Taro is going to play a card game. However, now he has only n cards, even though there should be 52 cards (he has no Jokers).

The 52 cards include 13 ranks of each of the four suits: spade, heart, club and diamond.

Note

解説



Input

In the first line, the number of cards n (n ≤ 52) is given.

In the following n lines, data of the n cards are given. Each card is given by a pair of a character and an integer which represent its suit and rank respectively. A suit is represented by 'S', 'H', 'C' and 'D' for spades, hearts, clubs and diamonds respectively. A rank is represented by an integer from 1 to 13.

Output

Print the missing cards. The same as the input format, each card should be printed with a character and an integer separated by a space character in a line. Arrange the missing cards in the following priorities:

* Print cards of spades, hearts, clubs and diamonds in this order.
* If the suits are equal, print cards with lower ranks first.

Example

Input

47
S 10
S 11
S 12
S 13
H 1
H 2
S 6
S 7
S 8
S 9
H 6
H 8
H 9
H 10
H 11
H 4
H 5
S 2
S 3
S 4
S 5
H 12
H 13
C 1
C 2
D 1
D 2
D 3
D 4
D 5
D 6
D 7
C 3
C 4
C 5
C 6
C 7
C 8
C 9
C 10
C 11
C 13
D 9
D 10
D 11
D 12
D 13


Output

S 1
H 3
H 7
C 12
D 8
import java.util.Scanner;
public class Main {
	public static void main(String[] args){
		Scanner scan=new Scanner(System.in);
		boolean[][] cards=new boolean[4][13];
		int n=scan.nextInt();
		int number;
		String mark;
		for(int i=0;i<n;i++){
			mark=scan.next();
			number=scan.nextInt();
			if(mark.equals("S")){
				cards[0][number-1]=true;
			}else if(mark.equals("H")){
				cards[1][number-1]=true;
			}else if(mark.equals("C")){
				cards[2][number-1]=true;
			}else{
				cards[3][number-1]=true;
			}
		}
		for(int i=0;i<4;i++){
			for(int j=0;j<13;j++){
				if(!cards[i][j]){
					if(i==0){
						System.out.println("S "+(j+1));
					}else if(i==1){
						System.out.println("H "+(j+1));
					}else if(i==2){
						System.out.println("C "+(j+1));
					}else{
						System.out.println("D "+(j+1));
					}
				}
			}
		}
		scan.close();
	}
}