Snuke is standing on a two-dimensional plane. In one operation, he can move by 1 in the positive x-direction, or move by 1 in the positive y-direction.

Let us define a function f(r, c) as follows:

* f(r,c) :=  (The number of paths from the point (0, 0) to the point (r, c) that Snuke can trace by repeating the operation above)



Given are integers r_1, r_2, c_1, and c_2. Find the sum of f(i, j) over all pair of integers (i, j) such that r_1 ≤ i ≤ r_2 and c_1 ≤ j ≤ c_2, and compute this value modulo (10^9+7).

Constraints

* 1 ≤ r_1 ≤ r_2 ≤ 10^6
* 1 ≤ c_1 ≤ c_2 ≤ 10^6
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


r_1 c_1 r_2 c_2


Output

Print the sum of f(i, j) modulo (10^9+7).

Examples

Input

1 1 2 2


Output

14


Input

314 159 2653 589


Output

602215194
a1,b1,a2,b2=map(int,input().split())

import sys
sys.setrecursionlimit(2000000000)

p = 10 ** 9 + 7
N = a2+b2+2  # N は必要分だけ用意する
R = max(a2+1,b2+1)
fact = [1, 1]  # fact[n] = (n! mod p)
factinv = [1, 1]  # factinv[n] = ((n!)^(-1) mod p)
inv = [0, 1]  # factinv 計算用

for i in range(2, N + 1):
  fact.append((fact[-1] * i) % p)
  
for i in range(2, R + 1):
  inv.append((-inv[p % i] * (p // i)) % p)
  factinv.append((factinv[-1] * inv[-1]) % p)

def comb(n, r, p):
  if (r < 0) or (n < r):
    return 0
  r = min(r, n - r)
  return fact[n] * factinv[r] * factinv[n-r] % p

score=comb(a2+b2+2,a2+1,p)-comb(a2+b1+1,a2+1,p)-comb(a1+b2+1,a1,p)+comb(a1+b1,a1,p)
print(score%(10**9+7))