what are the chances of dying in russian roulette
Russian roulette Because only one chamber is loaded, the player has a one in x chance of being shot; x is the number of chambers in the cylinder. So, for instance, if a revolver holds six chambers, the chance is one in six. That assumes that each chamber is equally likely to come to rest in the "correct" position. However, due to gravity, in a properly maintained weapon with a single round inside the cylinder, the full chamber, which weighs more than the empty chambers, will usually end up near the bottom of the cylinder when its axis is not vertical, altering the odds in favor of the player.[citation needed] This only applies to swing-out cylinder type revolvers, and only if the cylinder is spun outside of the revolver and allowed to come to a complete stop before being locked back in.[citation needed] The number of pulls of the trigger before a round is expected to discharge is 3.5 (without spinning between the pulls) or 6 (with spinning between the pulls).[1]
Lottery mathematics In a typical 6/49 game, each player chooses six non-duplicate numbers from a range of 1-49. If the six numbers on a ticket match the numbers drawn by the lottery, the ticket holder is a jackpot winnerâ€”regardless of the order of the numbers. The probability of this happening is 1 in 13,983,816.