A string s of length n (1 ≤ n ≤ 26) is called alphabetical if it can be obtained using the following algorithm:

  * first, write an empty string to s (i.e. perform the assignment s := ""); 
  * then perform the next step n times; 
  * at the i-th step take i-th lowercase letter of the Latin alphabet and write it either to the left of the string s or to the right of the string s (i.e. perform the assignment s := c+s or s := s+c, where c is the i-th letter of the Latin alphabet). 



In other words, iterate over the n first letters of the Latin alphabet starting from 'a' and etc. Each time we prepend a letter to the left of the string s or append a letter to the right of the string s. Strings that can be obtained in that way are alphabetical.

For example, the following strings are alphabetical: "a", "ba", "ab", "bac" and "ihfcbadeg". The following strings are not alphabetical: "z", "aa", "ca", "acb", "xyz" and "ddcba".

From the given string, determine if it is alphabetical.

Input

The first line contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

Each test case is written on a separate line that contains one string s. String s consists of lowercase letters of the Latin alphabet and has a length between 1 and 26, inclusive.

Output

Output t lines, each of them must contain the answer to the corresponding test case. Output YES if the given string s is alphabetical and NO otherwise.

You can output YES and NO in any case (for example, strings yEs, yes, Yes and YES will be recognized as a positive answer).

Example

Input


11
a
ba
ab
bac
ihfcbadeg
z
aa
ca
acb
xyz
ddcba


Output


YES
YES
YES
YES
YES
NO
NO
NO
NO
NO
NO

Note

The example contains test cases from the main part of the condition.
#include <bits/stdc++.h>
using namespace std;
#define ff first
#define ss second
#define pb push_back
#define debug(val) cerr << "The value of " << #val << " is = " << val << '\n';
typedef long double ld;
typedef long long ll;
typedef unsigned long long ull;
const ld PI = 4*atan((ld)1);
const ll mod = 1e9 + 7;
const ll inf = 922337203685477;
const ll nax = 0;

ll t;
string s;

int main(){ 
    ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);
    //freopen("test.in", "r", stdin);
    //freopen("test.out", "w", stdout);
    
    cin >> t;
    while(t--){
		ll idx = -1;
		cin >> s;
		for(ll i = 0; i < s.size(); i++){
			if(s[i] == 'a'){
				idx = i;
				break;
			}
		}
		if(idx == -1){
			cout << "No\n";
		}
		else{
			ll l = idx-1;
			ll r = idx+1;
			ll cek = 1;
			for(ll i = 1; i < (ll)s.size(); i++){
				char c = 'a' + i;
				if(s[l] != -1 && s[l] == c){
					l--;
				}
				else if(s[r] != (ll)s.size() && s[r] == c){
					r++;
				}
				else{
					cek = 0;
					break;
				}
			}
			if(cek){
				cout << "Yes\n";
			}
			else{
				cout << "No\n";
			}
		}
	}
}

