A recently found Ancient Prophesy is believed to contain the exact Apocalypse date. The prophesy is a string that only consists of digits and characters "-".

We'll say that some date is mentioned in the Prophesy if there is a substring in the Prophesy that is the date's record in the format "dd-mm-yyyy". We'll say that the number of the date's occurrences is the number of such substrings in the Prophesy. For example, the Prophesy "0012-10-2012-10-2012" mentions date 12-10-2012 twice (first time as "0012-10-2012-10-2012", second time as "0012-10-2012-10-2012").

The date of the Apocalypse is such correct date that the number of times it is mentioned in the Prophesy is strictly larger than that of any other correct date.

A date is correct if the year lies in the range from 2013 to 2015, the month is from 1 to 12, and the number of the day is strictly more than a zero and doesn't exceed the number of days in the current month. Note that a date is written in the format "dd-mm-yyyy", that means that leading zeroes may be added to the numbers of the months or days if needed. In other words, date "1-1-2013" isn't recorded in the format "dd-mm-yyyy", and date "01-01-2013" is recorded in it.

Notice, that any year between 2013 and 2015 is not a leap year.

Input

The first line contains the Prophesy: a non-empty string that only consists of digits and characters "-". The length of the Prophesy doesn't exceed 105 characters.

Output

In a single line print the date of the Apocalypse. It is guaranteed that such date exists and is unique.

Examples

Input

777-444---21-12-2013-12-2013-12-2013---444-777


Output

13-12-2013
days = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]

def pattern(s):
	for i in [0, 1, 3, 4, 6, 7, 8, 9]:
		if s[i] < '0' or s[i] > '9':
			return False
	for i in [2, 5]:
		if s[i] != '-':
			return False
	return True

def extract(s):
	return map(int, [s[:2], s[3:5], s[6:]])

s = raw_input()
d = {}
for i in xrange(len(s)-9):
	p = s[i:i+10]
	if not pattern(p): continue
	dd, mm, yy = extract(p)
	if yy < 2013 or yy > 2015: continue
	if mm < 1 or mm > 12: continue
	if dd < 1 or dd > days[mm-1]: continue
	d[p] = 1 if p not in d else d[p] + 1
print sorted(zip(d.values(), d.keys()))[-1][1]
