On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
days = int(input())

dmax = 0
dmin = 0



w = days
while w >= 0:
	w -= 7
	if w >= 0:

		dmin += 2
		dmax += 2

	elif w > - 7 :
		if w == -1:
			dmax += 2
			dmin += 1
		elif w == -6:
			dmax += 1
		elif w >= -5:
			dmax += 2



print(dmin,dmax)