You are given an array a consisting of n integer numbers.

You have to color this array in k colors in such a way that: 

  * Each element of the array should be colored in some color; 
  * For each i from 1 to k there should be at least one element colored in the i-th color in the array; 
  * For each i from 1 to k all elements colored in the i-th color should be distinct. 



Obviously, such coloring might be impossible. In this case, print "NO". Otherwise print "YES" and any coloring (i.e. numbers c_1, c_2, ... c_n, where 1 ≤ c_i ≤ k and c_i is the color of the i-th element of the given array) satisfying the conditions above. If there are multiple answers, you can print any.

Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 5000) — the length of the array a and the number of colors, respectively.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 5000) — elements of the array a.

Output

If there is no answer, print "NO". Otherwise print "YES" and any coloring (i.e. numbers c_1, c_2, ... c_n, where 1 ≤ c_i ≤ k and c_i is the color of the i-th element of the given array) satisfying the conditions described in the problem statement. If there are multiple answers, you can print any.

Examples

Input


4 2
1 2 2 3


Output


YES
1 1 2 2


Input


5 2
3 2 1 2 3


Output


YES
2 1 1 2 1


Input


5 2
2 1 1 2 1


Output


NO

Note

In the first example the answer 2~ 1~ 2~ 1 is also acceptable.

In the second example the answer 1~ 1~ 1~ 2~ 2 is also acceptable.

There exist other acceptable answers for both examples.
#prices = map(int, raw_input().rstrip().split())

"""
        try:
            dict[i] += 1
        except:
            dict[i] = 1
"""
#print (" ".join(l))

#from collections import Counter


def f(n,k,a):
    dict = {}
    for i in a:
        try:
            dict[i] += 1
        except:
            dict[i] = 1
    if max(dict.values()) > k:
        print "NO"
    else:
        print "YES"
        l = []
        key = 0
        for d in dict:
            el = dict[d]
            dict[d] = []
            for i in range(el):
                key += 1
                key %= k
                if key == 0:
                    key = k
                dict[d].append(key)
        dovesiamo = {}
        for i in a:
            try:
                dovesiamo[i] += 1
            except:
                dovesiamo[i] = 0
            l.append(str(dict[i][dovesiamo[i]]))
        print (" ".join(l))
            
        
if __name__ == '__main__':
    nk = map(int, raw_input().rstrip().split())
    n = nk[0]
    k = nk[1]
    a = map(int, raw_input().rstrip().split())
    f(n,k,a)