On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
num_days = int(raw_input())

if num_days <= 2:
	print 0, num_days
else:
	remainder_2 = (num_days-2) % 7
	to_add_2 = (remainder_2-5) if remainder_2 >= 5 else 0
	remainder_5 = (num_days-5) % 7
	if remainder_5 == 0:
		to_add_5 = 0
	elif remainder_5 == 1:
		to_add_5 = 1
	else:
		to_add_5 = 2
	min_days = ((num_days-2)/7)*2+2+to_add_2
	max_days = (num_days-5)/7*2 + to_add_5
	print max_days, min_days