There is a grid with H rows and W columns, where each square is painted black or white.

You are given H strings S_1, S_2, ..., S_H, each of length W. If the square at the i-th row from the top and the j-th column from the left is painted black, the j-th character in the string S_i is `#`; if that square is painted white, the j-th character in the string S_i is `.`.

Find the number of pairs of a black square c_1 and a white square c_2 that satisfy the following condition:

* There is a path from the square c_1 to the square c_2 where we repeatedly move to a vertically or horizontally adjacent square through an alternating sequence of black and white squares: black, white, black, white...

Constraints

* 1 \leq H, W \leq 400
* |S_i| = W (1 \leq i \leq H)
* For each i (1 \leq i \leq H), the string S_i consists of characters `#` and `.`.

Input

Input is given from Standard Input in the following format:


H W
S_1
S_2
:
S_H


Output

Print the answer.

Examples

Input

3 3
.#.
..#
#..


Output

10


Input

3 3
.#.
..#
..


Output

10


Input

2 4
....
....


Output

0


Input

4 3


...


Output

6
import java.awt.Point;
import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;

public class Main {
	static char[][] c;
	static int H, W;
	static List<Point> p;
	static long ans = 0;
	static boolean[][] m;
	static int[][] g;
	static long cnt1 = 0;
	static long cnt2 = 0;
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		H = sc.nextInt();
		W = sc.nextInt();
		String[] S = new String[H];
		for(int i = 0; i < H; i++) {
			S[i] = sc.next();
		}
		sc.close();
		c = new char[H][W];
		m = new boolean[H][W];
		g = new int[H][W];

		for(int i = 0; i < H; i++) {
			for(int j = 0; j < W; j++) {
				m[i][j] = true;
			}
		}
		p = new ArrayList<Point>();
		for(int i = 0; i < H; i++) {
			for(int j = 0; j < W; j++) {
				c[i][j] = S[i].charAt(j);
				if(c[i][j] == '#') {
					p.add(new Point(j, i));
				}
			}
		}
		for(int i = 0; i < p.size(); i++) {
			int x = p.get(i).x;
			int y = p.get(i).y;
			//System.out.println(y + " " + x);
			if(!m[y][x]) {
				continue;
			}
			g[y][x] = 1;
			m[y][x] = false;
			cnt1 = 0;
			cnt2 = 1;
			rec('#', x, y);
			//System.out.println(cnt1 +" " + cnt2);
			ans += cnt1 * cnt2;

		}
		System.out.println(ans);
	}
	static void rec(char color, int x, int y) {
		int[] dx = {1, -1, 0, 0};
		int[] dy = {0, 0, 1, -1};
		for(int i = 0; i < 4; i++) {
			int nx = x + dx[i];
			int ny = y + dy[i];
			if(nx >= 0 && nx < W && ny >= 0 && ny < H) {
				if(color == '#' && m[ny][nx] && c[ny][nx] == '.') {
					m[ny][nx] = false;
					cnt1++;
					rec('.', nx, ny);
				}else if(color == '.' && m[ny][nx] && c[ny][nx] == '#') {
					g[ny][nx] = 1;
					m[ny][nx] = false;
					cnt2++;
					rec('#', nx, ny);
				}
			}
		}
	}
}