Let s(x) be sum of digits in decimal representation of positive integer x. Given two integers n and m, find some positive integers a and b such that 

  * s(a) ≥ n, 
  * s(b) ≥ n, 
  * s(a + b) ≤ m. 

Input

The only line of input contain two integers n and m (1 ≤ n, m ≤ 1129).

Output

Print two lines, one for decimal representation of a and one for decimal representation of b. Both numbers must not contain leading zeros and must have length no more than 2230.

Examples

Input

6 5


Output

6 
7


Input

8 16


Output

35 
53

Note

In the first sample, we have n = 6 and m = 5. One valid solution is a = 6, b = 7. Indeed, we have s(a) = 6 ≥ n and s(b) = 7 ≥ n, and also s(a + b) = s(13) = 4 ≤ m.

import java.io.OutputStream;
import java.io.PrintWriter;
import java.util.StringTokenizer;
import java.io.IOException;
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.InputStream;
import java.util.*;

public class B {

    public static void main(String[] args) {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        InputReader in = new InputReader(inputStream);
        PrintWriter out = new PrintWriter(outputStream);

        Solver solver = new Solver();
        
        solver.solve(1, in, out);

        out.close();
    }

    static class Solver {

        public void solve(int testNumber, InputReader in, PrintWriter out) {            
            int n = in.nextInt();
            int m = in.nextInt();
            int[] a = new int[n + 1];
            int[] b = new int[n + 1];
            int sum = 0;
            for (int i = 1 ; i <= n ; i++) {
                a[i] = 1;
                b[i] = 1;
                sum += 2;
            }
            int last = n;
            while (sum > m) {
                a[last] = 9;
                if (last != n) {
                    a[last] = 8;
                }
                last -= 1;
                sum = 0;
                int rem = 0;
                for (int i = n ; i >= 0 ; i--) {
                    int cur = a[i] + b[i] + rem;
                    sum += cur % 10;
                    rem = cur / 10;
                }
            }
            int first = 1;
            if (a[0] != 0) first = 0;
            for (int i = first ; i <= n ; i++) {
                out.print(a[i]);
            }
            out.println();
            for (int i = 1 ; i <= n ; i++) {
                out.print(b[i]);
            }
        }


    }

    static class InputReader {

        public BufferedReader reader;
        public StringTokenizer tokenizer;

        public InputReader(InputStream stream) {
            reader = new BufferedReader(new InputStreamReader(stream), 32768);
            tokenizer = null;
        }

        public String next() {
            while (tokenizer == null || !tokenizer.hasMoreTokens()) {
                try {
                    tokenizer = new StringTokenizer(reader.readLine());
                } catch (IOException e) {
                    throw new RuntimeException(e);
                }
            }
            return tokenizer.nextToken();
        }

        public int nextInt() {
            return Integer.parseInt(next());
        }

        public long nextLong() {
            return Long.parseLong(next());
        }

        public double nextDouble() {
            return Double.parseDouble(next());
        }

        public float nextFloat() {
            return Float.parseFloat(next());
        }
    }
}
