Given are N integers A_1,\ldots,A_N.

We will choose exactly K of these elements. Find the maximum possible product of the chosen elements.

Then, print the maximum product modulo (10^9+7), using an integer between 0 and 10^9+6 (inclusive).

Constraints

* 1 \leq K \leq N \leq 2\times 10^5
* |A_i| \leq 10^9

Input

Input is given from Standard Input in the following format:


N K
A_1 \ldots A_N


Output

Print the maximum product modulo (10^9+7), using an integer between 0 and 10^9+6 (inclusive).

Examples

Input

4 2
1 2 -3 -4


Output

12


Input

4 3
-1 -2 -3 -4


Output

1000000001


Input

2 1
-1 1000000000


Output

1000000000


Input

10 10
1000000000 100000000 10000000 1000000 100000 10000 1000 100 10 1


Output

999983200
N,K = map(int,input().split())
MOD = 10**9 + 7
A = list(map(int,input().split()))
Ap = [a for a in A if a >= 0]
An = [-a for a in A if a < 0]
Ap.sort()
Ap.reverse()
An.sort()
An.reverse()

if len(Ap) == 0 and K % 2 == 1:
	ans = 1
	An.reverse()
	for i in range(K):
		ans = (ans * -An[i]) % MOD
	print(ans)
	exit()

B = [(a, 1) if a >= 0 else (-a, -1) for a in A]
B.sort()
B.reverse()
M = [0 if B[0][1] > 0 else 1]
for i in range(1, N):
	M.append(M[i-1] + (0 if B[i][1] > 0 else 1))

i = K-1
if M[i] % 2 == 0 or K == N:
	ans = 1
	v = 1 if (M[i] % 2 == 0) else -1
	for j in range(K):
		ans = (ans * B[j][0]) % MOD
	print((ans * v) % MOD)
else:
	n = M[i]
	p = K - n
	if len(An) == n or p == 0:
		n -= 1
		p += 1
	elif len(Ap) == p:
		n += 1
		p -= 1
	elif Ap[p-1] * Ap[p] >= An[n-1] * An[n]:
		n -= 1
		p += 1
	else:
		n += 1
		p -= 1
	ans = 1
	for i in range(p):
		ans = (ans * Ap[i]) % MOD
	for i in range(n):
		ans = (ans * An[i]) % MOD
	print(ans)