One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.

For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two primes". Let's modify it. How about a statement like that: "each integer no less than 12 can be expressed as the sum of two composite numbers." Not like the Goldbach's conjecture, I can prove this theorem.

You are given an integer n no less than 12, express it as a sum of two composite numbers.

Input

The only line contains an integer n (12 ≤ n ≤ 106).

Output

Output two composite integers x and y (1 < x, y < n) such that x + y = n. If there are multiple solutions, you can output any of them.

Examples

Input

12


Output

4 8


Input

15


Output

6 9


Input

23


Output

8 15


Input

1000000


Output

500000 500000

Note

In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.

In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number.
#include <bits/stdc++.h>
using namespace std;
int SieveOfEratosthenes(int **arr, int n) {
  int c = 0;
  int *ar;
  ar = (int *)malloc(sizeof(int *) * n);
  bool prime[n + 1];
  memset(prime, true, sizeof(prime));
  for (int p = 2; p * p <= n; p++) {
    if (prime[p] == true) {
      for (int i = p * 2; i <= n; i += p) prime[i] = false;
    }
  }
  for (int p = 2; p <= n; p++) {
    if (!prime[p]) {
      ar[c] = p;
      c++;
    }
  }
  (*arr) = ar;
  return c;
}
int main() {
  int m;
  cin >> m;
  int n = 1000000;
  int *arr;
  arr = (int *)malloc(sizeof(int *) * n);
  arr[n] = {0};
  int z = SieveOfEratosthenes(&arr, n);
  for (int i = 0; i < z; i++) {
    int d = m - arr[i];
    if (binary_search(arr, arr + z, d)) {
      cout << arr[i] << " " << d << endl;
      break;
    }
  }
  return 0;
}
