Paul hates palindromes. He assumes that string s is tolerable if each its character is one of the first p letters of the English alphabet and s doesn't contain any palindrome contiguous substring of length 2 or more.

Paul has found a tolerable string s of length n. Help him find the lexicographically next tolerable string of the same length or else state that such string does not exist.

Input

The first line contains two space-separated integers: n and p (1 ≤ n ≤ 1000; 1 ≤ p ≤ 26). The second line contains string s, consisting of n small English letters. It is guaranteed that the string is tolerable (according to the above definition).

Output

If the lexicographically next tolerable string of the same length exists, print it. Otherwise, print "NO" (without the quotes).

Examples

Input

3 3
cba


Output

NO


Input

3 4
cba


Output

cbd


Input

4 4
abcd


Output

abda

Note

String s is lexicographically larger (or simply larger) than string t with the same length, if there is number i, such that s1 = t1, ..., si = ti, si + 1 > ti + 1.

The lexicographically next tolerable string is the lexicographically minimum tolerable string which is larger than the given one.

A palindrome is a string that reads the same forward or reversed.
import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.ArrayDeque;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collection;
import java.util.Comparator;
import java.util.HashMap;
import java.util.Iterator;
import java.util.Map;
import java.util.PriorityQueue;
import java.util.StringTokenizer;


public class Main {

    
    private static boolean sameset(int a, int b, int[] uf) {
        
        return find(a,uf) == find(b,uf);
    }

    private static void union(int a, int b, int[] uf) {
        uf[find(a,uf)] = find(b,uf);
    }

    private static int find(int a, int[] uf) {
        if(a == uf[a])  return a;
        int root = find(uf[a],uf);
        uf[a] = root;
        return root;
    }

    private static void BFS(int i, int[][] G, int[][] path) {
       // System.out.println("source vertex "+i);
        int[] v = new int[G.length]; // current maximum dist in u---v path
        ArrayDeque<Integer> A = new ArrayDeque();
        A.add(i);
        while(A.isEmpty() == false){
            int u = A.pop();
            //System.out.println("for node "+u);
            for(int a=0;a<v.length;a++){
                if(G[u][a] > 0 && v[a]==0 && a!=i){//edge in MST, later make faster
                    //System.out.println(a+" is and edge from "+u);
                    if(G[u][a] > v[u]){
                        //System.out.println(" and it incrases the sub path max ");
                        v[a] = G[u][a];
                    }
                    else    v[a] = v[u];
                    path[i][a] = v[a];
                    path[a][i] = v[a];
                   // System.out.println("finally path from "+i+" to "+a+" is "+path[i][a]);
                    
                    A.add(a);
                }
            }
        }
    }

    private static int numd(int x) {
        Double xx = Double.parseDouble(String.valueOf(x));
        int y = (int) Math.log10(xx);
        return (y+1);
       
         
        
    }

    private static String primeFactor(int n, boolean[] x) {
        String ans = "";
        for(int i=2;i<x.length;i++){
            if(i*i > n) break;
            if(x[i]){
                //System.out.println("testing prome "+i);
                while(n!=1 && i*i <= n){
                    while(n%i==0){
                       // System.out.println(i+" can divide "+n);
                        if(ans.equals(""))  ans=String.valueOf(i);
                        else    ans+=" x "+i;
                        n/=i;
                    }
                    break;
                }
            }
        }
        if(n!=1){
           // System.out.println("Remainig "+n);
            if(ans.equals(""))  ans=String.valueOf(n);
            else    ans+=" x "+n;
        }
        return ans;
    }

    private static String solve(String s) {
        
        
        
        return null;
    }

    //counts the number of divisors using the fundamental theorem of arithmetic
    private static int getDivisorCount(int n) {
        
        int count = 1;
        
        int tmp = n;
        
        for(int i=2;i*i<=n;i=(i==2?3:i+2)){
            
            //System.out.println(i+" is odd");
            
            int pow = 0;
            
            while(n%i==0){
                pow+=1;
                n/=i;
            }
            
            if(pow != 0){
                ///System.out.println(i+" must be a prime");
                count*=(pow+1);
            }
        }
        
        if(n!=1){
            //System.out.println(n+" is the last prime factor");
            count*=2;
        }
        
        //System.out.println("number of divisors of "+tmp+" is "+count);
        return count;
    }

    private static long nchoosek(int n, int k) {
        
        long prod = 1;
        int j = 1;
        
        int st = Math.max(n-k, k)+1;
        int ed = Math.min(n-k, k);
        
        for(int i=st;i<=n;i++){
            for(;j<=ed;j++){
                if(prod%j==0)   prod/=j;
                else break;
            }
            prod*=i;
        }
        
        for(;j<=ed;j++){
            prod/=j;
        }
        
        return prod;
    }
    
    //related to extgcd problems
    private static boolean check() {
        //System.out.println(a+" "+b+" "+c1+" "+c2);
        if(n%ibgcd(a,b)!=0) {
           // System.out.println("not possible");
            return false;
        }
        
        extgcd(a,b);
        long gcd=0,m1=x,m2=y;
        gcd=d;
        m1*=(n/d);
        m2*=(n/d);
        a/=d;
        b/=d;
        
        double f1 = (m1/b);f1*=-1;
        double f2 = (m2/a);
        long le = (long) Math.ceil(f1);
        long re = (long) Math.floor(f2);
        if(le > re) return false;
        long cf=c1*b-c2*a;
        if(cf*le < cf*re){
        
