On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
n = input()
a = n%7
b = n/7
b = b*2

maxi = 0
mi = 0
if a==1:
	maxi = b+1
	mi = b
elif a==2:
	maxi = b+2
	mi = b
elif a>2 and a<6:
	maxi = b+2
	mi = b
elif a==6:
	maxi = b+2
	mi = b+1
elif a==7:
	maxi = b+2
	mi = b+2
elif a==0:
	maxi = b
	mi = b

print mi,maxi