You've got a string a_1, a_2, ..., a_n, consisting of zeros and ones.

Let's call a sequence of consecutive elements a_i, a_{i + 1}, …, a_j (1≤ i≤ j≤ n) a substring of string a. 

You can apply the following operations any number of times:

  * Choose some substring of string a (for example, you can choose entire string) and reverse it, paying x coins for it (for example, «0101101» → «0111001»); 
  * Choose some substring of string a (for example, you can choose entire string or just one symbol) and replace each symbol to the opposite one (zeros are replaced by ones, and ones — by zeros), paying y coins for it (for example, «0101101» → «0110001»). 



You can apply these operations in any order. It is allowed to apply the operations multiple times to the same substring.

What is the minimum number of coins you need to spend to get a string consisting only of ones?

Input

The first line of input contains integers n, x and y (1 ≤ n ≤ 300 000, 0 ≤ x, y ≤ 10^9) — length of the string, cost of the first operation (substring reverse) and cost of the second operation (inverting all elements of substring).

The second line contains the string a of length n, consisting of zeros and ones.

Output

Print a single integer — the minimum total cost of operations you need to spend to get a string consisting only of ones. Print 0, if you do not need to perform any operations.

Examples

Input

5 1 10
01000


Output

11


Input

5 10 1
01000


Output

2


Input

7 2 3
1111111


Output

0

Note

In the first sample, at first you need to reverse substring [1 ... 2], and then you need to invert substring [2 ... 5]. 

Then the string was changed as follows:

«01000» → «10000» → «11111».

The total cost of operations is 1 + 10 = 11.

In the second sample, at first you need to invert substring [1 ... 1], and then you need to invert substring [3 ... 5]. 

Then the string was changed as follows:

«01000» → «11000» → «11111».

The overall cost is 1 + 1 = 2.

In the third example, string already consists only of ones, so the answer is 0.
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Random;
import java.util.StringTokenizer;


public class Main {

	static boolean visited[] ; 
	static boolean ends[] ;
	static long mod = 1000000007 ;
	static int lens[] ; 
	static int seeds[] ; 
	static char a[] ;
	static double total ; 
	public static ArrayList adj[] ; 
	public static long x,y ;
	public static ArrayList<Long> xx ;	
	public static double dp[][][] ;
	public static void main(String[] args) throws IOException, InterruptedException {
		Scanner sc =  new Scanner(System.in) ;

		int n =sc.nextInt() ; 
		int x = sc.nextInt() ; 
		int y = sc.nextInt() ; 

		char arr[] = sc.next().toCharArray() ; 
		int m=0 ;
		if(arr[0]=='0') m++; 
		for (int i = 1; i < arr.length; i++)
		{
			if(arr[i-1]=='1'&& arr[i]=='0')
				m++ ;
		}

		long min=Long.MAX_VALUE ;
		for (int i = 0; i <m ; i++)
		{
			int a=i ; 
			int b=m-i ;
			long ans1= 1l*a*x + 1l*b*y ;
			min =Math.min(ans1,min);
		}
		if(min!=Long.MAX_VALUE)System.out.println(min);
		else System.out.println(0);

	}
	public static int x(String s)
	{
		int ans=0;
		for (int i = 0; i < s.length(); i++)
		{
			if(s.charAt(i)=='X')
				ans++;
		}
		return ans ;
	}





























	public static void dfss(int root , int len)
	{
		visited[root]=true ; 
		if(ends[root] && root!=0) lens[root] = len ; 

		for (int i = 0; i < adj[root].size(); i++)
		{
			int c= (int) adj[root].get(i) ; 
			if(visited[c]==false)
				dfss(c, len+1);
		}
	}

	public static void pr(int root ,  int seed){
		visited[root] = true ;
		int dv = adj[root].size()-1 ; 
		if(root==0) dv++ ;

		for (int i = 0; i < adj[root].size(); i++)
		{
			int c = (int)adj[root].get(i) ; 
			seeds[c]=dv*seed ;
		}

		for (int i = 0; i < adj[root].size() ; i++)
		{
			int c = (int)adj[root].get(i) ; 
			if(visited[c]==false)
				pr(c , seeds[c]);

