A tennis tournament with n participants is running. The participants are playing by an olympic system, so the winners move on and the losers drop out.

The tournament takes place in the following way (below, m is the number of the participants of the current round):

  * let k be the maximal power of the number 2 such that k ≤ m, 
  * k participants compete in the current round and a half of them passes to the next round, the other m - k participants pass to the next round directly, 
  * when only one participant remains, the tournament finishes. 



Each match requires b bottles of water for each participant and one bottle for the judge. Besides p towels are given to each participant for the whole tournament.

Find the number of bottles and towels needed for the tournament.

Note that it's a tennis tournament so in each match two participants compete (one of them will win and the other will lose).

Input

The only line contains three integers n, b, p (1 ≤ n, b, p ≤ 500) — the number of participants and the parameters described in the problem statement.

Output

Print two integers x and y — the number of bottles and towels need for the tournament.

Examples

Input

5 2 3


Output

20 15


Input

8 2 4


Output

35 32

Note

In the first example will be three rounds:

  1. in the first round will be two matches and for each match 5 bottles of water are needed (two for each of the participants and one for the judge), 
  2. in the second round will be only one match, so we need another 5 bottles of water, 
  3. in the third round will also be only one match, so we need another 5 bottles of water. 



So in total we need 20 bottles of water.

In the second example no participant will move on to some round directly.
import java.io.InputStreamReader;
import java.io.IOException;
import java.util.InputMismatchException;
import java.io.BufferedReader;
import java.io.OutputStream;
import java.io.PrintWriter;
import java.util.StringTokenizer;
import java.io.InputStream;

/**
 * Built using CHelper plug-in
 * Actual solution is at the top
 */
public class Main {
	public static void main(String[] args) {
		InputStream inputStream = System.in;
		OutputStream outputStream = System.out;
		QuickScanner in = new QuickScanner(inputStream);
		PrintWriter out = new PrintWriter(outputStream);
		TaskA solver = new TaskA();
		solver.solve(1, in, out);
		out.close();
	}
}

class TaskA {
    public void solve(int testNumber, QuickScanner in, PrintWriter out) {
        int n=in.nextInt();
        int b=in.nextInt();
        int p=in.nextInt();

        int res1=0;
        int res2=p*n;
        while(n>1)
        {
            int pw=n-1;
            pw|=pw>>1;
            pw|=pw>>2;
            pw|=pw>>4;
            pw|=pw>>8;
            pw|=pw>>16;
            pw++;
            res1+=pw/2*(2*b+1);
            n-=pw;
            n+=pw/2;
        }
        out.printf("%d %d\n",res1,res2);
    }
}

class QuickScanner {
    BufferedReader in;
    StringTokenizer token;
    String delim;
    public QuickScanner(InputStream inputStream)
    {
        this.in=new BufferedReader(new InputStreamReader(inputStream));
        this.delim=" \n\t";
        this.token=new StringTokenizer("",delim);
    }

    public boolean hasNext()
    {
        while(!token.hasMoreTokens())
        {
            try {
                String s=in.readLine();
                if(s==null) return false;
                token=new StringTokenizer(s,delim);
            } catch (IOException e) {
                throw new InputMismatchException();
            }
        }
        return true;
    }

    public String next()
    {
        hasNext();
        return token.nextToken();
    }

    public int nextInt()
    {
        return Integer.parseInt(next());
    }

}

