Constraints

* 1 ≤ |V| ≤ 1000
* 0 ≤ |E| ≤ 2000
* -10000 ≤ di ≤ 10000
* There are no parallel edges
* There are no self-loops

Input

An edge-weighted graph G (V, E) and the source r.


|V| |E| r
s0 t0 d0
s1 t1 d1
:
s|E|-1 t|E|-1 d|E|-1


|V| is the number of vertices and |E| is the number of edges in G. The graph vertices are named with the numbers 0, 1,..., |V|-1 respectively. r is the source of the graph.

si and ti represent source and target vertices of i-th edge (directed) and di represents the cost of the i-th edge.

Output

If the graph contains a negative cycle (a cycle whose sum of edge costs is a negative value) which is reachable from the source r, print


NEGATIVE CYCLE


in a line.

Otherwise, print


c0
c1
:
c|V|-1


The output consists of |V| lines. Print the cost of the shortest path from the source r to each vertex 0, 1, ... |V|-1 in order. If there is no path from the source to a vertex, print "INF".

Examples

Input

4 5 0
0 1 2
0 2 3
1 2 -5
1 3 1
2 3 2


Output

0
2
-3
-1


Input

4 6 0
0 1 2
0 2 3
1 2 -5
1 3 1
2 3 2
3 1 0


Output

NEGATIVE CYCLE


Input

4 5 1
0 1 2
0 2 3
1 2 -5
1 3 1
2 3 2


Output

INF
0
-5
-3
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
#define int long long
#define rep(i,n) for(int i=0;i<n;i++)
#define MOD 1000000007
#define INF 1000000000000000
#define fi first
#define se second
#define all(v) v.begin(),v.end()
int dx[]={0,1,0,-1},dy[]={1,0,-1,0};
#define pb push_back
//struct edge{int to,cost;};
struct edge{int from,to,cost;};
typedef pair<int,int> P;
int n,m,r,d[1010];
edge es[2010];
bool NEGATIVE_CYCLE;
void bell(int s){
	fill(d,d+n,INF);
	d[s]=0;
	for(int i=0;i<=n;i++){
		bool update=false;
		for(edge e:es){
			if(d[e.from]!=INF&&d[e.to]>d[e.from]+e.cost){
				d[e.to]=d[e.from]+e.cost;
				update=true;
			}
		}
		if(i==n&&update)NEGATIVE_CYCLE=1;
	}
}
signed main(){
	cin>>n>>m>>r;
	rep(i,m){
		int a,b,c;
		cin>>a>>b>>c;
		es[i]={a,b,c};
	}
	bell(r);
	if(NEGATIVE_CYCLE)puts("NEGATIVE CYCLE");
	else{
		rep(i,n){
			if(d[i]==INF)puts("INF");
			else cout<<d[i]<<endl;
		}
	}
	return 0;
}

