Levko loves permutations very much. A permutation of length n is a sequence of distinct positive integers, each is at most n.

Let’s assume that value gcd(a, b) shows the greatest common divisor of numbers a and b. Levko assumes that element pi of permutation p1, p2, ... , pn is good if gcd(i, pi) > 1. Levko considers a permutation beautiful, if it has exactly k good elements. Unfortunately, he doesn’t know any beautiful permutation. Your task is to help him to find at least one of them.

Input

The single line contains two integers n and k (1 ≤ n ≤ 105, 0 ≤ k ≤ n).

Output

In a single line print either any beautiful permutation or -1, if such permutation doesn’t exist.

If there are multiple suitable permutations, you are allowed to print any of them.

Examples

Input

4 2


Output

2 4 3 1

Input

1 1


Output

-1

Note

In the first sample elements 4 and 3 are good because gcd(2, 4) = 2 > 1 and gcd(3, 3) = 3 > 1. Elements 2 and 1 are not good because gcd(1, 2) = 1 and gcd(4, 1) = 1. As there are exactly 2 good elements, the permutation is beautiful.

The second sample has no beautiful permutations.
import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.io.PrintWriter;
import java.util.StringTokenizer;

public class B361 {
	
	static StringTokenizer st;
	static BufferedReader in;
	static PrintWriter pw;
	
	public static void main(String[] args) throws IOException {
		in = new BufferedReader(new InputStreamReader(System.in));
		pw = new PrintWriter(new BufferedWriter(new OutputStreamWriter(System.out)));
		int n = nextInt();
		int k = nextInt();
		if (n==k) {
			System.out.println(-1);
			return;
		}
		int[]a = new int[n+1];
		for (int i = n-k+1; i <= n; i++) {
			a[i] = i;
		}
		a[1] = n-k;
		for (int i = 2; i <= n-k; i++) {
			a[i] = i-1;
		}
		for (int i = 1; i <= n; i++) {
			pw.print(a[i]+" ");
		}
		pw.println();
		pw.close();
	}
	private static int nextInt() throws IOException{
		return Integer.parseInt(next());
	}
	
	private static long nextLong() throws IOException{
		return Long.parseLong(next());
	}
	
	private static double nextDouble() throws IOException{
		return Double.parseDouble(next());
	}
	
	private static String next() throws IOException {
        while (st == null || !st.hasMoreTokens()) {
            st = new StringTokenizer(in.readLine());
        }
        return st.nextToken();
    }
}
