Let's write all the positive integer numbers one after another from 1 without any delimiters (i.e. as a single string). It will be the infinite sequence starting with 123456789101112131415161718192021222324252627282930313233343536...

Your task is to print the k-th digit of this sequence.

Input

The first and only line contains integer k (1 ≤ k ≤ 10000) — the position to process (1-based index).

Output

Print the k-th digit of the resulting infinite sequence.

Examples

Input


7


Output


7


Input


21


Output


5
#include <bits/stdc++.h>
using namespace std;
long long arr[1000001];
long long arrC = 1;
void func(long long n) {
  long long brr[1010], brrC = 0;
  while (n > 0) {
    long long d = n % 10LL;
    brr[brrC++] = d;
    n = n / 10;
  }
  for (long long i = brrC - 1; i >= 0; i--) {
    arr[arrC++] = brr[i];
  }
}
int main() {
  for (long long i = 1; i <= 10000; i++) {
    func(i);
  }
  long long n;
  cin >> n;
  cout << arr[n] << endl;
}
