You are given an integer n and an integer k.

In one step you can do one of the following moves: 

  * decrease n by 1; 
  * divide n by k if n is divisible by k. 



For example, if n = 27 and k = 3 you can do the following steps: 27 → 26 → 25 → 24 → 8 → 7 → 6 → 2 → 1 → 0.

You are asked to calculate the minimum number of steps to reach 0 from n. 

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of queries.

The only line of each query contains two integers n and k (1 ≤ n ≤ 10^{18}, 2 ≤ k ≤ 10^{18}).

Output

For each query print the minimum number of steps to reach 0 from n in single line. 

Example

Input


2
59 3
1000000000000000000 10


Output


8
19

Note

Steps for the first test case are: 59 → 58 → 57 → 19 → 18 → 6 → 2 → 1 → 0.

In the second test case you have to divide n by k 18 times and then decrease n by 1.
# coding: UTF-8
import sys
#sys.setrecursionlimit(n)
import heapq
import re
import bisect
import random
import math
import itertools
from collections import defaultdict, deque
from copy import deepcopy
from decimal import *

readl= lambda: list(map(int, sys.stdin.readline().split()))
readt= lambda: tuple(map(int, sys.stdin.readline().split()))
read = lambda: sys.stdin.readline().rstrip()
readi = lambda: int(read())
readmi = lambda: map(int, sys.stdin.readline().split())
readms = lambda: map(str, sys.stdin.readline().split())

n = readi()
for i in range(n):
    m, k = readmi()
    count = 0
    while(m > 0):
        if m % k == 0:
            count += 1
            m //= k
        else:
            t = m % k
            count += t
            m -= t
    print(count)
