We have a grid of squares with N rows and M columns. Let (i, j) denote the square at the i-th row from the top and j-th column from the left. We will choose K of the squares and put a piece on each of them.

If we place the K pieces on squares (x_1, y_1), (x_2, y_2), ..., and (x_K, y_K), the cost of this arrangement is computed as:

\sum_{i=1}^{K-1} \sum_{j=i+1}^K (|x_i - x_j| + |y_i - y_j|)

Find the sum of the costs of all possible arrangements of the pieces. Since this value can be tremendous, print it modulo 10^9+7.

We consider two arrangements of the pieces different if and only if there is a square that contains a piece in one of the arrangements but not in the other.

Constraints

* 2 \leq N \times M \leq 2 \times 10^5
* 2 \leq K \leq N \times M
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N M K


Output

Print the sum of the costs of all possible arrangements of the pieces, modulo 10^9+7.

Examples

Input

2 2 2


Output

8


Input

4 5 4


Output

87210


Input

100 100 5000


Output

817260251
def framod(n, mod, a=1):
    for i in range(1,n+1):
        a=a * i % mod
    return a

def power(n, r, mod):
    if r == 0: return 1
    if r%2 == 0:
        return power(n*n % mod, r//2, mod) % mod
    if r%2 == 1:
        return n * power(n, r-1, mod) % mod

def comb(n, k, mod):
    a=framod(n, mod)
    b=framod(k, mod)
    c=framod(n-k, mod)
    return (a * power(b, mod-2, mod) * power(c, mod-2, mod)) % mod

N, M, K = map(int, input().split())

ans = 0

for i in range(1, M):
    ans += (i * (M-i) * N**2) % (10**9 + 7) 
for i in range(1, N):
    ans += (i * (N-i) * M**2) % (10**9 + 7)

ans *= comb(N*M-2 , K-2, 10**9+7)

print(int(ans % (10**9+7)))

