A string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:

* S is a palindrome.
* Let N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.
* The string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.



Determine whether S is a strong palindrome.

Constraints

* S consists of lowercase English letters.
* The length of S is an odd number between 3 and 99 (inclusive).

Input

Input is given from Standard Input in the following format:


S


Output

If S is a strong palindrome, print `Yes`; otherwise, print `No`.

Examples

Input

akasaka


Output

Yes


Input

level


Output

No


Input

atcoder


Output

No
import java.util.*;

public class Main{
    public static void main(String[] args){
        Scanner scan = new Scanner(System.in);
        String s = scan.next();
        int n = s.length();
        System.out.println(isPal(s) && isPal(s.substring(0, (n - 1) / 2)) && isPal(s.substring((n + 3) / 2 - 1)) ? "Yes" : "No");
        scan.close();
    }
    
    public static boolean isPal(String s){
        for(int i = 0; i < s.length(); i++){
            if(s.charAt(i) != s.charAt(s.length() - i - 1)) return false;
        }
        return true;
    }
}
