On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
a=int(input())

if(a==1):
    print(0,1)
elif(2<=a<6):
    print(0,2)
elif(a==6):
    print(1,2)
elif(a==7):
    print(2,2)
else:
    if(a%7==0):
        print((a//7)*2,(a//7)*2)
    else:
        if(a%7==1):
            print((a//7)*2,(a//7)*2+1)
        elif(a%7==6):
            print((a//7)*2+1,(a//7)*2+2)
        else:
            print((a//7)*2,(a//7)*2+2)