Given is an integer sequence A_1, ..., A_N of length N.

We will choose exactly \left\lfloor \frac{N}{2} \right\rfloor elements from this sequence so that no two adjacent elements are chosen.

Find the maximum possible sum of the chosen elements.

Here \lfloor x \rfloor denotes the greatest integer not greater than x.

Constraints

* 2 \leq N \leq 2\times 10^5
* |A_i|\leq 10^9
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N
A_1 ... A_N


Output

Print the maximum possible sum of the chosen elements.

Examples

Input

6
1 2 3 4 5 6


Output

12


Input

5
-1000 -100 -10 0 10


Output

0


Input

10
1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000


Output

5000000000


Input

27
18 -28 18 28 -45 90 -45 23 -53 60 28 -74 -71 35 -26 -62 49 -77 57 24 -70 -93 69 -99 59 57 -49


Output

295
n=int(input())
a= list(map(int, input().split()))

if n==2:
    print(max(a[0],a[1]))
    exit()
    
dp=[[-float('inf'),-float('inf'),-float('inf')] for i in range(n)]
# dp[i][0]:iまででまだ飛ばしてない
# dp[i][1]:一つ飛ばしてる
# dp[i][2]:２つ飛ばしてる
dp[0][0]=a[0]
dp[1][1]=a[1]
dp[2][2]=a[2]

for i in range(2,n):
    dp[i][0]=dp[i-2][0]+a[i]
    if i>=3:
        dp[i][1]=max(dp[i-2][1]+a[i],dp[i-3][0]+a[i])
    if i>=4:
        dp[i][2]=max(dp[i-2][2]+a[i],dp[i-3][1]+a[i],dp[i-4][0]+a[i])

if n%2==0:
    print(max(dp[-2][0],dp[-1][1]))
else:
    print(max(dp[-3][0],dp[-2][1],dp[-1][2]))