Let s(x) be sum of digits in decimal representation of positive integer x. Given two integers n and m, find some positive integers a and b such that 

  * s(a) ≥ n, 
  * s(b) ≥ n, 
  * s(a + b) ≤ m. 

Input

The only line of input contain two integers n and m (1 ≤ n, m ≤ 1129).

Output

Print two lines, one for decimal representation of a and one for decimal representation of b. Both numbers must not contain leading zeros and must have length no more than 2230.

Examples

Input

6 5


Output

6 
7


Input

8 16


Output

35 
53

Note

In the first sample, we have n = 6 and m = 5. One valid solution is a = 6, b = 7. Indeed, we have s(a) = 6 ≥ n and s(b) = 7 ≥ n, and also s(a + b) = s(13) = 4 ≤ m.
import java.util.*;


public class JavaApplication8 {

    static String[] get(int n, int m){
        String[] s = new String[2] ;
        
        s[0] = "" ;
        s[1] = "" ;
        
        
        
        int  l = (n / 4) + 1 ;
        
        for(int i=1;i<=l;i++){
            s[0] += "5" ;
        }
        
        for(int i=1;i<=l-1;i++){
            s[1]+="4" ;
        }
        
        s[1]+=5;
        
        return s;
    }
            
    public static void main(String[] args) {
       Scanner in = new Scanner(System.in) ;
       int n = in.nextInt() ;
       int m = in.nextInt() ;
       
       String[] s = get(n, m) ;
       
       System.out.println(s[0]+"\n"+s[1]) ;
    }
}