Constraints

* 1 ≤ |V| ≤ 1000
* 0 ≤ |E| ≤ 2000
* -10000 ≤ di ≤ 10000
* There are no parallel edges
* There are no self-loops

Input

An edge-weighted graph G (V, E) and the source r.


|V| |E| r
s0 t0 d0
s1 t1 d1
:
s|E|-1 t|E|-1 d|E|-1


|V| is the number of vertices and |E| is the number of edges in G. The graph vertices are named with the numbers 0, 1,..., |V|-1 respectively. r is the source of the graph.

si and ti represent source and target vertices of i-th edge (directed) and di represents the cost of the i-th edge.

Output

If the graph contains a negative cycle (a cycle whose sum of edge costs is a negative value) which is reachable from the source r, print


NEGATIVE CYCLE


in a line.

Otherwise, print


c0
c1
:
c|V|-1


The output consists of |V| lines. Print the cost of the shortest path from the source r to each vertex 0, 1, ... |V|-1 in order. If there is no path from the source to a vertex, print "INF".

Examples

Input

4 5 0
0 1 2
0 2 3
1 2 -5
1 3 1
2 3 2


Output

0
2
-3
-1


Input

4 6 0
0 1 2
0 2 3
1 2 -5
1 3 1
2 3 2
3 1 0


Output

NEGATIVE CYCLE


Input

4 5 1
0 1 2
0 2 3
1 2 -5
1 3 1
2 3 2


Output

INF
0
-5
-3
# Input acceptance
import sys

file_input = sys.stdin

V, E, r = map(int, file_input.readline().split())

edges = []

for line in file_input:
    edges.append(tuple(map(int, line.split())))


# Bellman???Ford algorithm
distance = [float("inf")] * V
distance[r] = 0
notUpdated = True

for i in range(V - 1):
    notUpdated = True
    for s, t, w in edges:
        temp_d = distance[s] + w
        if temp_d < distance[t]:
            distance[t] = temp_d
            notUpdated = False
    if notUpdated:
        break


# Output
if notUpdated:
    print(*map(lambda x: str(x).upper(), distance), sep = '\n')
else:
    flag = True
    for s, t, w in edges:
        temp_d = distance[s] + w
        if temp_d < distance[t]:
            print("NEGATIVE CYCLE")
            flag = False
            break
    if flag:
        print(*map(lambda x: str(x).upper(), distance), sep = '\n')