On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Examples

Input

14


Output

4 4


Input

2


Output

0 2

Note

In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .

In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off.
x=int(raw_input())
if x%7==6:
    print (x/7)*2+1,(x/7)*2+2
elif x%7==2 or x%7>2:
    print (x/7)*2,(x/7)*2+2    
elif x%7==1:
    print (x/7)*2,(x/7)*2+1
else:
    print (x/7)*2,(x/7)*2
    