Given is a string S consisting of digits from `1` through `9`.

Find the number of pairs of integers (i,j) (1 ≤ i ≤ j ≤ |S|) that satisfy the following condition:

Condition: In base ten, the i-th through j-th characters of S form an integer that is a multiple of 2019.

Constraints

* 1 ≤ |S| ≤ 200000
* S is a string consisting of digits from `1` through `9`.

Input

Input is given from Standard Input in the following format:


S


Output

Print the number of pairs of integers (i,j) (1 ≤ i ≤ j ≤ |S|) that satisfy the condition.

Examples

Input

1817181712114


Output

3


Input

14282668646


Output

2


Input

2119


Output

0
# -*- coding: utf-8 -*-

surplus = [0]*2019
surplus[0] += 1

d = 1
n = 0
for i in reversed(input()):
    n = (n + int(i)*d) %2019
    d = d*10 % 2019
    surplus[n] += 1

print(sum([i*(i-1)//2 for i in surplus]))
