You are given an array a consisting of n integers. Each a_i is one of the six following numbers: 4, 8, 15, 16, 23, 42.

Your task is to remove the minimum number of elements to make this array good.

An array of length k is called good if k is divisible by 6 and it is possible to split it into k/6 subsequences 4, 8, 15, 16, 23, 42.

Examples of good arrays:

  * [4, 8, 15, 16, 23, 42] (the whole array is a required sequence); 
  * [4, 8, 4, 15, 16, 8, 23, 15, 16, 42, 23, 42] (the first sequence is formed from first, second, fourth, fifth, seventh and tenth elements and the second one is formed from remaining elements); 
  * [] (the empty array is good). 



Examples of bad arrays: 

  * [4, 8, 15, 16, 42, 23] (the order of elements should be exactly 4, 8, 15, 16, 23, 42); 
  * [4, 8, 15, 16, 23, 42, 4] (the length of the array is not divisible by 6); 
  * [4, 8, 15, 16, 23, 42, 4, 8, 15, 16, 23, 23] (the first sequence can be formed from first six elements but the remaining array cannot form the required sequence). 

Input

The first line of the input contains one integer n (1 ≤ n ≤ 5 ⋅ 10^5) — the number of elements in a.

The second line of the input contains n integers a_1, a_2, ..., a_n (each a_i is one of the following numbers: 4, 8, 15, 16, 23, 42), where a_i is the i-th element of a.

Output

Print one integer — the minimum number of elements you have to remove to obtain a good array.

Examples

Input


5
4 8 15 16 23


Output


5


Input


12
4 8 4 15 16 8 23 15 16 42 23 42


Output


0


Input


15
4 8 4 8 15 16 8 16 23 15 16 4 42 23 42


Output


3
#include <bits/stdc++.h>
using namespace std;
const long long int MOD = 1000000007;
const long double PI = 2 * acos(0.0);
const vector<long long int> dx = {1, -1, 0, 0};
const vector<long long int> dy = {0, 0, 1, -1};
vector<long long int> ga(long long int n, bool oneIndexed = false) {
  vector<long long int> a;
  if (oneIndexed) a.push_back(0ll);
  for (long long int i = 0; i < n; i++) {
    long long int p;
    cin >> p;
    a.push_back(p);
  }
  return move(a);
}
vector<unsigned long long int> gau(unsigned long long int n,
                                   bool oneIndexed = false) {
  vector<unsigned long long int> a;
  if (oneIndexed) a.push_back(0llu);
  for (unsigned long long int i = 0; i < n; i++) {
    unsigned long long int p;
    cin >> p;
    a.push_back(p);
  }
  return move(a);
}
vector<string> gas(unsigned long long int n, bool oneIndexed = false) {
  vector<string> a;
  if (oneIndexed) a.push_back("");
  for (unsigned long long int i = 0; i < n; i++) {
    string p;
    cin >> p;
    a.push_back(p);
  }
  return move(a);
}
template <typename T, typename A>
void pa(vector<T, A> const &a, long long int begin = 0,
        long long int end = -1) {
  if (end == -1) end = (long long int)a.size() - 1;
  for (long long int i = begin; i <= end; i++) {
    cout << a[i] << " ";
  }
  cout << "\n";
}
template <typename T, typename A>
void papair(vector<T, A> const &a, long long int begin = 0,
            long long int end = -1) {
  if (end == -1) end = (long long int)a.size() - 1;
  for (long long int i = begin; i <= end; i++) {
    cout << a[i].first << " " << a[i].second << "\n";
  }
  cout << "\n";
}
void yes() { cout << "YES\n"; }
void no() { cout << "NO\n"; }
void yesno(int f) {
  if (f)
    yes();
  else
    no();
}
long long int indexof(const vector<long long int> &a, long long int val) {
  for (long long int i = 0; i < (long long int)a.size(); i++) {
    if (a[i] == val) return i + 1;
  }
  return -1;
}
void solve() {
  long long int n;
  cin >> n;
  vector<long long int> a = ga(n);
  set<long long int> nums = {4, 8, 15, 16, 23, 42};
  vector<long long int> numsvec(nums.begin(), nums.end());
  vector<long long int> freq(100);
  for (long long int i = 0; i < n; i++) {
    if (nums.find(a[i]) != nums.end()) {
      freq[a[i]]++;
    }
  }
  long long int nos;
  for (auto n : nums)
    if (freq[n] < nos) nos = freq[n];
  ;
  map<long long int, long long int> poses;
  poses[0] = 1e15;
  poses[1] = 0;
  poses[2] = 0;
  poses[3] = 0;
  poses[4] = 0;
  poses[5] = 0;
  poses[6] = 0;
  for (long long int i = 0; i < (long long int)a.size(); i++) {
    long long int pos = indexof(numsvec, a[i]);
    if (pos != -1 && poses[pos - 1]) {
      poses[pos - 1]--;
      poses[pos]++;
    }
  }
  long long int ans = poses[6];
  cout << n - ans * 6;
}
int main(void) {
  ios::sync_with_stdio(0);
  cin.tie(0);
  cout.tie(0);
  solve();
  return 0;
}
