You are given an array a consisting of n integer numbers.

You have to color this array in k colors in such a way that: 

  * Each element of the array should be colored in some color; 
  * For each i from 1 to k there should be at least one element colored in the i-th color in the array; 
  * For each i from 1 to k all elements colored in the i-th color should be distinct. 



Obviously, such coloring might be impossible. In this case, print "NO". Otherwise print "YES" and any coloring (i.e. numbers c_1, c_2, ... c_n, where 1 ≤ c_i ≤ k and c_i is the color of the i-th element of the given array) satisfying the conditions above. If there are multiple answers, you can print any.

Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 5000) — the length of the array a and the number of colors, respectively.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 5000) — elements of the array a.

Output

If there is no answer, print "NO". Otherwise print "YES" and any coloring (i.e. numbers c_1, c_2, ... c_n, where 1 ≤ c_i ≤ k and c_i is the color of the i-th element of the given array) satisfying the conditions described in the problem statement. If there are multiple answers, you can print any.

Examples

Input


4 2
1 2 2 3


Output


YES
1 1 2 2


Input


5 2
3 2 1 2 3


Output


YES
2 1 1 2 1


Input


5 2
2 1 1 2 1


Output


NO

Note

In the first example the answer 2~ 1~ 2~ 1 is also acceptable.

In the second example the answer 1~ 1~ 1~ 2~ 2 is also acceptable.

There exist other acceptable answers for both examples.
#include <bits/stdc++.h>
using namespace std;
inline void file() {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  cout.tie(NULL);
  if (0) {
    freopen(".in", "r", stdin);
    freopen(".out", "w", stdout);
  }
}
const int PX[8] = {1, 0, -1, 0, 1, 1, -1, -1},
          PY[8] = {0, 1, 0, -1, -1, 1, 1, -1}, N = 5010, INF = 1e9,
          MOD = 1e9 + 7;
const long long INFL = 1e18, MODL = 1e9 + 7;
const long double EPS = 1e-6;
template <typename type>
inline void up(type& a, type b) {
  if (a < b) a = b;
}
inline long long rnd(long long l = 1, long long r = INFL) {
  unsigned long long ans = rand();
  ans = (ans << 16LL) ^ rand();
  ans = (ans << 16LL) ^ rand();
  ans = (ans << 16LL) ^ rand();
  ans %= r - l + 1;
  return (long long)ans + l;
}
int n, k, a[N], ans[N];
map<int, set<int>> v;
inline void setCol(int pos, int c) {
  v[a[pos]].erase(pos);
  if (v[a[pos]].empty()) v.erase(a[pos]);
  ans[pos] = c + 1;
}
int main() {
  file();
  cin >> n >> k;
  for (int i = 0; i < n; ++i) {
    cin >> a[i];
    v[a[i]].insert(i);
  }
  for (int i = 0; i < N; ++i)
    if (v.count(i) && v[i].size() > k) {
      cout << "NO\n";
      return 0;
    }
  for (int i = 0; i < k; ++i) setCol(i, i);
  for (int i = 0; i < k; ++i)
    for (int j = 0; j < N; ++j)
      if (j != a[i] && v.count(j)) setCol(*v[j].begin(), i);
  cout << "YES\n";
  for (int i = 0; i < n; ++i) cout << ans[i] << ' ';
}
