On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
class Holidays:
    def solve(self,n):
        minimum = (n/7)*2
        maximum = ((n/7)*2)
        if n%7>2:
            maximum+=2
            if n%7==6:minimum+=1
        else:
            maximum+=n%7
        return str(minimum)+" "+ str(maximum)
if __name__ == "__main__":
    n = int(raw_input())
    hd = Holidays()
    print hd.solve(n)