The prison of your city has n prisoners. As the prison can't accommodate all of them, the city mayor has decided to transfer c of the prisoners to a prison located in another city.

For this reason, he made the n prisoners to stand in a line, with a number written on their chests. The number is the severity of the crime he/she has committed. The greater the number, the more severe his/her crime was.

Then, the mayor told you to choose the c prisoners, who will be transferred to the other prison. He also imposed two conditions. They are,

  * The chosen c prisoners has to form a contiguous segment of prisoners. 
  * Any of the chosen prisoner's crime level should not be greater then t. Because, that will make the prisoner a severe criminal and the mayor doesn't want to take the risk of his running away during the transfer. 



Find the number of ways you can choose the c prisoners.

Input

The first line of input will contain three space separated integers n (1 ≤ n ≤ 2·105), t (0 ≤ t ≤ 109) and c (1 ≤ c ≤ n). The next line will contain n space separated integers, the ith integer is the severity ith prisoner's crime. The value of crime severities will be non-negative and will not exceed 109. 

Output

Print a single integer — the number of ways you can choose the c prisoners.

Examples

Input

4 3 3
2 3 1 1


Output

2


Input

1 1 1
2


Output

0


Input

11 4 2
2 2 0 7 3 2 2 4 9 1 4


Output

6
import java.io.IOException;

public class B {

	private static final int IN_BUFFER_SIZE = 1 << 16;
	private static final int OUT_BUFFER_SIZE = 1 << 16;
	private byte[] input = new byte[IN_BUFFER_SIZE];
	private int ix = IN_BUFFER_SIZE;
	private int bytesRead = ix;
	private byte[] output = new byte[OUT_BUFFER_SIZE];
	private int ox = 0;

	private void readMore() {
		try {
			bytesRead = System.in.read(input, 0, IN_BUFFER_SIZE);
			if (bytesRead <= 0)
				throw new RuntimeException();
			ix = 0;
		} catch (IOException e) {
			throw new RuntimeException();
		}
	}

	private void flushOut() {
		System.out.write(output, 0, ox);
		ox = 0;
	}

	private void append(char c) {
		if (ox == OUT_BUFFER_SIZE)
			flushOut();
		output[ox++] = (byte) c;
	}

	private int nextInt() {
		skipSpaces();
		int ret = 0;
		if (ix == bytesRead) {
			readMore();
		}
		int sign = 1;
		if (input[ix] == '-') {
			sign = -1;
			ix++;
		}
		while (true) {
			if (ix == bytesRead) {
				try {
					readMore();
				} catch (RuntimeException e) {
					return ret;
				}
			}
			if (input[ix] < '0') {
				break;
			}
			ret *= 10;
			ret += input[ix++] - '0';
		}
		return sign * ret;
	}

	int cntSize;

	private void skipSpaces() {
		while (true) {
			if (ix == bytesRead) {
				readMore();
			}
			if (input[ix] > ' ')
				break;
			ix++;
		}
	}

	private char[] nn = new char[32];

	private void printInt(int n) {
		if (n == 0) {
			append('0');
		} else {
			if (n < 0) {
				append('-');
				n = -n;
			}
			int kk = 0;
			while (n > 0) {
				nn[kk++] = (char) (n % 10 + '0');
				n /= 10;
			}
			for (int i = kk - 1; i >= 0; i--) {
				append(nn[i]);
			}
		}
	}

	int maxVal, bit[];

	public static void main(String[] args) throws IOException {
		new B().work();
	}

	private void work() {
		int n = nextInt();
		int t = nextInt();
		int c = nextInt();
		int[] a = new int[n];
		for (int i = 0; i < n; i++) {
			a[i] = nextInt();
		}
		int bad = 0;
		for (int i = 0; i < c; i++) {
			if (a[i] > t)
				bad++;
		}
		int left = 0;
		int right = c - 1;
		int res = bad > 0 ? 0 : 1;
		while (right + 1 < n) {
			if (a[left++] > t)
				bad--;
			if (a[++right] > t)
				bad++;
			if (bad == 0)
				res++;
		}
		printInt(res);
		append('\n');
		if (ox > 0)
			flushOut();
		System.out.close();
	}
}
