On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
import java.io.*;
import java.util.*;

public class Main {

	public static void main(String[] args) throws IOException {
		BufferedReader sc = new BufferedReader(new InputStreamReader(System.in));
		int n = Integer.parseInt(sc.readLine());
		PrintWriter pw = new PrintWriter(System.out);

		int ans = n / 7 * 2;
		int rem = n % 7;
		if (rem > 5) {
			System.out.println((ans + rem - 5) + " " + (ans + 2));
		} else {
			if (rem == 1) {
				System.out.println(ans + " " + (ans + 1));
			} else if (rem > 1) {
				System.out.println(ans + " " + (ans + 2));
			} else {
				System.out.println(ans + " " + ans);
			}
		}
	}
}