You are given an equation: 

Ax2 + Bx + C = 0. 

Your task is to find the number of distinct roots of the equation and print all of them in ascending order.

Input

The first line contains three integer numbers A, B and C ( - 105 ≤ A, B, C ≤ 105). Any coefficient may be equal to 0.

Output

In case of infinite root count print the only integer -1. In case of no roots print the only integer 0. In other cases print the number of root on the first line and the roots on the following lines in the ascending order. Print roots with at least 5 digits after the decimal point.

Examples

Input

1 -5 6


Output

2
2.0000000000
3.0000000000
import java.io.BufferedReader;
import java.io.FileReader;
import java.io.FileWriter;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.io.PrintWriter;
import java.io.Reader;
import java.io.StreamTokenizer;
import java.io.Writer;
import java.util.Locale;

public class Main {
    public static void main(String[] args) throws IOException {
        new Main().run();
    }
    StreamTokenizer in; PrintWriter out; boolean oj;
    BufferedReader br; Reader reader; Writer writer;

    void init() throws IOException {
        Locale.setDefault(Locale.US);
        oj = System.getProperty("ONLINE_JUDGE") != null;
        reader = oj ? new InputStreamReader(System.in) : new FileReader("input.txt");
        writer = oj ? new OutputStreamWriter(System.out) : new FileWriter("output.txt");
        br = new BufferedReader(reader);
        in = new StreamTokenizer(br);
        out = new PrintWriter(writer);
    }

    void run() throws IOException {
        long beginTime = System.currentTimeMillis();
        init();
        solve();
        if(!oj){
            long endTime = System.currentTimeMillis();
            if (!oj) {
                System.out.println("Memory used = " + (Runtime.getRuntime().totalMemory() - Runtime.getRuntime().freeMemory()));
                System.out.println("Running time = " + (endTime - beginTime));
            }
        }
        out.flush();
    }
    
    void solve() throws IOException {
        double a=nD(), b=nD(), c=nD(), x1, x2;
        double D = b*b-4*a*c; final double e=1e-6;
        if(a==0){
            if(b==0){
                out.printf("%d\n", c==0?-1:0);
            }else{
                out.printf("1\n%.5f\n", -1.0*c/b);
            }
        }else if(D>e){
            D = Math.sqrt(D); x1 = 0.5*(-b-D)/a; x2 = 0.5*(-b+D)/a;
            out.printf("2\n%.5f\n%.5f\n", Math.min(x1, x2), Math.max(x1, x2));
        }else if(D<-e){
            out.printf("0\n");
        }else{
            out.printf("1\n%.5f\n", 0.5*(-b)/a);
        }
    }
    
    int nI() throws IOException {
        in.nextToken();
        return (int) in.nval;
    }

    long nL() throws IOException {
        in.nextToken();
        return (long) in.nval;
    }

    String nS() throws IOException {
        in.nextToken();
        return in.sval;
    }

    double nD() throws IOException {
        in.nextToken();
        return in.nval;
    }
}