A recently found Ancient Prophesy is believed to contain the exact Apocalypse date. The prophesy is a string that only consists of digits and characters "-".

We'll say that some date is mentioned in the Prophesy if there is a substring in the Prophesy that is the date's record in the format "dd-mm-yyyy". We'll say that the number of the date's occurrences is the number of such substrings in the Prophesy. For example, the Prophesy "0012-10-2012-10-2012" mentions date 12-10-2012 twice (first time as "0012-10-2012-10-2012", second time as "0012-10-2012-10-2012").

The date of the Apocalypse is such correct date that the number of times it is mentioned in the Prophesy is strictly larger than that of any other correct date.

A date is correct if the year lies in the range from 2013 to 2015, the month is from 1 to 12, and the number of the day is strictly more than a zero and doesn't exceed the number of days in the current month. Note that a date is written in the format "dd-mm-yyyy", that means that leading zeroes may be added to the numbers of the months or days if needed. In other words, date "1-1-2013" isn't recorded in the format "dd-mm-yyyy", and date "01-01-2013" is recorded in it.

Notice, that any year between 2013 and 2015 is not a leap year.

Input

The first line contains the Prophesy: a non-empty string that only consists of digits and characters "-". The length of the Prophesy doesn't exceed 105 characters.

Output

In a single line print the date of the Apocalypse. It is guaranteed that such date exists and is unique.

Examples

Input

777-444---21-12-2013-12-2013-12-2013---444-777


Output

13-12-2013
from sys import stdin
di = {}
pos = [0,31,28,31,30,31,30,31,31,30,31,30,31]
a= stdin.readline().strip()
def valid(x):
	#print "from ",x
	x = x.split('-')
	if len(x)!=3:
		return 0
	d,m,y = x
	#print "date ",d,m,y
	if len(d)!=2:
		return 0
	if len(m)!=2:
		return 0
	if len(y)!=4:
		return 0
	if d[0]=='0':
		d = d[1:]
	d=int(d)
	if m[0]=='0':
		m=m[1:]
	if y[0]=='0':
		y=y[1:]
	if y[0]=='0':
		y=y[1:]
	if y[0]=='0':
		y=y[1:]
	m=int(m)
	y=int(y)
	#print "till now ",d,m,y
	if y>2015:
		return 0
	if y<2013:
		return 0
	if m>12:
		return 0
	if m<1:
		return 0
	if d<1:
		return 0
	if d>pos[m]:
		return 0
	return 1
	
l = len(a)
for i in xrange(l-9):
	b = a[i:i+10]
	if valid(b):
		di[b] = di.get(b,0)+1
ans = ''
co = 0
for i in di:
	if di[i] > co:
		co = di[i]
		ans = i
print ans