Recently, you found a bot to play "Rock paper scissors" with. Unfortunately, the bot uses quite a simple algorithm to play: he has a string s = s_1 s_2 ... s_{n} of length n where each letter is either R, S or P.

While initializing, the bot is choosing a starting index pos (1 ≤ pos ≤ n), and then it can play any number of rounds. In the first round, he chooses "Rock", "Scissors" or "Paper" based on the value of s_{pos}: 

  * if s_{pos} is equal to R the bot chooses "Rock"; 
  * if s_{pos} is equal to S the bot chooses "Scissors"; 
  * if s_{pos} is equal to P the bot chooses "Paper"; 



In the second round, the bot's choice is based on the value of s_{pos + 1}. In the third round — on s_{pos + 2} and so on. After s_n the bot returns to s_1 and continues his game.

You plan to play n rounds and you've already figured out the string s but still don't know what is the starting index pos. But since the bot's tactic is so boring, you've decided to find n choices to each round to maximize the average number of wins.

In other words, let's suggest your choices are c_1 c_2 ... c_n and if the bot starts from index pos then you'll win in win(pos) rounds. Find c_1 c_2 ... c_n such that (win(1) + win(2) + ... + win(n))/(n) is maximum possible.

Input

The first line contains a single integer t (1 ≤ t ≤ 1000) — the number of test cases.

Next t lines contain test cases — one per line. The first and only line of each test case contains string s = s_1 s_2 ... s_{n} (1 ≤ n ≤ 2 ⋅ 10^5; s_i ∈ \{R, S, P\}) — the string of the bot.

It's guaranteed that the total length of all strings in one test doesn't exceed 2 ⋅ 10^5.

Output

For each test case, print n choices c_1 c_2 ... c_n to maximize the average number of wins. Print them in the same manner as the string s.

If there are multiple optimal answers, print any of them.

Example

Input


3
RRRR
RSP
S


Output


PPPP
RSP
R

Note

In the first test case, the bot (wherever it starts) will always choose "Rock", so we can always choose "Paper". So, in any case, we will win all n = 4 rounds, so the average is also equal to 4.

In the second test case: 

  * if bot will start from pos = 1, then (s_1, c_1) is draw, (s_2, c_2) is draw and (s_3, c_3) is draw, so win(1) = 0; 
  * if bot will start from pos = 2, then (s_2, c_1) is win, (s_3, c_2) is win and (s_1, c_3) is win, so win(2) = 3; 
  * if bot will start from pos = 3, then (s_3, c_1) is lose, (s_1, c_2) is lose and (s_2, c_3) is lose, so win(3) = 0; 

The average is equal to (0 + 3 + 0)/(3) = 1 and it can be proven that it's the maximum possible average.

A picture from Wikipedia explaining "Rock paper scissors" game: 

<image>
/*
                       _oo0oo_
                      o8888888o
                      88" . "88
                      (| -_- |)
                      0\  =  /0
                    ___/`---'\___
                  .' \\|     |// '.
                 / \\|||  :  |||// \
                / _||||| -:- |||||- \
               |   | \\\  -  /// |   |
               | \_|  ''\---/''  |_/ |
               \  .-\__  '-'  ___/-. /
             ___'. .'  /--.--\  `. .'___
          ."" '<  `.___\_<|>_/___.' >' "".
         | | :  `- \`.;`\ _ /`;.`/ - ` : | |
         \  \ `_.   \_ __\ /__ _/   .-` /  /
     =====`-.____`.___ \_____/___.-`___.-'=====
                       `=---='
 
*/
import java.util.function.Consumer;
import java.util.*;
import java.math.BigDecimal;
import java.math.BigInteger;
import java.math.RoundingMode;
import java.text.DecimalFormat;
import java.io.*;
import java.lang.Math.*;
 public class KickStart2020{
	static class FastReader {
        BufferedReader br;
        StringTokenizer st;
        public FastReader(){br = new BufferedReader(
           new InputStreamReader(System.in));}
        String next(){
            while (st == null || !st.hasMoreElements()) {
                try { st = new StringTokenizer(br.readLine()); }
                catch (IOException e) {e.printStackTrace();}}
            return st.nextToken();}
        int nextInt() { return Integer.parseInt(next()); }
        long nextLong() { return Long.parseLong(next()); }
        double nextDouble() { return Double.parseDouble(next());}
        float nextFloat() {return Float.parseFloat(next());}
        String nextLine() {
            String str = "";
            try {str = br.readLine();}
            catch (IOException e) { e.printStackTrace();}
            return str; }}
	static boolean isBracketSequence(String s, int a, int b) {
		Stack<Character> ss = new Stack<>();
		boolean hachu = true;
		for(int i = a; i <= b; i++) {
			if(s.charAt(i) == ')' && ss.isEmpty()) {hachu = false; break;}
			if(s.charAt(i) == '(') ss.add('(');
			else ss.pop();
		}
		return ss.empty() && hachu;
	}
	static String reverseOfString(String a) {
		StringBuilder ssd = new StringBuilder();
		for(int i = a.length() - 1; i >= 0; i--) {
			ssd.append(a.charAt(i));
		}
		return ssd.toString();
	}
	static char[] reverseOfChar(char a[]) {
		char b[] = new char[a.length];
		int j = 0;
		for(int i = a.length - 1; i >= 0; i--) {
			b[i] = a[j];
			j++;
		}
		return b;
	}
	static boolean isPalindrome(char a[]) {
		boolean hachu = true;
		for(int i = 0; i <= a.length / 2; i++) {
			if(a[i] != a[a.length - 1 - i]) {
				hachu = false;
				break;
			}
		}
		return hachu;
	} 
	static long gcd(long a, long b)
	{
	    if (b == 0)
	        return a;
	    return gcd(b, a % b);
	     
