The only difference between easy and hard versions is constraints.

You are given a sequence a consisting of n positive integers.

Let's define a three blocks palindrome as the sequence, consisting of at most two distinct elements (let these elements are a and b, a can be equal b) and is as follows: [\underbrace{a, a, ..., a}_{x}, \underbrace{b, b, ..., b}_{y}, \underbrace{a, a, ..., a}_{x}]. There x, y are integers greater than or equal to 0. For example, sequences [], [2], [1, 1], [1, 2, 1], [1, 2, 2, 1] and [1, 1, 2, 1, 1] are three block palindromes but [1, 2, 3, 2, 1], [1, 2, 1, 2, 1] and [1, 2] are not.

Your task is to choose the maximum by length subsequence of a that is a three blocks palindrome.

You have to answer t independent test cases.

Recall that the sequence t is a a subsequence of the sequence s if t can be derived from s by removing zero or more elements without changing the order of the remaining elements. For example, if s=[1, 2, 1, 3, 1, 2, 1], then possible subsequences are: [1, 1, 1, 1], [3] and [1, 2, 1, 3, 1, 2, 1], but not [3, 2, 3] and [1, 1, 1, 1, 2].

Input

The first line of the input contains one integer t (1 ≤ t ≤ 2000) — the number of test cases. Then t test cases follow.

The first line of the test case contains one integer n (1 ≤ n ≤ 2000) — the length of a. The second line of the test case contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 26), where a_i is the i-th element of a. Note that the maximum value of a_i can be up to 26.

It is guaranteed that the sum of n over all test cases does not exceed 2000 (∑ n ≤ 2000).

Output

For each test case, print the answer — the maximum possible length of some subsequence of a that is a three blocks palindrome.

Example

Input


6
8
1 1 2 2 3 2 1 1
3
1 3 3
4
1 10 10 1
1
26
2
2 1
3
1 1 1


Output


7
2
4
1
1
3
import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.InputMismatchException;
import java.io.IOException;
import java.util.ArrayList;
import java.io.InputStream;

/**
 * Built using CHelper plug-in Actual solution is at the top
 *
 * @author MakeMoroccoGreatAgain
 */
public class Main {
  public static void main(String[] args) {
    InputStream inputStream = System.in;
    OutputStream outputStream = System.out;
    InputReader in = new InputReader(inputStream);
    PrintWriter out = new PrintWriter(outputStream);
    E1ThreeBlocksPalindromeEasyVersion solver = new E1ThreeBlocksPalindromeEasyVersion();
    solver.solve(1, in, out);
    out.close();
  }

  static class E1ThreeBlocksPalindromeEasyVersion {
    public final void solve(int testNumber, InputReader in, PrintWriter out) {
      int t = in.nextInt();
      while (t-- > 0) {
        int n = in.nextInt();
        int[] a = in.nextIntArrayOneBased(n);
        int[][] pre = new int[201][n + 1];
        ArrayList<Integer>[] idx = new ArrayList[201];
        for (int i = 1; i <= 200; i++) {
          idx[i] = new ArrayList<>();
        }
        for (int i = 1; i <= n; i++) {
          pre[a[i]][i]++;
          for (int j = 1; j <= 200; j++) {
            pre[j][i] += pre[j][i - 1];
          }
          idx[a[i]].add(i);
        }

        int ans = 1;
        for (int i = 1; i <= 200; i++) {
          int l = 0, r = idx[i].size() - 1;
          while (l <= r) {
            int L = idx[i].get(l), R = idx[i].get(r);
            for (int j = 1; j <= 200; j++) {
              ans =
                  Math.max(
                      ans,
                      (l + 1) * 2 - (l == r ? 1 : 0) + RangeQueriesUtils.get(pre[j], L + 1, R - 1));
            }
            ++l;
            --r;
          }
        }

        out.println(ans);
      }
    }
  }

  static final class RangeQueriesUtils {
    private RangeQueriesUtils() {
      throw new RuntimeException("DON'T");
    }

    public static final int get(int[] pre, int i, int j) {
      if (i > j) {
        return 0;
      }
      if (i == 0) {
        return pre[j];
      }
      return pre[j] - pre[i - 1];
    }
  }

  static final class InputReader {
    private final InputStream stream;
    private final byte[] buf = new byte[1 << 16];
    private int curChar;
    private int numChars;

    public InputReader() {
      this.stream = System.in;
    }

    public InputReader(final InputStream stream) {
      this.stream = stream;
    }

    private final int read() {
      if (this.numChars == -1) {
        throw new UnknownError();
      } else {
        if (this.curChar >= this.numChars) {
          this.curChar = 0;

          try {
            this.numChars = this.stream.read(this.buf);
          } catch (IOException ex) {
            throw new InputMismatchException();
          }

          if (this.numChars <= 0) {
            return -1;
          }
        }

        return this.buf[this.curChar++];
      }
    }

    public final int nextInt() {
      int c;
      for (c = this.read(); isSpaceChar(c); c = this.read()) {}

      byte sgn = 1;
      if (c == 45) { // 45 == '-'
        sgn = -1;
        c = this.read();
      }

      int res = 0;

      while (c >= 48 && c <= 57) { // 48 == '0', 57 == '9'
        res *= 10;
        res += c - 48; // 48 == '0'
        c = this.read();
        if (isSpaceChar(c)) {
          return res * sgn;
        }
      }

      throw new InputMismatchException();
    }

    private static final boolean isSpaceChar(final int c) {
      return c == 32 || c == 10 || c == 13 || c == 9
          || c == -1; // 32 == ' ', 10 == '\n', 13 == '\r', 9 == '\t'
    }

    public final int[] nextIntArrayOneBased(final int n) {
      int[] ret = new int[n + 1];
      for (int i = 1; i <= n; i++) {
        ret[i] = nextInt();
      }
      return ret;
    }
  }
}
