You've got an array a, consisting of n integers. The array elements are indexed from 1 to n. Let's determine a two step operation like that:

  1. First we build by the array a an array s of partial sums, consisting of n elements. Element number i (1 ≤ i ≤ n) of array s equals <image>. The operation x mod y means that we take the remainder of the division of number x by number y. 
  2. Then we write the contents of the array s to the array a. Element number i (1 ≤ i ≤ n) of the array s becomes the i-th element of the array a (ai = si). 



You task is to find array a after exactly k described operations are applied.

Input

The first line contains two space-separated integers n and k (1 ≤ n ≤ 2000, 0 ≤ k ≤ 109). The next line contains n space-separated integers a1, a2, ..., an — elements of the array a (0 ≤ ai ≤ 109).

Output

Print n integers — elements of the array a after the operations are applied to it. Print the elements in the order of increasing of their indexes in the array a. Separate the printed numbers by spaces.

Examples

Input

3 1
1 2 3


Output

1 3 6


Input

5 0
3 14 15 92 6


Output

3 14 15 92 6
// Don't place your source in a package
import javax.swing.*;
import java.lang.reflect.Array;
import java.text.DecimalFormat;
import java.util.*;
import java.lang.*;
import java.io.*;
import java.math.*;
import java.util.stream.Stream;



// Please name your class Main
public class Main {
    static FastScanner fs=new FastScanner();
    static class FastScanner {
        BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
        StringTokenizer st=new StringTokenizer("");
        public String next() {
            while (!st.hasMoreElements())
                try {
                    st=new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            return st.nextToken();
        }
        int Int() {
            return Integer.parseInt(next());
        }

        long Long() {
            return Long.parseLong(next());
        }

        String Str(){
            return next();
        }
    }


    public static void main (String[] args) throws java.lang.Exception {
        PrintWriter out = new PrintWriter(new BufferedWriter(new OutputStreamWriter(System.out)));
        //BufferedReader in = new BufferedReader(new InputStreamReader(System.in));

        //reading /writing file
        //Scanner sc=new Scanner(new File("input.txt"));
        //PrintWriter pr=new PrintWriter("output.txt");


        int T=1;
        for(int t=0;t<T;t++){
            int n=Int(),k=Int();
            int A[]=Arr(n);
            Solution sol=new Solution(out);
            sol.solution(A,k);
        }
        out.close();

    }

    public static int[] Arr(int n){
        int A[]=new int[n];
        for(int i=0;i<n;i++)A[i]=Int();
        return A;
    }
    public static int Int(){
        return fs.Int();
    }
    public static long Long(){
        return fs.Long();
    }
    public static String Str(){
        return fs.Str();
    }

}








class Solution{
    PrintWriter out;
    public Solution(PrintWriter out){
        this.out=out;
    }


    int mod=1000000007;
    public void solution(int A[],int k){
        long fact[]=new long[A.length+10];
        fact[0]=fact[1]=1;
        for(int i=2;i<fact.length;i++){
            fact[i]=fact[i-1]*i;
            fact[i]%=mod;
        }



        for(int i=0;i<A.length;i++){
            long sum=A[i];
            int cnt=0;
            long a=k;
            for(int j=i-1;j>=0;j--){
                cnt++;
                //C(k+cnt,cnt)
                long coe=divide(a,fact[cnt]);
                sum+=(coe*A[j]);
                sum%=mod;
                a=a*(k+cnt);
                a%=mod;
            }
            out.print(sum+" ");
        }
    }


    public long divide(long a,long b){
        BigInteger B= BigInteger.valueOf(b);
        long binverse=modInverse(b,mod);
        return ((a)*(binverse%mod))%mod;
    }

    static long modInverse(long a, long m)
    {
        long m0 = m;
        long y = 0, x = 1;

        if (m == 1)
            return 0;

        while (a > 1) {
            // q is quotient
            long q = a / m;

            long t = m;

            // m is remainder now, process
            // same as Euclid's algo
            m = a % m;
            a = t;
            t = y;

            // Update x and y
            y = x - q * y;
            x = t;
        }

        // Make x positive
        if (x < 0)
            x += m0;

        return x;
    }

}











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