You are given an array a consisting of n integers. Each a_i is one of the six following numbers: 4, 8, 15, 16, 23, 42.

Your task is to remove the minimum number of elements to make this array good.

An array of length k is called good if k is divisible by 6 and it is possible to split it into k/6 subsequences 4, 8, 15, 16, 23, 42.

Examples of good arrays:

  * [4, 8, 15, 16, 23, 42] (the whole array is a required sequence); 
  * [4, 8, 4, 15, 16, 8, 23, 15, 16, 42, 23, 42] (the first sequence is formed from first, second, fourth, fifth, seventh and tenth elements and the second one is formed from remaining elements); 
  * [] (the empty array is good). 



Examples of bad arrays: 

  * [4, 8, 15, 16, 42, 23] (the order of elements should be exactly 4, 8, 15, 16, 23, 42); 
  * [4, 8, 15, 16, 23, 42, 4] (the length of the array is not divisible by 6); 
  * [4, 8, 15, 16, 23, 42, 4, 8, 15, 16, 23, 23] (the first sequence can be formed from first six elements but the remaining array cannot form the required sequence). 

Input

The first line of the input contains one integer n (1 ≤ n ≤ 5 ⋅ 10^5) — the number of elements in a.

The second line of the input contains n integers a_1, a_2, ..., a_n (each a_i is one of the following numbers: 4, 8, 15, 16, 23, 42), where a_i is the i-th element of a.

Output

Print one integer — the minimum number of elements you have to remove to obtain a good array.

Examples

Input


5
4 8 15 16 23


Output


5


Input


12
4 8 4 15 16 8 23 15 16 42 23 42


Output


0


Input


15
4 8 4 8 15 16 8 16 23 15 16 4 42 23 42


Output


3
n = int(input())
a = [int(i) for i in input().split()]
d = {4: 0, 8: 0, 15: 0, 16: 0, 23: 0, 42: 0}
mi = 1e9
for i in range(n):
    d[a[i]] += 1
    if a[i] == 8:
        if d[8] > d[4]:
            d[8] = d[4]
    elif a[i] == 15:
        if d[15] > d[8]:
            d[15] = d[8]
    elif a[i] == 16:
        if d[16] > d[15]:
            d[16] = d[15]
    elif a[i] == 23:
        if d[23] > d[16]:
            d[23] = d[16]
    elif a[i] == 42:
        if d[42] > d[23]:
            d[42] = d[23]
for x in d:
    mi = min(mi, d[x])
print(n - 6 * mi)