A recently found Ancient Prophesy is believed to contain the exact Apocalypse date. The prophesy is a string that only consists of digits and characters "-".

We'll say that some date is mentioned in the Prophesy if there is a substring in the Prophesy that is the date's record in the format "dd-mm-yyyy". We'll say that the number of the date's occurrences is the number of such substrings in the Prophesy. For example, the Prophesy "0012-10-2012-10-2012" mentions date 12-10-2012 twice (first time as "0012-10-2012-10-2012", second time as "0012-10-2012-10-2012").

The date of the Apocalypse is such correct date that the number of times it is mentioned in the Prophesy is strictly larger than that of any other correct date.

A date is correct if the year lies in the range from 2013 to 2015, the month is from 1 to 12, and the number of the day is strictly more than a zero and doesn't exceed the number of days in the current month. Note that a date is written in the format "dd-mm-yyyy", that means that leading zeroes may be added to the numbers of the months or days if needed. In other words, date "1-1-2013" isn't recorded in the format "dd-mm-yyyy", and date "01-01-2013" is recorded in it.

Notice, that any year between 2013 and 2015 is not a leap year.

Input

The first line contains the Prophesy: a non-empty string that only consists of digits and characters "-". The length of the Prophesy doesn't exceed 105 characters.

Output

In a single line print the date of the Apocalypse. It is guaranteed that such date exists and is unique.

Examples

Input

777-444---21-12-2013-12-2013-12-2013---444-777


Output

13-12-2013
import sys, re

s = sys.stdin.read().strip()

M = [0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]

cn = {}
#r = re.compile('^((0[1-9]|1[0-9]|2[0-8])-(0[1-9]|1[0-2])|(29|30)-01|(29|30)-0[3-9]|(29|30)-1[0-2]|31-0[13578]|31-1[02])-201[345]$')
for i in range(0, len(s)-9):
    if s[i+2] == s[i+5] == '-':
        d = s[i:i+10]
        try:
            day = int(d[0:2])
            month = int(d[3:5])
            year = int(d[6:10])
            if 1 <= month <= 12:
                if 1 <= day <= M[month]:
                    if 2013 <= year <= 2015:
                        if d in cn:
                            cn[d] += 1
                        else:
                            cn[d] = 1
        except:
            pass

mx = max(cn.values())
for k, v in cn.iteritems():
    if v == mx:
        sys.stdout.write(k)
        break
