For given an integer $n$, print all permutations of $\\{1, 2, ..., n\\}$ in lexicographic order.

Constraints

* $1 \leq n \leq 9$

Input

An integer $n$ is given in a line.

Output

Print each permutation in a line in order. Separate adjacency elements by a space character.

Examples

Input

2


Output

1 2
2 1


Input

3


Output

1 2 3
1 3 2
2 1 3
2 3 1
3 1 2
3 2 1
#include <bits/stdc++.h>

#define INF (2e9)
#define FOR(i, a, b) for (ll (i) = (a); (i) < (b); ++(i))
#define REP(i, n) FOR(i, 0, n)

using namespace std;

template<class T>
bool chmax(T& a, const T& b) {
    if (a < b) {
        a = b;
        return true;
    }
    return false;
}

template<class T>
bool chmin(T& a, const T& b) {
    if (b < a) {
        a = b;
        return true;
    }
    return false;
}

using ll = long long;
using ld = long double;

#define ALL(x) (x).begin(), (x).end()
template<class T>
using vc = vector<T>;
using vi = vc<ll>;
using vvi = vc<vi>;

template<class T>
using va = valarray<T>;
using vad = va<ld>;
using vai = va<ll>;

using pii = pair<ll, ll>;

vi Read(ll n) {
    auto      v = vi(n);
    for (auto i = std::size_t(0); i < n; ++i) {
        cin >> v[i];
    }
    return v;
}

template<class T>
void DumpRow(const T& A) {
    for (const auto& value : A)
        cout << value << "\n";
}

template<class T>
void DumpColumn(const T& A) {
    auto isFirst = true;
    for (const auto& value : A) {
        if (isFirst) {
            cout << value;
            isFirst = false;
        } else {
            cout << " " << value;
        }

    }
    cout << endl;
}

int main() {
    cin.tie(0);
    ios::sync_with_stdio(false);

    ll n;
    cin >> n;
    auto v = vi(n);
    iota(ALL(v), 1);

    do {
        DumpColumn(v); // now
    } while (next_permutation(ALL(v)));

    return 0;
}

