On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
import java.util.Scanner;

public class Test
{
    static int minNumber = 0;
    static int maxNumber = 0;

    public static void main(String[] args)
    {

        Scanner scanner = new Scanner(System.in);
        int numberofDays = scanner.nextInt();

        int x = numberofDays % 7;
        if (x == 0)
        {
            zero(numberofDays);
        }
        else
        {
            lessThanWeek(x);

            if (numberofDays > 7)
            {
                zero(numberofDays - x);
            }
        }
        System.out.println(minNumber + " " + maxNumber);
    }

    private static void zero(int x)
    {
        int offDays = (x / 7) * 2;
        minNumber += offDays;
        maxNumber += offDays;
    }

    private static void lessThanWeek(int x)
    {
        if (x <= 2)
        {
            maxNumber += x;
        }
        else
        {
            if (x == 6)
                minNumber += 1;
            maxNumber += 2;
        }
    }

}