Given is an integer sequence A_1, ..., A_N of length N.

We will choose exactly \left\lfloor \frac{N}{2} \right\rfloor elements from this sequence so that no two adjacent elements are chosen.

Find the maximum possible sum of the chosen elements.

Here \lfloor x \rfloor denotes the greatest integer not greater than x.

Constraints

* 2 \leq N \leq 2\times 10^5
* |A_i|\leq 10^9
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N
A_1 ... A_N


Output

Print the maximum possible sum of the chosen elements.

Examples

Input

6
1 2 3 4 5 6


Output

12


Input

5
-1000 -100 -10 0 10


Output

0


Input

10
1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000


Output

5000000000


Input

27
18 -28 18 28 -45 90 -45 23 -53 60 28 -74 -71 35 -26 -62 49 -77 57 24 -70 -93 69 -99 59 57 -49


Output

295
N=int(input())
A=list(map(int, input().split()))
if N==2:
  print(max(A))
  exit() 
  
dp=[[0,0,0] for i in range(N)]
dp[0][0]=A[0]
dp[1][1]=A[1]
dp[2][2]=A[2]
for i in range(N):
  if i>1:
    dp[i][0]=dp[i-2][0]+A[i]
  if i>2:
    dp[i][1]=max(dp[i-3][0],dp[i-2][1])+A[i]
  if i>3 :
    dp[i][2]=max(dp[i-4][0],dp[i-3][1],dp[i-2][2])+A[i]
if N%2==1:
  ans=max(dp[-1][2],dp[-2][1],dp[-3][0])
else:
  ans=max(dp[-1][1],dp[-2][0])
print(ans)