Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print `-1` instead.

Constraints

* 2 \leq N \leq 10^5
* 0 \leq A_i \leq 10^{18}
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N
A_1 ... A_N


Output

Print the value A_1 \times ... \times A_N as an integer, or `-1` if the value exceeds 10^{18}.

Examples

Input

2
1000000000 1000000000


Output

1000000000000000000


Input

3
101 9901 999999000001


Output

-1


Input

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0


Output

0
#include<bits/stdc++.h>
 using  namespace  std; 
#define int long long 
int32_t  main()
{
 int n, m,s1=0,k=1e18,i,j; cin>>n; 
 int a[n];
 for(i=0;i<n;i++)
 {
  cin>>a[i];if(a[i]==0) s1++;}
 if(s1>0) cout<<"0";
else 
{
  int p=1;bool hi=true;
 for(i=0;i<n;i++)
 { 
  if(p>k/a[i]) {hi=false;break;} p=p*a[i];
}
 if(hi) cout<<p; 
 else cout<<"-1";}
}
