Try guessing the statement from this picture: 

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You are given a non-negative integer d. You have to find two non-negative real numbers a and b such that a + b = d and a ⋅ b = d.

Input

The first line contains t (1 ≤ t ≤ 10^3) — the number of test cases.

Each test case contains one integer d (0 ≤ d ≤ 10^3).

Output

For each test print one line.

If there is an answer for the i-th test, print "Y", and then the numbers a and b.

If there is no answer for the i-th test, print "N".

Your answer will be considered correct if |(a + b) - a ⋅ b| ≤ 10^{-6} and |(a + b) - d| ≤ 10^{-6}.

Example

Input


7
69
0
1
4
5
999
1000


Output


Y 67.985071301 1.014928699
Y 0.000000000 0.000000000
N
Y 2.000000000 2.000000000
Y 3.618033989 1.381966011
Y 997.998996990 1.001003010
Y 998.998997995 1.001002005
/* package whatever; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
public class Ideone
{
	public static void main (String[] args) throws java.lang.Exception
	{
		// your code goes here
		Scanner sc=new Scanner(System.in);
		int t=sc.nextInt();
		while(t-->0)
		{
			int d=sc.nextInt();
			double a=0;
			double b=0;
			if(d==0)
			{
				System.out.println("Y"+" "+a+" "+b);
				continue;
			}
		
			int res=d*d-4*d;
			if(res<0)
			{
				System.out.println("N");
				continue;
			}
			a=(d+Math.pow(res,0.5))/2;
			b=(d-Math.pow(res,0.5))/2;
			if (a < 0 || b < 0) {
                System.out.println("N");
            } 
            else
			System.out.println("Y"+" "+a+" "+b);
			
			
			
		}
	}
}