On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
import java.util.*;
public class CF670A{
  public static void main(String [] args){
    Scanner input = new Scanner(System.in);
    int n = input.nextInt();
    int x = n/7; int u = n%7;
    if(u==0)System.out.println(x*2+" "+x*2);
     else{
      if(u==1)System.out.println(x*2+" "+((x*2)+1));
      else if(u > 1 && u<6) System.out.println(x*2+" "+((x*2)+2));
      else{
        System.out.println(((x*2)+1)+" "+((x*2)+2));
      }
    }
  }
}
    
    