Let's write all the positive integer numbers one after another from 1 without any delimiters (i.e. as a single string). It will be the infinite sequence starting with 123456789101112131415161718192021222324252627282930313233343536...

Your task is to print the k-th digit of this sequence.

Input

The first and only line contains integer k (1 ≤ k ≤ 10000) — the position to process (1-based index).

Output

Print the k-th digit of the resulting infinite sequence.

Examples

Input


7


Output


7


Input


21


Output


5
import java.util.*;
import java.io.*;


public class A1177{
	public static void main(String args[])throws IOException{
		Scanner sc=new Scanner(new BufferedReader(new InputStreamReader(System.in)));
		PrintWriter pw=new PrintWriter(System.out);
		int n=sc.nextInt();
		int d=1;
		int count=0;
		while(n>0){
			int p=(int)Math.pow(10,d);
			int c=(int)Math.pow(10,d-1);	
			int no=p-c;
			if(n>no*d){
				n-=(no*d);
			}
			else{
				c+=(n/d);
				n%=d;
				if(n==0){
					c--;
					pw.println(c%10);
				}
				else{
					pw.println(Integer.toString(c).charAt(n-1));
				}
					break;
			}
			d++;
		}
		pw.close();
	}
}