There are n children, who study at the school №41. It is well-known that they are good mathematicians. Once at a break, they arranged a challenge for themselves. All children arranged in a row and turned heads either to the left or to the right.

Children can do the following: in one second several pairs of neighboring children who are looking at each other can simultaneously turn the head in the opposite direction. For instance, the one who was looking at the right neighbor turns left and vice versa for the second child. Moreover, every second at least one pair of neighboring children performs such action. They are going to finish when there is no pair of neighboring children who are looking at each other. 

You are given the number n, the initial arrangement of children and the number k. You have to find a way for the children to act if they want to finish the process in exactly k seconds. More formally, for each of the k moves, you need to output the numbers of the children who turn left during this move.

For instance, for the configuration shown below and k = 2 children can do the following steps: 

<image> At the beginning, two pairs make move: (1, 2) and (3, 4). After that, we receive the following configuration:  <image> At the second move pair (2, 3) makes the move. The final configuration is reached. Good job.  <image>

It is guaranteed that if the solution exists, it takes not more than n^2 "headturns".

Input

The first line of input contains two integers n and k (2 ≤ n ≤ 3000, 1 ≤ k ≤ 3000000) — the number of children and required number of moves.

The next line contains a string of length n and consists only of characters L and R, where L means that the child looks to the left and R means that the child looks to the right. 

Output

If there is no solution, print a single line with number -1.

Otherwise, output k lines. Each line has to start with a number n_i (1≤ n_i ≤ n/2) — the number of pairs of children, who turn at this move. After that print n_i distinct integers — the numbers of the children who will turn left during this move. 

After performing all "headturns", there can't be a pair of two neighboring children looking at each other.

If there are many solutions, print any of them.

Examples

Input


2 1
RL


Output


1 1 


Input


2 1
LR


Output


-1

Input


4 2
RLRL


Output


2 1 3 
1 2

Note

The first sample contains a pair of children who look at each other. After one move, they can finish the process.

In the second sample, children can't make any move. As a result, they can't end in k>0 moves.

The third configuration is described in the statement.
import java.util.LinkedList;
import java.util.Queue;
import java.util.ArrayList;
import java.util.Arrays;
import java.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;
import java.util.Random;
import java.io.FileWriter;
import java.io.PrintWriter;
/*
    Solution Created: 22:09:35 08/04/2020
    Custom Competitive programming helper.
*/

public class Main {
	public static void solve(Reader in, Writer out) {
		int n = in.nextInt(), k = in.nextInt();
		char[] a = in.next().toCharArray();
		int sz = k+10;
		Queue<Integer> v[] = new LinkedList[sz];
		for(int i = 0; i<sz; i++) v[i] = new LinkedList<Integer>();
		int steps = 0, totalSteps = 0;
		while(true) {
			for(int i = 0; i<n-1; i++) {
				if(a[i]=='R'&&a[i+1]=='L') {
					v[steps].add(i);
					a[i] = 'L';
					a[i+1] = 'R';
					totalSteps++;
					i++;
				}
			}
			if(v[steps].isEmpty()) break;
			if(steps>k) break;
			steps++;
		}
		if(steps<=k&&k<=totalSteps) {
			int idx = 0;
			for(int i = 0; i<k; i++) {
				if(v[idx].isEmpty()) idx++;
				if(steps<k) {
					out.println(1+" "+(v[idx].poll()+1));
					if(!v[idx].isEmpty()) steps++;
				}else {
					out.print(v[idx].size()+" ");
					while(!v[idx].isEmpty()) out.print((v[idx].poll()+1)+" ");
					out.println();
				}
			}
		}else out.println(-1);
	}
	
	public static void main(String[] args) {
		Reader in = new Reader();
		Writer out = new Writer();
		solve(in, out);
		out.exit();
	}

static class Graph {
	private ArrayList<Integer> con[];
	private boolean[] visited;

	public Graph(int n) {
		con = new ArrayList[n];
		for (int i = 0; i < n; ++i)
			con[i] = new ArrayList();
		visited = new boolean[n];
	}

	public void reset() {
		Arrays.fill(visited, false);
	}

	public void addEdge(int v, int w) {
		con[v].add(w);
	}

	public void dfs(int cur) {
		visited[cur] = true;
		for (Integer v : con[cur]) {
			if (!visited[v]) {
				dfs(v);
			}
		}
	}

