A bracket sequence is a string that is one of the following:

1. An empty string;
2. The concatenation of `(`, A, and `)` in this order, for some bracket sequence A ;
3. The concatenation of A and B in this order, for some non-empty bracket sequences A and B /



Given are N strings S_i. Can a bracket sequence be formed by concatenating all the N strings in some order?

Constraints

* 1 \leq N \leq 10^6
* The total length of the strings S_i is at most 10^6.
* S_i is a non-empty string consisting of `(` and `)`.

Input

Input is given from Standard Input in the following format:


N
S_1
:
S_N


Output

If a bracket sequence can be formed by concatenating all the N strings in some order, print `Yes`; otherwise, print `No`.

Examples

Input

2
)
(()


Output

Yes


Input

2
)(
()


Output

No


Input

4
((()))
((((((
))))))
()()()


Output

Yes


Input

3
(((
)
)


Output

No
def main():
    from sys import stdin
    input = stdin.readline
    n = int(input())
    S = [input() for _ in [0]*n]
    s2 = []
    s3 = []
    for s in S:
        temp = [0, 0]
        m = 0
        now = 0
        for i in s.strip('\n'):
            if i == "(":
                now += 1
            else:
                now -= 1
            m = min(m, now)
        temp = [-m, (s.count("(")-s.count(")"))-m]
        if temp[0] < temp[1]:
            s2.append(temp)
        else:
            s3.append(temp)
    s2.sort(key=lambda x: (x[0]))
    s3.sort(key=lambda x: (-x[1]))
    cnt = 0
    for i, j in s2:
        cnt -= i
        if cnt < 0:
            print("No")
            return
        cnt += j
    for i, j in s3:
        cnt -= i
        if cnt < 0:
            print("No")
            return
        cnt += j
    if cnt != 0:
        print("No")
        return
    print("Yes")


main()
