On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
import math


def get_primes(prime_supr):

    is_prime = [0]*2 + [1]*prime_supr

    for i in range(2,int(math.sqrt(prime_supr)) + 1):
        if is_prime[i]:
            for j in range(i * i, prime_supr + 1, i):
                is_prime[j] = 0

    return is_prime

get_int = lambda: map(int, input().split())

n = int(input())

ans = (n//7) * 2
n -= 7 * (ans//2)
if n == 1:
    print(ans, ans + 1)
elif n == 6:
    print(ans + 1, ans + 2)
elif n == 0:
    print(ans, ans)
else:
    print(ans, ans + 2)
