We have N colored balls arranged in a row from left to right; the color of the i-th ball from the left is c_i.

You are given Q queries. The i-th query is as follows: how many different colors do the l_i-th through r_i-th balls from the left have?

Constraints

* 1\leq N,Q \leq 5 \times 10^5
* 1\leq c_i \leq N
* 1\leq l_i \leq r_i \leq N
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N Q
c_1 c_2 \cdots c_N
l_1 r_1
l_2 r_2
:
l_Q r_Q


Output

Print Q lines. The i-th line should contain the response to the i-th query.

Examples

Input

4 3
1 2 1 3
1 3
2 4
3 3


Output

2
3
1


Input

10 10
2 5 6 5 2 1 7 9 7 2
5 5
2 4
6 7
2 2
7 8
7 9
1 8
6 9
8 10
6 8


Output

1
2
2
1
2
2
6
3
3
3
#include<bits/stdc++.h>
using namespace std;
int n,q,xl,xr,res;
int a[1000010],cnt[1000010],ans[1000010];
struct Node{
	int l,r,num;
}f[1000010];
inline int read(){
	int ans=0;
	char c=getchar();
	while(c<'0'||c>'9')
		c=getchar();
	while(c>='0'&&c<='9'){
		ans=ans*10+c-'0';
		c=getchar();
	}
	return ans;
}
inline bool cmp(Node a,Node b){
	if(a.l/1500!=b.l/1500)
		return a.l<b.l;
	if(a.l/1500%2)
		return a.r<b.r;
	else
		return a.r>b.r;
}
inline void Add(int x){
	if(cnt[x]==0)
		res++;
	cnt[x]++;
}
inline void Delete(int x){
	if(cnt[x]==1)
		res--;
	cnt[x]--;
}
int main(){
	n=read();
 	q=read();
	for(int i=1;i<=n;i++)
		a[i]=read();
	for(int i=1;i<=q;i++){
		f[i].l=read();
		f[i].r=read();
		f[i].num=i;
	}
	sort(f+1,f+q+1,cmp);
	xl=1,xr=1,res=1;
	cnt[a[1]]=1;
	for(int i=1;i<=q;i++){
		while(xl<f[i].l){
			Delete(a[xl]);
			xl++;
		}
		while(xl>f[i].l){
			xl--;
			Add(a[xl]);
		}
		while(xr<f[i].r){
			xr++;
			Add(a[xr]);
		}
		while(xr>f[i].r){
			Delete(a[xr]);
			xr--;
		}
		ans[f[i].num]=res;
	}
	for(int i=1;i<=q;i++)
		printf("%d\n",ans[i]);
	return 0;
}