Levko loves permutations very much. A permutation of length n is a sequence of distinct positive integers, each is at most n.

Let’s assume that value gcd(a, b) shows the greatest common divisor of numbers a and b. Levko assumes that element pi of permutation p1, p2, ... , pn is good if gcd(i, pi) > 1. Levko considers a permutation beautiful, if it has exactly k good elements. Unfortunately, he doesn’t know any beautiful permutation. Your task is to help him to find at least one of them.

Input

The single line contains two integers n and k (1 ≤ n ≤ 105, 0 ≤ k ≤ n).

Output

In a single line print either any beautiful permutation or -1, if such permutation doesn’t exist.

If there are multiple suitable permutations, you are allowed to print any of them.

Examples

Input

4 2


Output

2 4 3 1

Input

1 1


Output

-1

Note

In the first sample elements 4 and 3 are good because gcd(2, 4) = 2 > 1 and gcd(3, 3) = 3 > 1. Elements 2 and 1 are not good because gcd(1, 2) = 1 and gcd(4, 1) = 1. As there are exactly 2 good elements, the permutation is beautiful.

The second sample has no beautiful permutations.
# Problem: B. Levko and Permutation
# Contest: Codeforces - Codeforces Round #210 (Div. 2)
# URL: https://codeforces.com/problemset/problem/361/B
# Memory Limit: 256 MB
# Time Limit: 1000 ms
# 
# Powered by CP Editor (https://cpeditor.org)

n,k=[int(_) for _ in input().split()]
if n==k:
	print(-1)
else:
	if (n-k)%2==0:
		for _ in range(0,n-k,2):
			print(_+2,_+1,end=" ")
	else:
		print(1,end=" ")
		for _ in range(1,n-k,2):
			print(_+2,_+1,end=" ")
	for _ in range(n-k,n):
			print(_+1,end=" ")