Arpa is researching the Mexican wave.

There are n spectators in the stadium, labeled from 1 to n. They start the Mexican wave at time 0. 

  * At time 1, the first spectator stands. 
  * At time 2, the second spectator stands. 
  * ...
  * At time k, the k-th spectator stands. 
  * At time k + 1, the (k + 1)-th spectator stands and the first spectator sits. 
  * At time k + 2, the (k + 2)-th spectator stands and the second spectator sits. 
  * ...
  * At time n, the n-th spectator stands and the (n - k)-th spectator sits. 
  * At time n + 1, the (n + 1 - k)-th spectator sits. 
  * ...
  * At time n + k, the n-th spectator sits. 



Arpa wants to know how many spectators are standing at time t.

Input

The first line contains three integers n, k, t (1 ≤ n ≤ 109, 1 ≤ k ≤ n, 1 ≤ t < n + k).

Output

Print single integer: how many spectators are standing at time t.

Examples

Input

10 5 3


Output

3


Input

10 5 7


Output

5


Input

10 5 12


Output

3

Note

In the following a sitting spectator is represented as -, a standing spectator is represented as ^.

  * At t = 0  ---------- <image> number of standing spectators = 0. 
  * At t = 1  ^--------- <image> number of standing spectators = 1. 
  * At t = 2  ^^-------- <image> number of standing spectators = 2. 
  * At t = 3  ^^^------- <image> number of standing spectators = 3. 
  * At t = 4  ^^^^------ <image> number of standing spectators = 4. 
  * At t = 5  ^^^^^----- <image> number of standing spectators = 5. 
  * At t = 6  -^^^^^---- <image> number of standing spectators = 5. 
  * At t = 7  --^^^^^--- <image> number of standing spectators = 5. 
  * At t = 8  ---^^^^^-- <image> number of standing spectators = 5. 
  * At t = 9  ----^^^^^- <image> number of standing spectators = 5. 
  * At t = 10 -----^^^^^ <image> number of standing spectators = 5. 
  * At t = 11 ------^^^^ <image> number of standing spectators = 4. 
  * At t = 12 -------^^^ <image> number of standing spectators = 3. 
  * At t = 13 --------^^ <image> number of standing spectators = 2. 
  * At t = 14 ---------^ <image> number of standing spectators = 1. 
  * At t = 15 ---------- <image> number of standing spectators = 0. 
#include <bits/stdc++.h>
using namespace std;
void fast() {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  cout.tie(NULL);
}
bool isprime(long long n) {
  for (long long i = 2; (long long)i * i <= n; i++) {
    if (n % i == 0) {
      return false;
    }
  }
  return true;
}
long long fib(int n) {
  long long a = 0, b = 1, c, i;
  if (n == 0) return a;
  for (i = 2; i <= n; i++) {
    c = (a + b);
    a = b;
    b = c;
  }
  return b;
}
long long gcd(long long a, long long b) {
  if (b == 0) return a;
  return gcd(b, a % b);
}
long long extendedgcd(long long a, long long b, long long &x, long long &y) {
  if (b == 0) {
    x = 1;
    y = 0;
    return a;
  }
  long long x1, y1;
  long long d = extendedgcd(b, a % b, x1, y1);
  x = y1;
  y = x1 - y1 * (a / b);
  return d;
}
long long findgrouplcm(vector<int> &arr, int n) {
  long long ans = arr[0];
  for (long long i = 1; i < n; i++) ans = (arr[i] * (ans / (gcd(arr[i], ans))));
  return ans;
}
long long powerwithmod(long long x, unsigned long long y, long long p) {
  long long res = 1;
  x = x % p;
  if (x == 0) return 0;
  while (y > 0) {
    if (y & 1) res = (res * x) % p;
    y = y >> 1;
    x = (x * x) % p;
  }
  return res;
}
bool comp(const pair<int, int> &a, const pair<int, int> &b) {
  return a.first < b.first;
  if (a.first == b.first) return a.second < b.second;
}
void solve() {
  long long n, k, t;
  cin >> (n) >> k >> t;
  if (t < k) {
    cout << (t);
  } else if (t >= k and t <= n) {
    cout << (k);
  } else {
    cout << (n + k - t);
  }
}
int main() {
  fast();
  long long t = 1;
  while (t--) {
    solve();
  }
  return 0;
}
