Let's write all the positive integer numbers one after another from 1 without any delimiters (i.e. as a single string). It will be the infinite sequence starting with 123456789101112131415161718192021222324252627282930313233343536...

Your task is to print the k-th digit of this sequence.

Input

The first and only line contains integer k (1 ≤ k ≤ 10000) — the position to process (1-based index).

Output

Print the k-th digit of the resulting infinite sequence.

Examples

Input


7


Output


7


Input


21


Output


5
import sys
import math

#to read string
get_string = lambda: sys.stdin.readline().strip()
#to read list of integers
get_int_list = lambda: list( map(int,sys.stdin.readline().strip().split()) )
#to read integers
get_int = lambda: int(sys.stdin.readline())
#to print fast
pt = lambda x: sys.stdout.write(str(x)+'\n')

#--------------------------------WhiteHat010--------------------------------------#
n = get_int()
end = 0
digit = 0

while True:
    digit += 1
    a = 10**(digit-1)
    b = int('9'*digit)
    start = end+1
    end = end + (b-a+1)*digit
    if n <= end:
        break

rem = (n-start+1)%digit
seq = (n-start+1)//digit

if rem != 0:
    x = 1
else:
    x = 0
term = str( a + ( seq + x -1) )
#print(start,end,a,b)
#print('rem, seq',rem,seq)
#print('Term: ',term)
print(term[rem-1])


