A recently found Ancient Prophesy is believed to contain the exact Apocalypse date. The prophesy is a string that only consists of digits and characters "-".

We'll say that some date is mentioned in the Prophesy if there is a substring in the Prophesy that is the date's record in the format "dd-mm-yyyy". We'll say that the number of the date's occurrences is the number of such substrings in the Prophesy. For example, the Prophesy "0012-10-2012-10-2012" mentions date 12-10-2012 twice (first time as "0012-10-2012-10-2012", second time as "0012-10-2012-10-2012").

The date of the Apocalypse is such correct date that the number of times it is mentioned in the Prophesy is strictly larger than that of any other correct date.

A date is correct if the year lies in the range from 2013 to 2015, the month is from 1 to 12, and the number of the day is strictly more than a zero and doesn't exceed the number of days in the current month. Note that a date is written in the format "dd-mm-yyyy", that means that leading zeroes may be added to the numbers of the months or days if needed. In other words, date "1-1-2013" isn't recorded in the format "dd-mm-yyyy", and date "01-01-2013" is recorded in it.

Notice, that any year between 2013 and 2015 is not a leap year.

Input

The first line contains the Prophesy: a non-empty string that only consists of digits and characters "-". The length of the Prophesy doesn't exceed 105 characters.

Output

In a single line print the date of the Apocalypse. It is guaranteed that such date exists and is unique.

Examples

Input

777-444---21-12-2013-12-2013-12-2013---444-777


Output

13-12-2013
#! /usr/bin/env python2

import datetime

s = raw_input().strip()

record = {}

for i in xrange(len(s) - 9):
    ss = s[i:i+10]
    if ss[2] == '-' and ss[5] == '-':
        sss = ss.split('-')
        if len(sss) == 3:
            if len(sss[0]) == len(sss[1]) == 2:
                if len(sss[2]) == 4:
                    d, m, y = map(int, sss)
                    if 2013 <= y <= 2015:
                        try:
                            datetime.date(y, m, d)
                            record.setdefault(ss, 0)
                            record[ss] += 1
                        except:
                            pass

m = max(record.values())
for k in record.keys():
    if record[k] == m:
        print k
        break
