A Hitachi string is a concatenation of one or more copies of the string `hi`.

For example, `hi` and `hihi` are Hitachi strings, while `ha` and `hii` are not.

Given a string S, determine whether S is a Hitachi string.

Constraints

* The length of S is between 1 and 10 (inclusive).
* S is a string consisting of lowercase English letters.

Input

Input is given from Standard Input in the following format:


S


Output

If S is a Hitachi string, print `Yes`; otherwise, print `No`.

Examples

Input

hihi


Output

Yes


Input

hi


Output

Yes


Input

ha


Output

No
import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		String s = getString(sc);
		String[] otherString = s.split("hi");

		boolean isHitachi = true;
		for (String os : otherString) {
			if (!os.equals("")) {
				isHitachi = false;
				break;
			}
		}
		if (isHitachi) {
			System.out.println("Yes");
		} else {
			System.out.println("No");
		}
	}

	/**
	 * *汎用メソッド <br>
	 * スキャナーからの入力値をlongで返却
	 *
	 * @return
	 */
	public static long getLong(Scanner sc) {

		return Long.parseLong(sc.next());
	}

	/**
	 * *汎用メソッド <br>
	 * スキャナーからの入力値をintで返却
	 *
	 * @return
	 */
	public static int getInt(Scanner sc) {

		return Integer.parseInt(sc.next());
	}

	/**
	 * *汎用メソッド <br>
	 * スキャナーからの入力値をStringで返却
	 *
	 * @return
	 */
	public static String getString(Scanner sc) {

		return sc.next();
	}

	/**
	 * *汎用メソッド <br>
	 * スキャナーからの入力値をint配列で返却
	 *
	 * @return
	 */
	public static int[] getIntArray(Scanner sc) {
		String line = "";
		// 直前にnext()を実行していると改行コードだけ取ってしまうのでその対策
		while (line.equals("")) {
			line = sc.nextLine();
		}

		String[] strArray = line.split(" ");
		int[] intArray = new int[strArray.length];
		for (int i = 0; i < strArray.length; i++) {
			intArray[i] = Integer.parseInt(strArray[i]);
		}
		return intArray;
	}

}
