On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.

import java.util.*;

public class Solution 
{	
	public static void main(String[] args)
	{
		Scanner kb = new Scanner(System.in);
		int days = kb.nextInt();
		
		int remains = days % 7;
		
		int a = days - remains;
		
		 a /= 7;
		 a *= 2;
		 
		 int max = 0;
		 int min = 0;
		 
		 if(remains <= 5)
		 {
			 if(remains > 1)
				 max = 2;
			 else 
				 max = remains;
			 min = 0;
		 }
		 else
		 {
			 max = 2;
			 min = 1;
		 }
		 
		 max += a;
		 min += a;
		 
		 System.out.println(min + " " + max);
	}
}
