You are given an array a consisting of n integer numbers.

You have to color this array in k colors in such a way that: 

  * Each element of the array should be colored in some color; 
  * For each i from 1 to k there should be at least one element colored in the i-th color in the array; 
  * For each i from 1 to k all elements colored in the i-th color should be distinct. 



Obviously, such coloring might be impossible. In this case, print "NO". Otherwise print "YES" and any coloring (i.e. numbers c_1, c_2, ... c_n, where 1 ≤ c_i ≤ k and c_i is the color of the i-th element of the given array) satisfying the conditions above. If there are multiple answers, you can print any.

Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 5000) — the length of the array a and the number of colors, respectively.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 5000) — elements of the array a.

Output

If there is no answer, print "NO". Otherwise print "YES" and any coloring (i.e. numbers c_1, c_2, ... c_n, where 1 ≤ c_i ≤ k and c_i is the color of the i-th element of the given array) satisfying the conditions described in the problem statement. If there are multiple answers, you can print any.

Examples

Input


4 2
1 2 2 3


Output


YES
1 1 2 2


Input


5 2
3 2 1 2 3


Output


YES
2 1 1 2 1


Input


5 2
2 1 1 2 1


Output


NO

Note

In the first example the answer 2~ 1~ 2~ 1 is also acceptable.

In the second example the answer 1~ 1~ 1~ 2~ 2 is also acceptable.

There exist other acceptable answers for both examples.
ar = input()   # takes the whole line of n numbers
ll = list(map(int,ar.split(' ')))

n=ll[0]
k=ll[1]

arr = input()   # takes the whole line of n numbers
l = list(map(int,arr.split(' ')))
l1=list()

for i in range(n):
	l1.append((i,l[i]))

flag=0
c=0

l1.sort(key=lambda x:x[1])  
l2=list()

if(n<k):
	flag=1
else:
	for it in range(n):
		i=l1[it][1]
		if(l.count(i)>k):
			flag=1
			break
		else:
			l2.append(((l1[it][0]),c))
			c=(c+1)%k

if(flag==1)	:
	print("NO")
else:
	l2.sort(key=lambda x:x[0]) 
	print("YES") 
	for i in l2:
		print(i[1]+1, end=" ")