A bracket sequence is a string that is one of the following:

1. An empty string;
2. The concatenation of `(`, A, and `)` in this order, for some bracket sequence A ;
3. The concatenation of A and B in this order, for some non-empty bracket sequences A and B /



Given are N strings S_i. Can a bracket sequence be formed by concatenating all the N strings in some order?

Constraints

* 1 \leq N \leq 10^6
* The total length of the strings S_i is at most 10^6.
* S_i is a non-empty string consisting of `(` and `)`.

Input

Input is given from Standard Input in the following format:


N
S_1
:
S_N


Output

If a bracket sequence can be formed by concatenating all the N strings in some order, print `Yes`; otherwise, print `No`.

Examples

Input

2
)
(()


Output

Yes


Input

2
)(
()


Output

No


Input

4
((()))
((((((
))))))
()()()


Output

Yes


Input

3
(((
)
)


Output

No
N = int(input())
S = [input() for _ in range(N)]

def calc(T):
    now = 0
    ret = 0
    for s in T:
        if s == '(':
            now += 1
        elif s == ')':
            now -= 1
        ret = min(ret, now)
    return ret

H = []
P = []
L = []

for s in S:
    less = -calc(s)
    if less == 0:
        H.append(s)
    else:
        l = s.count('(')
        r = len(s) - l
        if l >= r:
            P.append((less, s))
        else:
            L.append((less - (r - l), s))

P.sort(key=lambda a: a[0])
L.sort(key=lambda a: a[0], reverse=True)
P = [s for _, s in P]
L = [s for _, s in L]
ans = ''.join(H) + ''.join(P) + ''.join(L)

l = ans.count('(')
r = len(ans) - l

if l != r or calc(ans) < 0:
    print('No')
else:
    print('Yes')
