A recently found Ancient Prophesy is believed to contain the exact Apocalypse date. The prophesy is a string that only consists of digits and characters "-".

We'll say that some date is mentioned in the Prophesy if there is a substring in the Prophesy that is the date's record in the format "dd-mm-yyyy". We'll say that the number of the date's occurrences is the number of such substrings in the Prophesy. For example, the Prophesy "0012-10-2012-10-2012" mentions date 12-10-2012 twice (first time as "0012-10-2012-10-2012", second time as "0012-10-2012-10-2012").

The date of the Apocalypse is such correct date that the number of times it is mentioned in the Prophesy is strictly larger than that of any other correct date.

A date is correct if the year lies in the range from 2013 to 2015, the month is from 1 to 12, and the number of the day is strictly more than a zero and doesn't exceed the number of days in the current month. Note that a date is written in the format "dd-mm-yyyy", that means that leading zeroes may be added to the numbers of the months or days if needed. In other words, date "1-1-2013" isn't recorded in the format "dd-mm-yyyy", and date "01-01-2013" is recorded in it.

Notice, that any year between 2013 and 2015 is not a leap year.

Input

The first line contains the Prophesy: a non-empty string that only consists of digits and characters "-". The length of the Prophesy doesn't exceed 105 characters.

Output

In a single line print the date of the Apocalypse. It is guaranteed that such date exists and is unique.

Examples

Input

777-444---21-12-2013-12-2013-12-2013---444-777


Output

13-12-2013
s = input()

date_ = {1:31,2:28,3:31,4:30,5:31,6:30,7:31,8:31,9:30,10:31,11:30,12:31}
def is_Date_Correct(s):
    return (1<=int(s[3:5])<=12 and 2013<=int(s[6:])<=2015 and 1<=int(s[:2])<=date_[int(s[3:5])])

def is_dateformat(s):
    if s[2]=='-' and s[5]=='-':
        for i in range(len(s)):
            if i==2 or i==5: continue
            if s[i] == '-':
                return False;
        return True;
    return False;

i = 0
map = {}
while(i<len(s)):
    x = s[i:i+10]
    if is_dateformat(x) and is_Date_Correct(x):
        if x in map:
            map[x]+=1
        else:
            map[x]=1
        i+=8
    else: 
        i+=1
    if i+10>len(s): break

count = 0
res = ""
for i in map:
    if map[i] > count:
        res = i
        count = map[i]

print(res)
