One unknown hacker wants to get the admin's password of AtForces testing system, to get problems from the next contest. To achieve that, he sneaked into the administrator's office and stole a piece of paper with a list of n passwords — strings, consists of small Latin letters.

Hacker went home and started preparing to hack AtForces. He found that the system contains only passwords from the stolen list and that the system determines the equivalence of the passwords a and b as follows:

  * two passwords a and b are equivalent if there is a letter, that exists in both a and b; 
  * two passwords a and b are equivalent if there is a password c from the list, which is equivalent to both a and b. 



If a password is set in the system and an equivalent one is applied to access the system, then the user is accessed into the system.

For example, if the list contain passwords "a", "b", "ab", "d", then passwords "a", "b", "ab" are equivalent to each other, but the password "d" is not equivalent to any other password from list. In other words, if:

  * admin's password is "b", then you can access to system by using any of this passwords: "a", "b", "ab"; 
  * admin's password is "d", then you can access to system by using only "d". 



Only one password from the list is the admin's password from the testing system. Help hacker to calculate the minimal number of passwords, required to guaranteed access to the system. Keep in mind that the hacker does not know which password is set in the system.

Input

The first line contain integer n (1 ≤ n ≤ 2 ⋅ 10^5) — number of passwords in the list. Next n lines contains passwords from the list – non-empty strings s_i, with length at most 50 letters. Some of the passwords may be equal.

It is guaranteed that the total length of all passwords does not exceed 10^6 letters. All of them consist only of lowercase Latin letters.

Output

In a single line print the minimal number of passwords, the use of which will allow guaranteed to access the system.

Examples

Input


4
a
b
ab
d


Output


2

Input


3
ab
bc
abc


Output


1

Input


1
codeforces


Output


1

Note

In the second example hacker need to use any of the passwords to access the system.
import java.io.*;
import java.math.BigDecimal;
import java.math.BigInteger;
import java.math.RoundingMode;
import java.util.*;
import java.util.concurrent.LinkedBlockingDeque;

import java.util.ArrayList;
import java.util.HashMap;
import java.util.LinkedList;


// graph, dfs,bfs, get connected components,iscycle, isbipartite, dfs on trees



public class scratch_25 {
    static class Graph{

        public static class Vertex{
            HashMap<Integer,Integer> nb= new HashMap<>();     // for neighbours of each vertex
        }

        public static HashMap<Integer,Vertex> vt;   // for vertices(all)

        public Graph(){
            vt= new HashMap<>();
        }

        public static int numVer(){
            return vt.size();
        }

        public static boolean contVer(int ver){
            return vt.containsKey(ver);
        }

        public static void addVer(int ver){
            Vertex v= new Vertex();
            vt.put(ver,v);
        }
        public class Pair{
            int vname;
            ArrayList<Integer> psf= new ArrayList<>();       // path so far
            int dis;
            int col;
        }





        public static void addEdge(int ver1, int ver2, int weight){
            if(!vt.containsKey(ver1) || !vt.containsKey(ver2)){
                return;
            }
            Vertex v1= vt.get(ver1);
            Vertex v2= vt.get(ver2);
            v1.nb.put(ver2,weight);                                 // if previously there is an edge, then this replaces that edge
            v2.nb.put(ver1,weight);
        }

        public static void delEdge(int ver1, int ver2){

            if(!vt.containsKey(ver1) || !vt.containsKey(ver2)){
                return;
            }
            vt.get(ver1).nb.remove(ver2);
            vt.get(ver2).nb.remove(ver1);
        }
        public static void delVer(int ver){
            if(!vt.containsKey(ver)){
                return;
            }
            Vertex v1= vt.get(ver);
            ArrayList<Integer> arr= new ArrayList<>(v1.nb.keySet());
            for (int i = 0; i <arr.size() ; i++) {
                int s= arr.get(i);
                vt.get(s).nb.remove(ver);
            }
            vt.remove(ver);
        }
           static boolean done[];
            static int parent[];
            static ArrayList<Integer>vals= new ArrayList<>();


        public static boolean isCycle(int i){
            Stack<Integer>stk= new Stack<>();

            stk.push(i);
            while(!stk.isEmpty()){
                int x= stk.pop();
                vals.add(x);
             //   System.out.print("current="+x+" stackinit="+stk);
                if(!done[x]){
                    done[x]=true;
                }
                else if(done[x] ){
                    return true;
                }

                ArrayList<Integer>ar= new ArrayList<>(vt.get(x).nb.keySet());
                for (int j = 0; j <ar.size() ; j++) {
                   if(parent[x]!=ar.get(j)){
                       parent[ar.get(j)]=x;
                    stk.push(ar.get(j));
                   }
                }
               // System.out.println(" stackfin="+stk);
            }
            return false;
        }
        static int distance[];
        static ArrayList<Integer>ans= new ArrayList<>();

        public static void bfs(int v,ArrayList<Integer>vals,HashMap<Integer, ArrayList<Integer>>graph){
            Queue<Integer>q= new LinkedList<>();
            q.add(v);
            while(!q.isEmpty()){
                int x= q.poll();
                done[x]=true;
                vals.add(x);
                ArrayList<Integer>nei= graph.get(x);
                for (int i = 0; i <nei.size() ; i++) {
                    int a= nei.get(i);
                    if(!done[a]){
                        q.add(a);
                    }
                }
            }
        }
















