Let s(x) be sum of digits in decimal representation of positive integer x. Given two integers n and m, find some positive integers a and b such that 

  * s(a) ≥ n, 
  * s(b) ≥ n, 
  * s(a + b) ≤ m. 

Input

The only line of input contain two integers n and m (1 ≤ n, m ≤ 1129).

Output

Print two lines, one for decimal representation of a and one for decimal representation of b. Both numbers must not contain leading zeros and must have length no more than 2230.

Examples

Input

6 5


Output

6 
7


Input

8 16


Output

35 
53

Note

In the first sample, we have n = 6 and m = 5. One valid solution is a = 6, b = 7. Indeed, we have s(a) = 6 ≥ n and s(b) = 7 ≥ n, and also s(a + b) = s(13) = 4 ≤ m.
import java.util.*;
public class HelloWorld{

     public static void main(String []args){
        Scanner sc=new Scanner(System.in);
        int len=0;
        int a[]=new int[2230];
        int n=sc.nextInt();
        int m=sc.nextInt();
        /*if(n<10)
        {
            if(n>5)
            {
            System.out.println(n%5+""+5);
            System.out.println(n%5+""+5);
            }else
            {
                System.out.println(n);
                System.out.println(n);
            }
        }else
        {*/
        int i;
        int num=n;
        a[len]=5;
        num-=5;
        while(num>0)
        {
            len++;
            a[len]=4;
            num-=4;
        }
        //System.out.println(len);
        for(i=0;i<=len;i++)
        System.out.print(5+"");
        System.out.println();
        for(i=len;i>=0;i--)
        System.out.print(a[i]+"");
        
     }
}