On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
a=int(input())
if a%7==0:
    s=(a/7)*2
    print(int(s),int(s))
elif a<6 and a>1:

    print(0,2)
elif a==1:
    print(0,1)
elif a<7:
    print(1,2)
elif a>7:
    s=a%7
    a-=s
    if s<6 and s>1:
        print(int(a/7)*2,int(a/7)*2+2)
    elif s==1:
        print(int(a/7)*2,int(a/7)*2+1)
    else:
        print(int(a/7)*2+1,int(a/7)*2+2)

