There is a building with n rooms, numbered 1 to n.

We can move from any room to any other room in the building.

Let us call the following event a move: a person in some room i goes to another room j~ (i \neq j).

Initially, there was one person in each room in the building.

After that, we know that there were exactly k moves happened up to now.

We are interested in the number of people in each of the n rooms now. How many combinations of numbers of people in the n rooms are possible?

Find the count modulo (10^9 + 7).

Constraints

* All values in input are integers.
* 3 \leq n \leq 2 \times 10^5
* 2 \leq k \leq 10^9

Input

Input is given from Standard Input in the following format:


n k


Output

Print the number of possible combinations of numbers of people in the n rooms now, modulo (10^9 + 7).

Examples

Input

3 2


Output

10


Input

200000 1000000000


Output

607923868


Input

15 6


Output

22583772
N=2*10**5+3
mod=10**9+7
fac=[1]*(N+1)
for i in range(1,N+1):
    fac[i]=fac[i-1]*i%mod
inv_fac=[1]*(N+1)
inv_fac[N]=pow(fac[N],mod-2,mod)
for i in range(N-1,0,-1):
    inv_fac[i]=inv_fac[i+1]*(i+1)%mod
def nCr(n,r):
    if n<=0 or r<0 or r>n:
        return 0
    return fac[n]*inv_fac[r]%mod*inv_fac[n-r]%mod

n,k=map(int,input().split())
def count(n,x):
    ret=nCr(n,x)*nCr(n-1,n-x-1)%mod
    return ret

ans=0
x=0
if k==1:
    x=1
while x<=k and x<n:
    ans=(ans+count(n,x))%mod
    x+=1
print(ans)