On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
n = int(input())
a=0
if n>7:
    a = n%7
    if a == 0:
        print(2*(n//7),2*(n//7))
    else:
        if a<3:
            print(2*(n//7),2*(n//7)+a)
        elif a>=3 and a<=5:
            print(2*(n//7),2*(n//7)+2)
        elif a == 6:
            print(2*(n//7)+1,2*(n//7)+2)

elif n<7:
    if n == 1:
        print(0,1)
    elif n>=1 and n<=5:
        print(0,2)
    elif n==6:
        print(1,2)

else:
    print(2,2)