You are given three integers a, b and x. Your task is to construct a binary string s of length n = a + b such that there are exactly a zeroes, exactly b ones and exactly x indices i (where 1 ≤ i < n) such that s_i ≠ s_{i + 1}. It is guaranteed that the answer always exists.

For example, for the string "01010" there are four indices i such that 1 ≤ i < n and s_i ≠ s_{i + 1} (i = 1, 2, 3, 4). For the string "111001" there are two such indices i (i = 3, 5).

Recall that binary string is a non-empty sequence of characters where each character is either 0 or 1.

Input

The first line of the input contains three integers a, b and x (1 ≤ a, b ≤ 100, 1 ≤ x < a + b).

Output

Print only one string s, where s is any binary string satisfying conditions described above. It is guaranteed that the answer always exists.

Examples

Input

2 2 1


Output

1100


Input

3 3 3


Output

101100


Input

5 3 6


Output

01010100

Note

All possible answers for the first example: 

  * 1100; 
  * 0011. 



All possible answers for the second example: 

  * 110100; 
  * 101100; 
  * 110010; 
  * 100110; 
  * 011001; 
  * 001101; 
  * 010011; 
  * 001011. 
import java.io.*;
import java.util.*;
import java.util.Map.Entry;
import javax.swing.text.InternationalFormatter;
import java.math.*;
import java.util.Arrays;
public class RATHOD 
{
     public static void main(String[] args) throws IOException
    { 
     Reader sc=new Reader();    
     int a=sc.nextInt();
     int b=sc.nextInt();
     int k=sc.nextInt();
     int n=a+b;
     String sol="";
     int i=1;
     if(k%2==0)
     {
         if(Math.max(a,b)==a)
         {
              i=1;
             sol="0";
             for(i=1;i<=(k-2);i=i+2)
             sol=sol+"10";
             int r1=b-((k-2))/2;
             int r0=a-1-(k-2)/2;
             for(i=1;i<=r1;i++)
             sol=sol+"1";
             for(i=1;i<=r0;i++)
             sol=sol+"0";
         }
         else
         {
             i=1;
             sol="1";
             for(i=1;i<=(k-2);i=i+2)
             sol=sol+"01";
             int r1=b-1-((k-2))/2;
             int r0=a-(k-2)/2;
             for(i=1;i<=r0;i++)
             sol=sol+"0";
             for(i=1;i<=r1;i++)
             sol=sol+"1";
             
         }
     }
     else
     {
         for(i=1;i<=(k-2);i=i+2)
         {
             sol=sol+"10";
         }
         int r1=b-(k-1)/2;
         int r0=a-(k-1)/2;
         for(i=1;i<=r1;i=i+1)
         {
             sol=sol+"1";
         }
         for(i=1;i<=r0;i=i+1)
         {
             sol=sol+"0";
         }
     }
     System.out.println(sol);
    }
   
	// _________________________TEMPLATE_____________________________________________________________

	// private static int gcd(int a, int b) {
	// if(a== 0)
	// return b;
	//
	// return gcd(b%a,a);
	// }

	// static class comp implements Comparator<pair> {
	//
	// @Override
	// public int compare(pair o1, pair o2) {
	// return o2.b - o1.b;
	// }
	//
	// }

	static class pair implements Comparable<pair> {
		int min;
		int max;
		int ans;

		pair(int a, int b) {
			min = a;
			max = b;
		}

		@Override
		public int compareTo(pair o) {

			return (int) (this.min - o.max);

		}
	}

	public static class Reader {
		final private int BUFFER_SIZE = 1 << 16;
		private DataInputStream din;
		private byte[] buffer;
		private int bufferPointer, bytesRead;

		public Reader() {
			din = new DataInputStream(System.in);
			buffer = new byte[BUFFER_SIZE];
			bufferPointer = bytesRead = 0;
		}

		public Reader(String file_name) throws IOException {
			din = new DataInputStream(new FileInputStream(file_name));
			buffer = new byte[BUFFER_SIZE];
			bufferPointer = bytesRead = 0;
		}

		public String readLine() throws IOException {
			byte[] buf = new byte[100000 + 1]; // line length
			int cnt = 0, c;
			while ((c = read()) != -1) {
				if (c == '\n')
					break;
				buf[cnt++] = (byte) c;
			}
			return new String(buf, 0, cnt);
		}

		public int nextInt() throws IOException {
			int ret = 0;
			byte c = read();
			while (c <= ' ')
				c = read();
			boolean neg = (c == '-');
			if (neg)
				c = read();
			do {
				ret = ret * 10 + c - '0';
			} while ((c = read()) >= '0' && c <= '9');

			if (neg)
				return -ret;
			return ret;
		}

		public long nextLong() throws IOException {
			long ret = 0;
			byte c = read();
			while (c <= ' ')
				c = read();
			boolean neg = (c == '-');
			if (neg)
				c = read();
			do {
				ret = ret * 10 + c - '0';
			} while ((c = read()) >= '0' && c <= '9');
			if (neg)
				return -ret;
			return ret;
		}

		public double nextDouble() throws IOException {
			double ret = 0, div = 1;
			byte c = read();
			while (c <= ' ')
				c = read();
			boolean neg = (c == '-');
			if (neg)
				c = read();

			do {
				ret = ret * 10 + c - '0';
			} while ((c = read()) >= '0' && c <= '9');

			if (c == '.') {
				while ((c = read()) >= '0' && c <= '9') {
					ret += (c - '0') / (div *= 10);
				}
			}

			if (neg)
				return -ret;
			return ret;
		}

		private void fillBuffer() throws IOException {
			bytesRead = din.read(buffer, bufferPointer = 0, BUFFER_SIZE);
			if (bytesRead == -1)
				buffer[0] = -1;
		}

		private byte read() throws IOException {
			if (bufferPointer == bytesRead)
				fillBuffer();
			return buffer[bufferPointer++];
		}

		public void close() throws IOException {
			if (din == null)
				return;
			din.close();
		}

		public int[] nextIntArray(int n) throws IOException {
			int[] arr = new int[n];
			for (int i = 0; i < n; i++) {
				arr[i] = nextInt();
			}
			return arr;
		}

		public long[] nextLongArray(int n) throws IOException {
			long[] arr = new long[n];
			for (int i = 0; i < n; i++) {
				arr[i] = nextLong();
			}
			return arr;
		}

		public int[][] nextInt2DArray(int m, int n) throws IOException {
			int[][] arr = new int[m][n];
			for (int i = 0; i < m; i++) {
				for (int j = 0; j < n; j++)
					arr[i][j] = nextInt();
			}
			return arr;
		}

	}

}