In the beginning of the new year Keivan decided to reverse his name. He doesn't like palindromes, so he changed Naviek to Navick.

He is too selfish, so for a given n he wants to obtain a string of n characters, each of which is either 'a', 'b' or 'c', with no palindromes of length 3 appearing in the string as a substring. For example, the strings "abc" and "abca" suit him, while the string "aba" doesn't. He also want the number of letters 'c' in his string to be as little as possible.

Input

The first line contains single integer n (1 ≤ n ≤ 2·105) — the length of the string.

Output

Print the string that satisfies all the constraints.

If there are multiple answers, print any of them.

Examples

Input

2


Output

aa


Input

3


Output

bba

Note

A palindrome is a sequence of characters which reads the same backward and forward.
# sys.setrecursionlimit(300000)
import sys
def main():
    pass
def binary(n):
    # decimal to binary
    return (bin(n).replace("0b", ""))
def decimal(s):
    # binary to decimal
    return (int(s, 2))
def pow2(n):
    # power of a number base 2
    p = 0
    while n > 1:
        n //= 2
        p += 1
    return (p)
def isPrime(n):
    # if  number is prime in √n time
    if (n == 1):
        return (False)
    else:
        root = int(n ** 0.5)
        root += 1
        for i in range(2, root):
            if (n % i == 0):
                return (False)
        return (True)
def lts(l):
    # list to string ,no spaces
    s = ''.join(map(str, l))
    return s
def stl(s):
    # for each character in string to list with no spaces -->
    l = list(s)
    # for space in string  -->
    # l=list(s.split(" "))
    return l
# Returns list of numbers with a particular sum
def sq(a, target, arr=[]):
    s = sum(arr)
    if (s == target):
        return arr
    if (s >= target):
        return
    for i in range(len(a)):
        n = a[i]
        remaining = a[i + 1:]
        ans = sq(remaining, target, arr + [n])
        if (ans):
            return ans
# 1000000007
mod = int(1e9) + 7
def ssinp(): return sys.stdin.readline().strip()
#s=input()
def iinp(): return int(input())
#n=int(input())
def nninp(): return map(int, sys.stdin.readline().strip().split())
#n, m, a=[int(x) for x in input().split()]
def llinp(): return list(map(int, sys.stdin.readline().strip().split()))
#a=list(map(int,input().split()))
def p(xyz): print(xyz)
def p2(a, b): print(a, b)
import math
from collections import OrderedDict
#for _ in range(iinp()):
n=iinp()
print(("aabb"*n)[:n])

