We have a grid of squares with N rows and M columns. Let (i, j) denote the square at the i-th row from the top and j-th column from the left. We will choose K of the squares and put a piece on each of them.

If we place the K pieces on squares (x_1, y_1), (x_2, y_2), ..., and (x_K, y_K), the cost of this arrangement is computed as:

\sum_{i=1}^{K-1} \sum_{j=i+1}^K (|x_i - x_j| + |y_i - y_j|)

Find the sum of the costs of all possible arrangements of the pieces. Since this value can be tremendous, print it modulo 10^9+7.

We consider two arrangements of the pieces different if and only if there is a square that contains a piece in one of the arrangements but not in the other.

Constraints

* 2 \leq N \times M \leq 2 \times 10^5
* 2 \leq K \leq N \times M
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N M K


Output

Print the sum of the costs of all possible arrangements of the pieces, modulo 10^9+7.

Examples

Input

2 2 2


Output

8


Input

4 5 4


Output

87210


Input

100 100 5000


Output

817260251

public class Main {


  private static void solve() {
    long n = ni();
    long m = ni();
    long k = ni();
    
    int mod = (int)1e9 + 7;
    int[][] fif = enumFIF(300000, mod);

    long ret = 0;
    for (int d = 1; d < n; d ++) {
      ret += m * m * (n - d) * d;
      ret %= mod;
     }
    for (int d = 1; d < m; d ++) {
      ret += n * n * (m - d) * d;
      ret %= mod;
     }

    System.out.println(ret * CX(n * m - 2, k - 2, mod, fif) % mod);
  }
  

  public static long CX(long n, long r, int p, int[][] fif)
  {
      if(n < 0 || r < 0 || r > n)return 0;
      int np = (int)(n%p), rp = (int)(r%p);
      if(np < rp)return 0;
      if(n == 0 && r == 0)return 1;
      int nrp = np-rp;
      if(nrp < 0)nrp += p;
      return (long)fif[0][np]*fif[1][rp]%p*fif[1][nrp]%p*CX(n/p, r/p, p, fif)%p;
  }

  public static int[][] enumFIF(int n, int mod)
  {
      int[] f = new int[n+1];
      int[] invf = new int[n+1];
      f[0] = 1;
      for(int i = 1;i <= n;i++){
          f[i] = (int)((long)f[i-1] * i % mod);
      }
      long a = f[n];
      long b = mod;
      long p = 1, q = 0;
      while(b > 0){
          long c = a / b;
          long d;
          d = a; a = b; b = d % b;
          d = p; p = q; q = d - c * q;
      }
      invf[n] = (int)(p < 0 ? p + mod : p);
      for(int i = n-1;i >= 0;i--){
          invf[i] = (int)((long)invf[i+1] * (i+1) % mod);
      }
      return new int[][]{f, invf};
  }
  
  
  public static void main(String[] args) {
    new Thread(null, new Runnable() {
      @Override
      public void run() {
        long start = System.currentTimeMillis();
        String debug = args.length > 0 ? args[0] : null;
        if (debug != null) {
          try {
            is = java.nio.file.Files.newInputStream(java.nio.file.Paths.get(debug));
          } catch (Exception e) {
            throw new RuntimeException(e);
          }
        }
        reader = new java.io.BufferedReader(new java.io.InputStreamReader(is), 32768);
        solve();
        out.flush();
        tr((System.currentTimeMillis() - start) + "ms");
      }
    }, "", 64000000).start();
  }

  private static java.io.InputStream is = System.in;
  private static java.io.PrintWriter out = new java.io.PrintWriter(System.out);
  private static java.util.StringTokenizer tokenizer = null;
  private static java.io.BufferedReader reader;

  public static String next() {
    while (tokenizer == null || !tokenizer.hasMoreTokens()) {
      try {
        tokenizer = new java.util.StringTokenizer(reader.readLine());
      } catch (Exception e) {
        throw new RuntimeException(e);
      }
    }
    return tokenizer.nextToken();
  }

  private static double nd() {
    return Double.parseDouble(next());
  }

  private static long nl() {
    return Long.parseLong(next());
  }

  private static int[] na(int n) {
    int[] a = new int[n];
    for (int i = 0; i < n; i++)
      a[i] = ni();
    return a;
  }

  private static char[] ns() {
    return next().toCharArray();
  }

  private static long[] nal(int n) {
    long[] a = new long[n];
    for (int i = 0; i < n; i++)
      a[i] = nl();
    return a;
  }

  private static int[][] ntable(int n, int m) {
    int[][] table = new int[n][m];
    for (int i = 0; i < n; i++) {
      for (int j = 0; j < m; j++) {
        table[i][j] = ni();
      }
    }
    return table;
  }

  private static int[][] nlist(int n, int m) {
    int[][] table = new int[m][n];
    for (int i = 0; i < n; i++) {
      for (int j = 0; j < m; j++) {
        table[j][i] = ni();
      }
    }
    return table;
  }

  private static int ni() {
    return Integer.parseInt(next());
  }

  private static void tr(Object... o) {
    if (is != System.in)
      System.out.println(java.util.Arrays.deepToString(o));
  }
}
