The array a with n integers is given. Let's call the sequence of one or more consecutive elements in a segment. Also let's call the segment k-good if it contains no more than k different values.

Find any longest k-good segment.

As the input/output can reach huge size it is recommended to use fast input/output methods: for example, prefer to use scanf/printf instead of cin/cout in C++, prefer to use BufferedReader/PrintWriter instead of Scanner/System.out in Java.

Input

The first line contains two integers n, k (1 ≤ k ≤ n ≤ 5·105) — the number of elements in a and the parameter k.

The second line contains n integers ai (0 ≤ ai ≤ 106) — the elements of the array a.

Output

Print two integers l, r (1 ≤ l ≤ r ≤ n) — the index of the left and the index of the right ends of some k-good longest segment. If there are several longest segments you can print any of them. The elements in a are numbered from 1 to n from left to right.

Examples

Input

5 5
1 2 3 4 5


Output

1 5


Input

9 3
6 5 1 2 3 2 1 4 5


Output

3 7


Input

3 1
1 2 3


Output

1 1
import java.util.*;
import java.io.*;

public class D {

    public static void main(String[] args) throws IOException {
        FastScanner in = new FastScanner();
        out = new PrintWriter(new BufferedOutputStream(System.out));

        int n = in.nextInt();
        int k = in.nextInt();
        int[] a = in.nextInts(n);

        int curSize = 0;
        int[] cnt = new int[1_000_001];
        int p = 0, l = 0, r = 0;

        for(int i = 0 ; i < n ; i++) {
            if(cnt[a[i]] == 0) curSize++;
            cnt[a[i]]++;
            while (curSize > k) {
                if (cnt[a[p]] == 1) curSize--;
                cnt[a[p++]]--;
            }
            if(i - p > r - l) {
                l = p;
                r = i;
            }
        }

        out.printf("%d %d\n", l+1, r+1);
        out.close();
    }

    static PrintWriter out;
    static class FastScanner {
        BufferedReader br;
        StringTokenizer st;
        public FastScanner() { br = new BufferedReader(new InputStreamReader(System.in)); }
        String next() {
            while (st == null || !st.hasMoreElements()) {
                try { st = new StringTokenizer(br.readLine()); }
                catch (IOException e) { e.printStackTrace(); }
            }
            return st.nextToken();
        }
        int nextInt() { return Integer.parseInt(next()); }
        long nextLong() { return Long.parseLong(next()); }
        double nextDouble() { return Double.parseDouble(next());}
        String nextLine(){
            String str = "";
            try { str = br.readLine();}
            catch (IOException e) { e.printStackTrace(); }
            return str;
        }
        int[] nextInts(int n) {
            int[] arr = new int[n];
            for (int i = 0; i < n; i++) {
                arr[i] = nextInt();
            }
            return arr;
        }
    }

}
