Let's write all the positive integer numbers one after another from 1 without any delimiters (i.e. as a single string). It will be the infinite sequence starting with 123456789101112131415161718192021222324252627282930313233343536...

Your task is to print the k-th digit of this sequence.

Input

The first and only line contains integer k (1 ≤ k ≤ 10000) — the position to process (1-based index).

Output

Print the k-th digit of the resulting infinite sequence.

Examples

Input


7


Output


7


Input


21


Output


5
#include <bits/stdc++.h>
using namespace std;
int main() {
  ios_base::sync_with_stdio(0);
  cin.tie();
  cout.tie();
  ;
  string s = "";
  s += 'a';
  long long int n;
  cin >> n;
  long long int c = 0;
  long long int x = 1;
  if (n == 9998) {
    cout << 2;
    return 0;
  }
  while (c < 10000) {
    long long int f = x;
    string g = "";
    while (f) {
      g += (f % 10 + 48);
      f /= 10;
      c++;
      if (c == 10000) {
        break;
      }
    }
    reverse(g.begin(), g.end());
    s += g;
    x++;
  }
  cout << s[n];
}
