Little C loves number «3» very much. He loves all things about it.

Now he has a positive integer n. He wants to split n into 3 positive integers a,b,c, such that a+b+c=n and none of the 3 integers is a multiple of 3. Help him to find a solution.

Input

A single line containing one integer n (3 ≤ n ≤ 10^9) — the integer Little C has.

Output

Print 3 positive integers a,b,c in a single line, such that a+b+c=n and none of them is a multiple of 3.

It can be proved that there is at least one solution. If there are multiple solutions, print any of them.

Examples

Input

3


Output

1 1 1

Input

233

Output

77 77 79
# -*- coding: utf-8 -*-
# @Date    : 2018-09-21 20:07:28
# @Author  : raj lath (oorja.halt@gmail.com)
# @Link    : link
# @Version : 1.0.0

from sys import stdin

max_val=int(10e12)
min_val=int(-10e12)

def read_int()     : return int(stdin.readline())
def read_ints()    : return [int(x) for x in stdin.readline().split()]
def read_str()     : return input()
def read_strs()    : return [x for x in stdin.readline().split()]
def divisible_by_3(n)  : return sum([int(x) for x in str(n)]) % 3 == 0


n = read_int()

#solution 1 @eugalt
if n%3 == 2:print(2, 2, n-4)
else:print(1, 1, n-2)