Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print `-1` instead.

Constraints

* 2 \leq N \leq 10^5
* 0 \leq A_i \leq 10^{18}
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N
A_1 ... A_N


Output

Print the value A_1 \times ... \times A_N as an integer, or `-1` if the value exceeds 10^{18}.

Examples

Input

2
1000000000 1000000000


Output

1000000000000000000


Input

3
101 9901 999999000001


Output

-1


Input

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0


Output

0
import java.math.BigInteger;
import java.util.Scanner;

public class Main {

	static Main instance = new Main();

	public static void main(String[] args) {

		Scanner scan = new Scanner(System.in);

		//入力値取得
		int N = scan.nextInt();

		long[] A = new long[N];

		for (int i = 0; i < N; i++) {
			A[i] = scan.nextLong();
		}

		//WK変数
		BigInteger result = BigInteger.valueOf(1);

		//演算
		for (int i = 0; i < N; i++) {

			if (A[i] == 0L) {
			result = BigInteger.ZERO;
			break;
			}
		}

		for (int i = 0; i < N; i++) {

			result = result.multiply(BigInteger.valueOf(A[i]));

			if (result.compareTo(BigInteger.valueOf(1000000000000000000L)) > 0) {
			result = BigInteger.ONE.negate();
			break;
			}
		}

		//結果出力
			System.out.println(result);
	}
}