On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
from math import *
n = int(input())
if n % 7 == 0:
    m = n / 7
    x = y = m * 2
elif n < 2:
    x = 0
    y = n
elif n < 7:
    x = 0
    y = 2
else:
    x = floor(n / 7) * 2
    if n % 7 < 2:
        a = 1
    else:
        a = 2
    y = x + a
if n % 7 == 6:
    x = x + 1
print("%d %d" % (x, y))