On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
import java.util.Scanner;

public class Main{
    // Выходные на Марсе
    public static void main(String[] args) {
        int n;
        int min=0, max=0;
        int w,rest;
        Scanner sc = new Scanner(System.in);
        n = sc.nextInt();
        w = n/7;
        rest = n%7;
        min = w*2 + Math.max(0, rest - 5);
        max = w*2;
        if (rest==1){
            max += 1;
        }
        else {
            if (rest > 1)
                max += 2;
        }

        System.out.println(min + " " + max);
    }
}