Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print `-1` instead.

Constraints

* 2 \leq N \leq 10^5
* 0 \leq A_i \leq 10^{18}
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N
A_1 ... A_N


Output

Print the value A_1 \times ... \times A_N as an integer, or `-1` if the value exceeds 10^{18}.

Examples

Input

2
1000000000 1000000000


Output

1000000000000000000


Input

3
101 9901 999999000001


Output

-1


Input

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0


Output

0
import java.util.*;
public class Main {
  public static void main(String[] args){
    Scanner sc = new Scanner(System.in);
    
    int n = sc.nextInt();
    long a[] =new long[n];
    long count = 1;
    
    //入力値を配列に格納
    for(int i = 0; i < n; ++i){
      a[i] = sc.nextLong();
      //0があったら0を代入
      if(0 == a[i]){
        count = 0;
      }
    }
    //0が含まれてなかった場合
    if(count != 0){
      for(int i = 0 ; i < n ; ++i){
        if(a[i]<=(long)Math.pow(10,18)/count){
          count *= a[i];
        }else{
          count = -1;
          break;
        }
        
      }
     
    }
    System.out.println(count);
  }
}