One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.

For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two primes". Let's modify it. How about a statement like that: "each integer no less than 12 can be expressed as the sum of two composite numbers." Not like the Goldbach's conjecture, I can prove this theorem.

You are given an integer n no less than 12, express it as a sum of two composite numbers.

Input

The only line contains an integer n (12 ≤ n ≤ 106).

Output

Output two composite integers x and y (1 < x, y < n) such that x + y = n. If there are multiple solutions, you can output any of them.

Examples

Input

12


Output

4 8


Input

15


Output

6 9


Input

23


Output

8 15


Input

1000000


Output

500000 500000

Note

In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.

In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number.
#include <bits/stdc++.h>
using namespace std;
string tos(int a) {
  ostringstream os("");
  os << a;
  return os.str();
}
const int MAXN = 1000000;
bool isp[MAXN + 100];
int main() {
  ios_base::sync_with_stdio(0);
  for (int i = 0; i <= MAXN; ++i) isp[i] = 1;
  isp[0] = isp[1] = 1;
  for (int i = 2; i <= MAXN; ++i)
    if (isp[i])
      for (int j = i + i; j <= MAXN; j += i) isp[j] = 0;
  int n;
  while (cin >> n) {
    int x, y;
    for (int i = 2; i < MAXN; ++i) {
      x = i, y = n - x;
      if (!isp[x] && !isp[y]) break;
    }
    cout << x << ' ' << y << '\n';
  }
  return 0;
}
