Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print `-1` instead.

Constraints

* 2 \leq N \leq 10^5
* 0 \leq A_i \leq 10^{18}
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N
A_1 ... A_N


Output

Print the value A_1 \times ... \times A_N as an integer, or `-1` if the value exceeds 10^{18}.

Examples

Input

2
1000000000 1000000000


Output

1000000000000000000


Input

3
101 9901 999999000001


Output

-1


Input

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0


Output

0
import java.util.Scanner;

public class Main {
	public static void main(String[] args){
		Scanner stdIn = new Scanner(System.in);
		int N = stdIn.nextInt();
		long ans = 1;
		long []A = new long[N];
		for(int a = 0; a < N; a++){
			A[a] = stdIn.nextLong();
		}
		for(int b = 0; b < N; b++){
			if(A[b] == 0){
				ans = 0;
				break;
			}
			else if(A[b] > (long)Math.pow(10, 18)/ans){
				ans = -1;
			}
			else{
				ans *= A[b];
			}
		}
		System.out.println(ans);
		stdIn.close();
	}
}