A recently found Ancient Prophesy is believed to contain the exact Apocalypse date. The prophesy is a string that only consists of digits and characters "-".

We'll say that some date is mentioned in the Prophesy if there is a substring in the Prophesy that is the date's record in the format "dd-mm-yyyy". We'll say that the number of the date's occurrences is the number of such substrings in the Prophesy. For example, the Prophesy "0012-10-2012-10-2012" mentions date 12-10-2012 twice (first time as "0012-10-2012-10-2012", second time as "0012-10-2012-10-2012").

The date of the Apocalypse is such correct date that the number of times it is mentioned in the Prophesy is strictly larger than that of any other correct date.

A date is correct if the year lies in the range from 2013 to 2015, the month is from 1 to 12, and the number of the day is strictly more than a zero and doesn't exceed the number of days in the current month. Note that a date is written in the format "dd-mm-yyyy", that means that leading zeroes may be added to the numbers of the months or days if needed. In other words, date "1-1-2013" isn't recorded in the format "dd-mm-yyyy", and date "01-01-2013" is recorded in it.

Notice, that any year between 2013 and 2015 is not a leap year.

Input

The first line contains the Prophesy: a non-empty string that only consists of digits and characters "-". The length of the Prophesy doesn't exceed 105 characters.

Output

In a single line print the date of the Apocalypse. It is guaranteed that such date exists and is unique.

Examples

Input

777-444---21-12-2013-12-2013-12-2013---444-777


Output

13-12-2013
from collections import defaultdict
t = input()
s = defaultdict(int)
for i in range(len(t) - 9):
    if t[i + 2] == '-' and t[i + 5: i + 9] == '-201' and '2' < t[i + 9] < '6' and '32' > t[i: i + 2] > '00' and '13' > t[i + 3: i + 5] > '00':
        if t[i + 3: i + 5].isdigit():
            if t[i: i + 2].isdigit():
                if t[i: i + 2] < '29': s[t[i: i + 10]] += 1
                elif t[i: i + 2] < '31': 
                    if not (t[i + 3: i + 5] == '02'): s[t[i: i + 10]] += 1
                elif not (t[i + 3: i + 5] in ['04', '06', '09', '11']): s[t[i: i + 10]] += 1
m = max(s.values())
for i in s:
    if s[i] == m:
        print(i)
        break