You are given an integer n and an integer k.

In one step you can do one of the following moves: 

  * decrease n by 1; 
  * divide n by k if n is divisible by k. 



For example, if n = 27 and k = 3 you can do the following steps: 27 → 26 → 25 → 24 → 8 → 7 → 6 → 2 → 1 → 0.

You are asked to calculate the minimum number of steps to reach 0 from n. 

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of queries.

The only line of each query contains two integers n and k (1 ≤ n ≤ 10^{18}, 2 ≤ k ≤ 10^{18}).

Output

For each query print the minimum number of steps to reach 0 from n in single line. 

Example

Input


2
59 3
1000000000000000000 10


Output


8
19

Note

Steps for the first test case are: 59 → 58 → 57 → 19 → 18 → 6 → 2 → 1 → 0.

In the second test case you have to divide n by k 18 times and then decrease n by 1.
from collections import Counter as D, defaultdict as dd
from math import factorial as ft, ceil as aron, log
from fractions import gcd as pg 
from bisect import insort as ins, bisect_left as bl, bisect_right as br
import sys

#sys.stdin=open("./testfile1.py","r")
raw_input=sys.stdin.readline

f1=lambda : map(int,raw_input().split())
f2=lambda : map(int,list(raw_input()))
f3=lambda : int(raw_input())
f4=lambda : raw_input().rstrip()




def main():
    
    for _ in xrange(f3()):
        n,k=f1()
        ans=0
        while n>0:
            if n%k>0:
                ans+=n%k
                n=n-n%k
            else:
                ans+=1
                n/=k
        print ans

	


if __name__ == '__main__':
	main()