Rama is in love with geometry. So once he was playing with circles and rectangles. Given the center of circle and radius and also the co-ordinates of vertices of rectangle, he wants to check whether the rectangle lies inside the circle or not.

Note: If all the vertices are lie the circumference of circle then it should be considered to be inside.

Input:

First line will contain a positive integer t - number of test cases.
For each test case there will be 5 lines - first will contain three space separated integers radius r, x co-ordinate of center xc and y co-ordinate of circle yc . For next 4 lines there will be 2 space separated numbers each, first denoting the x co-ordinate of that vertex(Xi) and the y co-ordinate of that vertex(Yi) of the rectangle.

Output:

For each test case, output a single line containing “Yes” (without quotes) if the rectangle lies inside the circle, or “No” (without quotes) if it does not lie inside.

Constraints:

1 ≤ t ≤ 10^4
1 ≤ r ≤ 10^4
-10^4 ≤ xc , yc , Xi , Yi ≤ 10^4

SAMPLE INPUT
1
5 0 0
-3 2
2 2
2 -2
-3 -2

SAMPLE OUTPUT
Yes
from math import sqrt
t = input()
for tests in range(0,t):
	temp = raw_input().split()
	r,x,y = int(temp[0]),int(temp[1]),int(temp[2])
	temp = raw_input().split()
	x1,y1 = int(temp[0]),int(temp[1])
	temp = raw_input().split()
	x2,y2 = int(temp[0]),int(temp[1])
	temp = raw_input().split()
	x3,y3 = int(temp[0]),int(temp[1])
	temp = raw_input().split()
	x4,y4 = int(temp[0]),int(temp[1])
	d1 = sqrt((x-x1)**2+(y-y1)**2)
	d2 = sqrt((x-x2)**2+(y-y2)**2)
	d3 = sqrt((x-x3)**2+(y-y3)**2)
	d4 = sqrt((x-x4)**2+(y-y4)**2)
	if d1<=r and d2<=r and d3<=r and d4<=r:
		print("Yes")
	else:
		print("No")