You are given a tree that consists of n nodes. You should label each of its n-1 edges with an integer in such way that satisfies the following conditions: 

  * each integer must be greater than 0; 
  * the product of all n-1 numbers should be equal to k; 
  * the number of 1-s among all n-1 integers must be minimum possible. 



Let's define f(u,v) as the sum of the numbers on the simple path from node u to node v. Also, let ∑_{i=1}^{n-1} ∑_{j=i+1}^n f(i,j) be a distribution index of the tree.

Find the maximum possible distribution index you can get. Since answer can be too large, print it modulo 10^9 + 7.

In this problem, since the number k can be large, the result of the prime factorization of k is given instead.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.

The first line of each test case contains a single integer n (2 ≤ n ≤ 10^5) — the number of nodes in the tree.

Each of the next n-1 lines describes an edge: the i-th line contains two integers u_i and v_i (1 ≤ u_i, v_i ≤ n; u_i ≠ v_i) — indices of vertices connected by the i-th edge.

Next line contains a single integer m (1 ≤ m ≤ 6 ⋅ 10^4) — the number of prime factors of k.

Next line contains m prime numbers p_1, p_2, …, p_m (2 ≤ p_i < 6 ⋅ 10^4) such that k = p_1 ⋅ p_2 ⋅ … ⋅ p_m.

It is guaranteed that the sum of n over all test cases doesn't exceed 10^5, the sum of m over all test cases doesn't exceed 6 ⋅ 10^4, and the given edges for each test cases form a tree.

Output

Print the maximum distribution index you can get. Since answer can be too large, print it modulo 10^9+7.

Example

Input


3
4
1 2
2 3
3 4
2
2 2
4
3 4
1 3
3 2
2
3 2
7
6 1
2 3
4 6
7 3
5 1
3 6
4
7 5 13 3


Output


17
18
286

Note

In the first test case, one of the optimal ways is on the following image:

<image>

In this case, f(1,2)=1, f(1,3)=3, f(1,4)=5, f(2,3)=2, f(2,4)=4, f(3,4)=2, so the sum of these 6 numbers is 17.

In the second test case, one of the optimal ways is on the following image:

<image>

In this case, f(1,2)=3, f(1,3)=1, f(1,4)=4, f(2,3)=2, f(2,4)=5, f(3,4)=3, so the sum of these 6 numbers is 18.
/**
 * BaZ :D
 */

import java.util.*;
import java.io.*;
import static java.lang.Math.*;

public class Main
{
    static MyScanner scan;
    static PrintWriter pw;
    static long MOD = 1_000_000_007;
    static long INF = 2_000_000_000_000_000_000L;
    static long inf = 2_000_000_000;
    public static void main(String[] args) {
        new Thread(null, null, "BaZ", 1 << 27) {
            public void run() {
                try {
                    solve();
                } catch (Exception e) {
                    e.printStackTrace();
                    System.exit(1);
                }
            }
        }.start();
    }

    static int n, subtree_size[];
    static ArrayList<Integer> adj[];
    static ArrayList<Long> edge_weights;
    static void solve() throws IOException
    {
        //initIo(true, "");
        initIo(false, "");
        StringBuilder sb = new StringBuilder();
        int t = ni();
        while (t-->0) {
            n = ni();
            adj = new ArrayList[n+1];
            for(int i=1;i<=n;i++) {
                adj[i] = new ArrayList<>();
            }
            for(int i=1;i<n;i++) {
                int u = ni(), v = ni();
                adj[u].add(v);
                adj[v].add(u);
            }
            int m = ni();
            Integer arr[] = new Integer[m];
            for(int i=0;i<m;i++) {
                arr[i] = ni();
            }
            Arrays.sort(arr);
            edge_weights = new ArrayList<>();
            subtree_size = new int[n+1];
            dfs(1, 1);
            Collections.sort(edge_weights);
            //pa("Weights", edge_weights);
            long ans = 0;
            long contrib[] = new long[n-1];
            for(int i=0;i<n-1;i++) {
                contrib[i] = edge_weights.get(i)%MOD;
            }
            int ptr = m-1;
            int last_count = max(1, m-(n-2));
            for(int i=0;i<last_count;i++) {
                if(ptr>=0) {
                    contrib[n - 2] *= arr[ptr--];
                    contrib[n - 2] %= MOD;
                }
                else {
                    break;
                }
            }

            for(int i=n-3;i>=0;--i) {
                if(ptr>=0) {
                    contrib[i]*=arr[ptr--];
                    contrib[i]%=MOD;
                }
                else {
                    break;
                }
            }

            for(int i=0;i<=n-2;i++) {
                ans+=contrib[i];
                ans%=MOD;
            }
//
//            pa("weights", edge_weights);
//            pa("final contrib", contrib);
            pl(ans);
        }

