You are given an array a consisting of n integer numbers.

You have to color this array in k colors in such a way that: 

  * Each element of the array should be colored in some color; 
  * For each i from 1 to k there should be at least one element colored in the i-th color in the array; 
  * For each i from 1 to k all elements colored in the i-th color should be distinct. 



Obviously, such coloring might be impossible. In this case, print "NO". Otherwise print "YES" and any coloring (i.e. numbers c_1, c_2, ... c_n, where 1 ≤ c_i ≤ k and c_i is the color of the i-th element of the given array) satisfying the conditions above. If there are multiple answers, you can print any.

Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 5000) — the length of the array a and the number of colors, respectively.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 5000) — elements of the array a.

Output

If there is no answer, print "NO". Otherwise print "YES" and any coloring (i.e. numbers c_1, c_2, ... c_n, where 1 ≤ c_i ≤ k and c_i is the color of the i-th element of the given array) satisfying the conditions described in the problem statement. If there are multiple answers, you can print any.

Examples

Input


4 2
1 2 2 3


Output


YES
1 1 2 2


Input


5 2
3 2 1 2 3


Output


YES
2 1 1 2 1


Input


5 2
2 1 1 2 1


Output


NO

Note

In the first example the answer 2~ 1~ 2~ 1 is also acceptable.

In the second example the answer 1~ 1~ 1~ 2~ 2 is also acceptable.

There exist other acceptable answers for both examples.
from collections import defaultdict,Counter
n,k=map(int,raw_input().split())
l=map(int,raw_input().split())
f=0

d=defaultdict(list)
for i in xrange(5001):
    d[i]=range(1,k+1)
ans=[]
for i in xrange(n):
    try:
        #print d[l[i]]
        ans.append(d[l[i]].pop())
    except:
        f=1
        break
if f==1:
    print "NO"
else:
    d=Counter(ans)
    i=0
    for j in xrange(1,k+1):
        if d[j]==0:
            for i in xrange(n):
                if d[ans[i]]>1:
                    
                    d[ans[i]]-=1
                    ans[i]=j
                    d[j]+=1
                    break
    
    
    print "YES"
    for i in ans:
        print i,
