A bracket sequence is a string that is one of the following:

1. An empty string;
2. The concatenation of `(`, A, and `)` in this order, for some bracket sequence A ;
3. The concatenation of A and B in this order, for some non-empty bracket sequences A and B /



Given are N strings S_i. Can a bracket sequence be formed by concatenating all the N strings in some order?

Constraints

* 1 \leq N \leq 10^6
* The total length of the strings S_i is at most 10^6.
* S_i is a non-empty string consisting of `(` and `)`.

Input

Input is given from Standard Input in the following format:


N
S_1
:
S_N


Output

If a bracket sequence can be formed by concatenating all the N strings in some order, print `Yes`; otherwise, print `No`.

Examples

Input

2
)
(()


Output

Yes


Input

2
)(
()


Output

No


Input

4
((()))
((((((
))))))
()()()


Output

Yes


Input

3
(((
)
)


Output

No
def check(pt, brackets):
    brackets.sort(reverse=True)
    for m, t in brackets:
        if pt + m < 0:
            return -1
        pt += t
    return pt


n = int(input())
brackets_p = []  # (始めを0として、( = +1, ) = -1 として、最後はいくつか, 途中の最小値はいくつか)
brackets_m = []
pt = 0
mt = 0
for _ in range(n):
    s = input()
    total = 0
    mini = 0
    for c in s:
        if c == '(':
            total += 1
        else:
            total -= 1
            mini = min(mini, total)

    if total >= 0:
        if mini == 0:
            pt += total
        else:
            brackets_p.append((mini, total))
    else:
        total, mini = -total, mini - total
        if mini == 0:
            mt += total
        else:
            brackets_m.append((mini, total))

pt = check(pt, brackets_p)
mt = check(mt, brackets_m)

if (pt == -1) or (mt == -1) or (pt != mt):
    print('No')
else:
    print('Yes')
