Levko loves permutations very much. A permutation of length n is a sequence of distinct positive integers, each is at most n.

Let’s assume that value gcd(a, b) shows the greatest common divisor of numbers a and b. Levko assumes that element pi of permutation p1, p2, ... , pn is good if gcd(i, pi) > 1. Levko considers a permutation beautiful, if it has exactly k good elements. Unfortunately, he doesn’t know any beautiful permutation. Your task is to help him to find at least one of them.

Input

The single line contains two integers n and k (1 ≤ n ≤ 105, 0 ≤ k ≤ n).

Output

In a single line print either any beautiful permutation or -1, if such permutation doesn’t exist.

If there are multiple suitable permutations, you are allowed to print any of them.

Examples

Input

4 2


Output

2 4 3 1

Input

1 1


Output

-1

Note

In the first sample elements 4 and 3 are good because gcd(2, 4) = 2 > 1 and gcd(3, 3) = 3 > 1. Elements 2 and 1 are not good because gcd(1, 2) = 1 and gcd(4, 1) = 1. As there are exactly 2 good elements, the permutation is beautiful.

The second sample has no beautiful permutations.
#!/usr/bin/env python3

# ------------------------------
# cs104c/assignment7/CutRibbon.py
# Copyright (C) 2017
# Drew Romanyk
# ------------------------------

# -------
# imports
# -------

import math
import sys


# -------
# solve
# -------

def solve(r, w):
    """
    :param r:
    :param w:
    :return:
    """

    data = [int(v) for v in r.readline().split()]
    n = data[0]
    k = data[1]

    if n == k:
        print(-1)
    else:
        ans = [i for i in range(n+1)]
        for i in range(n-k,1,-1):
            ans[i] = ans[i-1]
        ans[1] = n - k

        del ans[0]
        for elem in ans:
            print(elem, end=" ")


# -------
# main
# -------

if __name__ == "__main__":
    solve(sys.stdin, sys.stdout)
