On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
import java.util.*;
public class NewClass
{
    public static void main(String[] args)
    {
        Scanner sc=new Scanner(System.in);
       int n,a,b,c,d;
       n=sc.nextInt();
       a=n/7;
       b=n%7; 
       
        
        if(b==6) System.out.print((a*2+1));
        else System.out.print(a*2);
       
       if(b==0) System.out.print(" "+a*2);
       else if(b==1) System.out.print(" "+(a*2+1));
       else System.out.print(" "+(a*2+2));
       
    
    }
}