On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
import java.io.*;
import java.util.*;

public class Main {

    public static void main(String[] args) {
        InputStream inputStream = System.in;
        PrintStream out = System.out;

//        try {
//            inputStream = new FileInputStream("input.txt");
//        } catch (FileNotFoundException e) {
//            System.exit(13);
//        }

        Scanner in = new Scanner(inputStream);
        int n = in.nextInt();
        int answer = n / 7 * 2;
        n %= 7;
        out.println(String.format("%d %d", answer + Math.max(0, n - 5), answer + Math.min(2, n)));
    }
}
