Let's write all the positive integer numbers one after another from 1 without any delimiters (i.e. as a single string). It will be the infinite sequence starting with 123456789101112131415161718192021222324252627282930313233343536...

Your task is to print the k-th digit of this sequence.

Input

The first and only line contains integer k (1 ≤ k ≤ 10000) — the position to process (1-based index).

Output

Print the k-th digit of the resulting infinite sequence.

Examples

Input


7


Output


7


Input


21


Output


5
import java.io.*;

public class ADigitalSequence {

	public static void main(String[] args) throws IOException{
		int ans = -1;
		
//		InputStreamReader stream = new InputStreamReader(System.in);
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
	
		int n = Integer.parseInt(br.readLine());
		
		
		int pow = 1;
		
		while (n>= 9*Math.pow(10, pow-1)*pow){
			n-= 9*pow*Math.pow(10, pow-1);
			pow++;
		}
//		System.out.println("what's left of n: " + n);
		
		int num = n/pow + (int)Math.pow(10,pow-1) -1;
		int rem = n%pow;
		if (rem == 0){
			ans = num%10;
		} else{
			num ++;
			ans = (int)(num/Math.pow(10, pow-rem))%10;
		}
		System.out.println(ans);

	}

}
