Given an integer x, find 2 integers a and b such that: 

  * 1 ≤ a,b ≤ x 
  * b divides a (a is divisible by b). 
  * a ⋅ b>x. 
  * a/b<x. 

Input

The only line contains the integer x (1 ≤ x ≤ 100).

Output

You should output two integers a and b, satisfying the given conditions, separated by a space. If no pair of integers satisfy the conditions above, print "-1" (without quotes).

Examples

Input

10


Output

6 3

Input

1


Output

-1
import java.io.*;
import java.util.*;
 
public class Main{
   public static void main(String[] args) {
      MyScanner sc = new MyScanner();
      out = new PrintWriter(new BufferedOutputStream(System.out));
      
      //begin
      int x = sc.nextInt();
      boolean found = false;
      for(int a = 1; a <= x; a++)
      {
          for(int b = 1; b <= x; b++)
          {
              if(found)
                  break;
              if(a % b == 0 && a * b > x && a / b < x)
              {
                found = !found;
                out.println(a + " " + b);
              }
          }
          if(found)
            break;
      }
      if(!found)
        out.println(-1);
      //end
      out.close();
   }
 
   public static PrintWriter out;
      
   public static class MyScanner {
      BufferedReader br;
      StringTokenizer st;
 
      public MyScanner() {
         br = new BufferedReader(new InputStreamReader(System.in));
      }
 
      String next() {
          while (st == null || !st.hasMoreElements()) {
              try {
                  st = new StringTokenizer(br.readLine());
              } catch (IOException e) {
                  e.printStackTrace();
              }
          }
          return st.nextToken();
      }
 
      int nextInt() {
          return Integer.parseInt(next());
      }
      long nextLong() {
          return Long.parseLong(next());
      }
      double nextDouble() {
          return Double.parseDouble(next());
      }
      String nextLine(){
          String str = "";
	  try {
	     str = br.readLine();
	  } catch (IOException e) {
	     e.printStackTrace();
	  }
	  return str;
      }
   }
}