A recently found Ancient Prophesy is believed to contain the exact Apocalypse date. The prophesy is a string that only consists of digits and characters "-".

We'll say that some date is mentioned in the Prophesy if there is a substring in the Prophesy that is the date's record in the format "dd-mm-yyyy". We'll say that the number of the date's occurrences is the number of such substrings in the Prophesy. For example, the Prophesy "0012-10-2012-10-2012" mentions date 12-10-2012 twice (first time as "0012-10-2012-10-2012", second time as "0012-10-2012-10-2012").

The date of the Apocalypse is such correct date that the number of times it is mentioned in the Prophesy is strictly larger than that of any other correct date.

A date is correct if the year lies in the range from 2013 to 2015, the month is from 1 to 12, and the number of the day is strictly more than a zero and doesn't exceed the number of days in the current month. Note that a date is written in the format "dd-mm-yyyy", that means that leading zeroes may be added to the numbers of the months or days if needed. In other words, date "1-1-2013" isn't recorded in the format "dd-mm-yyyy", and date "01-01-2013" is recorded in it.

Notice, that any year between 2013 and 2015 is not a leap year.

Input

The first line contains the Prophesy: a non-empty string that only consists of digits and characters "-". The length of the Prophesy doesn't exceed 105 characters.

Output

In a single line print the date of the Apocalypse. It is guaranteed that such date exists and is unique.

Examples

Input

777-444---21-12-2013-12-2013-12-2013---444-777


Output

13-12-2013
from collections import defaultdict
line = raw_input()
datedict = defaultdict(int)
for i in xrange(0, len(line) - 10 + 1):
  date = line[i:i + 10]
  try:
    day = int(date[0:2])
    month = int(date[3:5])
    year = int(date[6:10])
  except:
    continue
  if date[2] != '-' or date[5] != '-': continue
  if year < 2013 or year > 2015: continue
  if month < 1 or month > 12: continue
  if day > 31 or day < 1: continue
  if month in [2,4,6,9,11] and day > 30: continue
  if month == 2 and day > 28: continue
  datedict[date] += 1
print max([(datedict[key], key) for key in datedict])[1]
