You are given N integers A_1, A_2, ..., A_N.

Consider the sums of all non-empty subsequences of A. There are 2^N - 1 such sums, an odd number.

Let the list of these sums in non-decreasing order be S_1, S_2, ..., S_{2^N - 1}.

Find the median of this list, S_{2^{N-1}}.

Constraints

* 1 \leq N \leq 2000
* 1 \leq A_i \leq 2000
* All input values are integers.

Input

Input is given from Standard Input in the following format:


N
A_1 A_2 ... A_N


Output

Print the median of the sorted list of the sums of all non-empty subsequences of A.

Examples

Input

3
1 2 1


Output

2


Input

1
58


Output

58
#include<iostream>
#include<cstdio>
#include<bitset>
using namespace std;
const int N=2000005;
int n,s;
bitset<N>v;
int main()
{
	scanf("%d",&n);
	v[0]=1;
	for(int i=1,x;i<=n;i++)
	{
		scanf("%d",&x);
		s+=x,v|=v<<x;
	}
	for(int i=s/2;;i--)
		if(v[i])
		{
			printf("%d\n",s-i);
			return 0;
		}
	return 0;
}