Given is a string S consisting of digits from `1` through `9`.

Find the number of pairs of integers (i,j) (1 ≤ i ≤ j ≤ |S|) that satisfy the following condition:

Condition: In base ten, the i-th through j-th characters of S form an integer that is a multiple of 2019.

Constraints

* 1 ≤ |S| ≤ 200000
* S is a string consisting of digits from `1` through `9`.

Input

Input is given from Standard Input in the following format:


S


Output

Print the number of pairs of integers (i,j) (1 ≤ i ≤ j ≤ |S|) that satisfy the condition.

Examples

Input

1817181712114


Output

3


Input

14282668646


Output

2


Input

2119


Output

0
S = list(map(int, list(input())))
S.reverse()
a = [0]*len(S)
y = 2019
x = 1
t = 0
cnt = [0]*y
res = 0
for i in range(len(S)):
    cnt[t] += 1
    t += S[i]*x
    t %= y
    res += cnt[t]
    x = x*10%y
print(res)