One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.

For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two primes". Let's modify it. How about a statement like that: "each integer no less than 12 can be expressed as the sum of two composite numbers." Not like the Goldbach's conjecture, I can prove this theorem.

You are given an integer n no less than 12, express it as a sum of two composite numbers.

Input

The only line contains an integer n (12 ≤ n ≤ 106).

Output

Output two composite integers x and y (1 < x, y < n) such that x + y = n. If there are multiple solutions, you can output any of them.

Examples

Input

12


Output

4 8


Input

15


Output

6 9


Input

23


Output

8 15


Input

1000000


Output

500000 500000

Note

In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.

In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number.
import java.io.*;
import java.math.BigInteger;
import java.util.*;
import java.util.concurrent.SynchronousQueue;

public class SolveA {
	BufferedReader br;
	StringTokenizer in;
	PrintWriter out;

	public String nextToken() throws IOException {
		while (in == null || !in.hasMoreTokens()) {
			in = new StringTokenizer(br.readLine());
		}
		return in.nextToken();
	}

	public int nextInt() throws IOException {
		return Integer.parseInt(nextToken());
	}

	public double nextDouble() throws IOException {
		return Double.parseDouble(nextToken());
	}

	public long nextLong() throws IOException {
		return Long.parseLong(nextToken());
	}

	public static void main(String[] args) throws IOException {
		new SolveA().run();
	}

	public void solve() throws IOException {
		int n = nextInt();
		boolean[] isPrime = new boolean[n + 1];
		Arrays.fill(isPrime, true);
		for (int i = 2; i <= n; i++) {
			for (int j = 2; 1L * i * j <= n; j++) {
				isPrime[i * j] = false;
			}
		}
		for (int i = 1; i <= n; i++) {
			if (!(isPrime[i] ||isPrime[n - i])) {
				out.println(i + " " + (n - i));
				return;
			}
		}
	}

	public void run() {
		try {
			br = new BufferedReader(new InputStreamReader(System.in)); // new
																		// InputStreamReader(System.in)
			out = new PrintWriter(System.out); // System.out

			solve();

			out.close();
		} catch (IOException e) {
			e.printStackTrace();
			System.exit(1);
		}
	}
}
