Ashish has an array a of size n.

A subsequence of a is defined as a sequence that can be obtained from a by deleting some elements (possibly none), without changing the order of the remaining elements.

Consider a subsequence s of a. He defines the cost of s as the minimum between: 

  * The maximum among all elements at odd indices of s. 
  * The maximum among all elements at even indices of s. 



Note that the index of an element is its index in s, rather than its index in a. The positions are numbered from 1. So, the cost of s is equal to min(max(s_1, s_3, s_5, …), max(s_2, s_4, s_6, …)).

For example, the cost of \{7, 5, 6\} is min( max(7, 6), max(5) ) = min(7, 5) = 5.

Help him find the minimum cost of a subsequence of size k.

Input

The first line contains two integers n and k (2 ≤ k ≤ n ≤ 2 ⋅ 10^5) — the size of the array a and the size of the subsequence.

The next line contains n integers a_1, a_2, …, a_n (1 ≤ a_i ≤ 10^9) — the elements of the array a.

Output

Output a single integer — the minimum cost of a subsequence of size k.

Examples

Input


4 2
1 2 3 4


Output


1

Input


4 3
1 2 3 4


Output


2

Input


5 3
5 3 4 2 6


Output


2

Input


6 4
5 3 50 2 4 5


Output


3

Note

In the first test, consider the subsequence s = \{1, 3\}. Here the cost is equal to min(max(1), max(3)) = 1.

In the second test, consider the subsequence s = \{1, 2, 4\}. Here the cost is equal to min(max(1, 4), max(2)) = 2.

In the fourth test, consider the subsequence s = \{3, 50, 2, 4\}. Here the cost is equal to min(max(3, 2), max(50, 4)) = 3.
from fractions import Fraction
import bisect
import os
import io
from collections import Counter
import bisect
from collections import defaultdict
import math
import random
import heapq as hq
from math import sqrt
import sys
from functools import reduce, cmp_to_key
from collections import deque
import threading
from itertools import combinations
from io import BytesIO, IOBase
from itertools import accumulate
from queue import Queue


# sys.setrecursionlimit(200000)
# input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline


def input():
    return sys.stdin.readline().strip()


def iinput():
    return int(input())


def tinput():
    return input().split()


def rinput():
    return map(int, tinput())


def rlinput():
    return list(rinput())


mod = int(1e9)+7


def factors(n):
    return set(reduce(list.__add__,
                      ([i, n//i] for i in range(1, int(n**0.5) + 1) if n % i == 0)))


# ----------------------------------------------------
# sys.stdin = open('input.txt', 'r')
# sys.stdout = open('output.txt', 'w')

def isPossible(value, isEven):
    subsequence_size = 0
    for i in a:
        if isEven:
            if i <= value:
                subsequence_size += 1
                isEven = False
        else:
            subsequence_size += 1
            isEven = True
    return k <= subsequence_size


def bin_search(l, r):
    while l < r:
        mid = (l+r)//2
        if isPossible(mid, True) or isPossible(mid, False):
            r = mid
        else:
            l = mid+1
    return l


t = 1
# t = iinput()
for _ in range(t):
    n, k = rinput()
    a = rlinput()
    print(bin_search(0, int(1e9)))
