A bracket sequence is a string that is one of the following:

1. An empty string;
2. The concatenation of `(`, A, and `)` in this order, for some bracket sequence A ;
3. The concatenation of A and B in this order, for some non-empty bracket sequences A and B /



Given are N strings S_i. Can a bracket sequence be formed by concatenating all the N strings in some order?

Constraints

* 1 \leq N \leq 10^6
* The total length of the strings S_i is at most 10^6.
* S_i is a non-empty string consisting of `(` and `)`.

Input

Input is given from Standard Input in the following format:


N
S_1
:
S_N


Output

If a bracket sequence can be formed by concatenating all the N strings in some order, print `Yes`; otherwise, print `No`.

Examples

Input

2
)
(()


Output

Yes


Input

2
)(
()


Output

No


Input

4
((()))
((((((
))))))
()()()


Output

Yes


Input

3
(((
)
)


Output

No
# F

N = int(input())

list_plus = []
list_minus = []
for i in range(N):
    S = input()
    state = 0
    min_state = 0
    for s in S:
        if s == '(':
            state += 1
        else:
            state -= 1
        min_state = min(min_state, state)
    
    if state > 0:
        list_plus.append((min_state, state))
    else:
        list_minus.append((min_state - state, -state))

def compute(arr):
    total_state = 0
    for min_state, state in arr[::-1]:
        if total_state + min_state < 0:
            print('No')
            exit()
        total_state += state
    return total_state

list_plus.sort()
total_state_plus = compute(list_plus)
list_minus.sort()
total_state_minus = compute(list_minus)

print('Yes' if total_state_plus == total_state_minus else 'No')