You are given an array a consisting of n integers. Each a_i is one of the six following numbers: 4, 8, 15, 16, 23, 42.

Your task is to remove the minimum number of elements to make this array good.

An array of length k is called good if k is divisible by 6 and it is possible to split it into k/6 subsequences 4, 8, 15, 16, 23, 42.

Examples of good arrays:

  * [4, 8, 15, 16, 23, 42] (the whole array is a required sequence); 
  * [4, 8, 4, 15, 16, 8, 23, 15, 16, 42, 23, 42] (the first sequence is formed from first, second, fourth, fifth, seventh and tenth elements and the second one is formed from remaining elements); 
  * [] (the empty array is good). 



Examples of bad arrays: 

  * [4, 8, 15, 16, 42, 23] (the order of elements should be exactly 4, 8, 15, 16, 23, 42); 
  * [4, 8, 15, 16, 23, 42, 4] (the length of the array is not divisible by 6); 
  * [4, 8, 15, 16, 23, 42, 4, 8, 15, 16, 23, 23] (the first sequence can be formed from first six elements but the remaining array cannot form the required sequence). 

Input

The first line of the input contains one integer n (1 ≤ n ≤ 5 ⋅ 10^5) — the number of elements in a.

The second line of the input contains n integers a_1, a_2, ..., a_n (each a_i is one of the following numbers: 4, 8, 15, 16, 23, 42), where a_i is the i-th element of a.

Output

Print one integer — the minimum number of elements you have to remove to obtain a good array.

Examples

Input


5
4 8 15 16 23


Output


5


Input


12
4 8 4 15 16 8 23 15 16 42 23 42


Output


0


Input


15
4 8 4 8 15 16 8 16 23 15 16 4 42 23 42


Output


3
# Problem: C. Lose it!
# Contest: Codeforces - Codeforces Round #565 (Div. 3)
# URL: https://codeforces.com/problemset/problem/1176/C
# Memory Limit: 256 MB
# Time Limit: 2000 ms
# 
# Powered by CP Editor (https://cpeditor.org)

from sys import stdin, stdout 

def INI():
	return int(stdin.readline())
	
def INL():
	return [int(_) for _ in stdin.readline().split()]
	
def INS():
	return stdin.readline()
	
def OPS(ans):
	stdout.write(str(ans)+"\n")
	
def OPL(ans):
	[stdout.write(str(_)+" ") for _ in ans]
	stdout.write("\n")

	
if __name__=="__main__":
	n=INI()
	A=INL()
	_4, _8, _15, _16, _23, _42= [0]*6
	ans=0
	
	for _ in range(n):
		if A[_]==4:
			_4+=1
		elif A[_]==8:
			if _4>_8:
				_8+=1
		elif A[_]==15: 
			if _8>_15:
				_15+=1
		elif A[_]==16:
			if _15>_16:
				_16+=1
		elif A[_]==23: 	
			if _16>_23:
				_23+=1
		else:
			if _23>_42:
				_42+=1
			
	s=sum([_4,_8,_15,_16,_23,_42])
	OPS(n-s+sum([_-_42 for _ in [_4, _8, _15, _16, _23, _42]]))