Let's write all the positive integer numbers one after another from 1 without any delimiters (i.e. as a single string). It will be the infinite sequence starting with 123456789101112131415161718192021222324252627282930313233343536...

Your task is to print the k-th digit of this sequence.

Input

The first and only line contains integer k (1 ≤ k ≤ 10000) — the position to process (1-based index).

Output

Print the k-th digit of the resulting infinite sequence.

Examples

Input


7


Output


7


Input


21


Output


5
#include <bits/stdc++.h>
using namespace std;
int main() {
  ios::sync_with_stdio(false);
  cin.tie(0);
  long long k;
  cin >> k;
  long long s = 0, p = 1;
  for (long long l = 1;; ++l) {
    long long num = 9LL * p;
    if (s + l * num >= k) {
      k -= s;
      long long q = k / l, r = k % l;
      if (r == 0)
        cout << to_string(p + q - 1).back() << '\n';
      else
        cout << to_string(p + q)[r - 1] << '\n';
      return 0;
    } else {
      s += l * num;
    }
    p *= 10;
  }
}
