Let's introduce some definitions that will be needed later.

Let prime(x) be the set of prime divisors of x. For example, prime(140) = \{ 2, 5, 7 \}, prime(169) = \{ 13 \}.

Let g(x, p) be the maximum possible integer p^k where k is an integer such that x is divisible by p^k. For example:

  * g(45, 3) = 9 (45 is divisible by 3^2=9 but not divisible by 3^3=27), 
  * g(63, 7) = 7 (63 is divisible by 7^1=7 but not divisible by 7^2=49). 



Let f(x, y) be the product of g(y, p) for all p in prime(x). For example:

  * f(30, 70) = g(70, 2) ⋅ g(70, 3) ⋅ g(70, 5) = 2^1 ⋅ 3^0 ⋅ 5^1 = 10, 
  * f(525, 63) = g(63, 3) ⋅ g(63, 5) ⋅ g(63, 7) = 3^2 ⋅ 5^0 ⋅ 7^1 = 63. 



You have integers x and n. Calculate f(x, 1) ⋅ f(x, 2) ⋅ … ⋅ f(x, n) mod{(10^{9} + 7)}.

Input

The only line contains integers x and n (2 ≤ x ≤ 10^{9}, 1 ≤ n ≤ 10^{18}) — the numbers used in formula.

Output

Print the answer.

Examples

Input


10 2


Output


2


Input


20190929 1605


Output


363165664


Input


947 987654321987654321


Output


593574252

Note

In the first example, f(10, 1) = g(1, 2) ⋅ g(1, 5) = 1, f(10, 2) = g(2, 2) ⋅ g(2, 5) = 2.

In the second example, actual value of formula is approximately 1.597 ⋅ 10^{171}. Make sure you print the answer modulo (10^{9} + 7).

In the third example, be careful about overflow issue.
import math

X, N = map(int, input().split())

def prime(n):
    factor = {}
    tmp = int(math.sqrt(n)) + 1
    for num in range(2, tmp):
        while n % num == 0:
            n //= num
            if not num in factor.keys():
                factor[num] = 1
            else:
                factor[num] += 1
    if n != 1:
        if not n in factor.keys():
            factor[n] = 1
        else:
            factor[n] += 1
    return factor

def power_func(a,n,p):
    bi=str(format(n,"b"))#2進表現に
    res=1
    for i in range(len(bi)):
        res=(res*res) %p
        if bi[i]=="1":
            res=(res*a) %p
    return res

def main():
    NUM = {}
    for num in prime(X).keys():
        a = N
        c = 0
        while a > 0:
            a //= num
            c += a
        NUM[num] = c

    mod = int(1E9+7)
    ans = 1
    for num, c in NUM.items():
        ans = (ans * power_func(num, c, mod)) % mod

    print(ans)

if __name__ == "__main__":
    main()