You have unlimited number of coins with values 1, 2, …, n. You want to select some set of coins having the total value of S. 

It is allowed to have multiple coins with the same value in the set. What is the minimum number of coins required to get sum S?

Input

The only line of the input contains two integers n and S (1 ≤ n ≤ 100 000, 1 ≤ S ≤ 10^9)

Output

Print exactly one integer — the minimum number of coins required to obtain sum S.

Examples

Input

5 11


Output

3

Input

6 16


Output

3

Note

In the first example, some of the possible ways to get sum 11 with 3 coins are: 

  * (3, 4, 4)
  * (2, 4, 5)
  * (1, 5, 5)
  * (3, 3, 5) 



It is impossible to get sum 11 with less than 3 coins.

In the second example, some of the possible ways to get sum 16 with 3 coins are: 

  * (5, 5, 6)
  * (4, 6, 6) 



It is impossible to get sum 16 with less than 3 coins.
import sys
def rr(): return sys.stdin.readline().rstrip()
#def pp(*args, end="\n"): sys.stdout.write(" ".join(map(str, args))+end)
rp = print
def print(*args, **kwargs): rp("DBG:# ", *args, **kwargs, file=sys.stderr)
def rri(): return int(rr())
def rrl(): return list(map(int, rr().split()))
def rrt(): return tuple(map(int, rr().split()))
def rrle(): return (line.rstrip() for line in sys.stdin.readlines())
def rrtl(): return [tuple(map(int, l.split())) for l in rrle()]
from collections import defaultdict
def mus(d=lambda: 0): return defaultdict(lambda: defaultdict(d))
def dd0(d=lambda: 0): return defaultdict(d)
def ms(x, y, d=0): return [[0]*y for i in range(x)]
def ar(x, d=0): return [d]*x
def ppm(m, n=0, x=0, y=0): print("\n".join(("\t".join((str(m[j][i]) for j in range(y or n))) for i in range(x or n))))
def ppa(a, n): print("\t".join(map(str, a[0:n])))
def ppl(a=0, x=[1]): x[0]=a or (x[0]+1); print("-"+"- -"*14+"-# "+str(x[0]-2)+" #-"+"- -"*14+"-")
def fltn(a): (i for sub in a for i in sub)
def yn(x): return "YES" if x else "NO"
def cpc(arr): return zip(arr, arr[1:])
from itertools import accumulate
from itertools import groupby
from itertools import permutations
def grp(x, key=None): return ((i, sum(1 for _ in g)) for i, g in groupby(x, key=key))
import math
def rnar(): return (*rrl(), rrl())
def rn(): return (*rrl(),)
def dpp(a, b=""): print("#| {} |#:^ {} ^:".format(a, b))
def str_join(i, sep=" "): return sep.join(map(str, i))
MOD17 = 10**9 + 7

def read():
    return (*rrl(),)

def solve(n, k):
    ans = math.ceil(k/n)
    return ans

if __name__ == "__main__":
    #test_count = rri()
    test_count = 1
    for _ in range(test_count):
        input_data = read()
        result = solve(*input_data)
        rp(result)
