Let's denote d(n) as the number of divisors of a positive integer n. You are given three integers a, b and c. Your task is to calculate the following sum:

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Find the sum modulo 1073741824 (230).

Input

The first line contains three space-separated integers a, b and c (1 ≤ a, b, c ≤ 100).

Output

Print a single integer — the required sum modulo 1073741824 (230).

Examples

Input

2 2 2


Output

20


Input

5 6 7


Output

1520

Note

For the first example.

  * d(1·1·1) = d(1) = 1; 
  * d(1·1·2) = d(2) = 2; 
  * d(1·2·1) = d(2) = 2; 
  * d(1·2·2) = d(4) = 3; 
  * d(2·1·1) = d(2) = 2; 
  * d(2·1·2) = d(4) = 3; 
  * d(2·2·1) = d(4) = 3; 
  * d(2·2·2) = d(8) = 4. 



So the result is 1 + 2 + 2 + 3 + 2 + 3 + 3 + 4 = 20.
import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.Map;
import java.util.Scanner;
import java.util.HashMap;

/**
 * Built using CHelper plug-in
 * Actual solution is at the top
 *
 * @author Mouna Cheikhna
 */
public class Main {
    public static void main(String[] args) {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        Scanner in = new Scanner(inputStream);
        PrintWriter out = new PrintWriter(outputStream);
        TaskB solver = new TaskB();
        solver.solve(1, in, out);
        out.close();
    }

    static class TaskB {
        public void solve(int testNumber, Scanner in, PrintWriter out) {
            int a = in.nextInt();
            int b = in.nextInt();
            int c = in.nextInt();

            Map<Integer, Integer> m = new HashMap<>();
            int count = 0;
            for (int i = 1; i <= a; i++) {
                for (int j = 1; j <= b; j++) {
                    for (int k = 1; k <= c; k++) {
                        int v = i * j * k;
                        if (m.containsKey(v)) {
                            count += m.get(v);
                        } else {
                            int divCount = countDivisors(v);
                            m.put(v, divCount);
                            count += divCount;
                        }
                    }
                }
            }
            out.println(count);
        }

        int countDivisors(int n) {
            int cnt = 0;
            for (int i = 1; i <= Math.sqrt(n); i++) {
                if (n % i == 0) {
                    // If divisors are equal,
                    // count only one
                    if (n / i == i) {
                        cnt++;
                    } else { // Otherwise count both
                        cnt = cnt + 2;
                    }
                }
            }
            return cnt;
        }

    }
}

