Jeff's got n cards, each card contains either digit 0, or digit 5. Jeff can choose several cards and put them in a line so that he gets some number. What is the largest possible number divisible by 90 Jeff can make from the cards he's got?

Jeff must make the number without leading zero. At that, we assume that number 0 doesn't contain any leading zeroes. Jeff doesn't have to use all the cards.

Input

The first line contains integer n (1 ≤ n ≤ 103). The next line contains n integers a1, a2, ..., an (ai = 0 or ai = 5). Number ai represents the digit that is written on the i-th card.

Output

In a single line print the answer to the problem — the maximum number, divisible by 90. If you can't make any divisible by 90 number from the cards, print -1.

Examples

Input

4
5 0 5 0


Output

0


Input

11
5 5 5 5 5 5 5 5 0 5 5


Output

5555555550

Note

In the first test you can make only one number that is a multiple of 90 — 0.

In the second test you can make number 5555555550, it is a multiple of 90.
import java.util.*;
import java.lang.*;
import java.io.*;
import java.math.*;

/*
 * @author Mahmoud Aladdin <aladdin3>
 *
 */
 
public class Main {
    public static void main (String[] args) throws java.lang.Exception {
		InputReader scan = new InputReader(System.in);
		PrintWriter writer = new PrintWriter(System.out, true);
		(new Main(scan, writer)).run();
		writer.close();
    }
    
    private InputReader jin;
    private PrintWriter jout;
    
    public Main(InputReader in, PrintWriter out) {
    	this.jin  = in;
    	this.jout = out;
    }
    
    public void run() throws Exception {
		int n = jin.integer();
		int five = 0;
		int zero = 0;
		for(int i = 0; i < n; i++) {
			int t = jin.integer();
			five += t == 5? 1: 0;
			zero += t == 0? 1: 0;
		}
		five = (five / 9) * 9;
		if(zero == 0) {
			jout.println(-1);
			return;
		}
		for(int i = 0; i < five; i++) {
			jout.print("5");
		}
		for(int i = 0; i < zero; i++) {
			jout.print("0");
			if(five == 0) break;
		}
		jout.println();
    }
}
 
class InputReader {
    private static final int bufferMaxLength = 1024;
    private InputStream in;
    private byte[] buffer;
    private int currentBufferSize;
    private int currentBufferTop;
    private static final String tokenizers = " \t\r\f\n";
    
    public InputReader(InputStream stream) {
        this.in = stream;
        buffer = new byte[bufferMaxLength];
        currentBufferSize = 0;
        currentBufferTop = 0;
    }
    
    private boolean refill() throws IOException {
        this.currentBufferSize = this.in.read(this.buffer);
        this.currentBufferTop = 0;
        return this.currentBufferSize > 0;
    }
    
    
    private Byte readChar() throws IOException {
        if(currentBufferTop < currentBufferSize) {
            return this.buffer[this.currentBufferTop++];
        } else {
            if(!this.refill()) {
                return null;
            } else {
                return readChar();
            }
        }
    }
    
    
    public String token() throws IOException {
        StringBuffer tok = new StringBuffer();
        Byte first;
        while((first = readChar()) != null && (tokenizers.indexOf((char) first.byteValue()) != -1));
        if(first == null) return null;
        tok.append((char)first.byteValue());
        while((first = readChar()) != null && (tokenizers.indexOf((char) first.byteValue()) == -1)) {
            tok.append((char)first.byteValue());
        }
        return tok.toString();
    }
    
    public String line() throws IOException {
		Byte first;
		StringBuffer line = new StringBuffer();
		while ((first = readChar()) != null && (char)first.byteValue() != '\n') {
			line.append((char)first.byteValue());
		}
		return (first == null && line.length() == 0)? null : line.toString();
    }
    
    public Integer integer() throws NumberFormatException, IOException {
        String tok = token();
        return tok == null? null : Integer.parseInt(tok);
    }
    
}
