We have N colored balls arranged in a row from left to right; the color of the i-th ball from the left is c_i.

You are given Q queries. The i-th query is as follows: how many different colors do the l_i-th through r_i-th balls from the left have?

Constraints

* 1\leq N,Q \leq 5 \times 10^5
* 1\leq c_i \leq N
* 1\leq l_i \leq r_i \leq N
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N Q
c_1 c_2 \cdots c_N
l_1 r_1
l_2 r_2
:
l_Q r_Q


Output

Print Q lines. The i-th line should contain the response to the i-th query.

Examples

Input

4 3
1 2 1 3
1 3
2 4
3 3


Output

2
3
1


Input

10 10
2 5 6 5 2 1 7 9 7 2
5 5
2 4
6 7
2 2
7 8
7 9
1 8
6 9
8 10
6 8


Output

1
2
2
1
2
2
6
3
3
3
import sys
from collections import defaultdict
input = sys.stdin.readline

n, q = map(int, input().split())
c = list(map(int, input().split()))
lr = []
for i in range(q):
    l, r = map(int, input().split())
    lr.append((l, r, i))

# 1-indexed
left_index_dict = {}
d = defaultdict(int)

for i, ci in enumerate(c):
    index = d[ci]
    if index in left_index_dict:
        left_index_dict[index].append(i+1)
    else:
        left_index_dict[index] = [i+1]
    d[ci] = i + 1

lr.sort(key=lambda x:x[0])

index = list(left_index_dict.keys())
index.sort()
i = 0

N = n
bit = [0] * (N+1)

def sum(i):
    s = 0
    while i > 0:
        s += bit[i]
        i -= i & -i
    return s

def add(i, x):
    while i <= N:
        bit[i] += x
        i += i & -i

ans = [0] * q

for l, r, _i in lr:
    while i < len(index) and index[i] < l:
        for j in left_index_dict[index[i]]:
            add(j, 1)
        i += 1
    ans[_i] = sum(r) - sum(l-1)

for ansi in ans:
    print(ansi) 
    



    
