Let's write all the positive integer numbers one after another from 1 without any delimiters (i.e. as a single string). It will be the infinite sequence starting with 123456789101112131415161718192021222324252627282930313233343536...

Your task is to print the k-th digit of this sequence.

Input

The first and only line contains integer k (1 ≤ k ≤ 10000) — the position to process (1-based index).

Output

Print the k-th digit of the resulting infinite sequence.

Examples

Input


7


Output


7


Input


21


Output


5
import java.util.ArrayList;
import java.util.Collections;
import java.util.Scanner;

public class sort {

	public static void main(String[] args) {
	Scanner sc = new Scanner(System.in);
	int k = sc.nextInt();
	int numOfDigits = 0;
	while(k > 0) {
		numOfDigits++;
		k -= 9*(int)Math.pow(10, numOfDigits-1)*numOfDigits;
		}
	k +=  9*Math.pow(10, numOfDigits-1)*numOfDigits;
	int count = k/numOfDigits;
	k = k % numOfDigits;
	int start = (int)Math.pow(10, numOfDigits-1);
	start += count - 1;
	if(k==0) {
		String s = start+"";
		System.out.println(s.charAt(s.length()-1));
	}
	else
	{
		String s = (start + 1) + "";
		System.out.println(s.charAt(k-1));
	}
	
	
	}

}