You are given an array a consisting of n integer numbers.

You have to color this array in k colors in such a way that: 

  * Each element of the array should be colored in some color; 
  * For each i from 1 to k there should be at least one element colored in the i-th color in the array; 
  * For each i from 1 to k all elements colored in the i-th color should be distinct. 



Obviously, such coloring might be impossible. In this case, print "NO". Otherwise print "YES" and any coloring (i.e. numbers c_1, c_2, ... c_n, where 1 ≤ c_i ≤ k and c_i is the color of the i-th element of the given array) satisfying the conditions above. If there are multiple answers, you can print any.

Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 5000) — the length of the array a and the number of colors, respectively.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 5000) — elements of the array a.

Output

If there is no answer, print "NO". Otherwise print "YES" and any coloring (i.e. numbers c_1, c_2, ... c_n, where 1 ≤ c_i ≤ k and c_i is the color of the i-th element of the given array) satisfying the conditions described in the problem statement. If there are multiple answers, you can print any.

Examples

Input


4 2
1 2 2 3


Output


YES
1 1 2 2


Input


5 2
3 2 1 2 3


Output


YES
2 1 1 2 1


Input


5 2
2 1 1 2 1


Output


NO

Note

In the first example the answer 2~ 1~ 2~ 1 is also acceptable.

In the second example the answer 1~ 1~ 1~ 2~ 2 is also acceptable.

There exist other acceptable answers for both examples.
"""
idea
sort given array
iterate through sorted array
; you mark your color(1~k) in answersheet
    and flag +=1
get different number
reset the flag
"""
n, k = map(int, input().split())   #5, 2 # n = len(array), colors

array = list(map(int, input().split()))  # [3, 2, 1, 2, 3] #given array 
answersheet = [0]*n
sorted_array = sorted(array)
for key in set(array):  # was for key in range(1, n+1) <<-- counter-input 3 2; 5000 5000 5000; output = YES answer:no
    if array.count(key) > k:
        print(f"NO")
        break 
else:
    while sorted_array:
        for color in range(1,k+1):
            current_num = sorted_array.pop(0)
            answersheet[array.index(current_num)] += color
            array[array.index(current_num)] = 0
            if not sorted_array:
                break
    print("YES")
    print(" ".join(map(str, answersheet)))
