Let's write all the positive integer numbers one after another from 1 without any delimiters (i.e. as a single string). It will be the infinite sequence starting with 123456789101112131415161718192021222324252627282930313233343536...

Your task is to print the k-th digit of this sequence.

Input

The first and only line contains integer k (1 ≤ k ≤ 10000) — the position to process (1-based index).

Output

Print the k-th digit of the resulting infinite sequence.

Examples

Input


7


Output


7


Input


21


Output


5
import math
n=int(input())
# 99-9
# 999-99
a=[9]
for i in range(2,20):
    a.append(10**i   - 10**(i-1) )
b=[0]
for i in range(1,20):
    b.append(b[-1]+ i*a[i-1])
for i in range(20):
    if n<=b[i]:
        break
p=b[i-1]
k=n-p
# print(p,k)
ans=10**(i-1) - 1 + math.ceil(k/(i))
# print(k,p,i)
# print(ans,i,k)
if k%i==0:
    print(('0'+str(ans))[i])
else:
    print(('0'+str(ans))[k%i])