Rohit was doing the work of his math class about three days but he is tired of make operations a lot and he should deliver his task tomorrow. His math’s teacher gives two numbers a and b. The problem consist in find the last digit of the potency of base a and index b. Help Rohit with his problem. You are given two integer numbers: the base a (number of digits d, such that 1 ≤ d ≤ 1000) and the index b (0 ≤ b ≤ 922*10^15). You
have to find the last digit of a^b.

Input

The first line of input contains an integer t, the number of test cases (t ≤ 30). t test cases follow. For each test case will appear a and b separated by space.

Output

For each test case output an integer per line representing the result.

SAMPLE INPUT
3
3 10
6 2
150 53

SAMPLE OUTPUT
9
6
0
from math import pow

def getLastDigit(n):
    return n%10

tc = int(raw_input())

for i in range(tc):
    s = raw_input().strip()
    l = s.split()
    a,b = int(l[0]),int(l[1])
    last_digit = getLastDigit(a)
    fourth_power = b%4
    if fourth_power == 0:
        fourth_power = 4
    ans = int(pow(last_digit,fourth_power))
    print getLastDigit(ans)