problem

Given $ N $ different natural numbers $ a_i $. I decided to make a pair by choosing a different natural number from the given natural numbers. Output one pair that can be created with a value difference that is a multiple of $ N -1 $.

It should be noted that such a pair always exists.





Example

Input

5
1 2 4 7 10


Output

2 10
#include <iostream>
#include <cmath>
#include <vector>
#include <string>
#include <map>
#include <algorithm>
#include <tuple>
#include <set>
#include <stack>
#include <queue>
#include <deque>
#include <cstdio>
#include <bitset>
#include <limits.h>
#define REP(i, n) for(LL i = 0;i < n;i++)
#define REPR(i, n) for(LL i = n;i >= 0;i--)
#define FOR(i, m, n) for(LL i = m;i < n;i++)
#define FORR(i, m, n) for(LL i = m;i >= n;i--)
#define SORT(v, n) sort(v, v+n);
#define VSORT(v) sort(v.begin(), v.end());
#define pb(a) push_back(a)
#define all(x) (x).begin(),(x).end()
#define INF (LL)1e15
#define MOD 1000000007
using namespace std;
typedef long long LL;
typedef pair<int, int> P;
typedef pair<LL, LL> LP;
typedef pair<int, P> PP;
typedef pair<LL, LP> LPP;
int dy[]={0, 0, 1, -1, 0};
int dx[]={1, -1, 0, 0, 0};

//#define int long long

/*************** using variables ***************/
int n;
vector<int> a;
/**********************************************/

signed main(){
    cin >> n;
    a.resize(n);
    REP(i, n) cin >> a[i];
    REP(i, n){
        REP(j, n){
            if(i == j) continue;
            if(abs(a[i]-a[j]) % (n-1) == 0){
                cout << a[i] << " " << a[j] << endl;
                return 0;
            }
        }
    }
}

