One unknown hacker wants to get the admin's password of AtForces testing system, to get problems from the next contest. To achieve that, he sneaked into the administrator's office and stole a piece of paper with a list of n passwords — strings, consists of small Latin letters.

Hacker went home and started preparing to hack AtForces. He found that the system contains only passwords from the stolen list and that the system determines the equivalence of the passwords a and b as follows:

  * two passwords a and b are equivalent if there is a letter, that exists in both a and b; 
  * two passwords a and b are equivalent if there is a password c from the list, which is equivalent to both a and b. 



If a password is set in the system and an equivalent one is applied to access the system, then the user is accessed into the system.

For example, if the list contain passwords "a", "b", "ab", "d", then passwords "a", "b", "ab" are equivalent to each other, but the password "d" is not equivalent to any other password from list. In other words, if:

  * admin's password is "b", then you can access to system by using any of this passwords: "a", "b", "ab"; 
  * admin's password is "d", then you can access to system by using only "d". 



Only one password from the list is the admin's password from the testing system. Help hacker to calculate the minimal number of passwords, required to guaranteed access to the system. Keep in mind that the hacker does not know which password is set in the system.

Input

The first line contain integer n (1 ≤ n ≤ 2 ⋅ 10^5) — number of passwords in the list. Next n lines contains passwords from the list – non-empty strings s_i, with length at most 50 letters. Some of the passwords may be equal.

It is guaranteed that the total length of all passwords does not exceed 10^6 letters. All of them consist only of lowercase Latin letters.

Output

In a single line print the minimal number of passwords, the use of which will allow guaranteed to access the system.

Examples

Input


4
a
b
ab
d


Output


2

Input


3
ab
bc
abc


Output


1

Input


1
codeforces


Output


1

Note

In the second example hacker need to use any of the passwords to access the system.
import java.util.*;
import java.math.*;
import java.io.*;
import java.lang.*;

public class Main {
	public static void main(String[] args) {
        FastReader sc = new FastReader();
        int n = sc.nextInt();
        List<int[]> pass=new ArrayList<int[]>();
        for(int i=0;i<n;i++)
        {
            String s=sc.next();
            int a[]=new int[26];
            for(char ch: s.toCharArray())
            {
                int ind=(int)(ch-'a');
                a[ind]++;
            }
            pass.add(a);
        }
        //I have stored pass in teh form of the list;
        HashMap<Integer,List<int[]>> graph=new HashMap<>();
        for(int i=0;i<26;i++)
        {
            char ch=(char)((i)+'a');
            graph.put(i,new ArrayList<>());
        }
        /*
        for(int i=0;i<n;i++)
        {
            System.out.println(Arrays.toString(pass.get(i)));
        }*/
        for(int i=0;i<26;i++) //
        {
            for(int j=0;j<n;j++)
            {
                if(pass.get(j)[i]>0)
                {
                    //first pass contains ch;
                    //System.out.println(i+" "+j);
                    graph.get(i).add(pass.get(j));
                }
            }
        }
        //a is denoted as zero;
        boolean visited[]=new boolean[26];
        int count=0;
        for(int i=0;i<26;i++)
        {
            if(graph.get(i).size()>0 && visited[i]==false)
            {
                //I need to vissited this;
                //System.out.println(i +""+ visited[i]);
                count++;
                dfs(graph,visited,i); //character visiting;
            }
        } 
        System.out.println(count);
    }
    public static void dfs(HashMap<Integer,List<int[]>> graph, boolean visited[], int i)
    {
        if(visited[i]==true) return;
        visited[i]=true;
        //I can visited all the pass;
        List<int[]> pass=graph.get(i);
        //there are n number of pass;
        for(int j=0;j<pass.size();j++)
        {
            int thisPass[]=pass.get(j);
            //System.out.println(Arrays.toString(thisPass)+" "+j);
            //Now thispass has different alphbets;
            
