You have n gifts and you want to give all of them to children. Of course, you don't want to offend anyone, so all gifts should be equal between each other. The i-th gift consists of a_i candies and b_i oranges.

During one move, you can choose some gift 1 ≤ i ≤ n and do one of the following operations:

  * eat exactly one candy from this gift (decrease a_i by one); 
  * eat exactly one orange from this gift (decrease b_i by one); 
  * eat exactly one candy and exactly one orange from this gift (decrease both a_i and b_i by one). 



Of course, you can not eat a candy or orange if it's not present in the gift (so neither a_i nor b_i can become less than zero).

As said above, all gifts should be equal. This means that after some sequence of moves the following two conditions should be satisfied: a_1 = a_2 = ... = a_n and b_1 = b_2 = ... = b_n (and a_i equals b_i is not necessary).

Your task is to find the minimum number of moves required to equalize all the given gifts.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 1000) — the number of test cases. Then t test cases follow.

The first line of the test case contains one integer n (1 ≤ n ≤ 50) — the number of gifts. The second line of the test case contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is the number of candies in the i-th gift. The third line of the test case contains n integers b_1, b_2, ..., b_n (1 ≤ b_i ≤ 10^9), where b_i is the number of oranges in the i-th gift.

Output

For each test case, print one integer: the minimum number of moves required to equalize all the given gifts.

Example

Input


5
3
3 5 6
3 2 3
5
1 2 3 4 5
5 4 3 2 1
3
1 1 1
2 2 2
6
1 1000000000 1000000000 1000000000 1000000000 1000000000
1 1 1 1 1 1
3
10 12 8
7 5 4


Output


6
16
0
4999999995
7

Note

In the first test case of the example, we can perform the following sequence of moves:

  * choose the first gift and eat one orange from it, so a = [3, 5, 6] and b = [2, 2, 3]; 
  * choose the second gift and eat one candy from it, so a = [3, 4, 6] and b = [2, 2, 3]; 
  * choose the second gift and eat one candy from it, so a = [3, 3, 6] and b = [2, 2, 3]; 
  * choose the third gift and eat one candy and one orange from it, so a = [3, 3, 5] and b = [2, 2, 2]; 
  * choose the third gift and eat one candy from it, so a = [3, 3, 4] and b = [2, 2, 2]; 
  * choose the third gift and eat one candy from it, so a = [3, 3, 3] and b = [2, 2, 2]. 
import sys,math,collections
from collections import defaultdict

#from itertools import permutations,combinations
	
def file():
	sys.stdin = open('input.py', 'r')
	sys.stdout = open('output.py', 'w') 
def get_array():
	l=list(map(int, input().split()))
	return l
def get_2_ints():	
	a,b=map(int, input().split())
	return a,b
def get_3_ints():	
	a,b,c=map(int, input().split())
	return a,b,c	
def sod(n):
	n,c=str(n),0
	for i in n:	
		c+=int(i)
	return c	
def isPrime(n):
    if (n <= 1):
        return False
    if (n <= 3):
        return True
    if (n % 2 == 0 or n % 3 == 0):
        return False
    i = 5
    while(i * i <= n):
        if (n % i == 0 or n % (i + 2) == 0):
            return False
        i = i + 6
  
    return True
def getFloor(A, x):

	(left, right) = (0, len(A) - 1)

	floor = -1
	while left <= right:
		mid = (left + right) // 2
		if A[mid] == x:
			return A[mid]
		elif x < A[mid]:
			right = mid - 1
		else:
			floor = A[mid]
			left = mid + 1
			
	return floor
def floorSqrt(x) : 
  
    # Base cases 
    if (x == 0 or x == 1) : 
        return x 
   
    # Do Binary Search for floor(sqrt(x)) 
    start = 1
    end = x    
    while (start <= end) : 
        mid = (start + end) // 2
          
        # If x is a perfect square 
        if (mid*mid == x) : 
            return mid 
              
        # Since we need floor, we update  
        # answer when mid*mid is smaller 
        # than x, and move closer to sqrt(x) 
        if (mid * mid < x) : 
            start = mid + 1
            ans = mid 
              
        else : 
              
            # If mid*mid is greater than x 
            end = mid-1
              
    return ans	
#file()
def main():
	for tt in range(int(input())):
		n=int(input())
		a=get_array()
		b=get_array()
		p,q=min(a),min(b)
		c=0
		for i in range(n):
			if(a[i]==p and b[i]!=q):
				c+=(b[i]-q)
			elif(a[i]!=p and b[i]==q):
				c+=(a[i]-p)
			elif(a[i]==p and b[i]==q):
				continue
			else:
				temp=min(a[i]-p,b[i]-q)
				c+=temp
				a[i]-=temp
				b[i]-=temp
				c+=(a[i]-p)
				c+=(b[i]-q)
		print(c)		

			



	





		


	


























	

	
	

		











		
		

		























































				

			







            
			
































		








if __name__ == '__main__':
    main()