Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons: 

  * Tetrahedron. Tetrahedron has 4 triangular faces. 
  * Cube. Cube has 6 square faces. 
  * Octahedron. Octahedron has 8 triangular faces. 
  * Dodecahedron. Dodecahedron has 12 pentagonal faces. 
  * Icosahedron. Icosahedron has 20 triangular faces. 



All five kinds of polyhedrons are shown on the picture below:

<image>

Anton has a collection of n polyhedrons. One day he decided to know, how many faces his polyhedrons have in total. Help Anton and find this number!

Input

The first line of the input contains a single integer n (1 ≤ n ≤ 200 000) — the number of polyhedrons in Anton's collection.

Each of the following n lines of the input contains a string si — the name of the i-th polyhedron in Anton's collection. The string can look like this:

  * "Tetrahedron" (without quotes), if the i-th polyhedron in Anton's collection is a tetrahedron. 
  * "Cube" (without quotes), if the i-th polyhedron in Anton's collection is a cube. 
  * "Octahedron" (without quotes), if the i-th polyhedron in Anton's collection is an octahedron. 
  * "Dodecahedron" (without quotes), if the i-th polyhedron in Anton's collection is a dodecahedron. 
  * "Icosahedron" (without quotes), if the i-th polyhedron in Anton's collection is an icosahedron. 

Output

Output one number — the total number of faces in all the polyhedrons in Anton's collection.

Examples

Input

4
Icosahedron
Cube
Tetrahedron
Dodecahedron


Output

42


Input

3
Dodecahedron
Octahedron
Octahedron


Output

28

Note

In the first sample Anton has one icosahedron, one cube, one tetrahedron and one dodecahedron. Icosahedron has 20 faces, cube has 6 faces, tetrahedron has 4 faces and dodecahedron has 12 faces. In total, they have 20 + 6 + 4 + 12 = 42 faces.
/*
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 * To change this template file, choose Tools | Templates
 * and open the template in the editor.
 */

import java.util.*;

public class NewMain {
    static Scanner key = new Scanner(System.in);
    
    public static int sumOfFaces(int s){
        int result = 0;
        String[] shapes = {"tetrahedron","cube","octahedron","dodecahedron","icosahedron"};
        for (int i = 0; i < s; i++) {
            int numOfShapes = 0;
            String sh = key.nextLine();
            sh = sh.toLowerCase();
            if(sh.equals(shapes[0])){
                numOfShapes = 4; 
            } else if(sh.equals(shapes[1])){
                numOfShapes = 6;
            } else if(sh.equals(shapes[2])){
                numOfShapes = 8;
            }else if(sh.equals(shapes[3])){
                numOfShapes = 12;
            } else{
                numOfShapes = 20;
            }
            result += numOfShapes;
        }
        return result;
    }
    public static void main(String[] args) {
        int num = Integer.parseInt(key.nextLine());
        System.out.println(sumOfFaces(num));
    }
    
}
