One day, Snuke was given a permutation of length N, a_1, a_2, ..., a_N, from his friend.

Find the following:

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Constraints

* 1 ≦ N ≦ 200,000
* (a_1, a_2, ..., a_N) is a permutation of (1, 2, ..., N).

Input

The input is given from Standard Input in the following format:


N
a_1 a_2 ... a_N


Output

Print the answer.

Note that the answer may not fit into a 32-bit integer.

Examples

Input

3
2 1 3


Output

9


Input

4
1 3 2 4


Output

19


Input

8
5 4 8 1 2 6 7 3


Output

85
class BinaryIndexTree:  # 1-indexed
    def __init__(self, N):
        """
        INPUT
        N [int] -> 全部0で初期化
        N [list] -> そのまま初期化
        """
        if isinstance(N, int):
            self.N = N
            self.depth = N.bit_length()
            self.tree = [0] * (N + 1)
            self.elem = [0] * (N + 1)
        elif isinstance(N, list):
            self.N = len(N)
            self.depth = self.N.bit_length()
            self.tree = [0] + N
            self.elem = [0] + N
            self._init()
        else:
            raise "INVALID INPUT: input must be int or list"

    def _init(self):
        size = self.N + 1
        for i in range(1, self.N):
            if i + (i & -i) > size:
                continue
            self.tree[i + (i & -i)] += self.tree[i]

    def add(self, i, x):
        self.elem[i] += x
        while i <= self.N:
            self.tree[i] += x
            i += i & -i

    def sum(self, i):
        res = 0
        while i > 0:
            res += self.tree[i]
            i -= i & -i
        return res

    def lower_bound(self, val):
        if val <= 0:
            return 0
        i = 0
        k = 1 << self.depth
        while k:
            if i + k <= self.N and self.tree[i + k] < val:
                val -= self.tree[i + k]
                i += k
            k >>= 1
        return i + 1


if __name__ == "__main__":
    N = int(input())
    P = list(map(int, input().split()))
    idx = {a: i for i, a in enumerate(P, start=1)}

    bit = BinaryIndexTree(N)
    ans = 0
    for i in range(1, N + 1):
        bit.add(idx[i], 1)
        s = bit.sum(idx[i])
        l = bit.lower_bound(s)-bit.lower_bound(s-1)
        r = bit.lower_bound(s+1) - idx[i]
        ans += i*l*r
    print(ans)