You are given an array a consisting of n integer numbers.

You have to color this array in k colors in such a way that: 

  * Each element of the array should be colored in some color; 
  * For each i from 1 to k there should be at least one element colored in the i-th color in the array; 
  * For each i from 1 to k all elements colored in the i-th color should be distinct. 



Obviously, such coloring might be impossible. In this case, print "NO". Otherwise print "YES" and any coloring (i.e. numbers c_1, c_2, ... c_n, where 1 ≤ c_i ≤ k and c_i is the color of the i-th element of the given array) satisfying the conditions above. If there are multiple answers, you can print any.

Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 5000) — the length of the array a and the number of colors, respectively.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 5000) — elements of the array a.

Output

If there is no answer, print "NO". Otherwise print "YES" and any coloring (i.e. numbers c_1, c_2, ... c_n, where 1 ≤ c_i ≤ k and c_i is the color of the i-th element of the given array) satisfying the conditions described in the problem statement. If there are multiple answers, you can print any.

Examples

Input


4 2
1 2 2 3


Output


YES
1 1 2 2


Input


5 2
3 2 1 2 3


Output


YES
2 1 1 2 1


Input


5 2
2 1 1 2 1


Output


NO

Note

In the first example the answer 2~ 1~ 2~ 1 is also acceptable.

In the second example the answer 1~ 1~ 1~ 2~ 2 is also acceptable.

There exist other acceptable answers for both examples.
line = input().split(" ")
n,k = int(line[0]), int(line[1])
a = [int(i) for i in input().split(" ")]
# s = set()
m = {}
for num in a:
    # s.add(num)
    if num not in m.keys():
        m[num] = 1
    else:
        m[num] += 1

flag = True
if len(a) < k:
    print("NO")
else:
    for i in m.keys():
        if m[i] > k:
            print("NO")
            flag = False
            break
    if flag:
        print("YES")
        m1 = {}
        idx = 0
        res = ""
        for i in range(k):
            m1[i] = set()
        for num in a:
            idx = idx%k
            while num in m1[idx]:
                # print(m1)
                # print(k)

                idx += 1
                idx = idx % k
            m1[idx].add(num)
            res = res + " " + str(idx+1)
            idx += 1
        print(res.strip())

 	 		 	 		 	    	  		 					  		