You are given an array a consisting of n integer numbers.

You have to color this array in k colors in such a way that: 

  * Each element of the array should be colored in some color; 
  * For each i from 1 to k there should be at least one element colored in the i-th color in the array; 
  * For each i from 1 to k all elements colored in the i-th color should be distinct. 



Obviously, such coloring might be impossible. In this case, print "NO". Otherwise print "YES" and any coloring (i.e. numbers c_1, c_2, ... c_n, where 1 ≤ c_i ≤ k and c_i is the color of the i-th element of the given array) satisfying the conditions above. If there are multiple answers, you can print any.

Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 5000) — the length of the array a and the number of colors, respectively.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 5000) — elements of the array a.

Output

If there is no answer, print "NO". Otherwise print "YES" and any coloring (i.e. numbers c_1, c_2, ... c_n, where 1 ≤ c_i ≤ k and c_i is the color of the i-th element of the given array) satisfying the conditions described in the problem statement. If there are multiple answers, you can print any.

Examples

Input


4 2
1 2 2 3


Output


YES
1 1 2 2


Input


5 2
3 2 1 2 3


Output


YES
2 1 1 2 1


Input


5 2
2 1 1 2 1


Output


NO

Note

In the first example the answer 2~ 1~ 2~ 1 is also acceptable.

In the second example the answer 1~ 1~ 1~ 2~ 2 is also acceptable.

There exist other acceptable answers for both examples.
N,K=map(int,raw_input().split())
arr=map(int,raw_input().split())

d=dict()
s=list()
n=0
for i in arr:
	try: d[i]+=1
	except:
		d[i]=1
		s.append(i)
		n=n+1
m=0
for i in s:
	if d[i]>m:
		m=d[i]
if N<K  or (m>K):
	print "NO"
else:
	print "YES"
	dc={i:1 for i in s}
	ans=list()
	m1=0
	for i in xrange(N):
		ans.append(str(dc[arr[i]]))
		if dc[arr[i]]>m1: m1=dc[arr[i]]
		dc[arr[i]]+=1
		
	if m1<K:
		j=K-m1
		de={}
		for i in xrange(N):
			if j==0: break
			try:
				de[ans[i]]+=1
				m1=m1+1
				ans[i]=str(m1)
				j=j-1
			except:
				de[ans[i]]=1		
	print " ".join(ans)
