Let's write all the positive integer numbers one after another from 1 without any delimiters (i.e. as a single string). It will be the infinite sequence starting with 123456789101112131415161718192021222324252627282930313233343536...

Your task is to print the k-th digit of this sequence.

Input

The first and only line contains integer k (1 ≤ k ≤ 10000) — the position to process (1-based index).

Output

Print the k-th digit of the resulting infinite sequence.

Examples

Input


7


Output


7


Input


21


Output


5
import java.util.Scanner;

public class DigitsSequence {
	

	public static int nthDigit(int n) {
		
		int m = n;
		int start = 1, count = 9;
		int length = 1;
		
		while(n > length*count) {
			n = n - (length*count);
			length++;
			start = start*10;
			count = count*10;
		}
		start = start + (n-1)/length;
		
		int digit = String.valueOf(start).charAt((int)((n-1)%length)) - '0';
		
		return digit;
	}

	public static void main(String[] args) {
		Scanner in = new Scanner(System.in);
		int n = in.nextInt();
		//nthDigit(n);
		System.out.println(nthDigit(n));
	}

}
