You are given N integers A_1, A_2, ..., A_N.

Consider the sums of all non-empty subsequences of A. There are 2^N - 1 such sums, an odd number.

Let the list of these sums in non-decreasing order be S_1, S_2, ..., S_{2^N - 1}.

Find the median of this list, S_{2^{N-1}}.

Constraints

* 1 \leq N \leq 2000
* 1 \leq A_i \leq 2000
* All input values are integers.

Input

Input is given from Standard Input in the following format:


N
A_1 A_2 ... A_N


Output

Print the median of the sorted list of the sums of all non-empty subsequences of A.

Examples

Input

3
1 2 1


Output

2


Input

1
58


Output

58
#include <bits/stdc++.h>
using namespace std;

int n; bitset <4000001> dp;

int main(){
	int i, sum = 0, v;
	scanf("%d", &n);
	dp[0] = true;
	for(i = 1; i <= n; ++ i){
		scanf("%d", &v);
		dp |= dp << v;
		sum += v;
	}
	for(i = (sum + 1) >> 1; !dp[i]; ++ i) ;
	printf("%d\n", i);
	return 0;
}