After the educational reform Polycarp studies only two subjects at school, Safety Studies and PE (Physical Education). During the long months of the fourth term, he received n marks in them. When teachers wrote a mark in the journal, they didn't write in what subject the mark was for, they just wrote the mark.

Now it's time to show the journal to his strict parents. Polycarp knows that recently at the Parent Meeting the parents were told that he received a Safety Studies marks and b PE marks (a + b = n). Now Polycarp wants to write a subject's name in front of each mark so that: 

  * there are exactly a Safety Studies marks, 
  * there are exactly b PE marks, 
  * the total average score in both subjects is maximum. 



An average subject grade is the sum of all marks in it, divided by the number of them. Of course, the division is performed in real numbers without rounding up or down. Polycarp aims to maximize the x1 + x2, where x1 is the average score in the first subject (Safety Studies), and x2 is the average score in the second one (Physical Education).

Input

The first line contains an integer n (2 ≤ n ≤ 105), n is the number of marks in Polycarp's Journal. The second line contains two positive integers a, b (1 ≤ a, b ≤ n - 1, a + b = n). The third line contains a sequence of integers t1, t2, ..., tn (1 ≤ ti ≤ 5), they are Polycarp's marks.

Output

Print the sequence of integers f1, f2, ..., fn, where fi (1 ≤ fi ≤ 2) is the number of a subject to which the i-th mark should be attributed. If there are several possible solutions, then print such that the sequence f1, f2, ..., fn is the smallest lexicographically.

The sequence p1, p2, ..., pn is lexicographically less than q1, q2, ..., qn if there exists such j (1 ≤ j ≤ n) that pi = qi for all 1 ≤ i < j, аnd pj < qj.

Examples

Input

5
3 2
4 4 5 4 4


Output

1 1 2 1 2 

Input

4
2 2
3 5 4 5


Output

1 1 2 2 

Input

6
1 5
4 4 4 5 4 4


Output

2 2 2 1 2 2 

Note

In the first sample the average score in the first subject is equal to 4, and in the second one — to 4.5. The total average score is 8.5.
import java.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException; 
import java.io.InputStreamReader; 
import java.util.Scanner; 
import java.util.StringTokenizer; 
import java.util.*;
import java.io.*;
public class codeforces 
{ 
   static class Student{
       int x,y;//z;
        Student(int x,int y){
            this.x=x;
            this.y=y;
            //this.z=z;
        }
    }
    static int prime[];
    static void sieveOfEratosthenes(int n) 
    { 
        // Create a boolean array "prime[0..n]" and initialize 
        // all entries it as true. A value in prime[i] will 
        // finally be false if i is Not a prime, else true. 
        int pos=0;
        prime= new int[n+1]; 
        for(int p = 2; p*p <=n; p++) 
        { 
            // If prime[p] is not changed, then it is a prime 
            if(prime[p] == 0)
            { 
                // Update all multiples of p
                prime[p]=p;
                for(int i = p*p; i <= n; i += p)
                    if(prime[i]==0)
                    prime[i] = p; 
            } 
        } 
    }
static    class Sortbyroll implements Comparator<Student> 
{ 
    // Used for sorting in ascending order of 
    // roll number 
    public int compare(Student c, Student b) 
    {
        if(c.x<b.x)
            return c.x-b.x;
        if(b.x<c.x)
            return 1;
        return c.y - b.y;
    } 
} 
static class FastReader 
    { 
        BufferedReader br; 
        StringTokenizer st; 
  
        public FastReader() 
        { 
            br = new BufferedReader(new
                     InputStreamReader(System.in)); 
        } 
  
        String next() 
        { 
            while (st == null || !st.hasMoreElements()) 
            { 
                try
                { 
                    st = new StringTokenizer(br.readLine()); 
                } 
                catch (IOException  e) 
                { 
                    e.printStackTrace(); 
                } 
            } 
            return st.nextToken(); 
        } 
  
        int nextInt() 
        { 
            return Integer.parseInt(next()); 
        } 
  
        long nextLong() 
        { 
            return Long.parseLong(next()); 
        } 
  
        double nextDouble() 
        { 
            return Double.parseDouble(next()); 
        } 
  
        String nextLine() 
        { 
            String str = ""; 
            try
            { 
                str = br.readLine(); 
            } 
            catch (IOException e) 
            { 
                e.printStackTrace(); 
            } 
            return str; 
        } 
    } 
 
