For given an integer $n$, print all permutations of $\\{1, 2, ..., n\\}$ in lexicographic order.

Constraints

* $1 \leq n \leq 9$

Input

An integer $n$ is given in a line.

Output

Print each permutation in a line in order. Separate adjacency elements by a space character.

Examples

Input

2


Output

1 2
2 1


Input

3


Output

1 2 3
1 3 2
2 1 3
2 3 1
3 1 2
3 2 1
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
const ll INF = 1e18;
const ll mod = 1000000007;

#define rep(i, n) for (int i = 0; i < (int)(n); i++)
template<class T> inline bool chmax(T& a, T b) {
  if (a < b) {
    a = b;
    return 1;
  }
  return 0;
}
template<class T> inline bool chmin(T& a, T b) {
  if (a > b) {
    a = b;
    return 1;
  }
  return 0;
}
int ctoi(char c) {
  if (c >= '0' && c <= '9') {
    return c - '0';
  }
  return 0;
}
ll factorial(ll n) {
  if (n == 1) {
    return 1;
  }
  ll ans = factorial(n-1);
  return ans*n;
}
ll gcd(ll a, ll b) {
  if (a < b) {
    ll tmp = a;
    a = b;
    b = tmp;
  }
  ll r = a%b;
  while(r != 0) {
    a = b;
    b = r;
    r = a%b;
  }
  return b;
}
ll lcm(ll a, ll b) {
  return (a/gcd(a, b))*b;
}
bool prime(ll n) {
  if (n == 1) {
    return false;
  } else {
    for (ll i = 2; i <= (ll)pow(n, 0.5); i++) {
      if (n%i == 0) return false;
    }
  }
  return true;
}
ll RepeatSquaring(ll n, ll p, ll m) {
  if (p == 0) return 1;
  if (p%2 == 0) {
    ll t = RepeatSquaring(n, p/2, m);
    return (t*t)%m;
  }
  return (n*RepeatSquaring(n, p-1, m))%m;
}

int main() {
  ll n;
  cin >> n;
  vector <ll> v(n);
  rep(i, n) v.at(i) = i+1;
  do {
    rep(i, n) {
      if (i) {
        cout << ' ' << v.at(i);
      } else {
        cout << v.at(i);
      }
    }
    cout << endl;
  } while (next_permutation(v.begin(), v.end()));
}
