Try guessing the statement from this picture: 

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You are given a non-negative integer d. You have to find two non-negative real numbers a and b such that a + b = d and a ⋅ b = d.

Input

The first line contains t (1 ≤ t ≤ 10^3) — the number of test cases.

Each test case contains one integer d (0 ≤ d ≤ 10^3).

Output

For each test print one line.

If there is an answer for the i-th test, print "Y", and then the numbers a and b.

If there is no answer for the i-th test, print "N".

Your answer will be considered correct if |(a + b) - a ⋅ b| ≤ 10^{-6} and |(a + b) - d| ≤ 10^{-6}.

Example

Input


7
69
0
1
4
5
999
1000


Output


Y 67.985071301 1.014928699
Y 0.000000000 0.000000000
N
Y 2.000000000 2.000000000
Y 3.618033989 1.381966011
Y 997.998996990 1.001003010
Y 998.998997995 1.001002005


import java.io.*;
import java.math.*;
import java.util.*;


// @author : Dinosparton 

public class test {
	 
	   static class Pair{ 
		   long x;
		   long y;
		   
		   Pair(long x,long y){ 
			   this.x = x;
			   this.y = y;
			   
		   }
	   }
	  
	   static class Compare { 
		   
		     void compare(Pair arr[], int n) 
		    { 
		        // Comparator to sort the pair according to second element 
		        Arrays.sort(arr, new Comparator<Pair>() { 
		            @Override public int compare(Pair p1, Pair p2) 
		            { 
		                return (int)(p1.x - p2.x); 
		            } 
		        }); 
		  
//		        for (int i = 0; i < n; i++) { 
//		            System.out.print(arr[i].x + " " + arr[i].y + " "); 
//		        } 
//		        System.out.println(); 
		    } 
		} 
	 
	   static class Scanner {
	        BufferedReader br;
	        StringTokenizer st;
	 
	        public Scanner()
	        {
	            br = new BufferedReader(
	                new InputStreamReader(System.in));
	        }
	 
	        String next()
	        {
	            while (st == null || !st.hasMoreElements()) {
	                try {
	                    st = new StringTokenizer(br.readLine());
	                }
	                catch (IOException e) {
	                    e.printStackTrace();
	                }
	            }
	            return st.nextToken();
	        }
	 
	        int nextInt() { return Integer.parseInt(next()); }
	 
	        long nextLong() { return Long.parseLong(next()); }
	 
	        double nextDouble()
	        {
	            return Double.parseDouble(next());
	        }
	 
	        String nextLine()
	        {
	            String str = "";
	            try {
	                str = br.readLine();
	            }
	            catch (IOException e) {
	                e.printStackTrace();
	            }
	            return str;
	        }
	    }
	   
	   static boolean isPerfectSquare(double x)
	    {
	        if (x >= 0) {
	           
	            // Find floating point value of
	            // square root of x.
	            double sr = Math.sqrt(x);
	           
	            // if product of square root
	            // is equal, then
	            // return T/F
	 
	            return ((sr * sr) == x);
	        }
	        return false;
	    }
	   

	   public static void main(String args[]) throws Exception { 
		
		   Scanner sc = new Scanner();
		   StringBuffer ans = new StringBuffer();
		   
		  
			
		   int tc = sc.nextInt();
		   
		   while(tc-->0) { 
			   
			   int t = sc.nextInt();
			   double root1,root2;
			   
               double D = Math.sqrt((Math.pow(t, 2)) - (4 * t));
               if (t==0){
                   System.out.println("Y 0.000000000000 0.000000000000");
               }
               else if (t<4){
                   System.out.println("N");
               }
               else {
                   if (D < 0) {
                       System.out.println("N");

                   }
                       else {
                       root1 = (t + D) / 2;
                       root2 = (t - D) / 2;
                       System.out.println("Y" + " " + root1 + " " + root2);
                   }
               }
		   }
			  
			System.out.println(ans);
	   }
}  




