A string s of length n (1 ≤ n ≤ 26) is called alphabetical if it can be obtained using the following algorithm:

  * first, write an empty string to s (i.e. perform the assignment s := ""); 
  * then perform the next step n times; 
  * at the i-th step take i-th lowercase letter of the Latin alphabet and write it either to the left of the string s or to the right of the string s (i.e. perform the assignment s := c+s or s := s+c, where c is the i-th letter of the Latin alphabet). 



In other words, iterate over the n first letters of the Latin alphabet starting from 'a' and etc. Each time we prepend a letter to the left of the string s or append a letter to the right of the string s. Strings that can be obtained in that way are alphabetical.

For example, the following strings are alphabetical: "a", "ba", "ab", "bac" and "ihfcbadeg". The following strings are not alphabetical: "z", "aa", "ca", "acb", "xyz" and "ddcba".

From the given string, determine if it is alphabetical.

Input

The first line contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

Each test case is written on a separate line that contains one string s. String s consists of lowercase letters of the Latin alphabet and has a length between 1 and 26, inclusive.

Output

Output t lines, each of them must contain the answer to the corresponding test case. Output YES if the given string s is alphabetical and NO otherwise.

You can output YES and NO in any case (for example, strings yEs, yes, Yes and YES will be recognized as a positive answer).

Example

Input


11
a
ba
ab
bac
ihfcbadeg
z
aa
ca
acb
xyz
ddcba


Output


YES
YES
YES
YES
YES
NO
NO
NO
NO
NO
NO

Note

The example contains test cases from the main part of the condition.
/******************************************************************************

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/******************************************************************************

                            Online Java Compiler.
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Write your code in this editor and press "Run" button to execute it.

*******************************************************************************/
import java.util.*;
import java.lang.*;
import java.io.*;
public class Main
{
    
	public static void main(String[] args) {
		Scanner sc=new Scanner(System.in);
		int t=sc.nextInt();
		while(t--!=0)
		{
		   String s=sc.next();
		   if(s.length()==1)
		   {
		       if( s.charAt(0)!='a')
		       {
		        System.out.println("NO");
		       }
		       else
		       {
		         System.out.println("Yes");  
		       }
		   }
		   else if(s.length()==2)
		   {
		       if((s.charAt(0)=='a' &&  s.charAt(1)=='b') || (s.charAt(0)=='b' &&  s.charAt(1)=='a'))
		       {
		           System.out.println("Yes");
		       }
		       else
		       {
		          System.out.println("NO"); 
		       }
		   }
		   else
		   {
		       int ca=0;
		       int inda=0;
		       for(int i=0;i<s.length();i++)
		       {
		           if(s.charAt(i)=='a')
		           {
		               inda=i;
		               ca++;
		           }
		       }
		       if(ca>1 || ca==0)
		       {
		          System.out.println("NO");  
		       }
		       
		       else{
    		       int k=inda;
    		       int i=inda;
    		       int j=inda;
    		       int f=0;
    		       int ct=1;
    		       //System.out.println(s.charAt(k)+1=='b');
    		       while(ct!=s.length())
    		       {
    		           if(i-1>=0 && s.charAt(k)+1==s.charAt(i-1))
    		           {
    		               k=i-1;
    		               i--;
    		               ct++;
    		           }
    		           else if(j+1<s.length() && s.charAt(k)+1==s.charAt(j+1))
    		           {
    		              k=j+1;
    		              j++;
    		              ct++;
    		           }
    		           else
    		           {
    		               f=1;
    		               System.out.println("NO");  
    		               break;
    		           }
    		       }
    		       if(f!=1)
    		       {
    		         System.out.println("YES");  
    		       }
		       }
		   }
		}
	}
}
