Let's write all the positive integer numbers one after another from 1 without any delimiters (i.e. as a single string). It will be the infinite sequence starting with 123456789101112131415161718192021222324252627282930313233343536...

Your task is to print the k-th digit of this sequence.

Input

The first and only line contains integer k (1 ≤ k ≤ 10000) — the position to process (1-based index).

Output

Print the k-th digit of the resulting infinite sequence.

Examples

Input


7


Output


7


Input


21


Output


5
from math import ceil   
n=int(input())
if n<=9:
    print(n)
elif n<=189:
    v=ceil((n-9)/2)+9
    print(str(v)[(n-10)%2])
elif n<=2889:
    v=ceil((n-189)/3)+99  
    print(str(v)[(n-190)%3])
else:
    v=ceil((n-2889)/4)+999
    print(str(v)[(n-2890)%4])