You are given N integers A_1, A_2, ..., A_N.

Consider the sums of all non-empty subsequences of A. There are 2^N - 1 such sums, an odd number.

Let the list of these sums in non-decreasing order be S_1, S_2, ..., S_{2^N - 1}.

Find the median of this list, S_{2^{N-1}}.

Constraints

* 1 \leq N \leq 2000
* 1 \leq A_i \leq 2000
* All input values are integers.

Input

Input is given from Standard Input in the following format:


N
A_1 A_2 ... A_N


Output

Print the median of the sorted list of the sums of all non-empty subsequences of A.

Examples

Input

3
1 2 1


Output

2


Input

1
58


Output

58
#include<bits/stdc++.h>
#define F(i,a,b) for(int i=(a);i<=(b);++i)
using namespace std;
int n,x,c;
bitset<4000000> St;
int main(){
	scanf("%d",&n);
	St[0]=1;
	F(i,1,n) scanf("%d",&x), St|=St<<x;
	x=St.count();
	F(i,0,4000000){
		if(St[i]) ++c;
		if(c==x/2+1) {printf("%d",i); return 0;} 
	}
	return 0;
}