On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.

def solve(offset, n):
  result = 0
  for day in range(offset, min(7, offset + n)):
    if day % 7 >= 5:
      result += 1
    n -= 1
  result += (n // 7) * 2
  for day in range(n % 7):
    if day % 7 >= 5:
      result += 1
  return result

n = int(raw_input())
print('%d %d' % (solve(0, n), solve(5, n)))