	public void bfs(int cur) {
		Queue<Integer> q = new LinkedList<>();
		q.add(cur);
		visited[cur] = true;
		while (!q.isEmpty()) {
			cur = q.poll();
			for (Integer v : con[cur]) {
				if (!visited[v]) {
					visited[v] = true;
					q.add(v);
				}
			}
		}
	}
}

static class Reader {
	static BufferedReader br;
	static StringTokenizer st;
	private int charIdx = 0;
	private String s;

	public Reader() {
		this.br = new BufferedReader(new InputStreamReader(System.in));
	}
	
	public Reader(String f){
		try {
			this.br = new BufferedReader(new FileReader(f));
		} catch (IOException e) {
			e.printStackTrace();
		}
	}
	
	public int[] na(int n) {
		int[] a = new int[n];
		for (int i = 0; i < n; i++)
			a[i] = nextInt();
		return a;
	}

	public double[] nd(int n) {
		double[] a = new double[n];
		for (int i = 0; i < n; i++)
			a[i] = nextDouble();
		return a;
	}

	public char nextChar() {
		if (s == null || charIdx >= s.length()) {
			if (st == null || !st.hasMoreTokens())
				try {
					readLine();
				} catch (Exception e) {
				}
			s = st.nextToken();
			charIdx = 0;
		}
		return s.charAt(charIdx++);
	}

	public long[] nl(int n) {
		long[] a = new long[n];
		for (int i = 0; i < n; i++)
			a[i] = nextLong();
		return a;
	}

	public char[] nca() {
		return next().toCharArray();
	}

	public String[] nS(int n) {
		String[] a = new String[n];
		for (int i = 0; i < n; i++)
			a[i] = next();
		return a;
	}

	public int nextInt() {
		if (st == null || !st.hasMoreTokens())
			try {
				readLine();
			} catch (Exception e) {
			}
		return Integer.parseInt(st.nextToken());
	}

	public double nextDouble() {
		if (st == null || !st.hasMoreTokens())
			try {
				readLine();
			} catch (Exception e) {
			}
		return Double.parseDouble(st.nextToken());
	}

	public Long nextLong() {
		if (st == null || !st.hasMoreTokens())
			try {
				readLine();
			} catch (Exception e) {
			}
		return Long.parseLong(st.nextToken());
	}

	public String next() {
		if (st == null || !st.hasMoreTokens())
			try {
				readLine();
			} catch (Exception e) {
			}
		return st.nextToken();
	}

	public static void readLine() {
		try {
			st = new StringTokenizer(br.readLine());
		} catch (Exception e) {
		}
	}
}

static class Util{
		private static Random random = new Random();
		
		//##################################################################################################################
		//# Factorial computation algorithm																				   #
		//##################################################################################################################
		static long[] fact;
		public static void initFactorial(int n, long mod) {
			fact = new long[n+1];
			fact[0] = 1;
			for (int i = 1; i < n+1; i++) fact[i] = (fact[i - 1] * i) % mod;
		}
		
		//##################################################################################################################
		//# Mod inverse algorithm																						   #
		//##################################################################################################################
		public static long modInverse(long a, long MOD) {
			long[] gcdE = gcdExtended(a, MOD);
			if (gcdE[0] != 1) return -1; // Inverted doesn't exist
			long x = gcdE[1];
			return (x % MOD + MOD) % MOD;
		}

		//##################################################################################################################
		//# Euclid's gcd extended algorithm																				   #
		//##################################################################################################################
		public static long[] gcdExtended(long p, long q) {
			if (q == 0) return new long[] { p, 1, 0 };
			long[] vals = gcdExtended(q, p % q);
			long tmp = vals[2];
			vals[2] = vals[1] - (p / q) * vals[2];
			vals[1] = tmp;
			return vals;
		}
		
		//##################################################################################################################
		//# nCr computation algorithms.																					   #
		//##################################################################################################################
		public static long nCr(int n, int r, long MOD) {
			if (r == 0) return 1;
			return (fact[n] * modInverse(fact[r], MOD) % MOD * modInverse(fact[n - r], MOD) % MOD) % MOD;
		}
		public static long nCr(int n, int r) {
			return (fact[n]/fact[r])/fact[n-r];
		}
		
		//##################################################################################################################
		//# nPr computation algorithms.																					   #
		//##################################################################################################################
		public static long nPr(int n, int r, long MOD) {
			if (r == 0) return 1;
			return (fact[n] * modInverse(fact[n - r], MOD) % MOD) % MOD;
		}
		public static long nPr(int n, int r) {
			return fact[n]/fact[n-r];
		}
		
