A recently found Ancient Prophesy is believed to contain the exact Apocalypse date. The prophesy is a string that only consists of digits and characters "-".

We'll say that some date is mentioned in the Prophesy if there is a substring in the Prophesy that is the date's record in the format "dd-mm-yyyy". We'll say that the number of the date's occurrences is the number of such substrings in the Prophesy. For example, the Prophesy "0012-10-2012-10-2012" mentions date 12-10-2012 twice (first time as "0012-10-2012-10-2012", second time as "0012-10-2012-10-2012").

The date of the Apocalypse is such correct date that the number of times it is mentioned in the Prophesy is strictly larger than that of any other correct date.

A date is correct if the year lies in the range from 2013 to 2015, the month is from 1 to 12, and the number of the day is strictly more than a zero and doesn't exceed the number of days in the current month. Note that a date is written in the format "dd-mm-yyyy", that means that leading zeroes may be added to the numbers of the months or days if needed. In other words, date "1-1-2013" isn't recorded in the format "dd-mm-yyyy", and date "01-01-2013" is recorded in it.

Notice, that any year between 2013 and 2015 is not a leap year.

Input

The first line contains the Prophesy: a non-empty string that only consists of digits and characters "-". The length of the Prophesy doesn't exceed 105 characters.

Output

In a single line print the date of the Apocalypse. It is guaranteed that such date exists and is unique.

Examples

Input

777-444---21-12-2013-12-2013-12-2013---444-777


Output

13-12-2013
prop = raw_input().split('-')
from calendar import monthrange
allowed_years = ['2013','2014','2015']
allowed_months = ['01','02','03','04','05','06','07','08','09','10','11','12']
from collections import Counter
date_counter = Counter()
allowed_dates = {'2013': {}, '2014': {}, '2015': {}}
for y in allowed_dates.keys():
    months = {}
    for i in range(1,13):
        months[i] = str(monthrange(int(y), i)[1])
    allowed_dates[y] = months
for i in xrange(len(prop)):
    if len(prop[i]) == 2 and prop[i] in allowed_months:
        if i-1 >= 0 and i+1 < len(prop):
            if len(prop[i-1]) >= 2 and len(prop[i+1]) >= 4:
                if prop[i+1][:4] in allowed_years and prop[i-1][-2:] >= '01' and prop[i-1][-2:] <= allowed_dates[prop[i+1][:4]][int(prop[i])]:
                    d = prop[i-1][-2:] + '-' + prop[i] + '-' + prop[i+1][:4]
                    date_counter[d] += 1
print date_counter.most_common(1)[0][0]