Let's denote the number of slips drawn as \( n \).

There are 5 odd numbers (1, 3, 5, 7, 9) and 5 even numbers (0, 2, 4, 6, 8) among the integers from 0 to 9. The total number of ways to draw \( n \) slips from the 10 slips is \( \binom{10}{n} \).

The number of ways to draw \( n \) slips that all have odd numbers on them is \( \binom{5}{n} \), since there are only 5 odd numbers.

The probability \( P \) that all \( n \) slips drawn have an odd number on them is given by the ratio of the number of successful outcomes to the total number of possible outcomes:

\[ P = \frac{\binom{5}{n}}{\binom{10}{n}} \]

We are given that \( P = 0.023809523809523808 \).

Let's calculate the probability for different values of \( n \) and see which one matches the given probability.

For \( n = 1 \):
\[ P = \frac{\binom{5}{1}}{\binom{10}{1}} = \frac{5}{10} = 0.5 \]
This is not the correct probability.

For \( n = 2 \):
\[ P = \frac{\binom{5}{2}}{\binom{10}{2}} = \frac{10}{45} = \frac{2}{9} \approx 0.2222222222222222 \]
This is not the correct probability.

For \( n = 3 \):
\[ P = \frac{\binom{5}{3}}{\binom{10}{3}} = \frac{10}{120} = \frac{1}{12} \approx 0.08333333333333333 \]
This is not the correct probability.

For \( n = 4 \):
\[ P = \frac{\binom{5}{4}}{\binom{10}{4}} = \frac{5}{210} = \frac{1}{42} \approx 0.023809523809523808 \]
This matches the given probability.

Therefore, \( n = 4 \) slips are drawn.
추첨된 응모권의 수를 \( n \), 즉 5장으로 표시해 보겠습니다.

0부터 9까지의 정수 중 홀수(1, 3, 5, 7, 9)는 5개, 짝수(0, 2, 4, 6, 8)는 5개입니다. 10장의 추첨권에서 \( n \) 장의 추첨권을 뽑을 수 있는 총 방법은 \( \binom{10}{n} \).

홀수가 5개뿐이므로 \( n \) 장의 추첨권을 모두 홀수로 그리는 방법의 수는 \( \binom{5}{n} \).

뽑힌 모든 \( n \) 장의 추첨권에 홀수가 있는 확률 \( P \), 즉 성공 결과의 수와 가능한 총 결과의 비율에 따라 다음과 같이 계산됩니다:

\[ P = \frac{\binom{5}{n}}{\binom{10}{n}} \]

P = 0.023809523809523808 \).

다양한 값의 \( n \), 즉 \( n = 1 \):
\[ P = \frac{\binom{5}{1}}{\binom{10}{1}} = \frac{5}{10} = 0.5 \]
이것은 올바른 확률이 아닙니다.

n = 2 \):
\[ P = \frac{\binom{5}{2}}{\binom{10}{2}} = \frac{10}{45} = \frac{2}{9} \approx 0.2222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222