Let's write all the positive integer numbers one after another from 1 without any delimiters (i.e. as a single string). It will be the infinite sequence starting with 123456789101112131415161718192021222324252627282930313233343536...

Your task is to print the k-th digit of this sequence.

Input

The first and only line contains integer k (1 ≤ k ≤ 10000) — the position to process (1-based index).

Output

Print the k-th digit of the resulting infinite sequence.

Examples

Input


7


Output


7


Input


21


Output


5
#include <bits/stdc++.h>
using namespace std;
void c_p_c() {
  ios_base::sync_with_stdio(0);
  cin.tie(0);
  cout.tie(0);
}
long long me(long long x, long long y, long long p) {
  long long res = 1;
  x = x % p;
  if (x == 0) return 0;
  while (y > 0) {
    if (y & 1) res = (res * x) % p;
    y = y >> 1;
    x = (x * x) % p;
  }
  return res;
}
int main() {
  c_p_c();
  long long k;
  cin >> k;
  string s;
  long long c = 1;
  for (long long i = 0; i < 10000; i++) {
    string p = to_string(c);
    s = s + p;
    c++;
  }
  cout << s[k - 1] << endl;
  return 0;
}
