You are given n numbers a1, a2, ..., an. You can perform at most k operations. For each operation you can multiply one of the numbers by x. We want to make <image> as large as possible, where <image> denotes the bitwise OR. 

Find the maximum possible value of <image> after performing at most k operations optimally.

Input

The first line contains three integers n, k and x (1 ≤ n ≤ 200 000, 1 ≤ k ≤ 10, 2 ≤ x ≤ 8).

The second line contains n integers a1, a2, ..., an (0 ≤ ai ≤ 109).

Output

Output the maximum value of a bitwise OR of sequence elements after performing operations.

Examples

Input

3 1 2
1 1 1


Output

3


Input

4 2 3
1 2 4 8


Output

79

Note

For the first sample, any possible choice of doing one operation will result the same three numbers 1, 1, 2 so the result is <image>. 

For the second sample if we multiply 8 by 3 two times we'll get 72. In this case the numbers will become 1, 2, 4, 72 so the OR value will be 79 and is the largest possible result.
import java.io.*;
import java.util.StringTokenizer;
import java.util.stream.IntStream;

public class D {

    private static class Solution implements Runnable {

        private static final long modulo = 1000000007;


        private void solve() {

            int n = in.nextInt();
            int k = in.nextInt();
            int x = in.nextInt();
            int[] a = new int[n];

            for (int i = 0; i < n; i++) {
                a[i] = in.nextInt();
            }

            long pow = pow(x, k);

            long[] leftOr = new long[n + 2];
            long[] rightOr = new long[n + 2];

            IntStream.rangeClosed(1, n).forEach(i -> leftOr[i] = leftOr[i - 1] | a[i - 1]);
            IntStream.rangeClosed(1, n).map(i -> n + 1 - i).forEach(i -> rightOr[i] = rightOr[i + 1] | a[i - 1]);

            long result = IntStream.rangeClosed(1, n)
                    .mapToLong(i -> leftOr[i - 1] | a[i - 1] * pow | rightOr[i + 1])
                    .max().getAsLong();

            out.print(result);
        }

        private int gcd(int a, int b) {
            if (b == 0)
                return a;
            else
                return gcd(b, a % b);
        }

        private long inverse(long a) {
            long result = 1;
            int n = (int) modulo - 2;
            while (n != 0) {
                if ((n & 1) == 1)
                    result = (result * a) % modulo;
                a = (a * a) % modulo;
                n >>= 1;
            }
            return result;
        }

        private long pow(long a, long n) {
            if (n == 0) return 1;
            if (n % 2 == 0) {
                long ans = pow(a, n / 2);
                return ans * ans;
            } else {
                return a * pow(a, n - 1);
            }
        }

        private void closeStreams() {
            in.close();
            out.close();
        }

        @Override
        public void run() {
            solve();
            closeStreams();
        }

        private final FastScanner in = new FastScanner();
        private final PrintWriter out = new PrintWriter(new BufferedOutputStream(System.out));
    }


    public static void main(String[] args) {
        Thread thread = new Thread(null, new Solution(), "solution", 1 << 27);
        thread.setPriority(Thread.MAX_PRIORITY);
        thread.start();
    }


    public static class FastScanner {

        private BufferedReader br;
        private StringTokenizer st;

        public FastScanner() {
            br = new BufferedReader(new InputStreamReader(System.in));
        }

        String next() {
            while (st == null || !st.hasMoreElements()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }

        int nextInt() {
            return Integer.parseInt(next());
        }

        long nextLong() {
            return Long.parseLong(next());
        }

        double nextDouble() {
            return Double.parseDouble(next());
        }

        String nextLine() {
            String str = "";
            try {
                str = br.readLine();
            } catch (IOException e) {
                e.printStackTrace();
            }
            return str;
        }

        void close() {
            try {
                br.close();
            } catch (IOException e) {
                e.printStackTrace();
            }
        }

    }
}