On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
import java.io.*;
import java.util.*;
public class HelloWorld{

     public static void main(String []args){
         Scanner sc=new Scanner(System.in);
        int n=sc.nextInt();
        int k=n/7;
        int minof=2*k;
        int maxof=2*k;
        int z=n%7;
        if(z==1)
         maxof+=1;
         if(z>1)
          maxof+=2;
          if(z==6)
           minof+=1;
           System.out.println(minof+" "+maxof);
     }
}