Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print `-1` instead.

Constraints

* 2 \leq N \leq 10^5
* 0 \leq A_i \leq 10^{18}
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N
A_1 ... A_N


Output

Print the value A_1 \times ... \times A_N as an integer, or `-1` if the value exceeds 10^{18}.

Examples

Input

2
1000000000 1000000000


Output

1000000000000000000


Input

3
101 9901 999999000001


Output

-1


Input

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0


Output

0
#include <stdio.h>
long long a [100010];
int main (){
int n;
scanf("%d",&n);
for(int i=0;i<n;i++) scanf("%lld",&a[i]);
int zero =0;
for(int i=0;i<n;i++)if(a[i]==0) zero++;
if(zero >0){
printf("0\n");
return 0;
}
long long prod =1;
for(int i=0;i<n;i++){
if(a[i ] <=1000000000000000000/ prod ){
prod *=a[i];
}else{
printf("-1\n");
return 0;
}
}
printf("%lld\n",prod );
}
