On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
s=input()
s=int(s)
if s%7==0:
    x=int((s/7)*2)
    print(x,end=" ")
    print(x)
else:
    if s<7:
        if s%7==1:
            print(0, end=" ")
            print(1)
        if s%7>1 and s%7<6:
            print(0, end=" ")
            print( 2)
        if s%7==6:
            print(1, end=" ")
            print(2)
    else:
        if s%7==1:
            x=int((s/7))*2
            print(x, end=" ")
            print(x+1)
        if s%7>1 and s%7<6:
            x=int((s/7))*2
            print(x, end=" ")
            print(x + 2)
        if s%7==6:
            x = int((s / 7)) * 2
            print(x+1, end=" ")
            print(x + 2)