A string s of length n (1 ≤ n ≤ 26) is called alphabetical if it can be obtained using the following algorithm:

  * first, write an empty string to s (i.e. perform the assignment s := ""); 
  * then perform the next step n times; 
  * at the i-th step take i-th lowercase letter of the Latin alphabet and write it either to the left of the string s or to the right of the string s (i.e. perform the assignment s := c+s or s := s+c, where c is the i-th letter of the Latin alphabet). 



In other words, iterate over the n first letters of the Latin alphabet starting from 'a' and etc. Each time we prepend a letter to the left of the string s or append a letter to the right of the string s. Strings that can be obtained in that way are alphabetical.

For example, the following strings are alphabetical: "a", "ba", "ab", "bac" and "ihfcbadeg". The following strings are not alphabetical: "z", "aa", "ca", "acb", "xyz" and "ddcba".

From the given string, determine if it is alphabetical.

Input

The first line contains one integer t (1 ≤ t ≤ 10^4) — the number of test cases. Then t test cases follow.

Each test case is written on a separate line that contains one string s. String s consists of lowercase letters of the Latin alphabet and has a length between 1 and 26, inclusive.

Output

Output t lines, each of them must contain the answer to the corresponding test case. Output YES if the given string s is alphabetical and NO otherwise.

You can output YES and NO in any case (for example, strings yEs, yes, Yes and YES will be recognized as a positive answer).

Example

Input


11
a
ba
ab
bac
ihfcbadeg
z
aa
ca
acb
xyz
ddcba


Output


YES
YES
YES
YES
YES
NO
NO
NO
NO
NO
NO

Note

The example contains test cases from the main part of the condition.
import java.util.*;
import java.io.*;

public class Solution {

    public static void main(String[] args) throws IOException {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

        int t = Integer.parseInt(br.readLine());

        BufferedWriter output = new BufferedWriter(new OutputStreamWriter(System.out));

        StringTokenizer st;

        while (t-- > 0) {

            String s = br.readLine();
            int len = s.length();

            int ascii = 96 + len;
            int flag = 0;
            for(int i = 0 ; i < len; i++)
            {
                char c = (char)ascii;
                if(s.charAt(0) == c)
                s = s.substring(1);

                else if(s.charAt(s.length() - 1) == c)
                s = s.substring(0, s.length() - 1);

                else
                {
                    flag = 1;
                    break;
                }

                ascii--;
            }

            if(flag == 0)
            output.write("YES\n");

            else
            output.write("NO\n");

            // int n = Integer.parseInt(br.readLine());
            
            // st = new StringTokenizer(br.readLine());

            // int arr[] = new int[n];

            // for(int i = 0; i < n; i++)
            // {
            // int e = Integer.parseInt(st.nextToken());
            // arr[i] = e;
            // }

            // int k = Integer.parseInt(st.nextToken());


            // output.write();
            // int n = Integer.parseInt(st.nextToken());

            // HashMap<Character, Integer> map = new HashMap<Character, Integer>();

            // if
            // output.write("YES\n");
            // else
            // output.write("NO\n");

            // long a = Long.parseLong(st.nextToken());
            // long b = Long.parseLong(st.nextToken());

            // if(flag == 1)
            // output.write("NO\n");
            // else
            // output.write("YES\n" + x + " " + y + " " + z + "\n");

            // output.write(n+ "\n");

        }

        output.flush();

    }

}