On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
n=input()
mina =1000
maxa =-1
if n<=7:
    if n<=5:
        mina = 0
        if n>=2:
            maxa=2
        else:
            maxa=n
    else:
        maxa = 2
        mina = n-5
else:
    tmp = (n%7)/5
    if n%7>5:
        tmp = tmp
    else:
        tmp = 0
    mina = (n/7)*2 + tmp
    tmp = n%7
    if tmp>=2:
        tmp=2
    else:
        tmp = tmp
    maxa = (n/7)*2 + tmp
print mina,maxa
