The ABC number of a string T is the number of triples of integers (i, j, k) that satisfy all of the following conditions:

* 1 ≤ i < j < k ≤ |T| (|T| is the length of T.)
* T_i = `A` (T_i is the i-th character of T from the beginning.)
* T_j = `B`
* T_k = `C`



For example, when T = `ABCBC`, there are three triples of integers (i, j, k) that satisfy the conditions: (1, 2, 3), (1, 2, 5), (1, 4, 5). Thus, the ABC number of T is 3.

You are given a string S. Each character of S is `A`, `B`, `C` or `?`.

Let Q be the number of occurrences of `?` in S. We can make 3^Q strings by replacing each occurrence of `?` in S with `A`, `B` or `C`. Find the sum of the ABC numbers of all these strings.

This sum can be extremely large, so print the sum modulo 10^9 + 7.

Constraints

* 3 ≤ |S| ≤ 10^5
* Each character of S is `A`, `B`, `C` or `?`.

Input

Input is given from Standard Input in the following format:


S


Output

Print the sum of the ABC numbers of all the 3^Q strings, modulo 10^9 + 7.

Examples

Input

A??C


Output

8


Input

ABCBC


Output

3


Input

????C?????B??????A???????


Output

979596887
from itertools import accumulate as ac
s=input()
n=len(s)
mod=int(1e9)+7

*aca,=ac([0]+[1 if i=="A" else 0 for i in s])
*acc,=ac([0]+[1 if i=="C" else 0 for i in s])
*acq,=ac([0]+[1 if i=="?" else 0 for i in s])

v=0
for i in range(1,n-1):
  if s[i]=="B" or s[i]=="?":
    a=aca[i]
    l=acq[i]
    c=acc[n]-acc[i+1]
    r=acq[n]-acq[i+1]
    v+=(a*c*pow(3,l+r,mod))
    if l+r-1>=0:
      v+=(a*r*pow(3,l+r-1,mod))+(l*c*pow(3,l+r-1,mod))
    if l+r-2>=0:
      v+=(l*r*pow(3,l+r-2,mod))
    v%=mod
print(v)