Given is an integer sequence A_1, ..., A_N of length N.

We will choose exactly \left\lfloor \frac{N}{2} \right\rfloor elements from this sequence so that no two adjacent elements are chosen.

Find the maximum possible sum of the chosen elements.

Here \lfloor x \rfloor denotes the greatest integer not greater than x.

Constraints

* 2 \leq N \leq 2\times 10^5
* |A_i|\leq 10^9
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N
A_1 ... A_N


Output

Print the maximum possible sum of the chosen elements.

Examples

Input

6
1 2 3 4 5 6


Output

12


Input

5
-1000 -100 -10 0 10


Output

0


Input

10
1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000


Output

5000000000


Input

27
18 -28 18 28 -45 90 -45 23 -53 60 28 -74 -71 35 -26 -62 49 -77 57 24 -70 -93 69 -99 59 57 -49


Output

295
import collections, sys
sys.setrecursionlimit(100005)
N = int(input())
A = [int(_) for _ in input().split()]
INF = float('inf')
memo = collections.defaultdict(lambda: INF)


def c(start, res):
    if memo[start, res] != INF:
        return memo[start, res]
    elif 2 * res - 1 > N - start:
        memo[start, res] = -INF
    elif start >= N:
        memo[start, res] = -INF
    elif res > 1:
        memo[start, res] = max(A[start] + c(start + 2, res - 1),
                               c(start + 1, res), c(start + 2, res))
    else:
        memo[start, res] = max(A[start], c(start + 1, res))
    return memo[start, res]


print(c(0, N // 2))
