Given is a string S consisting of digits from `1` through `9`.

Find the number of pairs of integers (i,j) (1 ≤ i ≤ j ≤ |S|) that satisfy the following condition:

Condition: In base ten, the i-th through j-th characters of S form an integer that is a multiple of 2019.

Constraints

* 1 ≤ |S| ≤ 200000
* S is a string consisting of digits from `1` through `9`.

Input

Input is given from Standard Input in the following format:


S


Output

Print the number of pairs of integers (i,j) (1 ≤ i ≤ j ≤ |S|) that satisfy the condition.

Examples

Input

1817181712114


Output

3


Input

14282668646


Output

2


Input

2119


Output

0
s=list(input())
s=[int(i) for i in s]
now=0
c=[0]*2019
c[0]=1
for n,i in enumerate(s[::-1]):
    now+=i*pow(10,n,2019)
    c[now%2019]+=1
ans=0
for k in range(2019):
    ans+=c[k]*(c[k]-1)//2
print(ans)
