Oleg's favorite subjects are History and Math, and his favorite branch of mathematics is division.

To improve his division skills, Oleg came up with t pairs of integers p_i and q_i and for each pair decided to find the greatest integer x_i, such that: 

  * p_i is divisible by x_i; 
  * x_i is not divisible by q_i. 

Oleg is really good at division and managed to find all the answers quickly, how about you?

Input

The first line contains an integer t (1 ≤ t ≤ 50) — the number of pairs.

Each of the following t lines contains two integers p_i and q_i (1 ≤ p_i ≤ 10^{18}; 2 ≤ q_i ≤ 10^{9}) — the i-th pair of integers.

Output

Print t integers: the i-th integer is the largest x_i such that p_i is divisible by x_i, but x_i is not divisible by q_i.

One can show that there is always at least one value of x_i satisfying the divisibility conditions for the given constraints.

Example

Input


3
10 4
12 6
179 822


Output


10
4
179

Note

For the first pair, where p_1 = 10 and q_1 = 4, the answer is x_1 = 10, since it is the greatest divisor of 10 and 10 is not divisible by 4.

For the second pair, where p_2 = 12 and q_2 = 6, note that 

  * 12 is not a valid x_2, since 12 is divisible by q_2 = 6; 
  * 6 is not valid x_2 as well: 6 is also divisible by q_2 = 6. 

The next available divisor of p_2 = 12 is 4, which is the answer, since 4 is not divisible by 6.
    import java.io.PrintWriter;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Comparator;
import java.util.Scanner;
import java.util.Stack;

public class TP {

  public static PrintWriter out = new PrintWriter(System.out);
  public static Scanner in = new Scanner(System.in);

  public static void main(String[] args) {
    int t = ni();
    while (t-- > 0) solve();
    out.flush();
  }

  static int[] primes = sieveEratosthenes(100000);

  private static void solve() {

    long P = nl(), Q = nl();
    if (P % Q != 0) {
      out.println(P);
      return;
    }
    int[] fs = facs((int) Q, primes);
    long ans = 1;
    for (int f : fs) {
      long R = P;
      while (R % f == 0) {
        R /= f;
        if (R % Q != 0) {
          ans = Math.max(ans, R);
          break;
        }
      }
    }
    out.println(ans);
  }

  public static int[] facs(int n, int[] primes) {
    int[] ret = new int[9];
    int rp = 0;
    for (int p : primes) {
      if (p * p > n) break;
      int i;
      i = 0;
      while (n % p == 0) {
        n /= p;
        i++;
      }
      if (i > 0) ret[rp++] = p;
    }
    if (n != 1) ret[rp++] = n;
    return Arrays.copyOf(ret, rp);
  }

  public static int[] sieveEratosthenes(int n) {
    if (n <= 32) {
      int[] primes = {2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31};
      for (int i = 0; i < primes.length; i++) {
        if (n < primes[i]) {
          return Arrays.copyOf(primes, i);
        }
      }
      return primes;
    }

    int u = n + 32;
    double lu = Math.log(u);
    int[] ret = new int[(int) (u / lu + u / lu / lu * 1.5)];
    ret[0] = 2;
    int pos = 1;

    int[] isnp = new int[(n + 1) / 32 / 2 + 1];
    int sup = (n + 1) / 32 / 2 + 1;

    int[] tprimes = {3, 5, 7, 11, 13, 17, 19, 23, 29, 31};
    for (int tp : tprimes) {
      ret[pos++] = tp;
      int[] ptn = new int[tp];
      for (int i = (tp - 3) / 2; i < tp << 5; i += tp) ptn[i >> 5] |= 1 << (i & 31);
      for (int j = 0; j < sup; j += tp) {
        for (int i = 0; i < tp && i + j < sup; i++) {
          isnp[j + i] |= ptn[i];
        }
      }
    }

    // 3,5,7
    // 2x+3=n
    int[] magic = {
      0, 1, 23, 2, 29, 24, 19, 3, 30, 27, 25, 11, 20, 8, 4, 13, 31, 22, 28, 18, 26, 10, 7, 12, 21,
      17, 9, 6, 16, 5, 15, 14
    };
    int h = n / 2;
    for (int i = 0; i < sup; i++) {
      for (int j = ~isnp[i]; j != 0; j &= j - 1) {
        int pp = i << 5 | magic[(j & -j) * 0x076be629 >>> 27];
        int p = 2 * pp + 3;
        if (p > n) break;
        ret[pos++] = p;
        if ((long) p * p > n) continue;
        for (int q = (p * p - 3) / 2; q <= h; q += p) isnp[q >> 5] |= 1 << q;
      }
    }

    return Arrays.copyOf(ret, pos);
  }

  private static int ni() {
    return in.nextInt();
  }

  private static int[] na(int n) {
    int[] a = new int[n];
    for (int i = 0; i < n; i++) a[i] = ni();
    return a;
  }

  private static long[] nal(int n) {
    long[] a = new long[n];
    for (int i = 0; i < n; i++) a[i] = nl();
    return a;
  }

  private static long nl() {
    return in.nextLong();
  }

  private float nf() {
    return in.nextFloat();
  }

  private static double nd() {
    return in.nextDouble();
  }
}
