Calen originally had 5 more pencils than does Caleb, and Caleb has 3 less than twice as many pencils as does Candy.  If Calen lost 10 pencils, which left him with 10 pencils, then how many pencils does Candy have?
If Calen lost 10 pencils, which left him with 10 pencils, then Calen originally had 10+10=<<10+10=20>>20 pencils.
Calen originally had 5 more pencils than does Caleb, and thus Caleb has 20-5=<<20-5=15>>15 pencils.
Let's let "x" represent the number of pencils owned by Candy.
Since Caleb has 3 less than twice as many pencils as does Candy, then (2*x)-3=15.
This simplifies to 2*x=18.
Thus, the number of pencils owned by Candy is x=<<9=9>>9 pencils.
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human
Calen originally had 5 more pencils than does Caleb, and Caleb has 3 less than twice as many pencils as does Candy.  If Calen lost 10 pencils, which left him with 10 pencils, then how many pencils does Candy have?
gpt
If Calen lost 10 pencils, which left him with 10 pencils, then Calen originally had 10+10=<<10+10=20>>20 pencils.
Calen originally had 5 more pencils than does Caleb, and thus Caleb has 20-5=<<20-5=15>>15 pencils.
Let's let "x" represent the number of pencils owned by Candy.
Since Caleb has 3 less than twice as many pencils as does Candy, then (2*x)-3=15.
This simplifies to 2*x=18.
Thus, the number of pencils owned by Candy is x=<<9=9>>9 pencils.
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