You are given three integers a, b and x. Your task is to construct a binary string s of length n = a + b such that there are exactly a zeroes, exactly b ones and exactly x indices i (where 1 ≤ i < n) such that s_i ≠ s_{i + 1}. It is guaranteed that the answer always exists.

For example, for the string "01010" there are four indices i such that 1 ≤ i < n and s_i ≠ s_{i + 1} (i = 1, 2, 3, 4). For the string "111001" there are two such indices i (i = 3, 5).

Recall that binary string is a non-empty sequence of characters where each character is either 0 or 1.

Input

The first line of the input contains three integers a, b and x (1 ≤ a, b ≤ 100, 1 ≤ x < a + b).

Output

Print only one string s, where s is any binary string satisfying conditions described above. It is guaranteed that the answer always exists.

Examples

Input

2 2 1


Output

1100


Input

3 3 3


Output

101100


Input

5 3 6


Output

01010100

Note

All possible answers for the first example: 

  * 1100; 
  * 0011. 



All possible answers for the second example: 

  * 110100; 
  * 101100; 
  * 110010; 
  * 100110; 
  * 011001; 
  * 001101; 
  * 010011; 
  * 001011. 
import java.io.*;
import java.util.*;

public class Main {
    private static class Solver {
        private void Solve() {
            int[] a = inp.nextArrayInt(2);
            int x = inp.nextInt();

            int[] ans = new int[a[0] + a[1]];
            int val = (a[0] > a[1]) ? 0 : 1;
            for (int i = 0; i < x + 1; ++i) {
                ans[i] = (i % 2 == 0) ? val : (1 - val);
                a[ans[i]] -= 1;
            }

            for (int i = 0; i < x + 1; ++i) {
                int freq = (i < 2) ? (a[ans[i]] + 1) : 1;
                for (int j = 0; j < freq; ++j) {
                    out.print(ans[i]);
                }
            }
            out.println();
        }
        static InputReader inp;
        static PrintWriter out;
    }

    private static class InputReader {
        private BufferedReader reader;
        private StringTokenizer tokenizer;

        private InputReader(InputStream stream) {
            reader = new BufferedReader(new InputStreamReader(stream), 32768);
            tokenizer = null;
        }

        private String next() {
            while (tokenizer == null || !tokenizer.hasMoreTokens()) {
                try {
                    tokenizer = new StringTokenizer(reader.readLine());
                } catch (IOException e) {
                    throw new RuntimeException(e);
                }
            }
            return tokenizer.nextToken();
        }

        private int nextInt() {
            return Integer.parseInt(next());
        }
        private long nextLong() {
            return Long.parseLong(next());
        }
        private int[] nextArrayInt(int n) {
            int[] a = new int[n];
            for (int i = 0; i < n; ++i) {
                a[i] = nextInt();
            }
            return a;
        }
    }
    public static void main(String[] args) throws IOException {
        if (!"true".equals(System.getProperty("ONLINE_JUDGE"))) {
            System.setIn(new FileInputStream(new File("input.txt")));
        }
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        Solver.inp = new InputReader(inputStream);
        Solver.out = new PrintWriter(outputStream);
        Solver solver = new Solver();
        solver.Solve();
        Solver.out.close();
    }
}