Ayoub had an array a of integers of size n and this array had two interesting properties: 

  * All the integers in the array were between l and r (inclusive). 
  * The sum of all the elements was divisible by 3. 



Unfortunately, Ayoub has lost his array, but he remembers the size of the array n and the numbers l and r, so he asked you to find the number of ways to restore the array. 

Since the answer could be very large, print it modulo 10^9 + 7 (i.e. the remainder when dividing by 10^9 + 7). In case there are no satisfying arrays (Ayoub has a wrong memory), print 0.

Input

The first and only line contains three integers n, l and r (1 ≤ n ≤ 2 ⋅ 10^5 , 1 ≤ l ≤ r ≤ 10^9) — the size of the lost array and the range of numbers in the array.

Output

Print the remainder when dividing by 10^9 + 7 the number of ways to restore the array.

Examples

Input


2 1 3


Output


3


Input


3 2 2


Output


1


Input


9 9 99


Output


711426616

Note

In the first example, the possible arrays are : [1,2], [2,1], [3, 3].

In the second example, the only possible array is [2, 2, 2].
//  package cp;
import java.io.*;
import java.math.*;
import java.util.*;
public class Cf_three {
	long gcd(long a,long b) {if(b==0)return a;else return gcd(b,a%b);}
	void swap(long a,long b) {long temp=a;a=b;b=temp;}
	StringBuilder sb=new StringBuilder();
	Integer[] ARR=new Integer[5];
	//Integer sort-TLE-Initialize object elements i.e a[0].
	void divisor(long n,int start) {
		int cnt=0;for(int i=start;i<=Math.sqrt(n);i++) {
		if(n%i==0) {if(i==n/i)cnt++;else cnt+=2;}}}
	
	public static void main(String[] args) throws IOException {	
		PrintWriter out = new PrintWriter(System.out);
		Readers.init(System.in);
		Cf_three obj=new Cf_three();
		int n=Readers.nextInt();long l=Readers.nextLong();long r=Readers.nextLong();
		long[][] dp=new long[n+1][3];long[] arr=new long[3];
		long count=(r-l+1)/3;arr[0]=count;arr[1]=count;arr[2]=count;
		long extra=(r-l+1)%3;long start=l%3;
		if(extra==1)arr[(int)start]++;
		if(extra==2) {arr[(int)start]++;arr[(int)(start+1)%3]++;}
		int m=(int) (1e9+7);
		for (int i = 0; i <=n ; i++) {
			for (int j = 0; j <3; j++) {
				if(i==0)dp[i][j]=0;
				else if(i==1)dp[i][j]=arr[j];
				else {
					dp[i][j]=(dp[i-1][(3-j)%3]*arr[(3-j)%3]+
							dp[i-1][(4-j)%3]*arr[(5-j)%3]+
							dp[i-1][(5-j)%3]*arr[(4-j)%3])%m;
				}
			}
		}
		System.out.println(dp[n][0]);
		out.flush();
	}
}
class Readers {
 
    static BufferedReader reader;
 
    static StringTokenizer tokenizer;
 
 
 
    /** call this method to initialize reader for InputStream */
 
    static void init(InputStream input) {
 
        reader = new BufferedReader(
 
                     new InputStreamReader(input) );
 
        tokenizer = new StringTokenizer("");
 
    }
 
 
 
    /** get next word */
 
    static String next() throws IOException {
 
        while ( ! tokenizer.hasMoreTokens() ) {
 
            //TODO add check for eof if necessary
 
            tokenizer = new StringTokenizer(
 
                   reader.readLine() );
 
        }
 
        return tokenizer.nextToken();
 
    }
 
 
 
    static int nextInt() throws IOException {
 
        return Integer.parseInt( next() );
 
    }
 
	
 
    static double nextDouble() throws IOException {
 
        return Double.parseDouble( next() );
 
    }
    
    
    static long nextLong() throws IOException{
    	
		return Long.parseLong(next());
	}
 
}