Try guessing the statement from this picture: 

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You are given a non-negative integer d. You have to find two non-negative real numbers a and b such that a + b = d and a ⋅ b = d.

Input

The first line contains t (1 ≤ t ≤ 10^3) — the number of test cases.

Each test case contains one integer d (0 ≤ d ≤ 10^3).

Output

For each test print one line.

If there is an answer for the i-th test, print "Y", and then the numbers a and b.

If there is no answer for the i-th test, print "N".

Your answer will be considered correct if |(a + b) - a ⋅ b| ≤ 10^{-6} and |(a + b) - d| ≤ 10^{-6}.

Example

Input


7
69
0
1
4
5
999
1000


Output


Y 67.985071301 1.014928699
Y 0.000000000 0.000000000
N
Y 2.000000000 2.000000000
Y 3.618033989 1.381966011
Y 997.998996990 1.001003010
Y 998.998997995 1.001002005
import math
for i in range(int(input())):
	d=int(input())
	x=d**2 -(4*d)
	if x<0:
		print('N')
	else:
		x=math.sqrt(x)
		b1=(d+x)/2
		b2=(d-x)/2
		if b2==1:
			a1=b1/(b1-1)
			print('Y',end=" ")
			print(a1,end=" ")
			print(b1)
		elif b1==1:
			a2=b2/(b2-1)
			print('Y',end=" ")
			print(a2,end=" ")
			print(b2)
		else:
			a1=b1/(b1-1)
			print('Y',end=" ")
			print(a1,end=" ")
			print(b1)