A string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:

* S is a palindrome.
* Let N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.
* The string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.



Determine whether S is a strong palindrome.

Constraints

* S consists of lowercase English letters.
* The length of S is an odd number between 3 and 99 (inclusive).

Input

Input is given from Standard Input in the following format:


S


Output

If S is a strong palindrome, print `Yes`; otherwise, print `No`.

Examples

Input

akasaka


Output

Yes


Input

level


Output

No


Input

atcoder


Output

No
#include <algorithm>
#include <iostream>

using namespace std;

bool pal(string &s, int n) {
	for (int i = 0, j = n - 1; i < j; i++, j--)
		if (s[i] != s[j])
			return false;
	return true;
}

int main() {
	string s; cin >> s;
	int n = s.length();
	cout << (pal(s, n) && pal(s, n / 2) ? "Yes" : "No") << '\n';
	return 0;
}
