On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
import java.io.PrintWriter;
import java.util.Scanner;

/**
 * Created by fatminmin on 5/6/16.
 */
public class A {
    Scanner sc = new Scanner(System.in);
    PrintWriter pw = new PrintWriter(System.out);
    public void run() {
        int n = sc.nextInt();
        int a, b;
        a = b = (n / 7) * 2;
        a += Math.min(2, n % 7);
        b += Math.max(0, (n % 7) - 5);
        pw.println(b + " " + a);
        pw.flush();
    }
    public static void main(String[] args) {
        new A().run();
    }
}
