On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
import java.util.Scanner;

public class Main {

	public static void main(String[] args) {		
		Scanner sc = new Scanner(System.in);
		int day = sc.nextInt();
		
		int max = (day>=7) ? day/7 *2 : 0;
		int min = max;
		
		if (day%7 >= 2)
			max+=2;
		if (0<day%7 && day%7<2)
			max+=day%7;
		if (day%7==6)
		    min+=1;
		
		System.out.println(min); 
		System.out.println(max);
	}
	 
}