You are given an array a consisting of n integer numbers.

You have to color this array in k colors in such a way that: 

  * Each element of the array should be colored in some color; 
  * For each i from 1 to k there should be at least one element colored in the i-th color in the array; 
  * For each i from 1 to k all elements colored in the i-th color should be distinct. 



Obviously, such coloring might be impossible. In this case, print "NO". Otherwise print "YES" and any coloring (i.e. numbers c_1, c_2, ... c_n, where 1 ≤ c_i ≤ k and c_i is the color of the i-th element of the given array) satisfying the conditions above. If there are multiple answers, you can print any.

Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 5000) — the length of the array a and the number of colors, respectively.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 5000) — elements of the array a.

Output

If there is no answer, print "NO". Otherwise print "YES" and any coloring (i.e. numbers c_1, c_2, ... c_n, where 1 ≤ c_i ≤ k and c_i is the color of the i-th element of the given array) satisfying the conditions described in the problem statement. If there are multiple answers, you can print any.

Examples

Input


4 2
1 2 2 3


Output


YES
1 1 2 2


Input


5 2
3 2 1 2 3


Output


YES
2 1 1 2 1


Input


5 2
2 1 1 2 1


Output


NO

Note

In the first example the answer 2~ 1~ 2~ 1 is also acceptable.

In the second example the answer 1~ 1~ 1~ 2~ 2 is also acceptable.

There exist other acceptable answers for both examples.
from collections import Counter

n, k = map(int, input().split())
arr = list(map(int, input().split()))
dct = Counter(arr)
flag = 0
for keys in dct:
    if dct[keys]>k:
        print("NO")
        flag = 1
        break
if flag==0:
    if k==n:
        print("YES")
        ans = [i+1 for i in range(k)]
        print(*ans)
    else:
        s = list(set(arr))
        kColors = set([i+1 for i in range(k)])
        ans = [i+1 for i in range(k)]
        dct1 = dict()
        for i in s:
            dct1[i] = set()
        for i in range(k):
            dct1[arr[i]].add(ans[i])
        for i in range(k, n):
            colorsLeft = list(kColors - dct1[arr[i]])
            ans.append(colorsLeft[0])
            dct1[arr[i]].add(colorsLeft[0])
        print("YES")
        print(*ans)
    
