Let s(x) be sum of digits in decimal representation of positive integer x. Given two integers n and m, find some positive integers a and b such that 

  * s(a) ≥ n, 
  * s(b) ≥ n, 
  * s(a + b) ≤ m. 

Input

The only line of input contain two integers n and m (1 ≤ n, m ≤ 1129).

Output

Print two lines, one for decimal representation of a and one for decimal representation of b. Both numbers must not contain leading zeros and must have length no more than 2230.

Examples

Input

6 5


Output

6 
7


Input

8 16


Output

35 
53

Note

In the first sample, we have n = 6 and m = 5. One valid solution is a = 6, b = 7. Indeed, we have s(a) = 6 ≥ n and s(b) = 7 ≥ n, and also s(a + b) = s(13) = 4 ≤ m.
import java.util.*;
import java.io.*;
import java.math.*;
import java.awt.geom.*;
public class FastScanner{
    public static void main(String[] args) {
      MyScanner sc=new MyScanner();
      StringBuilder a=new StringBuilder();
      StringBuilder b=new StringBuilder();
      for(int i=0;i<1000;i++){
          a.append(4);
          b.append(5);
      }
      a.append(5);
      b.append(5);
      System.out.println(a+" "+b);
  }

    private static class MyScanner {
      BufferedReader br;
      StringTokenizer st;

      public MyScanner() {
         br = new BufferedReader(new InputStreamReader(System.in));
      }

      String next() {
          while (st == null || !st.hasMoreElements()) {
              try {
                  st = new StringTokenizer(br.readLine());
              } catch (IOException e) {
                  e.printStackTrace();
              }
          }
          return st.nextToken();
      }

      int ni() {
          return Integer.parseInt(next());
      }
      float nf() {
        return Float.parseFloat(next());
      }
      long nl() {
          return Long.parseLong(next());
      }

      double nd() {
          return Double.parseDouble(next());
      }

      String nextLine(){
          String str = "";
	  try {
	     str = br.readLine();
	  } catch (IOException e) {
	     e.printStackTrace();
	  }
	  return str;
      }
   }
}