On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
import java.util.Scanner;

/**
 *
 * @author USER
 */
public class Main {

    /**
     * @param args the command line arguments
     */
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int day = sc.nextInt();
        int max = 0;
        int min = 0;
        int carry = day / 7;

        int note = day - (carry * 7);

        if (carry == 0) {
            if (day == 7) {
                min = 2;
            } else if (day <= 5) {
                min = 0;
            } else {
                min = 1;
            }
            System.out.print(min + " ");
            if(day>=2){
                 System.out.print(2);
            } else  System.out.print(1);
           
        } else {
            //min
            int memo = 0;
            if (note > 5) {
                memo = 7 - note;
            }
            if (note == 0) {
                System.out.print(carry * 2 + " ");
            } else {
                System.out.print((carry) * 2 + memo + " ");
            }
            // max
           
            
            if (note == 0) {
                System.out.print(carry * 2);
            } else {
                if (note <= 2) {
                memo = note;
                System.out.print((carry) * 2 + memo);
            } else {
                     System.out.print((carry + 1) * 2 );
                }
                
            }

        }

    }

}
