We have N colored balls arranged in a row from left to right; the color of the i-th ball from the left is c_i.

You are given Q queries. The i-th query is as follows: how many different colors do the l_i-th through r_i-th balls from the left have?

Constraints

* 1\leq N,Q \leq 5 \times 10^5
* 1\leq c_i \leq N
* 1\leq l_i \leq r_i \leq N
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N Q
c_1 c_2 \cdots c_N
l_1 r_1
l_2 r_2
:
l_Q r_Q


Output

Print Q lines. The i-th line should contain the response to the i-th query.

Examples

Input

4 3
1 2 1 3
1 3
2 4
3 3


Output

2
3
1


Input

10 10
2 5 6 5 2 1 7 9 7 2
5 5
2 4
6 7
2 2
7 8
7 9
1 8
6 9
8 10
6 8


Output

1
2
2
1
2
2
6
3
3
3
from operator import itemgetter
import sys


def read():
    return sys.stdin.readline().rstrip()


def add(arr, i, x):
    while i < len(arr):
        arr[i] += x
        i += i & -i


def range_sum(arr, a, b):
    s = 0
    i = b
    while i > 0:
        s += arr[i]
        i -= i & -i
    i = a - 1
    while i > 0:
        s -= arr[i]
        i -= i & -i
    return s


def main():
    n, q = map(int, read().split())
    c = [int(i) - 1 for i in read().split()]
    queries = [(0, 0, 0) for _ in range(q)]
    for i in range(q):
        l, r = map(int, read().split())
        queries[i] = (i, l, r)
    queries = iter(sorted(queries, key=itemgetter(2)))
    last = [0] * n
    bit = [0] * (n + 1)
    ans = [-1] * q
    k, l, r = next(queries)
    for i in range(n):
        ci = c[i]
        li = last[ci]
        if li > 0:
            add(bit, li, -1)
        last[ci] = i + 1
        add(bit, i + 1, 1)
        while i + 1 == r:
            ans[k] = range_sum(bit, l, r)
            try:
                k, l, r = next(queries)
            except StopIteration:
                break
    print(*ans, sep="\n")


if __name__ == '__main__':
    main()
