You're given a list of n strings a1, a2, ..., an. You'd like to concatenate them together in some order such that the resulting string would be lexicographically smallest.

Given the list of strings, output the lexicographically smallest concatenation.

Input

The first line contains integer n — the number of strings (1 ≤ n ≤ 5·104).

Each of the next n lines contains one string ai (1 ≤ |ai| ≤ 50) consisting of only lowercase English letters. The sum of string lengths will not exceed 5·104.

Output

Print the only string a — the lexicographically smallest string concatenation.

Examples

Input

4
abba
abacaba
bcd
er


Output

abacabaabbabcder


Input

5
x
xx
xxa
xxaa
xxaaa


Output

xxaaaxxaaxxaxxx


Input

3
c
cb
cba


Output

cbacbc
//package GeneralProblems;

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.Arrays;

public class smallestStringConcatenation {
	static class sort implements Comparable<sort>{
		String str;
		public sort(String s) {
			str= s;
		}
		@Override
		public int compareTo(sort s) {
			//opt1
			for (int i = 0; i < s.str.length()+str.length(); i++) {
				char one ='a', two = 'a';
				//str+s.str
				if(i>=str.length()) {
					one = s.str.charAt(i-str.length());
				}
				else one = str.charAt(i);
				if(i>=s.str.length()) {
					two = str.charAt(i-s.str.length());
				}//
				else two = s.str.charAt(i);
//				System.out.println(one+" "+two+" "+i);
				if(one<two)
					return -1;
				else
					if(one>two)
						return 1;
			}
			return 0;
			
		}
	}
public static void main(String[] args) throws IOException{
	BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
	int n = Integer.parseInt(in.readLine());
	sort [] ar = new sort[n];
	for (int i = 0; i < ar.length; i++) {
		ar[i] = new sort(in.readLine());
	}
	PrintWriter out = new PrintWriter(System.out);
//	System.out.println(ar[0].compareTo(ar[1]));
		Arrays.sort(ar);
	for (int i = 0; i < ar.length; i++) {
		out.print(ar[i].str);
	}
	out.flush();out.close();
}
}
