One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.

For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two primes". Let's modify it. How about a statement like that: "each integer no less than 12 can be expressed as the sum of two composite numbers." Not like the Goldbach's conjecture, I can prove this theorem.

You are given an integer n no less than 12, express it as a sum of two composite numbers.

Input

The only line contains an integer n (12 ≤ n ≤ 106).

Output

Output two composite integers x and y (1 < x, y < n) such that x + y = n. If there are multiple solutions, you can output any of them.

Examples

Input

12


Output

4 8


Input

15


Output

6 9


Input

23


Output

8 15


Input

1000000


Output

500000 500000

Note

In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.

In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number.
#include <bits/stdc++.h>
using namespace std;
void solve() {
  int n;
  cin >> n;
  vector<bool> isPrime(1000001, true);
  isPrime[1] = false;
  for (long long int i = 2ll; i < 1000001ll; i++) {
    if (isPrime[i] == false) continue;
    long long int j = i * i;
    while (j < 1000001ll) {
      isPrime[j] = false;
      j += i;
    }
  }
  for (int i = 2; i < n; i++) {
    if (isPrime[i] || isPrime[n - i]) continue;
    cout << i << ' ' << (n - i);
    return;
  }
}
int main() {
  std::ios::sync_with_stdio(false);
  cin.tie(0);
  cout.precision(10);
  cout << fixed;
  int T = 1;
  while (T--) {
    solve();
  }
  return 0;
}
