Let's write all the positive integer numbers one after another from 1 without any delimiters (i.e. as a single string). It will be the infinite sequence starting with 123456789101112131415161718192021222324252627282930313233343536...

Your task is to print the k-th digit of this sequence.

Input

The first and only line contains integer k (1 ≤ k ≤ 10000) — the position to process (1-based index).

Output

Print the k-th digit of the resulting infinite sequence.

Examples

Input


7


Output


7


Input


21


Output


5
n = int(input())
i = 1
s = 0
while(n - (9 * i * (10**(i-1)))) > 0:
    n -= 9*i*(10**(i-1))
    i += 1
if i == 1:
    print(n)
elif i == 2:
    s = 9 + n//i
    if n % 2 == 1:
        print(str(s+1)[0])
    else:
        print(str(s)[1])
elif i == 3:
    s = 99 + n//i
    if n % 3 == 1:
        print(str(s+1)[0])
    elif n % 3 == 2:
        print(str(s+1)[1])
    else:
        print(str(s)[2])
elif i == 4:
    s = 999 + n//i
    if n % i == 1:
        print(str(s + 1)[0])
    elif n % i == 2:
        print(str(s+1)[1])
    elif n % i == 3:
        print(str(s + 1)[2])
    else:
        print(str(s)[3])

