Anfisa the monkey learns to type. She is yet unfamiliar with the "space" key and can only type in lower-case Latin letters. Having typed for a fairly long line, Anfisa understood that it would be great to divide what she has written into k lines not shorter than a and not longer than b, for the text to resemble human speech more. Help Anfisa.

Input

The first line contains three integers k, a and b (1 ≤ k ≤ 200, 1 ≤ a ≤ b ≤ 200). The second line contains a sequence of lowercase Latin letters — the text typed by Anfisa. It is guaranteed that the given line is not empty and its length does not exceed 200 symbols.

Output

Print k lines, each of which contains no less than a and no more than b symbols — Anfisa's text divided into lines. It is not allowed to perform any changes in the text, such as: deleting or adding symbols, changing their order, etc. If the solution is not unique, print any of them. If there is no solution, print "No solution" (without quotes). 

Examples

Input

3 2 5
abrakadabra


Output

ab
rakad
abra


Input

4 1 2
abrakadabra


Output

No solution
/**
 * Created by IntelliJ IDEA.
 * User: aircube
 * Date: 11.01.11
 * Time: 4:14
 * To change this template use File | Settings | File Templates.
 */

import sun.nio.cs.ext.Big5;

import java.io.*;
import java.math.BigInteger;
import java.util.*;


public class Template {
    BufferedReader br;
    PrintWriter out;
    StringTokenizer st;

    public static void main(String[] args) throws IOException {
        new Template().run();
    }

    void run() throws IOException {
        br = new BufferedReader(new InputStreamReader(System.in));
        st = null;
        out = new PrintWriter(System.out);
        solve();
        br.close();
        out.close();
    }


    void solve() throws  IOException {
        int k = nextInt();
        int a = nextInt();
        int b = nextInt();
        String s = nextToken();
        int n = s.length();
        if(n / k < a|| (n + k - 1)/ k > b) {
            out.print("No solution");
        } else {
            int each = n / k ;
            int m = n % k ;
            int done[] = new int[k];
            Arrays.fill(done, each);
            for(int i =0 ; i < m; ++i) {
                done[i] ++ ;
            }
            int ptr = 0;
            for(int i = 0; i < k; ++i) {
                for(int j = 0; j < done[i]; ++j, ++ptr) {
                    out.print(s.charAt(ptr));
                }
                out.println();
            }
        }
    }

    int nextInt() throws IOException {
        return Integer.parseInt(nextToken());
    }

    double nextDouble() throws IOException {
        return Double.parseDouble(nextToken());
    }

    long nextLong() throws IOException {
        return Long.parseLong(nextToken());
    }
    BigInteger nextBigInteger() throws IOException {
        return new BigInteger(nextToken());
    }
    String nextToken() throws IOException {
        while (st == null || !st.hasMoreTokens()) {
            st = new StringTokenizer(br.readLine());
        }
        return st.nextToken();
    }
}