A recently found Ancient Prophesy is believed to contain the exact Apocalypse date. The prophesy is a string that only consists of digits and characters "-".

We'll say that some date is mentioned in the Prophesy if there is a substring in the Prophesy that is the date's record in the format "dd-mm-yyyy". We'll say that the number of the date's occurrences is the number of such substrings in the Prophesy. For example, the Prophesy "0012-10-2012-10-2012" mentions date 12-10-2012 twice (first time as "0012-10-2012-10-2012", second time as "0012-10-2012-10-2012").

The date of the Apocalypse is such correct date that the number of times it is mentioned in the Prophesy is strictly larger than that of any other correct date.

A date is correct if the year lies in the range from 2013 to 2015, the month is from 1 to 12, and the number of the day is strictly more than a zero and doesn't exceed the number of days in the current month. Note that a date is written in the format "dd-mm-yyyy", that means that leading zeroes may be added to the numbers of the months or days if needed. In other words, date "1-1-2013" isn't recorded in the format "dd-mm-yyyy", and date "01-01-2013" is recorded in it.

Notice, that any year between 2013 and 2015 is not a leap year.

Input

The first line contains the Prophesy: a non-empty string that only consists of digits and characters "-". The length of the Prophesy doesn't exceed 105 characters.

Output

In a single line print the date of the Apocalypse. It is guaranteed that such date exists and is unique.

Examples

Input

777-444---21-12-2013-12-2013-12-2013---444-777


Output

13-12-2013
#!/usr/bin/env python
# -*- coding: utf-8 -*-

import re


text = raw_input()

all_matches = re.findall('(?=(\d\d-\d\d-\d\d\d\d))', text)

days_in_month = (0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31)

date = ''
date_cout = 0

for result in set(all_matches):
    y, m, d = int(result[6:10]), int(result[3:5]), int(result[0:2])
    
    if y<2013 or y>2015:
        continue
    if m<1 or m>12:
        continue
    if d<1 or d>days_in_month[m]:
        continue;

    if all_matches.count(result) > date_cout:
        date = result
        date_cout = all_matches.count(result)

print date
