A bracket sequence is a string that is one of the following:

1. An empty string;
2. The concatenation of `(`, A, and `)` in this order, for some bracket sequence A ;
3. The concatenation of A and B in this order, for some non-empty bracket sequences A and B /



Given are N strings S_i. Can a bracket sequence be formed by concatenating all the N strings in some order?

Constraints

* 1 \leq N \leq 10^6
* The total length of the strings S_i is at most 10^6.
* S_i is a non-empty string consisting of `(` and `)`.

Input

Input is given from Standard Input in the following format:


N
S_1
:
S_N


Output

If a bracket sequence can be formed by concatenating all the N strings in some order, print `Yes`; otherwise, print `No`.

Examples

Input

2
)
(()


Output

Yes


Input

2
)(
()


Output

No


Input

4
((()))
((((((
))))))
()()()


Output

Yes


Input

3
(((
)
)


Output

No
n=int(input())
A=[]
B=[]
c=0
for i in range(n):
  S=input()
  a=0
  b=0
  for j in range(len(S)):
    if S[j]=="(":
      a=a+1
    else:
      a=a-1
      if a<b:
        b=a
  b=b*-1
  if b==0:
    c=c+a
  elif a>=0:
    B.append([b,-1*a])
  else:
    A.append([b+a,a])
A.sort()
B.sort()
f=0
for i in range(len(B)):
  if c-B[i][0]<0:
    f=1
  c=c-B[i][1]
d=0
for i in range(len(A)):
  if d-A[i][0]<0:
    f=1
  d=d-A[i][1]
if c!=d:
  f=1
if f==0:
  print("Yes")
else:
  print("No")