Let's write all the positive integer numbers one after another from 1 without any delimiters (i.e. as a single string). It will be the infinite sequence starting with 123456789101112131415161718192021222324252627282930313233343536...

Your task is to print the k-th digit of this sequence.

Input

The first and only line contains integer k (1 ≤ k ≤ 10000) — the position to process (1-based index).

Output

Print the k-th digit of the resulting infinite sequence.

Examples

Input


7


Output


7


Input


21


Output


5
import java.util.Scanner;

public class DigitsSequence {
    public DigitsSequence(){

    }
    public String toString(int i){
        return ""+i;
    }
    public static void main(String[] args){
        Scanner in = new Scanner(System.in);
        int k = in.nextInt();
        String s ="";
        DigitsSequence o = new DigitsSequence();
        for (int i = 0; i<k; i++){
            String temp = o.toString(i+1);
            s = s + temp;
        }
        System.out.println(s.charAt(k-1));

    }
}
