The ABC number of a string T is the number of triples of integers (i, j, k) that satisfy all of the following conditions:

* 1 ≤ i < j < k ≤ |T| (|T| is the length of T.)
* T_i = `A` (T_i is the i-th character of T from the beginning.)
* T_j = `B`
* T_k = `C`



For example, when T = `ABCBC`, there are three triples of integers (i, j, k) that satisfy the conditions: (1, 2, 3), (1, 2, 5), (1, 4, 5). Thus, the ABC number of T is 3.

You are given a string S. Each character of S is `A`, `B`, `C` or `?`.

Let Q be the number of occurrences of `?` in S. We can make 3^Q strings by replacing each occurrence of `?` in S with `A`, `B` or `C`. Find the sum of the ABC numbers of all these strings.

This sum can be extremely large, so print the sum modulo 10^9 + 7.

Constraints

* 3 ≤ |S| ≤ 10^5
* Each character of S is `A`, `B`, `C` or `?`.

Input

Input is given from Standard Input in the following format:


S


Output

Print the sum of the ABC numbers of all the 3^Q strings, modulo 10^9 + 7.

Examples

Input

A??C


Output

8


Input

ABCBC


Output

3


Input

????C?????B??????A???????


Output

979596887
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.Scanner;

/*
 * AtCoder Beginner Contest 104 D "We Love ABC"
 *   https://abc104.contest.atcoder.jp/tasks/abc104_d/
 */
public class Main {

	public static void main(String[] args) {

		InputScanner in = new InputScanner(System.in);
		PrintWriter out = new PrintWriter(System.out);

		Task task = new Task();
		task.run(in, out);

		in.close();
		out.close();
	}

	static class Task {

		public void run(InputScanner in, PrintWriter out) {

			String S = in.next();
			int MOD = 1000000007;
			long[][] dp = new long[S.length() + 1][4];

			for (int i = S.length(); i >= 0; i--) {
				for (int j = 3; j >= 0; j--) {

					if (i == S.length()) {
						dp[i][j] = (j == 3 ? 1 : 0);
					} else {
						dp[i][j] = dp[i + 1][j] * (S.charAt(i) == '?' ? 3 : 1);
						if (j < 3) {
							if (S.charAt(i) == '?' ||
								S.charAt(i) == 'A' && j == 0 ||
								S.charAt(i) == 'B' && j == 1 ||
								S.charAt(i) == 'C' && j == 2) {
								dp[i][j] += 1 * dp[i + 1][j + 1];
							}
						}
					}
					dp[i][j] %= MOD;
				}
			}

			out.println(dp[0][0]);
		}
	}

	static long combination(long n, long k) {

		long res = 1;

		for (int i = 1; i <= k; i++) {
			res *= (n - k + i);
			res /= i;
		}

		return res;
	}

	/*
	 * extends java.util.Scanner
	 */
	static class InputScanner {

		Scanner scanner;

		public InputScanner(InputStream inputStream) {
			this.scanner = new Scanner(inputStream);
		}

		public boolean hasNext() {
			return scanner.hasNext();
		}

		public int nextInt() {
			return Integer.parseInt(scanner.next());
		}

		public long nextLong() {
			return Long.parseLong(scanner.next());
		}

		public double nextDouble() {
			return Double.parseDouble(scanner.next());
		}
		public String next() {
			return scanner.next();
		}

		public int[] nextIntArray(int n) {
			int[] ret = new int[n];
			for (int i = 0; i < n; i++) {
				ret[i] = scanner.nextInt();
			}
			return ret;
		}

		public int[][] nextIntArray(int h, int w) {
			int[][] ret = new int[h][w];
			for (int i = 0; i < h; i++) {
				for (int j = 0; j < w; j++) {
					ret[i][j] = scanner.nextInt();
				}
			}
			return ret;
		}

		public long[] nextLongArray(int n) {
			long[] ret = new long[n];
			for (int i = 0; i < n; i++) {
				ret[i] = scanner.nextLong();
			}
			return ret;
		}

		public long[][] nextlongArray(int h, int w) {
			long[][] ret = new long[h][w];
			for (int i = 0; i < h; i++) {
				for (int j = 0; j < w; j++) {
					ret[i][j] = scanner.nextLong();
				}
			}
			return ret;
		}

		public double[] nextDoubleArray(int n) {
			double[] ret = new double[n];
			for (int i = 0; i < n; i++) {
				ret[i] = scanner.nextDouble();
			}
			return ret;
		}

		public double[][] nextDoubleArray(int h, int w) {
			double[][] ret = new double[h][w];
			for (int i = 0; i < h; i++) {
				for (int j = 0; j < w; j++) {
					ret[i][j] = scanner.nextLong();
				}
			}
			return ret;
		}

		public String[] nextStringArray(int n) {
			String[] ret = new String[n];
			for (int i = 0; i < n; i++) {
				ret[i] = scanner.next();
			}
			return ret;
		}

		public String[] nextStringArray(String split) {
			String[] ret = scanner.next().split(split);
			return ret;
		}

		public String[][] nextStringArray(int h, int w) {
			String[][] ret = new String[h][w];
			for (int i = 0; i < h; i++) {
				for (int j = 0; j < w; j++) {
					ret[i][j] = scanner.next();
				}
			}
			return ret;
		}

		public String[][] nextStringArray(int h, String split) {
			String[][] ret = new String[h][];
			for (int i = 0; i < h; i++) {
				ret[i] = scanner.next().split(split);
			}
			return ret;
		}

		public void close() {
			scanner.close();
		}

	}

}
