Oleg's favorite subjects are History and Math, and his favorite branch of mathematics is division.

To improve his division skills, Oleg came up with t pairs of integers p_i and q_i and for each pair decided to find the greatest integer x_i, such that: 

  * p_i is divisible by x_i; 
  * x_i is not divisible by q_i. 

Oleg is really good at division and managed to find all the answers quickly, how about you?

Input

The first line contains an integer t (1 ≤ t ≤ 50) — the number of pairs.

Each of the following t lines contains two integers p_i and q_i (1 ≤ p_i ≤ 10^{18}; 2 ≤ q_i ≤ 10^{9}) — the i-th pair of integers.

Output

Print t integers: the i-th integer is the largest x_i such that p_i is divisible by x_i, but x_i is not divisible by q_i.

One can show that there is always at least one value of x_i satisfying the divisibility conditions for the given constraints.

Example

Input


3
10 4
12 6
179 822


Output


10
4
179

Note

For the first pair, where p_1 = 10 and q_1 = 4, the answer is x_1 = 10, since it is the greatest divisor of 10 and 10 is not divisible by 4.

For the second pair, where p_2 = 12 and q_2 = 6, note that 

  * 12 is not a valid x_2, since 12 is divisible by q_2 = 6; 
  * 6 is not valid x_2 as well: 6 is also divisible by q_2 = 6. 

The next available divisor of p_2 = 12 is 4, which is the answer, since 4 is not divisible by 6.
import java.util.*;
import java.io.*;

public class tr0 {
	static PrintWriter out;
	static StringBuilder sb;
	static long mod = (long) 1e9 + 7;
	static long inf = (long) 1e16;
	static int n, m, k;
	static ArrayList<Integer>[] ad;
	static int[][] remove, add;
	static long[][] memo;
	static boolean vis[];
	static long[] inv, ncr[];
	static HashMap<Integer, Integer> hm;
	static int[] pre, suf, Smax[], Smin[];
	static int idmax, idmin;
	static ArrayList<Integer> av;
	static HashMap<Integer, Integer> mm;
	static boolean[] msks;
	static int[] lazy[], lazyCount;
	static int[] dist;
	static int[] g;
	static int s;
	static ArrayList<Integer> gl;
	static int[] a, q;

	public static void main(String[] args) throws Exception {
		Scanner sc = new Scanner(System.in);
		out = new PrintWriter(System.out);
		int t = sc.nextInt();
		while (t-- > 0) {
			long p = sc.nextLong();
			long q = sc.nextLong();
			if (p % q != 0) {
				out.println(p);
				continue;
			} else {
				long ans = p;
				while (ans % q == 0)
					ans /= q;
				TreeMap<Long, Integer> tm = new TreeMap<>();
				for (long i = 2; i * i <= q; i++) {
					int c = 0;
					while (q % i == 0) {
						c++;
						q /= i;
					}
					if (c != 0)
						tm.put(i, c);
				}
				if (q != 1)
					tm.put(q, 1);
				// System.out.println(tm);
				long pr = 1;
				for (long num : tm.keySet()) {
					int cnt = tm.get(num);
					int max = 0;
					while (p % num == 0) {
						max++;
						p /= num;
					}
					pr = Math.max(pr, p * ((long) Math.pow(num, cnt - 1)));
					while (max-- > 0)
						p *= num;
				}
				out.println(pr);
			}
		}
		out.flush();
	}

	static class Scanner {
		StringTokenizer st;
		BufferedReader br;

		public Scanner(InputStream system) {
			br = new BufferedReader(new InputStreamReader(system));
		}

		public Scanner(String file) throws Exception {
			br = new BufferedReader(new FileReader(file));
		}

		public String next() throws IOException {
			while (st == null || !st.hasMoreTokens())
				st = new StringTokenizer(br.readLine());
			return st.nextToken();
		}

		public String nextLine() throws IOException {
			return br.readLine();
		}

		public int nextInt() throws IOException {
			return Integer.parseInt(next());
		}

		public double nextDouble() throws IOException {
			return Double.parseDouble(next());
		}

		public char nextChar() throws IOException {
			return next().charAt(0);
		}

		public Long nextLong() throws IOException {
			return Long.parseLong(next());
		}

		public int[] nextArrInt(int n) throws IOException {
			int[] a = new int[n];
			for (int i = 0; i < n; i++)
				a[i] = nextInt();
			return a;
		}

		public long[] nextArrLong(int n) throws IOException {
			long[] a = new long[n];
			for (int i = 0; i < n; i++)
				a[i] = nextLong();
			return a;
		}

		public int[] nextArrIntSorted(int n) throws IOException {
			int[] a = new int[n];
			Integer[] a1 = new Integer[n];
			for (int i = 0; i < n; i++)
				a1[i] = nextInt();
			Arrays.sort(a1);
			for (int i = 0; i < n; i++)
				a[i] = a1[i].intValue();
			return a;
		}

		public long[] nextArrLongSorted(int n) throws IOException {
			long[] a = new long[n];
			Long[] a1 = new Long[n];
			for (int i = 0; i < n; i++)
				a1[i] = nextLong();
			Arrays.sort(a1);
			for (int i = 0; i < n; i++)
				a[i] = a1[i].longValue();
			return a;
		}

		public boolean ready() throws IOException {
			return br.ready();
		}

		public void waitForInput() throws InterruptedException {
			Thread.sleep(3000);
		}
	}
}