G: Working

Kou decided to do the same number of jobs every day for the next $ N $.

$ A_i $ jobs are added on the $ i $ day of the $ N $ day.

Mr. Kou has no work to do now, and he doesn't have to finish all the work by the $ N $ day.

How many jobs can you do in a day?

However, Mr. Kou is excellent, so he can do as many jobs as he has.

input

$ N $ is given on the first line.

On the second line, $ N $ integers $ A_1, A_2, A_3, \ dots, A_N $ are given, separated by blanks.

output

Output the maximum number of jobs you can do in a day. Insert a line break at the end.

Constraint

* $ N $ is an integer greater than or equal to $ 1 $ and less than or equal to $ 100 $
* $ A_1, A_2, A_3, \ dots, A_N $ are integers between $ 1 $ and $ 100 $



Input example 1


Five
4 2 5 3 1


Output example 1


3


If you decide to work more than $ 4 $ a day, you'll run out of work on the second day.

Input example 2


Five
9 9 1 9 9


Output example 2


6






Example

Input

5
4 2 5 3 1


Output

3
#include <iostream>
#include <string>
#include <algorithm>
#include <functional>
#include <vector>
#include <utility>
#include <cstring>
#include <iomanip>
#include <numeric>
#include <cmath>
#include <cassert>
using namespace std;
using ll = long long;
const int INF = 1<<30;
const int MOD = 1e9 + 7;
int main()
{
    cin.tie(0);
    ios::sync_with_stdio(false);
    int n; cin >> n;
    vector<int> v(n);
    for(int i = 0; i < n; i++) cin >> v[i];
    int ans = 101;
    while(ans--)
    {
        int tmp = 0;
        for(int i = 0; i < n; i++)
        {
            if(v[i] + tmp < ans) break;
            tmp = (v[i] + tmp) - ans;
            if(i == n - 1)
            {
                cout << ans << endl;
                return 0;
            }
        }
    }
    return 0;
}


