A recently found Ancient Prophesy is believed to contain the exact Apocalypse date. The prophesy is a string that only consists of digits and characters "-".

We'll say that some date is mentioned in the Prophesy if there is a substring in the Prophesy that is the date's record in the format "dd-mm-yyyy". We'll say that the number of the date's occurrences is the number of such substrings in the Prophesy. For example, the Prophesy "0012-10-2012-10-2012" mentions date 12-10-2012 twice (first time as "0012-10-2012-10-2012", second time as "0012-10-2012-10-2012").

The date of the Apocalypse is such correct date that the number of times it is mentioned in the Prophesy is strictly larger than that of any other correct date.

A date is correct if the year lies in the range from 2013 to 2015, the month is from 1 to 12, and the number of the day is strictly more than a zero and doesn't exceed the number of days in the current month. Note that a date is written in the format "dd-mm-yyyy", that means that leading zeroes may be added to the numbers of the months or days if needed. In other words, date "1-1-2013" isn't recorded in the format "dd-mm-yyyy", and date "01-01-2013" is recorded in it.

Notice, that any year between 2013 and 2015 is not a leap year.

Input

The first line contains the Prophesy: a non-empty string that only consists of digits and characters "-". The length of the Prophesy doesn't exceed 105 characters.

Output

In a single line print the date of the Apocalypse. It is guaranteed that such date exists and is unique.

Examples

Input

777-444---21-12-2013-12-2013-12-2013---444-777


Output

13-12-2013
'''                      
   	
   			 ||Sri:||                 

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 /\  /\    |   |___    |    |   |___|      |      |    |___|
/  \/  \   |   ___|    |    |         |_/    |___|    |___

I am a beginner. Feel free to send tutorials/help to srinivasan1995@gmail.com.

Codeforces, SPOJ handle: desikachariar.
Hackerrank, Codechef handle: Prof_Calculus.

Advices/Help are welcome. You will definitely get a thanks in return. Comments to be avoided.

College: International Institute of Information Technology, Bangalore.

'''

import math

def fn():
	return

months = {1:31, 2:28, 3:31, 4:30, 5:31, 6:30, 7:31, 8:31, 9:30, 10:31, 11:30, 12:31}
dates = {}
mx_date = ''
mx_val = 0

if __name__ == '__main__':
	x = raw_input()
	for i in range(9, len(x)):
		yr = 0
		try:
			yr = int(x[i-3]+x[i-2]+x[i-1]+x[i])
		except:
			pass
		if yr >= 2013 and yr <= 2015:
			if x[i-4] == '-':
				mnth = 0
				try:
					mnth = int(x[i-6]+x[i-5])
				except:
					pass
				if mnth in months:
					if x[i-7] == '-':
						day = 0
						try:
							day = int(x[i-9]+x[i-8])
						except:
							pass
						if day >= 1 and day <= months[mnth]:
							current = x[i-9:i+1]
							if current in dates:
								dates[current] += 1
							else:
								dates[current] = 1
							if dates[current] > mx_val:
								mx_val = dates[current]
								mx_date = current
	print mx_date
				
				
				
				
				
				
				
				
				
				
				
				
				
				
				
			
