A recently found Ancient Prophesy is believed to contain the exact Apocalypse date. The prophesy is a string that only consists of digits and characters "-".

We'll say that some date is mentioned in the Prophesy if there is a substring in the Prophesy that is the date's record in the format "dd-mm-yyyy". We'll say that the number of the date's occurrences is the number of such substrings in the Prophesy. For example, the Prophesy "0012-10-2012-10-2012" mentions date 12-10-2012 twice (first time as "0012-10-2012-10-2012", second time as "0012-10-2012-10-2012").

The date of the Apocalypse is such correct date that the number of times it is mentioned in the Prophesy is strictly larger than that of any other correct date.

A date is correct if the year lies in the range from 2013 to 2015, the month is from 1 to 12, and the number of the day is strictly more than a zero and doesn't exceed the number of days in the current month. Note that a date is written in the format "dd-mm-yyyy", that means that leading zeroes may be added to the numbers of the months or days if needed. In other words, date "1-1-2013" isn't recorded in the format "dd-mm-yyyy", and date "01-01-2013" is recorded in it.

Notice, that any year between 2013 and 2015 is not a leap year.

Input

The first line contains the Prophesy: a non-empty string that only consists of digits and characters "-". The length of the Prophesy doesn't exceed 105 characters.

Output

In a single line print the date of the Apocalypse. It is guaranteed that such date exists and is unique.

Examples

Input

777-444---21-12-2013-12-2013-12-2013---444-777


Output

13-12-2013
s = input()
nums = set([str(x) for x in range(0, 9+1)])
cnt = dict()
m = -1
ans = 0
days_in_month = {1: 31, 2: 28, 3: 31, 4: 30, 5: 31, 6: 30, 7: 31, 8: 31, 9: 30, 10: 31, 11: 30, 12:31}
for i in range(len(s) - 10+1):
    q = s[i:i+10]
    if q[0] in nums and q[1] in nums and q[2] == "-":
        if q[3] in nums and q[4] in nums and q[5] == "-": 
            if q[6] in nums and q[7] in nums and q[8] in nums and q[9] in nums:
                try:
                    day = int(q[0:1+1])
                    month = int(q[3:4+1])
                    year = int(q[6:9+1])
                except:
                    continue
                #print(day, month)
                if 0 < month <= 12 and 0 < day <= days_in_month[month] and 2013 <= year <= 2015:
                    try:
                        cnt[q] += 1
                    except:
                        cnt[q] = 0
#print(cnt)
for key in cnt.keys():
    if cnt[key] > m:
        m = cnt[key]
        ans = key
print(ans)