Chouti was doing a competitive programming competition. However, after having all the problems accepted, he got bored and decided to invent some small games.

He came up with the following game. The player has a positive integer n. Initially the value of n equals to v and the player is able to do the following operation as many times as the player want (possibly zero): choose a positive integer x that x<n and x is not a divisor of n, then subtract x from n. The goal of the player is to minimize the value of n in the end.

Soon, Chouti found the game trivial. Can you also beat the game?

Input

The input contains only one integer in the first line: v (1 ≤ v ≤ 10^9), the initial value of n.

Output

Output a single integer, the minimum value of n the player can get.

Examples

Input


8


Output


1


Input


1


Output


1

Note

In the first example, the player can choose x=3 in the first turn, then n becomes 5. He can then choose x=4 in the second turn to get n=1 as the result. There are other ways to get this minimum. However, for example, he cannot choose x=2 in the first turn because 2 is a divisor of 8.

In the second example, since n=1 initially, the player can do nothing.
import java.util.*;
import java.io.*;
public class Main
{
	static class FastReader 
	{ 
	    BufferedReader br; 
	    StringTokenizer st; 

	    public FastReader() 
	    { 
	        br = new BufferedReader(new
	                 InputStreamReader(System.in)); 
	    } 
	    String next() 
	    { 
	        while (st == null || !st.hasMoreElements()) 
	        { 
	            try
	            { 
	                st = new StringTokenizer(br.readLine()); 
	            } 
	            catch (IOException  e) 
	            { 
	                e.printStackTrace(); 
	            } 
	        } 
	        return st.nextToken(); 
	    }
	    int nextInt() 
	    { 
	        return Integer.parseInt(next()); 
	    } 
	    long nextLong() 
	    { 
	        return Long.parseLong(next()); 
	    } 
	}

	public static void main(String args[])
	{
		FastReader s=new FastReader();
		int n=s.nextInt();
		if(n!=2)
			System.out.println("1");
		else
			System.out.println("2");
	}
		
}