Given is a string S consisting of `L` and `R`.

Let N be the length of S. There are N squares arranged from left to right, and the i-th character of S from the left is written on the i-th square from the left.

The character written on the leftmost square is always `R`, and the character written on the rightmost square is always `L`.

Initially, one child is standing on each square.

Each child will perform the move below 10^{100} times:

* Move one square in the direction specified by the character written in the square on which the child is standing. `L` denotes left, and `R` denotes right.



Find the number of children standing on each square after the children performed the moves.

Constraints

* S is a string of length between 2 and 10^5 (inclusive).
* Each character of S is `L` or `R`.
* The first and last characters of S are `R` and `L`, respectively.

Input

Input is given from Standard Input in the following format:


S


Output

Print the number of children standing on each square after the children performed the moves, in order from left to right.

Examples

Input

RRLRL


Output

0 1 2 1 1


Input

RRLLLLRLRRLL


Output

0 3 3 0 0 0 1 1 0 2 2 0


Input

RRRLLRLLRRRLLLLL


Output

0 0 3 2 0 2 1 0 0 0 4 4 0 0 0 0
S=raw_input()

ans=[ 0 for _ in range(len(S)) ]

r_cnt=0
l_cnt=0
start=0
prev=None
for i,a in enumerate(S):
	if prev=="L" and a=="R":
		all=r_cnt+l_cnt

		if all%2==0:
			ans[r_blackhole]=all/2
			ans[l_blackhole]=all/2
		else:
			if (r_blackhole-start)%2==0:
				ans[r_blackhole]=all/2+1
				ans[l_blackhole]=all/2
			else:
				ans[r_blackhole]=all/2
				ans[l_blackhole]=all/2+1

		l_cnt, r_cnt=0,1
		l_blackhole , r_blackhole=None,None
		start=i
		
	else:
		if a=="R": r_cnt+=1
		elif a=="L": l_cnt+=1
		if prev=="R" and a=="L":
			r_blackhole , l_blackhole=i-1,i
	prev=a
else:
	all=r_cnt+l_cnt

	if all%2==0:
		ans[r_blackhole]=all/2
		ans[l_blackhole]=all/2
	else:
		if (r_blackhole-start)%2==0:
			ans[r_blackhole]=all/2+1
			ans[l_blackhole]=all/2
		else:
			ans[r_blackhole]=all/2
			ans[l_blackhole]=all/2+1


for i in ans:
	print i,