You've gotten an n × m sheet of squared paper. Some of its squares are painted. Let's mark the set of all painted squares as A. Set A is connected. Your task is to find the minimum number of squares that we can delete from set A to make it not connected.

A set of painted squares is called connected, if for every two squares a and b from this set there is a sequence of squares from the set, beginning in a and ending in b, such that in this sequence any square, except for the last one, shares a common side with the square that follows next in the sequence. An empty set and a set consisting of exactly one square are connected by definition.

Input

The first input line contains two space-separated integers n and m (1 ≤ n, m ≤ 50) — the sizes of the sheet of paper. 

Each of the next n lines contains m characters — the description of the sheet of paper: the j-th character of the i-th line equals either "#", if the corresponding square is painted (belongs to set A), or equals "." if the corresponding square is not painted (does not belong to set A). It is guaranteed that the set of all painted squares A is connected and isn't empty.

Output

On the first line print the minimum number of squares that need to be deleted to make set A not connected. If it is impossible, print -1. 

Examples

Input

5 4
####
#..#
#..#
#..#
####


Output

2


Input

5 5
#####
#...#
#####
#...#
#####


Output

2

Note

In the first sample you can delete any two squares that do not share a side. After that the set of painted squares is not connected anymore.

The note to the second sample is shown on the figure below. To the left there is a picture of the initial set of squares. To the right there is a set with deleted squares. The deleted squares are marked with crosses. 

<image>
/*	/ ﾌﾌ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ム
	/ )\⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀  Y
	(⠀⠀| ( ͡° ͜ʖ ͡°）⠀⌒(⠀ ノ
	(⠀ ﾉ⌒ Y ⌒ヽ-く __／
	| _⠀｡ノ| ノ｡ |/
	(⠀ー '_人`ー ﾉ
	⠀|\ ￣ _人'彡ﾉ
	⠀ )\⠀⠀ ｡⠀⠀ /
	⠀⠀(\⠀ #⠀ /
	⠀/⠀⠀⠀/ὣ====================D-
	/⠀⠀⠀/⠀ \ \⠀⠀\
	( (⠀)⠀⠀⠀⠀ ) ).⠀)
	(⠀⠀)⠀⠀⠀⠀⠀( | /
	|⠀ /⠀⠀⠀⠀⠀⠀ | /
	[_] ⠀⠀⠀⠀⠀[___]                     */
// Main Code at the Bottom
import java.util.*;
import java.lang.*;
import java.io.*;
import java.math.BigInteger; 
public class Main {
	//Fast IO class
    static class FastReader {
        BufferedReader br; 
        StringTokenizer st; 
        public FastReader() {
        	boolean env=System.getProperty("ONLINE_JUDGE") != null;
        	if(!env) {
        		try {
					br=new BufferedReader(new FileReader("src\\input.txt"));
				} catch (FileNotFoundException e) {
					e.printStackTrace();
				}
        	}
        	else br = new BufferedReader(new InputStreamReader(System.in)); 
        } 
        String next() {
            while (st == null || !st.hasMoreElements()) {
                try {
                    st = new StringTokenizer(br.readLine()); 
                } 
                catch (IOException  e) {
                    e.printStackTrace(); 
                } 
            } 
            return st.nextToken(); 
        } 
        int nextInt() {
            return Integer.parseInt(next()); 
        } 
        long nextLong() {
            return Long.parseLong(next()); 
        } 
        double nextDouble() {
            return Double.parseDouble(next()); 
        } 
        String nextLine() {
            String str = ""; 
            try {
                str = br.readLine(); 
            } 
            catch (IOException e) {
                e.printStackTrace(); 
            } 
            return str; 
        } 
    }     
    static long MOD=1000000000+7;
    //Euclidean Algorithm
    static long gcd(long A,long B){
    	return (B==0)?A:gcd(B,A%B);
    }
    //Modular Exponentiation
    static long fastExpo(long x,long n){
        if(n==0) return 1;
        if((n&1)==0) return fastExpo((x*x)%MOD,n/2)%MOD;
        return ((x%MOD)*fastExpo((x*x)%MOD,(n-1)/2))%MOD;
    }
    //Modular Inverse
    static long inverse(long x) {
    	return fastExpo(x,MOD-2);
    }
    //Prime Number Algorithm
    static boolean isPrime(long n){
        if(n<=1) return false;
        if(n<=3) return true;
        if(n%2==0 || n%3==0) return false;
        for(int i=5;i*i<=n;i+=6) if(n%i==0 || n%(i+2)==0) return false;
        return true;
    }
    //Reverse an array
    static void reverse(int arr[],int l,int r){
    	while(l<r) {
    		int tmp=arr[l];
    		arr[l++]=arr[r];
    		arr[r--]=tmp;
    	}
    }
    //Print array
    static void print1d(int arr[]) {
    	out.println(Arrays.toString(arr));
    }
    static void print2d(int arr[][]) {
    	for(int a[]: arr) out.println(Arrays.toString(a));
    }
    // Pair
    static class pair{
    	int x,y;
    	pair(int a,int b){
    		this.x=a;
    		this.y=b;
    	}
    	public boolean equals(Object obj) {
    		if(obj == null || obj.getClass()!= this.getClass()) return false;
            pair p = (pair) obj;
            return (this.x==p.x && this.y==p.y);
        }
    	public int hashCode() {
            return Objects.hash(x,y);
        }
    }
    static FastReader sc=new FastReader();
    static PrintWriter out=new PrintWriter(System.out);  
    //Main function(The main code starts from here)
    static char graph[][];
    static int visited[][],n,m;
    static void dfs(int i,int j) {
    	if(i>=n || i<0 || j>=m || j<0 || visited[i][j]==1 || graph[i][j]=='.') return;
    	visited[i][j]=1;
    	dfs(i+1,j);
    	dfs(i-1,j);
    	dfs(i,j+1);
    	dfs(i,j-1);
    }
    public static void main (String[] args) throws java.lang.Exception {
    	int test;
    	test=1;
    	//test=sc.nextInt();
    	while(test-->0){	
    		n=sc.nextInt();m=sc.nextInt();
    		graph=new char[n][m];
    		for(int i=0;i<n;i++) graph[i]=sc.nextLine().toCharArray();
    		int ans=-1;
    		for(int i=0;i<n;i++) {
    			for(int j=0;j<m;j++) {
    				if(graph[i][j]=='.') continue;
    				graph[i][j]='.';
    				visited=new int[n][m];
    				ArrayList<pair> arr=new ArrayList<>();
    				if(i+1<n && graph[i+1][j]=='#') arr.add(new pair(i+1,j));
    				if(i-1>=0 && graph[i-1][j]=='#') arr.add(new pair(i-1,j));
    				if(j+1<m && graph[i][j+1]=='#') arr.add(new pair(i,j+1));
    				if(j-1>=0 && graph[i][j-1]=='#') arr.add(new pair(i,j-1));
    				int N=arr.size();
    				if(N<2) {
    					graph[i][j]='#';
    					continue;
    				}
    				ans=2;
    				int flag=0;
    				dfs(arr.get(0).x,arr.get(0).y);
    				for(int k=1;k<N;k++) {
    					if(visited[arr.get(k).x][arr.get(k).y]!=1) {
    						flag=1;
    						break;
    					}
    				}
    				if(flag==1) {
    					System.out.println(1);
    					return;
    				}
    				graph[i][j]='#';
    			}
    		}
    		out.println(ans);
    	} 	
        out.flush();
        out.close();
    }
}