Hearing that energy drinks increase rating in those sites, Takahashi decides to buy up M cans of energy drinks.

There are N stores that sell energy drinks. In the i-th store, he can buy at most B_i cans of energy drinks for A_i yen (the currency of Japan) each.

What is the minimum amount of money with which he can buy M cans of energy drinks?

It is guaranteed that, in the given inputs, a sufficient amount of money can always buy M cans of energy drinks.

Constraints

* All values in input are integers.
* 1 \leq N, M \leq 10^5
* 1 \leq A_i \leq 10^9
* 1 \leq B_i \leq 10^5
* B_1 + ... + B_N \geq M

Input

Input is given from Standard Input in the following format:


N M
A_1 B_1
A_2 B_2
\vdots
A_N B_N


Output

Print the minimum amount of money with which Takahashi can buy M cans of energy drinks.

Examples

Input

2 5
4 9
2 4


Output

12


Input

4 30
6 18
2 5
3 10
7 9


Output

130


Input

1 100000
1000000000 100000


Output

100000000000000
import java.util.Arrays;
import java.util.Scanner;
public class Main {
	public static void main(String[] args) {
		Scanner stdIn=new Scanner(System.in);
		int N=stdIn.nextInt();
		int M=stdIn.nextInt();
		long A[][]=new long[N][2];
		int z=0,y=0;
		long man=0,cou=0;
		while(z<N){
			A[z][0]=stdIn.nextInt();
			A[z][1]=stdIn.nextInt();
			z++;
		}z=0;
		Arrays.sort(A, (a, b) -> Long.compare(a[0], b[0]));
		while(z<N){
			if(cou<M)
				if(M>=A[z][1]+cou){
					cou+=A[z][1];
					man+=A[z][0]*A[z][1];
				}
				else{
					man+=A[z][0]*(M-cou);
					break;
				}
			else
				break;
			z++;
		}
		System.out.println(man);
	}

}