		}

	}



	static class Scanner {
		StringTokenizer st;
		BufferedReader br;

		public Scanner(InputStream s) {
			br = new BufferedReader(new InputStreamReader(s));
		}

		public String next() throws IOException {
			while (st == null || !st.hasMoreTokens())
				st = new StringTokenizer(br.readLine());
			return st.nextToken();
		}

		public int nextInt() throws IOException {
			return Integer.parseInt(next());
		}

		public long nextLong() throws IOException {
			return Long.parseLong(next());
		}

		public String nextLine() throws IOException {
			return br.readLine();
		}

		public double nextDouble() throws IOException {
			return Double.parseDouble(next());
		}

		public boolean ready() throws IOException {
			return br.ready();
		}
	}


	public static long getGCD(long n1, long n2) {
		if (n2 == 0) {
			return n1;
		}
		return getGCD(n2, n1 % n2);
	}


	public static void shuffle(ArrayList<Integer> ss){
		if(ss.size()==1)
			return ; 
		for (int i = 0; i < ss.size(); i++)
		{
			Random rand = new Random();

			int  n = rand.nextInt(ss.size()-1) + 0;

			int tmp = ss.get(n);
			ss.remove(n);
			ss.add(tmp);
		}
	}
	//	public static int binary(ArrayList<pair> arr, int l, int r, long x)   /// begin by 0 and n-1
	//	{
	//		if (r>=l)
	//		{
	//			int mid = l + (r - l)/2;
	//			if (arr.get(mid).x== x)
	//				return mid;
	//			if (arr.get(mid).x> x)
	//				return binary(arr, l, mid-1, x);
	//			return binary(arr, mid+1, r, x);
	//		}
	//		return -1;
	//	}

	/// searching for the index of first elment greater than x
	public static int binary1(int[]arr , int x) {
		int low = 0, high = arr.length; // numElems is the size of the array i.e arr.size() 
		while (low != high) {
			int mid = (low + high) / 2; // Or a fancy way to avoid int overflow
			if (arr[mid] <= x) {
				/* This index, and everything below it, must not be the first element
				 * greater than what we're looking for because this element is no greater
				 * than the element.
				 */
				low = mid + 1;
			}
			else {
				/* This element is at least as large as the element, so anything after it can't
				 * be the first element that's at least as large.
				 */
				high = mid;
			}
		}
		return low ; // return high ; 
	}


	////// searching for last element less than X 
	//	public static int binary2(pair[]arr , int x) {
	//		int low = 0, high = arr.length; // numElems is the size of the array i.e arr.size() 
	//		while (low != high) {
	//			int mid = (low + high) / 2; // Or a fancy way to avoid int overflow
	//			if (arr[mid].x >= x) {
	//				/* This index, and everything below it, must not be the first element
	//				 * greater than what we're looking for because this element is no greater
	//				 * than the element.
	//				 */
	//				high=mid;
	//			}
	//			else {
	//				/* This element is at least as large as the element, so anything after it can't
	//				 * be the first element that's at least as large.
	//				 */
	//				low = mid+1 ; 
	//			}
	//		}
	//		return low ; // return high ; 
	//	}







	public static int binary(long []arr , long target , int low , long shift) {
		int high = arr.length; 
		while (low != high) {
			int mid = (low + high) / 2; 
			if (arr[mid]-shift <= target) {
				low = mid + 1;
			}
			else {
				high = mid;
			}
		}
		return low ; // return high ; 
	}
	public static boolean isLetter(char x){
		if(x+0 <=122 && x+0 >=97 )
			return true ;
		else if (x+0 <=90 && x+0 >=65 )
			return true ; 
		else return false; 
	}
	public static long getPrimes(long x ){
		if(x==2 || x==3 || x==1)
			return 2 ;
		if(isPrime(x))
			return 5 ;
		for (int i = 2; i*i<=x; i++)
		{
			if(x%i==0 && isPrime(i))
				return getPrimes(x/i) ;
		}
		return -1;
	}







	public static int lis( int[]a , int n){
		int lis[] = new int[n] ; 
		Arrays.fill(lis,1) ; 

		for(int i=1;i<n;i++)
			for(int j=0 ; j<i; j++)
				if (a[i]>a[j] &&  lis[i] < lis[j]+1)   
					lis[i] = lis[j] + 1;           

		int max = lis[0];

		for(int i=1; i<n ; i++)
			if (max < lis[i])
				max = lis[i] ;
		return (max);

