On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.

import java.util.Scanner;

/**
 *
 * @author Rishabh
 */
public class Main {
    public static void main(String[] args) {
        Scanner s=new Scanner(System.in);
        int n=s.nextInt();
        int x=n/7;
        int y=n%7;
        if(y==0){System.out.println((x*2)+" "+(x*2));}
        else
        {
        if(y==1)System.out.println(x*2+" "+(x*2+1));
        else if(y==6)System.out.println((x*2+1)+" "+(x*2+2));
        else System.out.println(x*2+" "+(x*2+2));
        }
    }
}
