Let's write all the positive integer numbers one after another from 1 without any delimiters (i.e. as a single string). It will be the infinite sequence starting with 123456789101112131415161718192021222324252627282930313233343536...

Your task is to print the k-th digit of this sequence.

Input

The first and only line contains integer k (1 ≤ k ≤ 10000) — the position to process (1-based index).

Output

Print the k-th digit of the resulting infinite sequence.

Examples

Input


7


Output


7


Input


21


Output


5
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.Scanner;

public class Main {

    private static String DIGITS = "";
    private static final int MAX_DIGIT = 10000;

    static {
        for (int i = 1; i < 3000; i++) {
            DIGITS = DIGITS + i;
            if (DIGITS.length() > MAX_DIGIT) {
                break;
            }
        }
    }


    public static void main(String[] args) {
        Scanner I = new Scanner(new BufferedReader(new InputStreamReader(System.in)));

        int n = I.nextInt();
        
        if (n > MAX_DIGIT) {
            error("invalid inpyt");
        }

        System.out.println(DIGITS.charAt(n - 1));

    }


    private static void error(String msg) {

        throw new RuntimeException(msg);
    }


}