Polycarp remembered the 2020-th year, and he is happy with the arrival of the new 2021-th year. To remember such a wonderful moment, Polycarp wants to represent the number n as the sum of a certain number of 2020 and a certain number of 2021.

For example, if: 

  * n=4041, then the number n can be represented as the sum 2020 + 2021; 
  * n=4042, then the number n can be represented as the sum 2021 + 2021; 
  * n=8081, then the number n can be represented as the sum 2020 + 2020 + 2020 + 2021; 
  * n=8079, then the number n cannot be represented as the sum of the numbers 2020 and 2021. 



Help Polycarp to find out whether the number n can be represented as the sum of a certain number of numbers 2020 and a certain number of numbers 2021.

Input

The first line contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

Each test case contains one integer n (1 ≤ n ≤ 10^6) — the number that Polycarp wants to represent as the sum of the numbers 2020 and 2021.

Output

For each test case, output on a separate line: 

  * "YES" if the number n is representable as the sum of a certain number of 2020 and a certain number of 2021; 
  * "NO" otherwise. 



You can output "YES" and "NO" in any case (for example, the strings yEs, yes, Yes and YES will be recognized as positive).

Example

Input


5
1
4041
4042
8081
8079


Output


NO
YES
YES
YES
NO
#include <iostream>
#include <vector>
#include <algorithm>
#include <math.h>

using namespace std;

#define fi first
#define se second
#define all(x) x.begin(), x.end()
#define sz(x) x.size()
#define pb push_back
#define mk make_pair
#define tests int t; cin >> t; while(t--)
#define forn(i, a, b) for (int i = a; i < b; i++)

typedef long long ll;
typedef long double ld;

const int Z = (int)1e5 + 123;
const int inf = (int)2e9 + 123;
const ll llinf = (ll)9e18 + 123;

int main() {
    tests {
        int n;
        cin >> n;
        ll a = 0, b = n % 10;
        bool flag = false;
        while ((b * 2021) + (a * 2020) <= n) {
            if ((n - (b * 2021)) % 2020 > 0) {
                b += 10;
                continue;
            } else {
                flag = true;
                break;
            }
        }
        cout << (flag ? "YES\n" : "NO\n");
    }
    return 0;
}
