Omkar is building a waterslide in his water park, and he needs your help to ensure that he does it as efficiently as possible.

Omkar currently has n supports arranged in a line, the i-th of which has height a_i. Omkar wants to build his waterslide from the right to the left, so his supports must be nondecreasing in height in order to support the waterslide. In 1 operation, Omkar can do the following: take any contiguous subsegment of supports which is nondecreasing by heights and add 1 to each of their heights. 

Help Omkar find the minimum number of operations he needs to perform to make his supports able to support his waterslide!

An array b is a subsegment of an array c if b can be obtained from c by deletion of several (possibly zero or all) elements from the beginning and several (possibly zero or all) elements from the end.

An array b_1, b_2, ..., b_n is called nondecreasing if b_i≤ b_{i+1} for every i from 1 to n-1.

Input

Each test contains multiple test cases. The first line contains the number of test cases t (1 ≤ t ≤ 100). Description of the test cases follows.

The first line of each test case contains an integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of supports Omkar has.

The second line of each test case contains n integers a_{1},a_{2},...,a_{n} (0 ≤ a_{i} ≤ 10^9) — the heights of the supports.

It is guaranteed that the sum of n over all test cases does not exceed 2 ⋅ 10^5.

Output

For each test case, output a single integer — the minimum number of operations Omkar needs to perform to make his supports able to support his waterslide.

Example

Input


3
4
5 3 2 5
5
1 2 3 5 3
3
1 1 1


Output


3
2
0

Note

The subarray with which Omkar performs the operation is bolded.

In the first test case:

  * First operation:

[5, 3, 2, 5] → [5, 3, 3, 5]

  * Second operation:

[5, 3, 3, 5] → [5, 4, 4, 5]

  * Third operation:

[5, 4, 4, 5] → [5, 5, 5, 5]




In the third test case, the array is already nondecreasing, so Omkar does 0 operations.
#include <bits/stdc++.h>
using namespace std;
struct P {
  int x, y;
  bool operator<(const P &a) const { return x > a.x; };
};
int a, b, c, d, i, n, m, e, k, dx[10] = {1, 0, -1, 0, 1, 1, -1, -1},
                               dy[10] = {0, 1, 0, -1, 1, -1, 1, -1};
int o[222221];
int l[1];
int ss[1];
long long x, y, z, mod = 1000000007, hf = (mod + 1) / 2;
char r[1];
vector<P> v;
P u[1];
queue<int> q;
map<int, int> p;
bool as(P a, P b) { return a.y < b.y; }
int main() {
  int ttt;
  scanf("%d", &ttt);
  for (int tt = 1; tt <= ttt; tt++) {
    scanf("%d", &a);
    stack<int> s;
    x = 0;
    for (int t = 1; t <= a; t++) {
      scanf("%d", &n);
      if (s.size() == 0 || s.top() <= n) {
        for (; s.size() && s.top() <= n; s.pop())
          ;
        s.push(n);
      } else {
        x += s.top() - n;
        s.push(n);
      }
    }
    printf("%lld\n", x);
  }
}
