Given is a string S of length N-1. Each character in S is `<` or `>`.

A sequence of N non-negative integers, a_1,a_2,\cdots,a_N, is said to be good when the following condition is satisfied for all i (1 \leq i \leq N-1):

* If S_i= `<`: a_i<a_{i+1}
* If S_i= `>`: a_i>a_{i+1}



Find the minimum possible sum of the elements of a good sequence of N non-negative integers.

Constraints

* 2 \leq N \leq 5 \times 10^5
* S is a string of length N-1 consisting of `<` and `>`.

Input

Input is given from Standard Input in the following format:


S


Output

Find the minimum possible sum of the elements of a good sequence of N non-negative integers.

Examples

Input

<>>


Output

3


Input

<>>><<><<<<<>>><


Output

28
import java.io.IOException;
import java.io.InputStream;
import java.util.*;
import java.lang.*;

public class Main{
	public static void main(String[] args) {
		FastScanner sc = new FastScanner();
		String s = sc.next();
		int[] num = new int[s.length() + 1];
		for (int i = 0; i < s.length() + 1; i++) {
			num[i] = -1;
		}
		int now = 0;
		for (int i = s.length() - 1; i >= 0; i--) {
			if (s.charAt(i) == '>') {
				if (now == 0) {
					num[i + 1] = Math.max(0, num[i + 1]);
					num[i] = Math.max(1, num[i]);
					now = 1;
				} else {
					num[i] = Math.max(num[i + 1] + 1, num[i]);
				}
			} else {
				now = 0;
			}
		}
		now = 0;
		for (int i = 0; i < s.length(); i++) {
			if (s.charAt(i) == '<') {
				if (now == 0) {
					num[i] = Math.max(0, num[i]);
					num[i + 1] = Math.max(1, num[i + 1]);
					now = 1;
				} else {
					num[i + 1] = Math.max(num[i] + 1, num[i + 1]);
				}
			} else {
				now = 0;
			}
		}
		long sum = 0;
		for (int i = 0; i < s.length() + 1; i++) {
			sum += num[i];
		}
		System.out.println(sum);
	}
}

class FastScanner {
	private final InputStream in = System.in;
	private final byte[] buffer = new byte[1024];
	private int ptr = 0;
	private int buflen = 0;
	private boolean hasNextByte() {
		if (ptr < buflen) {
			return true;
		} else {
			ptr = 0;
			try {
				buflen = in.read(buffer);
			} catch (IOException e) {
				e.printStackTrace();
			}
			if (buflen <= 0) {
				return false;
			}
		}
		return true;
	}
	private int readByte() {
		if (hasNextByte()) {
			return buffer[ptr++];
		} else {
			return -1;
		}
	}
	private static boolean isPrintableChar(int c) {
		return 33 <= c && c <= 126;
	}
	public boolean hasNext() {
		while (hasNextByte() && !isPrintableChar(buffer[ptr])) {
			ptr++;
		}
		return hasNextByte();
	}
	public String next() {
		if (!hasNext()) {
			throw new NoSuchElementException();
		}
		StringBuilder sb = new StringBuilder();
		int b = readByte();
		while (isPrintableChar(b)) {
			sb.appendCodePoint(b);
			b = readByte();
		}
		return sb.toString();
	}
	public long nextLong() {
		if (!hasNext()) {
			throw new NoSuchElementException();
		}
		long n = 0;
		boolean minus = false;
		int b = readByte();
		if (b == '-') {
			minus = true;
			b = readByte();
		}
		if (b < '0' || '9' < b) {
			throw new NumberFormatException();
		}
		while (true) {
			if ('0' <= b && b <= '9') {
				n *= 10;
				n += b - '0';
			} else if (b == -1 || !isPrintableChar(b)) {
				return minus ? -n : n;
			} else {
				throw new NumberFormatException();
			}
			b = readByte();
		}
	}
	public int nextInt() {
		long nl = nextLong();
		if (nl < Integer.MIN_VALUE || Integer.MAX_VALUE < nl) {
			throw new NumberFormatException();
		}
		return (int) nl;
	}
	public double nextDouble() {
		return Double.parseDouble(next());
	}
}
