There are N integers, A_1, A_2, ..., A_N, written on a blackboard.

We will repeat the following operation N-1 times so that we have only one integer on the blackboard.

* Choose two integers x and y on the blackboard and erase these two integers. Then, write a new integer x-y.



Find the maximum possible value of the final integer on the blackboard and a sequence of operations that maximizes the final integer.

Constraints

* 2 \leq N \leq 10^5
* -10^4 \leq A_i \leq 10^4
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N
A_1 A_2 ... A_N


Output

Print the maximum possible value M of the final integer on the blackboard, and a sequence of operations x_i, y_i that maximizes the final integer, in the format below.

Here x_i and y_i represent the integers x and y chosen in the i-th operation, respectively.

If there are multiple sequences of operations that maximize the final integer, any of them will be accepted.


M
x_1 y_1
:
x_{N-1} y_{N-1}

Output

Print the maximum possible value M of the final integer on the blackboard, and a sequence of operations x_i, y_i that maximizes the final integer, in the format below.

Here x_i and y_i represent the integers x and y chosen in the i-th operation, respectively.

If there are multiple sequences of operations that maximize the final integer, any of them will be accepted.


M
x_1 y_1
:
x_{N-1} y_{N-1}

Examples

Input

3
1 -1 2


Output

4
-1 1
2 -2


Input

3
1 1 1


Output

1
1 1
1 0


import java.util.*;

 class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int N = sc.nextInt();
        Integer[] x = new Integer[N];
        for(int i = 0; i<N; i++) {
        	x[i] = sc.nextInt();
        }
        Arrays.sort(x, Comparator.reverseOrder());
//        for(int i = 0; i<N; i++) {
//        	System.out.println(x[i]);
//        }
        int M = 0;
        int pul = x[0];
        int mai = x[N-1];
        
        for(int i=1;i<N-1;i++) {
        	if(x[i]<0) {
        		pul = pul - x[i];
        	} else {
        		mai = mai - x[i];
        	}
         }
        M = pul - mai;
        System.out.println(M);
        
        int max=x[0];
        int min=x[N-1];
        for(int i=1;i<N-1;i++) {
        	if(x[i]<0) {
        		System.out.println(max + " " + x[i]);
        		max = max - x[i];
        	} else {
        		System.out.println(min + " " + x[i]);
        		min = min - x[i];
        	}        	
        }
        System.out.println(max + " " + min);
//        System.out.println(ans);
    }
}
