On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
n = int(raw_input())
n_parc = n
minn = 0
maxx = 0
while n_parc > 0:
	n_parc -= 5
	if n_parc >= 2: 
		minn += 2
		n_parc -= 2
	elif n_parc >= 1:
		minn += 1
		n_parc -= 1
		
while n > 0:
	if n >= 2: 
		maxx += 2
		n -= 2
	elif n >= 1:
		maxx += 1
		n -= 1
	n -= 5
	
print "{} {}".format(minn, maxx)
