In the beginning of the new year Keivan decided to reverse his name. He doesn't like palindromes, so he changed Naviek to Navick.

He is too selfish, so for a given n he wants to obtain a string of n characters, each of which is either 'a', 'b' or 'c', with no palindromes of length 3 appearing in the string as a substring. For example, the strings "abc" and "abca" suit him, while the string "aba" doesn't. He also want the number of letters 'c' in his string to be as little as possible.

Input

The first line contains single integer n (1 ≤ n ≤ 2·105) — the length of the string.

Output

Print the string that satisfies all the constraints.

If there are multiple answers, print any of them.

Examples

Input

2


Output

aa


Input

3


Output

bba

Note

A palindrome is a sequence of characters which reads the same backward and forward.

import java.util.*;
import java.lang.*;
import java.io.*;

public class Te2 {
	static int imax = Integer.MAX_VALUE, imin = Integer.MIN_VALUE;
	static long lmax = Long.MAX_VALUE, lmin = Long.MIN_VALUE;
	static long mod = (long) 1e9 + 7;
	static File inFile = new File("input.txt");

	public static void main(String[] args) throws java.lang.Exception {

		new Thread(null, new Runnable() {
			public void run() {
				try {
					solve();
				} catch (Exception e) {
					e.printStackTrace();
				}
			}
		}, "1", 1 << 26).start();

	}

	static void solve() {
		InputReader in = new InputReader(System.in);
		PrintWriter out = new PrintWriter(System.out);
		// int test = in.ni();
		int test = 1;
		while (test-- > 0) {
			int n = in.ni();
			for (int i = 0; i < n / 4; i++) {
				out.print("aabb");
			}
			if (n % 4 == 1) {
				out.print("a");
			} else if (n % 4 == 2) {
				out.print("aa");
			} else if (n % 4 == 3) {
				out.print("aab");
			}
		}
		out.close();
	}

	static class Pair {
		int x, y;

		Pair(int x, int y) {
			this.x = x;
			this.y = y;
		}

		public String toString() {
			return x + " " + y;
		}

	}

	static void print(int arr[], int len) {
		for (int i = 0; i < len; i++)
			System.out.print(arr[i] + " ");
		System.out.println();
	}

	static class InputReader {

		private InputStream stream;
		private byte[] buf = new byte[1024];
		private int curChar;
		private int numChars;

		public InputReader(InputStream stream) {
			this.stream = stream;
		}

		public int read() {
			if (numChars == -1)
				throw new InputMismatchException();
			if (curChar >= numChars) {
				curChar = 0;
				try {
					numChars = stream.read(buf);
				} catch (IOException e) {
					throw new InputMismatchException();
				}
				if (numChars <= 0)
					return -1;
			}
			return buf[curChar++];
		}

		public int ni() {
			int c = read();
			while (isSpaceChar(c))
				c = read();
			int sgn = 1;
			if (c == '-') {
				sgn = -1;
				c = read();
			}
			int res = 0;
			do {
				if (c < '0' || c > '9')
					throw new InputMismatchException();
				res *= 10;
				res += c & 15;
				c = read();
			} while (!isSpaceChar(c));
			return res * sgn;
		}

		public long nl() {
			int c = read();
			while (isSpaceChar(c))
				c = read();
			int sgn = 1;
			if (c == '-') {
				sgn = -1;
				c = read();
			}
			long res = 0;
			do {
				if (c < '0' || c > '9')
					throw new InputMismatchException();
				res *= 10;
				res += c & 15;
				c = read();
			} while (!isSpaceChar(c));
			return res * sgn;
		}

		public String ns() {
			int c = read();
			while (isSpaceChar(c))
				c = read();
			StringBuilder res = new StringBuilder();
			do {
				res.appendCodePoint(c);
				c = read();
			} while (!isSpaceChar(c));
			return res.toString();
		}

		public char[] ncs() {
			return ns().toCharArray();
		}

		public String nLine() {
			int c = read();
			// while (c != '\n' && c != '\r' && c != '\t' && c != -1)
			// c = read();
			StringBuilder res = new StringBuilder();
			do {
				res.appendCodePoint(c);
				c = read();
			} while (c != '\n' && c != '\r' && c != '\t' && c != -1);
			return res.toString();
		}

		public static boolean isSpaceChar(int c) {
			return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1;
		}

	}

}
