user15303: I'm just curious about this. I'm not sure if the length of zeros in the hash result is directly proportional to the probability, or how to calculate this.

user7144: (Average hashing power of network per second between the last difficulty adjustment and the difficulty adjustment that came before it) * 600 
or (2^32 * difficulty)

15303: <p>I'm just curious about this. I'm not sure if the length of zeros in the hash result is directly proportional to the probability, or how to calculate this.</p>
 7144: <p>(Average hashing power of network per second between the last difficulty adjustment and the difficulty adjustment that came before it) * 600 </p>

<p>or (2^32 * difficulty)</p>
