A bracket sequence is a string that is one of the following:

1. An empty string;
2. The concatenation of `(`, A, and `)` in this order, for some bracket sequence A ;
3. The concatenation of A and B in this order, for some non-empty bracket sequences A and B /



Given are N strings S_i. Can a bracket sequence be formed by concatenating all the N strings in some order?

Constraints

* 1 \leq N \leq 10^6
* The total length of the strings S_i is at most 10^6.
* S_i is a non-empty string consisting of `(` and `)`.

Input

Input is given from Standard Input in the following format:


N
S_1
:
S_N


Output

If a bracket sequence can be formed by concatenating all the N strings in some order, print `Yes`; otherwise, print `No`.

Examples

Input

2
)
(()


Output

Yes


Input

2
)(
()


Output

No


Input

4
((()))
((((((
))))))
()()()


Output

Yes


Input

3
(((
)
)


Output

No
N = int(input())
G2,G4 = [],[]
cnt2 = 0
cnt3 = 0
for _ in range(N):
    S = input()
    MIN = 0
    cnt = 0
    for s in list(S):
        if s == '(':
            cnt += 1
        else:
            cnt -= 1
        MIN = min(MIN,cnt)
    if MIN == 0 and cnt >= 0:
        cnt2 += cnt
    if MIN < 0 and cnt >= 0:
        G2.append([MIN,cnt])
    if MIN == cnt and cnt < 0:
        cnt3 += cnt
    if MIN < cnt and cnt < 0:
        G4.append([MIN,cnt])


G2.sort(reverse=True)
for L in G2:
    if cnt2 + L[0] < 0:
        print('No')
        exit()
    else:
        cnt2 += L[1]
for L in G4:
    if cnt2 + L[0] < 0:
        print('No')
        exit()
    else:
        cnt2 += L[1]

cnt2 += cnt3

if cnt2 == 0:
    print('Yes')
else:
    print('No')
