Let's write all the positive integer numbers one after another from 1 without any delimiters (i.e. as a single string). It will be the infinite sequence starting with 123456789101112131415161718192021222324252627282930313233343536...

Your task is to print the k-th digit of this sequence.

Input

The first and only line contains integer k (1 ≤ k ≤ 10000) — the position to process (1-based index).

Output

Print the k-th digit of the resulting infinite sequence.

Examples

Input


7


Output


7


Input


21


Output


5
from math import floor
from sys import stdin

CONST = 9

def solve(k):
    i = 0
    while k > CONST * (10 ** i) * (i + 1):
        k -= floor(CONST * (10 ** i)) * (i + 1)
        i += 1
    num_digits = i + 1
    num = floor((k - 1) / num_digits)
    num += floor(10 ** (i))
    print(('{}'.format(num))[(k - 1) % num_digits])

if __name__ == '__main__':
    for line in stdin:
        solve(int(line.rstrip()))