We have a grid of squares with N rows and M columns. Let (i, j) denote the square at the i-th row from the top and j-th column from the left. We will choose K of the squares and put a piece on each of them.

If we place the K pieces on squares (x_1, y_1), (x_2, y_2), ..., and (x_K, y_K), the cost of this arrangement is computed as:

\sum_{i=1}^{K-1} \sum_{j=i+1}^K (|x_i - x_j| + |y_i - y_j|)

Find the sum of the costs of all possible arrangements of the pieces. Since this value can be tremendous, print it modulo 10^9+7.

We consider two arrangements of the pieces different if and only if there is a square that contains a piece in one of the arrangements but not in the other.

Constraints

* 2 \leq N \times M \leq 2 \times 10^5
* 2 \leq K \leq N \times M
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N M K


Output

Print the sum of the costs of all possible arrangements of the pieces, modulo 10^9+7.

Examples

Input

2 2 2


Output

8


Input

4 5 4


Output

87210


Input

100 100 5000


Output

817260251
import sys
input = sys.stdin.readline

N,M,K=map(int,input().split())
mod=10**9+7

def Combi2(a,b):#aは大きいが、bは小さいとき
    if b>a:
        return 0
    ANS=1
    for i in range(min(b,a-b)):
        ANS=ANS*(a-i)*pow(min(b,a-b)-i,mod-2,mod)%mod

    return ANS%mod

SUM_N=SUM_M=0
for i in range(N):
    SUM_N+=i*(N-i)

for i in range(M):
    SUM_M+=i*(M-i)

#print((SUM_N*(M**2)+SUM_M*(N**2))/Combi2(N*M,2)*Combi2(N*M,K)*K*(K-1)//2%mod)
print((SUM_N*(M**2)+SUM_M*(N**2))*pow(Combi2(N*M,2),mod-2,mod)*Combi2(N*M,K)*K*(K-1)*pow(2,mod-2,mod)%mod)
