On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.

# 0  0 0 
# 1  0 1
# 2  0 2
# 3  0 2
# 4  0 2
# 5  0 2
# 6  1 2
# 7  2 2
# 8  2 3
# 9  2 4
# 10 2 4
# 11 2 4
# 12 2 4
# 13 3 5
# 14 4 6

n=int(input())
if True:
    

    low = int(n//7)*2
    high = int((n+5)//7)*2
    if n%7==6:
        low+=1
    if (n)%7==1:
        high+=1

    print(low,high)