A Hitachi string is a concatenation of one or more copies of the string `hi`.

For example, `hi` and `hihi` are Hitachi strings, while `ha` and `hii` are not.

Given a string S, determine whether S is a Hitachi string.

Constraints

* The length of S is between 1 and 10 (inclusive).
* S is a string consisting of lowercase English letters.

Input

Input is given from Standard Input in the following format:


S


Output

If S is a Hitachi string, print `Yes`; otherwise, print `No`.

Examples

Input

hihi


Output

Yes


Input

hi


Output

Yes


Input

ha


Output

No
import java.io.*;
import java.util.*;
public class Main
{
	
	private void solve()throws IOException
	{
		String s=nextLine();
		int n=s.length();
		if(n%2!=0)
		{
			out.println("No");
			return;
		}
		for(int i=0;i<n;i+=2)
		{
			if(s.charAt(i)=='h' && s.charAt(i+1)=='i');
			else
			{
				out.println("No");
				return;
			}
		}
		out.println("Yes");
	}

	 
	///////////////////////////////////////////////////////////

	public void run()throws IOException
	{
		br=new BufferedReader(new InputStreamReader(System.in));
		st=null;
		out=new PrintWriter(System.out);

		solve();

		br.close();
		out.close();
	}
	public static void main(String args[])throws IOException{
		new Main().run();
	}
	BufferedReader br;
	StringTokenizer st;
	PrintWriter out;
	String nextToken()throws IOException{
		while(st==null || !st.hasMoreTokens())
		st=new StringTokenizer(br.readLine());
		return st.nextToken();
	}
	String nextLine()throws IOException{
		return br.readLine();
	}
	int nextInt()throws IOException{
		return Integer.parseInt(nextToken());
	}
	long nextLong()throws IOException{
		return Long.parseLong(nextToken());
	}
	double nextDouble()throws IOException{
		return Double.parseDouble(nextToken());
	}
}