You are given two arrays a_1, a_2, ... , a_n and b_1, b_2, ... , b_m. Array b is sorted in ascending order (b_i < b_{i + 1} for each i from 1 to m - 1).

You have to divide the array a into m consecutive subarrays so that, for each i from 1 to m, the minimum on the i-th subarray is equal to b_i. Note that each element belongs to exactly one subarray, and they are formed in such a way: the first several elements of a compose the first subarray, the next several elements of a compose the second subarray, and so on.

For example, if a = [12, 10, 20, 20, 25, 30] and b = [10, 20, 30] then there are two good partitions of array a: 

  1. [12, 10, 20], [20, 25], [30]; 
  2. [12, 10], [20, 20, 25], [30]. 



You have to calculate the number of ways to divide the array a. Since the number can be pretty large print it modulo 998244353.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 2 ⋅ 10^5) — the length of arrays a and b respectively.

The second line contains n integers a_1, a_2, ... , a_n (1 ≤ a_i ≤ 10^9) — the array a.

The third line contains m integers b_1, b_2, ... , b_m (1 ≤ b_i ≤ 10^9; b_i < b_{i+1}) — the array b.

Output

In only line print one integer — the number of ways to divide the array a modulo 998244353.

Examples

Input


6 3
12 10 20 20 25 30
10 20 30


Output


2


Input


4 2
1 3 3 7
3 7


Output


0


Input


8 2
1 2 2 2 2 2 2 2
1 2


Output


7
#include <bits/stdc++.h>
using namespace std;
template <typename T1, typename T2>
istream &operator>>(istream &in, pair<T1, T2> &a) {
  in >> a.first >> a.second;
  return in;
}
template <typename T1, typename T2>
ostream &operator<<(ostream &out, pair<T1, T2> a) {
  out << a.first << " " << a.second;
  return out;
}
template <typename T, typename T1>
T maxs(T &a, T1 b) {
  if (b > a) a = b;
  return a;
}
template <typename T, typename T1>
T mins(T &a, T1 b) {
  if (b < a) a = b;
  return a;
}
const long long MOD = 998244353;
struct mod_int {
  long long val;
  mod_int(long long v = 0) {
    if (v < 0) v = v % MOD + MOD;
    if (v >= MOD) v %= MOD;
    val = v;
  }
  static long long mod_inv(long long a, long long m = MOD) {
    long long g = m, r = a, first = 0, second = 1;
    while (r != 0) {
      long long q = g / r;
      g %= r;
      swap(g, r);
      first -= q * second;
      swap(first, second);
    }
    return first < 0 ? first + m : first;
  }
  explicit operator long long() const { return val; }
  mod_int &operator+=(const mod_int &other) {
    val += other.val;
    if (val >= MOD) val -= MOD;
    return *this;
  }
  mod_int &operator-=(const mod_int &other) {
    val -= other.val;
    if (val < 0) val += MOD;
    return *this;
  }
  static unsigned fast_mod(uint64_t first, unsigned m = MOD) {
    return first % m;
    unsigned x_high = first >> 32, x_low = (unsigned)first;
    unsigned quot, rem;
    asm("divl %4\n" : "=a"(quot), "=d"(rem) : "d"(x_high), "a"(x_low), "r"(m));
    return rem;
  }
  mod_int &operator*=(const mod_int &other) {
    val = fast_mod((uint64_t)val * other.val);
    return *this;
  }
  mod_int &operator/=(const mod_int &other) { return *this *= other.inv(); }
  friend mod_int operator+(const mod_int &a, const mod_int &b) {
    return mod_int(a) += b;
  }
  friend mod_int operator-(const mod_int &a, const mod_int &b) {
    return mod_int(a) -= b;
  }
  friend mod_int operator*(const mod_int &a, const mod_int &b) {
    return mod_int(a) *= b;
  }
  friend mod_int operator/(const mod_int &a, const mod_int &b) {
    return mod_int(a) /= b;
  }
  mod_int &operator++() {
    val = val == MOD - 1 ? 0 : val + 1;
    return *this;
  }
  mod_int &operator--() {
    val = val == 0 ? MOD - 1 : val - 1;
    return *this;
  }
  mod_int operator++(int32_t) {
    mod_int before = *this;
    ++*this;
    return before;
  }
  mod_int operator--(int32_t) {
    mod_int before = *this;
    --*this;
    return before;
  }
  mod_int operator-() const { return val == 0 ? 0 : MOD - val; }
  bool operator==(const mod_int &other) const { return val == other.val; }
  bool operator!=(const mod_int &other) const { return val != other.val; }
  mod_int inv() const { return mod_inv(val); }
  mod_int pow(long long p) const {
    assert(p >= 0);
    mod_int a = *this, result = 1;
    while (p > 0) {
      if (p & 1) result *= a;
      a *= a;
      p >>= 1;
    }
    return result;
  }
  friend ostream &operator<<(ostream &stream, const mod_int &m) {
    return stream << m.val;
  }
  friend istream &operator>>(istream &stream, mod_int &m) {
    return stream >> m.val;
  }
};
const long long N = 2e5 + 5;
long long solve() {
  long long n, m;
  cin >> n >> m;
  if (m > n) {
    cout << 0 << "\n";
    return 0;
  }
  set<long long> s;
  vector<long long> a(n + 1), b(m + 1);
  stack<pair<long long, long long> > st;
  vector<long long> l(n + 1), suff(n + 1), p(n + 1, 1e18);
  map<long long, long long> r;
  for (long long i = 1; i < n + 1; i++) {
    cin >> a[i];
    p[i] = min(p[i - 1], a[i]);
    r[a[i]] = i;
    s.insert(a[i]);
  }
  suff[n] = a[n];
  for (long long i = n - 1; i > 0; i--) suff[i] = min(a[i], suff[i + 1]);
  for (long long i = 1; i < m + 1; i++) {
    cin >> b[i];
    if (s.count(b[i]) == 0) {
      cout << 0 << "\n";
      return 0;
    }
  }
  for (long long i = n; i >= 1; i--) {
    while (!st.empty() && st.top().first > a[i]) {
      l[st.top().second] = i;
      st.pop();
    }
    st.push({a[i], i});
  }
  while (!st.empty()) {
    l[st.top().second] = 0;
    st.pop();
  }
  mod_int ans = 1;
  long long t = -1;
  for (long long i = 1; i <= m; i++) {
    if (i == 1) {
      long long idx = r[b[1]];
      if (suff[idx] != b[1] || p[idx] != b[1]) {
        cout << 0 << "\n";
        return 0;
      }
      t = idx;
    } else {
      long long idx = r[b[i]];
      if (idx < t) {
        cout << 0 << "\n";
        return 0;
      }
      if (suff[idx] != b[i]) {
        cout << 0 << "\n";
        return 0;
      }
      mod_int val = idx - l[idx];
      ans *= val;
      t = idx;
    }
  }
  cout << ans << "\n";
  return 0;
}
signed main() {
  ios_base::sync_with_stdio(0);
  cin.tie(0);
  cout.tie(0);
  long long t = 1;
  while (t--) {
    solve();
  }
  return 0;
}
