AtCoDeer is thinking of painting an infinite two-dimensional grid in a checked pattern of side K. Here, a checked pattern of side K is a pattern where each square is painted black or white so that each connected component of each color is a K × K square. Below is an example of a checked pattern of side 3:

cba927b2484fad94fb5ff7473e9aadef.png

AtCoDeer has N desires. The i-th desire is represented by x_i, y_i and c_i. If c_i is `B`, it means that he wants to paint the square (x_i,y_i) black; if c_i is `W`, he wants to paint the square (x_i,y_i) white. At most how many desires can he satisfy at the same time?

Constraints

* 1 ≤ N ≤ 10^5
* 1 ≤ K ≤ 1000
* 0 ≤ x_i ≤ 10^9
* 0 ≤ y_i ≤ 10^9
* If i ≠ j, then (x_i,y_i) ≠ (x_j,y_j).
* c_i is `B` or `W`.
* N, K, x_i and y_i are integers.

Input

Input is given from Standard Input in the following format:


N K
x_1 y_1 c_1
x_2 y_2 c_2
:
x_N y_N c_N


Output

Print the maximum number of desires that can be satisfied at the same time.

Examples

Input

4 3
0 1 W
1 2 W
5 3 B
5 4 B


Output

4


Input

2 1000
0 0 B
0 1 W


Output

2


Input

6 2
1 2 B
2 1 W
2 2 B
1 0 B
0 6 W
4 5 W


Output

4
#include<cstdio>
#include<algorithm>
#define MAXN 100006
#define MAXK 2006
using namespace std;
int n,k;
char c;
int map[MAXK][MAXK],a,b,black,maxone,minone=MAXN;
int main()
{
	scanf("%d%d",&n,&k);
	for(int i=1;i<=n;i++)
	{
		scanf("%d%d %c",&a,&b,&c);
		black=0;
		if(c=='B') black=1;
		a%=k*2;
		b%=k*2;
		if(a>=k)
		{
			a%=k;
			black^=1;
		}
		if(b>=k)
		{
			b%=k;
			black^=1;
		}
		if(black)
		{
			map[a][k-1]+=1;
			map[k-1][b-1]+=1;
			map[a][b-1]-=2;
		}
		else
		{
			map[k-1][k-1]+=1;
			map[a][k-1]-=1;
			map[k-1][b-1]-=1;
			map[a][b-1]+=2;
		}
	}
	for(int i=k-1;i>=0;i--)
		for(int j=k-1;j>=0;j--)
		{
			map[i][j]+=map[i+1][j]+map[i][j+1]-map[i+1][j+1];
			maxone=max(maxone,map[i][j]);
			minone=min(minone,map[i][j]);
		}
	printf("%d",max(maxone,(n-minone)));
}