problem

Given $ N $ different natural numbers $ a_i $. I decided to make a pair by choosing a different natural number from the given natural numbers. Output one pair that can be created with a value difference that is a multiple of $ N -1 $.

It should be noted that such a pair always exists.





Example

Input

5
1 2 4 7 10


Output

2 10
// header {{{
#include <bits/stdc++.h>
using namespace std;

// {U}{INT,LONG,LLONG}_{MAX,MIN}
#define INF         INT_MAX/3
#define LLINF       LLONG_MAX/3
#define MOD         (1000000007LL)
#define MODA(a, b)  a=((a)+(b))%MOD
#define MODP(a, b)  a=((a)*(b))%MOD
#define inc(i, l, r)   for(int i=(l);i<(r);i++)
#define dec(i, l, r)   for(int i=(r)-1;i>=(l);i--)
#define pb          push_back
#define se          second
#define fi          first
#define mset(a, b)  memset(a, b, sizeof(a))

using LL  = long long;
using G   = vector<vector<int>>;

int di[] = {0, -1, 0, 1};
int dj[] = {1, 0, -1, 0};
// }}}

int main() {
    cin.tie(0);ios::sync_with_stdio(false);
    int n;cin >> n;
    vector<int> a(n);
    for(int i=0;i<n;i++){
        cin >> a[i];
    }
    for(int i=0;i<n;i++){
        for(int j=0;j<n;j++){
            if(i == j) continue;
            int d = abs(a[i]-a[j]);
            if(d%(n-1) == 0){
                cout << a[i] << " " << a[j] << endl;
                return 0;
            }
        }
    }
    return 0;
}

