Snuke has a permutation (P_0,P_1,\cdots,P_{N-1}) of (0,1,\cdots,N-1).

Now, he will perform the following operation exactly once:

* Choose K consecutive elements in P and sort them in ascending order.



Find the number of permutations that can be produced as P after the operation.

Constraints

* 2 \leq N \leq 200000
* 2 \leq K \leq N
* 0 \leq P_i \leq N-1
* P_0,P_1,\cdots,P_{N-1} are all different.
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N K
P_0 P_1 \cdots P_{N-1}


Output

Print the number of permutations that can be produced as P after the operation.

Examples

Input

5 3
0 2 1 4 3


Output

2


Input

4 4
0 1 2 3


Output

1


Input

10 4
2 0 1 3 7 5 4 6 8 9


Output

6
from collections import deque
from itertools import accumulate

def slide_min(A, K):
    res = []
    Q = deque()
    for i, a in enumerate(A):
        while Q and A[Q[-1]] > a:
            Q.pop()
        Q.append(i)
        if Q[0] == i - K:
            Q.popleft()
        res.append(Q[0])
    return res[K - 1:]

N, K, *P = map(int, open(0).read().split())

mi = slide_min(P, K)
ma = slide_min([-p for p in P], K)

B = [mi != i or ma != i + K for i, (mi, ma) in enumerate(zip(mi, ma[1:]))]

A = [0] + list(accumulate(x < y for x, y in zip(P, P[1:])))
S = [y - x != K - 1 for x, y in zip(A, A[K - 1:])]

ans = 1 + sum(b for b, s in zip(B, S[1:]) if s)
if S[0] and not all(S):
    ans += 1
print(ans)