Try guessing the statement from this picture: 

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You are given a non-negative integer d. You have to find two non-negative real numbers a and b such that a + b = d and a ⋅ b = d.

Input

The first line contains t (1 ≤ t ≤ 10^3) — the number of test cases.

Each test case contains one integer d (0 ≤ d ≤ 10^3).

Output

For each test print one line.

If there is an answer for the i-th test, print "Y", and then the numbers a and b.

If there is no answer for the i-th test, print "N".

Your answer will be considered correct if |(a + b) - a ⋅ b| ≤ 10^{-6} and |(a + b) - d| ≤ 10^{-6}.

Example

Input


7
69
0
1
4
5
999
1000


Output


Y 67.985071301 1.014928699
Y 0.000000000 0.000000000
N
Y 2.000000000 2.000000000
Y 3.618033989 1.381966011
Y 997.998996990 1.001003010
Y 998.998997995 1.001002005
#!/usr/bin/env python3
from typing import Dict, List, Tuple


def input_lst() -> List[int]:
    return [int(x) for x in input().split()]

def print_out(res: List[int]):
    print(' '.join([str(x) for x in res]))

# def eratosthenes(n):     # n - число, до которого хотим найти простые числа
#

def main():

    n,  = (int(x) for x in input().split())
    for _ in range(n):
        d = int(input())
        discr = d**2 - 4*d
        if discr < 0:
            print('N')
            continue

        x = (d + discr**0.5)/2
        print('Y {:0.9f} {:0.9f}'.format(x, d-x))


if __name__ == '__main__':
    main()
