A recently found Ancient Prophesy is believed to contain the exact Apocalypse date. The prophesy is a string that only consists of digits and characters "-".

We'll say that some date is mentioned in the Prophesy if there is a substring in the Prophesy that is the date's record in the format "dd-mm-yyyy". We'll say that the number of the date's occurrences is the number of such substrings in the Prophesy. For example, the Prophesy "0012-10-2012-10-2012" mentions date 12-10-2012 twice (first time as "0012-10-2012-10-2012", second time as "0012-10-2012-10-2012").

The date of the Apocalypse is such correct date that the number of times it is mentioned in the Prophesy is strictly larger than that of any other correct date.

A date is correct if the year lies in the range from 2013 to 2015, the month is from 1 to 12, and the number of the day is strictly more than a zero and doesn't exceed the number of days in the current month. Note that a date is written in the format "dd-mm-yyyy", that means that leading zeroes may be added to the numbers of the months or days if needed. In other words, date "1-1-2013" isn't recorded in the format "dd-mm-yyyy", and date "01-01-2013" is recorded in it.

Notice, that any year between 2013 and 2015 is not a leap year.

Input

The first line contains the Prophesy: a non-empty string that only consists of digits and characters "-". The length of the Prophesy doesn't exceed 105 characters.

Output

In a single line print the date of the Apocalypse. It is guaranteed that such date exists and is unique.

Examples

Input

777-444---21-12-2013-12-2013-12-2013---444-777


Output

13-12-2013
import datetime
s = raw_input()
result = {}
for i in xrange(len(s)-9):
    try:
        if s[i+2] != '-' or s[i+5] != '-' or  (not 2012<int(s[i+6:i+10])<2016):
            raise ValueError
        datetime.date(int(s[i+6:i+10]), int(s[i+3:i+5]), int(s[i:i+2]))
    except ValueError:
        continue
    if s[i:i+10] in result:        result[s[i:i+10]] += 1
    else:                          result[s[i:i+10]] = 1

if not result or result.values().count(max(result.values())) > 1:
    print -1
else:
    m = max(result.values())
    for i in result:
        if result[i] == m:            
            print i
            break
        
    
