G: Working

Kou decided to do the same number of jobs every day for the next $ N $.

$ A_i $ jobs are added on the $ i $ day of the $ N $ day.

Mr. Kou has no work to do now, and he doesn't have to finish all the work by the $ N $ day.

How many jobs can you do in a day?

However, Mr. Kou is excellent, so he can do as many jobs as he has.

input

$ N $ is given on the first line.

On the second line, $ N $ integers $ A_1, A_2, A_3, \ dots, A_N $ are given, separated by blanks.

output

Output the maximum number of jobs you can do in a day. Insert a line break at the end.

Constraint

* $ N $ is an integer greater than or equal to $ 1 $ and less than or equal to $ 100 $
* $ A_1, A_2, A_3, \ dots, A_N $ are integers between $ 1 $ and $ 100 $



Input example 1


Five
4 2 5 3 1


Output example 1


3


If you decide to work more than $ 4 $ a day, you'll run out of work on the second day.

Input example 2


Five
9 9 1 9 9


Output example 2


6






Example

Input

5
4 2 5 3 1


Output

3
# include <iostream>
# include <algorithm>
#include <array>
# include <cassert>
#include <cctype>
#include <climits>
#include <numeric>
# include <vector>
# include <string>
# include <set>
# include <map>
# include <cmath>
# include <iomanip>
# include <functional>
# include <tuple>
# include <utility>
# include <stack>
# include <queue>
# include <list>
# include <bitset>
# include <complex>
# include <chrono>
# include <random>
# include <limits.h>
# include <unordered_map>
# include <unordered_set>
# include <deque>
# include <cstdio>
# include <cstring>
#include <stdio.h>
#include<time.h>
#include <stdlib.h>
#include <cstdint>
#include <cfenv>
#include<fstream>
//#include <bits/stdc++.h>
using namespace std;
using LL = long long;
using ULL = unsigned long long;
long long MOD = 1000000000 + 7; //924844033 1000000000 + 7;
constexpr long long INF = numeric_limits<LL>::max();
const double PI = acos(-1);
#define fir first
#define sec second
#define thi third
#define debug(x) cerr<<#x<<": "<<x<<'\n'
typedef pair<LL, LL> Pll;
typedef pair<double, double> Dll;
typedef pair<LL, pair<LL, LL>> Ppll;
typedef pair<LL, pair<LL, bitset<100001>>> Pbll;
typedef pair<LL, pair<LL, vector<LL>>> Pvll;
typedef pair<LL, LL> Vec2;
struct Tll { LL first, second, third; };
struct Fll { LL first, second, third, fourth; };
typedef pair<LL, Tll> Ptll;
#define rep(i,rept) for(LL i=0;i<rept;i++)
#define Rrep(i,mf) for(LL i=mf-1;i>=0;i--)
LL h, w, n, m, k, t, s, p, q, last, first, cnt, sum, ans, dp[40000],a[200000],b[200000];
string str, ss;
bool f;
char c;
int di[4][2] = { { 0,1 },{ 1,0 },{ 0,-1 },{ -1,0 } };
struct Edge { LL to, cost; };
struct edge { LL from, to, cost; };
vector<LL>vec;
vector<edge>ed;
vector<Pll>v;
map<LL,LL>ma;
set<LL>st;
void YN(bool f) {
	if (f)
		cout << "YES" << endl;
	else
		cout << "NO" << endl;
}
void yn(bool f) {
	if (f)
		cout << "Yes" << endl;
	else
		cout << "No" << endl;
}

int main() {
	cin >> n;
	rep(i, n) {
		cin >> a[i];
	}
	rep(i, 101) {
		sum = 0;
		rep(j, n) {
			if (sum < 0) {
				f = 1;
				break;
			}
			sum += a[j];
			sum -= i;
		}
		if (sum >= 0 && f == 0) {
			ans = i;
		}
	}
	cout << ans << endl;
	return 0;
}

