A recently found Ancient Prophesy is believed to contain the exact Apocalypse date. The prophesy is a string that only consists of digits and characters "-".

We'll say that some date is mentioned in the Prophesy if there is a substring in the Prophesy that is the date's record in the format "dd-mm-yyyy". We'll say that the number of the date's occurrences is the number of such substrings in the Prophesy. For example, the Prophesy "0012-10-2012-10-2012" mentions date 12-10-2012 twice (first time as "0012-10-2012-10-2012", second time as "0012-10-2012-10-2012").

The date of the Apocalypse is such correct date that the number of times it is mentioned in the Prophesy is strictly larger than that of any other correct date.

A date is correct if the year lies in the range from 2013 to 2015, the month is from 1 to 12, and the number of the day is strictly more than a zero and doesn't exceed the number of days in the current month. Note that a date is written in the format "dd-mm-yyyy", that means that leading zeroes may be added to the numbers of the months or days if needed. In other words, date "1-1-2013" isn't recorded in the format "dd-mm-yyyy", and date "01-01-2013" is recorded in it.

Notice, that any year between 2013 and 2015 is not a leap year.

Input

The first line contains the Prophesy: a non-empty string that only consists of digits and characters "-". The length of the Prophesy doesn't exceed 105 characters.

Output

In a single line print the date of the Apocalypse. It is guaranteed that such date exists and is unique.

Examples

Input

777-444---21-12-2013-12-2013-12-2013---444-777


Output

13-12-2013
import re
s = raw_input()
x=re.finditer(r'(?=(\d\d-\d\d-\d\d\d\d))',s)
ans={}
days= [0,31,28,31,30,31,30,31,31,30,31,30,31]
for i in x:
	i=i.group(1)
	day=i[:2]
	month = i[3:5]
	year = i[6:]
	#print i, day, month, year
	if (int(year) >= 2013 and int(year) <= 2015) and (int(month) >0 and int(month)<13) and (int(day)>0 and int(day) <= days[int(month)]) :
		if i in ans:
			ans[i]+=1
		else:
			ans[i]=1
max_cnt=0
max_ans=""
#print ans
for i in ans:
	if ans[i]>max_cnt:
		max_ans = i
		max_cnt = ans[i]

#print ans
print max_ans