G: Working

Kou decided to do the same number of jobs every day for the next $ N $.

$ A_i $ jobs are added on the $ i $ day of the $ N $ day.

Mr. Kou has no work to do now, and he doesn't have to finish all the work by the $ N $ day.

How many jobs can you do in a day?

However, Mr. Kou is excellent, so he can do as many jobs as he has.

input

$ N $ is given on the first line.

On the second line, $ N $ integers $ A_1, A_2, A_3, \ dots, A_N $ are given, separated by blanks.

output

Output the maximum number of jobs you can do in a day. Insert a line break at the end.

Constraint

* $ N $ is an integer greater than or equal to $ 1 $ and less than or equal to $ 100 $
* $ A_1, A_2, A_3, \ dots, A_N $ are integers between $ 1 $ and $ 100 $



Input example 1


Five
4 2 5 3 1


Output example 1


3


If you decide to work more than $ 4 $ a day, you'll run out of work on the second day.

Input example 2


Five
9 9 1 9 9


Output example 2


6






Example

Input

5
4 2 5 3 1


Output

3
#include<iostream>
#include<string>
#include<iomanip>
#include<cmath>
#include<vector>
#include<algorithm>

using namespace std;

#define int long long
#define rep(i,n) for(int i = 0; i < (n); i++)
#define INF (long long)(1e18)
#define MOD (int)(1e9+7)

#define yn(f) ((f)?"Yes":"No")
#define YN(f) ((f)?"YES":"NO")

signed main(){
	cout<<fixed<<setprecision(7);

	int N, A[200];
	
	cin>>N;
	
	rep(i,N){
		cin>>A[i];
	}
	for(int i = 1; i <= 101; i++){
		bool flag = true;
		int xx = 0;
		for(int j = 0; j < N; j++){
			xx += A[j];
			xx -= i;
			if(xx < 0)flag = false;
		}
		if(flag == false){
			cout<<i-1<<endl;
			break;
		}
	}
	
	return 0;
}
