On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
# coding: utf-8

from __future__ import print_function
from __future__ import unicode_literals
from __future__ import division
from __future__ import absolute_import
import math
import string
import itertools
import fractions
import heapq
import collections
import re
import array
import bisect

n = int(input())

w = n // 7
d = n % 7
min_off = w * 2
max_off = w * 2
if d <= 2:
    max_off += d
elif 2 < d and d <= 5:
    max_off += 2
else:                           # d==6
    max_off += 2
    min_off += 1
print("{} {}".format(min_off, max_off))
