One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.

For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two primes". Let's modify it. How about a statement like that: "each integer no less than 12 can be expressed as the sum of two composite numbers." Not like the Goldbach's conjecture, I can prove this theorem.

You are given an integer n no less than 12, express it as a sum of two composite numbers.

Input

The only line contains an integer n (12 ≤ n ≤ 106).

Output

Output two composite integers x and y (1 < x, y < n) such that x + y = n. If there are multiple solutions, you can output any of them.

Examples

Input

12


Output

4 8


Input

15


Output

6 9


Input

23


Output

8 15


Input

1000000


Output

500000 500000

Note

In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.

In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number.
#include <bits/stdc++.h>
using namespace std;
vector<long long int> vec;
long long int prime[1000000];
void sieve(long long int n) {
  vec.push_back(2);
  for (int i = 3; i * i <= n; i += 2) {
    for (int j = i * i; j <= n; j += (2 * i)) {
      prime[j] = 1;
    }
  }
}
int main() {
  long long int n, ans = 0;
  sieve(1000000);
  cin >> n;
  for (int i = 4; i <= n / 2; i++) {
    long long int a = n - i;
    if ((prime[n - i] == 1 || (n - i) % 2 == 0) &&
        (prime[i] == 1 || i % 2 == 0)) {
      cout << i << " " << n - i << endl;
      break;
    }
  }
  cout << endl;
  return 0;
}
