Bear Limak has n colored balls, arranged in one long row. Balls are numbered 1 through n, from left to right. There are n possible colors, also numbered 1 through n. The i-th ball has color ti.

For a fixed interval (set of consecutive elements) of balls we can define a dominant color. It's a color occurring the biggest number of times in the interval. In case of a tie between some colors, the one with the smallest number (index) is chosen as dominant.

There are <image> non-empty intervals in total. For each color, your task is to count the number of intervals in which this color is dominant.

Input

The first line of the input contains a single integer n (1 ≤ n ≤ 5000) — the number of balls.

The second line contains n integers t1, t2, ..., tn (1 ≤ ti ≤ n) where ti is the color of the i-th ball.

Output

Print n integers. The i-th of them should be equal to the number of intervals where i is a dominant color.

Examples

Input

4
1 2 1 2


Output

7 3 0 0 


Input

3
1 1 1


Output

6 0 0 

Note

In the first sample, color 2 is dominant in three intervals:

  * An interval [2, 2] contains one ball. This ball's color is 2 so it's clearly a dominant color. 
  * An interval [4, 4] contains one ball, with color 2 again. 
  * An interval [2, 4] contains two balls of color 2 and one ball of color 1. 



There are 7 more intervals and color 1 is dominant in all of them.
import java.io.*;
import java.util.*;

public class SolveC {
	BufferedReader br;
	StringTokenizer in;
	PrintWriter out;

	public String nextToken() throws IOException {
		while (in == null || !in.hasMoreTokens()) {
			in = new StringTokenizer(br.readLine());
		}
		return in.nextToken();
	}

	public int nextInt() throws IOException {
		return Integer.parseInt(nextToken());
	}

	public double nextDouble() throws IOException {
		return Double.parseDouble(nextToken());
	}

	public long nextLong() throws IOException {
		return Long.parseLong(nextToken());
	}

	public static void main(String[] args) throws IOException {
		new SolveC().run();
	}

	public void solve() throws IOException {
		int n = nextInt();
		int[] a = new int[n];
		for (int i = 0; i < n; i++) {
			a[i] = nextInt() - 1;
		}
		int[] ans = new int[n];
		for (int i = 0; i < n; i++) {
			int[] val = new int[n];
			int max = -1;
			int maxPos = -1;
			for (int j = i; j < n; j++) {
				int c = a[j];
				val[c]++;
				if (val[c] > max || (val[c] == max && c < maxPos)) {
					max = val[c];
					maxPos = c;
				}
				ans[maxPos]++;
			}
		}
		for (int i = 0; i < n; i++) {
			out.print(ans[i] + " ");
		}
	}

	int min(int a, int b) {
		if (b < a) {
			return b;
		}
		return a;
	}

	int max(int a, int b) {
		if (a < b) {
			return b;
		}
		return a;
	}

	void meow() {
		while (true) {
			// meow
		}
	}

	public void run() {
		try {
			br = new BufferedReader(new InputStreamReader(System.in)); // new
																		// InputStreamReader(System.in)
			out = new PrintWriter(System.out); // System.out

			solve();

			out.close();
		} catch (IOException e) {
			e.printStackTrace();
			System.exit(1);
		}
	}
}
