On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
#include <bits/stdc++.h>
using namespace std;
const int N6 = 1e6 + 6, N3 = 1e3 + 6, oo = 1e9 + 9, base = 1e9 + 7;
const long long ool = 1e18 + 9;
int main() {
  ios_base ::sync_with_stdio(0);
  cin.tie(0);
  int n;
  cin >> n;
  cout << (n % 7 == 6 ? n / 7 * 2 + 1 : n / 7 * 2) << " "
       << (n % 7 == 1 ? n / 7 * 2 + 1 : (n + 6) / 7 * 2);
  return 0;
}