	}
	static long powermod(long x, long y, long mod){
	    long ans = 1;
	    x = x % mod; 
	    if (x == 0)
	      return 0; 
	    int i = 1;
	    while (y > 0){
	      if ((y & 1) != 0)
	        ans = (ans * x) % mod;
	      y = y >> 1; 
	      x = (x * x) % mod;
	    }
	    return ans;
	  }
	static long power(long x, long y){
	    long ans = 1;
	    if (x == 0)
	      return 0; 
	    int i = 1;
	    while (y > 0){
	      if ((y & 1) != 0)
	        ans = (ans * x);
	      y = y >> 1; 
	      x = (x * x);
	    }
	    return ans;
	  }
	static boolean check(String a) {
		boolean hachu = true;
		for(int i = 0; i < a.length(); i++) {
			if(a.charAt(0) != a.charAt(i)) {hachu = false; break;}
		}
		return hachu;
	}
	static boolean checkArray(int x, int arr[]) {
		boolean hachu = true;
		for(int i = 0; i < arr.length; i++) {
			if(x != arr[i]) {hachu = false; break;}
		}
		return hachu;
	}
	 public static class Pair implements Comparable<Pair> {
	        public  int index;
	        public  int value;
	 
	        public Pair(int index, int value) {
	            this.index = index;
	            this.value = value;
	        }
	        @Override
	        public int compareTo(Pair other) {
	            //multiplied to -1 as the author need descending sort order
	            return   -1 * Integer.valueOf(this.value).compareTo(other.value);
	        }
	 }
	 static boolean equalString(int i, int j, int arr[], String b) {
		 int brr[] = new int[26];
		 for(int k = i; k <= j; k++) brr[b.charAt(k) - 'a']++;
		 for(int k = 0; k < 26; k++) {
			 if(arr[k] != brr[k]) return false;
		 }
		 return true;
	 }
	 static boolean cequalArray(String a, String b) {
		  int count[] = new int[26];
		  int count1[] = new int[26];
		  for(int i = 0; i < a.length(); i++) count[a.charAt(i) - 'a']++;
		  for(int i = 0; i < a.length(); i++) count1[b.charAt(i) - 'a']++;
		  for(int i = 0; i < 26; i++) if(count[i] != count1[i]) return false;
		  return true;
	 }
	 static boolean isPrime(long d) {
		 if(d == 1) return true;
		 for(int i = 2; i <= (long)Math.sqrt(d); i++) {
			 if(d % i == 0) return false;
		 }
		 return true;
	 }
	 static String decimalTob(int n, int b, String g) {
		  int z = n % b;
		  g = String.valueOf(z) + g;
		  n /= b;
		  if(n > 0) {
			  g = decimalTob(n, b, g);
		  }
		  return g;
	 }
		public static void main(String[] args) throws Exception{
			FastReader sc = new FastReader();
			PrintWriter out = new PrintWriter(System.out);
              int t = sc.nextInt();
              outerloop:
              while(t-- > 0) {
                  String s = sc.next();
                  Pair arr[] = new Pair[3];
                  arr[0] = new Pair('R', 0);
                  arr[1] = new Pair('P', 0);
                  arr[2] = new Pair('S', 0);
                  for(int i = 0; i < s.length(); i++) {
                	  if(s.charAt(i) == 'R') arr[0].value++;
                	  else if(s.charAt(i) == 'P') arr[1].value++;
                	  else arr[2].value++;
                  }
                  Arrays.sort(arr);
                  char a = (char)arr[0].index;
                  char b = ' ';
                 if(a == 'R') b = 'P';
                 else if(a == 'P') b = 'S';
                 else b = 'R';
                  for(int i = 0; i < s.length(); i++) out.print(b);
                  out.println();
            	  } 
                 out.close();
			}
		}