You are given two integer sequences of length N: a_1,a_2,..,a_N and b_1,b_2,..,b_N. Determine if we can repeat the following operation zero or more times so that the sequences a and b become equal.

Operation: Choose two integers i and j (possibly the same) between 1 and N (inclusive), then perform the following two actions simultaneously:

* Add 2 to a_i.
* Add 1 to b_j.

Constraints

* 1 ≤ N ≤ 10 000
* 0 ≤ a_i,b_i ≤ 10^9 (1 ≤ i ≤ N)
* All input values are integers.

Input

Input is given from Standard Input in the following format:


N
a_1 a_2 .. a_N
b_1 b_2 .. b_N


Output

If we can repeat the operation zero or more times so that the sequences a and b become equal, print `Yes`; otherwise, print `No`.

Examples

Input

3
1 2 3
5 2 2


Output

Yes


Input

5
3 1 4 1 5
2 7 1 8 2


Output

No


Input

5
2 7 1 8 2
3 1 4 1 5


Output

No
import java.io.*;
import java.math.*;
import java.util.*;
public class Main {
	public static void main(String[] args) { 
		//If max is greater than sum of rest, the first person can hog biggest to win
		FastScanner I = new FastScanner(); //Input
		OutPut O = new OutPut(); //Output
		int N = I.nextInt();
		int[] a = new int[N];
		int[] b = new int[N];
		for (int i = 0; i < N; i++) a[i] = I.nextInt();
		for (int i = 0; i < N; i++) b[i] = I.nextInt();
		long bad = 0;
		long TWO = 0;
		for (int i = 0; i < N; i++) {
			if (a[i]>b[i]) {
				bad+=a[i]-b[i];
			}else if (b[i]>a[i]) {
				TWO+=(b[i]-a[i])/2;
			}
		}
		O.pln(TWO>=bad?"Yes":"No"); //Leftovers can be adjusted using the +1 differential
	}
	public static double max(double a, double b) {return Math.max(a, b);}
	public static double min(double a, double b) {return Math.min(a, b);}
	public static long min(long a, long b) {return Math.min(a,b);}
	public static long max(long a, long b) {return Math.max(a,b);}
	public static int min(int a, int b) {return Math.min(a,b);}
	public static int max(int a, int b) {return Math.max(a,b);}
	public static long abs(long x) {return Math.abs(x);}
	public static long ceil(long num, long den) {long ans = num/den; if (num%den!=0) 
	ans++; return ans;}
	public static long GCD(long a, long b) {
		if (a==0||b==0) return max(a,b);
		return GCD(min(a,b),max(a,b)%min(a,b));
	}
	public static long FastExp(long base, long exp, long mod) {
		long ans=1;
		while (exp>0) {
			if (exp%2==1) ans*=base;
			exp/=2;
			base*=base;
			base%=mod;
			ans%=mod;
		}
		return ans;
	}
	public static long ModInv(long num,long mod) {return FastExp(num,mod-2,mod);}
	public static int pop(long x) { //Returns number of bits within a number
		int cnt = 0;
		while (x>0) {
			if (x%2==1) cnt++;
			x/=2;
		}
		return cnt;
	}
	static class FastScanner {
		BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
		StringTokenizer st=new StringTokenizer("");
		String next() {
			while (!st.hasMoreTokens())
				try {
					st=new StringTokenizer(br.readLine());
				} catch (IOException e) {
					e.printStackTrace();
				}
			return st.nextToken();
		}
		int nextInt() {return Integer.parseInt(next());}
		long nextLong() {return Long.parseLong(next());};
		double nextDouble() {return Double.parseDouble(next());}
	}
	static class OutPut{
		PrintWriter w = new PrintWriter(System.out);
		void pln(double x) {w.println(x);w.flush();}
		void pln(boolean x) {w.println(x);w.flush();}
		void pln(int x) {w.println(x);w.flush();}
		void pln(long x) {w.println(x);w.flush();}
		void pln(String x) {w.println(x);w.flush();}
		void pln(char x) {w.println(x);w.flush();}
		void pln(StringBuilder x) {w.println(x);w.flush();}
		void pln(BigInteger x) {w.println(x);w.flush();}
		void p(int x) {w.print(x);w.flush();}
		void p(long x) {w.print(x);w.flush();}
		void p(String x) {w.print(x);w.flush();}
		void p(char x) {w.print(x);w.flush();}
		void p(StringBuilder x) {w.print(x);w.flush();}
		void p(BigInteger x) {w.print(x);w.flush();}
		void p(double x) {w.print(x);w.flush();}
		void p(boolean x) {w.print(x);w.flush();}
	}
}
