A recently found Ancient Prophesy is believed to contain the exact Apocalypse date. The prophesy is a string that only consists of digits and characters "-".

We'll say that some date is mentioned in the Prophesy if there is a substring in the Prophesy that is the date's record in the format "dd-mm-yyyy". We'll say that the number of the date's occurrences is the number of such substrings in the Prophesy. For example, the Prophesy "0012-10-2012-10-2012" mentions date 12-10-2012 twice (first time as "0012-10-2012-10-2012", second time as "0012-10-2012-10-2012").

The date of the Apocalypse is such correct date that the number of times it is mentioned in the Prophesy is strictly larger than that of any other correct date.

A date is correct if the year lies in the range from 2013 to 2015, the month is from 1 to 12, and the number of the day is strictly more than a zero and doesn't exceed the number of days in the current month. Note that a date is written in the format "dd-mm-yyyy", that means that leading zeroes may be added to the numbers of the months or days if needed. In other words, date "1-1-2013" isn't recorded in the format "dd-mm-yyyy", and date "01-01-2013" is recorded in it.

Notice, that any year between 2013 and 2015 is not a leap year.

Input

The first line contains the Prophesy: a non-empty string that only consists of digits and characters "-". The length of the Prophesy doesn't exceed 105 characters.

Output

In a single line print the date of the Apocalypse. It is guaranteed that such date exists and is unique.

Examples

Input

777-444---21-12-2013-12-2013-12-2013---444-777


Output

13-12-2013
s = input().split('-')

ex = {}
ans = 0
sans = ''

def solve(i):
    global ex
    global ans
    global sans
    global s
    
    day = s[i]
    month = s[i+1]
    year = s[i+2]
    
    if len(day) < 2 or len(month) != 2 or len(year) < 4:
        return
    
    day = day[-2:]
    year = year[:4]
    
    if int(year) < 2013 or int(year) > 2015:
        return
    
    if int(month) < 1 or int(month) > 12:
        return
    
    if int(day) < 1 or int(day) > 31:
        return
    
    # verifica dia de acordo com o mês (meu Deus...)
    tm = int(month)
    
    if tm in [1, 3, 5, 7, 8, 10, 12] and int(day) > 31:
        return
    
    if tm == 2 and int(day) > 28:
        return
    
    if tm in [4, 6, 9, 11] and int(day) > 30:
        return
    
    date = day+month+year
    
    if date in ex:
        ex[date] += 1
        
        if ex[date] > ans:
            ans = ex[date]
            sans = date
            
    else:
        ex[date] = 1
        
        if ans == 0:
            ans = 1
            sans = date

def c(s):
    print(f'{s[:2]}-{s[2:4]}-{s[4:]}')

for i in range(len(s)-2):
    if len(s[i]) <= 1:
        continue
    
    solve(i)
    
c(sans)