You are given an array a consisting of n integer numbers.

You have to color this array in k colors in such a way that: 

  * Each element of the array should be colored in some color; 
  * For each i from 1 to k there should be at least one element colored in the i-th color in the array; 
  * For each i from 1 to k all elements colored in the i-th color should be distinct. 



Obviously, such coloring might be impossible. In this case, print "NO". Otherwise print "YES" and any coloring (i.e. numbers c_1, c_2, ... c_n, where 1 ≤ c_i ≤ k and c_i is the color of the i-th element of the given array) satisfying the conditions above. If there are multiple answers, you can print any.

Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 5000) — the length of the array a and the number of colors, respectively.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 5000) — elements of the array a.

Output

If there is no answer, print "NO". Otherwise print "YES" and any coloring (i.e. numbers c_1, c_2, ... c_n, where 1 ≤ c_i ≤ k and c_i is the color of the i-th element of the given array) satisfying the conditions described in the problem statement. If there are multiple answers, you can print any.

Examples

Input


4 2
1 2 2 3


Output


YES
1 1 2 2


Input


5 2
3 2 1 2 3


Output


YES
2 1 1 2 1


Input


5 2
2 1 1 2 1


Output


NO

Note

In the first example the answer 2~ 1~ 2~ 1 is also acceptable.

In the second example the answer 1~ 1~ 1~ 2~ 2 is also acceptable.

There exist other acceptable answers for both examples.
def fun(n,k,arr):
    arrd={}
    if(k>n):
        return "0"
    for i in range(len(arr)):
        if arr[i] in arrd.keys():
            temp = arrd[arr[i]]
            temp.append(i)
            arrd[arr[i]]=temp
        else:
            arrd[arr[i]]=[i]
    color = 1
    res = [0 for i in range(n)]
    for item in arrd.keys():
        temp = arrd[item]
        if(len(temp)>k):
            return []
        for i in range(len(temp)):
            res[temp[i]]=color
            color = color + 1
            if(color > k):
                color = 1
    
    return res

n,k = list(map(int,input().split(" ")))
arr = list(map(int,input().split(" ")))
res = fun(n,k,arr)
if(len(res) == 0):
    print("NO")
else:
    print("YES")
    print(' '.join(str(i) for i in res))

	  			 		 	   			 		 									