Let's write all the positive integer numbers one after another from 1 without any delimiters (i.e. as a single string). It will be the infinite sequence starting with 123456789101112131415161718192021222324252627282930313233343536...

Your task is to print the k-th digit of this sequence.

Input

The first and only line contains integer k (1 ≤ k ≤ 10000) — the position to process (1-based index).

Output

Print the k-th digit of the resulting infinite sequence.

Examples

Input


7


Output


7


Input


21


Output


5
#include <bits/stdc++.h>
using namespace std;
int ROW[] = {+1, -1, +0, +0};
int COL[] = {+0, +0, +1, -1};
int X[] = {+0, +0, +1, -1, -1, +1, -1, +1};
int Y[] = {-1, +1, +0, +0, +1, +1, -1, -1};
int KX[] = {-2, -2, -1, -1, 1, 1, 2, 2};
int KY[] = {-1, 1, -2, 2, -2, 2, -1, 1};
long long GCD(long long a, long long b) { return b == 0 ? a : GCD(b, a % b); }
int LCM(int a, int b) { return a * (b / GCD(a, b)); }
bool CMP(int a, int b) { return a > b; }
int main() {
  int n;
  cin >> n;
  string s = "";
  for (int i = 1; i <= 10000; i++) s += to_string(i);
  cout << s[n - 1] << endl;
  return 0;
}
