Orac is studying number theory, and he is interested in the properties of divisors.

For two positive integers a and b, a is a divisor of b if and only if there exists an integer c, such that a⋅ c=b.

For n ≥ 2, we will denote as f(n) the smallest positive divisor of n, except 1.

For example, f(7)=7,f(10)=2,f(35)=5.

For the fixed integer n, Orac decided to add f(n) to n. 

For example, if he had an integer n=5, the new value of n will be equal to 10. And if he had an integer n=6, n will be changed to 8.

Orac loved it so much, so he decided to repeat this operation several times.

Now, for two positive integers n and k, Orac asked you to add f(n) to n exactly k times (note that n will change after each operation, so f(n) may change too) and tell him the final value of n.

For example, if Orac gives you n=5 and k=2, at first you should add f(5)=5 to n=5, so your new value of n will be equal to n=10, after that, you should add f(10)=2 to 10, so your new (and the final!) value of n will be equal to 12.

Orac may ask you these queries many times.

Input

The first line of the input is a single integer t\ (1≤ t≤ 100): the number of times that Orac will ask you.

Each of the next t lines contains two positive integers n,k\ (2≤ n≤ 10^6, 1≤ k≤ 10^9), corresponding to a query by Orac.

It is guaranteed that the total sum of n is at most 10^6. 

Output

Print t lines, the i-th of them should contain the final value of n in the i-th query by Orac.

Example

Input


3
5 1
8 2
3 4


Output


10
12
12

Note

In the first query, n=5 and k=1. The divisors of 5 are 1 and 5, the smallest one except 1 is 5. Therefore, the only operation adds f(5)=5 to 5, and the result is 10.

In the second query, n=8 and k=2. The divisors of 8 are 1,2,4,8, where the smallest one except 1 is 2, then after one operation 8 turns into 8+(f(8)=2)=10. The divisors of 10 are 1,2,5,10, where the smallest one except 1 is 2, therefore the answer is 10+(f(10)=2)=12.

In the third query, n is changed as follows: 3 → 6 → 8 → 10 → 12.
import java.io.*; 
import java.io.FileInputStream; 
import java.io.IOException; 
import java.io.InputStreamReader; 
import java.util.*; 
import java.util.StringTokenizer; 

public class Main 
{ 
    static int MAXN=1000001;
    static int spf[] = new int[MAXN]; 
    static int ans[]=new int[MAXN];
    static int id[]=new int[MAXN];
    static int sz[]=new int[MAXN];
    static HashSet s=new HashSet();
	static class FastReader 
	{ 
		BufferedReader br; 
		StringTokenizer st; 

		public FastReader() 
		{ 
			br = new BufferedReader(new
					InputStreamReader(System.in)); 
		} 

		String next() 
		{ 
			while (st == null || !st.hasMoreElements()) 
			{ 
				try
				{ 
					st = new StringTokenizer(br.readLine()); 
				} 
				catch (IOException e) 
				{ 
					e.printStackTrace(); 
				} 
			} 
			return st.nextToken(); 
		} 

		int nextInt() 
		{ 
			return Integer.parseInt(next()); 
		} 

		long nextLong() 
		{ 
			return Long.parseLong(next()); 
		} 

		double nextDouble() 
		{ 
			return Double.parseDouble(next()); 
		} 

		String nextLine() 
		{ 
			String str = ""; 
			try
			{ 
				str = br.readLine(); 
			} 
			catch (IOException e) 
			{ 
				e.printStackTrace(); 
			} 
			return str; 
		} 
	} 
    static void sieves() 
    { 
        spf[1] = 1; 
        for (int i=2; i<MAXN; i++) 
            spf[i] = i; 
        for (int i=4; i<MAXN; i+=2) 
            spf[i] = 2; 
        for (long i=3; i*i<MAXN; i++) 
        { 
            if (spf[(int)i] == i) 
            { 
                for (long j=i*i; j<MAXN; j+=i) 
                    if (spf[(int)j]==j) 
                        spf[(int)j] = (int)i; 
            } 
        } 
    } 
    static void getFactorizations(int x) 
    { 
        Vector<Integer> ret = new Vector<>(); 
        HashSet w=new HashSet();
        while (x != 1 && spf[x]!=1) 
        { 
            if(!w.contains(spf[x]) && spf[x]!=1)
            {
            w.add(spf[x]);
            ans[spf[x]]++; 
            }
            x = x / spf[x]; 
        }
    } 
	public static void main(String[] args) 
	{ 
		FastReader sc=new FastReader();
	    int T=sc.nextInt();
	    sieves();
	    while(T-->0){
	        int N=sc.nextInt();
	        long K=sc.nextLong();
	        int ans=N;
	        while(K>0){
	            ans+=spf[ans];
	            K--;
	            if(ans%2==0)break;
	        }
	        long a=2*K+ans;
	        System.out.println(a);
	    }
	} 
	public static int root(int i)
    {
        while(i!=id[i])
        i=id[i];
        return i;
    }
    public static void union(int p,int q)
    {
        int i=root(p);
        int j=root(q);
        //System.out.println(i+" "+j);
        if(sz[i]<sz[j])
        {
            id[i]=j;
            sz[j]+=sz[i];
        }
        else
        {
            id[j]=i;
            sz[i]+=sz[j];
        }
        //max=Math.max(max,Math.max(sz[i],sz[j]));
    }
	public static void sieven(int n) 
    {
        boolean prime[] = new boolean[n+1]; 
        for(int i=0;i<n;i++) 
            prime[i] = true; 
        for(int p = 2; p*p <=n; p++) 
        { 
            if(prime[p] == true) 
            { 
                for(int i = p*2; i <= n; i += p) 
                    prime[i] = false; 
            } 
        } 
        for(int p=2; p<=n;p++)
        if(prime[p]==true)
        s.add(p);
    } 
	public static long gcd(long a,long b)
	{
	    if(b==0)
	    return a;
	    return gcd(b,a%b);
	}
	static long power(long x, long y, int p) 
    { 
        long res = 1;      
        x = x % p;  
        while (y > 0) 
        { 
            if((y & 1)==1) 
                res = (res * x) % p; 
            y = y >> 1;  
            x = (x * x) % p;  
        } 
        return res; 
    }
    static class Pair
	{ 
		int x; 
		int y;
		public Pair(int x, int y) 
		{	 
			this.x = x; 
			this.y = y; 
		}	 
	} 
    static class Compare
	{ 
		static void compare(Pair arr[], int n) 
		{ 
			// Comparator to sort the pair according to second element 
			Arrays.sort(arr, new Comparator<Pair>() { 
				@Override public int compare(Pair p1, Pair p2) 
				{ 
					if(p1.x>p2.x)
					{
						return 1;
					}
					else if(p2.x>p1.x)
					{
						return -1;
					}
					else
					{
						return 0;
					} 
				} 
			}); 
		} 
	}
}
