We have N colored balls arranged in a row from left to right; the color of the i-th ball from the left is c_i.

You are given Q queries. The i-th query is as follows: how many different colors do the l_i-th through r_i-th balls from the left have?

Constraints

* 1\leq N,Q \leq 5 \times 10^5
* 1\leq c_i \leq N
* 1\leq l_i \leq r_i \leq N
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N Q
c_1 c_2 \cdots c_N
l_1 r_1
l_2 r_2
:
l_Q r_Q


Output

Print Q lines. The i-th line should contain the response to the i-th query.

Examples

Input

4 3
1 2 1 3
1 3
2 4
3 3


Output

2
3
1


Input

10 10
2 5 6 5 2 1 7 9 7 2
5 5
2 4
6 7
2 2
7 8
7 9
1 8
6 9
8 10
6 8


Output

1
2
2
1
2
2
6
3
3
3
# Binary Indexed Tree (Fenwick Tree)
class BIT:
    # 1-index
    def __init__(self, n):
        self.size = n
        self.tree = [0] * (n + 1)
 
    def sum(self, i):
        s = 0
        while i > 0:
            s += self.tree[i]
            i -= i & -i
        return s
 
    def add(self, i, x):
        while i <= self.size:
            self.tree[i] += x
            i += i & -i

N, Q = map(int, input().split())
c = list(map(int, input().split()))
q = []
for k in range(Q):
  l, r = map(int, input().split())
  l -= 1
  r -= 1
  q.append([l, r, k])


q.sort(key = lambda x: x[1])
ans = [0 for k in range(Q)]


good = BIT(N)
lastapp = [-1 for _ in range(N)]
end = -1
for k in range(Q):
  l = q[k][0]
  r = q[k][1]
  a = q[k][2]
  for j in range(r, end, -1):
    if lastapp[c[j]-1] == -1:
      lastapp[c[j]-1] = j
      good.add(j+1, 1)
    elif lastapp[c[j]-1] < j:
      good.add(lastapp[c[j]-1]+1, -1)
      good.add(j+1, 1)
      lastapp[c[j]-1] = j
  ans[a] = good.sum(r+1) - good.sum(l)
  end = r
  
for k in range(Q):
  print(ans[k])