Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print `-1` instead.

Constraints

* 2 \leq N \leq 10^5
* 0 \leq A_i \leq 10^{18}
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N
A_1 ... A_N


Output

Print the value A_1 \times ... \times A_N as an integer, or `-1` if the value exceeds 10^{18}.

Examples

Input

2
1000000000 1000000000


Output

1000000000000000000


Input

3
101 9901 999999000001


Output

-1


Input

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0


Output

0
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.IOException;

public class Main {
  public static void main(String[] args) throws IOException {
    BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
    int n = Integer.parseInt(in.readLine());
    long[] a = new long[n];
    long sum = 1;
    long lastSum = 1;
    boolean over = false;
    String[] str = in.readLine().split(" ");
    for(int i = 0; i < n; i++){
      a[i] = Long.parseLong(str[i]);
      if(a[i]==0) {
        System.out.println(0);
        return;
      }
      sum *= a[i];
      if(lastSum > sum || sum > 1000000000000000000L) {
        over = true;
      }
      lastSum = sum;
    }
    System.out.println(over?-1:sum);
  }
}