One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.

For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two primes". Let's modify it. How about a statement like that: "each integer no less than 12 can be expressed as the sum of two composite numbers." Not like the Goldbach's conjecture, I can prove this theorem.

You are given an integer n no less than 12, express it as a sum of two composite numbers.

Input

The only line contains an integer n (12 ≤ n ≤ 106).

Output

Output two composite integers x and y (1 < x, y < n) such that x + y = n. If there are multiple solutions, you can output any of them.

Examples

Input

12


Output

4 8


Input

15


Output

6 9


Input

23


Output

8 15


Input

1000000


Output

500000 500000

Note

In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.

In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number.
#include <bits/stdc++.h>
using namespace std;
int Composite(int a) {
  int i, p = 0;
  for (int i = 1; i <= a; i++) {
    if (a % i == 0) {
      p++;
    }
  }
  if (p == 2) {
    return 0;
  } else {
    return 1;
  }
}
int main() {
  {
    int n, a, b;
    cin >> n;
    if (n % 2 == 0) {
      a = n / 2;
      b = a;
      if (Composite(a) == 1) {
        cout << a << " " << b << endl;
      } else {
        a++;
        b--;
        cout << a << " " << b << endl;
      }
    } else {
      a = ceil(float(n) / 2);
      b = floor(float(n) / 2);
      for (int i = 0; a != b; i++) {
        if ((Composite(a) == 1) && (Composite(b) == 1)) {
          cout << a << " " << b << endl;
          break;
        } else {
          a++;
          b--;
        }
      }
    }
  }
  return 0;
}
