The prison of your city has n prisoners. As the prison can't accommodate all of them, the city mayor has decided to transfer c of the prisoners to a prison located in another city.

For this reason, he made the n prisoners to stand in a line, with a number written on their chests. The number is the severity of the crime he/she has committed. The greater the number, the more severe his/her crime was.

Then, the mayor told you to choose the c prisoners, who will be transferred to the other prison. He also imposed two conditions. They are,

  * The chosen c prisoners has to form a contiguous segment of prisoners. 
  * Any of the chosen prisoner's crime level should not be greater then t. Because, that will make the prisoner a severe criminal and the mayor doesn't want to take the risk of his running away during the transfer. 



Find the number of ways you can choose the c prisoners.

Input

The first line of input will contain three space separated integers n (1 ≤ n ≤ 2·105), t (0 ≤ t ≤ 109) and c (1 ≤ c ≤ n). The next line will contain n space separated integers, the ith integer is the severity ith prisoner's crime. The value of crime severities will be non-negative and will not exceed 109. 

Output

Print a single integer — the number of ways you can choose the c prisoners.

Examples

Input

4 3 3
2 3 1 1


Output

2


Input

1 1 1
2


Output

0


Input

11 4 2
2 2 0 7 3 2 2 4 9 1 4


Output

6
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.ArrayList;
import java.util.StringTokenizer;

public class B {
  FastScanner in;
  PrintWriter out;

  public void run() {
    try {
      in = new FastScanner(new InputStreamReader(System.in));
      out = new PrintWriter(System.out);
      solve();
      out.close();
    } catch (IOException e) {
      e.printStackTrace();
    }
  }

  public void solve() throws IOException {
    int n = in.nextInt();
    int t = in.nextInt();
    int c = in.nextInt();
    ArrayList<Integer> aa = new ArrayList<Integer>();
    int a = 0;
    int counter = 0;
    for (int i=0; i<n; i++) {
      a = in.nextInt();
      if (a <= t) {
        counter++;
      } else {
        if (counter >= c) {
          aa.add(counter);
        }
        counter = 0;
      }
    }
    if (counter >= c) {
      aa.add(counter);
    }
    counter = 0;
    for (int k : aa) {
      counter += k - c + 1;
    }
    out.println(counter);
  }

  class FastScanner {
    BufferedReader br;
    StringTokenizer st;

    FastScanner(InputStreamReader in) {
      br = new BufferedReader(in);
    }

    String nextLine() {
      String str = null;
      try {
        str = br.readLine();
      } catch (IOException e) {
        e.printStackTrace();
      }

      return str;
    }

    String next() {
      while (st == null || !st.hasMoreTokens()) {
        try {
          st = new StringTokenizer(br.readLine());
        } catch (IOException e) {
          e.printStackTrace();
        }
      }
      return st.nextToken();
    }

    int nextInt() {
      return Integer.parseInt(next());
    }
  }

  public static void main(String[] arg) {
    B o = new B();
    o.run();
  }

}