Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print `-1` instead.

Constraints

* 2 \leq N \leq 10^5
* 0 \leq A_i \leq 10^{18}
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N
A_1 ... A_N


Output

Print the value A_1 \times ... \times A_N as an integer, or `-1` if the value exceeds 10^{18}.

Examples

Input

2
1000000000 1000000000


Output

1000000000000000000


Input

3
101 9901 999999000001


Output

-1


Input

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0


Output

0
#include <stdio.h>

int main() {
 int t,zero = 0,flag = 0;
 scanf("%d",&t);
 long long int n,max = 1e18,sum = 1;
 	for(int i=0;i<t;i++){
 		scanf("%lld",&n);
 		n>max ? flag = 1 : flag;
		 sum *= n;
		 n==0 ? zero = 1 : max /= n; 
	 }
	 if(zero ==1){
	 	puts("0");
	 }
	 else{
	 	flag==1 ? puts("-1") : printf("%lld\n",sum);
	 }

  return 0;
}