There is a grid with H rows and W columns, where each square is painted black or white.

You are given H strings S_1, S_2, ..., S_H, each of length W. If the square at the i-th row from the top and the j-th column from the left is painted black, the j-th character in the string S_i is `#`; if that square is painted white, the j-th character in the string S_i is `.`.

Find the number of pairs of a black square c_1 and a white square c_2 that satisfy the following condition:

* There is a path from the square c_1 to the square c_2 where we repeatedly move to a vertically or horizontally adjacent square through an alternating sequence of black and white squares: black, white, black, white...

Constraints

* 1 \leq H, W \leq 400
* |S_i| = W (1 \leq i \leq H)
* For each i (1 \leq i \leq H), the string S_i consists of characters `#` and `.`.

Input

Input is given from Standard Input in the following format:


H W
S_1
S_2
:
S_H


Output

Print the answer.

Examples

Input

3 3
.#.
..#
#..


Output

10


Input

3 3
.#.
..#
..


Output

10


Input

2 4
....
....


Output

0


Input

4 3


...


Output

6
import sys
sys.setrecursionlimit(10 ** 7)

h, w = map(int, input().split())
s = [list(input()) for _ in range(h)]

seen = [[0] * w for _ in range(h)]

dxdy = [(-1, 0), (1, 0), (0, -1), (0, 1)]

global ans
def dfs(x, y):
    seen[y][x] = 1
    a, b = 1, 0
    for dx, dy in dxdy:
        nx = x + dx
        ny = y + dy
        if 0 <= nx < w and 0 <= ny < h and not seen[ny][nx] and s[y][x] != s[ny][nx]:
            p = dfs(nx, ny)
            a += p[1]
            b += p[0]
    
    return (a, b)

ans = 0
for i in range(h):
    for j in range(w):
        if not seen[i][j]:
            p = dfs(j, i)
            ans += p[0] * p[1]
print(ans)
