You are given an array a consisting of n integer numbers.

You have to color this array in k colors in such a way that: 

  * Each element of the array should be colored in some color; 
  * For each i from 1 to k there should be at least one element colored in the i-th color in the array; 
  * For each i from 1 to k all elements colored in the i-th color should be distinct. 



Obviously, such coloring might be impossible. In this case, print "NO". Otherwise print "YES" and any coloring (i.e. numbers c_1, c_2, ... c_n, where 1 ≤ c_i ≤ k and c_i is the color of the i-th element of the given array) satisfying the conditions above. If there are multiple answers, you can print any.

Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 5000) — the length of the array a and the number of colors, respectively.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 5000) — elements of the array a.

Output

If there is no answer, print "NO". Otherwise print "YES" and any coloring (i.e. numbers c_1, c_2, ... c_n, where 1 ≤ c_i ≤ k and c_i is the color of the i-th element of the given array) satisfying the conditions described in the problem statement. If there are multiple answers, you can print any.

Examples

Input


4 2
1 2 2 3


Output


YES
1 1 2 2


Input


5 2
3 2 1 2 3


Output


YES
2 1 1 2 1


Input


5 2
2 1 1 2 1


Output


NO

Note

In the first example the answer 2~ 1~ 2~ 1 is also acceptable.

In the second example the answer 1~ 1~ 1~ 2~ 2 is also acceptable.

There exist other acceptable answers for both examples.
import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.HashSet;
import java.util.Scanner;

/**
 * Built using CHelper plug-in
 * Actual solution is at the top
 *
 * @author Kristopher
 */
public class Main {
    public static void main(String[] args) {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        Scanner in = new Scanner(inputStream);
        PrintWriter out = new PrintWriter(outputStream);
        BArrayKColoring solver = new BArrayKColoring();
        solver.solve(1, in, out);
        out.close();
    }

    static class BArrayKColoring {
        public void solve(int testNumber, Scanner in, PrintWriter out) {
            int n = in.nextInt();
            int k = in.nextInt();
            int[] a = new int[n];
            for (int i = 0; i < n; i++)
                a[i] = in.nextInt();

            if (n < k) {
                out.println("NO");
                return;
            }

            StringBuilder clr = new StringBuilder();
            HashSet<String> used = new HashSet<String>();
            for (int i = 0; i < n; i++) {
                if (i < k) {
                    // First k elements get colors 1-k
                    int qq = i + 1;
                    clr.append(qq + " ");
                    used.add(a[i] + ":" + qq);
                } else {
                    // Next elements, we just look for a color that will accept this element
                    for (int qq = 1; qq <= k; qq++) {
                        if (!used.contains(a[i] + ":" + qq)) {
                            clr.append(qq + " ");
                            used.add(a[i] + ":" + qq);
                            break;
                        }

                        if (qq == k) {
                            out.println("NO");
                            return;
                        }
                    }
                }
            }

            out.println("YES");
            out.println(clr.toString().trim());
        }

    }
}

