Rama is in love with geometry. So once he was playing with circles and rectangles. Given the center of circle and radius and also the co-ordinates of vertices of rectangle, he wants to check whether the rectangle lies inside the circle or not.

Note: If all the vertices are lie the circumference of circle then it should be considered to be inside.

Input:

First line will contain a positive integer t - number of test cases.
For each test case there will be 5 lines - first will contain three space separated integers radius r, x co-ordinate of center xc and y co-ordinate of circle yc . For next 4 lines there will be 2 space separated numbers each, first denoting the x co-ordinate of that vertex(Xi) and the y co-ordinate of that vertex(Yi) of the rectangle.

Output:

For each test case, output a single line containing “Yes” (without quotes) if the rectangle lies inside the circle, or “No” (without quotes) if it does not lie inside.

Constraints:

1 ≤ t ≤ 10^4
1 ≤ r ≤ 10^4
-10^4 ≤ xc , yc , Xi , Yi ≤ 10^4

SAMPLE INPUT
1
5 0 0
-3 2
2 2
2 -2
-3 -2

SAMPLE OUTPUT
Yes
import sys
import math
t = int(input())
while(t>0):
    r,c1,c2 = map(int,sys.stdin.readline().split())
    x1,y1 =   map(int,sys.stdin.readline().split())
    x2,y2 =   map(int,sys.stdin.readline().split())
    x3,y3 =   map(int,sys.stdin.readline().split())
    x4,y4 =   map(int,sys.stdin.readline().split())
    if((x1-c1)**2+(y1-c2)**2-r**2<=0 and (x2-c1)**2+(y2-c2)**2-r**2<=0 and (x3-c1)**2+(y3-c2)**2-r**2<=0and (x4-c1)**2+(y4-c2)**2-r**2<=0):
        print("Yes")
    else:
        print("No")
    t-=1