Vitya has learned that the answer for The Ultimate Question of Life, the Universe, and Everything is not the integer 54 42, but an increasing integer sequence a_1, …, a_n. In order to not reveal the secret earlier than needed, Vitya encrypted the answer and obtained the sequence b_1, …, b_n using the following rules:

  * b_1 = a_1;
  * b_i = a_i ⊕ a_{i - 1} for all i from 2 to n, where x ⊕ y is the [bitwise XOR](https://en.wikipedia.org/wiki/Bitwise_operation#XOR) of x and y. 



It is easy to see that the original sequence can be obtained using the rule a_i = b_1 ⊕ … ⊕ b_i.

However, some time later Vitya discovered that the integers b_i in the cypher got shuffled, and it can happen that when decrypted using the rule mentioned above, it can produce a sequence that is not increasing. In order to save his reputation in the scientific community, Vasya decided to find some permutation of integers b_i so that the sequence a_i = b_1 ⊕ … ⊕ b_i is strictly increasing. Help him find such a permutation or determine that it is impossible.

Input

The first line contains a single integer n (1 ≤ n ≤ 10^5).

The second line contains n integers b_1, …, b_n (1 ≤ b_i < 2^{60}).

Output

If there are no valid permutations, print a single line containing "No".

Otherwise in the first line print the word "Yes", and in the second line print integers b'_1, …, b'_n — a valid permutation of integers b_i. The unordered multisets \\{b_1, …, b_n\} and \\{b'_1, …, b'_n\} should be equal, i. e. for each integer x the number of occurrences of x in the first multiset should be equal to the number of occurrences of x in the second multiset. Apart from this, the sequence a_i = b'_1 ⊕ … ⊕ b'_i should be strictly increasing.

If there are multiple answers, print any of them.

Examples

Input

3
1 2 3


Output

No


Input

6
4 7 7 12 31 61


Output

Yes
4 12 7 31 7 61 

Note

In the first example no permutation is valid.

In the second example the given answer lead to the sequence a_1 = 4, a_2 = 8, a_3 = 15, a_4 = 16, a_5 = 23, a_6 = 42.
#include <bits/stdc++.h>
using namespace std;
const long long mod = 998244353;
const int maxn = 2e5 + 5;
vector<long long> v[60];
void go() {
  int n;
  cin >> n;
  for (int i = 1; i < n + 1; i++) {
    long long x;
    cin >> x;
    for (int j = 59; j >= 0; j--) {
      if (x & (1LL << j)) {
        v[j].push_back(x);
        break;
      }
    }
  }
  vector<long long> ans;
  long long cur = 0;
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < 60; j++) {
      if (!(cur & (1LL << j)) && v[j].size()) {
        ans.push_back(v[j].back());
        cur ^= ans.back();
        v[j].pop_back();
        break;
      }
    }
    if (ans.size() != i + 1) {
      cout << "No\n";
      return;
    }
  }
  cout << "Yes\n";
  for (auto &i : ans) {
    cout << i << ' ';
  }
  cout << '\n';
}
int main() {
  ios_base::sync_with_stdio(0);
  cin.tie(0);
  int c = 0;
  int t;
  if (!c) {
    t = 1;
  } else {
    cin >> t;
  }
  while (t--) {
    go();
  }
}
