A string s of length n (1 ≤ n ≤ 26) is called alphabetical if it can be obtained using the following algorithm:

  * first, write an empty string to s (i.e. perform the assignment s := ""); 
  * then perform the next step n times; 
  * at the i-th step take i-th lowercase letter of the Latin alphabet and write it either to the left of the string s or to the right of the string s (i.e. perform the assignment s := c+s or s := s+c, where c is the i-th letter of the Latin alphabet). 



In other words, iterate over the n first letters of the Latin alphabet starting from 'a' and etc. Each time we prepend a letter to the left of the string s or append a letter to the right of the string s. Strings that can be obtained in that way are alphabetical.

For example, the following strings are alphabetical: "a", "ba", "ab", "bac" and "ihfcbadeg". The following strings are not alphabetical: "z", "aa", "ca", "acb", "xyz" and "ddcba".

From the given string, determine if it is alphabetical.

Input

The first line contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

Each test case is written on a separate line that contains one string s. String s consists of lowercase letters of the Latin alphabet and has a length between 1 and 26, inclusive.

Output

Output t lines, each of them must contain the answer to the corresponding test case. Output YES if the given string s is alphabetical and NO otherwise.

You can output YES and NO in any case (for example, strings yEs, yes, Yes and YES will be recognized as a positive answer).

Example

Input


11
a
ba
ab
bac
ihfcbadeg
z
aa
ca
acb
xyz
ddcba


Output


YES
YES
YES
YES
YES
NO
NO
NO
NO
NO
NO

Note

The example contains test cases from the main part of the condition.
#include<bits/stdc++.h>

using namespace std;

typedef long long int li;
typedef long double ld;
typedef vector<li> vi;
typedef pair<li,li> pi;
#define PB push_back
#define MP make_pair
#define F first
#define S second
#define B begin()
#define E end()
#define f(i,l,r) for(li i=l;i<=r;++i)
#define fr(i,l,r) for(li i=l;i>=r;--i)
#define u_map unordered_map
#define endl "\n"
#define debug(x) cerr<<#x<<" = "<<x<<endl

li fastpow(li base,li exp,li M) 
{
    li res=1;
    while(exp>0) {
        if(exp&1)
            res=(res*base)%M;

        base=(base*base)%M;
        exp>>=1;
    }
    return res;
}

bool solve()
{
    string s;

    cin>>s;

    li n=s.length();

    li i=0,j=n-1;

    string tp="";

    char last = ('a'+ n);

    while(i<=j)
    {
        if(s[i]==(last-1))
        {
            last=s[i];
            i++;
            continue;
        }

        if(s[j]==(last-1))
        {
            last=s[j];
            j--;
            continue;
        }

        break;
    }

    if(last=='a')
    {
        return true;
    }

    return false;
}

int main()
{    
    //remove this in kickstart

    #ifndef ONLINE_JUDGE
    freopen("input.txt", "r", stdin);
    freopen("output.txt", "w", stdout);
    freopen("error.txt", "w", stderr);
    #endif

    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    cout.tie(NULL);

    li t=1;

    cin>>t;

    f(i,1,t)
    {
        // cout<<"Case #"<<i<<": ";

        if(solve())
        {
            cout<<"YES\n";
        }
        else
        {
            cout<<"NO\n";
        }
    }

    return 0;
}