A string s of length n (1 ≤ n ≤ 26) is called alphabetical if it can be obtained using the following algorithm:

  * first, write an empty string to s (i.e. perform the assignment s := ""); 
  * then perform the next step n times; 
  * at the i-th step take i-th lowercase letter of the Latin alphabet and write it either to the left of the string s or to the right of the string s (i.e. perform the assignment s := c+s or s := s+c, where c is the i-th letter of the Latin alphabet). 



In other words, iterate over the n first letters of the Latin alphabet starting from 'a' and etc. Each time we prepend a letter to the left of the string s or append a letter to the right of the string s. Strings that can be obtained in that way are alphabetical.

For example, the following strings are alphabetical: "a", "ba", "ab", "bac" and "ihfcbadeg". The following strings are not alphabetical: "z", "aa", "ca", "acb", "xyz" and "ddcba".

From the given string, determine if it is alphabetical.

Input

The first line contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

Each test case is written on a separate line that contains one string s. String s consists of lowercase letters of the Latin alphabet and has a length between 1 and 26, inclusive.

Output

Output t lines, each of them must contain the answer to the corresponding test case. Output YES if the given string s is alphabetical and NO otherwise.

You can output YES and NO in any case (for example, strings yEs, yes, Yes and YES will be recognized as a positive answer).

Example

Input


11
a
ba
ab
bac
ihfcbadeg
z
aa
ca
acb
xyz
ddcba


Output


YES
YES
YES
YES
YES
NO
NO
NO
NO
NO
NO

Note

The example contains test cases from the main part of the condition.
t=int(input())

for i in range(t):
    s=input()
    x=len(s)
    if x>26:
        print("NO")
        continue
    # print(s)
    flag=True
    ai=-1
    x=[0 for z in range(26)]
    val=[0 for z in range(len(s))]
    for i in range(len(s)):
        x[int(ord(s[i]))-97]+=1
        val[i]=int(ord(s[i]))
        if s[i]=="a":
            ai=i

    if ai==-1:
        print("NO")
        continue

    for i in range(len(s)):
        if x[i]!=1:
            print("NO")
            flag=False
            break
    if flag:
        for i in range(0,ai):
            if val[i]<val[i+1]:
                print("NO")
                flag=False
                break
    if flag:
        for i in range(ai,len(s)-1):
            if val[i]>val[i+1]:
                print("NO")
                flag=False
                break

    
    if flag:
        print("Yes")

    