    }
    // int count=0;
    //static long count=0;
    static class Reader {
        static BufferedReader reader;
        static StringTokenizer tokenizer;

        /**
         * call this method to initialize reader for InputStream
         */
        static void init(InputStream input) {
            reader = new BufferedReader(
                    new InputStreamReader(input));
            tokenizer = new StringTokenizer("");
        }

        /**
         * get next word
         */
        static String next() throws IOException {
            while (!tokenizer.hasMoreTokens()) {
                //TODO add check for eof if necessary
                tokenizer = new StringTokenizer(
                        reader.readLine());
            }
            return tokenizer.nextToken();
        }

        static int nextInt() throws IOException {
            return Integer.parseInt(next());
        }

        static double nextDouble() throws IOException {
            return Double.parseDouble(next());
        }

        static long nextLong() throws IOException {
            return Long.parseLong(next());
        }
    }



    static class DisjointSet{
        HashMap<String,Node> mp= new HashMap<>();

        public static class Node{
            String data;
            Node parent;
            int rank;
        }


        public void create(String val){
            Node nn= new Node();
            nn.data=val;
            nn.parent=nn;
            nn.rank=0;
            mp.put(val,nn);
        }

        public String find(String val){

            return findn(mp.get(val)).data;

        }


        public Node findn(Node n){
            if(n==n.parent){
                return n;
            }
            Node rr= findn(n.parent);
            n.parent=rr;
            return rr;
        }



        public void union(String val1, String val2){                                                                               // can also be used to check cycles

            Node n1= findn(mp.get(val1));
            Node n2= findn(mp.get(val2));


            if(n1.data.equals(n2.data)) {
                return;
            }



            if(n1.rank<n2.rank){
                n1.parent=n2;
            }

            else if(n2.rank<n1.rank){
                n2.parent=n1;
            }

            else {
                n2.parent=n1;
                n1.rank++;
            }

        }
    }



    // After writing solution, quick scan for:
    //   array out of bounds
    //   special cases e.g. n=1?
    //
    // Big numbers arithmetic bugs:
    //   int overflow
    //   sorting, or taking max, or negative after MOD
    public static void main(String[] args)  throws IOException {
        Reader.init(System.in);
        BufferedWriter out = new BufferedWriter(new OutputStreamWriter(System.out));
        int n= Reader.nextInt();
        DisjointSet set= new DisjointSet();
        String arr[]= new String[n];
        for (int i = 0; i <n ; i++) {
            String str= Reader.next();
            arr[i]= str;
            set.create(str);
        }
     //   System.out.println(set.mp);
        for (int i = 0; i <26 ; i++) {
            char c= (char)(i+97);
           ArrayList<String>ar= new ArrayList<>();
           boolean b=false;
            for (int j = 0; j <n ; j++) {
                String s= arr[j];
                for (int k = 0; k <s.length() ; k++) {
                    if(s.charAt(k)==c){
                        ar.add(s);
                        break;
                    }
                }
            }
            for (int j = 1; j <ar.size() ; j++) {
                set.union(ar.get(0),ar.get(j));
            }
        }
       ArrayList<String>x= new ArrayList<>(set.mp.keySet());
        Set<String>ans= new HashSet<>();
        for (int i = 0; i <x.size() ; i++) {
            ans.add(set.find(x.get(i)));
          //  System.out.println(x.get(i)+" "+set.mp.get(x.get(i)).parent.data);
        }

    out.append(ans.size()+" ");









        out.flush();
        out.close();
        }








    static long modExp(long a, long b, long mod) {
        //System.out.println("a is " + a + " and b is " + b);
        if (a==1) return 1;
        long ans = 1;
        while (b!=0) {
            if (b%2==1) {
                ans = (ans*a)%mod;
            }
            a = (a*a)%mod;
            b/=2;
        }
        return ans;
    }


    public static long modmul(long a, long b, long mod) {
        return b == 0 ? 0 : ((modmul(a, b >> 1, mod) << 1) % mod + a * (b & 1)) % mod;
    }

    static long sum(long n){
        //   System.out.println("lol="+ (n*(n-1))/2);
        return (n*(n+1))/2;
    }






    public static ArrayList<Integer> Sieve(int n) {
        boolean arr[]= new boolean [n+1];
        Arrays.fill(arr,true);
        arr[0]=false;
        arr[1]=false;
        for (int i = 2; i*i <=n ; i++) {
            if(arr[i]){
                for (int j = 2; j <=n/i ; j++) {
                    int u= i*j;
                    arr[u]=false;
                }}
        }
        ArrayList<Integer> ans= new ArrayList<>();
        for (int i = 0; i <n+1 ; i++) {
            if(arr[i]){
                ans.add(i);
            }
        }
        return ans;
    }




    static long power( long x, long y, long p)
    {

        long res = 1;


        x = x % p;

        if (x == 0) return 0;

        while (y > 0)
        {

            if((y & 1)==1)
                res = (res * x) % p;


            y = y >> 1;
            x = (x * x) % p;
        }
        return res;
    }

    public static long ceil_div(long a, long b){
        return (a+b-1)/b;
    }

    static long gcd(long a, long b)
    {
        if (a == 0)
            return b;
        return gcd(b % a, a);
    }

    static long lcm(long a, long b)
    {
        return (a*b)/gcd(a, b);
    }

}