The ABC number of a string T is the number of triples of integers (i, j, k) that satisfy all of the following conditions:

* 1 ≤ i < j < k ≤ |T| (|T| is the length of T.)
* T_i = `A` (T_i is the i-th character of T from the beginning.)
* T_j = `B`
* T_k = `C`



For example, when T = `ABCBC`, there are three triples of integers (i, j, k) that satisfy the conditions: (1, 2, 3), (1, 2, 5), (1, 4, 5). Thus, the ABC number of T is 3.

You are given a string S. Each character of S is `A`, `B`, `C` or `?`.

Let Q be the number of occurrences of `?` in S. We can make 3^Q strings by replacing each occurrence of `?` in S with `A`, `B` or `C`. Find the sum of the ABC numbers of all these strings.

This sum can be extremely large, so print the sum modulo 10^9 + 7.

Constraints

* 3 ≤ |S| ≤ 10^5
* Each character of S is `A`, `B`, `C` or `?`.

Input

Input is given from Standard Input in the following format:


S


Output

Print the sum of the ABC numbers of all the 3^Q strings, modulo 10^9 + 7.

Examples

Input

A??C


Output

8


Input

ABCBC


Output

3


Input

????C?????B??????A???????


Output

979596887
S=raw_input()
N=len(S)
mod=10**9+7

num=[ [ 0 for i in range(4) ] for j in range(N) ]		# i=0 A, i=1 B, i=2 C, i=3 ?

for i in range(N):
	if i==0:
		if S[i]=="A":  num[i][0]=1
		elif S[i]=="B":  num[i][1]=1		
		elif S[i]=="C":  num[i][2]=1
		elif S[i]=="?":  num[i][3]=1
	else:
		for j in range(4):
			num[i][j]=num[i-1][j]
			
		if S[i]=="A":  num[i][0]+=1
		elif S[i]=="B":  num[i][1]+=1		
		elif S[i]=="C":  num[i][2]+=1
		elif S[i]=="?":  num[i][3]+=1		

ans=0

for i in range(1,N):
	if S[i]=="B" or S[i]=="?":
		a=num[i-1][0]
		c=num[N-1][2]-num[i][2]
		ql=num[i-1][3]
		qr=num[N-1][3]-num[i][3]

		#ABC
		ans+=a*pow(3,ql,mod)*c*pow(3,qr,mod)

		#AB?
		if qr>0:
			ans+=a*pow(3,ql,mod)*pow(3,(qr-1),mod )*qr

		#?BC
		if ql>0:
			ans+=pow(3,(ql-1),mod )*ql*c*pow(3,qr,mod)

		#?B?
		if ql>0 and qr>0:
			ans+=pow(3,(ql-1),mod )*ql*pow(3,(qr-1),mod )*qr

print ans%mod

