On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
def hd_ext_max(days):
    return days if days < 2 else 2


def hd_ext_min(days):
    return 1 if days == 6 else 0


def main():
    days_num = int(input())
    full_weeks_num = days_num // 7
    min_hd = full_weeks_num * 2 + hd_ext_min(days_num % 7)
    max_hd = min_hd + hd_ext_max(days_num % 7) - hd_ext_min(days_num % 7)
    print(min_hd, max_hd)


if __name__ == '__main__':
    main()
