The preferred way to generate user login in Polygon is to concatenate a prefix of the user's first name and a prefix of their last name, in that order. Each prefix must be non-empty, and any of the prefixes can be the full name. Typically there are multiple possible logins for each person.

You are given the first and the last name of a user. Return the alphabetically earliest login they can get (regardless of other potential Polygon users).

As a reminder, a prefix of a string s is its substring which occurs at the beginning of s: "a", "ab", "abc" etc. are prefixes of string "{abcdef}" but "b" and 'bc" are not. A string a is alphabetically earlier than a string b, if a is a prefix of b, or a and b coincide up to some position, and then a has a letter that is alphabetically earlier than the corresponding letter in b: "a" and "ab" are alphabetically earlier than "ac" but "b" and "ba" are alphabetically later than "ac".

Input

The input consists of a single line containing two space-separated strings: the first and the last names. Each character of each string is a lowercase English letter. The length of each string is between 1 and 10, inclusive. 

Output

Output a single string — alphabetically earliest possible login formed from these names. The output should be given in lowercase as well.

Examples

Input

harry potter


Output

hap


Input

tom riddle


Output

tomr
import java.util.*;
import java.io.*;

public class test {
	public static void main(String[] args) throws IOException {
		Scanner s = new Scanner(System.in);
		StringTokenizer st = new StringTokenizer(s.nextLine());
		String first = st.nextToken();
		String second = st.nextToken();
		String ret = first+second;
		for(int i=1;i<=first.length();i++)
		{
			for(int j=1;j<=second.length();j++)
			{
				String test = first.substring(0, i) + second.substring(0,  j);
				if(test.compareTo(ret) < 0)
				{
					ret = test;
				}
			}
		}
		System.out.println(ret);
		s.close();
	}
}
