On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
x=int(input())
lu=0
zo=0
x0=x
while x>0:
    if x==1:
        lu+=1
        x=0
    elif x>1 and x<7:
        lu+=2
        x=0
    lu+=(x//7)*2
    x%=7
while x0>0:
    if x0==6:
        zo+=1
        x0=0
    elif x0<6:
        x0=0
    zo+=(x0//7)*2
    x0%=7
print(zo,lu)