The array a with n integers is given. Let's call the sequence of one or more consecutive elements in a segment. Also let's call the segment k-good if it contains no more than k different values.

Find any longest k-good segment.

As the input/output can reach huge size it is recommended to use fast input/output methods: for example, prefer to use scanf/printf instead of cin/cout in C++, prefer to use BufferedReader/PrintWriter instead of Scanner/System.out in Java.

Input

The first line contains two integers n, k (1 ≤ k ≤ n ≤ 5·105) — the number of elements in a and the parameter k.

The second line contains n integers ai (0 ≤ ai ≤ 106) — the elements of the array a.

Output

Print two integers l, r (1 ≤ l ≤ r ≤ n) — the index of the left and the index of the right ends of some k-good longest segment. If there are several longest segments you can print any of them. The elements in a are numbered from 1 to n from left to right.

Examples

Input

5 5
1 2 3 4 5


Output

1 5


Input

9 3
6 5 1 2 3 2 1 4 5


Output

3 7


Input

3 1
1 2 3


Output

1 1

def CallMyFunc():
    n = input()
    data = map(int, raw_input().split())

    res = []
    temp_arr = {}
    start = 0
    for i in range(n):
        if temp_arr.has_key(data[i]):
            temp_arr = {}
            res += [[start + 1, i + 1]]
            start = i + 1
        else:
            temp_arr[data[i]] = 1

    if len(res) == 0:
        print -1
    else:
        res[len(res) - 1][1] = n
        print len(res)
        for i in range(len(res)):
            temp_arr = res[i]
            print temp_arr[0], " ", temp_arr[1]



if __name__ == '__main__':
    CallMyFunc()
