Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print `-1` instead.

Constraints

* 2 \leq N \leq 10^5
* 0 \leq A_i \leq 10^{18}
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N
A_1 ... A_N


Output

Print the value A_1 \times ... \times A_N as an integer, or `-1` if the value exceeds 10^{18}.

Examples

Input

2
1000000000 1000000000


Output

1000000000000000000


Input

3
101 9901 999999000001


Output

-1


Input

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0


Output

0
#include<bits/stdc++.h>
using namespace std;
int main(){
  int n;cin>>n;long long an=1;bool x=true;
  vector<long long>a(n);
  for(int i=0;i<n;i++){cin>>a[i];if(a[i]==0)x=false;}
  for(int i=0;i<n;i++){
    if(a[i]>1000000000000000000/an){
      an=-1;break;
    }
    an*=a[i];
  }
  if(x)cout<<an<<endl;
  else cout<<0<<endl;
}

