You invited n guests to dinner! You plan to arrange one or more circles of chairs. Each chair is going to be either occupied by one guest, or be empty. You can make any number of circles. 

Your guests happen to be a little bit shy, so the i-th guest wants to have a least l_i free chairs to the left of his chair, and at least r_i free chairs to the right. The "left" and "right" directions are chosen assuming all guests are going to be seated towards the center of the circle. Note that when a guest is the only one in his circle, the l_i chairs to his left and r_i chairs to his right may overlap.

What is smallest total number of chairs you have to use?

Input

First line contains one integer n — number of guests, (1 ⩽ n ⩽ 10^5). 

Next n lines contain n pairs of space-separated integers l_i and r_i (0 ⩽ l_i, r_i ⩽ 10^9).

Output

Output a single integer — the smallest number of chairs you have to use.

Examples

Input

3
1 1
1 1
1 1


Output

6


Input

4
1 2
2 1
3 5
5 3


Output

15


Input

1
5 6


Output

7

Note

In the second sample the only optimal answer is to use two circles: a circle with 5 chairs accomodating guests 1 and 2, and another one with 10 chairs accomodationg guests 3 and 4.

In the third sample, you have only one circle with one person. The guest should have at least five free chairs to his left, and at least six free chairs to his right to the next person, which is in this case the guest herself. So, overall number of chairs should be at least 6+1=7.
/* Author: Ronak Agarwal, reader part not written by me*/
import java.io.* ; import java.util.* ;
import static java.lang.Math.min ; import static java.lang.Math.max ;
import static java.lang.Math.abs ; import static java.lang.Math.log ;
import static java.lang.Math.pow ; import static java.lang.Math.sqrt ;
/* Thread is created here to increase the stack size of the java code so that recursive dfs can be performed */
public class Codeshefcode{
	public static void main(String[] args) throws IOException{
		new Thread(null,new Runnable(){	public void run(){ exec_Code() ;} },"Solver",1l<<27).start() ;
	}
	static void exec_Code(){
		try{
			Solver Machine = new Solver() ;
			Machine.Solve() ; Machine.Finish() ;}
		catch(Exception e){ e.printStackTrace() ; print_and_exit() ;}
		catch(Error e){ e.printStackTrace() ; print_and_exit() ; }
	}
	static void print_and_exit(){ System.out.flush() ; System.exit(-1) ;}
}
/* Implementation of the Reader class */
class Reader { 
	private InputStream mIs;
	private byte[] buf = new byte[1024];
	private int curChar,numChars;
	public Reader() { this(System.in); } 
	public Reader(InputStream is) { mIs = is;} 
	public int read() {
		if (numChars == -1) throw new InputMismatchException();    
		if (curChar >= numChars) {
			curChar = 0;
			try { numChars = mIs.read(buf);} catch (IOException e) { throw new InputMismatchException();}
			if (numChars <= 0) return -1;            
		}
		return buf[curChar++];
	} 
	public String nextLine(){
		int c = read();
		while (isSpaceChar(c)) c = read();        
		StringBuilder res = new StringBuilder();
		do {
			res.appendCodePoint(c);
			c = read();
		} while (!isEndOfLine(c));
		return res.toString() ;
	} 
	public String s(){
		int c = read();
		while (isSpaceChar(c)) c = read();        
		StringBuilder res = new StringBuilder();
		do {
			res.appendCodePoint(c);
			c = read();
		}while (!isSpaceChar(c));
		return res.toString();
	} 
	public long l(){
		int c = read();
		while (isSpaceChar(c)) c = read();        
		int sgn = 1;
		if (c == '-') { sgn = -1 ; c = read() ; }
		long res = 0;
		do{
			if (c < '0' || c > '9') throw new InputMismatchException();
			res *= 10 ; res += c - '0' ; c = read();
		}while(!isSpaceChar(c));
		return res * sgn;
	} 
	public int i(){
		int c = read() ;
		while (isSpaceChar(c)) c = read();        
		int sgn = 1;
		if (c == '-') { sgn = -1 ; c = read() ; }
		int res = 0;
		do{
			if (c < '0' || c > '9') throw new InputMismatchException();
			res *= 10 ; res += c - '0' ; c = read() ;
		}while(!isSpaceChar(c));
		return res * sgn;
	} 
	public void readL(long arr[],int l,int r){
		for(int i=l ; i<=r ; i++) arr[i] = l();
	}
	public void readI(int arr[],int l,int r){
		for(int i=l ; i<=r ; i++) arr[i] = i();
	}
	public boolean isSpaceChar(int c) { return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1; } 
	public boolean isEndOfLine(int c) { return c == '\n' || c == '\r' || c == -1; } 
}   
/* All the useful functions,constants,renamings are here*/
class Template{
	/* Constants Section */
	final int INT_MIN = Integer.MIN_VALUE ; final int INT_MAX = Integer.MAX_VALUE ;
	final long LONG_MIN = Long.MIN_VALUE ; final long LONG_MAX = Long.MAX_VALUE ;
	static long MOD = 1000000007 ;
	static Reader ip = new Reader() ;	
	static PrintWriter op = new PrintWriter(System.out) ;
	/* Methods for writing */
	static void p(Object o){ op.print(o) ; }
	static void pln(Object o){ op.println(o) ;}
	static void Finish(){ op.flush(); op.close(); }
	/* Implementation of operations modulo MOD */
	static long inv(long a){ return powM(a,MOD-2) ; }
	static long m(long a,long b){ return (a*b)%MOD ; }
	static long d(long a,long b){ return (a*inv(b))%MOD ; }
	static long powM(long x,long n){
		if(n<0) return powM(inv(x),-n) ;
		long y=1 ;
		for( ; n!=0 ; x=(x*x)%MOD , n/=2) if((n&1)==1) y = (y*x)%MOD ;
		return y ;
	}
	/* Renaming of some generic utility classes */
	final static class mylist extends ArrayList<pair>{}
	final static class myset extends TreeSet<pair>{}
	final static class mystack extends Stack<Integer>{}
	final static class mymap extends TreeMap<Long,Integer>{}
}
/* Implementation of the pair class, useful for every other problem */
class pair implements Comparable<pair>{
	long x ; int y ;
	pair(long _x,int _y){ x=_x ; y=_y ;} 
	public int compareTo(pair p){
		return (this.x<p.x ? -1 : (this.x>p.x ? 1 : (this.y<p.y ? -1 : (this.y>p.y ? 1 : 0)))) ;
	}
}
/* Main code starts here */
class Solver extends Template{
 	public void Solve() throws IOException{
 		int n = ip.i();
 		long l[] = new long[n+1];
 		long r[] = new long[n+1];
 		long ans=0;
 		for(int i=1 ; i<=n ; i++){
 			l[i] = ip.i();
 			r[i] = ip.i();
 			ans+=(l[i]+r[i]+1);
 		}
 		myset setl = new myset();
 		myset setr = new myset();
 		for(int i=1 ; i<=n ; i++) setl.add(new pair(l[i],i));
 		for(int i=1 ; i<=n ; i++) setr.add(new pair(r[i],i));
 		for(int i=1 ; i<=n ; i++){
 			pair pl = setl.pollFirst();
 			pair pr = setr.pollFirst();
 			ans-=min(pl.x,pr.x);
 		}
 		pln(ans);
 	}
} 
