You are given 4n sticks, the length of the i-th stick is a_i.

You have to create n rectangles, each rectangle will consist of exactly 4 sticks from the given set. The rectangle consists of four sides, opposite sides should have equal length and all angles in it should be right. Note that each stick can be used in only one rectangle. Each stick should be used as a side, you cannot break the stick or use it not to the full length.

You want to all rectangles to have equal area. The area of the rectangle with sides a and b is a ⋅ b.

Your task is to say if it is possible to create exactly n rectangles of equal area or not.

You have to answer q independent queries.

Input

The first line of the input contains one integer q (1 ≤ q ≤ 500) — the number of queries. Then q queries follow.

The first line of the query contains one integer n (1 ≤ n ≤ 100) — the number of rectangles.

The second line of the query contains 4n integers a_1, a_2, ..., a_{4n} (1 ≤ a_i ≤ 10^4), where a_i is the length of the i-th stick.

Output

For each query print the answer to it. If it is impossible to create exactly n rectangles of equal area using given sticks, print "NO". Otherwise print "YES".

Example

Input


5
1
1 1 10 10
2
10 5 2 10 1 1 2 5
2
10 5 1 10 5 1 1 1
2
1 1 1 1 1 1 1 1
1
10000 10000 10000 10000


Output


YES
YES
NO
YES
YES
import java.util.*;
import java.lang.*;
import java.io.*;
public class Codechef
{   static PrintWriter out=new PrintWriter(System.out);
	static FastScanner in = new FastScanner(System.in);
     static class FastScanner {BufferedReader br;StringTokenizer stok;FastScanner(InputStream is) {br = new BufferedReader(new InputStreamReader(is));}
        String next() throws IOException {while (stok == null || !stok.hasMoreTokens()) {String s = br.readLine();if (s == null) {return null;}
                stok = new StringTokenizer(s);}return stok.nextToken();}
        int ni() throws IOException {    return Integer.parseInt(next());}
        long nl() throws IOException {return Long.parseLong(next());}
        double nd() throws IOException {return Double.parseDouble(next());}
        char nc() throws IOException {return (char) (br.read());}
        String ns() throws IOException {return br.readLine();}
        int[] nia(int n) throws IOException{int a[] = new int[n];for (int i = 0; i < n; i++)a[i] = ni();return a;}
        long[] nla(int n) throws IOException {
            long a[] = new long[n];for (int i = 0; i < n; i++)a[i] = nl();return a;}
        double[] nda(int n)throws IOException {double a[] = new double[n];for (int i = 0; i < n; i++)        a[i] = nd();    return a;}
        int [][] imat(int n,int m) throws IOException
        {   int mat[][]=new int[n][m];for(int i=0;i<n;i++){   for(int j=0;j<m;j++)mat[i][j]=ni();}return mat;}
        
    }
        
    ///MAIN METHOD
    
    
    
    
	static long mod=Long.MAX_VALUE;
	public static void main (String[] args) throws java.lang.Exception
	{   int i,j;
	    HashSet<Integer> set=new HashSet<Integer>();
        PriorityQueue<Integer> pq=new PriorityQueue<Integer>();
        /*  int n = in.ni();
            int m = in.ni();
            String s=in.ns();
            int a[]=in.nia(n);
            int b[][]=in.im(n,m);
            pia(a);
		    pimat(b);
            sort(a,0,a.length-1);
        */
        int t=in.ni();
        while(t--!=0)
        {
            ArrayList<Integer> arr=new ArrayList<>();
            int n=in.ni();
            int z=4*n;
            for(i=0;i<z;i++)
                arr.add(in.ni());
            Collections.sort(arr);
            int temp=arr.get(0)*arr.get(z-1);
            int ans=0;
            int counter1=0 ,counter2=z-1;int temp1=1;
            while(temp1!=n+1)
            {   int flag1=arr.get(counter1);
                int flag2=arr.get(counter1+1);
                int flag3=arr.get(counter2);
                int flag4=arr.get(counter2-1);
                if(flag1!=flag2)
                    break;
                if(flag3!=flag4)
                    break;
                if(flag1*flag4==temp)
                    ans++;
                counter1+=2;
                    counter2-=2;
                    temp1++;
            }
            if(ans==n)
                out.println("YES");
            else
                out.println("NO");
            ///out.println(ans);
        }    
        out.close();
	}
		static long gcd(long a,long b)
	{   if(b==0)
	        return a;
	    return gcd(b,a%b);    
	}
	static long exponent(long a,long n)
	{   long ans=1;
	    while(n!=0)
	    {   if(n%2==1)
	            ans=(ans*a)%mod;
	       a=(a*a)%mod;
	       n=n>>1;
	    }
	    return ans;
	}
	static int binarySearch(int a[], int item, int low, int high) 
    {   if (high <= low) 
            return (item > a[low])?  (low + 1): low; 
        int mid = (low + high)/2; 
        if(item == a[mid]) 
            return mid+1; 
        if(item > a[mid]) 
            return binarySearch(a, item, mid+1, high); 
        return binarySearch(a, item, low, mid-1); 
    } 
   static void merge(int arr[], int l, int m, int r) 
    {   int n1 = m - l + 1; int n2 = r - m; int L[] = new int [n1]; int R[] = new int [n2]; 
        
        for (int i=0; i<n1; ++i) L[i] = arr[l + i]; for (int j=0; j<n2; ++j) R[j] = arr[m + 1+ j]; int i = 0, j = 0; int k = l; 
        while (i < n1 && j < n2) {   if (L[i] <= R[j]) {   arr[k] = L[i]; i++; } else{   arr[k] = R[j]; j++; } k++; } while (i < n1){   arr[k] = L[i]; i++; k++; } while (j < n2) { arr[k] = R[j];   j++;     k++; } 
    } 
    static void Sort(int arr[], int l, int r) 
    {    if (l < r) {   int m = (l+r)/2; Sort(arr, l, m); Sort(arr , m+1, r); merge(arr, l, m, r); } } 
    
    static void sort(int a[])
    {Sort(a,0,a.length-1);}
}