problem

Given $ N $ different natural numbers $ a_i $. I decided to make a pair by choosing a different natural number from the given natural numbers. Output one pair that can be created with a value difference that is a multiple of $ N -1 $.

It should be noted that such a pair always exists.





Example

Input

5
1 2 4 7 10


Output

2 10
#include<iostream>
#include<vector>
#include<algorithm>
#include<utility>
#include<string>
#include<cmath>
#include<cstring>
#include<queue>
#include<map>
#include<climits>
#include<set>


using namespace std;
typedef pair<int, int> pii;
typedef long long int ll;
typedef pair<ll, ll> pll;
int dx[4] = { 1,0,0,-1 };
int dy[4] = { 0,1,-1,0 };

#define ARRAY_MAX 100005

const ll INF = 1e9 + 7;
const ll MOD = 1e9 + 7;

int main() {

	int n;
	cin >> n;
	vector<int> a(n);
	for (int i = 0; i < n; i++)
	{
		cin >> a[i];
	}

	sort(a.begin(), a.end());

	for (int i = 0; i < n; i++)
	{
		for (int j = i+1; j < n; j++)
		{
			if ((a[j] - a[i]) % (n - 1) == 0)
			{
				cout << a[i] << " " << a[j] << endl;
				return 0;
			}
		}
	}



}
