A bracket sequence is a string that is one of the following:

1. An empty string;
2. The concatenation of `(`, A, and `)` in this order, for some bracket sequence A ;
3. The concatenation of A and B in this order, for some non-empty bracket sequences A and B /



Given are N strings S_i. Can a bracket sequence be formed by concatenating all the N strings in some order?

Constraints

* 1 \leq N \leq 10^6
* The total length of the strings S_i is at most 10^6.
* S_i is a non-empty string consisting of `(` and `)`.

Input

Input is given from Standard Input in the following format:


N
S_1
:
S_N


Output

If a bracket sequence can be formed by concatenating all the N strings in some order, print `Yes`; otherwise, print `No`.

Examples

Input

2
)
(()


Output

Yes


Input

2
)(
()


Output

No


Input

4
((()))
((((((
))))))
()()()


Output

Yes


Input

3
(((
)
)


Output

No
n = int(input())
S = [input() for i in range(n)]
AB = []
for i in range(n):
    a, b = 0, 0
    for c in S[i]:
        if c == '(':
            b += 1
        if c == ')':
            if b > 0:
                b -= 1
            else:
                a += 1
    AB.append((a, b))
AB0 = [(a, b) for a, b in AB if -a + b >= 0]
AB1 = [(a, b) for a, b in AB if -a + b < 0]
AB0.sort()
AB1.sort(key=lambda x: -x[1])
AB = AB0 + AB1
x = 0
for a, b in AB:
    x -= a
    if x < 0:
        print('No')
        exit()
    x += b
if x == 0:
    print('Yes')
else:
    print('No')
