Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons: 

  * Tetrahedron. Tetrahedron has 4 triangular faces. 
  * Cube. Cube has 6 square faces. 
  * Octahedron. Octahedron has 8 triangular faces. 
  * Dodecahedron. Dodecahedron has 12 pentagonal faces. 
  * Icosahedron. Icosahedron has 20 triangular faces. 



All five kinds of polyhedrons are shown on the picture below:

<image>

Anton has a collection of n polyhedrons. One day he decided to know, how many faces his polyhedrons have in total. Help Anton and find this number!

Input

The first line of the input contains a single integer n (1 ≤ n ≤ 200 000) — the number of polyhedrons in Anton's collection.

Each of the following n lines of the input contains a string si — the name of the i-th polyhedron in Anton's collection. The string can look like this:

  * "Tetrahedron" (without quotes), if the i-th polyhedron in Anton's collection is a tetrahedron. 
  * "Cube" (without quotes), if the i-th polyhedron in Anton's collection is a cube. 
  * "Octahedron" (without quotes), if the i-th polyhedron in Anton's collection is an octahedron. 
  * "Dodecahedron" (without quotes), if the i-th polyhedron in Anton's collection is a dodecahedron. 
  * "Icosahedron" (without quotes), if the i-th polyhedron in Anton's collection is an icosahedron. 

Output

Output one number — the total number of faces in all the polyhedrons in Anton's collection.

Examples

Input

4
Icosahedron
Cube
Tetrahedron
Dodecahedron


Output

42


Input

3
Dodecahedron
Octahedron
Octahedron


Output

28

Note

In the first sample Anton has one icosahedron, one cube, one tetrahedron and one dodecahedron. Icosahedron has 20 faces, cube has 6 faces, tetrahedron has 4 faces and dodecahedron has 12 faces. In total, they have 20 + 6 + 4 + 12 = 42 faces.
# 785A
# θ(n) time
# θ(1) space

__author__ = 'artyom'


# SOLUTION

def main():
    mp = {
        'Icosahedron': 20,
        'Cube': 6,
        'Tetrahedron': 4,
        'Dodecahedron': 12,
        'Octahedron': 8
    }
    s = 0
    for i in range(read()):
        s += mp[read(0)]
    return s


# HELPERS

def read(mode=1, size=None):
    # 0: String
    # 1: Integer
    # 2: List of strings
    # 3: List of integers
    # 4: Matrix of integers
    if mode == 0: return input().strip()
    if mode == 1: return int(input().strip())
    if mode == 2: return input().strip().split()
    if mode == 3: return list(map(int, input().strip().split()))
    a = []
    for _ in range(size):
        a.append(read(3))
    return a


def write(s="\n"):
    if s is None: s = ''
    if isinstance(s, tuple) or isinstance(s, list): s = ' '.join(map(str, s))
    s = str(s)
    print(s, end="\n")


write(main())