For a given sequence $A = \\{a_0, a_1, ..., a_{n-1}\\}$ which is sorted by ascending order, find a specific value $k$ given as a query.

Constraints

* $1 \leq n \leq 100,000$
* $1 \leq q \leq 200,000$
* $0 \leq a_0 \leq a_1 \leq ... \leq a_{n-1} \leq 1,000,000,000$
* $0 \leq k_i \leq 1,000,000,000$

Input

The input is given in the following format.


$n$
$a_0 \; a_1 \; ,..., \; a_{n-1}$
$q$
$k_1$
$k_2$
:
$k_q$


The number of elements $n$ and each element $a_i$ are given in the first line and the second line respectively. In the third line, the number of queries $q$ is given and the following $q$ lines, $q$ integers $k_i$ are given as queries.

Output

For each query, print 1 if any element in $A$ is equivalent to $k$, and 0 otherwise.

Example

Input

4
1 2 2 4
3
2
3
5


Output

1
0
0
#include <iostream>
#include <fstream>
#include <algorithm>
#include <vector>
#include <cstring>
//#define LOCAL
using namespace std;
typedef long long ll;
const int mx=1e5+10;
ll a[mx];

void display(ll n, ll num[mx]){
    for(ll i=1;i<=n;i++){
        if(1==i)printf("%lld", num[i]);
        else printf(" %lld", num[i]);
    }
    puts("");
}


int main() {
#ifdef LOCAL
ifstream fin("1.txt");
streambuf*p;
p=cin.rdbuf(fin.rdbuf());
#endif // LOCAL
ll n;
cin>>n;
for(ll i=0;i<n;i++) cin>>a[i];
ll qn;
cin>>qn;
for(ll i=1;i<=qn;i++){
    ll k;
    cin>>k;
    (binary_search(a, a+n, k))?puts("1"):puts("0");
}

#ifdef LOCAL
fin.close();
#endif // LOCAL
}


