You are given an integer N. Build an undirected graph with N vertices with indices 1 to N that satisfies the following two conditions:

* The graph is simple and connected.
* There exists an integer S such that, for every vertex, the sum of the indices of the vertices adjacent to that vertex is S.



It can be proved that at least one such graph exists under the constraints of this problem.

Constraints

* All values in input are integers.
* 3 \leq N \leq 100

Input

Input is given from Standard Input in the following format:


N


Output

In the first line, print the number of edges, M, in the graph you made. In the i-th of the following M lines, print two integers a_i and b_i, representing the endpoints of the i-th edge.

The output will be judged correct if the graph satisfies the conditions.

Example

Input

3


Output

2
1 3
2 3
import java.util.*;
import java.io.*;
import java.lang.reflect.Array;

import static java.lang.Math.*;
import static java.util.Arrays.*;
import static java.util.Collections.*;
 
public class Main{
    static final long mod=1000000007;
//    static int dx[]={-1,0,1,0};
//    static int dy[]={0,-1,0,1};

    public  static void main(String[] args)   throws Exception, IOException{        
        Reader sc = new Reader(System.in);
        PrintWriter out=new PrintWriter(System.out);

        int n=sc.nextInt();
        int d[]=new int[n+1];
        boolean m[][]=new boolean[n+1][n+1];
        
        for (int i = 1; i <= n; i++) {
			for (int t = i+1; t <= n; t++) {
				m[i][t] = m[t][i] = true;
			}
		}


       int s=n*(n+1)/2;
	   for (int i = 1; i <= n; i++) {
    	   d[i]=s-i;
       }
	   for (int i = 1; i <= n; i++) {
    	   d[i]-=d[n];
    	   if(n%2==0) {
    		   d[i]++;
    	   }
	   }
	   db(d);
	   for (int i = 1; i <= n; i++) {
		   m[i][d[i]]=m[d[i]][i]=false;
	   }
	   int e=0;
       for (int i = 1; i <= n; i++) {
			for (int t = i+1; t <= n; t++) {
				if(m[i][t]) {
					e++;
				}
			}
		}
       out.println(e);
       for (int i = 1; i <= n; i++) {
			for (int t = i+1; t <= n; t++) {
				if(m[i][t]) {
					out.println(i+" "+t);
				}
			}
		}
       


//        out.println();
        out.flush();
    }



    static boolean validpos(int x,int y,int r, int c){
        return x<r && 0<=x && y<c && 0<=y;
    }

    static void db(Object... os){
        System.err.println(Arrays.deepToString(os));
    }  
}

//class P {
//    int id, d;
//    P(int  id, int d) {
//        this.id=id;
//        this.d=d;
//    }
//}

class P implements Comparable<P>{
    int id,T;
    P(int id, int T) {
        this.id=id;
        this.T=T;
    }
    public int compareTo(P p){
        return id-p.id; //des
    }
}

class Reader
{ 
    private BufferedReader x;
    private StringTokenizer st;
    
    public Reader(InputStream in)
    {
        x = new BufferedReader(new InputStreamReader(in));
        st = null;
    }
    public String nextString() throws IOException
    {
        while( st==null || !st.hasMoreTokens() )
            st = new StringTokenizer(x.readLine());
        return st.nextToken();
    }
    public int nextInt() throws IOException
    {
        return Integer.parseInt(nextString());
    }
    public int[] nextIntArray(int size) throws IOException{
    	int r[] = new int[size];
    	for (int i = 0; i < size; i++) {
			r[i] = this.nextInt(); 
		}
    	return r;
    }
    public long[] nextLongArray(int size) throws IOException{
    	long r[] = new long[size];
    	for (int i = 0; i < size; i++) {
			r[i] = this.nextLong(); 
		}
    	return r;
    }
    public long nextLong() throws IOException
    {
        return Long.parseLong(nextString());
    }
    public double nextDouble() throws IOException
    {
        return Double.parseDouble(nextString());
    }
}
