On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
n=int(input())

if(n%7==1):
    min1=0
    max1=1
    for i in range(0,n-1,7):
        min1=min1+2
        max1=max1+2
    print(min1,max1)
    
if((n%7==2)or(n%7==3)or(n%7==4)or(n%7==5)):
     min1=0
     max1=2
     for i in range(7,n-1,7):
        min1=min1+2
        max1=max1+2
     print(min1,max1)
if(n%7==6):
    min1=1
    max1=2
    for i in range(7,n-1,7):
        min1=min1+2
        max1=max1+2
    print(min1,max1)
if(n%7==0):
    min1=0
    max1=0
    for i in range(0,n-1,7):
        min1=min1+2
        max1=max1+2
    print(min1,max1)