There are N rabbits on a number line. The rabbits are conveniently numbered 1 through N. The coordinate of the initial position of rabbit i is x_i.

The rabbits will now take exercise on the number line, by performing sets described below. A set consists of M jumps. The j-th jump of a set is performed by rabbit a_j (2≤a_j≤N-1). For this jump, either rabbit a_j-1 or rabbit a_j+1 is chosen with equal probability (let the chosen rabbit be rabbit x), then rabbit a_j will jump to the symmetric point of its current position with respect to rabbit x.

The rabbits will perform K sets in succession. For each rabbit, find the expected value of the coordinate of its eventual position after K sets are performed.

Constraints

* 3≤N≤10^5
* x_i is an integer.
* |x_i|≤10^9
* 1≤M≤10^5
* 2≤a_j≤N-1
* 1≤K≤10^{18}

Input

The input is given from Standard Input in the following format:


N
x_1 x_2 ... x_N
M K
a_1 a_2 ... a_M


Output

Print N lines. The i-th line should contain the expected value of the coordinate of the eventual position of rabbit i after K sets are performed. The output is considered correct if the absolute or relative error is at most 10^{-9}.

Examples

Input

3
-1 0 2
1 1
2


Output

-1.0
1.0
2.0


Input

3
1 -1 1
2 2
2 2


Output

1.0
-1.0
1.0


Input

5
0 1 3 6 10
3 10
2 3 4


Output

0.0
3.0
7.0
8.0
10.0
#include<bits/stdc++.h>
using namespace std;

const int N = 1e5 + 9;

int n, x[N], f[N], m, g[N], ans[N];
long long k;

int main () {
	scanf("%d", &n);
	for (int i = 1; i <= n; ++i) scanf("%d", &x[i]), f[i] = ans[i] = i;
	scanf("%d%lld", &m, &k);
	for (int i = 1, a; i <= m; ++i) scanf("%d", &a), swap(f[a], f[a - 1]);
	for (; k; k >>= 1) {
		if (k & 1) {
			for (int i = 1; i < n; ++i) g[i] = ans[f[i]];
			for (int i = 1; i < n; ++i) ans[i] = g[i];
		}
		for (int i = 1; i < n; ++i) g[i] = f[f[i]];
		for (int i = 1; i < n; ++i) f[i] = g[i];
	}
	long long s = x[1];
	for (int i = 1; i <= n; ++i) {
		printf("%lld\n", s);
		s += x[ans[i] + 1] - x[ans[i]];
	}
	return  0;
}