problem

Given $ N $ different natural numbers $ a_i $. I decided to make a pair by choosing a different natural number from the given natural numbers. Output one pair that can be created with a value difference that is a multiple of $ N -1 $.

It should be noted that such a pair always exists.





Example

Input

5
1 2 4 7 10


Output

2 10
#include <iostream>
#include <algorithm>
#include <string>
#include <vector>
#include <stack>
#include <queue>
#include <set>
#include <bitset>
#include <map>
#include <tuple>
#include <unordered_set>
#include <unordered_map>
#include <list>
#include <numeric>
#include <utility>
#include <iterator>
#include <cstdio>
#include <cmath>
#include <cstdlib>
#include <cstring>
#include <climits>
#include <ctime>
#include <cassert>
#include <random>
#include <cstring>


#define rep(i,n) for(int i=0;i<int(n);i++)
#define all(x) (x).begin(),x.end()
#define pb push_back

using namespace std;
using ll = long long;

const ll mod = 1000000007;
int dx[4]={1,0,-1,0};
int dy[4]={0,1,0,-1};
int ddx[8]={-1,-1,0,1,1,1,0,-1};
int ddy[8]={0,1,1,1,0,-1,-1,-1};
bool debug=false;

/*---------------------------------------------------*/

int main(){
  int N;
  cin >> N;
  vector<int> a(N);
  for(int i = 0; i < N; i++) cin >> a[i];

  for(int i = 0; i < N; i++){
    for(int j = 0; j < N; j++){
      if(i == j) continue;
      if(abs(a[i] - a[j]) % (N - 1) == 0){
	cout << a[i] << " " << a[j] << endl;
	return 0;
      }
    }
  }
  return 0;
}

