Let's write all the positive integer numbers one after another from 1 without any delimiters (i.e. as a single string). It will be the infinite sequence starting with 123456789101112131415161718192021222324252627282930313233343536...

Your task is to print the k-th digit of this sequence.

Input

The first and only line contains integer k (1 ≤ k ≤ 10000) — the position to process (1-based index).

Output

Print the k-th digit of the resulting infinite sequence.

Examples

Input


7


Output


7


Input


21


Output


5
    import java.util.Scanner;
     
    public class ABC {
        public static void main(String[] args){
     
            Scanner sc=new Scanner(System.in);
            long k,c,n,d;
            c=1;
            d=9;
            n=1;
            k= sc.nextLong();
            while(k>(c*d)) {
                k-=(c*d);
                n*=10;
                d*=10;
                c++;
            }
            n+=(k-1)/c;
            char[] num = String.valueOf(n).toCharArray();
            System.out.println(num[(int)((k-1)%c)]);
        }
     
    }


				 	     		 	 			   	 	  	  	