On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
days = int(raw_input())
daysm = days
min_aPomba = 0
max_Atacado = 0
#Computing MIM Days off

while daysm - 7 > 0:
	min_aPomba += 2
	daysm -= 7

if daysm <= 5:
	min_aPomba += 0

else:
	min_aPomba += daysm - 5

#Computing MAX Days off
if days < 2:
	max_Atacado = days

elif days < 7:
	max_Atacado = 2

else:
	while days - 7 > 0:
		max_Atacado += 2
		days -= 7
	if days >= 2:
		max_Atacado += 2
	else:
		max_Atacado += days
		

print min_aPomba, max_Atacado 
