Let's write all the positive integer numbers one after another from 1 without any delimiters (i.e. as a single string). It will be the infinite sequence starting with 123456789101112131415161718192021222324252627282930313233343536...

Your task is to print the k-th digit of this sequence.

Input

The first and only line contains integer k (1 ≤ k ≤ 10000) — the position to process (1-based index).

Output

Print the k-th digit of the resulting infinite sequence.

Examples

Input


7


Output


7


Input


21


Output


5

import java.io.BufferedReader;
import java.io.InputStreamReader;

public class Solution {

	public static void main(String[] args) throws Exception{
		// TODO Auto-generated method stub
		BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
		int k = Integer.parseInt(in.readLine());
		
		String str = "";
		
		for(int i=1; i<=k; i++) {
			str += Integer.toString(i);
		}
		
		System.out.println(str.charAt(k-1));
		
	}

}
