On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
a = int(input().strip())

min_h = 0
max_h = 0

if a <= 5:
    min_h = 0
elif a <= 7:
    min_h = a - 5
else:
    min_h = 2 * (a // 7)
    if a % 7 == 6:
        min_h += 1

if a == 1:
    max_h = 1
elif a > 1 and  a <= 7:
    max_h = 2
else:
    max_h = 2 * (a // 7)
    if a % 7 == 1:
        max_h += 1
    elif a % 7 >= 2:
        max_h += 2


print(min_h, max_h)