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You are given a non-negative integer d. You have to find two non-negative real numbers a and b such that a + b = d and a ⋅ b = d.

Input

The first line contains t (1 ≤ t ≤ 10^3) — the number of test cases.

Each test case contains one integer d (0 ≤ d ≤ 10^3).

Output

For each test print one line.

If there is an answer for the i-th test, print "Y", and then the numbers a and b.

If there is no answer for the i-th test, print "N".

Your answer will be considered correct if |(a + b) - a ⋅ b| ≤ 10^{-6} and |(a + b) - d| ≤ 10^{-6}.

Example

Input


7
69
0
1
4
5
999
1000


Output


Y 67.985071301 1.014928699
Y 0.000000000 0.000000000
N
Y 2.000000000 2.000000000
Y 3.618033989 1.381966011
Y 997.998996990 1.001003010
Y 998.998997995 1.001002005
from math import sqrt
global valid
def calc(d):

    l = []
    delt = sqrt((d**2)-(4*d))
    x = (d+delt)/2
    l.append(x)
    x = (d-delt)/2
    l.append(x)
    return l

m = int(input())
while m!=0:
    n = int(input())
    if(n>3 or n==0):
        l = calc(n)
        print("Y {0:.9f} {1:.9f}".format(l[0],l[1]))
    else:
        print("N")
    m-=1
