A recently found Ancient Prophesy is believed to contain the exact Apocalypse date. The prophesy is a string that only consists of digits and characters "-".

We'll say that some date is mentioned in the Prophesy if there is a substring in the Prophesy that is the date's record in the format "dd-mm-yyyy". We'll say that the number of the date's occurrences is the number of such substrings in the Prophesy. For example, the Prophesy "0012-10-2012-10-2012" mentions date 12-10-2012 twice (first time as "0012-10-2012-10-2012", second time as "0012-10-2012-10-2012").

The date of the Apocalypse is such correct date that the number of times it is mentioned in the Prophesy is strictly larger than that of any other correct date.

A date is correct if the year lies in the range from 2013 to 2015, the month is from 1 to 12, and the number of the day is strictly more than a zero and doesn't exceed the number of days in the current month. Note that a date is written in the format "dd-mm-yyyy", that means that leading zeroes may be added to the numbers of the months or days if needed. In other words, date "1-1-2013" isn't recorded in the format "dd-mm-yyyy", and date "01-01-2013" is recorded in it.

Notice, that any year between 2013 and 2015 is not a leap year.

Input

The first line contains the Prophesy: a non-empty string that only consists of digits and characters "-". The length of the Prophesy doesn't exceed 105 characters.

Output

In a single line print the date of the Apocalypse. It is guaranteed that such date exists and is unique.

Examples

Input

777-444---21-12-2013-12-2013-12-2013---444-777


Output

13-12-2013
s=input()
def correct(s):
    c={2,5}
    for i in range(10):
        if i not in c:
            if s[i]=="-":
                return False
        else:
            if s[i]!="-":
                return False

###check for day
    if int(s[0:2])<32 and int(s[0:2])>0:
        pass
    else:
        return False

##check for month
    if int(s[3:5])>0 and int(s[3:5])<13:
        pass
    else:
        return False
#check for year
    y={"2013","2014","2015"}
    if s[6:] not in y:
        return False
    if s[0:2]=="31":
        m={"01","03","05","07","08","10","12"}
        if s[3:5] not in m:
            return False
    if s[3:5]=="02":
        if int(s[0:2])>28:
            return False
    return True


dict={}
n=len(s)
i=0
while i<=n-10:
    if correct(s[i:i+10])==True:
        if s[i:i+10] in dict:
            dict[s[i:i+10]]+=1
        else:
            dict[s[i:i+10]]=1
        i+=8
    else:
        i+=1
m=0
ans=None
for key,item in dict.items():
    if item>m:
        m=item
        ans=key
print(ans)