Let's write all the positive integer numbers one after another from 1 without any delimiters (i.e. as a single string). It will be the infinite sequence starting with 123456789101112131415161718192021222324252627282930313233343536...

Your task is to print the k-th digit of this sequence.

Input

The first and only line contains integer k (1 ≤ k ≤ 10000) — the position to process (1-based index).

Output

Print the k-th digit of the resulting infinite sequence.

Examples

Input


7


Output


7


Input


21


Output


5
#include <bits/stdc++.h>
using namespace std;
const int maxn = 1e5 + 50;
int main() {
  ios::sync_with_stdio(false);
  long long k;
  cin >> k;
  long long now = 9;
  long long cnt = 1;
  while (k > 0) {
    k -= now * cnt;
    now *= 10;
    ++cnt;
  }
  now /= 10;
  cnt--;
  k += now * cnt;
  long long a = (k - 1) / cnt;
  long long b = (k - 1) % cnt + 1;
  long long c = 1;
  for (int i = 1; i < cnt; i++) {
    c *= 10;
  }
  if (b == 0) --a;
  c += a;
  for (int i = 1; i <= cnt - b; i++) c /= 10;
  cout << c % 10 << endl;
  return 0;
}
