On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
'''
Created on May 5, 2016

@author: Md. Rezwanul Haque
'''
n = int(input())
ans =0
res = 0
mn = 0
z = 0
rezwan =0
if(n%7 == 0):
    ans = n//7
    print((ans*2),(ans*2))
else:
    res = n//7
    mn = res*2
    z = n%7
    if(z==1):
        rezwan = mn +1
    elif z==2 or z==3 or z == 4 or z==5:
        rezwan = mn + 2
    elif z==6:
        
        rezwan = mn + 2 
        mn+=1
    print(mn,rezwan)
    