The prison of your city has n prisoners. As the prison can't accommodate all of them, the city mayor has decided to transfer c of the prisoners to a prison located in another city.

For this reason, he made the n prisoners to stand in a line, with a number written on their chests. The number is the severity of the crime he/she has committed. The greater the number, the more severe his/her crime was.

Then, the mayor told you to choose the c prisoners, who will be transferred to the other prison. He also imposed two conditions. They are,

  * The chosen c prisoners has to form a contiguous segment of prisoners. 
  * Any of the chosen prisoner's crime level should not be greater then t. Because, that will make the prisoner a severe criminal and the mayor doesn't want to take the risk of his running away during the transfer. 



Find the number of ways you can choose the c prisoners.

Input

The first line of input will contain three space separated integers n (1 ≤ n ≤ 2·105), t (0 ≤ t ≤ 109) and c (1 ≤ c ≤ n). The next line will contain n space separated integers, the ith integer is the severity ith prisoner's crime. The value of crime severities will be non-negative and will not exceed 109. 

Output

Print a single integer — the number of ways you can choose the c prisoners.

Examples

Input

4 3 3
2 3 1 1


Output

2


Input

1 1 1
2


Output

0


Input

11 4 2
2 2 0 7 3 2 2 4 9 1 4


Output

6
import static java.lang.System.in;
import static java.lang.System.out;

import java.io.*;
import java.util.*;

public class B427 {
	static final double EPS = 1e-10;
	static final double INF = 1 << 31;
	static final double PI = Math.PI;

	public static Scanner sc = new Scanner(in);
	StringBuilder sb = new StringBuilder();
	BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

	public void run() throws IOException {
		String input;
		String[] inputArray;
		input = br.readLine();
		inputArray = input.split(" ");

		int n = Integer.valueOf(inputArray[0]);
		int t = Integer.valueOf(inputArray[1]);
		int c = Integer.valueOf(inputArray[2]);
		input = br.readLine();
		inputArray = input.split(" ");
		int pre=-1;
		int ans = 0;
		for (int i=0; i<n; i++){
			int x = Integer.valueOf(inputArray[i]);
			if (x>t){
				ans+=Math.max(i-pre-c, 0);
				pre=i;
			}
		}
		ans+=Math.max(n-pre-c, 0);
		sb.append(ans);
		ln(sb);
	}

	public static void main(String[] args) throws IOException {
		new B427().run();
	}
	public static void ln(Object obj) {
		out.println(obj);
	}
}
