AtCoDeer is thinking of painting an infinite two-dimensional grid in a checked pattern of side K. Here, a checked pattern of side K is a pattern where each square is painted black or white so that each connected component of each color is a K × K square. Below is an example of a checked pattern of side 3:

cba927b2484fad94fb5ff7473e9aadef.png

AtCoDeer has N desires. The i-th desire is represented by x_i, y_i and c_i. If c_i is `B`, it means that he wants to paint the square (x_i,y_i) black; if c_i is `W`, he wants to paint the square (x_i,y_i) white. At most how many desires can he satisfy at the same time?

Constraints

* 1 ≤ N ≤ 10^5
* 1 ≤ K ≤ 1000
* 0 ≤ x_i ≤ 10^9
* 0 ≤ y_i ≤ 10^9
* If i ≠ j, then (x_i,y_i) ≠ (x_j,y_j).
* c_i is `B` or `W`.
* N, K, x_i and y_i are integers.

Input

Input is given from Standard Input in the following format:


N K
x_1 y_1 c_1
x_2 y_2 c_2
:
x_N y_N c_N


Output

Print the maximum number of desires that can be satisfied at the same time.

Examples

Input

4 3
0 1 W
1 2 W
5 3 B
5 4 B


Output

4


Input

2 1000
0 0 B
0 1 W


Output

2


Input

6 2
1 2 B
2 1 W
2 2 B
1 0 B
0 6 W
4 5 W


Output

4
#include<iostream>
#include<cstdio>
#include<ctype.h>
using namespace std;
inline int read(){
    int x=0,f=0;char ch=getchar();
    while(!isdigit(ch))f|=ch=='-',ch=getchar();
    while(isdigit(ch))x=x*10+(ch^48),ch=getchar();
    return f?-x:x;
}
int a[1007][1007];
char c;
int main(){
	int n=read(),k=read(),ans=0;
	for(int i=0;i<n;++i){
		int x=read()%(k+k)+1,y=read()%(k+k)+1;cin>>c;
		int f=c=='B';
		if(x>k)x-=k,f^=1;
		if(y>k)y-=k,f^=1;
		if(f)a[1][1]++,a[x][1]--,a[1][y]--,a[x][y]+=2;
		else a[1][y]++,a[x][1]++,a[x][y]-=2;
	}
	for(int i=1;i<=k;++i)for(int j=1;j<=k;++j){
		a[i][j]+=a[i][j-1]+a[i-1][j]-a[i-1][j-1];
		ans=max(ans,max(n-a[i][j],a[i][j]));
	}
	printf("%d\n",ans);
}