A string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:

* S is a palindrome.
* Let N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.
* The string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.



Determine whether S is a strong palindrome.

Constraints

* S consists of lowercase English letters.
* The length of S is an odd number between 3 and 99 (inclusive).

Input

Input is given from Standard Input in the following format:


S


Output

If S is a strong palindrome, print `Yes`; otherwise, print `No`.

Examples

Input

akasaka


Output

Yes


Input

level


Output

No


Input

atcoder


Output

No
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        try (Scanner sc = new Scanner(System.in)) {
            String S = sc.next();
            int N = S.length();
            System.out.println(isPalindrome(S) && isPalindrome(S.substring(0, (N - 1) / 2)) && isPalindrome(S.substring((N + 3) / 2 - 1, N)) ? "Yes" : "No");
        }
    }

    private static boolean isPalindrome(String s) {
        for (int l = 0, r = s.length() - 1; l < r; l++, r--) {
            if (s.charAt(l) != s.charAt(r)) {
                return false;
            }
        }
        return true;
    }
}
