On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
import java.util.Scanner;

public class Main {
    public static Scanner scanner = new Scanner(System.in);

    public static void main(String[] args) {

        holidays(scanner.nextInt());
    }


    public static void holidays(int n) {
        int weeks = n/7;
        int restDays = n%7;
        int minHolidays= weeks*2;
        int maxHolidays = minHolidays;
        if(restDays>5)
            minHolidays++;
        if(restDays >2){
            maxHolidays +=2;
        }else {
            maxHolidays +=restDays;
        }

        System.out.println(minHolidays);
        System.out.println(maxHolidays);
    }
}