You are given an array a consisting of n integer numbers.

You have to color this array in k colors in such a way that: 

  * Each element of the array should be colored in some color; 
  * For each i from 1 to k there should be at least one element colored in the i-th color in the array; 
  * For each i from 1 to k all elements colored in the i-th color should be distinct. 



Obviously, such coloring might be impossible. In this case, print "NO". Otherwise print "YES" and any coloring (i.e. numbers c_1, c_2, ... c_n, where 1 ≤ c_i ≤ k and c_i is the color of the i-th element of the given array) satisfying the conditions above. If there are multiple answers, you can print any.

Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 5000) — the length of the array a and the number of colors, respectively.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 5000) — elements of the array a.

Output

If there is no answer, print "NO". Otherwise print "YES" and any coloring (i.e. numbers c_1, c_2, ... c_n, where 1 ≤ c_i ≤ k and c_i is the color of the i-th element of the given array) satisfying the conditions described in the problem statement. If there are multiple answers, you can print any.

Examples

Input


4 2
1 2 2 3


Output


YES
1 1 2 2


Input


5 2
3 2 1 2 3


Output


YES
2 1 1 2 1


Input


5 2
2 1 1 2 1


Output


NO

Note

In the first example the answer 2~ 1~ 2~ 1 is also acceptable.

In the second example the answer 1~ 1~ 1~ 2~ 2 is also acceptable.

There exist other acceptable answers for both examples.
# -*- coding: utf-8 -*-
# @Time    : 2019/1/9 22:49
# @Author  : LunaFire
# @Email   : gilgemesh2012@gmail.com
# @File    : B. Array K-Coloring.py


def main():
    n, k = map(int, input().split())
    a = list(map(int, input().split()))
    c = [0] * len(a)

    color_dict = {}
    curr_color = 0
    length = len(a)
    for i in range(length):
        while a[i] in color_dict and curr_color in color_dict[a[i]]:
            if len(color_dict[a[i]]) == k:
                print('NO')
                return
            curr_color = (curr_color + 1) % k

        c[i] = curr_color + 1
        if a[i] not in color_dict:
            color_dict[a[i]] = set()
        color_dict[a[i]].add(curr_color)
        curr_color = (curr_color + 1) % k
    print('YES')
    for x in c:
        print(x, end=' ')
    print()


if __name__ == '__main__':
    main()
