Let's write all the positive integer numbers one after another from 1 without any delimiters (i.e. as a single string). It will be the infinite sequence starting with 123456789101112131415161718192021222324252627282930313233343536...

Your task is to print the k-th digit of this sequence.

Input

The first and only line contains integer k (1 ≤ k ≤ 10000) — the position to process (1-based index).

Output

Print the k-th digit of the resulting infinite sequence.

Examples

Input


7


Output


7


Input


21


Output


5
import java.util.Scanner;

/**
 *
 * @author Dell
 */
public class JavaApplication21 {

    /**
     * @param args the command line arguments
     */
    public static void main(String[] args) {
        int k , c=0 ;
       Scanner in=new Scanner(System.in);
       k = in.nextInt();
      String  s="";

        for(int i=0 ; i < 10000 ; i++){
          s+=String.valueOf(i);
          //  c++;
           //if(c==k)
             
            
        }
       System.out.println(s.charAt(k));
    }
    
}
