On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
import java.util.Scanner;
import java.io.*;
public class code
{
    static int n,w,d,min,max;
    public static void main (String[] args)
    { 
       Scanner ob=new Scanner(System.in);
       n=ob.nextInt();
     w=n/7;
     d=n%7;
    min=w*2;
    max=w*2;
    if(d==1)
    max=max+1;
    else if(d==0)
    {}
    else if(d==6)
    {
        max=max+2;
        min=min+1;
    }
    else
    max=max+2;
    System.out.println(min+" "+max);
    }
}