You are given an array a consisting of n integer numbers.

You have to color this array in k colors in such a way that: 

  * Each element of the array should be colored in some color; 
  * For each i from 1 to k there should be at least one element colored in the i-th color in the array; 
  * For each i from 1 to k all elements colored in the i-th color should be distinct. 



Obviously, such coloring might be impossible. In this case, print "NO". Otherwise print "YES" and any coloring (i.e. numbers c_1, c_2, ... c_n, where 1 ≤ c_i ≤ k and c_i is the color of the i-th element of the given array) satisfying the conditions above. If there are multiple answers, you can print any.

Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 5000) — the length of the array a and the number of colors, respectively.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 5000) — elements of the array a.

Output

If there is no answer, print "NO". Otherwise print "YES" and any coloring (i.e. numbers c_1, c_2, ... c_n, where 1 ≤ c_i ≤ k and c_i is the color of the i-th element of the given array) satisfying the conditions described in the problem statement. If there are multiple answers, you can print any.

Examples

Input


4 2
1 2 2 3


Output


YES
1 1 2 2


Input


5 2
3 2 1 2 3


Output


YES
2 1 1 2 1


Input


5 2
2 1 1 2 1


Output


NO

Note

In the first example the answer 2~ 1~ 2~ 1 is also acceptable.

In the second example the answer 1~ 1~ 1~ 2~ 2 is also acceptable.

There exist other acceptable answers for both examples.
# n=int(input())
# arr=list(map(int,input().strip().split(' ')))
# arr=input().strip().split(' ')

def getNext(count):
    global k
    if count==k:
        count=1
        return count
    else:
        count+=1
        return count

n,k=map(int,input().strip().split(' '))
arr=list(map(int,input().strip().split(' ')))
dic=dict()
curs=dict()
cur=0
ans=[]
for i in arr[:k]:
    dic.setdefault(i, 0)
    dic[i] = dic[i] + 1
for key,v in dic.items():
    curs[key]=cur
    cur+=v
for index,i in enumerate(arr):
    # cur=getNext(cur)
    if index>=k:
        dic.setdefault(i,0)
        dic[i]=dic[i]+1
    curs.setdefault(i,0)
    curs[i]=getNext(curs[i])
    ans.append(str(curs[i]))
    if dic[i]>k:
        print("NO")
        quit()
print("YES")
print(" ".join(ans))











   	 	    		 	 	 	   				   		