You are given an array a consisting of n integer numbers.

You have to color this array in k colors in such a way that: 

  * Each element of the array should be colored in some color; 
  * For each i from 1 to k there should be at least one element colored in the i-th color in the array; 
  * For each i from 1 to k all elements colored in the i-th color should be distinct. 



Obviously, such coloring might be impossible. In this case, print "NO". Otherwise print "YES" and any coloring (i.e. numbers c_1, c_2, ... c_n, where 1 ≤ c_i ≤ k and c_i is the color of the i-th element of the given array) satisfying the conditions above. If there are multiple answers, you can print any.

Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 5000) — the length of the array a and the number of colors, respectively.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 5000) — elements of the array a.

Output

If there is no answer, print "NO". Otherwise print "YES" and any coloring (i.e. numbers c_1, c_2, ... c_n, where 1 ≤ c_i ≤ k and c_i is the color of the i-th element of the given array) satisfying the conditions described in the problem statement. If there are multiple answers, you can print any.

Examples

Input


4 2
1 2 2 3


Output


YES
1 1 2 2


Input


5 2
3 2 1 2 3


Output


YES
2 1 1 2 1


Input


5 2
2 1 1 2 1


Output


NO

Note

In the first example the answer 2~ 1~ 2~ 1 is also acceptable.

In the second example the answer 1~ 1~ 1~ 2~ 2 is also acceptable.

There exist other acceptable answers for both examples.
import java.util.*;
import java.io.*;
import java.math.BigInteger;

public class Main {

    public static void main(String[] args) {
        Kattio in = new Kattio(System.in);
        int n = in.nextInt();
        int k = in.nextInt();

        int[] arr = new int[n];
        int[] occ = new int[5050];

        boolean ans = true;
        HashMap<Integer, ArrayList<Integer>> positions = new HashMap<>();
        for (int i = 0; i < n; ++i) {
            arr[i] = in.nextInt();

            ++occ[arr[i]];
            if (occ[arr[i]] > k) {
                ans = false;
            }

            ArrayList<Integer> li = positions.get(arr[i]);
            if (positions.get(arr[i]) == null) {
                li = new ArrayList<>();
                positions.put(arr[i], li);
            }

            li.add(i);
            
        }

        if (ans == false) {
            in.println("NO");
        } else {
            int[] colors = new int[n];
            int cur = 1;
            for (Integer u : positions.keySet()) {
                ArrayList<Integer> li = positions.get(u);
                for (int v : li) {
                    colors[v] = cur++;
                    if (cur > k) cur = 1;
                }
            }


            in.println("YES");
            for (int i = 0; i < n; ++i) {
                in.print(colors[i] + " ");
            }

        }

        in.flush();
        in.close();
    }


}


class Kattio extends PrintWriter {

    private BufferedReader r;
    private String line;
    private StringTokenizer st;
    private String token;
    
    public Kattio(InputStream i) {
        super(new BufferedOutputStream(System.out));
        r = new BufferedReader(new InputStreamReader(i));
    }
    public Kattio(InputStream i, OutputStream o) {
        super(new BufferedOutputStream(o));
        r = new BufferedReader(new InputStreamReader(i));
    }

    public boolean hasNext() {
        return peekToken() != null;
    }

    public int nextInt() {
        return Integer.parseInt(nextToken());
    }

    public double nextDouble() { 
        return Double.parseDouble(nextToken());
    }

    public long nextLong() {
        return Long.parseLong(nextToken());
    }

    public String next() {
        return nextToken();
    }
    
    public String nextLine() {
        token = null;
        st = null;
        try {
            return r.readLine();
        } catch (IOException e) {
            return null;
        }
    }

    private String peekToken() {
        if (token == null) 
            try {
                while (st == null || !st.hasMoreTokens()) {
                    line = r.readLine();
                    if (line == null) return null;
                    st = new StringTokenizer(line);
                }
                token = st.nextToken();
            } catch (IOException e) { }
        return token;
    }

    private String nextToken() {
        String ans = peekToken();
        token = null;
        return ans;
    }
}