The problem of hiding a part of a formula and searching for the hidden number is called verbal arithmetic. This time, I'm dealing with an expression in which some numbers in the expression are hidden by X. Enter the following formula and create a program that outputs the result.

Formula

* A simple one-line addition expression in the form of "number string + number string = number string".
* A "number sequence" is a sequence of numbers 0-9 and the letter X.
* It is assumed that the leftmost number in the "number string" with two or more digits is not 0.
* X must be at least one in the entire formula.



result

* The answer to the verbal arithmetic. It is one of 0 to 9 with a value of X such that the formula holds. Suppose there are no more than one answer.
* If there is no answer, the result should be “NA”.



Input

Given multiple datasets. For each dataset, an addition expression containing one or more Xs (a string of up to 126 characters without spaces) is given on one line. The number of datasets does not exceed 150.

Output

For each data set, output the result of the verbal arithmetic on one line. Print the numbers 0-9 or NA.

Example

Input

123+4X6=X79
12X+4X6=X79
XX22+89=X2XX


Output

5
NA
1
#include<iostream>
#include<algorithm>
#include<vector>
#include<stack>
#include<map>
#include<set>
#include<queue>
#include<cstdio>
#include<climits>
#include<cmath>
#include<cstring>
#include<string>
#include<sstream>

#define f first
#define s second
#define mp make_pair

#define REP(i,n) for(int i=0; i<(int)(n); i++)
#define FOR(i,c) for(__typeof((c).begin()) i=(c).begin(); i!=(c).end(); i++)
#define ALL(c) (c).begin(), (c).end()

using namespace std;

typedef unsigned int uint;
typedef long long ll;

class BigInteger{
private:
  void fromStr(const std::string &str){
    int len = str.size();
    int tmp = 0;

    if(str[0] == '+'){
      sign = 1;
      tmp=1;
    }else if (str[0] == '-'){
      sign = -1;
      tmp=1;
    }else{
      sign = 1;
    }

    nums = std::vector<char>(len-tmp);
    for(int i=0;i<len-tmp;i++){
      nums[i]=str[len-1-i]-'0';
    }
  }
public:
  std::vector<char> nums;
  char sign;
  /*
   * constructors
   */
  BigInteger(){sign = 1;nums = std::vector<char>(1,0);}
  BigInteger(const std::vector<char> n,char s){
    nums = n;
    sign = s;
  }
  BigInteger(const std::string &str){
    fromStr(str);
  }
  BigInteger(int n){
    char buff[16];
    sprintf(buff,"%d",n);
    fromStr(std::string(buff));
  }

  int size() const{
    return nums.size();
  }
  int len() const{
    return nums.size();
  }

  char operator [] (int n) const{
    if(n<size() && n>=0)
      return nums[n];
    else
      return 0;
  }

  const std::vector<char> &vec() const{
    return nums;
  }
  char sig() const{
    return sign;
  }

  std::string toString() const{
    std::string ret="";
    if(sign == -1) ret+="-";
    for(int i=nums.size()-1;i>=0;i--){
      ret+=nums[i]+'0';
    }
    return ret;
  }

  void debug() const{
    std::cout << "sign =" << (int)sign << std::endl;
    for(int i=nums.size()-1;i>=0;i--){
      std::cout << (int)nums[i] << " ";
    }
    std::cout << std::endl;
  }
};

bool operator == (const BigInteger &a,const BigInteger &b){
  char as = a.sig();
  char bs = b.sig();
  if(as != bs) return false;

  if(a.len() != b.len()){
    return false;
  }else{
    for(int i=0;i<a.len();i++){
      if(a[i]!=b[i]) return false;
    }
  }
  return true;
}

BigInteger operator + (const BigInteger &a,const BigInteger &b){
  int lena = a.size();
  int lenb = b.size();
  int maxlen = std::max(lena,lenb);
  std::vector<char> v = std::vector<char>(maxlen+1,0);
  int sig = 1;

  for(int i=0;i<maxlen;i++){
    v[i] += a.sig()*a[i]+b.sig()*b[i];
    while(v[i] < 0){
      v[i+1]--;
      v[i]+=10;
      std::cout << "test" << std::endl;
    }
    if(v[i] >=10){
      v[i+1] = v[i]/10;
      v[i]%=10;
    }
  }

  if(v[maxlen]<0){
    sig = -1;
    for(int i=0;i<maxlen;i++){
      v[i]=-v[i];
      while(v[i]<0){
        v[i+1]++;
        v[i]+=10;
      }
    }
    v[maxlen]=-v[maxlen];
  }

  int pos=v.size();
  while(pos!=1 && v[pos-1]==0) pos--;
  if(pos != v.size()) v.resize(pos);

  return BigInteger(v,sig);
}

int main(){
  string str;
  while(cin>>str){
    int posP, posE;
    posP = str.find('+');
    posE = str.find('=');

    string op1, op2, ans;
    op1 = str.substr(0, posP);
    op2 = str.substr(posP+1, posE - posP - 1);
    ans = str.substr(posE+1);
    //cout << op1 << " + " << op2 << " = " << ans << endl;

    bool canZero = true;
    if((op1.size() != 1 && op1[0] == 'X') ||
       (op2.size() != 1 && op2[0] == 'X') ||
       (ans.size() != 1 && ans[0] == 'X'))
      canZero = false;

    int ret = -1;
    for(char c = (canZero ? '0' : '1'); c <= '9'; c++){
      string opt1=op1, opt2=op2, anst=ans;
      while(opt1.find('X') != -1) opt1[opt1.find('X')] = c;
      while(opt2.find('X') != -1) opt2[opt2.find('X')] = c;
      while(anst.find('X') != -1) anst[anst.find('X')] = c;
      BigInteger a(opt1);
      BigInteger b(opt2);
      BigInteger d(anst);

      if(a+b == d){
        ret = c - '0';
        break;
      }
    }
    if(ret == -1) cout << "NA" << endl;
    else cout << ret << endl;
  }
  return 0;
}