Snuke has a permutation (P_0,P_1,\cdots,P_{N-1}) of (0,1,\cdots,N-1).

Now, he will perform the following operation exactly once:

* Choose K consecutive elements in P and sort them in ascending order.



Find the number of permutations that can be produced as P after the operation.

Constraints

* 2 \leq N \leq 200000
* 2 \leq K \leq N
* 0 \leq P_i \leq N-1
* P_0,P_1,\cdots,P_{N-1} are all different.
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N K
P_0 P_1 \cdots P_{N-1}


Output

Print the number of permutations that can be produced as P after the operation.

Examples

Input

5 3
0 2 1 4 3


Output

2


Input

4 4
0 1 2 3


Output

1


Input

10 4
2 0 1 3 7 5 4 6 8 9


Output

6
from collections import deque
n,k=map(int,input().split())
p=list(map(int,input().split()))

minp=[0]*(n-k+1)
maxp=[0]*(n-k+1)
q1=deque([0])
q2=deque([0])
for i in range(1,k):
    while p[q1[-1]]>p[i]:
        q1.pop()
        if len(q1)==0:
            break
    while p[q2[-1]]<p[i]:
        q2.pop()
        if len(q2)==0:
            break
    q1.append(i)
    q2.append(i)
for i in range(n-k+1):
    minp[i]=p[q1[0]]
    maxp[i]=p[q2[0]]
    if i==n-k:
        break
    if q1[0]==i:
        q1.popleft()
    if q2[0]==i:
        q2.popleft()
    while p[q1[-1]]>p[i+k]:
        q1.pop()
        if len(q1)==0:
            break
    while p[q2[-1]]<p[i+k]:
        q2.pop()
        if len(q2)==0:
            break
    q1.append(i+k)
    q2.append(i+k)

d=[0]*n
d[0]=1
for i in range(1,n):
    if p[i]>p[i-1]:
        d[i]=d[i-1]+1
    else:
        d[i]=1

ans=int(k in d)
if d[k-1]!=k:
    ans+=1
for i in range(n-k):
    if d[i+k]>=k:
        continue
    if not (p[i]==minp[i] and p[i+k]==maxp[i+1]):
        ans+=1

print(ans)