user139869: First I want to thank Jimmy Song for pointing me to this site. I'm running into a small problem with Chapter 4 Exercise 5: Find the Address corresponding to the public keys whose private key secrets are:
5002 (use uncompressed SEC on testnet)
I'm not a Python programmer, so I started to complete the exercises in Java! Since the intermediate results are not published in the book, I'm now trying to reproduce the exercise using Python.
Could anyone that has done the exercises tell me the byte array for the private key secret (5002 uncompressed SEC on telnet) when the final call to "return encode_base58_checksum(prefix + h160)" is?
Thank you so much for the support.
Here is what I generate:
answer: "mmTPbXQFxboEtNRkwfh6K51jvdtHLxGeMA";
my result:  mopAiY7pn2XV3DGrGKmVkuvjhMLLNcHZLv
Dave

user139869: Teaching myself python produced this answer:
prefix + h160
b'oA$6\x14\xae\xcd\x13\x81\x9dz\x7f4\x8aJ\x07\xfb\xcb)\xd8\xe5'
Thank you for all that reviewed the question.

139869: <p>First I want to thank Jimmy Song for pointing me to this site. I'm running into a small problem with Chapter 4 Exercise 5: Find the Address corresponding to the public keys whose private key secrets are:</p>
<p>5002 (use uncompressed SEC on testnet)</p>
<p>I'm not a Python programmer, so I started to complete the exercises in <strong>Java</strong>! Since the intermediate results are not published in the book, I'm now trying to reproduce the exercise using Python.</p>
<p>Could anyone that has done the exercises tell me the byte array for the private key secret (5002 uncompressed SEC on telnet) when the final call to &quot;return encode_base58_checksum(prefix + h160)&quot; is?</p>
<p>Thank you so much for the support.</p>
<p>Here is what I generate:</p>
<p>answer: &quot;mmTPbXQFxboEtNRkwfh6K51jvdtHLxGeMA&quot;;<br />
my result:  mopAiY7pn2XV3DGrGKmVkuvjhMLLNcHZLv</p>
<p>Dave</p>
 139869: <p>Teaching myself python produced this answer:</p>
<p>prefix + h160
b'oA$6\x14\xae\xcd\x13\x81\x9dz\x7f4\x8aJ\x07\xfb\xcb)\xd8\xe5'</p>
<p>Thank you for all that reviewed the question.</p>
