User ainta has a permutation p1, p2, ..., pn. As the New Year is coming, he wants to make his permutation as pretty as possible.

Permutation a1, a2, ..., an is prettier than permutation b1, b2, ..., bn, if and only if there exists an integer k (1 ≤ k ≤ n) where a1 = b1, a2 = b2, ..., ak - 1 = bk - 1 and ak < bk all holds.

As known, permutation p is so sensitive that it could be only modified by swapping two distinct elements. But swapping two elements is harder than you think. Given an n × n binary matrix A, user ainta can swap the values of pi and pj (1 ≤ i, j ≤ n, i ≠ j) if and only if Ai, j = 1.

Given the permutation p and the matrix A, user ainta wants to know the prettiest permutation that he can obtain.

Input

The first line contains an integer n (1 ≤ n ≤ 300) — the size of the permutation p.

The second line contains n space-separated integers p1, p2, ..., pn — the permutation p that user ainta has. Each integer between 1 and n occurs exactly once in the given permutation.

Next n lines describe the matrix A. The i-th line contains n characters '0' or '1' and describes the i-th row of A. The j-th character of the i-th line Ai, j is the element on the intersection of the i-th row and the j-th column of A. It is guaranteed that, for all integers i, j where 1 ≤ i < j ≤ n, Ai, j = Aj, i holds. Also, for all integers i where 1 ≤ i ≤ n, Ai, i = 0 holds.

Output

In the first and only line, print n space-separated integers, describing the prettiest permutation that can be obtained.

Examples

Input

7
5 2 4 3 6 7 1
0001001
0000000
0000010
1000001
0000000
0010000
1001000


Output

1 2 4 3 6 7 5


Input

5
4 2 1 5 3
00100
00011
10010
01101
01010


Output

1 2 3 4 5

Note

In the first sample, the swap needed to obtain the prettiest permutation is: (p1, p7).

In the second sample, the swaps needed to obtain the prettiest permutation is (p1, p3), (p4, p5), (p3, p4). 

<image>

A permutation p is a sequence of integers p1, p2, ..., pn, consisting of n distinct positive integers, each of them doesn't exceed n. The i-th element of the permutation p is denoted as pi. The size of the permutation p is denoted as n.
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.ArrayList;
import java.util.Collections;
import java.util.InputMismatchException;

public class TaskB {

	public FasterScanner mFScanner;
	public PrintWriter mOut;
	private int N;
	private int id[];
	private char [][] mapping;
	private boolean marked[];
	private int [] array;
	
	public void QuickFind(int N) {
		this.N = N;
		id = new int[N];
		for (int i = 0; i < N; i++)
			id[i] = i;
	}

	public boolean connected(int v, int w) {
		return id[v] == id[w];
	}

	public void connect(int p, int q) {
		if (connected(p, q))
			return;
		for (int i = 0; i < N; i++) {
			if (id[i] == id[p])
				id[i] = id[q];
		}
	}

	public TaskB() {
		mFScanner = new FasterScanner();
		mOut = new PrintWriter(System.out);
	}

	public void solve() {
		int res[];
		int idd;
		N = mFScanner.nextInt();
		array = mFScanner.nextIntArray(N);
		mapping = mFScanner.nextChar2DArray(N, N);
		marked = new boolean[N];
		QuickFind(N);
		
		for (int i = 0; i < N; i++) {
			for (int j = 0; j < N; j++) {
				
				if (mapping[i][j] == '1') {
					connect(i, j);
				}
			}
		}
		
		res = new int[N];
		ArrayList<Point> temp = new ArrayList<Point>();
		ArrayList<Integer> index = new ArrayList<Integer>();
		
		for (int i = 0; i < N; i++) {
			
			if (marked[i])
				continue;
			temp.clear();
			index.clear();
			marked[i] = true;
			
			temp.add(new Point(i, array[i]));
			index.add(i);
			
			for (int j = i + 1; j < N; j++) {
				if (connected(i, j)) {
					marked[j] = true;
					
					temp.add(new Point(j, array[j]));
					index.add(j);
				}
			}
			
			Collections.sort(index);
			Collections.sort(temp);
			
			for (int j = 0; j < temp.size(); j++) {
				
				Point p = temp.get(j);
				int ind = index.get(j);
				
				res[ind] = p.num;
				
			}
			
		}
		
		for (int i = 0; i < N; i++) {
			mOut.print(res[i]);
			if (i != N - 1)
				mOut.print(" ");
		}
		mOut.println();
		
		
	}
	
	class Point implements Comparable<Point> {
		
		int index;
		int num;
		
		public Point(int index, int num) {
			// TODO Auto-generated constructor stub
			this.index = index;
			this.num = num;
		}

