You are given an array a consisting of n integers. Each a_i is one of the six following numbers: 4, 8, 15, 16, 23, 42.

Your task is to remove the minimum number of elements to make this array good.

An array of length k is called good if k is divisible by 6 and it is possible to split it into k/6 subsequences 4, 8, 15, 16, 23, 42.

Examples of good arrays:

  * [4, 8, 15, 16, 23, 42] (the whole array is a required sequence); 
  * [4, 8, 4, 15, 16, 8, 23, 15, 16, 42, 23, 42] (the first sequence is formed from first, second, fourth, fifth, seventh and tenth elements and the second one is formed from remaining elements); 
  * [] (the empty array is good). 



Examples of bad arrays: 

  * [4, 8, 15, 16, 42, 23] (the order of elements should be exactly 4, 8, 15, 16, 23, 42); 
  * [4, 8, 15, 16, 23, 42, 4] (the length of the array is not divisible by 6); 
  * [4, 8, 15, 16, 23, 42, 4, 8, 15, 16, 23, 23] (the first sequence can be formed from first six elements but the remaining array cannot form the required sequence). 

Input

The first line of the input contains one integer n (1 ≤ n ≤ 5 ⋅ 10^5) — the number of elements in a.

The second line of the input contains n integers a_1, a_2, ..., a_n (each a_i is one of the following numbers: 4, 8, 15, 16, 23, 42), where a_i is the i-th element of a.

Output

Print one integer — the minimum number of elements you have to remove to obtain a good array.

Examples

Input


5
4 8 15 16 23


Output


5


Input


12
4 8 4 15 16 8 23 15 16 42 23 42


Output


0


Input


15
4 8 4 8 15 16 8 16 23 15 16 4 42 23 42


Output


3
n=int(input())
a=[int(i) for i in input().split()]
ar=[]
vis=[]
ans=n
for _ in range(6):
    ar.append([])
    vis.append([])
for i in range(n):
    if(a[i]==4):
        ar[0].append(i)
        vis[0].append(False)
    elif(a[i]==8):
        ar[1].append(i)
        vis[1].append(False)
    elif(a[i]==15):
        ar[2].append(i)
        vis[2].append(False)
    elif(a[i]==16):
        ar[3].append(i)
        vis[3].append(False)
    elif(a[i]==23):
        ar[4].append(i)
        vis[4].append(False)
    elif(a[i]==42):
        ar[5].append(i)
        vis[5].append(False)
i=[0]*6
p=-1
flag=True
while(flag):
    z=0
    while(z<6):
        if(len(ar[z])<=i[z]):
            flag=False
            break
        if(ar[z][i[z]]>p):
            if(z==5):
                ans-=6
                p=-1
                i[z]+=1
                z=6
            else:
                p=ar[z][i[z]]
                i[z]+=1
                z+=1
        else:
            i[z]+=1
print(ans)