Recently Vasya decided to improve his pistol shooting skills. Today his coach offered him the following exercise. He placed n cans in a row on a table. Cans are numbered from left to right from 1 to n. Vasya has to knock down each can exactly once to finish the exercise. He is allowed to choose the order in which he will knock the cans down.

Vasya knows that the durability of the i-th can is a_i. It means that if Vasya has already knocked x cans down and is now about to start shooting the i-th one, he will need (a_i ⋅ x + 1) shots to knock it down. You can assume that if Vasya starts shooting the i-th can, he will be shooting it until he knocks it down.

Your task is to choose such an order of shooting so that the number of shots required to knock each of the n given cans down exactly once is minimum possible.

Input

The first line of the input contains one integer n (2 ≤ n ≤ 1 000) — the number of cans.

The second line of the input contains the sequence a_1, a_2, ..., a_n (1 ≤ a_i ≤ 1 000), where a_i is the durability of the i-th can.

Output

In the first line print the minimum number of shots required to knock each of the n given cans down exactly once.

In the second line print the sequence consisting of n distinct integers from 1 to n — the order of indices of cans that minimizes the number of shots required. If there are several answers, you can print any of them.

Examples

Input


3
20 10 20


Output


43
1 3 2 


Input


4
10 10 10 10


Output


64
2 1 4 3 


Input


6
5 4 5 4 4 5


Output


69
6 1 3 5 2 4 


Input


2
1 4


Output


3
2 1 

Note

In the first example Vasya can start shooting from the first can. He knocks it down with the first shot because he haven't knocked any other cans down before. After that he has to shoot the third can. To knock it down he shoots 20 ⋅ 1 + 1 = 21 times. After that only second can remains. To knock it down Vasya shoots 10 ⋅ 2 + 1 = 21 times. So the total number of shots is 1 + 21 + 21 = 43.

In the second example the order of shooting does not matter because all cans have the same durability.

import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.StringTokenizer;
import java.io.IOException;
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.InputStream;

/**
 * Built using CHelper plug-in
 * Actual solution is at the top
 */
public class Main {
    public static void main(String[] args) throws IOException {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        InputReader sc = new InputReader(inputStream);
        PrintWriter out = new PrintWriter(outputStream);
        Task solver = new Task();
        solver.solve(1, sc, out);
        out.close();
    }

    static class Task {
        public void solve(int testNumber, InputReader sc, PrintWriter out) throws IOException {
        	int n=sc.nextInt();
        	Node[] buf=new Node[n+1];
        	
        	for(int i=1;i<=n;i++) {
        		int val=sc.nextInt();
        		buf[i]=new Node(i,val);
        	}
        	Arrays.sort(buf,1,n+1);
            long ans=0;
            ArrayList<Integer> res=new ArrayList<Integer>();
            for(int i=1;i<=n;i++) {
            	ans+=(i-1)*buf[i].val+1;
            	res.add(buf[i].index);
            }
            out.println(ans);
            for(int v:res)
            	out.print(v+" ");
        }

    }
    
    static class Node implements Comparable<Node>{
    	int index;
    	int val;
    	
    	public Node(int index,int val) {
    		this.index=index;
    		this.val=val;
    	}

		@Override
		public int compareTo(Node o) {
			return o.val-this.val;
		}
    }

    static class InputReader {
        private InputStreamReader reader;
        private char[] buf;
        private int len, now;
     
        public InputReader(InputStream stream) {
            reader = new InputStreamReader(stream);
            buf = new char[1024];
            len = 0;
            now = 0;
        }
     
        public String next() throws IOException {
            if (!hasNext()) throw new NullPointerException();
            StringBuilder sb = new StringBuilder();
            while (!isSpaceChar(buf[now])) {
                sb.append(buf[now]);
                if (!move()) break;
            }
            return sb.toString();
        }
     
        public int nextInt() throws IOException {
            if (!hasNext()) throw new NullPointerException();
            boolean x = false;
            if (buf[now] == '-') {
                x = true;
                if (!move()) throw new NumberFormatException();
            }
            int ans = 0;
            while (!isSpaceChar(buf[now])) {
                if (isNum(buf[now])) ans = ans * 10 + buf[now] - '0';
                else throw new NumberFormatException();
                if (!move()) break;
            }
            return (x ? -1 : 1) * ans;
        }
     
        public String nextLine() throws IOException {
            if (!hasNextLine()) throw new NullPointerException();
            StringBuilder sb = new StringBuilder();
            while (buf[now] != '\n') {
                sb.append(buf[now]);
                if (!move()) return sb.toString();
            }
            now++;
            return sb.toString();
        }
     
        public long nextLong() throws IOException {
            if (!hasNext()) throw new NullPointerException();
            boolean x = false;
            if (buf[now] == '-') {
                x = true;
                if (!move()) throw new NumberFormatException();
            }
            long ans = 0;
            while (!isSpaceChar(buf[now])) {
                if (isNum(buf[now])) ans = ans * 10 + buf[now] - '0';
                else throw new NumberFormatException();
                if (!move()) break;
            }
            return (x ? -1 : 1) * ans;
        }
     
        public double nextDouble() throws IOException {
            return Double.parseDouble(next());
        }
     
        public int nextHexInt() throws IOException {
            if (!hasNext()) throw new NullPointerException();
            boolean x = false;
            if (buf[now] == '-') {
                x = true;
                if (!move()) throw new NumberFormatException();
            }
            int ans = 0;
            while (!isSpaceChar(buf[now])) {
                if (isHex(buf[now])) ans = ans * 16 + toHex(buf[now]);
                else throw new NumberFormatException();
                if (!move()) break;
            }
            return (x ? -1 : 1) * ans;
        }
     
        public char nextChar() throws IOException {
            if (!hasNext()) throw new NullPointerException();
            char tmp = buf[now];
            move();
            return tmp;
        }
        public int next(char[] s) throws IOException {
            if (!hasNext()) throw new NullPointerException();
            int len=0;
            while (!isSpaceChar(buf[now])&&len<s.length) {
                s[len++]=buf[now];
                if (!move()) break;
            }
            return len;
        }
        public boolean hasNext() throws IOException {
            return skip();
        }
     
        public boolean hasNextLine() throws IOException {
            return now < len || refill();
        }
     
        private boolean move() throws IOException {
            now++;
            return hasNextLine();
        }
     
        private boolean skip() throws IOException {
            if (!hasNextLine()) return false;
            while (isSpaceChar(buf[now])) {
                if (!move()) return false;
            }
            return true;
        }
     
        private boolean isSpaceChar(char c) {
            return !(c >= 33 && c <= 126);
        }
     
        private boolean isNum(char c) {
            return c >= '0' && c <= '9';
        }
     
        private boolean isHex(char c) {
            return c >= '0' && c <= '9' || c >= 'A' && c <= 'F';
        }
     
        private int toHex(char c) {
            if (c >= '0' && c <= '9') return c - '0';
            else return c - 'A' + 10;
        }
     
        private boolean refill() throws IOException {
            len = reader.read(buf);
            now = 0;
            return len > 0;
        }
    }
}
