There is a grid with H rows and W columns, where each square is painted black or white.

You are given H strings S_1, S_2, ..., S_H, each of length W. If the square at the i-th row from the top and the j-th column from the left is painted black, the j-th character in the string S_i is `#`; if that square is painted white, the j-th character in the string S_i is `.`.

Find the number of pairs of a black square c_1 and a white square c_2 that satisfy the following condition:

* There is a path from the square c_1 to the square c_2 where we repeatedly move to a vertically or horizontally adjacent square through an alternating sequence of black and white squares: black, white, black, white...

Constraints

* 1 \leq H, W \leq 400
* |S_i| = W (1 \leq i \leq H)
* For each i (1 \leq i \leq H), the string S_i consists of characters `#` and `.`.

Input

Input is given from Standard Input in the following format:


H W
S_1
S_2
:
S_H


Output

Print the answer.

Examples

Input

3 3
.#.
..#
#..


Output

10


Input

3 3
.#.
..#
..


Output

10


Input

2 4
....
....


Output

0


Input

4 3


...


Output

6
# aising2019C - Alternating Path
import sys

sys.setrecursionlimit(10 ** 9)


def dfs(x: int, y: int) -> None:
    global blk, wht
    seen[x][y] = 1
    cur = S[x][y]
    if cur:
        blk += 1
    else:
        wht += 1
    for dx, dy in dxy:
        nx, ny = x + dx, y + dy
        if 0 <= nx < H and 0 <= ny < W and S[nx][ny] != cur and not seen[nx][ny]:
            dfs(nx, ny)


def main():
    # separate S to connected components
    global H, W, S, seen, dxy, blk, wht
    H, W, *S = open(0).read().split()
    H, W = int(H), int(W)
    S = [[1 if i == "#" else 0 for i in s] for s in S]
    seen = [[0] * W for _ in range(H)]
    dxy = [(1, 0), (-1, 0), (0, 1), (0, -1)]
    ans = 0
    for i in range(H):
        for j in range(W):
            if not seen[i][j]:
                blk, wht = 0, 0
                dfs(i, j)
                ans += blk * wht
    print(ans)


if __name__ == "__main__":
    main()