Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons: 

  * Tetrahedron. Tetrahedron has 4 triangular faces. 
  * Cube. Cube has 6 square faces. 
  * Octahedron. Octahedron has 8 triangular faces. 
  * Dodecahedron. Dodecahedron has 12 pentagonal faces. 
  * Icosahedron. Icosahedron has 20 triangular faces. 



All five kinds of polyhedrons are shown on the picture below:

<image>

Anton has a collection of n polyhedrons. One day he decided to know, how many faces his polyhedrons have in total. Help Anton and find this number!

Input

The first line of the input contains a single integer n (1 ≤ n ≤ 200 000) — the number of polyhedrons in Anton's collection.

Each of the following n lines of the input contains a string si — the name of the i-th polyhedron in Anton's collection. The string can look like this:

  * "Tetrahedron" (without quotes), if the i-th polyhedron in Anton's collection is a tetrahedron. 
  * "Cube" (without quotes), if the i-th polyhedron in Anton's collection is a cube. 
  * "Octahedron" (without quotes), if the i-th polyhedron in Anton's collection is an octahedron. 
  * "Dodecahedron" (without quotes), if the i-th polyhedron in Anton's collection is a dodecahedron. 
  * "Icosahedron" (without quotes), if the i-th polyhedron in Anton's collection is an icosahedron. 

Output

Output one number — the total number of faces in all the polyhedrons in Anton's collection.

Examples

Input

4
Icosahedron
Cube
Tetrahedron
Dodecahedron


Output

42


Input

3
Dodecahedron
Octahedron
Octahedron


Output

28

Note

In the first sample Anton has one icosahedron, one cube, one tetrahedron and one dodecahedron. Icosahedron has 20 faces, cube has 6 faces, tetrahedron has 4 faces and dodecahedron has 12 faces. In total, they have 20 + 6 + 4 + 12 = 42 faces.
"""
#********************************************************************************
#* Author : Susmith Poochali
#*
#* Anton and Polyhedrons
#* Problem: https://codeforces.com/problemset/problem/785/A
#*
#*  
#* Program needs two inputs
#* nums 	- (Integer) The number of polyhedrons in Anton's collection
#* shapes 	-  List of shape names
#********************************************************************************
"""

from typing import List

class Polyhedrons:
	__SHAPES = {
		'Tetrahedron' 	: 	4,
		'Cube' 			: 	6,
		'Octahedron'	:	8, 
		'Dodecahedron'	: 	12,
		'Icosahedron'	: 	20
	}
	def find_no_faces(self) -> int:
		no_of_faces = 0
		for shape in self.shapes:
			if shape in self.__SHAPES:
				no_of_faces += self.__SHAPES[shape]
		return no_of_faces
	
	def get_shapes(self, count):
		self.shapes = []
		if count > 0 and count <= 200000:
			for c in range(count):
				self.shapes.append(input())
				
# Execution begins here
if __name__ == '__main__':
	no_of_polyhedrons = int(input())
	poly = Polyhedrons()
	poly.get_shapes(no_of_polyhedrons)
	print(poly.find_no_faces())

		
	