		//			ArrayList<Integer> s = new ArrayList<Integer>() ;
		//			for (int i = n-1; i >=0; i--)
		//			{
		//				if(lis[i]==max)
		//				{
		//					s.add(a[i].z);
		//					max --; 
		//				}
		//			}
		//
		//			for (int i = s.size()-1 ; i>=0 ;  i--)
		//			{
		//				System.out.print(s.get(i)+" ");
		//			}
		//
	}
	public static int calcDepth(Vertix node){
		if(node.depth>0) return node.depth; 
		// meaning it has been updated before;
		if(node.parent != null)
			return 1+ calcDepth(node.parent);
		else
			return -1;
	}

	public static boolean isPrime (long num){
		if (num < 2) return false;
		if (num == 2) return true;
		if (num % 2 == 0) return false;
		for (int i = 3; i * i <= num; i += 2)
			if (num % i == 0) return false;
		return true;
	}


	public static ArrayList<Long> getDiv(Long n)
	{
		ArrayList<Long>  f = new ArrayList<Long>() ; 

		while (n%2==0)
		{
			if(!f.contains(2))f.add((long) 2) ;
			n /= 2;
		}

		// n must be odd at this point.  So we can
		// skip one element (Note i = i +2)
		for (long i = 3; i <= Math.sqrt(n); i+= 2)
		{
			// While i divides n, print i and divide n
			while (n%i == 0)
			{
				if(!f.contains(i))f.add(i);
				n /= i;
			}
		}

		// This condition is to handle the case whien
		// n is a prime number greater than 2
		if (n > 2)
			if(!f.contains(n))f.add(n);


		return f ;



	}

	//		public static boolean dfs(Vertix v , int target){
	//			try{
	//				visited[v.i]= true ;
	//			} catch (NullPointerException e)
	//			{
	//				System.out.println(v.i);
	//			}
	//			if(v.i == target)
	//
	//				return true ;
	//			for (int i =0 ; i< v.neighbours.size() ; i++)
	//			{ 
	//
	//				Vertix child = v.neighbours.get(i) ;
	//				if(child.i == target){
	//					found = true  ; 
	//				}
	//				if(visited[child.i]==false){
	//					found |= dfs(child, target) ;
	//				}
	//			}
	//			return found; 
	//		}









	public static class Vertix{
		long i ; 
		int depth ;
		ArrayList<Vertix> neighbours ; 
		Vertix parent ; 
		Vertix child ; 


		public Vertix(long i){
			this.i = i ;
			this.neighbours = new ArrayList<Vertix> () ;
			this.parent = null ;
			depth =-1;
			this.child = null ;
		}
	}

	public static class pair implements Comparable<pair> {
		long x ; 
		int y ; 




		public pair(long x, int y ){

			this.x=x ; 
			this.y =y ;


		}


		@Override
		public int compareTo(pair p) {
			if(this.x > p.x)
				return 1 ; 
			else if (this.x == p.x) 
				return 0 ; 
			else 
				return -1 ;
		}




	}

	public static class pair2 implements Comparable<pair2>{
		int i ; 
		int j ;
		int plus ;

		public pair2(int i , int j , int plus){
			this.i =i ;
			this.j = j ; 
			this.plus = plus ;
		}

		@Override
		public int compareTo(pair2 p) {
			if(this.j > p.j)
				return 1 ; 
			else if (this.j == p.j) return 0 ;
			else 
				return -1 ;
		}


	}
	public static class point implements  Comparable<point>
	{
		int x, y ; 
		public point(int x,int y){
			this.x=x ; this.y=y;
		}
		@Override
		public boolean equals(Object o) {

			// If the object is compared with itself then return true  
			if (o == this) {
				return true;
			}

			/* Check if o is an instance of Complex or not
	          "null instanceof [type]" also returns false */
			if (!(o instanceof point)) {
				return false;
			}

			// typecast o to Complex so that we can compare data members 
			point c = (point) o;

			// Compare the data members and return accordingly 
			return Integer.compare(x, c.x) == 0
					&& Integer.compare(y, c.y) == 0;
		}
		@Override
		public int compareTo(point p) {
			if(this.x == p.x && this.y ==p.y)
				return 0 ; 
			else
				return -1 ; 
		}

		@Override
		public int hashCode()
		{
			return 15+x+(y%2) ;
		}



	}


}