A bracket sequence is a string that is one of the following:

1. An empty string;
2. The concatenation of `(`, A, and `)` in this order, for some bracket sequence A ;
3. The concatenation of A and B in this order, for some non-empty bracket sequences A and B /



Given are N strings S_i. Can a bracket sequence be formed by concatenating all the N strings in some order?

Constraints

* 1 \leq N \leq 10^6
* The total length of the strings S_i is at most 10^6.
* S_i is a non-empty string consisting of `(` and `)`.

Input

Input is given from Standard Input in the following format:


N
S_1
:
S_N


Output

If a bracket sequence can be formed by concatenating all the N strings in some order, print `Yes`; otherwise, print `No`.

Examples

Input

2
)
(()


Output

Yes


Input

2
)(
()


Output

No


Input

4
((()))
((((((
))))))
()()()


Output

Yes


Input

3
(((
)
)


Output

No
def scan(s):
    m = 0
    a = 0
    for c in s:
        if c == '(':
            a += 1
        elif c == ')':
            a -= 1
        m = min(m, a)
    return m, a


def key(v):
    m, a = v
    if a >= 0:
        return 1, m, a
    else:
        return -1, a - m, a

N = int(input())
S = [input() for _ in range(N)]

c = 0
for m, a in sorted([scan(s) for s in S], reverse=True, key=key):
    if c + m < 0:
        c += m
        break
    c += a

if c == 0:
    print('Yes')
else:
    print('No')
