Let s(x) be sum of digits in decimal representation of positive integer x. Given two integers n and m, find some positive integers a and b such that 

  * s(a) ≥ n, 
  * s(b) ≥ n, 
  * s(a + b) ≤ m. 

Input

The only line of input contain two integers n and m (1 ≤ n, m ≤ 1129).

Output

Print two lines, one for decimal representation of a and one for decimal representation of b. Both numbers must not contain leading zeros and must have length no more than 2230.

Examples

Input

6 5


Output

6 
7


Input

8 16


Output

35 
53

Note

In the first sample, we have n = 6 and m = 5. One valid solution is a = 6, b = 7. Indeed, we have s(a) = 6 ≥ n and s(b) = 7 ≥ n, and also s(a + b) = s(13) = 4 ≤ m.
import java.math.BigInteger;
import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		
		int n, m;
		n = sc.nextInt();
		m = sc.nextInt();
		
		String r1 = "";
		String r2 = "";
		
		for (int i = 0; i < 2220; i++)
		{
			if (i % 2 == 0)
			{
				r1 += "5";
				r2 += "4";
			}
			else 
			{
				r1 += "4";
				r2 += "5";
			}
		}
		r1 += "5";
		r2 += "5";
		
//		BigInteger b = new BigInteger(r1);
//		BigInteger c = new BigInteger(r2);
//		System.out.println(b.add(c).toString());
		
		System.out.println(r1 + "\n" + r2);
		
	}

}
