There are N squares arranged in a row, numbered 1, 2, ..., N from left to right. You are given a string S of length N consisting of `.` and `#`. If the i-th character of S is `#`, Square i contains a rock; if the i-th character of S is `.`, Square i is empty.

In the beginning, Snuke stands on Square A, and Fnuke stands on Square B.

You can repeat the following operation any number of times:

* Choose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.



You want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.

Determine whether this is possible.

Constraints

* 4 \leq N \leq 200\ 000
* S is a string of length N consisting of `.` and `#`.
* 1 \leq A, B, C, D \leq N
* Square A, B, C and D do not contain a rock.
* A, B, C and D are all different.
* A < B
* A < C
* B < D

Input

Input is given from Standard Input in the following format:


N A B C D
S


Output

Print `Yes` if the objective is achievable, and `No` if it is not.

Examples

Input

7 1 3 6 7
.#..#..


Output

Yes


Input

7 1 3 7 6
.#..#..


Output

No


Input

15 1 3 15 13
...#.#...#.#...


Output

Yes
// https://atcoder.jp/contests/agc034/tasks/agc034_a

import java.util.Scanner;

class Main{
    public static void main(String[] args){
        Scanner sc = new Scanner(System.in);
        int N = sc.nextInt();
        int A = sc.nextInt();
        int B = sc.nextInt();
        int C = sc.nextInt();
        int D = sc.nextInt();
        String S = sc.next();
        sc.close();
        boolean pass = true;
        for (int i=A+1;i<C-1;i++){
            String s1 = String.valueOf(S.charAt(i-1));
            String s2 = String.valueOf(S.charAt(i));
            if (s1.equals("#") && s2.equals("#")){
                System.out.println("No");
                return;
            }
        }
        for (int i=B+1;i<D-1;i++){
            String s1 = String.valueOf(S.charAt(i-1));
            String s2 = String.valueOf(S.charAt(i));
            if (s1.equals("#") && s2.equals("#")){
                System.out.println("No");
                return;
            }
        }
        if (C>D){
            for (int i=B-1;i<D;i++){
                String s1 = String.valueOf(S.charAt(i-1));
                String s2 = String.valueOf(S.charAt(i));
                String s3 = String.valueOf(S.charAt(i+1));
                if (s1.equals(".") && s2.equals(".") && s3.equals(".")){
                    pass = true;
                    break;
                } else {
                    pass = false;
                }
            }
        }
        if (pass){
            System.out.println("Yes");
        } else {
            System.out.println("No");
        }
    }
}