A bracket sequence is a string that is one of the following:

1. An empty string;
2. The concatenation of `(`, A, and `)` in this order, for some bracket sequence A ;
3. The concatenation of A and B in this order, for some non-empty bracket sequences A and B /



Given are N strings S_i. Can a bracket sequence be formed by concatenating all the N strings in some order?

Constraints

* 1 \leq N \leq 10^6
* The total length of the strings S_i is at most 10^6.
* S_i is a non-empty string consisting of `(` and `)`.

Input

Input is given from Standard Input in the following format:


N
S_1
:
S_N


Output

If a bracket sequence can be formed by concatenating all the N strings in some order, print `Yes`; otherwise, print `No`.

Examples

Input

2
)
(()


Output

Yes


Input

2
)(
()


Output

No


Input

4
((()))
((((((
))))))
()()()


Output

Yes


Input

3
(((
)
)


Output

No
import sys
input = sys.stdin.readline
N = int(input())
css = [0] * N
mns = [0] * N
t = [x for x in range(N)]
for x in range(N):
  S = list(input())[: -1]
  for i in range(len(S)):
    if S[i] == "(": css[x] += 1
    if S[i] == ")":
      css[x] -= 1
      mns[x] = min(mns[x], css[x])
if sum(css):
  print("No")
  exit(0)
t.sort(key = lambda x: -10 ** 7 if mns[x] == 0 else -10 ** 7 - mns[x] if css[x] >= 0 else mns[x] - css[x])
l = 0
for i in t:
  if l + mns[i] < 0:
    print("No")
    exit(0)
  l += css[i]
print("Yes")