On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
n=input()
if n%7==0:
	w=n/7
	print w*2,w*2
elif n>=7:
	m=n%7
	w=n/7
	if m==1:
		mini=w*2
		maxi=w*2+1
	elif m==6:
		mini=w*2+1
		maxi=w*2+2
	else:
		mini=w*2
		maxi=w*2+2
	print mini,maxi
else:
	if n<=5:
		print 0,min(n,2)
	else:
		print 1,2