For a given polygon g and target points t, print "2" if g contains t, "1" if t is on a segment of g, "0" otherwise.

g is represented by a sequence of points p1, p2,..., pn where line segments connecting pi and pi+1 (1 ≤ i ≤ n-1) are sides of the polygon. The line segment connecting pn and p1 is also a side of the polygon.

Note that the polygon is not necessarily convex.

Constraints

* 3 ≤ n ≤ 100
* 1 ≤ q ≤ 1000
* -10000 ≤ xi, yi ≤ 10000
* No point of the polygon will occur more than once.
* Two sides of the polygon can intersect only at a common endpoint.

Input

The entire input looks like:


g (the sequence of the points of the polygon)
q (the number of queris = the number of target points)
1st query
2nd query
:
qth query


g is given by coordinates of the points p1,..., pn in the following format:


n
x1 y1
x2 y2
:
xn yn


The first integer n is the number of points. The coordinate of a point pi is given by two integers xi and yi. The coordinates of points are given in the order of counter-clockwise visit of them.

Each query consists of the coordinate of a target point t. The coordinate is given by two intgers x and y.

Output

For each query, print "2", "1" or "0".

Example

Input

4
0 0
3 1
2 3
0 3
3
2 1
0 2
3 2


Output

2
1
0
#include "bits/stdc++.h"
using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
#define INF 1<<30
#define LINF 1LL<<60

typedef long double ld;
typedef complex<ld> Point;
const ld eps = 1e-9, pi = acos(-1.0);
namespace std {
    bool operator<(const Point &lhs, const Point &rhs) {
        if (lhs.real() < rhs.real() - eps) return true;
        if (lhs.real() > rhs.real() + eps) return false;
        return lhs.imag() < rhs.imag();
    }
}
Point input_point() {ld x, y; cin >> x >> y; return Point(x, y);} // ????????\???
bool eq(ld a, ld b) {return (abs(a - b) < eps);} // ????????????????????????
ld dot(Point a, Point b) {return real(conj(a) * b);} // ??????
ld cross(Point a, Point b) {return imag(conj(a) * b);} // ??????

// ??´????????????
class Line {
public:
    Point a, b;
    Line() : a(Point(0, 0)), b(Point(0, 0)) {}
    Line(Point a, Point b) : a(a), b(b) {}
    Point operator[](const int _num) {
        if (_num == 0)return a;
        else if (_num == 1)return b;
        else assert(false);
    }
};

// ????????????
class Circle {
public:
    Point p;
    ld r;
    Circle() : p(Point(0, 0)), r(0) {}
    Circle(Point p, ld r) : p(p), r(r) {}
};

// ??????????¶?
Point proj(Line l, Point p) {
    ld t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);
    return l.a + t * (l.a - l.b);
}

// CCW
int ccw(Point a, Point b, Point c) {
    b -= a; c -= a;
    if (cross(b, c) > eps) return 1;   // a,b,c??????????¨???¨?????????????????¶
    if (cross(b, c) < -eps) return -1; // a,b,c???????¨???¨?????????????????¶
    if (dot(b, c) < 0) return 2;       // c,a,b???????????´???????????¶
    if (norm(b) < norm(c)) return -2;  // a,b,c???????????´???????????¶
    return 0;                          // a,c,b???????????´???????????¶
}

/* ???????????? */
// ??´?????¨??´??????????????????
bool isis_ll(Line l, Line m) {return !eq(cross(l.b - l.a, m.b - m.a), 0);}
// ??´?????¨?????????????????????
bool isis_ls(Line l, Line s) {
    return isis_ll(l, s) &&
    (cross(l.b - l.a, s.a - l.a) * cross(l.b - l.a, s.b - l.a) < eps);
}
// ????????¨?????????????????????
bool isis_ss(Line s, Line t) {
    return ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 &&
    ccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;
}
// ????????´????????????
bool isis_lp(Line l, Point p) {return (abs(cross(l.b - p, l.a - p)) < eps);}
// ?????????????????????
bool isis_sp(Line s, Point p) {return (abs(s.a - p) + abs(s.b - p) - abs(s.b - s.a) < eps);}


/* ????§???¢ */
typedef vector<Point> Polygon;
// ??????????????????
//  2 => out
//  0 => on
//  1 => in
int is_in_polygon(const Polygon &poly, Point p) {
    ld angle = 0;
    int n = (int)poly.size();
    for (int i = 0;i < n;i++) {
        Point a = poly[i], b = poly[(i + 1) % n];
        if (isis_sp(Line(a, b), p)) return 1;
        angle += arg((b - p) / (a - p));
    }
    return eq(angle, 0) ? 0 : 2;
}

int main(void) {
    cin.tie(0); ios::sync_with_stdio(false);
    int n; cin >> n;
    Polygon ps;
    for(int i = 0; i < n;i++) ps.emplace_back(input_point());
    int q; cin >> q;
    for(int i = 0; i < q;i++){
        cout << is_in_polygon(ps,input_point()) << endl;
    }
    return 0;
}