On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
import java.io.*;
import java.util.*;

public class Solution{ //class Ideone{
 
 
 public static void main(String[] args) {
     
         
        Scanner in = new Scanner(System.in);
        
        int n,q,r,min,max;
        
        n=in.nextInt();
        q=n/7;
        r=n%7;
        
        if(r<=5) min=2*q;
        else min=2*q+1;
        
        if(r==0) max=2*q;
        else if(r==1) max=2*q+1;
        else max=2*q+2;
        
        System.out.println(min+" "+max);
        
 }
}