Professor Dumbledore is helping Harry destroy the Horcruxes. He went to Gaunt Shack as he suspected a Horcrux to be present there. He saw Marvolo Gaunt's Ring and identified it as a Horcrux. Although he destroyed it, he is still affected by its curse. Professor Snape is helping Dumbledore remove the curse. For this, he wants to give Dumbledore exactly x drops of the potion he made. 

Value of x is calculated as maximum of p·ai + q·aj + r·ak for given p, q, r and array a1, a2, ... an such that 1 ≤ i ≤ j ≤ k ≤ n. Help Snape find the value of x. Do note that the value of x may be negative.

Input

First line of input contains 4 integers n, p, q, r ( - 109 ≤ p, q, r ≤ 109, 1 ≤ n ≤ 105).

Next line of input contains n space separated integers a1, a2, ... an ( - 109 ≤ ai ≤ 109).

Output

Output a single integer the maximum value of p·ai + q·aj + r·ak that can be obtained provided 1 ≤ i ≤ j ≤ k ≤ n.

Examples

Input

5 1 2 3
1 2 3 4 5


Output

30


Input

5 1 2 -3
-1 -2 -3 -4 -5


Output

12

Note

In the first sample case, we can take i = j = k = 5, thus making the answer as 1·5 + 2·5 + 3·5 = 30.

In second sample case, selecting i = j = 1 and k = 5 gives the answer 12.
#include <bits/stdc++.h>
using namespace std;
const int iinf = 1e9 + 7;
const int oo = 0x3f3f3f3f;
const long long linf = 1ll << 62;
const double dinf = 1e60;
template <typename T>
inline void scf(T &x) {
  bool f = 0;
  x = 0;
  char c = getchar();
  while (c != '-' && (c < '0' || c > '9')) c = getchar();
  if (c == '-') f = 1, c = getchar();
  while (c >= '0' && c <= '9') x = x * 10 + c - '0', c = getchar();
  if (f) x = -x;
  return;
}
template <typename T1, typename T2>
void scf(T1 &x, T2 &y) {
  scf(x);
  return scf(y);
}
template <typename T1, typename T2, typename T3>
void scf(T1 &x, T2 &y, T3 &z) {
  scf(x);
  scf(y);
  return scf(z);
}
template <typename T1, typename T2, typename T3, typename T4>
void scf(T1 &x, T2 &y, T3 &z, T4 &w) {
  scf(x);
  scf(y);
  scf(z);
  return scf(w);
}
inline char mygetchar() {
  char c = getchar();
  while (c == ' ' || c == '\n') c = getchar();
  return c;
}
template <typename T>
inline bool chkmax(T &x, const T &y) {
  return y > x ? x = y, 1 : 0;
}
template <typename T>
inline bool chkmin(T &x, const T &y) {
  return y < x ? x = y, 1 : 0;
}
const int maxn = 1e5 + 100;
int n;
long long a[maxn], b[4], ans = -linf;
long long dp[maxn][4];
int main() {
  scf(n);
  scf(b[3], b[2], b[1]);
  for (int i = (1), _end_ = (n); i <= _end_; ++i) {
    scf(a[i]);
  }
  dp[n][1] = a[n] * b[1];
  dp[n][2] = dp[n][1] + a[n] * b[2];
  dp[n][3] = dp[n][2] + a[n] * b[3];
  chkmax(ans, dp[n][3]);
  for (int i = (n - 1), _end_ = (1); i >= _end_; --i) {
    for (int j = (1), _end_ = (3); j <= _end_; ++j) {
      dp[i][j] = dp[i + 1][j];
      chkmax(dp[i][j], dp[i][j - 1] + a[i] * b[j]);
    }
    chkmax(ans, dp[i][3]);
  }
  cout << ans << endl;
  return 0;
}
