There is a polyline going through points (0, 0) – (x, x) – (2x, 0) – (3x, x) – (4x, 0) – ... - (2kx, 0) – (2kx + x, x) – .... 

We know that the polyline passes through the point (a, b). Find minimum positive value x such that it is true or determine that there is no such x.

Input

Only one line containing two positive integers a and b (1 ≤ a, b ≤ 109).

Output

Output the only line containing the answer. Your answer will be considered correct if its relative or absolute error doesn't exceed 10 - 9. If there is no such x then output  - 1 as the answer.

Examples

Input

3 1


Output

1.000000000000


Input

1 3


Output

-1


Input

4 1


Output

1.250000000000

Note

You can see following graphs for sample 1 and sample 3. 

<image> <image>
#include <bits/stdc++.h>
using namespace std;
int main() {
  long long i, j, k, n;
  long long x, y, x1, y1;
  long long m1, m2;
  cin >> x1 >> y1;
  if (x1 < y1) {
    cout << -1 << endl;
    return 0;
  }
  double l1 = x1 + y1, s, e, m;
  s = x1;
  e = y1;
  m1 = l1 / (2 * y1);
  m = m1;
  m = l1 / m;
  printf("%.10lf\n", m / 2);
  return 0;
}
