caption: Kinematics of a Particle moving in a Straight Line
exif: {"Image DocumentName": "Kinematics of a Particle moving in a Straight Line", "Image ImageDescription": "A ball, A, falls vertically from rest from the top of a tower 63m high. At the same time as A begins to fall, another ball, B, is projected vertically upwards from the bottom of the tower with velocity 21ms-1. The balls collide. Find the height at which this happens. You can use the formulae for constant acceleration to model an object moving vertically in a straight line under the influence of gravity. \ud835\udc35\ud835\udc4e\ud835\udc59\ud835\udc59 \ud835\udc34. \ud835\udc35\ud835\udc4e\ud835\udc59\ud835\udc59 \ud835\udc35. Draw a diagram. \ud835\udc60= \ud835\udc62+\ud835\udc63 2 \ud835\udc61. \ud835\udc60= \ud835\udc60 1. \ud835\udc60= \ud835\udc60 2. \ud835\udc63=\ud835\udc62+\ud835\udc4e\ud835\udc61. In this case we need to consider each ball separately. We can call the two distances s1 and s2. The time will be the same for both when they collide, so we can just use t. Make sure that acceleration is positive for A as it is travelling downwards and negative for B as it is travelling upwards. \ud835\udc62=0. \ud835\udc62=21. s1. \ud835\udc63= \ud835\udc63= \ud835\udc60=\ud835\udc62\ud835\udc61+ 1 2 \ud835\udc4e \ud835\udc61 2. 63m. \ud835\udc4e=9.8. \ud835\udc4e=\u22129.8. \ud835\udc63 2 = \ud835\udc62 2 +2\ud835\udc4e\ud835\udc60. \ud835\udc61=\ud835\udc61. \ud835\udc61=\ud835\udc61. s2. 21ms-1. \ud835\udc60=\ud835\udc63\ud835\udc61\u2212 1 2 \ud835\udc4e \ud835\udc61 2. 1) \ud835\udc60 1 =4.9 \ud835\udc61 2. 2) \ud835\udc60 2 =21\ud835\udc61\u22124.9 \ud835\udc61 2. Add the two equations together (this cancels the 4.9t2 terms) \ud835\udc60 1 +\ud835\udc60 2 =21\ud835\udc61. s1 + s2 must be the height of the tower (63m) 63=21\ud835\udc61. Divide by 21. 3=\ud835\udc61. So the balls collide after 3 seconds\u2026 2C.", "Image XResolution": "300", "Image YResolution": "300", "Image ResolutionUnit": "Pixels/Inch", "Image Software": "SlidePlayer", "Image YCbCrPositioning": "Centered"}