One beautiful July morning a terrible thing happened in Mainframe: a mean virus Megabyte somehow got access to the memory of his not less mean sister Hexadecimal. He loaded there a huge amount of n different natural numbers from 1 to n to obtain total control over her energy.

But his plan failed. The reason for this was very simple: Hexadecimal didn't perceive any information, apart from numbers written in binary format. This means that if a number in a decimal representation contained characters apart from 0 and 1, it was not stored in the memory. Now Megabyte wants to know, how many numbers were loaded successfully.

Input

Input data contains the only number n (1 ≤ n ≤ 109).

Output

Output the only number — answer to the problem.

Examples

Input

10


Output

2

Note

For n = 10 the answer includes numbers 1 and 10.
#include <bits/stdc++.h>
using namespace std;
using ll = long long int;
using ull = unsigned long long int;
int main() {
  ll a[514], ind = 1;
  a[0] = 0;
  ll n, ans = 0, done = 0;
  cin >> n;
  for (int i = 1; i <= n; i = i * 10) {
    int x = 0;
    while (a[x] < i) {
      a[ind] = i + a[x];
      if (a[ind] <= n)
        ans++;
      else {
        done = 1;
        break;
      }
      ind++;
      x++;
    }
    if (done) break;
  }
  cout << ans;
  return 0;
}
