A recently found Ancient Prophesy is believed to contain the exact Apocalypse date. The prophesy is a string that only consists of digits and characters "-".

We'll say that some date is mentioned in the Prophesy if there is a substring in the Prophesy that is the date's record in the format "dd-mm-yyyy". We'll say that the number of the date's occurrences is the number of such substrings in the Prophesy. For example, the Prophesy "0012-10-2012-10-2012" mentions date 12-10-2012 twice (first time as "0012-10-2012-10-2012", second time as "0012-10-2012-10-2012").

The date of the Apocalypse is such correct date that the number of times it is mentioned in the Prophesy is strictly larger than that of any other correct date.

A date is correct if the year lies in the range from 2013 to 2015, the month is from 1 to 12, and the number of the day is strictly more than a zero and doesn't exceed the number of days in the current month. Note that a date is written in the format "dd-mm-yyyy", that means that leading zeroes may be added to the numbers of the months or days if needed. In other words, date "1-1-2013" isn't recorded in the format "dd-mm-yyyy", and date "01-01-2013" is recorded in it.

Notice, that any year between 2013 and 2015 is not a leap year.

Input

The first line contains the Prophesy: a non-empty string that only consists of digits and characters "-". The length of the Prophesy doesn't exceed 105 characters.

Output

In a single line print the date of the Apocalypse. It is guaranteed that such date exists and is unique.

Examples

Input

777-444---21-12-2013-12-2013-12-2013---444-777


Output

13-12-2013
import sys
st = raw_input().strip()
date = [0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]

count = {}

l = len(st)
for i in range(2, l - 7):
	if st[i] != '-':
		continue
	if st[i + 3] != '-':
		continue
	try:
		day = int(st[i - 2: i])
		month = int(st[i + 1: i + 3])
		year = int(st[i + 4: i + 8])
	except:
		continue
	#print year, month, day
	if year < 2013 or year > 2015:
		continue
	if month < 1 or month > 12:
		continue
	if day < 1 or day > date[month]:
		continue
	try:
		count[st[i - 2 : i + 8]] += 1
	except:
		count[st[i - 2 : i + 8]] = 1

ans = ''
cnt = 0

for i in count:
	if count[i] > cnt:
		ans = i
		cnt = count[i]

print ans
