One beautiful July morning a terrible thing happened in Mainframe: a mean virus Megabyte somehow got access to the memory of his not less mean sister Hexadecimal. He loaded there a huge amount of n different natural numbers from 1 to n to obtain total control over her energy.

But his plan failed. The reason for this was very simple: Hexadecimal didn't perceive any information, apart from numbers written in binary format. This means that if a number in a decimal representation contained characters apart from 0 and 1, it was not stored in the memory. Now Megabyte wants to know, how many numbers were loaded successfully.

Input

Input data contains the only number n (1 ≤ n ≤ 109).

Output

Output the only number — answer to the problem.

Examples

Input

10


Output

2

Note

For n = 10 the answer includes numbers 1 and 10.
#include <bits/stdc++.h>
using namespace std;
void solve() {
  string st = "";
  cin >> st;
  long long n = st.length(), flag = 0;
  for (int i = 0; i < n; i++) {
    if (flag == 1)
      st[i] = '1';
    else if ((st[i] - '0') > 1) {
      st[i] = '1';
      flag = 1;
    }
  }
  cout << stoi(st, 0, 2);
}
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(0);
  cout.tie(0);
  long long q = 1;
  while (q--) {
    solve();
  }
  return 0;
}
