You are given an array a consisting of n integers. Each a_i is one of the six following numbers: 4, 8, 15, 16, 23, 42.

Your task is to remove the minimum number of elements to make this array good.

An array of length k is called good if k is divisible by 6 and it is possible to split it into k/6 subsequences 4, 8, 15, 16, 23, 42.

Examples of good arrays:

  * [4, 8, 15, 16, 23, 42] (the whole array is a required sequence); 
  * [4, 8, 4, 15, 16, 8, 23, 15, 16, 42, 23, 42] (the first sequence is formed from first, second, fourth, fifth, seventh and tenth elements and the second one is formed from remaining elements); 
  * [] (the empty array is good). 



Examples of bad arrays: 

  * [4, 8, 15, 16, 42, 23] (the order of elements should be exactly 4, 8, 15, 16, 23, 42); 
  * [4, 8, 15, 16, 23, 42, 4] (the length of the array is not divisible by 6); 
  * [4, 8, 15, 16, 23, 42, 4, 8, 15, 16, 23, 23] (the first sequence can be formed from first six elements but the remaining array cannot form the required sequence). 

Input

The first line of the input contains one integer n (1 ≤ n ≤ 5 ⋅ 10^5) — the number of elements in a.

The second line of the input contains n integers a_1, a_2, ..., a_n (each a_i is one of the following numbers: 4, 8, 15, 16, 23, 42), where a_i is the i-th element of a.

Output

Print one integer — the minimum number of elements you have to remove to obtain a good array.

Examples

Input


5
4 8 15 16 23


Output


5


Input


12
4 8 4 15 16 8 23 15 16 42 23 42


Output


0


Input


15
4 8 4 8 15 16 8 16 23 15 16 4 42 23 42


Output


3
n = int(input())
l = list(map(int,input().split()))

one = []
two = []
three = []
four = []
five = []
six = []

for i in range(n):
    if l[i] == 4:
        one.append(i)
    elif l[i] == 8:
        two.append(i)
    elif l[i] == 15:
        three.append(i)
    elif l[i] == 16:
        four.append(i)
    elif l[i] == 23:
        five.append(i)
    else:
        six.append(i)

one = one[::-1]
two = two[::-1]
three = three[::-1]
four = four[::-1]
five = five[::-1]
six = six[::-1]

if not one or not two or not three or not four or not five or not six:
    print(n)
    quit()

ans = 0 
while one and two and three and four and five and six:

    if not one:
        break
    
    lst = one[-1]
    one.pop();
    
    while two and two[-1] < lst:
        two.pop()
        
    if not two:
        break

    lst = two[-1]
    two.pop()

    while three and three[-1] < lst:
        three.pop()
    
    if not three:
        break
    
    lst = three[-1]
    three.pop()
    
    while four and four[-1] < lst:
        four.pop()

    if not four:
        break
    lst = four[-1]
    four.pop()
    while five and five[-1] < lst:
        five.pop()

    if not five:
        break

    lst = five[-1]
    five.pop()
    
    while six[-1] < lst:
        six.pop()
    six.pop()
    ans += 1
    if not one or not two or not three or not four or not five or not six:
        break

print(n-6*ans)
    
