You have unlimited number of coins with values 1, 2, …, n. You want to select some set of coins having the total value of S. 

It is allowed to have multiple coins with the same value in the set. What is the minimum number of coins required to get sum S?

Input

The only line of the input contains two integers n and S (1 ≤ n ≤ 100 000, 1 ≤ S ≤ 10^9)

Output

Print exactly one integer — the minimum number of coins required to obtain sum S.

Examples

Input

5 11


Output

3

Input

6 16


Output

3

Note

In the first example, some of the possible ways to get sum 11 with 3 coins are: 

  * (3, 4, 4)
  * (2, 4, 5)
  * (1, 5, 5)
  * (3, 3, 5) 



It is impossible to get sum 11 with less than 3 coins.

In the second example, some of the possible ways to get sum 16 with 3 coins are: 

  * (5, 5, 6)
  * (4, 6, 6) 



It is impossible to get sum 16 with less than 3 coins.
# -*- coding: utf-8 -*-
import sys
import math
import os
import itertools
import string
import heapq
import _collections
from collections import Counter
from collections import defaultdict
from functools import lru_cache
import bisect
import re
import queue
from decimal import *


class Scanner():
    @staticmethod
    def int():
        return int(sys.stdin.readline().rstrip())

    @staticmethod
    def string():
        return sys.stdin.readline().rstrip()

    @staticmethod
    def map_int():
        return [int(x) for x in Scanner.string().split()]

    @staticmethod
    def string_list(n):
        return [Scanner.string() for i in range(n)]

    @staticmethod
    def int_list_list(n):
        return [Scanner.map_int() for i in range(n)]

    @staticmethod
    def int_cols_list(n):
        return [Scanner.int() for i in range(n)]


class Math():
    @staticmethod
    def gcd(a, b):
        if b == 0:
            return a
        return Math.gcd(b, a % b)

    @staticmethod
    def lcm(a, b):
        return (a * b) // Math.gcd(a, b)

    @staticmethod
    def divisor(n):
        res = []
        i = 1
        for i in range(1, int(n ** 0.5) + 1):
            if n % i == 0:
                res.append(i)
                if i != n // i:
                    res.append(n // i)
        return res

    @staticmethod
    def round_up(a, b):
        return -(-a // b)

    @staticmethod
    def is_prime(n):
        if n < 2:
            return False
        if n == 2:
            return True
        if n % 2 == 0:
            return False
        d = int(n ** 0.5) + 1
        for i in range(3, d + 1, 2):
            if n % i == 0:
                return False
        return True


def pop_count(x):
    x = x - ((x >> 1) & 0x5555555555555555)
    x = (x & 0x3333333333333333) + ((x >> 2) & 0x3333333333333333)
    x = (x + (x >> 4)) & 0x0f0f0f0f0f0f0f0f
    x = x + (x >> 8)
    x = x + (x >> 16)
    x = x + (x >> 32)
    return x & 0x0000007f


MOD = int(1e09) + 7
INF = int(1e15)


def solve():
    N, S = Scanner.map_int()
    print(Math.round_up(S, N))


def main():
    # sys.stdin = open("sample.txt")
    solve()


if __name__ == "__main__":
    main()
