Try guessing the statement from this picture: 

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You are given a non-negative integer d. You have to find two non-negative real numbers a and b such that a + b = d and a ⋅ b = d.

Input

The first line contains t (1 ≤ t ≤ 10^3) — the number of test cases.

Each test case contains one integer d (0 ≤ d ≤ 10^3).

Output

For each test print one line.

If there is an answer for the i-th test, print "Y", and then the numbers a and b.

If there is no answer for the i-th test, print "N".

Your answer will be considered correct if |(a + b) - a ⋅ b| ≤ 10^{-6} and |(a + b) - d| ≤ 10^{-6}.

Example

Input


7
69
0
1
4
5
999
1000


Output


Y 67.985071301 1.014928699
Y 0.000000000 0.000000000
N
Y 2.000000000 2.000000000
Y 3.618033989 1.381966011
Y 997.998996990 1.001003010
Y 998.998997995 1.001002005

import java.util.Arrays;
import java.util.Scanner;


public class testing{

	public static void main(String[] args) throws Exception {
	
		Scanner sc = new Scanner(System.in);
		int t = sc.nextInt();
		while(t-- > 0) {
			double d = sc.nextInt();
			if(d == 0) {
				System.out.println("Y 0 0");
			}else if(d * d - d * 4 < 0) {
				System.out.println("N");
			}else {
				double rdelta = Math.sqrt(d * d - 4 * d);
				double a = (d + rdelta) / 2;
				double b = d - a;
				if(a >=0 & b >= 0) System.out.println("Y " + a + " " + b);
				else {
					a = (d - rdelta) / 2;
					b = d - a;
					if(a >= 0 & b >= 0) System.out.println("Y " + a + " " + b);
					else System.out.println("N");
						 
 				}
			}
		}
		
	}

}