You have n gifts and you want to give all of them to children. Of course, you don't want to offend anyone, so all gifts should be equal between each other. The i-th gift consists of a_i candies and b_i oranges.

During one move, you can choose some gift 1 ≤ i ≤ n and do one of the following operations:

  * eat exactly one candy from this gift (decrease a_i by one); 
  * eat exactly one orange from this gift (decrease b_i by one); 
  * eat exactly one candy and exactly one orange from this gift (decrease both a_i and b_i by one). 



Of course, you can not eat a candy or orange if it's not present in the gift (so neither a_i nor b_i can become less than zero).

As said above, all gifts should be equal. This means that after some sequence of moves the following two conditions should be satisfied: a_1 = a_2 = ... = a_n and b_1 = b_2 = ... = b_n (and a_i equals b_i is not necessary).

Your task is to find the minimum number of moves required to equalize all the given gifts.

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 1000) — the number of test cases. Then t test cases follow.

The first line of the test case contains one integer n (1 ≤ n ≤ 50) — the number of gifts. The second line of the test case contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9), where a_i is the number of candies in the i-th gift. The third line of the test case contains n integers b_1, b_2, ..., b_n (1 ≤ b_i ≤ 10^9), where b_i is the number of oranges in the i-th gift.

Output

For each test case, print one integer: the minimum number of moves required to equalize all the given gifts.

Example

Input


5
3
3 5 6
3 2 3
5
1 2 3 4 5
5 4 3 2 1
3
1 1 1
2 2 2
6
1 1000000000 1000000000 1000000000 1000000000 1000000000
1 1 1 1 1 1
3
10 12 8
7 5 4


Output


6
16
0
4999999995
7

Note

In the first test case of the example, we can perform the following sequence of moves:

  * choose the first gift and eat one orange from it, so a = [3, 5, 6] and b = [2, 2, 3]; 
  * choose the second gift and eat one candy from it, so a = [3, 4, 6] and b = [2, 2, 3]; 
  * choose the second gift and eat one candy from it, so a = [3, 3, 6] and b = [2, 2, 3]; 
  * choose the third gift and eat one candy and one orange from it, so a = [3, 3, 5] and b = [2, 2, 2]; 
  * choose the third gift and eat one candy from it, so a = [3, 3, 4] and b = [2, 2, 2]; 
  * choose the third gift and eat one candy from it, so a = [3, 3, 3] and b = [2, 2, 2]. 
'''input
5
3
3 5 6
3 2 3
5
1 2 3 4 5
5 4 3 2 1
3
1 1 1
2 2 2
6
1 1000000000 1000000000 1000000000 1000000000 1000000000
1 1 1 1 1 1
3
10 12 8
7 5 4
'''

import math
import sys
import itertools
import random
import bisect
import heapq
import collections

def lcm(x, y):
	return (x*y)//math.gcd(x,y)
def hcf(x, y):
	return math.gcd(x, y)
def primes(n):
	prime=[True for _ in range(0, n+1)]
	res=[]
	p=2
	while p*p<=n:
		if prime[p]==True:
			for i in range(p*p,n+1,p):
				prime[p]=False
		p+=1
	for i in range(0, n+1):
		if prime[i]==True:
			res.append(i)
	return res
def primeFactors(n):
	res=[]
	while n%2==0:
		res.append(2)
		n//=2
	for i in range(3, math.sqrt(n)+1, 2):
		while n%i==0:
			res.append(i)
			n//=i
	if n>2:
		res.append(n)
	return res


for _ in range(0, int(input())):
	n=int(input())                                 # Single Digit Input
	# x, y, z = map(int, input().strip().split())    # Many Digit Input
	c=list(map(int, input().strip().split()))      # List Input
	o=list(map(int, input().strip().split()))      # List Input
	# s=list(input())                                # Character Array Input

	min_c = min(c)
	min_o = min(o)

	res = 0

	for i in range(0, n):
		excess_from_candy_min = c[i]-min_c
		excess_from_orange_min = o[i]-min_o

		tem = min(excess_from_candy_min, excess_from_orange_min)
		res+=tem
		excess_from_orange_min-=tem
		excess_from_candy_min-=tem

		res+=max(excess_from_candy_min, excess_from_orange_min)
	print(res)