Try guessing the statement from this picture: 

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You are given a non-negative integer d. You have to find two non-negative real numbers a and b such that a + b = d and a ⋅ b = d.

Input

The first line contains t (1 ≤ t ≤ 10^3) — the number of test cases.

Each test case contains one integer d (0 ≤ d ≤ 10^3).

Output

For each test print one line.

If there is an answer for the i-th test, print "Y", and then the numbers a and b.

If there is no answer for the i-th test, print "N".

Your answer will be considered correct if |(a + b) - a ⋅ b| ≤ 10^{-6} and |(a + b) - d| ≤ 10^{-6}.

Example

Input


7
69
0
1
4
5
999
1000


Output


Y 67.985071301 1.014928699
Y 0.000000000 0.000000000
N
Y 2.000000000 2.000000000
Y 3.618033989 1.381966011
Y 997.998996990 1.001003010
Y 998.998997995 1.001002005
import java.util.Scanner;

public class MemeProblem {
    public static void main(String[] args) {
        Scanner s = new Scanner(System.in);
        int t = s.nextInt();
        while(t-- > 0) {
            double d = s.nextDouble();
            double D = d * d - 4 * d;
            double b1 = (d + Math.sqrt(D)) / 2;
            double b2 = (d - Math.sqrt(D)) / 2;
            double a1 = b1 / (b1 - 1);
            double a2 = b2 / (b2 - 1);
            if(a1 >= 0 && b1 >= 0) System.out.println("Y " + b1 + " " + a1);
            else if(a2 >= 0 && b2 >= 0) System.out.println("Y " + b2 + " " + a2);
            else System.out.println("N");
        }
    }
}
