hasMoreTokens()) {
						line = r.readLine();
						if (line == null)
							return null;
						st = new StringTokenizer(line);
					}
					token = st.nextToken();
				} catch (IOException e) {
				}
			return token;
		}

		private String nextToken() {
			String ans = peekToken();
			token = null;
			return ans;
		}
	}
	// System.out;

}