You are given two arrays of integers a and b. For each element of the second array bj you should find the number of elements in array a that are less than or equal to the value bj.

Input

The first line contains two integers n, m (1 ≤ n, m ≤ 2·105) — the sizes of arrays a and b.

The second line contains n integers — the elements of array a ( - 109 ≤ ai ≤ 109).

The third line contains m integers — the elements of array b ( - 109 ≤ bj ≤ 109).

Output

Print m integers, separated by spaces: the j-th of which is equal to the number of such elements in array a that are less than or equal to the value bj.

Examples

Input

5 4
1 3 5 7 9
6 4 2 8


Output

3 2 1 4


Input

5 5
1 2 1 2 5
3 1 4 1 5


Output

4 2 4 2 5
import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {
    private static int bs(int[] a,int l,int h,int x){
        int low=l;
        int high=h;
        
        while(low<=high){
            int mid=(low+high)/2;
            if(a[mid]<=x){
                low=mid+1;
            }
            else{
                high=mid-1;
            }
        }
        return low;
    }

    public static void main(String[] args) throws IOException{
        BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
            String[] str=br.readLine().split(" ");
            int m=Integer.parseInt(str[0]);
            int n=Integer.parseInt(str[1]);
            String[] str1=br.readLine().split(" ");
        String[] str2=br.readLine().split(" ");
            int[] arr1=new int[m+1];
        int[] arr2=new int[n];
        for(int i=0;i<m;i++){
            arr1[i]=Integer.parseInt(str1[i]);
        }
        arr1[m]=Integer.MAX_VALUE;
        for(int i=0;i<n;i++){
            arr2[i]=Integer.parseInt(str2[i]);
        }
        Arrays.parallelSort(arr1);
        int ans=0;
        for(int i=0;i<n;i++){
           if(i==0){
               ans=bs(arr1,0,m,arr2[i]);
           }
            else{
                if(arr2[i]>arr2[i-1]){
                    ans=bs(arr1,ans,m,arr2[i]);
                }
                else if(arr2[i]<arr2[i-1]) {ans=bs(arr1,0,ans,arr2[i]);}
            }
            System.out.print(ans+" ");
        }
        
    }  
}