		@Override
		public int compareTo(Point o) {
			// TODO Auto-generated method stub
			return Integer.compare(this.num, o.num);
		}
		
	}

	public void flush() {
		mOut.flush();
	}

	public void close() {
		mOut.close();
	}

	public static void main(String[] args) {
		TaskB mSol = new TaskB();
		mSol.solve();
		mSol.flush();
		mSol.close();
	}

	class FasterScanner {
		private InputStream mIs;
		private byte[] buf = new byte[1024];
		private int curChar;
		private int numChars;

		public FasterScanner() {
			this(System.in);
		}

		public FasterScanner(InputStream is) {
			mIs = is;
		}

		public int read() {
			if (numChars == -1)
				throw new InputMismatchException();
			if (curChar >= numChars) {
				curChar = 0;
				try {
					numChars = mIs.read(buf);
				} catch (IOException e) {
					throw new InputMismatchException();
				}
				if (numChars <= 0)
					return -1;
			}
			return buf[curChar++];
		}

		public String nextLine() {
			int c = read();
			while (isSpaceChar(c))
				c = read();
			StringBuilder res = new StringBuilder();
			do {
				res.appendCodePoint(c);
				c = read();
			} while (!isEndOfLine(c));
			return res.toString();
		}

		public String nextString() {
			int c = read();
			while (isSpaceChar(c))
				c = read();
			StringBuilder res = new StringBuilder();
			do {
				res.appendCodePoint(c);
				c = read();
			} while (!isSpaceChar(c));
			return res.toString();
		}

		public long nextLong() {
			int c = read();
			while (isSpaceChar(c))
				c = read();
			int sgn = 1;
			if (c == '-') {
				sgn = -1;
				c = read();
			}
			long res = 0;
			do {
				if (c < '0' || c > '9')
					throw new InputMismatchException();
				res *= 10;
				res += c - '0';
				c = read();
			} while (!isSpaceChar(c));
			return res * sgn;
		}

		public int nextInt() {
			int c = read();
			while (isSpaceChar(c))
				c = read();
			int sgn = 1;
			if (c == '-') {
				sgn = -1;
				c = read();
			}
			int res = 0;
			do {
				if (c < '0' || c > '9')
					throw new InputMismatchException();
				res *= 10;
				res += c - '0';
				c = read();
			} while (!isSpaceChar(c));
			return res * sgn;
		}

		public double nextDouble() {
			Double next;
			next = Double.parseDouble(nextString());
			return next;
		}

		public boolean isSpaceChar(int c) {
			return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1;
		}

		public boolean isEndOfLine(int c) {
			return c == '\n' || c == '\r' || c == -1;
		}

		public char[] nextCharArray(int N) {
			int i;
			char[] array;
			String str;

			array = new char[N];

			i = 0;

			str = nextLine();

			for (i = 0; i < N && i < str.length(); i++) {
				array[i] = str.charAt(i);
			}

			return array;
		}

		public char[][] nextChar2DArray(int M, int N) {
			int i;
			char[][] array;

			array = new char[M][N];

			i = 0;

			for (i = 0; i < M; i++) {
				array[i] = nextCharArray(N);
			}

			return array;
		}

		public int[] nextIntArray(int N) {
			int i;
			int[] array;

			array = new int[N];

			i = 0;

			for (i = 0; i < N; i++) {
				array[i] = nextInt();
			}

			return array;
		}

		public int[][] nextInt2DArray(int M, int N) {
			int i;
			int[][] array;

			array = new int[M][N];

			i = 0;

			for (i = 0; i < M; i++) {
				array[i] = nextIntArray(N);
			}

			return array;
		}

		public long[] nextLongArray(int N) {
			int i;
			long[] array;

			array = new long[N];

			i = 0;

			for (i = 0; i < N; i++) {
				array[i] = nextLong();
			}

			return array;
		}

		public long[][] nextLong2DArray(int M, int N) {
			int i;
			long[][] array;

			array = new long[M][N];

			i = 0;

			for (i = 0; i < M; i++) {
				array[i] = nextLongArray(N);
			}

			return array;
		}

		public double[] nextDoubleArray(int N) {
			int i;
			double[] array;

			array = new double[N];

			for (i = 0; i < N; i++) {
				array[i] = nextDouble();
			}

			return array;
		}

		public double[][] nextDouble2DArray(int M, int N) {
			int i;
			double[][] array;

			array = new double[M][N];

			for (i = 0; i < M; i++) {
				array[i] = nextDoubleArray(N);
			}

			return array;
		}

	}
}