Bear Limak has n colored balls, arranged in one long row. Balls are numbered 1 through n, from left to right. There are n possible colors, also numbered 1 through n. The i-th ball has color ti.

For a fixed interval (set of consecutive elements) of balls we can define a dominant color. It's a color occurring the biggest number of times in the interval. In case of a tie between some colors, the one with the smallest number (index) is chosen as dominant.

There are <image> non-empty intervals in total. For each color, your task is to count the number of intervals in which this color is dominant.

Input

The first line of the input contains a single integer n (1 ≤ n ≤ 5000) — the number of balls.

The second line contains n integers t1, t2, ..., tn (1 ≤ ti ≤ n) where ti is the color of the i-th ball.

Output

Print n integers. The i-th of them should be equal to the number of intervals where i is a dominant color.

Examples

Input

4
1 2 1 2


Output

7 3 0 0 


Input

3
1 1 1


Output

6 0 0 

Note

In the first sample, color 2 is dominant in three intervals:

  * An interval [2, 2] contains one ball. This ball's color is 2 so it's clearly a dominant color. 
  * An interval [4, 4] contains one ball, with color 2 again. 
  * An interval [2, 4] contains two balls of color 2 and one ball of color 1. 



There are 7 more intervals and color 1 is dominant in all of them.
#include <bits/stdc++.h>
using namespace std;
int N;
int T[5000];
int c[5000];
int ans[5000];
void Main() {
  scanf("%d", &N);
  for (int i = 0; i < (N); i++) {
    int t;
    scanf("%d", &t);
    T[i] = t - 1;
  }
  for (int st = 0; st < (N); st++) {
    memset(c, 0, sizeof(c));
    int d = -1;
    int ma = 0;
    for (int i = (st); i < (N); i++) {
      int t = T[i];
      c[t]++;
      if (c[t] > ma) {
        ma = c[t];
        d = t;
      } else if (c[t] == ma) {
        if (t < d) d = t;
      }
      ans[d]++;
    }
  }
  for (int i = 0; i < (N); i++) {
    (void)printf(i + 1 < N ? "%d " : "%d\n", ans[i]);
  }
}
int main() {
  cin.tie(0);
  ios::sync_with_stdio(false);
  Main();
  return 0;
}
