Write a program which manipulates a sequence A = {a1, a2, . . . , an} with the following operations:

* add(s, t, x): add x to as, as+1, ..., at.
* get(i): output the value of ai.



Note that the initial values of ai (i = 1, 2, . . . , n) are 0.

Constraints

* 1 ≤ n ≤ 100000
* 1 ≤ q ≤ 100000
* 1 ≤ s ≤ t ≤ n
* 1 ≤ i ≤ n
* 0 ≤ x ≤ 1000

Input


n q
query1
query2
:
queryq


In the first line, n (the number of elements in A) and q (the number of queries) are given. Then, ith query queryi is given in the following format:


0 s t x


or


1 t


The first digit represents the type of the query. '0' denotes add(s, t, x) and '1' denotes get(i).

Output

For each get operation, print the value.

Examples

Input

3 5
0 1 2 1
0 2 3 2
0 3 3 3
1 2
1 3


Output

3
5


Input

4 3
1 2
0 1 4 1
1 2


Output

0
1
/*
 * s????????????????´??????????s'????????????????´?????????¨????????¨
 * i < l s'[i] = s[i]
 * l <= i <= r s'[i] = s[i] + x*i - x*(l-1)
 * r < i s'[i] = s[i] + x*(r-l+1)
 * ?????????BIT???????????¨??????????£?
 * ????´°????????¬
 * dsl2_g,poj3468??¨??????
 */
#include <iostream>
#include <iomanip>
#include <string>
#include <vector>
#include <algorithm>
#include <numeric>
#include <map>
#include <set>
#include <cstdio>
#include <cstring>
#include <cmath>
#include <bitset>
#define REP(i,n) for (int i=0;i<(n);i++)
#define FOR(i,a,b) for (int i=(a);i<(b);i++)
#define RREP(i,n) for (int i=(n)-1;i>=0;i--)
#define RFOR(i,a,b) for (int i=(a)-1;i>=(b);i--)
#define ll long long
#define ull unsigned long long
int dx[4] = {1, 0, -1, 0};
int dy[4] = {0, 1, 0, -1};
const int INF = 1e9;
const int MOD = 1e9 + 7;

using namespace std;

//BIT
struct BIT{
	int N;
	ll data[200100];
	void init(int n){
		N = n;
		REP(i,N+1)data[i] = 0;
	}
void add(int a,ll w){
	for(int x = a;x <= N;x += x & -x) data[x] +=w;
}
//bit[1] + ... + bit[a]
ll sum(int a){
	ll ret = 0;
	for(int x = a; x > 0; x -= x & -x) ret+= data[x];
	return ret;
}
};

int main(){
  cin.tie(0);
  ios::sync_with_stdio(false);
	int n,q;
	cin >> n >> q;
	BIT bit0,bit1;
	bit0.init(n+1);
	bit1.init(n+1);
	REP(i,q){
		int c;cin >> c;
		if(!c){
			int l,r;cin >> l >> r;
			int x;cin >> x;
			bit0.add(l,x);
			bit0.add(r+1,-x);
			bit1.add(l,-(l-1)*x);
			bit1.add(r+1,r*x);
		}else{
			int a;cin >> a;
			cout << bit0.sum(a)*a + bit1.sum(a) - (bit0.sum(a-1)*(a-1) + bit1.sum(a-1)) << endl;
		}
	}
  return 0;
}