Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given n numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given n numbers finds one that is different in evenness.

Input

The first line contains integer n (3 ≤ n ≤ 100) — amount of numbers in the task. The second line contains n space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness.

Output

Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order.

Examples

Input

5
2 4 7 8 10


Output

3


Input

4
1 2 1 1


Output

2
import sys
#sys.stdin = open('in.in', 'rU')
#sys.stdout = open('in.out', 'w')
    
def main():
    n = scanner.nextLong()
    nEven = 0
    nOdd = 0
    for i in range(n):
        cur = scanner.nextLong()
        if cur % 2 == 0:
            nEven += 1
            even = i
        else:
            nOdd += 1
            odd = i
    if nEven < nOdd:
        print even+1
    else:
        print odd+1
    return 
    
# IO stuff
class Scanner():
    buf = sys.stdin
    tok = []
    def __init__(self, filename=''):
        if filename:
            self.buf = open(filename, 'rU')
    
    def nextLine(self):
        return self.buf.readline()
    
    def eat(self, string):
        self.tok = string.split()
    
    def hasNext(self):
        while not self.tok:
            s = self.nextLine()
            if not s: return False
            self.eat(s)
        return True
    
    def nextToken(self):
        self.hasNext()
        res = self.tok[0]
        del self.tok[0]
        return res
    
    def nextLong(self):
        return long(self.nextToken())
    
    def nextFloat(self):
        return float(self.nextFloat())
    
scanner = Scanner()
if __name__ == '__main__':
    main()
    sys.stdin.close()
    sys.stdout.close()
