There are N dots in a two-dimensional plane. The coordinates of the i-th dot are (x_i, y_i).

We will repeat the following operation as long as possible:

* Choose four integers a, b, c, d (a \neq c, b \neq d) such that there are dots at exactly three of the positions (a, b), (a, d), (c, b) and (c, d), and add a dot at the remaining position.



We can prove that we can only do this operation a finite number of times. Find the maximum number of times we can do the operation.

Constraints

* 1 \leq N \leq 10^5
* 1 \leq x_i, y_i \leq 10^5
* If i \neq j, x_i \neq x_j or y_i \neq y_j.
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N
x_1 y_1
:
x_N y_N


Output

Print the maximum number of times we can do the operation.

Examples

Input

3
1 1
5 1
5 5


Output

1


Input

2
10 10
20 20


Output

0


Input

9
1 1
2 1
3 1
4 1
5 1
1 2
1 3
1 4
1 5


Output

16
from collections import defaultdict,deque
import sys,heapq,bisect,math,itertools,string,queue
sys.setrecursionlimit(10**8)
INF = float('inf')
mod = 10**9+7
eps = 10**-7
def inpl(): return list(map(int, input().split()))
def inpl_str(): return list(input().split())

class UnionFind:
    def __init__(self,N): # 頂点数 N
        self.table = [i for i in range(N)]    #木の親 table[x] == x なら根
        self.rank  = [1 for i in range(N)]    #木の長さ
        self.size  = [1 for i in range(N)]    #集合のサイズ

    def Find(self,x):    #xの根を返す
        if self.table[x] == x:
            return x
        else:
            self.table[x] = self.Find(self.table[x])    #親の更新(根を直接親にして参照距離を短く)
            self.size[x] = self.size[self.table[x]]
            return self.table[x]

    def Unite(self,x,y):    #xとyを繋げる
        x,y = self.Find(x), self.Find(y)
        sx,sy = self.Size(x), self.Size(y)
        if x == y: return
        if self.rank[x] > self.rank[y]:
            self.table[y] = x
            self.size[x] = sx + sy
        else:
            self.table[x] = y
            self.size[y] = sx + sy
            if self.rank[x] == self.rank[y]:
                self.rank[y] += 1

    def Check(self,x,y):
        return self.Find(x) == self.Find(y)

    def Size(self,x):
        return self.size[self.Find(x)]



N = int(input())
UF = UnionFind(10**5+1)

xys = [inpl() for _ in range(N)]
xys.sort()
tatedict = defaultdict(list)
xx = set()
for x,y in xys:
    tatedict[x].append(y)
    xx.add(x)

for x in xx:
    s = tatedict[x][0]
    for t in tatedict[x]:
        if not UF.Check(s,t):
            UF.Unite(s,t)

ans = 0
for x in xx:
    s = tatedict[x][0]
    ans += UF.Size(s) - len(tatedict[x])

print(ans)
