We have N colored balls arranged in a row from left to right; the color of the i-th ball from the left is c_i.

You are given Q queries. The i-th query is as follows: how many different colors do the l_i-th through r_i-th balls from the left have?

Constraints

* 1\leq N,Q \leq 5 \times 10^5
* 1\leq c_i \leq N
* 1\leq l_i \leq r_i \leq N
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N Q
c_1 c_2 \cdots c_N
l_1 r_1
l_2 r_2
:
l_Q r_Q


Output

Print Q lines. The i-th line should contain the response to the i-th query.

Examples

Input

4 3
1 2 1 3
1 3
2 4
3 3


Output

2
3
1


Input

10 10
2 5 6 5 2 1 7 9 7 2
5 5
2 4
6 7
2 2
7 8
7 9
1 8
6 9
8 10
6 8


Output

1
2
2
1
2
2
6
3
3
3
import sys
input = sys.stdin.buffer.readline

N, Q = map(int, input().split())
C = list(map(lambda x: int(x) - 1, input().split()))

query = []

for i in range(Q):
    l, r, = map(int, input().split())
    query.append((l - 1, r, i))

query.sort(key = lambda x: x[1])

rt = 0
L = [None for _ in range(N)]
res = [0 for _ in range(Q)]
bit = [0 for _ in range(N + 1)]

for l, r, id in query:
    while rt < r:
        if L[C[rt]] is not None:
            idx = L[C[rt]] + 1
            while idx <= N:
                bit[idx] -= 1
                idx += idx & -idx
        L[C[rt]] = rt
        idx = rt + 1
        while idx <= N:
            bit[idx] += 1
            idx += idx & -idx
        rt += 1
    sr = 0
    sl = 0
    idx = r
    while idx:
        sr += bit[idx]
        idx -= idx & -idx
    idx = l
    while idx:
        sl += bit[idx]
        idx -= idx & -idx
    res[id] = sr - sl

print('\n'.join(map(str, res)))