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You are given a non-negative integer d. You have to find two non-negative real numbers a and b such that a + b = d and a ⋅ b = d.

Input

The first line contains t (1 ≤ t ≤ 10^3) — the number of test cases.

Each test case contains one integer d (0 ≤ d ≤ 10^3).

Output

For each test print one line.

If there is an answer for the i-th test, print "Y", and then the numbers a and b.

If there is no answer for the i-th test, print "N".

Your answer will be considered correct if |(a + b) - a ⋅ b| ≤ 10^{-6} and |(a + b) - d| ≤ 10^{-6}.

Example

Input


7
69
0
1
4
5
999
1000


Output


Y 67.985071301 1.014928699
Y 0.000000000 0.000000000
N
Y 2.000000000 2.000000000
Y 3.618033989 1.381966011
Y 997.998996990 1.001003010
Y 998.998997995 1.001002005
t = input()


def solve(v):
    if v == 0:
        print "Y",0,0
        return
    low,high = 1.,v/2.
    while high-low>=1e-14:
        mid = (low+high)/2
        tmp = mid*(v-mid)
        if tmp == v:
            print "Y",v-mid,mid
            return
        elif tmp<v:
            low = mid
        else:
            high = mid
    print "Y",v-mid,mid



for _ in range(t):
    d = input()
    if (d/2.)**2<d:
        print "N"
    else:
        solve(d)


 	  		   			 	 				 			 					