            for(int k=0;k<26;k++)
            {
                //means this color is not visited;
                if(visited[k]==false && thisPass[k]>0)
                {
                    //System.out.println(k);
                    dfs(graph,visited,k);
                    //visited[k]=true;
                }
            }
        }
    }
    public static int partition(int arr[], int low, int high) 
    { 
        int pivot = arr[high];  
        int i = (low-1);
        for (int j=low; j<high; j++) 
        { 
            if (arr[j] < pivot) 
            { 
                i++; 
                int temp = arr[i]; 
                arr[i] = arr[j]; 
                arr[j] = temp; 
            } 
        } 
        int temp = arr[i+1]; 
        arr[i+1] = arr[high]; 
        arr[high] = temp; 
  
        return i+1; 
    } 
    public static void sort(int arr[], int low, int high) 
    { 
        if (low < high) 
        { 
            int pi = partition(arr, low, high); 
            sort(arr, low, pi-1); 
            sort(arr, pi+1, high); 
        } 
    } 
    static class Pair
    {
        int x;
        int y;
        public Pair(int x, int  y)
        {
            this.x=x;
            this.y=y;
        }
    }
static class Comp implements Comparator<Pair>
    {
        public int compare(Pair p1, Pair p2)
        {
            return p1.y-p2.y;
        }
    }
    
    
    
    
    
    static int gcd(int a,int b)
    {
        if(b==0) return a;
        return gcd(b,a%b);
    }
    
    
    static void sort(int[] a) {
		ArrayList<Integer> l=new ArrayList<>();
		for (int i:a) l.add(i);
		Collections.sort(l);
		for (int i=0; i<a.length; i++) a[i]=l.get(i);
	}
    static void sort(long[] a) {
		ArrayList<Long> l=new ArrayList<>();
		for (long i:a) l.add(i);
		Collections.sort(l);
		for (int i=0; i<a.length; i++) a[i]=l.get(i);
	}
	static class FastReader {
		BufferedReader br;
		StringTokenizer st;
 
		public FastReader() {
			br = new BufferedReader(new InputStreamReader(System.in));
		}
 
		String next() {
			while (st == null || !st.hasMoreElements()) {
				try {
					st = new StringTokenizer(br.readLine());
				} catch (final IOException e) {
					e.printStackTrace();
				}
			}
			return st.nextToken();
		}

		int nextInt() {
			return Integer.parseInt(next());
		}

		long nextLong() {
			return Long.parseLong(next());
		}

		double nextDouble() {
			return Double.parseDouble(next());
		}

		String nextLine() {
			String str = "";
			try {
				str = br.readLine();
			} catch (final IOException e) {
				e.printStackTrace();
			}
			return str;
		}

		int[] nextIntArray(final int n) {
			final int a[] = new int[n];
			for (int i = 0; i < n; i++) {
				a[i] = Integer.parseInt(next());
			}
			return a;
		}

	}	
}
//private ArrayList<String[]> action = new ArrayList<String[]>();


//Templates for Comparator and Classes - @jagrit_07
/*
Arrays.sort(newEmployees, new Comparator<Employee>() {
    @Override
    public int compare(Employee emp1, Employee emp2) {
        return emp1.getName().compareTo(emp2.getName());
    }
});
class Pair
	{
		
		long i; //index;
		long l; //left;
		long c; //cost;
		public Pair(long x,long y,long z)
		{
			this.i=x;
			this.l=y;
			this.c=z;
		}
		public String toString()
		{
			return this.i+" "+this.l+" "+this.c;
		}
	}
class Comp implements Comparator<Pair>
	{
		public int compare(Pair p1, Pair p2)
		{
			if(p1.c!=p2.c)
			{
				return (int)(p1.c-p2.c); //sort acc to cost;
			}
			else{
				return (int)(p1.i-p2.i); //sort acc to index;
			}
			
		}
	}
*/

/*
  HashMap - Put template - d.put(a1,d.getOrDefault(a1,0)+1);
  for (Map.Entry<String, Integer> entry : map.entrySet()) {
        System.out.println(entry.getKey() + ":" + entry.getValue());
    }
*/