Let's write all the positive integer numbers one after another from 1 without any delimiters (i.e. as a single string). It will be the infinite sequence starting with 123456789101112131415161718192021222324252627282930313233343536...

Your task is to print the k-th digit of this sequence.

Input

The first and only line contains integer k (1 ≤ k ≤ 10000) — the position to process (1-based index).

Output

Print the k-th digit of the resulting infinite sequence.

Examples

Input


7


Output


7


Input


21


Output


5
from math import ceil   
n=int(input())
if n<=9:
    print(n)
else:
    d=2
    ov=9
    while n>d*9*(10**(d-1))+ov:
        ov=d*9*(10**(d-1))+ov
        d+=1
    v=ceil((n-ov)/d)+int('9'*(d-1))
    print(str(v)[(n-ov-1)%d])