A string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:

* S is a palindrome.
* Let N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.
* The string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.



Determine whether S is a strong palindrome.

Constraints

* S consists of lowercase English letters.
* The length of S is an odd number between 3 and 99 (inclusive).

Input

Input is given from Standard Input in the following format:


S


Output

If S is a strong palindrome, print `Yes`; otherwise, print `No`.

Examples

Input

akasaka


Output

Yes


Input

level


Output

No


Input

atcoder


Output

No
import java.util.Scanner;

public class Main {

    private static Scanner scanner = new Scanner(System.in);

    public static void main(String[] args) {


        solve();

    }

    private static void solve() {

        String s = scanner.next();

        int n = s.length();

        boolean result = true;

        for (int i = 0; i < n / 2; i++) {

            if (i < (n / 2) / 2) {
                result &= s.charAt(i) == s.charAt((n - 1) / 2 - i-1);
                int l = i + (n + 3) / 2;
                result &= s.charAt(l) == s.charAt(n - 1 - l);
            }

            result &= s.charAt(i) == s.charAt(n - 1 - i);

        }

        System.out.println(result ? "Yes" : "No");
    }
}