We have N colored balls arranged in a row from left to right; the color of the i-th ball from the left is c_i.

You are given Q queries. The i-th query is as follows: how many different colors do the l_i-th through r_i-th balls from the left have?

Constraints

* 1\leq N,Q \leq 5 \times 10^5
* 1\leq c_i \leq N
* 1\leq l_i \leq r_i \leq N
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N Q
c_1 c_2 \cdots c_N
l_1 r_1
l_2 r_2
:
l_Q r_Q


Output

Print Q lines. The i-th line should contain the response to the i-th query.

Examples

Input

4 3
1 2 1 3
1 3
2 4
3 3


Output

2
3
1


Input

10 10
2 5 6 5 2 1 7 9 7 2
5 5
2 4
6 7
2 2
7 8
7 9
1 8
6 9
8 10
6 8


Output

1
2
2
1
2
2
6
3
3
3
import sys

input = sys.stdin.buffer.readline
n, q = map(int, input().split())
C = list(map(int, input().split()))
LR = []
for i in range(q):
    l, r = map(int, input().split())
    LR.append((l, r, i))
LR.sort(key=lambda x: x[1])


BIT = [0] * (n + 1)


def update(idx, val):
    while idx <= n:
        BIT[idx] += val
        idx += idx & (-idx)


def query(idx):
    res = 0
    while idx > 0:
        res += BIT[idx]
        idx -= idx & (-idx)
    return res


pos = [-1] * (n + 1)


def func(idx):
    temp = C[idx]
    if pos[temp] == -1:
        pos[temp] = idx + 1
        update(idx + 1, 1)
    else:
        pre = pos[temp]
        pos[temp] = idx + 1
        update(pre, -1)
        update(idx + 1, 1)


ans = [0] * (q)
idx = 0
for i in range(q):
    l, r, ans_num = LR[i]
    # l,rは0-indexに戻す
    l -= 1
    r -= 1
    while idx < r + 1:  # rになるまで増やす
        if idx < n:  # n超えないように注意
            func(idx)
            idx += 1
        else:
            break
    res = 0
    res += query(r + 1)
    if l > 0:
        res -= query(l)
    ans[ans_num] = res

print(*ans, sep="\n")
