Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons: 

  * Tetrahedron. Tetrahedron has 4 triangular faces. 
  * Cube. Cube has 6 square faces. 
  * Octahedron. Octahedron has 8 triangular faces. 
  * Dodecahedron. Dodecahedron has 12 pentagonal faces. 
  * Icosahedron. Icosahedron has 20 triangular faces. 



All five kinds of polyhedrons are shown on the picture below:

<image>

Anton has a collection of n polyhedrons. One day he decided to know, how many faces his polyhedrons have in total. Help Anton and find this number!

Input

The first line of the input contains a single integer n (1 ≤ n ≤ 200 000) — the number of polyhedrons in Anton's collection.

Each of the following n lines of the input contains a string si — the name of the i-th polyhedron in Anton's collection. The string can look like this:

  * "Tetrahedron" (without quotes), if the i-th polyhedron in Anton's collection is a tetrahedron. 
  * "Cube" (without quotes), if the i-th polyhedron in Anton's collection is a cube. 
  * "Octahedron" (without quotes), if the i-th polyhedron in Anton's collection is an octahedron. 
  * "Dodecahedron" (without quotes), if the i-th polyhedron in Anton's collection is a dodecahedron. 
  * "Icosahedron" (without quotes), if the i-th polyhedron in Anton's collection is an icosahedron. 

Output

Output one number — the total number of faces in all the polyhedrons in Anton's collection.

Examples

Input

4
Icosahedron
Cube
Tetrahedron
Dodecahedron


Output

42


Input

3
Dodecahedron
Octahedron
Octahedron


Output

28

Note

In the first sample Anton has one icosahedron, one cube, one tetrahedron and one dodecahedron. Icosahedron has 20 faces, cube has 6 faces, tetrahedron has 4 faces and dodecahedron has 12 faces. In total, they have 20 + 6 + 4 + 12 = 42 faces.
#Wrong Substraction
    # n,k= input().split()
    # n= int(n)
    # k = int(k)
    # for i in range(k):
    #     if(n%10==0):
    #         n=n/10
    #     else:
    #         n-=1
    #     n=int(n)
    # print(n) 

#Easy Question
    # n = int(input())
    # h = 0
    # for i in range(n):
    #     k=int(input())
    #     if k == 0 or 1 :
    #         if k == 0 :
    #             pass
    #         else:
    #             h = 1
    # if k == 0 or 1 :
    #     if h == 1 :
    #         print("HARD")
    #     else:
    #         print("EASY")
        
# Bear and Big Brother
    # a ,b =input().split()
    # a=int(a)
    # b=int(b)
    # count = 0
    # if a <= b:
    #     while a<=b:
    #         a*=3
    #         b*=2
    #         count+=1
    #     print(int(count))

#Anton and Polyhedrons
n = int(input())
count = 0
for i in range(n):
    s=input()
    if(s == 'Tetrahedron'):
        count+=4
    elif(s== 'Cube'):
        count+=6
    elif(s=='Octahedron'):
        count+=8
    elif(s=='Dodecahedron'):
        count+=12
    elif(s=='Icosahedron'):
        count+=20
    else:
        count+=0
print(int(count))