Rohit was doing the work of his math class about three days but he is tired of make operations a lot and he should deliver his task tomorrow. His math’s teacher gives two numbers a and b. The problem consist in find the last digit of the potency of base a and index b. Help Rohit with his problem. You are given two integer numbers: the base a (number of digits d, such that 1 ≤ d ≤ 1000) and the index b (0 ≤ b ≤ 922*10^15). You
have to find the last digit of a^b.

Input

The first line of input contains an integer t, the number of test cases (t ≤ 30). t test cases follow. For each test case will appear a and b separated by space.

Output

For each test case output an integer per line representing the result.

SAMPLE INPUT
3
3 10
6 2
150 53

SAMPLE OUTPUT
9
6
0
t=int(raw_input())
ans=[]
for i in range(t):
	ao,bo=raw_input().split()
	a=int(ao)
	b=int(bo)
	if ao[len(ao)-1]==0:
		ans.append(0)
	if ao[len(ao)-1]==1:
		ans.append(1)
	else:
		last=int(ao[len(ao)-1])
		temp=str(last**b)
		ans.append(int(temp[len(temp)-1]))
for x in ans:
	print x