A string s of length n (1 ≤ n ≤ 26) is called alphabetical if it can be obtained using the following algorithm:

  * first, write an empty string to s (i.e. perform the assignment s := ""); 
  * then perform the next step n times; 
  * at the i-th step take i-th lowercase letter of the Latin alphabet and write it either to the left of the string s or to the right of the string s (i.e. perform the assignment s := c+s or s := s+c, where c is the i-th letter of the Latin alphabet). 



In other words, iterate over the n first letters of the Latin alphabet starting from 'a' and etc. Each time we prepend a letter to the left of the string s or append a letter to the right of the string s. Strings that can be obtained in that way are alphabetical.

For example, the following strings are alphabetical: "a", "ba", "ab", "bac" and "ihfcbadeg". The following strings are not alphabetical: "z", "aa", "ca", "acb", "xyz" and "ddcba".

From the given string, determine if it is alphabetical.

Input

The first line contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

Each test case is written on a separate line that contains one string s. String s consists of lowercase letters of the Latin alphabet and has a length between 1 and 26, inclusive.

Output

Output t lines, each of them must contain the answer to the corresponding test case. Output YES if the given string s is alphabetical and NO otherwise.

You can output YES and NO in any case (for example, strings yEs, yes, Yes and YES will be recognized as a positive answer).

Example

Input


11
a
ba
ab
bac
ihfcbadeg
z
aa
ca
acb
xyz
ddcba


Output


YES
YES
YES
YES
YES
NO
NO
NO
NO
NO
NO

Note

The example contains test cases from the main part of the condition.
t = int(input())
for i in range(t):
    s = input()
    n = len(s)
    d = {}
    if(n>26):
        print('No')
        continue
    limit = 97 + n - 1
    if(ord(s[n-1])==limit):
        j = n-1
        f = 0
        mid = 0
        while(j>=1):
            if(s[j] not in d):
                d[s[j]] = 1
            else:
                f = 1
                break
            if(ord(s[j-1])<ord(s[j])):
                j-=1
            else:
                if(ord(s[j])==97):
                    mid = 1
                    break
                else:
                    f = 1
                    break
        if(mid==0 and f==0 and ord(s[j])==97):
            print('Yes')
            continue
        elif(mid==1):
            j-=1
            f = 0
            while(j>=1):
                if(s[j] not in d):
                    d[s[j]] = 1
                else:
                    f = 1
                    break
                if(ord(s[j-1])>ord(s[j]) and ord(s[j-1])<limit):
                    j-=1
                else:
                    f = 1
                    break
            if(f==0 and ord(s[j])<limit and s[j] not in d):
                print('Yes')
            else:
                print('No')
        else:
            print('No')
    elif(ord(s[0])==limit):
        f = 0
        mid = 0
        j = 0
        while(j<n-1):
            if(s[j] not in d):
                d[s[j]] = 1
            else:
                f = 1
                break
            if(ord(s[j])>ord(s[j+1])):
                j+=1
            else:
                if(ord(s[j])==97):
                    mid = 1
                    break
                else:
                    f = 1
                    break
        if(mid==0 and f==0 and ord(s[j])==97):
            print('Yes')
            continue
        elif(mid==1):
            j+=1
            f = 0
            while(j<n-1):
                if(s[j] not in d):
                    d[s[j]] = 1
                else:
                    f = 1
                    break
                if(ord(s[j])<ord(s[j+1]) and ord(s[j+1])<limit):
                    j+=1
                else:
                    f = 1
                    break
            if(f==0 and ord(s[j])<limit and s[j] not in d ):
                print('Yes')
            else:
                print('No')
        else:
            print('No')
    else:
        print('No')
