On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
n=int(input())

if n<7:
    if n<2:
        print(0,n)
    elif 2<=n<=5:
        print(0,2)
    else:
        print(1,2)
else:
    p=n//7*2
    q=n%7
    if q<2:
        print(p,p+q)
    elif 2<=q<=5:
        print(p,p+2)
    else:
        print(p+1,p+2)