		//##################################################################################################################
		//# Checks if the given integer is Prime																		   #
		//##################################################################################################################
		public static boolean isPrime(int n) { 
	        if (n <= 1) return false; 
	        if (n <= 3) return true; 
	        if (n % 2 == 0 || n % 3 == 0) return false; 
	        for (int i = 5; i * i <= n; i = i + 6) 
	            if (n % i == 0 || n % (i + 2) == 0) 
	            return false; 
	        return true; 
	    }
		
		//##################################################################################################################
		//# Returns the smallest index i such that a[i]>=val, for int and long values									   #
		//##################################################################################################################
	    public static int lowerBound(int[] a, int v) {
	    	int l = 0, h = a.length;
	    	while(l<h) {
	    		int mid = (l+h)/2;
	    		if(v<=a[mid]) h = mid;
	    		else l = mid+1;
	    	}
	    	return l;
	    }
	    public static int lowerBound(long[] a, long v) {
	    	int l = 0, h = a.length;
	    	while(l<h) {
	    		int mid = (l+h)/2;
	    		if(v<=a[mid]) h = mid;
	    		else l = mid+1;
	    	}
	    	return l;
	    }
	    
		//##################################################################################################################
		//# Returns the smallest index i such that a[i]>val, for int and long values									   #
		//##################################################################################################################
	    public static int upperBound(int[] a, int v) {
	    	int l = 0, h = a.length;
	    	while(l<h) {
	    		int mid = (l+h)/2;
	    		if(a[mid]<=v) l = mid+1;
	    		else h = mid;
	    	}
	    	return l;
	    }
	    public static int upperBound(long[] a, long v) {
	    	int l = 0, h = a.length;
	    	while(l<h) {
	    		int mid = (l+h)/2;
	    		if(a[mid]<=v) l = mid+1;
	    		else h = mid;
	    	}
	    	return l;
	    }
		
		//##################################################################################################################
		//# Returns the sieve of eratosthenes up to a value n.				   											   #
		//##################################################################################################################
	    public static boolean[] getSieve(int n) {
	        boolean[] isPrime = new boolean[n+1];
	        for (int i = 2; i <= n; i++) isPrime[i] = true;
	        for (int i = 2; i*i <= n; i++) if (isPrime[i]) 
	                for (int j = i; i*j <= n; j++) isPrime[i*j] = false;
	        return isPrime;
	    }
	    
		//##################################################################################################################
		//# Gcd algorithms for long and int values.							   											   #
		//##################################################################################################################
	    public static int gcd(int a, int b) { 
	    	int tmp = 0;
	    	while(b != 0) {
	    		tmp = b;
	    		b = a%b;
	    		a = tmp;
	    	}
	    	return a;
	    }
	    public static long gcd(long a, long b) { 
	    	long tmp = 0;
	    	while(b != 0) {
	    		tmp = b;
	    		b = a%b;
	    		a = tmp;
	    	}
	    	return a;
	    }
	    
	    //##################################################################################################################
	    //# Random number generator, from min to max.											   						   #
	    //##################################################################################################################
	    public static int random(int min, int max) {
	    	return random.nextInt(max-min+1)+min;
	    }
	    
	    //##################################################################################################################
	    //# Helper function for debug.															   						   #
	    //##################################################################################################################
		public static void dbg(Object... o) { 
			System.out.println(Arrays.deepToString(o)); 
		}
		
		//##################################################################################################################
		//# Reverse functions for int, long, float, double, char data types and for objects. 							   #
		//##################################################################################################################
		public static void reverse(int[] s, int l , int r) {
			for(int i = l; i<=(l+r)/2; i++) {
				int tmp = s[i];
				s[i] = s[r+l-i];
				s[r+l-i] = tmp;
			}
	    }
		public static void reverse(int[] s) {
			reverse(s, 0, s.length-1);
	    }
		public static void reverse(long[] s, int l , int r) {
			for(int i = l; i<=(l+r)/2; i++) {
				long tmp = s[i];
				s[i] = s[r+l-i];
				s[r+l-i] = tmp;
			}
	    }
		public static void reverse(long[] s) {
			reverse(s, 0, s.length-1);
	    }
		public static void reverse(float[] s, int l , int r) {
			for(int i = l; i<=(l+r)/2; i++) {
				float tmp = s[i];
				s[i] = s[r+l-i];
				s[r+l-i] = tmp;
			}
	    }
		public static void reverse(float[] s) {
			reverse(s, 0, s.length-1);
	    }
		public static void reverse(double[] s, int l , int r) {
			for(int i = l; i<=(l+r)/2; i++) {
				double tmp = s[i];
				s[i] = s[r+l-i];
				s[r+l-i] = tmp;
			}
	    }
		public static void reverse(double[] s) {
			reverse(s, 0, s.length-1);
	    }
		public static <T> void reverse(T[] s, int l , int r) {
			for(int i = l; i<=(l+r)/2; i++) {
				T tmp = s[i];
				s[i] = s[r+l-i];
				s[r+l-i] = tmp;
			}
	    }
		public static <T> void reverse(T[] s) {
			reverse(s, 0, s.length-1);
	    }
		
