On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
import java.util.Scanner;

/**
 * Created by user on 18.01.2017.
 */
public class A670 {
    public static void main(String args[]) {
        Scanner scanner = new Scanner(System.in);
        int n = scanner.nextInt();
        if (n % 7 == 0) {
            System.out.println((n / 7 * 2) + " " + (n / 7) * 2);
            return;
        }
        int c;
        int d, e;
        c = (n / 7) * 2;
        d = (n / 7) * 2 + 2;
        e = (n / 7) * 2 + 1;
        if (n > 7) {
            if (n % 7 >= 2 && n % 7 < 6) {
                System.out.println(c + " " + d);
            } else if (n % 7 == 6) {
                System.out.println(e + " " + d);
            } else if (n % 7 == 1) {
                System.out.println(c + " " + e);
            }
        } else if (n == 1) {
            System.out.println(0 + " " + 1);
        } else if (n == 6) {
            System.out.println(1 + " " + 2);
        } else if (n > 1 && n < 7) {
            System.out.println(0 + " " + 2);
        }
    }
}
