We have N colored balls arranged in a row from left to right; the color of the i-th ball from the left is c_i.

You are given Q queries. The i-th query is as follows: how many different colors do the l_i-th through r_i-th balls from the left have?

Constraints

* 1\leq N,Q \leq 5 \times 10^5
* 1\leq c_i \leq N
* 1\leq l_i \leq r_i \leq N
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N Q
c_1 c_2 \cdots c_N
l_1 r_1
l_2 r_2
:
l_Q r_Q


Output

Print Q lines. The i-th line should contain the response to the i-th query.

Examples

Input

4 3
1 2 1 3
1 3
2 4
3 3


Output

2
3
1


Input

10 10
2 5 6 5 2 1 7 9 7 2
5 5
2 4
6 7
2 2
7 8
7 9
1 8
6 9
8 10
6 8


Output

1
2
2
1
2
2
6
3
3
3
#include<bits/stdc++.h>
using namespace std;
typedef int64_t ll;
const ll N=500001;
ll n,q,c[N],l[N],r[N],a[N],b[N],ans[N];
vector<pair<ll,ll>> x[N];

void add(ll x,ll v){
  for(int i=x;i<=n;i+=i&(-i))
    b[i]+=v;
}

int sum(ll x){
  ll v=0;
  for(int i=x;i>0;i-=i&(-i))v+=b[i];
  return v;
}

int main(){
  cin>>n>>q;
  for(int i=1;i<=n;i++)cin>>c[i];
  for(int i=1;i<=q;i++){
    cin>>l[i]>>r[i];
    x[r[i]].push_back({l[i],i});
  }
  for(int i=1;i<=n;i++){
    if(a[c[i]])add(a[c[i]],-1);
    a[c[i]]=i;
    add(i,1);
    for(auto [d,e]:x[i])ans[e]=sum(i)-sum(d-1);
  }
  for(int i=1;i<=q;i++)cout<<ans[i]<<endl;
}