problem

Given $ N $ different natural numbers $ a_i $. I decided to make a pair by choosing a different natural number from the given natural numbers. Output one pair that can be created with a value difference that is a multiple of $ N -1 $.

It should be noted that such a pair always exists.





Example

Input

5
1 2 4 7 10


Output

2 10
#include<iostream>
#include<iomanip>
#include<map>
#include<set>
#include<string>
#include<algorithm>
#include<cmath>
#include<vector>
#include<queue>
#include<stack>
 
using namespace std;
 
#define P(p) cout<<(p)<<endl
#define rep(i,m,n) for(int i = (m); i < (int)(n); i++)
#define rrep(i,m,n) for(int i=(int)(m); i>=(int)(n); i--)
#define vsort(v) sort(v.begin(), v.end());
#define rvsort(v) sort(v.begin(), v.end(),greater<int>());
#define YES cout<<"YES"<< endl
#define NO cout<<"NO"<<endl
#define Yes cout<<"Yes"<<endl
#define No cout<<"No"<<endl  
#define yes cout<<"yes"<<endl
#define no cout<<"no"<<endl
#define ret return
#define C(i) cin>>i
#define C2(i,j) cin>>i>>j
#define C3(i,j,k) cin>>i>>j>>k
#define C4(i,j,k,m) cin>>i>>j>>k>>m
////////////////////////////////////////////////////////////

int main(){
	int n;	
	cin >> n;
	int a[n];

	rep(i,0,n)
		cin >> a[i];

	int d = n - 1;
	rep(i,0,n){
		int num = a[i];
		rep(j,0,n){
			if(i == j )
				continue;

			if( (num - a[j] ) % d == 0 ){
				cout << num << " " << a[j] << endl;
				ret 0;
			}
		}
	}
	ret 0;
}
