You are given an array of n integer numbers a0, a1, ..., an - 1. Find the distance between two closest (nearest) minimums in it. It is guaranteed that in the array a minimum occurs at least two times.

Input

The first line contains positive integer n (2 ≤ n ≤ 105) — size of the given array. The second line contains n integers a0, a1, ..., an - 1 (1 ≤ ai ≤ 109) — elements of the array. It is guaranteed that in the array a minimum occurs at least two times.

Output

Print the only number — distance between two nearest minimums in the array.

Examples

Input

2
3 3


Output

1


Input

3
5 6 5


Output

2


Input

9
2 1 3 5 4 1 2 3 1


Output

3
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.StringTokenizer;
import java.util.ArrayList;
public class Hello{
	public static void main(String[] args)throws IOException
		{

		Scanner sc=new Scanner(System.in);
		int n=sc.nextInt();
		int x[]=new int[n];
		 x[0]=sc.nextInt();
		int min=x[0];


		for(int i=1 ;i<n ; i++){
			x[i]=sc.nextInt();
			if(min>x[i]){
				min=x[i];
				}


			}
			int distance1=1;
			int distance2=0;
			int dis=n;
			int count=0;
			for(int i=0 ; i<n ; i++){
				if(min==x[i]){
					distance1=i+1;
					count++;
					if(distance1-distance2<dis && count>=2){
						dis=distance1-distance2;

						}
						distance2=distance1;
				}



		}
		System.out.println(dis);
		}



		static class Scanner {
		StringTokenizer st;
		BufferedReader br;

		public Scanner(InputStream s) {
			br = new BufferedReader(new InputStreamReader(s));
		}

		public String next() throws IOException {
			while (st == null || !st.hasMoreTokens())
				st = new StringTokenizer(br.readLine());
			return st.nextToken();
		}

		public int nextInt() throws IOException {
			return Integer.parseInt(next());
		}

		public int[] nextIntArr(int n) throws IOException {
			int[] arr = new int[n];
			for (int i = 0; i < n; i++)
				arr[i] = nextInt();
			return arr;
		}

		public long[] nextLongArr(int n) throws IOException {
			long[] arr = new long[n];
			for (int i = 0; i < n; i++)
				arr[i] = nextLong();
			return arr;
		}

		public long nextLong() throws IOException {
			return Long.parseLong(next());
		}

		public String nextLine() throws IOException {
			return br.readLine();
		}

		public double nextDouble() throws IOException {
			return Double.parseDouble(next());
		}

		public boolean ready() throws IOException {
			return br.ready();
		}
	}

}