A recently found Ancient Prophesy is believed to contain the exact Apocalypse date. The prophesy is a string that only consists of digits and characters "-".

We'll say that some date is mentioned in the Prophesy if there is a substring in the Prophesy that is the date's record in the format "dd-mm-yyyy". We'll say that the number of the date's occurrences is the number of such substrings in the Prophesy. For example, the Prophesy "0012-10-2012-10-2012" mentions date 12-10-2012 twice (first time as "0012-10-2012-10-2012", second time as "0012-10-2012-10-2012").

The date of the Apocalypse is such correct date that the number of times it is mentioned in the Prophesy is strictly larger than that of any other correct date.

A date is correct if the year lies in the range from 2013 to 2015, the month is from 1 to 12, and the number of the day is strictly more than a zero and doesn't exceed the number of days in the current month. Note that a date is written in the format "dd-mm-yyyy", that means that leading zeroes may be added to the numbers of the months or days if needed. In other words, date "1-1-2013" isn't recorded in the format "dd-mm-yyyy", and date "01-01-2013" is recorded in it.

Notice, that any year between 2013 and 2015 is not a leap year.

Input

The first line contains the Prophesy: a non-empty string that only consists of digits and characters "-". The length of the Prophesy doesn't exceed 105 characters.

Output

In a single line print the date of the Apocalypse. It is guaranteed that such date exists and is unique.

Examples

Input

777-444---21-12-2013-12-2013-12-2013---444-777


Output

13-12-2013
# -*- coding: utf-8 -*-

import re
text = raw_input()

length = len(text)

years = [2013, 2014, 2015]

m_days = {1: 31, 2: 28, 3: 31, 4: 30, 5: 31, 6: 30, 7: 31, 8: 31, 9: 30, 10: 31, 11: 30, 12: 31}

res = {}

cur_max = 0
cur_s = ''

ind = range(0,10)

for i in xrange(0, length-9):
	s = text [i:(i+10)]
	try:
		if ((s[2]!='-') or (s[5]!='-')):
			continue
		year =  int(s[6:10]) 
		if year not in years:
			continue
		month = int(s[3:5])
		if ((month > 12) or (month <= 0)):
			continue
		days = int(s[0:2])
		if ((days <= 0) or (days > m_days[month])):
			continue
	except ValueError:
		continue
	tmp = 1 
	if s in res:
		tmp = res[s] + 1
		res[s] = tmp
	else:
		res[s] = tmp
	if tmp > cur_max:
		cur_s = s
		cur_max = tmp

print cur_s 
