You are given an array a consisting of n integer numbers.

You have to color this array in k colors in such a way that: 

  * Each element of the array should be colored in some color; 
  * For each i from 1 to k there should be at least one element colored in the i-th color in the array; 
  * For each i from 1 to k all elements colored in the i-th color should be distinct. 



Obviously, such coloring might be impossible. In this case, print "NO". Otherwise print "YES" and any coloring (i.e. numbers c_1, c_2, ... c_n, where 1 ≤ c_i ≤ k and c_i is the color of the i-th element of the given array) satisfying the conditions above. If there are multiple answers, you can print any.

Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 5000) — the length of the array a and the number of colors, respectively.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 5000) — elements of the array a.

Output

If there is no answer, print "NO". Otherwise print "YES" and any coloring (i.e. numbers c_1, c_2, ... c_n, where 1 ≤ c_i ≤ k and c_i is the color of the i-th element of the given array) satisfying the conditions described in the problem statement. If there are multiple answers, you can print any.

Examples

Input


4 2
1 2 2 3


Output


YES
1 1 2 2


Input


5 2
3 2 1 2 3


Output


YES
2 1 1 2 1


Input


5 2
2 1 1 2 1


Output


NO

Note

In the first example the answer 2~ 1~ 2~ 1 is also acceptable.

In the second example the answer 1~ 1~ 1~ 2~ 2 is also acceptable.

There exist other acceptable answers for both examples.
if __name__ == "__main__":
    n, k = map(int, input().split())
    numbers = list(map(int, input().split()))
    if n >= k:
        colors = [i + 1 for i in range(k)]
        judge, ans, cnt = [colors[:] for i in range(5002)], [], 0
        for i in range(k):
            ans.append(colors[i])
            judge[numbers[0]].remove(colors[i])
            numbers.pop(0)
        for number in numbers:
            if judge[number]:
                ans.append(judge[number].pop(0))
            else:
                cnt = 1
                break
        if cnt == 0:
            print("YES")
            for i in range(n):
                print(ans[i], end = " ")
            print("")
        else:
            print("NO")
    else:
        print("NO")
	  	   	    	  		  		 	 		 		