    static class Edge{
        int a,b;
        Edge(int a,int b){
            this.a=a;
            this.b=b;
        }
    }
    static class Trie{
        HashMap<Character,Trie>map;
         int c;
        Trie(){
            map=new HashMap<>();
            //z=null;
            //o=null;
            c=0;
        }
    }
    //static long ans;
    static int parent[];
    static int rank[];
    static int b[];
    static int bo[][];
    static int ho[][];
    static int seg[];
    //static int pos;
    static long mod=1000000000+7;
    //static int dp[][];
    static HashMap<Integer,Integer>map;
    static PriorityQueue<Student>q=new PriorityQueue<>();
    //static Stack<Integer>st;
   // static ArrayList<Character>ans;
    static ArrayList<ArrayList<Integer>>adj;
    //static long ans;
    static int pos;
    static Trie root;
    static long fac[];
    static int gw,gb;
    //static long mod=(long)(998244353);
    static long ans;
    static void solve()throws IOException{
        FastReader sc=new FastReader();
        int n,a,b,i,j,tb;
        n=sc.nextInt();
        a=sc.nextInt();
        b=sc.nextInt();
        int x[]=new int[n];
        for(i=0;i<n;i++)
            x[i]=sc.nextInt();
        StringBuilder sb=new StringBuilder();
        int ans[]=new int[n];
        if(a>b){
            tb=b;
            //ta=a;
            for(i=5;i>=1;i--){
                if(tb<=0)
                    break;
                for(j=n-1;j>=0;j--){
                    if(x[j]==i){
                        ans[j]=2;
                        --tb;
                        if(tb<=0)
                            break;
                    }
                }
            }
            for(i=0;i<n;i++){
                if(ans[i]==0)
                    sb.append(1+" ");
                else
                    sb.append(2+" ");
            }
        }
        else if(a<b){
            tb=b;
            for(i=1;i<=5;i++){
                if(tb<=0)
                    break;
                for(j=n-1;j>=0;j--){
                    if(x[j]==i){
                        ans[j]=2;
                        --tb;
                        if(tb<=0)
                            break;
                    }
                }
            }
            for(i=0;i<n;i++){
                if(ans[i]==0)
                    sb.append(1+" ");
                else
                    sb.append(2+" ");
            }
        }
        else{
            for(i=1;i<=a;i++)
                sb.append(1+" ");
            for(i=1;i<=b;i++){
                sb.append(2+" ");
            }
        }
        System.out.println(sb.toString());
    }
    static double dist(long x,long y,long z,long w){
        return Math.sqrt((x-y)*(x-y)+(z-w)*(z-w));
    }
    static boolean isSafe(int x,int y,int b[][],String s[] ){
        if(x>=0&&x<b.length&&y>=0&&y<b[0].length&&s[x].charAt(y)=='#'&&b[x][y]==0)
            return true;
        return false;
    }
    static void add(int x,int y,Queue<Integer>q,Queue<Integer>v,int b[][]){
        q.add(x);
        v.add(y);
        b[x][y]=1;
    }
    static long nCr(long n, long r, 
                                    long p) 
    { 
        return (fac[(int)n]* modInverse(fac[(int)r], p) 
                % p * modInverse(fac[(int)(n-r)], p) 
                                    % p) % p; 
    } 
    //static int prime[];
    //static int dp[];
    public static void main(String[] args){
        //long sum=0;
        try {
                codeforces.solve();
                } catch (Exception e) {
                    e.printStackTrace();
                }
    }
       static long modInverse(long n, long p) 
    { 
        return power(n, p-(long)2,p); 
    } 
 static long power(long x, long y, long p) 
{ 
    long res = 1;      // Initialize result 
  
    x = x % p;  // Update x if it is more than or  
                // equal to p 
  
    while (y > 0) 
    { 
        // If y is odd, multiply x with result 
        if (y %(long)2!=0) 
            res = (res*x) % p; 
  
        // y must be even now 
        y = y>>1; // y = y/2 
        x = (x*x) % p;   
    } 
    return res%p;
 }
    /*public static long power(long x,long a) {
		if(a==0) return 1;
		if(a%2==1)return (x*1L*power(x,a-1))%mod;
		return (power((int)((x*1L*x)%mod),a/2))%mod;
	}*/
   static int find(int x) 
    { 
        // Finds the representative of the set 
        // that x is an element of 
        while(parent[x]!=x) 
        { 
            // if x is not the parent of itself 
            // Then x is not the representative of 
            // his set,
            x=parent[x];
  
            // so we recursively call Find on its parent 
            // and move i's node directly under the 
            // representative of this set 
        } 
  
        return x; 
    }
    static void union(int x, int y) 
    { 
        // Find representatives of two sets 
        int xRoot = find(x), yRoot = find(y); 
  
        // Elements are in the same set, no need 
        // to unite anything. 
        if (xRoot == yRoot) 
            return; 
  
         // If x's rank is less than y's rank 
        if (rank[xRoot] < rank[yRoot]) 
  
            // Then move x under y  so that depth 
            // of tree remains less 
            parent[xRoot] = yRoot; 
  
        // Else if y's rank is less than x's rank 
        else if (rank[yRoot] < rank[xRoot]) 
  
            // Then move y under x so that depth of 
            // tree remains less 
            parent[yRoot] = xRoot; 
  
        else // if ranks are the same 
        { 
            // Then move y under x (doesn't matter 
            // which one goes where) 
            parent[yRoot] = xRoot; 
  
            // And increment the the result tree's 
            // rank by 1 
            rank[xRoot] = rank[xRoot] + 1; 
        } 
    } 
    static long gcd(long a, long b) 
    { 
        if (a == 0){ 
             //ans+=b;
            return b;
        }
        return gcd(b % a, a); 
    }
}