		//##################################################################################################################
		//# Shuffle functions for int, long, float, double, char data types and for objects. 							   #
		//##################################################################################################################
		public static void shuffle(int[] s) {
	        for (int i = 0; i < s.length; ++i) {
	            int j = random.nextInt(i + 1);
	            int t = s[i];
	            s[i] = s[j];
	            s[j] = t;
	        }
	    }
	    public static void shuffle(long[] s) {
	        for (int i = 0; i < s.length; ++i) {
	            int j = random.nextInt(i + 1);
	            long t = s[i];
	            s[i] = s[j];
	            s[j] = t;
	        }
	    }
	    public static void shuffle(float[] s) {
	        for (int i = 0; i < s.length; ++i) {
	            int j = random.nextInt(i + 1);
	            float t = s[i];
	            s[i] = s[j];
	            s[j] = t;
	        }
	    }
	    public static void shuffle(double[] s) {
	        for (int i = 0; i < s.length; ++i) {
	            int j = random.nextInt(i + 1);
	            double t = s[i];
	            s[i] = s[j];
	            s[j] = t;
	        }
	    }
	    public static void shuffle(char[] s) {
	        for (int i = 0; i < s.length; ++i) {
	            int j = random.nextInt(i + 1);
	            char t = s[i];
	            s[i] = s[j];
	            s[j] = t;
	        }
	    }
	    public static <T> void shuffle(T[] s) {
	        for (int i = 0; i < s.length; ++i) {
	            int j = random.nextInt(i + 1);
	            T t = s[i];
	            s[i] = s[j];
	            s[j] = t;
	        }
	    }
		
		//##################################################################################################################
		//# Sort functions for int, long, float, double, char data types and for Objects that implement comparable. 	   #
	    //# The reason that we shuffle all the data types except the Object one, is that java uses merge sort for 		   #
	    //# Objects and quickSort for the other data types. QuickSort can go up to O(n^2) for some anti-java testcases,	   #
	    //# so we need to shuffle the array to prevent that.															   #
		//##################################################################################################################
		public static void sortArray(int[] a) {
	        shuffle(a);
	        Arrays.sort(a);
	    }
		public static void sortArray(long[] a) {
			shuffle(a);
	        Arrays.sort(a);
	    }
		public static void sortArray(float[] a) {
			shuffle(a);
	        Arrays.sort(a);
	    }
		public static void sortArray(double[] a) {
			shuffle(a);
	        Arrays.sort(a);
	    }
		public static void sortArray(char[] a) {
			shuffle(a);
	        Arrays.sort(a);
	    }
		public static <T extends Comparable<T>> void sortArray(T[] a) {
	        Arrays.sort(a);
	    }
	}

static class Writer {
	private PrintWriter pw;
	public Writer(){
		pw = new PrintWriter(System.out);
	}
	
	public Writer(String f){
		try {
			pw = new PrintWriter(new FileWriter(f));
		} catch (IOException e) {
			e.printStackTrace();
		}
	}
	
	public void printArray(int[] a) {
		for(int i = 0; i<a.length; i++) print(a[i]+" ");
	}
	public void printlnArray(int[] a) {
		for(int i = 0; i<a.length; i++) print(a[i]+" ");
		pw.println();
	}
	public void printArray(long[] a) {
		for(int i = 0; i<a.length; i++) print(a[i]+" ");
	}
	public void printlnArray(long[] a) {
		for(int i = 0; i<a.length; i++) print(a[i]+" ");
		pw.println();
	}
	public void print(Object o) {
		pw.print(o.toString());
	}
	public void println(Object o) {
		pw.println(o.toString());
	}
	public void println() {
		pw.println();
	}
	public void flush() {
		pw.flush();
	}
	public void exit() {
		pw.close();
	}
}
}
