There is a grid with H rows and W columns, where each square is painted black or white.

You are given H strings S_1, S_2, ..., S_H, each of length W. If the square at the i-th row from the top and the j-th column from the left is painted black, the j-th character in the string S_i is `#`; if that square is painted white, the j-th character in the string S_i is `.`.

Find the number of pairs of a black square c_1 and a white square c_2 that satisfy the following condition:

* There is a path from the square c_1 to the square c_2 where we repeatedly move to a vertically or horizontally adjacent square through an alternating sequence of black and white squares: black, white, black, white...

Constraints

* 1 \leq H, W \leq 400
* |S_i| = W (1 \leq i \leq H)
* For each i (1 \leq i \leq H), the string S_i consists of characters `#` and `.`.

Input

Input is given from Standard Input in the following format:


H W
S_1
S_2
:
S_H


Output

Print the answer.

Examples

Input

3 3
.#.
..#
#..


Output

10


Input

3 3
.#.
..#
..


Output

10


Input

2 4
....
....


Output

0


Input

4 3


...


Output

6
import queue
H, W = map(int, input().split())
S = [list(map(int, input().replace(".", "0").replace("#","1"))) for h in range(H)]

Search = [(-1, 0), (0, -1), (1, 0), (0, 1)]
Total = 0
Visited = [[False for w in range(W)] for h in range(H)]
for h in range(H):
    for w in range(W):
        if not Visited[h][w]:
            Visited[h][w] = True
            Color = ([1, 0] if S[h][w] == 0 else [0, 1])
            Q = queue.Queue()
            Q.put((h, w, S[h][w]))
            while not Q.empty():
                nh, nw, nc = Q.get()
                for s in Search:
                    nexth, nextw = nh + s[0], nw + s[1]
                    if 0 <= nexth < H and 0 <= nextw < W:
                        if not Visited[nexth][nextw] and S[nexth][nextw] != nc:
                            nextc = S[nexth][nextw]
                            Visited[nexth][nextw] = True
                            Q.put((nexth, nextw, nextc))
                            Color[nextc] += 1
            Total += Color[0] * Color[1]

print(Total)