On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
n = int(input())
max = max(((n - 2) // 7)* 2 + 2, ((n - 1) // 7)*2 + 1, (n // 7) * 2)
max = min(max, n)

def f(x):
    return {
        0 : 0,
        1 : 0,
        2 : 0,
        3 : 0,
        4 : 0,
        5 : 0,
        6 : 1
    }.get(x, 0)

min = (n // 7) * 2 + f(n % 7)
print(str(min) + " " + str(max))
