In the snake exhibition, there are n rooms (numbered 0 to n - 1) arranged in a circle, with a snake in each room. The rooms are connected by n conveyor belts, and the i-th conveyor belt connects the rooms i and (i+1) mod n. In the other words, rooms 0 and 1, 1 and 2, …, n-2 and n-1, n-1 and 0 are connected with conveyor belts.

The i-th conveyor belt is in one of three states:

  * If it is clockwise, snakes can only go from room i to (i+1) mod n. 
  * If it is anticlockwise, snakes can only go from room (i+1) mod n to i. 
  * If it is off, snakes can travel in either direction. 

<image>

Above is an example with 4 rooms, where belts 0 and 3 are off, 1 is clockwise, and 2 is anticlockwise.

Each snake wants to leave its room and come back to it later. A room is returnable if the snake there can leave the room, and later come back to it using the conveyor belts. How many such returnable rooms are there?

Input

Each test contains multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 1000): the number of test cases. The description of the test cases follows. 

The first line of each test case description contains a single integer n (2 ≤ n ≤ 300 000): the number of rooms.

The next line of each test case description contains a string s of length n, consisting of only '<', '>' and '-'.

  * If s_{i} =  '>', the i-th conveyor belt goes clockwise. 
  * If s_{i} =  '<', the i-th conveyor belt goes anticlockwise. 
  * If s_{i} =  '-', the i-th conveyor belt is off. 



It is guaranteed that the sum of n among all test cases does not exceed 300 000.

Output

For each test case, output the number of returnable rooms.

Example

Input


4
4
-&gt;&lt;-
5
&gt;&gt;&gt;&gt;&gt;
3
&lt;--
2
&lt;&gt;


Output


3
5
3
0

Note

In the first test case, all rooms are returnable except room 2. The snake in the room 2 is trapped and cannot exit. This test case corresponds to the picture from the problem statement.

In the second test case, all rooms are returnable by traveling on the series of clockwise belts.
/*
 * To change this license header, choose License Headers in Project Properties.
 * To change this template file, choose Tools | Templates
 * and open the template in the editor.
 */

/**
 *
 * @author wilso
 */
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.*;
public class codeforces {
    public static void main(String[] args) {
        FastScanner sc = new FastScanner();
        PrintWriter pw = new PrintWriter(System.out);
       
        int tc = sc.ni();
        for (int rep = 0; rep < tc; rep++) {
            int n = sc.ni();
            String s = sc.next();
            pw.println(solve(s));
        }
        
        
        pw.close();
    }
    static int solve(String s) {
//       Map<Integer, Set<Integer>> graph = new HashMap<>(0);
//       for (int i = 0; i < s.length(); i++) {
//           int neighbor = (i + 1) % s.length();
//           switch (s.charAt(i)) {
//               
//           
//               case '-':
//                   graph.putIfAbsent(i, new HashSet());
//                   graph.get(i).add(neighbor);
//                   graph.putIfAbsent(neighbor, new HashSet());
//                   graph.get(neighbor).add(i);
//                   break;
//               case '>':
//                   graph.putIfAbsent(i, new HashSet());
//                   graph.get(i).add(neighbor);
//                   break;
//               default:
//                   graph.putIfAbsent(neighbor, new HashSet());
//                   graph.get(neighbor).add(i);
//           }
//                   
//       }
        if (!s.contains(">") || !s.contains("<")) return s.length();
        Set<Integer> set = new HashSet();
        for (int i = 0; i < s.length(); i++) {
            int neighbor = (i + 1) % s.length();
            if (s.charAt(i) == '-') {
                set.add(neighbor);
                set.add(i);
            }
        }
        return set.size();
    }
 
    static int summation(int x) {
        return x * (x+1) / 2;
    }
   
    
  
        
       
        
   
    
    
    static long pow(long num, long exp, long mod){
        long ans=1;
        for(int i=1;i<=exp;i++){
            ans=(ans*num)%mod;
        }
        return ans;
    }
    static boolean isPrime(int n)
    {
 
