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// The technique demonstrated in the example monte_carlo.cu | |
// assigns an independently seeded random number generator to each | |
// of 30K threads, and uses a hashing scheme based on thread index to | |
// seed each RNG. This technique, while simple, may be succeptible | |
// to correlation among the streams of numbers generated by each RNG | |
// because there is no guarantee that the streams are not disjoint. | |
// This example demonstrates a slightly more sophisticated technique | |
// which ensures that the subsequences generated in each thread are | |
// disjoint. To achieve this, we use a single common stream | |
// of random numbers, but partition it among threads to ensure no overlap | |
// of substreams. The substreams are generated procedurally using | |
// default_random_engine's discard(n) member function, which skips | |
// past n states of the RNG. This function is accelerated and executes | |
// in O(lg n) time. | |
struct estimate_pi : public thrust::unary_function<unsigned int,float> | |
{ | |
__host__ __device__ | |
float operator()(unsigned int thread_id) | |
{ | |
float sum = 0; | |
unsigned int N = 5000; // samples per stream | |
// note that M * N <= default_random_engine::max, | |
// which is also the period of this particular RNG | |
// this ensures the substreams are disjoint | |
// create a random number generator | |
// note that each thread uses an RNG with the same seed | |
thrust::default_random_engine rng; | |
// jump past the numbers used by the subsequences before me | |
rng.discard(N * thread_id); | |
// create a mapping from random numbers to [0,1) | |
thrust::uniform_real_distribution<float> u01(0,1); | |
// take N samples in a quarter circle | |
for(unsigned int i = 0; i < N; ++i) | |
{ | |
// draw a sample from the unit square | |
float x = u01(rng); | |
float y = u01(rng); | |
// measure distance from the origin | |
float dist = sqrtf(x*x + y*y); | |
// add 1.0f if (u0,u1) is inside the quarter circle | |
if(dist <= 1.0f) | |
sum += 1.0f; | |
} | |
// multiply by 4 to get the area of the whole circle | |
sum *= 4.0f; | |
// divide by N | |
return sum / N; | |
} | |
}; | |
int main(void) | |
{ | |
// use 30K subsequences of random numbers | |
int M = 30000; | |
float estimate = thrust::transform_reduce(thrust::counting_iterator<int>(0), | |
thrust::counting_iterator<int>(M), | |
estimate_pi(), | |
0.0f, | |
thrust::plus<float>()); | |
estimate /= M; | |
std::cout << "pi is around " << estimate << std::endl; | |
return 0; | |
} | |