the first presidential election in the united states
United States presidential election, 1788–89 The United States presidential election of 1788â€“89 was the first quadrennial presidential election. It was held from Monday, December 15, 1788, to Saturday, January 10, 1789. It was conducted under the new United States Constitution, which had been ratified earlier in 1788. In the election, George Washington was unanimously elected for the first of his two terms as president, and John Adams became the first vice president.
United States presidential election, 1800 Under the United States Constitution as it then stood, each elector cast two votes, and the candidate with a majority of the votes was elected president, with the vice presidency going to the runner-up. The Federalists therefore arranged for one of their electors to vote for John Jay rather than for Pinckney. The Democratic-Republicans had a similar plan to have one of their electors cast a vote for another candidate instead of Burr, but failed to execute it, thus all of the Democratic-Republican electors cast their votes for both Jefferson and Burr, 73 in all for each of them. According to a provision of the United States Constitution, a tie in a case of this type had to be resolved by the House of Representatives, with each state casting one vote. Although the congressional election of 1800 turned over majority control of the House of Representatives to the Democratic-Republicans by 65 seats to 35,[10] the presidential election had to be decided by the outgoing House that had been elected in the congressional election of 1798 (at that time, the new presidential and congressional terms all started on March 4 of the year after a national election). In the outgoing House, the Federalists retained a majority of 90 seats to 54.[10][3]