We have N colored balls arranged in a row from left to right; the color of the i-th ball from the left is c_i.

You are given Q queries. The i-th query is as follows: how many different colors do the l_i-th through r_i-th balls from the left have?

Constraints

* 1\leq N,Q \leq 5 \times 10^5
* 1\leq c_i \leq N
* 1\leq l_i \leq r_i \leq N
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N Q
c_1 c_2 \cdots c_N
l_1 r_1
l_2 r_2
:
l_Q r_Q


Output

Print Q lines. The i-th line should contain the response to the i-th query.

Examples

Input

4 3
1 2 1 3
1 3
2 4
3 3


Output

2
3
1


Input

10 10
2 5 6 5 2 1 7 9 7 2
5 5
2 4
6 7
2 2
7 8
7 9
1 8
6 9
8 10
6 8


Output

1
2
2
1
2
2
6
3
3
3
def main():
	import sys
	input=sys.stdin.readline
	n,q=map(int,input().split())
	c=list(map(int,input().split()))
	ab=[[]for i in range(n)]
	lr=[[]for i in range(n)]
	num=[-1]*n
	for i in range(n):
		if num[c[i]-1]!=-1:
			ab[num[c[i]-1]].append(i)
		num[c[i]-1]=i
	for i in range(q):
		l,r=map(int,input().split())
		lr[l-1].append((r-1,i))
	ans=[-1]*q
	BIT=[0]*n
	for i in range(n-1,-1,-1):
		for x in ab[i]:
			x+=1
			while x<=n:
				BIT[x-1]+=1
				x=x+(x&-x)
		for x,y in lr[i]:
			X=x
			x+=1
			ret=0
			while x!=0:
				ret+=BIT[x-1]
				x=x-(x&-x)
			ans[y]=X-i+1-ret
	for x in ans:
		print(x)
if __name__ == '__main__':
	main()