You are given an array a consisting of n integers. Each a_i is one of the six following numbers: 4, 8, 15, 16, 23, 42.

Your task is to remove the minimum number of elements to make this array good.

An array of length k is called good if k is divisible by 6 and it is possible to split it into k/6 subsequences 4, 8, 15, 16, 23, 42.

Examples of good arrays:

  * [4, 8, 15, 16, 23, 42] (the whole array is a required sequence); 
  * [4, 8, 4, 15, 16, 8, 23, 15, 16, 42, 23, 42] (the first sequence is formed from first, second, fourth, fifth, seventh and tenth elements and the second one is formed from remaining elements); 
  * [] (the empty array is good). 



Examples of bad arrays: 

  * [4, 8, 15, 16, 42, 23] (the order of elements should be exactly 4, 8, 15, 16, 23, 42); 
  * [4, 8, 15, 16, 23, 42, 4] (the length of the array is not divisible by 6); 
  * [4, 8, 15, 16, 23, 42, 4, 8, 15, 16, 23, 23] (the first sequence can be formed from first six elements but the remaining array cannot form the required sequence). 

Input

The first line of the input contains one integer n (1 ≤ n ≤ 5 ⋅ 10^5) — the number of elements in a.

The second line of the input contains n integers a_1, a_2, ..., a_n (each a_i is one of the following numbers: 4, 8, 15, 16, 23, 42), where a_i is the i-th element of a.

Output

Print one integer — the minimum number of elements you have to remove to obtain a good array.

Examples

Input


5
4 8 15 16 23


Output


5


Input


12
4 8 4 15 16 8 23 15 16 42 23 42


Output


0


Input


15
4 8 4 8 15 16 8 16 23 15 16 4 42 23 42


Output


3
n = int(input())
a = list(map(int,input().split(' ')))

data = {4:0, 8:1, 15:2, 16:3, 23:4, 42:5}

# req0=0
req1=0
req2=0
req3=0
req4=0
req5=0

seqs = []

ans=0
for c in a:

	if data[c]==0:
		seqs.append([c])
		# req0+=1
	elif data[c]==1:
		if len(seqs)>=req1+1 and len(seqs[req1])==1:
			seqs[req1].append(c)
			req1+=1
		else:
			ans+=1
	elif data[c]==2:
		if len(seqs)>=req2+1 and len(seqs[req2])==2:
			seqs[req2].append(c)
			req2+=1
		else:
			ans+=1
	elif data[c]==3:
		if len(seqs)>=req3+1 and len(seqs[req3])==3:
			seqs[req3].append(c)
			req3+=1
		else:
			ans+=1
	elif data[c]==4:
		if len(seqs)>=req4+1 and len(seqs[req4])==4:
			seqs[req4].append(c)
			req4+=1
		else:
			ans+=1
	elif data[c]==5:
		if len(seqs)>=req5+1 and len(seqs[req5])==5:
			seqs[req5].append(c)
			req5+=1
		else:
			ans+=1

# print(seqs)

for l in seqs:
	if len(l)!=6:
		ans+=len(l)

print(ans)