A string s of length n (1 ≤ n ≤ 26) is called alphabetical if it can be obtained using the following algorithm:

  * first, write an empty string to s (i.e. perform the assignment s := ""); 
  * then perform the next step n times; 
  * at the i-th step take i-th lowercase letter of the Latin alphabet and write it either to the left of the string s or to the right of the string s (i.e. perform the assignment s := c+s or s := s+c, where c is the i-th letter of the Latin alphabet). 



In other words, iterate over the n first letters of the Latin alphabet starting from 'a' and etc. Each time we prepend a letter to the left of the string s or append a letter to the right of the string s. Strings that can be obtained in that way are alphabetical.

For example, the following strings are alphabetical: "a", "ba", "ab", "bac" and "ihfcbadeg". The following strings are not alphabetical: "z", "aa", "ca", "acb", "xyz" and "ddcba".

From the given string, determine if it is alphabetical.

Input

The first line contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

Each test case is written on a separate line that contains one string s. String s consists of lowercase letters of the Latin alphabet and has a length between 1 and 26, inclusive.

Output

Output t lines, each of them must contain the answer to the corresponding test case. Output YES if the given string s is alphabetical and NO otherwise.

You can output YES and NO in any case (for example, strings yEs, yes, Yes and YES will be recognized as a positive answer).

Example

Input


11
a
ba
ab
bac
ihfcbadeg
z
aa
ca
acb
xyz
ddcba


Output


YES
YES
YES
YES
YES
NO
NO
NO
NO
NO
NO

Note

The example contains test cases from the main part of the condition.
import java.util.*;
import java.io.*;

public class Solution {

    private static ArrayList<Integer> prime = new ArrayList<>();

    public static void main(String[] args) throws IOException {

        Scanner in=new Scanner(System.in);
        BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
        StringBuffer out = new StringBuffer();

        int T = in.nextInt();

        OUTER:
        while(T-->0) {

            char s[]=in.next().toCharArray();

            int n=s.length;
            char max='a';
            for(char item: s)
                max=(char)Math.max(max, item);

            if(n!=max-'a'+1) {
                out.append("NO\n");
                continue OUTER;
            }

            int lo=0, hi=n-1;
            while(lo<=hi) {
                if(s[lo]==max)
                    lo+=1;
                else if(s[hi]==max)
                    hi-=1;
                else {
                    out.append("NO\n");
                    continue OUTER;
                }
                max=(char)(max-1);
            }
            out.append("YES\n");
        }

        System.out.print(out);
    }

    private static long lcm(long a, long b) {
        return (a*b)/gcd(a, b);
    }

    private static long gcd(long a, long b) {
        if (a==0)
            return b;
        return gcd(b%a, a);
    }

    private static int toInt(String s) {
        return Integer.parseInt(s);
    }

    private static long toLong(String s) {
        return Long.parseLong(s);
    }
}