On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
n = int(input())
q = 0 
cmin = 1 
cmax = 6
mn = 0
mx = 0
while (q<n):
    #print(cmin,cmax)
    if cmin>5:
        mn+=1;
        if cmin==7:
            cmin = 0
    if cmax>5:
        mx+=1
        if cmax==7:
            cmax=0
    q+=1
    cmin+=1
    cmax+=1
    
print(mn,mx)