            x = m1+b*le;
            y = m2-a*le;
        }else{
            x = m1+b*re;
            y = m2-a*re;
        }
        //System.out.println("upper and lower are "+le+" "+re);
        
        
        return true;
    }

    private static void extgcd(long a, long b) {
        
        if(b==0){
            x=1;y=0;d=a;return;
        }
        extgcd(b,a%b);
        long x1 = y;
        long y1 = x-(a/b)*y;
        x=x1;
        y=y1;
    }

    private static Pair floyd_cycle(int z, int I, int m, int x0) {
        
        int tor = func(z,I,m,x0);
        int har = func(z,I,m,tor); //one step ahead of tor
        //System.out.println("initial value for tor and har "+tor+" "+har);
        
        while(tor!=har){
            tor = func(z,I,m,tor);
            har = func(z,I,m,har);
            har = func(z,I,m,har);
            //System.out.println("tor and har "+tor+" "+har);
        }
        
        //at r-x%m now
        int x = 0;
        har = tor;
        tor = x0;
        
        while(har!=tor){
            
            tor = func(z,I,m,tor);
            har = func(z,I,m,har);
            x+=1;
            //System.out.println("findind x tor and har "+tor+" "+har);
        }
        
        //now at first reapting node
        int lam = 1;
        har = func(z,I,m,tor);
        
        while(har!=tor){
            har = func(z,I,m,har);
            lam+=1;
            //System.out.println("finding lam, tor and har "+tor+" "+har);
        }
        
        return new Pair(z,lam);
    }

   private static int func(int z, int I, int m, int x0) {
        return ((z*x0)%m+I%m)%m;
    }
    

    static class Node{
        
        int d=-1;
        long num;
        public Node(int a,long c){
            this.d = a;
            
            this.num = c;
            
        }
    }
    
    static class Edge{
        
        String d;
        int p;//ids of nodes
        int q;
        public Edge( String x1, int y1, int w){
            
            this.d = x1;
            this.p = y1;
            this.q = w;
        }
    }
    
    //simple sieve
    static boolean[] getPrimes(int n){
        
        boolean[] ret = new boolean[n+1];
        Arrays.fill(ret, true);
        
        ret[0] = ret[1] = false;
        
        for(int i=2;i*i <= n; i++){
            
            if(ret[i]){
                
                for(int j=i*i;j<=n;j+=i){
                    
                    ret[j]=false;
                }
            }
        }
        
        return ret;
    }
   
    static long ibgcd(long a, long b){
        
        while(b > 0){
            long r = a%b;
            a=b;
            b=r;
        }
        return a;
    }
    
    //for extgcd
    static long x,y,d; //output and gdc
    static long c1,c2,a,b,n; // inputs
    //static boolean[] p = getPrimes(5000001);
    
    static class Pair{
        int x;
        int y;
        public Pair(int x, int y){
            this.x=x;
            this.y=y;
        }
    }
    public static void main(String[] args) throws IOException {
        
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        BufferedWriter bw = new BufferedWriter(new PrintWriter(System.out));
      
        String[] _x = br.readLine().split(" ");
        int n = Integer.parseInt(_x[0]);
        int p = Integer.parseInt(_x[1]);
        
        String s = br.readLine();
        
        int[] X = new int[n];
        int[] Y = new int[n];
        
        for(int i=0;i<n;i++){
            char t = s.charAt(i);
            X[i] = (int)t-97;
        }
        
        boolean seen= false;
        
        //for some K
        
        for(int K=n-2;K>=-1;K--){
            for(int i=0;i<n;i++){
                Y[i]=X[i];
            }
            //System.out.println("First K equal "+K);
            
            int cnt = 0; // for counting generated positions
            int d = X[K+1]; // disagreed position
            if(d==p-1)  continue;
            d+=1;
            
            while(d < p){
                if(K==-1){
                    cnt+=1;
                    cnt=p==1?0:cnt;
                    break;
                }
                if(K==0 && d!=X[K]){
                    cnt+=1;
                   // System.out.println("next d is "+d);
                    break;
                }else if(K>=1 && d!=X[K] && d!=X[K-1]){
                    cnt+=1;
                    //System.out.println("next d is "+d);
                    break;
                }else{
                    d+=1;
                }
            }
            if(cnt==0)  continue;
            
            Y[K+1] = d;
            
            //all other chars
            for(int m=K+2;m<n;m++){
                
                for(int g=0;g<p;g++){
                    
                    if(m==1 && Y[m-1]!=g){
                        cnt+=1;
                        Y[m]=g;
                       // System.out.println("Assigned at position "+m+" value of "+g);
                        break;
                        
                    }else if(m>1 && Y[m-1]!=g && Y[m-2]!=g){
                        cnt+=1;
                        Y[m]=g;
                       // System.out.println("Assigned at position "+m+" value of "+g);
                        break;
                    }else{
                    
                    }
                }
            }
            if(n-K-1 == cnt){
                //System.out.println("full match "+cnt);
                seen=true;
                for(int i=0;i<n;i++){
                    int v = Y[i];
                    char t = (char)(v+97);
                    bw.append(t+"");
                }
                bw.append("\n");
                break;
            }
            
        }
        if(!seen)   bw.append("NO\n");
        
      bw.close();
    } 

} 