Recently n students from city S moved to city P to attend a programming camp.

They moved there by train. In the evening, all students in the train decided that they want to drink some tea. Of course, no two people can use the same teapot simultaneously, so the students had to form a queue to get their tea.

i-th student comes to the end of the queue at the beginning of li-th second. If there are multiple students coming to the queue in the same moment, then the student with greater index comes after the student with lesser index. Students in the queue behave as follows: if there is nobody in the queue before the student, then he uses the teapot for exactly one second and leaves the queue with his tea; otherwise the student waits for the people before him to get their tea. If at the beginning of ri-th second student i still cannot get his tea (there is someone before him in the queue), then he leaves the queue without getting any tea. 

For each student determine the second he will use the teapot and get his tea (if he actually gets it).

Input

The first line contains one integer t — the number of test cases to solve (1 ≤ t ≤ 1000).

Then t test cases follow. The first line of each test case contains one integer n (1 ≤ n ≤ 1000) — the number of students.

Then n lines follow. Each line contains two integer li, ri (1 ≤ li ≤ ri ≤ 5000) — the second i-th student comes to the end of the queue, and the second he leaves the queue if he still cannot get his tea.

It is guaranteed that for every <image> condition li - 1 ≤ li holds.

The sum of n over all test cases doesn't exceed 1000.

Note that in hacks you have to set t = 1.

Output

For each test case print n integers. i-th of them must be equal to the second when i-th student gets his tea, or 0 if he leaves without tea.

Example

Input

2
2
1 3
1 4
3
1 5
1 1
2 3


Output

1 2 
1 0 2 

Note

The example contains 2 tests:

  1. During 1-st second, students 1 and 2 come to the queue, and student 1 gets his tea. Student 2 gets his tea during 2-nd second. 
  2. During 1-st second, students 1 and 2 come to the queue, student 1 gets his tea, and student 2 leaves without tea. During 2-nd second, student 3 comes and gets his tea. 
import org.omg.PortableInterceptor.SYSTEM_EXCEPTION;

import java.io.*;
import java.math.*;
import java.util.*;


// author @mdazmat9
public class codeforces{


    public static void main(String[] args) throws IOException {

        Scanner sc = new Scanner(System.in);
        PrintWriter out = new PrintWriter(System.out);
        int test = sc.nextInt();
        for (int ind = 0; ind < test; ind++) {
           int n=sc.nextInt();
            int ans=1;
            String str="";
            for(int i=0;i<n;i++)
            {
                int l=sc.nextInt();
                int r=sc.nextInt();
                if(ans<l)
                    ans=l;
                if(ans<=r)
                {
                    str=str+ans+" ";
                    ans++;
                }
                else
                    str=str+0+" ";

            }

           out.println(str);

        }
        out.flush();
    }

    static long fast_pow(long a, long b) {
        if(b == 0)
            return 1L;

        long val = fast_pow(a, b / 2);

        if(b % 2 == 0)
            return val * val % mod;
        else
            return val * val % mod * a % mod;
    }
    static long mod = (long)1e9 + 7;
    static   void shuffle(int[] a) {
        int n = a.length;
        for(int i = 0; i < n; i++) {
            int r = i + (int) (Math.random() * (n - i));
            int tmp = a[i];
            a[i] = a[r];
            a[r] = tmp;
        }
    }
    static long gcd(long a , long b)
    {
        if(b == 0)
            return a;
        return gcd(b , a % b);
    }

}
class Scanner {
    public BufferedReader reader;
    public StringTokenizer st;

    public Scanner(InputStream stream) {
        reader = new BufferedReader(new InputStreamReader(stream));
        st = null;
    }

    public String next() {
        while (st == null || !st.hasMoreTokens()) {
            try {
                String line = reader.readLine();
                if (line == null) return null;
                st = new StringTokenizer(line);
            } catch (Exception e) {
                throw (new RuntimeException());
            }
        }
        return st.nextToken();
    }

    public int nextInt() {
        return Integer.parseInt(next());
    }

    public long nextLong() {
        return Long.parseLong(next());
    }

    public double nextDouble() {
        return Double.parseDouble(next());
    }
}

class OutputWriter {
    BufferedWriter writer;

    public OutputWriter(OutputStream stream) {
        writer = new BufferedWriter(new OutputStreamWriter(stream));
    }

    public void print(int i) throws IOException {
        writer.write(i);
    }

    public void print(String s) throws IOException {
        writer.write(s);
    }

    public void print(char[] c) throws IOException {
        writer.write(c);
    }

    public void close() throws IOException {
        writer.close();
    }

}
class Pair {
    int x;
    int y;

    // Constructor
    public Pair(int x, int y)
    {
        this.x = x;
        this.y = y;
    }
}
class Compare {

    static void compare(Pair arr[], int n)
    {
        // Comparator to sort the pair according to second element
        Arrays.sort(arr, new Comparator<Pair>() {
            @Override public int compare(Pair p1, Pair p2)
            {
                return p1.x - p2.x;
            }
        });
    }
}

class Graph {

    int V;
    ArrayList<Integer>[] adjListArray;

    // constructor
    Graph(int V) {
        this.V = V;

        adjListArray = new ArrayList[V];

        for (int i = 0; i < V; i++) {
            adjListArray[i] = new ArrayList<>();
        }
    }

    // Adds an edge to an undirected graph
    void addEdge(int src, int dest) {

        adjListArray[src].add(dest);
        adjListArray[dest].add(src);
    }


    ArrayList<Integer> DFSUtil(int u, boolean visited[], int parent,ArrayList<Integer> list)
    {
        // Mark the current node as visited
        visited[u] = true;

        for (int i = 0; i < adjListArray[u].size(); i++) {
            int n = adjListArray[u].get(i);
            list.add(n);

            if (!visited[i]) {
                DFSUtil(n, visited, u,list);
            }
        }
        return list;

    }


    // The function to do DFS traversal. It uses recursive DFSUtil()
    void DFS(int r,int c) {
        // Mark all the vertices as not visited(set as
        // false by default in java)
        boolean visited[] = new boolean[V];
       ArrayList<Integer> list=new ArrayList<>();
        // Call the recursive helper function to print DFS traversal
        boolean bool=true;

    }


    }
