A pair of positive integers (a,b) is called special if ⌊ a/b ⌋ = a mod b. Here, ⌊ a/b ⌋ is the result of the integer division between a and b, while a mod b is its remainder.

You are given two integers x and y. Find the number of special pairs (a,b) such that 1≤ a ≤ x and 1 ≤ b ≤ y.

Input

The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases.

The only line of the description of each test case contains two integers x, y (1 ≤ x,y ≤ 10^9).

Output

For each test case print the answer on a single line.

Example

Input


9
3 4
2 100
4 3
50 3
12 4
69 420
12345 6789
123456 789
12345678 9


Output


1
0
2
3
5
141
53384
160909
36

Note

In the first test case, the only special pair is (3, 2).

In the second test case, there are no special pairs.

In the third test case, there are two special pairs: (3, 2) and (4, 3).
#include <bits/stdc++.h>  // This will work only for g++ compiler.


#define for0(i, n) for (int i = 0; i < (int)(n); ++i) // 0 based indexing
#define for1(i, n) for (int i = 1; i <= (int)(n); ++i) // 1 based indexing
#define forc(i, l, r) for (int i = (int)(l); i <= (int)(r); ++i) // closed interver from l to r r inclusive
#define forr0(i, n) for (int i = (int)(n) - 1; i >= 0; --i) // reverse 0 based.
#define forr1(i, n) for (int i = (int)(n); i >= 1; --i) // reverse 1 based

//short hand for usual tokens
#define pb push_back
#define fi first
#define se second

// to be used with algorithms that processes a container Eg: find(all(c),42)
#define all(x) (x).begin(), (x).end() //Forward traversal
#define rall(x) (x).rbegin, (x).rend() //reverse traversal

// find if a given value is present in a container. Container version. Runs in log(n) for set and map
#define present(c,x) ((c).find(x) != (c).end())

// Avoiding wrap around of size()-1 where size is a unsigned int.
#define sz(a) int((a).size())


using namespace std;

// Shorthand for commonly used types
typedef vector<int> vi;
typedef vector<vi> vvi;
typedef pair<int, int> ii;
typedef vector<ii> vii;
typedef long long ll;
typedef vector<ll> vll;
typedef vector<vll> vvll;
typedef double ld;


int main() {
    ios::sync_with_stdio(false);
    cin.tie(0);
    cout.precision(10);
    cout << fixed;

    int tc = 1;
    cin>>tc;
    while(tc--){
		ll x,y;
	    cin>>x>>y;
	
	    if(x<3){
	    	cout<<0<<endl;
	    	continue;
	    }
	    ll ans =0;
	    ans += min(y-1, x-2);
	    for(int i=2; i*i<=x;i++){
	    	ll remainder = i;
	    	ll qui = i;
	    	ll temp = x-remainder;
	    	ll beg = temp/qui;
	    	ll ans_t = max(0LL,min(beg-i, y-i));
	    	ans+=ans_t;
	    }
	    cout<<ans<<endl;
	}

    return 0;
}

