There are n piles of stones, where the i-th pile has a_i stones. Two people play a game, where they take alternating turns removing stones.

In a move, a player may remove a positive number of stones from the first non-empty pile (the pile with the minimal index, that has at least one stone). The first player who cannot make a move (because all piles are empty) loses the game. If both players play optimally, determine the winner of the game.

Input

The first line contains a single integer t (1≤ t≤ 1000) — the number of test cases. Next 2t lines contain descriptions of test cases.

The first line of each test case contains a single integer n (1≤ n≤ 10^5) — the number of piles.

The second line of each test case contains n integers a_1,…,a_n (1≤ a_i≤ 10^9) — a_i is equal to the number of stones in the i-th pile.

It is guaranteed that the sum of n for all test cases does not exceed 10^5.

Output

For each test case, if the player who makes the first move will win, output "First". Otherwise, output "Second".

Example

Input


7
3
2 5 4
8
1 1 1 1 1 1 1 1
6
1 2 3 4 5 6
6
1 1 2 1 2 2
1
1000000000
5
1 2 2 1 1
3
1 1 1


Output


First
Second
Second
First
First
Second
First

Note

In the first test case, the first player will win the game. His winning strategy is: 

  1. The first player should take the stones from the first pile. He will take 1 stone. The numbers of stones in piles will be [1, 5, 4]. 
  2. The second player should take the stones from the first pile. He will take 1 stone because he can't take any other number of stones. The numbers of stones in piles will be [0, 5, 4]. 
  3. The first player should take the stones from the second pile because the first pile is empty. He will take 4 stones. The numbers of stones in piles will be [0, 1, 4]. 
  4. The second player should take the stones from the second pile because the first pile is empty. He will take 1 stone because he can't take any other number of stones. The numbers of stones in piles will be [0, 0, 4]. 
  5. The first player should take the stones from the third pile because the first and second piles are empty. He will take 4 stones. The numbers of stones in piles will be [0, 0, 0]. 
  6. The second player will lose the game because all piles will be empty. 

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.Arrays;
import java.util.StringTokenizer;

public final class CodeForces658B {

    public static void main(String args[]) {
        FastReader sc = new FastReader();
        PrintWriter out = new PrintWriter(System.out);
        int t = sc.nextInt();
        while (t-- > 0) {
            int n = sc.nextInt();
            int a[] = new int[n];
            int max = 0;
            int s = 0;
            int startOne = 0;
            for (int i = 0; i < n; i++) {
                s = sc.nextInt();
                //if(s>0)
                    a[max++] = s;
            }
            
            for (int i = 0; i < n-1; i++) {
                if(a[i]==1){
                    startOne++;
                }
                else{
                    break;
                }
            }
            if(startOne%2!=0 && n!=1){
                System.out.println("Second");
            }
            else{
                System.out.println("First");
            }
            /*int chance = 1;
            int lastCheck = 0;
            while (lastCheck<max) {
                if (a[lastCheck] == 0) {
                    lastCheck++;
                    continue;
                }
                if (a[lastCheck] == 1) {
                    a[lastCheck] = 0;
                    lastCheck++;
                } else if (lastCheck+1==max) {
                    a[lastCheck] = 0;
                    lastCheck++;
                }
                else if (lastCheck+1!=max && a[lastCheck] != 1 && a[lastCheck + 1] == 1) {
                    a[lastCheck] = 0;
                    lastCheck++;
                } else {
                    a[lastCheck]=1;
                }
                if (chance == 1) {
                    chance = 2;
                } else {
                    chance = 1;
                }
                //System.out.println(Arrays.toString(a));
            }
            if(chance==1){
                System.out.println("Second");
            }
            else{
                System.out.println("First");
        }*/
        }
        out.flush();
        out.close();
    }

    static class FastReader {

        BufferedReader br;
        StringTokenizer st;

        public FastReader() {
            br = new BufferedReader(new InputStreamReader(System.in));
        }

        String next() {
            while (st == null || !st.hasMoreElements()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                }
            }
            return st.nextToken();
        }

        int nextInt() {
            return Integer.parseInt(next());
        }

        long nextLong() {
            return Long.parseLong(next());
        }

        double nextDouble() {
            return Double.parseDouble(next());
        }

        String nextLine() {
            String str = "";
            try {
                str = br.readLine();
            } catch (IOException e) {

            }
            return str;
        }
    }
}
