For given an integer $n$, print all permutations of $\\{1, 2, ..., n\\}$ in lexicographic order.

Constraints

* $1 \leq n \leq 9$

Input

An integer $n$ is given in a line.

Output

Print each permutation in a line in order. Separate adjacency elements by a space character.

Examples

Input

2


Output

1 2
2 1


Input

3


Output

1 2 3
1 3 2
2 1 3
2 3 1
3 1 2
3 2 1
#include <iostream>
#include <string>
#include <vector>
#include <queue>
#include <set>
#include <map>
#include <utility>
#include <stack>
#include <numeric>
#include <algorithm>
#include <stdio.h>
#include <bitset>
#include <limits.h>
#include <complex>
#include <deque>
#include <iomanip>
using namespace std;
#define MM 1000000000
#define MOD MM+7
#define pi pair<int32,int32>
#define pl pair<int64,int64>
#define chmax(a,b) (a<b ? a=b:0)
#define chmin(a,b) (a>b ? a=b:0)
const long double PI = acos(-1);
const long long INF = 1e15;
int dx[8] = {-1,0,1,0,-1,-1,1,1};
int dy[8] = {0,-1,0,1,-1,1,1,-1};
template<typename T>
T GCD(T u,T v){
    return v ? GCD(v,u%v) : u;
}
template<typename T>
T lcm(T x,T y){
    return x*y/GCD(x,y);
}
long long Pow(long long base,long long x){
    if (x == 0) return 1;
    if (x%2 == 1) return (base*Pow(base,x-1))%MOD;
    long long y = Pow(base, x/2);
    return y*y%MOD;
}

int main(){
    int n; cin >> n;
    int a[n];
    for(int i = 0; i < n; i++){
        a[i] = i+1;
    }
    do {
        for(int i = 0; i < n; i++){
            cout << a[i];
            if (i == n-1) cout << endl;
            else cout << ' ';
        } 
    } while (next_permutation(a,a+n));
    return 0;
}
  


