You are given three integers a, b and x. Your task is to construct a binary string s of length n = a + b such that there are exactly a zeroes, exactly b ones and exactly x indices i (where 1 ≤ i < n) such that s_i ≠ s_{i + 1}. It is guaranteed that the answer always exists.

For example, for the string "01010" there are four indices i such that 1 ≤ i < n and s_i ≠ s_{i + 1} (i = 1, 2, 3, 4). For the string "111001" there are two such indices i (i = 3, 5).

Recall that binary string is a non-empty sequence of characters where each character is either 0 or 1.

Input

The first line of the input contains three integers a, b and x (1 ≤ a, b ≤ 100, 1 ≤ x < a + b).

Output

Print only one string s, where s is any binary string satisfying conditions described above. It is guaranteed that the answer always exists.

Examples

Input

2 2 1


Output

1100


Input

3 3 3


Output

101100


Input

5 3 6


Output

01010100

Note

All possible answers for the first example: 

  * 1100; 
  * 0011. 



All possible answers for the second example: 

  * 110100; 
  * 101100; 
  * 110010; 
  * 100110; 
  * 011001; 
  * 001101; 
  * 010011; 
  * 001011. 
import java.util.*;
public class q2
{
	public static void main(String[] args) 
	{
		Scanner s=new Scanner(System.in);
		int x=s.nextInt();
		int y=s.nextInt();
		int k=s.nextInt();
		/*char c1,c2;
		if(k1>k2)
		{
			c1='0';
			c2='1';
		}
		else
		{
			c1='1';
			c2='0';
		}*/
		int now=0;
		//char[] c=new char[a+b];
		String sb=new String("");
		if(k==1)
		{
			while(x!=0)
			{
				sb=sb+"0";
				x--;
			}
			while(y!=0)
			{
				sb=sb+"1";
				y--;
			}
			System.out.println(sb);
			System.exit(0);
		}
		while(now+2<=k)
		{
		//	System.out.println("yyyy");
			now+=2;
			sb=sb+"01";
			x--;
			y--;
		}
		
		//System.out.println("  ff"+now+k);
		if(now==k)
		{
			
			while(y!=0&&x!=0)
			{
			//	System.out.println("yyyy2");
				sb=sb+"1";
				y--;
			}
			while(y!=0&&x==0)
			{
			//	System.out.println("yyyy2");
				sb="1"+sb;
				y--;
			}
			while(x!=0)
			{
			//	System.out.println("yyyy1");
				sb=sb+"0";
				x--;
			}
		}
		else
		{
			if(x!=0)
			{
				while(y!=1)
				{
					sb=sb+"1";
					y--;
				}	
				while(x!=0)
				{
					sb=sb+"0";
					x--;
				}
				if(y==1)
				{
					sb=sb+"1";
					y--;
				}
			}
			else
			{
				while(y!=0)
				{
					sb="1"+sb;
					y--;
				}
			}
		}
		System.out.println(sb);



	}
}