We have N colored balls arranged in a row from left to right; the color of the i-th ball from the left is c_i.

You are given Q queries. The i-th query is as follows: how many different colors do the l_i-th through r_i-th balls from the left have?

Constraints

* 1\leq N,Q \leq 5 \times 10^5
* 1\leq c_i \leq N
* 1\leq l_i \leq r_i \leq N
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N Q
c_1 c_2 \cdots c_N
l_1 r_1
l_2 r_2
:
l_Q r_Q


Output

Print Q lines. The i-th line should contain the response to the i-th query.

Examples

Input

4 3
1 2 1 3
1 3
2 4
3 3


Output

2
3
1


Input

10 10
2 5 6 5 2 1 7 9 7 2
5 5
2 4
6 7
2 2
7 8
7 9
1 8
6 9
8 10
6 8


Output

1
2
2
1
2
2
6
3
3
3
import sys
input=sys.stdin.readline
n,q=map(int, input().split())
*c,=map(int, input().split())

qu=[list(map(int, input().split())) +[i] for i in range(q)]
qu.sort(key=lambda x:x[1])
bit=[0]*(n+1)

last=[-1]*(n+1)

def add(t,x):
    while t<=n:
        bit[t]+=x
        t += t&(-t)

def query(t):
    res=0
    while t:
        res+=bit[t]
        t-=t&(-t)
    return res

used=1
ans=[0]*q
for l,r,i in qu:
    while used<=r:
        add(used,1)
        if last[c[used-1]]>=0:
            add(last[c[used-1]],-1)
        last[c[used-1]]=used
        used+=1
    ansi=query(r)-query(l-1)
    ans[i]=ansi
for ansi in ans:
    print(ansi)