        pw.flush();
        pw.close();
    }

    static void dfs(int v, int par) {
        subtree_size[v]++;
        for(int e : adj[v]) {
            if(e!=par) {
                dfs(e, v);
                subtree_size[v]+=subtree_size[e];
                edge_weights.add(1L*subtree_size[e]*(n-subtree_size[e]));
            }
        }
    }

    static void assert_in_range(String varName, int n, int l, int r) {
        if (n >=l && n<=r) return;
        System.out.println(varName + " is not in range. Actual: "+n+" l : "+l+" r: "+r);
        System.exit(1);
    }
    static void assert_in_range(String varName, long n, long l, long r) {
        if (n>=l && n<=r) return;
        System.out.println(varName + " is not in range. Actual: "+n+" l : "+l+" r: "+r);
        System.exit(1);
    }

    static void initIo(boolean isFileIO, String suffix) throws IOException {
        scan = new MyScanner(isFileIO, suffix);
        if(isFileIO) {
            pw = new PrintWriter("/Users/amandeep/Desktop/output"+suffix+".txt");
        }
        else {
            pw = new PrintWriter(System.out, true);
        }
    }
    static int ni() throws IOException
    {
        return scan.nextInt();
    }
    static long nl() throws IOException
    {
        return scan.nextLong();
    }
    static double nd() throws IOException
    {
        return scan.nextDouble();
    }
    static String ne() throws IOException
    {
        return scan.next();
    }
    static String nel() throws IOException
    {
        return scan.nextLine();
    }
    static void pl()
    {
        pw.println();
    }
    static void p(Object o)
    {
        pw.print(o+" ");
    }
    static void pl(Object o)
    {
        pw.println(o);
    }
    static void psb(StringBuilder sb)
    {
        pw.print(sb);
    }
    static void pa(String arrayName, Object arr[])
    {
        pl(arrayName+" : ");
        for(Object o : arr)
            p(o);
        pl();
    }
    static void pa(String arrayName, int arr[])
    {
        pl(arrayName+" : ");
        for(int o : arr)
            p(o);
        pl();
    }
    static void pa(String arrayName, long arr[])
    {
        pl(arrayName+" : ");
        for(long o : arr)
            p(o);
        pl();
    }
    static void pa(String arrayName, double arr[])
    {
        pl(arrayName+" : ");
        for(double o : arr)
            p(o);
        pl();
    }
    static void pa(String arrayName, char arr[])
    {
        pl(arrayName+" : ");
        for(char o : arr)
            p(o);
        pl();
    }
    static void pa(String arrayName, boolean arr[])
    {
        pl(arrayName+" : ");
        for(boolean o : arr)
            p(o);
        pl();
    }
    static void pa(String listName, List list)
    {
        pl(listName+" : ");
        for(Object o : list)
            p(o);
        pl();
    }
    static void pa(String arrayName, Object[][] arr) {
        pl(arrayName+" : ");
        for(int i=0;i<arr.length;++i) {
            for(Object o : arr[i])
                p(o);
            pl();
        }
    }
    static void pa(String arrayName, int[][] arr) {
        pl(arrayName+" : ");
        for(int i=0;i<arr.length;++i) {
            for(int o : arr[i])
                p(o);
            pl();
        }
    }
    static void pa(String arrayName, long[][] arr) {
        pl(arrayName+" : ");
        for(int i=0;i<arr.length;++i) {
            for(long o : arr[i])
                p(o);
            pl();
        }
    }
    static void pa(String arrayName, char[][] arr) {
        pl(arrayName+" : ");
        for(int i=0;i<arr.length;++i) {
            for(char o : arr[i])
                p(o);
            pl();
        }
    }
    static void pa(String arrayName, double[][] arr) {
        pl(arrayName+" : ");
        for(int i=0;i<arr.length;++i) {
            for(double o : arr[i])
                p(o);
            pl();
        }
    }
    static void pa(String arrayName, boolean[][] arr) {
        pl(arrayName+" : ");
        for(int i=0;i<arr.length;++i) {
            for(boolean o : arr[i])
                p(o);
            pl();
        }
    }
    static class MyScanner
    {
        BufferedReader br;
        StringTokenizer st;
        MyScanner(boolean readingFromFile, String suffix) throws IOException
        {
            if(readingFromFile) {
                br = new BufferedReader(new FileReader("/Users/amandeep/Desktop/input"+suffix+".txt"));
            }
            else {
                br = new BufferedReader(new InputStreamReader(System.in));
            }
        }
        String nextLine()throws IOException
        {
            return br.readLine();
        }
        String next() throws IOException
        {
            if(st==null || !st.hasMoreTokens())
                st = new StringTokenizer(br.readLine());
            return st.nextToken();
        }
        int nextInt() throws IOException
        {
            return Integer.parseInt(next());
        }
        long nextLong() throws IOException
        {
            return Long.parseLong(next());
        }
        double nextDouble() throws IOException
        {
            return Double.parseDouble(next());
        }
    }
}