Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print `-1` instead.

Constraints

* 2 \leq N \leq 10^5
* 0 \leq A_i \leq 10^{18}
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N
A_1 ... A_N


Output

Print the value A_1 \times ... \times A_N as an integer, or `-1` if the value exceeds 10^{18}.

Examples

Input

2
1000000000 1000000000


Output

1000000000000000000


Input

3
101 9901 999999000001


Output

-1


Input

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0


Output

0
import java.math.BigInteger;
import java.util.Scanner;
import java.util.stream.IntStream;

public class Main {

	/** 10^18 */
	private static final BigInteger BIG = BigInteger.valueOf(1_000_000_000_000_000_000L);

	public static void main(String[] args) {
		try (Scanner scanner = new Scanner(System.in)) {
			int n = scanner.nextInt();
			long[] a = new long[n];
			if (IntStream.range(0, n).mapToLong(i -> a[i] = scanner.nextLong()).filter(i -> i == 0L).count() > 0) {
				System.out.println(0);
				return;
			}
			BigInteger result = BigInteger.ONE;
			for (int i = 0; i < n; i++) {
				result = result.multiply(BigInteger.valueOf(a[i]));
				if (result.compareTo(BIG) > 0) {
					System.out.println(-1);
					return;
				}
			}
			System.out.println(result);
		}
	}
}
