You are given N integers A_1, A_2, ..., A_N.

Consider the sums of all non-empty subsequences of A. There are 2^N - 1 such sums, an odd number.

Let the list of these sums in non-decreasing order be S_1, S_2, ..., S_{2^N - 1}.

Find the median of this list, S_{2^{N-1}}.

Constraints

* 1 \leq N \leq 2000
* 1 \leq A_i \leq 2000
* All input values are integers.

Input

Input is given from Standard Input in the following format:


N
A_1 A_2 ... A_N


Output

Print the median of the sorted list of the sums of all non-empty subsequences of A.

Examples

Input

3
1 2 1


Output

2


Input

1
58


Output

58
#include <stdio.h>
#include <stdlib.h>
#include <bitset>
using namespace std;
 
int n, sum;
 
bitset<4000005> B;
 
int main() {
	int i, x; 
	scanf("%d", &n);
	B[0]=1;
	for(i = 1; i <= n; ++i) {
		scanf("%d", &x); sum += x;
		B |= B<<x;
	}
	for(i = sum/2+sum%2; !B[i]; ++i);
	printf("%d\n", i);
}