On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
import java.util.Scanner;
public class Test {
	static Scanner in =new Scanner(System.in);
	public static void main(String[] args){
		int n=in.nextInt();
		int min=(n/7)*2;
		int max;
		if(n%7==1)max=min+1;
		else if(n%7>=2&&n%7<6)max=min+2;
		else if(n%7==6){
			max=min+2;
			min+=1;
		}
		else max=min;
		System.out.println(min+" "+max);
	}
}