        // Check if number is less than
        // equal to 1
        if (n <= 1)
            return false;
 
        // Check if number is 2
        else if (n == 2)
            return true;
 
        // Check if n is a multiple of 2
        else if (n % 2 == 0)
            return false;
 
        // If not, then just check the odds
        for (int i = 3; i <= Math.sqrt(n); i += 2) 
        {
            if (n % i == 0)
                return false;
        }
        return true;
    }
    static int gcd(int a, int b)
    {
        if (a == 0)
            return b; 
        return gcd(b % a, a); 
    }
    static long gcd(long a, long b) {
        if (a == 0) return b;
        return gcd(b % a, a);
    }
     
    // method to return LCM of two numbers
    static int lcm(int a, int b)
    {
        return (a / gcd(a, b)) * b;
    }
    public static void sort(int[] arr) {
        Random rgen = new Random();
        for (int i = 0; i < arr.length; i++) {
            int r = rgen.nextInt(arr.length);
            int temp = arr[i];
            arr[i] = arr[r];
            arr[r] = temp;
        }
        Arrays.sort(arr);
    }
 
    public static void sort(long[] arr) {
        Random rgen = new Random();
        for (int i = 0; i < arr.length; i++) {
            int r = rgen.nextInt(arr.length);
            long temp = arr[i];
            arr[i] = arr[r];
            arr[r] = temp;
        }
        Arrays.sort(arr);
    }
     
    public static void sort(int[][] arr) {
        //Sort an array (immune to quicksort TLE)
        Random rgen = new Random();
        for (int i = 0; i < arr.length; i++) {
            int randomPosition = rgen.nextInt(arr.length);
            int[] temp = arr[i];
            arr[i] = arr[randomPosition];
            arr[randomPosition] = temp;
        }
        Arrays.sort(arr, new Comparator<int[]>() {
            @Override
            public int compare(int[] a, int[] b) {
                if (a[1] > b[1])
                    return 1;
                else if (a[1] < b[1])
                    return -1;
                else
                    return 0;
            }
        });
    }
}

class FastScanner {
    BufferedReader br;
    StringTokenizer st;

    public FastScanner() {
        br = new BufferedReader(new InputStreamReader(System.in), 32768);
        st = null;
    }

    String next() {
        while (st == null || !st.hasMoreElements()) {
            try {
                st = new StringTokenizer(br.readLine());
            } catch (IOException e) {
                e.printStackTrace();
                
            }
        }
        return st.nextToken();
    }

    int ni() {
        return Integer.parseInt(next());
    }

    int[] intArray(int N) {
        int[] ret = new int[N];
        for (int i = 0; i < N; i++)
            ret[i] = ni();
        return ret;
    }

    long nl() {
        return Long.parseLong(next());
    }

    long[] longArray(int N) {
        long[] ret = new long[N];
        for (int i = 0; i < N; i++)
            ret[i] = nl();
        return ret;
    }

    double nd() {
        return Double.parseDouble(next());
    }

    String nextLine() {
        String str = "";
        try {
            str = br.readLine();
        } catch (IOException e) {
            e.printStackTrace();
        }
        return str;
    }
}

class MultiSet {
    TreeMap<Long, Integer> map = new TreeMap<>();
    private int size = 0;
    public MultiSet() {
    }
    public void add(Long val) {
        map.put(val, map.getOrDefault(val, 0) + 1);
        size++;
    }
    public void remove(Long val) {
        map.put(val, map.get(val) - 1);
        if (map.get(val) == 0) {
            map.remove(val);
        }
        size--;
    }
    public int size() {
        return size;
    }
    public Long higher(Long val) {
        return map.higherKey(val);
    }
    public Long lower(Long val) {
        return map.lowerKey(val);
    }
    public Long ceiling(Long val) {
        return map.ceilingKey(val);
    }
    public Long floor(Long val) {
        return map.floorKey(val);
    }
    public Long first() {
        return map.firstKey();
    }
    public Long last() {
        return map.lastKey();
    }
    public boolean isEmpty() {
        return map.isEmpty();
    }
}
