On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
n = int(input())
m = 2 * int(n/7)
s = n % 7
if s <= 2:
    ma = s
    mi = 0
if 3<= s <= 5:
    ma = 2
    mi = 0
if s >= 6:
    ma = 2
    mi = 7 - s
maxs = m + ma
mins = m + mi
li = [str(mins), str(maxs)]
print(' '.join(li))