Let s(x) be sum of digits in decimal representation of positive integer x. Given two integers n and m, find some positive integers a and b such that 

  * s(a) ≥ n, 
  * s(b) ≥ n, 
  * s(a + b) ≤ m. 

Input

The only line of input contain two integers n and m (1 ≤ n, m ≤ 1129).

Output

Print two lines, one for decimal representation of a and one for decimal representation of b. Both numbers must not contain leading zeros and must have length no more than 2230.

Examples

Input

6 5


Output

6 
7


Input

8 16


Output

35 
53

Note

In the first sample, we have n = 6 and m = 5. One valid solution is a = 6, b = 7. Indeed, we have s(a) = 6 ≥ n and s(b) = 7 ≥ n, and also s(a + b) = s(13) = 4 ≤ m.
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;

public class Main {
	public static void main(String[] args) {
		FastReader sc = new FastReader();
		int n = sc.nextInt();
		int m = sc.nextInt();
		StringBuilder sb = new StringBuilder("");
		for(int i=0;i<300;i++) {
			sb.append("5");
		}
		System.out.println(sb.toString());
		sb = new StringBuilder("");
		for(int i=0;i<299;i++)
			sb.append("4");
			sb.append("5");
		System.out.println(sb.toString());
	}
}

class FastReader
{
	BufferedReader br;
	StringTokenizer st;

	public FastReader()
	{
		br = new BufferedReader(new
				InputStreamReader(System.in));
	}

	String next()
	{
		while (st == null || !st.hasMoreElements())
		{
			try
			{
				st = new StringTokenizer(br.readLine());
			}
			catch (IOException  e)
			{
				e.printStackTrace();
			}
		}
		return st.nextToken();
	}

	int nextInt()
	{
		return Integer.parseInt(next());
	}

	long nextLong()
	{
		return Long.parseLong(next());
	}

	double nextDouble()
	{
		return Double.parseDouble(next());
	}

	String nextLine()
	{
		String str = "";
		try
		{
			str = br.readLine();
		}
		catch (IOException e)
		{
			e.printStackTrace();
		}
		return str;
	}
}