On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
import java.util.Scanner;
/**
 *
 * @author eslam
 */
public class Holidays {

    /**
     * @param args the command line arguments
     */
    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);
        int n = input.nextInt();
        int r = n%7;
        if(r==0){
            System.out.println(n/7*2);
            System.out.println(n/7*2);
        }else{
            if(r<2){
                System.out.println(n/7*2);
                System.out.println(n/7*2+1);
            }else{
                if(r<6){
                    System.out.println(n/7*2);
                    System.out.println(n/7*2+2);
                }else{
                    System.out.println(n/7*2+1);
                    System.out.println(n/7*2+2);
                }
            }
        }
    }
    
}
