On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.

if __name__== "__main__":
    n=input()
    p=n%7
    q=n/7*2
    mn=mx=0
    if p==0:
        mn=mx=q
    elif p>=2:
        mx=q+2
        if p==6:
            mn=q+1
        else:
            mn=q
    elif p==1:
        mx=q+1
        mn=q
    print mn,mx