We have N colored balls arranged in a row from left to right; the color of the i-th ball from the left is c_i.

You are given Q queries. The i-th query is as follows: how many different colors do the l_i-th through r_i-th balls from the left have?

Constraints

* 1\leq N,Q \leq 5 \times 10^5
* 1\leq c_i \leq N
* 1\leq l_i \leq r_i \leq N
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N Q
c_1 c_2 \cdots c_N
l_1 r_1
l_2 r_2
:
l_Q r_Q


Output

Print Q lines. The i-th line should contain the response to the i-th query.

Examples

Input

4 3
1 2 1 3
1 3
2 4
3 3


Output

2
3
1


Input

10 10
2 5 6 5 2 1 7 9 7 2
5 5
2 4
6 7
2 2
7 8
7 9
1 8
6 9
8 10
6 8


Output

1
2
2
1
2
2
6
3
3
3
import sys
input = lambda: sys.stdin.readline().rstrip('\r\n')

N, Q = map(int, input().split())
C = list(map(int, input().split()))

by_R = [[] for _ in range(N+1)]
for i in range(Q):
	l, r = map(lambda s: int(s)-1, input().split())
	by_R[r+1].append((l, i))

s = [0] * N
def update(pos, dif):
	while pos < N:
		s[pos] += dif
		pos |= pos + 1

def query(pos):
	res = 0
	while pos > 0:
		res += s[pos-1]
		pos &= pos - 1
	return res

diff = 0
ans = [-1] * Q
last = [-1] * (N+1)

for i, v in enumerate(C):
	if last[v] != -1:
		update(last[v], -1)
	else:
		diff += 1

	update(i, 1)
	last[v] = i

	for l, j in by_R[i+1]:
		ans[j] = diff - query(l)

print('\n'.join(map(str, ans)))
