Anfisa the monkey learns to type. She is yet unfamiliar with the "space" key and can only type in lower-case Latin letters. Having typed for a fairly long line, Anfisa understood that it would be great to divide what she has written into k lines not shorter than a and not longer than b, for the text to resemble human speech more. Help Anfisa.

Input

The first line contains three integers k, a and b (1 ≤ k ≤ 200, 1 ≤ a ≤ b ≤ 200). The second line contains a sequence of lowercase Latin letters — the text typed by Anfisa. It is guaranteed that the given line is not empty and its length does not exceed 200 symbols.

Output

Print k lines, each of which contains no less than a and no more than b symbols — Anfisa's text divided into lines. It is not allowed to perform any changes in the text, such as: deleting or adding symbols, changing their order, etc. If the solution is not unique, print any of them. If there is no solution, print "No solution" (without quotes). 

Examples

Input

3 2 5
abrakadabra


Output

ab
rakad
abra


Input

4 1 2
abrakadabra


Output

No solution
import java.util.Scanner;


public class Main{
    static String palabra;
    static int k, a , b;
    public static void main(String [] args){
        Scanner sc = new Scanner (System.in);
        k = sc.nextInt();
        a = sc.nextInt();
        b = sc.nextInt();
        palabra = sc.next();    
        int lon = palabra.length();
        if(lon >= k*a && lon <= k*b){
            imprimir(k,palabra,a,b);                        
        }
        else{
            System.out.println("No solution");
        }
    }
    public static void imprimir(int k, String s, int a, int b){
        int r,u;
        for (int i = 0; i < k; i++)
        {
            r = s.length() % (k-i);
            u = s.length()/(k-i);
            if (r != 0){
                u++;                
            }
            int cont = 0;
            while (u-- != 0) 
                System.out.print(s.charAt(cont++));
            System.out.println ("");
            s = s.substring(cont);
        }
    }     
}