Let's write all the positive integer numbers one after another from 1 without any delimiters (i.e. as a single string). It will be the infinite sequence starting with 123456789101112131415161718192021222324252627282930313233343536...

Your task is to print the k-th digit of this sequence.

Input

The first and only line contains integer k (1 ≤ k ≤ 10000) — the position to process (1-based index).

Output

Print the k-th digit of the resulting infinite sequence.

Examples

Input


7


Output


7


Input


21


Output


5
#include <bits/stdc++.h>
using namespace std;
inline long long read() {
  register long long s = 0, f = 0;
  register char ch = getchar();
  while (!isdigit(ch)) f |= (ch == '-'), ch = getchar();
  while (isdigit(ch)) s = (s << 1) + (s << 3) + (ch ^ 48), ch = getchar();
  return f ? -s : s;
}
signed main() {
  string s = "";
  long long k = read();
  for (register long long i = 1; s.size() < k; i = -~i) s += to_string(i);
  cout << s[k - 1] << endl;
  return 0;
}
