A string s of length n (1 ≤ n ≤ 26) is called alphabetical if it can be obtained using the following algorithm:

  * first, write an empty string to s (i.e. perform the assignment s := ""); 
  * then perform the next step n times; 
  * at the i-th step take i-th lowercase letter of the Latin alphabet and write it either to the left of the string s or to the right of the string s (i.e. perform the assignment s := c+s or s := s+c, where c is the i-th letter of the Latin alphabet). 



In other words, iterate over the n first letters of the Latin alphabet starting from 'a' and etc. Each time we prepend a letter to the left of the string s or append a letter to the right of the string s. Strings that can be obtained in that way are alphabetical.

For example, the following strings are alphabetical: "a", "ba", "ab", "bac" and "ihfcbadeg". The following strings are not alphabetical: "z", "aa", "ca", "acb", "xyz" and "ddcba".

From the given string, determine if it is alphabetical.

Input

The first line contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

Each test case is written on a separate line that contains one string s. String s consists of lowercase letters of the Latin alphabet and has a length between 1 and 26, inclusive.

Output

Output t lines, each of them must contain the answer to the corresponding test case. Output YES if the given string s is alphabetical and NO otherwise.

You can output YES and NO in any case (for example, strings yEs, yes, Yes and YES will be recognized as a positive answer).

Example

Input


11
a
ba
ab
bac
ihfcbadeg
z
aa
ca
acb
xyz
ddcba


Output


YES
YES
YES
YES
YES
NO
NO
NO
NO
NO
NO

Note

The example contains test cases from the main part of the condition.
import java.util.*;
import java.lang.*;
import java.io.*;

public class B {

	public static void main(String[] args) throws Exception {
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
		int t = Integer.parseInt(br.readLine());
		StringBuilder sb = new StringBuilder();
		while (t-- > 0) {
			char[] str = (br.readLine()).toCharArray();

			int n = str.length;
			int idx = -1;
			boolean[] vis = new boolean[27];
			for (int i = 0; i < n; i++) {
				if (str[i] == 'a') {
					idx = i;
					break;
				}
			}
			boolean pos = true;
			if (idx == -1) {
				pos = false;
				sb.append(pos ? "YES" : "NO");

			} else {
				vis[0] = true;
				int i = idx - 1;
				int j = idx + 1;
				for (int k = 1; k < n; k++) {
					char ch = (char) (k + 'a');
					if (i >= 0 && str[i] == ch) {
						vis[k] = true;
						i -= 1;
					} else if (j < n && str[j] == ch) {
						vis[k] = true;
						j += 1;
					} else {
						pos = false;
						break;
					}
				}
				for (i = 0; i < n; i++) {
					if (!vis[i]) {
						pos = false;
					}
				}
				sb.append(pos ? "YES" : "NO");

			}

			sb.append("\n");
		}
		System.out.println(sb);
		return;

	}

	public static void sort(long[] arr) {
		int n = arr.length;
		for (int i = 0; i < n; i++) {
			int idx = (int) (Math.random() * n);
			long temp = arr[i];
			arr[i] = arr[idx];
			arr[idx] = temp;
		}
		Arrays.sort(arr);
	}

	public static void sort(int[] arr) {
		int n = arr.length;
		for (int i = 0; i < n; i++) {
			int idx = (int) (Math.random() * n);
			int temp = arr[i];
			arr[i] = arr[idx];
			arr[idx] = temp;
		}
		Arrays.sort(arr);
	}

	public static void print(long[][] dp) {
		for (long[] a : dp) {
			for (long ele : a) {
				System.out.print(ele + " ");
			}
			System.out.println();
		}
	}

	public static void print(int[][] dp) {
		for (int[] a : dp) {
			for (int ele : a) {
				System.out.print(ele + " ");
			}
			System.out.println();
		}
	}

	public static void print(int[] dp) {
		for (int ele : dp) {
			System.out.print(ele + " ");
		}
		System.out.println();
	}

	public static void print(long[] dp) {
		for (long ele : dp) {
			System.out.print(ele + " ");
		}
		System.out.println();
	}

}