Try guessing the statement from this picture: 

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You are given a non-negative integer d. You have to find two non-negative real numbers a and b such that a + b = d and a ⋅ b = d.

Input

The first line contains t (1 ≤ t ≤ 10^3) — the number of test cases.

Each test case contains one integer d (0 ≤ d ≤ 10^3).

Output

For each test print one line.

If there is an answer for the i-th test, print "Y", and then the numbers a and b.

If there is no answer for the i-th test, print "N".

Your answer will be considered correct if |(a + b) - a ⋅ b| ≤ 10^{-6} and |(a + b) - d| ≤ 10^{-6}.

Example

Input


7
69
0
1
4
5
999
1000


Output


Y 67.985071301 1.014928699
Y 0.000000000 0.000000000
N
Y 2.000000000 2.000000000
Y 3.618033989 1.381966011
Y 997.998996990 1.001003010
Y 998.998997995 1.001002005

import java.util.Scanner;

public class MemeProblem {
    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);
        int n = input.nextInt();

        for (int i = 0; i < n; i++) {
            boolean hasAnswer;
            double x1 = 0 , x2 = 0;
            int d = input.nextInt();
            float delta = (d*d) - 4*d;
            if (delta > 0){
                hasAnswer = true;
                x1 = ((d + Math.sqrt(delta))/2);
                x2 = ((d - Math.sqrt(delta))/2);
            }else if(delta == 0){
                hasAnswer = true;
                x1 = ((d + Math.sqrt(delta))/2);
                x2 = ((d - Math.sqrt(delta))/2);
            }else{
                hasAnswer = false;
            }

            if(hasAnswer){
                System.out.printf("Y %.9f %.9f\n" , x1 , x2);
            }else
                System.out.printf("N\n");
        }
    }
}
