Given is an integer sequence A_1, ..., A_N of length N.

We will choose exactly \left\lfloor \frac{N}{2} \right\rfloor elements from this sequence so that no two adjacent elements are chosen.

Find the maximum possible sum of the chosen elements.

Here \lfloor x \rfloor denotes the greatest integer not greater than x.

Constraints

* 2 \leq N \leq 2\times 10^5
* |A_i|\leq 10^9
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N
A_1 ... A_N


Output

Print the maximum possible sum of the chosen elements.

Examples

Input

6
1 2 3 4 5 6


Output

12


Input

5
-1000 -100 -10 0 10


Output

0


Input

10
1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000


Output

5000000000


Input

27
18 -28 18 28 -45 90 -45 23 -53 60 28 -74 -71 35 -26 -62 49 -77 57 24 -70 -93 69 -99 59 57 -49


Output

295
# 写経AC
from collections import defaultdict

N = int(input())
A = [int(i) for i in input().split()]

# dp[(i, x, flag)]:= i番目まででx個選んでいる時の最大値
# flag: i番目をとるフラグ
dp = defaultdict(lambda: -float("inf"))

# 初期条件
dp[(0, 0, 0)] = 0

for i, a in enumerate(A, 1):
    for x in range((i // 2) - 1, (i + 1) // 2 + 1):
        dp[(i, x, 0)] = max(dp[(i - 1, x, 0)], dp[(i - 1, x, 1)])
        dp[(i, x, 1)] = dp[(i - 1, x - 1, 0)] + a

print(max(dp[(N, N // 2, 0)], dp[(N, N // 2, 1)]))