who were the candidates in the presidential election of 1824 how was the winner determined
United States presidential election, 1824 The United States presidential election of 1824 was the tenth quadrennial presidential election, held from Tuesday, October 26, to Thursday, December 2, 1824. John Quincy Adams was elected President on February 9, 1825. The election was the only one in history to be decided by the House of Representatives under the provisions of the Twelfth Amendment to the United States Constitution after no candidate secured a majority of the electoral vote. It was also the first U.S. presidential election where the elected president lost the popular vote,[1] and the only presidential election in which the candidate who received the most electoral votes (Andrew Jackson) did not become President, a source of great bitterness for Jackson and his supporters, who proclaimed the election of Adams a corrupt bargain.
Electoral College (United States) Each state chooses electors, equal in number to that state's combined total of senators and representatives. There are a total of 538 electors, corresponding to the 435 representatives and 100 senators, plus the three electors for the District of Columbia as provided by the Twenty-third Amendment.[7] The Constitution bars any federal official, elected or appointed, from being an elector. The Office of the Federal Register is charged with administering the Electoral College.[8] Since the mid-19th century when all electors have been popularly chosen, the Electoral College has elected the candidate who received the most popular votes nationwide, except in four elections: 1876, 1888, 2000, and 2016. In 1824, there were six states in which electors were legislatively appointed, rather than popularly elected, so the true national popular vote is uncertain; the electors failed to select a winning candidate, so the matter was decided by the House of Representatives.[9]