Given N integers A_1, ..., A_N, compute A_1 \times ... \times A_N.

However, if the result exceeds 10^{18}, print `-1` instead.

Constraints

* 2 \leq N \leq 10^5
* 0 \leq A_i \leq 10^{18}
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N
A_1 ... A_N


Output

Print the value A_1 \times ... \times A_N as an integer, or `-1` if the value exceeds 10^{18}.

Examples

Input

2
1000000000 1000000000


Output

1000000000000000000


Input

3
101 9901 999999000001


Output

-1


Input

31
4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5 0


Output

0
#include<bits/stdc++.h>
#define ll long long
#define ld long double

using namespace std;
int main()
{
  int n;
cin >> n;
ll t;
ld ans = 1;
for (int i = 0; i < n; i++)
{
    cin >> t;
    if (ans != -1)
       ans *= t;
    if (ans > 1000000000000000000 || ans < 0)
       ans = -1;
    if (t == 0)
       ans = 0;
}
cout<<(ll)ans;
return 0;
}

