AtCoDeer is thinking of painting an infinite two-dimensional grid in a checked pattern of side K. Here, a checked pattern of side K is a pattern where each square is painted black or white so that each connected component of each color is a K × K square. Below is an example of a checked pattern of side 3:

cba927b2484fad94fb5ff7473e9aadef.png

AtCoDeer has N desires. The i-th desire is represented by x_i, y_i and c_i. If c_i is `B`, it means that he wants to paint the square (x_i,y_i) black; if c_i is `W`, he wants to paint the square (x_i,y_i) white. At most how many desires can he satisfy at the same time?

Constraints

* 1 ≤ N ≤ 10^5
* 1 ≤ K ≤ 1000
* 0 ≤ x_i ≤ 10^9
* 0 ≤ y_i ≤ 10^9
* If i ≠ j, then (x_i,y_i) ≠ (x_j,y_j).
* c_i is `B` or `W`.
* N, K, x_i and y_i are integers.

Input

Input is given from Standard Input in the following format:


N K
x_1 y_1 c_1
x_2 y_2 c_2
:
x_N y_N c_N


Output

Print the maximum number of desires that can be satisfied at the same time.

Examples

Input

4 3
0 1 W
1 2 W
5 3 B
5 4 B


Output

4


Input

2 1000
0 0 B
0 1 W


Output

2


Input

6 2
1 2 B
2 1 W
2 2 B
1 0 B
0 6 W
4 5 W


Output

4
#include<stdio.h>
#include<vector>
#include<algorithm>
using namespace std;
int d[7020][7020];
int main()
{
	int num, len;
	scanf("%d%d", &num, &len);
	for (int i = 0; i < num; i++)
	{
		int za, zb;
		char zc;
		scanf("%d%d %c", &za, &zb, &zc);
		za %= len * 2;
		zb %= len * 2;
		za++, zb++;
		for (int j = 0; j < 5; j++)
		{
			for (int k = 0; k < 5; k++)
			{
				if ((((j + k) & 1) != 0) == (zc == 'B'))
				{
					d[za + len*j][zb + len*k]++, d[za + len*(j + 1)][zb + len*k]--, d[za + len*j][zb + len*(k + 1)]--, d[za + len*(j + 1)][zb + len*(k + 1)]++;
				}
			}
		}
	}
	for (int i = 0; i <= len * 6; i++)for (int j = 0; j <= len * 6; j++)d[i + 1][j + 1] += d[i + 1][j] + d[i][j + 1] - d[i][j];
	int maxi = 0;
	for (int i = 0; i <= len * 6; i++)for (int j = 0; j <= len * 6; j++)maxi = max(maxi, d[i][j]);
	printf("%d\n", maxi);
}